#help-26

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timber hill
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topaz sinewBOT
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worldly pelican
#

could someone explain with a? i'm completely lost

south ivy
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So what have you tried??

worldly pelican
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so ive gotten 0<2t <= pi

south ivy
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Okay

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And??

worldly pelican
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nothing else

south ivy
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What can be the maximum value of sin(x)

worldly pelican
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1?

south ivy
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Yes

worldly pelican
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but why does sin(x) matter here?

south ivy
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And when is that??

south ivy
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y is representing the height

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And you need max height

worldly pelican
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oh i see

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so it would be sin2t = 1?

south ivy
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Yeah but is it in your interval

worldly pelican
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so rearrange for t?

south ivy
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No

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For what t when is sin(2t)=1

worldly pelican
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t = pi/2?

south ivy
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NO

worldly pelican
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t = (arcsin(1))/2 ?

south ivy
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And what is arcsin(1)

worldly pelican
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pi/2

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so just pi/4?

south ivy
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Yes and is that in your given interval??

worldly pelican
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yup

south ivy
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So there you have it

worldly pelican
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thanks for that

south ivy
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Yw

worldly pelican
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should i just close it?

south ivy
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Yes

worldly pelican
#

thanks again dude

#

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wispy kiln
#

I need to find for which x'es this is true, but I can't find any real number for which the condition is false.

merry mason
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What is this bracket

gentle owl
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ceiling function

merry mason
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Oh

gentle owl
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round up basically

merry mason
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How bout x=2

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It seems to be true for that x

gentle owl
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-1.5 it is false for

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wait no

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it seems to be true for like everything

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huh

merry mason
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There should be a method to prove that

wispy kiln
merry mason
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Just to make sure, ceiling 2.1 gives 3 right?

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Ceiling of a integer gives integer right?

wispy kiln
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here are all my testcases

merry mason
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You wrote uneven instead of odd 🤔

wispy kiln
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lmao that's what happens when you translate directly from another language

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but yes uneven is supposed to say odd

merry mason
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Also in case of even positive 2 cases will form

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One where x is 4n and one where x is just 2n

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Coz x being 4n will make it a integer and x being 2n will make LHS and RHS a fraction whose ceiling nonetheless matches the condition

wispy kiln
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in conclusion; works for all real numbers?

merry mason
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Can't be sure, I'm doing comprehensive reading atm

wispy kiln
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that's enough tests, I'm gonna have to prove that it's true for all real numbers

merry mason
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Yeah it works for all real nos

wispy kiln
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any idea how to prove it?

merry mason
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Yeah

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You may try converting the ceiling function to fractional function

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Like

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Ceiling of x =x+ (1- {x})

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Here you know the range of {x} is [0,1)

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So that should make it easier I guess

wispy kiln
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what is {x}?

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what do the curly brackets mean?

merry mason
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Fractional part of x

wispy kiln
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hmm

merry mason
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I dunno how you symbolise that there

topaz sinewBOT
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@wispy kiln Has your question been resolved?

wispy kiln
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kind of

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lets go with yes

topaz sinewBOT
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waxen spruce
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could someone walk me through this?

topaz sinewBOT
tough nest
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do you know what the rules for exponents are

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and the rules for logarithms?

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@waxen spruce

waxen spruce
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yes

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well theres one rule im a little confused about

leaden tusk
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this seems like a see or no see question, wouldn't you say katharine

tough nest
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fuck off

leaden tusk
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rude

tough nest
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ha

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says you

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comes in here

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while i'm trying to help chao

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being a rude

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@waxen spruce what rule are you confused about?

waxen spruce
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this one

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ive tried to use it in the past but its never worked out

tough nest
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what you should think when you see that

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take both sides to the power a

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so

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if you have

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$\log_a(x) = \log_a(y)$

thorny flameBOT
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Katharine

tough nest
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$a^{\log_a(x)} = a^{\log_a(y)}$

thorny flameBOT
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Katharine

tough nest
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the exponent and the logarithm are inverse functions

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this means they cancel

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like add and subtract

waxen spruce
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ahh

tough nest
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and multiply and divide

chrome glen
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I mean thats not really a log rule

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Its just a function rule

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$f(x)=f(y) \to x=y$

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Assuming f(x) is just any function

thorny flameBOT
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PapaBread

tough nest
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what is the rule of multiplying numbers that have exponents?

waxen spruce
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so i got as far as getting ln(xy) = ln(5)

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from the first equation

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could i then just say xy = 5?

tough nest
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$e^{x}e^{y} = e^{5}$

thorny flameBOT
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Katharine

tough nest
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what we know is that when you multiply the e

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it adds the exponents

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do you remember that rule?

waxen spruce
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yeah

tough nest
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so that means

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$e^{x + y} = e^{5}$

thorny flameBOT
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Katharine

waxen spruce
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ah so youd have ln(x + y) = ln(5)

tough nest
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you just have x + y = 5

waxen spruce
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true

tough nest
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because ln(e^x) = x

leaden tusk
tough nest
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you can now express x in terms of y and the other way around

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you see that?

waxen spruce
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yeah

tough nest
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can you try simplifying the second equation?

chrome glen
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Wait whyd you e^x it twice?

waxen spruce
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ln(2x + y) = ln(12)

chrome glen
tough nest
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x and then y

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that's correct btw

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and now

waxen spruce
tough nest
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exactly

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and now you have 2 simple equations with 2 variables

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that means you can find both x and y

waxen spruce
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ye ty

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<3

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sinful roost
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How would I evaluate this on my calculator for cot^-1 (5.4) I plugged in 1/tan^-1 (5.4) into my calculator and got something else

thorny flameBOT
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Theophania

leaden tusk
sinful roost
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ye its in degree mode im getting something else

topaz sinewBOT
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@sinful roost Has your question been resolved?

topaz sinewBOT
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@sinful roost Has your question been resolved?

topaz sinewBOT
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@sinful roost Has your question been resolved?

sinful roost
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!close

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.close

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topaz sinewBOT
topaz sinewBOT
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@neon iron Has your question been resolved?

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cunning wind
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How do i do this? Like, i don't even know where to start with this one. I tried rationalizing the denominator but its not like that does anything useful for me.

spark plover
wooden matrix
#

Nvm mine fails

spark plover
topaz sinewBOT
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@cunning wind Has your question been resolved?

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west granite
topaz sinewBOT
west granite
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Just confirm, this is false

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Just to confirm a

delicate goblet
west granite
#

thank you

#

.close

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coral flame
#

What is the value of w + x + y + z?
180 - 30
30 + (180 - z + y) + (180 - w + x) = 180
30 + 180 - z + y + 180 - w + x = 180
30 + 180 + 180 - z + y - w + x = 180
390 - z + y - w + x = 180

  • z + y - w + x = 180 - 390
  • z + y - w + x = -210
    z + y - w + x = 210
    w + x + y + z? z + y - w + x = 210
coral flame
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What did I do wrong???

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or what can i do next?

restive inlet
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you messed up your signs near the start

30 + (180 - z + y) + (180 - w + x) = 180

topaz sinewBOT
#

@coral flame Has your question been resolved?

restive inlet
#

redo that step

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where's

(180 - z + y)
coming from

coral flame
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this part

restive inlet
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but why did you write

(180 - z + y)
specifically

coral flame
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because the line is 180 degrees, if we do z + y, and then minus the total from 180, we can get that 1 angle degree from the triangle

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if that makes sense lol

restive inlet
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(180 - z + y)
does NOT represent z + y being subtracted from 180

coral flame
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will I have to do (180 - (z + x))??

restive inlet
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you mean (180 - (z + y))

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that would be more appropriate

coral flame
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ye

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Oh so thats what I did wrong

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and btw, when I remove the brackets, do I have to remove the brackets from (z + y) after that?

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right?

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well ig it will make sense...

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.close

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young vale
#

I have to demonstrate this

topaz sinewBOT
young vale
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How?

spark plover
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uk sum of ap formula ?

young vale
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no

restive inlet
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that's what they're trying to show, so they can't apply that directly

spark plover
young vale
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Ye

restive inlet
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depends on the course

young vale
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or reduction to absurd

restive inlet
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if you're required to do induction

young vale
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I got direct form, induction or absurd

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Any of them will work

restive inlet
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alternatively you could derive it how it was originally derived

young vale
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I just have to state if this is true or not and why

restive inlet
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by considering pairs of values that will have the same sum

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i.e. 1 with n
2 with n-1
etc

spark plover
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@young vale u need to say true or false or derive it ?

restive inlet
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and the numbers of pairs there are

young vale
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Wdym by derive it

spark plover
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what romonov is saying

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ya both will endup the same though

young vale
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Investigate and prove the following statements

spark plover
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here u derive it

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there u assume it is crt and prove it

young vale
restive inlet
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1 + n = ?

young vale
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Aha

restive inlet
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2 + (n-1) = ?

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3 + (n-2) = ?

spark plover
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n+1

young vale
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n+1 yeah

spark plover
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so there are n terms
when u pair up number of terms = n/2

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so u are adding n+1 n/2 terms

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so we get n/2 x n+1
which is n(n+1)/2

young vale
spark plover
young vale
#

but where the /2 comes from

spark plover
young vale
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Yeah

spark plover
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when u pair them up how much terms will be there ?

young vale
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1

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wait

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n/2

spark plover
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ya

young vale
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Okay

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And why we pairing number of terms?

spark plover
spark plover
young vale
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Oh ok

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Yes

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i got it

spark plover
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cool

young vale
#

So, 1+2+3+...+n = n(n+1)/2 is true because, knowing there are n terms, pairing them we will have n/2 terms, and knowing that 1+n = 2+(n-1) and so on, we get n/2*n+1

spark plover
young vale
#

Okay

#

thanks

#

.close

topaz sinewBOT
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neon iron
topaz sinewBOT
neon iron
#

5c pls

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What would be the suitable percentile

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maybe try to find the E(X)

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What's that?

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@neon iron

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actually it dm, you should make a frequency diagram according to your results

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then that will help you get your percentile

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Ight I'll try that thanks

topaz sinewBOT
#

@neon iron Has your question been resolved?

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neon iron
#

<@&286206848099549185>

topaz sinewBOT
neon iron
#

could you please explain to me how i can solve the second part of this question

topaz sinewBOT
#

@neon iron Has your question been resolved?

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thin plover
topaz sinewBOT
thin plover
#

hey all, part A is 21,090$, but for part B im having trouble figuring out where id go from

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this being the formula used to solve for A

dense elbow
#

2(cos(45))⁴ =1/2x3/5+1-2/2 cos=

topaz sinewBOT
#

@thin plover Has your question been resolved?

thin plover
#

how did we use cos in the formula?

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or why*

vestal hinge
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Use arithmetic sum to find out the value that's ≥ 27000

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Don't use cos

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I think he's asking a question

thin plover
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xd

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would I use the same formula from above? the one i sent

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27000 ≥ (1+.045/12)

vestal hinge
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27000 ≤

thin plover
#

what does r stand for in the formula ? @vestal hinge

vestal hinge
#

Rate of change

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In your case it would be 1.045

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Find n first and then divide by 12

thin plover
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n is .045/12

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?

vestal hinge
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It's quite messy putting 12 into the formula I think

vestal hinge
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n is what you have to solve for

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You know Sn, a, and r

thin plover
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so R would be (27,000 - 7350)?

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the difference between values

vestal hinge
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No

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R is 1.045

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i.e. 104.5%

thin plover
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so

vestal hinge
#

Interest is 4.5% but that doesn't mean that you have 4.5% what you initially put in a monthl later. You have the initial money PLUS 4.5% of it so it's 100%+4.5%

Ergo r = 1.045

thin plover
#

27,000 = 7350(1+(0.045))^12(t)

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or

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27000 = (7350)(1 + (0.045/12))^((12)(t))

vestal hinge
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Don't use 12

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Can you use the formula I sent you

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Without using 12

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Once you get n, just divide by 12 later

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It's dumb to put in 12 into the equation

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Also it's 27000 ≤ and not =, because you could end up with more (but you should never have less)

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i.e. at least n/12 amount of years

thin plover
#

what is S in the formula you sent ?

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27,000

vestal hinge
#

Yes

thin plover
#

27,000 ≤ (1 - 1.045^n) / 1- 1.045

vestal hinge
#

You forgot n

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And a

thin plover
#

what is A in the equation ?

vestal hinge
#

7350

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Initial deposit

thin plover
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so

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27,000 ≤ (7350(1-1.045)^n) / 1 - 1.045

vestal hinge
#

No

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Why did you add extra brackets

thin plover
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to make it easier to read but maybe not

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27,000 ≤ 7350(1-1.045)^n / (1 - 1.045)

vestal hinge
#

Still no

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You added brackets in wrong place

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No

thin plover
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LOL

vestal hinge
#

Bro

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It's

thin plover
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bare with me

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so sorry

vestal hinge
#

The n is supposed to be attributable to 1.045 only

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You n powered the whole bracket

thin plover
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27,000 ≤ 7350(1-1.045^n) / (1 - 1.045)

vestal hinge
#

No?

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What happened to 1

thin plover
#

let me get a paper

vestal hinge
#

...

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27,000 ≤ 7350(1-1.045^n) / (1 - 1.045)

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Ok now solve for n

thin plover
#

so n ≥ 3.47

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non rounded

vestal hinge
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Actually wtf

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I'm ill

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I've made you use wrong formula this whole time

thin plover
#

ok good cause ive never seen it before

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in my life

vestal hinge
#

Same values

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Same ≤

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Solve for n

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Ceil n,

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Divide n by 12

thin plover
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id get 7350n ≤ 7350(1.045)^n/12

vestal hinge
#

What

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No

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No

thin plover
#

I ended up trying to use a log of base (1+ (.045/12)) on both sides and got 28.96832582... or ~29 years

vestal hinge
#

Stop putting 12 into the equation please

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That's wrong

thin plover
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what would the new equation be with An = A1(r)^n-1

vestal hinge
#

27000 ≤ 7350(1.045)^(n-1)

thin plover
#

i was close

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i got n ≥ 31

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rounded

vestal hinge
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No rounding

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You ceil it

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N is 30.5.... but the required months is ceiling of N

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Which is 31

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Not sure if you're supposed to divide N by 12 or ceiling of N by 12

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Probably N by 12

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Idk

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Maybe ceil of n

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Actually don't know

thin plover
#

in conclusion fuck this class for not teaching me

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id assume 12

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i say 31 since

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but im sure i wouldnt get points docked off for it

topaz sinewBOT
#

@thin plover Has your question been resolved?

topaz sinewBOT
#
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patent kestrel
#

how to factor

$\frac{9^{\left(2n-1\right)}+9^{\left(2n+6\right)}}{9^{\left(2n-1\right)}+9^{\left(n+5\right)}}$

thorny flameBOT
#

Tom Joney

wide juniper
#

TOM

#

Oh what's n again

#

Imaginary number right

patent kestrel
#

No

wide juniper
#

Oh what's that

patent kestrel
#

'i' is imaginary number

#

'n' is just a variable

wide juniper
#

Ohhh

#

So whats m

topaz sinewBOT
#

@patent kestrel Has your question been resolved?

crimson rampart
#

The best I could do for the bottom is $9^{n-1}(9^n + 9^6)$

thorny flameBOT
#

RESIDGE

crimson rampart
#

I got $\frac{9^{n-1}(9^n)(1+9^7)}{9^{n-1}(9^n + 9^6)}$

thorny flameBOT
#

RESIDGE

crimson rampart
#

Hopefully it's right. Then I see that I can cancel 9^(n-1)

#

I think you can also factor out 9^n from the bottom and cancel again.

#

$\frac{1+9^7}{1+9^{6-n}}$

thorny flameBOT
#

RESIDGE

topaz sinewBOT
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next tree
topaz sinewBOT
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pliant leaf
#

Could use some help here

topaz sinewBOT
pliant leaf
#

I'm not sure how to proceed with this question.

#

Could I maybe find the first derivative of the function and insert 0 as x?

plain mica
#

try minimizing the square of the distance

pliant leaf
#

Alright

plain mica
#

do you know calculus?

pliant leaf
#

I do. (roughly 😅 )

pliant leaf
#

Could I set the original equation =0?

pliant leaf
#

and then solve for x?

plain mica
pliant leaf
plain mica
#

or.. do you know normals?

#

find the normal to this curve passing through the given point

pliant leaf
#

I do not sadly.

plain mica
#

the point of intersection of the normal with the curve is the point, the distance between it and the gievn point will be minimum

pliant leaf
#

Do you mean finding where the slope is 0?

#

Maybe the terminology is different.

#

So would I accomplish that by taking the first derivative of the function and setting it =0 maybe?

#

@plain mica I'm still not sure what to do even after reading through the link you sent. Should I just ask someone else?

plain mica
pliant leaf
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.close

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topaz sinewBOT
plain mica
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google

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you're welcome

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lucid fog
#

bh

topaz sinewBOT
lucid fog
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hi

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regal folio
#

How do I find v

topaz sinewBOT
regal folio
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clever temple
#

Hi I have to differentiate this

topaz sinewBOT
clever temple
#

But the textbook answer is 2/3x^4/3

#

How can I get 2?

wooden matrix
#

there's a 2 already there...

#

it's the coefficient

#

your 3rd line, you just simply ignored the 2

clever temple
#

Oh

#

I got it thanks!

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rich finch
#

can anybody explain to me how ones brain can come up with this way of splitting this fraction? I realise I'm in advanced maths but im doing university late and am a bit rusty on basics like this and they sometimes trip me up ;p

rich finch
#

i get that he is adding an s and subtracting an s but idk how that splits the fracction like that 😮

#

is it just partial fractions but written weirdly?

keen venture
#

Skipping this step:
[(s + 1) - s] / s(s + 1)
= (s + 1)/s(s + 1) - s/s(s + 1)

#

As always, the denominator can distribute over the numerator.

rich finch
#

ooo ok

#

so very simples 😂

#

ty

keen venture
#

Np, feel free to ask if you have anything else

#

Btw this is partial fractions, but without the algebra.

#

That is, they figured out the coefficients by messing with the fraction

rich finch
#

id probably do it via actual method

#

gonna do that now ;p

#

thanks!

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merry pier
#

Hello, can anyone tell me if the problem is correct. It is an arithmetic progression

merry pier
topaz sinewBOT
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@merry pier Has your question been resolved?

merry pier
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<@&286206848099549185>

restive inlet
#

you haven't solved it properly

#

$a_m + a_n \neq a_{m+n}$

thorny flameBOT
#

ℝamonov

merry pier
#

Yeah, I get it, but now how to solve?

restive inlet
#

it feels like you have an idea of what to do, you just need to notate it properly

#

i.e. show that
a_1 + a_12 = a_5 + a_8
using the definition of (the nth term of) an arithmetic sequence

merry pier
#

Clear. Now I will try again. I was confused precisely because of this property.

#

I think I've already fixed the mistake

neon iron
thorny flameBOT
wispy kiln
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spare lodge
topaz sinewBOT
spare lodge
#

I dont know what the 2 rules could be

#

A and D cant fit any of the rules, B has to fit both and I think C can either fit both or just fit 1 rule

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naive grove
#

and isosceles triangle's inner circle's radius = 10
what's the smallest perimeter of the triangle

naive grove
#

Hello, I'm having issues with the problem above

#

i've trieg going at it with trigonometry and algebra

#

where I would end up with an equation with 2 unknown variables, and said equations seemed like a pain in the ass to express one variable from

naive grove
#

trigonometric approach lead here

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naive grove
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D:

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tribal zephyr
#

How do I show that 1/(x+1) is not a probability measure

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odd frigate
#

$f(x) = 1 + \frac{4}{(x-7)(x-3)}$

topaz sinewBOT
thorny flameBOT
#

Guilhotina

odd frigate
#

when i have this, and has to integrate it, but the range of my domain is [7;10] how should i proceed?

toxic swift
#

I would use a substitution to make it simpler, u = x - 7, so x-3 = u+4, and du = dx.

modern bloom
odd frigate
#

i would resolve that by partial integration and then get a ln(x-7) where x approaches 7+

#

how do i found this limit? L'Hopital ?

#

i know it is $-\infty$

#

i know it is $-\infty$

#

a

thorny flameBOT
#

Guilhotina

odd frigate
#

but how to prove it

#

is this right?
$lim_{x \to 0+}(lnx) = lim_{y \to - \infty}(ln(e^{y})) = -\infty$ where $e^{y} = x$ and $ln(x) = y$

#

?

thorny flameBOT
#

Guilhotina

modern bloom
#

Mmm I think that should be enough if a proof is required. I mean, I think you can just assume that ln(0) approaches -infty from the right in this problem, but what you've done is correct :thumbsup_tone3:

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heady pendant
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heady pendant
topaz sinewBOT
heady pendant
ocean hare
#

@heady pendant are you aware of first and second differences?

#

you need to determine what type of function this is before you can do anything

#

btw (it's a quadratic i think)

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forest rune
topaz sinewBOT
forest rune
#

how can I solve this?

topaz sinewBOT
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@forest rune Has your question been resolved?

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@forest rune Has your question been resolved?

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@forest rune Has your question been resolved?

still void
#

Then solve for A.B and find angle between them from that

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neon iron
#

Got some issue with this task need to find lim x-> 0 (1-root(x))/x
But that schoudlnt be possible as we cant divide by 0... and its not 0/0 so i cant use l‘hospital or am i mistaken?

neon iron
#

So can i just say there is no limit ( if my conclusion is right ) or would i need to prove this somehow?

#

Thanks in advance

leaden tusk
#

limit doesn't exist, correct

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lusty ravine
#

What's the difference between these two notations?
$x^{(i)}$ and $x_{i}$

thorny flameBOT
#

THEBIGTHREE

empty sail
thorny flameBOT
#

dldh06

lusty ravine
#

ah alright, thank you!

empty sail
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shy grotto
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shy grotto
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<@&286206848099549185>

wheat laurel
#

wait

#

what's the standard deviation?

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meager glacier
#

Can you guys give me a tip in dividing fractions. I am good at it but I would like to know about it more.

meager glacier
#

answer

burnt badger
#

Dividing with a fraction is really multiplying with the reciprocal

#

This is the ultimate tip

cunning urchin
#

Yeah that’s all I do ^

meager glacier
#

ok thanks

burnt badger
#

In fact all division is really multiplying with the reciprocal

cunning urchin
#

(1/3) / (4/5) just do (1/3) x (5/4)

meager glacier
#

yeah I know

#

ok thanks

#

this really helps me

burnt badger
#

This gets you from here to calculus and beyond

At least for dealing with fractions xD

meager glacier
#

hehe

#

anyways thx

burnt badger
#

There are some other things you learn along the way

#

Yw

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loud coyote
#

I dont get why k*x^2 is removed for this induction problem? can someone teach me why

snow basalt
#

As in why you can remove kx^2 or why removing kx^2 is neeeded for the proof?

loud coyote
#

why you can remove kx^2

snow basalt
#

so first, k>=0 and x^2>=0 so kx^2>=0. Adding 1-(k+1)x to both sides of that, 1-(k+1)x+kx^2>=1-(k+1)x

#

So, we can rewrite the earlier inequality adding that in, $\(1-x)^{k+1}\geq 1-(k+1)x+kx^2\geq 1-(k+1)x$

thorny flameBOT
#

Sneaky

snow basalt
#

which leads to whats written

topaz sinewBOT
#

@loud coyote Has your question been resolved?

loud coyote
#

ok so basically since kx^2 is positive

#

and because 1-(k+1)x+kx^2>=1-(k+1)x, the kx^2 can be removed because the statement still holds true yes

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grand bough
topaz sinewBOT
grand bough
#

How do I find the vertical stretch of c and d?

#

Like for c) my answer is 4 VS but according to the textbook it is 8

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sudden leaf
#

is this asking me what the net force is? if so is the net force <-4,0>?

snow basalt
#

yes and no

sudden leaf
#

oh hm

snow basalt
#

The net force is just gonna be the sum of those vectors

#

you might have done some wrong arithmetic in the y coordinate? I only suggest that because you have the x coordinate of the net force correct so your method might be correct

sudden leaf
#

ohh i see

cunning urchin
#

-11 for y

sudden leaf
#

yeah i did -5+1+4

#

instead of -5+1-7

#

thank you!

#

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neon iron
#

How do you write a transformation of f(x) —> af(bx) with matrices or vectors?

neon iron
#

As in f(x) goes to a * f(b * x)

#

Just generally

#

@proven anvil

#

R for both

#

Continuous

#

Yes

#

Of f(x)

#

So for translations you can write it T_v(f(x)) = f(x-a) + b for v= vector (a; b)

#

So the translation of f(x) by vector ab is f(x-a)+b

#

I guess that's what I'm looking for then

neon iron
#

I know how matrices work yes

#

So something like [a 0]
0 b

#

You forgot the second $

#

It could be a vector I'm not even sure

#

Scaled by vector (a,b)?

#

That's confusing

#

I don't see how f(x) would really be a matrix

#

Although f(x) is technically an infinite set of vectors

#

Basically, the textbook says that you can translate f(x) by a vector, so I'm guessing scaling should work in a similar way

thorny flameBOT
#

KurtDee

neon iron
#

Not really...

#

So I don't really know if it would work as v(a, b)*f(x) or maybe instead of v a matrix

#

I should have formulated that better but I don't know how

thorny flameBOT
#

KurtDee

#

KurtDee

neon iron
#

Yep

#

Not an equation, a function

#

But yeah

#

So like every point of the function is moved by a vector ab

#

That's what they mean

thorny flameBOT
#

KurtDee

neon iron
#

Should we try first having vector ab * f(x) see if that works?

#

Lemme try plug that into wolfram alpha

thorny flameBOT
#

KurtDee

#

KurtDee

neon iron
#

So f(x) becomes [f(x) x] (as a matrix)

#

?

#

Oh okay tnhat makes sense

#

-b or +b?

#

Cause it's f(x-a)+b

#

Normally

#

Me too lol

thorny flameBOT
#

KurtDee

#

KurtDee

neon iron
#

So a and b are the opposite from what I have? As in f(x-b)+a?

#

Fair

#

So I can write:

#

$$ for m = \begin{bmatrix}a \ b\end{bmatrix}: \T_m(f(x)) = \begin{bmatrix}f(x) + a \ x +b\end{bmatrix}$$

thorny flameBOT
#

Etienne
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

neon iron
#

Shit

#

For $$ m = \begin{bmatrix}a \ b\end{bmatrix}: \T_m(f(x)) = \begin{bmatrix}f(x) + a \ x +b\end{bmatrix}$$

#

Whatever, you get it

#

Perfect

#

Now, what about scaling?

#

Would $\begin{bmatrix}f(x) \ x\end{bmatrix} * \begin{bmatrix}a \ b\end{bmatrix} = 0 \Rightarrow \begin{bmatrix}f(x) * a \ x *b\end{bmatrix}$

thorny flameBOT
#

KurtDee

#

Etienne

#

KurtDee

neon iron
#

2s

#

Fair yeah

#

So what would it look like?

thorny flameBOT
#

KurtDee

neon iron
#

A is alpha beta right?

#

Yes, matrix [alpha]
beta

#

My bad

#

Identity but with alpha and beta isntead of 1s

#

From $\begin{bmatrix}\alpha f(x) \ \beta x\end{bmatrix}$ how do we get to af(bx) though?

thorny flameBOT
#

Etienne

neon iron
#

with $\chib = x, \begin{bmatrix}f(\chib)*a \ \chi\end{bmatrix}$ ?

thorny flameBOT
#

Etienne

neon iron
#

So can I write for example, $A \begin{bmatrix}f(x)\x\end{bmatrix} = f(bx)a$ ?

thorny flameBOT
#

Etienne

neon iron
#

If I write A before

#

@proven anvil

#

Hello

#

So how do I kinda convert it back to a function?

#

f(bx)a

thorny flameBOT
#

KurtDee

#

KurtDee

#

KurtDee

#

KurtDee

#

KurtDee
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

neon iron
#

Wait why 11, 12, 21, 22?

#

Wdym?

#

So alpha_1 or 2 or 3 or 4 also works

#

Okay

#

However, still don't get how we go back to af(bx) at the end

#

So we do this the other way, have A and then got to af(bx)?

#

Okay

#

👍

#

So, let A = [3 0]
0 2
We can just say that because of what we did above, g(x) = 3*f(2x) ?

#

But if I write what we did earlier is that insufficient?

#

Shit

#

Oh

#

But didn't we start off with A = alpha, 0; beta, 0 ?

#

Oh okay

#

So how do we do it without assuming a = alpha, 0; beta, 0

#

?

thorny flameBOT
#

KurtDee

neon iron
#

I'm not really familiar with matrice equations

#

I can solve a system of linear equations with matrices, which is pretty easy, but solving to get a matrix like this that I don't know how to do

#

@proven anvil

#

Hello again, sorry

#

I should, but I may have cheated my way through high school

#

Yeah

#

Me too

#

Oh

#

I won't bother you anymore then

#

.close

topaz sinewBOT
#
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neon iron
#

Cheers

#

Thanks alot dude

topaz sinewBOT
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visual sorrel
#

need help with this please

A 40cm length of wire is cut into three lengths and these lengths are used to form an isosceles triangle of maximum area. Use calculus to determine the lengths of the sides of this triangle.

inner oracle
#

What's the formula for area of isoceles triangle

visual sorrel
#

1/2.b.h?

topaz sinewBOT
#

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@visual sorrel Has your question been resolved?

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@visual sorrel Has your question been resolved?

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topaz sinewBOT
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winged marsh
#

.close

topaz sinewBOT
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urban timber
#

So I'm a bit lost with some calculus again
In the following, we start with the gradient of some integral
$$\nabla \int P(\tau | \theta) R(\tau)$$
Then (I think?) because of the cyclic relationship between the derivative and integral, we're allowed to just move the gradient under the integral expression to it becomes
$$\int \nabla P(\tau | \theta) R(\tau)$$

But... isn't there an implicit parenthesis there? I mean, isn't it the gradient of the entire expression, not just the first factor?
It looks like they substitute $\nabla P(\tau|\theta)$ for its expansion and just leave $R(\tau)$ as is.

How does this work?

urban timber
thorny flameBOT
#

Amnesia

urban timber
#

It might be worth mentioning btw that R(T) does not depend on the parameters, so its gradient is 0
I still feel like, if that's the reason, then it should cancel out completely, and not just be left as is

topaz sinewBOT
#

@urban timber Has your question been resolved?

wheat laurel
#

i think you should post this in one of the advanced maths channels @urban timber

urban timber
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opal lance
#

Find T if:
\
$a=\sqrt{8} + 2$
\
$b=\sqrt{8} - 2$
\
$T = a^2 - b^2$

thorny flameBOT
#

slayer

opal lance
#

In this question i tried to put each a and b in brackets and power them up to 2 to get this which i think is probably wrong:

restive inlet
#

that's one way to do it

opal lance
#

$a^2= \sqrt{8}^2 + 2^2$
\

$b^2= \sqrt{8}^2 - 2^2$

thorny flameBOT
#

slayer

opal lance
#

@restive inlet is this right?

restive inlet
#

that however is wrong

opal lance
#

Yeah i was quite sure something was wrong

restive inlet
#

classic freshman's dream

opal lance
#

Oh and it tells me to give your final answer in c sqrt 2

restive inlet
#

recall the definition of exponentiation/distributive property and/or binomial theorem

opal lance
#

where c is an jnteger

restive inlet
#

what does it mean to square something

opal lance
#

Multiply each other

restive inlet
#

poor wording

opal lance
#

a x a = a^2

restive inlet
opal lance
#

well i never get asked to define it 😅

restive inlet
#

apply that here and expand (properly)

opal lance
#

Oh expand

restive inlet
#

(applying something like the distributive property)

topaz sinewBOT
#

@opal lance Has your question been resolved?

topaz sinewBOT
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topaz sinewBOT
#
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strong talon
#

I keep mixing up my stuff and I'm not sure where I'm going wrong

topaz sinewBOT
#

@strong talon Has your question been resolved?

grim jacinth
topaz sinewBOT
#

@strong talon Has your question been resolved?

grim jacinth
#

Bro man didn't take my advice one bit lmao

topaz sinewBOT
#

@strong talon Has your question been resolved?

slow zenith
topaz sinewBOT
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quartz shale
#

how do you find sine of any angle/radian?

topaz sinewBOT
chrome glen
#

Wdym

quartz shale
# chrome glen Wdym

the values that are given are for 0,30,45,60,90 right, now how would you find the sine of 42 for example

#

without a calculator

restive inlet
#

convert to radians,
use power series to get a decent approximation

chrome glen
#

Taylor series bleak

quartz shale
#

ik how to convert to radians

#

but what is this power series

restive inlet
#

then

find the sine of 42 for example
without a calculator
is not something you should worry about atm

quartz shale
restive inlet
#

why are you trying to do this without a calculator

quartz shale
restive inlet
#

ask them?

quartz shale
restive inlet
#

ask through email

quartz shale
#

ok

restive inlet
#

or phone

quartz shale
#

but there is no way to calculate sine of any angle/radian without calculator?

restive inlet
#

most places allow approved calculators unless its jee

#

i mentioned what you could use earlier but its too advanced for you to apply atm

quartz shale
#

so i use a calculator to find the sine in my question?

#

alr thank you very much

#

.close

topaz sinewBOT
#
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drifting jasper
#

-3 (4-3x) =9 - 12

topaz sinewBOT
drifting jasper
#

I think that has no solutions, But somebody said it has infinite solutions

#

Can someone double check?

restive inlet
#

you're both wrong

empty sail
drifting jasper
#

i got 6 = -13

empty sail
#

You mathed wrong

restive inlet
#

where'd the x disappear off to

drifting jasper
#

Shoot

#

Can you walk me threw it?

empty sail
#

Distribute, combine like terms, get x on one side and everything else on the other

quartz shale
#

so ya x is 1?

drifting jasper
#

So, Does it have infinite solutions or 1 solution or none?

empty sail
#

It has a solution

drifting jasper
#

Its on paper, But i basically butchered it, i got 6=-13

empty sail
drifting jasper
#

Ill draw it on note rq, I only have discord on a desktop

#

omg, before i post this, i see the mistakes lol, I messed this up in the worst way possible

#

I messed that up really hard lol

restive inlet
#

also this is different from the equation you initially gave

drifting jasper
#

it is?

empty sail
#

This is a different problem than what you gave before, which is why I asked if you typed it properly

drifting jasper
#

That is a ss of it

restive inlet
#

that is nonsense

drifting jasper
#

ik, Im relearning this material, I got it all mixed up

empty sail
#

-3 (4-3x) =9 - 12 is what you had originally sent

drifting jasper
#

i forgot the X

quartz shale
#

infinite solutions?

restive inlet
#

anyway what were you trying to do with
-3(4-3x)

empty sail
drifting jasper
empty sail
#

Actually check their work and see what went wrong @quartz shale

restive inlet
#

multiply / distribute properly yes

#

alternatively dividing both sides of the equation by -3 would also be acceptable

drifting jasper
#

Let me redo this rq

#

Got 9x and -12 Which cancels the other 9x and -12

#

So it has infinite solutions

#

Ok

#

It is that

#

Yes

#

.close

topaz sinewBOT
#
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topaz sinewBOT
#
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green arch
topaz sinewBOT
leaden tusk
#

what do you think the answer is?

green arch
#

no solution

leaden tusk
#

right

green arch
#

i also had a few more

#

im either just dumb or its just because its the morning

#

no solution right?

leaden tusk
#

not quite

#

look at the example on the left side of your screen

green arch
#

oh

#

its infinte solution

#

lol

leaden tusk
#

yep, it's the same line

green arch
#

than this is one solution

leaden tusk
#

yes

green arch
#

perfect

#

thanks

#

.close

topaz sinewBOT
#
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leaden tusk
#

👍

topaz sinewBOT
#
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topaz sinewBOT
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@neon iron Has your question been resolved?

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stark solstice
#

Hi

topaz sinewBOT
stark solstice
#

I did a chi squared test

#

And got a value of 1

#

What does that mean

topaz sinewBOT
#

@stark solstice Has your question been resolved?

stark solstice
#

Hello?

topaz sinewBOT
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@stark solstice Has your question been resolved?

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covert oriole
#

I have answered this question already I just want to see if i did it correctly

if "cathetus 1" = 7 1.e, and the "hypotenuse" = 9 1.e. Then what does "cathetus 2" equal?

subtle mountain
#

what

#

is a

#

catetus

covert oriole
#

my bad

#

speling error

subtle mountain
#

what