help-26

[safe lichen]

label that as a point

then

[restive inlet]

you mislabelled the diagram and miswrote a variable in the question

[safe lichen]

the diagram is poorly labelled

Yeah

[long trellis]

I mean yeah this is just an example

[long trellis]

Then what to do

[restive inlet]

using the midpoint formula here isn't optimal

consider that the points C,D split the line segment AD into 3 equal parts

and consider the change in the x and y coordinates

(those would similarly be split into 3 equal parts)

[long trellis]

Yes and?

[restive inlet]

have a think about it

[long trellis]

So B is (2,4) and C is (3,6)?

[restive inlet]

yes

[long trellis]

Oh actually I was looking for the solution with midpoint

Idk why but my teacher said hint is b is midpoint of ac and c is mindpoint of bd

[restive inlet]

there's a way to set it up like that but its a lot more tedious

[long trellis]

Oh well it’s a homework so I have to do it even it’s long

[restive inlet]

you could represent the point B as $(x_B,y_B)$, point C as $(x_C,y_C)$

[thorny flame]

ℝamonov

[restive inlet]

apply the midpoint formula using those variables and solve a system of equations

[long trellis]

Okay let me see

And?

[restive inlet]

solving the system will give you the x and y coordinates of B and C and hence your points

were you able to apply the midpoint formula (using the variables I stated) to get an equation(s) that represents

B is midpoint of AC

[long trellis]

Emm can you calculate in a book? I just started to learn midpoint -,-

[restive inlet]

someone posted the midpoint formula above

the x coordinate of the midpoint of A and C is the average of the x-coordinates of A and C

same idea for the rest

[long trellis]

Ahh I see

[long trellis]

Got the way thanks

.close

[topaz sinew]

Channel closed

Closed by @long trellis

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frail girder]

EN: Let (an) be a monotone sequence in an ordered field K, and (ak(n)) a subsequence that Cauchy sequence is.
Show that then (an) is also a Cauchy sequence.

DE: Sei (an) eine monotone Folge in einem angeordneten K¨orper K, und (ak(n)) eine Teilfolge, die Cauchyfolge ist.
Zeigen Sie, dass dann auch (an) eine Cauchyfolge ist.

[topaz sinew]

@frail girder Has your question been resolved?

[topaz sinew]

@frail girder Has your question been resolved?

[frail girder]

<@&286206848099549185>

[topaz sinew]

@frail girder Has your question been resolved?

[frail girder]

<@&286206848099549185>

[hollow obsidian]

cauchy sequence has a converging tail, so as its subsequence

[topaz sinew]

@frail girder Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[uncut agate]

Hi, I don't know how to proof the following statement :(
Use strong induction. Define the sequence $a_{n}$ by $a_{1} = 1$, $a_{2} = 2$, $a_{3} = 3$, $a_{n+3} = a_{n} + a_{n+1} + a_{n+2}$. Prove that $a_{n} \leq 2^{n-1}$

[thorny flame]

MαяιA

[hollow bone]

what is strong induction to you?

[hollow bone]

right so what would be S in your case?

[uncut agate]

Eeh S will be the set that holds the sequence?

[hollow bone]

in general S is the set of the numbers that have a certain property

and the goal is to prove that S =N

so that the property is true for all integers in N

so here S = {n | n in N and an=<2^n-1}

[uncut agate]

Okay okay

[hollow bone]

so lets try to apply this to S

is 1 in S?

[uncut agate]

Yes, because, if n=1 then $a_1= 1$ and $2^{1-1} = 2^0$ then $1 \leq 1$

[hollow bone]

yeah

so now lets do (2)

let k be in N

such that

[thorny flame]

MαяιA

[hollow bone]

for all i <=k

i is in S

we must prove that k+1 is in S

so that a_k+1<=2^k

now is time to use what we now about the (a_n) sequence

[uncut agate]

Okay, I will try

The statement gives me $a_{n+3} = a_{n} + a_{n+1} + a_{n+2}$ is correct to say that $a_{n} = a_{n-3} + a_{n-2} + a_{n-1}$?

[thorny flame]

MαяιA

[hollow bone]

its the same for values of n such that it makes sense yeah

a_-1 doesnt for exemple

this is the tricky part

consider k >=4 for now

you can deal with k =2 and 3 easily by hand

like you did with k=1

[hollow bone]

so yeah for k=> 4 what you said is right

[uncut agate]

Oooh okay okay

:( I get stuck
$a_{n} = a_{n-3} + a_{n-2} + a_{n-1} + a_{n+1} \leq 2^{n-1} + a_{n+1}$

[thorny flame]

MαяιA

[uncut agate]

Eeeh $a_{n+1} \leq 2^{n-3} + 2^{n-2} + 2^{n-1}$?

[thorny flame]

MαяιA

[hollow bone]

combine those twos now

like factorize by 2^n-3

[uncut agate]

$2^{n-3} + 2^{n-2} + 2^{n-1} \leq 2^{n-3} (1 + 2^1 + 2^2)?$

[thorny flame]

MαяιA

[hollow bone]

what is 1 + 2 + 2^2?

[uncut agate]

7? eeh I tried to use common factor, but, I don't be sure if I did it well, do I use correctly the exponents law?

[hollow bone]

7 is right

so now

an+1 < 2^n-3 x 7

but 2^n = 2^n-3 * 2^3

right?

[uncut agate]

Yes

Then $2^{n-3} * 7 \leq 2^n * 2^3 * 7$ and I want to arrive to $2^n$

[thorny flame]

MαяιA

[hollow bone]

compare $2^{n-3} * 7$ and $2^n$

[thorny flame]

Benjamin

[hollow bone]

using that $2^n = 2^{n-3} * 2^3$

[thorny flame]

Benjamin

[uncut agate]

$2^{n-3} * 7 \geq 2^n$

[thorny flame]

MαяιA

[hollow bone]

what is 2^3?

[uncut agate]

Aaaah sorry sorry

I was thinking 2^3 like 6 and not like 8 sorry sorry

[hollow bone]

dont worry

[uncut agate]

Then all calculations are?:

[hollow bone]

right

try to do the whole proof properly now

[uncut agate]

yes, of course, @hollow bone you don't know how grateful I am to you, thanks thanks thanks so much <<33 💖

.close

[topaz sinew]

Channel closed

Closed by @uncut agate

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[neon iron]

What steps do I take in solving this problem?

[narrow torrent]

Are you familiar with the concept of "n equations, n variables"?

[neon iron]

It kind of depends, but in this case, sadly no

[narrow torrent]

If you have n variables, then you need n equations to uniquely determine those variables

How many variables do you have here?

[neon iron]

There's (2,14) and (5,112)? If that's what you mean? But I'm not sure if either are those are x or y

[narrow torrent]

What are you trying to solve for?

[neon iron]

The value of f(-1)

[narrow torrent]

I'll just give this to you lmao

[neon iron]

😭

[narrow torrent]

In order to find the value of f(-1), you must first find f(x)

And you find f(x) by determining the values of a and b

[empty sail]

Use that info to find the exponential function

You can find a and b, with that given info

[neon iron]

Ohhh. Hmm. But how do I find a and b with those parentheses?

[neon iron]

How do I determine the values of a and b?

[narrow torrent]

What is f(2)?

[neon iron]

I'm presuming that 2 is the x?

[narrow torrent]

You're given it lmao

f(2) is a number

[neon iron]

OH

2 and 5 are my x's

and 14 and 112 are my y's

right?

[narrow torrent]

Yes

[neon iron]

okay, now I understand where you were going at

[neon iron]

I plotted those points but it never made sense-

[narrow torrent]

Yeah

You have to solve the system

[topaz sinew]

@neon iron Has your question been resolved?

[neon iron]

So like if y= ab^x

So from 5, 112, would it be 112 = ab ^ (5)?

[narrow torrent]

Yes

[neon iron]

Okay, give me a second

[neon iron]

I got a=112/b^5

and for the other, I got

a=14/b^2

I still don't follow what's happening

[narrow torrent]

Yeah

So then

112/b^5 = 14/b^2

Lol

[neon iron]

ohhhhhh

Okay, let me do that

I got b=2

I never got to study this cause I had an AP test on the very day of the quiz ✨

Sorry for troubling you 😭

[narrow torrent]

Alright then

Can you find a now?

[neon iron]

yes!

yes I think I got it from here

Thank you!

.close

[topaz sinew]

Channel closed

Closed by @soft hazel

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[neon iron]

how did they get blue from black

[hollow bone]

csc(x) = 1/sin(x)

[neon iron]

oh ok.. thx

.close

[topaz sinew]

Channel closed

Closed by @south narwhal

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[neon iron]

Prove that tan3𝑥.tan2𝑥.tan𝑥=tan3𝑥−tan2𝑥−tan𝑥 .

[neon iron]

how do i do this

just need the starting

[hollow bone]

either you mess with trigonometry formulas or you can use calculus

if you differentiate tan3𝑥.tan2𝑥.tan𝑥 -(tan3𝑥−tan2𝑥−tan𝑥)

and find that its equal to 0

you 'll have that its a constant

and thus it will be equal to the value at 0

which is 0

[neon iron]

ok i will do that way thx

[hollow bone]

remember tan'(x) =1/cos²(x)

before you go further i think its more horrendous than actually doing it the regular way

it gets too messy

[topaz sinew]

@neon iron Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mint karma]

i have a presentation tmr, can anyone check if my equation is wrong?

[mint karma]

the answer space is where i started writing, the part above is part of the question

anyone?

[topaz sinew]

@mint karma Has your question been resolved?

[mint karma]

.close

[topaz sinew]

Channel closed

Closed by @mint karma

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[acoustic yacht]

i was hoping to get some help on this assignment for extra credit i dont know anything about exponential growth or anything

[acoustic yacht]

Ive already chosen austin, texas and the populations for the year 2000 (911000 people) and 1990 (569000 people)

i think ive got the linear model down as P(t) = 34200t + 569000

[topaz sinew]

@acoustic yacht Has your question been resolved?

[acoustic yacht]

.close

[topaz sinew]

Channel closed

Closed by @acoustic yacht

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frail girder]

.reopen

[topaz sinew]

@neon iron Has your question been resolved?

[topaz sinew]

@neon iron Has your question been resolved?

[topaz sinew]

@neon iron Has your question been resolved?

[neon iron]

<@&286206848099549185>

[topaz sinew]

@neon iron Has your question been resolved?

[azure isle]

Can you check the question again?

is the second function really 2x + 2n

[neon iron]

ye

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gritty jungle]

Is this possible? Gcd(a,b) = 5 and Lcm(a,b) = 13 if a and b are positive integer.

[gritty jungle]

I can't find any number

[lime zealot]

a*b = Gcd(a,b)*Lcm(a,b) = 65

[long stirrup]

it's not possible

[lime zealot]

then only have 5*13 and 1*65 , they are not meet the original conditions, so it's impossible

[gritty jungle]

Ok

Thanks

.close

[topaz sinew]

Channel closed

Closed by @gritty jungle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[topaz lynx]

whats this method here they use?

i used an alternate method which is also on the ms, but im wondering what they are doing above is.

[marsh mortar]

sum of geometric series

a=beta

r=omega

[topaz lynx]

how do they prove its 0?

[marsh mortar]

sin(2pi) = 0

cos(2pi) = 1

1-1=0

[topaz lynx]

ohhh of course

and quick other question

i put 17/12 instead of -7/12

ms does not mention alternate answers being correct

i know they are the same thing, but the question does not specify -pi to pi or anything, does it?>

so im wondering why they have put the -7/12

[marsh mortar]

i believe in a-levels, the ranges they expect is $-\pi\leq\theta< \pi$

[thorny flame]

azeem321

[topaz lynx]

oh ok, i wasn't aware. ill stick to that then, thanks

.close

[topaz sinew]

Channel closed

Closed by @topaz lynx

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[topaz lynx]

trying to understand how little working out you have to do

basically i completely did the proof again

i said

prove for n = -1

assume true for n = k

therefore, for n = k-1

blah blah

i have no clue what the mark scheme does

dont understand it at all

they have a lot less lines than me though

[topaz sinew]

@topaz lynx Has your question been resolved?

[marsh mortar]

So if $n$ is negative then we can rewrite as

[thorny flame]

azeem321

[marsh mortar]

$(\cos{\theta}+i\sin{\theta})^{-n}=\frac{1}{(\cos{\theta} +i\sin{\theta})^n}$

[thorny flame]

azeem321

[marsh mortar]

You get that?

[topaz sinew]

@topaz lynx Has your question been resolved?

[topaz lynx]

yh

[marsh mortar]

Then because of our proof in first part we can rewrite as $\frac{1}{(\cos{\theta} +i\sin{\theta})^n}=\frac{1}{\cos{n\theta}+i\sin{n\theta}}=\frac{1}{e^{in\theta}} = \cos({-n\theta})+isin({-n\theta})$

[thorny flame]

azeem321

[marsh mortar]

did u understand my explanation or nah

[topaz lynx]

sorry, i started thinking about it then got carried away thinking about something else lol

yes i get it so basically

they get rid of the negative bit

so its just n

use the thing we already proved?

[marsh mortar]

yh if we have $a^{-n} = \frac{1}{a^n}$

[thorny flame]

azeem321

[topaz lynx]

yh i get that, that makes sense

[marsh mortar]

and then you can just use the thing proven in the first part

[topaz lynx]

thanks 🙂

.close

[topaz sinew]

Channel closed

Closed by @topaz lynx

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[broken condor]

https://1drv.ms/p/s!AnniB7QmdcmNiU2j1Q-s8lwlgLoK?e=nrDYT4

[broken condor]

can someone please check these calculations

[topaz sinew]

@broken condor Has your question been resolved?

[tulip light]

is that like your entire project?

and does CBA stand for cant be arsed?

two big questions

[knotty ledge]

"class room based assessment"

[tulip light]

ah

well my interpretation was better

[broken condor]

i did it

lets go

no help needed

2 good at this game

no cap

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jade cobalt]

hello

[jade cobalt]

ive got this question

ill translate xd

the function h(x) = -F(x)+b

in the field of -pai and pai

thats f(x) xd

i need to find B

justt nvm its complicated to describe xd

,_,

.close

[topaz sinew]

Channel closed

Closed by @jade cobalt

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[restive frost]

Do I need additional information to solve this?

[knotty ledge]

,rccw

[knotty ledge]

whats the question?

[restive frost]

Make the first four terms of the sequence

[knotty ledge]

why do you think you would need additional information?

[restive frost]

Idk one of my notes says I need to be given at least 1 term to start

[knotty ledge]

you're being told what every term is right there

plugging in a value for n, gives you a term

so if you want the first four terms, just plug in the first 4 values for n

[restive frost]

Ahh so would the first term be -1/6

[knotty ledge]

yep!

[restive frost]

Aight thanks a lot

.close

[topaz sinew]

Channel closed

Closed by @restive frost

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[onyx vessel]

The 2e^3t

Is what I have no idea

What to do

The rest is fine

[mellow venture]

sub 3t

then apply general integral e^u

[onyx vessel]

Do I have to ingrate 3t ?

[steel shoal]

$\int e^{3t} dt \newline
u = 3t \newline
t = \frac{u}{3} \newline
\frac{dt}{du} = \frac13 \newline
dt = \frac13 ; du \newline
\int (\frac13 e^u) du = \frac13 e^u = \frac13 e^{3t}$

[onyx vessel]

what happens to the 2

[steel shoal]

Oops mb

[thorny flame]

Olly

[steel shoal]

Forget the 2 ever existed

[onyx vessel]

why does it become a fraction

i kinda get it but it doesnt make sense

.close

[topaz sinew]

Channel closed

Closed by @onyx vessel

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[plain sigil]

I anybody good at triangle proofs and similar stuff? I would do anything if you could help me. Ik yall have probably heard this story time and time again, but I'm failing math rn because of my bad habit of procrastinating. I did good in Math 1, but I'm currently in Math 2, with below a passing grade. However, my teacher is holding a really long redemption assignment from Friday to Tuesday, tomorrow, and if I get a 100 on it, all of my HW grades will turn into 100's, which will raise my grade considerably! I did everything that ik, but I'm still only at 63%... so please, as a student who has nobody else to turn to, could you help me complete the rest? I promise that we'll try to work through it fast, and it should, AT MOST, take 1.5 hours. Ik I won't learn much doing it this way, but I promise to study and study, so I will never fall into this situation again. 😥

[plain sigil]

please mention me or reply if you got this, I'm going to try working on it now...

[topaz sinew]

@plain sigil Has your question been resolved?

[plain sigil]

please, I will fail this class and get kicked out of the school if nobody helps... my fate is on your hands 😢

I don't mean to pity party, but I will literally do anything

I don't want my life to get permanently screwed up because of this one situation

please...

[topaz sinew]

@plain sigil Has your question been resolved?

[tall wolf]

I could teach you how to do certain problems but I will not the whole thing

[plain sigil]

oc oc

[topaz sinew]

Channel closed

Closed by @plain sigil

Use .reopen if this was a mistake.

[plain sigil]

.reopen

[topaz sinew]

✅

[topaz sinew]

@plain sigil Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed due to the original message being deleted

[neon iron]

.close

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[iron fog]

d^2y / dx^2, y=e^(3x) - sin(3x) +ln[cos(3x)]-x

[muted pond]

use wolfram alpha

[topaz sinew]

@iron fog Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fossil moss]

Is $\int$ just doing the anti derivative?

[thorny flame]

b0a

[fossil moss]

If it is how do u work that out

[topaz sinew]

@fossil moss Has your question been resolved?

[fossil moss]

<@&286206848099549185>

[marsh mortar]

whats the question

[fossil moss]

How do I calculate the integral of things

And is the integral just the anti derivative

If it is how do I work it out

[fossil moss]

<@&286206848099549185>

[marsh mortar]

we cant teach you integral calc

you gotta teach yourself that

[fossil moss]

Idk what it is tho

Is it like going from f-1(x) to f(x)

?

[marsh mortar]

yh

[steady gull]

Hey there
That's an integral (anti-derivatives) yes
There are alot of ways to solve integrals, it varies depending on what is the function you want to fond its anti derivative to

[marsh mortar]

wait

[steady gull]

No
Those are different

[fossil moss]

Ah

[steady gull]

Anti derivatives are going from f'(x) to f(x)

[fossil moss]

Is there a rule for how to solve them?

[steady gull]

General form for a polynomial is
The integral of x^n = (x^n+1)/n+1 +c

But there are many other forms

Like the integral of e^x = e^x +c

1/x becomes ln|x| +c

So like

There are alot of formulas to cover... LIKE ALOT

[fossil moss]

Why did u do that or is it just "its that, go learn it"

[steady gull]

Typically the derivative of x^n is
nx^n-1 right?

[fossil moss]

Idk xd

[steady gull]

If you want to reverse that, u divide it by (n-1+1) and add 1 to the power

[fossil moss]

What's the derivative xd

[steady gull]

My suggestion is that u learn derivatives before anto derivatives

[fossil moss]

ah okk

Can u teach me them xd? my school won't teach me it till A level

[steady gull]

It's the rate of change of a function per variable, also could be recognized as the slope of the tangent line to a curve at a given abscissa

[steady gull]

Derivatives by itself is still a huge topic
Don't get too hasty... 10th grade or 11th grade will introduce them

[fossil moss]

10th grade?

How old is that

I'm from the uk

[steady gull]

If you really want an insight
Visit youtube

[steady gull]

I was 15 at the time

Most people in 10th grade are 15/16

[fossil moss]

I can't learn it till I'm at a level then

I need to be 17

[steady gull]

Education systems differ yeah
So until then if you want to get ahead of your time, try searching for derivative lessons in khan academy

Maybe youtube

You would start of with what's called "pre calculus" lessons

But also something I would encourage is that you don't need to take a massive leap right now if your school will teach it later, even if later means a couple of years ahead

If you decide to scroll through the internet, sure do ask if you have any inquiries about specific things you didn't quite get :)

[marsh mortar]

man there are 14 year olds here who have learned degree level math

the content is all there available on youtube

[fossil moss]

Ahh

[marsh mortar]

or books

[fossil moss]

I don't understand it tyo

So

Ik integrals are anti derivatives

[marsh mortar]

khan academy

[fossil moss]

But

Idk how to calculate derivatives

[topaz sinew]

@fossil moss Has your question been resolved?

[fossil moss]

.close

[topaz sinew]

Channel closed

Closed by @fossil moss

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[boreal stone]

hello I have a question

[boreal stone]

given a bowl with 10 balls in it

3 blues

what are the chances of drawing 3 blues in a row

There are 3 situations:

1. taking one ball from a bowl at a time and returning it back in the bowl again, 3 times

2. taking 3 balls from a bowl successively (one after another) without returning

3. taking 3 balls simultaneously

I think the answer is:

1. (3/10)^3 = 81/1000
2. 3/10 * 2/9 * 1/8 = 6/720
3. 3/10 * 2/9 * 1/8 = 6/720

but i want a confirmation

[stuck tusk]

yes this is that

[boreal stone]

a friend of mine says 2 and 3 are not the same

[stuck tusk]

yes they are

[clear kindle]

In 3), you remove 3 balls as well and each pick can't be a ball you've already chosen. They're the same

[topaz sinew]

@boreal stone Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wanton magnet]

Hello,

A bus departs from town A to town B, which is 105 km away from town A, at a constant speed of V km / h. 30 minutes after the departure of the bus, the car leaves the city in the same direction and travels at a constant speed of 40 km / h. When the car reaches the bus, car turns around and moves towards the same road and at the same speed towards town A.
Find all the values ​​of bus speed V at which the car returns to town A later than the bus arrives in town B. Write the answer in intervals.

[neon iron]

this is math?

[wanton magnet]

yes

[neon iron]

so its from a to b

we got the interval

show me your work

[wanton magnet]

i don't know where to start honestly

I know the answer, but i want to know how to get it

<@&286206848099549185>

[topaz sinew]

@wanton magnet Has your question been resolved?

[wanton magnet]

Is this a good start?

[wanton magnet]

no, it's not good. I'm lost. I think that I wrote down bus good, but i don't know about the car.

[wanton magnet]

i just need help with expressing car and bus, cuz i don't really get what should it be

[topaz sinew]

@wanton magnet Has your question been resolved?

[topaz sinew]

@wanton magnet Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frozen sphinx]

How do you determine the limit of a sequence when a factorial is involved?

[frozen sphinx]

I am treating it like a geometric sequence and finding what r is? I don’t know how to approach this at all, some pointers on how to begin would be awesome :,)

[narrow torrent]

i don't think there's much of a way to do this without the asymptotic argument

factorials are really big!

[frozen sphinx]

True! Which is why I’m at a loss haha… What’s the asymptotic argument?

[narrow torrent]

exponentials are smaller than factorials!

this limit is 0

[frozen sphinx]

ohhhhh

I understand! So you have to think about the relationship between the top and bottom!

Tysm!

.close 🥰

[topaz sinew]

Channel closed

Closed by @frozen sphinx

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[upper heron]

#3

[topaz sinew]

@upper heron Has your question been resolved?

[dusk forum]

Hi, so basically you’re given the Velocity vector’s norm and you’re asked to find it’s components Vx and Vy

[topaz sinew]

@upper heron Has your question been resolved?

Channel closed

Closed by @upper heron

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[thin oak]

draw it

[topaz sinew]

@proven narwhal Has your question been resolved?

[proven narwhal]

<@&286206848099549185>

[neon iron]

what have you tried???

[proven narwhal]

i've worked out the midpoint

after that idk what to do

[neon iron]

did u draw a diagram?

Use distance formula to make 2 eqns using the info given in line 1

[proven narwhal]

nope, idk how i'd go about doing that since some coordinates are in letters

[neon iron]

^^

[proven narwhal]

what's the distance formula

[topaz sinew]

@proven narwhal Has your question been resolved?

[proven narwhal]

so i'd use this to get the distance for HJ and HK?

[neon iron]

yea

[proven narwhal]

what about the values K and J

how would you plug those into the equation

[neon iron]

form simul eqn

[topaz sinew]

@proven narwhal Has your question been resolved?

[topaz sinew]

@proven narwhal Has your question been resolved?

[sweet shard]

.close

[topaz sinew]

Channel closed

Closed by @sweet shard

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[neon iron]

hi

[neon iron]

wait idk how it works

sec

[harsh panther]

Huh

[neon iron]

mb

go 27

[neon iron]

this

nothing is drawn

accurately

or

to scale

[sweet shard]

.close

[topaz sinew]

Channel closed

Closed by @sweet shard

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[neon iron]

If I have abs(A) > 0, where A is some expression that contains unknown x and x is a real number,
then I can always solve it by saying
A = 0 then find the x in this equation and then say that the solution to my inequality is all x values except that value from equation A = 0?
If this is true, how can I prove it?

[past kayak]

|A| is always greater than or equal to 0 by definition

By just asking when |A| is greater than, but not equal to 0, you only need to eliminate the case where |A| = 0

[brave torrent]

how can I divide x^3+5x^2+7x+3?

please

hi to everyone

[past kayak]

#❓how-to-get-help

[neon iron]

@past kayak
makes sense, thanks!

.close

[topaz sinew]

Channel closed

Closed by @slow mortar

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fierce zealot]

This one doesnt have an identity right?

If I do ea = e - a + 1 = a and ae = a - e + 1 = a, so e-a+1=a-e+1 so e = a

[fierce zealot]

It seems if I only do one side, then the identity exist but I need to check both sides, so ae = a = ea right

[topaz sinew]

@fierce zealot Has your question been resolved?

[fierce zealot]

<@&286206848099549185>

[sweet shard]

Identity seems easier to check

But your proof works too

[fierce zealot]

so the conclusion is that it doesnt have an inverse?

sorry

I meant ti say identity

I guess my question is, if through algebra we got that e = a, then how come when I try to apply it, it fails?

Take any element in integer, say 3

Then by the proof, a = 3 = e

So it should be that a - e + 1 = 3

But 3-3+1 = 1

[odd pagoda]

well no until now you just used that ea=ae. that doesn't mean that ea=a

[fierce zealot]

So should this be done properly?

Either a proof or counterexample

[odd pagoda]

well we assume there exists an identity. then in particular we need ae=ea. this leads to a=e. but then using a=3 we get ea != a which is a contradiction

[fierce zealot]

ok i see

So then the assumption is false, then there doesnt exist an element such that ae=ea.

So then it doesnt have an identity is the conclusion

Is that correct?

[odd pagoda]

yes

[fierce zealot]

Thanks, sometimes i forget what im doing

.close

[topaz sinew]

Channel closed

Closed by @fierce zealot

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vivid blade]

How can I calculate every dimension? (like the 5th dimension)

[worldly folio]

wut

[vivid blade]

I want to make a game engine for the 5th dimension but I don't know how to calculate it

[worldly folio]

ughh, human brains can't visualize anything other than 3 dimensions iirc

[vivid blade]

But it is possible to calculate more than just 3 dimensions right?

[iron ledge]

what do you mean by calculate?

[worldly folio]

it's a theoretical construct

[vivid blade]

Like to create vectors for higher dimensions

You'll need to know how to calculate them into 2d vectors to make the gui visualize it

[iron ledge]

alright let me do you one better

how would you create a game engine for the 5th dimension when you cant perceive the 5th dimension

[vivid blade]

Have you watched 4d miner?

[worldly folio]

I think he means the analogue of higher dimensional spaces

[vivid blade]

Well in sort I'm just going to transform it into 3d vectors

But I don't know how to calculate them into the 3d dimension

[worldly folio]

Although I don't know how to get analogues of shapes of higher dimensions but yeah that indeed is a thing. For eg, a tesseract, 3d analogue of a 4d cube.

[vivid blade]

Well do you know a good video on youtube or smth for dimensions higher than the 3rd dimension?

[worldly folio]

it would require more than a youtube video I'm afraid

[vivid blade]

Do you know someone who could explain it?

[worldly folio]

https://www.ics.uci.edu/~eppstein/junkyard/highdim.html

[vivid blade]

.close

[topaz sinew]

Channel closed

Closed by @vivid blade

Use .reopen if this was a mistake.

[spiral vault]

yo

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[velvet notch]

where did the 21 go

[worldly tendon]

you have to add 16 to both sides

so (x^2 - 8x) turns into (x^2 - 8x + 16)

which is a perfect square: (x - 4)^2

[velvet notch]

yeah i added 16 and 36 to both sides

[worldly tendon]

so (x - 4)^2 - (y^2 + 12y) = 37

[velvet notch]

i got 73

[worldly tendon]

now we add -36

[velvet notch]

why -36

[worldly tendon]

because there’s a minus in front of the y part

not a plus

that makes it - (y^2 + 12y + 36)

[velvet notch]

oh ok

[worldly tendon]

= -(y + 6)^2

thus 37 - 36 gets us our 1

[velvet notch]

thx

.close

[topaz sinew]

Channel closed

Closed by @velvet notch

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[neon iron]

Hey

[neon iron]

I forgot how to solve this

[strong totem]

AM means M-A

so you can just translate AM=-5BM to M-A=-5(M-B)

[neon iron]

I didn’t understand 😢

@strong totem can you solve please

[strong totem]

sure, but if i didnt read the question wrongly

wait

[neon iron]

Thks I love you

And then just 2 questions

This

[strong totem]

ehhh

[neon iron]

I think it’s done sorry

[strong totem]

can you translate it ?

ok then

[neon iron]

No I did it it’s done Thank you for your help

What a discord

I will stay here it’s nice

[topaz sinew]

@neon iron Has your question been resolved?

[neon iron]

Yes

[winged roost]

React with the green tick

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fierce zealot]

For a matrix A, is $A^{k+1} =A^k \times A$?

[thorny flame]

Kurama

[fierce zealot]

lol

nvm im stupid

.close

[topaz sinew]

Channel closed

Closed by @fierce zealot

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[foggy prawn]

ik intersection means multiplication, does union mean division?

[gleaming thunder]

usually represented by addition in similar contexts

[foggy prawn]

thanks!

.close

[topaz sinew]

Channel closed

Closed by @foggy prawn

Use .reopen if this was a mistake.

[neon iron]

/open

.open

.reopen

[topaz sinew]

✅

[neon iron]

.close

[topaz sinew]

Channel closed

Closed by @wraith prawn

Use .reopen if this was a mistake.

[gleaming thunder]

wtf

such an useful intervention jester

[neon iron]

wym?

[gleaming thunder]

it's just funny

[neon iron]

he had already closed it

[gleaming thunder]

lmao, I'm sorry but I'm just dead laughing

"helper struggles to open channel then closes it immediately" is just funny to me

[neon iron]

🤣 .

[gleaming thunder]

thought you had something interesting to say, was confused but well compensated

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gleaming kettle]

help please

[gleaming kettle]

i dont get how it adds up to 100??

[topaz sinew]

@gleaming kettle Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rich fossil]

okay lads

[rich fossil]

quick question

[winged roost]

yeah?

[rich fossil]

uh wait

ye

so i'm kinda being asked to find all polynomials given the zeros

for like instance

er

find all cubic functions given roots 2, 4, -7

ye

I understand that

[rich fossil]

I can't remember what my initial question was

[rich fossil]

but given this

Of course

One cubic would be (x-2)(x-4)(x+7)

or even a(x-2)(x-4)(x+7) for any a

[winged roost]

yeah

wouldn't that be it?

[rich fossil]

right but like that's just one

ye

but why am i being asked to 'determine' all

when there's like one

for any leading coefficient a

[winged roost]

yeah that's strange

ofc it doesn't work when a = 0

but other than that, it is a family of cubics no?

for any value a, a != 0

[rich fossil]

ye

okay

so basically

for any question like this

i just express it as what i've done

using the roots

[winged roost]

I suppose

[rich fossil]

then again do i just say a(x-r_1)(x-r_2)(x-r_3)...(x-r_n) for all a not equal to 0

should i do anything with this

that part was just for cubics

now we're going a degree higher

[winged roost]

sorry that's a bit out of my depth so I won't be able to further help you

[rich fossil]

ok no worries

.close

[topaz sinew]

Channel closed

Closed by @rich fossil

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pliant surge]

a and b is a real number

i think its done by manipulation but havent got a single clue

[topaz sinew]

@pliant surge Has your question been resolved?

[topaz sinew]

@pliant surge Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[topaz sinew]

@young patio Has your question been resolved?

[topaz sinew]

@young patio Has your question been resolved?

[topaz sinew]

@young patio Has your question been resolved?

[topaz sinew]

@young patio Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[kindred inlet]

can anyone please help?

[topaz sinew]

@kindred inlet Has your question been resolved?

[kindred inlet]

<@&286206848099549185>

[keen venture]

Do you have a normal distribution chart, or calculator?

[topaz sinew]

@kindred inlet Has your question been resolved?

[kindred inlet]

i got the answer ty

[topaz sinew]

Channel closed

Closed by @kindred inlet

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[kindred inlet]

is that permutation or combination?

<@&286206848099549185>

[keen venture]

9 choices to make, each choice has 4 possibilities.
4⁹

[kindred inlet]

ok ok

@keen venture

how do u do this?

[empty sail]

Don't ping specific people, it's not nice to do that unless they allow it

[keen venture]

All good, I answered already

[kindred inlet]

mbmb

[kindred inlet]

can any1 hw w that tho?

[fierce zealot]

how many numbered cards are there in a deck

[kindred inlet]

52

[fierce zealot]

numbered cards

[kindred inlet]

9

[fierce zealot]

in total

theres 4 suits and each suit has 9 numbered cards right

so in total there should be 36 numbered cards

[kindred inlet]

oh 36/52

[fierce zealot]

So if you draw from a deck, whats the probability of drawing a numbered card on the first time

[fierce zealot]

yep

since we are doing without replacement, once we draw that first card, we do not put it back

Now, how many cards are there left in total?

Out of which how many are numbered

[kindred inlet]

wait so its 36/52 x 34/50 right?

[fierce zealot]

why 34 and 50?

[kindred inlet]

cuz it said and 2 cards r drawn

[fierce zealot]

you're not drawing at the same itme

like if you have 36 numbered cards. After your first draw, there should be only 1 less right?

Then u go for the second draw

[kindred inlet]

35/52

?

[fierce zealot]

almost

but remember your total number of cards should also decrease by 1

right

[kindred inlet]

35/51

[fierce zealot]

yeah,

[kindred inlet]

then

?

[fierce zealot]

Then use this

[kindred inlet]

but it said 2 cards drawn right

isnt it supposed to be 34/50

?

[fierce zealot]

You are interested in the probability of drawing two numbered cards

34/50 describes how many numbered cards are left after you draw the 2 numbered cards

[kindred inlet]

yup

[fierce zealot]

It basically irrelavant

[kindred inlet]

isnt that what we need

[fierce zealot]

from what u want to know

[kindred inlet]

cuz thats the second draw

when 2 cards r removed

[fierce zealot]

Ok. So you have a deck of cards. The question is asking you, what is the probability of you taking a draw once, getting a numbered card, then taking another draw, and again getting a numbered card.

So you draw two cards in total

As you said, the probability of getting a numbered card on the first draw is 36/52

[kindred inlet]

oh bruh i understood something completely different

u r right

the answer is 105/221

[fierce zealot]

yep

[kindred inlet]

ty

[topaz sinew]

@kindred inlet Has your question been resolved?

[kindred inlet]

help?

.close

[topaz sinew]

Channel closed

Closed by @kindred inlet

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[waxen storm]

im confused by d<-b/2a<e

shudnt it be 2d<-b/2a<2e?

ah wait i get it lol

.close

[topaz sinew]

Channel closed

Closed by @waxen storm

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[grim trout]

how to calculate ln(72) ?

[topaz sinew]

Please don't occupy multiple help channels.

[keen venture]

It's k I gotchu fam

,calc ln(72)

[grim trout]

[thorny flame]

The following error occured while calculating:
Error: Undefined function ln

[keen venture]

Nvm I am powerless

[grim trout]

lol

I know the result, I want to know how

[sweet shard]

,calc log(72)

[thorny flame]

Result:

4.2766661190161

[sweet shard]

You use a calculator

[grim trout]

I can't in my exam

😕

[keen venture]

They won't expect you to calculate ln(72) with no other info

[sweet shard]

What kind of answer are you supposed to give

[keen venture]

Now, perhaps if you are expected to write it in terms of ln(2) and ln(3) that's more interesting

[sweet shard]

You don't need ln(72) to solve for x

[grim trout]

no?

[sweet shard]

Is that what you're really trying to do?

[grim trout]

yes

[sweet shard]

Use log properties

[keen venture]

log5 is not ln

[grim trout]

i did the log a (x) = ln (x) / ln (a)

😦

thought it would be easier

hehe

[keen venture]

Oh hah, I guess that's technically true

But no, the log5 and the 5^ will cancel

[grim trout]

oh

hm

[grim trout]

what property i use here?

then

[sweet shard]

Just simplify the left side

[sweet shard]

Go through all of them

[grim trout]

Ok

logb(xy) = logbx + logby.
logb(x/y) = logbx - logby.
logb(xn) = n logbx.
logbx = logax / logab.

its all of then

right?

[maiden wave]

Isnt 5^(x-2)=72 ?

[grim trout]

yes this is the original quesiton

you're smart

Resolve the equation 5^(x-2)=72 is the question

[keen venture]

Then why did you take the log?

[grim trout]

I am using log because I think its the easier way and we are learning log so I think he wants me to use log

hahah

He even said log2 = 0,30 and log = 0,48 but i dont know how i use this info

[keen venture]

So you'll use that third property:
log(5^(x-2)) = log(7)
(x-2)log(5) = log(7)

[maiden wave]

Well just do x-2=log_5(72)

put log_5(72) in calculator then add 2 and you found x

[grim trout]

$log(5^(x+2)) = log(7)$
$(x+2)log(5) = log(7)$

hmm

[grim trout]

hmmm ok

I will try it

[grim trout]

We cant use calculators =T

[maiden wave]

Oh

[grim trout]

it would be so much easier

[keen venture]

The final log we have will probably be good enough

[grim trout]

Ok

This is the answer then?

[keen venture]

You'll need to solve for x

However, that is a very good step!

[grim trout]

Ok!

Sorry to repeat the question, this properties are enough for a test with questions like this?

logb(xy) = logbx + logby.
logb(x/y) = logbx - logby.
logb(xn) = n logbx.
logbx = logax / logab.

Or I need some more?

I tried to google log properties but can't find good sources

[grim trout]

Awesome!!! Thank you

Gonna study this all week, you guys helped a lot

thanks

[topaz sinew]

@grim trout Has your question been resolved?

Channel closed

Closed by @grim trout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[delicate ivy]

This is a level 11 M1 question

How to do part c ?

[knotty ledge]

What have you tried

[delicate ivy]

I did part a and b

[delicate ivy]

But I forgot how to do area of region bounded 😅

[knotty ledge]

Integral?

[delicate ivy]

Probably yes

How to do it🥲

[topaz sinew]

@delicate ivy Has your question been resolved?

[sweet shard]

do you know anything about integrals?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[solid mirage]

These are my attempts

Any clue?

So I just don't know if I'm doing it right

Or should I approach it from a different angle

Cause I'm stuck and can't seem to do further calculations

[odd pagoda]

in your second line you wrote your n like an x

which made everything a lot more complicated

[solid mirage]

Second line?

[odd pagoda]

first picture on the right

[solid mirage]

Oh

I will do it again and try

Okay now I can get the answer

Thanks @odd pagoda

.close

[topaz sinew]

Channel closed

Closed by @solid mirage

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[steady ocean]

<@&286206848099549185>

okay

what the fuck is this question

someone solve it

please

been sitting here

20mins

[odd pagoda]

"use technology"? is this supposed to mean a computer?

[steady ocean]

lol

[odd pagoda]

you need to show that the integral of the function equals 1

[steady ocean]

do i use and intergral caltualator

yeah

so

waht ahppens

if i get this in an exam

wtf is technology lol

[odd pagoda]

well ask your teacher or whoever gave you the questions

[steady ocean]

its a textbook

cambridge

idk

weird

doubt id be given this in an exam tho

[odd pagoda]

unlikely

but you can use a couple of substitutions to get the integral int e^-x^2 from this which you may or may not know. this can be solved by squaring the integral and then transforming to polar coordinates

[muted pond]

they want you to integrate it

from -inf to int

and the result should be 1

because density function allways gives 1

for any distribution

https://www.wolframalpha.com/input?i=integrate+-infinity..infinity+(1%2F(1*sqrt(2*pi)))*e^((-(x-6)^2)%2F2*1*1)