help-13

[cedar kiln]

@remote tusk Has your question been resolved?

[remote tusk]

Ok thank you for clarifying ramonov I see my mistake now

Yes @cedar kiln

[livid hound]

type .close when done

[remote tusk]

.close

[cedar kiln]

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[inner atlas]

Any help

[cedar kiln]

@inner atlas Has your question been resolved?

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[sand jungle]

Help? I don't know how to determine A in this equation.

[upper abyss]

Ignoring the equation, how might you find the perimeter of a 9-gon?

Imagine breaking it up into triangles and finding the length of each of those triangles

[sand jungle]

360 / 9 = 40 (9 triangles with the top angle 40°)
Divide each triangle into two right triangles and use sine functions with the radius 3 as hypotenuse 3

But im not quite sure where to determine "A"

[upper abyss]

That's exactly right. Once you do that, you'll get a value in the correct form

The triangle, after being halved has angle 20, hypotenuse 3

[sand jungle]

yes?

[upper abyss]

3sin(20) = half of the triangle's length

There's 18 of those halves

[sand jungle]

1.03

18.47

[upper abyss]

Those are definitely decimals

So that makes the perimeter 54sin(20)

[sand jungle]

i rounded them to nearest hundredth

54?

im sorry but where did 54 come from

[upper abyss]

3sin(20) = half of the triangle's length
There's 18 of those halves

[sand jungle]

hold on

give me a min

Oh my god

Thank you so much!

thanks for the help, it means a lot to me.

.close

[cedar kiln]

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[pseudo hazel]

For 5b) I calculated mean( Xwith line) to be 76.92857
s to be 10.71281
im confused how to set up 5c) using this info
Would it me P(Z≤50)?
then calc my z score value * population?
P(Z≤((50-76.92857)/10.71281)
=P(Z≤(-2.51)
then 250 * 0.0062 = 1.55 individuals?

[cedar kiln]

@pseudo hazel Has your question been resolved?

[pseudo hazel]

.doe

.done

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[narrow root]

so the "cost" function is a function of what?

the abilities only?

so ideally the cost increases as the difficulty increases?

and maxLevels is a constant right?

[marble bone]

Umm so "cost" Is the cost of upgrading a weapon or something?

And as difficulty increases cost function increases

?

And also MaxLevel

Two parameters

[narrow root]

seems like you could just do a linear or exponential cost function depending on your preference

[marble bone]

Now u want the formula of the

Cost function?

So the players income is linear?

And if the cost is exponential?

Then cost might be too much

I see

So you want a cost function which is affordable?

For the players

I see

[cedar kiln]

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[devout crater]

if i have an elliptic curve with basepoint G and c * G + B public key (B = b * G, B is known to adversary) and i give c + b private key to adversary, can he calculate b? c is unknown to the adversary

[devout crater]

i'm thinking no but not sure

im not sure what channel i should b asking this in tbh

[cedar kiln]

@devout crater Has your question been resolved?

[devout crater]

[sick ruin]

Hm

[sick ruin]

I don’t see how he could find c or b alone

Adversary knows bG and hence cG; with these alone he can’t know b or c. But even with knowledge of b + c, I don’t think it could help very much

It might be able to narrow it down though (if b and c are both small, their sum will be small, and the attacker can use this fact to find the values. But I think this is easily overcome by choosing “good” values for b and c)

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[cedar kiln]

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[crimson sedge]

you can use heron's formula by equating it with 1/2 base * height

[crimson sedge]

alr nvm mind i too have a problem

wait wait

this que is not easy as it seems lol

[cedar kiln]

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[crimson sedge]

.reopen

[cedar kiln]

✅

[cedar kiln]

@crimson sedge Has your question been resolved?

[pulsar summit]

.

can you tell where to go from here

[crimson sedge]

How'd you you bring that alpha -1/2

[pulsar summit]

4a^2+2a-1 is already 0

so whatever I multiply it by, it's still 0

and by multiplying it by a-1/2, you'll notice it becomes really similar to one of the choices

[crimson sedge]

You made it a lot messy ig

Maybe we could do the other way yk

Like let's take the value of beta something

Or whatever it comes

Then we know that the other root is beta indeed

So if we substitute, we will equate it to beta

[pulsar summit]

if you still dont get it

[crimson sedge]

If it gets absolutely correct

[pulsar summit]

try adding -a-1/2 to both sides

that should make it really clear

[crimson sedge]

Ughh I need to try this again

Thanks but I might need your help again

[pulsar summit]

if you want to do it your way, here you go

takes more work though

[cedar kiln]

@crimson sedge Has your question been resolved?

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@crimson sedge Has your question been resolved?

[cedar kiln]

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[amber oriole]

how do i do ii idk how to show but i do know how to differentiate

[cedar kiln]

@amber oriole Has your question been resolved?

[amber oriole]

<@&286206848099549185>

[crimson sedge]

0 years after 2019 means at the beginning of 2019

So

[amber oriole]

no the part ii

not i

i know direct proportion is y=kx

and dp/dt is 650000me(mt)

[crimson sedge]

You are gonna set an differential equation

[amber oriole]

yea

but how do i show its direct proportion to P?

[crimson sedge]

$\frac{dP}{dt}=Pm$ where m is a constant

Jeez

Wait

[amber oriole]

k

[wraith dagger]

Cuneyt

[amber oriole]

what happened to the 650 000

[crimson sedge]

Included in m I guess

[amber oriole]

Then how about the original eqn P= 650 000e(mt)? or do you not need to use the original eqn

[crimson sedge]

Beats me, find someoene else

[amber oriole]

k

[cedar kiln]

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[polar warren]

Given an interval on the real line, say, [-1, 1], is there a relatively simple and principled manner of constructing polynomials that are monotonically increasing on the given interval?

[crimson sedge]

Uhh. Why not just choose y=x for any interval?

[polar warren]

Well, I'll have some additional restrictions on the polynomial

[crimson sedge]

Ok so give them

Otherwise you can differentiate the polynomial and check if the der is positive

[polar warren]

I'm kind of looking for a more general approach for either representing such monotone polynomials, or a general-purpose way of constructing them

Basically I'll have some requirements, such as the polynomial fitting certain points (i.e. p(a) = b for some a or b), maybe some requirements on the derivative, and in addition that the polynomial should be monotone

the other requirements are just algebra: but the monotone requirement is harder to satisfy by construction

[crimson sedge]

How comprehensive does the set of solutions need to be?

Does it need to contain ALL solutions?

Or just one

[polar warren]

I am not entirely sure. Do you mean the set of solutions in the sense of "all the polynomials satisfying these requirements"?

[crimson sedge]

Ye

[polar warren]

I suppose I don't need this to be comprehensive - I think being able to construct any polynomial with a given set of properties should be sufficient

I suppose... I could perhaps construct a positive polynomial (on the given interval) and then integrate it in order to obtain a monotone polynomial? 🤔 I'm not sure if this makes the problem any easier though, since it's not immediately obvious to me how to ensure a polynomial is positive on a given interval either

unless I use a Bernstein basis, which has positive basis functions IIRC

but that's getting very complicated

[cedar kiln]

@polar warren Has your question been resolved?

[polar warren]

It seems the answer to my question might be found in the paper "Fast and flexible methods for monotone polynomial fitting", https://www.researchgate.net/publication/292674112_Fast_and_flexible_methods_for_monotone_polynomial_fitting

Thanks for engaging with me so far, @crimson sedge!

I'll close this channel now and focus on reading that paper 🙂

.close

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[crimson sedge]

Oh

Fractions of polynomials

The writing is good

(b+3)(a+2)= ab + 2b +3a + 6

Do you see why?

Bruh

Wait

Do the same for the denominator

The thing was to realise that you want an expression of the form (a+ sth) (b+ sth else)

Let's say
(a+C) (b+D)

(ab+ Da + Cb + DC)

So for me the 6 stood out

As 6=2*3

[crimson sedge]

Reopen the brackets

Of your expression

Tell me what you get

Forget about the 3b

For jow

Now

[cedar kiln]

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[left dirge]

when given a polynomial attempting to find zeroes how do you know if it's positive or negative? i.e when given

f(x)=x4−3x3−3x2+11x−6 and the graph is between -2 and 3 would the zeroes be -2, -1, 1, 2 and 3? would i repeat -1 and 1?

[cedar kiln]

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[crimson sedge]

Can someone help me?

[narrow root]

yeah ask ur question

[crimson sedge]

How can I show that the Bessel functions are linearly independent to the Neumann function

Show that the Bessel function of the first order is linearly independent to the second order

[narrow root]

do you have the forms of the 1st and 2nd order bessel functions?

i think to show two functions are linearly independent just show that 1 is not a constant multiple of another?

[crimson sedge]

This is the first kind

This is the second kind

[narrow root]

sry im not too familiar with this, but i found this doc that seems helpful...https://homepage.tudelft.nl/11r49/documents/wi4006/bessel.pdf

[cedar kiln]

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@crimson sedge Has your question been resolved?

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[dark olive]

When I rearrange:

I get: ((e^3kt)- 1)/(2+(e^3kt))

how do I get the top image?

I don't see any other solution apart from my own

where did the - come from

on the power expression

[cedar kiln]

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[merry geyser]

how do i calculate the AF

[bitter reef]

pythagoras theorem a^2 + b^2 = c^2

[merry geyser]

so 12² + 13² = 313

.help

[cedar kiln]

Commands:
clopen: .close, .reopen
factoids: .tag
help: .help

Type .help <command name> for more info on a command.

[merry geyser]

what's the command for square root

,help

[wraith dagger]

A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!

[merry geyser]

.close

[cedar kiln]

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[glossy kettle]

HAII GUYS

SO

[glossy kettle]

MY FRIEND NEEDS HELP LIKE RN

Your school is going on a field trip. It takes 2 buses to carry 64 people. Write and solve a proportion to find the number of buses needed to carry 150 people.

I CANT READ HOW TO GET HELP

IM RUSHING

IM SO SORRY

BUT PLEASE HELP

she got 10mins left help me omg

im sorry for rushing

YES

uhm idk

[elfin hemlock]

Help on tests not allowed

[glossy kettle]

oh ok

no

its homework

shes on a deadline

yes

yep

yeahhh

omfg

SAME

i tried dividing it

like 64 to 150

but it seemed wrong

cries

o

o

girl no

64 = 2 busses

its uhm

lawd

YES

i hate math sm im sorry

i got 94 in math

it sucks

so i did math

and

5

thxxx

.close

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[bronze meteor]

i need help with venn diagrams but i cant post an image on here, whats the issue ? people in other rooms can post them freely

[celest ledge]

Can you describe it in words?

[bronze meteor]

it would be better to draw it but i can try...

35 students are taking a test with 3 exercises.

2 students solved only the first exercise ( A = 2 )
3 students solved only the second exercise ( B = 3 )
First and second exercise was solved by 16 students (A ∩ B = 16)
Second and third was solved by 14 students (B ∩ C = 14)
All exercises were solved by 10 students (A ∩ B ∩ C = 10)
First or third was solved by 31 students ( A + C = 31 ?? )
3 students didnt solve neither first nor second exercise (everything thats not in A or B = 3 ??)

Im not sure about the last two lines

Is my thinking correct ?

I used this image as an example

[celest ledge]

FFTTTFT

I got all parts

[bronze meteor]

how do you visualize "first or third was solved by 31 students"

[celest ledge]

|Their union| is 31

[bronze meteor]

so "3 students didnt solve neither first nor second exercise" basically means "3 students solved third exercise" ?

or does it mean "3 students solved third exercise or solved nothing" ?

[celest ledge]

This

[cedar kiln]

@bronze meteor Has your question been resolved?

[bronze meteor]

ok thanks very much

[cedar kiln]

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[cedar shell]

hiya

[cedar shell]

i am sorry but i have no clue how the hell this happened

idk what it’s called in english (this math type) but in german we call it nullstellen bestimmen which roughly translates to determine the zero point

and i was watching a youtube video and the guy explained jt like this but i don’t understand like at all so im hoping you can help

[heavy seal]

we'd call the 'zero points' 'roots' probably.

[cedar shell]

i see why he would move the 2 to the other side but

why did it go negative

[halcyon hound]

He substracted two from both sides

[heavy seal]

The main idea here is that, if you have an equation - something where the left hand side has the same value as the right hand side - doing the same thing to both sides keeps it equal. In order to 'move' the 2 to the right, really we are subtracting 2 from both sides, so that the left becomes 5x+2-2 which is just 5x, and the right becomes 0-2, ie: -2

[cedar shell]

and how did he get to -0.4🥲

[heavy seal]

to get from 5x to x, divide both sides by 5

5x over 5 is x, -2 over 5 is -0.4

[cedar shell]

man i hate math

also

what would i search up on YouTube to try and get YouTube videos explaining this in English?

like what is it called?

[heavy seal]

solving equations, or finding the roots of equations. this equation is 'linear', so adding that to your searches might yield better results too

[cedar shell]

kk

thank you very much

[cedar shell]

but the one thing i don’t understand

why is it not 3x = -2?

[heavy seal]

when you subtract 2 from 5x + 2, you only have to subtract the 2 from one part. The 5 in the 5x doesn't have to go down by 2 as well. Think about it: 10 + 15 - 2 equals 10 + 13, it doesn't equal 8 + 13, because then we would have subtracted 2 twice.

Also, subtracting 2 from 5x doesn't necessarily give 3x, because we dont know what x is. If x were 100, 5x would be 500, but 5x-2 would be 498, not 3x = 300

[cedar kiln]

@cedar shell Has your question been resolved?

[cedar kiln]

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[lost lance]

Could someone help me with the third part of this question

[lost lance]

Im a little lost because I dont know what the acceleration is and so I cant rearrange for the mass or maybe im approaching this wrong entirely

I worked the friction to be g/2 btw

[trim sentinel]

$$a =\frac{F}{m}$$

[wraith dagger]

Pluton

[trim sentinel]

By second newtons law

[lost lance]

Where do i use that, i do not have a mass to divide by

The mass is ultimately what I am trying to find

[trim sentinel]

Oh so you are trying to solve iii

[lost lance]

yeah

[trim sentinel]

Well mg > friction force

I think

[lost lance]

So if that is correct then would it be like this ?

[trim sentinel]

Is friction g/2

[lost lance]

yeah

[trim sentinel]

Then that should be correct

[lost lance]

Okay

Thank you for your help

Have a nice day/night

.close

[cedar kiln]

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[trim sentinel]

Wait

[lost lance]

.reopen

[cedar kiln]

✅

[trim sentinel]

@lost lance is that the friction force bc in question it says its accelaration

[lost lance]

Part ii was to work out friction and so this is what i did

So i think it is g/2 unless its a mistake carried forward

[trim sentinel]

So 4.9 is friction force?

[lost lance]

Yes

[trim sentinel]

I mean it should be close to 1/2

,calc 4.9/9.81

[wraith dagger]

Result:

0.49949031600408

[trim sentinel]

Ye close enough

Ok then it should be correct

[lost lance]

Okay thank you I really appreciate it

.close

[cedar kiln]

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[violet rapids]

what have you tried

[mental walrus]

Cuz there are doubles

since 2 of each

[cedar kiln]

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[crimson sedge]

first degree equations with two unknowns can somebody explain

[crimson sedge]

lets say i have 2x - y^2 = 0 how do i do that and why is there 0 after equal?

what does even first degree means

god pls somebody help me

<@&286206848099549185>

[vague fiber]

Okay, @crimson sedge, first of all, how have you tried to solve this problem?

[crimson sedge]

i have no idea how to do it when i have 2 letters

[vague fiber]

Okay, I am just going to point out that you can't actually "solve" this problem...

But you can write a formula to find the remaining variable if you have the other

[crimson sedge]

hmm okay lets see

okay i think i understand a few first excersises but then it gets really hard

[vague fiber]

https://youtu.be/o5e8fO1qyIw

https://www.google.com/search?q=how+to+find+the+degree+of+a+polynomial&oq=how+to+find+the+degree+of+a+polynomial&aqs=chrome..69i57j0i512l9.5206j0j7&sourceid=chrome&ie=UTF-8

These are some resources for finding out what a degree is...

Do you have any extra information about the equation you have above? @crimson sedge

[crimson sedge]

alr i think i understand now

so

the excercise is to tell which one of these are first degree with two equations not to solve them

[vague fiber]

Okay, so are you able to tell what ones are first degree polynomials?

[crimson sedge]

no idea what requirements they need

The first one

im just supposed to tell which ones are first degree

[vague fiber]

I am sorry, I don't understand the language that is written in.

[crimson sedge]

yeah i know so i wrote what im supposed to do there

[vague fiber]

Okay

[crimson sedge]

in excersise 5.2

what are the requirements for equation to be first degree?

[vague fiber]

Simply that the degree of the polynomial = 1

https://youtu.be/o5e8fO1qyIw
https://www.google.com/search?q=how+to+find+the+degree+of+a+polynomial&oq=how+to+find+the+degree+of+a+polynomial&aqs=chrome..69i57j0i512l9.5206j0j7&sourceid=chrome&ie=UTF-8
I think that these are great resources for finding out the degree of the polynomial

[crimson sedge]

could you tell me which ones of this excersise are first degree?

[vague fiber]

No, because it appears that is your homework and by #rules I can't

[crimson sedge]

this is not my homework i have a test tommorow and i wanna do every single excersise

so that im sure i will pass

[vague fiber]

It doesn't have an answer key in the back of the book? (Generally my books of that sort have an answer key in the back.)

[crimson sedge]

oh i forgot about it

alr, few next excersises are just about using numbersin brackets and checking if they fit the answer

and then boom

give three examples of pairs of numbers that satisfy the given equation. then, in a rectangular coordinate system, sketch the equation plot and mark points on it whose coordinates are equal to these pairs of numbers.

a) -3x+5y=10

[vague fiber]

Okay lets turn this into a formula so that we can input 'x' and output 'y' in order to get our three coordinate pairs.

[crimson sedge]

how do we do that

[vague fiber]

Do you know how to algebraically rearrange a equation? (Just asking to see what tools I can use.)

[crimson sedge]

no

its 9 grade math i think they know its really simple so they want me to just think about it

its like 2 + x = 5

[vague fiber]

Yes

[crimson sedge]

hmm

then -3x + 8 + 5 + 0 would be 10

i dont know how to draw it i mean the coordinate system

[earnest wedge]

Hey, so what's your question, snoop?

[crimson sedge]

i dont know how to draw coordinate system

thank you guys but im just going to cry for now

.close

[cedar kiln]

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[fervent viper]

Did I do this right?

We had to complete the square to find the formula for a surface formula. I deduced it was elliptic cone -- is this correct

I just need a check off

[celest ledge]

It’s a hyperbola rotate around a line, don’t know what it’s called

[fervent viper]

im following my textbook formulaa

a set of three with one variable being negative all = 0 is an elliptic cone

so did i do this right?

[celest ledge]

I see, then right

[fervent viper]

i completed the square correctly and the formula was done correctly as well ?

here is the graph in geoalgebra for reference

[violet rapids]

@fervent viper i love remi wolf

i have 215 scrobbles

[fervent viper]

she is the love of my life.

genuinely

[violet rapids]

she doesnt have a bad song

[cedar kiln]

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[pliant orbit]

you could further divide to

$$\frac{a}{3}$$

[wraith dagger]

geoxcaliber

[pliant orbit]

right? is it better?

oh shit you can't do that cuz theres a plus right

[vernal palm]

no, that's not how it works

exactly

you can simplify it a little bit tho

what's something that each of the three terms has

[pliant orbit]

3

[lusty flax]

So you can simply 3 right?

[pliant orbit]

yes

[vernal palm]

so what would that turn into

[pliant orbit]

$$\frac{2a^2}{2a+1}$$

[wraith dagger]

geoxcaliber

[vernal palm]

yep

that's all you can do tbh

[pliant orbit]

You can't just divide if there was a minus as well right?

[vernal palm]

exactly

[pliant orbit]

Ok thanks

[vernal palm]

ofc

you can .close the channel if ur done

[pliant orbit]

.close

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[crimson sedge]

this what I got

have you checked with synthetic?

[glad kestrel]

what is your question

[cedar kiln]

@crimson sedge Has your question been resolved?

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[tacit juniper]

Hey, quick limits question!

[tacit juniper]

I'm practing lhopital's rule

And I was wondering if, given the product law for limits

Would it be possible to rewrite a rational function as the product of two functions, one rational and the other not?

And then use LR on the first function to get the limit and just multiply it by the limit of the seconf function?

So like, f(x) is rational, let f(x) = R(x)*h(x), where R(x) is rational and the limit is of form 0/0, while the limit of h(x) is just 1

Can I just use l'hopital's rule on R(x) and multiply the resulting limit by 1? Again, based on the product law of limits

[upper abyss]

L'hospital's rule isn't doing anything in this case. Yes, you can split a limit between products.

[tacit juniper]

Not in splitting the function, I would use it after splitting.

Just so I don't have to find the derivative of an annoying product, really

I don't see anything that would immediately be wrong, but I wanted to make sure

[cedar kiln]

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[dusky pollen]

I need help on how to simplify this expression. The part I’m stuck on has a squiggly underline.

[dense wing]

what's x+x?

[dusky pollen]

2x

[dense wing]

yes

[dusky pollen]

so it would be 2sin0cos0?

[dense wing]

sin(theta)cos(theta), but yes

[dusky pollen]

thank you! i was told it was wrong

[dense wing]

well it can be more simplified if you know double angle identities

[dusky pollen]

but is there a way to simplify further??

oh i don’t know those too well

[dense wing]

But if you're not yet at double/half angle identities, then that's as simple

[dusky pollen]

thank you so much!

[dense wing]

If you've been shown them, then you need to apply it here

[dusky pollen]

.close

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[fossil coral]

hi

[fossil coral]

A 2kg crate rests on the floor. How much work is required to move it when pushing with 10 N of force: (HINT: Draw a free body diagram to determine the net force on the crate)
(a) 3m along the floor against a friction force of 4N

how to do this?

[glad kestrel]

have you drawn a diagram

[fossil coral]

nyet

no

[glad kestrel]

then draw a diagram

[fossil coral]

.close

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[tame socket]

I am having troubles with what to do in regardss to how what to do with a negative exponent and multiplying a coeefecient by a radical

[bold vine]

a^(-b) = 1/(a^b)

and √(ab) = √a • √b

These are the properties you'll use to simplify this

[cedar kiln]

@tame socket Has your question been resolved?

[tame socket]

lemme try osmething

i just dont get it

nvm

.close

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[crimson sedge]

can someone explain to me the ratio continued property rule thing

It doesn't make sense to me

[cedar kiln]

@crimson sedge Has your question been resolved?

[livid locust]

Do you understand what the ration is between dogs to squirrels?

[crimson sedge]

@livid locust

not really

like other than the numbers the problem gives me?

[livid locust]

Sorry I was helping someone else. But no, I mean from the numbers provided.

So the ratio of cats to dogs is 4 : 5

The ratio of dogs to squirrels would be what?

[crimson sedge]

@livid locust 5:12

[livid locust]

Exactly.

So for every 5 dogs, there are 12 squirrels.

[crimson sedge]

alright

[livid locust]

Now, what is the ratio between squirrels to raccoons

[crimson sedge]

10:3

@livid locust

.

?

@bold vine

can you help

[bold vine]

Don't ping random people.

I've said it before.

[crimson sedge]

the guy that was helping me

just randomly left

.close

[cedar kiln]

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[hollow crane]

Yo I need help please 🙏

[steady imp]

https://tenor.com/view/patrickbateman-pointing-at-dance-gif-12362561

[hollow crane]

This question

[hollow crane]

Based

[steady imp]

I'm not sure what I'm reading here

[dire geode]

yea there's not enough information here to help you.

[hollow crane]

What’s missing

I can send it

[dire geode]

like your question

what have you tried

what are you stuck on

[hollow crane]

I just don’t how to find a and then find the square root function

[dire geode]

we don't know how to find a either

since you didn't tell us what a is

[hollow crane]

I don’t know how to find a either

[dire geode]

probably in your textbook and/or notes

[hollow crane]

All I really need to know is which point here is “farther from the end point and appears to lie on or very close to the line of best for”

The endpoint is (160,10.16) right?

[dire geode]

idk what's the definition of endpoint?

why isn't it the first point near (0,0) ?

[hollow crane]

The graph is made out of data I recorded

[dire geode]

what does that have to do with the definition of "endpoint"

what does your textbook say an "endpoint" is ?

[hollow crane]

I don’t have a textbook

[dire geode]

lecture notes then

[hollow crane]

Well obviously the two points at the ends but it’s asking for only one

Idk which one

(160,10.16) or (0,0.8)

How am I supposed to figure out what this point is “farthest from the endpoint and appears to lie on or very close to the line of best fit”

<@&286206848099549185>

Someone please

How do I find a

And write the equation in transformative form

<@&286206848099549185>

[cedar kiln]

@hollow crane Has your question been resolved?

[cedar kiln]

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[plain wraith]

how do i find the value with the hint way

<@&286206848099549185>

[cedar kiln]

@plain wraith Has your question been resolved?

[pliant bear]

so each consecutive pair of terms is of the form n^2 - m^2

[plain wraith]

ok

[pliant bear]

more speficially n^2 - (n+2)^2

it's, hm, 2^2 - 4^2 + 6^2 - 8^2, right

[plain wraith]

6^2 - 8^2

yea yea

[pliant bear]

for the first four terms

so you can rewrite each pair of terms as (n-m)(n+m)

but m is n+2, right?

[plain wraith]

yea'

[pliant bear]

so that's (n-(n-2))(n+(n+2))

[plain wraith]

sub in

4n +4

[pliant bear]

and that simplifies to 2(2n+2), or 4n+4

and n is just 2k

now you have to only add the suym for odd k because you sucked in the even k's

[plain wraith]

ok so i get the 4n+4 but what is it equal to

equal to one part of (n-m)(n+m)?

[pliant bear]

in the sum, each consecutive pair of terms can be replaced by 4n+4

so instead of 4000 terms, yhou onlty have 2000, and you skip every other k

[plain wraith]

but first pair for eg is 4-16 which give -12

[pliant bear]

yes, this sum is negative

[plain wraith]

using the 4n+4 its 12?

[pliant bear]

which is weird, i don't get that either

obviously did something wrong 🙂

[plain wraith]

[pliant bear]

oh, right duh

m = n + 2

but i subbed n-2

so it's (n-(n+2))(n+(n+2))

and that comes to -2 (2n+2), or -4n-4

[plain wraith]

[pliant bear]

good spot

[plain wraith]

i do shortcut and forgot to open bracket

mistake

i will remember this

[pliant bear]

i flipped the minus twice

tbh i usually use sage for stuff like this, because i make little mistake slike that all the time

[plain wraith]

for 3rd and 4th term

36-64

-28

[pliant bear]

n was 2 for the first pair, 6 for the second, it'll be 10 for the third

so that means n is related to k how?

[plain wraith]

plus4

[pliant bear]

actually 2k-2

when k =1 n =2, k = 2 n = 6, k =3 n = 10

but also remember that you cut the nunber of terms in half, so your sum only goes to 2000 instead of 4000

[plain wraith]

isnt it 4k-2

[pliant bear]

yup, typo sorry

[plain wraith]

btw how u get 2 6 10

[pliant bear]

the third pair is 100 - 144

[plain wraith]

oo so it is found by calculation?

[pliant bear]

the calucluation helps you find the pattern

[plain wraith]

and base on the cal u find the parrtern

[cedar kiln]

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[plain wraith]

ahh

[pliant bear]

once you find the pattenr, you prove it's correct by algebra

.reopen

[plain wraith]

ahh

so i can make new formula right

i mean equation

[cedar kiln]

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[pliant bear]

yhou should be able to, i assime you know the formula for the sum of the first n integers

[plain wraith]

alright i think i can manage

thks a bunchh

[pliant bear]

np

good luck

[plain wraith]

[pliant bear]

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[round compass]

I need someone to walk me through some problems, this is for statistics.

[round compass]

Please ping me if you can help.

[glad kestrel]

• After 15 minutes, feel free to ping @Helpers.

[round compass]

Sorry.

[cedar kiln]

@round compass Has your question been resolved?

[round compass]

No.

<@&286206848099549185> Can someone help me out?

[dire geode]

Statistics isn't a popular topic for helpers

[round compass]

Why not?

[dire geode]

Considering most math departments don't even require a single statistics course for their bachelor's

Maybe try a statistics server

[round compass]

Can't find one.

If you could find one please let me know.

Guess I'm just gonna drop out of this class.

[cedar kiln]

@round compass Has your question been resolved?

[cedar kiln]

@round compass Has your question been resolved?

[cedar kiln]

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[small glen]

Hi. I need helpt with c or d. Thank you. spent a lot of time to think, but still stuck 😦

[cedar kiln]

@small glen Has your question been resolved?

[cedar kiln]

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[blissful mauve]

I have some math questions

[blissful mauve]

”What time is it if what is left of the day is 5/3 of what has gone of the day. One
day is 24 hours and starts at 00.00 ie midnight.”

[worldly seal]

@blissful mauve what have you tried?

[blissful mauve]

I haven’t tried to solve it

I couldn’t get it

[worldly seal]

Do you know what to do with the 5/3?

Its a ratio

5:3

How would you split 24 hours with this ratio?

[blissful mauve]

Wouldn’t it be 3

Like 24/8

[worldly seal]

Yep 24/8

Thats 1 part of it

Now you can go from there

[blissful mauve]

Still kinda lost

Sorry

[worldly seal]

3 is one part of the ratio

You have 5:3

You will have to times it by 5 to find what 5 are, as 3 is only 1

[blissful mauve]

So 15 + 3

18 hours has gone by ?

And the answer would be 6 pm ?

[worldly seal]

Why +3?

[blissful mauve]

Do you want explain how the whole thing works ? Cuz I feel a bit lost

[worldly seal]

We divided 24 by 8 to find how much 1 is worth in out ratio

Since the ratio is 5:3, to find where this is we could either times 24/8 by 5 or take 24/8 times 3 away from 24

[cedar kiln]

@blissful mauve Has your question been resolved?

[blissful mauve]

So just 15 then

That’s what’s left of the day

And the time would be 9 am ?

[cedar kiln]

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[blissful mauve]

.reopen

[cedar kiln]

✅

[blissful mauve]

Am I right ?

[cedar kiln]

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[steel ledge]

given a certain function f, how can i compute limit 0+ and 0- ? What's the difference between computing limit 0 ?

[steel ledge]

I mean, I know theoretically the difference, but when calculating the limit I do not know

[frigid canyon]

you calculate both the limits and then if they are equal, we say it's equal to the limit tends to zero

[narrow root]

^

but sometimes the limits aren't equal

consider the function $1/x^3$

[wraith dagger]

elemen

[narrow root]

$\lim_{x\to 0^+} \frac{1}{x^3} = \infty$ and $\lim_{x\to 0^-} \frac{1}{x^3} = -\infty$

[wraith dagger]

elemen

[steel ledge]

i agree, but i mean how do I calculate both the limits, like what's the difference between calculating limit of f(x) when x->0 and limit of f(x) when x-> 0+/-

[frigid canyon]

dude

use this

might be better

[steel ledge]

i do think i understand this part, just not the technical part of how to get the limit on both sides of x_0

because in my case, the function is the same on the entire domain

[frigid canyon]

what's your case, then?

[steel ledge]

defined on [-1,1] \ {0}

[frigid canyon]

see dude

we can use predefined results and evadecalculating both limits

do that

[steel ledge]

what does that mean

[frigid canyon]

like these

[glad kestrel]

what exactly are you trying to find

[frigid canyon]

lim tends to 0

[glad kestrel]

ah

[steel ledge]

I am looking for lim -> 0+ and lim -> 0- so that I can get g(0) the continuous extension of the function f

[elfin hemlock]

The difference is in signs only if no piece-wise definition (if there even is a difference)

[narrow root]

so you want to find lim x->0+ and lim x->0- of this function right?

[steel ledge]

oh so i just take -L for zero minus?

[steel ledge]

yes!

[elfin hemlock]

What no

[steel ledge]

what do you mean by the difference is in signs only

[elfin hemlock]

Say there is a fraction with x in numerator for example

If x approach 0 from the left then the fraction is negative always

If from the right its positive

[elfin hemlock]

As for calculating your limit try multiplying and dividing by 2x

(Or LH)

[steel ledge]

okay I think I understand a little better, though I do have a question
limit of x->0+ IxI/ x =1
limit of x->0- IxI/ x =-1

and i'm not sure why, though I think it's because of what you told me earlier? But limit of x/x = 1 always regardless of x->0+ or -

[elfin hemlock]

|x| is a piece-wise function

If x>=0 then |x|=x

If x<0 then |x|=-x

Understand the result now?

[cedar kiln]

@steel ledge Has your question been resolved?

[steel ledge]

yes!! thank you very much!

.close

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[willow karma]

I think this is the intergral

to solve for the mass

But i wanna make sure

[dire geode]

What's the definition of mass

Just integral of density on D?

[willow karma]

All i remember from lec

is that it uses

[dire geode]

I think you solved for y incorrectly

In the upper y limit

[willow karma]

∫∫P(x,y)dydx

is the def of the mass

[willow karma]

did i?

[dire geode]

Show your work

[willow karma]

That's-x^2 +4

[dire geode]

Mistake in first line

[willow karma]

BRUH

Ur right

SMH

Thank you

Omg

[dire geode]

[willow karma]

Idk how I got this far

[dire geode]

Small mistakes happen. Do it on hw, not tests

[willow karma]

Tyty

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[willow karma]

Would this be the correct way to set up the integral?

wait its center isnt at 0

It would be this right?

[jaunty mural]

Are you told to integrate in cartesian?

[willow karma]

Not specifically, should i convert to polar ?

[jaunty mural]

Think why it might be a good idea

[willow karma]

yeah cause its a circle

integrate from 0 - pi?

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[fervent bay]

I forgot how to explain the reasonings. (Study guide question, study guide isnt graded)

[cedar kiln]

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[fervent bay]

<@&286206848099549185>

[river drum]

Can you show me what you've attempted sofar?

Do you know what the symbols are representing such as ≅?

[fervent bay]

I know the symbol means congruent, and I know || means parallel

the postulates confuse me the most, im guessing its sas postulate since its a right trangle meaning R is 90 degrees

but I dont really know

[fervent bay]

I also dont know the name of the reasoning for Q ~= Q

[sonic thistle]

https://www.teachoo.com/4284/1051/Theorem-6.1---Basic-Proportionality-Theorem/category/Theorems/

look there at proff

proof

[cedar kiln]

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[crimson sedge]

angle RQS is common in both triangles

by corresponding angles angle QAB = angle QRS

likewise with angles QBA and QSR

therefore the triangles are similar

and so the ratio of corresponding sides is the same hence QA/QR = QB/QS

[fervent bay]

ty

.close

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[sharp bay]

A and B are matrices, find (B^-1 * A)^-1

[sharp bay]

Is it just B * A^-1

[upper abyss]

^-1 distributes AND flips the order

A^-1 * B

[sharp bay]

ah thank you, it was the last question in my textbook and was suspicious it might be too easy

I didn't know it flips the order

[dense wing]

It's same w/ transpose

[cedar kiln]

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[bold hinge]

Why can't we make it commute

It should commute

[late wing]

why should it commute?

[jaunty mural]

Is this joke

(a x b)(b x c) --> (a x c)

[dire geode]

EndTimes trollin' y'all

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[rough snow]

um im sorry mate but

i sent my pic a bit quicked so

this is my help channel

[bronze briar]

Oh my b

[rough snow]

sorry

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.close

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[slender sentinel]

how should one go about factorising $(z^2 - z +(-1+3i))$

[wraith dagger]

Vince Tafea

[dense wing]

are you sure your question isnt to solve that=0?

[slender sentinel]

its part of an overall question of finding linear factors to a polynomial. it is a factor so yeah it would be a root so yeah i think u can =0?

$(z^2 - z +(-1+3i))=0$

[wraith dagger]

Vince Tafea

[dense wing]

yeah, so you want to find the roots

so quad formula

[slender sentinel]

alright yeah thanks so i get:

$\frac{1+-sqrt(5-12i)}{2}$

[wraith dagger]

Vince Tafea

[slender sentinel]

ah yeah ok thanks ill just work on it n brb thank u for pointing me in right direction

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[fossil lava]

how does one verify that an optimal solution, given by the lagrange multiplier method, is indeed a max or min using the second derivative test?

[fossil lava]

more specifically, I have a solution to the problem: “minimize f(x,y,z) subject to g(x,y,z)=k”
how can I “verify my solution using the second partials test”?

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[warm vector]

I don’t understand how to find the coordinates of point C.

[steady imp]

are there some numbers involved with these lines and points

[warm vector]

Um yh two sec

These were the questions related to this diagram and I’m stuck on h)

[obsidian coral]

Is that a test?

[warm vector]

It’s a past paper from 2016 it says up there on the docx

[steady imp]

time travel?

[warm vector]

What?

Ok 2 sec

[steady imp]

I'm pretty sure there's still not enough information

someone else want to look at this?

[warm vector]

See, it’s a post on my classroom

For past papers In my school

Is this still not enough?

[obsidian coral]

Where exactly is point A?

[obsidian coral]

Don't see it here

[warm vector]

Oh yh it’s a typo point A is on the x axis wait let me mark it

[obsidian coral]

Did you do part E?

[warm vector]

Yes

I did the rest

[obsidian coral]

Did you find the equation of the line l2?

[warm vector]

Yes

Wait I will be back I have to go now

[obsidian coral]

Because the intersection, which is point c, is just set the two equations equal to each other, find x, then use that x, plug it into one of the equations, find y

[warm vector]

Ok

That’s what the answer also says but the where Did the equation of y= -2/3x+8 2/3 come from

[obsidian coral]

The answer from part E

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[cedar kiln]

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[pale kiln]

Is the domain

[-1, 7]

Infinity?

Oh cool, i didnt know that

Thank you

Polynomial is this right 3x^3

But not this

3x

Oh interesting

Whats not a polynomial

[sick ruin]

$$\sqrt x$$ is not a polynomial

[wraith dagger]

abs_0

[pale kiln]

So root numbers are not polynomials?

[sick ruin]

The power of x must be a number like 0, 1, 2, 3, …

So no fractions, no negatives, etc

[pale kiln]

Aight

Coolio

[sick ruin]

Also, $$\sqrt{x + 3}$$ is not a polynomial even though it’s technically $x^1$

[wraith dagger]

abs_0

[sick ruin]

Refer to this if you’re ever in doubt

[pale kiln]

The y values are decreasing as the x values increasing

Aight

In the graph

Its decreasing overall right?

[sick ruin]

No, it goes up then down then up then down again

[pale kiln]

So its neither increasing or decreasing?