#help-39
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Olympiad ahh 🥀
🥀
💔 💔
I don't see any other way you would solve this problem tbh 
also quick question, how did you even make this
Geogebra
just like you usually do
Calculate where each point is in 3D space to make it precise
i see, thanks!

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would this be right, i feel maybe i have double counted a bit
Inclusion exclusion principle
Yours is correct
Wait
I don’t get a 6! in the numerator, let me check
thats from arranging the 1 2 3 4 5 6 that we want but i think may be the cause for double counting idk
Mine is (Σbinom(6, k) (-1)^k (6-k)^n)/6^n
yeahh might have double counted a bit
So I don’t think yours is correct but I haven’t checked your steps
for n = 7 for example there are two ways you could've counted in 1 1 2 3 4 5 6
ohhh yh
$\frac{\sum_{k}(-1)^{k}\binom{6}{k}(6-k)^{n}}{6^{n}}$
Cogwheels of the mind
Idts.. the method fixes a set of {1,2,3,4,5,6}, permutes that in 6! and places it in 6 positions out of n and the remaining (n-6) slots can be filled in 6^(n-6) ways?
So ig its right
ok then what about these two ways
- 1, _, 2, 3, 4, 5, 6 and fill in the remaining 1 later
- _, 1, 2, 3, 4, 5, 6 and fill in the remaining 1 later
nah buts its like ( one 1 two three four five six ) and ( 1 one two three four fix six ) are the same but counted twice, the letter numbers being the fixed ones
A_j is set of cases the sequence doesn’t contain j. Clearly sum of |intersection of k many A_j| is binom(6,k)(6-k)^n
Which deduces this
ahhh i see
my bad
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for part b, idk why i didnt get aln2 (where a is some rational constant)
you've got that ln(6/8) which still can and should get some simplification
break ln(6/8) into 3/4 and then use ln m/n = ln m - ln n property, add 9 ln 3 and12 ln 3
ohhhh
kk i'll try that
you can write ln 4 as ln 2^2 and then use property ln m^n = n ln m
so it become 2 * 12 ln 2
so a = 24/5 and b = 21/5 (can be wrong didnt use calc or sheet, calc is short of calculator btw)
bet bet
btw which app? the handwriting is mindblowing
haha tysm! im using onenote
ahh, thank you :3
ah i didn't know u could simplify 9ln(3) + 12ln(3) to 21ln(3)
tysm!
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yes its like taking away common, best of luck
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A median of a random variable $X$ is defined as any $m \in \mathbb{R}$ such that $$P(X \le m) \ge 1/2\text{ and }P(X \ge m) \ge 1/2.$$ I know of an example when the median is not unique, but now I'd like to give and prove a condition for when it is unique. I know of an MSE related answer (see below), but I fail to understand why the condition given is equivalent to unique median. The answer claims that the median is unique iff $\lambda(F_X^{-1}({0.5}))=0$, where $F_X^{-1}$ is the inverse image of the CDF $F_X$. Appreciate any help.
psie
@wind lagoon Has your question been resolved?
@wind lagoon Has your question been resolved?
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What went wrong??
I gotta prove that there’s a double eigenvalue and a triple eigenvalue
U messed up one of ur signs
Methinks
When expanding along the 5th column
Alr yeah 1st line 2nd term should start with -
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okay so
AE => m^3 - 3m^2 + 4m - 2 = 0
m = 1, 1+i, 1-i
so CF = e^x(C1 cos x + C2 sin x) + C3 e^x
got that
how can i guess the PI like
applying Method of Undetermined Coefficients to Find a Particular Solution
should i just do
Ae^x + Bcos x + C sin x cos x ?
or Ae^x + Bcos x + Csin x + D sinx cos x
You already have e^x in your CF, so you multiply Ae^x by x.
can take sin x cos x as .5 sin 2x
The guess for the term cos(x) is Bcos(x) + Csin(x), yes.
Correct.
ill have to include it no?
these a, b, c, d arent arbitary constants
or are they?
wdym
They are constants that you have to calculate.
is this correct tho
You can absorb any contants into C and D
missing the sin x term
why do i need sin x
OH
yeah
coz theres cos x
Yes
imma do this then come back
@waxen agate if in my CF there wasnt e^x then i would have written just Ae^x right
Yes.
okok
@waxen agate is there a better way to solve this than what im doing rn
too lengthy god damn
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may i get some help on this
what have you tried? do you just not know where to start?
yea im not sure where to start
as the question directly asked for the midpoint rule, have you attempted using that?
ye
can you show your work/give your answer
i did one for 2,4,6,8 etc
yea one sec
i got my answer to be 6.6
but its incorrect
have you noticed/kept in mind that the graph gives you it in seconds and not minutes like the question asked?
what was the n value for the 6.6 answer? sorry for the many questions, im trying to see what went wrong here
should be 8
yeah 8 checks out
would it be possible for you to show how you got that 6.6?
sorry I need to go for a sec. is this time sensitive? I can get another helper here for you, if needed
<@&286206848099549185> if anyone could get this guy 'til I'm back
ohh dude wait, can you write down your c(t) values?
like c(0)=0, c(2)=6, so on and so forth? perhaps its just that?
*jesus sorry about that, your work is right, I got stuck in my method lol
its all g LOL
are you getting the same answer i was? maybe it's just a rounding error icl
idk i only have 1 more try on it 😭
I don't think it was a rounding error, no
hmm okay
c(1)=4, c(3)=7, c(5)=6, c(7)=5, c(9)=4, c(11)=3, c(13)=2, c(15)=1
is what you wrote yeah?
yup
I sent you something in dms, do check if possible
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hi
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let $x[n]$ be a discrete time signal. $y_1 = x[3n]$. if $y_1[n]$ is periodic, is $x[n]$ periodic?
is saying that $$y_1[n] = y_1[n + T] = x[3n+3T] = x[3n]$$ enough to say that only x[3n] is periodic, not x[n]
thiccfetus
and in the other direction, if $x[n]$ is periodic, is $y_1[n]$ periodic?
$$ x[n] = x[n+p] -> x[3n+ 3p] = x[3n] = y_1[n] $$ so y[n] is also periodic.
thiccfetus
i am also not sure that you can convert x[n] to x[3n] directly here
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@cedar harbor Has your question been resolved?
assuming what you mean by a discrete time signal is essentially a sequence (so an indexed list of numbers) and that your definition of a period p is that x[n]=x[n+p] for any n, this is true imo
yes
but i'm not sure if my proof is valid
like my process
for the x[n] periodic of period p implies the subsampled y_1[n]is periodic, you can use the period definition 3 times in a row to get what you want
how about y_1 is periodic?
but the other direction like y_1[n] periodic does not imply that x[n] is periodic imo
to refute that you would have to produce a counter example
so we can assume y is T periodic: y[n+T] = x[3n + 3T] = x[3n] = y[n]
asumme x is P periodic: x[n+P] = y[(n+P)/3] = x[n/3] != x[n]
you assume x[n] is periodic then you get with that hypothesis that y[n] is, implicitly that’s what justify your middle equal there
i thought x is given to be periodic. so we can hypothesise that y[n] is by using periodicity of x in the middle part
yes that’s how you start to prove an implication, but you can’t assume what you want to prove is true to prove it’s true if that’s what you mean by hypothesize. you have to start with x[n] = x[n+T] for each n and use that somewhere in your chain of equals
i'm not sure how this would work
to start with x[n+p]
so y[n] = x[3n] that’s the definition of y[n], then x[3n]=x[3n+p] because we use the periodicity on the index 3n of the sequence x
then can you see what you need to do to get to y[n]=y[n+p]?
i cannot
how can you say that x[3n] is periodic, with only given that x[n] is periodic
the property that the sequence x is periodic is applicable to each index of the sequence
maybe a drawing would help
i see, but i still do not know how to get y[n] = y[n+p]
so we have y[n]=x[3n]=x[3n+p] but because the signal repeats each p time steps we also have x[3n+p]=x[3n+2p]=x[3n+3p]
does this make sense
i'm not sure if this is true for all k*n
i think it's only for mod 3. since x[2(1) + p] != x[2(2) + p]
i’m still explaining the proof direction where we have that x[n] is periodic and want to show y[n] is, this will be good insight for the other direction
you have to separate the two proof directions in your head imo
this would not be true if we only had as an hypothesis that y[n] is periodic but again that’s the direction y[n] periodic implies (?) x[n] also periodic
uh how would you do the other direction
i said earlier i think it’s not true all the time
to confirm this a counter example is enough proof
can you say this ?
no because you are not sure n+P is a multiple of 3 and fractional indices on a sequence don’t make sense imo
so a counter example would be that n+ P is not a multiple of 3
a counter example is a particular choice of x where y is periodic but x is not
no i’m afraid to say that i perceived what you wrote earlier as gibberish unfortunately
but again learning to prove things is hard imo
but this made some sense
uh what i mean is that for x[n/3 + P/3] = x[n], it must be that n is divisible by 3. so you can come up with an x where x!=0 for n mod 3 != 0
yep, you can indeed cook up a sequence such that x[3n] = 0 for each n and the rest is free to be anything
if that's correct, what i'm struggling with is knowing when to give a counterexample
that means, this is enough for me to try to find a counter example?
a counterexample is a way to prove that a statement holding over many objects fail for one of the objects. Here the objects are sequence/signals and the statement is that for any signal, the periodicity of the downsampled one x[3n] imply the periodicity of the source signal x.
if the statement fails for some choice of x, it can’t be true for any x, it disproves directly the « for each/for all »
hence it disprove this whole proof direction
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Hi, So my doubt is not for any math question right now, But I have Caclulus in my second sem of college and would like to know how should i go about learning it to gain full conceptual clarity. I had also learnt calculus to some extent in my high school but due to lack of conceptual clarity topics like AOI, AOD, Limits, Continuity etc used to trouble me while solving questions. So Could anyone suggest which topic should I start with and from where should I be doing it, because this time i want full conceptual clarity for all the topics. I am attaching the photo of the syllabus as well.
Thanks
If someone could guide me, It'll be very helpful.
I am in a B-School. Hence the topics have business applications mentioned in them, But again, we need the concepts anyway.
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!done?
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do you remember the definition of "preorder" and "product of preorders"
Γ = {Refl: ⊢ ∀x x≤x, Trans: ⊢ ∀x y z (x≤y∧y≤z→x≤z)}.
def ≤×:
⊢ (a≤×b ↔ π₁a≤π₁b ∧ π₂a≤π₂b).
Γ ⊢ Refl× via ⟨Refl₁,Refl₂⟩
Γ ⊢ (a,a)≤×(a,a) (Refl∧Refl)
Γ ⊢ Trans× via π₁,π₂ + Trans
Γ ⊢ (a≤×b ∧ b≤×c → a≤×c) (Trans×).
⇒ Γ ⊢ Preorder(P×Q) ⇒ Γ ⊨ preorder(P×Q)
Preorder ⇔ (Reflexive ∧ Transitive).
so, if I get your notation, now all you have to show that "≤×" is such that "Refl×" and "Trans×"
hmm, or is that supposed to be some sort of closure
reflexive:
Refl× means ∀x, x≤×x.
take arbitrary x≔(a,b):
from Γ: Refl₁ ⊢ a≤ₚa, Refl₂ ⊢ b≤ᵩb.
∧-intro ⟨Refl₁,Refl₂⟩:
Γ ⊢ (a,b)≤×(a,b).
x≤×x ⇒ reflexive
transitive:
≤× is componentwise,
assume Γ ⊢ a≤×b ∧ b≤×c,
by π₁,π₂ (∧-elim):
- a₁≤b₁ ∧ b₁≤c₁
- a₂≤b₂ ∧ b₂≤c₂
apply Trans in P,Q:
- a₁≤c₁, a₂≤c₂
then ∧-intro ⇒ (a≤×c).
∴ Γ ⊢ Trans×.
∧-intro:
from Γ ⊢ φ and Γ ⊢ ψ, infer Γ ⊢ φ∧ψ
∧-elim:
from Γ ⊢ φ∧ψ, infer Γ ⊢ φ or Γ ⊢ ψ
π₁(a≤×b) = a₁≤b₁
π₂(a≤×b) = a₂≤b₂
@void grail Has your question been resolved?
I think it is possible to reason about this statement using just this information, the definition of Preorder and Product of categories
preorder P:
objects (p),
arrows (p → p'),
≤ defined by existence of arrow
reflexive: (p → p)
transitive: (p → p' ∧ p' → p'' ⇒ p → p'')
product P × Q:
objects (a,b),
arrows (f,g) with
f: a→a' in P,
g: b→b' in Q
order:
(a,b) ≤× (a',b') ⇔ a≤_P a' ∧ b≤_Q b'
reflexive:
(1_a,1_b): (a,b)→(a,b)
transitive:
(f',g') ∘ (f,g) = (f'∘f, g'∘g)
P×Q inherit reflexivity & transitivity
→ preorder
ty
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given this function derivative how to find the maximas and minimas
of f or f'?
of f
try to set $f'(x) = 0$
Annie Maqionde
I can see quite a few linear factors there
think if $f'' > 0$ its a minimum and if $f''<0$ its a maximum but there cud be a simpler way
Annie Maqionde
ye its changing at x=0,1/2 2 and 5
but how do decide which is max and min
If it's negative then positive it means that fx decreasing then increasing
So what it should be? down then up
ohk so i have to check at like for example x=2+ and x=2- sign of f'?
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solving for the inequality?
Can you send the full question please
Are those really the only options? 
yes
my tests are some of the most braindead ones so i cant tell if the answer isnt flip coin based
Well, sorry but the answer to what you posted is none of these four options
Kinda close though
Unless the question isn't exactly "what is the set of solutions"
Kinda... I guess they meant for it to be 4+x >= 7
so umm which answer i have the best chance with?
which do you think
i doubt the teacher cares
Well first of all, what's the answer you're getting?
i will tell once i finish the test
sure
Mmh how?
well thanks for help
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hi i am learning about logical notation i want to write this sentence in logical notation
yeah
great
you can
or do i use that fancy arrow
$\forall M \in \textbf{R}, \exists x \in \textbf{R}$ s.t.$ |x| \geq M$
holo_morph
not write anything
it can be either with the comma, or with nothing
definitely not arrow
∀ M ∈ ℝ, ∃ x ∈ ℝ : |f(x)| ≥ M
$A \implies B$
holo_morph
but if A is not true you cant say anything
it's a binary connective, so it's the same kind of thing as e.g. AND and OR (∧ and ∨); u dont use it to connect 2 quantifiers
thats just a mistake
oh ok
∀ M ∈ ℝ, ∃ x ∈ ℝ : |f(x)| ≥ M
yes
{ x ∈ ℝ | x > 0 }
Or ,
;
this is mostly for set construction tho
ohh right i remember |
youre probably fine using st.
but ; feels cool
basically, if you add commas between your quantifiers (forall, exists), you can use ":" and "|"
and if not, you can also use comma
Yea
yea
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I don't really understand why the symbolization of this english sentence into First-Order Logic didn't work
I've also posted the symbolization key on the 2nd image
My statement says: "For all x, if x likes cory, then x is a dog"
I don't get how that isn't logically equivalent to "Only a dog can be heavier than Cory"
oh wait, I used the wrong predicate lmao
I just needed to change L(x,c) into H(x,c), then it would be correct
Uh... so "for all x, if x is heavier than Cory, then x is a dog" ?
whats wrong with that?
Just asking for confirmation
yea, that's the right answer
I just wrote "For all x, if x likes cory, then x is a dog"
but i should've written "if x is heaver than cory"
instead of "if x likes cory"
What's the exercise? Writing the sentence with logic symbols?
yea, translating english sentences into First Order Logic sentences
but yeah, I just did a silly mistake lol
have any of you helpers heard of the Fitch proof system?
I may have some questions on that later on
No
To answer your question, "only a dog can be heavier than Cory" is logically equivalent but I'm not sure where that sentence came from, so...
oh, that sentence you put under quotes is the sentence we have to translate into FOL
(as long as the domain is the same, that is, animals)
we're given english sentences
and our job is to write that into FOL
Not sure what the issue is then
Also I have to leave, feel free to ping helpers if no one else is around
there's no issue anymore, it's resolved as I posted my issue
cuz I realized my issue halfway as I wrote the request
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hello in this why dont we convert the % into decimals
i mean, what happened here is essentially that QR was taken as length 60 and PR was taken as length 100
you could do the same thing with PR = 1 and QR = 0.6 if you wanted; you would get the same value of sin(PQR) this way
(for the record, i don't think PR=100 and QR=60 is the nicest way to do this)
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Is it possible to simplify it?
,rccw
What in the world is written here
You've got equals sign = in the denominator
with random floating fractions
hint: you've got a whole blank page - go to a new line
,rccw
great, another equals sign randomly appeared
I like to believe the original problem is $$\frac{(16x^2y^2)^{\frac 14}}{\sqrt{xy^4}}$$
Correct
Yes, and in the second step the fraction and denominator simply disappeared
You just copy and pasted
yes the solution is right.
Distributed the fourth root on the numerator, the sqrt in the denominator, and the next part is just the next stage, where hes cancelling terms
Yeah I know I was just exaggerating
But my point still stands
lmao
Please
Go to a new line
Don't cram things together
and also
more importantly
don't just leave stuff out
,w y^-3/2
Because $\frac{(16x^2y^2)^{\frac 14}}{\sqrt{xy^4}} \neq \sqrt[4]{16x^2y^2}$
USS-Enterprise
@viscid shale i have 2 * y^-3/2 now
How do you change y^-3/2 into positive power
Like
5^-1 is 1/5
$a^{-m} = \frac{1}{a^m}$
USS-Enterprise
USS-Enterprise
Ah i get it
USS-Enterprise

uh
what
how did
Why y^2 at the end
Also why is 1 1/2 written on top of everything
Hello, I'm in 8th grade and i have about 5 hours till my math's exam, i need someone to help me learn basic maths like propotion, Nth term etc
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Can someone please help explain horizontal stretch about a vertical line PQ to me? I know about dilation and I know about horizontal stretch for linear, quadratic, and exponential functions but I don't know how this is done here in this question, how am I supposed to visualize this?
This was a test that I had earlier and I picked D and that was correct, their explanation was that it wasn't a rigid transformation nor was it a dilation.
But I don't know what a horizontal stretch about a vertical line is actually doing for any transformation of any object.
To clarify, this is for geometry on Khan Academy.
a horizontal stretch about a vertical line means points move horizontally away from the vertical line but stay at the same vertical position. it changes distances but not angles. it’s not a rigid transformation or dilation. only angle measures are preserved, not segment lengths.
hope that helps
Ah nevermind I get it now, thank you so much 🩷
kinda late...
ight girl have a good one
a horizontal stretch about a vertical line means points move horizontally away from the vertical line but stay at the same vertical position
What vertical line are we talking about though?
Where does this exist?
Is it parallel to the y axis?
Is it arbitrary?
Is it just any 2 points that form a line segment on any shape or function in a 2d grid?
I don't understand.
good question
let me break it down for you
Thank you
the vertical line is the line around which the stretch happens
it’s parallel to the y-axis, and points move horizontally away from it. it’s not random; the problem will tell you which line it
is
Where is this line though?
wait wdym
because for example if it's here then it's going to be different than if it were here right?
It will transform the shape differently, no?
im not sure 
Does it matter where it is?
ty anyway 🩷
I know what a vertical stretch is now though
i think?
idk
Sth like this?
we need help
Horizontal stretch along some vert
That is, but I'm taking geometry and I don't think horizontal stretches were introduced in this course yet, they probably were in algebra 1 on the website but not on the course
so i'm pretty confused
wait this isnt about graph transformation?
No
It's about sequence transformations in geometry and what's preserved and what isn't
In terms of angles and line lengths
I suppose that it falls under this
I would love to be able to generalize the statement that "a stretch about line PQ transforms any given shape to where the angles and lengths do not match the original shape" but I don't know how to visualize that or show-case it on a graph or something like how I know how to do that with other transformations like dilations, rotations, reflections, and vertical and horizontal translations.
i mean stretching a square to a rhombus does that
Does stretching dilate a shape but not for all vertices?
i was watching this vid and idk if its him drawing things badly and not making the stretching up to scale, or if hes just moving AB away, parallel to its original. i hope its the former
But either way i don't remember him doing that before
In that geometry course at least
so idk how he devised that
Is this considered a dilation?
i think for the definition of "dilate" in ur chapter, it means growing/shrinking the entire thing, with a "point", which in art would be called a vanishing point
By moving b and c one to the right?
I see
i dont think this is what they mean, this type of transformation requires a matrix no?
Omggg i love vanishing points
Well I haven't learned matrices yet
yeah
Is this a horizontal stretch about line BC?
more like horizontal translation "of" line BC
this isn't a dilation. it looks like the shape has been... smudged
B and C have been moved 1 unit to the right.
if you're speaking obt dilation
i'm wondering if dilation is like stretching
no...
it's not?
dilation is like stretching or shrinking a shape
also
it changes the size of the shape but keeps the same proportions
Yea
The angles stay the same, but the lines aren't the same length as the pre-image
i said that already...
Can you say again or reply to it?
If you don't mind, please?
all points of the shape move away from or towards a fixed point (called the center of dilation). The shape doesn’t change its form, just its size. So, it's like uniformly scaling the entire shape
there
That's dilation
I think expanding is a better term btw
Dilations are not the same thing in this lesson
no like, replace ur use of "stretching" with her "expanding"
There's stretching, and also dilation
and also rotations, and translations
and reflections as well
Stretching is not dilation
I don't know what stretching is though
oh so she needs help with differentiating between those terms?
I know how to use stretching say in a linear equation like y=2/3x+9
imagine this same thing happening to a shape on a gridless paper maybe
wait igu
yes because stretching is a standalone action now
Tysmmmmm!!!!!!!!!!!!!!! I see now why the angles and segment lengths aren't the same as the pre-image, I have another question though if you don't mind, does this apply to a line that's being stretched about that has any slope? Or is it just vertical lines? In other words, do angles and length segments stay the same for a line that isn't a vertical one? Or is it only vertical lines where this is the case?
the angles clearly change, for example look at angle ABC, it's clearly bigger than the image of triangle ABC's respective angle A prime B prime C prime
if u dont have a coord system, if its just a shape on blank paper, then yeah the line can be in any direction. u can stretch a square diamond like 45 degrees topleft to make a slanted rectangle
this preserves angles but it generally doesnt, cuz i can do the same to a circle, then nothing is preserved
How about with a coordinate system
then i wouldnt know the math needed to do such a thing
but visually its possible ofc
Then how are they teaching me proofs after this when this isn't true?
what aint true
For example the line PQ with a slope of 1
That it preserves angles
it indeed doesnt preserve angles
for that case
it occasionally does
You're saying for a square diamond it will preserve the angles?
So then this is only useful for like any object that I'm just gonna normally be using in this course or proving with but not all then?
Like to say "Because of such and such"?
in a proof maybe?
ngl i never had a course in highschool talking about manipulating shapes
or double column proof?
oh
i'm doing this for fun
we transformed graphs
same in High School
Tysm for helping me 🥺
Algebra 1 we transformed all kinds of functions
@stuck spoke Tysmmmmmmmm too i really appreciate you both
i mean this course
have a good one
i think at the very least you can identify that sth is "stretched"
maybe for those khan academy questions idk i didnt do a single course of theirs
thats fair tysm anyway! ❤️
"because nothing is preserved" yeah
they arent gonna show you irregular transformations that straight up is just smudging the shape into sth else
(right)
Yea!
there you have it!
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!15m
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Sorry I might be a bit late but I’ll check I just need to plot it real quick
Well it sucks on phone bro 😭
I’ll switch to my pc right quick
It is indeed correct twin 👍
@flint wyvern
If you need anything I can try and help
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Sure thing
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why was the exponent dropped for the denominator
hm nothing was really dropped
this process is starting from something else
not exactly what’s given in the problem
can you elaborate? i assume we're trying to go from the form a/1-r to sum ar^n
what is the relation between f and 1/(1+4x)?
nnnnnnevermind i should've watched further in
the instructor creates a separate series that's functionally equivalent and then we just do some fiddling to make it look like f(x) somewhere
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yea something like that
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If k said horizontal transformation, translate 4 units. , over x axis, then up 3 is rhag also correct
If k said horizontal transformation, translate 4 units over x axis, then up 3 is rhag also correct
in what direction
did you mean to write "Translate 4 units left, then reflect over the x axis, then translate up 3 units"
because it looks like you're missing words here
if this is it, then no
that would give you $3-\frac{1}{x+4}$
Civil Service Pigeon
What’s wrong with it?
but you want $3-\frac{2}{x+4}$
Civil Service Pigeon
Oh yea I forgot the Vertical transformation of 2 I put that as the first step on my paper
then yes
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Where did the -x come from
Please don't occupy multiple help channels.
role well deserved
Sorrry I thought the other one got closed automatically I thought I read that 😭
close your prev girl 😭
Which is why I went to a new one
closed it for you
the x in the numerator gives you that x intercept at 0
the -1 factor seems to be vertical scale adjustment
also do 1 question at a time, from a learning pov
you know the eq is y = kx/((x+2)(x-2))
We haven’t done vertical scales for these types
so take any point on the graph and use it to find k
ah they say k could be anything <0
But there’s no concrete points
None of them ever go exactly on top of a grid line corner
So how would I know what point to do since I don’t know how to find the decimals
The only point is (0,0 but I don’t think we can use that point
(1, something positive)
the image says that you aren't expected to say anything about k except its sign
but it says it has to be negative and how do I know that without plugging a point in
and I also don’t see the difference the - is making
I don’t understand how we got all this information some of it is missing from the given info
vertical flip
the closest thing you have to that is (1, something positive)
I just don’t UNDESTAJD what I should do on my test
because now it seems like any of them could have a - without me realizing so how do I know which ones do and which ones don’t
How am I supposed to write the equations if I am not given the y and x intercepts
<@&286206848099549185>
I don’t understand how we are supposed to make and write the equation for this graph because we are not given the x intercepts s
^
part a?
Yea and part b in a way
Ok
Wdym
like you could also have h(x)*(x-6) and it would still not change much
I’m so confused
so its the bare minimum of an equatiob from the given data
There are set x intercepts those can’t be changed
just properly set the x and y asymptotes
for example the x+2 can be aby other x-a me thinks
because the second root is not given, you can make one up and it would lie under yohr given criteria
i hope you understood what i meant
Kinda but I don’t know if I would if I did not know the x intercepts from the answer key if thag makes sense
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The correlation coefficient is defined in terms of the covariance and variances of two random variables (it is the covariance divided by the square root of the variances). Can there be a situation where the covariance equals 0 (or simply finite) whereas the denominator is infinity?
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"Fill in the right column of the table with T if the statement is true, and F if it is false. Note that you do not need to provide justification here."
The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.
They are asking for answer checking not answer provided
Sorry
I cant see the last word in 1st pic
2nd pic seems mostly wrong
Defined
Please rewrite it this way: picture 1: FTT… picture 2 :… picture 3:…
By subset do you mean proper subset?
The function f(x) = sqrt(2x-6) is defined at x=3
you wrote that this is false. you are wrong about that
The domain of f(x)=1/(x^2-9) is all x except x=3
you wrote that this is true. you are also wrong about this. the domain also excludes x=-3
Ik I said that 7th is wrong
can you answer jewels' question as well
6 7 8
What?
yeah looks like those are your only 3 mistakes
Which
It can’t be defined…
The 2 ones after the sqrt one are wrong
These (Wikipedia says a quadratic function, a doesn’t equal 0)
It’s 0..
what's "it".
Which ?
Sqrt one
Can’t you just tell me
it would be really convenient if these were numbered
@autumn fossil are those only wrong?
The one right after is also incorrect (the statement)
And 6th
Why is 6th wrong?
I doubt this is beneficial to you in any way
It’s turning into 0…
sqrt(0) is well defined
Why is 8 wrong?
Oh my bad
No…
I wasn't aware I had to match all those letters to unnumbered statements here
Leading coefficient isn’t 0
It can be
a>0
a=0
a<0
is this about the b^2 - 4ac = 0 question?
Gosh that was so bitchy…
a>d = 2 solution
a=d = 1 solution
a<0 = 0 solutions
so, not only have you turned two of the 0s into ds, but now a is supposed to represent the discrim??
Why are you complaining about literally everything 😭
Yeah, uh, <@&268886789983436800> this person has been repeatedly and excessively rude to the people helping them. Can you give this a look?
"Tonight, on 'What does Attitude mean?'..."
Are you kidding me?
I mean if you dislike that people are pointing out definitions to you, you can always, not ask.
nobody here owes you time.
There isn’t such a thing, t=b^2-4ac, when a doesn’t equal 0, t>0 two, t=0 one, t<0 zero, a=0 infinite (presume you are talking about that over R)
He wasn't, though
THAT WAS CRASS
trolling? I don't think so? in a general quadratic ax^2 + bx + c, if a = 0, it indeed turns into a linear function
He says I am trolling. I say I am the one who blocks him
the fuck you on?
That's not a trolly response; he's implying your definition's wrong.
Namely, that this is wrong.
Why
How exactly was the response trolling?
You should know how the discriminant test works
He neglected me
Actively responding to you isn't neglect
@carmine juniper if you want assistance from anyone in life, not just from people giving their time for free on Discord, you should be at least respectful to them.
That's actually the opposite of that
Nenni, I'm not a mod, but with all due respect, you have a history of not exactly having a nice personality to helpers.
so, here's a quick and friendly reminder that narcissism won't get you too far here, especially towards people who are trying to help you for free.
now, where was I
Gonna ditto the two above comments 
a quick scribbled T / F on each question in mspaint would go so hard
I am trying to learn and he just comes with comments “oh it’s correct if you think that, but everyone else will know that you’re wrong”
That’s impudent
Not every class uses the same definitions.
In fairness that's cos multiple ppl had already told you otherwise
If you have a discriminant D = b^2 - 4ac of an equation ax^2 + bx + c = 0 (and we assume here that a != 0, because otherwise this is not a quadratic), then
- D > 0 means the equation has 2 distinct solutions
- D = 0 means the equation has 1 distinct solution
- D < 0 means the equation has no [real] solutions.
These kinds of statements are not always a matter of rudeness.
Can you see how this differs from the justification you'd provided?
Let's not forget the emoji spamming incident with you 10 days ago
It is cause he stated that he doesn’t want to help and I should think what I think
Because you were provoking me?
People don't owe you help and it's not rude to say "under that assumption you are right, but that is not a common assumption"
Feel free to read through the entire channel from the start and correct your sentence when you are ready.
Neglection
Okay cool
One - the noun is "neglect"
Two - I've pointed out that that's the opposite of neglect
Take a day off to consider how to interact civilly with people trying to give you free help.
Even if you think it's rude, and it's been argued why it isn't, it's not the same as neglect
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also, to tie up loose ends
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how to do this integration
Divide the top and bottom by x^2
In the denominator, one x to divide (1 + x^2), and the other goes inside the square root
o
complete the square inside the root and sub x + 1/x
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Given a circle (O) with A outside. Draw tangent AB (B belongs to (O)) and draw BE perpendicular to OA (E belongs to (O)). Prove that AE is a tangent to (O).
Can someone explain this to me? My brain just short-circuited all of a sudden.
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just testing
This channel will close soon, could you move to one of the available ones?
sorry ofc
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This is an example from discrete structures. We defined a ternary operator:
[
\Lambda(p,q,r) = (\neg p \implies q) \ \lor \ (r \land q)
]
I need to prove that ${\Lambda}$ is not a functionally complete set.
I simplified the operator to
[
\Lambda(p,q,r) = p \lor q
]
I understand that ${\lor}$ (and therefore ${\Lambda}$) is not a functionally complete set as you can not express $\neg$.
I know it can be proven using the monotonic property in Boolean algebra, but I am wondering if there is another way?
squared_apple
i mean, i dont think there would be a different way for your problem unless you have a different way of proving {or} isn't a functionally complete set
i was just wondering
because I don't fully understand how to prove it that way...
know was meant I know it's proved that way
but not that i know how to
OR is monotonic, therefore so is anything you build from nothing but ORs. NOT is... not.
Yes. is it enough to write that? and conclude that therefore it is not a funct. complete set?
failure to express even one function means failure to be functionally complete so yeah
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Let f be a real smooth function with f(0)=1,f(1)=0,f'<0 and F(x,y,z)=f(x²+y²)exp(-z). I have shown that F is submersion and preimage of F for every c on R is a normal submanifold woth dimension 2. I have to show that preimage is diffeomorphic with: R², if c>0, unit circle, if c<0. How?
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hi
Just post your question whatever it is with pictures and someone will try to help.
If you labeled the points correctly, then this is correct yes
GeoGebra 💪
There is no domain and range to be seen though
Also F is unnecessary
Also, I don't know what "equation of the axis" is supposed to mean
x = 0 and y = 0??
Also, I don't really see the point in this. You just typed the expression in the example in GeoGebra
But the graphs definitely are correct
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is the best way of solving this is putting Q(x,y,z) into matrix form then perform a regular diagonlization?
with eigenvalues
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Prove that if a matrix $A$ satisfies $A^5 =I$, then $A$ is diagonlizable
toast
how do you approach this problem
is A a real matrix or a complex matrix? 
if it's a real matrix, I don't think the statement is true
but if it's a complex matrix, consider the minimal polynomial of A
mhm!
hmm
hm, it's not going to be enough to conclude I don't think 
I don't see a way to get around the minimal polynomial
have you seen that before?
not really haha
ah well, it's just the "smallest polynomial" q such that q(A) = 0, i.e. q divides every polynomial p for which p(A) = 0
and A is the matrix right
a useful fact is that q has the same roots as the characteristic polynomial of A, so A is diagonalizable iff q splits into linear factors
yup
if you choose an appropriate p, you can apply your theorem to find out what the eigenvalues of A must be