help-13

[floral thistle]

remember to .close

[waxen plank]

How to close

[floral thistle]

it’s .close

[south tundra]

.close

[waxen plank]

.close

[cedar kiln]

Channel closed

Closed by @waxen plank

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sleek wharf]

How do you solve this?
x+y=29

[wheat grail]

Do you have any more information in that question?

[sleek wharf]

No

x + y =29

[wheat grail]

Ahh ok
So you need to take either x or y
And find them in terms of the other
So for example, represent y in terms of x

[sleek wharf]

Ok thank you

.close

[cedar kiln]

Channel closed

Closed by @sleek wharf

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

@sick ruin

[crimson sedge]

so

when i do mod 4 to the left side, i get 2.

also, why mod 4?

[tropic oxide]

original problem? @crimson sedge

[crimson sedge]

yes

[tropic oxide]

let me be more clear

can i see the original problem?

[crimson sedge]

Does the equation 12x^2+2=y^2 have any integer solutions (x,y)?

[tropic oxide]

uh huh

[crimson sedge]

they said that i could ping them since i had to go yesterday

but i want to do this problem mostly myself

[tropic oxide]

the left-hand side is always 2 mod 4, that's right.

what about the right?

[crimson sedge]

i dont know a thing about the right

[tropic oxide]

you do actually

try calculating the squares of 0, 1, 2 and 3 mod 4

you might just see something

[crimson sedge]

ok

i remember from a previous problem, isnt every even square divisible by 4?

2k*2k=4k^2

[tropic oxide]

sure, but that alone isn't enough nor is it what i was asking you to arrive at.

[crimson sedge]

even square mod 4 = 0

[tropic oxide]

if i must repeat myself,

try calculating the squares of 0, 1, 2 and 3 mod 4

trust me your fingers won't fall off from doing this little bit of arithmetic

[crimson sedge]

oh, calcuating

0 mod 4 = 0, 1 mod 4 = 1, 4 mod 4 = 0, 9 mod 4 = 1, 16 mod 4 = 0

i told you

[tropic oxide]

you didn't tell me the whole story

you chose to only tell parts of it

[crimson sedge]

all even squares = 0 mod 4

all odd squares = 1 mod 4

[tropic oxide]

you didn't say shit about odd squares until now

and that

that is important

[crimson sedge]

is it better to say nothing or say shit?

[tropic oxide]

"didn't say shit" is slang for "didn't say anything".

anyway,

the key point is:

[crimson sedge]

ah

[tropic oxide]

the residue of a square mod 4 is always either 0 or 1.

and in particular, it follows that the residue of a square mod 4 is never 2 or 3.

[crimson sedge]

why?

[tropic oxide]

why what

[crimson sedge]

waiy

because

(2k+1)(2k+1)=4k^2+4k+1

[tropic oxide]

you're overthinking it

[crimson sedge]

always 1 more than a multiple of 4

[tropic oxide]

you do not need to do any more calculations

[crimson sedge]

i like to know why

[tropic oxide]

you LITERALLY just calculated the square of every possible residue mod 4

maybe don't throw your own calculations in the trash like that eh?

[crimson sedge]

what calculations?

how is 2k*2k=4k^2

a bad thing

how is that a trash calculation

but whatever

[tropic oxide]

these calculations

jeez

im not saying your calculations are trash

im saying you're TREATING them like trash by ignoring them outright

but please dont put words in my mouth

[crimson sedge]

ok

so this means that 2=0, or 2=1

those are false statements

[tropic oxide]

this all means, coming back to the equation you had started with,

that the left-hand side is always not equal to the right-hand side mod 4

[crimson sedge]

so y can not be an integer

[tropic oxide]

weird way of putting it but yes

[crimson sedge]

which is a contradiction

but i have one question

why did you choose mod 4?

[tropic oxide]

there are not many quadratic residues mod 4

sometimes taking things mod other numbers works

4 also has the benefit of making the 12x^2 term vanish, and generally it's better if there's less things to worry about

[cedar kiln]

@crimson sedge Has your question been resolved?

[jaunty mural]

to show a Diophantine eq has no solutions, one method is showing LHS =/= RHS in some base (modulo)

You might try something small to try solve it --- 4 looks like a sensible one to try

[crimson sedge]

what does that mean?

i still dont understand why not another number

[tropic oxide]

a quadratic residue mod m is a number which is congruent mod m to a square

i had you verify that the only quadratic residues mod 4 are 0 and 1

4 just happens to work here tbh

there's no deeper reason

i think i remember seeing some equation where mod 5 worked nicely

tbh you can sort of consider mod 4 as a kind of step up from parity

[crimson sedge]

ok

so i would just have to try out numbers

[tropic oxide]

perhaps

[crimson sedge]

in my solution

do i have to explain why i chose mod 4?

or just outright go into doing the left side mod 4

[tropic oxide]

no

[crimson sedge]

ok

[tropic oxide]

choices like htis require no explanation

[crimson sedge]

ok

Let’s assume that x and y are integers. We can start by writing the left side mod 4, which is 2. Now we have 2=y^2 mod 4. Since y is an integer, every square of an even integer mod 4 is 0, and for every odd its 1. (Reasoning: (2k)(2k)=4k^2. (2k+1)(2k+1)=4k^2+4k+1). 
    This means that the equation can be 2=0 or 2=1, which are false statements, and we run into a contradiction. Which means that y can’t be an integer.

is this fine?

[tropic oxide]

no

but i'm not going to fix it

[crimson sedge]

ok

[crimson sedge]

i wasnt expecting you to

i just want some feadback

i will fi it myself

[tropic oxide]

i cannot give any constructive feedback.

[crimson sedge]

how about some vague feadback

[tropic oxide]

you want vague feedback? fine, have some vague feedback

basically every sentence sounds way off

[cedar kiln]

@crimson sedge Has your question been resolved?

[crimson sedge]

hmm.

o wel

.close

[cedar kiln]

Channel closed

Closed by @little wave

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[terse oak]

A box open at the top has a rectangular base 200mmx300mm and an
altitude of 150mm. If the base and the sides are 10mm thick, find the total
surface area of the box.

[terse oak]

So am I supposed to add 10mm to the altitude and also add 20mm on 200 and 300 mm?

[jaunty mural]

draw a picture of the box

[cedar kiln]

@terse oak Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[keen olive]

Can someone suggest me a good ressource where I can learn how to transform formulas?

[keen olive]

like if I have 2*n = 30 - how to get 2 alone and bring n to the other side

pretty basic stuff

[dense wing]

divide both sides by n

but idk why you'd isolate for 2 and not n, the variable

[keen olive]

So if I want to get 2 to the other side I have to divide by 2 and also If i want to bring n to the other side?

so I have +2*n = 30

[cedar kiln]

@keen olive Has your question been resolved?

[fossil nebula]

U may use log…

[cedar kiln]

Channel closed

Closed by @keen olive

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rapid maple]

How should i calculate the MacLaurin polinomial (4th degree) of this function? I already tried to derivate it but i gave up considering the second derivative was already like two line longs

[cedar kiln]

@rapid maple Has your question been resolved?

[rapid maple]

<@&286206848099549185>

[jaunty mural]

call the exponent u

or something

but you're going to have to differentiate it

[keen elbow]

let u = tan^2(x)+1

then take derivative of that until the fourth

[rapid maple]

Ok, thank you, then its just long

.close

[cedar kiln]

Channel closed

Closed by @rapid maple

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[earnest grove]

Is d^2y/dx^2 correct?

I'm confused on how to implicitly differentiate cos x (dy/dz)

[jaunty mural]

might be able to help

what exactly are you stuck on

[earnest grove]

So I'm applying product rule to differentiate cos x(dy/dz)

[jaunty mural]

with respect to x?

[earnest grove]

Yes

[jaunty mural]

ok

[earnest grove]

So I wrote cos x down

And I'm trying to differentiate dy/dz

[jaunty mural]

1 sec

[earnest grove]

Okay, thanks

[jaunty mural]

$$\frac{d}{dx}\left(\cos x\frac{dy}{dx}\right)$$

[wraith dagger]

Shuri2060

[jaunty mural]

$$\frac{d}{dx}\left(\cos x\frac{dy}{dz}\right) = \cos x\left(\frac{d}{dx}\left(\frac{dy}{dz}\right)\right) + \left(\frac{d}{dx}\left(\cos x\right)\right)\frac{dy}{dz}$$

[earnest grove]

I understand that

But it's cos x (dy/dz)

[jaunty mural]

typo

ok so you have this?

[wraith dagger]

Shuri2060

[jaunty mural]

The right term you are ok with?

[earnest grove]

Yes

[jaunty mural]

$$ \frac{d}{dx}\left(\frac{dy}{dz}\right)$$

[wraith dagger]

Shuri2060

[jaunty mural]

this is actually just

$$\frac{d^2y}{dxdz}$$

[wraith dagger]

Shuri2060

[earnest grove]

Right

I'm not really sure what to do with that

[jaunty mural]

No, that's the answer

You can't really do much with that unless you have more information

[earnest grove]

But their answer is this

[jaunty mural]

that just means differentiate y wrt z, then again wrt x

[jaunty mural]

Because of more info

ah i see, you have z = sin x

[jaunty mural]

so with this, figuring out something about dy/dx or dy/dz would help

which is what they do

$$\frac{d^2y}{dxdz} = \frac{d}{dx}\left(\frac{dy}{dz}\right) = \frac{d}{dz}\left(\frac{dy}{dx}\right) $$

[wraith dagger]

Shuri2060

[earnest grove]

Yeah

That's exactly what I just wrote

Now i feel stupid for not rewriting it like how you just did

🤦‍♂️

Thank you so much

[jaunty mural]

👌

[cedar kiln]

@earnest grove Has your question been resolved?

Channel closed

Closed by @earnest grove

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed due to the original message being deleted

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[main belfry]

how the hell do u solve this

[main belfry]

i dont even know where to start

[jaunty mural]

you have a quadratic in cot theta

[main belfry]

oh

ohh

my god

💀

ok got the answer thx @jaunty mural

.close

[cedar kiln]

Channel closed

Closed by @main belfry

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[main belfry]

how

[tight tusk]

Lol?

[main belfry]

Not an answer option

Someone explain how to do this please

I dont know how to deal with that square root

[sick ruin]

@main belfry factor out the sin

[main belfry]

-sin?

[dense wing]

this too, is a quadratic in sin(t)

[main belfry]

do i factor sin or -sin

[sick ruin]

Probably -sin would be better

[wary nexus]

How could you solve $0=-\sqrt{3}x-2x^2$?

[dense wing]

either or, but -sin(x) is the larger common factor

[wraith dagger]

ddxtanx

[dense wing]

they know how to solve it.

[main belfry]

rewrite it and complete the square

[sick ruin]

Bruh

[wary nexus]

Sure! Then i’d recommend looking at how that equation relates to yours and go from there!

[sick ruin]

Completing the square would be tedious and ugly

If you factor out sin, you’re good

[wary nexus]

It would tbh, but hey if thats a method they’re familiar w/ then it is what it is

[sick ruin]

But you’re free to do whatever you find easiest

[main belfry]

ok

so i factored -sin

[sick ruin]

So what do you have now

[main belfry]

bro wtf did i just do

[sick ruin]

What lol

[main belfry]

ok

so i did it properly now

-sintheta(square root of 3 + 2sintheta)

=0

@sick ruin @wary nexus

[sick ruin]

$$-\sin\theta(\sqrt 3 + 2\sin\theta)= 0$$

[main belfry]

yes

[wraith dagger]

abs_0

[sick ruin]

Ok nice

[wary nexus]

So what does $\sin(\theta)$ have to equal?

[wraith dagger]

ddxtanx

[main belfry]

0

wait

-sintheta = 0

[wary nexus]

Thats one option, how do u know it should be that?

[main belfry]

and square root of 3 + 2sintheta = 0

[wary nexus]

Eeee exactly

Go from there my dude u got this

[main belfry]

ohh

square root of 3

im seeing something here

yep

got the answer

thx guys

.close

[cedar kiln]

Channel closed

Closed by @main belfry

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[civic monolith]

This is a practice problem. I'm asked to simplify the problem at the top. I understand that I need to get the numbers in the radicals to be the same (9 in this case) but I have no idea how to actually do it. What steps are taken here?

[livid hound]

$\cbrt{ab} = \cbrt{a}\cdot \cbrt{b}$

[wraith dagger]

ℝamonov

[livid hound]

identify perfect cube factor(s) and apply that to simplify

[civic monolith]

I guess its the coefficients that's confusing me. I can't even picture the first step to take. It doesn't even seem like anything that I've read in my chapter relates to the problem. I can't understand how 3(3rd root of 9,000) simplifies to 30(3rd root of 9).

[livid hound]

focus on the cbrt

are you able to simplify cbrt(9000)

[civic monolith]

I'm not sure why this has my head so messed up, I feel as if I've just tried to read hieroglyphs. Thanks for the help, I'm just going to have to move on for now and skip this. Too much else to do to get hung up at the moment.

.close

[cedar kiln]

Channel closed

Closed by @civic monolith

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

Can anyone help with Q2 pls

[cedar kiln]

@crimson sedge Has your question been resolved?

[crimson sedge]

There's a way to show that using properties of probability, and a way to show it basically by definition of probability. Are you close to finding either one?

What are your thoughts so far?

[crimson sedge]

Alr so I used a sample space diagram to find the probability of getting a sum of 4

I'm just confused on how to find the probability of the same number

I tried using a tree diagram, where 1/6 is a number when when rolled again 1/6 is the same number

So multiplying them gave 1/36

Which was wrong

So I'm pretty much suck there

Maybe you've seen this but here's an equivalent definition of probability for a finite event space
In a set of N equally likely occurrences, the probability of any event A, where we will use the same name A for the number of equally likely occurrences that produce A, is A/N

[dense wing]

Show that there is an outcome shared b/w the 2 events

namely, find said outcome

[crimson sedge]

So you can show it's not mutually exclusive by just showing the set "rolls of two dice that produce a score of 4" and the set "rolls of two dice that have the same number" have a common element

[crimson sedge]

Aren't they supposed to be different

If they're the same I dont think they're mutually exclusive

I mean that's what the ms says, it shows that they're different

those sets of outcomes are different, but if they have a common element, then the events they represent are not mutually exclusive, correct

You are trying to show lack of mutual exclusion, not that they are mutually exclusive

OHHH

I misread it

Yh mb

I get what your saying

But I'm still confused on how to find the probability of the same numbers

Just as like, a side thing?

Cool yeah

[crimson sedge]

Yeah

So for the probability of equally likely rolls of two dice where you have a sum of 4, there's one of 2+2, 1+3, and 3+1 that's 3 equally likely occurrences so you would get 3/36 unless I'm buggin hard
For two rolls of equal value you have 1+1,...,6+6 pretty obvious the probability is 6/36

[crimson sedge]

Ahhh I see what u did

I only looked at it once, like 4 and 4 so I said 1/36

So u gotta look at all the possibilities?

well yeah the first event was "rolls that give you a sum of 4"

there's more than one occurrence where that happens

[crimson sedge]

Oh I mean the same number

I took one number that rolled twice

Instead of taking all 6

ohh I see how you misread that yeah, like "the same number" being the same number as in the first part of the sentence xD

[crimson sedge]

So how would we show there's a common element, because 3/36 and 6/36 arent the same?

[crimson sedge]

Yeahh

[crimson sedge]

hmm well we already did it in a much easier way, but if you want to do it only using these properties, well you can add probabilities of mutually exclusive events together when you look at the probability of either of them or both happening

Like if you wanted to see the probability of me getting a heads or the probability of me getting a tails, I would add the two probabilities since that's the same as adding the number of cases where they occur, and then dividing by the total number of cases

Ohhh so by adding them, I get the common element?

So here you would suppose purposely, for sake of contradiction, that "same number rolls" and "rolls that sum to 4" are mutally exclusive. Then you have 3+6 events for "rolls that sum to 4 or same number rolls." so now your probability is 9/36

nonono this is all for sake of contradiction

since they aren't really mutually exclusive

it's like making an argument showing that the earth is round by first assuming it's flat, and showing that something is wrong because of that assumption

lmk if I lost you anywhere before I keep going

Nah its fine so far

Ok, so we have "fake proven" so far that 9/36 is our probability of "rolls sum to 4" and "rolls are same"
Now 36/36 - 9/36 = 27/36 rolls are neither of these. So then there are 27 rolls that neither sum to 4 nor are the same

We can check that this is false, and then we are done

The wrong thing about the 9 cases is that actually by adding 3 and 6, we double counted the case of the 2+2 roll. So really it's just 8 cases, and we would be missing an extra roll in those other 27

[crimson sedge]

You lost me here but keep going

Basically if you ended up looking at all of them, you would find 28 total rolls that neither sum to 4 nor share the same face

[crimson sedge]

we added 3 cases where "rolls sum to 4" and 6 cases where "rolls share the same value"

which was incorrect, because there is one thing that is the same in both

[crimson sedge]

Ohhh yh

like if I concatenate the lists {Mario, Luigi} and {Luigi, Daisy} you get
{Mario, Luigi, Luigi, Daisy}

and saying "there's 4 unique mario characters in my list" would be inaccurate, because we forgot to ask whether the lists were mutually exclusive

[crimson sedge]

Ahh true

So what I'd say is that 9/36 is common in both so they are not mutually exclusive?

What does "9/36 is common in both" mean? I'm confused

9/36 isn't one of those events, 9/36 was the probability I calculated wrong on purpose when you add the probabilities of the two events

[crimson sedge]

Wait so we are kinda doing proof by contradiction?

yes that was one other way to show that those events were not mutually exclusive

[crimson sedge]

So it would be 8/36?

the probability of ("rolls summing to 4" OR "rolls with same value per roll") yeah

So the reason its 8/36 is because we counted the 2+2 twice?

yes, and that also 2+2 is the only common element between those sets

[crimson sedge]

OHHH

just like how the two earlier lists with two elements gave us a list with 4, but the number of unique mario characters was really 3

It was because one and only one character was common between them

Alrr that makes much more sense

Thank you so much

Helped a lot

🙏 I'm so glad!

.close

[cedar kiln]

Channel closed

Closed by @shrewd spade

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sudden lance]

confused because i can do it with ln

but no tlog

[cunning quail]

what's your function with ln?

[fading narwhal]

You can use the change of base formula to get it in terms of log(x)

[floral thistle]

just ln both sides to get y = something

and manipulate as needed

[sudden lance]

yeah so i get y = 2ln(x)+ln(3)+10x^5

no log though

[floral thistle]

log sometimes means ln

[cunning quail]

sure, are you aware of how to change the base of a logarithm?

[floral thistle]

oh wait

[cunning quail]

log sometimes means ln

this too

[floral thistle]

yeah never mind this fact isn’t necessary

[cunning quail]

maybe double check that

[floral thistle]

well

yeah

well anyways, you can use $\log_a(b) = \log_{a^c}(b^c)$

[wraith dagger]

quantum

[floral thistle]

although that would be quite ugly

[cunning quail]

ooh- I've always seen it written as $$\log_{a}b=\frac{\log_{c}b}{\log_{c}a}$$

[floral thistle]

oh yeah that works too

[wraith dagger]

dino dik

[cunning quail]

latex is hard

[floral thistle]

lol

[sudden lance]

thx\

wait would i get

y = 2(logx)/log(e)+log(3)/log(e)+10x^5

@cunning quail

[cunning quail]

assuming what you said earlier was right, yeah that looks good

but I must say it looks much nicer with ln, are you sure you're looking for log base 10?

[sudden lance]

yea its a problem i made up jst wanted to undersamd how to do it

[cunning quail]

ah I see

[cedar kiln]

@sudden lance Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sudden lance]

i know how ot integrate

buit what is the cumulative functin

[bright surge]

call the cumulative function c(x). then, c(x) = integral from 0 (in this case) to x of f(x) with respect to x

wait a second i just realized that that's the exact same thing they said in the prompt

[sudden lance]

im confused srry

[bright surge]

the cumulative function is like the indefinite integral

without the constant

[sudden lance]

oh so isnt it obvious

since we dont care about when x is less than 0

@bright surge

[dense wing]

cumulative function is defined though...?

like, the definition is on your screenshot

[bright surge]

yeah, the function said that f(x)=0 for x<0

[dense wing]

formally from probability, the cumulative density function is $F(x)=P(X\leq x)$

[wraith dagger]

Mosh

[dense wing]

which intuitively is the sum of all the probabilities P(X=a) for a between 0 and x

and the continuous sum is a definite integral

[sudden lance]

so is it just f(t) = -e^-5x ? @bright surge

[bright surge]

uhhhh
no

that's the indefinite integral

here the cumulative function's value should be 0 at x=0

[sudden lance]

so im taking the defininte integral of -e^-5x over the bounds given

0 to infinity

[dense wing]

no

from 0 to x

per the definition

$F(x)=\int_0^x 5e^{-5t}\dd{t}$

[wraith dagger]

Mosh

[sudden lance]

ahhhh

got it sorry for taking os lol

long

[cedar kiln]

@sudden lance Has your question been resolved?

Channel closed

Closed by @sudden lance

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sudden lance]

last question sorrry yall

[sudden lance]

i need help expanding a summation

i have the sum of e^ax from x = 1 to n

wouldnt this just expand to e^a+e^a2...+e^an?

what more can i do here

[dense wing]

e^(ax) or e^ax?

[magic bough]

If its xe^a then yeah.. Just an AP

If e^(ax) then just a GP

What is it? @sudden lance

[cedar kiln]

@sudden lance Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[sudden lance]

E^(ax)

.reopen

[cedar kiln]

✅

[sudden lance]

Sorry for late response

[magic bough]

Cool so its a GP

No prob

You can add GP right?

[sudden lance]

whats gp? @magic bough

[dense wing]

geometric progression

but you have $\sum_{i=1}^n (e^a)^x$

[wraith dagger]

Mosh

[sudden lance]

yes so?

[magic bough]

yeah it is e^a + e^2a+e^3a

+...+e^(na)

Makes sense

This is a GP

There is a formula for addition of GP series

Have a read @sudden lance sum of GP is most relevant

https://byjus.com/maths/geometric-progression/

[sudden lance]

ok

but why does it say it can be simpifed to (e^a-e^((a)(n+1))/(1-e^a)

@magic bough

[magic bough]

Because thats the formula of summation of GP

Have a reas at the article I sent you

See the section "Sum of GP"

*read

Also make sure you understand what GP is

[sudden lance]

ok thanks 🙂

so its polynomial long div

[magic bough]

Usually one remembers
the formula of GP since its a very fundamental series

[sudden lance]

[cedar kiln]

@sudden lance Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[sudden lance]

how cna i solve for g here

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sudden lance]

is there an intuitive way to do this

[magic bough]

g is constant?

I mean

Being multiplied to the term?

Man write this on paper or latex please

[glad kestrel]

$\sum_{i=1}^{n}{h^2x_i}=\sum_{i=1}^{n}{gx_i^2}$

[wraith dagger]

a disappointing son

[glad kestrel]

this is what i interpret from that

but i have no idea what you're supposed to do with this information

[magic bough]

There is a middle one as well

2 equal signs right?

[glad kestrel]

that's part of the i = 1

[dense kayak]

are h and g funcs?

[magic bough]

Wow so much confusion

So less solution

[cedar kiln]

@sudden lance Has your question been resolved?

[sudden lance]

Yes exactly that

Sorry guys for the late responses

Wait I’m so dumb

I got it

[cedar kiln]

Channel closed

Closed by @sudden lance

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson obsidian]

Where do you face problem here?

Equal sides in a triangle has equal base angles

[crystal scarab]

yeah it seems pretty straight forward

[floral thistle]

pretty sure opposite angles here add to 180

[crystal scarab]

x+50+50=180

[livid hound]

do you know what those markings indicate

[crimson vigil]

we do not need to use that property here

[crystal scarab]

100+y+y=180

[crimson vigil]

just use y + y + 100 = 180

yeah

[floral thistle]

oh darn i didn’t even realize that somehow

[cedar kiln]

Channel closed

Closed by @mild thunder

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[floral thistle]

<@&268886789983436800> user seemed to be getting help on a test

[floral thistle]

.close

[cedar kiln]

Channel closed

Closed by @floral thistle

Use .reopen if this was a mistake.

[floral thistle]

.

oh gosh that pinged them

[crimson vigil]

we already helped them I think

\

[ripe stone]

GUYS

HELP ME

PLS

[floral thistle]

#❓how-to-get-help

[ripe stone]

ITS NOT OF QUANTAM BTW

IM 13

BUT

[crimson vigil]

A = bh

h = A/b

and then do the math?

[ripe stone]

my one?

[crimson vigil]

yes

[ripe stone]

bh?

area

ye

area = b*h?

h= a/b?

@crimson vigil u sure

[crimson vigil]

yes

actually wait no

[ripe stone]

so 14 divde

by

126

[crimson vigil]

no no i had a brain fart

[ripe stone]

CONFIRM pls

[crimson vigil]

wait

A = 1/2 * b * h

[ripe stone]

ok

yes ik tht

[crimson vigil]

so h = 2 * A / b

then do the math?

[ripe stone]

ok

h = 2 * 126/14?

@crimson vigil confirm right?

?

[crimson vigil]

yeaaaa

[ripe stone]

?

ok

[crimson vigil]

just do it already

.close

[floral thistle]

i closed the channel, should become available any second now

[ripe stone]

thx

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ripe stone]

this

uh

its easy i just have to multiply then add the exponents right?

full form

<@&286206848099549185>

im stuck

[crystal scarab]

(23^2)^8=2^16

did u get how??

[ripe stone]

no

thts the full question

im getting 23 rasied to power 36

ik

im just confirming

[crystal scarab]

by the identity (a^b)^c=a^bc

so 23^16 cancels out

so the answer is 23^4

[ripe stone]

Oh wait

I forogt

its

divide

sorry

yup thx

thts easy

can u also solve this

its a bit hard

[crystal scarab]

6x*5x=27000

[thick blaze]

Is it an exam?

[crystal scarab]

yeah is it??

[ripe stone]

homework

i tried before

but could not get

[thick blaze]

Okay

[ripe stone]

these sUMS

oh ok

uh yes but dont close channel pls

i need tro understand answer

ok

one more sum

i will just show u

bruh she added another assignment

this is hard

wow ur fast

yes this actually is easy

thx lemillion

thxx

i can solve the others

dont close channel

[cedar kiln]

@ripe stone Has your question been resolved?

Channel closed

Closed by @ripe stone

Use .reopen if this was a mistake.

[ripe stone]

.close

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed by @true summit

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[royal musk]

Suppose two teams play a series of games, each producing a winner and a loser, until one team has won two or more games than the other. Let G be the number of games played. Assume each team has a chance of 0.5 to win each game, independent of the results of the previous games.

(a) Find the probability distribution of G.

I got that $P(G=2n)=2^{n-1}(0.5)^{2n}$
Working: G can only take even numbers cause we need a team to have won 2 or more games than the other. So G=2 when the first two games are won by a particular team, so $p=(0.5)^2$. So basically the last two games must be winning for a particular team and rest should have resulted in a draw. So for G=4, we have two cases: (for particular team) WLWW or LWWW, so probability this happens = $2(0.5)^4.$ Similarly for G=6 we can basically insert WL or LW in between the ones we got in the previous case and it'd be WLWLWW, WLLWWW, LWLWWW, LWWLWW,so $p=4*(0.5)^6$

Is there anything wrong that I'm doing (because I found a source having a different answer)?

[wraith dagger]

Schrödinger's cat

[cedar kiln]

@royal musk Has your question been resolved?

[royal musk]

.close

[cedar kiln]

Channel closed

Closed by @royal musk

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cosmic fox]

How do i put this into an equation "A side in a rectangle is 3 cm shorter than the other side. If every side is made 1 cm longer then the area will be 18 cubic cm larger. How long are the sides in the original rectangle

[cosmic fox]

ive tried (x+1)(x-2)=x^2+18

<@&286206848099549185>

[regal oak]

area is not x^2

area is x(x-3) right ??

[cosmic fox]

ohhhhh

thanks

[regal oak]

np try it any doubt let me know

[cosmic fox]

it worked, thanks

.close

[cedar kiln]

Channel closed

Closed by @cosmic fox

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frigid coral]

Hry

[frigid coral]

So let's say I got (2x+3)²

What's the method to work it quickly for exams

Without doing (2x+3)(2x+3) etc

[crimson sedge]

How so

What is your purpose exactly

[frigid coral]

Basically to not waste time in exam

Wanted to know if anyone has some short cut method

[crimson sedge]

As a university math student even we still sometimes have to multiply them

Like if we got (2x+5)(5x-7)

We just do four multiplications

I don't think there is another way

[frigid coral]

Ah

Alright thank you

Do you know what they are called? When you have stuff like (4x+3)² is there some specific name

[crimson sedge]

Factoring out?

My native language is not english tho

[frigid coral]

Alright ill check it out, same here I'm from malta but your English is good

[crimson sedge]

(x+y)^2=x^2+2xy+y^2

You might be asking this

[crimson sedge]

I am not used to terminology

[frigid coral]

Yes that method

[crimson sedge]

Oh okay

I don't know it's name sorry

[frigid coral]

It's alright s

So step 1 would be to square x

Alr got it

Ty

[crimson sedge]

Np

[frigid coral]

.close

[cedar kiln]

Channel closed

Closed by @frigid coral

Use .reopen if this was a mistake.

[crimson sedge]

I found this

Anyways

[frigid coral]

That helps alot

Thank you

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[floral hedge]

Hi

[floral hedge]

I have one question

Why does the fundamental principle of counting for permutations works?

I was amazed when I saw it

How ?

Just by doing that you have n choices and r ways to arrange

It goes n (n-1) ....(n-r+1)

[jaunty mural]

whats the principle?

[floral hedge]

Fundamental principle of multiplication

If there are n choices

And r ways to arrange

P = n! / (n-r)!

[jaunty mural]

do you remember the question you asked before?

i think the explanation is similar

last time it was n!/r!

right?

[floral hedge]

Yes

But how does fundamental principle works

[jaunty mural]

let me think for a sec

well actually

have you heard of combinations

[floral hedge]

Yes

[jaunty mural]

or are u not there

so n choose r

[floral hedge]

What

[jaunty mural]

ok maybe not yet

probably next section

its how to count for example

how many ways of choosing 5 books from 9

[floral hedge]

Yes

[jaunty mural]

i dont care about the order of my 5 books

and all 9 are distinct

then the answer is 9 choose 5

$$9!\over5!(9-5)!$$

[floral hedge]

Math tells that 98765

[wraith dagger]

Shuri2060

[jaunty mural]

maybe this is the next topic for u

[floral hedge]

What

[jaunty mural]

😅 ignore that for now haha

[floral hedge]

Okay

[jaunty mural]

back to this let me think of explanation

[floral hedge]

Okay

[jaunty mural]

is easier for me if we have concrete example

do you have?

[floral hedge]

Yes

I have 3 balls

Distinct

[jaunty mural]

🔴 🔵 🟡

[floral hedge]

🏀 ⚽⚾

Find all the combination

[jaunty mural]

surely that doesnt correspond back to what u said?

unless im missing something

You said n choices, r ways to arrange

[floral hedge]

Yes

3 choices

[jaunty mural]

n!/(n-r)!

[floral hedge]

Yes

[jaunty mural]

whats r

[floral hedge]

Ways to arrange

[jaunty mural]

🤔

[jaunty mural]

so whats r here

maybe 5 balls is better

[floral hedge]

No of ways to arrange

Okay

[jaunty mural]

because im pretty sure this boils down to the same problem as before

[floral hedge]

Yes

But is there a intuitive Explanation

I don't want to think from formulas

They can be easily derived once it's intuitive

[jaunty mural]

yes

[floral hedge]

Yes

[jaunty mural]

1 sec

[floral hedge]

0

1

Times up

lol

[jaunty mural]

so you have n objects

[floral hedge]

Yes

[jaunty mural]

and you choose r of them

[floral hedge]

Yes

[jaunty mural]

and the point is that order matters

so if we have 5 balls

[floral hedge]

Yes

[jaunty mural]

1 2 3 4 5

we have 135, 531, 245 as examples

[floral hedge]

Yeah

[jaunty mural]

well one way to think about it is

to choose the balls one at a time

so your first choice there is 5 to pick from

your 2nd, 4

[floral hedge]

Then ,4

[jaunty mural]

and 3rd, 3

[floral hedge]

Then 3

2

1

[jaunty mural]

so its 5*4*3

[floral hedge]

Why multiplication

[jaunty mural]

uhh

[floral hedge]

I got it

[jaunty mural]

copying

oh u got it?

[floral hedge]

Yes

[jaunty mural]

🔴 🔵 🟡 🟢 🟣

yh ok i was gonna try to demonstrate

but they multiply

[floral hedge]

Yes

For every choice

You can choose from rest of the choices

[jaunty mural]

yh

[floral hedge]

That's why

[jaunty mural]

its like picking one at a time

[floral hedge]

Yes

Do you like programming

[jaunty mural]

i do yes

[floral hedge]

Great

Programming helps apply math

And understand well

And understanding math is understanding patterns and symmetry

Majority of Universe is patterns

So you understand the Universe

[jaunty mural]

lol ok

[floral hedge]

lol

.close

[cedar kiln]

Channel closed

Closed by @floral hedge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

divergent series?

i dont quite understand

i mean i know that means it goes off

gets bigger and bigger?

[willow island]

meaning it won't converge to a specific digit when taking the limit to infinity

[crimson sedge]

how exactly are you meant to know if it will?

[willow island]

taking the limit

[crimson sedge]

#❓how-to-get-help and also helping in tests is against rules

[crimson sedge]

how are you supposed to do it in this case?

or are you just meant to imagine taking the limit

im still a little confused e.g

[crimson sedge]

oh so its just like

1^n

oh wait it can equal 1

ok so if its bigger than 1

then its diverging

[willow island]

left is a convergent series, right divergent

[crimson sedge]

if it was 0.5^n, it owuld be getting smaller alright

what about lower bound

oh wait thats wrong

its not diverging for n^1

whats it called? because its just staying the same right?

already converged?

[willow island]

iirc if the limit is not infinite

not sure though one sec

just if the term

[willow island]

if L is a specific number

here

https://youtu.be/lfZGtjSWcQs

@crimson sedge

[crimson sedge]

thanks ill check it out

just need to do something irl rq so ill check it out in like 10 15 mins thanks

[willow island]

good luck

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

@crimson sedge Has your question been resolved?

[crimson sedge]

sorry this is still open i dont wanna close it just yet busy rn ill watch the video and finish off in not long

[crimson sedge]

.close

[cedar kiln]

Channel closed

Closed by @wraith onyx

Use .reopen if this was a mistake.

[crimson sedge]

.reopen

[cedar kiln]

✅

[crimson sedge]

oh sorry mb

(i have re opened this, but im just looking for the mark scheme to the original question one sec)

i actually cant find it for the life of me

if i remember correctly

for part i

for some reason, b can equal -1

how does that work?

wait maybe i get it

it can't equal 1

but it can equal -1

thats my problem

is it because its already converged at 1?

[elfin hemlock]

(-1)^n={-1,1,-1,1,-1,…} so divergent

[crimson sedge]

so 1

1 is like

instantly converged?

is that why u dont include 1?

[elfin hemlock]

Because 1^n converges?

[crimson sedge]

does it 'instantly' converge

because

its not going towards a value, it just stays at the value its at

so i wanna make sure that im understanding it right

[elfin hemlock]

“Instantly converge” isn’t a thing

[crimson sedge]

so if it just stays at its value

from the start to infinity

that counts as a convergence, right?

so n = 5 converges?

[elfin hemlock]

Yes ofc? (Maybe recheck definition if unsure)

[crimson sedge]

thats where my slight issue is

because it says it gets more and more closely

but if its at the value and stays at the value

my problem is just that is it still count as converging

[elfin hemlock]

Thats not a definition (at least not a formal one)

[crimson sedge]

but after seeing what you said, im guessing it does

[elfin hemlock]

Find a proper definition

[crimson sedge]

this?

[elfin hemlock]

Also not a definition

[elfin hemlock]

Yes

[crimson sedge]

so its convergent if

[elfin hemlock]

If (x_n)=1 for all n then |1-1|=0<epsilon

Is certainly true

[crimson sedge]

uhhhhhhh this definition is hurting my brain but ig ill just watch a video if the definition is my problem

but if n = (any integer) counts as a converging series

then i guess my question is answerd

[elfin hemlock]

Series and sequence not the same thing

[crimson sedge]

i definitely do not know the difference

[elfin hemlock]

And idk why you are using n when you mean a sequence like (a_n) or (x_n)

[crimson sedge]

because i absolutely did not know there was a difference lol

i have noted to myself that i need to find out the difference and watch a few videos on this topic lol

thanks

.close

[cedar kiln]

Channel closed

Closed by @wraith onyx

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[regal ibex]

i just got this question wrong in a test.. can somebody help me understand

[floral thistle]

,w x^2-5x+6 = 0

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by quantum#6320

[floral thistle]

weird

that should be right

[livid hound]

nope

[floral thistle]

wait

[mighty drift]

Notice that f(3)=0

[floral thistle]

oh yeah

[livid hound]

you can't blindly set the denom to 0 and ignore the numerator

[floral thistle]

the top is 0 at 3

[livid hound]

that only gets you locations that are undefined, which may or may not be asymptotes

(you need to consider potential holes)

<@&268886789983436800>

[calm sierra]

ty

[cedar kiln]

@regal ibex Has your question been resolved?

Channel closed

Closed by @regal ibex

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rugged cedar]

https://i.gyazo.com/d7d1f0b5e3329f2904e2605d8eb2c193.png

Hello, may I ask a simpleish question I think? I'm not a mathematician and it's late I'm confused.

I am creating a clock. Notice it is half past 10 however the hour is exactly pointing at 10pm. I need it to point at 10 and a half pm.

My current code is:

(360 / 12 * THE_HOURS) degrees

(THE_HOURS is from 0 - 23)
(THE_MINUTES is from 0 - 59)
(THE_SECONDS is from 0 - 59)

[rugged cedar]

.close

[cedar kiln]

Channel closed

Closed by @rugged cedar

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[solid sleet]

I know subset is an antisymmetric relation (https://proofwiki.org/wiki/Subset_Relation_is_Antisymmetric), but is proper subset an antisymmetric relation? I am assuming No and trying to write a proof by contradiction with the first def of antisymmetry on proof wiki (https://proofwiki.org/wiki/Definition:Antisymmetric_Relation) but im not really sure where to go assumption wise right after asserting subset is antisymmetric relation

[proud barn]

Can you ever have two sets being proper subsets of eachother?

[solid sleet]

No

So is the antecedent just false

And hence the whole statement vacuously true?

[proud barn]

I might be missing something but I think so

[solid sleet]

Yea i think im barking up the wrong tree by assuming its not, by this argument proper subset is an antisymmetric relation

.close

[cedar kiln]

Channel closed

Closed by @solid sleet

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[slow sparrow]

May I get assistance for the meaning on this question?

[slow sparrow]

Number 8*

<@&286206848099549185>

[jaunty mural]

hmm

rephrase it like this

or wait

ok so (a,b) satisfies the 1st equation

so you can write a relation with a and b

?

[slow sparrow]

What’s that mean? Sorry we just came after break after self teaching so I’m not familiar with that terminology

[jaunty mural]

uhh

i mean since (a, b) is on that graph

you can write an equation with a and b

[slow sparrow]

Ok is there a point in converting it to exponential form?

[jaunty mural]

what youve written will be helpful

but first, you know

y = 5^x

and (a,b) lies on the graph

[slow sparrow]

So if I substitute 0 for the Y in x=5 to the power of y, would the answer be (1,0)

[jaunty mural]

thats not what theyre looking for

What they give you is that

b = 5^a

[jaunty mural]

because ^

$$b = 5^a$$

[wraith dagger]

Shuri2060

[jaunty mural]

with me?

[slow sparrow]

Yep I get it now

[jaunty mural]

next, you can use what you wrote

your new graph is

$$x=5^y$$

[wraith dagger]

Shuri2060

[slow sparrow]

Oh ok thank you

.close

[cedar kiln]

Channel closed

Closed by @slow sparrow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.