help-13

[fading summit]

:/

[cedar kiln]

@fading summit Has your question been resolved?

[west wyvern]

How long will it stay in the air?

[west wyvern]

Remember, the answer to this doesn't depend on the horizontal velocity at all

If you threw something straight up with velocity 5, how long does it take to fall back down?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bright sorrel]

how do I factor the left side of x^5+8x^4-x-8=0 so that I can find the roots?

[bright sorrel]

x^5+8x^4-x-8=0
x^5-x+8x^4-8=0
x(x^4-1)+8(x^4-1)=0
(x^4-1)(x+8)=0

right?

[buoyant latch]

yep

[bright sorrel]

so x^4=1 and -1

and -8

is also a root

I didn't factorize x^4-1

[buoyant latch]

?

[bright sorrel]

well it's an even number (-1)(-1)(-1)(-1)

meaning (-1)^4=1

so -1 and 1

is what I guess

[buoyant latch]

(x+8)(x^2+1)(x-1)(x+1)

[bright sorrel]

hmm

good one

you can factorize x^2+1 as well

[obsidian coral]

No you can't

[bright sorrel]

a^2+b^2=(a-b)(a^2+ab+b^2)

[buoyant latch]

but why

no point doing so

[obsidian coral]

This is for cubes

[buoyant latch]

oh yeah

that too

[bright sorrel]

yeah but wouldn't it work too?

[obsidian coral]

Because it doesn't

You have x^2

That identity is for cubes

[buoyant latch]

the square equivalence is a^2 + b^2 = (a+b)^2 - 2ab

but then why would you do that

[bright sorrel]

so just leave it at that?

[buoyant latch]

from this x = -8, 1, -1

[bright sorrel]

yeah

[buoyant latch]

and there are complex sols

[obsidian coral]

FYI, zero product property, you can just do x^2 + 1 = 0

[buoyant latch]

in x = i and -i

[obsidian coral]

Solve for x

[bright sorrel]

ill go with this ig

care if I keep this open for other problems?

of such nature?

[obsidian coral]

That's just (x^4 - 1) expanded more

[buoyant latch]

u can jsut open a new one if u wanted

[bright sorrel]

ight

.close

[cedar kiln]

Channel closed

Closed by @bright sorrel

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[twin coral]

how to do i part c? do i use cross product?

[reef steeple]

yes

[twin coral]

what do you do with the answer you get?

[reef steeple]

magnitude

[twin coral]

the magnitute is the area?

[reef steeple]

yes

[twin coral]

.close

[cedar kiln]

Channel closed

Closed by @twin coral

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stuck solar]

can you check if this trigonometry sum is correct or not?

[cedar kiln]

@stuck solar Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ornate salmon]

what is the altitude of a right triangle? (curious bcos ive gotten different answers for this)

[ornate salmon]

(like the leg, or what not a specific number)

haha sorry this doesnt make much sense ;-;"

[obsidian coral]

Do you have an example of what you mean?

[ornate salmon]

like which part

/line

is it the middle line that connects the vertex to the hypotenuse?

or like

a leg

or what not

[cosmic steppe]

Altitude come from the right angle

The legs themselves are altitudes

[ornate salmon]

so they btoh are?

[cosmic steppe]

Pretty much lol

[ornate salmon]

like the ones that are perpendicular

[cosmic steppe]

I mean if you're talking about one inside a triangle

[ornate salmon]

does hte middle line have to do with any thing?

[cosmic steppe]

Then it comes from the right angle

And perpendicular to the hypotenuse

[ornate salmon]

wait wiait wait

the one perpendicular to the hpotneuse

is that

the

alittude?

altitude?

[cosmic steppe]

Yes

[ornate salmon]

not the legs (b/h)

?

[cosmic steppe]

They can be

Triangles have 3 altitudes

[ornate salmon]

oh

[cosmic steppe]

The legs technically can be altitudes

[ornate salmon]

right

[cosmic steppe]

I'm pretty sure by stating that the legs are altitudes you'll start a riot

[ornate salmon]

oop

do like

any line from the vertex to the hypotenuse is a alittude??

altitude

[cosmic steppe]

No

Altitudes always make right angles

And are perpendicular to a segment from its respective opposite vertex

[cedar kiln]

@ornate salmon Has your question been resolved?

Channel closed

Closed by @ornate salmon

Use .reopen if this was a mistake.

[ornate salmon]

oh i see thank you so much

!!

.close

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[coarse lance]

A plant mail order company adds 5 tulip bulbs free of charge to every order. These are taken at random
from a large, constantly refilled bucket and packed. The bucket contains
bulbs which produce 50% red, 30% yellow and 20% violet tulip flowers.
2.1 Mrs. X has received a package with such a free package. Calculate the
probabilities for the following events:
A: all five bulbs form yellow flowers.
B: none of the bulbs form red flowers.
C: there is at least one flower of each colour.
D: four bulbs form red flowers and one forms purple flowers.

I am having trouble solving C

Normally Id calculate it by saying that P(C) = 1 - P(none of 1 or none of 2 colours), but according to the solutions this is wrong

Another (more strenous) solution I came up with is calculating P(C) = 0.5 * 0.3 * 0.2 * (the possible combinations of the 5 seeds). I did this and got 42 possible combinations, but that is impossible cause then P(C) would be over 1
I got this number by saying that a combination may look like this : ryvxx or rxyvx with x being a random color (since it doesnt really matter which one is represented multiple times)

It would be cool if somebody could tell me

• What I did wrong with the first approach
• What I did wrong with the second approach
• What is the correct approach

Thanks in advance

[cedar kiln]

@coarse lance Has your question been resolved?

[coarse lance]

<@&286206848099549185>

[coarse lance]

<@&286206848099549185> plz

[amber ridge]

could you use generating functions?
I really don't know but I heard they are a powerful tool.

[cedar kiln]

@coarse lance Has your question been resolved?

[coarse lance]

I dont know the term "generating functions" actually

so I assume we didnt learn that

[coarse lance]

Pls dont close the ticket while Im asleep

[cedar kiln]

@coarse lance Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fair geyser]

1 - P(none of 1 or none of 2 colours) is fine, i assume you made a mistake in calculating

[fair geyser]

.close

[cedar kiln]

Channel closed

Closed by @fair geyser

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[steep umbra]

so how do you go about turning this into partial fractions?

[livid hound]

since the degree of the numerator is higher than the denominator, start with long division

[steep umbra]

im getting 3 as remainder?

[livid hound]

yes

and what was your quotient

[steep umbra]

x - 1

[livid hound]

yes

[steep umbra]

do i write it as mixed fraction?

[livid hound]

I suppose you could call it that

[steep umbra]

so its going to be x-1 3/x+1

sorry idk latex

[livid hound]

no

bad notation

$x-1 \red{ + } \frac{3}{x+1}$

[wraith dagger]

ℝamonov

[livid hound]

forget my comment about mixed fractions, they just suck.

[steep umbra]

👍

thanks for your help

.close

[cedar kiln]

Channel closed

Closed by @steep umbra

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[drowsy stump]

Really stupid math question

Does xy^2 mean x^2y^2 or just the y is affected?

[livid hound]

as written the power only applies to the y

from order of operations

if there were parentheses,
(xy)^2 then it'd be x^2 * y^2

[drowsy stump]

Thank you

Im just bad at math lol

.close

[cedar kiln]

Channel closed

Closed by @drowsy stump

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[upper swallow]

question c

[upper swallow]

I don't understand how they got to the answer 4/3 pi r^3

[cedar kiln]

@upper swallow Has your question been resolved?

[grizzled dome]

Generally, in a volume of revolution problem like this ($y$ is a function of $x$, and you're revolving around the $y$-axis), you start with an integral of the form $\int_a^b \pi y^2 dx$.

[wraith dagger]

daveamayombo

[upper swallow]

yep I'm okay with that bit. Just when I did it I ended up with a very different answer

[grizzled dome]

Ah! The problem here is that r is just a constant. You don't need to (and definitely shouldn't) take an anti-derivative for the r^2 part.

Excuse me, misspoke a little. Should have said: you should take an anti-derivative of r^2 with respect to x.

[upper swallow]

oh okay, should I be removing r before adding pi and squaring f(x)?

[grizzled dome]

I'd start with: what is $\int r^2 dx$, where $r$ is just a constant?

[wraith dagger]

daveamayombo

[upper swallow]

1/3 r^3?

[grizzled dome]

It looks like it should be. But in this problem r is a constant... it's just a number, and doesn't depend on x. Kind of like asking what is $\int 3 dx$.

[wraith dagger]

daveamayombo

[grizzled dome]

And I'll answer that one: $\int 3dx = 3x$ (ignoring the plus-a-constant stuff). So, if $r^2$ is a constant (like 3), what is $\int r^2 dx$?

[wraith dagger]

daveamayombo

[upper swallow]

(r^2)x

[grizzled dome]

Yeah, exactly!

So, in the step after $\pi \int_{-r}^r (r^2 - x^2) dx$, you did everything right except you put $r^3/3$ instead of $r^2x$.

[wraith dagger]

daveamayombo

[upper swallow]

ah okay that makes sense, so r^2x would become (r^2)x^2/2?

[grizzled dome]

Nope, at that point you've already taken the integral.

[upper swallow]

oh right

pi [(r^2)x - 1/3x^3]?

[grizzled dome]

Exactly. And you have to evaluate that from -r to r (i.e. plug those in for x).

[upper swallow]

oh I see now, thank you so much!

[grizzled dome]

👍

[upper swallow]

.close

[cedar kiln]

Channel closed

Closed by @upper swallow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[prisma gulch]

What part do you not understand or need help on?

[sullen cedar]

Answer

[cedar kiln]

@sullen cedar Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wary scroll]

Tried expanding the denominator

I also tried dividing numeratoe and den by sin x

[amber ridge]

what if you just split the fraction into 2 and integrated separately

[wary scroll]

How?

[amber ridge]

sin(x)/thing - xcosx/thing

[wary scroll]

Sinx/x^2+xsinx

Can't go ahead this

[amber ridge]

try the xcosx part then, maybe it will get somewhere

[tawny warren]

yes split the integral

and cancel the x

[wary scroll]

Cos x/x+sinx

Then?

Can't proceed

[amber ridge]

now what if you did u=x+sin(x)

[tawny warren]

yes now add and sub 1

[wary scroll]

X+sinx -x -cosx

Right?

Ok

Got it thanks everyone

.close

[cedar kiln]

Channel closed

Closed by @wary scroll

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cedar kiln]

Channel closed

Closed due to the original message being deleted

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[primal sandal]

I'm reading a physics books. In it they just started introducting spherical coordinates

[crimson delta]

I think they just multiplied everything by r^2 ?

[primal sandal]

i don't understand where the r^2 went too in the second line

[primal sandal]

why would they do that? im not that strong math wise

[crimson delta]

it's one less thing to worry about

[primal sandal]

because V is independent of phi shouldn't the last part of the equation in the first line just disappear?

[crimson delta]

the RHS is 0 so it doesn't matter if you multiply it by something

[primal sandal]

oh I see

that makes sense

thank you for the very quick response

[crimson delta]

from the symmetry the third term vanishes

[primal sandal]

yeah

[crimson delta]

so they did two steps at once

[primal sandal]

okay I understand, thank you so much, have a nice day

[crimson delta]

u2

[primal sandal]

.close

[cedar kiln]

Channel closed

Closed by @primal sandal

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[open agate]

GUYS
I NEED HELP

[open agate]

DESPERATE

How did this guy got -23 here

PLS HELP.

I APPLIED THE P2K ALG I DIDNT GET -23

HOW DID THIS mAN get -23..

HELP

I GOT 1440 NOT -23

HELP

[crystal raptor]

Yo calm down a bit

[open agate]

WTF

NAH G I ASKED WAITED 3 hours No 1 helped me bro Im crying

Pls Hellp Sir... Anyone.

Pls Sir. I got 1440 not -23 what did i do wrong

help

I am desperate

[silent yew]

bruh

[open agate]

Bro ... whats the point of u saying bruh

[silent yew]

Why do u need it so fast

[open agate]

I need help man Im tryna implmeent the midpoint ellpse algoirthm

Bro it's bad

[silent yew]

R u giving an exam?

Or a test?

[open agate]

No

I just wanna know why I got wrong answer

I literally copied the P2K equation... substituted it correctly I get 1440

Pleasehelp

any math experts

if anyone wants more details tell me... if ur willing to help

ok I will rephrase this

I am making an app and I want to add an ellipse tool, for this I am looking a midpoint ellipse algorithm, I have figured out half of it, I just want to figure out the second half

For the second help, there is this equation called P2k

This is how it looks like

For this P2K algorithm, he got -23 as you can see here

when I substituted the right parameters, I got 1440

I am confused why I got 1440

if the bot asks if m yquestion is answered, I say No.

[cedar kiln]

@open agate Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

solve 5/7 + 2/6

[left parrot]

FR?

[tropic oxide]

we don't do your homework here

if you just want answers go to wolframalpha or chegg or symbolab or wherever else

[left parrot]

doesn't discord have 13 yo policy or smth? xD

[crimson sedge]

Please help I don't know how to do it

[tropic oxide]

do you know how to add fractions?

[velvet mortar]

f moment

[crimson sedge]

[crimson sedge]

no

are u like 7 yo?

[tropic oxide]

http://lmgtfy.com/?q=how+to+add+fractions

[crimson sedge]

I am 13 and very bad with math

[crimson sedge]

For all those people who find it more convenient to bother you with their question rather than to Google it for themselves.

[crimson sedge]

toooo bad at match

[tropic oxide]

no need to be unnecessarily mean like that.

[crimson sedge]

ok mb

srry

[velvet mortar]

bro this is a kid

[crimson sedge]

i will not belive that its a 13 yo

tho

[fresh mulch]

well maybe he is?

[left parrot]

maybe he said cuz... :D

[crimson sedge]

ya

[fresh mulch]

y’all are supposed to be helping him, not berating him because of his math skills 😭😭

[left parrot]

13 yo means grade 8 I guess..? at that age we used to do basic algebra and all, fractions are taught maybe at grade 3-5

[fresh mulch]

yea i know, but there’s no way to prove whether he’s 13 or not regardless

it’s ur word against his

[crimson sedge]

ann has given the proper response

[left parrot]

come on man I didn't come to argue 😭

[crimson sedge]

no ** rigorous ** proof ig

Please I don't know the process of getting the answer 😭

[fresh mulch]

alright charlie

5/7 + 2/6

you need to find a common denominator

do you know what that is?

[crimson sedge]

no

[fresh mulch]

the denominator is the bottom half of the fractions

so the left side of each one

[crimson sedge]

i know that yes

[fresh mulch]

okay

so what are the bottom halves of each fraction?

[crimson sedge]

7 and 6

[fresh mulch]

yes

so now

you have to find a number that both 7 and 6 fit into

by that i mean

a number that both 7 and 6 multiply into

can you do that?

[crimson sedge]

how can i find?

[fresh mulch]

well

one of the ways you can do that is by multiplying 6 by 7

because that way both are multiples of 42

do you understand?

[crimson sedge]

6 by 7 is 42 yes

[fresh mulch]

okay so now

if you multiple 6 by 7 on the first fraction

it becomes 5/42

but

you have to multiple the top number also by 7

to make it even

[crimson sedge]

you mean 5 by 7 and 6 by 7?

[fresh mulch]

nope

oh

no yeah

so

the top has to be

5 by 7

and the bottom has to be 6 by 7

so yes

what is the first fraction?

[crimson sedge]

5/7

[fresh mulch]

yes but what if you multiple both numbers by 6

[crimson sedge]

35/49

[fresh mulch]

*by 6 i mean

srry

what if you multiple 5 and 7 by 6

u get 30/42

and then

[crimson sedge]

oh right

[fresh mulch]

that’s the first fraction

the second fraction

you have to multiply both numbers by 7

so what’s 2/6 if you multiply both numbers by 7?

[crimson sedge]

second fraction is 2/6

21/42

[fresh mulch]

nice

so now you have a common denominator for both

30/42 + 21/42

[crimson sedge]

yes

[fresh mulch]

now that both bottoms of the fraction are the same

do you know how to get the answer?

[crimson sedge]

no

[fresh mulch]

okay#

[crimson sedge]

what do I do now?

[fresh mulch]

you have to add

both top numbers

so what is that?

you have to add both of the tops of the fraction together

[crimson sedge]

30+21?

[fresh mulch]

yes

[crimson sedge]

41

[fresh mulch]

yup

and the bottom of the fraction stays the same

so what’s the answer?

[velvet mortar]

51*

[fresh mulch]

*51

[crimson sedge]

51/42 + 51/42

[fresh mulch]

u only need one of them

because it’s the answer

so 51/42 is ur answer

[crimson sedge]

but what happened to the other one?

[fresh mulch]

no because

likewise how 1 + 2 = 3

30/42 + 21/42 = 51/42

ur adding both fractions together

to get the answer on the other side

[crimson sedge]

ohhhh

the bottom parts are comon that whuy

[fresh mulch]

yes

[crimson sedge]

so 51/42 is the final answer?

[fresh mulch]

yes

unless you have to turn it into a mixed number

[crimson sedge]

mix?

[fresh mulch]

yeah

do you have to?

[crimson sedge]

the question asked me to solve

[fresh mulch]

okay then ur good

don’t worry about it

if you need extra math help you should ask your teacher or mom probably

discord math servers can only do so much

[crimson sedge]

ok thanks but I have a question

[fresh mulch]

yeah?

[crimson sedge]

Do we always multiply the bottom numbers?

like we did for 6 and 7

[fresh mulch]

if the equation has multiplication then yes

because you’re trying to find the common bottom number

but if they’re already the same

like 1/6 + 3/6

you can skip that step and just add the top numbers

[crimson sedge]

ok thanks again

[fresh mulch]

no worries

[velvet mortar]

cringe to watch this one mate

[left parrot]

@fresh mulch appreciate the effort 🛐

[velvet mortar]

is your school that bad?

[crystal raptor]

Cut them some slack, they literally were scared to ask a question earlier bc they said they get bullied for being bad at maths

[cedar kiln]

@crimson sedge Has your question been resolved?

[velvet mortar]

To be honest even the biggest math professors sometimes forget the basic operations

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dark olive]

for v

I know that x=24t so x/24 =t

and y= 7t-4.9t^2, so when i sub in t expression: y= 7x/24 -4.9x^2/576

but what do i do next

[cedar kiln]

@dark olive Has your question been resolved?

[cedar kiln]

@dark olive Has your question been resolved?

[velvet mortar]

what velocity is v here?

[silent yew]

Like between Math and physics is so blurr

39% doubts on here are phy

[dark olive]

the question v

[velvet mortar]

where are you starting from?

like which equation?

[dark olive]

y= ut + 1/2at^2

[velvet mortar]

take 0.7x/576 common and you prove it

I am not sure what you arer struggling with here

[dark olive]

i did that

read my text

i got up to y= 7x/24 -4.9x^2/576

but now i’m stuck

[velvet mortar]

yes i know no I factor 0.7x/576 out of 7x/24 -4.9x^2/576

[cedar kiln]

@dark olive Has your question been resolved?

[cedar kiln]

Channel closed

Closed by @dark olive

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[nimble basalt]

Have I answered these questions correctly? Looking for clarification

[nimble basalt]

<@&286206848099549185>

[willow island]

yes
no
no

[cedar kiln]

@nimble basalt Has your question been resolved?

Channel closed

Closed by @nimble basalt

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[spice hazel]

hey. what is the difference between this 2 formulas

[spice hazel]

i mean

in spanish is called Teorema de Bayes

and its mean to be the same

but i dont understand why in the first you dont have to multiplicate but in the second you have to

[crimson delta]

well in the first it is $P(A\cap B)$. in the second it is $P(A|B)$ (I swapped the variables). that is a difference

[wraith dagger]

Denascite

[spice hazel]

i mean

i see

but

its meant to be the same

you know

same theoreme

[crimson delta]

$P(A\cap B)$ is the probability that $A$ and $B$ both happen. $P(A|B)$ is the probability that $A$ happens given $B$ happens

[wraith dagger]

Denascite

[crimson delta]

it's not

the first is conditional probability, the second is bayes theorem

two different things, although very closely related

[spice hazel]

i dont get it

[crimson delta]

they are two different ways to calculate the same thing

often you start with the first and maybe use that as a definition for what P(A|B) means. and then you can show the second which connects P(A|B) and P(B|A)

[velvet mortar]

Is there a difference between A and Ai?

[crimson delta]

in context maybe. here probably just notation

[velvet mortar]

Wdym in context?

[crimson delta]

well we don't know from what context both of these pictures come from

[velvet mortar]

So P(A|B) = P(B|A)*P(A)/P(B) right?

[crimson delta]

yes

[velvet mortar]

God I can't stand probability and statistics

[crimson delta]

or P(B|A) = P(A|B)*P(B)/P(A) switching around the A and B

[velvet mortar]

Fucks my brain up

Maybe I am too ignorant

[cedar kiln]

@spice hazel Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ocean lotus]

i am not sure how to do this.
when n = 1, 1 matching
n = 2, 2 matchings
n = 3, 3 matchings

[willow island]

what does a perfect matching mean

[ocean lotus]

it means every node on the left side of a bipartite graph is assigned to a unique node on the right

so this is a perfect matching, where the nodes only have a degree of 1

[crimson delta]

probably induction

if you add two nodes on the right, you can either connect them to each other, or connect them to the nodes to the left of them

each one of those options you can then extend to a matching given by how many matchings there are for 2(n-1) nodes or 2(n-2) nodes

[ocean lotus]

.close

[cedar kiln]

Channel closed

Closed by @ocean lotus

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

what is the probability that (assuming only two players playing) in texas holdem that both players get pockets (a pair preflop)?

[dire geode]

https://www.pokerstrategy.com/strategy/various-poker/texas-holdem-probabilities/

[fair geyser]

player1 gets a pair is 78/1326 = 5.88%

73 pairs "remain in the deck" and 1225 hands

= 5.96% that player2 gets one

it went up omg

0.350% combined

[crimson sedge]

i see thank u

[fair geyser]

thank you for the question, it's pretty neat how it goes up

[cedar kiln]

@crimson sedge Has your question been resolved?

Channel closed

Closed by @sage crystal

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[south hedge]

Why does the shortest distance bw 2 parallel lines in 3d is 0 ?

[willow island]

What do you mean

[south hedge]

Skew lines, parallel lines, and intersecting lines

My teacher told that shortest distance bw 2 parallel lines is 0

[cinder portal]

If the shortest distance between two parallel lines were 0 then they would be the same line

[crimson sedge]

your teacher was speaking in general or in particular? had you heard correct??

[south hedge]

Or intersecting too

[south hedge]

Idk...

[crimson sedge]

cz in general its false statement...

[south hedge]

I am just confused

[south hedge]

It seem so

Oof

[cinder portal]

If you say that a line is parallel with itself then its not necessarily false

[crimson sedge]

no it is..bro

[crimson sedge]

ain't they same line???

but you were talking about 2 lines

[cinder portal]

Yeah two separate parallel lines cannot have a distance of 0

[crimson sedge]

exactly

[cinder portal]

Maybe they said the shortest distance approaches 0

[crimson sedge]

but two parllel lines can be infinite distance apart too

[cinder portal]

Yes but we are talking about the shortest distance

[crimson sedge]

here shortest distance is being reffers as the perpendicular distance.....shrt dosen't means less value

infinite distance will also be the shortest distance b/n the two parallel lines

[cinder portal]

Yes the shortest perpendicular distance between two parallel lines can be <approaching 0>

Otherwise its a nonsensical question

[crimson sedge]

yep it can be close to 0..but if its 0 then we are talking about 1 line..not 2 lines

[cinder portal]

Yes

Hence approaching 0

[cedar kiln]

@south hedge Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bleak shale]

Maria has 20 cards. There are 10 cards labeled A, 6 cards labeled B, and 4 cards labeled C. What is the probability that Maria draws 2 cards without looking, and both cards are labeled 'B'?

Multiple Choice Answers:
A. 3/32
B. 3/5
C. 9/95
D. 3/40

I have gotten 9/100 and 3/38, with (6/20)^2 and 6/20 * 5/19. But none of those answer the question. I ended up picking A, pretty sure I got it wrong. (This was on my online exam today.)

[cinder portal]

I think its most likely D but they could have been more concise. I would initially have calculated 3/38 like you

[high coyote]

$\frac{6}{20}\cdot\frac{5}{19}=\frac{3}{38}$

[wraith dagger]

jnkena

[bleak shale]

Yeah...

[high coyote]

How do you justify D?

[cinder portal]

6/20 * 5/20

[high coyote]

mmm

[cinder portal]

Most likely they've answered their own question using replacement

Imo

[bleak shale]

That's presuming you put the card back into the bag, and you invalidated an 'B' card. (I think)

[high coyote]

Yes, drawing cards is considered without replacement I think de facto. So yes, I also think they should have detailed

[cinder portal]

Yeah idek what they've done

You're right

It would either be 6/20 * 6/20 or 6/20 * 5/19

[bleak shale]

However previously on the test, a more simple probability question came up and it had to explicitly state "without replacement" so idk

Ig I'll have to wait till the results to come out to truly know.

[high coyote]

As Olly said, it can only be with or without replacement. Given the possible answers, it is supposed to be with replacement and that's all. Maybe the teacher said unless explicitly all chooses are considered with replacement.

[cinder portal]

I think its without replacement but the teacher forgot to remove a card from the total and ending up calculating 3/40

But hard to tell

[bleak shale]

I did ask some of my friends who took the exam before me, and they all said either A or D.

No idea what the answer could be

.close

[cedar kiln]

Channel closed

Closed by @bleak shale

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wintry minnow]

Hi! How do I write an equation for these two points? I believe the slope is 0, so what do I do next? Thanks!

[crystal raptor]

What's the general equation for a line?

[wintry minnow]

y = mx + b?

[crystal raptor]

Yep

And you have m=0

[wintry minnow]

Right.

[crystal raptor]

So must be y=something, what do you think that something might be

[wintry minnow]

5?

[crystal raptor]

Yea

[wintry minnow]

Oh, I see it now. Thank you!

.close

[cedar kiln]

Channel closed

Closed by @wintry minnow

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed due to the original message being deleted

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[opal sierra]

What does x or p mean in algebra after a number. e.g 5x?

[opal sierra]

Like some in this sheet.

[sand hazel]

any letter means an unknown

[opal sierra]

Wdym?

[opal sierra]

What’s an unknown?

[acoustic nest]

An unknown is another word for a variable. For example, in the first problem you have (-20=-4x-6x), x is the unknown; meaning that x can be selected from all sorts of numbers

it might be easier to pretend that x can be from {…,-3,-2,-1,0,1,2,3,…} and youre just supposed to choose the "correct" value of x

[opal sierra]

Oh so x can be 5 or something?

[acoustic nest]

that is, the value of x that satisfies -20=-6x-4x

[acoustic nest]

yes yes, it could potentially be 5

[sand hazel]

it has a value and the purpose of solving an equation is to find the value of the unknown

[acoustic nest]

it could be a fraction as well

or irrational or imaginary, but youll get to those eventually

[cedar kiln]

@opal sierra Has your question been resolved?

[opal sierra]

Oh thanks

.close

[cedar kiln]

Channel closed

Closed by @opal sierra

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pulsar topaz]

Y = x^2/(1-x^2)

Trying to find symmetry :
I get f(x) = f(-x)
So there's symmetry over Y axis, but when I graph it, it ends being
https://gyazo.com/47fd950793634c8aaabc801b2fdfe90a

[fluid oriole]

Does anyone know what multiplying a linear function even as simple as y=x would look like on desmos?

[pulsar topaz]

What am i doing wrong...

[fluid oriole]

oops wrong channel sorry

[obsidian coral]

You definitely typed it wrong

[pulsar topaz]

OH

I forgot a ^2

thank you

[obsidian coral]

You got what I mean

[pulsar topaz]

yeah

[cedar kiln]

@pulsar topaz Has your question been resolved?

Channel closed

Closed by @pulsar topaz

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cedar kiln]

Please don't occupy multiple help channels.

[crude scroll]

How did they get from $-\phi(24)$ to $-4 \phi(6)$?

[wraith dagger]

Kurama

[crude scroll]

nvm .close

.close

[cedar kiln]

Channel closed

Closed by @crude scroll

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[warm vector]

How would I do part i) of this question?

[modern compass]

the same way you do part e)

[warm vector]

Hmm… ok I’ll try

Got it, thanks

.close

[cedar kiln]

Channel closed

Closed by @warm vector

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[scenic crest]

Hi

I got the right answer.

But I am confused why I needed to add probabilities instead of multiplying

I mean why to add probabilities of two different paths?

I mean we add probabilities when two things happen simultaneously and multiply when one of them happens.

And here either path one that is (R,R) will happen or Path 2 (B,R) will happen

[violet cobalt]

you add probabilities because these are different outcomes

and you need the probability of either of them occurring

[scenic crest]

That's kind of confusing me😅 ...i think I need to think more on this.

Okay but can please tell me how to do the same question with bayes theorem?

.close

[cedar kiln]

Channel closed

Closed by @scenic crest

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wide star]

i need help figuring this problem out

[fickle idol]

what trigonometric identities do you know?

[wide star]

i know of secant, cosecant, and cotangent

.close

[cedar kiln]

Channel closed

Closed by @wide star

Use .reopen if this was a mistake.

[wide star]

can someone help with this problem instead

nvm i also figured that one out on my own

.close

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wide star]

i need help with d

[crimson sedge]

try sin^2(x)+cos^2(x)=1

[wide star]

it worked, thanks!

.close

[cedar kiln]

Channel closed

Closed by @wide star

Use .reopen if this was a mistake.

[wide star]

can someone help me with this problem

[vestal bear]

Reopen the channel

So it doesn't close all the way

[wide star]

.reopen

[cedar kiln]

✅

[wide star]

thanks

[crimson sedge]

for part a try -404.20

[wide star]

says wrong:(

[crimson sedge]

hmph

[vestal bear]

You can make a triangle with this

Right triangle

Think of the unit circle

[crimson sedge]

wait do 211.96

[wide star]

correct!

what did you do?'

[crimson sedge]

apparently i converted to degrees wrong previously

for problems like these you can use a right triangle

[wide star]

ah, radians to degrees?

[crimson sedge]

yes

anyways

the angle of elevation as provided was 1.02 radians

the rocket traveled 405 yds with that angle

405 would be the hypotenuse of the triangle

[vestal bear]

👍

[wide star]

ohh i see!

[crimson sedge]

you need help with b too?

[wide star]

nope i got it! thank you again

.close

[cedar kiln]

Channel closed

Closed by @wide star

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[primal sparrow]

I found part a and b so far.

Rate of Return for a is: 19.2% and b is: 6.8%

I'm trying to get the Rate of Return for part c now. I need help

[cedar kiln]

@primal sparrow Has your question been resolved?

[primal sparrow]

I really need some help here

[cunning quail]

if she gets a $12,000 return in 7 years, how much would that be per year if spread over the 7 years

[primal sparrow]

Well, there is a formula I saw that I may have to use @cunning quail

Here's an example problem with the formula. So would I use this f = p * (1 + y)^n?

[cunning quail]

I see, have you applied it to this question yet?

[cunning quail]

ah I missed your question. Yeah, you'd use this

[primal sparrow]

Okay cool. Just wanted to make sure I'm on the right track

[primal sparrow]

@cunning quail So I got this: 12000 = 5000 * (1 + y)^7

12,000 / 5,000

=

5,000 * (1 + y)^7 / 5,000

2.4^(1/7) = ((1 + y)7)^(1/7)

1.133 = 1 + y

1.133 - 1 = 1 - 1 + y

.133 = y

and that becomes 13.3%

So the Rate of Return is 13.3 %

[cunning quail]

looks good to me

[primal sparrow]

Ok cool.

[cunning quail]

,calc 5000 * 1.133^7

[wraith dagger]

Result:

11983.381161983

[primal sparrow]

Oh what'd you do there?

[cunning quail]

just checking if it makes sense

so assuming that your rate of return is correct, if we apply it annually for 7 years on $5000 (the expression I typed), we'd expect $12,000

which 11,983 is close enough (rounding error)

[primal sparrow]

Oh good

@cunning quail May I share one more problem I'm struggling on?

[cunning quail]

sure

[primal sparrow]

Okay. Thanks

[cunning quail]

have you tried anything yet?

[primal sparrow]

I haven't. I'm actually confused of how to begin on this one.

[cunning quail]

with these it helps a lot to just write out the values for a few weeks and spot a trend, for example:

if they solve 18,000 copies in the first week, we know the in the second week they'll sell a certain percentage of the week before (ie. the first week)

since we don't know what that percentage is, let's denote it P

week 1: 18,000
week 2: 18,000 * P
week 3: 18,000 * P * P
....
week 12: 4,000

anything noteworthy here?

[primal sparrow]

Oh I think I see what you mean

Just helping things make more sense

Yeah that's what confused me about this one, because they don't give us the percentage. Which is supposed to be the Rate of Return, right?

[cunning quail]

I don't think I'd call it the rate of return, since we aren't working with any money here

[primal sparrow]

Ohh okay

[cunning quail]

it's more like an exercise in geometric series, where P is just a scaling factor

[primal sparrow]

Oh right! Yeah

[cunning quail]

so, what can we get out of this?

[primal sparrow]

Here's an example problem from my course that reminds me of this one, but it's sorta different.

[cunning quail]

it's the same idea, they just don't explicitly tell us the percentage

doesn't mean we can't work it out ourselves though

[primal sparrow]

Okay cool. I'm just wondering what way we'd work it out, because I want to make sure I show my work in the way they want me to. Based on examples i've had

[cunning quail]

right. So from this we can spot a trend in the first few weeks: the number sold can be expressed as $$18,000P^{n-1}$$ where $n$ is just what week we're on

[wraith dagger]

dino

[cunning quail]

would you agree?

[primal sparrow]

Yes

[cunning quail]

great, so on week 12 (ie. n=12) they'll sell 18,000 * P^11 copies

but hold on- the question told us how much they sold on week 12: 4,000

thus, those two must be equal

$18,000P^{11}=4,000$

[wraith dagger]

dino

[primal sparrow]

Hmm okay

[cunning quail]

what's bothering you

[primal sparrow]

I understand, but I think this is something I covered from last week's lesson, so I'm trying to find examples in my course from this week that are comparable in terms of solving for the percentage. I'm just trying to get this to ring a bell again

But I'm sure after we work the rest out it will

👍

[cunning quail]

okay, let's continue then

[cunning quail]

could you solve for P for me then?

[primal sparrow]

I think I can, one moment. I'm going to find how I did that last week

[cunning quail]

sure. Though keep in mind this is identical to the previous question

[primal sparrow]

Ohh

The one I checked with you about?

And you said was right?

[cunning quail]

the working below here

[primal sparrow]

Ohhh

[cunning quail]

like solving any equation, we first isolate the variable we're looking for then simplify until we're there

[primal sparrow]

Oh so I'd write it in the form of f = p * (1+y)^n?

[cunning quail]

no no

I'll walk through it, that'll be easiest to see what I mean

[primal sparrow]

Okay I appreciate it

[cunning quail]

\begin{align*}
18,000P^{11}&=4,000\
P^{11}&=\frac{4,000}{18,000}\
P^{11}&=\frac{2}{9}\
P&=\left(\frac29\right)^{\frac{1}{11}}\
&\approx 0.872
\end{align*}

[wraith dagger]

dino

[primal sparrow]

Ohh, okay I see what you did. I'm mainly just concerned about writing this part down since I have to show my work and I wasn't shown this kind of a situation for a problem this week.

[cunning quail]

this here is just rudimentary equation solving, there's no set way to go about this nor examples to follow

are you not comfortable with equations like these?

[primal sparrow]

This equation looks very familiar, but I'm having to refer to my course examples a lot to compare and reassure myself on things. I'm coming back to math in the current college class I'm taking lol.

[cunning quail]

welp the important things are the general steps of the solution, which are: 1) form an equation involving the percentage referenced in the question, 2) solve for said percentage, 3) apply the new information to find what is asked of us

we've done up till 2), let's try the last part

[primal sparrow]

Okay.

[cunning quail]

now that we know the number of copies sold is roughly 87.2% of the number sold the week prior, we can form a sum for the total number of albums that will be sold

total = copies sold in week 1 + copies sold in week 2 + .... on and on forever

plugging in some figures:

total = 18,000 + 18,000P + 18,000P^2 + 18,000P^3 + ...

this should seem a little familiar, perhaps?

[primal sparrow]

Oh I thought the next part would be like:

or using f = p * (1 + y)^n

[cunning quail]

it is like this, I was emphasising the geometric series that we end up with (the large sum)

since the formula used in the photo example is the infinite sum of a geometric series

[primal sparrow]

Ohh I understand

[cunning quail]

in our case, $g_1=18,000$ and $r=P\approx 0.872$

[wraith dagger]

dino

[primal sparrow]

Right

[cunning quail]

can you arrive at the final answer then?

[primal sparrow]

Yep. I'm gonna write it all down

I'll let you know. brb

So am I basically just doing this? But with my numbers plugged?

[cunning quail]

yeah

[primal sparrow]

Oh okay cool. Just making sure

I wrote Egs = 18,000 / 1 - .872

but what do I do to the other side? Looks like they multiplied their r by g1?

[cunning quail]

the other side is just evaluating the fraction

[primal sparrow]

Ohhh I see

Whoops. Brain fart

[cunning quail]

$\sum g_s=\frac{g_1}{1-r}=\frac{18,000}{1-0.872}=140,635$

[wraith dagger]

dino

[primal sparrow]

I got 140,625

[cunning quail]

you're right, I typo'd

[primal sparrow]

Oh okay

So total albums is 140,625 ?

[cunning quail]

yeap

[primal sparrow]

And not sure if I know what they meant by "Round your answer to the nearest album"

[cunning quail]

really instead of 0.872 we should've used (2/9)^(1/11)

,calc 18000/(1-(2/9)^(1/11))

[wraith dagger]

Result:

1.4084719936371e+5

[cunning quail]

lovely

that mess means 140,847.1993... albums

so rounded to the nearest album is 140,847

[primal sparrow]

Oh so 140,625 was wrong?

[cunning quail]

yeah, we shouldn't have used the rounded value for P

[cunning quail]

use the second-to-last line here instead

[primal sparrow]

I think I'm confused now. So is there something I need to rewrite? I did this:

[cunning quail]

so in the two spots where you wrote .872, either change it to (2/9)^(1/11) or just P

(I'd recommend P)

actually the bottom line on the left column can be left out, that's not needed

[primal sparrow]

Ohhhh

Okay I’ll erase = .872

And then on the right equation, I need to change .872 to (2/9)^(1/11) ?

[cunning quail]

just P works

since you already said what P equals on the left

[cunning quail]

if you prefer, go for it

so $\frac{80,000}{1-P}\approx 140.847$

[wraith dagger]

dino

[primal sparrow]

Ok

[cunning quail]

comma, not decimal point

[primal sparrow]

So I’m working it out for myself on calculator. So would I start with doing the 2/9^1/11 cause of exponents coming first in PEMDAS

?

Then do the 1- answer

Then the division?

[cunning quail]

yes, remember the parentheses around (2/9)^(1/11)

[primal sparrow]

Oh right

[cunning quail]

I've got to get going, if you have another problem you need help with feel free to occupy a free channel - remember to close this one

[cunning quail]

bruh. This is meant to be 18,000 as well, I'm losing it

[primal sparrow]

Hm?

[cunning quail]

$\frac{18,000}{1-P}\approx 140,847$

[wraith dagger]

dino

[cunning quail]

just correcting my mistakes

[primal sparrow]

Oh okay

I did this:

(2/9)^(1/11) =.0872201932

And now I do 1- that

[cunning quail]

,calc (2/9)^(1/11)

[wraith dagger]

Result:

0.87220193172944

[cunning quail]

seems like you threw in an extra zero?

[primal sparrow]

Ohh rly?

[cunning quail]

.08722...

[primal sparrow]

Oh whoops yeah

Okay I did 1 - that

And got:

[cunning quail]

18,000 divided by that and you’re finished

[primal sparrow]

Okay cool

Okay and by round to the nearest album, it just means get rid of what’s after the decimal?

@cunning quail We don’t look at any number to round up or down do we?

[cedar kiln]

@primal sparrow Has your question been resolved?

Channel closed

Closed by @primal sparrow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[turbid charm]

Can some one look at my solution and see where I’m going wrong ?

[cedar kiln]

@turbid charm Has your question been resolved?

[turbid charm]

<@&286206848099549185> may someone pls check my solution

[turbid charm]

.close

[cedar kiln]

Channel closed

Closed by @turbid charm

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[livid hound]

show work

[cedar kiln]

@kindred orbit Has your question been resolved?

[kindred orbit]

<@&286206848099549185> plz

[green notch]

have you made a drawing ?

@kindred orbit

Well you didn't solve it since you have the wrong answer

somewhere along your solving you messed something

so if we walk through that process we can find that

didnt do it gimme a minute

https://tenor.com/view/dconfused-math-solving-gif-10774777

14.641

https://www.quora.com/How-can-I-find-the-lengths-of-a-triangle-if-all-the-angles-are-given

[cedar kiln]

@kindred orbit Has your question been resolved?

Channel closed

Closed by @kindred orbit

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[spark igloo]

How can I integrate sec^3x

[cosmic steppe]

By parts

[velvet mortar]

sec x * sec^2 x

[cosmic steppe]

^

[spark igloo]

Umm

[spark igloo]

Im not stuck at integrating sec x

Now*

Original problem is this

[wraith dagger]

GG・Goof

GG・Goof

[cosmic steppe]

Use x = cot^2(u)

[spark igloo]

Umm

But...

[cosmic steppe]

Because x is in the denominator

[spark igloo]

I found it easier

Wait giving my solution

[cosmic steppe]

You have to use $x = a\cot^2{(u)}$ because the $x$ is in the denominator

[wraith dagger]

Umbraleviathan

[spark igloo]

Yes I got that

But then...

I got -2 cot u csc u du= dx

And its way more complex

See this

[cosmic steppe]

If you set x = atan^2 you'll get csc(u) • 2atan(u)sec^2(u)

[spark igloo]

Yea

And tan u csc u is equal to sec u

[cosmic steppe]

Yeah I see

You'll get the same result if you use acot(x)

[spark igloo]

Hm

[cosmic steppe]

But shifted

So they end up matching

But yeah I guess that works too

[wraith dagger]

GG・Goof

[spark igloo]

Where I= integration of sec^3x

[cosmic steppe]

Bruh these I subs

Just use IBP

[spark igloo]

What's that

[cosmic steppe]

Integration by Parts

[spark igloo]

Uh

I did it using parts only

Sec x=fx and sec^2x=gx

[cosmic steppe]

$$2a\int \sec^3{(x)}$$
$$2a(\sec{(x)}\tan{(x)}-\int \sec{(x)}\tan^2{(x)}dx)$

[wraith dagger]

Umbraleviathan
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[spark igloo]

Uh thats what I used

And then I substituted tan^2x= sec^2x-1

[cosmic steppe]

You'll be running in circles then

[spark igloo]

Why?

[cosmic steppe]

Well lemme think

Oh j see what you did

Alright

Yeah mb

Hence the 2I

[spark igloo]

$$\int \sec^3{(x)}
=\sec{(x)}\tan{(x)}-\int \sec^3{(x)}dx+\int\sec{x}dx$