#help-39

1 messages · Page 271 of 1

north talon
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2d euclidean geometry is bad enough😭😭

rotund ferry
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Olympiad ahh 🥀

frank violet
north talon
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💔 💔

rotund ferry
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I don't see any other way you would solve this problem tbh catshrug

frank violet
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You could do what I said earlier

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But ehh Ig coordinate is better at these

north talon
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also quick question, how did you even make this

frank violet
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Calculate where each point is in 3D space to make it precise

north talon
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i see, thanks!

frank violet
north talon
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doing anything but olym maths atp🫩🫩

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shut flicker
#

would this be right, i feel maybe i have double counted a bit

shut flicker
naive zinc
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Inclusion exclusion principle

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Yours is correct

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Wait

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I don’t get a 6! in the numerator, let me check

shut flicker
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thats from arranging the 1 2 3 4 5 6 that we want but i think may be the cause for double counting idk

naive zinc
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Mine is (Σbinom(6, k) (-1)^k (6-k)^n)/6^n

iron basin
naive zinc
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So I don’t think yours is correct but I haven’t checked your steps

iron basin
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for n = 7 for example there are two ways you could've counted in 1 1 2 3 4 5 6

shut flicker
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ohhh yh

naive zinc
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$\frac{\sum_{k}(-1)^{k}\binom{6}{k}(6-k)^{n}}{6^{n}}$

jolly parrotBOT
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Cogwheels of the mind

calm maple
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So ig its right

iron basin
shut flicker
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nah buts its like ( one 1 two three four five six ) and ( 1 one two three four fix six ) are the same but counted twice, the letter numbers being the fixed ones

naive zinc
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A_j is set of cases the sequence doesn’t contain j. Clearly sum of |intersection of k many A_j| is binom(6,k)(6-k)^n

naive zinc
shut flicker
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thanks

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torn lodge
#

for part b, idk why i didnt get aln2 (where a is some rational constant)

toxic lichen
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you've got that ln(6/8) which still can and should get some simplification

agile hedge
agile hedge
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you can write ln 4 as ln 2^2 and then use property ln m^n = n ln m

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so it become 2 * 12 ln 2

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so a = 24/5 and b = 21/5 (can be wrong didnt use calc or sheet, calc is short of calculator btw)

agile hedge
agile hedge
torn lodge
agile hedge
torn lodge
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tysm!

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agile hedge
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wind lagoon
#

A median of a random variable $X$ is defined as any $m \in \mathbb{R}$ such that $$P(X \le m) \ge 1/2\text{ and }P(X \ge m) \ge 1/2.$$ I know of an example when the median is not unique, but now I'd like to give and prove a condition for when it is unique. I know of an MSE related answer (see below), but I fail to understand why the condition given is equivalent to unique median. The answer claims that the median is unique iff $\lambda(F_X^{-1}({0.5}))=0$, where $F_X^{-1}$ is the inverse image of the CDF $F_X$. Appreciate any help.

jolly parrotBOT
wind lagoon
pearl pondBOT
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safe prairie
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What went wrong??

pearl pondBOT
safe prairie
#

I gotta prove that there’s a double eigenvalue and a triple eigenvalue

bitter herald
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Methinks

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When expanding along the 5th column

safe prairie
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Alr yeah 1st line 2nd term should start with -

bitter herald
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Ye

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Its -lambda

pearl pondBOT
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robust lichen
#

okay so

pearl pondBOT
robust lichen
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AE => m^3 - 3m^2 + 4m - 2 = 0

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m = 1, 1+i, 1-i

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so CF = e^x(C1 cos x + C2 sin x) + C3 e^x

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got that

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how can i guess the PI like

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applying Method of Undetermined Coefficients to Find a Particular Solution

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should i just do

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Ae^x + Bcos x + C sin x cos x ?

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or Ae^x + Bcos x + Csin x + D sinx cos x

waxen agate
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You already have e^x in your CF, so you multiply Ae^x by x.

robust lichen
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can take sin x cos x as .5 sin 2x

waxen agate
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The guess for the term cos(x) is Bcos(x) + Csin(x), yes.

waxen agate
robust lichen
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so

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Axe^x + B cos x + .5C sin 2x + .5D cos 2x

waxen agate
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No need for the 0.5 scaling

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Also where is your Ccos(x) term

robust lichen
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or are they?

robust lichen
waxen agate
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They are constants that you have to calculate.

robust lichen
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yeah

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cant absorb the .5 into them so ill need to write .5

robust lichen
waxen agate
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You can absorb any contants into C and D

robust lichen
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i can?

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oh

waxen agate
robust lichen
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OH

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yeah

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coz theres cos x

waxen agate
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Yes

robust lichen
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imma do this then come back

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@waxen agate if in my CF there wasnt e^x then i would have written just Ae^x right

waxen agate
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Yes.

robust lichen
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okok

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@waxen agate is there a better way to solve this than what im doing rn

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too lengthy god damn

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arctic hazel
#

may i get some help on this

pearl pondBOT
sharp fractal
arctic hazel
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yea im not sure where to start

sharp fractal
arctic hazel
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ye

sharp fractal
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can you show your work/give your answer

arctic hazel
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i did one for 2,4,6,8 etc

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yea one sec

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i got my answer to be 6.6

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but its incorrect

sharp fractal
arctic hazel
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oh wait

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wait no yeah i did

sharp fractal
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what was the n value for the 6.6 answer? sorry for the many questions, im trying to see what went wrong here

arctic hazel
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should be 8

sharp fractal
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yeah 8 checks out
would it be possible for you to show how you got that 6.6?

arctic hazel
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yea one sec

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mb its gonna be a little all over the place

sharp fractal
# arctic hazel

sorry I need to go for a sec. is this time sensitive? I can get another helper here for you, if needed

arctic hazel
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yes pls

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it's due in a bit

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ty for the help tho

sharp fractal
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<@&286206848099549185> if anyone could get this guy 'til I'm back

sharp fractal
# arctic hazel

ohh dude wait, can you write down your c(t) values?
like c(0)=0, c(2)=6, so on and so forth? perhaps its just that?

arctic hazel
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ight bet

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lemem see

sharp fractal
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*jesus sorry about that, your work is right, I got stuck in my method lol

arctic hazel
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its all g LOL

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are you getting the same answer i was? maybe it's just a rounding error icl

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idk i only have 1 more try on it 😭

sharp fractal
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I don't think it was a rounding error, no

arctic hazel
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hmm okay

sharp fractal
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c(1)=4, c(3)=7, c(5)=6, c(7)=5, c(9)=4, c(11)=3, c(13)=2, c(15)=1
is what you wrote yeah?

arctic hazel
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yup

sharp fractal
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I sent you something in dms, do check if possible

pearl pondBOT
#

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quiet plover
#

hi

pearl pondBOT
quiet plover
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cedar harbor
#

let $x[n]$ be a discrete time signal. $y_1 = x[3n]$. if $y_1[n]$ is periodic, is $x[n]$ periodic?

is saying that $$y_1[n] = y_1[n + T] = x[3n+3T] = x[3n]$$ enough to say that only x[3n] is periodic, not x[n]

jolly parrotBOT
#

thiccfetus

cedar harbor
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and in the other direction, if $x[n]$ is periodic, is $y_1[n]$ periodic?
$$ x[n] = x[n+p] -> x[3n+ 3p] = x[3n] = y_1[n] $$ so y[n] is also periodic.

jolly parrotBOT
#

thiccfetus

cedar harbor
pearl pondBOT
#

@cedar harbor Has your question been resolved?

pearl pondBOT
#

@cedar harbor Has your question been resolved?

errant cedar
# jolly parrot **thiccfetus**

assuming what you mean by a discrete time signal is essentially a sequence (so an indexed list of numbers) and that your definition of a period p is that x[n]=x[n+p] for any n, this is true imo

cedar harbor
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but i'm not sure if my proof is valid

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like my process

errant cedar
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for the x[n] periodic of period p implies the subsampled y_1[n]is periodic, you can use the period definition 3 times in a row to get what you want

cedar harbor
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how about y_1 is periodic?

errant cedar
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but the other direction like y_1[n] periodic does not imply that x[n] is periodic imo

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to refute that you would have to produce a counter example

cedar harbor
cedar harbor
errant cedar
cedar harbor
errant cedar
cedar harbor
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to start with x[n+p]

errant cedar
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so y[n] = x[3n] that’s the definition of y[n], then x[3n]=x[3n+p] because we use the periodicity on the index 3n of the sequence x

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then can you see what you need to do to get to y[n]=y[n+p]?

cedar harbor
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how can you say that x[3n] is periodic, with only given that x[n] is periodic

errant cedar
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the property that the sequence x is periodic is applicable to each index of the sequence

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maybe a drawing would help

cedar harbor
errant cedar
errant cedar
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does this make sense

cedar harbor
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i think it's only for mod 3. since x[2(1) + p] != x[2(2) + p]

errant cedar
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you have to separate the two proof directions in your head imo

errant cedar
cedar harbor
errant cedar
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i said earlier i think it’s not true all the time

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to confirm this a counter example is enough proof

cedar harbor
errant cedar
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no because you are not sure n+P is a multiple of 3 and fractional indices on a sequence don’t make sense imo

cedar harbor
errant cedar
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a counter example is a particular choice of x where y is periodic but x is not

errant cedar
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but again learning to prove things is hard imo

errant cedar
cedar harbor
errant cedar
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yep, you can indeed cook up a sequence such that x[3n] = 0 for each n and the rest is free to be anything

cedar harbor
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if that's correct, what i'm struggling with is knowing when to give a counterexample

cedar harbor
errant cedar
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a counterexample is a way to prove that a statement holding over many objects fail for one of the objects. Here the objects are sequence/signals and the statement is that for any signal, the periodicity of the downsampled one x[3n] imply the periodicity of the source signal x.

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if the statement fails for some choice of x, it can’t be true for any x, it disproves directly the « for each/for all »

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hence it disprove this whole proof direction

cedar harbor
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i see, tyhanks

#

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scarlet dragon
pearl pondBOT
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short fog
#

Hi, So my doubt is not for any math question right now, But I have Caclulus in my second sem of college and would like to know how should i go about learning it to gain full conceptual clarity. I had also learnt calculus to some extent in my high school but due to lack of conceptual clarity topics like AOI, AOD, Limits, Continuity etc used to trouble me while solving questions. So Could anyone suggest which topic should I start with and from where should I be doing it, because this time i want full conceptual clarity for all the topics. I am attaching the photo of the syllabus as well.
Thanks

short fog
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If someone could guide me, It'll be very helpful.

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I am in a B-School. Hence the topics have business applications mentioned in them, But again, we need the concepts anyway.

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@short fog Has your question been resolved?

short fog
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No

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pearl pondBOT
safe ore
#

everything does look good to me

#

yep part c looks good too

dusk willow
#

!done?

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@flint wyvern Has your question been resolved?

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void grail
pearl pondBOT
rotund ferry
slender viper
# void grail

do you remember the definition of "preorder" and "product of preorders"

void grail
# rotund ferry

Γ = {Refl: ⊢ ∀x x≤x, Trans: ⊢ ∀x y z (x≤y∧y≤z→x≤z)}.

def ≤×:
⊢ (a≤×b ↔ π₁a≤π₁b ∧ π₂a≤π₂b).

Γ ⊢ Refl× via ⟨Refl₁,Refl₂⟩
Γ ⊢ (a,a)≤×(a,a) (Refl∧Refl)

Γ ⊢ Trans× via π₁,π₂ + Trans
Γ ⊢ (a≤×b ∧ b≤×c → a≤×c) (Trans×).

⇒ Γ ⊢ Preorder(P×Q) ⇒ Γ ⊨ preorder(P×Q)

void grail
slender viper
#

so, if I get your notation, now all you have to show that "≤×" is such that "Refl×" and "Trans×"

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hmm, or is that supposed to be some sort of closure

void grail
# slender viper so, if I get your notation, now all you have to show that "≤×" is such that "Ref...

reflexive:
Refl× means ∀x, x≤×x.
take arbitrary x≔(a,b):
from Γ: Refl₁ ⊢ a≤ₚa, Refl₂ ⊢ b≤ᵩb.

∧-intro ⟨Refl₁,Refl₂⟩:
Γ ⊢ (a,b)≤×(a,b).

x≤×x ⇒ reflexive

transitive:
≤× is componentwise,
assume Γ ⊢ a≤×b ∧ b≤×c,
by π₁,π₂ (∧-elim):

  • a₁≤b₁ ∧ b₁≤c₁
  • a₂≤b₂ ∧ b₂≤c₂

apply Trans in P,Q:

  • a₁≤c₁, a₂≤c₂

then ∧-intro ⇒ (a≤×c).
∴ Γ ⊢ Trans×.

∧-intro:
from Γ ⊢ φ and Γ ⊢ ψ, infer Γ ⊢ φ∧ψ
∧-elim:
from Γ ⊢ φ∧ψ, infer Γ ⊢ φ or Γ ⊢ ψ

π₁(a≤×b) = a₁≤b₁
π₂(a≤×b) = a₂≤b₂

pearl pondBOT
#

@void grail Has your question been resolved?

void grail
#

I think it is possible to reason about this statement using just this information, the definition of Preorder and Product of categories

#

preorder P:
objects (p),
arrows (p → p'),
≤ defined by existence of arrow
reflexive: (p → p)
transitive: (p → p' ∧ p' → p'' ⇒ p → p'')
product P × Q:
objects (a,b),
arrows (f,g) with
f: a→a' in P,
g: b→b' in Q
order:
(a,b) ≤× (a',b') ⇔ a≤_P a' ∧ b≤_Q b'
reflexive:
(1_a,1_b): (a,b)→(a,b)
transitive:
(f',g') ∘ (f,g) = (f'∘f, g'∘g)

P×Q inherit reflexivity & transitivity
preorder

#

ty

#

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eager jewel
pearl pondBOT
eager jewel
#

given this function derivative how to find the maximas and minimas

tropic saddle
#

of f or f'?

eager jewel
#

of f

split void
#

try to set $f'(x) = 0$

jolly parrotBOT
#

Annie Maqionde

split void
#

I can see quite a few linear factors there

eager jewel
#

yes i found the critical points

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how do i decide now which is max and which is min

split void
#

think if $f'' > 0$ its a minimum and if $f''<0$ its a maximum but there cud be a simpler way

jolly parrotBOT
#

Annie Maqionde

eager jewel
#

bruh f''?

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u want me to find the double derivative?

frank violet
#

the change in sign of f'

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That should work

eager jewel
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but how do decide which is max and min

frank violet
#

If it's negative then positive it means that fx decreasing then increasing

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So what it should be? down then up

eager jewel
frank violet
#

You have to check between roots of f'x

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but yeah that's the idea

eager jewel
#

alr alr ty

#

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potent flax
pearl pondBOT
latent quail
#

solving for the inequality?

prisma kernel
#

Can you send the full question please

potent flax
#

i have optioms

glass meadow
#

Are those really the only options? pandahmm

potent flax
#

yes

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my tests are some of the most braindead ones so i cant tell if the answer isnt flip coin based

glass meadow
#

Well, sorry but the answer to what you posted is none of these four options

prisma kernel
#

Kinda close though

glass meadow
#

Unless the question isn't exactly "what is the set of solutions"

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Kinda... I guess they meant for it to be 4+x >= 7

potent flax
#

so umm which answer i have the best chance with?

prisma kernel
#

which do you think

light helm
#

Try to solve it properly
we can check the work
And report the problem

#

to the teacher

potent flax
#

i doubt the teacher cares

prisma kernel
#

Well first of all, what's the answer you're getting?

potent flax
#

i will tell once i finish the test

prisma kernel
#

sure

potent flax
#

ok

#

[–1; 5) was correct

#

💔

verbal whale
#

Mmh how?

potent flax
#

well thanks for help

potent flax
#

.close

pearl pondBOT
#
Channel closed

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pearl pondBOT
#
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wintry anvil
#

hi i am learning about logical notation i want to write this sentence in logical notation

wintry anvil
#

i know for all is ∀

#

so i suppose "for all M in Real Numbers looks like this:
∀M∈R

stray canyon
#

yeah

wintry anvil
#

great

stray canyon
#

do you know the "exists" symbol

#

?

wintry anvil
#

yes

#

#

do i write a comma

stray canyon
#

you can

wintry anvil
#

or do i use that fancy arrow

stray canyon
#

no

#

you can just

final shore
#

$\forall M \in \textbf{R}, \exists x \in \textbf{R}$ s.t.$ |x| \geq M$

jolly parrotBOT
#

holo_morph

stray canyon
#

not write anything

autumn fossil
#

definitely not arrow

wintry anvil
#

just like at all

#

what does the arrow even mean

stray canyon
#

it means

#

"implies"

#

so A => B

#

means that if A is true then B is true

cloud willow
#

∀ M ∈ ℝ, ∃ x ∈ ℝ : |f(x)| ≥ M

final shore
#

$A \implies B$

jolly parrotBOT
#

holo_morph

stray canyon
#

but if A is not true you cant say anything

autumn fossil
#

it's a binary connective, so it's the same kind of thing as e.g. AND and OR (∧ and ∨); u dont use it to connect 2 quantifiers

wintry anvil
#

ah ok

#

but why is absolute value of f(x) just |x|

stray canyon
#

thats just a mistake

wintry anvil
#

oh ok

cloud willow
wintry anvil
#

?

stray canyon
#

yes

wintry anvil
#

great

#

and there isnt a symbol for "such that"? that seems like a common one

stray canyon
#

you can use |

#

or :

#

but | is not really appropriate because of the absolute value

cloud willow
#

;

viscid shale
wintry anvil
#

ohh right i remember |

viscid shale
#

youre probably fine using st.

wintry anvil
#

but ; feels cool

stray canyon
#

basically, if you add commas between your quantifiers (forall, exists), you can use ":" and "|"

#

and if not, you can also use comma

wintry anvil
#

so this is fine?

cloud willow
stray canyon
#

yea

wintry anvil
#

great thanks guys

#

.close

pearl pondBOT
#
Channel closed

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pearl pondBOT
#
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odd tundra
#

I don't really understand why the symbolization of this english sentence into First-Order Logic didn't work

odd tundra
#

I've also posted the symbolization key on the 2nd image

#

My statement says: "For all x, if x likes cory, then x is a dog"
I don't get how that isn't logically equivalent to "Only a dog can be heavier than Cory"

#

oh wait, I used the wrong predicate lmao

#

I just needed to change L(x,c) into H(x,c), then it would be correct

glass meadow
#

Uh... so "for all x, if x is heavier than Cory, then x is a dog" ?

autumn fossil
glass meadow
#

Just asking for confirmation

odd tundra
#

but i should've written "if x is heaver than cory"

#

instead of "if x likes cory"

glass meadow
#

What's the exercise? Writing the sentence with logic symbols?

odd tundra
#

but yeah, I just did a silly mistake lol

#

have any of you helpers heard of the Fitch proof system?
I may have some questions on that later on

glass meadow
#

No

#

To answer your question, "only a dog can be heavier than Cory" is logically equivalent but I'm not sure where that sentence came from, so...

odd tundra
#

oh, that sentence you put under quotes is the sentence we have to translate into FOL

glass meadow
#

(as long as the domain is the same, that is, animals)

odd tundra
#

we're given english sentences
and our job is to write that into FOL

glass meadow
#

Not sure what the issue is then

#

Also I have to leave, feel free to ping helpers if no one else is around

odd tundra
#

there's no issue anymore, it's resolved as I posted my issue
cuz I realized my issue halfway as I wrote the request

#

.close

pearl pondBOT
#
Channel closed

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pearl pondBOT
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rare holly
#

hello in this why dont we convert the % into decimals

toxic lichen
#

i mean, what happened here is essentially that QR was taken as length 60 and PR was taken as length 100

#

you could do the same thing with PR = 1 and QR = 0.6 if you wanted; you would get the same value of sin(PQR) this way

#

(for the record, i don't think PR=100 and QR=60 is the nicest way to do this)

rare holly
#

thanks

#

.close

pearl pondBOT
#
Channel closed

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shut wren
pearl pondBOT
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carmine juniper
#

Is it possible to simplify it?

pearl pondBOT
warped violet
#

,rccw

jolly parrotBOT
warped violet
#

What in the world is written here

#

You've got equals sign = in the denominator

#

with random floating fractions

#

hint: you've got a whole blank page - go to a new line

carmine juniper
#

Final result

warped violet
#

,rccw

jolly parrotBOT
warped violet
#

great, another equals sign randomly appeared

viscid shale
#

I like to believe the original problem is $$\frac{(16x^2y^2)^{\frac 14}}{\sqrt{xy^4}}$$

jolly parrotBOT
carmine juniper
warped violet
carmine juniper
#

You just copy and pasted

warped violet
#

Well you clearly didn't

#

I am sorry but I have no clue what this means

viscid shale
#

yes the solution is right.

viscid shale
warped violet
#

But my point still stands

viscid shale
#

lmao

warped violet
#

Please

#

Go to a new line

#

Don't cram things together

#

and also

#

more importantly

#

don't just leave stuff out

carmine juniper
#

,w y^-3/2

warped violet
#

Because $\frac{(16x^2y^2)^{\frac 14}}{\sqrt{xy^4}} \neq \sqrt[4]{16x^2y^2}$

jolly parrotBOT
#

USS-Enterprise

carmine juniper
#

@viscid shale i have 2 * y^-3/2 now

#

How do you change y^-3/2 into positive power

#

Like

#

5^-1 is 1/5

warped violet
#

$a^{-m} = \frac{1}{a^m}$

jolly parrotBOT
#

USS-Enterprise

carmine juniper
#

So

#

1/y^3/2

warped violet
#

If you mean

#

1/(y^(3/2))

#

Yes

carmine juniper
#

And it’s the simple form

#

Simplest

warped violet
#

Yes

#

Some might prefer writing $\frac{2}{y \cdot \sqrt{y}}$

jolly parrotBOT
#

USS-Enterprise

carmine juniper
#

And hows that made bud

#

Huh

warped violet
#

Oh, we are buddies 😊

#

$a^{m+n} = a^m \cdot a^n$

carmine juniper
#

Ah i get it

jolly parrotBOT
#

USS-Enterprise

carmine juniper
#

Nvm

#

Don’t need to explain

warped violet
#

uh

#

what

#

how did

#

Why y^2 at the end

#

Also why is 1 1/2 written on top of everything

sudden tangle
#

Hello, I'm in 8th grade and i have about 5 hours till my math's exam, i need someone to help me learn basic maths like propotion, Nth term etc

pearl pondBOT
#

@carmine juniper Has your question been resolved?

pearl pondBOT
#
Channel closed

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pearl pondBOT
#
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Show your work, and if possible, explain where you are stuck.
Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

ruby wharf
#

Can someone please help explain horizontal stretch about a vertical line PQ to me? I know about dilation and I know about horizontal stretch for linear, quadratic, and exponential functions but I don't know how this is done here in this question, how am I supposed to visualize this?

ruby wharf
#

This was a test that I had earlier and I picked D and that was correct, their explanation was that it wasn't a rigid transformation nor was it a dilation.

#

But I don't know what a horizontal stretch about a vertical line is actually doing for any transformation of any object.

#

To clarify, this is for geometry on Khan Academy.

stuck spoke
#

hope that helps

ruby wharf
#

Ah nevermind I get it now, thank you so much 🩷

stuck spoke
#

ight girl have a good one

ruby wharf
#

Where does this exist?

#

Is it parallel to the y axis?

#

Is it arbitrary?

#

Is it just any 2 points that form a line segment on any shape or function in a 2d grid?

#

I don't understand.

stuck spoke
#

let me break it down for you

ruby wharf
#

Thank you

stuck spoke
#

the vertical line is the line around which the stretch happens

#

it’s parallel to the y-axis, and points move horizontally away from it. it’s not random; the problem will tell you which line it

#

is

stuck spoke
#

wait wdym

ruby wharf
#

because for example if it's here then it's going to be different than if it were here right?

#

It will transform the shape differently, no?

stuck spoke
#

im not sure sobdeflate

ruby wharf
#

Does it matter where it is?

#

ty anyway 🩷

#

I know what a vertical stretch is now though

#

i think?

#

idk

safe prairie
#

Sth like this?

stuck spoke
#

we need help

safe prairie
#

Horizontal stretch along some vert

ruby wharf
#

so i'm pretty confused

safe prairie
#

wait this isnt about graph transformation?

ruby wharf
#

It's about sequence transformations in geometry and what's preserved and what isn't

#

In terms of angles and line lengths

ruby wharf
#

I would love to be able to generalize the statement that "a stretch about line PQ transforms any given shape to where the angles and lengths do not match the original shape" but I don't know how to visualize that or show-case it on a graph or something like how I know how to do that with other transformations like dilations, rotations, reflections, and vertical and horizontal translations.

safe prairie
#

i mean stretching a square to a rhombus does that

ruby wharf
safe prairie
ruby wharf
#

In that geometry course at least

#

so idk how he devised that

ruby wharf
safe prairie
ruby wharf
safe prairie
#

i dont think this is what they mean, this type of transformation requires a matrix no?

ruby wharf
safe prairie
#

yeah

ruby wharf
safe prairie
#

more like horizontal translation "of" line BC

ruby wharf
#

Sorry i meant stretch

#

i got confused

stuck spoke
ruby wharf
stuck spoke
#

too

ruby wharf
#

In the lesson?

#

Do you know?

stuck spoke
#

if you're speaking obt dilation

ruby wharf
#

And why did he pick a and b?

#

Could it also work for segment bc?

ruby wharf
stuck spoke
#

no...

ruby wharf
stuck spoke
#

OH WAIT I MESSED UP

#

let me break it down for you

ruby wharf
#

You're good

#

Okay!

stuck spoke
#

dilation is like stretching or shrinking a shape

ruby wharf
#

Mhm! that makes sense

#

How about stretching?

stuck spoke
#

also
it changes the size of the shape but keeps the same proportions

ruby wharf
#

The angles stay the same, but the lines aren't the same length as the pre-image

stuck spoke
ruby wharf
#

If you don't mind, please?

stuck spoke
#

all points of the shape move away from or towards a fixed point (called the center of dilation). The shape doesn’t change its form, just its size. So, it's like uniformly scaling the entire shape

stuck spoke
ruby wharf
stuck spoke
#

STRETCHING or SHRINKING

#

yep

ruby wharf
#

I think expanding is a better term btw

stuck spoke
#

so we moved to expanding

#

instead of dilations

ruby wharf
#

Dilations are not the same thing in this lesson

safe prairie
ruby wharf
#

There's stretching, and also dilation

#

and also rotations, and translations

#

and reflections as well

#

Stretching is not dilation

#

I don't know what stretching is though

stuck spoke
ruby wharf
#

I know how to use stretching say in a linear equation like y=2/3x+9

safe prairie
#

imagine this same thing happening to a shape on a gridless paper maybe

stuck spoke
#

wait igu

safe prairie
ruby wharf
# safe prairie imagine this same thing happening to a shape on a gridless paper maybe

Tysmmmmm!!!!!!!!!!!!!!! I see now why the angles and segment lengths aren't the same as the pre-image, I have another question though if you don't mind, does this apply to a line that's being stretched about that has any slope? Or is it just vertical lines? In other words, do angles and length segments stay the same for a line that isn't a vertical one? Or is it only vertical lines where this is the case?

stuck spoke
#

ahh net

#

im lagging

ruby wharf
safe prairie
#

if u dont have a coord system, if its just a shape on blank paper, then yeah the line can be in any direction. u can stretch a square diamond like 45 degrees topleft to make a slanted rectangle

safe prairie
ruby wharf
safe prairie
#

then i wouldnt know the math needed to do such a thing

#

but visually its possible ofc

ruby wharf
safe prairie
#

what aint true

ruby wharf
ruby wharf
safe prairie
#

it indeed doesnt preserve angles

ruby wharf
#

for that case

safe prairie
#

it occasionally does

ruby wharf
safe prairie
#

it sometimes does

#

which means theres no theorem that says it preserves anything

ruby wharf
#

Like to say "Because of such and such"?

#

in a proof maybe?

safe prairie
#

ngl i never had a course in highschool talking about manipulating shapes

ruby wharf
#

or double column proof?

ruby wharf
#

i'm doing this for fun

safe prairie
#

we transformed graphs

ruby wharf
safe prairie
#

bewh

#

what course then?

ruby wharf
#

Tysm for helping me 🥺

ruby wharf
#

@stuck spoke Tysmmmmmmmm too i really appreciate you both

ruby wharf
#

Ty you too

safe prairie
#

maybe for those khan academy questions idk i didnt do a single course of theirs

ruby wharf
safe prairie
#

"because nothing is preserved" yeah
they arent gonna show you irregular transformations that straight up is just smudging the shape into sth else

#

(right)

ruby wharf
#

Yea!

safe prairie
#

there you have it!

ruby wharf
#

Tyyyyyyyyy 🫶

#

.close

pearl pondBOT
#
Channel closed

Closed by @ruby wharf

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#
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pearl pondBOT
plush bramble
#

!15m

pearl pondBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

#

Please do not ping individual helpers unprompted.

cinder flower
#

i have no interest in that sorry

#

and np on the ping

ancient valley
#

Sorry I might be a bit late but I’ll check I just need to plot it real quick

#

Well it sucks on phone bro 😭

#

I’ll switch to my pc right quick

#

It is indeed correct twin 👍

#

@flint wyvern

#

If you need anything I can try and help

pearl pondBOT
#

@flint wyvern Has your question been resolved?

pearl pondBOT
#

@flint wyvern Has your question been resolved?

ancient valley
#

Yup

#

Bit late but still there

pearl pondBOT
#
Channel closed

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#

Please do not ping individual helpers unprompted.

pearl pondBOT
#

@flint wyvern Has your question been resolved?

ancient valley
#

Sure thing

pearl pondBOT
#
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#
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wild vigil
#

why was the exponent dropped for the denominator

cinder flower
#

hm nothing was really dropped

#

this process is starting from something else

#

not exactly what’s given in the problem

wild vigil
#

can you elaborate? i assume we're trying to go from the form a/1-r to sum ar^n

cinder flower
#

what is the relation between f and 1/(1+4x)?

wild vigil
#

nnnnnnevermind i should've watched further in

#

the instructor creates a separate series that's functionally equivalent and then we just do some fiddling to make it look like f(x) somewhere

#

.close

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#
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cinder flower
#

yea something like that

pearl pondBOT
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fading nexus
#

If k said horizontal transformation, translate 4 units. , over x axis, then up 3 is rhag also correct

dense jasper
#

If k said horizontal transformation, translate 4 units over x axis, then up 3 is rhag also correct
in what direction

#

did you mean to write "Translate 4 units left, then reflect over the x axis, then translate up 3 units"

#

because it looks like you're missing words here

dense jasper
#

that would give you $3-\frac{1}{x+4}$

jolly parrotBOT
#

Civil Service Pigeon

fading nexus
#

What’s wrong with it?

dense jasper
#

but you want $3-\frac{2}{x+4}$

jolly parrotBOT
#

Civil Service Pigeon

fading nexus
#

Oh yea I forgot the Vertical transformation of 2 I put that as the first step on my paper

dense jasper
#

then yes

pearl pondBOT
#

If you are done with this channel, please mark your problem as solved by typing .close

#

@fading nexus Has your question been resolved?

bitter herald
#

.close

pearl pondBOT
#
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fading nexus
#

Where did the -x come from

pearl pondBOT
#

Please don't occupy multiple help channels.

random ermine
#

role well deserved

fading nexus
#

Sorrry I thought the other one got closed automatically I thought I read that 😭

toxic lichen
#

close your prev girl 😭

fading nexus
#

Which is why I went to a new one

crystal dew
#

closed it for you

toxic lichen
#

the x in the numerator gives you that x intercept at 0

fading nexus
#

Yea

#

I understand that

toxic lichen
#

the -1 factor seems to be vertical scale adjustment

random ermine
toxic lichen
#

you know the eq is y = kx/((x+2)(x-2))

fading nexus
#

We haven’t done vertical scales for these types

toxic lichen
#

so take any point on the graph and use it to find k

#

ah they say k could be anything <0

fading nexus
#

But there’s no concrete points

#

None of them ever go exactly on top of a grid line corner

#

So how would I know what point to do since I don’t know how to find the decimals

fading nexus
toxic lichen
#

(1, something positive)

toxic lichen
fading nexus
#

Huh

#

I’m so confused

fading nexus
#

and I also don’t see the difference the - is making

#

I don’t understand how we got all this information some of it is missing from the given info

toxic lichen
toxic lichen
fading nexus
#

I just don’t UNDESTAJD what I should do on my test

#

because now it seems like any of them could have a - without me realizing so how do I know which ones do and which ones don’t

#

How am I supposed to write the equations if I am not given the y and x intercepts

#

<@&286206848099549185>

compact sinew
#

yeah?

#

question?

fading nexus
#

I don’t understand how we are supposed to make and write the equation for this graph because we are not given the x intercepts s

compact sinew
#

Which part

#

Where is the question?

compact sinew
#

part a?

fading nexus
#

Yea and part b in a way

compact sinew
#

Ok

fair creek
#

i mean you have one, others are uhh guess work

#

doesn't have to be this one

compact sinew
#

use the information to the best of your ability

#

Domains tells you inputs

fading nexus
fair creek
#

like you could also have h(x)*(x-6) and it would still not change much

fading nexus
#

I’m so confused

fair creek
#

so its the bare minimum of an equatiob from the given data

fading nexus
#

There are set x intercepts those can’t be changed

compact sinew
#

just properly set the x and y asymptotes

fair creek
#

for example the x+2 can be aby other x-a me thinks

fair creek
fading nexus
#

I don’t know what I would do on a test tjo

#

Tho

fair creek
#

i hope you understood what i meant

fading nexus
#

Kinda but I don’t know if I would if I did not know the x intercepts from the answer key if thag makes sense

pearl pondBOT
#

@fading nexus Has your question been resolved?

pearl pondBOT
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wind lagoon
#

The correlation coefficient is defined in terms of the covariance and variances of two random variables (it is the covariance divided by the square root of the variances). Can there be a situation where the covariance equals 0 (or simply finite) whereas the denominator is infinity?

pearl pondBOT
#

@wind lagoon Has your question been resolved?

pearl pondBOT
#

@wind lagoon Has your question been resolved?

wind lagoon
#

.close

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carmine juniper
#

"Fill in the right column of the table with T if the statement is true, and F if it is false. Note that you do not need to provide justification here."

carmine juniper
#

F
T
T
T
T
F
T
T
F
T
F
F
T

#

Can anyone check this?

pearl pondBOT
#

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

naive zinc
#

They are asking for answer checking not answer provided

hot viper
#

Sorry

autumn fossil
#

2nd pic seems mostly wrong

naive zinc
carmine juniper
#

All are correct

#

Except I think one

crystal dew
#

don't think that's the word defined there

#

it's too short

carmine juniper
#

7th is wrong

#

??

naive zinc
#

Please rewrite it this way: picture 1: FTT… picture 2 :… picture 3:…

west vault
#

By subset do you mean proper subset?

carmine juniper
#

Okay this is in this order

#

F
T
T
T
T
F
T
T
F
T
F
F
T

toxic lichen
#

The function f(x) = sqrt(2x-6) is defined at x=3
you wrote that this is false. you are wrong about that

carmine juniper
#

I’m aware now

#

Rip that I got that wrong

#

I won’t get 100% 😭😭😭😭😭😭😭

toxic lichen
#

The domain of f(x)=1/(x^2-9) is all x except x=3
you wrote that this is true. you are also wrong about this. the domain also excludes x=-3

carmine juniper
bitter herald
#

can you answer jewels' question as well

naive zinc
#

6 7 8

carmine juniper
#

What?

toxic lichen
#

yeah looks like those are your only 3 mistakes

carmine juniper
#

It can’t be defined…

autumn fossil
#

The 2 ones after the sqrt one are wrong

naive zinc
carmine juniper
#

It’s 0..

toxic lichen
carmine juniper
#

Sqrt one

#

Can’t you just tell me

toxic lichen
#

it would be really convenient if these were numbered

carmine juniper
#

@autumn fossil are those only wrong?

warped violet
#

The one right after is also incorrect (the statement)

naive zinc
warped violet
#

Also

#

You should go through material on this

carmine juniper
#

Why is 6th wrong?

warped violet
#

I doubt this is beneficial to you in any way

carmine juniper
#

It’s turning into 0…

naive zinc
#

sqrt(0) is well defined

carmine juniper
#

Why is 8 wrong?

warped violet
carmine juniper
#

No…

warped violet
#

I wasn't aware I had to match all those letters to unnumbered statements here

naive zinc
#

Leading coefficient isn’t 0

carmine juniper
#

It can be

a>0
a=0
a<0

naive zinc
#

Then you are correct if you use this definition of yours

#

Most will disagree

bitter herald
#

is this about the b^2 - 4ac = 0 question?

hybrid ivy
#

a = 0 turns a quadratic into a linear function so...

#

but which one is this

carmine juniper
carmine juniper
hybrid ivy
#

so, not only have you turned two of the 0s into ds, but now a is supposed to represent the discrim??

warped violet
#

Why are you complaining about literally everything 😭

bitter herald
pastel umbra
#

"Tonight, on 'What does Attitude mean?'..."

hybrid ivy
naive zinc
#

There isn’t such a thing, t=b^2-4ac, when a doesn’t equal 0, t>0 two, t=0 one, t<0 zero, a=0 infinite (presume you are talking about that over R)

carmine juniper
#

HE WAS THE ONLY ONE WHO SAID THAT.

#

HE WAS TROLLING JN THE RESPONSE

bitter herald
#

He wasn't, though

carmine juniper
#

THAT WAS CRASS

hybrid ivy
#

trolling? I don't think so? in a general quadratic ax^2 + bx + c, if a = 0, it indeed turns into a linear function

naive zinc
#

He says I am trolling. I say I am the one who blocks him

hybrid ivy
#

the fuck you on?

pastel umbra
#

That's not a trolly response; he's implying your definition's wrong.

pastel umbra
carmine juniper
merry carbon
pastel umbra
#

You should know how the discriminant test works

carmine juniper
pastel umbra
#

Actively responding to you isn't neglect

warped violet
#

@carmine juniper if you want assistance from anyone in life, not just from people giving their time for free on Discord, you should be at least respectful to them.

pastel umbra
#

That's actually the opposite of that

hybrid ivy
#

Nenni, I'm not a mod, but with all due respect, you have a history of not exactly having a nice personality to helpers.
so, here's a quick and friendly reminder that narcissism won't get you too far here, especially towards people who are trying to help you for free.

#

now, where was I

merry carbon
#

Gonna ditto the two above comments SCneedy

unborn abyss
#

a quick scribbled T / F on each question in mspaint would go so hard

carmine juniper
#

I am trying to learn and he just comes with comments “oh it’s correct if you think that, but everyone else will know that you’re wrong”

#

That’s impudent

radiant terrace
#

Not every class uses the same definitions.

pastel umbra
#

In fairness that's cos multiple ppl had already told you otherwise

#

If you have a discriminant D = b^2 - 4ac of an equation ax^2 + bx + c = 0 (and we assume here that a != 0, because otherwise this is not a quadratic), then
- D > 0 means the equation has 2 distinct solutions
- D = 0 means the equation has 1 distinct solution
- D < 0 means the equation has no [real] solutions.

radiant terrace
#

These kinds of statements are not always a matter of rudeness.

warped violet
pastel umbra
warped violet
#

Let's not forget the emoji spamming incident with you 10 days ago

carmine juniper
carmine juniper
radiant terrace
#

People don't owe you help and it's not rude to say "under that assumption you are right, but that is not a common assumption"

warped violet
radiant terrace
#

Okay cool

pastel umbra
#

One - the noun is "neglect"

#

Two - I've pointed out that that's the opposite of neglect

radiant terrace
pastel umbra
#

Even if you think it's rude, and it's been argued why it isn't, it's not the same as neglect

radiant terrace
#

.close

pearl pondBOT
#
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hybrid ivy
#

also, to tie up loose ends

pearl pondBOT
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eager jewel
pearl pondBOT
eager jewel
#

how to do this integration

west vault
#

Divide the top and bottom by x^2

#

In the denominator, one x to divide (1 + x^2), and the other goes inside the square root

eager jewel
#

o

west vault
#

complete the square inside the root and sub x + 1/x

eager jewel
#

ok one sec

#

oh ok got it

#

ty

#

.close

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latent glen
#

Given a circle (O) with A outside. Draw tangent AB (B belongs to (O)) and draw BE perpendicular to OA (E belongs to (O)). Prove that AE is a tangent to (O).

Can someone explain this to me? My brain just short-circuited all of a sudden.

latent glen
#

ohhhh nvm

#

i see it now

#

.close

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bitter herald
#

just testing

distant folio
#

someone can correct that ( that’s french test )

autumn fossil
# distant folio

This channel will close soon, could you move to one of the available ones?

pearl pondBOT
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jolly trout
#

This is an example from discrete structures. We defined a ternary operator:

[
\Lambda(p,q,r) = (\neg p \implies q) \ \lor \ (r \land q)
]

I need to prove that ${\Lambda}$ is not a functionally complete set.
I simplified the operator to

[
\Lambda(p,q,r) = p \lor q
]

I understand that ${\lor}$ (and therefore ${\Lambda}$) is not a functionally complete set as you can not express $\neg$.
I know it can be proven using the monotonic property in Boolean algebra, but I am wondering if there is another way?

jolly parrotBOT
#

squared_apple

toxic lichen
#

i mean, i dont think there would be a different way for your problem unless you have a different way of proving {or} isn't a functionally complete set

jolly trout
#

because I don't fully understand how to prove it that way...

#

know was meant I know it's proved that way

#

but not that i know how to

toxic lichen
#

OR is monotonic, therefore so is anything you build from nothing but ORs. NOT is... not.

jolly trout
toxic lichen
#

failure to express even one function means failure to be functionally complete so yeah

jolly trout
#

👍

#

thank you

#

have a great day

#

.close

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#
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white mountain
#

Let f be a real smooth function with f(0)=1,f(1)=0,f'<0 and F(x,y,z)=f(x²+y²)exp(-z). I have shown that F is submersion and preimage of F for every c on R is a normal submanifold woth dimension 2. I have to show that preimage is diffeomorphic with: R², if c>0, unit circle, if c<0. How?

pearl pondBOT
#

@white mountain Has your question been resolved?

pearl pondBOT
#

@white mountain Has your question been resolved?

pearl pondBOT
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@white mountain Has your question been resolved?

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rugged leaf
#

hi

pearl pondBOT
rugged leaf
#

@prisma kernel

#

anybody

#

hrlooo

summer imp
rugged leaf
#

hi

#

can u js

#

double check

#

my graph

summer imp
#

Just post your question whatever it is with pictures and someone will try to help.

rugged leaf
#

here

warped violet
# rugged leaf

If you labeled the points correctly, then this is correct yes

#

GeoGebra 💪

#

There is no domain and range to be seen though

#

Also F is unnecessary

#

Also, I don't know what "equation of the axis" is supposed to mean

#

x = 0 and y = 0??

#

Also, I don't really see the point in this. You just typed the expression in the example in GeoGebra

#

But the graphs definitely are correct

pearl pondBOT
#

@rugged leaf Has your question been resolved?

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#
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warm elbow
pearl pondBOT
warm elbow
#

is the best way of solving this is putting Q(x,y,z) into matrix form then perform a regular diagonlization?

#

with eigenvalues

pearl pondBOT
#

@warm elbow Has your question been resolved?

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warm elbow
#

Prove that if a matrix $A$ satisfies $A^5 =I$, then $A$ is diagonlizable

jolly parrotBOT
warm elbow
#

how do you approach this problem

prime bramble
#

if it's a real matrix, I don't think the statement is true

#

but if it's a complex matrix, consider the minimal polynomial of A

warm elbow
#

@prime bramble i think we assume complex

#

is this theoreom particularitly usful?

prime bramble
warm elbow
prime bramble
#

hm, it's not going to be enough to conclude I don't think PaimonThink

#

I don't see a way to get around the minimal polynomial

#

have you seen that before?

warm elbow
#

not really haha

prime bramble
# warm elbow not really haha

ah well, it's just the "smallest polynomial" q such that q(A) = 0, i.e. q divides every polynomial p for which p(A) = 0

warm elbow
#

and A is the matrix right

prime bramble
#

a useful fact is that q has the same roots as the characteristic polynomial of A, so A is diagonalizable iff q splits into linear factors

prime bramble
warm elbow
#

ok cool!

#

so lemme see

#

ok

#

so my understanding is that

prime bramble
#

if you choose an appropriate p, you can apply your theorem to find out what the eigenvalues of A must be