help-13

[crimson sedge]

All interior angles of triangle sum up to 180°

[dusky pond]

they = 180°

yes

[crimson sedge]

What are you not seeing here then

[dusky pond]

are the two missing lengths 5?

[crimson sedge]

No….

[dusky pond]

ehm

i feel like its very obvious

[crimson sedge]

Just do the Pythagoras theorem

[dusky pond]

a^2 + b^ = c^2 or in this case 10

[crimson sedge]

Yes and a = b

Since the triangle is isosceles

Or all sides of square are equal

[dusky pond]

all sides of the sqaure are equal

[crimson sedge]

Yes

Then solve the equation

[crimson sedge]

This

C=10

Hence c^2 is 100

What are u not getting in this

[dusky pond]

i have this problem where i just have a sort of wall

like once you tell me i wont forget but i just

gimme a minute

[crimson sedge]

[dusky pond]

yea no i am lost

[crimson sedge]

Wut

This is literally so basic

[livid hound]

have you drawn a diagram

[dusky pond]

a^2 + b^2 = 100

[dusky pond]

yes bro i know

[crimson sedge]

And a=b

So u get 2a^2 = 100

a^2 = 50

[dusky pond]

a^2=50

[crimson sedge]

hence a will be ?

[dusky pond]

root 50?

[crimson sedge]

Yes

Which is ?

[dusky pond]

irational

7.071067812

[crimson sedge]

Yeh

[dusky pond]

thank you bro

[crimson sedge]

Np

Should I close this channel

[livid hound]

you shouldn't use a calc/round

unless told

[dusky pond]

well ill close it

[dusky pond]

wdym

i just left it as a surd

[livid hound]

7.071067812
is unwarranted (also not exact)

[crimson sedge]

Use 5sqrt(2)

[livid hound]

sqrt(50) can be simplified though

[dusky pond]

YES

[dusky pond]

TO WHAT

OOPS

oop

s

caps

[graceful karma]

Take a trip to the factor orchard

To find a factor tree

[crimson sedge]

Lol

[dusky pond]

bruh.

[crimson sedge]

Literally factor 50

[dusky pond]

yes yes

i know

[crimson sedge]

Take out the square terms

[dusky pond]

i found iut

shh

[crimson sedge]

Leave the rest in the root

[dusky pond]

5root2

[crimson sedge]

Yes

[dusky pond]

ty

[crimson sedge]

finally

[dusky pond]

shush

.close

[cedar kiln]

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[graceful karma]

[cedar kiln]

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[cloud mauve]

helllo

[cloud mauve]

bro how do i just figure out my question

.close

[cedar kiln]

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[fickle trellis]

Eh?

.reopen

[cedar kiln]

✅

[fickle trellis]

@cloud mauve

[cloud mauve]

?

i figured out my own question just by looking at it

[fickle trellis]

Oh.

Then its fine.

.close

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[fickle thicket]

hi i need help with this

[fickle thicket]

f(x)= (x-1)/x^2

we need f'(2)

[obsidian coral]

Find the derivative, plug in 2

[cedar kiln]

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[oblique prawn]

help for 12 pls

[obsidian coral]

,rotate

[obsidian coral]

Create a proportion

But be cautious with the units

[oblique prawn]

ok

would this work

[obsidian coral]

That's 0.25, correct?

[oblique prawn]

yea

.25 for a quarter hour

[obsidian coral]

Looks good

[oblique prawn]

would this work for 19

,rotate

[oblique prawn]

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[vale pike]

Compare them

And also prove it

[cedar kiln]

@vale pike Has your question been resolved?

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[real thunder]

I need help understanding how my diff eq text book is getting the answer of d^2h/dt^2 as a correct answer for one part of a problem and for the life of me I cant figure out why this is correct

[pallid arrow]

are you asking why $d \frac{d}{dt} (h)$ is wrong

[wraith dagger]

xdk1235

[real thunder]

no, I am asking why d( d/dt (h) ) = d^2 h/dt^2

[dense wing]

gonna need more context.

[real thunder]

so im asking why, $d \frac{d}{dt} (h)=\frac{d^2 h}{dt^2}$

[wraith dagger]

martiniman31

[real thunder]

i don't understand how the t^2 in the denominator is occurring

[dense wing]

and im asking for more context

[real thunder]

give me a sec

So I need help understanding how they are getting from initial velocity to acceleration and somehow they are getting the part I have written in red ink

so they are taking the derivative of dh/dt and getting $\frac{d^2 h}{dt^2}$

[wraith dagger]

martiniman31

[pallid arrow]

ah that's just how you write it

$d^2 h / dt^2$ means take the derivative of h with respect to t, and then take the derivative of that again with respect to t

[wraith dagger]

xdk1235

[pallid arrow]

so the power in the numerator denotes how many times you are differentiating in total

and the denominator tells you with respect to what variable each time

and dt^2 is just how you write "with respect to t, twice"

as another example $$\frac{d^2 h}{dx dy}$$ would be take the derivative of h, with respect to y, and then with respect to x

(notice the order)

[wraith dagger]

xdk1235

[real thunder]

I understand what it means the statement $\frac{d^2 h}{dt^2}$ means I just dont understand how to get from point a, $\frac{d}{dt}(\frac{dh}{dt})$ to point b, $\frac{d^2 h}{dt^2}$

[wraith dagger]

martiniman31

[real thunder]

I feel like the answer is very simple and I am just overlooking something

the answer being the written work from point a of the problem to point b

Let me phrase this better,

Please show work

<@&286206848099549185>

[pallid arrow]

d^2 h /dt^2 means d/dt (dh/dt)

they both have the same meaning

there's no "work" to show, it's just like how you write 1 + 1 + 1 = 1 * 3 without writing anything else

[real thunder]

that makes sense

then why is symbolab stating this?,

[pallid arrow]

it's probably interpreting dh/dt as literally like

d * h / d * t

[real thunder]

aaah

[pallid arrow]

or whatever

it probably just cant handle derivatives properly

[real thunder]

gotcha thx sm for helping me through that. I've just been second guessing myself then

[pallid arrow]

np!

[real thunder]

.close

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[crimson sedge]

Is casework the right way to go?

[crimson sedge]

,rotate

[jaunty mural]

I would try a recursive formula perhaps

[crimson sedge]

No

[jaunty mural]

no?

[crimson sedge]

I don’t know recursive formulas

[jaunty mural]

i mean its like

suppose we want the sequences of length 5

a_5

Can we use a_4 (and maybe a_3) to describe ?

reworded

But maybe this isn't the way 🤔

[crimson sedge]

.

[jaunty mural]

@crimson sedge ok ok, forget recursive

Consider which sequences you need to discard

I think that should be helpful

or maybe not aha. Inclusion exclusion?

======
tbh, you are able to write what all of these sequences must look like

to a certain extent

_?_?_?_?_?

[crimson sedge]

What about my original idea

[jaunty mural]

im not sure which cases ur doing

[crimson sedge]

Also, these sequences have a length of 10

[crimson sedge]

Starts in 0, 1 or 2

[jaunty mural]

ehhh

There are 2 cases you should be considering

[jaunty mural]

Ok, better, give me an example of a valid sequence

[crimson sedge]

0,1,0,1,0,1,0,1,0,1

[jaunty mural]

another one

but there is something in common

for all of these sequences

[crimson sedge]

0,1,2,1,0,1,2,1,0,1

[jaunty mural]

yh

[crimson sedge]

Which is?

[jaunty mural]

spot the pattern?

😶

If you write maybe like a few more u might see it

its not a pattern, but a property they all have in common

[crimson sedge]

Let me find it

Always 5 ones?

[jaunty mural]

👌

Think you can finish this now

[crimson sedge]

Ah

I think I can

But how can I prove that there will be always 5 ones

I would be skeptical if you told me that

[jaunty mural]

eh?

I would not bother proving

it is uh... fairly obvious 😅

If you think about how the sequence works

[crimson sedge]

Right

So the answe is 32

[jaunty mural]

i dont think so

[crimson sedge]

2^5

5 spots left, each can have either 0 or 2

[jaunty mural]

Its not 32, think reallllyyyy carefully

[crimson sedge]

O man, what am I missing

37?

I don’t know

[jaunty mural]

Youre assuming something about the 1's

u have half the solutions

[crimson sedge]

I’m undercounting?

By a factor of 2? Why?

[jaunty mural]

im pretty sure u r

You're assuming something about the placement of 1s

[crimson sedge]

1,0,1,0,1,0,1,0,1,0

What am I assuming wrong about the placement?

[jaunty mural]

thats fine yes

I dont think ur counting

0101010101

[crimson sedge]

?

Oh

Because those two are different? Yes?

I think I understand

Thank you

So much again

.close

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[graceful karma]

What would you guess

[native plank]

if you tell me the answer is 17 imma cry

am i just overthinking this ?

[graceful karma]

Maybe

[native plank]

hmm

fr is it

wait no

4

getting bullied rn

😔

[graceful karma]

I mean your work looks fine

[dire geode]

I can't even read this screen shot of an image

[native plank]

lmao

[livid hound]

which part of your work are you unsure
about?

[native plank]

i got 3.2

do i just round to 3

i have covid i missed out on the lesson ok chill out

what even is that bro its not in the chapter we're studying

ight i give up imma just leave it

ty guys

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[livid hound]

do not to round, keep the mean value as 3.2

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[violet flume]

hmm

should be what like

a+a+b = 180

a = 2b-10

guess and check is almost algebra

lol

but you should be able to use a system too

[cedar kiln]

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[primal ginkgo]

I am re-reading my notes, but I forgot how to find the reference angle

can someone help me please

Im looking for the reference angle of sintheta = -1/2

[cinder talon]

what quadrant(s) is sine negative in?

[primal ginkgo]

quadrant 3 and 4

[cinder talon]

yep

so

to have a negative output for sine, you should be within (π,2π)

now what angle for theta gives sin theta=1/2

[primal ginkgo]

wait sorry lol its all just coming back now wouldnt I just do sin^-1(1/2)

which would equal 30 degrees which would be the reference angle?

[cinder talon]

yeah

and then you would need to find that 30 degrees within the 3rd and 4th quadrant

[primal ginkgo]

so 210 and 330 degrees?

since i have to refer to the closest x-line for the +-30 right?

nvm i forgot the answer is in the pic lol

thank you though!

.close

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[strong ermine]

Hey

[cedar kiln]

@strong ermine Has your question been resolved?

[cedar kiln]

@strong ermine Has your question been resolved?

[pallid arrow]

do you know the cosine rule?

[cedar kiln]

@strong ermine Has your question been resolved?

[cedar kiln]

@strong ermine Has your question been resolved?

[tardy current]

draw the picture with a better, accurate scaling and drop an altitude from the top left vertex

[ripe stone]

@crimson sedge

remember this?

so]

so the value of m is 3.5 or 10?

<@&286206848099549185>

anyone

[gentle lintel]

also, ping helpers only after 15 mins

#❓how-to-get-help

[crimson sedge]

@ripe stone is that an exam

[ripe stone]

no why?

homework

[crimson sedge]

Ok

[ripe stone]

why?

[crimson sedge]

Nothing

[ripe stone]

tell

wait

i get it

if someone needs help in exam and u help

its cheating

[crimson sedge]

Yes

[ripe stone]

and u get banned

[gentle lintel]

you get ip banned and stuff

yes

[crimson sedge]

Yes

[ripe stone]

ok ok

[crimson sedge]

So anyway

It’s a linear equation in 1 variable

[merry steeple]

A chord of a circle divides the circular region. Name the region which contains the
centre of the circle

[crimson sedge]

Major sector

[cedar kiln]

@strong ermine Has your question been resolved?

[cedar kiln]

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[abstract pagoda]

is it possible to rewrite this as y=...

[hollow lodge]

Solve the quadratic in y

Taking -(x^2 -x + C) as the constant term

[abstract pagoda]

ok so for the discriminant I have: 25+4x^2+4x+c

4c

[hollow lodge]

Yee

y = (5 +- Disc)/2 then

[abstract pagoda]

the answer has this

why can't y be 5/2?

[hollow lodge]

Idk, maybe some condition before this in the question?

[abstract pagoda]

oh i see this was the question

so if y=5/2 2y-5 would be 0

thx for your help ❤️

[hollow lodge]

Nw!

[abstract pagoda]

.close

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[vagrant forge]

Please help, i forgot how to do thes eequations

[crimson sedge]

What have you tried?

[vagrant forge]

I tried to do put x on one side like this:

X= ((2x+1))/ 7)-17

[hollow lodge]

First and foremost take the lcm

[crimson sedge]

Where did the 7 come from

[vagrant forge]

10 right

[vagrant forge]

I made a tiny mistake xd

[hollow lodge]

Yes, now make the denominator uniform

[vagrant forge]

10x - 2x - 2?

[hollow lodge]

What about the RHS?

[vagrant forge]

Wait what is the RHs

[hollow lodge]

Right hand side

[vagrant forge]

Oh mb

[vagrant forge]

Yeah rhs is 10x - 2x - 2- 5x = 170

[hollow lodge]

Yay!

[vagrant forge]

Thats the whole thing

[hollow lodge]

Now just solve for x normally

[vagrant forge]

Not rhs only

[hollow lodge]

Yes

[vagrant forge]

Alr thanks for help

I had forgotten cause i havent done this in a while

.close

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[mental oak]

If a:3 = 12:a, calculate the positive value of a.

I have no idea how to get around this. Please help 🙇‍♂️

[crimson sedge]

What does : mean

[mental oak]

Ratio

Sorry for not mentioning that

[jaunty mural]

what can you do to ratios?

to both sides

and keep it the same

like 1 : 2

[mental oak]

That'd be (1/3) : (2/3)

But I couldn't get it to work

[jaunty mural]

is this 1:2

[mental oak]

(1/3) × 12 = (1/a) × (a) is where I stopped

[jaunty mural]

that looks like right approach

but not quite perhaps

with ratios i would prefer to keep them like that

[crimson sedge]

The a, are you sure it's like that?

[mental oak]

The as cancelled out so I came here

[jaunty mural]

and remember you can multiply

[mental oak]

Yeah

[jaunty mural]

a : 3 = 12 : a

[crimson sedge]

How did you do it

[jaunty mural]

a : 3 = 36 : 3a

a^2 : 3a = 36 : 3a

If you do your working like this, it is clearer

[mental oak]

You can multiply only one side like that?

[jaunty mural]

yes

ratios are

the same if u do that

1 : 2 = x?

then

2 : 4 = x

its just like a fraction

[mental oak]

I want to try this out gimme a second please

https://tenor.com/view/the-office-bow-michael-scott-steve-carell-office-gif-12985913

I understand now

that I'm an idiot

Thanks again

.close

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[tepid mirage]

got it

[crimson sedge]

Ok

.close

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[bright surge]

@crimson sedge

[crimson sedge]

Ok

[bright surge]

the sequence is

a_(n+1) = a_0*a_1*a_2*a_3 ... *a_(n-2)*a_(n-1)*a_n

[crimson sedge]

Yeh

[bright surge]

so let a_0 be a variable

let's say x

[crimson sedge]

Ok

[bright surge]

then

what will a_1 be

[crimson sedge]

X

[bright surge]

yep

and what about a_2

[crimson sedge]

X^2

[bright surge]

x_3?

[crimson sedge]

X^4

[bright surge]

you can continue this, right?

[crimson sedge]

Yes

But these terms are added right ?

[bright surge]

...added?

no

look at the formula

[crimson sedge]

Like in the sequence

[bright surge]

they're multiplied

not added

[crimson sedge]

The sequence is x + x + x^2

..

And forward

[hollow lodge]

You need nth term, not sum of n terms

[crimson sedge]

Oh

Well it’s a GP in the powers the

Since bases are same and multiplied

Got it

[hollow lodge]

Yes

[crimson sedge]

I was thinking u need the sum of n terms

Lol

.close

[cedar kiln]

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[bright surge]

actually, no, it's not a GP

GP implies that there's some common ratio

while the exponents, well, grow.... uh, exponentially

[crimson sedge]

Ik

But 2,4,8,16,32 are in GP

[bright surge]

if it's in GP, find a common ratio

and quick

[crimson sedge]

2 is the common ratio

[bright surge]

i'll be going to sleep in the next minute

,ti

[wraith dagger]

The current time for meg sam is 10:35 PM (WIB) on Mon, 17/01/2022.

[bright surge]

wait....

wait a sec

yeah

nvm

[crimson sedge]

Lol

I guess u are tired

[bright surge]

i'm a bit sleepy

[crimson sedge]

I can understand

[bright surge]

actually very sleepy

i guess i shouldn't even be here in the maths server

[crimson sedge]

.close

Good night Meg

[cedar kiln]

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[fair ridge]

So my answer here is wrong, i have a feeling it’s because i handled x to the 0 power wrong, but I’m not entirely sure

[livid hound]

your issue is with how you handled the
x^-1 in the denominator

what's $x^{-}$ supposed to mean?

[wraith dagger]

ℝamonov

[fair ridge]

X to the -1 power

[livid hound]

is not what you should have there

[fair ridge]

Was i supposed to leave it as a fraction

[livid hound]

$\frac{1}{x^{-1}}\neq x^{-1}$

[wraith dagger]

ℝamonov

[livid hound]

you didn't apply the law properly

try simplifying $\frac{1}{x^{-1}}$ again

[wraith dagger]

ℝamonov

[fair ridge]

Like such?

[livid hound]

yes

[fair ridge]

Thank you so much 🙏

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@nocturne dew Has your question been resolved?

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[hollow osprey]

So first take the derivative of both sides

Implicitly of course

[viral cloak]

You're given the first derivative and asked to find the 2nd derivative. So, just take the derivative.

[sturdy blade]

would i take the derivative with respect to y?

[livid hound]

no

d^2y/dx^2 is the derivative of dy/dx wrt x

differentiate wrt x and apply chain rule as needed

(which will involve differentiating something wrt y)

[sturdy blade]

idk how to use chain rule in this problem

[jaunty mural]

show us your working.

[sturdy blade]

i can’t even get started i’m really confused

[livid hound]

$\dv{x} e^{5y} = , ?$

[wraith dagger]

ℝamonov

[livid hound]

are you able to apply chain rule there?

[sturdy blade]

not sure

actually yes

@livid hound i got 0

is that the answer

[livid hound]

no

how are you getting 0 when applying chain rule

[cedar kiln]

@sturdy blade Has your question been resolved?

[jaunty mural]

@sturdy blade this is the chain rule.

$$\dv{^2y}{x^2}=\dv{x}\dv{y}{x}=\dv{\left(e^{5y}\right)}{x}$$
$$ =\left(\dv{y}{y}\right)\left(\dv{\left(e^{5y}\right)}{x}\right)= \left(\dv{y}{x}\right)\left(\dv{\left(e^{5y}\right)}{y}\right) $$

[wraith dagger]

Shuri2060

[sturdy blade]

@jaunty mural

thanks

but im still too dumb to do this

idk what comes after

[delicate canopy]

since we have a
$$\dv{e^{5y}}{y}$$
term, you can first find the derivative of that then move on to the other section of the problem

[wraith dagger]

Khazali

[cedar kiln]

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[cedar kiln]

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[crimson sedge]

help

[crimson sedge]

hm

you

:d

[glad kestrel]

stop posting in everyone else's channels

• you only need 1 channel

[crimson sedge]

then where do i go

im new

[hollow osprey]

you just claim one channel

and then you wait

if, after 15 minutes, no one has helped you / you haven't really gotten an answer, you can ping @ helpers

[crimson sedge]

ok

ty

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

@crimson sedge Has your question been resolved?

[crimson sedge]

bro

[cedar kiln]

@crimson sedge Has your question been resolved?

[dire geode]

First calculate the cost of each meal before sales tax. If a meal costs 13.25 with 6% tax, the meal before tax costs 12.50

If tip is 18%, then the tip on the original meal is 2.25.

So the cost of the meal with tax and tip is 13.25+2.25

[cedar kiln]

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[sonic glade]

Hi! I need a bit of help wrapping my head around a basic trig concept

[cinder talon]

ask

[glad kestrel]

what

[cinder talon]

thats not a question

[sonic glade]

sorry I'm not sure about formatting

let me try it this way: object A is moving at rate S and object B is moving at an unknown rate. if I have the distance between points at any given instant

and the speed of object A

what tools do I have to calculate the distance at different points in time?

[dense wing]

Well how are A and B moving?

[sonic glade]

I'm assuming linearly for now

at constant speeds

[dense wing]

that means nothing though

ok sure, they travel in straight lines, but how do they move relative to one another?

[sonic glade]

one moment

sorry that's a little awful but basically

[cinder talon]

,rotate

[sonic glade]

if I have speed of one and distance/theta relative to movement direction at any instant

• I know the difference between instants time-wise

how do I estimate the difference between positions at any given point in time

additionally, I think it should be possible to work out things like the how the angle will change based on the change of distance between objects and how the distance will change based on changes in the angle (considering I know the changes in distance and time of object a, but I'm not sure how that works

I know getting a better grasp of how sine/cosine work outside simple right triangles is probably the key to this, so I'm trying to work with parallel movement at different rates to try and get some triangles to simplify this

[cedar kiln]

@sonic glade Has your question been resolved?

[sonic glade]

worked it out by filling in right triangles based on complementary angles to theta, going to focus on just brushing up on the translation between sine/cosine values and angles

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[crimson sedge]

in a game i need to reach lvl 400 from lvl 300 the cost to get to lvl 301 is 5590 gold each level above that costs 5 more gold so as an example 5590+5595+5600 how do i make an equation for this?

[severe cave]

a line y=mx+b with
m; the slope that represents the increments of gold per level
b; the y int thats the gold at lvl 0

Solve b by plugging in the m value, a known x value with its corresponding y value, ie: put in a level for x that you know the gold amount for, and set the gold equal to y

and then restrict the x domain to the interval of levels for which the equation is valid for

i could give the answer but try it a bit, this is important building blocks kinda stuff if you attempt it instead of seeing the answer, things will click and ull be better off

[crimson sedge]

sweats in algebra 1 ight ill try it

thanks

[severe cave]

uni?

[crimson sedge]

middle school

[severe cave]

ur good , try and tell me if u get stuck

[crimson sedge]

ight thanks

.close

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[last moat]

Hi, i have no clue how to do 2 b) please help me out

[jaunty mural]

,rotate

[jaunty mural]

2a?

answers?

[last moat]

2b

[jaunty mural]

Hint: both parts are related.

[last moat]

Wait would it work if i plug in the value from part a to R

[last moat]

And 10 to d

[jaunty mural]

Notice

How the roots of a parabola

and the line of symmetry are related

[jaunty mural]

Number 2 and number 3 don't seem to be related.

[jaunty mural]

@crimson sedge ^ if that helps you.

[last moat]

No i meant from part a to part b of question 2

[jaunty mural]

Yes, they are related.

[last moat]

Oh ok thanks

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[small dust]

I'm here watching my teacher's lecture on Force using vectors

[small dust]

and she just kinda stated this without a clear explanation:

why is it cos120 and sin120 for our unit vector??

I'm trying to derive this myself but I can't seem to get it

but then, using the same logic, shouldn't for cord 2, it be cos150 and sin150??

[jaunty mural]

in polar coordinates

the angle/argument

is always taken anticlockwise from the positive x-axis

[small dust]

but then how is it even a triangle, 120 deg and then another 60 deg is impossible?

[jaunty mural]

uhhhh

I think you need to familiarize yourself with polar coordinates (and conversion)

or unit circle

(x, y) = r(cos theta, sin theta)

[small dust]

yes, I know that but I'm asking if that's the case and that cord 1 makes a 120deg angle, how is the other a 30deg one?

oh wait

omg

you're right

[small dust]

I was drawing a picture that makes no sense in cartesian coords

thanks thanks

much appreciated

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[somber zodiac]

ok

[small dust]

uhm

[cedar kiln]

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[clever bloom]

i put this in the calculator and it doesnt really give 312

[clever bloom]

im putting 1/3 * 9/4 * 12squared * 15

[crimson sedge]

Ok

What are u trying to find

Give the exact question

[clever bloom]

equilateral base height 15cm base 12cm

[crimson sedge]

Equilateral what ?

[clever bloom]

base

[crimson sedge]

Of what

[clever bloom]

pyramid

square pyramid

[crimson sedge]

Pls send the entire question

That's why I'm asking

[clever bloom]

ok give sec

it says "find volume to nearest whole number:

[crimson sedge]

I can't see any thing

Can u send again

[crimson sedge]

Bruh fine

U need to convert ur decimal answer to the nearest whole number

[clever bloom]

yeh

[crimson sedge]

So what u got on your calculator

[clever bloom]

1/3 * 9/4 * 12squared * 15

[crimson sedge]

Wait why u put 9/4

Put √3/4

[clever bloom]

1/3 * 3squared/4 * 12squared * 15

same answer cause 3squared is 9

[crimson sedge]

Bruh

Do u know formula for area of equilateral triangle

It's not 3 squared

It's 3 underoot

3 underoot and 3 squared are different

@clever bloom

[clever bloom]

oh fuck

1/3 * 1.73205081/4 * 12squared * 15

thanks it works :)

[crimson sedge]

Np

Just make sure to estimate it to closest whole number

[clever bloom]

.close

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[clever bloom]

.reopen

[cedar kiln]

✅

[clever bloom]

not done yet

@crimson sedge let me have a word with you, buddy

[crimson sedge]

Ok

[clever bloom]

.close

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[cedar kiln]

@vocal aurora Has your question been resolved?

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[lilac swan]

How do they get 2006 = 2 mod 6

[obsidian coral]

I think it's saying 2006 mod 6 = 2

[lilac swan]

Oh that would make sense

thanks

.close

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[mighty mortar]

,rotate -90

[dire geode]

What's your question? And what have you tried

[gray marten]

i’m just confused on what the next step is

[cedar kiln]

@gray marten Has your question been resolved?

[cedar kiln]

@gray marten Has your question been resolved?

[dire geode]

Generally you want to show you started something to get help.

[cedar kiln]

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[crimson sedge]

hello i need some assistance.

[crimson sedge]

With ?

Curve given by r. crosses the x-axis infinitely many times. Find the lenght of the curve which is in between 1st and 3rd crossing.

[jaunty mural]

try sketching first?

[crimson sedge]

how do i find the intersection which it crosses?

How do I sketch it? I apologize. We just had a lecture on parametric equations and polar coordinates but the lecturer wasn't very good so I barely understood..

[jaunty mural]

try plotting point by point

What I said doesn't help you solve directly but might be helpful

Maybe there's some geometry you can see

Or some pattern about the crossing

[crimson sedge]

Yes I'm trying to understand the concept.

nvm that came out wrong

rip 😭 .

.close

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[fallen adder]

Hello I have a question, I need help understanding pythrgtheorn triplets and how I can use them for calculating lengths of a triangle

[upper abyss]

3,4,5 is a Pythagorean triple
Because 3² + 4² = 5²

There's not a ton to know, what was your question?

[crimson sedge]

@fallen adder basically In a right angled triangle

a^2 + b^2 = c^2

Where a,b are the two length

And c is hypotenuse

Or the largest length

[fallen adder]

I understand that part but in the question I need to find the length of a specific area to another

[crimson sedge]

Like ?

[upper abyss]

Seems like you have everything you'll need. Good luck!

[crimson sedge]

Give me an example

[fallen adder]

Like this

[crimson sedge]

Use Pythagoras theorem

In both triangles

ABD and ABC

U just need to find AD

Using Pythagoras theorem

[fallen adder]

Which pythegroen theorm has 13 and 15 and even if i did x^2+13^2= 169

[crimson sedge]

Wut

No that’s wrong

Use Pythagorean theorem in ABD

[fallen adder]

so wuld it be

5 12 13

[crimson sedge]

Yes

So what is DC

@fallen adder

[fallen adder]

5?

[crimson sedge]

No

9-5

[fallen adder]

how???

[crimson sedge]

What’s AC

It’s given in your worksheet

U just calculated AD

[fallen adder]

9 cm

[crimson sedge]

What’s AD

@fallen adder

[fallen adder]

i still do not understand

[crimson sedge]

U just solved for AD

@fallen adder hello ?

[cedar kiln]

@fallen adder Has your question been resolved?

[cedar kiln]

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[steel ledge]

I have a question, how can I prove that a basis generates another?
I have a basis B and a basis C, and I know that the vectors of C can be written as a linear combination of the vectors of B. But I'm pretty sure the definition states it must be the other way around ?

[cedar kiln]

@steel ledge Has your question been resolved?

[dense wing]

any 2 bases can be converted by the change of basis matrix b/w them

[cedar kiln]

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[crimson sedge]

Is anyone good with solving systems of equations

[crimson sedge]

@crimson sedge what equation

By susbstition i ment

Pls how the equation

{6x+3y=-21
X. =3y

6x + 3y = -21

And x = 3y

Right ?

Yea

Put 3y = x in the first one then

0x^4+4x^3+2x^2-6x+9

• 4x^4+0x^3-3x^2+6x-4
  =====================
  -x^4+4x^3+5x^2+12x+13 ??????????

Is that with solving systems by substitution method?

Yes

@crimson sedge what

[crimson sedge]

is that true ?

Pls go to another channel

This one is occupied

ok

So @crimson sedge

What did u get

This is what it looks like

Ik

Substitute 3y = x into the first one

Into the Awnser?

Aorry am a bit confused

No

Into the first equation

So what should the ewuation look like

U have 6x + 3y = -21

U have 3y = x

Can u replace 3y in first equation by x?

Heh

Huh

X is nothing

What

Wot

Sorry am just confused

U get 7x = -21

6x + 3y = -21

6x + x = -21

7x=-21

x = -3

Do u get this much

So you multiply the 3 by 7 and get 21 and use the seven for the x

Wot

No

Thats what you did in the first step

It was x=3y

Now 7x=-21

[crimson sedge]

Start from here

Ok

[livid hound]

the first step is replacing the 3y in the first equation with x
(because 3y = x)

[crimson sedge]

Right

I gtg sleep now

Cya

Wow

[dire geode]

if you have two equations and two variables, substitution is helpful. a lengthier description might be "substituting one variable in one equation into the other equation"

"plug x = 3y into 6x + 3y = -21" translates to "6(3y) + 3y = -21"

[crimson sedge]

Okay

[dire geode]

oops

i got it swapped

"6x + (x) = 6x + x = -21 "

both are correct, the second one is faster

so can you solve for x?

and using that value of x, can you use x=3y to solve for y?

[crimson sedge]

Why do you have 2 6x+x

In the equation

[livid hound]

wdym by 2 6x + x

[dire geode]

from the first equation, x = 3y, so wherever a '3y' appears, you can substitute an 'x'

[crimson sedge]

“6x+(x) =6x+x

[dire geode]

i'm just removing parentheses to make it more obvious

ignore it if you want

[crimson sedge]

Shouldnt there be a 3y in the ewuation

[dire geode]

there was

then i substituted 3y for x because 3y = x

3y = x means i can replace any occurrence of 3y with x

[crimson sedge]

Im screwed

[dire geode]

if this isn't familiar, i suggest reading more on the subject
https://www.purplemath.com/modules/systlin4.htm

also https://www.mathplanet.com/education/algebra-1/systems-of-linear-equations-and-inequalities/the-substitution-method-for-solving-linear-systems

more reading = more learning

[livid hound]

performing substitution like gives you an equation with 1 variable; allowing you to determine its value

which you can then use and perform substitution again to determine the value of the other variable

we can use a much much simpler example of a system of equations
p = q + 5
q = 2

and you can substitute q=2 into the first equation to get
p = 2 + 5 = 7

[crimson sedge]

Ill just fail hehe…. I have no idea what im doing

[livid hound]

are able to understand what's going on in the basic example above?

[crimson sedge]

No

Pi also have to know solving systems by elimination

[livid hound]

which part of this don't you understand?

p = q + 5
q = 2
and you can substitute q=2 into the first equation to get
p = 2 + 5 = 7

[crimson sedge]

I dont understand anything haha …

[livid hound]

do you know the basic definition of substitution?

[crimson sedge]

No

[livid hound]

do you have access to a dictionary

[crimson sedge]

No

[livid hound]

or just look up definition substitution math online

[crimson sedge]

Ok

I hate this sm

[livid hound]

do you know what the word replace means

[crimson sedge]

You replace a number with something similar or the same

How tf do u graph

This is what happened when u miss 1 day of math lol

[livid hound]

I suggest watching a video on this

[crimson sedge]

I have

It doesnt help

[livid hound]

a good video

[crimson sedge]

I have a. Video the teacher sent out

[livid hound]

don't know the contents of that.
iirc organic chem tutor does a pretty good job

try that instead

[crimson sedge]

Okay

[livid hound]

it also feels like you have knowledge gaps from previous topics

[crimson sedge]

Yeah

Ill just get a tutor, thanks for helpinf

[cedar kiln]

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[crimson sedge]

part ii
im doing stuff like ((1/2)mv^2)/time
thats wrong
i attempted working out a force and doing fs/time, that wont work because a is not constant so that returns wrong answer
idk how to do it
correct ans is 0.241

[pallid arrow]

do you know how to find the total work done

[cedar kiln]

@crimson sedge Has your question been resolved?

[crimson sedge]

Fs

[cedar kiln]

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[crimson sedge]

.reopen

[cedar kiln]

✅

[crimson sedge]

.close

[cedar kiln]

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[sand ether]

@crimson sedge did u solve this?

[crimson sedge]

yh i got it, thanks anyway 🙂

[sand ether]

oki

.close

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[sick dagger]

how do i do this question
made so many mistakes

[cedar kiln]

@sick dagger Has your question been resolved?

[dire geode]

what have you tried?

[cedar kiln]

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[crimson sedge]

@steady imp

[crimson sedge]

How would you do this one? It has y which causes me a bit of confusion

Do u know similarity of triangles

[cedar kiln]

@crimson sedge Has your question been resolved?

[crimson sedge]

How did you decide which numbers you take?

Could you try to explain it?

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

@crimson sedge Has your question been resolved?

[dire geode]

,rotate 90

[cedar kiln]

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[zealous fractal]

How can I tell which is which

[pallid arrow]

do you know how to find the slope of a line given in that parametrized form

[zealous fractal]

what does this have to do with slope???

[pallid arrow]

how do you determine if two lines are parallel perpendicular or neither

[zealous fractal]

u tell me in matrix

i can tell if its in graph

.close

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[tired ravine]

does anyone knows how to prove these statements? I can't find any on the internet 😭

[dire geode]

do you have an abstract algebra textbook?