help-13

[silent yew]

Dbc

@void spade OH WAIT NO

Listen

[void spade]

?

[silent yew]

I meant triangle dbq

[void spade]

ok

[silent yew]

Dbq

Mb

Sry

[void spade]

i just need DB and BQ

[silent yew]

How i gonna figure out db?

[void spade]

12square+5square=db square

DB=13

[silent yew]

That would be 13

[void spade]

ye

and bq

[silent yew]

Or listen screw that

[void spade]

wat

[silent yew]

Draw a perpendicular from a to Dq

Let's name the intersection M

[void spade]

ok

[silent yew]

So now mq = ap

Mq + md = dq

We can figure out mq by figuring out ap

And then angle dam = 30°

So then u can figure out md

And so now u have dq

@void spade with me?

[void spade]

ye

[silent yew]

So now do that

[void spade]

how do u find out dam=30

[silent yew]

Since cbr = 30°

Dam also equal to 30°

Parallel lines so..

@void spade do u get this?

[void spade]

hm

not really

I get what ur saying

[silent yew]

So u know that dam is 30°

And u know why that is

And u also know Da is 12 cm

Now u tell me

Can u figure out md?

[void spade]

uh

da 12 dam 30 degree

how to find md

aaa

can't do it

[silent yew]

Okay so u will find md just like how u find cr

Sin(30°) = md/da

And u know da

[cedar kiln]

@void spade Has your question been resolved?

[cedar kiln]

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[cedar kiln]

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[coarse shuttle]

hi, so this question asks me to find out the average no. of socks a guy needs to pick up a pair if he can only pick two at a time and avoids repetition of selections. there is a total of three pairs of socks. I understand that he can pick anywhere b/w 2 and 6 socks. I did (6+5+4+3+2)/5 = 4.

the solution says (6+2)/2 = 4. why does this way work too?

[gleaming cave]

parentheses?

[coarse shuttle]

added

[scenic stirrup]

im not sure i get the problem but if you do the average of the first and last you get the same average. However this may not be the explanation and it may be more logical than this

so the average of 2, 3, 4, 5, 6 is the same as the average of 2 and 6

[buoyant latch]

https://math.stackexchange.com/questions/348723/finding-mean-of-n-consecutive-numbers-using-a-shortcut

[fair geyser]

i don't see how 6 is maximum, worst case seems to be 26 socks

[scenic stirrup]

i assume they don't put the socks back?

or maybe they do who knows

[fair geyser]

if you don;t put the socks back you just never pick a pair

[scenic stirrup]

hmm

wait give me a second to understnad the problem again lol

[fair geyser]

whatever i don't want to figure out what this means

[scenic stirrup]

wait a minute aren't there only four "pulls" at maximum

assuming the left and right socks are indistinguishable

if your socks are numbered 00 11 22 you can pick "01, 02, 12" but then you're forced to choose a pair

(assuming the order in which you choose them also doesn't matter)

[fair geyser]

so after you picked 01 you magically know which one is the other 0 and which is the other 1, so you can avoid doing it again?

[scenic stirrup]

i mean not in practice but to "pick two at a time and avoids repetition of selections" seems to mean avoiding repetition of colors

or they could mean something else, im not entirely sure; for example if the right vs left sock mattered i guess. if right vs left mattered though then it would be 12 possible choices?

[cedar kiln]

@coarse shuttle Has your question been resolved?

[coarse shuttle]

I seem to have done a bad job at explaining the problem lol

[coarse shuttle]

but this is what I don't understand

how does the math work out?

[scenic stirrup]

if you think about it the average of 1, 2, 3, 4 is the same as the average of 1 and 4

they're both 2.5

[scenic stirrup]

see this thread for a proof

[coarse shuttle]

okay, thanks

.close

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[tulip river]

a and b are real numbers with a<b.

[tulip river]

i'm dumb

.close

[cedar kiln]

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[shut reef]

What

[cedar kiln]

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[steep stump]

So I'm not sure how to solve for x to graph it, but I'm kinda sure I graphed y correctly??

[reef venture]

which line did you plot

[buoyant latch]

show us what u plotted

[steep stump]

i have no idea

[buoyant latch]

show us what u wrote

[reef venture]

how did you get y=3 for x=-1

[buoyant latch]

i assume u are doing this on paper

[steep stump]

nope-

[buoyant latch]

oh that dot is yours?

[steep stump]

unfortunately

[buoyant latch]

these are lines you're supposed to plot

not points

[steep stump]

damn

[buoyant latch]

ax + by = c
y = mx + d

these are forms of linear equations

where a, b, c, m, d are constants

and x and y change

[steep stump]

right

[buoyant latch]

so the first one is in the for y = mx + d

the 2nd one is in the form ax + by = c

[steep stump]

we only do y = mx + b

because we only started this year

so i've no idea about.. that

[buoyant latch]

ax + by = c

by = c - ax

y = b/c - ax/c

[reef venture]

have you plotted a line before?

[buoyant latch]

y = (-a/c)x + b/c

y = mx + d

[steep stump]

yeah

[buoyant latch]

they are the same thing

you can rearrange them by making y the subject

[steep stump]

ok

hold on give me a second i'll see if i can do it now

so y = 2 / 4 - 3x / 4?

ax + by = c
by = c - ax
y = b/c - ax/c using this?

[velvet mortar]

For the first equation what is y when x=0? plot that and also plot y when x= 1 and x =2. Three points are enough to grab a ruler and draw a straight line including the three points

Do the same for the other equation

You will get an interception

[steep stump]

oh my god thank you

so y = 2?

[velvet mortar]

When?

[steep stump]

in the second one

4 = -3x - 2y

if x equals 0

[sand wolf]

Hi Everyone i have a question in simplex method , Are we accept the optimality of solutions when they not satisfy the normal program constraints but it satisfies the standard form constaints

[velvet mortar]

4 = -3(0) - 2y

4 = -2y

y = -2

[steep stump]

oh okay

and what about for x?

[velvet mortar]

What did just plug in?

[steep stump]

?

i put down -2 for y

[velvet mortar]

What was zero here?

[steep stump]

x was zero

[velvet mortar]

Yes

So what about x?

[steep stump]

okay so plot -2 for y

x is zero

[velvet mortar]

Yes

[steep stump]

.close

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[shut salmon]

Hi please help

[shut reef]

no

[celest ledge]

I can’t see how it is possible, because clearly F(0)=0

[shut salmon]

i forgot the fonction sorry

[celest ledge]

Still

F(0)=0

I can’t see how it’s possible that F(0)=2In(2)

[crimson delta]

well the integral definition is only used for x>0

[celest ledge]

I see, I was so dumb

[crimson delta]

hmm first thought is to use $$\int_a^b f(x) dx \leq (b-a) \sup_{x\in [a,b]} |f(x)| $$

[wraith dagger]

Denascite

[crimson delta]

and a similar lower bound using the infimum

[shut salmon]

Max f(x)=+inf

[crimson delta]

well but not on the interval [a,b]

[shut salmon]

Sorry my bad you are right

thanks

[crimson delta]

maybe you'll also have to pull (b-a) into the max which then gives something like x*e^-x

[shut salmon]

but i couldnt find max ( f(x))

because x>0

[crimson delta]

well but on the interval [a,b] you still can

f is decreasing so the max is at a

[shut salmon]

thank you im trying to solve it with those 2 formulas its going to take me some time i think i should close the question meanwhile

.close

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[fathom kernel]

I was trying to solve this question using combinatrics and I got the answer to be between 3/4 and 1, I simulated the same problem in python, but I'm getting the answer as ~0.577, I'm not sure if I went wrong in the combinatrics or my code, can someone point out the problem

[fathom kernel]

The code I wrote to check the problem empirically

def prob(n):
    p1,p2=0,0
    for _ in range(n):
        w1,w2 = random.randint(1,10),random.randint(1,10)
        if w1 in random.choices([i for i in range(1,11)],k=5):
            p1+=1
        if all(x in random.choices([i for i in range(1,11)],k=5) for x in [w1,w2]):
            p2+=1
    return p1/n+p2/n

[obsidian coral]

Probably your code, if you're getting a negative value

[fathom kernel]

not negative, it was approximately 0.577

[cedar kiln]

@fathom kernel Has your question been resolved?

[chilly lantern]

let p_0 denote the probability of you having negative luckgetting no winning tickets. then, p_0 + p_1 + p_2 = ....

you should be able to take it from there

wait so the value you got wasnt negative after all

but i still dont think the value you ot from your code was correct

[fathom kernel]

I see, I never checked if w2 would also be in the choice of tickets in my code

Yes, I should've also considered the other ticket to be in the range

Thanks for the help, I just forgot to calculate the other winning ticket, guess my original working was correct after all

.close

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[modern compass]

do you know anything about f(x)?

[brazen sable]

Nope

[modern compass]

then this tells you the limit of f(x) is 8 as x goes to 2. It doesn't tell you anything about f(2)

[brazen sable]

I'll send the entire question but I couldn't figure whether or not if the denominator in a limit equals to 0 then there must be a 0/0 situation there

[modern compass]

if the limit of f(x) is anything but 8, then you end up in a k/0 situation (where k is non-zero) so the limit wouldn't exist

[brazen sable]

It's not in english but it should be understandable, it just gave me the equation above and is asking for what the one below equals to

[reef venture]

,rotate

[modern compass]

try factoring the top to get f(x) - 8 as a factor

[brazen sable]

I was thinking f(x)=(x-2)(x+a)

f(x)-8**

[modern compass]

you don't know that

and actually that can't be true, the limit wouldn't come out correctly

[grizzled dome]

Seems like the problem wants you to assume l'Hopital's rule applies (for example, assume f(x) is differentiable). Then the first limit allows you to figure out $\lim_{x \to 2} f'(x)$, and you can figure out the second limit using l'Hopital's rule again.

[wraith dagger]

daveamayombo

[modern compass]

I'm saying take -xf(x) +5f(x) -24 and factor it so you have f(x) - 8 as a factor

[brazen sable]

Oh oops that's correct one moment

[modern compass]

the key points here is if what multiplies f(x) to get -xf(x) and what multiplies -8 to get -24. that should give you your other factor

[grizzled dome]

If this problem has a unique correct answer, it'll be compatible with the one given by l'Hopital's rule. Are you familiar with it?

[brazen sable]

Yes I am

[grizzled dome]

So assume it applies. The first limit only makes sense if its a 0/0 situation, as said before. So that means $\lim_{x\to 2} f(x) = 8$. l'Hopital's rule then implies that $\lim_{x \to 2} f'(x) = 5$ (as the derivative of x-2 is just the constant 1).

[wraith dagger]

daveamayombo

[grizzled dome]

Now you can check the second limit is a "0/0 situation" too, so to find the second limit, apply l'Hopital's rule.

[brazen sable]

Okay I think I got it

Thank you

.close

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[manic acorn]

Is 42 correct?

[tropic oxide]

,rccw

[tropic oxide]

yes

[manic acorn]

Thanks

.close

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[crimson sedge]

i dont understand how u sub works for stuff such as
f(x) = x/sqrt(x-1)
it needs to be in the form of f(g(x))*d(g(x)) how though

[dire geode]

,w integral x/sqrt(x-1)

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by riemann#2529

[crimson sedge]

thats just a solution

[dire geode]

Differentiate it and see

Then reverse engineer the u sub

[crimson sedge]

alr

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[midnight zealot]

Everything here is wrong, right

isn't the vertex coordinate -10/4

and the k coordinate is obviously wrong

the x-intercepts are butchered

the y-intercept is correc though

Right?

[brazen sable]

Vertex and k are correct

For f(x)=ax^2+bc+c, T=(r,k) is T(-b/2a, f(r))

So it should be

[midnight zealot]

How is it correct, I'm getting 83/2

Wait wait

I mean I'm assyumiong that h is -10/4, not 10/4

Why would it be 10/4

omg

omg

omg

I can't believe I've been blind this whole time

[brazen sable]

Because -b/2a and b is -10 here lol

[midnight zealot]

I see it now

yeah I was literally just putting -10

not -(-10)

omg

I spent the entire day

confused

the entire day

[shut reef]

lmao

[midnight zealot]

a day literally wasted

but the x-intercepts, surely are wrong

[brazen sable]

Lol

[midnight zealot]

right guys?

[shut reef]

idk

[brazen sable]

Isn't delta<0? There should be no x intercepts

Wait nvm

[midnight zealot]

degree is 2

so max of 2 intercepts

[brazen sable]

Delta>0 so there are intercepts for sure

[midnight zealot]

but I'm getting

[brazen sable]

Is that the correct answer or what you've found

[midnight zealot]

Well the correct answer is unkown

that's an answer sheet above

but

It's been wrong before

many times

[midnight zealot]

this is what I got

[brazen sable]

One moment

[midnight zealot]

but its not what the sheet got

np

and ty

[brazen sable]

Ofc

[midnight zealot]

holy shit

I just put in -(10)

and solved it in like 30 seconds

when I've been confused this entire day

https://tenor.com/view/cat-kitty-storm-lightning-cloudy-gif-17607709

[brazen sable]

I was trying to figure out what was wrong for a solid few minutes too omg 😭😭

[midnight zealot]

So many things literally went into fooling the shit out of me with this question.

Literally the fourth question of 40 that I have to finish today

[brazen sable]

Good luck man thats a lot of qs

[midnight zealot]

Yeah ty

[brazen sable]

Np

[midnight zealot]

did you confirm if this was right or wrong? @brazen sable

Still not sure if the x-int./s they are giving are correct

Pretty sure they are wrong

[brazen sable]

Okay so I thought f(x)=a(x-5)(x+1)

[midnight zealot]

is that correct factorization ?

[brazen sable]

a(x^2-4x-5)=f(x) and maybe a polynomial division should do the trick? I'm not entirely sure

[midnight zealot]

What I did was plug the numbers into the quadratic formula

[brazen sable]

-b/a should equal to 5-1=4 which it clearly doesnt

[midnight zealot]

wait where

graphing it looks right

[brazen sable]

5 and -1 should be the roots of the equation since they're x interceptions

And sum of roots should be -b/a

[midnight zealot]

how?

[brazen sable]

How to which one

[midnight zealot]

^

[brazen sable]

Say we have a function like y=(x-5)(x+1), if x=5 or x=-1 then y=0 and when graphed that's where the x interceptions are

Wait

[midnight zealot]

Yeah yeah I know what x-intercept is

[brazen sable]

I did it for (5,0) and (-1,0) not otherwise omfg

[midnight zealot]

I just don't know why they are 5 and -1

[midnight zealot]

oh

[brazen sable]

No wait I did it correct

[midnight zealot]

oof

When I graph it the x intercepts are not 5 and -1

on desmos

[brazen sable]

Yeah thats the issue

[midnight zealot]

But the answer sheet has been wrong before

that's what I mean

I think it's wrong this time as well

[brazen sable]

I think there's a problem with the question itself

The roots of the function should equal to the x intercepts which don't

[midnight zealot]

But the x intercepts are not 5 and -1

they are

[brazen sable]

Yeah thats the issue

[midnight zealot]

wait wait wait

oh

I see what the problem is

[brazen sable]

And in the question didn't it say (5,0) and (-1,0)?

[midnight zealot]

This is the question

[midnight zealot]

this is the answer sheet

xd

[brazen sable]

Is this the answer key?

Oh lol

[midnight zealot]

Yeah but it's wrong

Lellelelel my bad

[brazen sable]

Then yeah your answer is correct

[midnight zealot]

I thought I mentioned that

[brazen sable]

Np lol

[midnight zealot]

Awesome awesome awesome

tysm

[brazen sable]

Yw

[cedar kiln]

@midnight zealot Has your question been resolved?

[cedar kiln]

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[true vortex]

So I know the equation would be y=(x-3)^2+5(x-3)-2 but I dont know how to determine what it means

[true vortex]

anyone help

[gaunt hamlet]

How does the resulting graph compare to the original?

For example, if we multiplied the whole function by, say, 2, then that would correspond to the original function being stretched vertically by a factor of 2

[velvet mortar]

Have you learned graph transformations?

[true vortex]

just started

[true vortex]

it would be +3 in all aspects of x?

so add 3 to what x is

[gaunt hamlet]

Let's say I had x². How does (x - 1)² compare to x² graphically? Try actually graphing it and compare them

[true vortex]

k

it shifts the graph to the right 3 units

[gaunt hamlet]

(x - 1)² shifts to the right 3 units?

[true vortex]

no the original one does

this one shifts to 1

[gaunt hamlet]

Yes

In general, replacing x with x - k shifts the graph to the right by k units

[true vortex]

if it was x+k it would to to the left right

[gaunt hamlet]

Yes

[true vortex]

how would you make a transformation up then

[gaunt hamlet]

Wdym

Oh

You add a number to the whole function. If you had f(x), then f(x) + k shifts the graph up by k units

Similarly, f(x) - k shifts downward

It's kinda backwards when compared to horizontal shifting when looking at the signs

[true vortex]

m

.close

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[true vortex]

Would this be a correct depiction because the x-3 means to the left 3 units and the +4 means up 4 units. And then the 2 means scaling the parabola up by 2.

[velvet mortar]

Yes

Now .close

[obsidian coral]

Don't make people close their channel, what if they aren't done with it yet?

[velvet mortar]

Well it's their choice

Not forcing them

[obsidian coral]

The way you stated that sounds very forceful

[true vortex]

.close

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[opal sierra]

What algebra is in calculus?

[gaunt hamlet]

You'll want a good understanding of algebra I and II along with trig

[opal sierra]

So both algebra

[gaunt hamlet]

Yep

[crimson sedge]

a lot of trig

[opal sierra]

Are they both absolutely essential ?

[dire geode]

all of algebra is in claculus

[dire geode]

yes

[crimson sedge]

learn logs, expediential numbers, natural logs, polynomial division stuff like that

[dire geode]

for future references, this isn't a math problem so isn't a good use of math help channels. ask in #chill or #discussion or #serious-discussion or #math-discussion

@crimson sedge please take your conversation there after i close

.close

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[cedar kiln]

Please don't occupy multiple help channels.

[pine lynx]

Okay

[velvet mortar]

Do you how to represent at least $700?

[cedar kiln]

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[pine lynx]

What do you mean?

[pine lynx]

No

[velvet mortar]

So the profit has to be >= 700

Get it?

So what are the things are you selling?

[pine lynx]

This

[velvet mortar]

All the things you are selling >=700

C and I and F all >= 700

Can you make the equation?

[pine lynx]

No unfortunately no

[velvet mortar]

C is the number of chocolate fudge bars right?

[pine lynx]

It's ok I got this I just asked my other friend

[velvet mortar]

What did you get?

[pine lynx]

I need this one solved he doesn't know

[pine lynx]

Idk he did it

[velvet mortar]

Do you know trigonometry?

[pine lynx]

I use to

I forgot tho

We studied it like 3 months ago

[velvet mortar]

Any idea about soh cah toa

[pine lynx]

Yes But idk

In cm

[velvet mortar]

Doesn't matter

[pine lynx]

Ohh

I remember now

Nvm I forgot I just remembere parts of it

[velvet mortar]

What do you remember?

[pine lynx]

Like tangent opp and one more but idk how to get them except the first one where the box points at

Plz answer for now then I'll study it later

Saturday Sunday after school I'm reviewing through all my math

I'm even gonna buy like a really expensive notebook and I'm retaking my sat so promise

[velvet mortar]

So remember that in a right triangle SOH CAH TOA. H means hypotenuse, O means opposite and A means adjacent

SOH basically means sin (angle) = O/H

cos (angle) = A/H

tan (angle) = O/A

[velvet mortar]

What is the adjacent side of Angle A here?

Better yet what is the length of the adjacent side?

@pine lynx ?

[pine lynx]

I got an answer but it wasn't right

Lmao I don't even want to say it

[velvet mortar]

Say it

[cedar kiln]

@pine lynx Has your question been resolved?

[velvet mortar]

@pine lynx if you are really struggling the adjacent side of A is 12 and the hypotenuse is 13. So cos(A) = 12/13. I trust you to learn it yourself

[cedar kiln]

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[heady thistle]

I have a pretty easy question I think, would something that would keep splitting itself (0.5^infinity) equal to 0?

[dire geode]

$\lim_{n \ra \infty}\left(\frac{1}{2}\right)^n = 0$

[wraith dagger]

riemann

[heady thistle]

why wouldn't just 0.5^infinity work?

sorry i don't know the syntaxes for TeXit

[modern compass]

infinity isn't a number. putting it into an equation or expression like that (while it might work for intuition purposes) isn't correct mathematically

[flint plinth]

you never actually reach zero, you can get as close as you desire by halving enough times

[heady thistle]

yea that was kind of my problem

i wasn't sure if it would equal 0 because I don 't know very well how infinity works

[dire geode]

https://tutorial.math.lamar.edu/Classes/CalcI/InfiniteLimits.aspx

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[inland dragon]

Can anyone help me figure out where I am going wrong?

I am jus trying to solve cos for 67a and I keep getting numbers that don't make sense

I tried c^2 = a^2 - b^2 and the number is greater than 1 when it should be less than 1

Perhaps I messed up the first part where I am trying to calculate the hypotenuse

I did...

Tan50degrees = 1mi/cos50degrees

Thinking about it now, Tangent !== hypotenuse...

Can anyone please help me figure out how to solve for hypotenuse given theta and sine?

[somber belfry]

maybe show the task itself

cause I cant read anything there

[inland dragon]

I have a triangle with theta of 40 and sine = 1 mile

Nvm, I think I was solving for tangent instead of hyp, but it should be Hyp = length of given side over function of other side?

Does this look correct to solve for hyp when theta is 40 and sine is 1?

I get ~1.56 mi

[cedar kiln]

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[inland dragon]

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[hybrid light]

what formula was used here?

[hybrid light]

.close

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[opal sierra]

What should you learn before polynomial equations?

[obsidian coral]

Variables

[opal sierra]

Because a polynomial equation video said coefficients and stuff.

[opal sierra]

Like what?

[obsidian coral]

A mix of both then

Well, honestly, it's been years since I messed with that topic. I've been dealing with variables and equations for a long time

[opal sierra]

Wdym?

[obsidian coral]

Knowing how variables and coefficients work

[opal sierra]

How long would that take?

[obsidian coral]

Depends on your prior knowledge and your math level

[opal sierra]

Oh

Anyway

Bye

Thanks 😊

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[opal sierra]

.reopen

[cedar kiln]

✅

[opal sierra]

One more question

Before you go

[obsidian coral]

Okay

[opal sierra]

What algebra is this?

[obsidian coral]

Not algebra but looks like calculus because of the dt part

[opal sierra]

The guy said to use algebra to figure it out?

[amber ridge]

is that a 3b1b video

[livid hound]

algebra is present throughout math

[opal sierra]

Yes

Why?

[amber ridge]

just wondering, it looks like it

[opal sierra]

Oh

So can anyone help?

[obsidian coral]

What video is that?

More context is needed

[opal sierra]

It’s a derivative video

[obsidian coral]

And derivatives are calculus

[opal sierra]

But he said solve this algebraically?

[obsidian coral]

As ramonov mentioned, algebra is everywhere in math

Even if that video is a calculus video, you'll still apply algebra in that topic

[opal sierra]

What algebra is it?

[obsidian coral]

Basic algebra

[opal sierra]

Polynomial or what

[obsidian coral]

Algebra in general

[opal sierra]

So a mixture?

Of stuff?

[obsidian coral]

Algebra is one of the broad areas of mathematics. Roughly speaking, algebra is the study of mathematical symbols and the rules for manipulating these symbols in formulas; it is a unifying thread of almost all of mathematics.

That is from Google

[opal sierra]

Oh

[opal sierra]

Can you recommend something explaining them?

[obsidian coral]

Algebra?

Watch videos

[opal sierra]

Should I learn them bit by bit or a massive video?

Like learn polynomial then linear or what?

[obsidian coral]

Whatever way you want to learn

[opal sierra]

Thanks 😊

Bye

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[radiant jolt]

need help with this question

time for fast train = 120/x

time for slow train = 120/ x - 9

how do you write an equation relating the two times tho?

what does that mean

😦

[buoyant latch]

The faster train takes 40minutes less

[radiant jolt]

afk 1 sec brb

back

this is the

answer

how is 2/3

there

tho?

[livid hound]

40 minutes is 2/3 of an hour

[radiant jolt]

oh

does this question mean that I

find the discriminant

[livid hound]

no

[radiant jolt]

then what

[livid hound]

it just want's you to simplify the equation in c)

and express that in the form of a quadratic equation

you are not explicitly asked to solve it yet

[radiant jolt]

I'm confused

isn't

already a quadratic equation?

or are you talking about the vertex form?

[livid hound]

no

the question is just asking you to do algebraic manipulation to get from
$$\frac 23 = \frac{120}{x-9} - \frac{120}{x}$$
to
$$x^2 - 9x - 1620=0$$

[wraith dagger]

ℝamonov

[livid hound]

no solving for x or whatever

[radiant jolt]

ohhhhhh

ok I got that

but can you explain

how that equals this

[livid hound]

don't know how you could interpret the instructions as anything else

[radiant jolt]

I'm still not 100%

on that

[livid hound]

do the algebraic manipulation

same operations to both sides, rid yourself of fractions , simplify etc

[rotund vine]

yea

just get rid of all fractions

by multiplying common factors

[radiant jolt]

alr

but this

I still don't get fully

how is the time of the fast train minus from the time of the slow train

2/3

[rotund vine]

the faster train takes 40 minutes less

just quoting

[livid hound]

40 minutes is 2/3 of an hour

[rotund vine]

yea

40/60 = 2/3

[radiant jolt]

oh yea

the faster train takes 40 minutes less time

so when you minus the two

you get 40 minutes and we just turn that into a fraction

alr

I'll do this

do I times both sides by

3x(x-9)

[rotund vine]

yes

[radiant jolt]

this is what I did rn, is it right?

[livid hound]

don't use x for multiplication

use $\cdot$

[wraith dagger]

ℝamonov

[radiant jolt]

wait

why not

isn't that

just

calc thing

[livid hound]

no

because with the plethora of variables present,
it can easily be confused with the variable x

[dire geode]

$x x y$ could mean $x^2y$ or x times y

[wraith dagger]

riemann

[radiant jolt]

alr alr

I'll use a dot

using $\cdot$

[wraith dagger]

Jarad Higgins

[rotund vine]

or just use ()

[radiant jolt]

oh that's better

[livid hound]

excessive parentheses is a bit painful on the eyes too

[rotund vine]

lol true

[livid hound]

but less criminal

[supple lion]

I use a small mini x in the middle

[rotund vine]

but small dots

[supple lion]

Is that ok?

[rotund vine]

yea if that works with you

but not so good in hw or exams or etc

[livid hound]

so small that its indistinguishable from a dot?

[supple lion]

I used a dot until I learned it meant something else when working with vectors. So it's ambiguous!

[rotund vine]

yea

dot product and cross product

different meanings

[supple lion]

And I don't want to have to switch it up depending on the subject lol

[rotund vine]

um, btw ben I would really like to continue the discussion

but let's just focus on the question for now 🙂

[radiant jolt]

wait

there's an error

on my calc

everytime

I press enter

[rotund vine]

yea

[radiant jolt]

It's like

Error: invalid implied multiply

what does that mean

[rotund vine]

um not a calculator expert

but what calculator are you using

[radiant jolt]

Ti inspire

[supple lion]

what did you type in it

[radiant jolt]

CAS

I just put i

[rotund vine]

84?

[radiant jolt]

what

umm

[rotund vine]

nvm

[radiant jolt]

it's literally

Ti-nspire cx roman 2

[rotund vine]

oh thanks

um I don't think I can help

I don't have ti calculators actually

[radiant jolt]

umm

alr

it's not working

for simple stuff

like

2x(x)

I mean it works without the brackets

[dire geode]

What we're saying applies here in text, not your calculator that probably very few people use

[radiant jolt]

yup, I got it right

Imma just use the quadratic formula

I got the answer

x=44.4969

but

why doesn't the answer

have the negative value as well

x= -35.4969

??

[livid hound]

negative speed...

[radiant jolt]

oh right

how do I do this one tho?

[cedar kiln]

@radiant jolt Has your question been resolved?

[radiant jolt]

<@&286206848099549185>

[cedar kiln]

@radiant jolt Has your question been resolved?

[buoyant latch]

Did you solve x

[radiant jolt]

Yes

I got it

x=45

[cedar kiln]

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[radiant jolt]

.reopen

[cedar kiln]

✅

[radiant jolt]

alr

Imma just

remember the equation

we came up with yesterday

well you did

T(fast) = 9 +(x - 9)

T(slow) = (x - 9)

and just sub x=45 in there

and get the speeds of both the trains

and I got it

Imma go and do my polynomials sheet now

.close

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[edgy hazel]

how to plot them in matlab? also how to estimate Value at Risk at different values for a[0.8, 0.99] at intervals of 0.01

[edgy hazel]

im trying to compare these two investment models

<@&286206848099549185>

i need help please

[cedar kiln]

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@edgy hazel Has your question been resolved?

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[bleak rain]

doing c)
i got that $\ker T \cong U \cap W$ and $\Im T = U + W$ so $\dim \ker T = \dim (U \cap W)$ and $\dim \Im T = \dim (U + V)$

[wraith dagger]

ally 🌈

[bleak rain]

but this would imply that by dimension formula $\dim (U \cap W) + \dim(U+W) = \dim V$ which is wrong since that would imply $\dim U + \dim W = \dim V$

[wraith dagger]

ally 🌈

[bleak rain]

where have i gone wrong

[cedar kiln]

@bleak rain Has your question been resolved?

[bleak rain]

<@&286206848099549185>

[tropic oxide]

but dim(ker(T)) + dim(im(T)) is the dimension of the domain of T, i.e. U times W

not its codomain

[bleak rain]

ohhh

thank you

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[main otter]

Having troubles on how do this question

[upper swallow]

input the values that are given in the question into the venn diagram

[cedar kiln]

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[peak sundial]

I need to find the limit

Previously they asked the limit to xn and i did that pretty easy using the fact that the function is bijective

[cedar kiln]

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[short chasm]

hey i need help solving this problem

[pulsar summit]

try rationalizing both of the roots

[short chasm]

btw no lohpital rule

[pulsar summit]

that would make the question far harder than it needs to be anyway

[pulsar summit]

you'll need to use (a-b)(a^2+ab+b^2)=a^3-b^3 for the cube roo

root

[short chasm]

what would be order of operations?

[pulsar summit]

wdym?

are you familiar with rationalizing the denominator

[short chasm]

Yes

[pulsar summit]

exactly which order of operation are you confused about here?

[short chasm]

Nothing about, thank you ill try rationalization

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[midnight zealot]

How do I go about finding b)?

I know that I have to find the maximum of the quadratic relative to the linear function. But I only know know how to do that by finding the vertex and I have know clue how to find the vertex relative to a linear function

@buoyant latch

[buoyant latch]

If u minus g(x) from f(x) you have a new function let’s call it h(x)

This h(x) means the distance of the balloon from the ground

h(x) = f(x) - g(x)

Now find the maximum of h(x)

[buoyant latch]

What is h(x) from this

[midnight zealot]

Oh

Interesting

I'm having trouble conceptualizing how that worked out

Or what this new function like exactly means

[midnight zealot]

@buoyant latchWait so the vertex of this doesn't look like it's the highest point

[austere heath]

use local maximum

idk i think im late

[midnight zealot]

How do I do that?

[austere heath]

i just finished solving

derivative

[midnight zealot]

There shouldn';t be any derivatives involved

[austere heath]

which part are you working on now

[midnight zealot]

Cause it's pre-calc

The next assignment

lmao

I have no clue where to even start

[austere heath]

you done?

[midnight zealot]

I've been working on this one quesiton all day

[austere heath]

part a just look at the graph

if no derivative

[midnight zealot]

No I was just waiting for some help

[austere heath]

500,200

[midnight zealot]

Part a I can get by finding the h of the vertex

yewah

200

c is easy

87.5

[austere heath]

yeah

[midnight zealot]

and d took a long time

but I found it

Now b I have no clue how to find

[austere heath]

idk but for local maximum, its just upper graph minus lower graph

make a new function
f(x)-0.1(x)=0

and find max

but idk what other way you were offered

[midnight zealot]

Why is this so hard

None of this was covered

in the lesson

[austere heath]

hmm

[austere heath]

i mean you still got a website, and this is the right answer

[midnight zealot]

But I don't actually know what it is

the vertex of h(x)-g(x) doesn't look right

[austere heath]

i mean its correct

i got the same answer

[midnight zealot]

The vertex is correct

[austere heath]

hm i have an idea

[midnight zealot]

it's just not the highest point

[austere heath]

no thats for part b

maximum height

[midnight zealot]

Yeah that's the question I'm trying to solve

[austere heath]

i have an idea

[midnight zealot]

Okokok

[austere heath]

f(x) - g(x) = 0

and find x for y = 0

divide largest x by 2

not sure if it works but worth a try

[midnight zealot]

f-g finds where the balloon is relative to the ground

[austere heath]

yes

[midnight zealot]

so = 50, for example

finds where horizontally

the balloon will be

when vertically it is 50

[austere heath]

yes

we talking about part b tho

[midnight zealot]

How do we use that to find the max though

[midnight zealot]

right right

[austere heath]

find the x-intercept

x/2

[midnight zealot]

why divide x by 2?

[austere heath]

doesn't it look equal on both sides to you

[midnight zealot]

yeah it does

[austere heath]

so find the middle point

by finding the max-min/2

[midnight zealot]

Wait wait

I don't get it

We're finding the max already

by finding the vertex

the problem is that it's not relative to the linear function

Or idek know

I understand none of this

[austere heath]

no max of x

maximum x-intercept

[midnight zealot]

Oh the highest root

[austere heath]

yeah

[midnight zealot]

Right

okay

[austere heath]

i think i said it weirdly

[midnight zealot]

so we find that

then what?

[midnight zealot]

npnpnp

[austere heath]

then we divide it by 2

so we find mid point

[midnight zealot]

Yeah that I don't udnerstand

how does that give us the midpoint?

[austere heath]

since its like symmetric

[midnight zealot]

the max root / 2 = mid point?

[austere heath]

symmetric

[midnight zealot]

yeah I'm just not seeing how this is relevant

[austere heath]

uh

[midnight zealot]

Probably cause they haven't actually taught me yet

THis question is fucking stupid

[austere heath]

no its just logic

[midnight zealot]

oh wait

[austere heath]

let me

put it

[midnight zealot]

okay okay ^

Ohhhhhhhh

[austere heath]

🌈🌈 highest point of a rainbow is its middle

[midnight zealot]

ohhhhhhh

[austere heath]

lol

[midnight zealot]

LMAO

LOOL

Right okay I think I get it now

So

This be the highest root

right

so 75/2

[austere heath]

wait no

[midnight zealot]

gives us the center of the linear

Okay nvm

I understand nothing

please help m,e

please

[austere heath]

you find the

f(x)-g(x)

let that be a function

[midnight zealot]

Yeah that's it

[austere heath]

you dont need the g(x) line anymore

find x intercept

of the black graph

[midnight zealot]

OHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH

OHHHHHHHH

Holy shit

Now I understand

[austere heath]

ye

[midnight zealot]

The vertex is indeed the maximum then

omg

I am no longer blind for the 10th time today

Tysm

[austere heath]

ok np

[cedar kiln]

@midnight zealot Has your question been resolved?

[cedar kiln]

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[fading summit]

hlep pls

<@&286206848099549185>

anyone knwo how to do

[supple lion]

wait 15 minutes to ping them

[fading summit]

oh yeah

crap

mb

[supple lion]

you have to use SUVAT right?

[fading summit]

just projectile

[velvet mortar]

what is "range of flight" meaning here?

[fading summit]

the x value

[supple lion]

what

[fading summit]

using thes rules

how would i go about solving tis equstion

anyone have a clue or nope?

<@&286206848099549185>

[velvet mortar]

can you find the intitial velocity at least?

[fading summit]

idk how

i need help