help-13

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[simple pine]

why is that segment m1 and -m2? since the differences of x from the two points is one then the slope is just the difference of y?

[spring prism]

yes

[simple pine]

lol

thanks

.close

[cedar kiln]

Channel closed

Closed by @simple pine

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed due to the original message being deleted

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[floral nexus]

we can prove that sqrt(2) is not rational through a proof by contradiction. I have attached a popular proof for this below.

[floral nexus]

what stops someone from proving that the sqrt(4) is irrational through this proof as well?

[tropic oxide]

have you tried reproducing the same proof for sqrt(4) and carefully examining whether or not the steps are still true?

[floral nexus]

I have

It seems to work exactly the same as proving that sqrt(5) is irrational though

[tropic oxide]

can you show your sqrt(4) proof?

[floral nexus]

yup i gotchu

sorry it took so long, i just rewrote it a bit neater

@tropic oxide here it is

same machinery as the other proof

[tropic oxide]

do you stand by this claim?

[floral nexus]

ahhh i see

i get it i get it that makes sense

[floral nexus]

i actually proved this statement for where its mod 2 and where its mod 5, and i assumed it worked for any integer

[tropic oxide]

it does not

[floral nexus]

im guessing then it only works for primes?

[tropic oxide]

wouldnt be so hasty as to say it ONLY works for primes

it works for all squarefree integers, to the best of my recollection?

[sage forge]

That remembers me on the video engineers in maths classes be like

[floral nexus]

unironically im a CS major so im going into software engineering

[tropic oxide]

link?

[sage forge]

https://youtu.be/F_OkdTTcO6o

[floral nexus]

@tropic oxide do you know what the proof for this is by any chance? so far I only know that to prove this for some integer n, where its p^2 congruent to 0 mod (n), is through casework

[tropic oxide]

the proof for what

[floral nexus]

my bad let me rephrase

[floral nexus]

for this image, you mentioned as per what you remember, it is true for squarefree integers

i want to see that proof, but don't know what to search up for it

do you have any idea what keywords i can use or the name of that proof

[tropic oxide]

chinese remainder theorem comes to mind

it's a bit of a nuke but it should work

or you could nuke it with FTA instead

factorization bullshit

[floral nexus]

ok that makes sense

one last thing

[tropic oxide]

yes?

[floral nexus]

so i learned this proof, but was wondering if there is a way to do this without casework

[tropic oxide]

"nuke it with FTA" is the first thing that comes to mind

[floral nexus]

should i still look in the direction of the chinese remainder theorem or FTA, or is there an easier way

ahh ok gotcha

[tropic oxide]

i mean lik

like*

you could try to pull some more abstract algebra-flavored nonsense

||like proving that Z/pZ is a field for p prime and thus has no nilpotents||

[floral nexus]

im not even gonna ask what that means

but thank you i shall look at FTA

thank you sm this really helped

i shall close the channel ig

.close

[cedar kiln]

Channel closed

Closed by @floral nexus

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[teal lake]

My instructor went from dy/dt = (150 - y)/200 to dy/(150-y) = dt/200

How is that possible

[thorny kite]

This is what's called "separation of variables"

[teal lake]

Shouldn't it be (150-y)/dy and 200/dt?

[thorny kite]

He left out 2 steps:

[teal lake]

Multiply both sides by 200, now you have 200dy/dt = 150 - y, then divide both sides by dy which gives you 200/dt = (150-y)/dy

@thorny kite

[thorny kite]

Multiply both sides by "dt" and divide both sides by (150-y)

[teal lake]

I see that makes sense, what's wrong with my method?

[thorny kite]

Nothing wrong, you can flip both sides

And preserve equality

[teal lake]

Ah I see, I guess his method makes it significantly easier to integrate though right?

[thorny kite]

It's just that we don't know how to integrate (1/dt)

[teal lake]

Makes sense, thanks

[cedar kiln]

@teal lake Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[scenic frost]

Guys

[scenic frost]

Can I get some help

[green belfry]

with?

[scenic frost]

Rational numbers

[green belfry]

what about them

[scenic frost]

Man, I'm really confused about division

[maiden citrus]

what about division confuses you

Try to be specific with your questions

[shut reef]

how old are you

[scenic frost]

I'm 14

[green belfry]

stranger danger

[green belfry]

do u mean algebraic division

or are u having a existential crisis regarding division

[scenic frost]

No

[shut reef]

yeah I'm a pedo

you confused with like 3/4?

[scenic frost]

-1/2 ÷ 3/4 = -2/3

[shut reef]

cool

[green belfry]

so what do u find confusing

[scenic frost]

I don't know how to create a right set of solution

[shut reef]

thats just $\frac{-1}{2}\cdot\frac{4}{3}$?

[scenic frost]

Shortly I'm confused about the process to get the answer.

[balmy apex]

what

now I'm scared

[shut reef]

Good

[balmy apex]

$a \div b = a \cdot \frac{1}{b}$

[shut reef]

smh

[wraith dagger]

.,..

illuminator3

[balmy apex]

$\therefore \frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \cdot \frac{d}{c} = \frac{a \cdot d}{b \cdot c}$

[wraith dagger]

illuminator3

[scenic frost]

Can anybody help me with how the process is done

[balmy apex]

@scenic frost

[balmy apex]

@scenic frost

[scenic frost]

I need a exact process

Step by step

[shut reef]

why

[balmy apex]

here is the exact process

step by step

[scenic frost]

For my rest of the assignment

[shut reef]

les say we got $\frac{3}{5}\div \frac{4}{7}$

[wraith dagger]

.,..

[scenic frost]

I need the exact process so I can see and learn how to do the process

[shut reef]

we do shit and its $\frac{3}{5}\cdot \frac{7}{4}$

[wraith dagger]

.,..

[scenic frost]

Ok

Then

[shut reef]

so $\frac{3\cdot 7}{5\cdot 4}$

[wraith dagger]

.,..

[shut reef]

$\frac{21}{20}$

[wraith dagger]

.,..

[scenic frost]

Thanks

.,..

[shut reef]

Now you can pay me

[scenic frost]

By what

[balmy apex]

oh god

[shut reef]

not really

[balmy apex]

please don't say what I think you're gonna say

[shut reef]

feet pics?

[balmy apex]

you have a problem

[shut reef]

Lol

I don't wabt feet pics

[scenic frost]

Thank god I thought you have a foot fatish

[shut reef]

lmao

[scenic frost]

Can I ask you a question

?

[shut reef]

yes

[balmy apex]

@shut reef what's your ssn

[scenic frost]

Where and when should we use cross multiplication

[balmy apex]

how did we go from basic algebra to linear algebra

[shut reef]

100705 and you guess the rest

[shut reef]

When we can

[balmy apex]

@scenic frost what kind of cross multiplication do you mean

[scenic frost]

Fraction obviously

[shut reef]

so what we did here?

[balmy apex]

wdym with cross multiplication there

never heard of it

[shut reef]

ig he means that thing we did

[scenic frost]

its where we multiply the numerator of the first fraction with the denominator of the second fraction and vice-versa

[balmy apex]

didn't know that has a name

[scenic frost]

I didn't knew about that

[shut reef]

when we dividing fractions by fractions

[scenic frost]

Oh so when we divide fraction with fraction we cross multiply them, thanks 😀

[cedar kiln]

@scenic frost Has your question been resolved?

Channel closed

Closed by @scenic frost

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ancient spire]

am clueless other than the fact i know I need to work backwards

Thanks!

[tidal bone]

you know you must have a root of x=-4 in the denominator

for that vertical asymptote

[ancient spire]

correct

[tidal bone]

so you get (x+4) there, yeah?

[ancient spire]

yes

[tidal bone]

and you know that when x=0

you should have y=-2

[ancient spire]

yes

[tidal bone]

so we now know

[wraith dagger]

grist

[ancient spire]

yes

[tidal bone]

plug in zero for x

[wraith dagger]

grist

[tidal bone]

multiply by -4c on both sides

[wraith dagger]

grist

[tidal bone]

now you get

[wraith dagger]

grist

[ancient spire]

correctr

[tidal bone]

now your job is to solve for a and c

[ancient spire]

okok thank you

[tidal bone]

the horizontal asymptote tells you how to do this

you just want a/c=3

or a=3c

[wraith dagger]

grist

grist

[tidal bone]

because the cs cancel out

🙂

[ancient spire]

thank you so much my friend

[tidal bone]

np

[ancient spire]

.close

[cedar kiln]

Channel closed

Closed by @ancient spire

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fast pollen]

@wanton sail sorry, the channel got closed

[fast pollen]

the only issue with the third term going to x^n is that you would have to subvtract 1

and you cant add 1 to n

because it cant go forward only backward

[wanton sail]

what do you mean?

[fast pollen]

lemme send a pic

[wanton sail]

you can reindex n=0 to start at n=1

[wanton sail]

that looks good so far!

[fast pollen]

but i am confused about the third term though

oh i would add it not sub

[wanton sail]

change it from starting at n=0 to starting at n=1

[fast pollen]

i thought you could only turn it back like n = 2 -> n = 1

but not n = 1 -> n = 2

[wanton sail]

nah you can do both

same exact concept

[fast pollen]

oh okay, i was watching a bunch of youtube videos on this topic to get a better understanding

but maybe it was just for that problem

now since i have all of them matching, would i try and get the middle 0 to be 1

or the other two sides to be 0 @wanton sail

[cedar kiln]

@fast pollen Has your question been resolved?

[wanton sail]

you can split the middle one up into the zero term plus a sum that starts at n=1

and then you can add all the sums together

[fast pollen]

So okay so I plug in 0 and get my answer and then add it to n = 1

[wanton sail]

yup

[fast pollen]

Okay I will try that thank you

.close

[cedar kiln]

Channel closed

Closed by @fast pollen

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[exotic tendon]

rational expression

i thought we multiply by the lcm

which the lcm is A right?

but it isn't A?

[shut reef]

It's not a

[exotic tendon]

what

[shut reef]

it's a/a

pretty much everything you can do

[exotic tendon]

Okay ty

.close

[cedar kiln]

Channel closed

Closed by @exotic tendon

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[willow lion]

how do i answer this question while showing my work?

[deft forum]

Firstly factorise it

Do you know how?

[willow lion]

idk how to factor the top, but the bottom you find what adds to -1, and multiplies to -6

right?

[deft forum]

Umm i didn't quite get it

First one you can factorise by the formula

Do you know $a^2-b^2=(a+b)(a-b)$

[wraith dagger]

Deep.

[willow lion]

yes

[deft forum]

So now we know 16= 4^2

[willow lion]

yup

[deft forum]

So $x^2-16= x^2-4^2$

[wraith dagger]

Deep.

[deft forum]

Now can you factorise?

Using formula above?

[willow lion]

isnt it like (x^2+4) (x^2 - 4)

?

oh wait

x+4, and x-4

isnt it?

[deft forum]

Yes

Last one

Cool now can we factorise denominator?

[willow lion]

yea

[deft forum]

Ok do you have any idea how to factorise that?

[willow lion]

this>

[deft forum]

Yes

Now can you think of such two numbers?

[willow lion]

-3 and 2

[deft forum]

Yea

Now can you factorise it?

[willow lion]

(x-3)(x+2)

[deft forum]

Cool

So now we got (x+4)(x-4)/(x-3)(x+2), so for domain we need to find it where the above expression doesn't hold true

Can you think when it won't give any result?

[willow lion]

x doesnt equal -2. 3, 4, or -4

i think?

[deft forum]

Umm why 4,-4?

[willow lion]

oh wait we are just speaking about the denomenator right

[deft forum]

Yes

[willow lion]

cuz the demonenator cant equal 0

got it

[deft forum]

Yes

[willow lion]

so xER l x cannot equal to -2, 3

[deft forum]

Ok so now have we found out domain right?

[willow lion]

yup

[deft forum]

Hi

Sorry for delay

@willow lion

Do you know how to find the range?

[willow lion]

no worries

no im not sure

[deft forum]

Okay

So let $\frac{x^2 -16} {x^2 -x-6} = y$

So we get $x^2 -16 = yx^2 -yx -6y$

Correct?

[willow lion]

just a sec lemme see

[wraith dagger]

Deep.

Deep.

[willow lion]

yup

[deft forum]

Okay so let's rearrange a bit

$yx^2 -x^2 -yx +16-6y=0$

[wraith dagger]

Deep.

[deft forum]

So we get $(y-1)x^2 -yx +16-6y=0$

[wraith dagger]

Deep.

[deft forum]

Correct?

[willow lion]

yea

[deft forum]

Now for this to be real in x we need determinant D>=0

Correct?

[willow lion]

yup

[deft forum]

So tell me determinant D

[willow lion]

isnt it x? like x doesnt equal to -2

and it doesnt equal to 3

[deft forum]

Umm no

That's domain

Do you know determinant?

[willow lion]

oh sorry i thought u meant domain

[deft forum]

https://youtu.be/6fU9ZgwbU74

[willow lion]

no we havent learned about determinant

ohhh discriminant

[deft forum]

The above

Oh shit

Yeah

I'm dumb

[willow lion]

haha nah dw

[shut reef]

I know

[willow lion]

so how can i find the discriminant

[shut reef]

on what

[deft forum]

This

[shut reef]

idk

[deft forum]

Okay we have quadratic in x, so in ax^2 +bx +c
D= b^2-4ac correct?

[willow lion]

yes

[deft forum]

So here in $(y-1)x^2 -yx +16-6y=0$can you find a, b, c?

[wraith dagger]

Deep.

[willow lion]

a is y-1, b is -6, c is 16

[deft forum]

Umm not quite right

b is coefficient of x term

[willow lion]

so b is y?

[deft forum]

Still close but not quite right

We have to consider minus sign

[willow lion]

so.. -y?

[deft forum]

Yes

And c isn't correct either

[willow lion]

uhh

c is -6?

[deft forum]

Umm no

[willow lion]

wait ok

a is y-1

b is -y

c isnt 16?

[deft forum]

C is remaining part that doesn't have any x term

[deft forum]

Close but incorrect

[willow lion]

its -6y

[deft forum]

Nope

It's 16-6y

Get it?

[willow lion]

the whole thing huh

i see

[deft forum]

Yeah

[willow lion]

cuz neither have x

[deft forum]

Yes

Okay so b^2-4ac>=0

[willow lion]

do i plug that into d

okay

[deft forum]

Yes

[willow lion]

got it

[deft forum]

Cool

[willow lion]

now i solve?

[deft forum]

Yes now you got inequality in y right?

Y is indeed our range

So the solution of inequality is our range

[willow lion]

how do i solve this?

[deft forum]

Although it's pretty ugly result, I've checked

[deft forum]

Can you tell me what D did you get?

[willow lion]

yea

$(-y)^2 - 4(y-1)(16-6y)$

[wraith dagger]

vanessa.v

[willow lion]

is greater than or equal to 0

[deft forum]

Yes

Simplify it

[willow lion]

so do i distribute?

[deft forum]

Yes

[willow lion]

ok

i got

$-6y^3 + 40y^2 - 40y - 64$

[wraith dagger]

vanessa.v

[willow lion]

is greater than or equal to 0

idk if that is right could you double check pls

[deft forum]

,w (-y)^2 - 4(y-1)(16-6y) simplify

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Deep.#8817

[deft forum]

Hmm doesn't look correct

Check again

We shouldn't get cube in the equation

[willow lion]

okok

i just got $25y^2 - 88y +64$

[wraith dagger]

vanessa.v

[deft forum]

Nice so $25y^2 - 88y +64 \geq 0$

[wraith dagger]

Deep.

[deft forum]

Now use quadratic formula to get y

[willow lion]

what is the formula to use again

[deft forum]

(-b +- sqrt(b^2-4ac))/2a

[willow lion]

ok 1 sec while i solve

[willow lion]

what should i set it equal to

[deft forum]

Y

We want y right?

Y is our range

[willow lion]

ok

i keep getting math error

[deft forum]

Hmm

But did you get what we have to do?

Here's the expected result

[willow lion]

yea

solve and then it gives the restrictions on y

[deft forum]

Yes correct

Okay now

What's next?

[willow lion]

ok so what should i write for range exactly? yER l y cannot equal to 1/25(44-4 sqrt21), and 1/25(44+4 sqrt21)

[deft forum]

No

Y belongs to (-infinity, 44-4root(21)/25] U [44 +sqrt(21)/25 , infinity)

[willow lion]

ohh

[deft forum]

,w (-y)^2 - 4(y-1)(16-6y) >= 0

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Deep.#8817

[willow lion]

one sec lemme write this and we'll move on

[deft forum]

Okay

[willow lion]

,rotate

[willow lion]

so is that correct?

[deft forum]

Yes

Now what else do you need help with?

[willow lion]

okay i got the intercepts, if you could just double check for me

x=-4

x=4

y=8/3

[deft forum]

Yup

[willow lion]

asymptotes are x=-2, x=3, and y=1

right?

[deft forum]

Yes

[willow lion]

perfect

now idk how to show the interval where the function is decreasing

[deft forum]

So we know asymptotes right?

We need x=-2,3 only

Wait

[willow lion]

wait do i erase the y=1 asymptote? or are you talking about how we find intervals

[deft forum]

No

[willow lion]

okok

[deft forum]

Wait Lemme think

I know 1 interval

Okay are we expected to use calculus here?

[willow lion]

nope

this is practice for grade 12 advanced func

no calc is learned before or during the course

[deft forum]

Hmm well I'm sorry but idk how will I find intervals without calc

[willow lion]

no worries you already helped me a lot!

[deft forum]

Maybe we can draw graph, but I don't understand how either without calc

[willow lion]

dont worry im gonna get help from my friend

thankyou vm!

[deft forum]

Sure no worries 🙂

[willow lion]

.close

[cedar kiln]

Channel closed

Closed by @willow lion

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wanton sail]

(please don't ping helpers unless fifteen minutes have gone by and no one's answered)

[eager pier]

do you know the coefficient of heat transfer?

do you know the formula?

this, right?

[celest seal]

.close

[cedar kiln]

Channel closed

Closed by @celest seal

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lost flame]

can someone explain why lna is there?

[lost flame]

im learning how to differentiate exponential functions but i don't understand why it works like that

[wraith dagger]

Elonmosqito96

Elonmosqito96

[lost flame]

how did the first line become the second line?

[violet jay]

It's the definition of a real exponent (or at least a very common way of defining it).

Where e^ is defined separately as the exp function.

Either way, it's an identity.

[lost flame]

thank you both!

[lost flame]

does that mean i should just remember it?

that a^x = e^ln(a)x

[violet jay]

It's a good thing to know, yes. Naively it's straightforward, since blindly using power laws we get $$e^{\ln(a)x} = (e^{\ln(a)})^x=a^x$$

[wraith dagger]

Morrow

[lost flame]

this helps alot, thank you again

.close

[cedar kiln]

Channel closed

Closed by @lost flame

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wary bramble]

v

[cedar kiln]

@wary bramble Has your question been resolved?

[shut reef]

show the choices smh

[wary bramble]

ok

[shut reef]

now do math with the given values

[wary bramble]

with the choices correct?

.close

[cedar kiln]

Channel closed

Closed by @wary bramble

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hexed jetty]

"define the complement of G using set differences"

[hexed jetty]

how do i do this?

like i know what a graph complement is

[crimson sedge]

is G a set?

or is it a graph

[hexed jetty]

it's a grah

*graph

[crimson sedge]

oh okay, I get it. basically if I'm not wrong, a graph compliment is like the same graph but every pair of connected nodes are not connected and vice vers

[hexed jetty]

yes

[crimson sedge]

so basically, a graph is a set of vertices V and a set of edges E = {vi,vj} for vi and vj in V.

[hexed jetty]

ok

[crimson sedge]

in order to define a compliment, you need to basically define the perfect graph first.

a perfect graph has all the possible edges.

[hexed jetty]

that makes sense

[crimson sedge]

I'd rather write it and show you, can you join mathematics voice?

[hexed jetty]

sure

[crimson sedge]

it will be easier to expain

[crimson delta]

that's a complete graph, not a perfect graph

[crimson sedge]

sorry bro you right

[hexed jetty]

.close

[cedar kiln]

Channel closed

Closed by @hexed jetty

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tawdry sparrow]

hey guys I was jsut wondering if this is valid

I got it from a friend comparing some answers

[sleek grove]

that's right. du=d(sin y)=cos y dy

so ∫siny cosy dy = ∫siny d(sin y)=½ sin²y +C

[tawdry sparrow]

alright thanks I got the answer

my way was distributing 1+sin ( cosy) but I only wrote siny cosy and didnt add the cosy infront

alright thanks

.close

[cedar kiln]

Channel closed

Closed by @tawdry sparrow

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[exotic loom]

yeah

are the lengths of the legs x and 2x or am i getting that wrong?

[kind venture]

sorry im choose antoher channel

[cedar kiln]

@exotic loom Has your question been resolved?

Channel closed

Closed by @exotic loom

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[exotic loom]

i've tried solving the quadratic after plugging in the initial height, but the answer it says that my answer is wrong

idk what my mistake is

[dawn junco]

well they specifically ask you to solve for when the height = 0

not height = 8

[exotic loom]

i meant to say the velocity

ik the height must be set to 0

[dawn junco]

ah ok

so you plugged in 1315 ft/sec as v_0 I suppose

we're gonna have to check your workings then

[exotic loom]

yeah

give me a sec

i honestly don't know what i'm doing

could you walk me through it after the quadratic is written?

[dawn junco]

you can post what you did anyway

if you attempted something, you prolly have some idea of what you're doing

and we can start from there

[exotic loom]

the problem is that i tried completing the square and i got a really large number so i stopped there

[dawn junco]

well yeah the 1315 doesn't help lol

what have you got then ?

ok yeah

let's just divide everything by -16 (so that we have a 1 in front of the t² it's gonna be easier)

so we get $\frac{-8}{-16} = t² - \frac{1315}{16}t$

[wraith dagger]

aPlatypus

[dawn junco]

i.e. $\frac{1}{2} = t²-\frac{1315}{16}t$

[wraith dagger]

aPlatypus

[dawn junco]

can you complete the square from that ?

I mean you'll have fractions

that's expected

we just have to suck it up here tbh

let's say we had this quadratic : t² - 1315t

can you complete the square on that ?

well 432306.25 being (1315/2)² I suppose

are you using a calculator to complete the square or what ?

at least with fractions you don't get to be weirded out by 7 billion decimals

[dawn junco]

so yeah we have that $$t²-1315t = \left(t-\frac{1315}{2}\right)² - \left(\frac{1315}{2}\right)^2$$

[wraith dagger]

aPlatypus

[dawn junco]

I mean you know how to divide a fraction by 2

I hope

lol

ok

[cedar kiln]

Channel closed

Closed by @exotic loom

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sullen briar]

help!

[sullen briar]

please!

[fallen solar]

that seems like a test...

[sullen briar]

its a practice test

if its was a real test I would not post it

[crimson sedge]

sus

Wait since when did a parabola get asymptotes

Sus

[cedar kiln]

@sullen briar Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crude maple]

ok lads final question

[crude maple]

i know the answer is 6x but does anyonr have a short way to solve this?

im supposed to answer this in less then 1 min

with no calculator

but i had to do sqrt(x^3)^3 * sqrt(216)^3

[livid hound]

prime factorisation

[crude maple]

and i not known what is sqrt(216)^3 this would've taken ages

[livid hound]

of 6, 9, 4

[crude maple]

what do you mean by that?

[livid hound]

express each number as a product of primes

[crude maple]

english is not my main language, can you give an example for one of those numbers?

[livid hound]

6 = 2*3

[crude maple]

ty

how does it make it faster

[livid hound]

well what do you get from the 4 and the 9?

[crude maple]

sqrt(2)(2)

and sqrt(3)(sqrt(3)

[livid hound]

no square roots

4 is just 2 * 2
9 is just 3 * 3

considering that (and basic exponent laws)
$$6 \cdot 4 \cdot 9 = 2 \cdot 3 \cdot 2 \cdot 2 \cdot 3 \cdot 3 = 2^3 \cdot 3^3$$
which is something you should be able to find the cube root of easily

[wraith dagger]

ℝamonov

[crude maple]

wait let me try again

Ty

.close

[cedar kiln]

Channel closed

Closed by @crude maple

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[clear oak]

Say I have a cubic equation

[clear oak]

ax^3 + bx^2 + cx + d

and I want to factor it

can't I just find the 1st derivative

equate it to zero

and now i know an x coordinate that goes into the cubic

then equate coefficients?

I have a really complicated cubic

and i have no idea how to solve it

[crimson sedge]

the only easy way to solve it is to notice a trivial solution like 0, 1, -1, .. then factorize the cubic polynomial by (x-the trivial solution)

[clear oak]

heres the cubic

i need to solve for x in terms of the variables

[crimson sedge]

ah not really a simple equation lol, your only solution then is to use cardano's formula

[gleaming cloud]

Equate them to what?

[clear oak]

no idea bruh

[clear oak]

bruh

thanks

[gleaming cloud]

Also there might not be a point where the derivative is 0

[clear oak]

true

i just wanna solve this cubic and go to bed

[dawn junco]

how in hell did you stumble upon this cubic ?

[clear oak]

for a math paper i have to do for school

basically

i need to find a general form of all w shaped quartics

then prove that the areas are equal

[iron lintel]

the ancient

[clear oak]

i need to prove that all w-shaped quartics have the same area ratio

so i found a general form

this cubic stems from finding the intersection of f(x)

with the tangent line

(the red line

im solving for this

right now

then i have to find all the areas

in terms of the variables

[gleaming cloud]

Maybe it's not necessary to find these points explicitly

[clear oak]

well how do i find the integration bounds

[gleaming cloud]

If you want to tho, I would suggest assigning (reccuring constants with complicated expressions) to (new constants)

[clear oak]

?

[gleaming cloud]

Call them something ig and see if in the resulting integral, you can cancel stuff given what you know about the bounds

[clear oak]

idk anything about the bounds yet

im solving for the x value of the bounds

i only know points P, Q, R, and S, and the equation of the tangent line to Q

as well as f(x) (the main function)

[gleaming cloud]

Well you know what equation the bounds satisfy

[gleaming cloud]

Eg. let A = abc^3

[clear oak]

i dont see the point of that

like i can just brute force it

[dawn junco]

readability

[gleaming cloud]

The point of this?

[dawn junco]

like someone has to read your paper after prolly

[clear oak]

idk what that means

[clear oak]

yes i just put in appendix

[gleaming cloud]

I added parentheses; maybe that helps

Also an example

[clear oak]

dw about the integrity of the paper

i just need to solve the cubic

[clear oak]

the brackets dont help giannis money

but thanks lol

eh

im going to sleep

.close

[cedar kiln]

Channel closed

Closed by @clear oak

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

[clear oak]

thanks guys

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fierce python]

where v=velocity and k is a constant

[fierce python]

how do i simplify this expression

ive been having troubles while tryna work out integrals in physics

also kindly ping me while replying

[compact junco]

well the left side is just v

[crystal raptor]

rhs integral is wrt t not v

[compact junco]

the t tho

yeah

[frosty ocean]

oh yess

sorry

[open dagger]

the right side should be with respect to v, not t. have you perhaps got it wrong?

[compact junco]

i think its a differential eq

[fierce python]

uh :)

[frosty ocean]

can you share the full question?

[fierce python]

sure

[dawn junco]

I mean you had dv/dt = -kv² at the beginning right, classic friction stuff

[compact junco]

bruh

its seperable though

[dawn junco]

yeah

[compact junco]

why didnt u divide both sides by v^2

[fierce python]

i dont know :)

[compact junco]

lmaooo

[frosty ocean]

ahh

makes sense

[dusty hazel]

$\dv{v}{t} = -kv^2$\
\
$\f{1}{v^2}dv = -k dt$\
$\int_{v_0}^v{\f{1}{v^2}} dv = -k \int_0^t dt$

[fierce python]

thats the complete answer?

[wraith dagger]

What the hell am I doing here?

[fierce python]

cuz thats wht i got as the answer here

[frosty ocean]

hmm

[dusty hazel]

I never gave you the answer.

[fierce python]

oh i see

[dusty hazel]

Nor I ever will.

[fierce python]

i appreciate that

[dusty hazel]

You solve it, if anything doesn't make sense, ask.

[fierce python]

yes sire

[cedar kiln]

@fierce python Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ancient spire]

so heres my question and and what ive got so far just now dont know how to put this into a interval chart?

[prisma oak]

it is >0 when x²+13x > 0 And (x-5)(x+5) >0
or when x²+13x<0 And (x-5)(x+5) <0

[ancient spire]

how would i implement that onto a interval chart though

prev one i did

[golden sundial]

do you know when x^2 - 1 > 0?

[ancient spire]

when x = .5?

nono

sorry

1 no?

[prisma oak]

and -1

[golden sundial]

well when you have an quadratic like ax^2 + bx + c > 0
you would solve the quadratic = 0 and then if a is positive write your answer as x> positive root or x<negative root

[ancient spire]

liitle confused

[golden sundial]

so for x^2 - 1 > 0
we find the roots
x^2 - 1 = 0
x^2 = 1
x = +-1
so x^2 - 1 > 0 is satisfied for x<-1 or x>1

[ancient spire]

so i should have stopped here?

[golden sundial]

huh no

[golden sundial]

no like the last step here

now you gotta find what x satisfies your inequality

[ancient spire]

ok... sorry

where are you seeing the x^2 that your satisfying

<@&286206848099549185>

[prisma oak]

,rotate

[prisma oak]

does it help?

[ancient spire]

indeed

so at this point of our equation we use all four terms for the chart?

[prisma oak]

yes because your looking for the sign of your equation

if you were only looking for zeros you'll just need the numerator

[ancient spire]

so explain how you got the top numbers

i understand where you got them just not how

[prisma oak]

we are looking for x + 13= 0

so it's x = -13

then we look when is it + or -

when x<-13 we have x+13<0

[ancient spire]

got it

and how bout the zero sorrry

[prisma oak]

same we look when x = 0

it's just a little simpler

[ancient spire]

okok thanks that helped to see it visualy

appreciate your time

.close

[cedar kiln]

Channel closed

Closed by @ancient spire

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vestal bear]

f-i?

[lyric wolf]

I am trying to find some help solving #4 f, g, h and I

Yeah

[vestal bear]

just do the opposite operations for the parts that you don't want isolated

so if you want to isolate L for 4f

[lyric wolf]

I had dabbled with this but I don’t know

[vestal bear]

no

you can subtract whole terms and bring them to the other side of the equation

So for the terms that don't contain L

On the same side of the equation as L

these terms are 2πr and 2r

You can subtract them from both sides of the equation to begin isolating L

then ofc divide 2 from both sides to completely isolate L

[lyric wolf]

Awesome thank you

.close

[cedar kiln]

Channel closed

Closed by @lyric wolf

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[prisma basin]

I don't understand on how to set this proportion up

like is it 8/4 = 6/10

or 8/6 = 4/10

?

[manic glade]

The smaller sides would correspond

[prisma basin]

oh so like 4/6 = 8/10?

@manic glade

[manic glade]

I think similar means they are proportional, right?

Yeah, your equation would be correct

But you need to check if it is equal

[prisma basin]

its not I did it and does not work

[manic glade]

If they're not equal, then it means that they aren't similar, right?

Since all sides would have the same similarity ratio

[prisma basin]

yeah

i just needed to know if my equation is correct

thx

.close

[cedar kiln]

Channel closed

Closed by @prisma basin

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[quiet hazel]

whats the difference between finding the cdf of a multivariable function?

[quiet hazel]

$F(x+y) = P(X +Y \le a) = \int_{-\infty}^{\infty} F_x(a-y)F_ydy$

[wraith dagger]

smooth

[quiet hazel]

and finding the conditional cdf of a multivariable function?

$F x|y (a | y) = P(X \le a | Y = y) = \int_{-\infty}^{a} f_x|_y(x|y)dx$

[wraith dagger]

smooth

[cedar kiln]

@quiet hazel Has your question been resolved?

[quiet hazel]

<@&286206848099549185>

[quiet hazel]

also is f denoted as cdf and F denoted as pdf?

[quiet hazel]

<@&286206848099549185>

[peak creek]

can soemone help me

@quiet hazel

<@&286206848099549185>

<@&286206848099549185>

[wanton sail]

aarya please open a new help channel

this one is for smooth

[peak creek]

oh sorry

@wanton sail how do i make a new one

[long arrow]

#help-8

[quiet hazel]

can you delete this bro

common now

[peak creek]

😭mb

[quiet hazel]

u ruined my channel ty

[peak creek]

4 messages

Chill out dawg

[quiet hazel]

helpers cant even see what i need help with

[peak creek]

Oh mb

[quiet hazel]

youre

suppose to wait

for 15 min

before you send a ping

its whatevs

[wanton sail]

@quiet hazel okay maybe that I'm not familiar enough with this to understand it properly, but can you post context, I'm not really understanding the notation

cdf is just the probability that x+y will be less than or equal to a, conditional cdf is just the same thing but assuming some extra condition

is F a function of two variables here or one?

[cedar kiln]

@quiet hazel Has your question been resolved?

[quiet hazel]

Two

[wanton sail]

I am really confused by your notation then

Is there a problem you're trying to solve using this, or is it just like a conceptual question

[quiet hazel]

No

I’m just trying to understand these concepts

And why each formula is used the way it’s used

[wanton sail]

wait so if F is a function of two variables, why does it only have one input in your equations

[quiet hazel]

Actually I take that back

Function of one variable

[wanton sail]

wait I'm confused now lol

what are x and y, and what is F?

[wanton sail]

ahh you're learning about convolutions

[quiet hazel]

It’s the formula in 3.1

[wanton sail]

I see now

this video might help you (it helped me when I was learning about convolutions)

https://www.youtube.com/watch?v=QmcoPYUfbJ8

[quiet hazel]

I thought convolutions helps us find the PDF of a multi variable function

Not cdf

I’m not talking about 3.2

I’m talking about 3.1

I wanna know the difference between that formula and the conditional cdf of multivariable function formula

[wanton sail]

in your mind, what are the similarities between them, like how are they the same

also in this textbook, the lowercase f is PDF and the uppercase F is CDF to answer your earlier question

[quiet hazel]

Wb in general?

[wanton sail]

in general, upper case letters are usually the integral of a lower case letter

[quiet hazel]

They’re similar because you need both in order to find the cdf of the function

[wanton sail]

so makes sense why they choose upper case letters to represent CDF and lower case to represent PDF

since CDF is integral of PDF

[quiet hazel]

So I’m guessing the 3.1 formula is used to find cdf of a multivariable function and the conditional cdf one is finding a a cdf of the expression that we got from condition pdf?

Ic

[wanton sail]

they are used in different situations, the first one is when you want to know the probability that X+Y is less than something (assuming X and Y are independent), the second one is when you want to know the probability that X is less than something given that Y is a certain value

also the formula for F_{X+Y} is a convolution

(why I linked you the video)

[quiet hazel]

For the first one can I change the formula to be X + Y is greater than something?

[wanton sail]

yes

[quiet hazel]

ic

[wanton sail]

just take 1 - the cdf

[quiet hazel]

So yeah second one mainly used for conditional prob

[quiet hazel]

U mean that formula?

[wanton sail]

yes, P(X+Y > a) = 1 - P(X+Y ≤ a)

since they are complements

either one can happen or the other

[quiet hazel]

Ah

Alright

Ty

[cedar kiln]

@quiet hazel Has your question been resolved?

[cedar kiln]

Channel closed

Closed by @quiet hazel

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[misty sable]

SOMEONE

[misty sable]

HELP

ME

NOW

wait

nvm

a diff question

wron question

wait

nvm it's the rigt question

SOMEONE HELP QUICK

[golden sundial]

how much does a robux cost?

[misty sable]

1 dollar is one robux y

[golden sundial]

curiosity. your goal here is to isolate your variable

[misty sable]

o

[golden sundial]

what's your variable in this question?

[misty sable]

okay

T

but it doesn't say the worth

[golden sundial]

perfect, so you need to have it alone in the left side

[misty sable]

it's 7th grade math soo

[misty sable]

that's how it is in 7th grade ig

[misty sable]

oh

so we ignore it?

[golden sundial]

no no lol

if you have 5t + 28 = 10
you would subtract the term on the same side as your variable

so subtract 28 from both sides

[misty sable]

so 5 - 28?

if u mean 5-28

[red raven]

No. 5t = 10-28

[golden sundial]

5t + 28 **- 28 **= 10 - 28

[misty sable]

-23

[golden sundial]

you subtract 28

[misty sable]

wait

where did we get 10

[golden sundial]

here?

[misty sable]

oh nvm

[golden sundial]

can you simplify this now?

[misty sable]

wait

it's not a fraction

to simplify

tho

[golden sundial]

subtract

[red raven]

5t+28=10
You take the 28 and convert it into a minus and put it next to the 10
5t = 10-28
Then the 5t you change it it into division with the quantity of 10-28
t= (10-28)/5

And you calculated t.

Which t would be -3.6

[misty sable]

o

makes sense a bit now

thankq

[red raven]

No problem.

.close

Oh wait

@misty sable do .close

[cedar kiln]

Channel closed

Closed by @autumn carbon

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[quiet hazel]

the first formula is used in normal cases right?

[upper abyss]

@crimson sedge
The first one is (45/50)(44/49).
That is, we multiply the probabilities that we pick one perfect chip after the other.

A perfect chip AND a perfect chip
(45/50) × (44/49)

Part c is a little harder. There's a few ways to pick one perfect and one defective chip

In simple situations like this, I like to think using a tree diagram

What's the probability that you get perfect, then defective? What's the probability that you get defective, then perfect? Add those.

I actually don't know that "P(x)" means in this context

But finding the expected number of calls is as easy as using the formula

Should have some kind of formula for expected value

Basically Σ xP(x)
Where x is the value, P(x) is the probability it happens

Yeye go ahead

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

@crimson sedge Has your question been resolved?

Channel closed

Closed by @oak tulip

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[celest comet]

should powers be subtracted from each other when they are divided? i literally forgot how to do this

[slim jackal]

i would first expand the brackets out