#help-13

428200 messages · Page 521 of 429

tight herald
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So find the area of the base

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Which is a rectangle

next thicket
#

Ok

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spring zealot
#

Can somebody help me calculate this in years?

gaunt hamlet
#

The length of the video?

spring zealot
#

Yeah

gaunt hamlet
#

Well, it's about 67 hours long

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It's not gonna be anywhere close to a year

spring zealot
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Oh wait really

gaunt hamlet
#

Well, the time says 67:34:46. That's 67 hours, 34 minutes, and 46 seconds

spring zealot
#

Oh I’m on mobile so that’s why I don’t see it as 67hrs

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For me it goes all the way to positive to negitive numbers

gaunt hamlet
#

That's odd. I'm on mobile, but the time displays just fine for me

spring zealot
#

Weird

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That’s how it looks for me

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Positive 0 through -0

gaunt hamlet
#

Damn

spring zealot
#

well uh thank you

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I’m going to close this now

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uncut quest
#

hiii, i need help on this question

cedar kilnBOT
uncut quest
#

i’m not too sure if have it right, and it’s worth a lot of points 😅

bold lotus
#

i dont think we can help with exams

uncut quest
#

Oh

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oh ok i see ty

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cedar kilnBOT
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@mental rain Has your question been resolved?

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mental rain
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lament spindle
#

dose someone know how i would find the value of cd

lament spindle
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CD

sonic thistle
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Yeah sty

lament kraken
sonic thistle
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And CYD*

lament spindle
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that they share the same angles

sonic thistle
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No

lament spindle
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that the sides are propotional to each other

sonic thistle
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Nice

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So write the ratios

lament spindle
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YX/YC = YZ/YD

sonic thistle
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Good

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And there is one more

lament spindle
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ZX/DC

sonic thistle
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Yes

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So $\frac{16}{CD}=\frac{XY}{CY}$

wraith daggerBOT
#

Master Oogway

sonic thistle
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But what is xy/cy

lament spindle
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1/2

sonic thistle
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No

lament spindle
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2

sonic thistle
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Yes

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2/1

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Now

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Do you know how to find cd?

lament spindle
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solve

sonic thistle
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Yes

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16/cd = 2/1

lament spindle
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How did you know DC and ZX were parallel

sonic thistle
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We use Thales' theorem

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Do you know that?

lament spindle
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nope

sonic thistle
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Ok

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If YX/YC = YZ/YD

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It mens DC and XZ are parralel

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Ok?

lament spindle
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yeah i see

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and the answer would be 8?

sonic thistle
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,w 16/x=2/1

wraith daggerBOT
sonic thistle
#

Yes

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Its 8

lament spindle
#

ty

sonic thistle
#

Np

lament spindle
#

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elfin condor
#

Can someone help me check if this is done correctly? (method-wise)

elfin condor
#

the question says simplification is not needed

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normal wadi
cedar kilnBOT
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@normal wadi Has your question been resolved?

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@normal wadi Has your question been resolved?

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median summit
cedar kilnBOT
median summit
#

Can someone help with q14

cloud wave
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im a young man that has never opened a math book so can someone explain why is that there?

median summit
#

It’s distributive property but I already asked for help on this channel

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@cloud wave

cloud wave
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shit

cloud wave
median summit
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<@&286206848099549185>

spark igloo
median summit
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Ahhh okok

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@spark igloo I’m still not getting it

spark igloo
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ahh

wraith daggerBOT
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GG・Goof

spark igloo
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use this identity

median summit
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This is what the answer book is saying

cedar kilnBOT
#

@median summit Has your question been resolved?

median summit
#

<@&286206848099549185>

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@median summit Has your question been resolved?

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hardy plover
#

hello

cedar kilnBOT
hardy plover
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What is the resultant of these 2 vectors

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  • I want a fast way to do it on the calculator
crystal raptor
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Find the horizontal and vertical components of E2 using trig

hardy plover
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I tried 3.9*10^-5 angle 90 + 1.8 x 10^5 angle -53.1
but I didn't get the results correct idk why

hardy plover
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this wastes time

crystal raptor
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How does it waste time, its literally how you do it

hardy plover
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ok I solved it with the calculator thanks

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rocky sand
cedar kilnBOT
rocky sand
#

Yh idrk how to proceed

gaunt hamlet
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What have you tried?

rocky sand
gaunt hamlet
#

Remember that 1/sinu = cscu

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The integral is a standard trig integral

rocky sand
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Ok lemme try it

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How did i not think of that smh

rocky sand
thick sorrel
rocky sand
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Do u do a level maths too

thick sorrel
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which page of the book is it in i wanna check it out

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yeah i do

rocky sand
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Page 307

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Exercise 11E challenge question

thick sorrel
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yeah i see it

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oof

rocky sand
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Lol it got me too

thick sorrel
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did you do paper 1 recently?

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which variant are you

rocky sand
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Yep yesterday

thick sorrel
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same here

rocky sand
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What does that mean

thick sorrel
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9MA0 then

rocky sand
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Yh

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How'd u find it

thick sorrel
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it was fine - i wasn't able to do the last question though because i forgot

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i had enough time but i was just stuck

rocky sand
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i ran out of time lol

thick sorrel
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howd you find it then oof

rocky sand
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it was pretty hard but mostly bc i forgot how to do some things

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i missed out 1 question and messed up a few others so not too good

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also everyone was saying that the last question was parametric integration but i did integraiton by parts lol

thick sorrel
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yeah it was integration for parametric

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also the dy/dx question for the velocity of the car messed me up, i wasnt able to get the dy/dx equation

rocky sand
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yh i didnt get that one either

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what grade u aiming for

thick sorrel
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i definitely think i can go for an A*, i practiced really hard for math

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and threshhold for an A* is like, 215 out of 300 if im not wrong (on average)

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wbu

rocky sand
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i was aiming for like an A but i managed my time shitty so i didnt have time for everything so now im just aiming for a B

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its not even like maths is hard its just that i didn't take it seriously until too late but whatever my own fault yk

thick sorrel
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yeah i got it

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you still have a chance for an A though

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all the best for paper 2 and paper 3 if you're doing it, my man^^

rocky sand
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meh i doubt it lol but thanks, good luck to you aswell 🙂

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tribal token
#

I need to find a formula for an (not recursive)

bitter reef
#

you can write $a_n$, then write the $a_{n - 1}$ inside it and so on until you see a pattern

wraith daggerBOT
tribal token
#

that's what they did in the solution but I don't understand this step

cedar kilnBOT
#

@tribal token Has your question been resolved?

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@tribal token Has your question been resolved?

crimson sedge
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raw thicket
#

a theatre has 840 seats. For one performance, the theatre was 75% full. How many people were in the theatre?

buoyant latch
raw thicket
#

1000?

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wait

buoyant latch
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If the theatre can sit 840 people and it was completely full how many people are there

kind blaze
#

I need help

buoyant latch
cedar kilnBOT
#

@raw thicket Has your question been resolved?

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kind blaze
#

I have been trying to solve this many times but still haven’t gotten the right answer

versed fulcrum
#

Khan academy moment

kind blaze
#

🙂

versed fulcrum
#

Do you know what a mean is?

kind blaze
#

Yes

versed fulcrum
#

What is it?

kind blaze
#

You have to add all the numbers and then divide by how many numbers there are

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Right?😟

versed fulcrum
#

That's right

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Can you show me your work process?

kind blaze
#

Alr lemme just get it, I am using a calculator rn

versed fulcrum
#

Your answer must have been erroneous because you forgot to do something.

kind blaze
#

WAIT

versed fulcrum
#

It's not 41

kind blaze
#

I added wrong

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I just realized

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40

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Oh da,m

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damn

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I just got the question right

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It was 10😭

versed fulcrum
#

yay

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nice

kind blaze
#

Well thanks

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For helping

versed fulcrum
#

🙂

#

You're welcome

cedar kilnBOT
#

@kind blaze Has your question been resolved?

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buoyant lichen
#

when rotating around a point that is not the origin

buoyant lichen
#

why would you subtract the shape your rotating by the point instead of add the point to it's coordinates

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ex: point a = [2,3] rotate shape ABCD 90 degrees where a=[2,3] b=[2,4] c=[3,6] d=[5,6] and you subtract [2,3] from each then rotate then add back

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where im thinking you should add [2,3], rotate, then subtract it

simple shale
#

coriolis?

hazy minnow
buoyant lichen
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when you translate it to the origin

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what do you mean

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im trying to get into the nitty gritty of it

simple shale
#

if point is off the origin by a vector

hazy minnow
buoyant lichen
#

why would you add -p instead of p

simple shale
#

you need to add opposite vector to get it into origin

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hence subtraction

buoyant lichen
#

but if the shape hasn't already been shifted, shouldn't you add [2,3] to make [2,3] it's origin

hazy minnow
#

What is [2,3]?

buoyant lichen
#

it's p

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in the example i gave

simple shale
#

if some point a has [2,3]

hazy minnow
#

Ok, you want to rotate a point x around p right?

simple shale
#

then you add [-2,-3] to set it to [0,0]

buoyant lichen
#

well shape or point yea

simple shale
#

and since [-2,-3] = -[2,3]

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you subtract

hazy minnow
#

just have to do is just translate x by adding -p. The map x -> x-p. If x = p we have it’s at the origin after the transformation.

buoyant lichen
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sorry, im trying to get a more inuitive understanding

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your telling me to subtract p but not why that works

hazy minnow
#

Ok, draw a point x.

buoyant lichen
#

ok

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one sec

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let me get a clipboard

hazy minnow
#

Imagine a circle where p is the origin and x is a point on the circle.

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Visualize what’s happens when your translate p to the origin.

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The circle moves along with it.

buoyant lichen
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but why would x be a point on the circle in the first place

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wouldn't it be a point of the circle of the origin

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since it hasn't been shifted yet

hazy minnow
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why are you considering the point of the circle of the origin? We’re trying to rotate around p, x would be moving in a circle with center p. This is what is happening and we are trying to achieve that.

buoyant lichen
#

well

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what does transforming the circle represent

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what step

hazy minnow
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The translation. x -> x-p.

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The whole reason we’re trying to move everything to the origin, is because we have a easy way to rotate around the origin.

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I will try to find additional sources online to explain it better than I am.

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Ok I draw it out, can’t find anything good online.

buoyant lichen
#

ok

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ok i drawed it out

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i think i understand

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not completely but somewhat

hazy minnow
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We’re trying to rotate x around p, that is take x to x’.

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We first translate x to x-p.

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f(x) = x-p, f(x’) = x’-p.

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So we can translate x and the rotate then translate back.

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I hope this was clearer.

buoyant lichen
#

i think i understand

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ill need to do some work on my own to understand

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though that often includes most things tbh

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thanks for the help, i think ill be able to better understand it with ur approach

hazy minnow
#

Definitely. I tell you, I didn’t get this properly the first time I learned it.

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So you will definitely get it.

buoyant lichen
#

alright

#

cya

#

.close

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narrow bison
#

Having trouble setting this one up

cedar kilnBOT
narrow bison
#

This correct?

cedar kilnBOT
#

@narrow bison Has your question been resolved?

narrow bison
#

<@&286206848099549185>

cedar kilnBOT
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@narrow bison Has your question been resolved?

narrow bison
#

<@&286206848099549185>

cedar kilnBOT
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@narrow bison Has your question been resolved?

cedar kilnBOT
#

@narrow bison Has your question been resolved?

narrow bison
#

.close

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crimson sedge
#

How much would a 24ct bullion weigh??

cedar kilnBOT
crimson sedge
#

Btw I’m really tired and I need help :/

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Use unitary method

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im in year 7

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btw

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?

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what is unitary method

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Basically

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oh

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ik what it is

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Use that then

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would i have to get the approximate

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because its not exactly accurate

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Take 9ct ---- 11.16 g/cm^3

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Then what will be 1 ct

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"accurate"?

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idk can you tell me

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what 1ct is

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If you have 9 ct as 11.16 density

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Take 1 ct as x density

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How would u find x now

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idk

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Try once.

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you divide it by 9

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?

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Yes

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But do you know the procedure

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How you reach that

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ye

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11.16 divided by 9

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Yes how do you reach that
I can explain if u want

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and i get 1.24 in density

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yes pls

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Okay

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You see

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Do u know about ratio and proportion?

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no

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Ah

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Okay so

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U have a fraction

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a/b

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Okay?

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yep

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Now think

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Both a and b are same quantities

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Quantities as in

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Same unit

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Like 3 meters / 2 meters

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4 density / 2 density

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2 kg / 4 kg

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And so on

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Okay?

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yes

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You represent such fractions

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As a:b

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"a is to b"

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Which is same as a/b

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But a and b have same quantities

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Okay?

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yes

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Now

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When you want to compare ratios

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Of two different quantities

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Example ratio of weight of sugar in kg is 2:3

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And ratio of surface area of the sugar bags is 8:9

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And the ratio of surface area of sugar bag changes when the ratio of weight in kg changes

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Just an example

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Then we say both ratios are in proportion

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Okay?

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yep

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can you pls give an example of the ratios changing

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Sure

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Say

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Ratio of speeds of two cars

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Is 4:5

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And the distance covered of them is 20:21

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When the ratio of speeds change

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The distance also change

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Like when u have more speed

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More distance is covered

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Okay?

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so if the speeds changed to 6:7

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Distance ratio will also change

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what would the distance covered change to

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It will change to smth

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I have to calculate

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But still you get the notion right

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yes

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Okay

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So you have 9 ct as 11.16 density

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You have 1 ct as x

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How u could use the ratio and proportion as I used earlier

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Here

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@crimson sedge

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Remember 9ct and 1 ct are same quantities

And 11.16 density and x density are same quantities

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Try again

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9:1

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Yes and density?

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11.6:x

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Yes

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Are they in proportion?

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yes

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Why

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because if one changes the other has to change otherwise it will be incorrect?

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Yes

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Good

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Now you can represent 9:1 as 9/1 right

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yes

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Which is 9

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And 11.16:x as?

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11.6/x

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So 9 = 11.16/x

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Solve for x

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Because two ratios are proportional

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Okay?

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yes

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What do u get

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x = ?

#

give me a second

#

Sure

#

Try to separate x on one side

#

And numbers on the other

#

wrt to the "=" sign

#

You need help?

#

yes please

#

Okay

#

Think of any equation as a weight machine with two plates

#

You've seen one right

#

i think

#

oh yeah

#

When u add weight on one side

#

The other one comes up

#

To maintain the equality you add the same weight to the other side too

#

Right?

#

yes

#

So say you have x-5 = 5

#

When you add "5" to the left hand side (x-5)

#

What will happen to the right hand side

#

they become equal

#

How

#

You add 5 to x-5

#

What does it mean

#

idk

#

x-5 + 5

#

Right?

#

"add"

#

thats 10

#

right

#

-5 + 5

#

Think

#

0?

#

Yes

#

So left hand side is x+0

#

Which is x

#

Right hand side is ?

crimson sedge
#

You added 5 on one side

#

On the other what will happen

#

Sorry

#

what happened

#

Let me re frame

#

You added

#

5 on one side

#

The equality is broken right?

#

yes

crimson sedge
#

What will happen to the right hand side then

#

oh so i need to make 9/1 and 11.6/x equal fractions?

#

No

#

oh

crimson sedge
#

We'll go on that after this

#

you need to add five to the right side

#

Yes

#

So x - 5 +5 = 5 +5

#

x = 10

#

Why did we add five?

#

to balance it

#

The main reason?

#

On both sides

#

because they are proportional

#

Nono

#

That's only for ratios

#

oh mb

#

you added 5 on both sides

#

Because you isolated x

#

you had x-5 = 5 right

#

You wanted to find x

#

In the end you got x=10

#

So you isolate numbers around to find x

#

While maintaining the equality

#

Okay?

#

ok

#

So for 9 = 11.16/x

#

How would you isolate or separate x?

#

Remember it's an equation now

#

And use multiplication or division operations here ^

#

i think we have to divide?

#

But we have to find x right

#

yes

#

We want to isolate it

#

From the denominator

#

Yknow what's denominator right

#

yes

#

So how will you remove x from denominator

#

And "bring it up"

#

In the end you always aim to get x = something

#

That's why we isolate x

#

If you multiply x to both sides to maintain the equality

#

In the equation 9 = 11.16/x

#

What will happen

#

9x=11.16?

#

Perfect

#

oh

#

i think i get it

#

That's what I meant to isolate x from the denominator

#

Yes

#

Last step is...?

#

x = ...?

#

Think how will you isolate x here now

#

From 9x

#

You want to extract x

#

In the left hand side

#

so we need to find what times 9 equals 11.16

#

Yes

#

In other words

#

You want to find x

#

How will u isolate x from 9x?

#

Dividing by 9 right?

#

oh yeah

#

we divide both sides by 9

#

Yes

#

To maintain the equality

#

So you have x = 11.16/9 = 1.24

#

yes

#

So 1ct is 1.24 density

#

This is unitary method

#

You find the unit quantity of the quantity you want to find

#

You found unit of ct

#

Where 1 ct is 1.24 density

#

so 24 ct is

#

You wanted to find 24ct

#

yes

#

Yes what is it

#

24 times 1.24?

#

Perfect that is the density

#

so then what is the weight

#

of 24ct

#

Can u send the question pic again

#

The whole question

#

Not cut off

#

I’m just need to do the 24ct part

#

Also 14ct is 23555g

#

In weight

#

And I’m trying to find the weight

#

Of 24ct

#

Then use unitary method for that

#

Alrifht

#

Before we got 1.24 answer of 1ct which is the density

#

If u have 14ct ----- 23555g

#

Find 1ct

#

Then find 24ct

#

24 ct is 40380g

#

,w 23555/14

wraith daggerBOT
crimson sedge
#

,w 1682.5 × 24

wraith daggerBOT
crimson sedge
#

yay

#

Correct 👍

#

tysm

#

Welcome

#

thank you

#

very nice stranger

#

You may close the thread with .close

#

.close

cedar kilnBOT
#
Channel closed

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crimson sedge
#

@fallow steppe

crimson sedge
cedar kilnBOT
#
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crimson sedge
#

<@&268886789983436800>

#

pls ban him <@&268886789983436800>

#

thank youi

buoyant latch
#

What a shame wasting this valuable resource space

cedar kilnBOT
#

@echo herald Has your question been resolved?

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solid mango
#

Using logic, do you equivalent the () then inverse using left hand side?

wooden harness
#

when you negate a bracket, you negate everything inside

#

including the or operator

#

well, it's not exactly like and is the negation of or, but you can think of it that way

cedar kilnBOT
#

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idle trout
cedar kilnBOT
modern compass
#

They factored it

obsidian coral
#

Make x = tan(x/2)

#

So the equation looks like 0 = 5x^2 +24x - 5

#

Then factor that, plug back in tan(x/2)

idle trout
#

how

obsidian coral
#

What do you mean how?

idle trout
#

where did the 24 go

obsidian coral
#

Do you know how to factor?

idle trout
#

ye

#

i think so

obsidian coral
#

Like factoring 5x^2 + 24x - 5

#

No

#

Not factoring by finding the GCF

idle trout
#

gcf?

#

as in a quadratic?

obsidian coral
#

Greatest common factor

idle trout
#

which is

#

is it like 5*(-5)

obsidian coral
#

On this lesson on factoring trinomials, you will learn how to factor a trinomial when a is not 1. When the leading coefficient is greater than one, the factoring process (the AC method) is a bit different--let's see why!

For more MashUp Math content, visit http://www.mashupmath.com and join our free mailing list! :)

This lesson answers the que...

▶ Play video
#

This algebra video tutorial shows you how to factor trinomials in the form ax2+bx+c when a, the leading coefficient, is not 1. It shows you how to use the ac method to factor such trinomials that contain 3 terms which involves factoring polynomials by grouping. This video contains plenty of examples and practice problems for you to work on. E...

▶ Play video
idle trout
#

ye i know that

obsidian coral
#

That's what's it does with 5x^2 + 24x - 5

#

You factor

idle trout
#

what multiples to give -25

#

and adds to give 24

obsidian coral
#

Yes

idle trout
#

oh

#

-25*1

#

25-1

obsidian coral
#

No

idle trout
#

wait

#

so factors 25

#

and -1

#

as in roots?

obsidian coral
#

No

#

Not roots

idle trout
#

oh yea the x

#

like tan x represents x

obsidian coral
#

25 and -1 aren't the roots

idle trout
#

the opposite sign

obsidian coral
#

It's the factors that multiply to -25 and add to 24

#

They're still not the roots

idle trout
#

they are the values for tanx

#

?

obsidian coral
#

No

idle trout
#

as in you factorise them

obsidian coral
#

I suggest you review factoring

idle trout
#

like you have to plug 25x and -x into the equation

#

and then factorise then group

#

then NFL

#

(null factor law)

obsidian coral
# idle trout

Because you're using 25 and -1 to get it into the line 2, that you wrote

idle trout
#

then find what and -

#

got it

#

thank you so much @obsidian coral

#

i appreciate your help

#

sorry for my wrong use of terminology/understanding

#

thank you

#

.close

cedar kilnBOT
#
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cedar kilnBOT
#
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lost parrot
#

why does it need to be a proper subset and not just a subset?

cedar kilnBOT
#

@lost parrot Has your question been resolved?

cedar kilnBOT
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mellow solstice
#

Help

cedar kilnBOT
devout radish
sonic thistle
#

,rotate

wraith daggerBOT
sonic thistle
#

do you know pythagorean theorem?

mellow solstice
#

Gotvit

#

Yup I did it

#

But

#

Now

sonic thistle
#

,roatate

#

,rotate

wraith daggerBOT
sonic thistle
#

bro

#

how did you go from pythagorsas to this?

#

😮

mellow solstice
#

I think its C

#

Lol

#

Dw

cedar kilnBOT
#

@mellow solstice Has your question been resolved?

shut reef
cedar kilnBOT
#
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Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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sudden raven
#

I have to find the next 3 numbers in this list but i really dont know where to start
1002 1330 1754 2253 2852 3588 4472

velvet mortar
#

,calc 1330-1002

wraith daggerBOT
#

Result:

328
velvet mortar
#

,calc 1754-1330

wraith daggerBOT
#

Result:

424
sudden raven
#

328
424
499
599
736
884

velvet mortar
#

,calc 1330/1002

wraith daggerBOT
#

Result:

1.3273453093812
velvet mortar
#

,calc 1754/1330

wraith daggerBOT
#

Result:

1.3187969924812
foggy mauve
#

BRO JUST USE A CALCULATOR

velvet mortar
#

Yeah it's neither arithmetic nor geometric series

foggy mauve
#

i think i found the first two digits

#

10, 13, 17, 22, 28, 35, 44
do u not see a pattern?

sudden raven
#

3 4 5 6 7 9

foggy mauve
#

first two digits are 53

#

did u understand how i did it.

#

give me some time for the next 2

sudden raven
#

i dont

foggy mauve
#

look at the first two digits of each number

velvet mortar
#

Oh nice

foggy mauve
#

and write them down

#

there's a pattern

sudden raven
#

but i dont see anything else

velvet mortar
#

Yeah that's the pattern

foggy mauve
#

:|

velvet mortar
#

Difference of the first two digits increase by 1 per term

sudden raven
foggy mauve
#

35 44

#

wait

#

28 35 sorry

#

waitt

#

u got a point

#

hmm wait

velvet mortar
#

,calc (1330/1002) - (1754/1330)

wraith daggerBOT
#

Result:

0.0085483169000344
velvet mortar
#

,calc (3588/2852)-(4472/3588)

wraith daggerBOT
#

Result:

0.011687704534829
sudden raven
#

left are the differences and right are the differences between the differences

#

it doesnt even grow faster everytime

#

cuz 75 is lower than 96

#

idk if i make sense

foggy mauve
#

why is this hard

#

can i see the question on the paper

sudden raven
#

well its a website where you have to guess different numbers

#

and these are the numbers that are guessed correctly by others

#

and no one can find the pattern

foggy mauve
#

can u send me the link if u can i am interested

velvet mortar
#

Have you tried summon

#

Summing

foggy mauve
#

yes

velvet mortar
#

,calc 1002+1330

wraith daggerBOT
#

Result:

2332
velvet mortar
#

,calc 1330+1754

wraith daggerBOT
#

Result:

3084
velvet mortar
#

,calc 1754+2253

wraith daggerBOT
#

Result:

4007
dusty hazel
#

I see 1330 is near 1331 and 1754 is near 1728. And 2253 is near 2197 etc.

#

Goodluck.

velvet mortar
#

,calc 1738/1331

wraith daggerBOT
#

Result:

1.3057851239669
foggy mauve
#

hm

dusty hazel
#

10^3 = 1000
11^3 = 1331
12^3 = 1728
13^3 = 2197
Even though this might not be getting anywhere. I just dropped another idea for you to try since that's what you were doing.

velvet mortar
#

,calc 2197/1738

wraith daggerBOT
#

Result:

1.2640966628308
spark igloo
#

I am thinking that the numbers in series might be sum/difference of two squares/cubes

velvet mortar
#

2253-2197

#

,calc 2253-2197

wraith daggerBOT
#

Result:

56
dusty hazel
#

Looks neat ngl 7*8

#

1002 - 1000 = 2 = 1*2

foggy mauve
#

and here comes the problem

#

-1

#

like -1^3?

dusty hazel
#

Lol.

spark igloo
#

,calc 1728+2197

wraith daggerBOT
#

Result:

3925
dusty hazel
#

,calc 141414

wraith daggerBOT
#

Result:

2744
dusty hazel
#

,calc 2852 - 2744

wraith daggerBOT
#

Result:

108
foggy mauve
#

it probably has something to do with your cube theory

dusty hazel
#

I think so.

spark igloo
#

,calc 1754+2253

wraith daggerBOT
#

Result:

4007
foggy mauve
#

it can't be a coincidence that they are this close

spark igloo
#

,calc 4007-3925

wraith daggerBOT
#

Result:

82
spark igloo
#

Sum of first 2 number is 10^3+11^3

sudden raven
#

it can be possible you have to use those ratings

foggy mauve
#

this shit hard

dusty hazel
spark igloo
velvet mortar
spark igloo
#

And the sum of next 2 number is 12^3+13^3+1^2+3^2

dusty hazel
#

Lol

#

First two is 10^3 + 11^3 + 1^2 then.

spark igloo
#

,calc 14^3+15^3+1^2+3^2+5^2

wraith daggerBOT
#

Result:

6154
spark igloo
#

,calc 2852+3588

wraith daggerBOT
#

Result:

6440
spark igloo
#

Ahh close

dusty hazel
#

Scheisse

spark igloo
#

,calc 6440-6154

wraith daggerBOT
#

Result:

286
foggy mauve
dusty hazel
#

Hmm.

foggy mauve
#

waitiwiaiiqiefaizae

#

let me take a picture of my shit wait let me calculate

#

nvm

#

i found a really ocmplext pattern

#

which says that the two first two digits of the next number are 81.

spark igloo
#

Umm what

foggy mauve
#

let's put the first two digits
10 = 2x5
13 = 2x6,5
17= 2x8,5
...
if we continue this we will have 2x40,5 = 81

#

a bit hard for a pattern

#

irregular

spark igloo
#

Hm

half chasm
#

hi! I got sent here. Looks like you guys do not have all the info you need. The pattern is for a fifa simulation website. long story. anyways, it is confirmed that you need to use a number on the card to find the next number. the full cards are here:

foggy mauve
#

sorry the next number 66

#

are u kidding

spark igloo
half chasm
#

Been working on it for a while already. I have received some more hints already but Im not sure how emotionally involved this server is so I will spoiler it:

||The pattern is: (previous number) - (A) + f(B) + f(previous number)||

lucid edge
#

B x z

half chasm
#

dont know. might be a constant, might be a number on the card. f is an unknown function, could be as easy as a multiplier

cedar kilnBOT
#

@sudden raven Has your question been resolved?

cedar kilnBOT
#

@sudden raven Has your question been resolved?

cedar kilnBOT
#
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#
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Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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opal sierra
#

In this video the guy says x is approaching -6 but couldn't x be approaching anything?

cosmic steppe
#

Wdym x is approaching -6

tropic oxide
#

what video and what problem is being solved?

cosmic steppe
#

Did he mean as x approaches 5, the limit is -6?

tropic oxide
#

@opal sierra

cedar kilnBOT
#

@opal sierra Has your question been resolved?

tropic oxide
#

ah yes, the correct response to someone asking a clarifying question is to completely fucking ghost them

shut reef
#

I love it when they post a question and answer years later

cedar kilnBOT
#
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solar dagger
#

quick question guys, why isn't 2^X in Big-O(X^2) by definition? i can't seem to understand the def x.x

solar dagger
#

Big-Oh definition in Wikipedia

dire geode
solar dagger
#

thx

#

will take a look on that

#

i'll close this in the meantime, tysm!

#

.close

cedar kilnBOT
#
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crimson sedge
cedar kilnBOT
crimson sedge
#

so um

#

os this 60 ?

#

is

versed fulcrum
#

You using degrees or radians?

crimson sedge
#

yo so um

#

idk what that is

#

im in year 9

#

i have my pc1's soon

#

so i thought i should revise

upbeat dune
#

Whats the issue tho ?

crimson sedge
#

like

#

i need to know if i got it wrong

#

to know if i got the formula down

upbeat dune
#

The answer is indeed 60 degrees

crimson sedge
#

lets goooo

#

.close

cedar kilnBOT
#
Channel closed

Closed by @magic swallow

Use .reopen if this was a mistake.

crimson sedge
#

can anyone send me a good place to revise for my pc1's

#

year 9

#

higher

#

south london

cedar kilnBOT
#
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obtuse basin
#

I'm going through beginners calc and this problem is about instantaneous velocity at some t

obtuse basin
#

The thing is, I can't figure out what h is supposed to be

#

The book describes it as some small change in time

#

And to my understanding, lim h->0 means that as you get closer and closer to some arbitrary moment in time, it approaches the expression on the right side of the limit

balmy apex
#

that's the definition for the derivative btw

balmy apex
#

h is the x

#

the top stuff is the y

obtuse basin
#

wrt?

balmy apex
#

with respect to

obtuse basin
#

Ah

#

This is a bit confusing

#

So given position and a time for that position, you can find the velocity of how fast some point had to travel to get to that position in that time by inventing a variable h, and then you get your equation in terms of that h, then do some other random stuff and then substitute 0 in for h after simplfying?

#

It just seems so arbitrary

#

Oh, I see what it's doing

#

It's basically taking t and adding a number that is close but not equal to 0 that gets closer and closer to 0 and seeing what value you get for your function

#

So I could find it by doing (f(t+0.1) - f(t)) / ((t + 0.1) - t)

#

And doing that also for 0.01 and 0.001, and so on.

#

.close

cedar kilnBOT
#
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tired glen
#

Hey all, I'm looking at how to get from one to another, can someone please help?

versed fulcrum
#

Why is it not

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$$2-4\left(1-2^n\right)$$

wraith daggerBOT
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AirToastie

tired glen
#

maybe i should've use = instead of ->

tired glen
versed fulcrum
#

This might help you

tired glen
#

i did watch that but id didnt really help me that much

dire geode
#

Figure out your r from their general formula

cedar kilnBOT
#

@tired glen Has your question been resolved?

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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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reef field
#

How would I continue to solve 13 b ??

cedar kilnBOT
obsidian coral
#

$\sqrt{y^2} + 1 \neq y + 1$

wraith daggerBOT
#

dldh06

obsidian coral
#

My suggestion, make y^2 + 1 not in the denominator

versed fulcrum
obsidian coral
versed fulcrum
#

$$\frac{1}{\sqrt{y^{2}}+1}\ne\frac{1}{y+1}$$

wraith daggerBOT
#

AirToastie

versed fulcrum
#

?

reef field
#

Would I have to multiply it to take it out?

obsidian coral
obsidian coral
versed fulcrum
obsidian coral
#

I only mentioned the denominator

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I didn't write fraction

versed fulcrum
obsidian coral
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Notice how my y^2 + 1 is just the denominator only

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It's what I stated already

versed fulcrum
#

uhhh

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Ohhh

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I didn't see his work process until now

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Yeah that's illegal

reef field
#

Ohhh ok I got the answer

versed fulcrum
#

Ayyy nice

reef field
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I was struggling with this one lol

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Thanks

cedar kilnBOT
#

@reef field Has your question been resolved?

cedar kilnBOT
#
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Ask your math question in a clear, concise manner.
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After 15 minutes, feel free to ping <@&286206848099549185>.
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versed fulcrum
#

Can anyone help me understand the squeeze theorem?

versed fulcrum
#

And maybe some examples?

crystal raptor
#

What exactly don't you understand

versed fulcrum
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$$\lim _{x\to :0}\left(\frac{\sin \left(x\right)}{x}\right)$$

wraith daggerBOT
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AirToastie

versed fulcrum
#

Why this equals 1

high coyote
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$\sin x\leq x\leq \tan x$ in $(0, \pi/2)$

wraith daggerBOT
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jnkena

high coyote
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$1\leq\frac{x}{\sin x}\leq \cos x$

wraith daggerBOT
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jnkena

high coyote
#

$\frac{1}{\cos x}\leq\frac{\sin x}{x}\leq 1$

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But

versed fulcrum
high coyote
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$\lim_{x\to 0} \cos x = 1$

wraith daggerBOT
#

jnkena

high coyote
versed fulcrum
#

Uhhhh

versed fulcrum
#

and less or equal to tan(0)?

wraith daggerBOT
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jnkena

high coyote
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But the inequality is true in (0,2π)

versed fulcrum
#

$$\lim _{x\to 0}\left(\frac{1}{:cos\left(x\right)}\right)$$

wraith daggerBOT
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AirToastie

versed fulcrum
#

Equal 1?

high coyote
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Yes

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cos(0)=1

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1/1=1

versed fulcrum
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Oh wait that was a stupid question

high coyote
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You have that sin(x)/x is bigger and less than functions which tend to zero as x → 0 so it must tend to 0 too

versed fulcrum