#help-26

226100 messages · Page 252 of 227

livid pelican
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and this is what I've done:

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I'm not too sure about how to carry on with this

novel token
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Do you know what separation of variables is in differential equations?

livid pelican
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um I don't think so

novel token
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Well basically just put all the r’s

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On the left

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And all the t’s on the right

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Which is almost what you did

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But..

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That thing you called b which is dr/dt has a t!

livid pelican
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yup

novel token
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So it can’t be on the same side as r

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Cuz we gotta separate them

livid pelican
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yes, that makes sense

novel token
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Let’s go back to this

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Cuz what you did became messy

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From this equation try and separate r and t

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Note: k and a can be wherever they don’t matter

livid pelican
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something a little more like this?

novel token
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Yes exactly

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Very good

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Now

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Integrate both sides

livid pelican
novel token
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Not quite

livid pelican
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oh yeah xD

novel token
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What’s the integral of x/(1-x^2)

livid pelican
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ln(x^2+1)/2

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oh one sec

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-ln(x^2-1)/2

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+C

novel token
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Exactly

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Now do it for a^2 instead of 1

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Which changes nothing fundamentally

livid pelican
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-ln(x^2-a^2)/2 +C

novel token
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-ln(a^2-x^2) +C

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Yea you don’t need to divide by 2 cuz you already have 2r

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And the denominator is a2-x2 not the other way around

livid pelican
novel token
novel token
livid pelican
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let u = a2-x2

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for some u sub

novel token
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ok

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keep going

livid pelican
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we get dx = -1/2x du

novel token
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good

livid pelican
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so we have -1/2 \int 1/u du

novel token
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ok

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now before you finish

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do the same steps for the integral we care about

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integral of 2r/(a^2-r^2)

livid pelican
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  • ∫ 1/u du
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which is nothing other than -ln(u)

novel token
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exactly

livid pelican
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yet u = a^2 - x^2

novel token
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yup

livid pelican
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so we have -ln(a^2 - x^2)

novel token
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+c

livid pelican
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ah yes

novel token
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so there you go

livid pelican
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so kt = -ln(a^2 -r^2) + C

novel token
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correct

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but thy want you to write r in terms of t

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so r = ?

livid pelican
novel token
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does r represent something specific

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?

livid pelican
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the radius

novel token
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ok so r is oisutuve

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positive

livid pelican
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yup

novel token
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cool

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now find A

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my bad

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not a, but A

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remember what they told you r=0 and t=0

livid pelican
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so A = a^2

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which means we can factor that out

novel token
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indeed

livid pelican
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ah thank you very much

novel token
#

perfect

livid pelican
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so for these type of problems we should seperate variables, then integrate, then use conditions?

novel token
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exactly

livid pelican
#

thank you again for your help

#

.close

topaz sinewBOT
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sturdy vigil
#

Who knows how to tackle this -1 into a logarithm?

sweet shard
sturdy vigil
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Yes

sweet shard
sturdy vigil
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What do you mean?

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It’s not an equation

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Shouldve used an arrow

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,rotate

thorny flameBOT
sweet shard
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and what equation are you working with and what variable are you solving for?

sturdy vigil
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It needs to be written an a whole logarithm

sweet shard
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use $\log_2(2) = 1$

thorny flameBOT
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riemann

sturdy vigil
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What?

sweet shard
sweet shard
sturdy vigil
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Your input

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Log(g) (a)?

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Same as ^g log (a)?

sweet shard
sweet shard
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than $^g \log(a)$

thorny flameBOT
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riemann

sturdy vigil
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I’m sorry I’ve just been taught differently hence the confusion

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I just want to know how to get the -1 into the logarithmic

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I have no formula’s

sweet shard
sturdy vigil
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Yes

sweet shard
sturdy vigil
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I come to ^2log(x^3) -1

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But -1 needs to be manipulated into the logarithm, that’s my question

sweet shard
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$-1 = - \log_2(2)$

thorny flameBOT
#

riemann

topaz sinewBOT
#

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topaz sinewBOT
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sturdy vigil
topaz sinewBOT
neon iron
#

62 students are picking two activities to do over the weekend.9 picked painting and sport.
11 did not pick painting or sport.
Twice as many students picked sport than painting as one of their activities.Find the amount that picked sport and not painting.

waxen storm
sturdy vigil
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How is 2^2=1 and not 4?

waxen storm
sturdy vigil
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I can only assume that ^g log(a) isn’t the same as the above mentioned

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It’s also looking like Chinese to me

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Perhaps I should go sleep 💤

sweet shard
sweet shard
topaz sinewBOT
#

@sturdy vigil Has your question been resolved?

neon iron
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misty basin
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Could i have help

topaz sinewBOT
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@misty basin Has your question been resolved?

marble hawk
#

S(y2-y1)dx =576 then solve for c.

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broken magnet
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for p-series, why arent they convergent at p = 1

broken magnet
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.close

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faint fox
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Hi I need help solving the scale factor

topaz sinewBOT
faint fox
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When I solve it the way my teacher showed, I get an answer of 2

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but when I do it in reverse, I get 0.5 which is what the textbook says

junior widget
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AB and DE are corresponding, to get from m(AB) to m(DE) what do you have to scale AB by?

faint fox
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2

junior widget
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1/2 is the correct answer

faint fox
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so then why does the textbook say 0.5

junior widget
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DEF is the image of ABC

junior widget
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The answer is 1/2

thin oak
faint fox
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huh

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im absolutely confused

junior widget
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AB * k = DE
8k = 4
k = 4/8 or 0.5

faint fox
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so smaller triangle to larger triangle? basically instead of 8/4 I do 4/8

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the way i solve it is:

n = AB/DE = number/number = number

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but instead of AB/DE

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do DE/AB?

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nvm ur way actually makes a lot more sense

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thanks man

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much appreciated

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topaz sinewBOT
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faint fox
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.reopen

topaz sinewBOT
#

faint fox
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wait a minute @junior widget

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can u explain how my teacher got this then

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scale factor of 2

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i just did it ur way and its also 0.5

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is her method even corrrect

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@junior widget

junior widget
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Your teacher doesn't understand why they are using ABC and DEF

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DEF is the image of ABC

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At least, thats how the alphabet works

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Either way, your answer and your teachers are both Correct in a way

faint fox
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thats helpful but also not helpful cause idk wth shes gonna quiz me on when the time comes, gotta ask her tmrw

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thanks for the help man

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much appreciated

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.close

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digital vale
topaz sinewBOT
faint fox
digital vale
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nvm

faint fox
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yea still idk what that is

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never learned it

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and im taking academic math

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:|

digital vale
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a you know trig?

faint fox
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just started it today

digital vale
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oh crap

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you could google the cosine rule

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it will help you solve it in a second lol

faint fox
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we're prob gonna learn it cause my teacher made a bunch of sub folders

faint fox
faint fox
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factoring is easy

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getting the roots without the quadratic equation in a trinomial is hard

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especially if ur me

digital vale
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use a computer lol

faint fox
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i used to use some wolfram alpha widget

digital vale
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it's much easier if you the computer and get the answer then factor it to get the answer

digital vale
faint fox
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cause of the scale factor?

empty sail
faint fox
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the scale factor is questionable but everything else seems right

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shes subbing it in from the other shape

empty sail
#

It's similar shapes, so $\frac{12}{6} = \frac{y}{4.5}$

thorny flameBOT
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dldh06

empty sail
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So y = 9

digital vale
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oh yea similiar shape

empty sail
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No need

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Similar shapes

digital vale
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i forgor about that thing

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thanks @empty sail

faint fox
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cant wait till i learn the cosine rule

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:D

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anyways thanks for all the help

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u guys have a great night

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😘

digital vale
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its gonna be great

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good day @faint fox

faint fox
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cya

empty sail
topaz sinewBOT
#

@digital vale Has your question been resolved?

topaz sinewBOT
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topaz sinewBOT
neon iron
#

<@&286206848099549185>

topaz sinewBOT
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@neon iron Has your question been resolved?

topaz sinewBOT
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@neon iron Has your question been resolved?

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gleaming pasture
topaz sinewBOT
gleaming pasture
#

Can someone help me with this proof

topaz sinewBOT
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@gleaming pasture Has your question been resolved?

wide berry
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void edge
#

anyone expert in algorithmic graph theory

topaz sinewBOT
void edge
#

please give a shout. need help

loud dawn
#

@void edge is it a very long/complicated question?

neon iron
loud dawn
#

It would be easier to find someone who’s willing to read beforehand

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Cause most people see big paragraph and nope out

neon iron
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well posting first is always faster

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we can just guide her later

loud dawn
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Ah

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True

neon iron
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KEK but i just needed an excuse to post that sticker

loud dawn
#

lol

topaz sinewBOT
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sterile ridge
#

Hey, what is the correct answer to the integral of 1/(3x) dx?

I got 1/3*ln|3x| when I used the formula 1/(ax+b) dx = 1/3*ln|ax+b| and my teacher got 1/3*ln|x| when he separated 1/3 from the original integral and integrated 1/x alone since constants survive.

Bottom line my teacher thinks we’re both right but he wasnt able to prove that the results were the same by trying to get to 1/3*ln|x| from 1/3*ln|3x|.

If you derivate both integrals you do get back to 1/(3x) eeveeThink

wide berry
sterile ridge
wide berry
sterile ridge
#

I didnt learn math in English catshrug

sterile ridge
#

I’ll share both our answers when I get home

topaz sinewBOT
#

@sterile ridge Has your question been resolved?

topaz sinewBOT
#

@sterile ridge Has your question been resolved?

sterile ridge
#

Hey, so I'm back home, and the original math problem was; ∫(x² + 2x + 1/(3x)) dx where I got 1/3⋅x³ + x² + 1/3⋅ln|3x| + C and my teacher got 1/3⋅x³ + x² + 1/3⋅ln|x| + C

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My teacher thinks we're both right, but struggled proving it. While we can see that these are two different solutions, how can these be the same? And if they're not the same, which is correct?

sterile ridge
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Thing is though, if you inserted a value for x, wouldn't these two functions produce two different results?

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So because of this, these can't both be correct solutions..?

wide berry
sterile ridge
#

So, since C is an unknown constant, we can't for sure know what f(x) will be if we integrate f'(x), thus f(x) will differ by C which includes 1/3ln|3x|, making both integrations correct?

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Is that what you mean?

sturdy oracle
thorny flameBOT
#

Umbraleviathan

sturdy oracle
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But then I'm getting (1/3)ln|x|

sterile ridge
sturdy oracle
#

It can't be ln|3x| because by chain rule, if you derive ln|3x| you get (1/x)

sterile ridge
#

However, if you use the formula ∫1/(ax+b)dx = 1/a⋅ln|ax+b| + C, then you get my result

sturdy oracle
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where a = 3 and b = 0?

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Uh lemme think

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No that's not right

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Lemme think

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Oh you know what

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That only works when b ≠ 0

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That's because if b = 0, the "a" would cancel out

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Leaving you, by chain rule, with (1/x)

sterile ridge
sturdy oracle
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Oh you have a 1/3 in front of it

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I thought you just had ln|3x| lol

sterile ridge
#

No 🙃

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If we differentiate both integrals, we get back to where we started

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So both have to be correct, unless I'm missing something

sturdy oracle
#

Oh atcually

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Hmm

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Well m $\frac{1}{3}\ln{|3x|} = \frac{1}{3}ln{|x|} + \frac{1}{3}\ln{(3)}$

thorny flameBOT
#

Umbraleviathan

sturdy oracle
#

Which would get the same result if you derived it

sterile ridge
#

True, so, can one say that 1/3⋅ln3 is part of the unknown constant C?

sturdy oracle
#

You could, but it isn't the value of C

sterile ridge
#

No, but it's part of it, right?

sturdy oracle
#

Yeah

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Somewhat

sterile ridge
#

There can be an infinite amount of constants technically

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So yeah

sturdy oracle
#

Mmhm

sterile ridge
#

Sweet, thanks!

#

.clsoe

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.close

topaz sinewBOT
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sturdy oracle
#

3x = u

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This is how you get (1/3)ln|3x|

topaz sinewBOT
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icy pilot
topaz sinewBOT
icy pilot
#

Is there a way to find the range just from the equation? or do you have to draw the graph and points

#

the 3 in the equation represents the y value so I get the 3, but how do you know whether it's going to go to positive or negative infinity from just the equation?

junior widget
#

Then you know it keeps going to to infinity

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The asymptote is just 3 because the +3

icy pilot
#

How do you know it keeps going to infinity?

junior widget
#

All real values work

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So you can just keep making x larger

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,w graph 2^x + 3

icy pilot
#

I see, that makes sense, thanks

#

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icy pilot
#

what's the latex of

topaz sinewBOT
floral rampart
#

$$f(x) = a\log_b(x-h)+k$$ do you want those arrows too?

thorny flameBOT
#

ohNoiAmHere

icy pilot
#

Btw, the b of the logarithmic graph doesn't represent growth / decay like how the exponentials does right?

floral rampart
#

hmm, it's simply the base of the logarithm, something with a larger base will be smaller. its not really growth though

#

there are models with log though

topaz sinewBOT
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old flicker
#

do you guys know if these two equations represent the same plane?
-x+3y-z=0
-5x+15y-5z=0

old flicker
#

I guess it does since u can multiply the top equation with 5

oak sequoia
#

probably check if the coefficents are in the same ratio

#

-1/-5 = 3/15 = -1/-5

old flicker
#

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hearty wraith
topaz sinewBOT
hearty wraith
#

can someone help me please

keen venture
#

First you'll want to find x in terms of θ

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Then the calculus is the easy part. Differentiate in terms of t, keeping in mind that dθ/dt = π

hearty wraith
#

oh

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mm thanksss

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mossy sapphire
#

what is half of 10 powered to 500? And what number gets the same result if you multiply it by 0,2 or subtract 0,2 from it?

topaz sinewBOT
#

@mossy sapphire Has your question been resolved?

mossy sapphire
#

<@&286206848099549185>

topaz sinewBOT
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@mossy sapphire Has your question been resolved?

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terse finch
#

hi

topaz sinewBOT
terse finch
#

i'm curently tring to do the 1 (a) for this i need to modifiate the 3 expretion to get the 1 ou the 2

#

for the moment i try partial integration but i don't fin an end to the cycle, i have been thinking of using change of variable but can't find one usefull so if you have any lead please

#

<@&286206848099549185>

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livid field
topaz sinewBOT
livid field
#

Also see the given figure of thos above question

thin oak
#

plug in the stuff u know then solve for h

livid field
#

I don't understand that whether they are talking about area of whole triangle or right angled triangle .

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trail timber
topaz sinewBOT
trail timber
#

im stuck

topaz sinewBOT
#

@trail timber Has your question been resolved?

topaz sinewBOT
#

@trail timber Has your question been resolved?

sweet shard
trail timber
#

.close7

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.close

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timber jungle
topaz sinewBOT
timber jungle
#

i need help with a decent amount of questions if anyone can help pls do i have a big exam tmrw

hallow depot
#

its to late

neon iron
timber jungle
neon iron
timber jungle
#

90?

neon iron
#

yes

#

so It'll form a right angle triangle right?

timber jungle
#

yes

#

i already solved for the hypo

#

but that didnt rlly help

neon iron
timber jungle
#

i did tan-1(theta) to get angle

#

and got 71.6

neon iron
timber jungle
#

not tan-1(theta) i mean tan-1(15/5)

neon iron
#

You did a common mistake

timber jungle
#

is it in the fourth quadrant

#

?

neon iron
#

nope

#

you've taken 5 as the base

#

so the angle you got is wrt east direction

#

got what you did wrong?

timber jungle
#

not rlly

#

this is how i drew it

neon iron
timber jungle
#

?

neon iron
#

you're getting confused b/w these two angles

neon iron
timber jungle
#

yes

neon iron
#

now look at the options

timber jungle
#

90-71.6?

#

is that it?

neon iron
#

perfect

neon iron
timber jungle
#

not rlly

#

theta1+theta2=90

idk which one of them is 71.6

#

im guessing theta 1

neon iron
#

because in the options you're trying to find the angle wrt south which is y axis, whereas the angle you calculated is wrt x axis

timber jungle
#

oh i see

#

so i found theta 1

neon iron
#

yes

neon iron
#

perfect

#

so if you've calculated tan-1(5/15) you'll get the angle from y axis

#

@timber jungle got it?

timber jungle
#

i got the first part but i dont rlly get why i would do tan-1(5/15) can u show me a triangle with the xy plane pls

timber jungle
# neon iron

this may be a dumb question but how do i know which is the perpendicular and which is the base ,-,

neon iron
#

1 min I'll explain

#

@timber jungle read it few times and try to visualise what I'm saying you'll get it ;)

#

the last lines are enough to get it

timber jungle
#

alr i get it i think

neon iron
#

nice

#

1 min

#

@timber jungle what is base in this case?

timber jungle
#

7?

neon iron
#

fuck this isn't a right angle

timber jungle
#

ye was gonna ask that xD

neon iron
#

assume the angle to be 90°

neon iron
# timber jungle 7?

"the line opposite to theata is the perpendicular" you need some visualisation

#

check some yt videos it'll help

timber jungle
#

isnt 7 the line opp to the angle?

neon iron
timber jungle
#

yes

#

ohhhh

#

u wanted base <_<

neon iron
#

hence 9 is the base

neon iron
timber jungle
#

ye ye i get it

neon iron
#

nice

#

look at the problem, now you'll be able to solve it

#

tan theata = (perpendicular/base)

timber jungle
#

alr ty!

neon iron
#

gotta go

timber jungle
#

np!

neon iron
#

have my physics work pending

timber jungle
sweet shard
#

r^2 = x^2 + y^2 etc

timber jungle
#

i dont get it i tried multiplying the whole thing by r

sweet shard
#

first step is $r (1 + \cos(\theta)) = 2$ then use $x = r\cos(\theta)$ and/or $y=r\sin(\theta)$

thorny flameBOT
#

riemann

timber jungle
#

so r+x=2

#

now what do i do

#

if i multiply by r i get

x^2+y^2+r^2cos(theta)=2

sweet shard
topaz sinewBOT
#

@timber jungle Has your question been resolved?

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unkempt stratus
#

@sweet shard

topaz sinewBOT
#

Please don't occupy multiple help channels.

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rapid inlet
topaz sinewBOT
sturdy oracle
#

Chain rule lol

#

I mean it says it right there

mellow venture
#

twice

#

yw

rapid inlet
#

Yeah I don't know exactly what it means

sturdy oracle
#

You don't know what the chain rule is?

rapid inlet
#

I know what the chain rule is

sturdy oracle
#

Well

#

You have to use it twice

#

Because you have uh

rapid inlet
#

-_-

sturdy oracle
#

A composite within a composite

#

derivOuter • derivInner • derivInnerInner • derivInnerInnerInner ...

#

So let's start with the sine

#

Take the derivative with respect to the outer

#

What would that look like

rapid inlet
#

um

#

-18sin(6x^7)?

sturdy oracle
#

Yeah so that's a beginning

#

So now you gotta multiply that by the derivative of sin(6x^7)

#

Doing this step-by-step

tulip light
#

$$\frac{d}{dx} f(g(h(x))) = f'(g(h(x))) \cdot \frac{d}{dx} g(h(x))$$
just as a note, you can think of g(h(x)) as a single function and use chain rule as if you had f(g(x)) then for the derivative of g(h(x)) you apply chain rule again

thorny flameBOT
atomic swift
#

I did a similar problem

rapid inlet
#

i'm not trying to be difficult i'm just trying to figure it out so i can do it myself later

sturdy oracle
#

Yeah you can use J42's as an example

#

You gotta like

#

Well you have the first step done

rapid inlet
#

I would think that would only apply if sin^2(x) = sin(sin(x))

#

brb gotta grab something from the oven

sturdy oracle
#

No

#

But uh

#

$-18\sin{\left(6x^7\right)}$

thorny flameBOT
#

Umbraleviathan

sturdy oracle
#

Is the correct first step

#

But now you gotta do the inner, which is the sine

atomic swift
#

First let u=6x^7 and find du/dx

sturdy oracle
#

It's easier to just use chain rule for this

atomic swift
#

Then let v=sin(u) and find dv/du

#

Finally differentiate your term with respect to v

#

Then multiply by du/dx and dv/du

sturdy oracle
#

Oh yeah that also works

#

I mean

#

That is the chain rule lol

atomic swift
#

Its the same thing but more working

#

Just watch black pen red pen on YouTube and you will be brilliant at differentiation it really helped me this year in maths

rapid inlet
#

so uhh then you get

#

cos(6x^7) right?

#

or no

#

I forget how to take a derivative of sin with something other than just x in it

rapid inlet
#

oh wait am I supposed to use chain rule here

#

like

#

$\frac{d}{dx}(sin(6x^7)) = cos(6x^7)*(42x^6)$

thorny flameBOT
#

Eyesonjune

sturdy oracle
#

Yeah

rapid inlet
#

now what do I do

neon iron
#

$\1+1

rapid inlet
#

I have -18sin(6x^7)

#

and cos(6x^7)*(42x^6)

#

do I just make it

thorny flameBOT
#

Eyesonjune

rapid inlet
#

.close

topaz sinewBOT
#
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jovial mason
#

I'm very stuck at b)

topaz sinewBOT
jovial mason
#

can you help me understand the hint? I'm not sure what it means by applying T n-1 times

#

for (b)

sweet shard
#

$T^{n-1}(v) =T(T(....(T(v))))$

thorny flameBOT
#

riemann

sweet shard
#

for n = 3: $T^2(v) = T(Tv)$

thorny flameBOT
#

riemann

sweet shard
#

If $v$ is an eigenvector, then $Tv = \lambda v$

thorny flameBOT
#

riemann

sweet shard
#

Since $T$ is a linear operator, factor out lambda

thorny flameBOT
#

riemann

jovial mason
#

I'm not sure how this proves linear independence, do I have to factor out lambda n times for every v_n?

sweet shard
#

do the hint first

jovial mason
#

ok

#

I will take a break and try later, thanks for the help

#

.close

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blazing crescent
#

what does a discriminant show?

topaz sinewBOT
blazing crescent
#

$b^2-4ac$

thorny flameBOT
#

yomiko

neon venture
#

it's one of the best way to determine the number of roots of a quadratic

blazing crescent
faint coral
neon venture
blazing crescent
#

what about if i want to know how many roots on other functions

blazing crescent
neon venture
#

quadratic = x^2

neon venture
#

A polynomial of degree n has at least n roots

blazing crescent
#

ok

#

.close

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subtle flame
#

Hello I’m very stuck at this question I don’t get it

subtle flame
#

This is basically my work

#

But it still feels wrong 🫤

#

Not sure if I’m doing it correctly but I cant grasp what the videos are saying either

bitter hemlock
#

hello, the key thing to notice is that triangles BAC and DBC are similar (they share angle C, they both have a 90 degree angle, therefore all their angles are congruent)
Using ratios of corresponding sides of similar triangles you can see there is this relation:
4/x = x/3; solving for x yields x = 2√ 3

#

here are the corresponding sides of these similar triangles if that makes it easier to visualize

topaz sinewBOT
#

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subtle flame
topaz sinewBOT
#
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buoyant path
#

I'm trying to get the primitive function of:

buoyant path
#

The answer is supposed to be

#

But I have no idea how that could be the answer

#

what I tried was just

visual rose
#

primitive function is the antiderivative?

buoyant path
#

Yeah

visual rose
#

ok

buoyant path
#

I really just need someone to explain to me how

#

we end up with that result

visual rose
#

do you recall the rules for derivation when $f=e^{ux}$ ?

thorny flameBOT
#

madlor

buoyant path
#

I'm pretty sure

#

I do

#

Is it not like

visual rose
#

ok, whats $f'$?

thorny flameBOT
#

madlor

buoyant path
#

If f = e^ux

#

then f' = u*e^ux

#

if i'm not mistaken

visual rose
#

that is correct

#

okay

#

now do you agree that the antiderivative would be the excact opposite?

buoyant path
#

I tried doing that but in reverse

visual rose
#

yeah, what did that look like?

buoyant path
#

I'm doing something wrong

#

because what I did

#

actually lemme think

visual rose
#

go for it 👍

buoyant path
#

yep I was just overthinking things

#

All I had to do was take 150/-0.3

#

ty for the help

visual rose
#

nice!

#

any time

buoyant path
#

.close

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#
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neon iron
#

"A solution contains 1% salt. The solution is set outside and aftersome time, water loss has occured. The solution has lost x% of it's mass and the new salt content is 10%. What is the value of x?"
I setup two equations, $\frac{S}{m} = 0.01$ which describes its intitial state. After the loss, $\frac{S}{mx} = 0.1$ We can subsitute S from the first equation to the second one: $\frac{0.01m}{mx} = 0.1 \Rightarrow x =\frac{0.01}{0.1} = 0.1$

thorny flameBOT
#

Duck Observer

neon iron
#

The answer sas "x has to be greater than 80%"

#

Which means mine is wrong

#

Could anyone guide me?

tulip light
thorny flameBOT
tulip light
#

@neon iron

neon iron
#

Does that mean that the final answer is umm

tulip light
#

I didn't yet write the equation and solve it

#

can't comment on final answer

neon iron
#

$x_f = 1-x = 1-0.1 = 0.9?$

thorny flameBOT
#

Duck Observer

neon iron
#

Ah

tulip light
#

your equation is wrong

neon iron
#

I will try and solve it with (1-x)

#

Oh 😦

#

Solving it with (1-x) in the second equation gives: $\frac{0.01}{(1-x)} = 0.1 \Rightarrow x = \frac{0.1-0.01}{0.1} = 0.9$

thorny flameBOT
#

Duck Observer

tulip light
#

mhm seems right

neon iron
topaz sinewBOT
#

@neon iron Has your question been resolved?

topaz sinewBOT
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final wren
#

Hey, can someone help me find the derivative of equations of type x^2 + y^2 = 1?

final wren
#

Like circle equations

#

.close

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sullen depot
#

how does induction work with the special E that means the sum of all?

sullen depot
#

llike for example this one

#

when i get to the step of replacing N with K do I just leave the I's alone? or do othey get replaced with k's too?

#

I don't need to solve it fully I only need to get it to the form of what the left and right side would be at k+1

topaz sinewBOT
#

@sullen depot Has your question been resolved?

sullen depot
#

<@&286206848099549185>

#

Im a bit confused about the K+1 step as well Like I understand your just putting K+1 instead of K but theres another thing you have to do to it that I'm not seeing and I don't quite get what I'm missing about it.

topaz sinewBOT
#

@sullen depot Has your question been resolved?

topaz sinewBOT
#

@sullen depot Has your question been resolved?

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ripe ridge
#

can someone explain how those two sets are equal

ripe ridge
#

so C is the subsets of A

#

which is S with one more element

#

how do they have the same number of elements when C has one more element

hollow bone
ripe ridge
#

i meant B is

hollow bone
#

its the set of subsets that contain element d

ripe ridge
#

my bad

hollow bone
#

B is not either

#

its the set of subesets that doesnt contain element d

ripe ridge
#

A without d

#

isnt it?

#

I mean it even says that

hollow bone
#

yeah its the set of subsets of A\ {d}

ripe ridge
#

then how is | B | = | C |

hollow bone
#

for each set in B you can match a set in C, (one to one correspondance)

#

forall X in B it corresponds to XU{d} in C

#

and forall X in C, since d is in X

#

X = {d} U Y where Y is a subset of A\ {d}

#

so Y is in B

#

so there is indeed a one to one correspondance between elements of B and C

ripe ridge
ripe ridge
#

but with d

hollow bone
#

the elements*

#

but yeah

#

elements of B are subsets of S

#

but they're elements of B

ripe ridge
#

hmm i think i got it, thanks

#

im gonna wait to see if anyone else has anything to add

#

if not ill close it

hollow bone
topaz sinewBOT
#

@ripe ridge Has your question been resolved?

ripe ridge
#

yeah i get it now

#

thanks

topaz sinewBOT
#
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fluid lark
#

for legendre's formula what if the number inside the brackets doesn't have a factorial?

topaz sinewBOT
#

@fluid lark Has your question been resolved?

topaz sinewBOT
#

@fluid lark Has your question been resolved?

fluid lark
#

<@&286206848099549185>

knotty ledge
#

You should show the formula and exactly what you mean

fluid lark
#

.close

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queen forum
#

Just doing some graphing functions revision, not sure how to go about rewriting this function\

topaz sinewBOT
#

@queen forum Has your question been resolved?

mental skiff
#

maybe first write this as $\frac{x^2 +x}{x-1}$

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and then using a nice trick

thorny flameBOT
#

Rœmer

mental skiff
#

We can find $\frac{x^2 +x}{x-1} = \frac{x^2-1+x+1}{x-1} = \frac{x^2 -1}{x-1} + \frac{x+1}{x-1}$

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and then rewriting should be fairly easy

thorny flameBOT
#

Rœmer

mental skiff
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does that make it any easier?

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@queen forum

queen forum
#

I can see where you're going with it manYES

mental skiff
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have you solved it ?

wraith marsh
#

Can anyone help me with some homework problems

mental skiff
queen forum
#

Just got it now manYES

mental skiff
#

nice !

queen forum
#

.close

topaz sinewBOT
#
Channel closed

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Use .reopen if this was a mistake.

queen forum
mental skiff
#

np

topaz sinewBOT
#
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jade cobalt
#

Umm I just asked a question but uhh I’m weak sry ;-;

jade cobalt
#

This equals this ?? I’m not sure about it but got nothing in my mind I could do to solve it xd

knotty ledge
#

,rccw

thorny flameBOT
jade cobalt
#

Cuz they both got different angles xd

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don’t think I could do that ?

knotty ledge
#

show the original question

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I think you mean to write $(\cos(x))^3$

thorny flameBOT
#

iCaird

jade cobalt
#

I have this function

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And need to get when the function touch X and Y

knotty ledge
#

,rccw

thorny flameBOT
jade cobalt
#

Cos x - cos x^3

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But the printer didn’t print it correctly xd

knotty ledge
#

take a screenshot of it on the computer/phone

jade cobalt
knotty ledge
#

no

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from the original question

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we need to know exactly what they wrote

jade cobalt
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I just got this paper

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And the teacher told me to write x^3

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Didn’t specify

knotty ledge
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alright

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and do they want every solution? just integer ones?

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because with the way you've wrote it, finding all solutions is very very tricky and I don't think you'd be expected to find those

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but if its meant to be what I wrote earlier than its a lot easier

jade cobalt
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Not sure tbh

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But it’s -90=>x=>90

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The function

hollow hedge
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so the problem just asks for roots in that interval?

jade cobalt
#

Umm

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Need to find where the function touch X and Y between -90=<x=<90

hollow hedge
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touch X and Y?

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as in tangent to the x and y axis?

jade cobalt
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Dunno how to say it in English xd

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Like when the function come across x and y xd

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Uhh

hollow hedge
#

right, that wouldnt be touching

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touching here would imply the curve is tangent to these axis

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a better word would be "intercepting" or simply "crossing"

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anyway, since you are restricted to an interval, it's easier to solve

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what have you tried?

jade cobalt
#

Since they don’t have same angle

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First 1 got cos x second got cos x^3

hollow hedge
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you work is wrong

jade cobalt
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Sooo uhh they not the same doesn’t work ig

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Ye ik xd

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But dunno what else to do

hollow hedge
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cos(x) if not a factor of cos(x^3)

jade cobalt
#

Wt u suggest xd

hollow hedge
#

ok so we are finding the x-intercepts first, lets agree on this first ok?

jade cobalt
#

I’ve been studying for programming exam for weeks so I’ve forgot a lot of math 😅

hollow hedge
#

so we dont get confused and think about the y-intercept

jade cobalt
#

Ok ok

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So if x is 0 it’s not possible maybe

hollow hedge
#

anyway, notice that since cos(x)-cos(x^3)=0, that implied cos(x)=cos(x^3)

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can you see how we can advance?

jade cobalt
#

Mhm

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But if x is 0

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Sin x = 0

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And demone can’t be 0 ?

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Denominator *

hollow hedge
#

yes, but that's not what i meant

jade cobalt
#

Umm a bit confused now

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We need to do F(0) right ?

hollow hedge
#

if cos(x)=cos(x^3), would it imply that x=x^3?

jade cobalt
#

Not sure tbh xd

hollow hedge
#

yes it would (kind of), because cosine here is a function, and a function (assuming that it is injective) can only be equal to itself if their input are equal to each other

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or well another way of saying it is if f(x_1)=f(x_2) then x_1=x_2 considering that f(x) is injective

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though, that's the easy part

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the hard part here is cosine is not injective

jade cobalt
#

What injective mean xd

hollow hedge
#

one-to-one, one input going in and only one output going out

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i dont want to go into this too much

hollow hedge
#

but basically just remember this, since cos(x) is an even function and periodic, hence if we have cos(x)=cos(y) then x=y+2kpi or x=-y+2kpi where k is an integer

hollow hedge
jade cobalt
#

Isn’t it 2pi * k ?

hollow hedge
#

(basically, i cant just throw you some random knowledge without explaining)

hollow hedge
jade cobalt
#

xd

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Ummm right xd

hollow hedge
#

but anyway, now that you have this knowledge, could you solve cos(x)=cos(x^3)?

jade cobalt
#

X = x^3 +2pi k ?

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And -x^3

jade cobalt
hollow hedge
#

(note that since we are restricted to [-90,90], there is no need for the 2kpi)

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the 2kpi here just represents the periodicity of the function, basically saying that there would be infinite solutions in general

jade cobalt
#

Mhm

hollow hedge
#

so anyway, it simplifies down to x=x^3 and x=-x^3

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can you solve for x in these equations?

jade cobalt
#

All I can think of is x = 0 xd or x = 1

hollow hedge
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yes, that's right

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and can x=0?

jade cobalt
#

Nope

hollow hedge
#

ok, but one thing to notice here, x=1 is actually not in degrees

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it is in radians

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so you have to convert to degrees here for the answer to be correct

jade cobalt
#

1 x pi / 180 ??

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How to convert xd ?

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I forgot

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Or 1 x180 / pi ?

hollow hedge
#

you are in radians, so you need to divide by radians, when you divide by radians you get the ratio between 1 and what you divided by, so you have to multiply by the same amount of what you divided by in degrees

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hence 1*180/pi

jade cobalt
#

Aha

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Ok listen

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This is the drawing

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The 1 and -1 is the 180 in radians ?

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Umm

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Wait

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Hold up xd

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No Brian working atm

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Those r the 1 we found

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I feel like I lost my math knowledge…

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Or our math teacher send question not normal

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Cuz if I have to do all that in exam I’m finished /:

jade cobalt
topaz sinewBOT
#

@jade cobalt Has your question been resolved?

#
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#
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jade cobalt
#

Hello I’ll translate xd

topaz sinewBOT
jade cobalt
#

BA = BC , AL=LK=KC

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Need to find BD/DC

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And idk what they mean with that tbh

topaz sinewBOT
#

@jade cobalt Has your question been resolved?

jade cobalt
#

Should I just close it ?

hollow hedge
#

and sorry, had to do something

#

the graph cross the x axis at (0,0) because the limit as x approaches to 0 of the function approaches the value 0

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you probably dont need this knowledge now

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and also yes, x=-1 is a root too, i forgot to mention that

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x=x^3 gives 3 solutions

hollow hedge
topaz sinewBOT
#

@jade cobalt Has your question been resolved?

jade cobalt
topaz sinewBOT
#
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swift condor
topaz sinewBOT
swift condor
#

Hi, not sure how to find this

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This is what I came up for the first part

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Since now p_0 is constant and the derivative should be constant too

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Does that mean I can just do it like this?

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Seems like it’s not actually correct

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I just made a simple linear demand curve and it does hold up, not sure if it works for a non-linear one, but this might be due to that assumption which I forgot the name of

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Something like this but not exactly

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Seems to hold up for non linear too

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So turns out that is correct but would be really helpful if someone could guide me on why it’s like this?

topaz sinewBOT
#

@swift condor Has your question been resolved?

topaz sinewBOT
#
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floral rampart
#

Find all functions that satisfy $$F(x) = \frac{x}{2} + xF(x+1).$$

thorny flameBOT
#

ohNoiAmHere

floral rampart
#

i have no clue how to start this

#

i tried a substitution but got some ugly recurence

topaz sinewBOT
#

@floral rampart Has your question been resolved?

floral rampart
#

<@&286206848099549185>

topaz sinewBOT
#

@floral rampart Has your question been resolved?

topaz sinewBOT
#
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#
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long trellis
#

In line AB there are 4 segments ABCD A(1,2) D(4,8) AB=BC=CD find B and C by using midpoint formula

topaz sinewBOT
#

@long trellis Has your question been resolved?

long trellis
#

<@&286206848099549185>

safe lichen
#

Midpoint formula

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Just an average

#

Thing of it as an avaerage

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Very simple formula

restive inlet
#

the midpoint formula isn't quite what you want to use here

safe lichen
#

But the questions asks you to use it

#

start by reading the question first @restive inlet

restive inlet
#

i am aware of what they wrote
sometimes questions are ill formed and/or it might be something they assumed they were supposed to use

long trellis
#

This is what I mean sorry for my bad English

safe lichen
#

You don't have to spam sorry for my bad englihs all the time

#

Can u send the photo not sideways pleas

restive inlet
#

,rcw

thorny flameBOT
safe lichen
#

Midpoint is just the average

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Of the points

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AB

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Find the middle

long trellis
safe lichen
#

WHAT point do u want to find

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What point do u want to know

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C and D?

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First find the midpopint

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Then