#help-26

226100 messages · Page 238 of 227

alpine carbon
#

Hello
x + y = 54
xy = 36
Inverse x + Inverse y = ?

restive inlet
#

by inverse x + inverse y do you mean:
$$\frac 1x + \frac1y$$

thorny flameBOT
#

ℝamonov

alpine carbon
#

Yes

restive inlet
#

hint: how would you simplify
$$\frac 12 + \frac13$$

thorny flameBOT
#

ℝamonov

alpine carbon
#

2/6

restive inlet
#

is wrong

#

2/6 simplfies to 1/3

alpine carbon
#

7/6

restive inlet
#

are you implying that 1/2 is equivalent to 0?

#

how are you getting 7/6?

alpine carbon
#

OOps

#

5/6

#

lol

restive inlet
#

5/6 is correct, and supposing you applied the correct steps to get that

#

apply pretty much the exact same methodology to your question

#

i.e. first combine 1/x + 1/y into a single fraction

alpine carbon
#

x + y / xy

restive inlet
#

(x+y)/(xy)

#

and then note the information you are given

#

$$\frac{x+y}{xy}$$

thorny flameBOT
#

ℝamonov

alpine carbon
restive inlet
#

wdym

#

what steps did you take to simplify
$$\frac12 + \frac13$$

thorny flameBOT
#

ℝamonov

alpine carbon
#

Oh I got it

alpine carbon
#

Thank you !

#

.close

topaz sinewBOT
#
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alpine carbon
#

a ^2 + b^2 + c^2 +3 = 2(a+b+c)
c = ?

topaz sinewBOT
restive inlet
#

what have you tried

alpine carbon
#

It has to do with algebraic union I guess

restive inlet
#

algebraic union?

alpine carbon
#

algebraic identity

restive inlet
#

hint: 3 = 1 + 1 + 1

alpine carbon
#

I have no idea

restive inlet
#

$$(p-1)^2 = p^2 - 2p + 1$$

thorny flameBOT
#

ℝamonov

alpine carbon
#

Ok then?

restive inlet
#

consider how that can be applied to you question

#

have a think for 5 minutes

alpine carbon
#

Got it

#

(a+1)^2 + (b+1)^2 + (c+1)^2 = 0

restive inlet
#

wrong sign

#

a-1,
b-1,
c-1

alpine carbon
#

Oh yes

#

OK what should I do next

restive inlet
#

consider the type of number you get when you square a real number

neon iron
restive inlet
#

and assuming a,b,c are real, consider the only possible way of getting 0 when adding the stuff on the left

neon iron
#

Uhh…

restive inlet
#

yes

alpine carbon
#

Thanks

#

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topaz lynx
topaz sinewBOT
topaz lynx
#

var(x) = e(x^2) - (e(x))^2

#

= (5.2736) - (2.0316)^2

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sqrt(var(x)) = s.d

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= 1.07

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it should be 1.08 :/

#

how am i supposed to get this exact answer

sweet shard
topaz lynx
#

still same issue

sweet shard
#

show your work?

topaz lynx
#

lemme type it all out 1 minute

#

$\frac{1(22) + 4(31) + 9(27) + 16(7)}{95} - ( \frac{1(22) + 2(31) + 3(27) + 4(7)}{95})^{2}$

thorny flameBOT
#

The Torrent v2

topaz lynx
#

idk how to do bigger brackets but thats my working

sweet shard
topaz lynx
#

answer is wrong :/

sweet shard
thorny flameBOT
#

riemann

topaz lynx
#

if my working is right...... why is answer wrong :/

#

mark scheme cant be just wrong

#

because i also have a different mark scheme which my teacher made

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which also says 1.0764

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both cant be wrong by co-incidence

topaz lynx
#

OH

#

that might explain it....................................

sweet shard
#

yea the key hint is "survey" and not "population"

#

explanation for why $n-1$ instead of $n$

thorny flameBOT
#

riemann

topaz lynx
#

thanks for the help, ill check out that link to make sure i dont forget in the future lol 👍

#

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topaz sinewBOT
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bright dagger
#

A rock is thrown downward at a speed of 20ft from the top edge of 500 ft. The height of the rock above the ground t seconds after the rock is thrown is: s(t)= 500-80t-16t^2
-how many seconds after the rock is thrown does it hit the ground?
-what is the sspeed of the rock when hits the ground?

viscid thistle
#

for second one, differentiate s(t)

bright dagger
#

so is v(20) = -20-32t ?

viscid thistle
#

s’(k) where k is the time when it hits ground

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v(20) = -80 - 32(20)

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assuming it doesn’t reach terminal velocity

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t= 20 is way too much

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i don’t think 20 is right

viscid thistle
#

i hope all of that made sense

bright dagger
#

yes

viscid thistle
#

there we go

#

all sorted

bright dagger
#

but in this case v(t) is negative, should I leave it like that or have a positive v?

#

because is ft/sec

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anyway tyvm

#

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topaz sinewBOT
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neon iron
#

hello

topaz sinewBOT
neon iron
#

how can i solve this?

#

and this one

restive inlet
#

what have you tried?

neon iron
#

and for the second one:

3x (x+1) = x (4x-1)
3x+3 = 4x - 1
x = 4

restive inlet
#

the work is fine

neon iron
#

is all correct?

restive inlet
#

sort of skipped a step for the first one,
should explicitly state what allowed you to cancel x from both sides like that
but other than that its fine

neon iron
#

hm

topaz sinewBOT
#

@neon iron Has your question been resolved?

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neon iron
#

thanks

#

.close

topaz sinewBOT
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analog tusk
topaz sinewBOT
grim jacinth
#

<@&268886789983436800>

thorn briar
#

@analog tusk do not spam the help channels with memes

#

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karmic fox
topaz sinewBOT
karmic fox
#

idk how to do

deep swift
#

You need to stop reopening under a new channel

karmic fox
#

what?

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Should i open under a "not new channel"?

deep swift
#

Havent you posted this like 3 times already?

karmic fox
#

what?

#

I posted once earlier

topaz sinewBOT
#

@karmic fox Has your question been resolved?

karmic fox
#

<@&286206848099549185>

topaz sinewBOT
#

@karmic fox Has your question been resolved?

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pastel gate
topaz sinewBOT
pastel gate
#

find derivative?

solemn wigeon
#

do you know how to find the derivative of sqrt(x)

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and e^x?

pastel gate
#

i am not familiar

solemn wigeon
#

first learn that

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then ask this question again

empty sail
#

How are you doing derivatives if you aren't familiar with the basic rules?

pastel gate
#

i'm gonna go check

#

thanks guys

#

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maiden wave
topaz sinewBOT
maiden wave
#

how can i convert this into a power series

#

i found the derivative of ln(5-x)

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however when i try to find its convergence, for which value do i center it

keen venture
#

Know any related power series?

keen venture
maiden wave
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(x-c)

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what would c be ?

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0 ?

keen venture
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Any (where f is defined)

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Since f is defined at x = 0, you can construct a series around x = 0.

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You should have a series in terms of ln given to you, though.

maiden wave
#

could you guide me through the whole problem i dont really undertsand very well

#

.close

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neon iron
#

Hello, I'm working on an assignment for Business Management (BUS-130-60) and I've been struggling to understand the assignment as a whole. I don't think its asking me to convert ratios as it gives me a list of ratios that seem to have been automatically converted from the finances it has given me. The assignment focuses on Financial Analysis and converting ratios. For the first question, I just answered that all the ratios are correct. I'll be sending a GIF of the entire assignment, along with a large list of all the finances, ratios, and questions given:
https://gyazo.com/a95c1f899d6bed350de48a628a8bc0e0

Use the following worksheet to help Bella and Matias Morales calculate the following twelve financial ratios from their income statement and balance sheet.

Identify those ratios for High Country Tires that are significantly different from the industry median.

Calculate High Country Tires’ cash conversion cycle using the following formula: Average Inventory Turnover Ratio + Average Collection Period Ratio – Average Payable Period Ratio. Make the same calculation for the typical firm in the industry. Comment on your calculations.

The Moraleses took on additional debt to open their second location. Does it appear that High Country Tires is overloaded with debt?

What are the potential problems that exist in High Country Tires that might cause the differences you identified in question 2?

What specific steps do you recommend the Moraleses take to resolve the problems you identified in question 5 and improve their ratios next year?

neon iron
#

High Country Tires Income Statement

Sales
Cash or Debit Card $1,912,504
Credit $762,327
Total Sales $2,674,831

Cost of Goods Sold
Beginning Inventory $136,321
Plus Purchases $1,961,070
Goods Available for Sale $2,097,391
Less Ending Inventory $356,875
Cost of Goods Sold $1,740,516
Gross Profit $934,315

Expenses
Mortgage $71,550
Wages, Salaries, and Benefits $494,565
Utilities $84,280
Advertising and Marketing $10,876
Vehicle Expense $49,532
Bank and Card Fees $2,400
Insurance $8,763
Maintenance and Repairs $8,943
Office Supplies $2,567
Internet and Telephone $1,200
Computer Equipment and Maintenance $7,489
Shipping and Postage $457
Depreciation $33,652
Accounting Services $4,800
Legal Fees $3,000
Business Licenses and Permits $2,000
Training and Education $2,575
Interest Expense $24,207
Miscellaneous Expenses $1,743
Total Expenses $814,599
Net Income (Before Taxes) $119,716

High Country Tires Balance Sheet

Assets
Current Assets
Cash
$138,232
Accounts Receivable $141,289
Less Allowance for Doubtful Accounts $5,000 $136,289
Inventory
$356,875
Prepaid Expenses and Other Current Assets
$50,245
Total Current Assets $681,641

Fixed Assets
Land
$155,750
Buildings $288,755
Less Accumulated Depreciation $145,250 $143,505
Furniture, Fixtures, and Equipment $189,670
Less Accumulated Depreciation $136,579 $53,091
Total Fixed Assets $352,346
Total Assets $1,033,987

Liabilities
Current Liabilities
Accounts Payable
$227,498
Bank Loan
$67,483
Notes Payable
$98,229
Accrued and Other Current Liabilities
$43,014
Total Current Liabilities $436,224

Long-Term Liabilities
Mortgage
$94,216
Note Payable
$42,485
Total Long-Term Liabilities $136,701
Total Liabilities $572,925

Owner's Equity
Net Worth $461,062
Total Liabilities and Owner's Equity $1,033,987

High Country Tires Ratios

Ratio This Year Last Year Industry Median
Current Ratio 1.56 1.42:1 1.4:1
Quick Ratio 0.74 0.68:1 0.7:1
Leverage
Debt 0.55 .58:1 0.725:1
Debt to Net Worth 1.24 1.31:1 1.73:1
Times Interest Earned 5.95 4.75:1 4.7:1
Operating
Average Inventory Turnover 7.06 times per year or 51.7 days 6.83 8.2 times per year
Average Collection Period 5.59 times per year or 65.3 days 5.12 8.0 times per year
Average Payable Period 8.62 times per year or 42.3 days 8.01 13.4 times per year
Net Sales to Total Assets 2.59 2.85 3.70:1
Profitability
Net Profit on Sales (Net Profit Margin) 4.5% 4.1% 4.8%
Net Profit to Assets (ROA) 11.6% 7.5% 11.4%
Net Profit to Equity (ROE) 26.0% 21.4% 23.8%

leaden tusk
#

im gonna be honest with you friend there is no way anyone is reading that

neon iron
#

lol

#

is there a person you think would?

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I just went to the 'Business' version of this server and they tried, and they sent me here

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and they said that the math people would understand this better

#

If you want I can send you the questions I was given, maybe they are easier then you think

#

nvm i already did that

leaden tusk
#

they sent you here cause they don't wanna read it

neon iron
#

are you familiar with what this is?

#

i went through all of it and i can promise you it isn't as terrifying as you think

#

ignore the large paragraphs at the beginning and just focus on the questions

topaz sinewBOT
#

@neon iron Has your question been resolved?

topaz sinewBOT
#

@neon iron Has your question been resolved?

neon iron
#

I did number 1 and 2

#

Can someone help me do

Calculate High Country Tires’ cash conversion cycle using the following formula: Average Inventory Turnover Ratio + Average Collection Period Ratio – Average Payable Period Ratio. Make the same calculation for the typical firm in the industry. Comment on your calculations.

#
  1. The Ratios are all-calculated to their exact ratios as intended.

  2. Ratios that are significantly different from industry median include; Debt, Debt to Net Worth, Times Interest Earned, Average Inventory Turnover, Average Collection Period, Average Payable Period, and Net Profit to Equity.

  3. High County: 4.03 Median Industry: 2.8. High County is making twice as much as the average Industry.

  4. Yes, most of the company's assets are being financed through debt as opposed to equity. Debt to Net Worth is also far above what it should be.

  5. Many of the ratios are above average but could be better then the Industry Median when it comes to everything. Debt could be a little better, but still remains better then the average Industry.

  6. I recommend that the Moraleses decrease their debt more and increase their profit from sales more.

#

Finished, if anyone wants to contribute more to this answer I'd appreciate it

sweet shard
#

At this point I suggest you hire a local tutor or tax accountant to do all that arithmetic for you

neon iron
#

.close

topaz sinewBOT
#
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Ask your math question in a clear, concise manner.
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After 15 minutes, feel free to ping <@&286206848099549185>.
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viscid summit
#

Hey

topaz sinewBOT
viscid summit
#

I need help with absolute value limits

#

<@&286206848099549185>

leaden tusk
#

• After 15 minutes, feel free to ping @Helpers.

#

what have you tried

marsh mortar
#

do u just want the answer or help solving it

viscid summit
leaden tusk
viscid summit
#

Okay so I tried subbing in x

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I got 0/0

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But when I common factor iut a 2 on top

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The limit is 2

leaden tusk
#

...?

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factoring out a 2 isn't gonna change the limit

viscid summit
#

Yea it is

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Cause

leaden tusk
#

...

viscid summit
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2 (x+4)

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Right

leaden tusk
#

mhm

viscid summit
#

Cancel that out

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With the denominator

leaden tusk
#

the denominator is the absolute value

viscid summit
#

Meaning there’s a hole

leaden tusk
#

no

viscid summit
#

Oh

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So you’re saying I have to get rid of that absolute value

leaden tusk
#

apply the definition of the absolute value

viscid summit
#

What even is absolute value

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Isn’t it where if it’s a negative it turns to a positive

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But it’s already positive

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On the inside

toxic badger
#

$\lvert x \rvert = \left{
\begin{array}{ll}
-x & \quad x < 0 \
x & \quad x \geq 0
\end{array}
\right.$

viscid summit
#

So if it’s less than 0 it’s negative

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Greater it’s positive

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So to get the answe

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So if |x+4| > 0. It’s just x+4

leaden tusk
#

that should just be a x < 0 not leq flonshed

leaden tusk
#

cause if you have geq and leq you're giving it two definitions at one point

toxic badger
#

Right, mb

viscid summit
#

What’s geq and leq

leaden tusk
#

greater than or equal to / less than or equal to

viscid summit
#

Ohh

thorny flameBOT
#

[TEB] darthlothins

leaden tusk
viscid summit
#

So it’s basically repetitive

leaden tusk
vital relic
leaden tusk
#

yeah i was gonna point that out too but same meaning lmao

#

if it works it works catblush

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and i don't know how to do arrays on latex bleak

viscid summit
#

So if it’s positive that means I’m approaching the limit from the positive side

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Which would give me 2

leaden tusk
#

yep

viscid summit
#

And if it’s negative

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The absolute value would be

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  • (x+4)
leaden tusk
#

right

viscid summit
#

Which would be negative 2

leaden tusk
#

yup

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so what can you say about the limit

viscid summit
#

Does not exist

leaden tusk
#

correcto

viscid summit
#

But how would I write that

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The equation

leaden tusk
#

DNE?

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what do you mean the equation

toxic badger
viscid summit
#

It’s a piece wise function right

vital relic
#

$$\abs{x}:=\begin{cases}\phantom{-}x,\quad x\geq0\-x,\quad x<0\end{cases}$$

thorny flameBOT
#

Shuri2060

leaden tusk
#

the absolute value function, yeah

viscid summit
#

Yea

leaden tusk
#

|x| implies the piecewise definition seem above ^ though

neon iron
#

how to get the ability to post on the advanced mathematics channels? I am currently unable to

leaden tusk
#

this is someone's help channel bleak

neon iron
#

What does that mean, Sorry, I am new to discord

viscid summit
leaden tusk
#

someone is asking for math help here

neon iron
#

Sorry

leaden tusk
viscid summit
#

Does it always have to be less and geq

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Or can it be leq and greater

neon iron
#

I did not know, please forgive me

leaden tusk
#

i'm pretty sure it can be the other way around, but it's the general consensus

viscid summit
#

Oh

leaden tusk
#

though correct me if i'm wrong shuri bleak

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wait i think i am wrong

viscid summit
#

You know how it says x>0

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Do I just isolate the x from x+4

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So x>4

leaden tusk
#

yeah i'm wrong that is the only definition

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and what do you mean by that

viscid summit
#

The absolute value function

leaden tusk
#

you're not solving for any inequality

#

you're just applying the definition seen based on if x >= 0 or x < 0

viscid summit
#

Don’t I have to do something like this

leaden tusk
#

you can just say the limit DNE

viscid summit
#

Yea

#

Oh

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Then when would I do that

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When I want to determine the anvoslute value function?

leaden tusk
#

or you can say
$$\lim_{x\to -4^+}f(x)=2$$ and $$\lim_{x\to -4^-}f(x)=-2$$ therefore $\lim_{x \to -4}f(x)=$DNE

thorny flameBOT
#

a disappointing son

viscid summit
#

If I wanted to find the function and not the limit

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I would do what I did above right

leaden tusk
#

i'm not sure what you mean by "find the function"

viscid summit
#

F(x) = the pic I sent

leaden tusk
#

like by breaking it into 2 parts?

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cause you already did that when you evaluated the limit

viscid summit
#

Like graphing approach

leaden tusk
#

OH

#

yeah

#

remember it's geq 0 though not just >

viscid summit
#

Oh

#

So could it be uh both ways or no

leaden tusk
#

no

viscid summit
#

Why’s that

#

Ohh

#

Is it because of the restriction

leaden tusk
#

wait

#

i said "OH" but i think i'm still confused lmao

viscid summit
#

Same

leaden tusk
#

AH

#

i think

#

i think? i get what you're asking

#

so what you'd write as the function's graph

#

like in a graphing calculator or something

viscid summit
#

Uh

leaden tusk
#

but you wrote 4 instead of -4

viscid summit
#

So what would the proper function look like

leaden tusk
#

same thing you have written but it would be x > -4 and x < -4

#

along with a y= in front

viscid summit
#

No geq?

#

Or leq?

leaden tusk
#

naw cause your actual function is undefined at x=-4

viscid summit
#

Cause that’s the restriction right

#

Meaning hole @-4

leaden tusk
#

there's not a whole

#

there's a jump

viscid summit
#

Wait

#

So on the graph would it just be 2 straight lines

leaden tusk
#

yeah

viscid summit
#

One at 2 and one at -2

leaden tusk
#

mhm

#

horizontal lines, to be clear

viscid summit
#

Yea

#

But both these lines don’t touch x=-4?

#

Cause that’s the limit

leaden tusk
#

they don't touch x=-4 cause your function is undefined at x=-4

#

$\frac{2x+8}{\abs{x+4}}$

thorny flameBOT
#

a disappointing son

viscid summit
#

Oh yea

#

So would the graph look something like this

leaden tusk
#

other way around

#

it's -2 for x less than -4

#

and 2 for x greater than -4

viscid summit
#

Oh

#

Okay

#

But the circle thing is correct right

leaden tusk
#

yes

viscid summit
#

Like the value would always be a certain number when x is greater or less than 4

leaden tusk
#

yes, that's true

viscid summit
#

Yea it makes sense

#

Wait but why 4 tho

#

I get the saying but like why’s it only when it’s greater or less than 4

#

That that value exists

#

Is it because of the absolute value

leaden tusk
#

ah shoot that's supposed to be -4

#

i keep forgetting your limit is x approaching -4 and not +4 bleakcat

viscid summit
#

Does it still work if it’s -4

#

Wait lemme see

topaz sinewBOT
#

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woeful ridge
#

Hello i was just wondering in the equation S=ut+1/2at^2 we times 2 not just to S but also to ut

mortal thunder
#

$S = ut + \frac{1}{2} at^2$ is the equation

thorny flameBOT
woeful ridge
#

oh whoops i meant when we are trying to solve for a

#

fuck sorry to mention that

mortal thunder
#

yeah you multiply with all

woeful ridge
#

ok but why do we multiply the, ut and not just the s cause arent we just multiplying to the other side to get rid of the 1/2

mortal thunder
#

$S - ut = \frac{1}{2}at^2$

thorny flameBOT
woeful ridge
#

so then if i wanted to figure out what A was equal to it would look like A = S - UT x 2 / t^2

topaz sinewBOT
#

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bronze cipher
#

hey as you know , this is a product law of logarithms , and what if the log is negative

how do i use the law then?

im sorry if my doubt is silly im just a 14 year old

leaden tusk
#

if which log is negative

bronze cipher
#

like this

#

what will be the ans if i use the product law on it

leaden tusk
#

same concept

bronze cipher
#

oh so will the second log be positive or negative

#

thats my doubt

leaden tusk
#

what do you think it will be?

bronze cipher
leaden tusk
#

you are correct

bronze cipher
#

omg thank you

#

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azure socket
#

can anyone help me please

topaz sinewBOT
azure socket
#

I did something like this

#

not sure im correct or not

topaz sinewBOT
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@azure socket Has your question been resolved?

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steep tiger
#

what's this method called?

topaz sinewBOT
steep tiger
#

the one where I subtract 10p=6,6666... with p=0,6666...

lyric gale
steep tiger
#

hmmm

neon iron
#

can you elaborate ?

steep tiger
#

so it's basically to find the fraction form of 0,6666... right?

neon iron
#

Are you doing geometric series ?

#

that's easy

steep tiger
neon iron
#

infact you can do it to all repeating numbers

steep tiger
#

this is not a geometric series

#

you need to find the x

#

also

#

, = .

neon iron
#

isn't that 0 tho ?

steep tiger
#

yes

neon iron
#

you can use logarithms next time

steep tiger
#

not sure it'd be easier

neon iron
#

remember log(a^b)=b*log(a) in this case you can take the log of both sides and it will be a product of two numbers

#

as in x*log(0.66666)=log(0.999999)

steep tiger
#

found the answer this way

neon iron
#

how did 9/9 become (2/3)^2?

steep tiger
#

that's 4/9

topaz sinewBOT
#

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wanton furnace
#

Express -125/216 in power notation

topaz sinewBOT
neon iron
#

(5/6)^3

wanton furnace
wooden matrix
chrome glen
#

(Epicly)

wanton furnace
#

thnks all!

#

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wanton furnace
#

can someone pls help?

topaz sinewBOT
empty sail
#

Exponent properties

neon iron
#

you have to sort of "distribute" the exponent over the numerator and the denominator

#

i.e. cube both negative 2 and 7

wanton furnace
#

like, -2/7^3 ?

empty sail
#

Not exactly

neon iron
#

no, do it to both the numerator and the denominator

empty sail
#

It gets distributed to both the numerator and denominator

wanton furnace
#

-(2/7)^3 ?

neon iron
#

that's the question

empty sail
wanton furnace
#

no the question is, (-2/7)^3

neon iron
#

technically it's the question

#

because the answer is the same for both

empty sail
#

Because luckily it's to an odd power

#

If it was to an even, different problem

#

$$\left(\frac{a}{b}\right)^x = \frac{a^x}{b^x} $$

thorny flameBOT
#

dldh06

empty sail
#

That's the property you're applying

wanton furnace
neon iron
#

yes correct but you have to be careful

#

because that would be wrong if it was an even power

empty sail
#

You keep signs with the numbers

neon iron
#

to be exact, the answer is
(-2^3)/(7^3)

empty sail
#

Don't separate the sign

wanton furnace
#

umm so, (-2^3)/(7^3) & -(2^3/7^3) both r correct?

empty sail
wanton furnace
#

oh okay! Thnks! U guys helped a lot!

empty sail
#

Example (-2)^3 = -8 but doing -(2^3), you do the inside first so -(8) so odd powers, just a coincidence

#

(-2)^2 = (-2) * (-2) = 4
But -(2^2) = -(2 * 2) = -(4) = -4

empty sail
wanton furnace
#

yeah

#

Now I understood

#

.close

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neon iron
topaz sinewBOT
neon iron
#

help pleasee

static void
#

I'm blanking

#

Can you factor?

#

First?

neon iron
static void
#

There we go

#

So it's really just 2x+13

#

Just multiplied by $\frac{x-4}{x-4}$

thorny flameBOT
neon iron
#

okayy

#

so we do 2x+13 times x-4/x-4

topaz sinewBOT
#

@neon iron Has your question been resolved?

golden moon
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neon iron
#

I have a question about Euclidian's algorithm. If we have integers a and b where b > a > 0, the HCF of a and b being x, we can let k = b - a, then x (the HCF) is still a factor of this new number k (b = ex, a = gx => k = b - a = ex - gx = x(e-g)). But I don't know how to explain why the HCF doesn't change (e.g increases) from the first pair a, b to the new pair a, k... maybe this is obvious but idk?

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#

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topaz sinewBOT
#

@neon iron Has your question been resolved?

wary oak
#

well the hcf of a is still x, so it cant be bigger than that for the pair (a, k)

topaz sinewBOT
#

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random bloom
#

Hi, I'm developing a game and I've got a problem. I got 2 objects, 1 and 2. I want to calculate the rotation of object 1 needed to exactly look at object 2. I've got the lengths A and B.

random bloom
#

How can I calculate this?

#

wait

#

i already know it lol

#

this is like literally just tan

#

ok im dumb this is like 9. grade stuff lmao

#

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serene hound
#

The M and N sets are such that M U E = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9), M - N = {0, 1, 2} and N- M = {7, 8, 9). Determine the M and N sets

serene hound
#

I need help

vital relic
#

could consider drawing a venn?

serene hound
#

Oh thanks

#

I’m stupid

#

.close

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small halo
#

Can I get help on these word problems?

topaz sinewBOT
oblique crag
#

At day 0 the watch is 1 second behind.
Your first point for your function should therefore be P(0|1)
His watch falls behind 2 seconds every day so by day one his watch will be 3 seconds behind
Your second Point therefore is P(1|3)
4)
The same as described in number 3 applies here
She has 75 photos already on her phone
P(0|75)
Each day she wants to take another 25.
P(1|100)

small halo
oblique crag
#

Do you know how to get a function with 2 points ?

small halo
#

Is P(0|1) P 0/1? Or am I misinterpreting?

oblique crag
#

P is point

oblique crag
#

Ok so lets break this down what is always at x =0?

oblique crag
#

?

small halo
#

Oh a question. 🤣 🤦

oblique crag
#

At x = 0 you will always find the y-axis intersection
In your general linear function where is the y-Intersection located ?
As a reminder (General Equation of a linear function):

f(x) = a*x+b
oblique crag
#

yes exactly so You know that the function you are trying to model will intersect the y-Axis at y = 1

#

F(x) = a*x +1

small halo
#

And x will equal 0?

oblique crag
#

when you set in the first point yes

#

but you still need a

#

the slope of the function

small halo
#

It increases by 2 right?

#

So thats the slope?

oblique crag
#

Yes so your complete function would be

f(x) = 2x+1
small halo
#

Alright so part a is done.

oblique crag
#

Yes now on to part b. In part b you are asked to find x. so you insert all the information given in the task

small halo
oblique crag
#

Not into x. X is the variable you are trying to calculate. Think about it. the function we modelled above will give us the seconds the watch is behind when we insert the number of days in x

small halo
oblique crag
#

Yes you were right on track you need to insert the 17 for y because why gives you the number of seconds the watch is behind.
In our case:

f(x) = 2*x+1
Now we insert y:
17 = 2*x+1
Then we solve for x.
small halo
#

Now I see.

#

Let me solve that real quick.

#

8?

oblique crag
#

Yes it's correct

small halo
#

Alright.

oblique crag
#

Need help with number 4 ?

small halo
#

For the second one I already got part a done: f(x) = 20x + 75 but I need help with part b.

oblique crag
#

We can just insert the number of days she plans to stay at the excavation site into x. Then we need to subtract the result with the maximum number of photos the result is the number of photos she needs to delete

small halo
#

So: 7 = 20x + 75? Or f(x) 20*7 + 75? 🤣

oblique crag
#

second one we insert for x

small halo
#

Ok.

#

And then subtract the result by 200. Let me do that real quick.

#

So the answer is 215.

#

So she would need to delete 15 photos?

oblique crag
#

yes that'is correct

small halo
#

Well thats it. Thank you for your help!

#

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#
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valid jungle
#

Can someone tell me why this is wrong?

topaz sinewBOT
oblique crag
#

,rotate

thorny flameBOT
sweet shard
#

share your work

valid jungle
#

I tried this first and it didn’t work

sweet shard
valid jungle
#

Where

sweet shard
#

$a + b / c + d \neq (a+b) / (c+d)$

thorny flameBOT
#

riemann

valid jungle
#

why

sweet shard
#

plug in numbers

#

PEMDAS is an acronym for the words parenthesis, exponents, multiplication, division, addition, subtraction. Learn about PEMDAS with concepts, definition, examples and solutions.

vital relic
#

maybe say where the error is

#

oh in the answer box?

sweet shard
sweet shard
sweet shard
valid jungle
#

So what you reckon I should do

sweet shard
#

i reckon you should learn PEMDAS

sweet shard
sweet shard
valid jungle
sweet shard
valid jungle
#

It gave me a wrong answer tho

sweet shard
sweet shard
sweet shard
sweet shard
valid jungle
#

Yeah cause parentheses come first?

sweet shard
sweet shard
valid jungle
#

Already did

sweet shard
valid jungle
sweet shard
#

what you want to enter is (a + b) / (c + d)

vital relic
#

The Answer Preview literally tells you what it interprets it as

sweet shard
#

because $( a + b ) / ( c + d) = \frac{a+b}{c+d} \neq a + b / c + d$

thorny flameBOT
#

riemann

sweet shard
#

does this look like your answer?

valid jungle
#

Nope

#

They two different answers

#

Both wrong tho

sweet shard
#

or at least you didn't show us

#

type out your answer here before you enter it

valid jungle
#

Ok

#

So this what I entered earlier

viscid thistle
#

that’s a minus

#

not a plus

#

sign error my friend

valid jungle
#

So like thiss?

viscid thistle
valid jungle
sweet shard
viscid thistle
#

gotta love that ey

sweet shard
viscid thistle
#

multiply the denominator on both sides, expand and implicit differentiation

viscid thistle
sweet shard
viscid thistle
valid jungle
#

so is it a minus or plus 🧔‍♂️

viscid thistle
#

plus

viscid thistle
viscid thistle
#

quotient rule

thorny flameBOT
#

riemann

viscid thistle
sweet shard
#

yup

viscid thistle
valid jungle
#

Should i shoot my last shoot

viscid thistle
#

if it says it’s incorrect, please email your professor

valid jungle
#

okay

#

Oof

#

It said correct

#

.close

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#
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sweet shard
valid jungle
#

Cause I already tried twice

#

And that was my last attempt

sweet shard
#

but it was correct so did you lose points?

topaz sinewBOT
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valid jungle
#

no last one is correct

topaz sinewBOT
valid jungle
#

So it counted

#

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valid jungle
#

.close

#

.close

#

.reopen

topaz sinewBOT
#

valid jungle
#

.close

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late pebble
#

hey um im reviewing for an exam and im having some trouble with the questions since these were from the start of the lesson a few weeks ag and it blanked out of my head it solving trig eqatons

late pebble
#

im on pc so i cant realy take a picture but the question asks cos x=3 cos x-2

#

<@&286206848099549185>

lean yacht
#

Sounds like you may have trouble reading directions since pinging helper is 15 min

late pebble
#

oh uh i pinged cus the last question asked was from yesterday

#

sorry

lean yacht
#

No worries, but it may be easier to snap a photo of the screen since "cos x = 3 cos x-2" doesn't sound like much of a question.

late pebble
#

let me try

#

this is the blank sheet

lean yacht
#

Thinking of the cosine graph, what sort of values are there?

late pebble
#

am i supposed to conbmine them somehow?

#

cosnie graph?

#

i dont think we used that in my class

lean yacht
#

Well you don't have to combine them, but it may be easier to visualize what cos(x) looks like

late pebble
#

ok ok

#

so when i have the wiggly line thing what do i do

#

you sure theres not an equivalent to this but on the unit circle?

lean yacht
#

that looks right. So what are some important values to note from there and how can they be relevant to cos x = 3 cos x-2

#

Think vertically

late pebble
#

-1 and pos 1

#

??

lean yacht
#

Good! Anyway to use either of those as a replacement for "cos x"? Since we know it will always be between -1,1

late pebble
#

can it be either

#

like the cos on this eqation could be either -1 or 1 and it wont matter?

lean yacht
#

Try substituting them into the original problem and see if both work out

late pebble
#

ok

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do i replace the x too?

lean yacht
#

not yet since that is what we are trying to solve for

late pebble
#

so like -1x=3-1x-2

#

?

lean yacht
#

Not exactly right. you replaced "cos"

late pebble
#

so i replace only x?

#

arent i supposed to replace cos with -1?

lean yacht
#

that isn't a valid substitution

#

You are replacing a function with a variable when you do that

late pebble
#

so only the x?

lean yacht
#

If you replace x, then what are you solving for?

late pebble
#

uh

#

what do i do with the -1,and 1 then

late pebble
#

but like ok

lean yacht
#

"cos x"

late pebble
#

cos -1?

#

but im not supposed to replace the xs no?

lean yacht
#

No. The cosine function goes from -1 to 1, which means that cos(x) is between -1 and 1. i.e. -1 <= cos x <= 1

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replace the whole thing

late pebble
#

but what is going to hapen to the 3 & 2

lean yacht
#

They help you determine which value in the graph is relevant

late pebble
#

ok

#

so for now i replace the entire equation with -1<=cos x<=1?

#

but this doesnt look like what i was tauught are you sure you're solving for ALL values of x?

#

are we going to get an answer like idk pi/2-pi/4

lean yacht
#

yes

#

using the original equation, and knowing that cos x is between -1 and 1 (inclusive). Test the lower end by substituting "cos x" = "-1"

late pebble
#

do i put that in a graph?

lean yacht
#

using the original equation,

late pebble
#

so i substitule the 3 with -1?

lean yacht
#

substituting "cos x" = "-1"

late pebble
#

iim sorry if im annoying you i kinda dont understand you want me to like substitute cost x with -1?

#

that hurts my eyes tf tf

lean yacht
#

cos x = 3 cos x-2
-1 = 3 * (-1) - 2

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Does that equation work?

late pebble
#

no

lean yacht
#

Not annoying 🙂 I am just trying to get you to arrive at the answer

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So, since we know that cos(x) = - 1 isn't going to work, maybe 0 would or maybe 1?

late pebble
#

but like you cant subsitive the cos no>

#

?

lean yacht
#

You will have to do it with whichever balances the equation

late pebble
#

so you can subsitute the cos then

#

?

lean yacht
#

you can't substitute the cosine function alone, but you can substitute values it produces

late pebble
#

let me try with the zero cus the 1 didnt show anything on the graph

lean yacht
#

"cos" is the function but "cos x" produces values ranging between -1,1 so we can substitute anything in that -1,1 range

#

You don't need a graph

#

at least not anymore

late pebble
#

i dont need a graph now that i know what cos shows ?

#

is it the same for ike sin or other fuctions too>

#

?

lean yacht
#

Usually, yes

lean yacht
#

If the equation still doesn't balance, try 1

late pebble
#

and what is it supposd to give me?

#

when i put it into the calculator it gves me a one

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1=1

lean yacht
#

Good! So that means that when cos(x) = 1, the equation is balanced. Now we have to find out "for what values of x is the cosine function 1?"

late pebble
#

ok

lean yacht
#

You're in the home strech

late pebble
#

do i change the eqation back to cos/

#

?

#

to mess with the xs?

lean yacht
# late pebble

You can..... but if you look at the original graph, where is the graph at 1?

late pebble
#

on the x axis?

#

0 no?

lean yacht
#

0 is one of them, any more?

late pebble
#

no

lean yacht
#

No?! but it is an equal wave, so surely there is more than just one instance where the function reaches 1

late pebble
#

OMG IM SO SORRY

#

um -2 pi &2 pi

#

?

lean yacht
#

Yea. So -2pi, 0, 2pi - likely 4pi, 6pi.... how would you write that as a single value?

lean yacht
late pebble
#

have a feeling but idk if correct

#

nvm

lean yacht
#

That hasn't stopped you yet KEK

late pebble
#

is it going to be written similar

lean yacht
#

Just kidding, what are you thinking it would be?

late pebble
#

with a denominator

lean yacht
#

denominator = 1, in the answer

late pebble
#

do the 3 and the -2 come into play here

lean yacht
#

Not anymore, we used those to determine that only the values in which cos(x) = 1 are correct, all we need to do now is write out all the answers for x where cos(x) = 1, so far we have -2pi, 0, 2pi, 4pi, 6pi

late pebble
#

oh ok

#

idk what to do after this

lean yacht
#

Simplify the sequence "-2pi, 0, 2pi, 4pi, 6pi"

late pebble
#

the hint you gave me makes me believe it would be like -2pi/1- 2pi/1

late pebble
lean yacht
#

That may have been a bad hint

#

Let's ignore the "-2pi" for a moment.... is there something easily noticeable that "2pi, 4pi, 6pi" have?

late pebble
#

sequence of 2?

lean yacht
#

Yea, 2 and pi

#

Is there a way to write that with some variable, say "n"?

late pebble
#

i dont know i dont want to give dumb answers

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2pi n?

late pebble
#

that was the answerbleak

#

?

lean yacht
#

Yes

late pebble
#

cos =-1 and 2pi n ?

lean yacht
#

Woah there.

#

not "-1"

late pebble
#

oh sorry

#

1

lean yacht
#

But yes, x = 2 pi n for all n as an integer

late pebble
#

ok,

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thank you ima go eat ill ask more questions later hopefully with another person cus i dont want to waste your time

#

thanks

lean yacht
#

Glad to help

topaz sinewBOT
#

@late pebble Has your question been resolved?

#
Channel closed

Closed by @late pebble

Use .reopen if this was a mistake.

topaz sinewBOT
#
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Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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frail gyro
#

Hi i have a few questions

topaz sinewBOT
frail gyro
#

for a) 1 ft = 30.48cm so 5(30.48) + 11(2.54)

#

for b i think:
1yd = 3ft = 36in(2.54) = 91.44cm(8yd) = 731.52
2ft = 2(12) = 24in(2.54) = cm = 60.96
9in = 9(2.54cm) = 22.86

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731.52 + 60.96 + 22.86 = 815cm

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is that good?

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c) 42yd 1ft 10in to m

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im not sure exactly how to do c without the conversion rates

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since im trying to do it without that because it may not be on the test on wednesday

chrome glen
#

Id just convert it all to inches or smthn

#

Then do one big conversion

frail gyro
#

ahh okay

#

thanks

chrome glen
#

Np

frail gyro
#

i got word problems too but ima first try them and then ask

chrome glen
#

Reasonable

frail gyro
#

since the conversion to inch is easy you just need to know how to convert that to yards

#

okok now i do more

#

ok so i believe a is 57.6m because 1 yd = 0.9m

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and 64 x 0.9 is just off by 0.10 so 10% of 64 is 6.4 which means 64 - 6.4 = 57.6m

#

sorry i was talking about a)

chrome glen
#

I mean youd prob just want to use a more accurate conversion factor

frail gyro
#

ah

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1yd = 0.9144m

#

my teacher lets it slide since we're not gonna have the exact conversion factor on the test

#

as long as i know 1yd = 9/10 its fine

#

but yea i will still remember these conversion factors

topaz sinewBOT
#

@frail gyro Has your question been resolved?

chrome glen
#

Thinking about the units

#

You have 0.52 dollars per km and 0.82 dollars per mile

#

Or, in other words

#

$0.52 \frac{dollars}{km}$

thorny flameBOT
#

PapaBread

chrome glen
#

And

#

$0.85 \frac{dollars}{mile}$

thorny flameBOT
#

PapaBread

chrome glen
#

What would you multiply for example 0.85 dollars per mile by

#

To cancel out the miles and put a km in its place

topaz sinewBOT
#

@frail gyro Has your question been resolved?

topaz sinewBOT
#
Channel closed

Closed by @frail gyro

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

frail gyro
frail gyro
#

im not too sure

chrome glen
#

Yes thats one half of it

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Then what about km

#

Cause you want to convert it to dollars per km to compare the two

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$\frac{dollars}{miles} \cdot \frac{?}{?} = \frac{dollars}{km}$

thorny flameBOT
#

PapaBread

frail gyro
#

hmm

#

we're tryna get km right

chrome glen
#

The amount of dollars you get per kilometer yes

frail gyro
#

im not sure then

#

sorry i just dont know this

chrome glen
#

Ill do this one then you try the other one

frail gyro
#

alr

chrome glen
#

$\frac{dollars}{miles} \cdot \frac{miles}{km} = \frac{dollars}{km}$

thorny flameBOT
#

PapaBread

chrome glen
#

Or in more english terms

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$ per mile * miles per km = $ per km

frail gyro
#

interesting

chrome glen
#

And you can see how the units cancel out

#

You can use this line of reasoning for normal conversions too

#

miles * km per mile = km

frail gyro
#

so we cross multiply

#

1 sec i dont think i understand

chrome glen
#

You just multiply the two fractions

#

Miles cancels out and uhh

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$\frac{dollars}{\cancel{miles}} \cdot \frac{\cancel{miles}}{km} = \frac{dollars}{km}$

thorny flameBOT
#

PapaBread

chrome glen
#

Youre left with just

frail gyro
#

$/km and $/km

chrome glen
#

$dollars \cdot \frac{1}{km} = \frac{dollars}{km}$

thorny flameBOT
#

PapaBread

frail gyro
#

but then do the digits change?

#

like does miles change or no

chrome glen
#

Yeah the conversion would be already done

#

Once you multiply the proper numbers

#

Im talking purely in the sense of units rn

frail gyro
#

oh ok

chrome glen
#

All of the "dollars per km" and stuff would have a number associated with it

#

Like 0.52 dollars per km

#

Or whatever it was

frail gyro
#

but i have a question

#

would the new conversion still be $0.82 per km

#

since it was 0.82$ per mile

chrome glen
#

Can you repost the question for reference?

#

I lost it

frail gyro
#

yea same lol

frail gyro
#

its f

chrome glen
#

So you could either convert 0.52 dollars per km to dollars per mile

#

Or 0.85 dollars per mile to dollars per km

#

Which one do you wanna do

#

It doesnt really matter which

frail gyro
#

lets do km

chrome glen
#

So you have 0.52 dollars per km

#

What can you multiply that by to get dollars per mile

#

Thinking of per again as a division of units

frail gyro
#

oh

#

km/$

#

0.52$/km x km/$

chrome glen
#

Thatd give you a unitless number

frail gyro
#

ah

chrome glen
#

Since all of the units would cancel

frail gyro
#

hm

#

im not sure

chrome glen
#

You could think of it in two steps

#

How would you cancel out the km

frail gyro
#

multiply by km

chrome glen
#

Yes

#

Then how would you get the "per mile"

frail gyro
#

hm

#

idk lol

chrome glen
#

Just divide by miles

frail gyro
#

yea

chrome glen
#

So you end up with a whole multiplication unit of km/miles

#

Or km per mile

#

How many km are in a mile?

#

Or how many km per mile

frail gyro
#

can we restart?

#

im getting a bit lost

#

sorry

#

im going to write it out this time

chrome glen
#

So you wanna convert 0.52 $ per km to $ per mile

#

And you need to find the conversion factor

#

Id recommend writing out your units like fractions for this problem

frail gyro
#

alr

chrome glen
#

$0.52 \frac{dollars}{km}$

thorny flameBOT
#

PapaBread

chrome glen
#

Like that

frail gyro
#

done

#

okay so if we're going to make it to km

#

we will need to multiply $/mi by km

#

ahghhg i dont get it

#

because why dont the numbers change

#

since we're converting miles to km