#help-26

226100 messages · Page 240 of 227

mortal thunder
static crest
#

Ansh!!!!

mortal thunder
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Let x \in A

static crest
mortal thunder
#

breh

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okay you tried

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I can not blame you anymore for this one

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(X) is : Let x \in C - B

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(XI) is: Suppose x \in A

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(XII) is: and A \subset C

#

static crest
#

Helps a lot

sweet shard
#

.close

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honest oyster
topaz sinewBOT
honest oyster
#

shouldnt it be $(x^2+cx-5)$ instead of $(x^2+cx-15)$?

thorny flameBOT
#

Reinhard von Lohenngram

cursive flax
#

Yeah

#

-5*-3=15

honest oyster
#

ok

#

.close

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idle stone
topaz sinewBOT
idle stone
#

what does the O mean in between d2 and r y=x

#

.close

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neon iron
topaz sinewBOT
neon iron
#

Am I doing this correctly

#

Finding by Euler method

topaz sinewBOT
#

@neon iron Has your question been resolved?

keen venture
#

Yes but you've made a calculation error from line 1 to line 2

#

y1 = 0 + 0.1(1) = 0.1

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valid jungle
#

can someone help me understand this better

vital relic
#

Missing.

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stuff.

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Let $f : A \to B$

thorny flameBOT
#

Shuri2060

vital relic
#

If $f$ is invertible, then the above statements hold.

thorny flameBOT
#

Shuri2060

vital relic
#

By definition of inverse...

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There isn't much else to say. Come up with your own examples.

valid jungle
vital relic
#

???

valid jungle
#

i just didnt understand why the exponent had to be in the inner function in the 2nd example

vital relic
#

the letters.............. are totally irrelevant

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That's not an exponent.......................

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$f^{-1}$ refers to the inverse function of $f$ by definition.

thorny flameBOT
#

Shuri2060

vital relic
#

$f^{-1}: B \to A$

thorny flameBOT
#

Shuri2060

vital relic
#

And by definition the above must hold.

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$f^{-1}\circ f = id_A$\
$f\circ f^{-1} = id_B$

valid jungle
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okay so what difference does it make if the inverse sign was in the outer or inner function

thorny flameBOT
#

Shuri2060

valid jungle
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okay

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same thing

vital relic
#

What do you mean what difference it makes

valid jungle
#

oh wait

vital relic
#

You should know which order you apply the functions

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when you have composition

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$(f^{-1}\circ f)(x) := f^{-1}(f(x))$

thorny flameBOT
#

Shuri2060

vital relic
#

This means 'do f' then 'do f inverse'

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to x.

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It is the order in which you apply the functions.

valid jungle
#

no i mean like A to B

vital relic
#

You need to come up/check up some examples

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It probaby isn't making sense because it is abstract as opposed to concrete.

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This is simple stuff expressed formally.

keen venture
#

Do the operation, then undo the operation. You'll have done nothing and be back where you started

valid jungle
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$f(x)^{-1}(f(x)): f(x)(f(x)^{-1})$

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are those two similar

vital relic
#

this looks like giberish to me

keen venture
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The weird one is when you perform the undo, then perform the operation, haha

vital relic
#

no idea what you are trying to express.

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Function composition has nothing to do with multiplication.

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^-1 indicates inverse.

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not reciprocal.

valid jungle
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oh wait

vital relic
#

I really suggest you to come up with some concrete examples

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And you will immediately stuff like this

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is right or wrong, usually.

valid jungle
#

$f^{-1}(x)(f(x)): f(x)(f^{-1}(x))$

thorny flameBOT
#

Nix Valentine

vital relic
#

Let $f : \bR \to \bR^+, f(x) = e^x$.\
Then $f^{-1} : \bR^+\to\bR, f(x) = \ln x$.

thorny flameBOT
#

Shuri2060

vital relic
#

Then proceed to have a think.

valid jungle
#

okay

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what about in the case of composition

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does it make any difference if the inverse sign is in the inner or outer function

vital relic
#

Of course it does.

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This is the key point.

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$$\ln(e^{-1}) = -1$$
$$e^{\ln(-1)} = undefined$$

thorny flameBOT
#

Shuri2060

valid jungle
#

ty

#

.close

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neon iron
#

hey

topaz sinewBOT
neon iron
#

guys

#

can you help em

#

me*

alpine mist
#

depends on your question....

static void
#

@neon iron just ask your question while answering the channel

vital relic
#

Original routine:

  1. Ask if you can ask a question/get help
  2. Get a reply
  3. Ask the question
  4. Get help

Optimization proposal:

  1. Ask the question
  2. Get help
topaz sinewBOT
#

@neon iron Has your question been resolved?

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karmic fox
#

anyone know what i did wrong with these?

topaz sinewBOT
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@karmic fox Has your question been resolved?

karmic fox
#

.cloes

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.close

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hollow otter
#

What is the condition for x^2+ax+b to be divisible by x+c?

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hollow otter
#

What is the condition for x^2+ax+b to be divisible by x+c?

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hollow otter
#

What is the condition for x^2+ax+b to be divisible by x+c?

neon iron
#

hi

hollow otter
#

hi

neon iron
#

(x+c)(x+b/c)

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what country r u from

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-c would

hollow otter
#

singapore but im in australia rn why?

neon iron
#

i just wanna make friends haha

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make it 0

hollow otter
#

Ahh okay I see

#

Ty 🙂

#

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marsh hollow
#

how would i simplify this

topaz sinewBOT
static void
#

Use your log rules

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also is this a quiz

neon iron
#

uhh

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log 3 6³ + log 3 9⁶

static void
#

@neon iron SHTAP GIVING PEOPLE ANSWERS

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that's not what helpers are supposed to do!

empty sail
topaz sinewBOT
#

@marsh hollow Has your question been resolved?

marsh hollow
#

u ever use cengage

#

i got the question right anyways but thx

#

.close

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upbeat tulip
#

Aight boys i am gonna solve algebra questions, most probably i am gonna get doubts. Be ready

supple jetty
topaz sinewBOT
#

@upbeat tulip Has your question been resolved?

upbeat tulip
#

The question is misprinted, but what would have been done if gif actually has an expression in it

#

Like suppose fractional part of x-3

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We should use fractional inequality?

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Like lies from 0 to 1

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Aight seems like nobody gonna help

#

.close

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stiff thorn
#

In square root equations, why is it written that assume that all variables are positive? What rule does that apply to?

wooden matrix
#

cause we want to stay within the real numbers

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assuming you're not already in the C plane/working with C

stiff thorn
#

Alright thanks, I knew that but just wanted to make sure it wasn't a certain rule or trick you could use when knowing that or something when it was variables that the teacher meant

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Thanks

#

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crisp hemlock
#

.open

#

.reopen

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hallow meteor
topaz sinewBOT
grim jacinth
hallow meteor
#

i tried using differentiation but got stuck

grim jacinth
#

,rotate

thorny flameBOT
median temple
#

Well, think about what you want to differentiate

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You don't want the minimum of the area, since that's fixed

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You want the minimum of the perimeter

grim jacinth
#

^^

hallow meteor
#

oh

median temple
#

Also, x*(32-x)=64 isn't the right way to parameterize this

hallow meteor
#

i tried differentiating the perimeter but it was 0

median temple
#

Your side lengths aren't x and 32-x

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Try some examples

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like x=1

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That rectangle doesn't have area 64

hallow meteor
#

ok

#

what sides shud i use?

median temple
#

Well, if one side length is x, can you work out what the other side length is?

hallow meteor
#

how am i meant to find the minimum perimeter tho

median temple
#

We'll get there in due time

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But to see how the perimeter can vary, we must study all rectangles that have an area of 64

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Because if we can express their perimeters in terms of a single variable, differentiation will end it

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So right now, the goal is to try to find a general form for the side lengths of rectangles that have area 64

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I reiterate, if a rectangle has area 64 and one of its side lengths is x, what is the other side length?

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Write it down on paper, give the other side length a name if you have to

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Just don't blindly guess, because I will know

hallow meteor
#

like this?

#

,rotate

thorny flameBOT
median temple
#

Correct!

#

The only constraint on x here is x>0

#

Now you know the side lengths in terms of x

hallow meteor
#

oo yes

median temple
#

You can now express the perimeter in terms of x

hallow meteor
#

ook

median temple
#

The final result is interesting, too

hallow meteor
#

I got this

#

,rotate

thorny flameBOT
median temple
#

you forgot to differentiate the x

hallow meteor
#

o

#

i got it

#

,rotate

thorny flameBOT
hallow meteor
#

:p

median temple
#

Yup

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If you plug this back into what you found earlier

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You find that both side lengths are equal to 8

hallow meteor
#

yes

median temple
#

So, the perimeter of a rectangle is always larger than the perimeter than the square with that same area

#

Which is fun and not quite trivial

hallow meteor
#

yes

#

ty for help

#

.close

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#
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spiral briar
topaz sinewBOT
spiral briar
#

Hey i need help

neon iron
#

with

spiral briar
#

This

leaden tusk
#

with what?

spiral briar
#

This question

#

Work out the value of t

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t At point C

leaden tusk
#

what have you tried

spiral briar
#

0.97?

#

You do realise it represents a coordinate

neon iron
#

hold on*

leaden tusk
#

don't do people's work for them

#

read the rules

spiral briar
#

I di dnt even see it lol

topaz sinewBOT
#

@spiral briar Has your question been resolved?

topaz sinewBOT
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neon iron
#

i need help

topaz sinewBOT
neon iron
#

HOW IS -7+4 is -3??

vital relic
#

How is it not?

neon iron
#

WDYM?

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i dont get it😭 wth

#

oh

#

i counted wrong

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nvm

#

ty

#

i put -1

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its -3

vocal trout
#

so basically

neon iron
#

-_-

vocal trout
#

lets put it in this way

#

what is -7+1?

neon iron
#

eh

#

uh

#

-6?

vocal trout
#

correct

neon iron
#

YES

vocal trout
#

what is... -15+7

neon iron
#

....

#

oky no thats too hard

vocal trout
#

why?

neon iron
#

😭

#

oky

#

mhm

#

-8?

vocal trout
#

yes

#

ok now subtraction

neon iron
#

yayy

#

EH..

#

oky

vocal trout
#

what is -2-2?

neon iron
#

you add

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so

#

its

vocal trout
#

think about it

neon iron
#

-4

#

!

vocal trout
#

it would be the opposite of adding

neon iron
#

no..

vocal trout
neon iron
#

oh

#

eh

#

yay

vocal trout
#

good job

#

:D

neon iron
#

yayy

#

haha

#

what bout multiplication?

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and division?

vocal trout
#

oh right

#

ok so

neon iron
#

and the quadratic or something

vocal trout
#

when a negative times a negative it becomes a positive

neon iron
#

yhh

vocal trout
#

same thing for division

#

and when you multiply a negative by a positive

#

its negative

#

same thing for division

#

so try this

neon iron
#

i see

vocal trout
#

-2 x -2

neon iron
#

so thats 4

vocal trout
#

exactly

neon iron
#

cause neg and neg makes a pos

#

aaaah oky

vocal trout
#

yes

#

-15 x -2?

neon iron
#

-_-

#

30?

#

...

vocal trout
#

yup you got it

neon iron
#

ayyyy

vocal trout
#

now for division?

neon iron
#

yess

vocal trout
#

ok

#

-15/3

#

the / is a division symbol for typing

neon iron
#

-5?..

#

yupp

vocal trout
#

yup

#

correct

neon iron
#

ahh right

#

yay

#

hahaha

vocal trout
#

you got it with negatives and stuff like that now?

#

feeling more confident hopefully

neon iron
#

yh but what about with quadratics?

#

i mean if ur free to help me with that part

vocal trout
#

alr

#

i dont know quadratics yet

#

unfortunatly

neon iron
#

ahh i see

vocal trout
#

i only know so much haha

neon iron
#

hahahha i see

vocal trout
#

alright have a nice day hope i helped!

neon iron
#

you too

#

Thank youuu

#

I MEAN

#

eh

#

you diddd

#

yh!

#

thank you

topaz sinewBOT
#

@neon iron Has your question been resolved?

#
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topaz sinewBOT
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bleak bough
#

Hey, i have a discrete math problem that i'm struggling with

bleak bough
#

I got a relation where

#

I need to prove that R is reflexive if Dom(R) =S, R is transitive and R is symmetric

#

If R is symmetric, then a r b and b r a exists

#

If R is transitive, a R b and b R a implies that a R a exist

#

thus it is reflexive

#

however, idk how to include the domain into the proof

topaz sinewBOT
#

@bleak bough Has your question been resolved?

wheat laurel
bleak bough
#

yes

#

my bad

#

The problem im having

#

proving that if i have (a)

wheat laurel
#

if Dom(R) isn't S, there might not be any pairs for which the relation is satisfied

bleak bough
#

that b is linked to this a

#

Yeah

#

but i'm having trouble writing it formally

wheat laurel
#

welp

#

Dom(R) = S

bleak bough
#

Would writing it like this work:

#

We take an a where a is an element of S,
By definition of the domain, a R b

wheat laurel
#

just mention that this is true for every such a

bleak bough
#

wdym?

#

If a is an element of S, it is part of the domain?

bleak bough
#

i got this definition for the domain

#

shouldn't we put

#

shouldn'T it be

topaz sinewBOT
#

@bleak bough Has your question been resolved?

#
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bleak bough
#

Thanks for the help @wheat laurel , forgot to thank you my bad 😄

topaz sinewBOT
#
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tiny sigil
#

can someone help elaborate on how this follows?

wooden matrix
wheat laurel
#

which isnt that hard

tiny sigil
wheat laurel
tiny sigil
wooden matrix
#

No

#

$A=[a_{ij}]$ just means the (i,j)-entry is $a_{ij}$

thorny flameBOT
wooden matrix
#

if A is mxn, then 1=<i=<m and 1=<j=<n

tiny sigil
#

Ahh okay i think i somewhat get it

wooden matrix
#

for example $I=[a_{ij}]$ where $a_{ij}=1$ if $i=j$ and 0 else

thorny flameBOT
tiny sigil
#

Oh so for the second line b_ij = 1/2 (an element of the original square matrix + an element of the transpose of the square matrix)?

#

Is that what i'm supposed to get out of that?

wooden matrix
#

$B^T$ is where you swap i and j

thorny flameBOT
wooden matrix
#

so the entries of $B^T$ look like $\frac{1}{2}(a_{ji}+a_{ij})$

thorny flameBOT
wooden matrix
#

which is identitcal to the entries of B

#

so $B^T=B$

thorny flameBOT
tiny sigil
wooden matrix
#

yes, but you get -C

tiny sigil
#

wait would would be the yeah

#

Oh

wooden matrix
#

so B is symmetric and C is skew

tiny sigil
#

I see that makes much more sense, thank you!

wooden matrix
#

then trivially, you get that B+C=A

topaz sinewBOT
#

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copper meteor
#

is anyone familiar with financial mathematics?

copper meteor
#

I don't have a specific question. I'm trying to find supplementary material for this other book I'm reading: "Introduction to the mathematics of Finance," which I find really hard to understand

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tough rune
topaz sinewBOT
tough rune
#

how is the blue line not concave up in graph A

topaz sinewBOT
#

@tough rune Has your question been resolved?

tough rune
cyan python
#

Its better to draw its graph in desmos

tough rune
#

we can start wherever

#

draw what

#

I litteraly just coped these off the assignment

topaz sinewBOT
#

@tough rune Has your question been resolved?

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grim rover
#

I'm not exactly sure what this lemma says

topaz sinewBOT
grim rover
#

like I get the part that r will be even because a tranposition raised to the 2nd power is id

#

so by mod 2, all even power of a transposition will give you the identity

#

i don't understand the "following cases for the last two transpositions"

#

case 1 makes sense

#

i don't understand case 2 or case case 4? case 3 commutes because they're disjoint transpositions

alpine mist
#

4 cases,
Both transpositions are the same
two different transpositions but have a common term
two different transpositions totally disjoint
two different transpositions but have a common term in a different place.

#

it is weird though. transpositions can be written different ways, like (a,b) = (b,a) so I don't know why they made a point to make 2 and 4 different cases...

topaz sinewBOT
#

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grim rover
#

because (b,c)(a,b) = (a,c,b)

#

(a,c,b) --> (a,c)(a,b)

#

OH WAIT

#

(a,c,b) == (c,b,a)

alpine mist
#

yep

grim rover
#

(c,b,a) = (c,b)(c,a)

#

then we can flip them inside to get (b,c)(a,c)

alpine mist
#

yep

grim rover
#

ah ok thanks

topaz sinewBOT
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pale knoll
#

hello

topaz sinewBOT
pale knoll
#

does anyone know why the last 2 are wrong?

empty sail
#

,w plot -6x^3+36x^2+90x+4

empty sail
#

Nothing to do with ordered pairs

pale knoll
#

@empty sail would local max be -1, and local min be 5?

empty sail
#

Is that what the x is?

pale knoll
#

yea

#

i solved the derivative

#

then set = 0 and found critical numbers

empty sail
pale knoll
#

@empty sail can u double check these 2

grim rover
#

Take the derivative

#

and check it

#

the second derivative could be useful here

#

rather it will be useful

#

go through your work,step by step. If you think you've got it down, you could probably just graph the function and verify it yourself

#

or plug into wolfram

topaz sinewBOT
#

@pale knoll Has your question been resolved?

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smoky ore
#

Anyidea how we can get k = logn?

topaz sinewBOT
snow basalt
#

using the method shown in the image lol

#

is there a part of that method in particular you dont understand

smoky ore
#

Yes how come logn / log 2 will give us log n?

empty sail
#

So $\log_2(2)$

thorny flameBOT
#

dldh06

smoky ore
#

Then why the log n is still in log but not in log 2 n?

empty sail
#

Because $\log_2(2) = 1$

thorny flameBOT
#

dldh06

empty sail
#

Nothing happens with the right hand side

smoky ore
#

So we can simply assume the base for one of the log?

#

I thought if we assume is base 2 , the bith the logs should be in base 2 isnt it?

snow basalt
#

both the logs are in base 2.

smoky ore
#

Omg is confusing

#

If both the log is in base 2 then why they just write log without mentioning base 2 in the last line

grim rover
#

your name is tcp/ip and you're asking about base 2 logs? is this for a cs class lol

#

in cs, you're (mostly) dealing with binary, so log(n) is typically assumed to be log_2(n) unless specificed otherwise

#

after seeing (2) -> (3) line, you know log_2(2) = 1, thus the other side must also be log_2 since we're dealing with an equation

#

Plus the comment is there as well

topaz sinewBOT
#

@smoky ore Has your question been resolved?

smoky ore
#

@grim rover so we can always just out log without any base right?

grim rover
#

wdym?

#

if you have an equation with logs on both sides that have undeclared/unspecified bases, then you could probably assume they're the same base

thorny flameBOT
#

suck2015

#

suck2015

topaz sinewBOT
#

@smoky ore Has your question been resolved?

topaz sinewBOT
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stoic elk
#

x^2 - 2xy cot a - y^2 = 0
find the angle

topaz sinewBOT
stoic elk
#

$x^2 - 2xy cot a - y^2 = 0$

thorny flameBOT
#

Saurav

$x^2 - 2xy cot a - y^2 = 0$
stoic elk
#

$ax^2 + 2hxy +by^2=0$

thorny flameBOT
#

Saurav

stoic elk
#

compare with this

celest shuttle
#

divide everything by x^2, then it's a quadratic equation which you can presumably solve

celest shuttle
#

?

stoic elk
#

i need to find the angle

#

.close

topaz sinewBOT
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full moss
#

can someone evaluate the limit cause theres no explanation here

acoustic tangle
#

You just sent the explanation sully

#

pi/cos(pi) = pi/(-1) = -pi

stuck lintel
#

,w evaluate cos(pi)

stuck lintel
#

If you were confused by that

topaz sinewBOT
#

@full moss Has your question been resolved?

full moss
#

yea i get it

topaz sinewBOT
#

@full moss Has your question been resolved?

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jaunty vector
topaz sinewBOT
jaunty vector
vital relic
jaunty vector
#

i see

#

so its 0.5 + other stuff

#

I dont what the other stuff is

vital relic
#

the 2nd line you wrote

#

is wrong

#

think carefully what it should be

jaunty vector
#

0.021?

#

cuz .21 is repreating

vital relic
#

write
0.5212121...

#

as a sum of 2 numbers

#

a terminating decimal
and a purely repeating decimal

jaunty vector
#

uhhh

#

so its 0.5 + 0.0212121...

vital relic
#

good

#

then proceed.

jaunty vector
#

uhhh

#

what

#

do i put 0.5 over something?

#

?

topaz sinewBOT
#

@jaunty vector Has your question been resolved?

jaunty vector
#

I got 516/990 as my final answer

#

want to see my work?

keen venture
#

There's a neat trick.
0.12121212... = 12/99

#

Using that, can quickly cobble it together

jaunty vector
#

My work (left side)

keen venture
#

Oh yeah, I see how you did it, with a geometric series

jaunty vector
#

is it correct?

#

did i use the right dp?

keen venture
#

I would do:
12/99 - 1/10 + 5/10
= 120/990 - 99/990 + 495/990
= 516/990

#

So yeah, our different methods get the same thing

#

Can also calculator it, if unsure

jaunty vector
#

ohh so we got the same answers?

#

I just used the method i was taught

keen venture
#

Oh, are you supposed to reduce the fraction?

jaunty vector
#

do i need to simplify?

#

didnt say

keen venture
#

That's up to your teacher, haha.

jaunty vector
#

just say into fraction

keen venture
#

Just doing it is safest

jaunty vector
#

i did. it was wrong

#

maybe my teacher wants it into a fraction not simplified

#

516/ 990 = 86/165?

mortal thunder
#

ehh

jaunty vector
#

?

mortal thunder
#

516/990

jaunty vector
#

yea. that was my answer too

#

idk if i should simplify it or not

mortal thunder
#

Yeah, think there's an issue

jaunty vector
#

i simplified it to 86/165. it was wrong

#

no exact value, as a fraction

mortal thunder
#

Actually

#

there's no $\ldots$ so probably your teacher did not mean for it to be a recurring decimal?

thorny flameBOT
mortal thunder
#

maybe it's just 5121212121212(however many times) / 10^(something)

#

?

#

$\frac{52121212121212}{10^{14}}?$

thorny flameBOT
jaunty vector
#

maybe but it states that its repeating

mortal thunder
#

oh right "repeating decimal". Yeah it's just your server problem or sth

jaunty vector
#

okay. its a coding problem

#

i already entered in 86/165 as an answer and its correct

#

but it didn't accepted it

mortal thunder
#

oof yes

jaunty vector
#

thanks for help

#

.close

topaz sinewBOT
#
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orchid holly
#

how do we go from the top one to the bottom one? I got the top one when doing the induction step and changing n to k + 1

orchid holly
#

.close

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heavy carbon
topaz sinewBOT
heavy carbon
#

Hi. I tried to multiply the right side (7/t) by the sqrt(1+t)/sqrt(1+t)

keen venture
#

Good start

heavy carbon
#

to get a lcd

keen venture
#

What do you get when you plug t = 0 into that?

heavy carbon
#

0

#

so i have

keen venture
#

Check again

#

Oh wait mb you totally do get 0/0

heavy carbon
#

all good!

#

right now ive simplified it to

#

lim t-> 0
7-7(sqrt(1+t))

tsqrt(1+t)

#

but im not sure what to do from here

unique tundra
#

you could write $\frac{7-7\sqrt{1+t}}{t\sqrt{1+t}} = \frac{7-7t\sqrt{\frac{2}{t}+\frac{1}{t^2}}}{t\sqrt{1+t}}$

thorny flameBOT
#

Big xdddd

unique tundra
#

and now divide t on the numerator and denominator

#

what do you get?

heavy carbon
#

can you please explain how you went from one to the other

unique tundra
#

$7\sqrt{1+t}=7\sqrt{t^2\cdot\left(\frac{1}{t^2}+\frac{1}{t}\right)}=7t\sqrt{\frac{1}{t^2}+\frac{1}{t}}$

#

but i just realised you need the limes for t to zero not to infinity

#

so this wouldnt help actually

thorny flameBOT
#

Big xdddd

heavy carbon
#

$\frac{7-7\sqrt{1+t}}{t\sqrt{1+t}}

#

how do u do that

unique tundra
#

you mean the writing?

heavy carbon
#

yea

#

wat

#

what if you multiply by the conjugate of the numerator

#

how would i distribute that

#

.close

topaz sinewBOT
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neon iron
#

1,4,7...301. find the summation of all terms in this sequence

wheat laurel
wheat laurel
neon iron
chilly kestrel
#

yes

neon iron
#

ty

#

.close

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winged pond
topaz sinewBOT
neon iron
#

U there rn so that I can start?

#

@winged pond

winged pond
#

me?

#

here

neon iron
#

First we can see that 20 degress

#

and imagine the sin of that 20 degress

#

That small triangle being formed

#

With hypotenuse 1

#

I can draw and show u if u want?

winged pond
#

sure

neon iron
#

Can u see the small triangle

winged pond
#

yea

neon iron
#

It has a hypotenuse of 1

#

The length of the green line

#

Is $sin$

thorny flameBOT
#

Dumbest Being

neon iron
#

Ok @winged pond ?

winged pond
#

oh

neon iron
#

And notice that the bigger triangle is

#

Just a scaled copy of the smaller

#

One

#

Thus each side length

#

In the small triangle

#

Gets multiplied by the same factor

winged pond
#

yes

neon iron
#

To get it's length on the bigger triangle

#

now we know that on the bigger triangle the length of the opposite is 62

#

And on the smaller it's $sin$

thorny flameBOT
#

Dumbest Being

neon iron
#

Thus factor by which it got scaled is $\frac {62}{sin(20)}$

thorny flameBOT
#

Dumbest Being

neon iron
#

Right @winged pond?

winged pond
#

yeah

neon iron
#

Now tell me on the smaller triangle

#

What's the length of the Adjacent

#

In the smaller triangle

winged pond
#

1?

neon iron
leaden tusk
#

bro what

neon iron
#

The length of the purple line

winged pond
#

x

neon iron
#

No in the smaller triangle

#

Not the bigger one

leaden tusk
#

what are you drawing another triangle for

#

??

neon iron
#

Dude wait lemme finish

winged pond
#

uhh im not sure

neon iron
#

Yea?

rare isle
#

you have derived sin = opp/hyp

neon iron
#

And that gets scaled by $\frac {62}{sin(20)}$

thorny flameBOT
#

Dumbest Being

neon iron
#

Thus the length of x is

#

cos(20) multiplied by the factor 62/sin(20)

leaden tusk
#

bro what

#

???

winged pond
#

im so confused

#

isnt it sohcahtoa..

leaden tusk
#

yeah i don't blame you

#

yes

#

it's just soh cah toa

neon iron
#

People don't understand that sin is just the length of a triangle

#

With hypotenuse 1

#

sully thats it in the most basics

leaden tusk
#

what

neon iron
rare isle
neon iron
#

Sin = opp/hypotenuse

#

= opp when hypotenuse is 1

#

That's just what sin even means

winged pond
#

oh..

leaden tusk
neon iron
leaden tusk
neon iron
#

Drawn on a unit

#

Circle

winged pond
#

i though it was tan k

neon iron
#

And the hypotenuse there is just the radius or 1

leaden tusk
#

"length of a triangle" makes no sense

neon iron
leaden tusk
neon iron
#

U will still get same thing

#

cot(20) * 62

#

Which is same as

#

cos(20) * 62/sin(20)

winged pond
#

tan(20)=62/x, is another way right

leaden tusk
#

yes, then just solve for x

winged pond
#

i got x=170.3 do yall agree

leaden tusk
#

yes

neon iron
#

And my answer is also same

#

So myne is also correct

winged pond
#

yeah just more complicated

neon iron
winged pond
#

ok sure

winged pond
neon iron
#

But my answer is not incorrect like @leaden tusk was saying

#

And in its mere inside 62/x=tan(20)
And saying tan(20) = sin(20) /cos(20) is actually same as the tan in the smaller triangle

leaden tusk
#

your answer is way overcomplicated and is not how you solve these types of problems

neon iron
leaden tusk
#

i don't care

#

i said you were overcomplicating it and not making sense

topaz sinewBOT
#

@winged pond Has your question been resolved?

winged pond
#

for this question i got 1386.79 as my answer but im pretty sure i messed up where in my work

leaden tusk
#

looks good to me

winged pond
#

but appreantly its 909.39 ft

leaden tusk
#

ah i should've read the question lmfao

#

i just looked at your work

#

i think you may have mislabeled your angle?

winged pond
#

oh.

#

ohh

#

is it xtan51=1123

leaden tusk
#

yes

topaz sinewBOT
#

@winged pond Has your question been resolved?

#
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radiant tree
#

I have a question regarding strong induction if you can help me.

What's wrong with the following proof.

topaz sinewBOT
#

Please don't occupy multiple help channels.

radiant tree
#

I have a question regarding strong induction if you can help me.

What's wrong with the following proof.
Show that for all $n >= 0, n^2$ is even.
Base case: $n = 0 \implies 0\times 2 = 0 = 2\times p\times 0$
Assume by strong induction the proof is true for all $n \le k$.
Show that $(k+1)^2$ is even.

  1. $(k+1)^2 = ((k-1) + 2)^2$
  2. $((k-1) + 2)^2 = (k-1)^2 + 2\cdot(k-1) + 4$
  3. By inductive hypothesis, $(k-1)$ is even, thus $2\cdot(k-1) + 4$ is even.
  4. $(k+1)^2 = ((k-1) + 2)^2$
thorny flameBOT
#

Titan1190X

grim jacinth
#

Not all squares of positive integers are even

radiant tree
#

That I understand, I'm more confused conceptually as to why strong induction doesn't hold

#

The way I understood strong induction is that we can take all $n<=k$ as a given assumption for any proof. We don't have to show each case is true

thorny flameBOT
#

Titan1190X

radiant tree
#

But then something must be wrong with my understanding of strong induction, because if that was true this proof would be valid...?

keen venture
#

Okay, so let's apply this proof to prove that 1² is even

#

That would be k = 0 here

radiant tree
#

Then the proof wouldn't follow, that's fair

#

And we can do that for any consecutive value past the base case, I see

keen venture
#

Right. k-1 is not a member of our proven integers and it fails

radiant tree
#

🙏 thank you

#

I understand now

keen venture
#

But yes you understand correctly, strong induction should always work, if you avoid problems like that one

radiant tree
#

.close

topaz sinewBOT
#
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knotty sapphire
topaz sinewBOT
knotty sapphire
#

I have the first three derivatives to find the pattern

#

y'=-2sin(2x)

#

y"=-4cos(2x)

#

y"'=8sin(2x)

#

I took the odd power derivative and attempted the pattern above, I'm not quite sure how to find this derivative

sweet shard
#

-, -, +, +, -, -, +, + ...

knotty sapphire
#

I'm supposed to come up with a pattern that will solve the nth derivative of an odd power, for future test purposes

sweet shard
knotty sapphire
#

That is were I'm having trouble, I don't know how to express that pattern in terms of an equation

sweet shard
#

floor function might help

knotty sapphire
#

Sorry to disappoint, but I still don't understand how the floor function would help. I round to the number that is less than or equal to that number but how would that apply to that -,-,+,+ pattern?

topaz sinewBOT
#

@knotty sapphire Has your question been resolved?

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unreal sparrow
#

Indefinite Integral
Can someone check if I went wrong anywhere

covert flume
#

yep

#

Looks all good

unreal sparrow
#

K thnxx

topaz sinewBOT
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earnest cradle
topaz sinewBOT
earnest cradle
#

Could anyone help me with this

#

I am having a final test

drifting swift
#

you are having a final test right now?

earnest cradle
#

Tommorow

drifting swift
#

mkay...

#

so what are you having trouble with?

earnest cradle
#

What rule do we use

#

No but like how are we gonna find the answer

drifting swift
#

in both of these cases, you are dealing with what is known as a system of equations

#

do you know how to solve systems of equations?

earnest cradle
#

Yes

#

Like linear equations?

drifting swift
#

yes, in this case your equations are linear

#

so you have a linear system

#

in problem 2, the system is $\begin{cases} 20m = 50t \ m + t = 7 \end{cases}$

thorny flameBOT
earnest cradle
#

OH

#

yea go on

drifting swift
#

in problem 3 it's $\begin{cases} 20m = 50t \ t - m = -6 \end{cases}$

thorny flameBOT
drifting swift
#

solve these as you normally would, then find what is asked of you

earnest cradle
#

Alright ima find them and let you know

drifting swift
#

ok

thorny flameBOT
earnest cradle
#

Oh I love you guys

#

I solved both

#

It’s correct as it says in the book

#

In the book it has solved it in a proportion kind of way

#

Muah thank you

#

.close

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topaz sinewBOT
#
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rare isle
#

multiplication

restive inlet
#

that's a multiplication dot

worthy linden
#

Ok thanks

#

.close

topaz sinewBOT
#
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shadow bison
#

what does 'a' have to be for y=1/a-1 x2 to be a parabola and for it's focus to be at 0;2?

topaz sinewBOT
#

@shadow bison Has your question been resolved?

topaz sinewBOT
#

@shadow bison Has your question been resolved?

topaz sinewBOT
#

@shadow bison Has your question been resolved?

drifting swift
#

parentheses

#

y = 1/(a-1) * x^2

#

it should be clear that your curve is always a parabola

#

you can find the focus of y = kx^2 in terms of k and match it to your thing

topaz sinewBOT
#

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topaz sinewBOT
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wooden matrix
#

Don't ping right away.

#

It says wait 15 minutes.

stuck lintel
#

^

marsh slate
stuck lintel
#

So yes, it is in the rules. And it says you cannot.

#

(until after 15 min)

wooden matrix
#

If you're just gonna give answers, don't.

stuck lintel
#

No

#

Stop

wooden matrix
#

You made no effort to gauge understanding

#

So I doubt it.

tulip light
#

btw he just retyped the question I think?

wooden matrix
#

Yeah, they have a history of being a shit helper by just giving answers

stuck lintel
#

So how would you approach this inequality.

tulip light
#

oh

wooden matrix
#

But anyway, post your attempt at solving it

stuck lintel
#

(If you already have, what have you tried)

wooden matrix
#

Or explain your confusion

#

So you haven't attempted it?

#

So post your attempt

#

Like it says to.

#

Are you just chosing to have selective reading?

#

Test questions?

#

Are you writing a test rn?

#

Answer the question.

stuck lintel
#

This is getting better and better

wooden matrix
#

Answer what I'm asking

#

Are you writing a test? Yes or no?

mild oasis
#

So online test

stuck lintel
#

bruh

wooden matrix
#

<@&268886789983436800>

neon iron
#

can you not ask people for the address

stuck lintel
#

In the meanwhile, read up on academic ethics and integrity @digital stream

grim jacinth
#

Not sure what we expected from some guy named Stalin lol

vapid lichen
#

.close

topaz sinewBOT
#
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topaz sinewBOT
#
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warm geyser
#

Math Question:

**Jason purchased an item originally for $65 and decided to resell online. How much profit did he make?

The sold item was $50, shipping was charged to the buyer to the amount of [$6 shipping fees]. The Item cost in total was $56 and Platform fees were $3 deducted from the total.

The shipping cost that Jason paid separately after fees were taken out was in the amount of $5.

how much did he earn Show your work**

thorny flameBOT
#

hps
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

solemn wigeon
#

well

#

Profit = Revenue - Cost

#

so just find the revenue that he made and then subtract the total cost that he made

topaz sinewBOT
#

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topaz sinewBOT
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candid kindle
#

Anybody know how I can solve for y? Answer key solves for z first

candid kindle
#

I figured out how to do it using a system and got it right but anybody know if there’s an easier way?

#

The system I made

cursive flax
grim jacinth
#

I think that's the angle of the arc

#

Cut off by lines tangent to the circle

cursive flax
#

I thought too, just confirming

cosmic salmon
topaz sinewBOT
#

@candid kindle Has your question been resolved?

cursive flax
#

Better now

candid kindle
cursive flax
#

Gotcha

candid kindle
#

Then 64 74 and 90 are the angles of the triangle