Wait
#help-13
dull anchor
trim stump
alr
dull anchor
Yea
dull anchor
AYYYYY
trim stump
trim stump
no
it was a celebration
of my braincells
commiting suicide
but thanks for ur time mate
dull anchor
Is this homework for school?
dull anchor
Yea fuck that teacher this shit isnt working
trim stump
trust me
dull anchor
But the answer is 100% correct
trim stump
man has the forehead for a plane landing but no brain inside
dull anchor
If you show this to your teacher hes not gonna cry
dull anchor
man has the forehead for a plane landing but no brain inside
HAHHAHAHAH
dull anchor
nah this shit massive correct you can trust me man
cedar kilnBOT
dull anchor
have a nice day
cedar kilnBOT
Available help channel!
bright flame
If you have this graph, is the right hand limit then +unlimited, or f(a)?
bright flame
If you have this graph, is the right hand limit then +unlimited, or f(a)?
For a
dense wing
$\lim_{x\to a^+}f(x)=\infty$
wraith daggerBOT
Mosh
dense wing
no
bright flame
Why not?
dense wing
the limit as you approach a DNE
bright flame
What's dne?
dense wing
does not exist.
dense wing
yeah, but the sided limits are different
I never said f(a) DNE, don't put words in my mouth
bright flame
I don't understand
dense wing
$\lim_{x\to a^-}f(x)=0$
wraith daggerBOT
Mosh
bright flame
Ye that I understand
dense wing
0 isn't infinity, so $\lim_{x\to a}f(x)$ DNE
wraith daggerBOT
Mosh
bright flame
Imagine if I get this function and have to find lim x->a
And I just enter a in the function and get 0,it would be wrong?
bright flame
Ahhh so only if we know it's continuous we don't have to check whether or not the right and left are different?
dense wing
if you know it's continuous, then $\lim_{x\to a}f(x)=f(a)$
wraith daggerBOT
Mosh
dense wing
By definition.
crimson sedge
what level of math is this
dense wing
And this one ain't so we check both sides and lim a DNE
yes
dense wing
what level of math is this
calculus.
cedar kilnBOT
crimson sedge
math
cedar kilnBOT
Available help channel!
sharp kettle
I have a DGL $4 \frac{\mathrm{d}^{2} x}{\mathrm{~d} t^{2}}+10 x=0$ with the general solution $x(t)=c_{1} \cos \omega t+c_{2} \sin \omega t$. I want to find $c_1$ and $c_2$.
wraith daggerBOT
Simplex
sharp kettle
$x'(t)=-\omega c_{1} \sin \omega t+\omega c_{2} \cos \omega t$
wraith daggerBOT
Simplex
sharp kettle
$x(t)=-(\omega^2 c_{1} \cos \omega t+\omega^2 c_{2} \cos \omega t)$
wraith daggerBOT
Simplex
dense wing
what are the initial conditions?
sharp kettle
x(0)=6 and x'(0)=5
dense wing
so plug those in, and you get equations for c_1 and c_2
you also know omega, idk why you haven't written it in explicitly
sharp kettle
How do I know Omega?
dense wing
you have the DE
sharp kettle
Yea
dense wing
$\ddot{x}+\frac{5}{2}x=0$
wraith daggerBOT
Mosh
dense wing
$x(t)=A\cos(\sqrt{2.5}t)+B\sin(\sqrt{2.5}t)$
wraith daggerBOT
Mosh
dense wing
$\ddot{x}+\omega_0^2x=0$.
wraith daggerBOT
Mosh
dense wing
DE for any SHO
dense wing
simple harmonic oscillator
sour glacier
Can I have some guidance on how to solve this? I just did a similar one but this one gives a general equation so I’m lost
sour glacier
When do they even intersect? Like what should I be looking for?
mighty drift
x1 is a set of points parameterized by t1 (more specifically a line). Find which point(s) also respect the equation of the plane
this should give a linear equation in t1
sour glacier
I see, that makes a little more sense so thank you. How would I start solving this tho? I was thinking of finding the direction vectors for both and the scalars but that wouldn’t work cause they’re not supposed to be parallel
mighty drift
using x = 1+t, y = 2-2t, z = 3+2t
plug this into the plane equation and solve for t, this gives you the point
sour glacier
Ohhhh!! I missed that completely, thank you so much
mighty drift
Always remember you can swap from thinking about points to thinking about their coordinates and vice-versa
sour glacier
I thought the position vector was (3,-2,6) but it’s incorrect. Where am I going wrong?
mighty drift
I thought the position vector was (3,-2,6) but it’s incorrect. Where am I going ...
don't know how got (3, -2, 6). You got 9t = 1, just plug t = 1/9 into the equation for the line, that gives you your point
sour glacier
I found that t=1/9 but I wasn’t sure how to plug it into the general equation, now I realise I was supposed to put it into the line equation 🤦♀️ sorry! thanks again
I hate vectors
.close
twin smelt
claim
obsidian coral
claim
You need to close the other channel you have open
You can't open multiple channels
modern compass
In step 5, what segment exists in those triangles that isn't in your picture?
twin smelt
oup
modern compass
What are the sides of that triangle?
twin smelt
up,op,ou
modern compass
is segment UP in your picture?
twin smelt
no
modern compass
So you need to draw it in step 1
cedar kilnBOT
cedar kilnBOT
Available help channel!
plucky rock
Hello, I'm currently stuck on a hw problem where I'm required to find my best chances of wining a game and my choices are to pick either 50 rolls or 150. The game is that I need to roll 2 dice and their sum must be greater then 8 on at least 40% of my rolls. I was wondering if I can get some help with this please? Thank you!
dire geode
Calculate the probability of each?
plucky rock
Yeah I'm not really sure how to do that... I tried doing the P(a)=1-P(notA)
but I can't get the answer to it...
is there a formula I can use to plug in the numbers?
dire geode
Binomial distribution
plucky rock
this one right?
dire geode
Yah
plucky rock
hey sorry I tried plugging it in but I still cant seem to get the right answer 😦
is there another way?
dire geode
Did you calculate the probabilities
plucky rock
yes i did
dire geode
Show your work
plucky rock
ok
p(15)=(36)(5/18)^15(13/18) (these numbers are for the exact same problem its just that the number changed a little I'm using htese numbers because I have the answer to this problem and not the one I posted)
dire geode
That's one exact value probability. You have to calculate the "at least" portion
dire geode
Sum all the relevant probabilities
plucky rock
sorry Im kinda confused by that...
dire geode
P(X>=8) = 1-P(X=0)-P(X=1)-...-P(X=7)
plucky rock
I see so you do 1-p0-p1-p2... to p7?
I got 1-(13/18)(5/18)(5/18)(5/18)(5/18)(5/18)(5/18)(5/18)(5/18)
wait actually i figure it out! thank you for your time and your help! 🙂
.close
twin smelt
claim
twin smelt
how do u do thesse types of problems
twin smelt
ok
steady imp
But lets go really generic
twin smelt
ok
wraith daggerBOT
KurtDee
twin smelt
ok
steady imp
So what does 12% mean
twin smelt
sugar?
steady imp
it means $\frac{S}{M} = 0.12$
wraith daggerBOT
KurtDee
twin smelt
ok
steady imp
Everything looks good so far?
twin smelt
ya
steady imp
So you can solve for the number of grams in the mixture assuming that 5g sugar is 12%
twin smelt
ok
steady imp
so what is it
twin smelt
i am stil a little confused
twin smelt
like the formula kinda
steady imp
what's confusing about it
steady imp
So how many grams is the mixture
twin smelt
36.67
twin smelt
thx for the help :))
twin smelt
.close
timber breach
This is tangent right?
cedar kilnBOT
This is tangent right?
median palm
This is tangent right?
It's tangent in the sense that tan(angle) = 5/2
So yes the answer is correct
cold tinsel
cedar kilnBOT
cold tinsel
so far I've tried substituting y for u and (-y^2/10) for u
but both havent gotten me anywhere
jaunty mural
well im pretty sure you have to do parts?
cold tinsel
ah mega fuck
Ill try that now
would I just keep going until I've got e^(-y^2/10) * y^2?
or would I know when to stop?
jaunty mural
would I just keep going until I've got e^(-y^2/10) * y^2?
doesnt sound right.
cedar kilnBOT
@cold tinsel Has your question been resolved?
chilly warren
I need to solve this question with Synthetic Differential Geometry
Basically I have to solve x^2 + (y-1)^2 = 1
What I did is I simplified it to x^2 + y^2 = 2y
But then I got stuck. I know that (d, 0) for all d ∈ D works. But, How do I know that y has to be 0? In fact, my intuition said that (sqrt(2d), d) should work too. But perhaps because I worked more with classical real numbers than synthetic differentiable geometry
cedar kilnBOT
I need to solve this question with Synthetic Differential Geometry
Basically I h...
@chilly warren Has your question been resolved?
cedar kilnBOT
@chilly warren Has your question been resolved?
chilly warren
<@&286206848099549185>
chilly warren
<@&286206848099549185>
cedar kilnBOT
@chilly warren Has your question been resolved?
chilly warren
<@&286206848099549185>
chilly warren
<@&286206848099549185>
versed glen
what is D
wraith crypt
maybe you should bring this to #diff-geo-diff-top
cedar kilnBOT
@chilly warren Has your question been resolved?
chilly warren
.close moved to #diff-geo-diff-top
zealous spear
Hey guys, I do want some help, but with Physics, just wondering if that is allowed
zealous spear
If it is allowed, here is the problem, I did this but got it incorrect and even followed a youtube video but no luck
<@&286206848099549185>
cedar kilnBOT
@zealous spear Has your question been resolved?
cedar kilnBOT
@zealous spear Has your question been resolved?
dense surge
If $f:C\toC$ and $|f’(z)|=1$ everywhere. Is f(z)=z
cedar kilnBOT
If $f:C\toC$ and $|f’(z)|=1$ everywhere. Is f(z)=z
wraith daggerBOT
Lord Mind
Compile Error! Click the 
reaction for more information.
(You may edit your message to recompile.)
dense surge
Further, |f(x)|=|x| for all complex numbers
My guess is it true up to a rotation but not sure how to prove
dense surge
Like trivially $r*e^{\theta i}$ also works
wraith daggerBOT
Lord Mind
cedar kilnBOT
@dense surge Has your question been resolved?
cedar kilnBOT
@dense surge Has your question been resolved?
cedar kilnBOT
@dense surge Has your question been resolved?
placid heart
Further, |f(x)|=|x| for all complex numbers
Is this also given?
dense surge
Yes @placid heart
Basically derivative is 1 (or negative 1) everywhere
And |f(x)|=|x|
placid heart
Basically derivative is 1 (or negative 1) everywhere
derivative is a vector of length 1
am i wrong in saying that?
Because f maps from C to C
dense surge
That would be an interpretation sure
Does that provide any insights?
Essential it’s sufficient to show it maps to z
placid heart
Does that provide any insights?
I am slightly lost, I took $z = r(\cos\theta + i\sin\theta )$
wraith daggerBOT
वाह्य
dense surge
Yes that’s one representation
placid heart
now $|f(z)| = |z|$
wraith daggerBOT
वाह्य
placid heart
so f preserves length
placid heart
$f(z) = p(r, \theta)$
wraith daggerBOT
वाह्य
placid heart
is this true??
placid heart
$p(r, \theta) = r(\cos(\frac{\theta}{r} + \phi) + i\sin(\frac{\theta}{r} + \phi))$
wraith daggerBOT
वाह्य
placid heart
if this is true $\frac{d}{d\theta}p(r, \theta)$ is a function which outputs a unit vector
wraith daggerBOT
वाह्य
placid heart
I mean partial derivative here
placid heart
So we really need a $p(r, \theta)$, is such a function guaranteed to exist? I mean this is just a change of coordinates notation
wraith daggerBOT
वाह्य
placid heart
Sorry for making all this confusion, I don't do calculus really
Wait, $f(z) = p(r, \theta) \implies f'(z) = \frac{\partial p(r, \theta)}{\partial r \partial\theta}$
cedar kilnBOT
@dense surge Has your question been resolved?
rancid estuary
Triangle WXY where w=120m, x=77m, y=115m
valid cloud
A man hosted an annual celebration only for a maximum of 12 people, The tickets were sold at 500 P, So people have the option to pay 500 P or 1000 P with 500 P change, One day there was a problem, The cash register doesnt have any money, Luckily the first customer only paid 500 P or else the man would go to the ATM machine and waste time., if the man sold 12 tickets With Ease, How many ways could've the transaction have gone.
gusty mason
Hi, why isn’t there an asymptote when x = 0?
cedar kilnBOT
Hi, why isn’t there an asymptote when x = 0?
gusty mason
(Ignore the red line on top)
jaunty mural
limits
lim of that function as it goes to 0 isn't infinity
That aside, why are you expecting one
gusty mason
That aside, why are you expecting one
x/x
gusty mason
I know this is equivalent to cube root of x
jaunty mural
Vertical asymptotes happen when the function goes to +- infinity
gusty mason
Vertical asymptotes happen when the function goes to +- infinity
Oh that makes sense
I mean I know that
gusty mason
But x/|x| is 0/0
jaunty mural
that doesnt mean it necessarily goes to infinity
You need to evaluate the limit at 0
gusty mason
lim is 1 at 0
And lim at 0 is 1 right?
jaunty mural
Of course f(0) is undefined
in all of these examples we're talking about
But for an asymptote to happen, the function has to go to +-infinity
as we approach 0
gusty mason
But for an asymptote to happen, the function has to go to +-infinity
Understood that
gusty mason
You need to evaluate the limit at 0
I see
gusty mason
Hi, why isn’t there an asymptote when x = 0?
How would we do that with this one?
jaunty mural
what find the limit?
gusty mason
the function doesn't blow up
Yeah makes sense
gusty mason
what find the limit?
Yeah
jaunty mural
$$\lim_{x\to0}\frac{x}{\abs{x}}\abs{x}^{\frac13}$$
gusty mason
Just plug in values close to x and see the trend?
wraith daggerBOT
Shuri2060
jaunty mural
You haven't learnt limits formally?
It not, then basically what you said.
or plot the graph
gusty mason
You haven't learnt limits formally?
I have, but only till common trigonometric limits and polynomials
jaunty mural
this isn't any different.
First, observe the modulus on x^1/3 doesnt do anything
$$\lim_{x\to0}\frac{x}{\abs{x}}x^{\frac13}$$
gusty mason
this isn't any different.
What troubles me is the absolute value
jaunty mural
Next we just consider the limit from each side
$$\lim_{x\to0^{+}}\frac{x}{\abs{x}}\abs{x}^{\frac13}$$
Limit from the right hand side
gusty mason
First, observe the modulus on x^1/3 doesnt do anything
It doesn’t? Isn’t it supposed to make it only positive?
jaunty mural
so x will be positive
jaunty mural
It doesn’t? Isn’t it supposed to make it only positive?
my bad it does
gusty mason
my bad it does
Ah okay
wraith daggerBOT
Shuri2060
jaunty mural
Sorry, so what I should do is indeed just this
consider the limit as x approaches 0 from the right hand side
then x is positive.
$$\lim_{x\to0^{+}}\frac{x}{x}x^{\frac13}$$
wraith daggerBOT
Shuri2060
jaunty mural
So now you're just evaluating this
which is indeed 0
$$\lim_{x\to0^{-}}\frac{x}{\abs{x}}\abs{x}^{\frac13}$$
wraith daggerBOT
Shuri2060
jaunty mural
Next we approach from the left. x is negative
$$\lim_{x\to0^{-}}\frac{x}{-x}\left(-x^{\frac13}\right)$$
wraith daggerBOT
Shuri2060
jaunty mural
But again, this is 0
since limit from the left and right are equal. The limit is indeed 0
lavish light
can anyone tell me how to solve this? the question says "the equation plans are...
a)orthogonal
b)none of the previous answers
c)coincident
d)parallel and distinct
cedar kilnBOT
can anyone tell me how to solve this? the question says "the equation plans are....
@lavish light Has your question been resolved?
shell lance
Do you know what the normal vector of a plane is?
lavish light
kind of
cedar kilnBOT
lavish light
.reopen
cedar kilnBOT
✅
shell lance
What is it?
cedar kilnBOT
@lavish light Has your question been resolved?
stone jackal
Does anyone know why I get this error message?
cedar kilnBOT
Does anyone know why I get this error message?
graceful karma
What does the error say? @stone jackal
still barn
That's kind of vague, do you have the toolbox installed
stone jackal
I made this script a year ago
just installed the latest version of matlab
with the same products as last year
still barn
.. Are you pasting documentation? Run the command - https://www.mathworks.com/help/matlab/ref/ver.html
still barn
What do you get when you run license('test', 'Symbolic Math Toolbox')
stone jackal
still barn
I don't really know if your code has an error if that's all it's returning but it doesn't look like you have a software license to run that toolbox which may be the cause
still barn
I don't know what software licenses your institution has, you would have to contact your faculty IT or whatever
stone jackal
thanks for your advice!
still barn
When I was a student, we only had access to 7 of the toolboxs my faculty license has access to all of them.
stone jackal
ahh
Im going to try to reinstall it
the entire program
hopefully it will work then
crimson sedge
can anyone help with part c pls
cedar kilnBOT
can anyone help with part c pls
dire geode
what have you tried?
cedar kilnBOT
@crimson sedge Has your question been resolved?
crimson sedge
what have you tried?
i tried doing nCr but that didnt work out
tbh i dont really know how to approach it
cedar kilnBOT
@crimson sedge Has your question been resolved?
crimson sedge
@dire geode ?
dire geode
Use binomial distribution. it's almost the same calculation as a and b
crimson sedge
Use binomial distribution. it's almost the same calculation as a and b
But how would I do the calculation for fewer than 6 sets of arrows?
12C5?
dire geode
what does "fewer than 6" mean?
dire geode
expand that out
dire geode
Yup. List all the cases X < 6
crimson sedge
Yup. List all the cases X < 6
1,2,3,4,5
dire geode
Yup. Now write the probability X equals any of those
crimson sedge
Yup. Now write the probability X equals any of those
Ohhh then I would add them together?
crimson sedge
you should understand why
Yehh that makes sense, could I have done that for b?
dire geode
i don't know what you did for b, but yea
crimson sedge
Alr thanks
cedar kilnBOT
Available help channel!
rigid cedar
I found the probability of the target being hit by doing (1/3 * each hit probability) and added it to get 0.7 then did 1/3*0.8 to get the probability it was hit and was charlie (4/15). then did (4/15)/(0.7) to get 0.381 to 3sf. However did i need to consider the outcomes of them being chosen and missing into the probability or is my answer correct?
dense wing
P(Charlie|Hit)=P(Hit and Charlie)/P(Hit)
to which you then have 3 cases of the target being hit
rigid cedar
so P(Hit and charlie) would be 0.8 * 1/3 and the 3 probabilities of it being hit would be (1/3 * 0.6)+(1/3 * 0.7)+(1/3 * 08)
rigid cedar
so 0.8/(0.8+0.7+0.6)
dense wing
yes
supple horizon
please help mee
cedar kilnBOT
please help mee
obsidian coral
What are you stuck on? You solve for x using algebraic manipulation
obsidian coral
Or because it's in a bizarre format, it wants you to cross multiply first
cedar kilnBOT
cedar kilnBOT
Available help channel!
cursive idol
cedar kilnBOT
cursive idol
I'm taking an AP Statistics class, and we're given multiple choice questions to answer online
When we submit them, they get graded but we never get to see what questions we got right or wrong
I score really inconsistently on these, and I just want someone to tell me if I got any of these wrong
I have a 68 in this class right now and this is the final grade of the marking period...
glad kestrel
sounds like a good way to find out is to submit it
hollow osprey
this is graded?
cursive idol
yup
hollow osprey
<@&268886789983436800>
glad kestrel
lmao
cursive idol
I don't wanan get any wrong
glad kestrel
caught in 4k
cursive idol
Oh, it's not a quiz
hollow osprey
but its graded?
glad kestrel
kinda looks like college board ngl
cursive idol
kinda looks like college board ngl
it is
glad kestrel
so it's a graded college board assignment that's not a quiz?
hollow osprey
well you should try asking specific questions
stuck jolt
does this assignment imply collaboration
glad kestrel
yes to mniip?
cursive idol
does this assignment imply collaboration
normally people work on it together
hollow osprey
and ur teacher wants u working together with people online?
cursive idol
but my friend who takes this class is pissed at me 😦
glad kestrel
lol
cursive idol
and ur teacher wants u working together with people online?
It's not an assesmnet, it's just multiple choice questions
hollow osprey
but its graded
stuck jolt
can you show the header of the page?
cursive idol
sure hang on
calm sierra
but its graded
the point of the rule is academic dishonesty
hollow osprey
yeah but at the start he phrased it like it was a quiz that he wanted the answers for (supposedly to raise his grade)
calm sierra
so in this case we're looking for whether outside help is allowed
hollow osprey
isn't that the same thing?
stuck jolt
some graded assignments imply outside help
hollow osprey
makes sense
stuck jolt
there's open book exams
being titled "homework" is usually a good indication that it implies collaboration
glad kestrel
lmfao
hollow osprey
lmaooo
hollow osprey
oh okay so its homework
anyways if you have any specific questions (which ones you think might be wrong) that would help
cuz i doubt many people would look through all the questions, work them out, and then tell you the answer
cursive idol
yeah that makes sense
They're the type of questions that don't require much math though
hang on
This
I'm very unsure of this one
It's these three that I'm having trouble with
<@&286206848099549185>
This is due in like 57 minutes 😬
cedar kilnBOT
@cursive idol Has your question been resolved?
cursive idol
No
Oh
Fuck I almost forgot I had to submit this assignment
Lol literally nobody said anything
You know what
Screw this
.close
livid tusk
cedar kilnBOT
wraith daggerBOT
nix
livid tusk
but im not sure how to get there
my first thought is to just add s to the expression in part b but idk what to do with that...
$s+t\leq u+s-a,\quad \forall a\in A$
wraith daggerBOT
nix
vestal bolt
Hi
livid tusk
im going to guess that my issue is that im looking at the problem completely wrong though 🤦
vestal bolt
Who can help me with calculus?
livid tusk
@vestal bolt #❓how-to-get-help
wind crane
yes please ask in an unoccupied channel
livid tusk
<@&286206848099549185>
dire geode
im stuck on part c of this...
Did you do parts a and b?
dire geode
Did you do the same thing for $s \leq u-b$?
wraith daggerBOT
riemann
wraith daggerBOT
nix
livid tusk
which seems even further away from where i want to be
but im going to look at it again
it could work if i can do the following
$\big(a+b\leq u\big)\land \big(s+t+a+b\leq 2u \big)\implies \big(s+t\leq u\big)$
but im pretty sure i cant do that
wraith daggerBOT
nix
livid tusk
could i do a proof by contradiction? suppose u<s+t
livid tusk
but idk if thats necessarily a contradiction...
wraith daggerBOT
nix
dire geode
You're on the right track
https://proofwiki.org/wiki/Supremum_of_Sum_equals_Sum_of_Suprema
cedar kilnBOT
@livid tusk Has your question been resolved?
cedar kilnBOT
@livid tusk Has your question been resolved?
cedar kilnBOT
@livid tusk Has your question been resolved?
round tangle
why does it matter if a vector field is conservative or not?
round tangle
we're learning about determining if a vector field is conservative or not but what's the point?
south tundra
If it's conservative, then it's much easier to calculate line integrals with it
warm vector
Question a part I, i don’t get how they got the answer
cedar kilnBOT
Question a part I, i don’t get how they got the answer
tropic oxide
let x be the original amount. what happens when you increase x by 20%?
warm vector
X+20%
tropic oxide
so then what is 20% of x?
warm vector
1/5x
warm vector
Why should we add?
tropic oxide
And then add it to the original amount
you said it yourself
so you should be asking yourself
tropic oxide
yes
warm vector
Ok
cedar kilnBOT
wraith daggerBOT
bookev
cedar kilnBOT
@wooden olive Has your question been resolved?
cedar kilnBOT
@wooden olive Has your question been resolved?
thin thunder
cedar kilnBOT
thin thunder
how to find black area
south tundra
You mean the side lengths?
south tundra
I don't think there's enough information given; the height could be anything
cedar kilnBOT
fallen heath
I don't think there's enough information given; the height could be anything
or the question is probably the difference of the two marked heights ._.
south tundra
Then it surely is solvable
thin thunder
or the question is probably the difference of the two marked heights ._.
the question is fnd perimeter and area of the given shape
cedar kilnBOT
Available help channel!
thin thunder
Then it surely is solvable
@south tundra
cedar kilnBOT
<@!348696743388381195>
thin thunder
bruh
south tundra
If you want the difference of the marked heights, then it's 4
But it looks like we can't determine value of the marked heights themselves
fallen heath
Question must be faulty then.
thin thunder
my teacher gave it?
cedar kilnBOT
@thin thunder Has your question been resolved?
silent bobcat
You already have one relation between x and y thanks to that
You would need to find an other one and, thanks to those two equations, you may get the possible values for x and y
The problem would then be to find an other one
cedar kilnBOT
silent bobcat
Nice.
cedar kilnBOT
Available help channel!
stark trench
,tex show that $\sqrt{\frac{4+2\sqrt{3}}{8}} = \frac{\sqrt{3}+1}{2\sqrt{2}}
wraith daggerBOT
Syphax
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)
rustic ridge
no clue what to do
cedar kilnBOT
no clue what to do
rustic ridge
<@&286206848099549185>
crimson sedge
hurdle?
crimson sedge
i mean what is your obstacle?
rustic ridge
nothing cuz im not sure what i have to do
yes i need a way to do it not the answer LOL
wraith daggerBOT
BritS
compact tartan
Hello i this server is for help
crimson sedge
Hello i this server is for help
could you please refer to #❓how-to-get-help
compact tartan
ok i am new to this server
crimson sedge
welcome to the server
rustic ridge
ok welcome
crimson sedge
btw, do you know cartesian coordinate?
rustic ridge
who?
crimson sedge
which consists of x and y respectively*
rustic ridge
yes i do
wraith daggerBOT
BritS
crimson sedge
yes
rustic ridge
how does that help me💀
rustic ridge
no clue what to do
if anyone who can read, has any clue on how i should get started please share.
<@&286206848099549185> desperate
spare herald
In math, the symbol U represents the union of two sets. The union is the set of all elements included in either (or both) sets
rustic ridge
literally nobody asked
rustic ridge
no clue what to do
where in ANY of this do u see a question abt the symbol OF UNION
rustic ridge
thats ok
copper cargo
crimson sedge
no clue what to do
If you look closely, (-1,0) and (0,inf) are open intervals. Just give a thought what could be the union of both these intervals, with respect to $\gamma$ and $\beta$
wraith daggerBOT
Pencil
crimson sedge
Gamma and beta are the inputs for f(x) which we have to prove (the equality). But first think what should be the inputs
rustic ridge
yes
crimson sedge
Like try framing the given union of both intervals in an inequality with respect to gamma and beta
crimson sedge
For checking what should be the inputs in the second part
rustic ridge
what inputs?
crimson sedge
Like for example, $x\in(a, b)$ then a\lessx\lessb
wraith daggerBOT
Pencil
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)
rustic ridge
i get what ur trying to say
crimson sedge
Yeah
rustic ridge
but how does that help at all
crimson sedge
So that we can check and analyze the second equality
If you don't even know what are the inputs, how can you proceed
rustic ridge
equality
crimson sedge
Yeah
rustic ridge
im so lost
dense wing
Kinda obvious thing to do since you're only asked to show existence of 1 soln
valid cloud
I want to know if there's a simpler way of knowing how many ways you can go in Point (5, 6) in a Cartesian plane where your starting place was at the origin and where you can't go at (3,2),(3,3),(3,4), And your movement restricts from upward and rightward
bold hinge
Draw a picture
This is taxicab geometry I'm assuming
You can only move north and east in integer quantities?
uncut hedge
I want to know if there's a simpler way of knowing how many ways you can go in P...
First count how many ways you can go to points accessible at x = 3
(assuming integer grid yeah)
bold hinge
You need 5 rights and 6 ups no matter what
valid cloud
Yes it's integer grid
fallen heath
Or you can find the number of ways of going from (0, 0) to (5, 6) and subtract the number of ways you end up going at (3, 2), (3, 3), (3, 4)
valid cloud
Complement rule works I see
valid cloud
Or you can find the number of ways of going from (0, 0) to (5, 6) and subtract t...
How do you find the number of ways you can go from the origin to (5,6)?
fallen heath
Hmm 👀
think about a smaller number first.. what do you think are the number of ways of going from (0, 0) to (1, 1)?
valid cloud
2
bold hinge
How do you find the number of ways you can go from the origin to (5,6)?
Permutations of:
RRRRRUUUUUU
fallen heath
2
You see, you basically counted: "Alright, I can first go 1 step to the right to (1, 0) then head up to (1, 1)"
or... uhh, "I could also go 1 step to the up first, to (0, 1) and then head right to (1, 1)"
So basically, what you did was counting the number of ways you could arrange from your number of choices of ups and rights
valid cloud
Permutations of:
RRRRRUUUUUU
462 if I'm not mistaken
wraith daggerBOT
Result:
462
so basically, for going to (5, 6) how many times would you have to go upwards, and how many steps would you go rightwards!?
and since every arrangement of these up and right choices give you a distinct path, the number of their arrangements give you the number of paths from (0, 0) to (5, 6)
crimson sedge
Ohh so 11 arrangements of ups and rights
Hence 11/5!6!
valid cloud
Ohh so 11 arrangements of ups and rights
Hence 11/5!6!
Yep I got 462
fallen heath
Yep I got 462
Now Kuristinaa, can you figure your question?
crimson sedge
👍
fallen heath
It's just a bunch of counting now
valid cloud
Now Kuristinaa, can you figure your question?
Yes, It's 462 - All ways where you go to (3,2),(3,3),(3,4)= Answer
.close
crimson sedge
I’m stuck
crimson sedge
2^2x
crimson sedge
log_2(27) is not 3
I know it’s not
tropic oxide
then why say an if-statement with a conclusion that you know is false?
crimson sedge
K is 6 I believe
tropic oxide
you believe?
crimson sedge
K is 6
tropic oxide
what's K?
your problem asks you about lowercase k
and you say something about uppercase K
and on the off-chance that you meant to say "k is 6" and not "K is 6"
do you have any work to show that
or are you just asserting it out of hand expecting us to take you at your word
tropic oxide
thank you for, once again, not answering a single one of my questions.
god fucking damnit
how hard can it fucking be
tropic oxide
if you're confused at my questions then fucking say you're confused at my questions
crimson sedge
Lowercase I meant
crimson sedge
also how did you get k is 6?
have you learned change of base rule???
@crimson sedge
tropic oxide
so you just randomly guessed that k = 6, entered it into the system, and got your point for the problem or whatever.
do i or do i not understand you correctly, @crimson sedge?
crimson sedge
is it just key answer?
tropic oxide
answer "yes, you understand me correctly" or "no, you do not understand me correctly"
i will keep repeating the question until i receive one of these answers
crimson sedge
miscommunication happens here, damn
tropic oxide
this person in particular likes to be difficult about communication.
crimson sedge
they literally considered it white noise
tropic oxide
so you just randomly guessed that k = 6, entered it into the system, and got your point for the problem or whatever.
do i or do i not understand you correctly, @crimson sedge?
why do i even bother anymore
should've blocked them 5 interactions ago
crimson sedge
if they react to bot asking if this has been resolved with ❌, this channel will be messy
dense wing
They probably will re previous times
livid hound
they seem to have a habit of abandoning the convo in the middle of help without telling anyone
cedar kilnBOT
@crimson sedge Has your question been resolved?
grizzled wadi
Hi could anyone help?
cedar kilnBOT
Hi could anyone help?
dawn jetty
grizzled wadi
4^3/2^5
dawn jetty
$\frac{4^3}{2^5}$
wraith daggerBOT
Deus_Vult
south tundra
I'll assume you're asked to simplify, for which you should view 4 as 2^2
dawn jetty
so what exactly is your question ?
grizzled wadi
The answer
dawn jetty
I'll assume you're asked to simplify, for which you should view 4 as 2^2
well yes
grizzled wadi
It’s not simplify it’s you have to get the answer for it
dawn jetty
simplifying it will make it easier for you to get the answer
grizzled wadi
How do I do that
south tundra
Yes
grizzled wadi
Ok thank you
cedar kilnBOT
Available help channel!
radiant mountain
i need help
cedar kilnBOT
i need help
radiant mountain
Asap
balmy apex
saying "asap" or "I need help fast" will not get you help any faster
you're not entitled to help
balmy apex
also, what have you tried so far? have you already made an attempt at solving it yourself?
radiant mountain
Yes
balmy apex
then show us what you've done already
obsidian coral
I don't think u sub will work, I think it's a trig substitution
radiant mountain
What trig substitution
crimson sedge
Hint: a^2 - x^2
radiant mountain
isnt hat complete square
obsidian coral
No
radiant mountain
i mean the diff of 2 square
balmy apex
maybe give this a read https://openstax.org/books/calculus-volume-2/pages/3-3-trigonometric-substitution
radiant mountain
ok
cedar kilnBOT
@radiant mountain Has your question been resolved?
dense wing
just do it graphically 
hearty elk
Heyyy
hearty elk
heyy could someone please help me with A level maths I need it done by tomorrow and I didnt have enough time to revise sadly 😦
these 2 questions 😄
I can do 1A but everything else confuses me
fallen heath
Show your work
hearty elk
its the picture above
fallen heath
(a) Gradient of AB can be found from the given coordinates of points A and B
(b) CD is given parallel to AB so gradient of CD = gradient of AB gives you value of "k"
(c) Use gradient of AB found in part (a) to determine the gradient of the line perpendicular to line AB, write the equation of the line passing through point A and having this new gradient you found, using the point-slope form of line equation
(d) Solve L with the equation for line CD[ line CD can also be written using the point-slope form]
that's Q1.
hearty elk
how do I use the parralel gradiant is it in the form of y-y=m(x-x)
for B
Ive gotten the gradiant for part a which was 2 ill send pic if you dont mind checking it over ffor me good sir 😄
crimson sedge
,rotate
wraith daggerBOT
fallen heath
,rotate 180
wraith daggerBOT
crimson sedge
Ive gotten the gradiant for part a which was 2 ill send pic if you dont mind che...
I think its correct
crimson sedge
<@456226577798135808> would you know if this is next step for (B)
yes it is
hearty elk
would you mind showing me how the formula would be done because my end result has 3 letters in it hah @crimson sedge
dont think thats right
crimson sedge
choose one of the points among C or D
suppose you take C......then the gradient of AB is 2
then the equation is......... (y-5)=2(x-5)
hearty elk
wouldnt i still end up with an x and y tho
or does one get removed somehow?
because you times the right side of equation brackets out right
leaving you with (y-5)= 2x -10
crimson sedge
an equation always has variables
and the above line has 2 variables which should be correct
hearty elk
how would i get rid of the x then to get a Y value? assume x=0?
crimson sedge
you dont need to get rid of x
hearty elk
how can i show k=5
crimson sedge
then the equation is......... (y-5)=2(x-5)
this is (y-5)=2(x-k)
sorry i mistook k as 5
hearty elk
no problem
crimson sedge
now you can simply put the values of x and y in the equation to get k
hearty elk
x and y of C right?
crimson sedge
yes
hearty elk
wait would the 5 change to -1 then? since were using C
crimson sedge
wait would the 5 change to -1 then? since were using C
no......just put coordinates of C in place of x and y
hearty elk
why is there a 5 there tho?
if we are using c
or are we allowed to use c and 1 variable from d?
sorry if its a silly question
crimson sedge
we need 2 points to define a line
so if both C and D lie on the line with gradient 2.....so line joining them should also have gradient 2
hearty elk
yes i understabnd however you currently have 3 points inserted + gradiant you have (x and y) from c and x from point d ( the 5)
ooooh nopooo
im so sorry im being very dumb
haha i see my mistake
could you help with question c now
@crimson sedge
crimson sedge
could you help with question c now
find gradient perpendicular to 2 and for equation using the new gradient and coordinates of A
cedar kilnBOT
@hearty elk Has your question been resolved?
hearty elk
@crimson sedge would the perpendicular gradiant be -2 or -1/2