help-13

[timid ingot]

I need help, my exams are coming but i have no idea what to do, i know most of the formula already but my teacher didnt give any sort of hw, so idk where to practice

[obsidian coral]

The book, Google questions on that concept

[cedar kiln]

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[timid ingot]

book?

[timid ingot]

like my textbook

or

[obsidian coral]

Yeah, textbook

[timid ingot]

oh

alright

btw

do yk a website

that shows

[obsidian coral]

Nope

[timid ingot]

all the formulas

for maths

oh

ok

[obsidian coral]

Well, depends

What level math?

[timid ingot]

wdym lvl

uh

idk

just

grade 9?

[obsidian coral]

Like algebra?

Trig?

[cedar kiln]

@timid ingot Has your question been resolved?

[cedar kiln]

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[timid ingot]

yes

[timid ingot]

algebra

trig

bearings

circle theorems

etc

[obsidian coral]

I don't know any helpful sites, sorry

[cedar kiln]

@timid ingot Has your question been resolved?

[timid ingot]

oh

[cedar kiln]

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[crimson fern]

.reopen

Oh oops

[crimson fern]

I need the answer for this

[cedar kiln]

@crimson fern Has your question been resolved?

[south tundra]

If 8cm isn't length of the entire side, then just use Pythagorean theorem

[cedar kiln]

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[stuck snow]

Can anyone help with this pls!

[glad kestrel]

gotta get a new help channel and that looks an awful lot like a quiz/test

[cedar kiln]

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[wise perch]

y=2/3x+2

[wise perch]

x=-3 y=?

its about coordinates i think so (x,y)

[south tundra]

Just plug in x = -3 into the equation

[wise perch]

ok

y=2/3-3+2

so do u multiply

[south tundra]

Ahem, y = 2/3*(-3) + 2

[wise perch]

ye

[south tundra]

2/3-3 is different

[wise perch]

ok

[south tundra]

So you have y = -2/9 + 2

Which is the same as -2/9 + 18/9 = 16/9

That's it

[wise perch]

oh ok

but its wrong

[crimson sedge]

n = 3, $f’=6\sin^2 2\theta \cos2\theta = 6\cos 2\theta-6\cos^3 2\theta$

[wraith dagger]

stangeqwq

[crimson sedge]

Remember the identity, $\sin^2 \theta = 1-\cos^2\theta$

[wraith dagger]

stangeqwq

[wise perch]

My teacher helped me with it

its 0

i still kind adont understand how 2/3 x -3 is 2 tho

[crimson sedge]

Its -2

Then u add 2

Boom, 0

The added 2 is the y-intercept

[cedar kiln]

@wise perch Has your question been resolved?

[wise perch]

but

how is it -2

it says 2/3

not v-2/3

[crimson sedge]

2/3 times -3 is -2 @wise perch @wise perch

[cedar kiln]

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[wise trail]

may i know does this notation meant 10p6 or is it 10c6? because i have never learn to write in this way, hence im confused

[torpid harness]

10C6

[wise trail]

tqvm bro

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[crimson sedge]

The 0.9 is bugging me

[south tundra]

You need 1 on the RHS, so you could divide both sides by 0.9, which is the same as multiplying by 10/9

[crimson sedge]

So, I'll have to multiply the whole LHS by 0.9...?

And then divide both sides by 0.9??

[south tundra]

No

Okay look

So we have $\frac{0.8x^2}{2} + \frac{0.7y^2}{5} = 0.9$

[wraith dagger]

Beans

[south tundra]

Multiplying both sides by 10 yields $4x^2 + \frac{7y^2}{5} = 9$

[wraith dagger]

Beans

[south tundra]

So we can divide everything by 9 to get that

$\frac{4x^2}{9} + \frac{7y^2}{5\cdot{9}} = 1$

[wraith dagger]

Beans

[south tundra]

From here it is easy to see the values of a and b coefficients

[crimson sedge]

Wait...

Oh!! Okay!!

Thank you!!

[south tundra]

You're welcome

[crimson sedge]

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[crimson sedge]

integral of (a) - integral of (b) = integral of (a - b)

[crimson sedge]

is this true?

just wanna check u can factor out the integral sign like that?

[magic bough]

Yes

[crimson sedge]

thanks 🙂

[magic bough]

If you can distribute it in

You can take it out

[crimson sedge]

oh yeah thats true

[magic bough]

Cuz x=y means y=x

#math

[crimson sedge]

thank you 🙂

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[magic bough]

Help

How to calculate how many numbers divisible by 5?

When repetition isnt allowed

So only having trouble with (ii)

Help the mango

[tropic oxide]

your number is ≥5000 and is divisible by 5

the first criterion means its first digit has to be 5 or 7

the second means its last digit has to be 0 or 5

[magic bough]

Right

[tropic oxide]

so you have three cases: 5xx0, 7xx0 and 7xx5

where x represents an undetermined digit

[magic bough]

Oh...

So 3*2 = 6 possibilities for each case?

Meaning 18

[tropic oxide]

appears so.

[magic bough]

Cool got it

Thanks for helping the mango

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[nocturne kernel]

Hi need help with this question

[cinder talon]

huh

thats the exact same thing @indigo forge asked

sorry for ping btw

[nocturne kernel]

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[stuck geode]

https://tenor.com/view/dick-shocked-john-cena-when-she-shows-you-her-dick-gif-16040163

[ashen monolith]

.close

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[vale pike]

I have to compare them

And also to prove it

[tropic oxide]

have you made any progress so far or are you stuck not knowing how to begin?

[vale pike]

I know the result

I just need to prove it

Idk how

[tropic oxide]

okay

well

[vale pike]

Haven’t compared anu square roots yet

[tropic oxide]

instead of comparing $\sqrt[3]{2}$ vs. $\sqrt[4]{3}$, try to compare $(\sqrt[3]{2})^{12}$ vs. $(\sqrt[4]{3})^{12}$

[wraith dagger]

Ann

[tropic oxide]

you might find their twelfth powers easier to compare

[vale pike]

Ah

Thanks

Finally i see it

.close

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[jaunty mural]

both?

[jaunty mural]

Do you have any clue for (i)

[remote palm]

no

[jaunty mural]

hmmm

It's kindof something you need to have 'seen' I guess

1x - 1y
0x - 2y
3x - 5y```

^ this is T(x y)

[remote palm]

ok

[jaunty mural]

Does this help you split it up into a matrix multiplied by a vector?

any clue?

$$\begin{pmatrix}
? & ? \
? & ? \
? & ? \
\end{pmatrix}
\begin{pmatrix}
x \
y \
\end{pmatrix}$$

[wraith dagger]

Shuri2060

[jaunty mural]

It's going to end up looking like this (hint)

[cedar kiln]

@remote palm Has your question been resolved?

[remote palm]

.close

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[inner needle]

I calculated the variance, it is 0.000225
How can I get the sample size for a 0.001 RMSE?
I tried some calculations but they don't make sense

[cedar kiln]

@inner needle Has your question been resolved?

[inner needle]

<@&286206848099549185>

[inner needle]

[cedar kiln]

@inner needle Has your question been resolved?

[inner needle]

<@&286206848099549185>

[cedar kiln]

@inner needle Has your question been resolved?

[inner needle]

<@&286206848099549185>

[granite canopy]

so how is rmse related to variance

[inner needle]

the rmse is the square root of the variance

[granite canopy]

yep

[inner needle]

so my idea was

still not sure how I can get the new sample size though

[granite canopy]

ok so if you assume that Y_i are normally distributed about some mean

and the mean is just the mean of the sample

[inner needle]

alright, I have the mean of the sample

[granite canopy]

and you have an estimated variance

[inner needle]

yes

0.000225

idk if I calculated it correctly, but I should have

[granite canopy]

now you can set up a normal distribution

[inner needle]

do I need to draw a graph for that?

[granite canopy]

well not really

do you know any test statistics?

https://en.wikipedia.org/wiki/Test_statistic

[inner needle]

not that much

so basically there isn't a formula I can use

[granite canopy]

there is

[inner needle]

to calculate the new sample size?

oh

so it's this ?

[granite canopy]

yep

you have sigma, you have mean

[inner needle]

let me try calc it, the number should be

freakishly large

[granite canopy]

for sure

you want a tiny rmse

[inner needle]

Oo nice

then my variance

is correct hopefully

so what is x with that line there?

[granite canopy]

thats expectation

[inner needle]

how do I get that

and also sqrt(n) , n is the sample size I used to get the mean?

yeah its the same n in the 1 / n - 1 I linked earlier to find the variance

[granite canopy]

https://en.wikipedia.org/wiki/Z-test

https://en.wikipedia.org/wiki/Standard_score

or this is probably better

[inner needle]

oh {\bar {x}} is the mean of the sample,

[granite canopy]

yeah but you dont just put in the mean

[inner needle]

why not?

[granite canopy]

rather, you calculate z for each individual measurement then you take the average

[granite canopy]

well then it would just be the mean then you get zero in the numerator

[inner needle]

hmm, im pretty sure I don't have to do all this though

I think our professor woulda told us

[granite canopy]

well im not sure what you have in your toolbox

[inner needle]

fair enough

[granite canopy]

and if you are taking a basic stats course there are definitely some test stats involved

essentially formulae used for hypothesis testing

[inner needle]

im running a monte carlo

if that helps you in any way

10,000 iterations

[granite canopy]

hmm then you can probably get gnuplot or whatever program you are using to do the evaluation automatically

[inner needle]

now I need to find the new number of iterations for that 0.001

im using c# ;p

dont think you can plot

thats why I don't think I have to do all this

would a KS- statistic make sense or am I speaking total nonsense ?

coz thats the only thing we learned

[granite canopy]

https://en.wikipedia.org/wiki/Kolmogorov–Smirnov_test

Intuitively, the statistic takes the largest absolute difference between the two distribution functions across all x values.

is that what you want?

[inner needle]

Not sure tbh

I suck at this

as you can see

[granite canopy]

i mean each test stat is designed to either prove, disprove or return unsure about some hypothesis. you gotta figure out which hypothesis you wanna test

[inner needle]

I dont want to test a hypothesis atm though

I just want to find the number of iterations to supply for monte carlo

a new sample size

[granite canopy]

id say the z test is probably the best

https://stackoverflow.com/questions/30939045/statistical-method-to-know-when-enough-performance-test-iterations-have-been-per

[inner needle]

hmm thanks ill look at that

so if I take https://media.discordapp.net/attachments/903430334681608232/930581442671558656/unknown.png

and for the x I put in the sample mean

will it be incorrect?

[granite canopy]

then you end up with z=0

[inner needle]

hmm

ill try it ;p

[granite canopy]

cos the sample mean is just mu_0

[inner needle]

oh

[granite canopy]

usually what you have is a predicted mean and a sample mean

[inner needle]

in this case all I have is the sample which I got from the monte carlo simulation

I still feel like im missing something obvious in my exam

[granite canopy]

wait this is an exam?

[inner needle]

sort of

[granite canopy]

you cant ask for help for exam questions lol

[inner needle]

lmfao

who would be doing this in their free time ?>:D

[granite canopy]

homework is fine but exams no

[inner needle]

oh yea well

you can count it as homework I guess

ty for trying to help I appreciate it

[granite canopy]

well i guess i cant help you more XD but yeah, find the appropriate test statistic and put it in

[inner needle]

alright tyvm

[granite canopy]

np

[inner needle]

!close

[calm sierra]

.close

[cedar kiln]

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[crimson sedge]

hi

[crimson sedge]

how do i find the exac value of cos 15

using double angle formulas

[limber rune]

https://www.youtube.com/watch?time_continue=133&v=LpbHXzlEbrg&feature=emb_title

@crimson sedge

bro went offline in 1 min

[crimson sedge]

hi

oh wow

let me chekc this out

[limber rune]

watch vid

[crimson sedge]

ty

this isnt what we are doing

no half angles

[last matrix]

What formula you have taught

cos(2x)=2(cosx)^2-1

[crimson sedge]

yeah those ones

[last matrix]

You can use this

[crimson sedge]

sorry tbh i just learned this like very recenlty

so i apologize for the bad qs

[last matrix]

Have you got it?

[crimson sedge]

no

[last matrix]

Just let x=a/2

Then 2x=a

Move the a/2 to the left hand side

[crimson sedge]

so it would be 15/2

[last matrix]

Normally

There will be a square root

[crimson sedge]

ohh 2x15

okay

tysm

[cedar kiln]

@crimson sedge Has your question been resolved?

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[devout sun]

The surface area of a cube is (54x²+36x+6) cm².Calculate the length,in cm,of the edges of the cube

[devout sun]

<@&286206848099549185>

[dense wing]

Ping after 15 minutes.

[jaunty mural]

you've already asked.

[dense wing]

That too

[jaunty mural]

Didn't someone help you

[devout sun]

No

[jaunty mural]

'how many sides does a cube have'

is quite helpful

[devout sun]

6

[jaunty mural]

ok.

You are told the surface area of the cube.

[jaunty mural]

How does this help you.

[devout sun]

Factorise it ?

By 6 ?

[jaunty mural]

And why does this help.

[devout sun]

Idk

[jaunty mural]

🤔

[jaunty mural]

.

[jaunty mural]

.

No coincidence, I promise.

[devout sun]

6 (9x²+6x+1)

?

[jaunty mural]

ok.

[jaunty mural]

this is the surface area of the cube

why would dividing by 6 help you?

[devout sun]

Because I want the area of the cube I guess

[devout sun]

What should I do next

[jaunty mural]

?

Be more specific

why does dividing by 6 help

on the total surface area

[devout sun]

Idk

[jaunty mural]

Remember I asked this?

and you answered 6

[devout sun]

What should I do after I got 6 (9x²+6x+1)

[jaunty mural]

You're missing my point

A cube has 6 faces

The surface area is the total area of those 6 faces

get it?

[devout sun]

I see

[jaunty mural]

Hope you can do the rest of the question

[devout sun]

I cant

[dense wing]

what's the SA of a cube with side length s?

[jaunty mural]

You know how to get the surface area of 1 face now.

Why are you stuck

What do the faces look like?

[jaunty mural]

=======
Alternative approach to the whole question is to do this ^

[devout sun]

Is this the surface area ?

[jaunty mural]

yes.

of the entire cube.

[devout sun]

Divide it by 6 again ?

[jaunty mural]

You never divided it by 6 before, but ok

Divide by 6 and get the surface area of 1 face then.

[devout sun]

Is it possible if I factorise this

I haven't learn how to divide this thing yet

[jaunty mural]

by 6?

[devout sun]

Yes

Or maybe 3

[jaunty mural]

you have 6 multiplied by something

and you're trying to divide by 6

???

[devout sun]

How to divide it

[jaunty mural]

How do you divide $6k$ by 6

[wraith dagger]

Shuri2060

[devout sun]

6k/6 = k

[jaunty mural]

Same idea.

6(9x²+6x+1) / 6

[devout sun]

(3x²+2x+1)/2 ?

[jaunty mural]

???

you need to review basic algebra

[devout sun]

3x+1 ?

[jaunty mural]

6(9x²+6x+1) / 6 = 9x²+6x+1

?????

[devout sun]

Do I need to know value of x ?

[jaunty mural]

no.

your answer will be in terms of x

[devout sun]

I don't get it

[jaunty mural]

Your side length will be something like 10x + 5

(it's not, just giving an example)

[devout sun]

How to get that side length

[jaunty mural]

What do the faces of a cube look like

You have the surface area of 1 face. You can find the side length.

[devout sun]

Divide by 2 ?

[jaunty mural]

???

bruh

[devout sun]

Because all the side value is same

[jaunty mural]

If you have a side of a square

if x is the side of a square

the surface area is $x^2$

???

[wraith dagger]

Shuri2060

[devout sun]

Do I need to use this √

[jaunty mural]

yes

exceptyou can factorise

9x²+6x+1

^ this into a square

[devout sun]

√9x²+6x+1 ?

[jaunty mural]

yes but you can factorise that quadratic

in a helpful way

[devout sun]

How to factorise it

[jaunty mural]

9x²+6x+1 = (ax + b)(cx + d)

In fact I gave you a hint

9x²+6x+1 = (ax + b)(ax + b)

[jaunty mural]

If you're doing these kinds of questions, you should know basic algebra and how to factorise tbh

[devout sun]

(3x+1)(3x+1)

Am I right

[jaunty mural]

yes

[proper field]

well, u gave an arbitrary expression

what does that mean in context?

[jaunty mural]

wut

[proper field]

what does (3x+1)(3x+1) mean

u want the length of 1 side

6 * the area of a face = surface area of the cube right?

[jaunty mural]

They're almost there

[proper field]

u are asked for the sidelenghts

[proper field]

yeah they are

how do u find the area of a square?

[devout sun]

length x width

[proper field]

but in a square, both are the same right?

[devout sun]

Yes

Oh

Wait

[proper field]

:)

[devout sun]

(3x+1) is the answer right ?

[proper field]

yes

[devout sun]

Bro my brain almost explode

[proper field]

dont forget ur units though

[devout sun]

Thanks

[eternal totem]

just solve it out dude

u know the trick right

[proper field]

?

[eternal totem]

its like

outer inner

inner outer

or something

[proper field]

read the context of the chat please

[eternal totem]

how to read??

[proper field]

and im not the one asking for hlep lol

[devout sun]

.close

[cedar kiln]

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[eternal totem]

ur an engineer

good

[cedar kiln]

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[deep bison]

The question is to find the constant of proportionality of C=5n+20

The formula is Q=kL

I don't see how to get to that form

[cedar kiln]

Channel closed

Closed due to the original message being deleted

[graceful karma]

Could you say like L is C-20 or something?

Im not sure if thats proper but

[deep bison]

I mean

Can I send pic of problem?

Maybe that would clarify

[graceful karma]

Try saying .reopen rq sorry the bot is confused

Also yeah thatd help

Prob

[deep bison]

Ok

Number 18

[graceful karma]

What are the instructions?

Like at the top of the group of problems

[deep bison]

Find the constant of proportionality

Oh wait

I re-read and it says it could also not be the right answer

It's asking if there is one

[graceful karma]

Oh

[deep bison]

Sry I made a mistake

But ty for pointing that out to me

[graceful karma]

Well directly proportional things have to be of the form y=kx so yeah like you said

There prob isnt a constant of proportionality

[deep bison]

Yeah

Tysm

[graceful karma]

Np

[cedar kiln]

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[onyx stratus]

can someone help me with this?

[crystal scarab]

either 2cosθ-rt(3) = 0 or 2tanθ-2=0

[onyx stratus]

i don't get the question

0<theta<360

[crystal scarab]

ye solve for theta between 0 and 360

[onyx stratus]

what does it mean?

[crystal scarab]

θ will have infinite values they are asking to find the values between 0 and 360

[onyx stratus]

oh okay

[onyx stratus]

i still don't know how to solve that

tho

<@&286206848099549185>

[graceful karma]

Did you try multiplying it out

[onyx stratus]

how?

[graceful karma]

Have you learned FOIL

[onyx stratus]

yea

[crystal scarab]

ok so

[onyx stratus]

i don't understand anything thats the thing

you gave me the straight answer

[graceful karma]

Just foil out the stuff

[onyx stratus]

but how do i get there?

[crystal scarab]

thats ..

[onyx stratus]

when u move the 2 doesn’t it become negative ?

[crystal scarab]

noo

how bro

u are dividing by 2

[graceful karma]

Oh wait nevermind Im dunb

[onyx stratus]

oh okay

i just have a difficult time with the radianta

radiants

[onyx stratus]

do i do this for both parentheses ?

[crystal scarab]

yep

[onyx stratus]

and then what do you do with the answer from both parentheses?

[crystal scarab]

find theta then find all answers for theta from 0 to 360

[onyx stratus]

so both answers are viable for the answer of the question ?

[crystal scarab]

yes

[onyx stratus]

okok thanks

[crystal scarab]

np

[onyx stratus]

.close

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[rugged tusk]

how to solve this limit ?

[livid hound]

consider conjugates and difference of two cubes

[rugged tusk]

$\lim_{x \to 1} (\frac{1+3 \sqrt{x}-2 \sqrt[3]{x}-2\sqrt[3]{x^2}}{1-x})$

[wraith dagger]

Michal

[rugged tusk]

ended up with thiis

dont know what to do next

[floral thistle]

you can use lhopitals rule here

[rugged tusk]

im not allwed use lhospital

[cedar kiln]

@rugged tusk Has your question been resolved?

[livid hound]

hmm, start with the sub
x = u^6

[last matrix]

@rugged tusk

[rugged tusk]

?

[last matrix]

do it

[rugged tusk]

i cant see the message

discord is buggy

[livid hound]

start with the sub
x = u^6

[rugged tusk]

$\lim_{t \to 1} (\frac{1+3t^3 -2t^2-2t^4}{(1-t^3)(1+t^3)})$

[wraith dagger]

Michal

[rugged tusk]

whats next

[last matrix]

i am thinking

can use lhospital rule?

[rugged tusk]

i cannot

[last matrix]

then how

<@&286206848099549185>

[livid hound]

start with making the sub at the very start

it'll be less tedious and easier to work with

[strong lantern]

yes

[strong lantern]

take x =t^6 here

[rugged tusk]

.close

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[strong lantern]

did you get it @rugged tusk ?

[cedar kiln]

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[rugged tusk]

i have tried the subtition, but i still cant solve it

[rugged tusk]

but stll trying

[livid hound]

what do you have after the sub i suggested

[tropic oxide]

what sub did you suggest @livid hound

[strong lantern]

yes use the substitution

you will get it

[livid hound]

x=u^6

[rugged tusk]

i ended up with $\lim_{t \to 1} (\frac{1+t-2t^2}{(1-t)(1+t+t^2)(1+t)})$

[wraith dagger]

Michal

[strong lantern]

instead of adding

[tropic oxide]

may i suggest looking at the numerator here @rugged tusk

there's something you can do to it

[rugged tusk]

hmm

[strong lantern]

yes this works too lol

[rugged tusk]

i dont have idea what

[strong lantern]

factorize it?

[rugged tusk]

yes, but how 😦

im going to try someting

[livid hound]

consider that when t=1, numerator = 0

[strong lantern]

take "-" sign common from numerator if that helps

[livid hound]

and that the numerator is also a quadratic polynomial

[strong lantern]

can you factorize this => -(2t^2 - t - 1)

[rugged tusk]

hmm

[strong lantern]

splitting the middle terms?

[rugged tusk]

i got it

(2t+1)(t-1)

[strong lantern]

yes

don't forget minus sign

[last matrix]

as t-1 is not zero

[rugged tusk]

ok thanks guys

.close

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[crimson sedge]

whats this transformation doing

i thought

its making all the (x,y,z), its making all the y values negative

so its x = z plane reflection???

i think thats wrong tho

oh wait

its not only doing that

its making the new x co ordinates negative y's

its making y co-ordinates x's

and is leaving z as z

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[crimson obsidian]

A line passes through the point A(k,4) and intercepts the x and y axis such as a triangle forms with the axis. Find the minimum area of the triangle using k.

I don't understand how do I solve it

I tried to find relation with k

I solved it but the book gives another ans

This is my work upto now....I've 2 equations atm and 3 variables

<@&286206848099549185>

[frigid canyon]

you have one more equation, y=mx+b

but it won't work

cuz every equation is equivalent and i think you can't go thru like that

use parametric form and solve the thing

[crimson obsidian]

What is parametric

[frigid canyon]

another form of equation of line

[crimson obsidian]

Oh

I remember

[frigid canyon]

so will you be able to do?

[crimson obsidian]

I don't think so

I thought parametric form of equation was xCosQ + YSinQ=P form

But it turn out(when I saw google) that I hadn't studied that form of equation as of yet lol

I am studying parametric equation in google

Give me some minutes and maybe I can solve !

[frigid canyon]

that's the normal form

[frigid canyon]

sure thing man

[crimson obsidian]

Yeah after this time I understood that x-x1/cosQ=y-y1/sinQ is parametric form

I will apply this to my question now!

I got the equation...m=(y-4)/(x-k)

I'm stuck after that lol

[frigid canyon]

np i'll help

[crimson obsidian]

Ty so much!

.close

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[crimson obsidian]

Hint: 4 into 5 = 20

[sick bronze]

i only know until
y(y-4)-5(y-4)

[crimson sedge]

Then take y - 4 common

U get (y-5)(y-4)

[sick bronze]

take y-4?

[livid hound]

identify the common factor and factor it out

[obsidian coral]

Factor out the common term, which is y - 4

[crimson sedge]

^

[obsidian coral]

As someone above stated

[livid hound]

i.e apply the exact same thing you supposedly used to reach the expressions
y(y-4) and -5(y-4)

[sick bronze]

ohok

so the answer be (y-4)(y-5)

[dapper raven]

what is the question?

it depends on the question what the answer is

[livid hound]

if you're being asked to factorise, yes

[sick bronze]

Factories

[dapper raven]

then you got it

[sick bronze]

ok tq

.close

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[floral hedge]

Hi

[floral hedge]

I have a question

Why 0! Is 1

[cedar kiln]

@floral hedge Has your question been resolved?

[dense wing]

what else would it be?

[cedar kiln]

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[wise aurora]

Determine the equation of the quadratic in factored form given the x-intercepts (-6, 0) and (2, 0) and that goes through the point (-2,48). Show all steps.

[plucky pawn]

start off with the form of y = a(x-a)(x-b) and plug in x intercept values into the equation. You then can find a from (-2,48)

[wise aurora]

Thank you

.close

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[frail dune]

how do I turn $x^2+x+6$ into $(x+a)^2+b$ form?

[frail dune]

is there a general rule for that?

[wraith dagger]

Erzis エルジス

[rain vessel]

https://en.wikipedia.org/wiki/Completing_the_square

[cedar kiln]

@frail dune Has your question been resolved?

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[frail dune]

thank you

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[noble sedge]

Help

[cedar kiln]

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[spare elm]

Hey i was wondering if someone could guide me on how to do regression

[spare elm]

like the theory behind it and the formulaes and stuff

cause I could use desmos or my calculator but I just want an understanding of whats happening

[graceful karma]

Linear regression specifically?

Or just in general

[rain vessel]

I think a math stat course would help. If not a full course, at least a few pages from such courses

[cedar kiln]

@spare elm Has your question been resolved?

[spare elm]

like non linear

[spare elm]

yeah i was just wondering if there was like a specific formula or something along those lines i could work wiht

[cedar kiln]

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[crimson sedge]

z = 1 + 2i

[crimson sedge]

for any n that is natural show that z^n = an + ibn where an and bn are both integers

[frail dune]

I'd try proving it with polar form somehow

algebraic seems way harder

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

@crimson sedge Has your question been resolved?

[vapid widget]

Is this not a proof by induction where you use z = 1
Z = k
Z = k+1

[crimson sedge]

eh nevermind i found solution

but i struggle evaluating (1+2i)^n + (1-2i)^n

what is (x+yi)^n + (x-yi)^n in general?

[cedar kiln]

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[unreal saffron]

prove that if n | 1227 and n | 619 then n | 11

[unreal saffron]

my idea is n | 11 => n = 11 or n = 1, and show that the only common factors of 1227 and 619 are 11 and (obviously) 1

[mighty drift]

You can use Euclid's algorithm to show that n | gcd(1227, 619), which I suppose is 11

[jaunty mural]

this works, but the more general fact that

a | b and a | c => a | gcd(b, c)

is probably what theyre after

[unreal saffron]

oh so actually you guys helped me hehe, they are coprime it seems

[jaunty mural]

?

oh lol

[unreal saffron]

so since n can either be 1 or 11 and it divides both of them it can only be 1

ty

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[crimson sedge]

Hello

[bright surge]

wow that's a big mess

which question are you asking about?

[crimson sedge]

I want to see if I did 25 right

Yes sorry

I was typing

[bright surge]

i don't know where you put the solution for 25....

[crimson sedge]

It’s circled

[bright surge]

so can you write it again in this channel?

[crimson sedge]

Yes

X = 3/14

[bright surge]

(also, is the question $\log_7(6)-\log_7(4x)=1$?)

[wraith dagger]

Mobius Earth Gang COO Sam.

[crimson sedge]

Yes

[glad kestrel]

yes, your solution is correct

[bright surge]

should be correct

[crimson sedge]

thanks I have1 more I am thinking is wrong

[bright surge]

i hate my internet

[crimson sedge]

You see 10

Did I do it correctly?

[bright surge]

no i don't

[crimson sedge]

It’s circled

the answer

My writing is not that bad come on

[bright surge]

can you send another pic so that the statement for q10 is clearer

[glad kestrel]

looks good to me

well the neatness doesn't but your answer does

[crimson sedge]

oh

Ok that’s still good

Thank you

How to close?

[cinder talon]

.close

[crimson sedge]

.close

[cedar kiln]

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[bright surge]

a disappointing son how could you read what that question AND HIS ANSWER said

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[warm vector]

Question 38.

[teal totem]

ok so you know what you are trying to find right

[warm vector]

Yes

Wait I’ll post my first step

[teal totem]

k

[teal totem]

so what was your thought process

[warm vector]

So I had to make the denominator same first

[teal totem]

ok thats good

but

That's not what you're supposed to do

[warm vector]

Why?

[teal totem]

So lets start with (x+y)

simplify (x+y)(x-y)

[warm vector]

X^2-y^2

[teal totem]

exactly

now if you apply this concept to the problem

[warm vector]

On the denominator part?

[teal totem]

yes

because it squares both things

[warm vector]

Yes

[teal totem]

so the root will be rationalized

[warm vector]

okay

[teal totem]

this is also known as multiplying the conjugate

[warm vector]

Okay

[teal totem]

For 3/(root(5)+2), conjugate would be root(5)-2

[warm vector]

I think I got it thanks.

[teal totem]

No problem!

[warm vector]

Thanks I got it I just didn’t apply that concept in the denominator

.close

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[golden basin]

60 needs to be the value that is equal to 100%, even though the actual rectangle’s width is 200. For instance, if a 30 is added it will cover 50% of the 200-width rectangle. I need to know a formula to make something like this work. Hope the question makes sense.

[cedar kiln]

@golden basin Has your question been resolved?

[violet flume]

it doesnt really make sense

whats the original question

[golden basin]

There’s no original question but does this visual clarify things?

[violet flume]

so what like

you take some number for y and then you know what percentage it is of ... z?

oh

i think i see

so x divided by y is z

but then its not really clear what is red?

why is it all read if y = 30

what is 15? x?

[golden basin]

@violet flume x can be any number. I used x = 15, x = 30 as examples

[dense kayak]

200 * (x / 60) will give some percent of 200 for x in [0, 60]

[golden basin]

I swear I did something like that

Bruh i did that. the error must be in my code

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[visual bloom]

guys how do i solve this?

[bright surge]

a^-n = 1/a^n

$a^{-n}=\frac{1}{a^n}$

[wraith dagger]

Mobius Earth Gang COO Sam.

[visual bloom]

what?

i don't understand?

am sorry am slow

[strong lantern]

it is an rule to convert negative powers into positive powers

[crimson sedge]

Lets use an example
$2^{-3}=\frac{1}{2^3}$

[wraith dagger]

holyyyy_K

[crimson sedge]

I'm sorry I'm new in discord and I'm doing mistakes lmao.

$\frac{1}{8}$
Will be the answer

[wraith dagger]

holyyyy_K

[crimson sedge]

So you can use this method and calculate other values.

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[crimson sedge]

Find two solutions to the equation 3x + y = 2

[crimson sedge]

anyone know how solve?

[crimson vigil]

you can isolate either x or y, preferably y

[jaunty mural]

try x = 0

then x = 1

[crimson sedge]

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[cosmic idol]

Qn 8, i dont know how to approach it

my working so far

not sure how to continue

[jaunty mural]

theres no picture in your working 😦

[cosmic idol]

there has to be a pic?

[jaunty mural]

wait so you have P and Q

[fickle trellis]

Yeh

So just

[jaunty mural]

differentiate?

[fickle trellis]

Find gradients of tangents to it.

[cosmic idol]

do i have to sketch the graph

[jaunty mural]

not rlly when ur pretty much there

[cosmic idol]

i dont know i just started differentiation and i dknt understand anything

[jaunty mural]

what does differentiation do

[cosmic idol]

find gradient

[jaunty mural]

yh ok

so whats derivative of curve

[cosmic idol]

what should i differentiate tho

[jaunty mural]

the curve ur tryna find the gradient of

the line meets the curve at P and Q

[cosmic idol]

i take the 3x^2 eqn to differentiate?

[jaunty mural]

yh

thats the curve

[cosmic idol]

ah okay thank you

like this?

[fickle trellis]

dy/dx tho

[jaunty mural]

well

theres some dodgy algebra there

that ends up not mattering

the 2nd to 3rd line u took the 5 off the fraction for no reason

[fickle trellis]

Yep doesnt

Just for the neatness haha

And adding more lines to read (for us)

[cosmic idol]

doesnt 5 become 0 after differentiating

?

[jaunty mural]

2nd to 3rd line

$$y = \frac{3x^2+5}{8} = \frac{3x^2}{8}+5$$

[wraith dagger]

Shuri2060

[cosmic idol]

oh its supposed to be 5/8 not 5

okayy thanks

wait but my final answer of the derivative is still the same right

3/4 x

[jaunty mural]

yh

[cosmic idol]

i got the answer!! thank you so much

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[fair narwhal]

guys does anyone know when to use 0 to 2pi and -pi to pi on the fourier series

[tropic oxide]

literally doesnt matter so use whichever is more convenient

[fair narwhal]

ok thank you

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[primal lichen]

$f(x) = (1-x)/(x+2)$ State the domain and range

[wraith dagger]

Pluto

[primal lichen]

I'm not sure how to show how it cannot be -2 using interval notation

i looked online but it wasnt much help

[south tundra]

(-infinity, 2)U(2, +infinity) or R\{2}

[primal lichen]

ok thank you!

.close

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[violet flume]

why is c not parametric?

this text doesnt really explain

whats missing that doesnt let us hit all cdf's with mean 0

<@&286206848099549185>

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[woven mist]

When is the solution of a linear system(matrix) the empty set?

[woven mist]

Is it when we have (0,0,0|X) where x is any non zero number?

[dense wing]

yes

REF has an all 0 row for the matrix, non-zero entry in the constant vector

[woven mist]

Ok thanks

And if it says one dimensional flat does this mean one free variable?

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[crimson sedge]

Are my answers good?

<@&286206848099549185>

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@crimson sedge Has your question been resolved?

[crimson sedge]

<@&286206848099549185>