help-26

[wooden matrix]

there's no vertical translation on the function

so the lowest you reach is purely b/c of the A value

[keen kindle]

We know that the minimal value of the function is -4, right?

And when x = 0 that the value of the function is -1

So the amplitude would be the value between these two

Is it (-4+(-1))/2?

So -5/2 🤔

[wooden matrix]

|y_min|=A

cause the lowest you reach is how much A makes the function stretch

[keen kindle]

When we write the absolute value of y_min, what does it mean?

[keen kindle]

Good point

[wooden matrix]

it means the absolute value of that number

🤨

[keen kindle]

No I mean like graphically

[wooden matrix]

nothing

[knotty osprey]

it’s the distance from that number to the x-axis

[wooden matrix]

the amplitude of a sinusoid is how far away the maximum/minimum values are from the axis of symmetry

[keen kindle]

So 4?

[wooden matrix]

yes

A=4

[knotty osprey]

yes

[keen kindle]

So the amplitude is 4

What is the line of symmetry?

[knotty osprey]

yes

[keen kindle]

Or is that not important

[wooden matrix]

y=c, where $f(x)=A\cos(\omega x+\varphi)+c$

[thorny flame]

Mosh

[wooden matrix]

here c=0, so y=0 is the axis of symmetry

[keen kindle]

Interesting

[knotty osprey]

think, what is the maximum and minimum values of cos(x-v)?

[keen kindle]

So we've found A, now v?

[wooden matrix]

yes

[keen kindle]

4*cos(-v) = -1

cos(v) = -0.25

[wooden matrix]

yes.

[keen kindle]

v = ±104,477 + 360n…

[wooden matrix]

approximate, yes

[keen kindle]

My friend wrote ’-v = ±75,52… + 360n’

Hmm

[wooden matrix]

,w solve cos(x)=-1/4

[thorny flame]

Results provided by WolframAlpha

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Requested by Omegabet_#9771

[keen kindle]

4*cos(180-v) = -1
cos(180-v) = -0.25
180-v = 104,477 + 360n
-v = −75,522… + 360n

Ah yes, same answer 😄

[wooden matrix]

Yeah

[keen kindle]

Could you send me a link so I can read more about this, bc my textbook doesn't have everything in it

[wooden matrix]

Google

[keen kindle]

Like this ”axis of symmetry trigonometry”?

I only get stuff about trigonometric identities, you know anything @knotty osprey ?

[wooden matrix]

function transformations as a whole as well probably

[knotty osprey]

The axis of symmetry usually refers to graphs of polynomials, i think what your talking about is the sinusoidal axis (or the midline)

it’s the line that is perfectly in the middle of the maximum and minimum values of the sinusoid wave

so for your example, the maximum value is $4$ when $\cos(x-v)=1$ and $-4$ when $\cos(x-v)=-1$

[thorny flame]

lgargaro

[knotty osprey]

so the midline would be the x-axis, the line y=0

[knotty osprey]

the only time it would be different is if there was a constant being added/subtracted like here

[topaz sinew]

@keen kindle Has your question been resolved?

[keen kindle]

Okay so I used this graph https://www.integral-domain.org/lwilliams/Applets/precalculus/trigTransformations.php

If the vertical shift is 1, does that mean the axis of symmetry is at y = 1?

[keen kindle]

👆

A should be -4

But it's essentially the same I think

For example, y = sin(x) + 2 has a midline at y = 2

I think that's the answer, the vertical shift is what determines the center line.

Thanks!

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[idle oracle]

so this is really puzzling me at the moment; of all the questions so far that I've gotten through so far, none of them have asked me do find/write the equation out myself, given only a single point. Also no where in the lesson portion (writing the notes, showing how to use X formula for a given problem, etc.) has given me an example of one of these and now I'm at a lose as to how to go about doing this question.

[solemn wigeon]

well what does perpendicular to the x-axis mean?

first off

[idle oracle]

I'm probably wrong here, but it has a slope going through the x-axis and it has to pass through the given point

[solemn wigeon]

it does have to go through given point

and it does have to go through x-axis

but its more specific than that

here

parallel to y = perpendicular to x

so from here you should see that we need a vertical line that goes through that point

[idle oracle]

oh okay, yeah I had no clue what it was asking of me because like I said it never gave an example of one for me to later figure on my own.
So because it's asking for a perpendicular line, why is the quote, unquote answer the opposite of what it's asking for, exactly?

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[broken steeple]

Help?

[solemn wigeon]

find the slope

[broken steeple]

alr

[solemn wigeon]

then use either point to write an equation in point slope form

[broken steeple]

the slope is -3

how do I do the second part

[solemn wigeon]

okay so the point slope form of a line is:

$y - b = m(x-a)$

[thorny flame]

M.E.G. Yottachad

[solemn wigeon]

where (a, b) is a point on the line

and m is the slope

[broken steeple]

how do i find the a,b

[solemn wigeon]

you already have it

any point on the line works

and it gives you two points

[neon iron]

(a, b) is a point on the line (which you already have 2 of)

[broken steeple]

I see

[neon iron]

gradient = change in y / change in x

so u could do

gradient aka slope

[solemn wigeon]

he already got slope

[neon iron]

diffrent name depending on where and when you were taught in the world

[solemn wigeon]

.

[neon iron]

miss scrolling down?

oh he already got it

i see

sorry

[broken steeple]

man i am confused

nvm

i got it

[solemn wigeon]

alright

if you have no more questions use .close to close channel

[weak jay]

.open

[weak jay]

If 2x + y = 5, then 4x + 2y is equal to _______.

pls help me

im a highschool math student

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[pure frigate]

Ay yo

[pure frigate]

My peeps that helped me for vectors

yall here?

[static void]

Just ask your question! :)

Someone will be able to help

[pure frigate]

ah oki oki

but is my peeps from before here tho?

21.364212231655

how do I find the ref and the theata?

[maiden wave]

Dude

[pure frigate]

AYY

😄

[maiden wave]

xD

[pure frigate]

yeh someone called me and I had to answer

MY MAN LETS GOO

[maiden wave]

xd

[pure frigate]

ndam your still here :DDDD

[maiden wave]

alr

Lets get this over with

[pure frigate]

yes please

[maiden wave]

You already found the x and y of the r vector

[pure frigate]

yee

[maiden wave]

You need the angle

[pure frigate]

360-21.364212231655?

[maiden wave]

where did 21 come from

[pure frigate]

Vr

[maiden wave]

uhm seems weird

Just sketch a triangle that has the x and y of the r vector

then use trigonometric

[pure frigate]

aight bet

[maiden wave]

sin cos tan whatever u want

So ?

[pure frigate]

sowwy I was cleaning my table

had bunch of ohm law

lol

[maiden wave]

Tan^-1(8/19)

[maiden wave]

What

[pure frigate]

other math course

[maiden wave]

thats electrical class

[pure frigate]

yee

alr so

you said draw

triangle

[maiden wave]

ye

Hurry up i gotta sleep

hop faster hop

xd

[pure frigate]

alr lol

sowwys

alr

[maiden wave]

u don’t even need to draw you can see the triangle in the picture

[pure frigate]

true

o/a

[maiden wave]

Yes

[pure frigate]

Tan= 8/19

[maiden wave]

Soh cah toa

Yes

[pure frigate]

tan-1 8/19

[maiden wave]

Yuh

[pure frigate]

22.83365418

[maiden wave]

Idk if its right but it should

[pure frigate]

aight

[maiden wave]

Thats all ?

[pure frigate]

well

so we just found out the ref angle

yeh?

[maiden wave]

What is the other angle ?

[pure frigate]

it says determine theata=

[maiden wave]

what does that mean ?

[pure frigate]

this

[maiden wave]

no i can see it

But like

[pure frigate]

oh

[maiden wave]

What does theta mean

[pure frigate]

it says Determine the Theta ref angle from standart position

the circle with the uhh

[maiden wave]

thats what we did no ?

[pure frigate]

thing that cuts it

Theta ref=

theta=

that's the question

from standard posotion

[maiden wave]

Uhm

[pure frigate]

lemme reword for you

[maiden wave]

u did that in class

prob

[pure frigate]

Determine the ref angle and the angle in standard position

is the question

[maiden wave]

Ok

Do you know how to find the magnitude ?

[pure frigate]

uhh

naw

[maiden wave]

Do you know what is the magnitude?

[pure frigate]

hey ndam if you need to go then it's aight man

I can wait for another person yk

you need sleep

[maiden wave]

i dont know for the angles but the magnitude is the length of the arrow

so use pythagorean’s theorem

im sure you can solve these questions by your own just think well and apply basic math rules and you will 100% find the answers

I believe in u

U got this

[pure frigate]

aight thanks again

sleep well

[maiden wave]

thx have fun solving math stuff

[pure frigate]

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[hasty copper]

question: let a,b,c be positive integers such that bc/(b+c), ca/(c+a), ab/(a+b) are all integers, prove that gcd(a,b,c)>1

[hasty copper]

i've assumed the gcd to be 1 and tried multiplying/adding the 3 terms given and i don't think i've found anything useful

[mortal thunder]

Do you want a hint?

[hasty copper]

sure

thank you :)

[mortal thunder]

given (a + b) divides ab, try pressing conditions on a, b for which $\frac{ab}{a+b}$ can be an integer.

[thorny flame]

Ansh

[hasty copper]

a+b is obviously bigger than either so it has to pull at least one prime factor from either number

is there anything else i should've gotten from that condition?

[mortal thunder]

so gcd(a, a + b) or gcd(b, a + b) > 1?

[hasty copper]

i see

[mortal thunder]

I'm only rephrasing what you said :o

[mortal thunder]

and this is equivalent to concluding gcd(a, b) > 1

[hasty copper]

so doing that through all 3 terms should give us the result

thank you!

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[paper umbra]

It's C, correct?

100% = 1
50% = 0.5

1/0.5=2

2=200%

Just need to ask if i did any mistakes

Or am overlooking something

[polar hemlock]

i think that's correct @paper umbra

[static void]

Correct

Good job!

[paper umbra]

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[analog grove]

Im currently looking over a problem sheet I have been given, and I made the mistake of using an estimate for the coin toss, rather than the probability equation given in the second image (from solution sheet). Could somebody explain why the probability is:

[topaz sinew]

@analog grove Has your question been resolved?

[analog grove]

I've formed a probability mass function, but I dont understand how to form equation 14

[frozen perch]

you have the likelihood function i assume?

[analog grove]

Yeah, that part is ok, just struggling with understanding how to form this equation from the pmf

f(x) = { p, x=1
         1-p, x=0

[frozen perch]

and X_i is...?

[analog grove]

A random variable

[frozen perch]

i know it's a random variable

what does it represent?

[analog grove]

Im assuming at a coin toss i, Xi is the observation

[frozen perch]

right okay

in this case, X_i will be either 1 or 0

say for 1 it's heads and for 0 it's tails, yeah?

[analog grove]

ye

[frozen perch]

so $Pr(X_i = 1; p) = p$

[thorny flame]

Camilleone

[frozen perch]

and $Pr(X_i = 0; p) = 1-p$

[thorny flame]

Camilleone

[frozen perch]

this is precisely your pmf but written in one line because $X_i$ only takes 0 and 1 values

[thorny flame]

Camilleone

[analog grove]

I follow

[frozen perch]

yay great

[analog grove]

The thing thats not clicking is why they are multiplied

[frozen perch]

well, you could really do anything as long as "it is p when X_i = 1 and 1-p when X_i = 0"

the simplest way is to use the fact that p^0 = 1 and (1-p)^0 = 1

[analog grove]

Oh I get it

Yeah

So, the $p^{X_i} = 1$ when $X_i=0$, and $(1-p)^{1-X_i} = (1-p)$

[thorny flame]

al0-

[frozen perch]

yep

[analog grove]

Thanks so much

Brain wasn't computing that

Lmao

Have a nice day/night

[frozen perch]

🙂

[analog grove]

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[carmine prism]

I am trying to derive the second equation from the first equation. But I do not know how to proceed, could you please help me?

[topaz sinew]

@carmine prism Has your question been resolved?

[frozen perch]

hint: it's an addition by zero trick. To the numerator of the first term, add $rB_0 - rB_0$. To the numerator of the second term, add $rB_1 - rB_1$. So on and so forth

[thorny flame]

Camilleone

[carmine prism]

@frozen perch Thank you very much! 😊

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[rigid whale]

u can divide the similar radicals and get 18 alone right

[waxen flame]

$\frac{18\sqrt{2}}{\sqrt{2}} = 18$

[thorny flame]

Saccharine

[rigid whale]

mhm

ok thx

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[normal marsh]

Show that if f is an odd function such that 0 is in the domain of f, then f(0) = 0.

[normal marsh]

I know how it came to be 0 but how do I write it down formally?

[hollow hedge]

you can start right with the definition of odd functions

[normal marsh]

so I should just say that they are symmetric wrt origin?

[hollow hedge]

well not quite

try to use the property, f(-x)=-f(x)

[normal marsh]

yes

zero doesn't have symmetric values about the origin

is that it?

[hollow hedge]

no you dont have too go too deep in the symmetry of the graph or how it looks

the property f(-x)=-f(x) is always true for all x in the domain

[normal marsh]

ah I see

[hollow hedge]

try to plug 0 in

and see what you can get from it

[normal marsh]

but we don't have a concrete function though

[hollow hedge]

we dont need to

here, if we plug 0 into the equation, we get f(-0)=-f(0) dont we?

and what is -0? it is still 0

so basically your equation now becomes f(0)=-f(0)

you now essentially have an equation in terms of f(0) which you can solve for

[normal marsh]

oh yes I see it now

thanks :')

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[sturdy holly]

How do I do this

[sturdy holly]

using index law

[junior widget]

You have a common factor that can be cancelled

[abstract wadi]

Do you know $\frac{a^m}{a^n}=a^{m-n}$

[thorny flame]

Sakata Yaksha

[sturdy holly]

But what do I do with the ab

[restive inlet]

wdym

[sturdy holly]

the one on the bottom is ab to the power of 2

[restive inlet]

that's a bit vague and may be misinterpreted

[sturdy holly]

Wdym

[restive inlet]

the one on the bottom is ab to the power of 2
will most likely be interpreted as (ab)^2 which isn't what you have in the denomintor

if you wanted to express it in words, the denominator would be a times b squared

anyway consider properties of multiplication you could express your fraction as
$$\frac{a^3}{a} \cdot \frac{b^2}{b^2}$$

[thorny flame]

ℝamonov

[sturdy holly]

idk

It's 2 am in the morning and I need to get this done idc as long as at least 50% of it is right

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[fresh maple]

I've been dealing with partial differentiation but I'm stuck on this question and don't even really know where to begin to solve it

[fresh maple]

jeez terrible quality image though

[acoustic tangle]

Rewrite that as $ee^xe^y$

[thorny flame]

Beans

[acoustic tangle]

Maybe

Or just use chainrule

Must be easier

[vital relic]

You differentiate partial by treating the other variable as constant...

Surely you can differentiate wrt $f(x) = e^{x+c}$ normally?

[thorny flame]

Shuri2060

[fresh maple]

wait so aren't they the same? ∂x and ∂y would both be e^x+y+1?

[acoustic tangle]

Wdym

[fresh maple]

i was looking at like

well the way you rewrote it

[acoustic tangle]

Yeah forget that that's not necessary

[fresh maple]

ok sorry i was doing $e e^y \frac{∂}{∂x} (e^x)

aw didnt work

i was doing

which im pretty sure is just

and then i dont think it goes any farther then this?

i think this is the same result for ∂y as well? i dont see why it would be any different then ∂x

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[remote grotto]

how does one simplify this?

[south island]

use daddy pythagoras

cos^2 + sin^2 = 1

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[tall halo]

Okay so I'm a bit confused about this problem and on how to approach it.

#20

[tall halo]

(believe this is non Euclidean geometry)

It's okay lol

Sorry, I wasn't specific

[polar hemlock]

i was thinking 20 about straight line = 180º

👀

[tall halo]

I don't think I'm solving for angle measures

I think somehow, I gotta use Exterior Angle Inequality Theorem

[polar hemlock]

x, and y are angles

[tall halo]

👀

[mortal thunder]

🙈

[tall halo]

@mortal thunder sorry for the ping, but do you know a little about this problem?

[mortal thunder]

I'm just tryna read 21 for context

[tall halo]

Ah

Well I could say that in this chapter, it introduces Exterior Angle Inequality Theorem, the Saccheri-Legendre Theorem,

[mortal thunder]

having knowledge only about Euclidean Geometry, the first thing that strikes every time I look at the figure is that
AC = CC' => CAC' = CC'A and by exterior angle property: 2y = x 🤦‍♂️ but I doubt that's anything nearly close to doing this one

[tall halo]

That would make sense

Hmmm

I've been having trouble with this problem and other ones

Took a break and studied abstract stuff for an exam ;(

I might just ask my professor about the problems I'm stuck on

.close

[topaz sinew]

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[naive turtle]

hi! can you help me finish the system of equations at the end?

[naive turtle]

or point me in a general direction - the numbers i'm getting don't seem right

[topaz sinew]

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[whole sun]

A pole leans away from the sun at an angle of 7° to the vertical, as shown in Figure 27. When the elevation of the sun is 55°, the pole casts a shadow 42 feet long on the level ground. How long is the pole? Round the answer to the nearest tenth. help

[sweet shard]

Figure 27?

[whole sun]

oops mb

[narrow torrent]

right off the bat you should be able to find angle BCA

and then you can just use law of sines

pretty simple!

@whole sun

[whole sun]

would that be sin55/7, sinB/b, sonC,42

[whole sun]

and then do all the cross multiplication

[narrow torrent]

not quite

let's let that point at the top of the vertical be point D

DBC = 7

so ABC = 90 - 7 = 83

then you can use law of sines

once you have found angle BCA

[whole sun]

wat would the law of sines be

for this because i got it wrong when i tried doing it

or is it just the sin55/a

[topaz sinew]

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[whole sun]

.close

[topaz sinew]

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[small rampart]

An inverted conical container of height 3m and radius 1m is full of water, which is evaporating at a rate proportional to the water surface area exposed to air, i.e. $\frac{dV}{dt}=kS.$

(A) Show that the height of water in the container is h m, the bolume V and the water surface area S are $\frac{\pi h^3}{27}$ and $\frac{\pi h^2}{9}$ respectively (which i got)

(B) If it takes one hour to reduce the height of the water by half, find k and the time taken for the water to fully evaporate.

[thorny flame]

Hamburglers

Hamburglers

Hamburglers

Hamburglers

[small rampart]

<@&286206848099549185>

[topaz sinew]

@small rampart Has your question been resolved?

[topaz sinew]

@small rampart Has your question been resolved?

[topaz sinew]

@small rampart Has your question been resolved?

[elder leaf]

Maybe first try to make sense of the statements the exercise gives you. For example, if you have an inverted conical shape as the volume, you may draw something in order to represent the system you're working with

We are talking about the height that is at half of the conical shape

Proportionality seems to be the reasoning

[topaz sinew]

@small rampart Has your question been resolved?

[mortal thunder]

@small rampartHammmmmmm burgler 👀

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[deep solar]

How does one do this proof

[topaz sinew]

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[sturdy needle]

hello

[sturdy needle]

So I have this question

That I do not know how to solve

it would be appreciated if you help me out

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[real sierra]

can someone see if i got 6) right

[sweet shard]

no

$\sqrt{(a + b^2)} \neq a + b$

[thorny flame]

riemann

[sweet shard]

you have to use the quadratic formula

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[vast radish]

i need help

[vast radish]

please

[neon iron]

what do you need help with

[vast radish]

The question is, find the perimeter of an isoscleles right triangle with a 6-cm hypotenuse

and i have to use pythagorean theorum

what does an isosceles right triangel look like?

[neon iron]

here i'll show

[vast radish]

ok

[vast radish]

oh

where would i go from there

[neon iron]

set up the pythagorean theorem with what you have currently

[vast radish]

ok

X squared + X squared = 36?

[neon iron]

yes

[vast radish]

how do i combine x squareds

[neon iron]

you don't have to, you already know that the two sides that you need to find are the same

[vast radish]

og

oh

but what is the perimeter

[neon iron]

actually

hold on

[vast radish]

ok

[neon iron]

it would be 2a^2=36

[vast radish]

oh

so then i do x^2 = 18

and then x = √9 * 2

and then x = 3√2?

[neon iron]

yep

[vast radish]

yay

i have one more

[neon iron]

nice job

sure

[vast radish]

thx

i will take picture

here

[neon iron]

15?

[vast radish]

number 16

[neon iron]

oh right

[vast radish]

i know the hypotenuse of the big one is 10

but i dont know what else i am supposed to do

[neon iron]

alright let me see

sorry i'm doing my math hw and this at the same time

[vast radish]

oh

[neon iron]

give me a minute

[vast radish]

sorry to bug u

[neon iron]

no it's all good

[vast radish]

ok

[neon iron]

this ones confusing me lmao

i might just be overthinking it

[vast radish]

oh

i think we gotta do pythagyrean theorum

[neon iron]

yeah but we gotta find the length of the line AD or DB for that

[vast radish]

yeah

is there like some sort of median theorum or something

[neon iron]

never heard of it

[vast radish]

awww

i think im overthinking it too

i got it

2√6

because there is a similar triangle theoru,m

[neon iron]

oh 💀

i'm glad and disappointed at the same time

[vast radish]

if you rotate triangle CDB 90 degrees left at point d

i guess u were overthinking it

i overthink things too

[neon iron]

yeah

well nice

[vast radish]

i think im good for now

right now i am studying for quiz

and finding problems

i will tell you if i find hard one

[neon iron]

sounds good

what grade are you in if you don't mind me asking

[vast radish]

7th, but i go to high school for 10th grade honors geometry

[neon iron]

damn you must be smart

[vast radish]

thx

r u 10th grade too

[neon iron]

i'm in 11th

[vast radish]

oh

cool

[neon iron]

i skipped geometry so i'm not very good in that department

[vast radish]

it is ok

[neon iron]

forgot most of it

yeah it is what it is

[vast radish]

i skipped 6th, 7th and 8th

[neon iron]

lmaoo yeah

[vast radish]

so im not that good in pre algebra

lol

[neon iron]

algebra is way easier than geometry for me

[vast radish]

ooh i found a difficult

[neon iron]

cant be good at everything

[vast radish]

If the perimeter of a rhombus is 8√5 and one diagonal has a length of 4√2 find the length of the other diangonal

[neon iron]

i'm not even gonna try to help you with that 💀

[vast radish]

oh

[neon iron]

if i learnt it before, i completely forgot

sorrry man

[vast radish]

did you forgor that stuff💀

[neon iron]

you can post it again and im sure others can help

yep

[vast radish]

ok

[neon iron]

pre calc is hell

[vast radish]

is it scary

[neon iron]

yes

very

[vast radish]

oh

many spooky🎃

[neon iron]

it's like geometry algebra and trigonometry all together

[vast radish]

oh no

i do not want that

[neon iron]

welll it seems like you're gonna have to deal with it

good luck mate

[vast radish]

thx

it's weird going to high school when your in 7th grade

[neon iron]

yeah definitely

[vast radish]

because i get stared at, cuz im small for a high schooler

im small for a 7th grader

[neon iron]

yeah

oh

tough

[vast radish]

eh i dont mind

ok anyway

i will tell u when i have problem that is hard

ok

[neon iron]

I probably can't help much but of course

[vast radish]

ok

but u helped some

to me u are pretty heplful

[neon iron]

thanks lol

[vast radish]

i have one

17

it is super hard

is u still there

[empty sail]

Just apply Pythagorean theorem multiple times

[vast radish]

but how to apply it on 1

[neon iron]

sorry can't help i'm currently walking home

[vast radish]

oh

bye bye

[neon iron]

good luck

[empty sail]

Do you know Pythagorean theorem?

[vast radish]

yes

a√2 + b√2 =c√2

[empty sail]

No

[vast radish]

no i mean squared

[empty sail]

a^2 + b^2 = c^2

[vast radish]

thx

yes

that is it

[empty sail]

Apply that, starting with the smallest triangle

[vast radish]

so 1 + 1 = c^2?

2 = c^2

[empty sail]

And so c is?

[vast radish]

√2

[empty sail]

Now do it again with the next triangle

[vast radish]

!?!?!

how to multiply that

[empty sail]

That’s all there is

[vast radish]

1 x √2

[neon iron]

you have to keep repeating until the last one

[vast radish]

yes but how to do 1 times √2

[empty sail]

It’s still Pythagorean theorem

[neon iron]

you have to use the theorem

[empty sail]

There’s no multiplying

[vast radish]

wait wait you are walking home? it is 5 o clock

oh

[neon iron]

yeah i had to do corrections

[vast radish]

1 + √2

[vast radish]

ah yes

[neon iron]

currently in a car right now actually

[vast radish]

you drive the car?

[neon iron]

yeah it wasn't really a homework 💀

[vast radish]

oh

[neon iron]

my friend does

[vast radish]

tell your friend i said meow

[neon iron]

sure

[empty sail]

That sqrt(2) is the hypotenuse of the first triangle but it’s also the leg of the next one

[vast radish]

yes

[empty sail]

That’s the pattern

[empty sail]

And no

That’s not applying Pythagorean theorem correctly

[vast radish]

is it √3?

[empty sail]

Yes

Now continue

[vast radish]

ok bye bye

ok

it is 3 this time?

[empty sail]

No

The sides are sqrt(3) and 1

[vast radish]

yes √3 times 3 is √9?

ah yes 4

it is 4

[empty sail]

And then?

[vast radish]

16 + 1 = c^2

√17

x = √36

x = 3√4

[empty sail]

No

The side is 4 and 1

Wait

It's sqrt(4)

[vast radish]

why

[empty sail]

You forgot the root

[vast radish]

im onto the last triangle tjough

[empty sail]

The side was sqrt(3) and 1

That hypotenuse isn't 4

It's sqrt(4)

If you applied pythagorean theorem correctly

[vast radish]

oh yeah

i am do different porblem now

[empty sail]

Did you get the other question?

[vast radish]

find the perimeter of a rectangle whose dagonal is 17 and base is 15

yes i did

it is being √5?

for the last one

[empty sail]

Yes

[vast radish]

ok

[empty sail]

Apply pythagorean theorem

[vast radish]

ok

hmmm what numbers go into 514

[empty sail]

1 and 514

[vast radish]

thats it?

oh wait

i did it wrong

diagonal is high pot in use

[empty sail]

You asked what numbers go into 514 and I gave you some

[vast radish]

other one is leg

does 2 go in it too

is 2 a perfect square

[empty sail]

2 is not a perfect square

[vast radish]

ok

so 225 + b^2 = 289?

b^2 = 64

b = 8

right?

[empty sail]

If you applied the formula right, sure

[vast radish]

yaaaaaaay

[empty sail]

Still not the end of the problem though

[vast radish]

oh yeah

8 + 17 + 15

is

40!

yay

😁

[empty sail]

No

[vast radish]

oh

46!

[empty sail]

.

[vast radish]

it is defently 46?

i think

yes

[empty sail]

You have the sides

[vast radish]

yeah

and i add them

[empty sail]

Just add them

[vast radish]

15 + 15 + 8 + 8

😁

is that it?

oh no

he not respond 😮

oh wait

[empty sail]

Did you use a calculator correctly?

[vast radish]

what did i do

8 + 8 is 16?

15 + 15 is 30

30 + 16 is 46

AM I DOING SOMETHING SuPER DUMB AGAIN

[empty sail]

So then the question is, why are you second guessing yourself if you did everything properly?

[vast radish]

um

i thought that um

yeah

um

yeah

.

ok

next problem

find the peremiter of a rhombus with diagonals 12 and 16

[empty sail]

That one, don't know

[vast radish]

ah yes

oh no

he arent respond

he must be DEAD

NOOOoooooooo

ok

so i have new problem

find the length of the diagonal of a square with perimeter 12 cm

[neon iron]

im back

im not home but i think i can still help

[vast radish]

ok

[vast radish]

hm

[neon iron]

obvious?

[vast radish]

i know this one

3 squar 2

are you dldh202

[neon iron]

no

thats a whole different person

[vast radish]

ah yes

did your friend say meow back

[neon iron]

unfortunately no

[vast radish]

did he say, what a weird child

[neon iron]

.

she didn't say anything

now get back to work

[vast radish]

Youre a SHE?!?!

wow

i didnt know

[neon iron]

no i'm a he

[vast radish]

Ah yes

ok

[neon iron]

my friend is a she

[vast radish]

so

[neon iron]

yeah

[vast radish]

ah

[neon iron]

we're studying for a test next week

lmao

[vast radish]

PM is alt of equilateral triangle PKO. if PK = 4. find PM

I can help you studying

[neon iron]

i highly doubt it

[vast radish]

ok

what is one problem

[neon iron]

uh

[vast radish]

what is a tangent

is it like a tangerine

[neon iron]

a trig function

dude lmfao

[vast radish]

yum

https://tenor.com/view/tumble-orange-fruit-yum-fresh-gif-4901972

u make me hungry

ok

back to my work

[neon iron]

yes

[vast radish]

this

[neon iron]

draw it out first

[vast radish]

the base is OK, with M in the midpoint

and alt is P

[neon iron]

hmm, send a picture

[vast radish]

um

there is not one

[neon iron]

d r a w i t

[vast radish]

my math book didnt give one

oh

[neon iron]

if you're stuck always draw one

helps you process what you have and what you can do

[vast radish]

ok

i am paste it now

[neon iron]

paste it?

[vast radish]

i kinda put it over a game

that screenshot is old

like 6 month

[neon iron]

whatever works for you haha

wait you did this before?

[vast radish]

no

the game in the back

[neon iron]

oh

[vast radish]

oh no the screenshot shows my name 😦

dont look

at the top left corner

top right i mean

[neon iron]

yeah of course

i will look

i mean not

[vast radish]

ok

[neon iron]

ok so

[vast radish]

i should have been more careful 😮

[neon iron]

equilateral triangles sides' measurements are the same right

[vast radish]

yes

[neon iron]

here ill sketch it

[vast radish]

ok

[neon iron]

do you think this is correct

[vast radish]

yes

om is 4

om is 2

i mean

[neon iron]

yes

and there you can use the theorem

[vast radish]

here is a video for helping me

you get paid in videos

[neon iron]

i appreciate it

[neon iron]

that must hurt

how many problems did you have in the homework?

[vast radish]

i am studying

[neon iron]

ah ok

[vast radish]

the best one of all

[neon iron]

what am i watching

[vast radish]

idk

did u watch

isnt it epic

but u gotta turn it on full volume

oh wait

i gotta go

i am finished for to day

[neon iron]

niceee

[vast radish]

i have study for 2 hour

i hope i get good grade

[neon iron]

same

[vast radish]

is the person in ur proficle pic u

the person in my profile pic is me

[neon iron]

no haha

[vast radish]

the frog dude

[neon iron]

reasonable

[vast radish]

i am frog dude

[neon iron]

i see

[vast radish]

and i wear hat

and as an ultimate reward for helping me...

do you have a chromebook

for school and stuff

because i know how to play fortnite, and rocket league, and basically any console game on it

make a geforce now account

and connect your epic games account

and then you select a game

and thenplay

ok anyway good bye

[neon iron]

i'm good lol, good luck with your stuff though

[vast radish]

ok bye bye

[neon iron]

do .close if you don't have more questions

[vast radish]

ok

also what is your tag

friend me

[neon iron]

sure

[vast radish]

i am t0enail 6442

😄

[neon iron]

added

[vast radish]

ok

.close

[topaz sinew]

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[topaz sinew]

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[real sierra]

can someone help me with 6

[topaz sinew]

@real sierra Has your question been resolved?

[real sierra]

.close

[topaz sinew]

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[remote grotto]

how is this incorrect?

[solemn wigeon]

look at the square root

have u made the problem simpler?

actually i think you just forgot that your sub was x = 3sin(theta)

[topaz sinew]

@remote grotto Has your question been resolved?

[topaz sinew]

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[uneven talon]

The one with the blue arrow is right and the one with the red arrow is wrong. Ive tried 45 and its still wrong haha

[topaz sinew]

@uneven talon Has your question been resolved?

[uneven talon]

Ive tried again -63 and 45 just to be sure and its wrong

[uneven talon]

😭

someone help plz

[topaz sinew]

@uneven talon Has your question been resolved?

[sweet shard]

Do the blue one first with rules of integration endpoints

Properties 1-6 here
https://tutorial.math.lamar.edu/classes/calci/defnofdefiniteintegral.aspx

[topaz sinew]

@uneven talon Has your question been resolved?

[topaz sinew]

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[mellow sequoia]

woo alrighty

I just wanna make sure I have the right setup for this

one minute while I actually set it up lol

[neon iron]

2 = 4
Devide by 2
1 = 2
Raymeen hypothesis solved

[mellow sequoia]

wha

oh sorry

I need to find the volume in the enclosed region rotated about x=1

[mellow sequoia]

sorry. forgot to also copy the instructions to the problem lol

[neon iron]

No idea, out of my leauge, lol. Good luck though.

[mellow sequoia]

lol thanks

hopefully a calc1 person can help

is this the answer (once I actually solve the integral)?

.close

[topaz sinew]

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[delicate pine]

Can someone help solve c

[polar hemlock]

,rotate

[polar hemlock]

Ah.

so you know the sum and product of roots

@delicate pine

?

[delicate pine]

U don't ;-;

I *

Wait sum should be 3 and product is -b

[polar hemlock]

hm?

wait

so how did you do (b)