GG・Goof
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#help-13
wraith daggerBOT
cosmic steppe
You're using a combination
cosmic steppe
$$\ln{|\sec{(x)} + \tan{(x)}|} + C$$
spark igloo
Ooo
wraith daggerBOT
Umbraleviathan
cosmic steppe
I have a list of these
wraith daggerBOT
spark igloo
Wait how
spark igloo
Hm I got that
cosmic steppe
So sec(x) implies that the hypoentuse is x, adjacent is 1
Find the other side
$\sqrt{x^2-1^2}$
wraith daggerBOT
Umbraleviathan
spark igloo
Hm yea
spark igloo
I know why it says
cosmic steppe
I read it as tan(arcsec
spark igloo
Sqrt sec x
spark igloo
;-;
cosmic steppe
Lol
spark igloo
Yea lol
Got my final answer
$a\sqrt{\frac{x^2}{a^2}+\frac{x}{a}}+a\log{|\sqrt{\frac{x}{a}+1}+\sqrt{\frac{x}{a}}|}$
spark igloo
Hmm k
wraith daggerBOT
GG・Goof
spark igloo
.close
dreamy lily
Help please this is hard
cedar kilnBOT
Help please this is hard
obsidian coral
<@&286206848099549185>
You have to wait at least 15 minutes before pinging helpers
dreamy lily
You have to wait at least 15 minutes before pinging helpers
i know i was in another chat and after 20 mins no one helped me
obsidian coral
Well, you opened a new channel, then, same rules apply, you still need to wait
dreamy lily
<@&286206848099549185>
cedar kilnBOT
@dreamy lily Has your question been resolved?
cedar kilnBOT
cedar kilnBOT
Available help channel!
marble aspen
Im stuck on question 13 (b) where u hv to form a formula
cedar kilnBOT
Im stuck on question 13 (b) where u hv to form a formula
marble aspen
This is what we use to form the formula
Heres what i did, when i looked at the back my answer ws very different and i dont know where i rly went wrong
Heres the answer at the back ex8.3 Q13(b)
<@&286206848099549185>
cedar kilnBOT
@marble aspen Has your question been resolved?
cedar kilnBOT
@marble aspen Has your question been resolved?
copper wagon
cedar kilnBOT
copper wagon
yours is already closed u have to make a new one
copper wagon
my question is how to do this I forgot to sauy
cedar kilnBOT
@copper wagon Has your question been resolved?
copper wagon
<@&286206848099549185>
velvet mortar
Regular polygon means all sides are equal
You can divide this hexagon into six congruent isosceles triangles
cedar kilnBOT
@copper wagon Has your question been resolved?
copper wagon
.close
cerulean ledge
help
cerulean ledge
@silent yew great Lelouch thanks to ur wisdom i did 2 more questions and i got them right
sonic thistle
something with similar triangles
cerulean ledge
ADE is similar to ABC
sonic thistle
"sir"
cerulean ledge
huh?
cerulean ledge
im sorry
cerulean ledge
yep
sonic thistle
$\left(\frac{3}{4}\right)^2$
wraith daggerBOT
Mike Oxbig
cerulean ledge
okok
cedar kilnBOT
@cerulean ledge Has your question been resolved?
cerulean ledge
ur gone again?
sorry i was using the restroom
cedar kilnBOT
cerulean ledge
.close
cedar kilnBOT
✅
honest gale
is it A?
velvet mortar
Think, brother
cedar kilnBOT
velvet mortar
The answer is wrong
velvet mortar
I'm curious how you reached that conclusion
velvet mortar
Children are so impatient
honest gale
Children are so impatient
kind of not a child but still
cedar kilnBOT
Available help channel!
sand cradle
Ben drives to his friend, which is 40 miles away and then drives back.
On the way there, he drives 40 miles an hour, but on the way back only 20 mph.
What is the average speed for the whole trip?
sand cradle
If he drives 40mph and 20mph, his average speed should be (40+20)/2 = (60)/2 = 30 => 30mph, right?
But it's actually 26 2/3 mph
Why?
sand cradle
in total he drives 80 miles in 3 hours
But they give you 2 speeds, so why not take the average of them?
crimson delta
you can't just add the two velocities because in a sense the 20 mph is more important, as it was present for a longer time
sand cradle
oh
sharp lotus
Children are so impatient
because when he's going slower, he's spending more time traveling back...so he's spending more time traveling at that speed
oops not sure why that was a reply for some reason
kind lily
Also formula of average speed is total distance by total time you have to use it
sharp lotus
yeah that's a good way to look at it
he travels a total of 80 miles and he spends 1 hour on the way there and 2 hours on the way back so 80 / 3 = 26.6...
sand cradle
yeah makes sense, the average speed will be lower than 30mph because he spends more time driving 20mph
thx
.close
clever wave
Hello
buoyant latch
ask your question please
clever wave
buoyant latch
,rotate
wraith daggerBOT
buoyant latch
what do you know about the probability as you go down the tree (towards the right side)
muted fjord
You multiply the numbers on the same branch that leads to only 1 win
And then add the parallel branches
buoyant latch
You multiply the numbers on the same branch that leads to only 1 win
And then a...
that doens't help why it works
if they knew they wouldn't be stuck
clever wave
I need the answer to B
clever wave
I don’t know
buoyant latch
what's the probability you lose
clever wave
0.6?
buoyant latch
where did you get 0.6
clever wave
0.2 x 3 = 0.6 all the losses added up
clever wave
50 50
buoyant latch
where did you get 50 50
muted fjord
You either lose or you don't
buoyant latch
dont confuse people
muted fjord
Aight sorry
clever wave
Leave that I thought u ment something else
clever wave
I don’t know
clever wave
50%
buoyant latch
what's the chance you get heads twice in a row
clever wave
50%
clever wave
25%
buoyant latch
how did you get 25%
clever wave
Bro I literally got my GCSE maths paper in 12 hours Paper 2 I ain’t got no time to be flipping coins
buoyant latch
just follow through here, there's no point telling you the answer if u cant apply it to a different problem
clever wave
Just tell me the answer
buoyant latch
the answer is 32%
muted fjord
😩
cedar kilnBOT
buoyant latch
@clever wave When asking for help, do not insist on getting just the answer; we are here to help you learn, not do the work for you. Likewise, if you are providing help to others, try your best to explain and elaborate instead of simply giving away the answer.
¯_(ツ)_/¯
cedar kilnBOT
Available help channel!
vagrant spindle
Find the maximum value of the function f(x) = x³-6ax²+9a²x-2a³ on the intervals within the domain 0 ≤ x ≤ 2. Assume that a > 0
vagrant spindle
I literally cant wrap my head around this question.
gaunt hamlet
What have you tried
vagrant spindle
I can find the values of the equations without intervals and with intervals using differential calculus, but I can't seem to understand how to even begin with these kinds.
buoyant latch
Find the maximum value of the function `f(x) = x³-6ax²+9a²x-2a³` on the interval...
do you know calculus
buoyant latch
what does maximum mean
vagrant spindle
about this question I have tried to get help
buoyant latch
what's special about maximums
buoyant latch
what's special about maximums in terms of calculus
vagrant spindle
there's relative/local and absolute/global maximums
vagrant spindle
what's special about maximums in terms of calculus
wdym
vagrant spindle
It teaches you on how to find derivatives?
buoyant latch
what are derivatives
vagrant spindle
The slope at a specific point on a graph
vagrant spindle
Idek
gaunt hamlet
They're asking how you calculate a max/min
buoyant latch
what's special about the slope at a maximum
vagrant spindle
It is 0
buoyant latch
right
vagrant spindle
yes
buoyant latch
so differentiate the function for its slope
and find when it's equal to 0
that's where the local maximum/minimum will be yeah?
vagrant spindle
that's where the local maximum/minimum will be yeah?
yea but the problem
is that
since
buoyant latch
is it not in the interval
vagrant spindle
there is another variable a
I get the derivative of the function
to be
3(x-a)(x-3a) so the critical points are at a, and 3a
but what do I do with this?
Find the maximum value of the function f(x) = x³-6ax²+9a²x-2a³ on the intervals within the domain 0 ≤ x ≤ 2. Assume that a > 0
just repost
static sage
no like what does this imply about the max of 3(x-a)(x-3a)
vagrant spindle
not sure
to be honest
Im assuming
that a is the maximum
and 3a is the minimum
muted fjord
Yes
vagrant spindle
based off the graph
static sage
ah oops i typoed
static sage
so you know 3(x-a)(x-3a) is the derivative right
vagrant spindle
that's kind of my logic to it
vagrant spindle
so you know 3(x-a)(x-3a) is the derivative right
yes
vagrant spindle
there can only be a max or a min when the derivative equals 0
yes
thats correct
makes sense
gaunt hamlet
Shouldn't you also consider the bounds of the interval?
muted fjord
that's kind of my logic to it
Remember this only applys when coefficient of leading term is positive
vagrant spindle
Shouldn't you also consider the bounds of the interval?
yea i mean it is between 0 and 2
vagrant spindle
Remember this only applys when coefficient of leading term is positive
what exactly is the "leading" term you are referring to?
gaunt hamlet
The max might be one of 0 or 2, if it's not a or 3a
buoyant latch
the max is either at x = 2 or x = a @vagrant spindle do you see this
muted fjord
what exactly is the "leading" term you are referring to?
The x³ term in the polynomial
vagrant spindle
The max might be one of 0 or 2, if it's not a or 3a
yea thats true
vagrant spindle
the max is either at x = 2 or x = a <@629854223013511178> do you see this
how exactly?
buoyant latch
it cant be 0
muted fjord
The max might be one of 0 or 2, if it's not a or 3a
It can't be 0 as its a and a > 0
vagrant spindle
The x³ term in the polynomial
yes of course
buoyant latch
if the max is at 0 then a would be 0
vagrant spindle
then the graph would flip otherwise
muted fjord
then the graph would flip otherwise
Ye
buoyant latch
how exactly?
think about hte graph
either a is within the bounds 0 < x < 2
and 3a isn't
then a must be the largest value
if 3a is also in the bound
vagrant spindle
buoyant latch
then it can grow up higher than 3a
buoyant latch
yes
now think about hte bounds
if i cut the bounds between a and 3a
then a is the top
if i cut after 3a
then there's a chance it can grow above x = a
so it's either x = a or x = 2
vagrant spindle
then a must be the largest value
yea because its closest to 0 on the positive x axis
so yes thats true
buoyant latch
do you see it now
vagrant spindle
if i cut the bounds between a and 3a
hm
buoyant latch
yea
muted fjord
3a can still be higher then 2
I don't understand what you mean
vagrant spindle
so what exactly is the method
buoyant latch
from here you do f(a) and f(2) and see what's bigger
gaunt hamlet
3a can still be higher then 2
I don't understand what you mean
The only way that's true is if 2 ≤ a, so neither point is in the bounds and 2 is the max, no?
muted fjord
then a is max in 0 < x < 2
If 3a is less then 2 how will that matter ? (Ik it can if the graph shoots back up again, but we don't know how long it will take that to happen)
buoyant latch
If 3a is less then 2 how will that matter ? (Ik it can if the graph shoots back ...
that's why we need to find f(a) and f(2) and see what's bigger
buoyant latch
yes
buoyant latch
so thats why 2 is the max
IF a is not within 0 -> 2
if a is within 0 -> 2 and 3a isn't
then a is the max
either way it must be either x=a is the max or x=2 is the max
plug them into your function and solve
see what's bigger
vagrant spindle
i mean a is arbitrary
so it wouldnt make any sense
you wouldnt get a definitive value
i suppose
buoyant latch
if f(a) > f(2) then f(a) is max if a < 2
muted fjord
If 3a is less then 2 then it depends on the graphs gradients wether 2 is the max or a is
muted fjord
if f(a) > f(2) then f(a) is max if a < 2
Bro we can't find f(a)
buoyant latch
if f(a) > f(2) then f(2) is max if 2 < a
muted fjord
We can't even find f(2)
muted fjord
Yea but when you plug in a you will have a² terms
Which will depend alot on the size of a when say comparing to a 2a term
vagrant spindle
so @buoyant latch how exactly would you recommend I go about these problems?
I looked at the answer
in the answer key
it just shows me
2 ranges and the maximum values corresponding to them in terms of a
there's no definitive maximum
buoyant latch
can u send a picture
vagrant spindle
sure
buoyant latch
it should be dependent on a
buoyant latch
ok do you see the right 3 graphs
those are the 3 situations i mentioned
either a > 2 in which case f(2) is the max
or a < 2 < 3a then f(a) is the max
or a < 3a < 2 in which case you test if f(a) or f(2) is greater, the greater is the maximum
vagrant spindle
aren't there more possibilties?
buoyant latch
oh but there's actual coefficients that lock the function in
vagrant spindle
oh but there's actual coefficients that lock the function in
??
buoyant latch
honestly i dont see why it says for values x > 3a, let f(x) = 2a^3
vagrant spindle
honestly i dont see why it says for values x > 3a, let f(x) = 2a^3
exactly
i didnt understand why they said it for x = 4a
and then they compared that
muted fjord
Seems like an arbitrary choice
muted fjord
Maybe its just an example to show such a possibility exists
vagrant spindle
similar to this
and they all use a different method to solve
thats why i cant understand the concept
of using intervals in diff. calc
jovial snow
hello
jovial snow
Does anyone have any recommendation for a free online calculator that can multiply a 15x15 matrix with another 15x15 matrix
thanks!
vernal viper
cedar kilnBOT
Available help channel!
crimson sedge
I forgot how to do this kind of equation, there’s little to work with
cedar kilnBOT
I forgot how to do this kind of equation, there’s little to work with
@crimson sedge Has your question been resolved?
azure monolith
I forgot how to do this kind of equation, there’s little to work with
cant read it
crimson sedge
cant read it
it says
"Determine, to the nearest tenth of a year, how long it would take an investment to double at a 3 and 3/4 interest rate, compounded continuously."
<@&286206848099549185>
crimson sedge
<@&286206848099549185>
:/
i really need help but I don't know how to do it
I'd really like if someone could walk me through it
thin topaz
so the formula is money = investment * e^(rt)
2 * investment = investment * e^(rt)
2 = e^rt
take logs...
am i missing something?
thin topaz
you feel like P is what?
crimson sedge
am i missing something?
it's like, for example,
Peter has $200,000 in his bank account, compounded continuously at a rate of {value of r} for unknown for somethin
you're missing P
thin topaz
you don't have to know P
thin topaz
mhm
crimson sedge
N = b^e
B^e = N
ln{b}N = e
right
so B is e, but ln does that for us so it's really just
ln2 = 0.0375(t)?
thin topaz
i've no idea what you did there but the last thing you said is correct
crimson sedge
you don't have to know P
also, if I don't need to know P, how do I get rid of it?
oh.
ok
thin topaz
you get rid of it because when you have this sort of compounding
crimson sedge
but P is a starting value
thin topaz
money = P * e^rt
crimson sedge
oh so P is just investment
thin topaz
yea. it's the amount that you put in initially
crimson sedge
so wouldn't it be 2P?
thin topaz
yes, that's what i wrote above too 😄
crimson sedge
oh right
thin topaz
also, if you substitute t = 0, you get your money at time zero
that is, the initial investment
thin topaz
no
cedar kilnBOT
cedar kilnBOT
Available help channel!
quiet hazel
cedar kilnBOT
crystal raptor
Would need to see the definition of f(x)
quiet hazel
crystal raptor
So f(x) is only defined from 0 to 2
And you want P(X>1)
That's where the 1 and 2 come from
quiet hazel
we cant have a value less than 0 in the bounds since x has to be greater than 1, right or nah?
and the only value than is greater than 1 is 2 in this case
how can i find the cdf of this? @crystal raptor
modern compass
Integrate it
quiet hazel
we cant have a value less than 0 in the bounds since x has to be greater than 1,...
@modern compass you know this?
modern compass
we cant have a value less than 0 in the bounds since x has to be greater than 1,...
your pdf is only non-zero between 0 and 2. so any bounds on an integral less than 0 or greater than 2 are pointless, they don't add anything to the value of the integral
quiet hazel
yes, the cdf F(x) is the integral from -infinity to x of the pdf
what is x?
quiet hazel
your pdf is only non-zero between 0 and 2. so any bounds on an integral less tha...
thats why the bound is from 1 to 2, because we want to find x that si greater than 1. so 0 wont fit in that case, and 2 wouldve been the limit since thats the highest the bound can go up to right?
what would x be in this case?
quiet hazel
o
quiet hazel
thats why the bound is from 1 to 2, because we want to find x that si greater th...
wut abt this tho?
modern compass
yes
stoic sluice
Can somebody explain to me why is it that on straigth line, a point on it for a certain segment is considered to be both a minimum and a maxium at the same time? https://www.youtube.com/watch?v=xmrhZ5ySaD0&t=78s
dire geode
Can somebody explain to me why is it that on straigth line, a point on it for a ...
Is the line horizontal
stoic sluice
My issue is that I don't understand how one value can be a minimum and maximum at the same time
the idea does not enter into my head
If we have y=2 and y=5, then 2 is the min. and 5 is the max
this makes sense, but how can one value be the two at the same time?
cedar kilnBOT
@stoic sluice Has your question been resolved?
cedar kilnBOT
@stoic sluice Has your question been resolved?
dire geode
If we have y=2 and y=5, then 2 is the min. and 5 is the max
Min and max only refer to one function.
y=5 is a horizontal line
Plot it and see what alternative could be if not max=min
stoic sluice
Min and max only refer to one function.
Could it not be only maximum ? or vice versa
dire geode
Could it not be only maximum ? or vice versa
Look up the definition of max and min
stoic sluice
Look up the definition of max and min
"In mathematical analysis, the maxima and minima (the respective plurals of maximum and minimum) of a function, known collectively as extrema (the plural of extremum), are the largest and smallest value of the function, either within a given range (the local or relative extrema), or on the entire domain (the global or absolute extrema)."
stoic sluice
how does this answer my problem of comprehension though
I understand the explanation, I just don't understand the rough case
stoic sluice
I found something
f(c) is a local maximum if f(c) ≥ f(x) for all x near c.
f(c) is a local minimum if f(c) ≤ f(x) for all x near c.
dire geode
The answer to your question about max and mins relies on you knowing the mathematical definition of them
stoic sluice
@dire geode
dire geode
f(c) is a local maximum if f(c) ≥ f(x) for all x near c.
f(c) is a local minimum...
Looks right. Apply it to constant functions
stoic sluice
In the case of a horizontal line, both definitions are satisfied, right?
dire geode
In the case of a horizontal line, both definitions are satisfied, right?
Show your work
stoic sluice
If we take y = 5 for all x
wait a minute let me write this down
@dire geode f(x) = 5, for one point x, is going to be superior or equal to all other f(x), on a certain segment of the horizontal line.
Inversely, f(x)=5, for one point x, is going to be inferior or equal to all other f(x), on a certain segment of the horizontal line
dire geode
I don't think people use inferior and superior but yeah that's right
stoic sluice
In both cases though, they're all equal to each other, so it satisfies both the definitions of minimum and maximum
@dire geode I said inferior or superior to put the definition as I gave it preivously, but it's obvious that they're equal in both cases, and not superior or inferior
dire geode
No I mean those words are outdated
stoic sluice
ohh
stoic sluice
ok, so the reason why it's a minimum and maximum at the same time, is because they both satisfy the two conditions at the same time
@dire geode Am i Understanding this right?
By condition, I mean the mathematical definition
stoic sluice
so I understand now, thanks very much for the help. What was my error then?
I di dnot understand the definition of the thing?
@dire geode sorry one last question
sick ruin
Inf and sup are not outdated what
stoic sluice
Hi, since you read the convo, could you tell me what was my error as to why I was not understanding it?
Is it because I had no idea of the mathematical definition of it?
sick ruin
Oh I see your question
stoic sluice
Now, I'm trying to understand why was it that I did not understand at first
sick ruin
I totally get it
stoic sluice
what was blocking in my head
sick ruin
The idea that maximum and minimum had to be two different things
In a room full of people, there’s inevitably going to be a tallest person and a shortest person
sick ruin
But if you’re the only person in the room, you are now both the tallest and the shortest
sick ruin
Right
stoic sluice
But if you’re the only person in the room, you are now both the tallest and the ...
do you have another metaphor for this
stoic sluice
My sister is my worst sister and my best sister
said this way it makes sense also
but what made me understand this thing was the mathematical definition funnily enough
buoyant latch
It’s like saying 3<= x<= 3
stoic sluice
It’s like saying 3<= x<= 3
oh yes, 3 is going to be satisfying these two conditions
x=3 satisfies those two conditions
buoyant latch
It’s also the minimum and maximum of that range
stoic sluice
But if you’re the only person in the room, you are now both the tallest and the ...
ok, i think also said this way it makes sense
sick ruin
What you were confused about makes perfect sense though
Minimum and maximum are inherently about comparison
But if there’s only one object, you’re not really comparing anymore
So it’s weird
stoic sluice
since there has to be inevitable one tallest and one shortest, when there's only one person left, he is the only one who can satisfy those two conditions in the room
sick ruin
Basically yeah
He is greater than or equal to everyone’s height
But “everyone” is him, and he is equal to his height
Hence he is the tallest person
And vice versa for minimum
stoic sluice
So it’s weird
exactly, I think the issue was that there's an intuitive understanding of the notion, and then there's the rough edge case which can only make sense if you have a precise definition for the notion, which is the mathematical definition of it
sick ruin
You said it perfectly, yep
stoic sluice
i was trying to understand it intuitvely, and trying to compare it to something, hence why I was blocking in my understanding
sick ruin
And in fact there are definitions of minimum/maximum which do follow the intuitive notion - that is, they must be strictly bigger or smaller (no “equal to” business) than all the numbers around it
Those are called relative minimums
stoic sluice
And in fact there are definitions of minimum/maximum which do follow the intuiti...
i was under the impresion taht relative had the equal to implied also?
relative minimum and relative maximum for a certain interval
sick ruin
Ah Im mistaken
stoic sluice
Basically yeah
said this way also it makes it clear, thanks again
stoic sluice
I have as a rule that I have to be able to explain something to myself if I understand it
stoic sluice
are you some university student?
stoic sluice
which domain?
sick ruin
Thanks
stoic sluice
you really helped me
sick ruin
Yeah
stoic sluice
im closing now
stoic sluice
.close
cedar kilnBOT
cedar kilnBOT
Available help channel!
buoyant latch
what have u tried
tropic oxide
y = kx**^**2
heady forge
ye thatgs what i did
tropic oxide
okay so do you know what it means to increase x by 200%?
heady forge
unfortunaetly no
buoyant latch
what does it mean if i improve something by 100%
heady forge
means you double the thing?
heady forge
means triple
buoyant latch
right
tropic oxide
right, so what happens when you replace x with 3x in your equation?
buoyant latch
expand it
heady forge
y=k3x^2?
buoyant latch
are you sure
heady forge
uh
heady forge
wait what
heady forge
y=3kx^2
buoyant latch
so you're saying that (ab)^n = ab^n
heady forge
yes
heady forge
yes
buoyant latch
,w (2*3)^2
wraith daggerBOT
heady forge
oh
buoyant latch
this is basic index laws
heady forge
ooh
buoyant latch
it's very difficult to progress forwards in math without understanding prior content
maths is like a building you cant understand higher level concepts if you dont get the fundamentals
heady forge
oh i see
buoyant latch
so i ask again, y = k(3x)^2 can you expand this
heady forge
yes
buoyant latch
ok do it
cedar kilnBOT
@heady forge Has your question been resolved?
fading pasture
.reopen
craggy anchor
cedar kilnBOT
rugged palm
what have you tried?
craggy anchor
assume distance = x, time = distance divided speed, so x/2/100 + x/2/60 = 2/3
which doesnt work
craggy anchor
haven't i converted everything
rugged palm
Send your work
but in our problem we have time in mins and speed in km/h
are you there @craggy anchor ?
tawny warren
tawny warren
ok how did u reach the second equation from the first?
craggy anchor
fraction rule
tawny warren
which is?
craggy anchor
a/b/c = ac/b
tawny warren
so that's the mistake
first of all do you mean $\frac{\left(\frac{a}{b}\right)}{c}$ or $\frac{a}{\left(\frac{b}{c}\right)}$?
wraith daggerBOT
newbienoob
cedar kilnBOT
queen pivot
I think that the TME wouldn't match
With
Set A and Set B
A
PE = 58800
KE = 0m/s
TME = 58800
B
PE = 51450
KE = 0m/s
TME = 51450
Am i dumb
Am i missing something here?
<@&286206848099549185>
lament kraken
Total mechanical energy
is it frictionless
queen pivot
Yes, i think so
lament kraken
Yes, i think so
okay denote where A, B and C are
because A and
B
which one is h =40
lament kraken
A
PE = 58800
KE = 0m/s
TME = 58800
B
PE = 51450
KE = 0m/s
TME = 51450
check PE of A
queen pivot
By check you mean correct right?
queen pivot
oh
lament kraken
A
PE = 58800
KE = 0m/s
TME = 58800
B
PE = 51450
KE = 0m/s
TME = 51450
dont denote it as m/s its not the unit for energy
Joules is the unit for energy
lament kraken
A
PE = 58800
KE = 0m/s
TME = 58800
B
PE = 51450
KE = 0m/s
TME = 51450
your part B is wrong
do you know the law of conservation of energy?
energy is always conserved and since there are no frictional forces
that means there is no energy really lost to the environment
so the person should have some kinetic energy at point B
and remember that total energy = kinetic energy + potential
queen pivot
dont denote it as m/s its not the unit for energy
Right
Im so confused at the problem
queen pivot
Yes
lament kraken
TME is
consistent
no matter where you are in that hill
so TME in A = TME in B = TME in C
does that make sesne?
due to the conservation of energy
lament kraken
yes
very good
you know the PE in every single one of the different points
thus you cans olv efor KE in the different points
does that make sense
queen pivot
Yes
lament kraken
ok great
queen pivot
I'm also watching a video rn
lament kraken
so whats your TME on point B
queen pivot
My answer is 51450
lament kraken
My answer is 51450
yup and then what is KE then
lament kraken
A
PE = 58800
KE = 0m/s
TME = 58800
B
PE = 51450
KE = 0m/s
TME = 51450
this is different to your answer here already :)
queen pivot
7350
queen pivot
this is different to your answer here already :)
I subtracted 51450 to 58800
queen pivot
Yeah Hahaha
lament kraken
you can always make sense with physics
queen pivot
you can always make sense with physics
True
queen pivot
Yes sir!
cedar kilnBOT
cedar kilnBOT
Available help channel!
vocal raptor
I gotta find S22 in arithmetical progression. a8+a15=48
cedar kilnBOT
I gotta find S22 in arithmetical progression. a8+a15=48
sonic thistle
is that an actual language?
iron berry
is that an actual language?
looks like georgian
lament kraken
I gotta find S22 in arithmetical progression. a8+a15=48
notice they are a difference of 7
iron berry
me
vocal raptor
notice they are a difference of 7
What that gives to me
silent yew
<@858404963382198313> great Lelouch thanks to ur wisdom i did 2 more questions a...
:3
Good job, son
vocal raptor
I gotta find S22 in arithmetical progression. a8+a15=48
<@&286206848099549185> anyone?
cedar kilnBOT
@vocal raptor Has your question been resolved?
silent yew
I gotta find S22 in arithmetical progression. a8+a15=48
What have you tried
silent yew
I gotta find S22 in arithmetical progression. a8+a15=48
Is the answer 528?
vocal raptor
Yeah I just got it
silent yew
Well then
silent yew
I think just like how u did the last question
You should be able to do this one as well
Good luck
inner gate
cedar kilnBOT
inner gate
<@&286206848099549185>
obsidian coral
You have to wait at least 15 minutes before pinging helpers
inner gate
Ok
crimson delta
what is your question?
obsidian coral
Also, all that is false
crimson delta
in the second picture we divided by 0
obsidian coral
crimson delta
in the first we took the sqrt but forgot to take the absolute value
inner gate
Is this correct
obsidian coral
None of it is correct
inner gate
Ok
obsidian coral
It breaks the laws of math
crimson delta
sqrt(x^2)=|x| and not sqrt(x^2)=x
inner gate
Hmm
crimson delta
or worded differently, x^2=y^2 does not mean x=y, it just means x=+-y
inner gate
or worded differently, x^2=y^2 does not mean x=y, it just means x=+-y
Ohh right
cedar kilnBOT
@inner gate Has your question been resolved?
upper swallow
I don't get what I'm doing wrong when I input -3 as X, the answer should be 243/2 but I don't get that
obsidian coral
I don't get what I'm doing wrong when I input -3 as X, the answer should be 243/...
Because you changed the bounds
tribal pier
it looks like you both switched bounds and back-substituted, you only need to do one
you put the U bounds into the X equation
obsidian coral
If you were using -3 to 1 as the bounds, you would keep it in terms of u still
upper swallow
so i'd do (1/6(-3)^6) instead of replacing u with the function?
tribal pier
think of it like this: why did it go from 0 and 2 to -3 and 1 in the first place? you already input x into your equations, now there's only u left
obsidian coral
So if you wanted to use the bounds of -3 to 1, you would use the equation 1/2(1/6(u)^6) because those bounds are specifically for the equation in terms of u
pulsar skiff
swap these
upper swallow
im confused on when to change the bounds and when not too
pulsar skiff
u should be -3 to 1
x should be 0 to 2
as it says in the original problem
since u = 2x - 3
tribal pier
changing the bounds happens when you want to change variables completely and not have to deal with x anymore. it's like "preprocessing" the bounds so that you don't have to get to the end result and swap everything back to be in terms of x at the end
obsidian coral
im confused on when to change the bounds and when not too
Depends on the variable in the equation. If it's in terms of x, you use the x bounds, typically the original ones. If it's in terms of u, then you use the bounds in terms of u, which is the part when you plug in the value for x, to get some u
pulsar skiff
also change bounds in step 1
tribal pier
there's a reason that you're often taught to write down your substitutions, that way you can track exactly what variable each set of bounds "belongs to"
in my calc courses we were always told that if we wanted to use a sub, we had to label the bounds as "x=a" and "x=b" first, so we could track what went where
upper swallow
okay so if im changing the bounds i input the new bounds as u into the equation, if im not replacing them I need to put the function for u back in and use the original bounds right?
livid estuary
does anyone have any good resources for circles at an undergrad level
tribal pier
okay so if im changing the bounds i input the new bounds as u into the equation,...
yes, exactly
upper swallow
does anyone have any good resources for circles at an undergrad level
open your own channel under Math help (avaliable)
tribal pier
you get to choose: change the end equation, or change the bounds. As long as you pick one or the other, not both, you should be fine
upper swallow
okay, that makes so much sense. I've been confused on how that works. Thank you!
tribal pier
okay, that makes so much sense. I've been confused on how that works. Thank you!
if you check out #help-11 you can see a good example of how it works in more crazy cases, and why labeling your substitutions is so important.
cedar kilnBOT
cedar kilnBOT
Available help channel!
pearl elm
Im trying to solve this example
cedar kilnBOT
Im trying to solve this example
pearl elm
This is my attempt
I'm getting the wrong answer, but I can't figure out what Im doing wrong
any help would be much appreciated
cedar kilnBOT
@pearl elm Has your question been resolved?
pearl elm
<@&286206848099549185>
cedar kilnBOT
@pearl elm Has your question been resolved?
cedar kilnBOT
@pearl elm Has your question been resolved?
reef steeple
I'm getting the wrong answer, but I can't figure out what Im doing wrong
looks right
but if its wrong then maybe they want a particular unwinding direction? like clockwise
velvet mortar
looks right
but if its wrong then maybe they want a particular unwinding direct...
Holy hypnosis
cedar kilnBOT
@pearl elm Has your question been resolved?
crimson sedge
How to get the Extremvalue of this following function in relation to the Parameter (a):
crimson sedge
.close
digital quiver
ok this might be a stupid question but how would you do this problem without the use of a calculator
digital quiver
<@144960544086949888>
32 and 4
quiet hazel
does ev ever change if you reroll a die?
cedar kilnBOT
does ev ever change if you reroll a die?
amber ridge
glacial sundial
cedar kilnBOT
glacial sundial
how to solve?
cedar kilnBOT
@glacial sundial Has your question been resolved?
gaunt hamlet
What have you tried?
next thicket
Finding the volume
cedar kilnBOT
Finding the volume
tight herald
What were the notes from class/Resources from your teacher?
tight herald
Area of the base * Height is good