#help-13

428200 messages · Page 447 of 429

rustic ridge
cedar kilnBOT
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@rustic ridge Has your question been resolved?

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lean sail
cedar kilnBOT
lean sail
#

<@&286206848099549185>

cedar kilnBOT
#

@lean sail Has your question been resolved?

faint dirge
#

ok so, you have a right triangle

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you want to find the rate of change of the hypotenuse

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one leg is the vertical distance between the radar and the bird (5km)

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the other leg is the horizontal distance between the radar and the bird. After 1/6th of an hour, that's 7km

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$x^2+y^2=z^2$

wraith daggerBOT
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Scythe

faint dirge
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x is the horizontal, y is the vertical, z is the hypotenuse/distance from radar to bird

lean sail
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oh

faint dirge
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with me so far?

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we don't want a distance, we want a rate

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so we differentiate this!

lean sail
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im writing it down

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yes

faint dirge
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$2xdx+2ydy=2zdz$

wraith daggerBOT
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Scythe

faint dirge
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this is still unhelpful, we don't want a change in distance, we want a change in distance over time. so divide by dt (and divide by 2)

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$x\frac{dx}{dt}+y\frac{dy}{dt}=z\frac{z}{dt}$

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ok so, now we have 6 variables

wraith daggerBOT
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Scythe

lean sail
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oh

faint dirge
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we know x: it's 7km after 1/6th of an hour /10mins.

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we know dx/dt: it's 42km/hr

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we know y: it's 5km

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we know dy/dt: it's 0km/hr (constant)

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we know z: it's the hypotenuse of a triangle with sides 5km and 7km (so sqrt74 km)

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$742+50=\sqrt{74}\frac{dz}{dt}$

wraith daggerBOT
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Scythe

faint dirge
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34.1768 km/hr

faint dirge
#

got it?

lean sail
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thank u so much

faint dirge
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glad I could help

lean sail
faint dirge
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I believe so

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I might've read your question incorrectly so

lean sail
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how do I do b

faint dirge
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since you sent the image sideways

lean sail
faint dirge
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well you do the same thing

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you get 0*42+5*0=5*dz/dt, thus dz/dt = 0

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since it's directly over for that moment its rate of change of distance is going from negative to positive, as it approaches and then leaves

cedar kilnBOT
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craggy pagoda
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Im having an issue with a statistics question. I dont know how to attempt it

lethal edge
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what is the question exactly?

craggy pagoda
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its this

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Im not sure how to do the square regression line

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<@&286206848099549185> hi can someone please assist me with this question? :))

cedar kilnBOT
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@craggy pagoda Has your question been resolved?

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@craggy pagoda Has your question been resolved?

cedar kilnBOT
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@craggy pagoda Has your question been resolved?

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@craggy pagoda Has your question been resolved?

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oblique lynx
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@smoky grove Sorry for ping, Ive had to use another channel but this is where it came from

oblique lynx
#

this is from my theses and its a trigonometric series

cedar kilnBOT
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@oblique lynx Has your question been resolved?

cedar kilnBOT
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@oblique lynx Has your question been resolved?

cedar kilnBOT
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@oblique lynx Has your question been resolved?

oblique lynx
#

btw the question is what does the R(C) means

cedar kilnBOT
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@oblique lynx Has your question been resolved?

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crimson sedge
cedar kilnBOT
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@crimson sedge Has your question been resolved?

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tough nacelle
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Can anyone help please?

cedar kilnBOT
tough nacelle
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i think its antiderivatives

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but im not sure how to do it

cinder garnet
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Just keep integrating with taking c into consideration

tough nacelle
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how’d you figure that out😲

cinder garnet
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(B) part is same keep integrating keeping c in consideration

tough nacelle
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ohh i see. Can i ask how you got t^2/2

cinder garnet
tough nacelle
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oh ur rught

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right

cinder garnet
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You may also say it as anti derivative

tough nacelle
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yep

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when u integrate 8, it becomes 8t?

cinder garnet
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Yep

tough nacelle
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ok!

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i understand!! thank u so much!

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Could u help with B in 5 min? ill write A out really quickly

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but it should be the same right

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except its just cos(x)

cinder garnet
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Ye

tough nacelle
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finished it this should look good

cinder garnet
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Yep

tough nacelle
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should i write any integral sign tho?

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or antiderivative

cinder garnet
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You should

tough nacelle
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how would it look?

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i know the integral sign but idk what’d be the top and bottom number

cinder garnet
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Just in case your teacher give marks on formulas you should

tough nacelle
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0 for both?

cinder garnet
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What

tough nacelle
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ill show toy

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you

cinder garnet
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Kk

tough nacelle
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this better?

cinder garnet
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Yep

tough nacelle
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cool!

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so then for b. I start eith cos(x)

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this is the first one how does it look @cinder garnet

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then i do the others?

cinder garnet
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F''(x)=sinx+c
F''(0)=sin0 +c=a
c=a

F''(x)=sinx +a
F'(x)=-cosx+ax+c
F'(0)=-cos(0)+c=b
F'(0)=c=b+1

F'(x)= -cosx+ax+b+1
F(x)=-sinx+ax²/2+bx+x+c
F(0)=0+c=f

F(x)=-sinx+ax²/2+bx+x+c

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Check yourself I gotta go bye

tough nacelle
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ohhh did i go backwards

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gotcha

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@cinder garnet thank u so much!!!

cedar kilnBOT
#

@tough nacelle Has your question been resolved?

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wintry wasp
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Is there a difference between multivariable functions and parametric curves? If so, what is it?

calm sierra
cedar kilnBOT
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@wintry wasp Has your question been resolved?

cedar kilnBOT
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crisp jay
#

how does one go about proving:\ $2k^2 > (k+1)^2 \ \forall \ k\geq 3$ \ Context: this was a proof by induction question but i've got to here

wraith daggerBOT
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i laik turtles

crisp jay
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only use the lhs

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i know it might be something to do with writing lhs as
k^2 + k^2 then changing one of the k's to 2 or 1 so that you can write another inequality expression

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but its not working

cedar kilnBOT
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@crisp jay Has your question been resolved?

dense wing
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You have all k, not all integers k

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Also you don't even need induction

cedar kilnBOT
#

@crisp jay Has your question been resolved?

crisp jay
crisp jay
#

.close

cedar kilnBOT
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crimson sedge
#

hi i was wondering how i should go about to solve this following question: determine the derivative function to the function f. this is my first question of this type and im completely lost

floral thistle
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i assume you’re using the limit definition of the derivative?

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wait

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i don’t think you can do this using the limit definition

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since it’s a fractional power

crimson sedge
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sorry if my english is off, but yes i am if that is the step i do since the exponent isnt an even number i need to find x>0. but now that the equasion it self isnt even im a bit lost

floral thistle
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this is what i mean by the limit definition

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$\lim_{h\to 0}\frac{f(x+h)-f(x)}{h}$

wraith daggerBOT
#

quantum

floral thistle
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are you supposed to use this?

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or use derivative rules

crimson sedge
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no i can send you an example of a previous question

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sorry if its a bit unclear but it should be clear to understand the point of it . in the book it tells me i need to solve the question in this style.

floral thistle
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so you need to use derivative rules

crimson sedge
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yes

floral thistle
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well you can pull out the constant

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and multiply that back in afterwards

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$\dv{x}x^n = nx^{n-1}$

wraith daggerBOT
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quantum

crimson sedge
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okay thank you

floral thistle
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if you’re done, do .close

crimson sedge
#

.close

cedar kilnBOT
#
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misty sedge
cedar kilnBOT
misty sedge
#

currently working it through again. I have expanded and removed the parentheses

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rn I have sin^2(t)=10/23

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to remove ^2 I squared both sides?

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so now I have sin(t)= +/- rad10/23

dense wing
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That would make 4th powers

misty sedge
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sry I mean square root

cedar kilnBOT
#

@misty sedge Has your question been resolved?

bright river
wraith daggerBOT
#

Twentycents

misty sedge
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yesm

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not sure where to go from here

bright river
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Well there is no "simple" answer besides the one that uses arcsinus function

misty sedge
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like this
theta=arcsin rad10/23 ?

bright river
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Yep

misty sedge
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ok simple enough, so I got 41.3

bright river
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The other solution being not of interest here since t>0

bright river
misty sedge
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Okay let me try, I think I already have and it was rejected

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nope got it wrong, I have to include 41.3, 138.7, 221.3, 318.7 etc

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ugh, I fucking hate this prof

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thanks for your help

bright river
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Oooh ok

misty sedge
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in other problems, he'll use the same exact working but we get it wrong if we dont put it like this "41.3deg+360degk" etc

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he fucks us

bright river
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Yeah I guess that would be from that step $\sin(t) = \pm \sqrt{\frac{10}{23}}$ to the next step

misty sedge
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literally no diff in the wording

wraith daggerBOT
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Twentycents

bright river
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You should have included those 360degk indeed
My bad I haven't read the beginning of the question (he asked for solution_s_)

misty sedge
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oh np, not your fault at all. He's the worst prof I've ever had

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appreciate the help

bright river
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Yeah 😅 well next time you'll think about those details 👍

misty sedge
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I did. I even solved it correctly with all the angles before I even posted here. His terrible attention to detail and lack of english is the problem.

cedar kilnBOT
#

@misty sedge Has your question been resolved?

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bronze swan
#

I'm stuck at the first part

cedar kilnBOT
bronze swan
slow shuttle
bronze swan
#

@slow shuttle channel occupied

upper abyss
#

Any thoughts on the question so far?

bronze swan
#

But don't know how to proceed further

slow shuttle
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Not yet

upper abyss
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That doesn't make any sense, it needs parenthesis

bronze swan
#

the braces are implied

upper abyss
#

If that is the case, then you are done

bronze swan
upper abyss
#

Or, sorry it's backwards

bronze swan
#

To be clear, what I got is $\lnot p \lor (q \land p) \lor (\lnot q \land r) \lor r$

wraith daggerBOT
#

Tāhā

bronze swan
#

This is in DNF isn't it

upper abyss
#

You can convert from one to the other using a double DeMorgan's application

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Been a while since I've done it, haha. I suggest Google to get that fully

bronze swan
#

let me try

cedar kilnBOT
#

@bronze swan Has your question been resolved?

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sand jungle
#

How do I solve this problem? I legit have no ideas.

violet flume
#

wow it took me a hot second to decipher this

elder tapir
#

use multiple time thales

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it's just thales and thales and thales all the way

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you know when you got a triangle and a line in it (here DE) if DE||AC then you have basic formula

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like AC/DE = AE/DB =CB/EB

sand jungle
#

.close

cedar kilnBOT
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cedar kilnBOT
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cedar kilnBOT
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cobalt meadow
#

Hi folks. If 2^x = 5, then what is 2^x+2?

cobalt meadow
#

I can't seem to get around to solving this. I'm getting a little confused.

crisp jackal
#

If 2^x = 5 then if we add +2 on both sides we get 2^x + 2 = 5 + 2 = 7 meaning we have 2^x + 2 = 7 ?

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$$ 2^x=5 \iff 2^x + 2 = 5 + 2 \iff 2^x + 2 = 7 $$

wraith daggerBOT
#

mrbrown

cobalt meadow
#

Not that.
Let me write the question rq.

crisp jackal
#

oh lol

#

sorry

cobalt meadow
#

No problem, I was able to get the solution with my calculator but I need to know how I should solve it manually

graceful karma
#

You'd say that like 2^(x+2) catthumbsup

cobalt meadow
#

first time writing maths equations on a keyboard :P

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one of the first anyway

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my bad

graceful karma
#

It's all good

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Do you know log?

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Like logarithms

bright surge
wraith daggerBOT
#

Kanga Gang ¬Sam

bright surge
#

@graceful karma why bring up logs?

graceful karma
#

I mean ig you could do it like that

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But logs are epic too

bright surge
graceful karma
cobalt meadow
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so i've got 2^(2x+2)

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okay let me try the hint differently? sad

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isn't there a specific rule where if the base = base then power = power?

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wait no

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alright i'm lost

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today's not a day for my maths brain WAHH

graceful karma
bright surge
tranquil oracle
bright surge
#

wait no

bright surge
tranquil oracle
#

idk

cobalt meadow
bright surge
#

i mean times

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hint: $a^b \times a^c=a^{b+c}$

wraith daggerBOT
#

Kanga Gang ¬Sam

bright surge
#

this is better

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omg i'm sooo clumsy

cobalt meadow
#

so do i multiply 2^x with 2^(x+2)?

bright surge
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no

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i mean

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let the base be 2

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and you have 2^{x+2}

cobalt meadow
#

yeah i don't get it

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i'm a little slow today sorry

graceful karma
#

$2^{b+c} =2^b \times 2^c$

wraith daggerBOT
#

PapaBread

cobalt meadow
#

got it!

#

it's gonna be 20

graceful karma
#

Indeed

cobalt meadow
#

that got confusing for me

graceful karma
#

I think it was just because the formula was """backwards"""

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You were trying to apply it left to right

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Instead of right to left

cobalt meadow
#

maybe

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alright, thank you guys a lot!

#

i actually wonder what you feel when you see some people struggling at a maths question that you probably consider easy :P

#

thanks again :)

#

.close

cedar kilnBOT
#
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crimson sedge
#

Hiii
I have a question related to the D.I. method
So i have $\int \qty(\frac{e^{-kx}}{x}+\frac{e^{-kx}}{kx^2})dx$

wraith daggerBOT
#

Insert nerdy name

crimson sedge
#

And if you try to integrate with the traditional integration by parts the uv - int u'v one

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Its easily solvable

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Because int u'v of the first integrand is the same as the second so they subtract each other out

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But if I try to do that with the D.I. method its not really obvious at first

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I'd like to know how to spot conditions like that if im not clear with my question then pls ping me

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<@&286206848099549185>

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

crimson sedge
#

.close

cedar kilnBOT
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opaque sluice
#

i need help with calc

cedar kilnBOT
opaque sluice
#

it says Write Eq (3) in terms of A and B to derive Rule (3)

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this is eq:3 cos(a+b)+cos(a-b)=2cosacosb

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this

dense wing
#

A=a+b and B=a-b.

opaque sluice
dense wing
#

yes.

opaque sluice
#

wait there is no working out?

dense wing
#

there is

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you need to know what a and b are to complete the sub.

wraith daggerBOT
opaque sluice
#

it said terms of A and B

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wait, is there a way for me to get the solving, not just the answer?

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Upper

dense wing
#

The solving is just look at what you need the sub to be to turn eqn 3 into rule 3.

opaque sluice
#

what does that mean-

dense wing
#

a and A are different variables.

dense wing
#

????

#

You're in calc and have never done a sub before???

opaque sluice
#

can I upload a document here? maybe itll make more sense

opaque sluice
dense wing
opaque sluice
opaque sluice
#

but calculus is hard fsr

dense wing
#

subbing stuff is an algebra concept

opaque sluice
#

ik its simple my classmates told me

#

but none offered to help

dense wing
#

Yeah part b is literally what I said.

opaque sluice
#

I did b, i had help from someone

dense wing
#

so c is obvious.

opaque sluice
#

i just need to figure out the rest

opaque sluice
dense wing
#

yes

#

just apply part b

opaque sluice
#

oh ok

#

but what about d?

dense wing
#

apply what you just derived..

opaque sluice
#

im gonna be dead honest right now

#

i dont understand ANYTHING youre saying

#

from sub to derive

#

god i hate this

#

how do i close the channel?

#

i dont want to solve this anymore

#

.close

cedar kilnBOT
#
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fierce egret
cedar kilnBOT
quaint otter
#

Bruh

fierce egret
#

Exactly bruh

quaint otter
#

I was here dude

fierce egret
#

It was open man

#

Sorry

quaint otter
#

Issok

fierce egret
#

<@&286206848099549185>

crisp jackal
#

@fierce egret I'd start by summarizing the two fractions on the right hand side into one fraction

fierce egret
#

You need to solve for the one on the right

crisp jackal
#

yeah

#

oh right

#

first get the expression 1/de = .................

#

and then summarize the two fractions

#

and then you can take the reciproce value

fierce egret
#

Don't I have to get common denominators to subtract them

crisp jackal
#

yes exactly! 🙂

fierce egret
#

Basically it becomes this

#

ofc I can factor these

#

But then I don't know how to actually subtract them becuase theres a fraction over a fraction

crisp jackal
#

you can use this $$ \frac{1}{a} = \frac{1}{b}- \frac{1}{c} \iff \frac{1}{a} = \frac{c}{bc} - \frac{b}{bc} \iff \frac{1}{a} = \frac{c-b}{bc} \iff a = \frac{bc}{c-b} $$

wraith daggerBOT
#

mrbrown

calm yoke
#

yoo how do u use texit? do i have to learn how to write in it?

crisp jackal
#

wait a second 😅 we are working on Voximity's problem atm here

calm yoke
#

im relative new here, sorry if its dumb question and not the theme

crisp jackal
#

you can use one of the 'free" help channels

calm yoke
#

yesss okok

crisp jackal
#

🙂

#

@fierce egret I will assume you already got to this part, right? $$ \frac{1}{d_e} = \frac{1}{f} - \frac{1}{d_i} $$

wraith daggerBOT
#

mrbrown

crisp jackal
#

let's summarize the two fractions on the right handside

fierce egret
#

Yeah

#

I have

crisp jackal
#

$$ \frac{1}{f} - \frac{1}{d_i} = \frac{d_i}{d_i f} - \frac{f}{fd_i} = \frac{d_i - f}{fd_i} $$

wraith daggerBOT
#

mrbrown

crisp jackal
#

now let's insert the bad bois 😄

#

$$ \frac{1}{d_e} = \frac{\frac{x^2+2x-3}{2x^2 + 10}- \frac{x^2-9}{x^2+x-2}}{\frac{x^2-9}{x^2+x-2} \frac{x^2+2x-3}{2x^2 + 10}} $$

wraith daggerBOT
#

mrbrown

crisp jackal
#

surely it is possible to simplify this further

#

i am not sure yet but we can try to factorize things, hopefully some terms will cancel out each other

#

no, actually it doens'T look like much will cancel each other out

#

we can try to rewrite it

#

$$ \frac{1}{d_e} = \frac{(x^2+2x-3)(x^2+x-2) - (x^2-9)(2x^2+10)}{(x^2-9)(x^2+2x-3)} $$

wraith daggerBOT
#

mrbrown

fierce egret
#

This is what I got yeah

crisp jackal
#

looks good!

fierce egret
#

Not sure how to simplify much further though

#

I guess that'd juts be the answer

crisp jackal
#

yeah it doesn't look like it can be simplified much further

fierce egret
#

Thanks for your help man @crisp jackal

#

Been struggling on this for a good 2hours

#

😂

crisp jackal
#

no problem :D:D

#

i have similar issues haha, the day before yesterday i was sitting at a problem for 5 hours lol

fierce egret
#

😂

#

.close

cedar kilnBOT
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wet gorge
#

This is a Desmos graphic calculator question. My z_step function contains an action V->V+tA where V is a list, t is a number, and A is a list. This action does not have an error, but it doesn't execute, even if I put it on its own line. I think this is because A is defined as such:

Is there a way to fix this? Link for reference: https://www.desmos.com/calculator/aybjlzytr5

wet gorge
#

If there is another way to calculate acceleration in a way that desmos allows to be used in an action, that would be fine

#

A list that is simply a set of numbers CAN be used in an action, but A is still a list so it should work as far as I know

cedar kilnBOT
#

@wet gorge Has your question been resolved?

wet gorge
#

<@&286206848099549185>

#

😦

calm yoke
#

what was the question ?

wet gorge
calm yoke
#

oh on(

#

sorry i have no clue

cedar kilnBOT
#

@wet gorge Has your question been resolved?

wet gorge
#

I'm assuming I don't ping helpers again?

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@wet gorge Has your question been resolved?

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open cedar
#

how to get from this to that

cedar kilnBOT
open cedar
#

i dont know what they did'

normal wraith
#

add 2 to both sides of the first equation

#

then square both sides

open cedar
#

ok but where does 6x come from

normal wraith
#

,tex $(x^2+3)^2=x^4+6x^2+9$

wraith daggerBOT
#

Brun。

open cedar
#

Oh.

#

thanks boi

#

!close

wet gorge
#

.reopen

cedar kilnBOT
#

@open cedar Has your question been resolved?

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crimson sedge
#

So does anyone know how to find the area and volume of a three sided prisms using the diagonal of the side?

crimson sedge
#

I got 9√3/4 x 6√2. And i do not know how to solve that

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

crimson sedge
#

<@&286206848099549185>

#

lol everyone has got at least 1 answer other than me

crimson sedge
#

<@&286206848099549185>

dense wing
#

No prism with 3 sides exists

crimson sedge
#

yes, a prism with 2 bases and 3 sides

dense wing
#

so a triangular prism.

#

not a "3-sided prism"

crimson sedge
#

Im translating from serbian to english ;-;

#

Sorry bout that

dense wing
#

Ok.. well still not enough info

#

cause you've not given any dimensions.

crimson sedge
#

Ah well i have been waiting for a response

#

so the diagonal of the side is 9 cm

#

like a base side is 3 cm

#

I need to calculate volume and area

#

<@&286206848099549185>

#

Of a triangular prism

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

cedar kilnBOT
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teal thorn
#

Is this true for all A and B if the angles can form a closed triangle?
Is this just implied to be true due to the construction of the triangle?

bright surge
teal thorn
#

let theta 1 be 50 degrees, A be 1, B be 1.5

#

good to know, and thanks for the response, @bright surge

#

.close

cedar kilnBOT
#
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bright surge
#

welp-
for your case, there are no triangles like that(here) (also @teal thorn do you understand why i'm drawing these?)

cedar kilnBOT
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teal thorn
#

I get its not a solid triangle.
Original problem is an offset crank, @bright surge

teal thorn
#

.close

cedar kilnBOT
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hollow basin
#

Hello, I am given the basis (1,1),(1,0)
(or any basis where this is the matrix )
( a a)
(b +1 b )

and I am asked to find a similar basis such as (2,1)’s first coordinate is 0. How do I do this?

hollow basin
#

The correction states that this is just the equivalent of saying that (2,1) is a scalar multiplication of (b+1, b)

#

But it’s like ???

cedar kilnBOT
#

@hollow basin Has your question been resolved?

hollow basin
#

<@&286206848099549185>

cedar kilnBOT
#

@hollow basin Has your question been resolved?

mighty drift
#

The trick would be to notice that (2,1) is of the form (x+1, x) for x=1, and that this can be expressed as (0,0) + (1+1,1) = 0.A + 1.B (with A,B the basis vectors).

Otherwise you can just setup the system: x = 2 = a + b + 1 and y = 1 = a + b, from which the solutions are clear ( (0,1) is solution)

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cedar kilnBOT
dense wing
#

<@&268886789983436800>

cedar kilnBOT
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mental tangle
#

I never got how the square root of 4x^2 is 2x. Why isnt it 4x

dense wing
#

square root of 4 is what?

bright surge
#

do you get 4x^2?

mental tangle
#

No

bright surge
mental tangle
#

Nah

bright surge
#

also, you can use this very handy thing:
$\sqrt{ab}=\sqrt{a}\sqrt{b}$

wraith daggerBOT
#

Kanga Gang ¬Sam

bright surge
#

(both are the positive square root of ab, if you don't believe me, just try squaring them)

#

anyways, for this problem, you must find $\sqrt{4x^2} = \sqrt{4}\sqrt{x^2}$

wraith daggerBOT
#

Kanga Gang ¬Sam

bright surge
#

i hope you can take it from here

cedar kilnBOT
#

@mental tangle Has your question been resolved?

bold vine
cedar kilnBOT
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distant gale
#

Help

cedar kilnBOT
distant gale
upper abyss
#

Do you have a formula for sin(a + b)?

distant gale
#

Yeah

heavy igloo
#

question F please

#

<@&286206848099549185>

#

nvm got it

cedar kilnBOT
#

@distant gale Has your question been resolved?

worldly iron
#

This channel is occupied

#

ask your question somewhere else in the available channels

#

@heavy igloo

cedar kilnBOT
#

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high flare
#

Hey! Anyone able to help me with these 3 questions, been practicing and don't understand these questions:

upper abyss
#

Blocking question 4

#

Or "is parallel to m" I suppose

teal field
#

lol i also need help but i think i can do this

#

lets say 5x+40 + 2x = 180 cus abc is also 5x (corres. angles) and they ar3 linear pair now, x = 20

#

5:
2x+1 = 85 (alternate interior angles)
solve for x
then solve for y since u know 2x+1 is 85 degrees, 180 - 85 = 3y + 5

#

6:
2m = 4m - 120 (corresponding angles)
once u get M, whatever 4m-120 is equals 5n cus vertical angle

#

@high flare

cedar kilnBOT
#

@high flare Has your question been resolved?

high flare
#

Alrighty, Thank you so much @teal field

#

!done

kindred storm
#

@high flare Use .close

#

.close

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#
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round mauve
cedar kilnBOT
round mauve
#

how did my prof manipulate this to amek it like that

#

what's the rule used in here?

south tundra
#

I think he just made common denominators

round mauve
#

really?

south tundra
#

Yeah

round mauve
#

ok i see it now

#

lol it seemed so foreign

#

it must be because of the brackets

#

these square brackets dont mean anything else do they?

south tundra
#

Nope, you can view them as regular brackets

round mauve
#

oh ok thanks

#

also lmaooo i jsut noticed ur nick

#

that's hilarious

south tundra
#

Long story

round mauve
#

haha ok

#

.close

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#
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shell seal
cedar kilnBOT
shell seal
#

Help?

glad kestrel
#

with what exactly

shell seal
#

I don't know how to solve it

glad kestrel
#

are you solving for y

shell seal
#

Both x and y

glad kestrel
#

huh

bold vine
#

System of equations

glad kestrel
#

oh

bold vine
#

Solve for one variable in one equation in terms of the other

prime flint
#

u have 2 variables in 2 equations

bold vine
#

Plug this expression into the other equation for the variable you solved for

prime flint
#

this should be doable

bold vine
#

You can then solve for this variable.

prime flint
#

so maybe try to rearrange one of the equations in terms of 1 variable, then substitute that for the same variable in the OTHER equation

bold vine
#

Once you get the value of this variable, you can then plug its value into either one of the original equations to solve for the other variable

shell seal
#

Hmm

#

I will try

cedar kilnBOT
#

@shell seal Has your question been resolved?

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#
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crimson sedge
cedar kilnBOT
cerulean star
#

B

#

Exponential:

#

Use u-substitution where u = -x. All this will do is negate the non-constant term

crimson sedge
#

$\int{2^{-x}}dx \implies u=-x, du=-dx \implies -\int{2^u}du = -\bigg[\frac{2^u}{\ln(2)}+C\bigg] \implies -\bigg[\frac{2^{-x}}{\ln(2)}+C\bigg] \implies -\frac{2^{-x}}{\ln(2)}+C$

wraith daggerBOT
crimson sedge
#

i was expanding on what disorganized said because they just gave an answer

dense wing
#

Theirs is less of an answer, you posted the entire solution.

crimson sedge
#

if the answer was already given i cant really control that

#

i mean yeah ig

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#

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crimson sedge
#

Let $f(x) = Ax + B$ and $g(x) = Bx + A$, where $A \neq B$. If $f(g(x)) - g(f(x)) = B - A$, what is $A + B$?

wraith daggerBOT
#

crabbo

crimson sedge
#

i got $abx^2+a^2x+b=b-a$

wraith daggerBOT
#

crabbo

crimson sedge
#

how do i continue

peak relic
#

I guess I'm confused as to how you got an x^2 term. When I plug g(x) info f I get f(g(x)) = A(Bx + A) + B. This won't end up with an x^2 term. Similarly for g(f(x)).

cedar kilnBOT
#

@crimson sedge Has your question been resolved?

sly iris
#

A(Bx+A)+B - B(Ax+B)+A

dense wing
#

f(g(x))=A[g(x)]+b

crimson sedge
#

oh im

#

wrong

#

i see

dense wing
#

yes.

crimson sedge
#

so ABx+A^2+B=B-A

crimson sedge
sly iris
#

That's f(g) - g(f)

#

Lol

crimson sedge
#

A(Bx+a)-B(Ax+B)=0

#

solve time

#

this means that

#

Ax=-B

#

and Bx=-A

#

or

#

A=0

#

or B=0

#

i need help on how to continue

livid hound
crimson sedge
#

oh

#

math error

#

A(Bx+a)-B(Ax+B)=-2A

livid hound
#

steps were skipped but

A(Bx+a)-B(Ax+B)=0
looks ok

#

what did you do after that

#

where's all that coming from
where's Ax=-B
and everything that follows coming from

crimson sedge
#

i see

#

either

#

Ax+B=Bx+A

#

or A = 0

#

or B = 0

livid hound
#

that's what you're saying but what's leading you to those conclusions

#

i.e where's Ax + B = Bx + A coming from

leaden otter
#

It's like saying if m+n=0 then m=0, n=0. That's the wrong conclusion. You can't assume anything like this.

livid hound
#

where's
orA=0
or B=0
coming from

#

show all work and/or reasoning leading to your statements

crimson sedge
#

i dont know how to solve it

leaden otter
#

Nothing stopping you from expanding the brackets.

crimson sedge
#

A^2+B^2=0

#

is the answer 0

#

A+B=0?

leaden otter
crimson sedge
#

so

#

(A+B)(A-B)=0

#

either A-B=0

#

or A+B=0

leaden otter
#

Yep

#

But notice A-B can't be equal to 0

crimson sedge
livid hound
#

read the question

crimson sedge
#

oh

#

i see

#

.close

cedar kilnBOT
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teal heath
#

hello I am struggling with this question

cedar kilnBOT
teal heath
soft cloak
#

i mean, have you tried each of them?

teal heath
#

yes

#

a is not true i know its 1

soft cloak
#

yup

teal heath
#

d is -1 so not true

soft cloak
#

indeed

teal heath
#

e is not true it is 1

soft cloak
#

yes

teal heath
#

when i do b i get negative infinity

#

and when i do c I get 0 so i am confused

soft cloak
#

yeah, i was for a second as well

#

and i think this is just the question being overly finnicky with the definition of "the limit exists"

#

because technically, if it tends to infinity it diverges so the implied finite limit doesn't exist

#

but usually you would disambiguate this by saying "converges towards a finite limit"

#

or something

teal heath
#

i think it was b because e^x exists for all values so there is a limit of 0

soft cloak
#

yep, the others are simply false, and for this one i can see how you could play with the definitions to make it work

#

but if someone actually expected someone to answer b) without any hesitation i'd slap them

#

figure of speech, but still

#

Things going to ±∞ are in general "kinda convergent". Like yeah it doesn't tend towards any particular real value, but c'mon it's regular, it's not like sin(n) or anything

teal heath
#

so why is the answer for b not exist because as that function approaches 0 from the right it gets closer to negative infinity

soft cloak
#

The only way i see the question working is if you say "-∞ isn't a number so the limit doesn't exist"

#

because limits are often understood to be finite values

teal heath
#

ok because when i graphed it i got this

soft cloak
#

and you're right

#

if you ask 100 mathematicians what this limit is, 99 will answer "-∞"

teal heath
#

im just confused because as it approaches 0 from the right it goes toward negative infinity, it never really hits 0

soft cloak
#

Just like when x approaches -∞ in e^-x, it never really hits -∞

#

Limits don't deal in "what happens at the value", you have a wonderful tool for that called a calculator

#

Limits deal in "what happens if i get arbitrarily close to this value"

#

so yeah, you never reach 0, but that wasn't the point

teal heath
#

ok thanks for the help

#

.close

cedar kilnBOT
#
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dusty stone
#

how many event possible in random experience

ornate mortar
dusty stone
#

the question ask if the number of possible events could be greater than the fondamental set

#

issued results

dense wing
#

Post the question verbatum

dusty stone
#

is the numbers of events associed to a random exprience greater than number of results in the fundamental set of that experience.

dense wing
#

Fundamental set is something from ODEs... it sounds like you're trying to talk about probability

dusty stone
#

yes

dense wing
#

So... what's fundamental set in this context...?

dusty stone
#

there is non

dense wing
#

???

dusty stone
#

just a question

dense wing
#

Then the question is bad

#

You're asking about something that apparently doesn't exist

dusty stone
#

well it is not me who posing the question it is the teacher

dense wing
#

No, it's getting lost in translation...

#

Given your broken English, you're translating the question

dusty stone
#

yes indeed

fickle trellis
#

Hassan, um what language is the original question in?

dusty stone
#

french

cedar kilnBOT
#

@dusty stone Has your question been resolved?

olive geyser
cedar kilnBOT
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rugged tusk
#

. (∃x a(x) ∨ ∃x b(x)) → ∃x (a(x) ∨ b(x))

#

.close

#

.close

#

.cloose

#

.close

cedar kilnBOT
rugged tusk
#

can someone help me prove this statement ?

cedar kilnBOT
#

@rugged tusk Has your question been resolved?

cedar kilnBOT
#

@rugged tusk Has your question been resolved?

south tundra
#

Define set non-empty A such that the statement a is true for only numbers in the A set and similarly define non-empty B such that the statement b is true for only numbers in the B set

#

This is basically what we conclude from (∃x a(x) ∨ ∃x b(x))

#

Then ∃x (a(x) ∨ b(x)) is clearly true, because we can choose x to be in the set $A\cup{B}$

#

Wait how do I write union in LaTeX

wraith daggerBOT
#

Touch Our Beans

south tundra
#

Oh thanks

rugged tusk
#

.close

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clever jewel
#

I know this is wrong, but where is it wrong?

cedar kilnBOT
#

@clever jewel Has your question been resolved?

south tundra
#

View $\frac{x - 1}{x + 1}$ as $1 - \frac{2}{x + 1}$

wraith daggerBOT
#

Touch Our Beans

clever jewel
south tundra
#

$\lim_{x\to\infty}(\frac{1 - \frac{2}{x} + \frac{1}{x^2}}{1 - \frac{1}{x^2}})^x \ne 1$

wraith daggerBOT
#

Touch Our Beans

south tundra
#

Only this part

clever jewel
#

can't I simply take each of those fractions as a separate limit and evaluate them separately?

#

and then plug in the values

south tundra
#

No, I can give you an example where such conclusion fails

#

$e = \lim_{n\to\infty}(1 + \frac{1}{n})^n$

wraith daggerBOT
#

Touch Our Beans

south tundra
#

1 + 1/n clearly approaches 1

#

Yet the limit isn't equal to 1

clever jewel
#

hmm

#

yeah, I know it's e

#

but like, what's stopping me from breaking that limit into smaller limits?

#

can't the limit of some addition be broken into an addition of 2 limits?

south tundra
#

Yes (1 + 1/n)^n is the same as (1 + 1/n) being multiplied n times

#

But the limit should be the value that the expression approaches as n gets arbitrarily large

#

We can't even guarantee that it's a natural number in the first place

#

To break (1 + 1/n)^n into (1 + 1/n) being taken n times

#

It's almost the same mistake as writing $\sum_{k=0}^N{k} = k\sum_{k=0}^N{1}$

wraith daggerBOT
#

Touch Our Beans

south tundra
#

I hope it's clear now

clever jewel
#

hmm

#

I just checked the limit laws

south tundra
clever jewel
#

yeah, it works

#

what I was about to say

#

was that I thought I could do something like this:

#

but it only works if g(x) is a constant

south tundra
#

I think it works as long as limits for f and g exist generally

clever jewel
#

oh

south tundra
#

g doesn't have to necessarily be constant function

clever jewel
#

well, I found this image

clever jewel
#

if the limit can be broken into separate ones

dense wing
clever jewel
#

so I can't just evaluate the function inside the paranthesis and then worry about the power?

clever jewel
dense wing
#

yes

clever jewel
dense wing
#

That I'm aware no, however those type of limits (ex. e's definition) require log tricks

elfin hemlock
#

1^inf is indeterminate form

#

You were saying 1^inf=1 but that is false

dense wing
#

$L:=\lim_{x\to a}(f^g)(x) \ \ln(L)=\lim_{x\to a}g(x)\ln(f(x))$

wraith daggerBOT
clever jewel
#

I was saying

#

1^x as x approaches infinity is 1

#

isn't that true?

dense wing
#

yeah but you never have that

elfin hemlock
#

You don’t have 1

#

You have something approaching 1

dense wing
#

you have like 1.001^(something not 1 WLOG)

elfin hemlock
clever jewel
#

ohhh

#

I see

#

alright, it's crystal clear now

#

can't separately evaluate the paranthesis and then the exponent, they both affect each other

dense wing
#

Also: the limit definition of e that was put here also is a counterexample

#

yes

elfin hemlock
#

If its like 2^inf yes you can

#

The only problem is 1^inf

clever jewel
#

I see

#

well, thanks a lot @south tundra, @dense wing and @elfin hemlock ! :P

#

.close

cedar kilnBOT
#
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crimson sedge
#

so i gotta minimise (a-1+1/a)(2-a+1/(3-a)) where 0<=a<=2

crimson sedge
#

ping me pls

#

<@&286206848099549185>

main needle
#

there's a symmetry that makes (a-1+1/a) and (2-a+1/(3-a)) the same thing

#

and the minimum will just be the center of the symmetry

crimson sedge
#

swagthink how do i show it tho

#

like is there a formal way to write it

main needle
#

hmmm I'm not entirely sure

#

something about the limit at a=0 and a=3 being +infinity, and the degree of the polynomial meaning it can only turn once

crimson sedge
junior iron
#

shift it to the origin and apply the definition of symmetry

crimson sedge
# crimson sedge

swagthink it does make sense, just that idk how to convince someone that the minimum will be at the middle

crimson sedge
crimson sedge
#

yea thanks got it

#

.close

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silk hazel
#

I forgot how to this, Am i suppose to give the highest exponent or give the sum of degrees

silk hazel
#

So its 6?

#

or 7

crimson sedge
silk hazel
#

Alright thanks

crimson sedge
#

Degree is the highest power after expanding.

#

It is currently in a factored form.

silk hazel
#

I see

#

thank you

#

.close

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boreal mist
#

i need help with this <@&286206848099549185>

floral thistle
#

don’t immediately ping helpers

south tundra
#

When he was walking 800m NE, you could conclude that he walked 800/sqrt(2) due to N (and 800/sqrt(2) due to eE)

#

So since he's walked 800/sqrt(2) due to N already and he wants to have walked 1000m

#

He now would need to walk 1000 - 800/sqrt(2) in the direction of North

#

(Feel free to rationalize the denominator in 800/sqrt(2))

boreal mist
#

ok

cedar kilnBOT
#

@boreal mist Has your question been resolved?

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ionic peak
#

I need to map a function onto a torus

cedar kilnBOT
radiant topaz
#

You want to map a function?

grizzled nacelle
wraith daggerBOT
ionic peak
#

I want to use stereographic projection to map the x and y values of a function onto a torus

#

The circle going around the top being the y-axis, and the circle going around the sides being the x-axis

#

So you can sorta see the whole infinite function in a finite space

cedar kilnBOT
#

@ionic peak Has your question been resolved?

cedar kilnBOT
#

@ionic peak Has your question been resolved?

#
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crimson sedge
#

Define the function $g(x)=3x+2$. If $g(x)=2f^{-1}(x)$ and $f^{-1}(x)$ is the inverse of the function $f(x)=ax+b$, find $\dfrac{a+b}{2}$.

wraith daggerBOT
#

crabbo

crimson sedge
#

What do i start solving

#

what will help me find the answer?

bright surge
#

and then use it to find f itself

crimson sedge
#

@bright surge $f^{-1}(x)=\frac{x-b}{a}$

livid hound
#

x not y

bright surge
crimson sedge
wraith daggerBOT
#

crabbo
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

crimson sedge
bright surge
livid hound
#

and then use the information given about g(x)

crimson sedge
#

?

bright surge
#

so it is....

crimson sedge
#

$\frac{3x+2}{2}=\frac{x-b}{a}$

wraith daggerBOT
#

crabbo

bright surge
crimson sedge
wraith daggerBOT
#

crabbo

bright surge
#

right

#

and so you can find f, right?

crimson sedge
bright surge
livid hound
#

equate coefficients and constants to determine the values of a and b

crimson sedge
#

2x+2?

livid hound
#

forget about finding f(x)

#

equate coefficients and constants to determine the values of a and b

crimson sedge
#

2=a

#

-2=b

livid hound
#

how are you getting that?

crimson sedge
#

im equating coefficients and constants

livid hound
#

what exactly are you equating

#

that leading you to those conclusions

crimson sedge
#

a=2

#

b=-2

livid hound
#

how are you getting a=2

#

how are you getting b-2

#

from that

#

show all work

crimson sedge
crimson sedge
#

im matching

livid hound
#

show all work

crimson sedge
#

ig its wrong

crimson sedge
#

which expressions should i work with

livid hound
#

by actually equating the coefficients of x and the constant terms

#

perhaps it would be easier to see if you split your fractions

#

to explicitly identify the coefficients and constants

#

just because a is the denominator on one side and there is a 2 in the denominator on the other side, that doesn't necessarily mean that a is 2

#

nor is that in anyway equating the coefficients and/or constants

crimson sedge
livid hound
#

no

#

explicitly express it as a sum of your x term and the constant term

crimson sedge
#

so

#

3x-2=ax+b?

livid hound
#

no

crimson sedge
#

im confused

livid hound
#

you're overthingking this

#

lets start with the elft side

crimson sedge
#

i just dont understand what you want me to do

livid hound
#

$\frac{3x+2}{2}$

wraith daggerBOT
#

ℝamonov

livid hound
#

split that fraction and express that as a sum of your x term and a constant

crimson sedge
#

or

livid hound
#

who said anything about like terms