help-26

[hazy pumice]

No, what would?

You are solving for "dy/dx"

[tiny ginkgo]

to isolate dy/dx we need to take them to opposite sides of each other?

[hazy pumice]

No

Both terms with dy/dx in it are already on the same side

Factor it out of both terms

[tiny ginkgo]

so itd be 3x^2+4y=2x

[hazy pumice]

Ok, let's assume I'm too distracted to recognize your genius

I'm trying to get there hang on

[tiny ginkgo]

4x(dy/dx)+3y^2(dy/dx)=2x-3x^2-4y

[hazy pumice]

3x^2 + (dy/dx)(4x + 3y^2) + 4y = 2x

dy/dx = (2x - 3x^2 - 4y)/(4x + 3y^2)

Yes, you were on it in your last post

[tiny ginkgo]

is it possible to isolate dy/dx from 4x(dy/dx)+3y^2(dy/dx)=2x-3x^2-4y?

is it possible to get dy/dx = (2x - 3x^2 - 4y)/(4x + 3y^2) from 4x(dy/dx)+3y^2(dy/dx)=2x-3x^2-4y?

[hazy pumice]

What are you talking about, its just factoring

It's up there ^

[tiny ginkgo]

why is (2x-3x^2-4y) on top and not the other one

[hazy pumice]

The terms without dy/dx as a factor will be on top, you can try this experiment

...on this problem, I mean

Or I guess

2x - 1 = 6, solve for x

Term without x in it on top

[tiny ginkgo]

would you multiply dx/dy on both sides

also we dont end up using the points for anything is that alright?

.close

[topaz sinew]

Channel closed

Closed by @tiny ginkgo

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stark thicket]

how to prove they are equal without using calculator

[neon iron]

factor both equations

[stark thicket]

didnt work

[neon iron]

are you trying to find the solution or prove they're equal?

[stark thicket]

prove they are equal

[mystic cobalt]

hm

[neon iron]

wtf they aren't equal though

[mystic cobalt]

interesting

let me see it for a bit

[stark thicket]

they are equal for certain solutions

[neon iron]

OH

so find the solution

[mystic cobalt]

u have to find these solutions?

[stark thicket]

i have to prove they are equal

without using solutions

[neon iron]

no you're not proving they're equal you're proving they intersect/the equaiton has a solution

it isn't equal for all v

[stark thicket]

its not possible to go from left

to right?

[neon iron]

multiple the four by each term

then subtract the common terms from each side

make it a quadratic

[stark thicket]

i tried everything m8

[neon iron]

UHHHH

ill help

[stark thicket]

they intersect in 2 points

[mystic cobalt]

well

i think

you must find some solutions and make a table for common answers

[thorny flame]

kaynsu

[neon iron]

i messed up

32 v^2 + 36 v +4

that's the LHS

[stark thicket]

so u telling i can only prove they are the same only when x is equal to 2 solutions

[mystic cobalt]

not quite that

[neon iron]

are you looking for real or complex solutions?

[stark thicket]

not trying to find solutions

trying to go from left to right

[neon iron]

yes y ouare

you are trying to find the place where the equality holds

they aren't equal that doesn't make any sense

[stark thicket]

they are equal in 2 points only

[neon iron]

yes

[stark thicket]

but not in other points

[neon iron]

yes

[stark thicket]

thkx m8

[neon iron]

those are the solutions

[empty sail]

Do you have the exact question?

Like post a screenshot of it

Because whatever you are asking makes no sense

[stark thicket]

teacher just gave it in the last minute in class

told us to right that only

[neon iron]

ok so you're trying to find the solutions

just trust me on that

[stark thicket]

ok

[mystic cobalt]

let me get some paper

[neon iron]

multiply the four on the LHS

then combine like terms

set it equal to 0 and use the quadratic equation

that's the game plan

[stark thicket]

i understand u

i made that

[neon iron]

let me see

[stark thicket]

25v^2+21v+2=0

[neon iron]

now use quadratic equation

what class are you in

algebra 2?

college algebra?

[stark thicket]

idk

my school dont go with that system

[neon iron]

have you learned about complex numbers

[stark thicket]

yes a year ago

[neon iron]

ok so you may have two complex or one complex or no complex solutions

just use the quadratic equation

[stark thicket]

kaynsu

i want to ask question

last question

[neon iron]

ok

shoot

[stark thicket]

this is true only if x is in solutions of the combined = 0 thingy

[neon iron]

if the RHS =0, then you can use the quadratic equation

RHS = right hand side

[mystic cobalt]

check this out

[stark thicket]

i didnt undestand last part

all other i understand

[mystic cobalt]

which part?

[stark thicket]

aaaa

u drew them

i understand

thanks for ur time

[mystic cobalt]

all gucci

[topaz sinew]

@stark thicket Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gloomy needle]

i need help plz

[wary frost]

anyone able to do 5th grade math?

[gloomy needle]

whats the probleM?

[gloomy needle]

question 13 is 72

its 2(length+width)

[wary oak]

Just plug in your point's coordinates into the transformation formula

[gloomy needle]

can u show me the formula?

[wary oak]

The formula is written there

[empty sail]

First, read #❓how-to-get-help
Don't ask in an occupied channel

[wary frost]

oh sorry im new

[empty sail]

Second, don't give out answers

[gloomy needle]

sorry

[empty sail]

Which is why I linked #❓how-to-get-help

[gloomy needle]

can u explain step-by-step on how?

[empty sail]

Plug in the P values into T(x, y) equation given

[gloomy needle]

k thx

got it

[topaz sinew]

@gloomy needle Has your question been resolved?

[gloomy needle]

?

.close

[topaz sinew]

Channel closed

Closed by @gloomy needle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[neon iron]

Are you stupid?

[devout halo]

No need for that. Everyone is at a different level.

[topaz sinew]

@neon iron Has your question been resolved?

[neon iron]

<@&286206848099549185>

Help him

He’s dumb

[arctic plank]

hey be nice

some people arent as smart as u

[neon iron]

I can see that

[empty sail]

One, don't ping helpers for other people, it's not necessary because people are capable of doing that on their own

Two, don't be rude

[arctic plank]

u can help him instead of beating him down

im sure he'll appreciate ur help

[empty sail]

And three, literally a rule

[arctic plank]

.close

[neon iron]

Ok

[topaz sinew]

Channel closed

Closed by @arctic plank

Use .reopen if this was a mistake.

[neon iron]

Nah

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[neon iron]

Butler

[arctic plank]

can u not

[empty sail]

Are you trolling?

Because stop

[arctic plank]

am i allowed to ping a mod

[neon iron]

No that was an accident

Calm ur tits

.close

[topaz sinew]

Channel closed

Closed by @split kestrel

Use .reopen if this was a mistake.

[empty sail]

Fyi, don't ping specific mods

[arctic plank]

k

[empty sail]

That's why the mod ping exists

[neon iron]

Yeah listen to the police

[arctic plank]

stop picking fights

[neon iron]

hop off

[empty sail]

<@&268886789983436800> Can you deal with this user? Being rude to others and seems very trollish

[arctic plank]

.close

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fading cypress]

Can someone please explain this limit law, I don't understand what it means

[sudden parcel]

simply put x equal to a

this law literally means to limit the observation of a function to the point 'a'

[fading cypress]

could you give an example?

[sudden parcel]

let's say, we take the limit of a function: f(x)=sin(x)/x

at 'x' = 0

that basically implies that we are observing what the function returns when the value of x becomes 0

[keen venture]

All continuous functions do this.
Like, the limit of 2x
as x approaches 3
is 2(3)

[fading cypress]

ohhh i get it

thank you both!

[sudden parcel]

@fading cypress if you are done, close this channel

type .close

[fading cypress]

.close

[topaz sinew]

Channel closed

Closed by @fading cypress

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[split solstice]

Hi I have a question about discrete mathematics

[vernal vale]

what have you tried?

[split solstice]

I have tried like finding the pattern with it. Too see if it would be true for every like example but I dont really know how to "prove" it

or is like all the variatons the proof or is there actually a physical format proof that I need to show

Im pretty sure its true for every combination of x y z but idk how to prove it unless I should list out every possibility

[fluid phoenix]

I've never done something like this before but I think that should be a good enough proof right?

how many cases are there though

[worldly tendon]

y and z are interchangeable so assume without loss of generality that y < z
reduces cases to check by 1/2

[split solstice]

I think there are 8 cases

[worldly tendon]

meaning you only need to check x < y < z, y < x < z, and y < z < x

there are 3 cases

[split solstice]

Why only 3

[worldly tendon]

i just said why

[split solstice]

oh sorry missed that

[worldly tendon]

´

[split solstice]

Oh ok I see what ur saying

so do you think just listing out those variations should suffice

thats what I would assume as well but just double checking

.close

[topaz sinew]

Channel closed

Closed by @split solstice

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frail lion]

yo

[wheat grove]

test?

[frail lion]

no

past papers

im doing them for my exam tommorow

[wheat grove]

perimeter is the outer boundary so

[worthy storm]

maybe the simplest way is to recognize that there's a related rectangle with the same perimeter

[frail lion]

i divided the shape

into two part

one which is a rectangle

[wheat grove]

then you just need to find two left sides (which are the differences of two sides)

[frail lion]

isnt the other shape a

square

[worthy storm]

"not drawn to scale"

just extend the right side so that instead of turning left where it does, it turns left at the bottom of the figure

you get a rectangle with sides 5x+4 and 3x

with the same perimeter

the x+1 and 2x are irrelevant

weird problem imo

[restive inlet]

the x+1 and 2x are irrelevant
this is only part i)
supposedly they'd be useful in later parts when the area is requested

[worthy storm]

fair enough, then just consider my observation a short cut for part i 😄

amusing and somewhat related:

[topaz sinew]

@frail lion Has your question been resolved?

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[neon iron]

so for this question i alreayd got the answer for it but i used trial and error, i was wondering if there is a formula for this type of question or can i only get it out of trial and error.

[vernal vale]

hmm

[neon iron]

How I got it was by 150/10 = 15

[fast sentinel]

the question alone has multiple solutions

[neon iron]

To make it easier

[fast sentinel]

are there any other requirements

[soft copper]

Is anybody here an expert in statistics?

[neon iron]

What do you mean?

[fast sentinel]

this channel is claimed, go to #help-3 or #help-2 in the available section

[fast sentinel]

like other requirements for the solution or something

[neon iron]

Well I’m not really good at math so I don’t know

[neon iron]

Do you mean do I have to solve it in a specific way?

[fast sentinel]

no like other attributes that would limit the solution

im working with a language barrier here so sorry if i dont make any sense

[neon iron]

I don’t understand

[fast sentinel]

ok its fine

[neon iron]

Sry

I’m pretty sure what you’re saying makes sense but I’m just stupid and don’t understand it

[fast sentinel]

so since each piece we cut would be related (each piece would be twice as long as the previous one) it would be helpful to possibly write each pieces length as a term of a variable

so lets assume that the shortest pieces length is x
can we work out how long the next piece would be

[neon iron]

Would it be 2x?

[fast sentinel]

yes

and how long would the next piece be

[neon iron]

Uh

[fast sentinel]

the piece after the one with length 2x

[neon iron]

2(2x)?

[fast sentinel]

yes

and what would be the one after that

[neon iron]

2•(2 x 2x)

[fast sentinel]

so 2*2*2*x?

[neon iron]

No

[fast sentinel]

you mean 2*2x*2x?

[neon iron]

2 x (2x2x)

Wait

I did it wrong

[neon iron]

Is that it?

[fast sentinel]

no think again

[neon iron]

K

[neon iron]

I’m still thinking

🤔

[fast sentinel]

if the next pieces length is double of the current one (which is 2(2x)) what would be its length

[neon iron]

Wouldn’t it be 2 x (2(2x))

Cause it’s double it’s length

[fast sentinel]

yes

assuming you mean 2 * (2(2x))

[neon iron]

Yup

That was what I was saying the whole time

[fast sentinel]

oh

so can you see a pattern

[neon iron]

Yup

[fast sentinel]

so the pieces length would be x, 2x, 2²x, 2³x, ... right

[neon iron]

Do I keep going?

[fast sentinel]

no lets see what we have right now

[fast sentinel]

which is x, 2x, 4x, 8x, ...

[neon iron]

Yea

Wait

Wtf

I didn’t see that the whole time

Mb

[fast sentinel]

now the problem here is that the question doesnt tell us how many pieces there are

[neon iron]

Yup

It just tells us it equals to 150

[fast sentinel]

which we will see why later

yeah

so if we were to assume the wire is cut into 4 pieces what would be x

[neon iron]

15

[fast sentinel]

think again

[neon iron]

X+2x+4x+8x=

[fast sentinel]

yes

[neon iron]

Oh

Wouldn’t it be 15x

?????

[fast sentinel]

indeed

[neon iron]

Wut

[fast sentinel]

and what is 15x

[neon iron]

Wdym

[fast sentinel]

right here what youve done is add the lengths of all the 4 pieces right

[neon iron]

Yup

[fast sentinel]

the answer we get here is still in terms of x

[neon iron]

So it’s the total length or 4 pieces

OfI

Of*

[fast sentinel]

yes

so the total length of the wire is the length of the 4 pieces combined

[fast sentinel]

but does the question give us a constant value of the total length of the wire

[neon iron]

How would u know that tho

Is it because we got 15?

15x

[fast sentinel]

because the wire is cut into 4 pieces

[neon iron]

I don’t understand

[fast sentinel]

right now were assuming the wire is only cut into 4 pieces

[neon iron]

I don’t think they told us the max would be 4 pieces

[neon iron]

Ohhhh

Yeah

[fast sentinel]

?

[neon iron]

What do you mean by that

[fast sentinel]

see it doesnt and we'll see why thats a problem later; for now were just gonna assume its cut into 4 pieces

[fast sentinel]

what does the question tell you about the length of the wire

that we got in terms of x as 15x

[neon iron]

It’s Double the amount

Of the first piece

[fast sentinel]

ok lets summarize the information that the question gave us first

[neon iron]

K

[neon iron]

You want me to do it?

[fast sentinel]

does it tell anything about the length of the wire

or any constant value

[neon iron]

Yup

[fast sentinel]

what is it

[neon iron]

They told us

That the wire is 150 long

[fast sentinel]

true

[neon iron]

And that the smallest piece/ first piece is over 9m long

[fast sentinel]

so what did we get for the length of the wire in terms of x a while ago

[neon iron]

15x

[fast sentinel]

so if the question tells us that the wire is 150 long

and we get that the wire is 15x long

can we form an equation

to solve for x

[neon iron]

15x=150?

[fast sentinel]

yes

and what would be x

[neon iron]

10

Oops

[fast sentinel]

so now lets check our answers

so the four pieces length would be x, 2x, 4x and 8x

which would be 10, 20, 40 and 80

[neon iron]

Yup

[fast sentinel]

which adds up to 150

[neon iron]

Yes

[fast sentinel]

now this is the problem

the question doesnt tell us how many pieces the wire is cut into

so lets look at it again

but this time assume that its cut into 2 pieces

only

[neon iron]

K

Then the answer would be 75

[fast sentinel]

chill out for a second

what would be the length of the 2 pieces in terms of x

when x is the length of the smallest piece

[neon iron]

Wut

Oh

[fast sentinel]

and then you do the same; add those together to get the length of the wire in terms of x then solve for x

what do you get

[neon iron]

X+2x?

[fast sentinel]

yes

[neon iron]

3x

3x=150

X=50

[fast sentinel]

correct

[neon iron]

Yup

[fast sentinel]

and if we check our answers; 50, 100
50+100=150

[neon iron]

Yea

[fast sentinel]

this is why the question has multiple solutions

[neon iron]

OHHHHH

[fast sentinel]

because both the solutions we found still satisfy the question

because theres no extra condition that limits it enough

[neon iron]

What the heck

[fast sentinel]

so yeah

[neon iron]

Wtf

[fast sentinel]

thats about it

[neon iron]

So basically the question is still trial and error?

[fast sentinel]

no

[neon iron]

Because there’s no exact formula for it

[neon iron]

Wut

[fast sentinel]

the method i presented is one apparent way of doing it

that doesnt involve trial and error

the problem here is the question doesnt have enough conditions to only have 1 answer

[neon iron]

But how did u come up with with cutting the thing into 2 pieces

Or 4

[neon iron]

Yea

[fast sentinel]

because the question didnt tell us how many pieces its cut into

i was demonstrating why thats a problem

[neon iron]

Oh

[fast sentinel]

because normally questions would only have 1 solution

[neon iron]

Yea

[fast sentinel]

and it would have to give us conditions that could only lead to 1 solution

but this problem doesnt have that

so yeah thats about it

[neon iron]

Ohhhhhh

Thanks alot for your time

[fast sentinel]

np

[neon iron]

Imma write this down

Then close

Or should I close first

[fast sentinel]

but if im going off what they want here they probably want the solution where its cut into 4 pieces because its "elegant" or something if thats the right word (integer sides, not too simple like the 2 pieces case, also satisifies that the smallest piece is more than 9 m long)

[fast sentinel]

you can close

[neon iron]

Thanks a lot😄

.close

[topaz sinew]

Channel closed

Closed by @mortal saffron

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[waxen storm]

Why are two diff approach giving me diff answers?

[abstract wadi]

Where is the second approach?

You mean the one you have ❌?

@waxen storm

[waxen storm]

Yes

[abstract wadi]

It's wrong.

$(\log_5{x})^2 \neq \log_5{x^2}$

[thorny flame]

What the hell am I doing here?

[abstract wadi]

What you did would be correct if you had $\log_5{x^2}$

[thorny flame]

What the hell am I doing here?

[waxen storm]

Ah ive got my mistake xd

Thanks

.close

[topaz sinew]

Channel closed

Closed by @waxen storm

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[acoustic wyvern]

hihi! could i please get help with the second question?

[acoustic wyvern]

i dont really understand how to get the perpendicular height of the triangle

i know that AB is 5 root 2 from the distance formula

[narrow torrent]

can you find the distance AP

[acoustic wyvern]

uhh root (p^4 -17p^2 -6p +90)

[narrow torrent]

i'll assume that's correct

now can you find the distance BP

[acoustic wyvern]

in the solutions, theres a thing like this

but i dont really understand what its saying-

[acoustic wyvern]

but how do you know that the triangle is right angled tho?

[narrow torrent]

i never made that assumption

[acoustic wyvern]

how do i find BP if its not right angled?

[narrow torrent]

just the distance formula

[acoustic wyvern]

but i dont know what P is and i only know BP and AP

[narrow torrent]

you do know what P is

(p, p^2)

[acoustic wyvern]

aa okieokie

root (p^4 -7p^2+4p+20)

[narrow torrent]

now this is going to get a bit messy but it will work

let k be the semiperimeter of this triangle, which is one half the sum of all the sides

$A = \sqrt{k(k-AB)(k-BP)(k-AP)}$

[thorny flame]

EndTimes

[narrow torrent]

Heron's formula, just to save us from having to mess with all the trig

[acoustic wyvern]

aa okok thank you

.close

[topaz sinew]

Channel closed

Closed by @acoustic wyvern

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[analog osprey]

how do i solve this

[olive plume]

The idea of (1,180) is not correct

[analog osprey]

they said a single period

imma write this on my paper

[analog osprey]

how do i write it?

[olive plume]

Why do you think that when x is 1, y will be 180?

[analog osprey]

Cause its a single period

[olive plume]

No

180 is the number of pages initially he has to read

[analog osprey]

yep he has read it

[olive plume]

Initially here means when time is 0 because he hasnt begun to read it

SO it shoud be (0,180)

[analog osprey]

hmm

i dont get it

can u explain it in other words?

[analog osprey]

how do u know that its initial?

[olive plume]

When he just started to read the pages left is 180

So t must be 0

If the pages left is not 180, then he must have started to read some time earlier

So t cannot be 0

[analog osprey]

oh the word left

wait i dont understand

the sentence said Conrad read a 180 page book cover to cover in a single session

it didnt said left

[olive plume]

But the question mentioned he took 6 hours to read 180 pages

So when he just started to read, at t = 0, the pages left must be 180

[analog osprey]

that means he already read it

[analog osprey]

oh ok

now?

[analog osprey]

,rotate

[analog osprey]

so theres a y intercept

[olive plume]

yes

[analog osprey]

so after 6 hours he read 180 books

[olive plume]

180 pages not books

[analog osprey]

so its 6,0

after 6 hours. 0 pages left to read

[olive plume]

yes

yes

[analog osprey]

x and y int

and no slope?

how do i identify if theres a slope

[olive plume]

slope is the gradient

From the question the gradient is not given

[analog osprey]

how do i know if theres a gradient?

delta y/delta x?

[olive plume]

Yes

so in this question will be (180-0)/(0-6)

= - 30

but since -30 is not stated in the question, so the slope is not given

[analog osprey]

how did u find that slope

give me a sec ill see if i can find the slope

[analog osprey]

i got 30 instead of -30

i think -30 and 30 is the same for the slope

right?

[olive plume]

this

[olive plume]

not right

(180-0)/(0-6)

[analog osprey]

thats right

oh -6

but -30 and 30 for the slope is same tho

think about it

1/30 1/-30

[analog osprey]

its (0,180) not (180,0)

i think ur confused

[waxen storm]

Slope is -30 only

[olive plume]

Yes, it is (0, 180)

Slope is (y2-y1)/(x2-x1)

x2 is 0 y2 is 180

x1 is 6 y1 is 0

(0, 180) and (6, 0)

[waxen storm]

Slope wud have been 30 if your y was no. of pages read

[analog osprey]

its the same as 30

[waxen storm]

How is it same, graph only changes

[analog osprey]

wait wait wait

30 represents the y right?

every x it moves 30 y

[waxen storm]

In the question given its moving -30 y

[analog osprey]

how

i dont get how its negative

[waxen storm]

Draw the graph

[analog osprey]

ok i see now

[topaz sinew]

@analog osprey Has your question been resolved?

Channel closed

Closed by @analog osprey

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cold sigil]

can someone helpp

15000 is the principle , 4.5 or 0.045 = interest rate , number of periods the interest compounded per year = 1

i supposed we need to use this formula right? mv = p ( 1 + r/n ) nt

[topaz sinew]

@cold sigil Has your question been resolved?

[summer dragon]

do you need help with the formula or have you already tried this question?

[cold sigil]

no i dont know how to do it and which formulae to use

[summer dragon]

where it says per annum I assume it's asking for compounding interest

[cold sigil]

yes

[summer dragon]

the compounding interest formula is A=P(1+r/n)^nt

P is the principle amount, r is the rate (0.045) n is the number of times it compounds in a year and t being the number of years

so we could solve this by plugging the values in A=15,000(1+0.045/2)^2

[cold sigil]

let me try

the question said once every 6 months

[summer dragon]

oh yeah I was solving a

do you need help with b?

[cold sigil]

wait isnt it 0.045/1

hold on

OH YEAH THATS RIGHT

thats right

[summer dragon]

it was 0.045/1?

[cold sigil]

no no

[summer dragon]

oh ok do you need help with question B as well? :]

[cold sigil]

sure

[summer dragon]

all you have to do is use the same formula, but change n to 6 since it compounds every 2 months and 2/12=6

[cold sigil]

so i calculated (1+0.045/2)

i got 1.0225

do i have to take all the numbers of just two numbers after the decimal point?

[summer dragon]

yea

I would try to calculate it all together because you need all the digits and then you round after

[cold sigil]

i got it

thank you so much for helping

:))

[topaz sinew]

@cold sigil Has your question been resolved?

Channel closed

Closed by @cold sigil

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[unkempt anvil]

Anyone tell me (h) and ( i)

[topaz sinew]

@unkempt anvil Has your question been resolved?

[topaz sinew]

@unkempt anvil Has your question been resolved?

[topaz sinew]

@unkempt anvil Has your question been resolved?

Channel closed

Closed by @unkempt anvil

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[flint moat]

I have a 3x3 covariance matrix that describes how xyz values correlate. How can i reconstruct xyz values from the covariance matrix

[flint moat]

scale does not matter.

It should be doable

[topaz sinew]

@flint moat Has your question been resolved?

[topaz sinew]

@flint moat Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[marsh mortar]

let u =1-x

[topaz sinew]

Channel closed

Closed by @sturdy iris

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[topaz lynx]

how to solve

[wide berry]

use exponential definitions of sinh and cosh

[topaz lynx]

What went wrong here?

all good

.close

[topaz sinew]

Channel closed

Closed by @topaz lynx

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[neon iron]

$\int e^{e^x} dx$

[thorny flame]

Gilgamesh

[neon iron]

Can someone help me?

Thats my solution, but at the end we see that we divide by 0

[mellow venture]

u forgot

+C

and you can pull of the n=0 term from the sum before you take the integral , the n=0 term is just 1, so the integral becomes x + the sum from n=1

[topaz sinew]

@neon iron Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[velvet notch]

how does this make any sense?

[velvet notch]

i cant understand why the initial velocity cant be expressed as itself

[tiny wolf]

,w 29 yards to feet

[thorny flame]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Migillope#7644

[velvet notch]

why must it be expressed as something else

oh

[mild oasis]

This is when living with imperial system is like living on hard mode

[tiny wolf]

Supposedly they expect you to use acceleration due to gravity in terms of ft/s^2

(Which I have literally never seen)

But in order to use this measurement, you need units to agree

So velocity needs to be in ft/s

[velvet notch]

ok thx

.close

[topaz sinew]

Channel closed

Closed by @velvet notch

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bold raptor]

Help with 29th question please

[bitter hemlock]

Just add the fractions together

Common denominator

[empty sail]

You realize it gives you the answer and explanations, right?

[bold raptor]

Wouldn't that be cheating

If I take a look

[empty sail]

No

If you're unsure, you can use it to assist you

[bold raptor]

Hmmmm

Alright

[topaz sinew]

@bold raptor Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[grizzled badge]

reviewing riemann sums and im not understanding why they're multiply by 2.5 and 4 and stuff

[grizzled badge]

like what i would do for the right riemann sum is f(1)(1-0) + f(2)(2-1) + f(2.5)(2.5-2) + f(4)(4-2.5)

finding the areas of these rectangles, right?

which is just base*height, with height being f(x) and base being the (b-a) stuff

so where does that other term they're multiplying by come from?

here's the actual question if you want it

[topaz sinew]

@grizzled badge Has your question been resolved?

[topaz sinew]

@grizzled badge Has your question been resolved?

[cosmic salmon]

note that it is the integral of rf(r), not just f(r)

the extra term comes from the value of r

[grizzled badge]

ohhhhh

so the riemann sum was fine, but it was the question

ty

.close

[topaz sinew]

Channel closed

Closed by @grizzled badge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cosmic salmon]

@grizzled badge ur good, just make sure to read everything carefully

[cosmic salmon]

good luck on the exam!

.close

[topaz sinew]

Channel closed

Closed by @cosmic salmon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[distant rapids]

How to write this out and solve it

[mellow venture]

so they have same area right

do you have know area formula for rectangles?

[topaz sinew]

@distant rapids Has your question been resolved?

[distant rapids]

Length X width?

Ayo?

.close

[topaz sinew]

Channel closed

Closed by @distant rapids

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fathom trellis]

so basically my question is this

[fathom trellis]

and i figured out this

[topaz sinew]

@fathom trellis Has your question been resolved?

[fathom trellis]

.close

[topaz sinew]

Channel closed

Closed by @fathom trellis

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tiny ginkgo]

so an equation for the tangent line towards the end of the problem would be y-y1 = m(x1-x)

just really not sure how to set this up

or why im given f(x)

I know that f(x)^x is also xln(x) I believe

this may or may not be some form of logarithmic differentiation idk

<@&286206848099549185>

[knotty ledge]

Why do you believe this to be true

[tiny ginkgo]

wait i forgot f(x) is just y

but there has to be natural log somewhere right?

so y^x

should be xln(y) no?

[bitter hemlock]

well you know what the point is right? just plug in 5 into G(x)

[tiny ginkgo]

so y = y^x then

[bitter hemlock]

G(5) = e^15 thats why you are given f(5) = e^3

have you trying getting a derivative of G now to find the slope?

[tiny ginkgo]

not yet no i am not sure where to start

would it be something like derivative of e^-12^x

why does G(5) = e^15?

[bitter hemlock]

f(5) = e^3 right?

[tiny ginkgo]

yes

[bitter hemlock]

and G(5) = f(5)^5, its how G is defined

(e^3)^5 = e^15

[tiny ginkgo]

and 5 comes from the x=5

[bitter hemlock]

ya

[tiny ginkgo]

okay thats established i understand that

okay let me check my notes for tangent line

[bitter hemlock]

im trying to figure out how to differentiate that now, its tricky since x is both in the base and exponent, so you can't use either power rule or exponent rule by themselves

since those only work if the exponent or base respectively are constant

[tiny ginkgo]

hmmmm maybe its asking for dy/dx?

[bitter hemlock]

yeah we need to get G'(5) thats the slope of the tangent line

[tiny ginkgo]

okay let me attempt that

[bitter hemlock]

remind me how can we rewrite f(x)^x so that its base e instead? multiply by some sort of logs but apparently ive forgotten how logs work : )

[tiny ginkgo]

ln(a)a^x ???

a^x = ln(a)a^x

e^x = e^x

if we used the power rule instead itd be 15e^14

but i dont think thats allowed given "e"

[bitter hemlock]

is there a typo here? you have a^x on both sides, e^x on the right?

[tiny ginkgo]

hold on

i think we need to multiply both sides by ln

because y=g(x)

so 5y*ln=xln(e^15)?

[bitter hemlock]

ok i think heres how you need to think of it

[tiny ginkgo]

because im assuming this is logarithmic differentiation

[bitter hemlock]

using $G(x)=f(x)^x$ take ln of both sides

[thorny flame]

Sooshon

[tiny ginkgo]

ahhhh thats probably right

[bitter hemlock]

then $\ln G(x) = x \ln(f(x))$

[thorny flame]

Sooshon

[bitter hemlock]

now you should be able to do some implicit differentiation

[tiny ginkgo]

that has to be it

[bitter hemlock]

and get G'(x) in terms of f'(x) and some other stuff you can find

[tiny ginkgo]

okay i will attempt it

[bitter hemlock]

product rule on the right etc

[tiny ginkgo]

given x=5

so would we just say its 5y? or just 5

[bitter hemlock]

5y?

[tiny ginkgo]

because g(5)

[bitter hemlock]

say what is 5y?

[tiny ginkgo]

or just dont think of constants for now

g(5) = 5y? or just 5

can we agree on the left side of the equation

[bitter hemlock]

im confused about what youre asking, sorry

[tiny ginkgo]

that it should be

1/g(x) * dg(x)/dx

[bitter hemlock]

yep

[tiny ginkgo]

okay great let me attempt the right side

given f*g' + f'*g

okay right side should be x * 1/f(x) + (ln(f(x))*1

[bitter hemlock]

i think you forgot to chain rule the first term

[tiny ginkgo]

its not just x?

[bitter hemlock]

i get $x \frac{f'(x)}{f(x)} + \ln(f(x))$

[thorny flame]

Sooshon

[tiny ginkgo]

so ln(f(x)) is not 1/f(x)?

[bitter hemlock]

and chain rule the inside of the ln

so multply by f'(x)

[tiny ginkgo]

because ln is multiplied by f(x) ahhh

oh why prime f'(x) though

because dy/dx?

[bitter hemlock]

$\frac{d}{dx} (\ln f(x)) = \frac{1}{f(x)} f'(x)$

[thorny flame]

Sooshon

[tiny ginkgo]

hmmm

[bitter hemlock]

just basic chain rule

you multiply by the derivative of the inside

the inside is f(x), its derivative is f'

[tiny ginkgo]

ahhh very true

so ill type equation we have now

1/g(x) * dg(x)/dx = x * f'(x)/f(x)+(ln(f(x))) * 1

would you say x * f'(x)/f(x) is just (xf'(x))/f(x)

and now that we have this format

its safe to multiply by G(x) on both sides

[bitter hemlock]

yes

[tiny ginkgo]

to isolate dG(x)/dx

[bitter hemlock]

im going to write this out in latex in outside program since its kind of a confusing one without math notation

ill put it here after and see if you agree with my steps

[tiny ginkgo]

yes okay sounds great

[bitter hemlock]

something like this?

bigger

[tiny ginkgo]

yes

but dont we multiply G(x) on both sides

we'd be getting f(x)^x on the right

[bitter hemlock]

multiply by G(x) on both sides at what step?

oh you mean by the e^15 yes i did it at the end there

[tiny ginkgo]

1/g(x) * dg(x)/dx = xf'(x)/f(x)+(ln(f(x)))

we multiply by g(x) on both sides

[bitter hemlock]

yes, i multip-ied through by g(5) = e^15 we got earlier right at the last step

[tiny ginkgo]

so it'd look like = G(x) * ((xf'(x)/f(x))+(ln(f(x))))

[bitter hemlock]

yeah, whenever you want to do that, i started plugging in values already before that

[tiny ginkgo]

ahhhhh i see okay

and the three came from ln(e^3)?

[bitter hemlock]

so point slope form would be i guess: $y - e^{15} = (5+3e^{15})(x - 5)$

[thorny flame]

Sooshon

[bitter hemlock]

yes, if i didnt make a mistake

[tiny ginkgo]

no you're correct

[bitter hemlock]

which isnt entirely unlikely, this problem doesnt want to simplify too nicely : )

[tiny ginkgo]

yeah my teacher will except exact answers and not too simplified

you multiplied e^15 on both sides

oh wait

how'd you get the right side of the equation

[bitter hemlock]

at which step

(they are numbered, tell me number of step)

[tiny ginkgo]

(5+3e^15)

step 7

[bitter hemlock]

just plugging in x = 5, f(5), f'(5) etc

[tiny ginkgo]

oh i guess after that then

[tiny ginkgo]

at here how'd you get here

[bitter hemlock]

e^-12 / e^3 = e^-15

then when both sides get multiplied by e^15 that just becomes 1

[tiny ginkgo]

it would be e^15 * G'(5) then on the left ?

[bitter hemlock]

we had a e^15 in the denominator on the left right? so the step involves multiplying both sides by e^15 to cancel that out

[tiny ginkgo]

yes

[bitter hemlock]

so left just becomes G'(5)

and each of the terms on the right get multiplied by e^15

[tiny ginkgo]

ahhhh canceling

yes

so why is it y-e^15 now?

[bitter hemlock]

wheres that?

oh

well we now the slope now right

[tiny ginkgo]

lets just go back a quick sec

[tiny ginkgo]

our equation is now G'(5) = 5e^-12/e^3 + 3

[bitter hemlock]

umm

no

its

[tiny ginkgo]

g(x)=e^15 yes

[bitter hemlock]

now its just algebra, you know the point (5, e^15) and you know the slope and have to write the line equation

I've got to go eat so good luck : )

[tiny ginkgo]

okay thanks

[topaz sinew]

Channel closed

Closed due to the original message being deleted

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[worldly tendon]

divide numerator and denominator by x

x = sqrt(x^2) also

so 5x -> 5
while sqrt(x^2 + 3x) -> sqrt(1 + 3/x)
and sqrt(x^2 - 2x) -> sqrt(1 - 2/x)

[knotty fulcrum]

makes sense

[worldly tendon]

you can do this because dividing by x/x is the same as dividing by 1

so equality is maintained because x/1 = x

[knotty fulcrum]

ty

.close

[topaz sinew]

Channel closed

Closed by @knotty fulcrum

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dawn cloud]

<@&286206848099549185> pls 👉 👈

[topaz sinew]

@dawn cloud Has your question been resolved?

[dawn cloud]

<@&286206848099549185> hope this is allowed

[dawn cloud]

<@&286206848099549185> tell me if / what part of the question is hard to comprehend

[topaz sinew]

@dawn cloud Has your question been resolved?

[novel token]

no youre right

[topaz sinew]

@dawn cloud Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bold cloud]

https://media.discordapp.net/attachments/533787328141983755/970508521072381972/unknown.png?width=1218&height=671

[bold cloud]

I dont understand hint b and onwards with this series

[topaz sinew]

@bold cloud Has your question been resolved?

[topaz sinew]

@bold cloud Has your question been resolved?

[bold cloud]

<@&286206848099549185>

[novel token]

you might wanna take this to #advanced-analysis

[bold cloud]

sure

[novel token]

.close

[topaz sinew]

Channel closed

Closed by @novel token

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[uncut agate]

Hi, I don't understand what happens with the log(x+1) :c
why can I write log(x+1) like log(1+1/x) + log(x)?

[restive inlet]

prod to sum law for logs

[uncut agate]

Please, can you explain me that?

[restive inlet]

log(ab) = log(a)+log(b)

[uncut agate]

Aah I get it! thanks you! ❤️

.close

[topaz sinew]

Channel closed

Closed by @uncut agate

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cinder rapids]

not sure if its b or c

[cinder rapids]

im leaning towards b tho

because "enforce" might be a loaded word

[drifting swift]

this doesnt sound like a math question

however

what is your defn of an 'unbiased question'?

[cinder rapids]

its from a stats class so

ig unbiased question meaning it doesnt lead to biased answers

biased data* is probably better

eh i'll just sitck with that

.close

[topaz sinew]

Channel closed

Closed by @cinder rapids

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[warm finch]

I got a good idea for this one

I would first multiply both sides by cos to get cos^2 on the left and just 1-sin on the right

@lofty elm

[lofty elm]

hmm

i see im gonna try that

@warm finch could you write out the formula

equation*

[warm finch]

Idk how to use the bot but I’ll try

[lofty elm]

kk thank u

[warm finch]

$\frac{cos(\Theta)^{2}}{1 + sin(\Theta)} = 1 - sin(\Theta)$

[thorny flame]

VictorLee

[warm finch]

It would look like this

[lofty elm]

Thank you so much

[warm finch]

Then the trick i had in mind is to multiply the 1+sin on both sides

And then the magic happens

[topaz sinew]

@lofty elm Has your question been resolved?

Channel closed

Closed by @lofty elm

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fathom girder]

Pls help

[bitter hemlock]

With what?

[fathom girder]

Math

pls

it’s physic

im french

it’s like

i need to calculate the light of speed

Instead of it being in kilometer

It need to be in meter

in a scientific notation

i think it’s

300 000 x 1000

=

300 000 000

but in scientific notation

ru here

[fathom girder]

so

It’s

3 x 10’8

if am right

okay thanks

how do I close

.clode

.close

[topaz sinew]

Channel closed

Closed by @fathom girder

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[topaz sinew]

@shut obsidian Has your question been resolved?

Channel closed

Closed due to the original message being deleted

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[livid pelican]

I've been given this

[livid pelican]

I would like to do this