#help-26

226100 messages · Page 241 of 227

cursive flax
#

We just need 64° and 146° and tangent theorems (two) to find angle y

candid kindle
#

So is the system I made the right way to do that?

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Or is there a better way

topaz sinewBOT
#
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cursive flax
#

Y is angle subtended at centre by those tangents ?

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Or angle made at joining point of tangents

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Here

topaz sinewBOT
#
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neon iron
topaz sinewBOT
neon iron
#

Salutations, i dont know how to find angle V

mellow venture
#

what's 3. 4

neon iron
#

length of BC

cursive flax
#

BC is median?

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Or any other info given apart from measurements

neon iron
#

3.4 is lenght from B to C

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well, i sent the assignment, ty regardless

#

.close

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glossy patrol
#

how do i find the big-O order of each growth rate

topaz sinewBOT
#

@glossy patrol Has your question been resolved?

sweet shard
#

should probably read a chapter on what it means then. something like
https://brilliant.org/wiki/big-o-notation/

Big O notation is a notation used when talking about growth rates. It formalizes the notion that two functions "grow at the same rate," or one function "grows faster than the other," and such. It is very commonly used in computer science, when analyzing algorithms. Algorithms have a specific running time, usually declared as a function on its in...

glossy patrol
#

but like for the first one would it be the greater function

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so 4nlog (n)'s Big O

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so O(n * log(n))

tough nest
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yes

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the + 2n is negligable at huge n

glossy patrol
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so 1a.) is O(n * log n)

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would 1b) be 2^n

tough nest
#

well no

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it doesn't contain an n

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unless that is implicit

glossy patrol
#

exponential growth function

glossy patrol
#

that is it just a constant

tough nest
#

2^10 is just a number

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at huge n it's still just a number

glossy patrol
#

constant

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so O(1)?

tough nest
#

as far as i know yes

glossy patrol
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so O(1) if explicit

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and O(2^n) if implciit

tough nest
#

if they mean 2^n with n = 10 then it would be O(2^n) otherwise it would be O(1)

idle flax
#

Ok can someone help me with gaming

glossy patrol
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the log(n) is throwing me off

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but i can just treat that as n right

tired spear
#

<@&268886789983436800>

mellow venture
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:/

topaz sinewBOT
#

@glossy patrol Has your question been resolved?

topaz sinewBOT
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icy pilot
topaz sinewBOT
icy pilot
#

how does the action of canceling out work?

vital relic
#

$\frac aa = 1$ when $a\neq 0$

thorny flameBOT
vital relic
#

You utilize this identity.

icy pilot
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Wouldn't you still have 1 somewhere

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is it the fact that

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1 * (fractions) = same thing so need to put it?

vital relic
#

If you wish to write an extra step

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you can write 1* whatever for every cancellation

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but 1 is the multiplicative identity

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so it will not change anything

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meaning it will go away in the next steps

topaz sinewBOT
#

@icy pilot Has your question been resolved?

icy pilot
#

Ok thanks

topaz sinewBOT
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topaz sinewBOT
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neon iron
topaz sinewBOT
grim jacinth
#

Start by finding the common difference

chilly kestrel
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then find the explicit form of the sequence

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(come on, just one more person for the finishing step!)

neon iron
neon iron
#

so 2009 = 2x-3 + (2008)3x-8?

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x = 3?

#

@chilly kestrel

grim jacinth
#

You can find the value of the common difference as a number with just the information you're given

neon iron
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I did find it

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the common difference was 3x - 8

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wait I found out that x = 4

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so its 5,9,13

grim jacinth
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Yup - now you can find 2009

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It'll be a bit far down the sequence, though

neon iron
#

2009 = 5 + (n-1)4

grim jacinth
#

Yup 🙂

neon iron
#

502...?

grim jacinth
#

Given the nth term of the sequence

neon iron
#

.close

topaz sinewBOT
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neon iron
#

thanks

topaz sinewBOT
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lunar girder
#

so im on this law of cosine problem but for some reason its wrong ?

lunar girder
glossy portal
#

check ur calculation

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Make sure ur in degree mode

lunar girder
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yeah ive check twice

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i wrote it 380 but its 3800.865486 instead

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i have no idea, what im doing wrong ??

glossy portal
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Oh my bad

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divide by 2

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It's only 30

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min

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Lmao

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I am blind I guess

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Everything should be divide by 2. Cuz it travels from 2:00 pm to 2:30 pm. It takes half.

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cos35 stay same

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58/2 and 40/2. You should have answer from there

lunar girder
#

okok

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omg yeah

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thanks i didnt even think about it the time difference

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gritty laurel
#

the value of c (perfect square) in the trinomial y² - 18y + c | then the answer c written as a binomial

gritty laurel
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i got the value c

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which is 81

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i need help making the binomial

sweet shard
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i ask again, what does "making binomial" mean

sweet shard
gritty laurel
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according to the question

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that is a trinomial

sweet shard
#

oh i stand corrected

gritty laurel
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then maybe the binomial is just y² + 81

sweet shard
#

show the entire question

leaden tusk
#

pretty sure all you need to do is factor lmao

gritty laurel
leaden tusk
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yep

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the wonders of knowing the full question instead of 80% of the full question

sweet shard
#

you missed the "squared" in "binomial squared"

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this is a binomial (x-a)

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this is a binomial squared (x-a)^2

gritty laurel
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so?

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what now

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81²?

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@leaden tusk i'm still lost who

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that's the second answer

sweet shard
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expand (x-a)^2

gritty laurel
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bro that just confuses me more

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cuz a is 1

sweet shard
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do you know what binomial is?

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write an example of a binomial

gritty laurel
#

a² + b?

sweet shard
#

right

gritty laurel
#

so my answer is y² + 81?

sweet shard
#

you have (x^2 -2a + a^2)

sweet shard
gritty laurel
#

sigh i'm still lost

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what are u trying to say

sweet shard
#

about (x-a)^2 = x^2 - 2a + a^2 ?

gritty laurel
#

could you tell me the answer

sweet shard
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no

gritty laurel
#

then explain it

leaden tusk
#

he's trying

sweet shard
leaden tusk
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you're not listening

gritty laurel
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i am

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i'm just not understanding

sweet shard
#

be a little more helpful than "i don't get it"

leaden tusk
#

"what don't you understand" >"tell me answer"

gritty laurel
#

cuz usually a is the first value

sweet shard
#

how am i supposed to know that?

gritty laurel
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and since its y² it'll be 1

sweet shard
#

pick another letter

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(x-t)^2 = x^2 - 2t + t^2

sweet shard
gritty laurel
#

9?

sweet shard
#

there, you're done

sweet shard
gritty laurel
#

so it's y² + 9²

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?

sweet shard
gritty laurel
#

(y-9)^2

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i'm dumb founded

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hello?

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it's late and i really need to finish this but i'm not understanding what you're saying

#

.close

topaz sinewBOT
#
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sweet shard
topaz sinewBOT
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sweet shard
topaz sinewBOT
sweet shard
#

.close

topaz sinewBOT
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fierce harbor
#

I don't understand this last part my notes. I need bit more explanation.

fierce harbor
#

I just don't know wha it means by ×=5 not in the domain or where they even got 27/4 from

narrow torrent
#

Ok. Let me ask you something.

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What is 1/0?

fierce harbor
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0

narrow torrent
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Are you sure

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,calc 1/0

thorny flameBOT
#

Result:

Infinity
fierce harbor
#

Oh

narrow torrent
#

When the denominator of a function is 0, we say that the expression is undefined

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Because division by 0 is not defined within the real numbers

fierce harbor
#

Oh

narrow torrent
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So to find the points at which an expression is undefined, you can set the denominator equal to 0, and those are the points which will not be a part of the domain

fierce harbor
#

5 is undefined because it's 5/0

narrow torrent
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Not quite

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What is h(x)

vale jacinth
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He can find h(x) though

fierce harbor
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h(x)=x+2/x-5

vale jacinth
#

By finding a matrix A such that A^2=
(3 -8
-4 27)

narrow torrent
#

Yep. What happens when x = 5?

fierce harbor
#

5-5 will be 0

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The denominator going be 0

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Right

narrow torrent
#

(5+2)/(5-5)

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Which is 7/0

fierce harbor
#

That makes since but where did they get 27/4 from

narrow torrent
#

By setting the denominator of h(h(x)) equal to 0

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h(h(x)) = (3x-8)/(-4x+27)

vital relic
#

One thing to notice is:
We know x = 5 is not possible for h(x). We exclude this from the domain.

That means when we compute h(h(x)), firstly x cannot be 5 for the inside h(x).

Secondly h(x) itself cannot be 5. Because we are inputting the inside h(x) as a parameter into the outside h.

That is the idea behind why there are 2 points we cannot input, and not just 1.

fierce harbor
#

Oh so -4(27/4)+27 equals 0

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Now I understand

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Thanks

fierce harbor
#

I add this information with my notes

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Thank you alot

#

.close

topaz sinewBOT
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normal marsh
#

Explain why there does not exist a rational function $r$ such that $r(x) = 2^x$ for every real number x.

thorny flameBOT
#

Jef Costello

vital relic
#

,w rational function

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can you define it

normal marsh
#

A rational function is a function r such that $r(x) = \frac {p(x)}{q(x)}$, where $p$ and $q$ are polynomials, with $q\neq 0$

thorny flameBOT
#

Jef Costello

vital relic
#

feels like an odd question to me

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topic?

normal marsh
#

exponential and logarithm functions

vital relic
#

I have not much clue what the approach is meant to be

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maybe repetitive differentiation

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Suppose there is

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then you can equate

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and multiply both sides by q(x)

vital relic
#

maybe theres a better approach

normal marsh
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hmmm

vital relic
#

another approach is to attempt bounding I guess

normal marsh
#

okay

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how does that work?

vital relic
#

2^x is an exponential

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these grow faster than polynomials

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so you find a way to show this with inequalities

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For example
q = 1
p = x^2

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I can show that p < 2^x for any x greater than 10 for example

vital relic
#

2^x will keep doubling

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You goal is to show p/q cannot keep doubling forever

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I think this sounds easier but not totally sure hmm

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Theres also the fact 2^x is a strictly increasing always positive function

normal marsh
#

I have an idea

vital relic
#

Maybe you can show there is no such p/q that can satisfy this via differentiation

normal marsh
#

$r(x) = \frac {2^{x + 2}}{2^2}$

thorny flameBOT
#

Jef Costello

vital relic
#

Ahhh i have an actual solution finally 😂 but lets hear yours first

vale jacinth
#

Of course not, if there exists p(x)/q(x)=2^x

vital relic
#

yes yes that is the good and simple idea

vale jacinth
#

Then limit of p(x)/q(x) when x approaches positive and minus infinitely respectively are (infinity, infinity ) or (0,0) or (non-zero real number , non-zero real number) but the limit of 2^x when x approaches positive and minus infinity respectively is (positive infinity,0) they don’t match.

vital relic
#

that is good solution also

normal marsh
vital relic
#

Ah i was thinking this instead

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consider r(2x) = r(x)^2

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Then use an argument about mismatching degrees

normal marsh
#

oh okay

topaz sinewBOT
#

@normal marsh Has your question been resolved?

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topaz sinewBOT
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leaden frigate
#

Hello! I was wondering if I could get help on this "improper integral on an infinite domain" problem? I'm mainly just stuck on the actual integral part. I tried the u-substitution as shown but it seems to get more complicated so I'm lost lol.

topaz sinewBOT
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@leaden frigate Has your question been resolved?

leaden frigate
#

.close

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tawdry steppe
#

How do I know when to apply sandwich/squeeze theorem over something else?

wooden matrix
#

you typically don't know

tawdry steppe
#

for example I have the question lim x->infinity sinx/x

wooden matrix
#

you try stuff and see what works

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yeah that you should be able to use squeeze law on

tawdry steppe
#

so if I tried continuity first and it failed, then go to sandwich?

wooden matrix
#

wdym tried continuity?

tawdry steppe
#

like uhh sorry i don't remember the proper name, still just learning, but when you can move the limit inside of a composite function if it's continuous

wooden matrix
#

yeah that won't help

tawdry steppe
#

like lim x-> infinity sin x becoming sin lim x-> infinity x

wooden matrix
#

yeah that's just false

#

but yeah, you can use squeeze law

#

$-1\leq\sin(x)\leq 1$

thorny flameBOT
tawdry steppe
#

and then divide by x right?

wooden matrix
#

yes since x is not 0

#

cause we're going out to infinity

keen venture
wooden matrix
#

This too, you should never try to evaluate an infinite limit explicitly

tawdry steppe
#

ok thanks

#

.close

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neon iron
topaz sinewBOT
topaz egret
#

try letting n=4 and see what you find

#

does that help?

neon iron
#

@topaz egret

#

like let the total be 4 or n be 4

topaz egret
#

let n be 4

neon iron
#

so

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u6 = 2(u5) + u4

#

it looks like a term is sum of two times the previous term and the one 2 previous before

topaz egret
#

good now do the same for n=3

neon iron
#

u5 = 2(u4) + u3

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u5 = 2(u4) + 9

topaz egret
#

good now sub in values for u3 and u6 and you can solve simultaneous equatiosn

neon iron
#

what does that mean

#

what values do I sub in

#

@topaz egret

topaz egret
#

for n=4 you have
u6 = 2(u5) + u4
for n=3 you have
u5 = 2(u4) + u3
and you know u3=9 and u6=128 sub them into the above equations and solve

neon iron
#

oh ok

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128 = 2(u5) + u4

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u5 = 2(u4) + 9

topaz egret
#

yep

neon iron
#

systems of equations?

topaz egret
#

yes

neon iron
#

ok

#

👍

#

uh

#

I got u4 = 22

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and 5u = 53

#

@topaz egret

topaz egret
#

lemme check

neon iron
#

is that correect?

#

oke

topaz egret
#

yep

#

all good

novel stratus
#

I was able to get up to not q or p

#

<@&286206848099549185>

topaz sinewBOT
#

@neon iron Has your question been resolved?

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prime hollow
topaz sinewBOT
#

@prime hollow Has your question been resolved?

prime hollow
#

<@&286206848099549185>

prime hollow
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remote vector
#

Hi so I need some math help, its comp math stuff not very difficult i think i just want someone to help me out and explain the thinking behind solving them and stuff

remote vector
#

especially for probobility

#

like how would i do this

marsh slate
#

which one do you need help with?

remote vector
#

all of them ig

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lets start with the first one tho

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do i have to do something with grouping?

marsh slate
#

the first one i dont see the entire problem

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is the po polynimials?

remote vector
#

mb

#

yea its polynomials

marsh slate
#

try to see if you can make any of them perfect squares

remote vector
#

I see x^2 - 9?

marsh slate
#

thats difference of squares

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look at x^2, m^2, and xm terms

remote vector
#

oooh so (x+4m)^2 ?

marsh slate
#

yea

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so the rest of the expression are p terms

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what can you do with them

remote vector
#

factor out 5p?

marsh slate
#

no

remote vector
#

wait just factor the remaning quadratic right

#

lemme try to do that

#

so is it (-5p+3)^2

marsh slate
remote vector
#

wait ahhh how do i factor again 😭

#

i have the right numbers just need the right signs

#

wait i think i got it yea

#

-(5p-3)^2

neon iron
#

FOIL to expand

#

ac=b to factor

remote vector
#

yea i was just doing a dumb way of factoring since i suck at doing it normally 😭

#

ok i got it

#

now

#

(x+4m)^2 * -(5p-3)^2

#

is that it?

marsh slate
#

you need a product

#

so now you have $(x+4m)^2-(5p-3)^2$

thorny flameBOT
remote vector
#

ah ok so would i just multiply them like (x+4m)(5p-3) ?

neon iron
#
  • carries to the outside
#

$(x+4m)^2*-1(5p-3)^2$

thorny flameBOT
#

DoomKing

neon iron
#

is what you actually have

#

which contracts to $-(x+4m)(5p-3)$

thorny flameBOT
#

DoomKing

marsh slate
#

no

#

the 2 square terms are subtracting

#

not multiplying

neon iron
#

oh wait i misread the question

#

woops

marsh slate
remote vector
#

yea im kind of confused im thinking i can just do (x+4m)^2 - (5p-3)^2 = (x+4m)(5p-3)... obv that makes no sense now im thinking about it

#

how do i make it into a product

marsh slate
#

do you know how to factor $m^2-n^2$

thorny flameBOT
remote vector
#

waittt i got it ahhhh ok so its (x+4m + 5p - 3)(x+4m - 5p +3) right

#

now it makes more sense lol

remote vector
#

that would be my final answer

marsh slate
#

yep

remote vector
#

oh ok thx for that

#

r u able to help me with the other problems or?

marsh slate
#

sure

remote vector
#

ok so how would i do the continued fraction thing that is.... very intimidating lol

marsh slate
#

try substituting x infinitely and tile them

#

(or just work from the bottom and simplify each fraction one by one)

neon iron
#

or u can simplify the fraction

remote vector
#

wait

#

is x 1

#

i feel like i did something wrong

marsh slate
#

there are 2 solutions

marsh slate
remote vector
#

acc i didnt do anything wrong i just guessed lol so how would u do it analytically again

marsh slate
remote vector
#

if i did tiling what am i supposed to do to cancel it all

marsh slate
#

if you tile them youd get this right

neon iron
#

is the fraction repeating or is it just what you are given

remote vector
# marsh slate

yea i get this but how woudl i derive the actual number

remote vector
neon iron
#

then tiling is better imo

marsh slate
#

notice that the 2 circles are the same thing

remote vector
#

yea...

#

would u do a variable sub then?

#

no that would just bring us to where we started hmm

marsh slate
#

so the entire thing is x right

remote vector
#

yes

marsh slate
#

so the smaller circle is..?

remote vector
#

also x?

#

since they repeat

marsh slate
#

yea

#

so $\frac{2}{3-x}=x$

thorny flameBOT
remote vector
#

ohhhhhhhh ok ok ok ok broooo im so bad at seeing these patterns and stuff

#

and u would get x = 2 or x = 1

marsh slate
#

yes

remote vector
#

for the continued fraction thing, would all comp math questions be similar like that

#

where u would be able to subsitute x like that

#

or would u have to do something else

marsh slate
#

you only get problems like those like not that much

#

and sometimes you cant just substitute x because you dont know if x exists, but comp math probably wont do that

remote vector
#

hm ok thanks a lot for your help

#

i think im done for the day

#

i really appreciate everything u did now this stuff makes more sense

#

.close

topaz sinewBOT
#
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stuck sorrel
#

How would I prove the statement?

topaz sinewBOT
stuck sorrel
#

Nevermind I have successfully done it

#

.close

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graceful elk
topaz sinewBOT
graceful elk
#

I don't understand

leaden tusk
#

have you tried anything

graceful elk
#

No I just started the unit

#

the only knowledge I have so far is restrictions

#

Like repeating, vowels, first letter being a specific

#

for this I tried doing 9x8x7x6x5x4x3x2x1

teal sigil
#

first thing, don’t ask to ask, second thing, use the vacant help channel above

graceful elk
#

?

teal sigil
teal sigil
# graceful elk ?

uhh was talking to another guy who slammed the question in the occupied channel

graceful elk
#

oh kk

graceful elk
#

where did u get those #s from?

teal sigil
#

i just made those up so I can start representing switches with numbers

teal sigil
graceful elk
#

Why is it only 3 states only

#

is that made up too

#

?

teal sigil
#

oh, it is in the problem

graceful elk
#

ohh

teal sigil
#

moving 9 switches to any one of 3 positions

graceful elk
#

3 positions

#

makes sense

#

wait so u made up those numbers right 0,1,2?

#

can I do it with for ex

#

4,5,6

#

?

teal sigil
#

yes you can, if you can distinguish between 3 states

graceful elk
#

will all give the same answer tho

#

because would it not make sense

teal sigil
#

for example, 000000000 or 120102000

teal sigil
graceful elk
#

okk

#

ok so 3 positions

teal sigil
#

each switch has 3 positions, if you have two switches for example that would be
00,01,02,10,11,12,20,21,22

#

now try apply that to 9 switches

graceful elk
#

Same thing as u did right?

teal sigil
graceful elk
#

im still quite confused

teal sigil
#

let me start over

#

imagine you are flicking that switches

graceful elk
#

from 1 to 9?

teal sigil
#

yes

#

now let’s start with the first switch

#

how many options do you think you have for the first switch

graceful elk
#

1

#

wait

#

2

#

NVM 3

#

because there is a top middle and down

#

?

teal sigil
#

yes

graceful elk
#

u can stop at each of those

#

mhm

teal sigil
#

now how about the second switch

#

how many options do you think you have

graceful elk
#

same thing?

teal sigil
#

3, right?

graceful elk
#

ye

teal sigil
#

now you repeat this until the ninth switch

#

you will find that each switch has 3 options each

#

so to find the combinations of all nine switches

#

how would you do it

graceful elk
#

Ok so this is how I thought of it

#

since I'm using my three options

#

I only did the 3 options 6 different plates

#

let me show you

#

got 729

teal sigil
#

okay

#

how about 9 switches

graceful elk
#

19683

teal sigil
#

okay thats right

graceful elk
#

ohh

#

OHH

#

sorry I thought the # I got from doing that was wrong

#

didnt notice it as an answer option

#

so I tried an opposite way

#

ended up with an answer that I saw on the options

#

I have 1 more quesiton

teal sigil
#

go on

graceful elk
teal sigil
#

so, what is the requirement of the word tho

graceful elk
#

wym

teal sigil
#

like if it needs to have one vowel, or one letter, or just freestyle

teal sigil
#

ok

#

this question

#

try using the same switch logics

#

firstly, how many option i can give a gold medal to 8 competitors?

graceful elk
#

3

#

gold, silver, and bronze

teal sigil
#

nope

#

i mean just the gold medal

graceful elk
#

1

teal sigil
#

let me tell you, it is 8

#

you pick one from 8 competitors to get 1 gold medal

graceful elk
#

yup

teal sigil
#

how about silver medal

graceful elk
#

just 1 aswell

#

can't be 2 people winning 2nd

teal sigil
#

let’s start again

#

we have 8 guys right here

#

and one gold medal

#

how many options you can give the gold medal

graceful elk
#

8

teal sigil
#

ok

#

now we have one guy getting a gold medal

#

how many options I could give a silver medal here

graceful elk
#

7

teal sigil
#

yeah, now without image

#

how about the bronze medal, how many options

graceful elk
#

6

teal sigil
#

ok so we have
8 ways to give gold medal
7 ways to give silver medal
6 ways to give bronze medal

#

what will you do

graceful elk
#

multiply them

#

8 x 7 x 6

teal sigil
#

ok

#

correct

#

now i wanna say, each of them is the subproblem of the last problem alright

#

first problem is, giving a gold medal

#

second problem is, giving a silver medal while one of them already got a medal

#

third problem, you can work that out

graceful elk
#

so the answer isnt 316

#

?

#

336*

teal sigil
#

yeah it’s 336

graceful elk
#

Do you have any tips on what I should focus on

#

with counting methods

#

so i'm better in the future?

teal sigil
#

maybe start on how counting works

#

from addition principle and multiplication principle

graceful elk
#

ok ty

teal sigil
#

this will be really helpful and you will work out on combinations and permutations after this

topaz sinewBOT
#

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#
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mortal jackal
#

i just want to make sure i dont have the wrong idea about reduced echelon form, it just refers to 0 on top of the pivot column and below the pivot column right?

mortal jackal
#

and echelon form only refers to 0 below the pivot columns?

topaz sinewBOT
#

@mortal jackal Has your question been resolved?

mortal jackal
#

.close

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neon iron
topaz sinewBOT
neon iron
#

can someone check over my work? thanks

hollow hedge
#

,rotate

thorny flameBOT
hollow hedge
#

if they are three consecutive terms in a geometric sequence then you are wrong

topaz sinewBOT
#

@neon iron Has your question been resolved?

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copper ether
#

I'm curious on how to solve this

topaz sinewBOT
#

@copper ether Has your question been resolved?

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neon iron
#

Can anyone check my answer to this question pls?

leaden tusk
#

,w integral of (9x-2)/(3sqrt(x))

thorny flameBOT
leaden tusk
#

yeah

neon iron
#

ohhh

leaden tusk
#

looks good

neon iron
#

okay!

#

so its fine in the format I've written it?

leaden tusk
#

,w expand 2/3sqrt(x)(3x-2)

thorny flameBOT
leaden tusk
#

they're equivalent, yes

neon iron
#

okay, thanks!

#

.close

topaz sinewBOT
#
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compact nest
#

would LM be LM=LE

topaz sinewBOT
static void
#

,w centroid triangle

#

@compact nest what's the definition for centroid of a triangle

compact nest
#

Where all medians meet

abstract wadi
compact nest
#

the whole line

abstract wadi
#

LM is a part of LE.

#

How can a part be equal to whole?

compact nest
#

it can’t

#

so JM then

abstract wadi
#

Xd are you making random guesses?

compact nest
#

no… it’s literally across LM

abstract wadi
compact nest
#

it’s across LM

abstract wadi
#

Are you saying LM=JM perhaps?

compact nest
#

yes

abstract wadi
#

Based on what?

compact nest
abstract wadi
#

I know what you mean, but why would you say something like that?

#

Is the triangle equilateral?

#

They can be equal, not necessarily always.

#

Let's stop that, and start solving your question without classifying tem equal.

#

They might be equal, we'll see if that's the case.

compact nest
#

well LM=ME wouldn’t work as you said a part doesn’t = one whole the only thing that makes sense would be LM=JM bc i don’t see how anything else would work

abstract wadi
#

So, do you know centroid divides the median in some ratio? What's it?

compact nest
#

3

abstract wadi
#

Wdym?

compact nest
#

3 triangles have to intersect to make a centroid or am i wrong

abstract wadi
#

Wrong yes you are.

abstract wadi
compact nest
#

yea

abstract wadi
#

And now you have a different definition, how does that work?

compact nest
#

doesn’t it take 3 triangles and where they all meet is what a centroid is

abstract wadi
#

In your original figure, how many triangles do you have?

#

Well?

compact nest
#

6

abstract wadi
#

Okay, now I got what you're trying to say.

#

Okay, sure three triangles but that doesn't help the question.
What I'm asking is, the centroid is where the medians meet.

#

So what is the ratio the median is divided by the centroid.

#

EM:ML basically.

#

Have you studied something like this?

abstract wadi
# compact nest 6

Wrong there are more. But that doesn't matter that's not your question.

topaz sinewBOT
#

@compact nest Has your question been resolved?

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tired briar
#

Looking for some guidance

topaz sinewBOT
tired briar
#

I believe I should first come up with the indefinite integral?

wooden matrix
#

Yes

#

You should set up the integral first

tired briar
#

@wooden matrix

wooden matrix
#

Yes.

tired briar
#

Wait.

#

Thats a definite integral

#

@wooden matrix not sure what to do with the bounds in order to set up an indefinite integral.

wooden matrix
#

It's area under a curve

#

Which is a definite integral

#

Hence why I said yes and not no

tired briar
#

Thats what I think but the question is asking for an indefinite integral

#

@wooden matrix

wooden matrix
#

Read what I just said

tired briar
#

@wooden matrix Its asking first for the indefinite integral, then it is asking to differentiate the indefinite, then lastly it says to apply the limits to the integration. It would seem that I am not using a definite integral until the last step.

wooden matrix
#

The question you posted wants a definite integral

#

And stop pinging every message

tired briar
#

<@&286206848099549185> Looking for some guidance with a calculus question. Thanks.

topaz sinewBOT
#

@tired briar Has your question been resolved?

topaz sinewBOT
#

@tired briar Has your question been resolved?

tired briar
#

<@&286206848099549185> Anyone available?

tired briar
#

.close

topaz sinewBOT
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round latch
#

Hey can someone help me with Quadratics (math)
Really need it 💀

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@round latch Has your question been resolved?

rich fossil
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wicked steppe
#

I have this question. I can't figure out how they got from one step to the next. I tried looking in books and online, but still don't know

abstract wadi
#

Do you know laws of exponents?

wicked steppe
#

I think yes, learning it in school

abstract wadi
#

So you don't necessarily need to follow this exact same procedure, your steps might be slightly different.

wicked steppe
#

but even so, I have no idea how they get from fractions to integers

abstract wadi
#

The answer you're getting is not an integer.

#

Although, I understand I'll explain a little.

#

First you have a fifth root of some ugly fraction.

#

And it's raised to -3 exponent.

#

Okay so let's forget the exponent and fifth root for now, and solve what's inside the parenthesis.

#

Alright?

wicked steppe
#

okay

abstract wadi
#

$\frac{\sqrt{2}\cdot\frac{1}{\sqrt{2}}}{\frac{1}{\sqrt[6]{2^5}}$

#

Rip

#

My god.

#

On mobile I can't do this shit.

#

I'll be back.

tulip light
#

$\frac{\sqrt{2}\cdot\frac{1}{\sqrt{2}}}{\frac{1}{\sqrt[6]{2^5}}}$

thorny flameBOT
tulip light
#

meant this or?

abstract wadi
#

I just did not have one bracket, on mobile it's hard to realise thanks.

#

So @wicked steppe

abstract wadi
thorny flameBOT
#

Sakata Yaksha

wicked steppe
#

yeah

abstract wadi
#

So that is exactly what the first step is.

#

Do you see that?

#

Well?

wicked steppe
#

well, how exactly it goes to that

abstract wadi
#

$\frac{a}{b}$ divided by $\frac{c}{d}$

#

How would you do this?

thorny flameBOT
#

Sakata Yaksha

wicked steppe
#

a/b * d/c = ad/bc

#

?

abstract wadi
#

Uhm so it's ad/bc

wicked steppe
#

yeah sorry, autocorrect

abstract wadi
#

Yeah, I got that.

#

$\frac{\sqrt{2}\cdot\frac{1}{\sqrt[3]{2}}}{\frac{1}{\sqrt[6]{2^5}}}$

thorny flameBOT
#

Sakata Yaksha

abstract wadi
#

Here a is sqrt 2, b is cube root 2 c is the 1 below and d is the last term.

wicked steppe
#

okay

abstract wadi
#

So it becomes ad/bc

wicked steppe
#

okay, makes sense

abstract wadi
#

It should, now look at what they did in the first step.

wicked steppe
#

and to get rid of the negative square, you flip the fraction

#

ok, I think I get it now

abstract wadi
#

I really hope you did, since my explanation didnt really help.

wicked steppe
#

it did, thank you for your help

#

.close

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#
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broken wren
#

with what values of x and y are the matrixes identical? probably have to show how i came to it

gentle owl
#

well if you compare A and B you can say x = 2 - y and 2x = y + 1 and then solve the system of equations

broken wren
#

oh okay. imma try

#

thanks it worked

#

.close

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misty heron
topaz sinewBOT
misty heron
#

<@&286206848099549185>

wooden matrix
#

the radius would never be 0

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#

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toxic marsh
topaz sinewBOT
toxic marsh
#

Tangent is 1/(1+x^2)

#

And I know what cosine is but idk what sine or arc sine is

topaz sinewBOT
#

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toxic marsh
topaz sinewBOT
toxic marsh
#

How is this wrong exactly?

grim jacinth
#

Do you have work?

toxic marsh
#

They thought me 2 things that lecture

#

Derivative of arcsine is 1/sqrt(1-x^2)

grim jacinth
#

You don't need derivatives

toxic marsh
#

And derivative of tan is 1/(1+x^2)

#

I have never in my life been tought the algebraic equivalent to any trig function

#

So outside of knowing those two things from the lecture

#

I'm lost

topaz sinewBOT
#

@toxic marsh Has your question been resolved?

toxic marsh
#

<@&286206848099549185>

pulsar heron
#

Okay so what we do is draw a triangle

#

We imagine that we have a triangle in quadrant 1 with theta as the angle

#

Since we have arcsin(x) we draw the triangle using opposite over hypotenuse with opposite being x and hypotenuse being 1

toxic marsh
#

Ok

#

Do I need to find adjacent?

pulsar heron
#

Yep

#

Then u find the tangent of that angle theta

toxic marsh
#

Sqrt(1-x^2)

#

Is the adjacent

#

X/(sqrt(1-x^2))

#

Got it

#

Ty so much

#

.close

topaz sinewBOT
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tidal cypress
#

Most likely overthinking this problem, but to solve this would you use Pythagorean theorem?

leaden tusk
#

yes

tidal cypress
# neon iron yes

That would make it 18.78, but the question does not ask to round what should I put?

leaden tusk
#

i think you messed up somewhere

tidal cypress
#

Ok

neon iron
#

wtf

leaden tusk
#

the hypotenuse is always the longest side, so your calculation shouldn't be greater than 17

neon iron
#

yes

#

UT^2 = 17^2 - 8^2 = 289 - 64 = 225
UT = root(225) = 15

#

the answer is 15 brother

keen tundra
#

a^2=b^2+c^2
17^2=8^2+UT^2
UT=sqrt(289-64)=15

neon iron
#

not 18.78

tidal cypress
#

Hm but to be a right triangle 8^2+17^2 has to equal UT or am I tripping

#

Oh yeah

neon iron
#

wait

#

you are thinking wrong

leaden tusk
leaden tusk
keen tundra
#

youre mixing up a hypotenuse and a leg

neon iron
#

See the 90* angle.

keen tundra
tidal cypress
keen tundra
#

i wont do it again

leaden tusk
neon iron
tidal cypress
#

I actually am just trying to understand the concept not the answer

keen tundra
neon iron
leaden tusk
neon iron
#

let's back to problem

#

@tidal cypress you got it?

tidal cypress
#

Yes

neon iron
#

okay good

leaden tusk
#

you seem to be thinking the side length 17 is a leg, but that's the hypotenuse

#

the hypotenuse is always located opposite the right angle

tidal cypress
leaden tusk
#

yes

tidal cypress
#

Makes so much more sense, thanks all

neon iron
#

goodluck

tidal cypress
#

ty!

#

.close

topaz sinewBOT
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gray basin
#

I don’t really understand this question

topaz sinewBOT
gray basin
#

I did something like this but I’m not sure if I’m correct..

topaz sinewBOT
#

@gray basin Has your question been resolved?

gray basin
#

<@&286206848099549185>

sweet shard
thorny flameBOT
#

riemann

gray basin
#

You mean (root of 4)^2

#

?

#

Because that’s root 4 whole squared

#

You there?

sweet shard
#

the side length is just $\sqrt{4}$

thorny flameBOT
#

riemann

sweet shard
#

just like how the hypotenuse's length isn't 5. it's $\sqrt{5}$

thorny flameBOT
#

riemann

gray basin
#

It is Root 5 though

sweet shard
#

ok we're in agreement then

sweet shard
gray basin
#

So how do I fix it?

sweet shard
gray basin
#

But that would make it 16 and 1 which is not equal to root 5

#

Oh sorry I get what you mean

#

Bruh…

#

Thanks for help

#

.close

topaz sinewBOT
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normal mist
topaz sinewBOT
normal mist
#

Do I have these answers right so far?

keen tundra
#

i think you need to reevaluate the first and second problem

#

notice the dashed line in the composite figure, meaning that shape does not count towards the area of the composite figure

topaz sinewBOT
#

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topaz sinewBOT
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topaz egret
topaz sinewBOT
topaz egret
#

phi here is a representation and i'm trying to show that phi_k is isomorphic to phi_k+8. How would I go about doing this?

#

i'm not sure how to show that there exist invertible f in Hom_G(phi_k,phi_k+8)

#

<@&286206848099549185>

topaz sinewBOT
#

@topaz egret Has your question been resolved?

keen venture
#

What is phi_k+8? What do the matricies look like?

topaz sinewBOT
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topaz sinewBOT
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pulsar wyvern
#

I keep getting an answer of 35.78%, which rounds to 36%. The answer key says it's C) 38%. Can anyone confirm this answer? I redid the question multiple times and got the same answer.

loud dawn
#

Weird I got 34%

#

Tedious question

topaz sinewBOT
#

@pulsar wyvern Has your question been resolved?

hazy pumice
#

not worth the 7 points

#

I say that with a Bachelors degree

pulsar wyvern
#

7 points is the most for these questions. :P

loud dawn
#

Lmao just a tedious, annoying question

hazy pumice
#

maybe it's not that bad...

#

total area of the rectangle is

#

26 times 12-root-3-plus-1

#

where tf is my calculator

#

566.399852

#

the hexagons are just triangles

#

most the same size

#

the bottom is

#

1/2 times 6 times 3-root-3

#

...times 3

#

that's 27-root-3

topaz sinewBOT
#
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hazy pumice
#

plus 10 more of those

#

so adding 90-root-3

topaz sinewBOT
#
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hazy pumice
#

altogether the hexagons are 117-root-3

topaz sinewBOT
hazy pumice
#

202.6499445

#

...and I got about 36%. 0.3577860124

#

answer key is a lie I guess. No way I messed that up, rite?

loud dawn
#

Idk bruh, I got 34 and I thought I was cracked

topaz sinewBOT
#

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topaz sinewBOT
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kind fractal
#

what is the difference between SSres/SStot and 1-SSres/SStot in regards to calculating r^2. (SSres= residual sum of squares formula and SStot=total sum of squares formula)

topaz sinewBOT
#

@kind fractal Has your question been resolved?

kind fractal
#

<@&286206848099549185>

topaz sinewBOT
#

@kind fractal Has your question been resolved?

cursive flax
#

Did you try latex or its just some mathematical gibberish I don't know abt? thinkies

kind fractal
#

i dont know what that is

#

.close

topaz sinewBOT
#
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hearty wraith
topaz sinewBOT
hearty wraith
#

why is the range and domain [0,1]

#

i dont understand how they got this

topaz sinewBOT
#

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spiral saffron
#

if the intersection of any finite number of open sets sets is open, how does it follow from that that the union of any finite number of closed sets is a closed set?

topaz sinewBOT
#

@spiral saffron Has your question been resolved?