#help-26
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Y is angle subtended at centre by those tangents ?
Or angle made at joining point of tangents
Here
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Salutations, i dont know how to find angle V
what's 3. 4
length of BC
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how do i find the big-O order of each growth rate
@glossy patrol Has your question been resolved?
do you not know any of them?
should probably read a chapter on what it means then. something like
https://brilliant.org/wiki/big-o-notation/
Big O notation is a notation used when talking about growth rates. It formalizes the notion that two functions "grow at the same rate," or one function "grows faster than the other," and such. It is very commonly used in computer science, when analyzing algorithms. Algorithms have a specific running time, usually declared as a function on its in...
ya ik them
but like for the first one would it be the greater function
so 4nlog (n)'s Big O
so O(n * log(n))
exponential growth function
as far as i know yes
if they mean 2^n with n = 10 then it would be O(2^n) otherwise it would be O(1)
Ok can someone help me with gaming
for 1c) is it O(2^n)
the log(n) is throwing me off
but i can just treat that as n right
<@&268886789983436800>
:/
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how does the action of canceling out work?
$\frac aa = 1$ when $a\neq 0$
You utilize this identity.
Wouldn't you still have 1 somewhere
is it the fact that
1 * (fractions) = same thing so need to put it?
If you wish to write an extra step
you can write 1* whatever for every cancellation
but 1 is the multiplicative identity
so it will not change anything
meaning it will go away in the next steps
@icy pilot Has your question been resolved?
Ok thanks
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Start by finding the common difference
then find the explicit form of the sequence
(come on, just one more person for the finishing step!)
(5x-11)-(2x-3) = 3x-8
An = A1 + (n-1)d

so 2009 = 2x-3 + (2008)3x-8?
x = 3?
@chilly kestrel
You can find the value of the common difference as a number with just the information you're given
I did find it
the common difference was 3x - 8
wait I found out that x = 4
so its 5,9,13
2009 = 5 + (n-1)4
Yup 🙂
Given the nth term of the sequence
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thanks
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so im on this law of cosine problem but for some reason its wrong ?
yeah ive check twice
i wrote it 380 but its 3800.865486 instead
i have no idea, what im doing wrong ??
Oh my bad
divide by 2
It's only 30
min
Lmao
I am blind I guess
Everything should be divide by 2. Cuz it travels from 2:00 pm to 2:30 pm. It takes half.
cos35 stay same
58/2 and 40/2. You should have answer from there
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the value of c (perfect square) in the trinomial y² - 18y + c | then the answer c written as a binomial
i ask again, what does "making binomial" mean
also nothing about this expression is "trinomial"
oh i stand corrected
then maybe the binomial is just y² + 81
show the entire question
pretty sure all you need to do is factor lmao
you missed the "squared" in "binomial squared"
this is a binomial (x-a)
this is a binomial squared (x-a)^2

expand (x-a)^2
a² + b?
right
so my answer is y² + 81?
you have (x^2 -2a + a^2)
which is this expanded
what don't you understand
about (x-a)^2 = x^2 - 2a + a^2 ?
could you tell me the answer
no
then explain it
he's trying
.
you're not listening
be a little more helpful than "i don't get it"
"what don't you understand" >"tell me answer"
cuz usually a is the first value
how am i supposed to know that?
and since its y² it'll be 1
you have the left hand side. figure out what t equals
9?
there, you're done
.
left hand side
(y-9)^2
i'm dumb founded
hello?
it's late and i really need to finish this but i'm not understanding what you're saying
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right
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expand this to be sure
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I don't understand this last part my notes. I need bit more explanation.
I just don't know wha it means by ×=5 not in the domain or where they even got 27/4 from
0
Result:
Infinity
Oh
When the denominator of a function is 0, we say that the expression is undefined
Because division by 0 is not defined within the real numbers
Oh
So to find the points at which an expression is undefined, you can set the denominator equal to 0, and those are the points which will not be a part of the domain
5 is undefined because it's 5/0
He can find h(x) though
h(x)=x+2/x-5
By finding a matrix A such that A^2=
(3 -8
-4 27)
Yep. What happens when x = 5?
That makes since but where did they get 27/4 from
One thing to notice is:
We know x = 5 is not possible for h(x). We exclude this from the domain.
That means when we compute h(h(x)), firstly x cannot be 5 for the inside h(x).
Secondly h(x) itself cannot be 5. Because we are inputting the inside h(x) as a parameter into the outside h.
That is the idea behind why there are 2 points we cannot input, and not just 1.
Oh okie that very helpful
I add this information with my notes
Thank you alot
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Explain why there does not exist a rational function $r$ such that $r(x) = 2^x$ for every real number x.
Jef Costello
A rational function is a function r such that $r(x) = \frac {p(x)}{q(x)}$, where $p$ and $q$ are polynomials, with $q\neq 0$
Jef Costello
exponential and logarithm functions
I have not much clue what the approach is meant to be
maybe repetitive differentiation
Suppose there is
then you can equate
and multiply both sides by q(x)
and do this ig
maybe theres a better approach
hmmm
another approach is to attempt bounding I guess
2^x is an exponential
these grow faster than polynomials
so you find a way to show this with inequalities
For example
q = 1
p = x^2
I can show that p < 2^x for any x greater than 10 for example
ahhh i have another idea
consider only integer inputs
2^x will keep doubling
You goal is to show p/q cannot keep doubling forever
I think this sounds easier but not totally sure hmm
Theres also the fact 2^x is a strictly increasing always positive function
I have an idea
Maybe you can show there is no such p/q that can satisfy this via differentiation
$r(x) = \frac {2^{x + 2}}{2^2}$
Jef Costello
Ahhh i have an actual solution finally 😂 but lets hear yours first
Of course not, if there exists p(x)/q(x)=2^x
yes yes that is the good and simple idea
Then limit of p(x)/q(x) when x approaches positive and minus infinitely respectively are (infinity, infinity ) or (0,0) or (non-zero real number , non-zero real number) but the limit of 2^x when x approaches positive and minus infinity respectively is (positive infinity,0) they don’t match.
that is good solution also
so with this we can look at the values of r(x) when mod(x) is bigger
Ah i was thinking this instead
consider r(2x) = r(x)^2
Then use an argument about mismatching degrees
oh okay
gotcha 
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Hello! I was wondering if I could get help on this "improper integral on an infinite domain" problem? I'm mainly just stuck on the actual integral part. I tried the u-substitution as shown but it seems to get more complicated so I'm lost lol.
@leaden frigate Has your question been resolved?
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How do I know when to apply sandwich/squeeze theorem over something else?
you typically don't know
for example I have the question lim x->infinity sinx/x
you try stuff and see what works
yeah that you should be able to use squeeze law on
so if I tried continuity first and it failed, then go to sandwich?
wdym tried continuity?
like uhh sorry i don't remember the proper name, still just learning, but when you can move the limit inside of a composite function if it's continuous
yeah that won't help
like lim x-> infinity sin x becoming sin lim x-> infinity x
Mosh
and then divide by x right?
Worth noticing that sin is not continuous at x = inf, whatever that might have meant. So the limit doesn't work that way
This too, you should never try to evaluate an infinite limit explicitly
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let n be 4
so
u6 = 2(u5) + u4
it looks like a term is sum of two times the previous term and the one 2 previous before
good now do the same for n=3
good now sub in values for u3 and u6 and you can solve simultaneous equatiosn
for n=4 you have
u6 = 2(u5) + u4
for n=3 you have
u5 = 2(u4) + u3
and you know u3=9 and u6=128 sub them into the above equations and solve
yep
systems of equations?
yes
lemme check
@neon iron Has your question been resolved?
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<@&286206848099549185>
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Hi so I need some math help, its comp math stuff not very difficult i think i just want someone to help me out and explain the thinking behind solving them and stuff
which one do you need help with?
all of them ig
lets start with the first one tho
do i have to do something with grouping?
try to see if you can make any of them perfect squares
I see x^2 - 9?
oooh so (x+4m)^2 ?
factor out 5p?
no
wait just factor the remaning quadratic right
lemme try to do that
so is it (-5p+3)^2
expand that, see if its correct
wait ahhh how do i factor again 😭
i have the right numbers just need the right signs
wait i think i got it yea
-(5p-3)^2
yea i was just doing a dumb way of factoring since i suck at doing it normally 😭
ok i got it
now
(x+4m)^2 * -(5p-3)^2
is that it?
R31_
ah ok so would i just multiply them like (x+4m)(5p-3) ?
DoomKing
DoomKing
what do you mean by that
yea im kind of confused im thinking i can just do (x+4m)^2 - (5p-3)^2 = (x+4m)(5p-3)... obv that makes no sense now im thinking about it
how do i make it into a product
do you know how to factor $m^2-n^2$
R31_
waittt i got it ahhhh ok so its (x+4m + 5p - 3)(x+4m - 5p +3) right
now it makes more sense lol
yep
sure
ok so how would i do the continued fraction thing that is.... very intimidating lol
try substituting x infinitely and tile them
(or just work from the bottom and simplify each fraction one by one)
or u can simplify the fraction
there are 2 solutions
what did you do?
acc i didnt do anything wrong i just guessed lol so how would u do it analytically again
do this
or this
if i did tiling what am i supposed to do to cancel it all
is the fraction repeating or is it just what you are given
yea i get this but how woudl i derive the actual number
its a continued fraction
then tiling is better imo
yea...
would u do a variable sub then?
no that would just bring us to where we started hmm
so the entire thing is x right
yes
so the smaller circle is..?
R31_
ohhhhhhhh ok ok ok ok broooo im so bad at seeing these patterns and stuff
and u would get x = 2 or x = 1
yes
for the continued fraction thing, would all comp math questions be similar like that
where u would be able to subsitute x like that
or would u have to do something else
you only get problems like those like not that much
and sometimes you cant just substitute x because you dont know if x exists, but comp math probably wont do that
hm ok thanks a lot for your help
i think im done for the day
i really appreciate everything u did now this stuff makes more sense
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How would I prove the statement?
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I don't understand
have you tried anything
No I just started the unit
the only knowledge I have so far is restrictions
Like repeating, vowels, first letter being a specific
for this I tried doing 9x8x7x6x5x4x3x2x1
first thing, don’t ask to ask, second thing, use the vacant help channel above
?
gonna give you a clue
- we have 9 switches
- each switch can be 0,1,2 (3 states)
then every switch, 3 states each
uhh was talking to another guy who slammed the question in the occupied channel
oh kk
why just 0,1,2
where did u get those #s from?
i just made those up so I can start representing switches with numbers
so that should be 120211011
oh, it is in the problem
ohh
moving 9 switches to any one of 3 positions
3 positions
makes sense
wait so u made up those numbers right 0,1,2?
can I do it with for ex
4,5,6
?
yes you can, if you can distinguish between 3 states
now we want to count how many numbers are like this
for example, 000000000 or 120102000
i will show you that later, for now let us solve this question
each switch has 3 positions, if you have two switches for example that would be
00,01,02,10,11,12,20,21,22
now try apply that to 9 switches
Same thing as u did right?
first switch = 3
second switch = 3
combination = 3*3 = 9
im still quite confused
from 1 to 9?
yes
now let’s start with the first switch
how many options do you think you have for the first switch
yes
same thing?
3, right?
ye
now you repeat this until the ninth switch
you will find that each switch has 3 options each
so to find the combinations of all nine switches
how would you do it
Ok so this is how I thought of it
since I'm using my three options
I only did the 3 options 6 different plates
let me show you
got 729
19683
okay thats right
ohh
OHH
sorry I thought the # I got from doing that was wrong
didnt notice it as an answer option
so I tried an opposite way
ended up with an answer that I saw on the options
I have 1 more quesiton
go on
so, what is the requirement of the word tho
wym
like if it needs to have one vowel, or one letter, or just freestyle
ok
this question
try using the same switch logics
firstly, how many option i can give a gold medal to 8 competitors?
1
yup
how about silver medal
let’s start again
we have 8 guys right here
and one gold medal
how many options you can give the gold medal
8
ok
now we have one guy getting a gold medal
how many options I could give a silver medal here
7
6
ok so we have
8 ways to give gold medal
7 ways to give silver medal
6 ways to give bronze medal
what will you do
ok
correct
now i wanna say, each of them is the subproblem of the last problem alright
first problem is, giving a gold medal
second problem is, giving a silver medal while one of them already got a medal
third problem, you can work that out
yeah it’s 336
Do you have any tips on what I should focus on
with counting methods
so i'm better in the future?
maybe start on how counting works
from addition principle and multiplication principle
ok ty
this will be really helpful and you will work out on combinations and permutations after this
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i just want to make sure i dont have the wrong idea about reduced echelon form, it just refers to 0 on top of the pivot column and below the pivot column right?
and echelon form only refers to 0 below the pivot columns?
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can someone check over my work? thanks
,rotate
if they are three consecutive terms in a geometric sequence then you are wrong
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I'm curious on how to solve this
@copper ether Has your question been resolved?
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Can anyone check my answer to this question pls?
,w integral of (9x-2)/(3sqrt(x))
yeah
ohhh
looks good
,w expand 2/3sqrt(x)(3x-2)
they're equivalent, yes
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would LM be LM=LE
Where all medians meet
LM won't be equal to LE, how is that even possible?
the whole line
Xd are you making random guesses?
no… it’s literally across LM
What about it?
it’s across LM
Are you saying LM=JM perhaps?
yes
Based on what?
I know what you mean, but why would you say something like that?
Is the triangle equilateral?
They can be equal, not necessarily always.
Let's stop that, and start solving your question without classifying tem equal.
They might be equal, we'll see if that's the case.
well LM=ME wouldn’t work as you said a part doesn’t = one whole the only thing that makes sense would be LM=JM bc i don’t see how anything else would work
So, do you know centroid divides the median in some ratio? What's it?
3
Wdym?
3 triangles have to intersect to make a centroid or am i wrong
Wrong yes you are.
This is what you said earlier.
yea
And now you have a different definition, how does that work?
doesn’t it take 3 triangles and where they all meet is what a centroid is
6
That is true, but you only have one triangle, it's a different story that the medians divide the triangle into multiple new triangles.
Okay, now I got what you're trying to say.
Okay, sure three triangles but that doesn't help the question.
What I'm asking is, the centroid is where the medians meet.
So what is the ratio the median is divided by the centroid.
EM:ML basically.
Have you studied something like this?
Wrong there are more. But that doesn't matter that's not your question.
@compact nest Has your question been resolved?
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Looking for some guidance
I believe I should first come up with the indefinite integral?
@wooden matrix
Yes.
Wait.
Thats a definite integral
@wooden matrix not sure what to do with the bounds in order to set up an indefinite integral.
It's area under a curve
Which is a definite integral
Hence why I said yes and not no
Thats what I think but the question is asking for an indefinite integral
@wooden matrix
It isnt
Read what I just said
@wooden matrix Its asking first for the indefinite integral, then it is asking to differentiate the indefinite, then lastly it says to apply the limits to the integration. It would seem that I am not using a definite integral until the last step.
@tired briar Has your question been resolved?
@tired briar Has your question been resolved?
<@&286206848099549185> Anyone available?
.close
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Hey can someone help me with Quadratics (math)
Really need it 💀
@round latch Has your question been resolved?
Post the question (math)
It'll heavily benefit us 💀
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I have this question. I can't figure out how they got from one step to the next. I tried looking in books and online, but still don't know
Do you know laws of exponents?
I think yes, learning it in school
So you don't necessarily need to follow this exact same procedure, your steps might be slightly different.
but even so, I have no idea how they get from fractions to integers
The answer you're getting is not an integer.
Although, I understand I'll explain a little.
First you have a fifth root of some ugly fraction.
And it's raised to -3 exponent.
Okay so let's forget the exponent and fifth root for now, and solve what's inside the parenthesis.
Alright?
okay
$\frac{\sqrt{2}\cdot\frac{1}{\sqrt{2}}}{\frac{1}{\sqrt[6]{2^5}}$
Rip
My god.
On mobile I can't do this shit.
I'll be back.
$\frac{\sqrt{2}\cdot\frac{1}{\sqrt{2}}}{\frac{1}{\sqrt[6]{2^5}}}$
Doggo
meant this or?
I just did not have one bracket, on mobile it's hard to realise thanks.
So @wicked steppe
When you divide the $\sqrt[6]{2^5}$ gets to the numerator do you know that?
Sakata Yaksha
yeah
well, how exactly it goes to that
Sakata Yaksha
Uhm so it's ad/bc
yeah sorry, autocorrect
Yeah, I got that.
$\frac{\sqrt{2}\cdot\frac{1}{\sqrt[3]{2}}}{\frac{1}{\sqrt[6]{2^5}}}$
Sakata Yaksha
Here a is sqrt 2, b is cube root 2 c is the 1 below and d is the last term.
okay
So it becomes ad/bc
okay, makes sense
It should, now look at what they did in the first step.
and to get rid of the negative square, you flip the fraction
ok, I think I get it now
I really hope you did, since my explanation didnt really help.
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with what values of x and y are the matrixes identical? probably have to show how i came to it
well if you compare A and B you can say x = 2 - y and 2x = y + 1 and then solve the system of equations
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<@&286206848099549185>
the radius would never be 0
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How is this wrong exactly?
Do you have work?
You don't need derivatives
And derivative of tan is 1/(1+x^2)
I have never in my life been tought the algebraic equivalent to any trig function
So outside of knowing those two things from the lecture
I'm lost
@toxic marsh Has your question been resolved?
<@&286206848099549185>
Okay so what we do is draw a triangle
We imagine that we have a triangle in quadrant 1 with theta as the angle
Since we have arcsin(x) we draw the triangle using opposite over hypotenuse with opposite being x and hypotenuse being 1
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Most likely overthinking this problem, but to solve this would you use Pythagorean theorem?
yes
yes
That would make it 18.78, but the question does not ask to round what should I put?
i think you messed up somewhere
Ok
wtf
the hypotenuse is always the longest side, so your calculation shouldn't be greater than 17
a^2=b^2+c^2
17^2=8^2+UT^2
UT=sqrt(289-64)=15
not 18.78
don't do people's work for them. #❓how-to-get-help #rules
same to you
youre mixing up a hypotenuse and a leg
See the 90* angle.
my bad i literally just joined.
Yes
i wont do it again
okay
first thing you should do upon joining = read the rules
good 👍
I actually am just trying to understand the concept not the answer
yea i skimmed over them lol
yes, me too trying to get you too the concept, not the answer. but nevermind
pythagorean theorem states that the sum of the squares of the two legs must equal the square of the hypotenuse for any right triangle
Yes
okay good
you seem to be thinking the side length 17 is a leg, but that's the hypotenuse
the hypotenuse is always located opposite the right angle
Ohhh I see so that makes 17 the hyp
yes
Makes so much more sense, thanks all
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I don’t really understand this question
I did something like this but I’m not sure if I’m correct..
@gray basin Has your question been resolved?
<@&286206848099549185>
looks good. probably should simplify $\sqrt{4}$
riemann
the side length isn't squared though
the side length is just $\sqrt{4}$
riemann
just like how the hypotenuse's length isn't 5. it's $\sqrt{5}$
riemann
It is Root 5 though
ok we're in agreement then
as long as you understand this
So how do I fix it?
remove the squares on square root of 1 and square root of 4
But that would make it 16 and 1 which is not equal to root 5
Oh sorry I get what you mean
Bruh…
Thanks for help
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Do I have these answers right so far?
i think you need to reevaluate the first and second problem
notice the dashed line in the composite figure, meaning that shape does not count towards the area of the composite figure
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phi here is a representation and i'm trying to show that phi_k is isomorphic to phi_k+8. How would I go about doing this?
i'm not sure how to show that there exist invertible f in Hom_G(phi_k,phi_k+8)
<@&286206848099549185>
@topaz egret Has your question been resolved?
What is phi_k+8? What do the matricies look like?
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I keep getting an answer of 35.78%, which rounds to 36%. The answer key says it's C) 38%. Can anyone confirm this answer? I redid the question multiple times and got the same answer.
@pulsar wyvern Has your question been resolved?
7 points is the most for these questions. :P
Lmao just a tedious, annoying question
maybe it's not that bad...
total area of the rectangle is
26 times 12-root-3-plus-1
where tf is my calculator
566.399852
the hexagons are just triangles
most the same size
the bottom is
1/2 times 6 times 3-root-3
...times 3
that's 27-root-3
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altogether the hexagons are 117-root-3
202.6499445
...and I got about 36%. 0.3577860124
answer key is a lie I guess. No way I messed that up, rite?
Idk bruh, I got 34 and I thought I was cracked
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what is the difference between SSres/SStot and 1-SSres/SStot in regards to calculating r^2. (SSres= residual sum of squares formula and SStot=total sum of squares formula)
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@kind fractal Has your question been resolved?
Did you try latex or its just some mathematical gibberish I don't know abt? 
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if the intersection of any finite number of open sets sets is open, how does it follow from that that the union of any finite number of closed sets is a closed set?
@spiral saffron Has your question been resolved?
