#help-26
226100 messages · Page 238 of 227
by inverse x + inverse y do you mean:
$$\frac 1x + \frac1y$$
ℝamonov
Yes
hint: how would you simplify
$$\frac 12 + \frac13$$
ℝamonov
2/6
7/6
5/6 is correct, and supposing you applied the correct steps to get that
apply pretty much the exact same methodology to your question
i.e. first combine 1/x + 1/y into a single fraction
x + y / xy
ℝamonov
It's the answer but how?
ℝamonov
Oh I got it
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a ^2 + b^2 + c^2 +3 = 2(a+b+c)
c = ?
what have you tried
It has to do with algebraic union I guess
algebraic union?
algebraic identity
hint: 3 = 1 + 1 + 1
I have no idea
$$(p-1)^2 = p^2 - 2p + 1$$
ℝamonov
Ok then?
consider the type of number you get when you square a real number
and assuming a,b,c are real, consider the only possible way of getting 0 when adding the stuff on the left
Uhh…
So c = 1 ?
yes
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var(x) = e(x^2) - (e(x))^2
= (5.2736) - (2.0316)^2
sqrt(var(x)) = s.d
= 1.07
it should be 1.08 :/
how am i supposed to get this exact answer
don't round here
show your work?
lemme type it all out 1 minute
$\frac{1(22) + 4(31) + 9(27) + 16(7)}{95} - ( \frac{1(22) + 2(31) + 3(27) + 4(7)}{95})^{2}$
The Torrent v2
idk how to do bigger brackets but thats my working
this is right
answer is wrong :/
$\left ( \frac{1}{2} \right)$
riemann
if my working is right...... why is answer wrong :/
mark scheme cant be just wrong
because i also have a different mark scheme which my teacher made
which also says 1.0764
both cant be wrong by co-incidence
yea the key hint is "survey" and not "population"
explanation for why $n-1$ instead of $n$
riemann
thanks for the help, ill check out that link to make sure i dont forget in the future lol 👍
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A rock is thrown downward at a speed of 20ft from the top edge of 500 ft. The height of the rock above the ground t seconds after the rock is thrown is: s(t)= 500-80t-16t^2
-how many seconds after the rock is thrown does it hit the ground?
-what is the sspeed of the rock when hits the ground?
solve quadratic for s(t) = 0
for second one, differentiate s(t)
so is v(20) = -20-32t ?
s’(k) where k is the time when it hits ground
v(20) = -80 - 32(20)
assuming it doesn’t reach terminal velocity
t= 20 is way too much
i don’t think 20 is right
v(t) = -80-32t
if that’s what you were tryna say
i hope all of that made sense
yes
but in this case v(t) is negative, should I leave it like that or have a positive v?
because is ft/sec
anyway tyvm
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hello
what have you tried?
for the first one:
x^2 = (3^2)^2
x^2 = 9^2
x^2 = 81
x = √81
x = 9
i really don't know if its correct
and for the second one:
3x (x+1) = x (4x-1)
3x+3 = 4x - 1
x = 4
the work is fine
is all correct?
sort of skipped a step for the first one,
should explicitly state what allowed you to cancel x from both sides like that
but other than that its fine
hm
@neon iron Has your question been resolved?
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Elp
idk how to do
You need to stop reopening under a new channel
Havent you posted this like 3 times already?
@karmic fox Has your question been resolved?
<@&286206848099549185>
@karmic fox Has your question been resolved?
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find derivative?
i am not familiar
How are you doing derivatives if you aren't familiar with the basic rules?
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how can i convert this into a power series
i found the derivative of ln(5-x)
however when i try to find its convergence, for which value do i center it
Know any related power series?
Any (where f is defined)
what do you mean ?
(x-c)
what would c be ?
0 ?
Any (where f is defined)
Since f is defined at x = 0, you can construct a series around x = 0.
You should have a series in terms of ln given to you, though.
could you guide me through the whole problem i dont really undertsand very well
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Hello, I'm working on an assignment for Business Management (BUS-130-60) and I've been struggling to understand the assignment as a whole. I don't think its asking me to convert ratios as it gives me a list of ratios that seem to have been automatically converted from the finances it has given me. The assignment focuses on Financial Analysis and converting ratios. For the first question, I just answered that all the ratios are correct. I'll be sending a GIF of the entire assignment, along with a large list of all the finances, ratios, and questions given:
https://gyazo.com/a95c1f899d6bed350de48a628a8bc0e0
Use the following worksheet to help Bella and Matias Morales calculate the following twelve financial ratios from their income statement and balance sheet.
Identify those ratios for High Country Tires that are significantly different from the industry median.
Calculate High Country Tires’ cash conversion cycle using the following formula: Average Inventory Turnover Ratio + Average Collection Period Ratio – Average Payable Period Ratio. Make the same calculation for the typical firm in the industry. Comment on your calculations.
The Moraleses took on additional debt to open their second location. Does it appear that High Country Tires is overloaded with debt?
What are the potential problems that exist in High Country Tires that might cause the differences you identified in question 2?
What specific steps do you recommend the Moraleses take to resolve the problems you identified in question 5 and improve their ratios next year?
High Country Tires Income Statement
Sales
Cash or Debit Card $1,912,504
Credit $762,327
Total Sales $2,674,831
Cost of Goods Sold
Beginning Inventory $136,321
Plus Purchases $1,961,070
Goods Available for Sale $2,097,391
Less Ending Inventory $356,875
Cost of Goods Sold $1,740,516
Gross Profit $934,315
Expenses
Mortgage $71,550
Wages, Salaries, and Benefits $494,565
Utilities $84,280
Advertising and Marketing $10,876
Vehicle Expense $49,532
Bank and Card Fees $2,400
Insurance $8,763
Maintenance and Repairs $8,943
Office Supplies $2,567
Internet and Telephone $1,200
Computer Equipment and Maintenance $7,489
Shipping and Postage $457
Depreciation $33,652
Accounting Services $4,800
Legal Fees $3,000
Business Licenses and Permits $2,000
Training and Education $2,575
Interest Expense $24,207
Miscellaneous Expenses $1,743
Total Expenses $814,599
Net Income (Before Taxes) $119,716
High Country Tires Balance Sheet
Assets
Current Assets
Cash
$138,232
Accounts Receivable $141,289
Less Allowance for Doubtful Accounts $5,000 $136,289
Inventory
$356,875
Prepaid Expenses and Other Current Assets
$50,245
Total Current Assets $681,641
Fixed Assets
Land
$155,750
Buildings $288,755
Less Accumulated Depreciation $145,250 $143,505
Furniture, Fixtures, and Equipment $189,670
Less Accumulated Depreciation $136,579 $53,091
Total Fixed Assets $352,346
Total Assets $1,033,987
Liabilities
Current Liabilities
Accounts Payable
$227,498
Bank Loan
$67,483
Notes Payable
$98,229
Accrued and Other Current Liabilities
$43,014
Total Current Liabilities $436,224
Long-Term Liabilities
Mortgage
$94,216
Note Payable
$42,485
Total Long-Term Liabilities $136,701
Total Liabilities $572,925
Owner's Equity
Net Worth $461,062
Total Liabilities and Owner's Equity $1,033,987
High Country Tires Ratios
Ratio This Year Last Year Industry Median
Current Ratio 1.56 1.42:1 1.4:1
Quick Ratio 0.74 0.68:1 0.7:1
Leverage
Debt 0.55 .58:1 0.725:1
Debt to Net Worth 1.24 1.31:1 1.73:1
Times Interest Earned 5.95 4.75:1 4.7:1
Operating
Average Inventory Turnover 7.06 times per year or 51.7 days 6.83 8.2 times per year
Average Collection Period 5.59 times per year or 65.3 days 5.12 8.0 times per year
Average Payable Period 8.62 times per year or 42.3 days 8.01 13.4 times per year
Net Sales to Total Assets 2.59 2.85 3.70:1
Profitability
Net Profit on Sales (Net Profit Margin) 4.5% 4.1% 4.8%
Net Profit to Assets (ROA) 11.6% 7.5% 11.4%
Net Profit to Equity (ROE) 26.0% 21.4% 23.8%
im gonna be honest with you friend there is no way anyone is reading that
lol
is there a person you think would?
I just went to the 'Business' version of this server and they tried, and they sent me here
and they said that the math people would understand this better
If you want I can send you the questions I was given, maybe they are easier then you think
nvm i already did that
they sent you here cause they don't wanna read it
are you familiar with what this is?
i went through all of it and i can promise you it isn't as terrifying as you think
ignore the large paragraphs at the beginning and just focus on the questions
@neon iron Has your question been resolved?
@neon iron Has your question been resolved?
I did number 1 and 2
Can someone help me do
Calculate High Country Tires’ cash conversion cycle using the following formula: Average Inventory Turnover Ratio + Average Collection Period Ratio – Average Payable Period Ratio. Make the same calculation for the typical firm in the industry. Comment on your calculations.
-
The Ratios are all-calculated to their exact ratios as intended.
-
Ratios that are significantly different from industry median include; Debt, Debt to Net Worth, Times Interest Earned, Average Inventory Turnover, Average Collection Period, Average Payable Period, and Net Profit to Equity.
-
High County: 4.03 Median Industry: 2.8. High County is making twice as much as the average Industry.
-
Yes, most of the company's assets are being financed through debt as opposed to equity. Debt to Net Worth is also far above what it should be.
-
Many of the ratios are above average but could be better then the Industry Median when it comes to everything. Debt could be a little better, but still remains better then the average Industry.
-
I recommend that the Moraleses decrease their debt more and increase their profit from sales more.
Finished, if anyone wants to contribute more to this answer I'd appreciate it
At this point I suggest you hire a local tutor or tax accountant to do all that arithmetic for you
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Hey
do u just want the answer or help solving it
I have the answer but I don’t know the steps
.
Okay so I tried subbing in x
I got 0/0
But when I common factor iut a 2 on top
The limit is 2
...
mhm
the denominator is the absolute value
Meaning there’s a hole
no
apply the definition of the absolute value
What even is absolute value
Isn’t it where if it’s a negative it turns to a positive
But it’s already positive
On the inside
$\lvert x \rvert = \left{
\begin{array}{ll}
-x & \quad x < 0 \
x & \quad x \geq 0
\end{array}
\right.$
So if it’s less than 0 it’s negative
Greater it’s positive
So to get the answe
So if |x+4| > 0. It’s just x+4
that should just be a x < 0 not leq 
Why’s that
cause if you have geq and leq you're giving it two definitions at one point
Right, mb
What’s geq and leq
greater than or equal to / less than or equal to
Ohh
[TEB] darthlothins

So it’s basically repetitive
but yes, right concept here
this is a very interesting order (that I usually don't see)
yeah i was gonna point that out too but same meaning lmao
if it works it works 
and i don't know how to do arrays on latex 
So if it’s positive that means I’m approaching the limit from the positive side
Which would give me 2
yep
right
Which would be negative 2
Does not exist
correcto
I copy pasted the format from a site since I didn't know how to do piecewise in tex either 
It’s a piece wise function right
$$\abs{x}:=\begin{cases}\phantom{-}x,\quad x\geq0\-x,\quad x<0\end{cases}$$
Shuri2060
the absolute value function, yeah
Yea
|x| implies the piecewise definition seem above ^ though
how to get the ability to post on the advanced mathematics channels? I am currently unable to
this is someone's help channel 
What does that mean, Sorry, I am new to discord
Also for this
someone is asking for math help here
Sorry
I did not know, please forgive me
i'm pretty sure it can be the other way around, but it's the general consensus
Oh
The absolute value function
you're not solving for any inequality
you're just applying the definition seen based on if x >= 0 or x < 0
Yea
Oh
Then when would I do that
When I want to determine the anvoslute value function?
or you can say
$$\lim_{x\to -4^+}f(x)=2$$ and $$\lim_{x\to -4^-}f(x)=-2$$ therefore $\lim_{x \to -4}f(x)=$DNE
a disappointing son
If I wanted to find the function and not the limit
I would do what I did above right
i'm not sure what you mean by "find the function"
F(x) = the pic I sent
like by breaking it into 2 parts?
cause you already did that when you evaluated the limit
Like graphing approach
no
Same
AH
i think
i think? i get what you're asking
so what you'd write as the function's graph
like in a graphing calculator or something
Uh
cause that's what i think you're trying to do here
but you wrote 4 instead of -4
So what would the proper function look like
same thing you have written but it would be x > -4 and x < -4
along with a y= in front
naw cause your actual function is undefined at x=-4
yeah
One at 2 and one at -2
they don't touch x=-4 cause your function is undefined at x=-4
$\frac{2x+8}{\abs{x+4}}$
a disappointing son
yes
Oh also I think Ik what I meant when I did this
Like the value would always be a certain number when x is greater or less than 4
yes, that's true
Yea it makes sense
Wait but why 4 tho
I get the saying but like why’s it only when it’s greater or less than 4
That that value exists
Is it because of the absolute value
ah shoot that's supposed to be -4
i keep forgetting your limit is x approaching -4 and not +4 
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Hello i was just wondering in the equation S=ut+1/2at^2 we times 2 not just to S but also to ut
nope
$S = ut + \frac{1}{2} at^2$ is the equation
yeah you multiply with all
ok but why do we multiply the, ut and not just the s cause arent we just multiplying to the other side to get rid of the 1/2
not really
$S - ut = \frac{1}{2}at^2$
so then if i wanted to figure out what A was equal to it would look like A = S - UT x 2 / t^2
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hey as you know , this is a product law of logarithms , and what if the log is negative
how do i use the law then?
im sorry if my doubt is silly im just a 14 year old
if which log is negative
same concept
what do you think it will be?
i think the second log will be negative
you are correct
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can anyone help me please
@azure socket Has your question been resolved?
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what's this method called?
the one where I subtract 10p=6,6666... with p=0,6666...
i dont think it has a name
hmmm
can you elaborate ?
so it's basically to find the fraction form of 0,6666... right?
no
infact you can do it to all repeating numbers
isn't that 0 tho ?
yes
you can use logarithms next time
not sure it'd be easier
remember log(a^b)=b*log(a) in this case you can take the log of both sides and it will be a product of two numbers
as in x*log(0.66666)=log(0.999999)
found the answer this way
how did 9/9 become (2/3)^2?
that's 4/9
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Express -125/216 in power notation
(5/6)^3
could u pls give the explanation as well
write 216 as a power, and write -125 as a power
(Epicly)
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can someone pls help?
Exponent properties
you have to sort of "distribute" the exponent over the numerator and the denominator
i.e. cube both negative 2 and 7
like, -2/7^3 ?
Not exactly
no, do it to both the numerator and the denominator
It gets distributed to both the numerator and denominator
-(2/7)^3 ?
that's the question
Technically not exactly
no the question is, (-2/7)^3
Because luckily it's to an odd power
If it was to an even, different problem
$$\left(\frac{a}{b}\right)^x = \frac{a^x}{b^x} $$
dldh06
That's the property you're applying
so the answer is, -(2^3/7^3) ?
yes correct but you have to be careful
because that would be wrong if it was an even power
You keep signs with the numbers
to be exact, the answer is
(-2^3)/(7^3)
Don't separate the sign
umm so, (-2^3)/(7^3) & -(2^3/7^3) both r correct?
Technically to the odd power yes, but even power, no
oh okay! Thnks! U guys helped a lot!
Example (-2)^3 = -8 but doing -(2^3), you do the inside first so -(8) so odd powers, just a coincidence
(-2)^2 = (-2) * (-2) = 4
But -(2^2) = -(2 * 2) = -(4) = -4
Notice the difference with parentheses?
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help pleasee
0= x(2x+13)-4(2x+13)/x-4
sills
@neon iron Has your question been resolved?
which means you can cancel out, and then you can have a f(a) value
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I have a question about Euclidian's algorithm. If we have integers a and b where b > a > 0, the HCF of a and b being x, we can let k = b - a, then x (the HCF) is still a factor of this new number k (b = ex, a = gx => k = b - a = ex - gx = x(e-g)). But I don't know how to explain why the HCF doesn't change (e.g increases) from the first pair a, b to the new pair a, k... maybe this is obvious but idk?
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well the hcf of a is still x, so it cant be bigger than that for the pair (a, k)
@neon iron Has your question been resolved?
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Hi, I'm developing a game and I've got a problem. I got 2 objects, 1 and 2. I want to calculate the rotation of object 1 needed to exactly look at object 2. I've got the lengths A and B.
How can I calculate this?
wait
i already know it lol
this is like literally just tan
ok im dumb this is like 9. grade stuff lmao
.close
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The M and N sets are such that M U E = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9), M - N = {0, 1, 2} and N- M = {7, 8, 9). Determine the M and N sets
I need help
could consider drawing a venn?
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Can I get help on these word problems?
At day 0 the watch is 1 second behind.
Your first point for your function should therefore be P(0|1)
His watch falls behind 2 seconds every day so by day one his watch will be 3 seconds behind
Your second Point therefore is P(1|3)
4)
The same as described in number 3 applies here
She has 75 photos already on her phone
P(0|75)
Each day she wants to take another 25.
P(1|100)
So whats my equation for part a?
Do you know how to get a function with 2 points ?
Is P(0|1) P 0/1? Or am I misinterpreting?
P is point
I think.
Ok so lets break this down what is always at x =0?
Ok.
?
Oh a question. 🤣 🤦
At x = 0 you will always find the y-axis intersection
In your general linear function where is the y-Intersection located ?
As a reminder (General Equation of a linear function):
f(x) = a*x+b
b?
yes exactly so You know that the function you are trying to model will intersect the y-Axis at y = 1
F(x) = a*x +1
when you set in the first point yes
but you still need a
the slope of the function
Yes so your complete function would be
f(x) = 2x+1
Alright so part a is done.
Yes now on to part b. In part b you are asked to find x. so you insert all the information given in the task
So would I do f(x) = 2x+1 but I insert 17 into x? 🤔
Not into x. X is the variable you are trying to calculate. Think about it. the function we modelled above will give us the seconds the watch is behind when we insert the number of days in x
So how do we find the number of days? By calculating it sure but there is something extra to do right?
Yes you were right on track you need to insert the 17 for y because why gives you the number of seconds the watch is behind.
In our case:
f(x) = 2*x+1
Now we insert y:
17 = 2*x+1
Then we solve for x.
Ah.
Now I see.
Let me solve that real quick.
8?
Yes it's correct
Alright.
Need help with number 4 ?
For the second one I already got part a done: f(x) = 20x + 75 but I need help with part b.
We can just insert the number of days she plans to stay at the excavation site into x. Then we need to subtract the result with the maximum number of photos the result is the number of photos she needs to delete
So: 7 = 20x + 75? Or f(x) 20*7 + 75? 🤣
second one we insert for x
Ok.
And then subtract the result by 200. Let me do that real quick.
So the answer is 215.
So she would need to delete 15 photos?
yes that'is correct
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Can someone tell me why this is wrong?
,rotate
share your work
I tried this first and it didn’t work
oh you just need parentheses
Where
$a + b / c + d \neq (a+b) / (c+d)$
riemann
why
this looks right to me
but that's not equal to what's entered in the box
because pemdas
So what you reckon I should do
i reckon you should learn PEMDAS
and understand this
and apply it here
Can you at least tell me which line im wrong?
there's nothing wrong with your work here
It gave me a wrong answer tho
read this and understand how it applies to how you entered it in the website
you didn't enter your answer correctly
because you made this mistake
do you understand why this isn't true?
Yeah cause parentheses come first?
are you asking cuz you still don't understand?
read this if you still aren't sure
Already did
use parentheses and try entering your answer again
I still cant see where im wrong tho i did try to enter my answer just like this earlier and it also said wrong
you entered a + b / c + d
what you want to enter is (a + b) / (c + d)
The Answer Preview literally tells you what it interprets it as
because $( a + b ) / ( c + d) = \frac{a+b}{c+d} \neq a + b / c + d$
riemann
you didn't enter this
or at least you didn't show us
type out your answer here before you enter it
So like thiss?
^^
all this work because of user error 😭
gotta love that ey
did you come up with this?
multiply the denominator on both sides, expand and implicit differentiation
most of the working
this is the answer. just enter it correctly.
that’s what you get if you do this
so is it a minus or plus 🧔♂️
plus
self contradiction, you said the same answer as wrong and right
riemann
yeah, that’s the right answer, right ?
yup
that’s what you do for that
if it says it’s incorrect, please email your professor
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why oof
but it was correct so did you lose points?
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no last one is correct
Closed by @valid jungle
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✅
.close
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hey um im reviewing for an exam and im having some trouble with the questions since these were from the start of the lesson a few weeks ag and it blanked out of my head it solving trig eqatons
im on pc so i cant realy take a picture but the question asks cos x=3 cos x-2
<@&286206848099549185>
Sounds like you may have trouble reading directions since pinging helper is 15 min
No worries, but it may be easier to snap a photo of the screen since "cos x = 3 cos x-2" doesn't sound like much of a question.
Thinking of the cosine graph, what sort of values are there?
am i supposed to conbmine them somehow?
cosnie graph?
i dont think we used that in my class
Well you don't have to combine them, but it may be easier to visualize what cos(x) looks like
ok ok
so when i have the wiggly line thing what do i do
you sure theres not an equivalent to this but on the unit circle?
that looks right. So what are some important values to note from there and how can they be relevant to cos x = 3 cos x-2
Think vertically
Good! Anyway to use either of those as a replacement for "cos x"? Since we know it will always be between -1,1
can it be either
like the cos on this eqation could be either -1 or 1 and it wont matter?
Try substituting them into the original problem and see if both work out
not yet since that is what we are trying to solve for
Not exactly right. you replaced "cos"
that isn't a valid substitution
You are replacing a function with a variable when you do that
so only the x?
If you replace x, then what are you solving for?
^
but like ok
"cos x"
No. The cosine function goes from -1 to 1, which means that cos(x) is between -1 and 1. i.e. -1 <= cos x <= 1
replace the whole thing
but what is going to hapen to the 3 & 2
They help you determine which value in the graph is relevant
ok
so for now i replace the entire equation with -1<=cos x<=1?
but this doesnt look like what i was tauught are you sure you're solving for ALL values of x?
are we going to get an answer like idk pi/2-pi/4
yes
using the original equation, and knowing that cos x is between -1 and 1 (inclusive). Test the lower end by substituting "cos x" = "-1"
do i put that in a graph?
using the original equation,
so i substitule the 3 with -1?
substituting "cos x" = "-1"
iim sorry if im annoying you i kinda dont understand you want me to like substitute cost x with -1?
that hurts my eyes tf tf
no
Not annoying 🙂 I am just trying to get you to arrive at the answer
So, since we know that cos(x) = - 1 isn't going to work, maybe 0 would or maybe 1?
do i do this wih postive one or with zero then?
but like you cant subsitive the cos no>
?
You will have to do it with whichever balances the equation
you can't substitute the cosine function alone, but you can substitute values it produces
let me try with the zero cus the 1 didnt show anything on the graph
"cos" is the function but "cos x" produces values ranging between -1,1 so we can substitute anything in that -1,1 range
You don't need a graph
at least not anymore
i dont need a graph now that i know what cos shows ?
is it the same for ike sin or other fuctions too>
?
Usually, yes
So we know that cos(x) does have 0 in the range so follow the same thing done here
If the equation still doesn't balance, try 1
and what is it supposd to give me?
when i put it into the calculator it gves me a one
1=1
Good! So that means that when cos(x) = 1, the equation is balanced. Now we have to find out "for what values of x is the cosine function 1?"
ok
You're in the home strech
You can..... but if you look at the original graph, where is the graph at 1?
0 is one of them, any more?
no
No?! but it is an equal wave, so surely there is more than just one instance where the function reaches 1
Yea. So -2pi, 0, 2pi - likely 4pi, 6pi.... how would you write that as a single value?
See here for hint
That hasn't stopped you yet 
is it going to be written similar
Just kidding, what are you thinking it would be?
with a denominator
denominator = 1, in the answer
do the 3 and the -2 come into play here
Not anymore, we used those to determine that only the values in which cos(x) = 1 are correct, all we need to do now is write out all the answers for x where cos(x) = 1, so far we have -2pi, 0, 2pi, 4pi, 6pi
Simplify the sequence "-2pi, 0, 2pi, 4pi, 6pi"
the hint you gave me makes me believe it would be like -2pi/1- 2pi/1
howww???
That may have been a bad hint
Let's ignore the "-2pi" for a moment.... is there something easily noticeable that "2pi, 4pi, 6pi" have?
sequence of 2?
Yes
cos =-1 and 2pi n ?
But yes, x = 2 pi n for all n as an integer
ok,
thank you ima go eat ill ask more questions later hopefully with another person cus i dont want to waste your time
thanks
Glad to help
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Hi i have a few questions
for a) 1 ft = 30.48cm so 5(30.48) + 11(2.54)
for b i think:
1yd = 3ft = 36in(2.54) = 91.44cm(8yd) = 731.52
2ft = 2(12) = 24in(2.54) = cm = 60.96
9in = 9(2.54cm) = 22.86
731.52 + 60.96 + 22.86 = 815cm
is that good?
c) 42yd 1ft 10in to m
im not sure exactly how to do c without the conversion rates
since im trying to do it without that because it may not be on the test on wednesday
Np
i got word problems too but ima first try them and then ask
Reasonable
yeah that works great actually
since the conversion to inch is easy you just need to know how to convert that to yards
okok now i do more
ok so i believe a is 57.6m because 1 yd = 0.9m
and 64 x 0.9 is just off by 0.10 so 10% of 64 is 6.4 which means 64 - 6.4 = 57.6m
sorry i was talking about a)
I mean youd prob just want to use a more accurate conversion factor
ah
1yd = 0.9144m
my teacher lets it slide since we're not gonna have the exact conversion factor on the test
as long as i know 1yd = 9/10 its fine
but yea i will still remember these conversion factors
@frail gyro Has your question been resolved?
how would i do f)
Thinking about the units
You have 0.52 dollars per km and 0.82 dollars per mile
Or, in other words
$0.52 \frac{dollars}{km}$
PapaBread
PapaBread
What would you multiply for example 0.85 dollars per mile by
To cancel out the miles and put a km in its place
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to cancel out miles i think we need to multiply by miles?
im not too sure
Yes thats one half of it
Then what about km
Cause you want to convert it to dollars per km to compare the two
$\frac{dollars}{miles} \cdot \frac{?}{?} = \frac{dollars}{km}$
PapaBread
The amount of dollars you get per kilometer yes
Ill do this one then you try the other one
alr
$\frac{dollars}{miles} \cdot \frac{miles}{km} = \frac{dollars}{km}$
PapaBread
interesting
And you can see how the units cancel out
You can use this line of reasoning for normal conversions too
miles * km per mile = km
You just multiply the two fractions
Miles cancels out and uhh
$\frac{dollars}{\cancel{miles}} \cdot \frac{\cancel{miles}}{km} = \frac{dollars}{km}$
PapaBread
Youre left with just
$/km and $/km
$dollars \cdot \frac{1}{km} = \frac{dollars}{km}$
PapaBread
Yeah the conversion would be already done
Once you multiply the proper numbers
Im talking purely in the sense of units rn
oh ok
All of the "dollars per km" and stuff would have a number associated with it
Like 0.52 dollars per km
Or whatever it was
but i have a question
would the new conversion still be $0.82 per km
since it was 0.82$ per mile
yea same lol
So you could either convert 0.52 dollars per km to dollars per mile
Or 0.85 dollars per mile to dollars per km
Which one do you wanna do
It doesnt really matter which
lets do km
So you have 0.52 dollars per km
What can you multiply that by to get dollars per mile
Thinking of per again as a division of units
Thatd give you a unitless number
ah
Since all of the units would cancel
multiply by km
Just divide by miles
yea
So you end up with a whole multiplication unit of km/miles
Or km per mile
How many km are in a mile?
Or how many km per mile
So you wanna convert 0.52 $ per km to $ per mile
And you need to find the conversion factor
Id recommend writing out your units like fractions for this problem
alr
$0.52 \frac{dollars}{km}$
PapaBread
Like that
