help-26

[subtle mountain]

does

1.e mean

[covert oriole]

might be l.e

[subtle mountain]

what's I.e

[covert oriole]

ask the authors of my book man

[lusty ravine]

7x 10^1?

[subtle mountain]

:/

I think

it means

for example

idk

so

[covert oriole]

maybe 7*e?

[subtle mountain]

u know one side which is 7 units

and hypotenuse is 9

so u know 2 aides

sides

one unknown side

Pythagoras

ur done

QED

[covert oriole]

this is what its written like

[lusty ravine]

What’s the context? Just like a regular pythag thm?

[covert oriole]

let me just send the whole question translated for you

[lusty ravine]

Seems just like i.e

[covert oriole]

"In a right-angled triangle, the hypotenuse is 8 1.e. and a catheter 5 1.e. Determine the exact length of the other catheter."

I changed the values because I did one on my own to test if i knew it or not

[subtle mountain]

it's just

[lusty ravine]

This is just a regular like hs geometry class tho right?

[subtle mountain]

Pythagoras

[lusty ravine]

Yeah ^

[subtle mountain]

read the messages that I have sent

[lusty ravine]

Ignore the 1e

[covert oriole]

like 8*2,71?

ok

[subtle mountain]

formula is

x^2=a^2+b^2

with x the hypothenusa

and a and b the cathesuses

plug in the known values

and solve for the unknown

[covert oriole]

the thing that throws me off is that the answer _/39 1.e.

[subtle mountain]

what

[covert oriole]

yeah.

[subtle mountain]

_/ 39 1.e

what language is that

[covert oriole]

_/ (meaning square root)

[subtle mountain]

square root of 39?

[covert oriole]

square root of 39 1.e.

yeah

cant do the fancy symbols on desktop

[subtle mountain]

,w 8^2=5^2+x^2

[thorny flame]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by alepk#4230

[subtle mountain]

ignore the nonsense 1.e

its just sqrt39

[covert oriole]

ok

alrighty

ok thanks guys

,w 9^2=7^2+x^2

[thorny flame]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Lama#5171

[covert oriole]

well that did not make me any smarter

[subtle mountain]

?

[topaz sinew]

@covert oriole Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[topaz sinew]

@neon iron Has your question been resolved?

Channel closed

Closed by @green valley

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[covert oriole]

What does the " | | " mean

(question 11 a,)

[covert oriole]

ok danke

.close

[topaz sinew]

Channel closed

Closed by @covert oriole

Use .reopen if this was a mistake.

[covert oriole]

.reopen

[topaz sinew]

✅

[covert oriole]

How do I calculate it?

|b|

a=(2,3) and b=(3, -1)

[jovial rock]

square root 3^2+(-1)^2

[covert oriole]

syntax error

[leaden tusk]

that means it's a you error

[covert oriole]

https://tenor.com/view/sad-walk-of-shame-shame-shameful-head-down-gif-5548725

the answer is square root of 10

how

[topaz sinew]

@covert oriole Has your question been resolved?

[main mauve]

what is 3^2+(-1)^2

whatever that is square root it

wow that makes it sound like i actually don’t know the answer lol

[leaden tusk]

"what is 9+1" - you

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[trail stirrup]

<@&286206848099549185> hello, who can help me?

[trail stirrup]

lim (1/sqrt(arctg(x))-((1)/(e^sqrt(x)-1))) as x -> 0

[topaz sinew]

@trail stirrup Has your question been resolved?

[topaz sinew]

@trail stirrup Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[neon iron]

did i do it correctly?

[neon iron]

13/3 is the constanc C.... what I got anyway

i would check the answer myself but idk how to plug this into a calculato

.close

[topaz sinew]

Channel closed

Closed by @worldly coyote

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[modest hawk]

What are the rules on reshaping absolute values? e.g.

[modest hawk]

is it
|x| = 1/4 +5
|| can be left out for this case
|x+5| = 1/4
x = 1/4 -5???

[chrome glen]

Wdym

[modest hawk]

english name is absolute value

[chrome glen]

A useful rule ive found is

$\abs{a}=b \\ a=\pm b$

[thorny flame]

PapaBread

[chrome glen]

Cause the opposite of absolute value is plus minus

[modest hawk]

so if I want to solve for all possible values x.
I have to solve
+(term) and -(term)
for x and union the results?

[chrome glen]

Ye

Usually you can just keep the plus minus in there and evaluate at the end though

Rather than solving it twice

You might end up with like 23+-2 for example

Which would of course give you 21 and 25

[modest hawk]

I assume this also works for fractions?

[chrome glen]

Ye

[modest hawk]

ok thank you

.close

[topaz sinew]

Channel closed

Closed by @modest hawk

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hollow shore]

<@&286206848099549185>

[hollow shore]

Can any helper just dm me

[radiant marlin]

.close

[topaz sinew]

Channel closed

Closed by @radiant marlin

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[topaz sinew]

@neon iron Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[topaz sinew]

@tidal ether Has your question been resolved?

[topaz sinew]

@tidal ether Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hazy tusk]

if i have two vectors in component form as shown in the diagram and i have their magnitudes and their direction angles, how do i find the distance between them ?

[hazy tusk]

excuse the poor diagram i drew it up in paint

wait nvm i just figured it out

.close

[topaz sinew]

Channel closed

Closed by @hazy tusk

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[nocturne forge]

Prove algebraically that the sum of n(n + 1) and n + 1 is always a square number.

[radiant marlin]

add n many (n+1)'s with one (n+1)

[nocturne forge]

wdym?

[radiant marlin]

there's this distributive law that says ab+cb = (a+c)b

because that's how many b's total there are

same thing here with n(n+1) and 1(n+1)

[nocturne forge]

so how do i prove that? just write the law in?

[radiant marlin]

sure

"n(n+1) + 1*(n+1) = (n+1)(n+1) by the distributive law"

[nocturne forge]

ok thanks

.close

[topaz sinew]

Channel closed

Closed by @nocturne forge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[versed forge]

If a toy rocket is launched vertically upward from ground level with an initial velocity of 128 feet per second, then its height h after t seconds is given by the equation h(t) = -16^t2 + 128t. How long will it take the rocket to return to the ground?

I do not understand this question at all :/

All I know is that t is time and h is height. Also I think I need to expand the 16t^2.

[versed forge]

when anyone gets a chance please ping me @versed forge

[restive inlet]

what is the height at ground level?

@versed forge

[versed forge]

0 right?

[restive inlet]

yes

[versed forge]

what should I find next?

[restive inlet]

t when h=0

[versed forge]

ok

its also 0, because the rocket did not move

[restive inlet]

there are two solutions to the equation

t=0 is the trivial solution

but you're interested in when the rocket returns to the ground

[versed forge]

yes

So, do I have to simplify -16t2 + 128t? (if possible) please tell me if I'm wrong

[restive inlet]

no

equations don't become expressions

you have an equation giving the relation between height and time

and your interested in the time(s) when h(t) = 0

sub h(t) = 0
and then solve the equation

[versed forge]

ohhh so 0=-16t2 + 128t?

and solve?

[restive inlet]

use ^ to denote exponentiation

ohhh so 0=-16t^2 + 128t?

[versed forge]

yes

sorry

wait...

I dont get it

if I have to do 0=-16^2+128t, then would t be 0?

[restive inlet]

there are two solutions

solve that like you would other quadratics

to get all solutions

[versed forge]

I could also solve for t right?

[restive inlet]

that's what you want..

[versed forge]

oh

so that would be 8 right?

or-

no?

[restive inlet]

yes 8 would be correct

[versed forge]

yay

thank you

I have a few more if you dont mind?

you dont have to though

[restive inlet]

just ask, if not me someone else will

[versed forge]

nevermind, I had to go

its very late

.close

[topaz sinew]

Channel closed

Closed by @versed forge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[flat rivet]

i genuinely have no idea how to solve this, in the answer key the answer is 2600

[restive inlet]

perhaps rearranging the terms may help
$$(x^2 -2xy +y^2) +(2x-2y)$$

[thorny flame]

ℝamonov

[flat rivet]

i still cant think of a way to get the answer from this

[neon iron]

in the 2nd equation

pick one variable

and solve for it

[modern imp]

you can also simplify the first equation down too

[neon iron]

either x or y

so

y=x-50

or

x=50+y

[modern imp]

you can factor the 1st equation down

[flat rivet]

then i substitute all Ys with (x-50)?

[twilit rapids]

i would go with what ramanov said

(2x - 2y) can be factored to 2(x - y)

and (x^2 -2xy + y^2) can be factor using the fact that a^2 - 2ab + b^2 = (a - b)^2

[flat rivet]

ooh

now i get it

thank you guys

.close

[topaz sinew]

Channel closed

Closed by @flat rivet

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[neon iron]

16a and b pls

[topaz sinew]

@neon iron Has your question been resolved?

[neon iron]

what you are searching for is the intersection of the curve C and the line
so the intersection point P lies on both the line and the curve

so you can write y as a coordinate of C, but also of the line

that means that for y:
y = x^2-2x+6 = px+p
because p is the intersection point

and since the line is tangent to the curve, you also need to check that

do you know how?

YHHH

Discriminant?

@neon iron

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[topaz sinew]

@celest pewter Has your question been resolved?

[topaz sinew]

@celest pewter Has your question been resolved?

[topaz sinew]

@celest pewter Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[near solar]

how do i find x for

-3(2x-1)^3=-192

[restive inlet]

what have you tried so far?

[near solar]

photomath

divide by -3

then i could do the square root thingy by 3 but i dont thinj my teacher wants me to use our calculators like that😭

[restive inlet]

$\cbrt{,,}$ is called the cube root

[thorny flame]

ℝamonov

[near solar]

YEAH THAT THUNG

I DONT THINK IM SUPOOSED TO USE IT ON THIS ASSIGNMENT THO😭

[restive inlet]

you don't really need a calculator

[near solar]

SHOULD I JUST ANYWYAS

[restive inlet]

the numbers are simple enough to calculate without a calculator

[near solar]

oh

[restive inlet]

but why do you think you shouldn't be using the cube root here

[near solar]

bc thats what my math tutor in my math class said

ok ok lets just use it anywyas

i forgot how to cube root can u help me

[restive inlet]

it depends on the context.
if you just want the real solutions applying the cube root is fine

[late sigil]

expand it

oh wait

[near solar]

omg i tried that but then it just became a mess and i gave ip

[late sigil]

that's not the way

because x^3 term

lol

i much stupid

[restive inlet]

if you're interested in complex solutions, something that is probably advanced for you, you'd factorise using a difference of two cubes

i forgot how to cube root can u help me
don't overthink this

[near solar]

i think im judt solving for x and checking for extraneous solutions

[late sigil]

just use a cube root

[near solar]

so x=4?

[restive inlet]

do you know the basic definition of a cube root

the cube root of 64 is 4 however your equation isn't quite
x^3 = 64

your equation is
(2x-1)^3 = 64

[near solar]

ok ok

yes

OHH

[restive inlet]

applying the cube root to both sides gets you
2x-1 = 4

[near solar]

2x-1

yes

ok ok

x=2.5? does that sound right

RAMNOVVVV

WYA BROSKI

[restive inlet]

yes

[near solar]

OMG

THANK YOU

I JUST tranSFERRED SCHOOLS AND THERE @ A DIFF PART IN MATH THAN ME SO ITS A STRUGLG

TYSM

.close

[topaz sinew]

Channel closed

Closed by @near solar

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mild spindle]

hey hey, can someone explain to me how this summation works

[mild spindle]

Like i may be really dumb because i havent slept much but i just cant seem to understand

[wooden matrix]

telescoping series

[prisma badger]

The outside limit is supposed to be n approaching infinity and not x

[mild spindle]

oh

[mild spindle]

yeah i know

[mild spindle]

i see it now lmao sorry

thank you

.close

[topaz sinew]

Channel closed

Closed by @mild spindle

Use .reopen if this was a mistake.

[prisma badger]

Variable inside summation shouldn't have been n

[mild spindle]

no no its okay the question was taken with n as a variable

just that step is a mistake where they wrote x

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vast radish]

how do i get help?

[vivid spire]

Hi! Please type in or send your question here

[vast radish]

ok

in geometry honors

i have a test

on monday

and i am having trouble classifying types of shapes

and what is the equation to find slope

on graphs

am i supposed to post a problem?

i have a homework problem that is, "prove that if no two medians of a triangle are congruent, then the triangle is scalene.

i can not figure it out.

[topaz sinew]

@vast radish Has your question been resolved?

Channel closed

Closed by @vast radish

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[devout vale]

can anyone explain where did the negative sign came from in the inequation after "then"?

[topaz sinew]

@devout vale Has your question been resolved?

[devout vale]

<@&286206848099549185> can I get some help over here?

[topaz sinew]

@devout vale Has your question been resolved?

[last quarry]

where?

that is given because we can prove I-A is invertible if |A|<1

[devout vale]

talking about this

@last quarry

[last quarry]

• honestly doesn't matter there

all you need is that |B'H| < 1

so I+B'H will be invertible

or I-B'H will be invertible, you choose the one that suites you needs

[devout vale]

yep, it was given just above this corollary xD

[devout vale]

ah, I see

[last quarry]

the - sign is given to fit the corollary

[devout vale]

if we just put a negative sign in the first inequality, wouldn't it make more sense?

[last quarry]

whatever

makes no difference

[devout vale]

for me, it makes sense, so I am just gonna assume that it was meant to be there

thanks for your time, though!

.close

[topaz sinew]

Channel closed

Closed by @devout vale

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lavish mica]

Hi}

[lavish mica]

Anyone that can help me with numerical methods?

[wooden matrix]

Don't ask to ask

[lavish mica]

well the thing is, i've already asked some numerical methods related questions and no one answered, so maybe there's no one who works in that area or that uses that stuff

def RungeKutta(f,x0,a,b,n):
import numpy as np
h=(b-a)/n
print(h)
x=np.zeros(n+1,dtype=float)
t=np.zeros(n+1,dtype=float)
x[0]=x0
t[0]=a
for i in range (n):
F = np.zeros(4, dtype=float)
F[0]=hf(t[i],x[i])
F[1]=hf(t[i]+h/2,x[i]+F[0]/2)
F[2]=hf(t[i]+h/2,x[i]+F[1]/2)
F[3]=hf(t[i]+h,x[i]+F[2])
x[i+1]=x[i]+(F[0]+2F[1]+2F[2]+F[3])/6
t[i+1]=t[i]+h
return x

def f(x,t):
import numpy as np
f=x*(np.cos(t))
return f
x0=1
a=0
b=0.2
n=2
SOL=RungeKutta(f,x0,a,b,2)
print(SOL)

why I'm not getting the right answer? to the diff equation

this is Python btw

I'm trying to calculate x(0.2) and the program yields 1.01071542 as the result which I know is wrong

the answer is close to 1.219779

[topaz sinew]

@lavish mica Has your question been resolved?

[lavish mica]

ok thanks for the help ._.

solved it myself

[lavish mica]

yes

.close

[topaz sinew]

Channel closed

Closed by @lavish mica

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vocal mulch]

A 14 cm wire is cut into two pieces. We form a square by folding each of the
pieces in four. The sum of the areas of the two squares is 7.25 cm2

What is the length of the thread of each piece?

[vocal mulch]

I tried doing this

But cant solve it

a friend of mine showed me this

so i dont rlly know what he tried to do

[short kettle]

All right. First what is the lenght of the two wires? One is x and the other is 14-x, right?

[vocal mulch]

yes

[short kettle]

Now the sides of the first one are x/4 and of the other one (14-x)/4

[vocal mulch]

yea

[short kettle]

So we have the equation (x/4)^2+((14-x)/4)^2=7.25

[vocal mulch]

we get rid of the 4s?

by multiplying each side?

[short kettle]

You know that (a/b)^2=a^2/b^2

[vocal mulch]

yea

[short kettle]

Ok then multiply both sides with 16

[vocal mulch]

I got this

[short kettle]

then simplify (14-x)^2

with the binomial formula

[vocal mulch]

Then i bring 116 to the left side?

[short kettle]

Yes

and then quadratic formula

[vocal mulch]

.close

[topaz sinew]

Channel closed

Closed by @vocal mulch

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[modern fractal]

does anyone know where the +1 in the unsimplified equation went when they simplified

[short kettle]

C is a constant so a constant + 1 is still a constant.

not the same constant obviosuly but you get the point

[modern fractal]

OH ok

ty

.close

[topaz sinew]

Channel closed

Closed by @modern fractal

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[real sierra]

,rotate

[real sierra]

can someone help me

[void horizon]

@real sierra use the identity $\sin^2\alpha = 1-\cos^2\alpha$

[thorny flame]

gramschmidtty

[topaz sinew]

@real sierra Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[onyx grove]

I proved -> but am having trouble with proving <-

How would I start this?

[topaz sinew]

@onyx grove Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[neon iron]

question
How many 4-digit positive integers have four different digits, where the leading digit is not zero, the integer is a multiple of 5, and 5 is the largest digit?

[neon iron]

my solution:
We have 4 options for the first digit (4, 3, 2, 1), since 0 and 5 must be the last for it to be a multiple of 5. 3 options for the second digit, 2 options for the third digit, and 2 for the last (0 and 5). 432*2=48. 48 different 4 digit positive integers.

is it correct

did i overcount

[next helm]

We have 4 options for the first digit (4, 3, 2, 1),
this step is a mistake because 5 can be the first digit if 0 is the final digit

i think you should break this problem into cases, case 1 is last digit 0 and case 2 is last digit 5

do you get what im saying @neon iron ?

[neon iron]

oh

[neon iron]

ok

[next helm]

ping me if u need any help

[topaz sinew]

@neon iron Has your question been resolved?

[neon iron]

What I am confused on is that 5 is the largest digit,

So when the last digit is 0, how do I incorporate 5 into the amount of combinations

[next helm]

so when the last digit is 0

there are 5 options for the first number

(1,2,3,4,5)

then 4 for the second, then 3 for the third

third*

and only 1 for the fourth since we already decided that it si 0

is*

[neon iron]

It 5 can be in the second and third digits also

Right?

I mean

When we get to the third digit

And the previous 2 don’t have 5

The the third digit has to have 5

How do I do that then

[next helm]

no because each digit needs to be different

thats what the question says

[neon iron]

ok, but 5 has to be in the number

[next helm]

no?

where does it say that

it just says that no digit above 5 can be in the number

dosent say 5 HAS to be in it

for example 4320 is a valid number

[neon iron]

oh

ok

i see

how is this

        Let’s break this into 2 cases. The first where 5 is the last digit, and the second where 0 is the last digit. If 5 is the last digit, then we have 4 options for the first digit, (4, 3, 2, 1), 4 for the next, and 3 for the last. This gives us 4*4*3 or 48 different options. 
        When 0 is the last digit, we have 5 options for the first digit, 4 for the second, and 3 for the last, giving 60 different options. In total, there are 60+48=108 different options.

@next helm

[next helm]

its wrong

if 5 is the last digit there are 5 options for the first digit

4,3,2,1,0

u forgot abt 0

[neon iron]

0 cant be the first digits

where the leading digit is not zero

[next helm]

oh ur right

[neon iron]

i really hope that it is corect

[next helm]

yup ur right

my bad

i think your solution is correct :)

[neon iron]

Ok

I think that I can trust you

you had to earn those, right?

[next helm]

no, you select those for yourself

i got them to get access to advanced channels

[empty sail]

No, in #get-advanced-access if you know that topic well enough, you can add those roles by clicking the buttons

[subtle mountain]

it's about drive, it's about power

we stay hungry we devour

[neon iron]

ah

well, can at least someone else confirm

[restive inlet]

whoops

[neon iron]

its correct

[restive inlet]

misread the question

[neon iron]

ah

do you think that it is right?

[restive inlet]

seems ok

[topaz sinew]

@neon iron Has your question been resolved?

Channel closed

Closed by @crisp star

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[desert coral]

.open

.close

/open

[fleet willow]

.help

[topaz sinew]

Commands:
clopen: .close, .reopen
factoids: .tag
help: .help

Type .help <command name> for more info on a command.

[fleet willow]

help

[quick dragon]

I feel like I just saw this in another channel

[fleet willow]

can u help?

[quick dragon]

dont really know power series sorry

[fading ermine]

What is part a?

[fleet willow]

<@&286206848099549185>

<@&286206848099549185> anyone?

[topaz sinew]

@fleet willow Has your question been resolved?

[topaz sinew]

@fleet willow Has your question been resolved?

[fleet willow]

<@&286206848099549185>

[inner oracle]

What's the problem

[fleet willow]

i dont get this problem ata ll

at all

like r we doing continous derivatives

[inner oracle]

Isn't that what you did for part a

[fleet willow]

ya i did it once

but now its like derivative ception

[inner oracle]

Ception?

[fleet willow]

like im lost

its says use a

but how

[inner oracle]

You asked this already in other channel?

[fleet willow]

yes but the helper had to go\o

go*

[inner oracle]

What did they say tho?

[fleet willow]

idk they said do the same thing for a

but like idk how i would apply it

[inner oracle]

There will be difference in n only

[fleet willow]

can u explain plz

im very bad at this stuff

[fleet willow]

sigh

.close

[topaz sinew]

Channel closed

Closed by @fleet willow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[naive glacier]

https://i.imgur.com/BR6zvRq.png

[naive glacier]

How do I use the sample size into this problem?

I got my answer for lower and upper bounds by doing =NORMINV(0.025;-4.5;5.9) into a spreadsheet

-4.5 is the mean, 5.9 is the std

[still void]

iirc the sample mean X bar ~ Norm(mu, sigma^2/n)

where X ~ Norm(mu, sigma^2)

and n is the sample size

[topaz sinew]

@naive glacier Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[zinc mist]

anyone know what should i do? I used dot product but no vector parallel the (2,1,2)

[zinc mist]

Heres my work

[still void]

you should start with p first, since the condition for being parallel is easier

[zinc mist]

im a bit confused, so i multiply the scaling factor to (2,1,2) ?

[still void]

yea

p = k (2,1,2)

where k is some scalar

[zinc mist]

then i input to p+q = (4,3,1) ?

[still void]

not yet

do you know what p.q is

[zinc mist]

dot product ?

[still void]

yea

but like

from the information given

can you deduce the value

of p.q

hint : ||you can try putting in the expression for p we found earlier into p.q||

[zinc mist]

soo we input the p to p.q and make it equal to 0 right??

[still void]

no

just try to find

what p.q is

like what is k(2,1,2).q

[still void]

you can use what you did here

any progress?

[zinc mist]

Im stuck here, what should i do? Im feeling very dumb rn😞

[still void]

ok think of it this way instead

you know p is parallel to (2,1,2)

and q is perpendicular to (2,1,2)

then what is the angle between them

[zinc mist]

between p and q ?

[still void]

yea

[zinc mist]

This wont work i think

[still void]

instead of putting it as an equation

[still void]

try to think what these conditions mean

like q is perpendicular to the same vector that p is parallel to

answer: ||p is perpendicular to q, meaning p.q=0||

you can also show it using an equation

||p.q = k (2,1,2).q = 0 since (2,1,2).q = 0||

do you understand?

[zinc mist]

lemme process it

[topaz sinew]

@zinc mist Has your question been resolved?

[zinc mist]

so if p.q=0 , how do we know the vector p and q ? im confused again 😦

[still void]

ok now that we have that

we can do p.(p+q) = p.(4,3,1)

use the fact that p.q=0 and p=k(2,1,2) to find k and hence p

then q = (4,3,1) - p

[zinc mist]

am i supposed to use distributive properties here?

[still void]

yea

[still void]

stuck?

[zinc mist]

yeah 😦

[still void]

alright

so we have

p.(p+q)

which is p.p + p.q = p.p

since we know p.q = 0

p.p = k(2,1,2).k(2,1,2) = 9k^2

and on the RHS we have

p.(4,3,1)

which is k(2,1,2).(4,3,1) = 13k

giving us 9k^2=13k

i assume you can solve from here

[zinc mist]

Is this necessarily correct?

[still void]

well you can check

is p parallel to (2,1,2)

is q perpendicular to (2,1,2)

and is p+q=4

btw your attempt at the start could also be made into a solution but this way looks cleaner imo

[zinc mist]

ok i get it now, thank you so much for helping me 🙂

[still void]

welcome

[topaz sinew]

@zinc mist Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vivid spire]

Hi

[gleaming dock]

hi

do you know what i should do for that

[vivid spire]

Do you have to find theta, which lies in the range 0 - 360 deg?

[gleaming dock]

yes

[vivid spire]

Okay fine

Can you tell me the general value of cos x

[thorny flame]

Muhammad Hussaini

Muhammad Hussaini

[gleaming dock]

im not sure how i should work it out

[thorny flame]

Muhammad Hussaini

[gleaming dock]

is it pi/6 ?

[vivid spire]

Yes...

[gleaming dock]

30 degrees?

[vivid spire]

It is not only pi/6

The thing is cos is repetitive

That means

this sqrt3/2 will come again

[gleaming dock]

i see

but how will we get to the answer in degrees?

[vivid spire]

Well, what is your level Nico

[gleaming dock]

i am very dumb

i understand that you first need to find the quadrants in which cos(theta) = sqrt(3)/2 is positive

which are quadrants 1 and 4

[vivid spire]

That is one part

I mean to say, you have to find the angles na

Lets go the general way

[gleaming dock]

yea?

[thorny flame]

Muhammad Hussaini

[vivid spire]

• or - depends on quadrants

[gleaming dock]

yes

[vivid spire]

So I said

$cos(30^{\circ}) = \pm cos(30+180)$

[thorny flame]

Muhammad Hussaini

[vivid spire]

So
$cos(210) = -\frac{\sqrt{3}}{2} [III^{rd} quadrant]$

[thorny flame]

Muhammad Hussaini

[prisma badger]

cos(x) is always equal to -cos(180°+x) regardless of the quadrant

[vivid spire]

Hm, just giving em an idea

Because I got to know

He knows the quadrant stuff

But not the general solution stuff

The next value of cos would be positive again, but it will be on 210+180 degrees. that would be greater than 360 degrees

So the simple answer would come to be 30 degrees

[gleaming dock]

yes

but isn't there 2 answers?

[vivid spire]

Which is the second one

[gleaming dock]

so 210 and 30 degrees?

[vivid spire]

On 210 degrees... Cos is negative... But we got to find the positive one

[gleaming dock]

i see

[thorny flame]

Muhammad Hussaini

[gleaming dock]

yes, i can see

[thorny flame]

Euclid31415

[gleaming dock]

im sorry but i still dont understand lol

my friend told me the answers were 330 degrees and 30 degrees

but i do not understand what method he used to get to those answers

[vivid spire]

330?

[prisma badger]

Yes. 30° and 360°-330°=30°

[gleaming dock]

he told me that first, i should find which quadrants cos(theta) = root(3)/2

[vivid spire]

Well why didnt our general form provide an answer.

[gleaming dock]

and then he told me that i should find the reference rotation

[vivid spire]

Well @prisma badger

330

Is or is not?

[prisma badger]

cos(330°)=√3/2

[vivid spire]

Yeah it is.

Thats why

I need to show him this general form

[prisma badger]

$\cos(x)=\cos(a)\implies x=2n\pi\pm a$

[thorny flame]

Euclid31415

[vivid spire]

Hmm

[prisma badger]

Where n is an integer

[thorny flame]

Muhammad Hussaini

[prisma badger]

Yes

[vivid spire]

Thats why Id asked before whether he knew of general forms

[gleaming dock]

so can someone explain to me what the domain is

[prisma badger]

This also works. Notice we get √3/2 in 1st and 4th quadrant

[gleaming dock]

yes

i think for my working out

[vivid spire]

Domain, as in functions?

[gleaming dock]

with the unit circle, how many times you go around it

i honestly dont know mathematical terms lol

[vivid spire]

... @prisma badger

[prisma badger]

The question gives that theta lies on [0,2π]

Which goes around the circle once

[gleaming dock]

yes

[vivid spire]

Oh, well havent seen this kind of a question

[gleaming dock]

i worked it out such that 0+30 and 360-30 were the answers

thats how my brain did it or smth

since cos(theta) = root(3)/2 would be positive in 1st and 4th quadrants

but im dum

[prisma badger]

Yep. That's correct

[gleaming dock]

wow is that it

[prisma badger]

Yes

[gleaming dock]

breh

ok thanks

can i close this channel now

[prisma badger]

Yes if you want

[gleaming dock]

ok thanks

.close

[topaz sinew]

Channel closed

Closed by @gleaming dock

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jaunty pilot]

Hey, could somebody give an idea of how to calculate integral of sqrt(1 + x2) * x? I forgot many things 😦 . I tried integration by parts, but it only complicates it

[vivid spire]

Hi

[thorny flame]

Muhammad Hussaini

[jaunty pilot]

No, x^2 there

[vivid spire]

Oh

[jaunty pilot]

$$x\sqrt{1 + x^2}$$

[thorny flame]

Oryp4ik

[jaunty pilot]

mb I can try hyperbolic sine?

[drifting swift]

no lol just substitute u := 1+x^2

and you get $\int \frac{1}{2} \sqrt{u} \dd{u}$

[thorny flame]

Kanga Gang Annihilator Ann

[jaunty pilot]

Oh Ann, you 🤩

Thanks, will try

yeah it worked, thanks XD

.close

[topaz sinew]

Channel closed

Closed by @jaunty pilot

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[supple flicker]

can someone help me

[supple flicker]

so how do i calculate the m and z

all i can figure out is that n = m and y = z

[thorn wagon]

n=m=90

[supple flicker]

but how can you be sure of that

actualyl

wait im stupid

ok i see how that can be

cause supplementary angles

[thorn wagon]

Yeah since the line separating the base into 2 equal halves

Yes

[supple flicker]

ight thanks

the rest will be easy

.close

[topaz sinew]

Channel closed

Closed by @supple flicker

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[little bolt]

How can I find the pdf from a moment generating function?
eg. [λ/(λ - t)]^7
for this?
I think it'll be a gamma distribution since it's a sum of 7 exp. distributions.

[topaz sinew]

@little bolt Has your question been resolved?

[little bolt]

<@&286206848099549185>

[last quarry]

something live inverse fft or laplace idk

try #probability-statistics

[little bolt]

hmm, ok

i'll ask it there

[topaz sinew]

@little bolt Has your question been resolved?

[little bolt]

.close

[topaz sinew]

Channel closed

Closed by @little bolt

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[untold solstice]

I have cos(5pi/6). I could plug that into a calculator and get the answer but how would I keep that as a fraction?

[wooden matrix]

wdym

cos(5pi/6) is an exact value.

[untold solstice]

like

I guess a better way to phrase it would be how do I find the exact value of a trigonometric ratio

[wooden matrix]

unit circle

[untold solstice]

oh yeah

lol it's been a while since I've done this

.close

[topaz sinew]

Channel closed

Closed by @untold solstice

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[haughty trout]

hello

[haughty trout]

rotate your purple figure 90°clockwise, and plot your new figure.

is the green figure that I translated correct?

[gusty dome]

it seems right to me (if it wants you to rotate for 0,0

[haughty trout]

yeah it wants me to rotate 0,0

clockwise

.close

[topaz sinew]

Channel closed

Closed by @haughty trout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[neon iron]

Is there a general formula that shows how much times the number 2 should be added to itself for n-power? for example 2^3 = 222 = 2+2+2+2. How can I say how many times should I add 2 to itself for n-power?

[next helm]

$2^{n-1}$ times

[thorny flame]

Kanga Gang Mafia Toad

[next helm]

you just want to find the x where $2x=2^n$

[thorny flame]

Kanga Gang Mafia Toad

[next helm]

divide both sides by 2 to solve for x

[neon iron]

.close

[topaz sinew]

Channel closed

Closed by @hollow latch

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[river steppe]

hello how do i solve this?

[wooden matrix]

what have you tried?

[river steppe]

i moved ax^2 to the right hand side which bcame -c +d =ax^2-bx^2

[wooden matrix]

yep

actually you have a - missing

$ax^2-c=bx^2-d\implies ax^2-bx^2=-d+c$

[thorny flame]

Mosh

[river steppe]

oh i see

then i dvided a and b which gave me -d+c/ a-b= x^2+x^2?

[wooden matrix]

no

[river steppe]

oh

[wooden matrix]

$(a-b)x^2=c-d$

[thorny flame]

Mosh

[river steppe]

may i ask you how u got this?

[wooden matrix]

factored.

[river steppe]

ah i see

so answer is x= squre root c-d/ a-b

[wooden matrix]

no

missing the +-

[river steppe]

oh i see thank you so much

[topaz sinew]

@river steppe Has your question been resolved?

Channel closed

Closed by @river steppe

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hazy cave]

Hi could someone help me with this question?

[hazy cave]

I need to determine the equivalences classes for this relation

How I found out is by listing all of them-
[1] = {1,2}
[2] = {2}
[3] = {3}
[4] = {4}

so are my equivalence classes - {1,2} {2} {3} {4} ?

[topaz sinew]

@hazy cave Has your question been resolved?

[hazy cave]

<@&286206848099549185>

[lunar flicker]

what grade r u in

@hazy cave

[hazy cave]

I'm in college

[lunar flicker]

ya im 0 help

<@&286206848099549185> HELP DIS MAN

[austere badge]

I'm no expert, but Isn't [2] = {1,2}?

(do let me know, I really am not an expert, lol)

[hazy cave]

yeah even the answers didn't list 2

so as it gets included in that set we don't count that separately?

[austere badge]

I'm tired, not sure what that (the above message) means. Since [1]=[2], then perhaps the equivalent classes are [1], [3], and [4]. Is that what you meant?

(aka: {1,2}, {3}, {4})

[hazy cave]

ohhh ohh

right yes

i get what u mean now

thanks!

[austere badge]

np gl

[hazy cave]

.close

[topaz sinew]

Channel closed

Closed by @hazy cave

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lunar flicker]

is ur major math???

[hazy cave]

no computer science

[topaz sinew]

@lunar flicker Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[old flame]

Hi, I'm having issues coming up with a function that meets all the requirements. Some help would be greatly appreciated!

[cinder forge]

Hi, did you try some examples ?

[old flame]

Hi, yes but they all end up not being bounded

[cinder forge]

Yup, the idea is that there exist functions that grow "infinitely fast" at some point.
The image that you can have is the "tangent line" point of view. You're looking for a function whose tangent on some point is vertical

(Recall that the derivative is defined as the slope of this tangent line)

[old flame]

I understand, but i still find it hard to come up with a function like that..

[cinder forge]

Did you find any example, let's say on [0,1], instead of R ?

[old flame]

sqrt(x)?

[cinder forge]

Yep

I'm pretty sure that you can transform that on a Lipschitz function on R

[old flame]

I unfortunately don't know what that means..

[cinder forge]

Hm wait the example I had in mind does not work

Oh it does

I think

How about $x \mapsto \arctan(\sqrt{|x|}))$

The idea is to "bound" the square root with a function that resembles x at 0 (the point which causes the non-Lipschitz-ness (?) )

[thorny flame]

Twentycents

[old flame]

Okay thank you so much! I'll think more about the function you gave me and come back if I ahve more questions!

.close

[topaz sinew]

Channel closed

Closed by @old flame

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[thorny flame]

azeem321

[marsh mortar]

This seems to expand out to right answer, but apparently it's incorrect

[topaz sinew]

Channel closed

Closed due to the original message being deleted

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[viral turret]

Suppose that y varies inversely as x, and x is tripled. What is the effect on y? Explain or prove your answer
using a solution.

Is this a good proof for "we would get 1/3 of y?"

[thin kindle]

not quite sure what ur meaning

[wooden matrix]

no, cause you lost x

$y=\frac{2}{x}$

[thorny flame]

Mosh

[viral turret]

Oh... Do you know how can I prove this?

[wooden matrix]

$y_1=\frac{2}{x_1} \ x_2:=3x_1$

[thorny flame]

Mosh

[wooden matrix]

then you show that y_2=(1/3)y_1

[viral turret]

ohhhhhh

gotcha

got it know thank you

.close

[topaz sinew]

Channel closed

Closed by @viral turret

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[narrow torrent]

What is the cardinality of R

[keen venture]

Haha that question can be boring or very interesting depending on the answer you're looking for

The cardinality of R is uncountable.

Which means "there exists no bijection between R and N, the positive integers".

[narrow torrent]

Can we compare the size of R to other sets

Is R smaller than C

[keen venture]

You can compare R to other sets.
R and C have the same cardinality

[narrow torrent]

Wait what how

[keen venture]

Basically C is just two copies of R put together

And, as you'll find with some experience, sticking copies together doesn't change cardinality

It's worth mentioning that cardinality and "size" aren't the same thing, and that there's no great notion of "size" on infinite sets

[narrow torrent]

How are R and C equal tho

[topaz sinew]

@narrow torrent Has your question been resolved?

[compact nebula]

having the same cardinality just means there is a possible bijection between 2 sets

[narrow torrent]

Yeah exactly but how

[compact nebula]

cardinality is defined like that I am not sure what you are asking? are you asking why is cardinality defined that way or are you asking about the actual bijection from R to C?

[narrow torrent]

Yeah how is there a bijection

From R to R2

[compact nebula]

idk about an actual bijection but you prove it using schroeder-bernstein where you show injection from R to R^2 (trivial) and another from R^2 to R

[narrow torrent]

Yeah but how

[compact nebula]

ok instead of giving you latex gore I will just send this MSE post which has a proof 🙂

https://math.stackexchange.com/questions/197735/injective-function-from-mathbbr2-to-mathbbr

[narrow torrent]

Wow that's cringe

Infinite decimals

[compact nebula]

it can also be finite decimals just x_n=0 for n>m

[narrow torrent]

Oh that makes sense

It's just a vector

R^2 is a vector space!!!

[topaz sinew]

@narrow torrent Has your question been resolved?

Channel closed

Closed by @narrow torrent

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[thorny flame]

KurtDee

KurtDee

[topaz sinew]

@proven anvil Has your question been resolved?

[topaz sinew]

@proven anvil Has your question been resolved?

Channel closed

Closed by @proven anvil

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[coarse arrow]

It's a differential equation. The question is to draw it with the available information, we're told what kind of differential equation it is, logistic differential equation and we're told a point P(1,4) so have i answered the question correctly?

[topaz sinew]

@coarse arrow Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dense pecan]

What is the irrational number between 3 and 4? I’ve tried looking everywhere but I haven’t found an answer

[wooden matrix]

an irrational number is the square root of a non-square natural number

[topaz sinew]

@dense pecan Has your question been resolved?

Channel closed

Closed by @dense pecan

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vivid musk]

hey guys, what divergence test is best for this?

[topaz sinew]

@vivid musk Has your question been resolved?

[vivid musk]

,close

.close

[topaz sinew]

Channel closed

Closed by @vivid musk

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stoic lynx]

Hi, I don’t know how to solve this? Find an equation of the ellipse with the x-axis and the y-axis as the axis of symmetry and passing through the points P(2,4) and Q(6,2).

[topaz sinew]

@stoic lynx Has your question been resolved?

[topaz sinew]

@stoic lynx Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ivory field]

Differential Equations - how do I rewrite this matrix in these terms here in problem 2?

[ivory field]

like this?

[topaz sinew]

@ivory field Has your question been resolved?

[ivory field]

.close

[topaz sinew]

Channel closed

Closed by @ivory field

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lost plover]

Could someone help me with this problem?

[topaz sinew]

@lost plover Has your question been resolved?

[lost plover]

<@&286206848099549185>

[topaz sinew]

@lost plover Has your question been resolved?

[subtle mountain]

Might this have to do with Fourier Series?