help-13

[cedar kiln]

Channel closed

Closed by @barren patrol

Use .reopen if this was a mistake.

[crimson sedge]

i did it

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mortal dome]

how can I create an equation for the angle theta in terms of x?

[glad kestrel]

what two sides do you have relative to your angle?

[cedar kiln]

@mortal dome Has your question been resolved?

[mortal dome]

the 75 ft and the variable x

this is the rest of this question

[radiant topaz]

You can solve it by sin(theta)

Then use chain rule for differentiation

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[woeful spear]

yes

[cedar kiln]

@woeful spear Has your question been resolved?

[cedar kiln]

@woeful spear Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cerulean shard]

Hey so I need help with steps to solve this it says to simplify

[cerulean shard]

Says simplify. Only positive exponents with no fractional exponents in the denominator

[graceful karma]

So yeah you can split up that fraction into many diff fractions

Just cause thats how division works

Just like:

$\frac{1}{2} * \frac{m^{1/4}}{m^{1/3}} * \frac{n^{1/4}}{n^{2/3}}$

[wraith dagger]

PapaBread

[graceful karma]

Then youve got your exponent rules

[cerulean shard]

Where did the 1/2 come from?

Oh nvm

Divided

So half

[graceful karma]

Ye its a bit weird

[cerulean shard]

I gotchu

[graceful karma]

Cause the 1 comes out of nowhere

[cerulean shard]

Ya

Uhm

So what would I do next then?

[graceful karma]

Just remember how multiplying/dividing exponents of the same base adds/subtracts the exponent

[cerulean shard]

I can’t do m1/4 • n1/4

Cause different exponents?

[graceful karma]

Focus on the division

[cerulean shard]

Ok

[graceful karma]

Cause the multiplication can be pushed back to later

For the sake of simplifying it

[cerulean shard]

Ok

So m1/4 - m1/3?

Cause divide exponent is subtract.

[graceful karma]

The exponents specifically subtract

Not the whole number

[cerulean shard]

Sorry if I’m missing anything your saying or my question seem dumb. I forgot I had a test on this so it’s like 11 pm and I’m doing this

[graceful karma]

Its all right I could be more specific

So like

[cerulean shard]

Ok

[graceful karma]

$\frac{a^b}{a^c}=a^{b-c}$

[wraith dagger]

PapaBread

[cerulean shard]

Ok

Sorry phone died

So that equals -1 right?

[graceful karma]

Wdym

[cerulean shard]

Oh would that just equal 1 I mean

1/4-1/3

[graceful karma]

The fractions have to be the same base to add or subtradt

[cerulean shard]

Oh ya my bad gimme a second

So m -1/12

Right?

[graceful karma]

Yeah I think thats right

[cerulean shard]

Ok

So that’s what I got after the same base

Now multiply by 1/2

?

[graceful karma]

The question says no negative exponents

So id just fix that and multiply it out ye

And you should be done

[cerulean shard]

The • is multiplication sign

Ok how do I “fix” negative?

[graceful karma]

A negative exponent is just the reciprocal of the whole thing

So like x^-1 = 1/x

[cerulean shard]

Ok

[graceful karma]

Or x^-2 = 1/x^2

Etc

[cerulean shard]

Alr

Is the right then?

[graceful karma]

Wot do you have

[graceful karma]

Ye

Your teacher prob wants you to multiply it all together but

[cerulean shard]

Ok

[graceful karma]

Just so its all under one 1/

[cerulean shard]

And I have to multiply by 1/2 still right?

[graceful karma]

Ye

Just add the 2 underneath

With the rest

Speaking of rest

I prob need to go to sleep

[cerulean shard]

Lol ok real quick 1 last thing is this right?

[graceful karma]

Make sure you keep the 1/12

It reciprocals the whole thing but not the exponent

Its confusing

[cerulean shard]

Ok

[graceful karma]

Just remember that negative exponent means the reciprocal of the whole exponential and base

And a reciprocal in the exponent doesnt

Well uhh adios

Dont forget the rules

For your test

Teachers love rules

[cerulean shard]

Ok lol

Thanks and goodnight

.close

[cedar kiln]

Channel closed

Closed by @cerulean shard

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jolly halo]

What log rule do i use to solve for x?

[jolly halo]

.close

[cedar kiln]

Channel closed

Closed by @jolly halo

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

is it possible to answer: 9a^4(3a-5b^3c^2)+2abc^2(7a^3b^2-6b)-a(2bc-12a^4) in less than 20 seconds? Cause I can't seem to work it out within that time, does anyone know any shortcuts?

[crimson sedge]

Note: I already know how to expand and simplify, I'm just looking for other methods which can sort it out faster

Here is the equation if it helps:

[obsidian coral]

Why 20 seconds?

With long problems like this, it takes time

[crimson sedge]

then perhaps 1 minute then

since 30 minutes and 60 questions

If I have a minute in the end, how would i solve this quickly? or is it not possible?

[obsidian coral]

What are you solving exactly?

[crimson sedge]

its just expansion and simplification

Just wondering if there exists a cheat method for long stuff like this

[obsidian coral]

If you are efficient and make little mistakes, it's doable in a minute

[crimson sedge]

k thx, inf practise it is

[obsidian coral]

Also you don't need to ping reply to every message

[crimson sedge]

mb

.close

[cedar kiln]

Channel closed

Closed by @spice estuary

Use .reopen if this was a mistake.

[crimson sedge]

wait

was that right?

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[austere oasis]

really quick question

i need part b

in take n=(-1,-2,-1)

then need P = (1,-1,4)

a(x-x0)+b(y-y0)+c(z-z0)=0

-1(x-1)-2(y+1)-(z-4)=0

-x+1-2y-1-z+4=0

-x-2y-z+4=0

x+2y+z=4

but the answer says its x+2y+z=3

<@&286206848099549185>

[cedar kiln]

@austere oasis Has your question been resolved?

[austere oasis]

<@&286206848099549185>

its a really quick question

i must be messing something up in the formula idk

ok i found the problem

i didnt multiply the -2(y+1) correctly

but now im getting

x+2y+z=-3

<@&286206848099549185>

[cedar kiln]

@austere oasis Has your question been resolved?

Channel closed

Closed by @austere oasis

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

Find the vertex of the graph of the equation $y = -2x^2 + 8x - 15.$

[crimson sedge]

i got (-4, 17/2) which is wrong

what happened?

i got this by using completing the square

on the rhs

to get

well

oh!

wait

i divided by -2

to get $y/-2=x^2-4x+15/2$

[wraith dagger]

static

[crimson sedge]

completed the sqare:

$(y/-2)-7/2=x^2-4x+15/2-7/2$

[wraith dagger]

static

[radiant topaz]

Wait

You are completing square?

[crimson sedge]

$(y/-2)-7/2=(y-2)^2$

[wraith dagger]

static

[crimson sedge]

$y=-2(y-2)^2+7/2$

wait

[wraith dagger]

static

[crimson sedge]

my vertex is completely different now

it is

(2,7/2)

which is incorrect...

[radiant topaz]

y= -2 (x²-4x)-15
y= -2 (x²-4x+4-4)-15
y= -2(x-2)²+8-15
y=-2(x-2)²-7

[crimson sedge]

wait what

[radiant topaz]

Is it (2,-7)?

[crimson sedge]

why no fraction?

it is (2,-7)

howw??!!

i don't understand

[livid hound]

your x turned into a y for some reason
and you didn't multiply both sides of the equation by -2 properly

[radiant topaz]

This is complete procedur what I did

Yeah you did that mistake

[livid hound]

and you went the inefficient route of dividing both sides by -2 instead of simply factoring out -2 from the rhs

[crimson sedge]

you factored out a -2

ah

why did you do this?

y= -2 (x²-4x+4-4)-15

[radiant topaz]

To complete square

[crimson sedge]

but you are just adding 0

[livid hound]

exactly

[crimson sedge]

technically

[crimson sedge]

?

[radiant topaz]

(x+y)²= x²+2xy+y²

Right

[crimson sedge]

wait what

[livid hound]

that's how completing the square works

[radiant topaz]

Yes

[crimson sedge]

adding zero?

that is not how i learned it

[livid hound]

you're adding something equivalent to 0, which doesn't change the value of your expressions

[crimson sedge]

right

[livid hound]

and maintains the equality of the equation

[crimson sedge]

but then how do you get to y= -2(x-2)²+8-15

[radiant topaz]

This can be written in different ways but it's still same

[crimson sedge]

where did the 8 come from

i thought the 4-4 is 0

[livid hound]

after completing the square for the stuff within the parentheses, redistribute the -2

[crimson sedge]

redistribure

wdymbt

[livid hound]

expand

[radiant topaz]

4 remains in bracket and -4 cums out to give -2×-4=8

y= -2 (x²-4x)-15
y= -2 (x²-4x+4-4)-15
y=-2(x²-4x+4)-2(-4)-15
y= -2(x-2)²+8-15
y=-2(x-2)²-7

[crimson sedge]

can you do -2(x²-4x+4)-2(-4)

[radiant topaz]

Yes thats just reverse distribution

[crimson sedge]

i just don't see why you add the 4-4

[livid hound]

to complete the square

[crimson sedge]

i don't see how it does tho

when you complete hte square

[livid hound]

how would you complete the square for
x^2 - 4x
?

[crimson sedge]

you aren't supposed to subtract 4 again

it makes sense to add 4

just not subtract it again...?

[livid hound]

yeh but as implied earlier

just adding 4 would change the value of the expression

[crimson sedge]

right

[wraith dagger]

it's Sam

[livid hound]

adding 4 then subtracting 4, effectively adding 0 does not

[radiant topaz]

We have the rightmost form

[crimson sedge]

oh

[radiant topaz]

x²-4x = x² - 2(2)x

[crimson sedge]

and it is possible to take out the 4 ?

-2(x²-4x+4)-2(-4)

[radiant topaz]

Ye

[crimson sedge]

why is it possible

[livid hound]

distributive property

[crimson sedge]

oh

right

ok

i think i see it now

but i am still a tiny bit skeptical

what was wrong with the way i did it then?

[livid hound]

your x turned into a y for some reason
and you didn't multiply both sides of the equation by -2 properly

[radiant topaz]

Your way can work too but you did it wrong

[crimson sedge]

oh

i forgot to multiply the 7/-2 by -2

then i would've gotten the same exact thing

.close

[cedar kiln]

Channel closed

Closed by @little wave

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[idle nimbus]

How do we prove for this when A is an infinite set

[cedar kiln]

@idle nimbus Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[halcyon sand]

how would i figure this out?

[main needle]

what's 9! mod 9?
what's 10! mod 9?

[halcyon sand]

0

and 0

[main needle]

right, so you just need to calculate the first few numbers

[halcyon sand]

oh makes sense

thank you

.close

[cedar kiln]

Channel closed

Closed by @halcyon sand

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pallid inlet]

Hi so I know the forumla to use for this problem, but I'm getting stuck on what I put as a certain variable

[pallid inlet]

I know lamba is 10 and what idk what t would be since n would be 25

[cedar kiln]

@pallid inlet Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cedar kiln]

Channel closed

Closed due to the original message being deleted

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pallid inlet]

<@&286206848099549185>

[cedar kiln]

@pallid inlet Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[worn flax]

I'm not gonna lie I don't got any clue how to do this. I have an 87/100 just tryna get a couple more points.

[worn flax]

i tried to write it as a simple logarithm but I cant seem to get the correct answer

this was my original answer

[cedar kiln]

@worn flax Has your question been resolved?

[livid hound]

you didn't read the instructions properly

and didn't manipulate properly

your end goal would be to get an expression in the form
$$a\log_3(x) + b\log_3(y) + c\log_3(z)$$

[wraith dagger]

ℝamonov

[floral thistle]

they left the server

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[main pagoda]

I’m on questions C and D

I’ve had a lot of trouble calculating covariance for awhile. As well as what the covariance actually means

<@&286206848099549185>

[lucid bolt]

Can someone help me with a concavity problem?

[main pagoda]

This help room has already been claimed. You might have better luck getting help in an unclaimed help room

[lucid bolt]

Gotcha thx

[main pagoda]

Np

I’ve had a lot of trouble calculating covariance for awhile. As well as what the covariance actually means

I now just need help with question D

[cedar kiln]

@main pagoda Has your question been resolved?

Channel closed

Closed by @main pagoda

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[oblique cypress]

Hey guys! I just started my Introduction to Algorithms class for my masters and have hit a bit of a brick wall. It's been since high school that I've had to take a math class, and so I've been trying my best to hit the books and catch myself up to speed. I'm running into an issue with an exercise in my textbook though (not part of an assignment), and I've really been trying to figure it out. The question is specifically finding which values insertion sort beats merge sort for a given implementation, where insertion sort is 8n^2 and merge sort is 64n * lg n (I'm not sure if this notation is standard, so lg == log_2. I wrote this down as 8n^2 < 64n * lg n.

I tried my best to simplify it, dusting off some of my old online resources to relearn logarithms, but I simply couldn't figure it out. I decided to put it into Wolfram Alpha to see the answer and work backwards from there, but it completely blind-sided me with something I've never seen before, being the Lambert W function. I won't write it here simply because I don't know how to feed LaTeX to the bot, or if that's possible, but the link is this: https://www.wolframalpha.com/input/?i=8n^2<64n*log_2(n)+solve+for+n

I'm mainly wondering, what is the Lambert W function, how do I solve it, how do I use it, and how was it used in this context? I've looked at some online resources and figured out that it's the inverse of f(x) = x * e^x, but it's been so, so long since I've done this sort of math that I'm struggling to understand it. I've really been trying to learn it on my own, and this was the last resource I had, as I didn't want to trouble you guys with something I could learn on my own. If you take your time to help me understand this, I thank you greatly.

[oblique cypress]

And, if possible, the steps taken to solve for the expression would be extremely helpful. I'm not the sharpest tool in the shed for this kind of mathematics, so I might need a bit more than others to follow along 😓

[cedar kiln]

@oblique cypress Has your question been resolved?

[oblique cypress]

<@&286206848099549185> Sorry for the ping, I'm just hoping to grab someone that might know about this

[sweet forge]

maybe ask in a corresponding topic channel (further down in the channel list) if this is too advanced for these general help channels

[oblique cypress]

ooh ok. Which channel do you feel this would fit best in? #numerical-analysis ? Though, the Lambert W function isn't CS-specific

#groups-rings-fields ?

I'll try #groups-rings-fields first

[sweet forge]

i woulnd't know 😄 i have never heard about the Lambert W function

[oblique cypress]

.close

[cedar kiln]

Channel closed

Closed by @oblique cypress

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gray vine]

6. Determine the numbers a, b and c so that the curve y = ax^2 + bx + c goes through the points (-1, 2), (2, 5) and (1, -2).

[radiant topaz]

Can you use matrix?

You will get 3 equations

[gray vine]

@radiant topaz I’m not used to matrixes yet

-2 = a((1)^2) + b(1) + c

-2 = a + b + c

5 = a((2)^2) + b(2) + c

5=4a+2b+c

2 = a((-1)^2) + b(-1) + c

2 = a - b + c

-2 = a + b + c
5=4a+2b+c
2 = a - b + c

[radiant topaz]

Ok these 3 equations right

[gray vine]

Yes

So for the first one, I solve for a?

[radiant topaz]

You know how to solve then

[gray vine]

-2-b-c = a, for first one

5 = 4(-2-b-c) + 2b + c

5 = -8-4b-4c+2b+c

[radiant topaz]

Well yes you have to do it in a way you do it for two equations in two variables

[gray vine]

5 = -2b-3c-8

[radiant topaz]

2b+3c=-13

[gray vine]

13 = -2b-3c

[gray vine]

Why

[radiant topaz]

My addition mistake

[gray vine]

I think I’m going to solve for b here

13+3c = -2b
13/-2 + 3c/-2 = b

[radiant topaz]

No wait

Do it this way

[gray vine]

What way

[wraith dagger]

it's Sam

[radiant topaz]

Then find c

[gray vine]

How do I eliminate c?

Which method did I use?

[radiant topaz]

Equation 1 - Equation 2

[gray vine]

-2 = a + b + c
5=4a+2b+c

So…

-2-5 = a-4a + b-2b + c-c

Right?

[radiant topaz]

Yes

[gray vine]

-7 = -3a - b

And from here we do?

[radiant topaz]

I gave you other pair of equations too

Eliminate c in that too

[gray vine]

Ok sec

-7 = -3a - b
2 = a - b + c

-7-2 = -3a-a -b-b + c

-9 = -4a -2b + c

@radiant topaz

[radiant topaz]

How is c still there

[gray vine]

Yeah

Idk

[gray vine]

This is what I got last time.

One moment

I think I misunderstood you.

5=4a+2b+c

2 = a - b + c

[radiant topaz]

See from fist system I get 3a+b=7 and from second system I get 3a-3b=3

Now I have two equations

3a+b=7
3a-3b=3

[gray vine]

-7 = -3a - b
is the same as
7 = 3a + b, right?

[radiant topaz]

Yes

[gray vine]

And as for the second system, I will check what it is.

[radiant topaz]

So eliminating a I get 4b=4

[gray vine]

How do you choose equations for these systems?

[radiant topaz]

So b=1

[gray vine]

You chose one equation in both system, for example

[radiant topaz]

1st equation and 2nd equation
1st equation and 3rd equation
2nd equation and 3rd equation
Give 3 systems

[gray vine]

5=4a+2b+c

Oh ok

So ok, 3a + b = 7. That’s our first equation from the system. Then another equation from a different system.

5=4a+2b+c
2 = a - b + c

5-2 = 4a-a + 2b-b

3 = 3a + b

1 = a + b

1. 3a + b = 7
2. 1 = a + b

3. ?

[cedar kiln]

@gray vine Has your question been resolved?

[gray vine]

1. -2 = a + b + c
2. 5=4a+2b+c
3. 2 = a - b + c
   -2 - 2 = a - a + b-b + c-c

@radiant topaz What am I doing wrong? 😔

[radiant topaz]

Wow what have you done

[gray vine]

You said the first and third equation for the last system, right?

1st equation and 2nd equation
1st equation and 3rd equation
2nd equation and 3rd equation
Give 3 systems

[pseudo perch]

you just substitute one co-ordinate to find a, b and c

[gray vine]

1. 3a + b = 7
2. 1 = a + b
   These are the systems I have right now. The third one remain.

[pseudo perch]

i have 2 = a + b + c

[gray vine]

From this?

2 = a((-1)^2) + b(-1) + c

Determine the numbers a, b and c so that the curve y = ax^2 + bx + c goes through the points (-1, 2), (2, 5) and (1, -2).

Omg… I’m coming nowhere

[cedar kiln]

@gray vine Has your question been resolved?

[gray vine]

Bump

[zinc mason]

so you have
\begin{align}
-2 &= a+b+c \
5&=4a+2b+c\
2&=a-b+c
\end{align}

[wraith dagger]

kiid

[zinc mason]

and from (1) you got $a=-2-b-c$

[wraith dagger]

kiid

[zinc mason]

try substituting that into (3)

[gray vine]

Okay.

(3) $$-2-b-c-b+c= 2$$

[wraith dagger]

Theophania

[gray vine]

$$4 = -2b$$

[wraith dagger]

Theophania

[gray vine]

$$b=-2$$

[wraith dagger]

Theophania

[gray vine]

@zinc mason Now what?

[zinc mason]

cool so now you have b = -2

put that back into (1) and (2) then you can solve for a and c

[gray vine]

(1) $$-2 = a-2+c$$

[wraith dagger]

Theophania

[gray vine]

$0=a+c$
\newline
$-c=a$

[wraith dagger]

Theophania

[gray vine]

(2) $$5 = 4(-c) + 2(-2) + c$$

[wraith dagger]

Theophania

[gray vine]

$5 = -4c - 4 + c$

[wraith dagger]

Theophania

[gray vine]

$9 = -3c$
\newline
$-3 = c$
\newline
$a = -c \implies a = 3$

[wraith dagger]

Theophania

[gray vine]

$a = 3, c = -3, b = -2$

[wraith dagger]

Theophania

[gray vine]

@zinc mason Is this correct?

Determine the numbers a, b and c so that the curve y = ax^2 + bx + c goes through the points (-1, 2), (2, 5) and (1, -2).

,w graph y = 3x^2 - 2x - 3

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Theophania#1704

[gray vine]

@zinc mason @it’s Sam is this correct now? Hehe.

@radiant topaz

[zinc mason]

well it works so 🙂

[gray vine]

Alright thanks.

.close

[cedar kiln]

Channel closed

Closed by @gray vine

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

Assuming trinomial means polynomial with 3 terms like ax² + bx +c,
Perfect square trinomial means (ax+c)².

Any trinomial which can be written like
(ax+c)² is a perfect square trinomial.

Like (x²+4x+4) = x² + 2•2x + 2² = (x+2)²

Hence a perfect trinomial.

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[proud forge]

Pls help me with this

[proud forge]

Am i correct? KerL is kernel L btw

<@&286206848099549185>

[cedar kiln]

@proud forge Has your question been resolved?

[cedar kiln]

@proud forge Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[agile marsh]

question is what is z?

.close

[cedar kiln]

Channel closed

Closed by @agile marsh

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cedar kiln]

@nova geyser Has your question been resolved?

[nova geyser]

<@&286206848099549185> can u ans this:)

[gray vine]

@nova geyser Are you familiar with the remainder theorem?

[nova geyser]

yeah its using phorogaphite

its long division ing english i tjhinl

oof i typo alot and i dont realy know the theorem in english

[gray vine]

The remainder theorem states that if a polynomial, p(x), is divided by x-a, then the remainder will be p(a).

In your case, I'm not sure if it'd be p(1) or p(-1). You'll have to wait for somebody else to help.

[wraith dagger]

Result:

4017

[crimson sedge]

its p(-1) and you get 1

[gray vine]

@nova geyser

[nova geyser]

yeah

its 4017 or 1?

[gray vine]

,calc (-1)^2008 + 2008(-1) + 2008

[wraith dagger]

Result:

1

[gray vine]

👆

[nova geyser]

ok

[gray vine]

Do you understand why?

[nova geyser]

yeah

i just found it on google polynominal

some how my teacher didnt tell me

[gray vine]

Google ”remainder theorem polynomial”

[nova geyser]

my teacher teach me using long divison only

[gray vine]

Yeah it plays a part in it too

[nova geyser]

can i ask another to?

[gray vine]

I can't help with more sorry

I'm not that good in this area

You can ofc ask anyway

[nova geyser]

i will close

close

.close

[cedar kiln]

Channel closed

Closed by @nova geyser

Use .reopen if this was a mistake.

[nova geyser]

.reopen

[cedar kiln]

✅

[nova geyser]

.close

[cedar kiln]

Channel closed

Closed by @nova geyser

Use .reopen if this was a mistake.

[nova geyser]

i just found

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[icy relic]

I am solving a non homogenous differential equation of 1 variable of order 2 and degree 1.

[icy relic]

I am stuck at doing the integral of (1/e^x +e^2x)

Unless my steps are wrong, I should be able to proceed.

[cedar kiln]

@icy relic Has your question been resolved?

[icy relic]

<@&286206848099549185> I'm having difficulties with differential equations

[cedar kiln]

@icy relic Has your question been resolved?

[cedar kiln]

@icy relic Has your question been resolved?

[icy relic]

.close

[cedar kiln]

Channel closed

Closed by @icy relic

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[terse osprey]

heya, i can't make sense of this one:

[terse osprey]

my problem is that the LHS of the inequality in the hint is smaller than ║fn-f║_1 (when i plug fn-f in)
so i don't see how i can use it to prove that if RHS converges than ║fn-f║_1 also converges

isn't this question asking me to use A<C to prove that B<C when A<B?

shouldn't be possible

[short magnet]

What if you plug |f_n-f| instead?

[terse osprey]

well that would make a=b and fix the issue, but am i allowed to do that?
i mean, i don't know that fn-f is necessarily positive for any value
can't it make a difference in the integration over it?

[terse osprey]

yeah ok i worked it out.
thanks for the nudge

.close

[cedar kiln]

Channel closed

Closed by @terse osprey

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[short magnet]

Yaaaay @terse osprey 👌👍👍👍

[tiny dagger]

Hi. Anyone able to help me solve this. It was a game question but it seemingly to hard to understand. My clues were its arithmetic sequence and it 4 possible answers out of 9. Here is the question.

ARITHMETICS

1333 = 31 X 43
1260 = 21 X 60
3000 = 10 X 300
2201 = 71 X 31
1435 = 35 X 41
2187 = 27 X 81
6880 = 80 X 86
1827 = 21 X 87
1748 = 76 X 23

​*What shouldn't be here?

[cedar kiln]

@short magnet Has your question been resolved?

[crimson sedge]

so you need to remove 4 numbers?

[tiny dagger]

Yes. I need to know which 4 out of 9 shouldn't be there

[crimson sedge]

i think you just need to look at digits in LHS and RHS

[short magnet]

.close

[cedar kiln]

Channel closed

Closed by @short magnet

Use .reopen if this was a mistake.

[crimson sedge]

like 1260 = 21 X 60 so on both sides you got 1,2,6,0 and there are 5 numbers like that here other 4 doesnt work

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gray vine]

lg(x) = lg 6 + lg 6 - lg 9

I need to solve this without a calculator, anyone got any advice?

[livid hound]

consider stuff like sum/difference to product/quotient

[gray vine]

@livid hound lg 6 - lg 9 = lg6/lg9

lg 6 + lg6/lg9 = lg(6+6/9) = lg(60/9)?

According to Symbolab it’s incorrect…

I solved it in accordance with the 1&2 rule

[livid hound]

you didn't apply the log rules properly

[gray vine]

Where was the mistake

lg 6-lg9 = lg6/lg9

lg 6 + lg 6/9 = lg(6*6/9)?

Lg((54*6)/9) = Lg(x)?

,calc (54*6)/9

[wraith dagger]

Result:

36

[gray vine]

Lg(36) = Lg(x)?

Wait…

lg 6-lg9 = lg6/lg9
= lg2/lg3

lg 6 + (lg2/lg3) = lg(x)

Omg… anyone?

[livid hound]

lg6-lg9 = lg6/lg9
wheres that coming from

[gray vine]

Oh shoot one sec

lg 6 + lg(2/3) = lg(x)

lg(6*(2/3)) = lg(x)

lg(12/3) = lg(x)

lg(4)=lg(x)

Thanks

[cedar kiln]

@gray vine Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[azure harness]

Hey I got a relatively simple question, in those 3D cones, not sure how they're called in english, what's the more broad cone, 2(x^2+y^2), or 1/2(x^2+y^2)?

[azure harness]

Paraboloid is what I'm reffering to

like this, I assume multiplying it by 2 makes it "faster" therefore tighter, correct?

.solved

.close

[cedar kiln]

Channel closed

Closed by @azure harness

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

a

[crimson sedge]

this guy tried doing it but the answer was wrong

[crimson sedge]

graph this on a 3d graph

$\frac{x^2+y^2}{b^2} + \frac{z^2}{c^2} = 1$

[wraith dagger]

senku

[crimson sedge]

@crimson sedge

wym by a 3d graph

[crimson sedge]

You can plot a graph that maps out the output to third axis

woah

Like this function

ive never used that lol

i have no idea how that works tbh

[crimson sedge]

It's multivariable calc

stuff

so if you want to try it out

it's about time to learn some more calc

😏

idk

im just tryna get this answer lol

[crimson sedge]

<@&286206848099549185>

https://cdn.discordapp.com/attachments/903430334681608232/909211306589048903/unknown.png
https://cdn.discordapp.com/attachments/903430334681608232/909213302138212402/unknown.png

[crimson sedge]

so every boy can be paired with one of eight girls

so it would be like

if we picked the first boy

it would be 8 possibilities to make the team if one boy stays fixed

so given this

it would be mean that there exist 8*10

ways to sort the team

so 80 ways

yeah

i tried 80*79/2

gave me 3160

but it was wrong

so was 80 correct

didnt try that

thats wrong

[crimson sedge]

🤔

its college math

so its prob hard

harder than 1 multiplication

[crimson sedge]

wait what do they mean by double game

https://cdn.discordapp.com/attachments/903430334681608232/909213302138212402/unknown.png

look at how this guy did it

its somehow wrong

but

idk

[crimson sedge]

if the question was asking for the number of ways to sort out a team of two v two saying that atleast one member at that team must be boy and the other a girl

then for the next member it could be chosen freely

if that was the case then it would be the number of ways to chose 1 boy and 1 girl + the number of ways to sort out the other in the respective sides

no matter the gender

so first is 80 then add it with the permuation of chosing two from 16 people

because gender wouldn't matter

that is how I understand it

😩

[cedar kiln]

Channel closed

Closed by @narrow coral

Use .reopen if this was a mistake.

✅

[crimson sedge]

https://cdn.discordapp.com/attachments/903430334681608232/909222052915974144/unknown.png

<@&286206848099549185> can someone help me with this plz

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

@crimson sedge Has your question been resolved?

[cedar kiln]

@crimson sedge Has your question been resolved?

[icy kiln]

Use a choose function for both sides and multiply

[crimson sedge]

@icy kiln wouldn't that just be 80?

[icy kiln]

There’s 80 choices for the first team. Now you must construct the other team, without using those two

Disregard my first message. This way is easier

[crimson sedge]

wym*

is it 80 and then the second one is 1?

@icy kiln

[icy kiln]

Yeah so the first team has 80 choices (10 boys and 8 girls to choose from) and the second team now has 9 boys and 7 girls to choose from

[crimson sedge]

so 9*7?

for the second team?

@icy kiln

[icy kiln]

Does that make sense? I’m not really down to fact check guesses

[crimson sedge]

well yeah since the first time is 10 and 8

and

the second team is 9 and 7

10 * 8 = 80

9 * 7 = 63

[icy kiln]

Yup, and the multiplying is because for each guy you have that many girls to pair with that person. And for each team 1, you have 63 team 2’s to choose from. So you multiply those as well

[crimson sedge]

so the answer leaves you with 80 * 63

[icy kiln]

https://tenor.com/view/noice-nice-click-gif-8843762

[crimson sedge]

lol

but thats wrong tho

wait whered u get 9 and 7 from

@icy kiln

[icy kiln]

Since you’ve already used 1 boy and 1 girl in the first team, you’ve only got 9 boys and 7 girls to choose from. Ngl I can’t see what’s wrong with this

[crimson sedge]

hmmm

[icy kiln]

welp since apparently I know nothing about combinatorics, <@&286206848099549185> can you see a flaw in my reasoning?

[cedar kiln]

@crimson sedge Has your question been resolved?

[crimson sedge]

<@&286206848099549185>

😦

[icy kiln]

I stg, what a poorly worded question if so

[nova geyser]

@crimson sedge are u done?

so 1 boy and 1 girl on side 1 1 boy and 1 girl on side 2

so the left is 8 boys and 6 girls

8+6= 14

we must pick 7 people so

14C7

its 3432

[crimson sedge]

hm

[nova geyser]

u understand?

is it?

[crimson sedge]

yeah im just writing it odwn

down

so it makes sense

ok

wait

3432

is wrong

tho

@nova geyser

[nova geyser]

hm

it fr`om website or ur teacher make it

oh wait

i just relise

its a double game:/

so its 2vs 2 right?

to have in side 1 its 10 ways x 8 ways x 9 ways x 7 ways

its 5040

and its wrong WOW

ask ur Teacher:)

[cedar kiln]

@crimson sedge Has your question been resolved?

[nova geyser]

@crimson sedge if not using it anymore do .close

Okay

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[open dagger]

intuitively, I suppose that both changes in the system would increase the population. Does anyone have an idea of how these changes would affect the population? Mine's an educated guess, but a guess nevertheless

[cedar kiln]

@open dagger Has your question been resolved?

[cedar kiln]

@open dagger Has your question been resolved?

[open dagger]

<@&286206848099549185>

[pure quartz]

I would also agree that it is both of the above. px-xy-x^2 shows that the number of parakets increase with p (we'll assume p is food), decreases with more hawks (predators) and decreases exponentially with more parakets (because food competition).
y = -hy + xy shows that hawk population is dependent on the paraket population, but also by -hy, where h is environment. Therefore the greater the h, the less hawks we have. So an increase in h, would mean a loss of habitat for hawk.

[open dagger]

oh thank you for your time! just glad to know it's not just me who thinks that. appreciate it :)

ill leave the channel open a little longer to know what others' think too

[pure quartz]

Tbh it's an odd question, it missing variable definition and context. Seems like a statistical question where the answer is "Missing context means we have to assume things" and generally you don't want to assume things 😛

[open dagger]

it is an odd question, relies entirely on mathematical intuition

[pure quartz]

Yeah but that's kinda the thing, if someone gives you a set of equation with incomplete context, your intuition should to tell them to give you context and the full picture 😛 Like I could see the question being useful if you're a teacher where half your job is inferring what the student meant, but in most real world context you either get the full picture or don't use the data at all

[cedar kiln]

@open dagger Has your question been resolved?

Channel closed

Closed by @open dagger

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

How can i get zero point of this function? g(x)=2x**2+4x

[graceful karma]

Python notation

By zero point do you just mean where it equals zero?

[crimson sedge]

I got it

.close

[cedar kiln]

Channel closed

Closed by @pine pelican

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[worthy ruin]

can any1 help

[cedar kiln]

@worthy ruin Has your question been resolved?

[stray helm]

gradient = 0 means the derivative = 0

just take the derivative and set it to 0, and solve for x

@worthy ruin

[worthy ruin]

idk how to simplify the question

so I can get the derivative

thats all I need help with

i know what to do once it's slightly more simple

[stray helm]

you can write x^2*sqrt(x) as x^2.5

and you can write 1 / x*sqrt(x) as x^(-1.5)

[worthy ruin]

o

.close

[cedar kiln]

Channel closed

Closed by @worthy ruin

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wicked dust]

How would I put this equation into factored form (steps) ?

[cedar kiln]

@wicked dust Has your question been resolved?

[cedar kiln]

@wicked dust Has your question been resolved?

[cedar kiln]

@wicked dust Has your question been resolved?

[viral cloak]

Perhaps SA = πr(r+s)

?

[wicked dust]

Yeah I figured it out, that’s what I got. I was getting confused but yeah thanks

[viral cloak]

That's the only factoring I can see

[viral cloak]

Oh, ok!

[wicked dust]

.close

[cedar kiln]

Channel closed

Closed by @wicked dust

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[quaint furnace]

if $\mathcal{R}_1 = { x\mathcal{R}y \mid (x,y) \in \mathbb{X} \times \mathbb{Y}}$ and $\mathcal{R}_2 = { x\mathcal{R}y \mid (z,t) \in \mathbb{X} \times \mathbb{Y}}$ are two binary relation what is their product?

[wraith dagger]

Tera

[quaint furnace]

.close

[cedar kiln]

Channel closed

Closed by @quaint furnace

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

;-; where is everyone

Does congruence include multiples of side lengths?

Yes right?

[crimson sedge]

Yes

Then it is valid as 2 sides and an angle should uniquely define a triangle

Unless I'm mistaken lol

Ok thank you!

Is there enough information to prove that the triangles are congruent?

If yes, provide the correct Triangle Congruence Postulate or Theorem and a congruence statement.

If no, justify your answer.

.close

[cedar kiln]

Channel closed

Closed by @signal marsh

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[inner basalt]

The boxed equation is the starting function. I found the derivative but was a bit confused, so I checked on Desmos. The critical point where there is no slope is 4, but if x=4 the equation would be undefined since it would be 4/0. How come we can say 4 works?

[untold torrent]

@inner basalt I think that minimum and maximum points are not ONLY when the slope is 0. For example, if you have a function with a certain interval then you could have a minimum/maximum at at start and end of the interval even though the derivative does not equal 0.

So when you find critical points at these sorts of function, try look at where the derivative isn't defined aswell.

This is the definition for a minimum point. It's not only when the slope is 0.

[inner basalt]

Yes, but the definition of a critical point is “a point on the graph of a function where the derivative is zero or infinite.”

[untold torrent]

Well the derivative is approaching infinity from the right and negative infinity from the left, so I think it still counts.

Google says, more specifically, that the point is when the function is not differentiable, or in other words, that the derivative is undefined.

And you could say it means that the derivative is infinity.

So all of these things mean the same.

I'm just a student and I'm not an expert but hopefully I'm not mistaken here.

[cedar kiln]

@inner basalt Has your question been resolved?

[inner basalt]

That makes sense, thank you

[cedar kiln]

Channel closed

Closed by @inner basalt

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tame shadow]

i dont know how to go about this question

[main needle]

so O(x^2) + O(xlnx)

lnx is smaller than x right? so x^2 wins

[tame shadow]

xf(x) == O(x^2)?

[main needle]

yeah, f(x) is like c*x

so xf(x) is like c*x^2

[tame shadow]

hmm okay thanks

.close

[cedar kiln]

Channel closed

Closed by @tame shadow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[golden charm]

<@&286206848099549185>

[cedar kiln]

@golden charm Has your question been resolved?

[cedar kiln]

@golden charm Has your question been resolved?

[cedar kiln]

@golden charm Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[compact pelican]

Can anyone help me learn how this works? My teacher just explained it but I'm a bit confused.

[floral thistle]

@compact pelican what exactly confuses you?

exponent subtraction or negative exponents?

[cedar kiln]

@compact pelican Has your question been resolved?

[compact pelican]

substraction

[floral thistle]

ok so i can give you an example, we have (a*a)/(a*a*a*a*a)

this would equal 1/(a*a*a), can you see why?

two of the as in the numerator and denominator cancel

it’s basically the same as exponent addition, just with division instead of subtraction

[compact pelican]

ohh

Thanks

[floral thistle]

no problem

[compact pelican]

.close

[cedar kiln]

Channel closed

Closed by @compact pelican

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed due to the original message being deleted

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crystal pivot]

Hey guys so I am converting complex numbers into polar form and I am currently stuck. Heres the equasion:

[crystal pivot]

What I am trying to find is theta when given sin cos

cos: sqrt10/10
sin: -3sqrt10/10

[cedar kiln]

@crystal pivot Has your question been resolved?

[cedar kiln]

@crystal pivot Has your question been resolved?

[main needle]

the angle inside cos and sin will be the same

2-6i is like the coordinate (2,-6), and you can find it's angle with arctan(y/x)

,w arctan(-6/2)

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Plurmorant#1811

[main needle]

so -1.249 is the angle you want for both

[cedar kiln]

@crystal pivot Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[latent gust]

Right so, I need to prove this trig identity. I simplified the left side down to 1 * 1 + 2cos^2xsin^2x. I'm not entirely sure if that is correct, nor do I know how to proceed with this question.

Any help will be greatly appreciated 😭

[leaden otter]

You know cos²(x)+sin²(x)=1 right?

[latent gust]

yes, thats where i got the 1 * 1 from

mainly stuck on what to do with 2cos^2xsin^2x

[leaden otter]

You mean cos⁴(x)+sin⁴(x)=1???

[latent gust]

well i broke it into (cos²(x)+sin²(x)) (cos²(x)+sin²(x)), and I could very much be wrong

[leaden otter]

Try squaring both sides of this equation

[leaden otter]

(cos²(x)+sin²(x))(cos²(x)+sin²(x)) is the whole of left side including 2sin²(x)cos²(x)

[latent gust]

no, not including

[leaden otter]

Yes it is

[latent gust]

oh

[leaden otter]

(a+b)(a+b)=a²+2ab+b²

[latent gust]

oh

Right, that makes a lot more sense

[latent gust]

I didn't notice that! Thank you so much

.close

[cedar kiln]

Channel closed

Closed by @latent gust

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed due to the original message being deleted

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[agile quail]

Can someone explain where 3+root3 came from

[agile quail]

<@&286206848099549185>

[lusty zephyr]

You get it if you factorise the quadratic

Actually no

Actually yes

[lusty zephyr]

Just use the quadratic formula

[agile quail]

it says using calculus tho

so how does the derivative show the vertexes

[cedar kiln]

@agile quail Has your question been resolved?

[livid hound]

solving y' = 0
gives you the location of stationary points

the calculus component was getting y'

[cedar kiln]

@agile quail Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rugged aurora]

$\cos a = b \ a = \cos^{-1} b$ is this true?

[wraith dagger]

Limón

[graceful karma]

Yes

If -1 means the inverse of cosine

[cedar kiln]

@rugged aurora Has your question been resolved?

Channel closed

Closed by @rugged aurora

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[copper oyster]

Angles - what would a 67° be counted as?

[short blade]

what do you mean

[copper oyster]

What would it be

Acute or something else?

[short blade]

what does acute mean?

[copper oyster]

Idk

[short blade]

that’s a good place to start

find out what acute means

[copper oyster]

Okay

Give me a moment

Acute angles measure less than 90 degrees. Right angles measure 90 degrees. Obtuse angles measure more than 90 degrees.

[short blade]

so from those definitions

what does 67 fall under

[copper oyster]

Acute

It's not accurate though

I measured again

It said 66°

[short blade]

so where does that fall under

[copper oyster]

My friend is saying it's 68°

Acute

[short blade]

where do those all full under

yes so whichever it is, it’s acute

[copper oyster]

Ok

Ty

.close

[cedar kiln]

Channel closed

Closed by @copper oyster

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lime lava]

.close

[cedar kiln]

Channel closed

Closed by @lime lava

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

How did they come to this judgement.

[crimson sedge]

oh

its simply if y = 0, x = -1/2

.close

[cedar kiln]

Channel closed

Closed by @mortal elm

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sharp summit]

hello
i have to find the expression that determines the function

[crimson sedge]

find change of gradient

find any given point and substitute to y - y1 = m (x - x1)

and check on symbolab to confirm your answer

or simply check by substituting values of x to retrieve the original number of y

so if you substitute x = 0, then you should get 4 for y.

if you substitute y = 0, then you should get 4 for x.

I wont tell you how to construct the expression. You just have to figure it out

[sharp summit]

i see

ty

[crimson sedge]

you're welcome, please use mathsgenie or examsolutions!

and do lots of practise problems

[sharp summit]

sure!

.close

[cedar kiln]

Channel closed

Closed by @sharp summit

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mild ore]

how to construct an isosceles triangle knowing the length of the base and one base angle?

[mild ore]

can someone please help me out?

[main needle]

you're given this right?

[mild ore]

yup

[main needle]

one fact of isoceles triangles is that the angles at the base are equal

[mild ore]

yup

[main needle]

since it's mirror symmetric across

[mild ore]

I'm sorry?

[main needle]

that gives you the triangle

[mild ore]

how should i construct that?

[main needle]

I mean that both the left and right side look the same

[mild ore]

yup i know that

[main needle]

I'm not sure what you mean by construct then

[mild ore]

how can I get the same angle on the second side too without manually measuring the angle using a protractor?

[main needle]

oh you mean physical straight-edge construction

[mild ore]

yeah

I think that's it

[main needle]

the only thing you can do is a perpendicular bisector, and that just works I think

[mild ore]

where should I draw it?

[main needle]

hm?

isn't there only one place it can be

[mild ore]

I'm not sure where that is

all I have is this

I know the red angle and the black base

[main needle]

do you know how to construct a perpendicular bisector?

[mild ore]

yup its a line that goes through the center of another line in 90° right?