help-23

[flat frigate]

Nonna

[upbeat ridge]

THANK YOUUU

Yes, that one

[cedar rover]

But with exponents it's harder

[junior jacinth]

https://tenor.com/view/wtf-is-that-confused-gif-14675917

nah I’ll ask my teacher, hate these divisions in radicals

[cedar rover]

wait a second

[junior jacinth]

Waiting..

[cedar rover]

$\sqrt[3]{4^3} \cdot \sqrt[3]{\frac{2}{3}}$

[flat frigate]

Nonna

[cedar rover]

Notice that you can simplify the ^3 and get 4

Now you can just multiply what's inside the cubic roots

$\sqrt[3]{4^3 \cdot \frac{2}{3}}$

[flat frigate]

Nonna

[cedar rover]

See what I did?

[cedar rover]

[Don't forget that this rule works with multiplication/division only!]

[junior jacinth]

on the surface it looks like you combined the two to simplify it

Took the root and put it over the 4^3 * 2 / 3

[cedar rover]

exactly what step do you not understand?

[junior jacinth]

Where the root on the the left side went

how do I explain this

[cedar rover]

ok, first of all, roots are another way of writing powers, but with fractions

Is that clear?

[cedar rover]

.

[junior jacinth]

yup this basically answers my question

[cedar rover]

Ok let's explain the rest just in case

$\sqrt[3]{4^3} = 4$

[flat frigate]

Nonna

[junior jacinth]

my lack of understanding the power rules

[junior jacinth]

this I can solve no problem

[cedar rover]

We got to this, that is a multiplication of roots (aka powers, which means that the rules of powers apply)
$$\sqrt[3]{4^3} \cdot \sqrt[3]{\frac{2}{3}}$$

[flat frigate]

Nonna

[junior jacinth]

So then how would we turn that expression into an entire radical

[cedar rover]

yes

And you are done ^^

[junior jacinth]

hm

gotta catch up on my rules of powers

thanks tho

I’ll prolly b back with questions lmao

[cedar rover]

Sure

[junior jacinth]

.close

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[safe radish]

Please don't occupy multiple help channels.

[trim condor]

how do i describe the tranformation here

[safe radish]

@trim condor Has your question been resolved?

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[drifting heath]

Can @flat frigate bt give answer for a question

[idle parrot]

No

Its just latex bot

But you can use wolfram to solve

For example

,w x^2 -5x +6=0

[flat frigate]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Deep.#0001

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[hazy elk]

If image is unclear, the question is, "How many standard 6 sided dice do i have to roll to guarantee that some nonempty subset of the rolls add up to a multiple of 5"

[hazy elk]

i know that this question requires the pigeon-hole principle, but i don't know how to start

[safe radish]

@hazy elk Has your question been resolved?

[hazy elk]

<@&286206848099549185>

.close

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[cunning cloak]

can someone help me with the remainder theorem?

[cunning cloak]

ive tried researching

but everything is too confusing

this is the question im on

[idle parrot]

Do you know what remainder theorem is?

[cunning cloak]

i dont

thats what im asking - what is the remainder theorem

[idle parrot]

ig you understand hindi right?

https://youtu.be/F6onUHbWCus

[cunning cloak]

a little bit 😅 | mei kuchnai hindi chanthaho

[flat tangle]

https://www.khanacademy.org/math/algebra2/x2ec2f6f830c9fb89:poly-div/x2ec2f6f830c9fb89:remainder-theorem/v/polynomial-remainder-theorem

[cunning cloak]

ty

.close

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[viscid ore]

<@&286206848099549185>

[viscid ore]

I need someone to help m explain how Construct three Midsegments of the same triangle.

[rough swift]

randomly choose two sides of this triangle, then take the midpoint of each side and link these two midpoints, that's one of the three midsegments

[safe radish]

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[safe radish]

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[junior wagon]

What are the orders of R0, R90, R180, R270 in the group D4?

[junior wagon]

R0 is id, so order is just 1

But doesn't that mean we move the square 90 deg counterclockwise once?

How is that the identity then

[digital zephyr]

R0 is rotating by 0 deg

[junior wagon]

ah thanks

makes so much more sense

.close

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[timber atlas]

I’m having trouble forming the equation

Isn’t I =16?

So I wrote this

[stoic dune]

For some value of D, I is 16, yes.

[timber atlas]

So 16=425D?

[stoic dune]

Why is k the investment size?

When you put k there, what were you going to use it for?

[timber atlas]

I was using the format y=kx

[stoic dune]

Right. k is the "slope" that relates I and D

[timber atlas]

Ye

[stoic dune]

And you're given that I = 16, D = 425 is a point on your line

[timber atlas]

Yes

I don’t know but why is the answer this ? 16 with the investment and yeah it’s like the other way around

[stoic dune]

Okay. So you are correct that the equation is I = kD
For some unknown k

[timber atlas]

ok

[stoic dune]

You want to use your known point to solve for k

[timber atlas]

hm.. ok

So 16=425D, this equation?

Also I still don’t get why we solve for k here

[stoic dune]

D represents the investment amount
$425 is the initial investment

425 gets put in for D, not k.

[timber atlas]

Would it be this?

[stoic dune]

No, see reply

[light shoal]

this is about a 0.31% interest rate 😆

[timber atlas]

Is the investment the size of the deposit?

[light shoal]

(assuming monthly compounding)

almost no better than putting your money in a shoebox

[timber atlas]

Interesting

[light shoal]

ah wait i lied, that's the monthly interest rate

not so bad when you annualize it

[timber atlas]

Ok I got it thanks

.close

[safe radish]

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[fickle trail]

How come I can’t use FOIL to solve this? Yet I can do so with algebraic terms

[final halo]

You are probably foiling wrong

[fickle trail]

Hmmm I got a different answer

Close but not the same

[final halo]

Show your work

[fickle trail]

Thanks .. 0.25 and 0.5 this is what is throwing me off

I’m expecting 0.75 out of this

But when you subtract 0.25-0.5 it really makes me think that I miscalculated

Dunno why that is 🤷🏻‍♂️

It’s like an illusion. Expecting a different result

0.25-0.5 = -0.25

Same for anyone else or just me?

Perhaps I am thinking like how I would count money .. 1.25 - 0.5 = 0.75

But for 0.25-0.5 = -0.25 I need to think with the x coordinate and a line graph maybe

Good to know that FOIL still holds up

[worthy hemlock]

Are you still stuck on this?

[fickle trail]

.close

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[worthy hemlock]

I'll take that as a no

[safe radish]

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[faint folio]

what is the differnence between each term in the first one and the ratio between eachterm in the second one

[faint folio]

i dont know how to find it if the numbers are not next to eachother

would i do something like substitistion?

[cedar rover]

How do you call the constant that you keep adding to get the next element (sorry english is not my main language)?

Anyways, you can find that using the formula

$a_n = a_m + (n - m) \cdot d$

[flat frigate]

Nonna

[cedar rover]

and then solve for d

[faint folio]

sorry i dont get it

cause i dont have a or d

[cedar rover]

$t_n = t_m + (n - m) \cdot d$

[flat frigate]

Nonna

[cedar rover]

The d is what you are finding

[faint folio]

yeah idk how to find the d

[cedar rover]

Substitute the values you have and then solve for d

[radiant tapir]

For the second just use the fact that 72x^2 = 40.5 and solve for x. Then the general formula is some constant(which is easy to solve for) times x^n

X is the ratio between following terms btw

[cedar rover]

Ooof my bad, I didn't read the question!

[faint folio]

oh also , would 20 = a +(0)(d) become 20= a?

[radiant tapir]

No, your answer is the correct one for the first one

[faint folio]

.close

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[hallow blade]

cos(π/18) ≈ 0.984807753

[hallow blade]

how?

[nova creek]

Is that radians or degrees?

I figure radians, but you never know

Why do you ask how? Why shouldn't it be that value?

[hallow blade]

sin(4π/9) into cos(π/18)

the calculator said 0.9848 radians but how?

[nova creek]

What do you mean "into?"

[hallow blade]

well it was expressed into its co-function

[peak estuary]

pi/18 is somewhat small so cos(pi/18) should be somewhere near 1

do you not know what cosine is?

[hallow blade]

i'm starting to not know.. i've been stuck on this question for 30 mins now

hold on lemme get a pic

see item no. 7

oh mb it's not cos(pi/18) it's just pi/18

[nova creek]

It should say cos(pi/18)

Must be a typo

[hallow blade]

okay, then how did it convert to 0.9849 radians?

[nova creek]

The answer isn't in radians

It's not an angle

Just take your calculator and plug in cos(pi/18)

[nova creek]

The answer is just ≈ 0.985. Not 0.985 radians, just 0.985

[hallow blade]

you rounded it up but my question is how?

[nova creek]

Are you asking how the calculator calculated cos(pi/18)?

[hallow blade]

into 0.9848 radians, yes

[nova creek]

It's not radians

It's just 0.9848

[peak estuary]

the input is in radians. the output is just a number

[nova creek]

π/18 is in radians

Anyway, I don't actually know how calculators actually calculate it. I know there's infinite series to approximate it, at least

[fiery prawn]

mclaurin series

[hallow blade]

i don't watch anime

i have homework

[nova creek]

You're probably never going to have to calculate it by hand. Scratch that, I can guarantee you'll never need to calculate by hand

[peak estuary]

calculators afaik often use the CORDIC algorithm instead of taylor series

not that I know how it works

[hallow blade]

huh?

ok hold up, so pi/18 is already in radians, and 0.9848 is just a number equal to pi/18?

[peak estuary]

no

[fiery prawn]

pi is irrational and goes on forever

[peak estuary]

cos(pi/18)=0.9849....

[fiery prawn]

thats just an approximation

[nova creek]

cos(pi/18) ≠ pi/18

[peak estuary]

the function cos at the input pi/18 (in radians) equals 0.9848... (a number)

[hallow blade]

so 0.9848 is NOT in radians?

what do i do then? i need something in radians, i just leave it as pi/18?

[peak estuary]

you don't need a result in radians

[hallow blade]

well the instructions says that i also need to find the value of the trigonometric function

all the other examples had radians at the end

[nova creek]

And you found it. It's 0.9848. The answer is unitless

[peak estuary]

none of the other examples have radians as a result either

[hallow blade]

these are not radians?

sin 52deg = 0.907 (in something no units?)

[peak estuary]

sin 52 deg should be somewhat closer to 0.7 I think

but yes no units

[hallow blade]

okay so the value of the function is not in radians

[peak estuary]

actually not sure how you got 0.907

the value of the function is a number

[hallow blade]

it's in a number with no units

how do i calculate for this number?

[peak estuary]

use a calculator

[hallow blade]

noted.

.close

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[flat forge]

i don’t understand where to start here

[fiery prawn]

Asking for the inverse input of -2

[tiny gorge]

they are asking the reciprocal of the function

[flat forge]

ok i get that but

how do i figure that out

is that just -5?

[tiny gorge]

yea

[fiery prawn]

Yh

[wise shell]

f maps x to y

[flat forge]

ohhh

its that easy?

[tiny gorge]

yea lol

[wise shell]

F inverse maps y to x

[flat forge]

ok thx

would this one be the same thing

but 2 x -5 -4?

-14?

[safe radish]

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[vagrant sand]

A game uses a deck of n different cards, where n is an integer and n is greater than or equal to 6 The number of possible sets of 6 cards that can be drawn from the deck is 6 times the number of possible sets of 3 cards that can be drawn. Find n.

[vagrant sand]

i got 26 for this one

since a 6 card set is 6 times as much as a 3 card set

i formulated the formula 6x = 3

divide both by 6

and got 1/2 for x

than i made another formulan n = 52x

since there are 52 cards in a deck

i plug in 1/2 for x

and i got 26

[stoic dune]

There are not 52 cards in this deck

There are n cards, all of them different

[vagrant sand]

in a standard deck that would be true though right?

[stoic dune]

6 times as much what?

[vagrant sand]

6 times more than the 3 card set

[stoic dune]

6 times more what?

6 times more ways to rearrange?

[vagrant sand]

6 times more cards

[molten heart]

this is the number of possible sets of k elements from n elements?

[vagrant sand]

ok?

what does binomial coefficient have to do with this problem

we're dealing with combinations

so we would use binomial coefficient to solve this

[molten heart]

is 13 the answer?

[vagrant sand]

ye

there is different combinations thats why we use ncr

[molten heart]

you get cubic equation

when you write nC6= 6*(nC3)

and nCk write like this

do you understand it

[safe radish]

@vagrant sand Has your question been resolved?

[vagrant sand]

how were you able to find n from the factor?

[molten heart]

is it ok?

[safe radish]

@vagrant sand Has your question been resolved?

[safe radish]

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