help-13

[brisk drum]

and -2

[crimson sedge]

where do u get -1 and 1

[brisk drum]

in a*b

since that is 1, then x must be 2 so that (1*1)^2 = 1 and( 1+1)^2 = 4

[crimson sedge]

solve for a and b first

[jovial parcel]

how did u got -2?

[crimson sedge]

by solving

[jovial parcel]

it's not matching

try to substitute it

oh sorry

it's correct

my bad

[brisk drum]

am i going mad or smth

a+b = 4 has no solution? maybe im just overloaded idk where im doing wrong

in the system i switched a+b=1 to a= 1/b, then substituted it for a in the a+b=4 but it gives me no solution

[crimson sedge]

a+b=4
a*b=1 cant you solve this?

yes a=1/b you put in and get 1/b + b = 4 multiple by b b^2-4b+1=0 then solve quadratic

[brisk drum]

oh dude yeah

multiply not jst substitute

ok one sec

[crimson sedge]

i will go offline after 10 mins

[brisk drum]

ah its okay then, ill just try to continue on my own

im a lil busy so i dont wanna keep the channel away from others

.close

[cedar kiln]

Channel closed

Closed by @brisk drum

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[meager dome]

I have gotten this far with the question but now I am stuck with the total and the cheese sections does anyone know how I can work these out?

[cedar kiln]

@meager dome Has your question been resolved?

[meager dome]

<@&286206848099549185>

[meager dome]

.close

[cedar kiln]

Channel closed

Closed by @meager dome

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rancid swift]

4-88 plz

I don’t even know where to begin

[cedar kiln]

@rancid swift Has your question been resolved?

[cedar kiln]

@rancid swift Has your question been resolved?

[regal sentinel]

Try relating the rotations to the circumference of the tire

[rancid swift]

Is there a certain formula for that

[regal sentinel]

circumference?

C = 2 pi r

[rancid swift]

I’m not sure how knowing the radius and rpm is going to give me the speed

Is there a formula I need to know

[regal sentinel]

If you change rotations per minute to inches per minute by calculating circumference then you could convert that to miles per hour?

[rancid swift]

16/166360

[cedar kiln]

@rancid swift Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[low jewel]

hi does this look like the correct region of integration for the following double integral?

[placid thistle]

It's 4 bro

If I gotta guess

[cedar kiln]

@low jewel Has your question been resolved?

[low jewel]

<@&286206848099549185>

after looking again, I think this is a more accurate region of integration?

[cedar kiln]

@low jewel Has your question been resolved?

[cedar kiln]

@low jewel Has your question been resolved?

[leaden otter]

Shouldn't it be more like this?

[low jewel]

what about the original equation y?

woudlnt that be a part of the region of integration?

@leaden otter thanks for the response though

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[main sage]

I am stuck, i don't know how to proceed

But i know the answer is A

[cedar kiln]

@main sage Has your question been resolved?

[cedar kiln]

@main sage Has your question been resolved?

[shell cloud]

So you expand the top and you get cosx +cos^2 x + sin ^2 x. And you can combine cos^2 x + sin ^2 x to get 1 making the numerator cosx +1

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[chilly shuttle]

How do you do trig identities (prove both sides equal) for this

[cedar kiln]

@chilly shuttle Has your question been resolved?

[cedar kiln]

@chilly shuttle Has your question been resolved?

[chilly shuttle]

<@&286206848099549185>

[leaden otter]

Try dividing by cos²(x) on both numerator and denominator of LHS

[cedar kiln]

@chilly shuttle Has your question been resolved?

[jovial parcel]

the right hand side will become (1+tanx)^2/(1-tanx)^2 after putting sec^2x=1+tan^2x.now put tanx=sinx/cosx

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

@rotund fjord Has your question been resolved?

Channel closed

Closed by @rotund fjord

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed due to the original message being deleted

[sudden hawk]

hi need help with this question

[tropic oxide]

have you made any progress so far?

[sudden hawk]

18x + 106

for 3.

for a im confused

[tropic oxide]

looks correct

i suppose they just want you to factor out a number from this

[sudden hawk]

yea, im unsure how to do it tho

[tropic oxide]

find the greatest common factor of 18 and 106

[sudden hawk]

wait let me try and see what i get one secon

i got 2 as the gcf

but for part a wouldn't the answer be something like y = a(x-r) (x-s)?

because i got 18x - 106 and im pretty sure it answers a

*3.

[tropic oxide]

here the expression is linear in x so it cannot be written as a(x-r)(x-s)

[sudden hawk]

oh okay, so that means the answer i have is for part a?

im confused then what does the first part of the question want me to answer?

[tropic oxide]

maybe they are looking for 2(9x+53)

nothing else comes to mind

[sudden hawk]

ohh that makes sense

wait let me try solving this and let me know if my answer is correct

i got 232, is that right?

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[opaque umbra]

Is the vectors: OB - OA, AB or BA

[cedar kiln]

@opaque umbra Has your question been resolved?

[opaque umbra]

<@&286206848099549185>

[cedar kiln]

@opaque umbra Has your question been resolved?

[eager elk]

OB-OA means the B point measured from A

so tell me what should it be AB or BA?

[opaque umbra]

BA?

is this wrong?

[eager elk]

ok, what's OA mean? vector O from A or A from O?

[opaque umbra]

O to A?

But its minus so i flipped it

[eager elk]

so now how would you write "B from A"

[opaque umbra]

AB?

[eager elk]

yes

make sure you have understood

[opaque umbra]

why is it AB

[eager elk]

well there are two possible answers so

[opaque umbra]

can u draw a diagram

@eager elk

[eager elk]

not atm, no

[opaque umbra]

whats wrong here?

[eager elk]

well OB-OA=BA => OB-BA=OA. you -BA vector is pointing in pointing in the opposite direction

[opaque umbra]

OB-OA=BA yea but dont u flip OA

whats wrong

[eager elk]

ig alright

[silk swift]

isn't OB - OA = AB?

OB - OA = OB + AO = AB

[eager elk]

yes

[opaque umbra]

but i dont understand

i drew that figure right

and then i flipped OA because its negative

[eager elk]

u did

[opaque umbra]

then using tip to tail method I Get BA

[eager elk]

yes

[opaque umbra]

what is wrong

[eager elk]

that's correct

[opaque umbra]

u said its AB

[eager elk]

no I said you write B vector from A as AB

didn't say that was the answer

[cedar kiln]

@opaque umbra Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vast gull]

Simplify
i) 322/391
ii) 247/209
iii) 117/156

[vast gull]

Ping when replying

[obsidian coral]

Find the GCM of the numerator and denominator

[vast gull]

GCM?

[obsidian coral]

Greatest common multiple

[vast gull]

Kk

[vast gull]

It's 23

Correct?

[obsidian coral]

Yes

[vast gull]

So 23 is the answer?

[obsidian coral]

Not the final answer

That's the GCM

Divide the terms by that GCM

[vast gull]

How to find final answer

[vast gull]

Like 322 ÷ 23 and 391 ÷ 23

[obsidian coral]

Yes

And stop ping replying

[vast gull]

Alr

[vast gull]

Answer is 14/17

Thanks for helping

.close

[cedar kiln]

Channel closed

Closed by @vast gull

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[steep basin]

Solve the following LPP by graphical method Minimize z = 5x1+4x2 Subject to constraints 4x1+ x2 ≥ 40 ;
2x1+3x2 ≥ 90 and x1, x2 > 0.

[cedar kiln]

@steep basin Has your question been resolved?

[crimson sedge]

and all they can say is

why are you so sad kid

thats what the mask is

thats what the poiNt oF tHe MaSk is

[sage frost]

no dream song 🔫

[crimson sedge]

but they told me to make dreams come true

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

In a 20-floor house, an elevator has two buttons. Pressing "UP" gets the elevator up 13 floors; pressing "DOWN" gets the elevator down 8 floors. Is it possible to get from the 13th floor to the 8th floor?  [If pushing a button would mean going to a floor that does not exist, the elevator does not move (e.g. pressing “UP” on the 10thfloor).]

[crimson sedge]

please someone help

[silk swift]

Isn’t it very obvious

Like from 13th you can only go down

13 ↓ 5 ↑ 18 ↓ 10 ↓ 2 ↑ 15 ↓ 7 ↑ 20 ↓ 12 ↓ 4 ↑ 17 ↓ 9↓ 1 ↑ 14 ↓ 6 ↑ 19 ↓ 11 ↓ 3 ↑ 16 ↓ 8

There’s no other way

[cedar kiln]

@crimson sedge Has your question been resolved?

[crimson sedge]

right

i see

is there an easier way to think about it tho?

@silk swift

[silk swift]

What do you mean

[crimson sedge]

like without making the list
13 ↓ 5 ↑ 18 ↓ 10 ↓ 2 ↑ 15 ↓ 7 ↑ 20 ↓ 12 ↓ 4 ↑ 17 ↓ 9↓ 1 ↑ 14 ↓ 6 ↑ 19 ↓ 11 ↓ 3 ↑ 16 ↓ 8

[graceful karma]

You could prob get a list of possible solutions by finding integer solutions for 13+13u-8d=8

It could still go above though

And that'd be real nasty

[crimson sedge]

i don't think that that is the way

[graceful karma]

I mean it's a way

[crimson sedge]

yeah

[graceful karma]

,w integer solutions 13+13x-8y=8

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by PapaBread#3820

[crimson sedge]

sometimes i shouldn't overthink it

[graceful karma]

So yeah n=0 ends up as the solution

You'd have to find a way to manually eliminate stuff

Like for example you can't ever go down twice in a row

So at the very least every other thing has to be a down

So if ups+downs<ups/2 then you can eliminate

That's super overthinking it though prob

Do you have any more context?

Like is this for a certain type of class

[crimson sedge]

how is this solutionj

This is a really simple problem because there is only possible path:

13 ↓ 5 ↑ 18 ↓ 10 ↓ 2 ↑ 15 ↓ 7 ↑ 20 ↓ 12 ↓ 4 ↑ 17 ↓ 9↓ 1 ↑ 14 ↓ 6 ↑ 19 ↓ 11 ↓ 3 ↑ 16 ↓ 8 

Therefore, it is possible.

@silk swift

[silk swift]

I made like 4 edits on that list lol

My calculation is rusty you may need to recheck

[crimson sedge]

ok

i will check

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[graceful karma]

I mean wolfram agrees with your solution

Or at least the number of ups and downs

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

wait, what?

[cedar kiln]

@crimson sedge Has your question been resolved?

[crimson sedge]

@graceful karma

what did you mean

[graceful karma]

That wolfram alphas solution was potentially the same as his

[crimson sedge]

this @graceful karma

[graceful karma]

Yes

[crimson sedge]

what does it show

[graceful karma]

All of the possible solutions

[crimson sedge]

how?

[cedar kiln]

@crimson sedge Has your question been resolved?

[crimson sedge]

@graceful karma

are you still there

[graceful karma]

It's just showing the possible solutions of 13+13a-8b=8

[cedar kiln]

@crimson sedge Has your question been resolved?

[crimson sedge]

The question says find the point of intersection of the two functions in red

This is how i did it but I'm not sure if it is correct

[cedar kiln]

Channel closed

Closed by @little wave

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dense pilot]

i need to find the area of the shaded part

[humble cipher]

incorrect
line 2
-4(5-x) = -20 + 4x

[crimson sedge]

-20 +4x?

[humble cipher]

yeah

-4*5 = -20
-4*(-x) = 4x

[crimson sedge]

Oh yeah that's a stupid mistake

Damn

But it's the correct way to approach the question right?

[humble cipher]

yeah

[cedar kiln]

@dense pilot Has your question been resolved?

[humble cipher]

are the lines going from the corners of the square towards the middle supposed to be in a 45 degree angle?

[dense pilot]

the lines are going from the corners of the square but the angle isnt given and they arent necessarily going through the middle, just the end and start are in the corners

[humble cipher]

Not possible

[dense pilot]

...

if u make the angle between the 4.5 line and the first 2 line smaller it evetually becomes a square

[humble cipher]

oh i get what you mean

the first picture was confusing

[humble cipher]

Yeah ive no clue how to solve that sorry

[cedar kiln]

@dense pilot Has your question been resolved?

[cedar kiln]

@dense pilot Has your question been resolved?

Channel closed

Closed by @dense pilot

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[elfin drift]

for this question I got -1.5 but it says im wrong. Can anyone point out what I did wrong?

[short blade]

not if we can't see your work

[elfin drift]

ok hold up

sorry for the messy handwriting

[short blade]

you divided wrong on the right side

10/15 =/= 1.5

[elfin drift]

but isn't negative 10 divided by 15 negative 1.5?

[short blade]

no

-15 divided by 10 is 1.5

but not -10 divided by 15

[elfin drift]

OH YES

now I know what I did wrong

I put the smallest number on top

instead the bottom right

[short blade]

-10/15 is correct

but -1.5 is not

[elfin drift]

wait but I thought a negative divided by a positive is a negative

[short blade]

it is

$\frac{10}{15}$

[wraith dagger]

maximo

[short blade]

$\frac{10}{15} = \frac{2\cdot 5}{3\cdot 5}$

[wraith dagger]

maximo

[short blade]

the fives cancel out

and you're left with 2/3

[elfin drift]

ok

thx

.close

[cedar kiln]

Channel closed

Closed by @elfin drift

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cedar kiln]

@agile relic Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[untold comet]

What am I doing wrong?

[cedar kiln]

@untold comet Has your question been resolved?

[cerulean star]

your coefficient is wrong

also I think you should simplify, it lowers the chance of a false negative

[untold comet]

how is my coefficient wrong

[cerulean star]

you decremented the exponent but not the coefficient

brain fart

you forgot

[untold comet]

what

[cerulean star]

it's a common error

[untold comet]

i don't know what you mean

i did it the way i was taught

[cerulean star]

your exponent is 0.53

and so should your coefficient be

[untold comet]

0.53W^0.53?

[cerulean star]

yeah

the 0.12 is still out front too, but you should simplify

[untold comet]

0.12(0.53)W^0.53

[cerulean star]

yeah

[untold comet]

so the answer is

0.0636w^0.53

[cerulean star]

try it

[untold comet]

i'm on my last attempt

if i miss it i get it wrong

[cerulean star]

I would have tried this on my first attempt. Pretty confident.

[neon star]

I’d do what he says

[cerulean star]

🔫

[untold comet]

capital w?

[cerulean star]

yes. Match the variables in the original problem

[untold comet]

it was wrong

[cerulean star]

screenshot

oh...

[untold comet]

I'D Do WhAt He SaYs

[cerulean star]

oh, relax...the important thing is we understand the concept

[untold comet]

this is my grade bro

[cerulean star]

so I think the problem here

[untold comet]

it was my fault for trusting a random guy on the internet for help

[cerulean star]

lol, sorry man

but I think this is an implicit differentiation problem?

what unit is this from

[neon star]

What grade r u guys in

[cerulean star]

$\frac{dC}{dt}=0.0636W^{0.53}\frac{dW}{dt}$

[wraith dagger]

Disorganized

[cerulean star]

solve for dW/dt

$\frac{dW}{dt}= \frac{2500}{159}W^{-0.53}\frac{dC}{dt}}$

[wraith dagger]

Disorganized
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[sly hornet]

maybe the question is wrong?

have u tried writing it using index notation?

bu changing the exponent to a fraction and simplifying after

[cedar kiln]

@untold comet Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[civic coral]

i have a weird question

[civic coral]

how'd i know (x-1)^4 divided by (x-1)^3 would have a remainder or not?

also i know 2^4 divided by 2^3 has no remainder

its kinda abstract without expanding the whole (x-1)^4 and (x-1)^3 then put it into long division to see if it has a remainder or not

[silk swift]

because (x-1)^4 = (x-1)^3 * (x-1)

[civic coral]

then the (x-1) is the quotient i guess

[silk swift]

a = qb + r but as you write it r is obviously zero

yeah

[civic coral]

what if its (32)(x-1)^4 divided by (x-1)^3

(32)(x-1)^4=(32)(x-1)^3 * (x-1)

so i guess it still has no remainder

ohhh i got another question

does (x-1)^2 divided by (x-1)^3 has a remainder

[silk swift]

when we talk about remainder the number we work with are integers I think

so you can say the quotient is zero and remainder is (x-1)^3

if (x-1) is integer

[civic coral]

what if the remainder isn't integers

i dont get it

[silk swift]

it is like that by definition I think

[civic coral]

i didnt know that remainder has to be integer

[silk swift]

remainder only make senses in the integer realm

[civic coral]

okay

[silk swift]

obviously 5/2 = 2.5 in the real set, no remainder

oh I just look it up

there's actually remainder definition on the real realm too

sorry

[civic coral]

the remainder is negative (x-1)^3

its wrong right?

god, what is the remainder when (x-1)^2 being divided by (x-1)^3

Am I right

[cedar kiln]

@civic coral Has your question been resolved?

[cedar kiln]

@civic coral Has your question been resolved?

Channel closed

Closed by @civic coral

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[civic coral]

Can someone put it on wolfram for me

is it 1023?

[wraith dagger]

LeonNeol

[eager elk]

yes

[cedar kiln]

@civic coral Has your question been resolved?

Channel closed

Closed by @civic coral

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hard ginkgo]

doesn't this mean that there are two increasing subsequences of the same length? eg
8, 11, 9, 1, 4, 6, 12, 10, 5, 7
here:
1, 4, 6, 12
5, 7, 8, 11
i don't see how
an increasing subsequence of length i_t + 1 can be built
follows, considering the fact that i_k is the length of the longest increasing subsequence

[tropic oxide]

what the proof is saying is this:

there is an increasing sequence of length i_t starting at a_t, by the definition of i_t
in the case that a_s < a_t, if you prepend a_s to this sequence, you will get a sequence with one more term, which will go in contradiction with the assumption that i_s = i_t

[hard ginkgo]

prepend?

[tropic oxide]

append at the beginning

[hard ginkgo]

alright

thanks

.close

[cedar kiln]

Channel closed

Closed by @hard ginkgo

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[barren harness]

Need help

[silk swift]

#❓how-to-get-help

[tropic oxide]

@barren harness you should actually post your question instead of just going "i NeEd HeLp" and not saying anything else

oh, you posted something in another channel

.close

[cedar kiln]

Channel closed

Closed by @tropic oxide

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[modest scroll]

How can we show that arctan of (-1/sqrt3) equals -pi/6

[wraith blaze]

what do you know about sin(-x) and cos(-x)?

and what would that tell you about tan(-x)

[sly iris]

so you wish to solve:

[modest scroll]

wouldnt that make sin(-x) = -1 and cos(-x) = sqrt 3 as tan is sin over cosine

[sly iris]

tan(x) = -1/sqrt(3)

for x within the range of the arctangent function

what is the range of the arctangent function

it is the interval (0,pi)

[modest scroll]

this is what the problem showed, I was able to find the answer by giving up but cant see how the last step converts from the arctan (-1/sqrt3)=-pi/6

[sly iris]

do you have a unit circle graph

[modest scroll]

yes

[sly iris]

it's pretty easy to verify

you will only really be asked about the values of these functions at very specific points

when is sin(x)/cos(x) = -1/sqrt(3) for -90<x<90?

i apologize.

[modest scroll]

oooh i see pi/6 is where the cos is -1/sqrt3

[sly iris]

the range of the arctangent function is -90 to 90

[modest scroll]

we just need to convert the sqrt out of the denominator which gives us that value

thanks that helped a lot

.close

[cedar kiln]

Channel closed

Closed by @modest scroll

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pale hazel]

how do i approach these problems

[abstract pollen]

@pale hazel That's a lot of questions. What have you tried?

[pale hazel]

i tried 9a

by making it arg(z-2) - arg(z) = pi/2

[abstract pollen]

Ok good

[pale hazel]

i dont know where to go from there

[abstract pollen]

Can you tell me in words what that means?

First what z and z-2 are

[pale hazel]

z is rcisθ and z-2 is z shifted to the point 2+0i

[abstract pollen]

How do they look generally on an argand diagram?

[pale hazel]

a line at origin

θ degrees from the horizontal

for z

and z-2 is that but on the point (2,0)

[abstract pollen]

z is just an arbitrary complex number

Its any number in the form of x+iy

[wraith dagger]

Xetrov

[abstract pollen]

and z-2 is that point shifted two units to the left

[abstract pollen]

This statement is correct and means that considering angles at the original, they're separated by pi/2

[pale hazel]

so what would it look like?

[abstract pollen]

Play with this and look for points where the two lines form a right angle

[pale hazel]

i looked at the answers

OHHH wait i get it now

if you move it around it forms the path of a semicircle

[abstract pollen]

yep

[pale hazel]

okay thank you so much

for your help

[abstract pollen]

There are a few shortcuts and as you go through them, you'll see them

[pale hazel]

okay thank you

[abstract pollen]

no problem

.close

@pale hazel can you close?

[pale hazel]

.close

[cedar kiln]

Channel closed

Closed by @pale hazel

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[harsh onyx]

can I get some help

[chrome slate]

#❓how-to-get-help

[harsh onyx]

this was free

so i took it

nvm i need to read 😂

[harsh onyx]

I have solved a) i and ii

but i am getting stuck at b

[chrome slate]

What did you get as an answer on a) ii?

[harsh onyx]

2(l+b)

so

2(x+(x+5)

= (4x+10)

[chrome slate]

right

in b, they tell you that the perimeter is 21.6cm, that means you can equate this number with the expression you found under a) ii, amd solve for x

[harsh onyx]

my unit is quadratic expressions

i have to get it in that form

like x+x2+21.6= 0

like that

[harsh onyx]

example

[chrome slate]

oh no, its just 4x+10=21.6

[harsh onyx]

oh

but what bout x2

x+10-21.6= 0

x+2.5-5.4= 0

[tropic oxide]

when you say x2 are you trying to say x squared?

bc that's written x^2

[harsh onyx]

ye

[harsh onyx]

sorry

x^2

[tropic oxide]

can you show what your expression is for the area?

just to make sure you got that right

[harsh onyx]

x(x+5)

cm^2

[tropic oxide]

okay

so, you have P = 4x+10 and A = x^2 + 5x

in part b you are told that the perimeter is 21.6 cm

[harsh onyx]

yes

[tropic oxide]

are you able to find the value of x?

[harsh onyx]

4x+10= 21.6

4x+10-21.6

4x-11.6

?

[tropic oxide]

why did you write 4x+10-21.6 and not 4x+10-21.6=0?

[harsh onyx]

oh shi

[tropic oxide]

sounds like you're either overthinking things or don't know how to solve a linear equation.

[harsh onyx]

i forgot

[harsh onyx]

i doooo

know how to solve these equations

4x+10-21.6= 0

[tropic oxide]

okay, so keep going

[harsh onyx]

4x-11.6= 0

[tropic oxide]

i want you to solve this equation and tell me the value of x

[harsh onyx]

4x= 11.6

x= 2.9?

[tropic oxide]

yes, excellent

[harsh onyx]

i think its wrong

oh

[tropic oxide]

oh?

why do you think it's wrong?

[harsh onyx]

yay

[tropic oxide]

why do you think it's wrong? do you think one of your steps was done incorrectly?

[harsh onyx]

this is the 1st time I did it this way

[tropic oxide]

so you didn't actually think it was wrong, you were just not confident that you did it right.

there's a big difference between these.

[harsh onyx]

yes

🥲

[tropic oxide]

okay anyway you showed all your work so i can tell you that what you did is legitimate

now that we know x = 2.9, are you able to find the area?

[harsh onyx]

4(2.9)+10?

no its giving me 21.6

so this is not the way

will I have to use x(x+5)

[tropic oxide]

you want the area

which of the expressions 4x+10 and x(x+5) represents the area?

[harsh onyx]

x2+5x= 2.9

[tropic oxide]

no!

[harsh onyx]

5x+x^2-2.9= 0

[tropic oxide]

no!!!

you don't want "if the area is 2.9, what is x?"

you want "if x is 2.9, what's the area?"

[harsh onyx]

yes

[tropic oxide]

you don't need to solve a quadratic equation for this...

all you need to do is calculate the value of x(x+5) when x=2.9

[harsh onyx]

there r 2 x's

x(2.9+5)?

[tropic oxide]

so what that there's two x's

this shouldn't deter you

unless you are allergic to the concept of replacing x with 2.9 in more than one place

[harsh onyx]

= 7.9x?

(2.9+5)= 7.9

x*7.9

[tropic oxide]

no... why are you replacing one of the x's with 2.9 but not the other

[harsh onyx]

umm

2.9(2.9+5)?

2.9(7.9)

= 22.91

OMG yess this is the answer

[tropic oxide]

is this your first time evaluating an expression with more than one x in it

[harsh onyx]

yes

I have never done questions like this b4

[tropic oxide]

that's weird.

[harsh onyx]

im in 8th...

[tropic oxide]

anyway whatever i guess we can move on

[harsh onyx]

yes

[tropic oxide]

to part c

unless you wish to do it yourself

[harsh onyx]

if the area is 176 cm^2, what is the perimeter

[chrome slate]

wouldnt say thats weird at all considering the fact that they needed help solving the problem

but ight go on

[tropic oxide]

i'd say "evaluate this expression" is a much easier task than "solve this equation" even if the expression is 'complicated' by virtue of containing multiple instances of x

anyway

[harsh onyx]

[tropic oxide]

do you see how to proceed here?

[harsh onyx]

yes

now we use (4x+10)

[tropic oxide]

i'm not asking you to calculate or solve anything, but i want you to say what you're setting out to do.

[harsh onyx]

cause we findin perimeter

[tropic oxide]

what equation you are going to solve, for example.

[harsh onyx]

4x+10= 176

[tropic oxide]

no

[harsh onyx]

oh

[tropic oxide]

does it say "the perimeter is 176"?

no it doesn't say "the perimeter is 176"

it says "the area is 176"

[harsh onyx]

4(176)+10?

[tropic oxide]

no!!!!!

x isn't the area!!!

[harsh onyx]

yup that was wrong

[harsh onyx]

o

[tropic oxide]

try to THINK instead of just plugging random shit into random places until it sticks.

such trial and error is no way to do math.

[harsh onyx]

damn im sorry

[tropic oxide]

Area = x^2 + 5x
Perimeter = 4x + 10
x = width of rectangle

Area = 176

if you keep all this in mind or on paper, it should be clear that the way to proceed is to write x^2 + 5x = 176

you should write down on paper what you know and what you want to find or do

not having a clear goal in mind will mean you can never solve any math problems ever

[harsh onyx]

I cant understand this

[tropic oxide]

please tell me which part you don't understand

[harsh onyx]

we did the area but now perimeter

[tropic oxide]

parts b and c are completely unrelated. calculations from part b will not have anything to do with part c.

.....

[harsh onyx]

sorry

[tropic oxide]

did you read what i wrote up there?

[harsh onyx]

176/2

[tropic oxide]

yes or no

did you read what i wrote up there? yes or no

[harsh onyx]

no

[tropic oxide]

why not?

do you think i said it all just for fun?

[tropic oxide]

read this and tell me if you don't understand something

[harsh onyx]

176/x?

that will give me 1 side

[tropic oxide]

???

can you at least articulate clearly what you're trying to do?

[harsh onyx]

I have got the area

i hv to find the length and width

[tropic oxide]

first and foremost you 'have to' find the value of x.

[harsh onyx]

yes

[tropic oxide]

because that's what your sides are expressed in terms of

do you understand how to find the value of x, yes or no

[harsh onyx]

i do

[tropic oxide]

okay, tell me how to find the value of x

i don't want you to actually go and find the value of x, only tell me what you'll do to find it.

[harsh onyx]

2x= 172?

[tropic oxide]

?????

where are you getting that from?

[harsh onyx]

oh wait I have to find the dimensions

[tropic oxide]

minus x1

[harsh onyx]

yes

[tropic oxide]

are you actually paying attention to the things i'm telling you

bc i think you aren't

[harsh onyx]

i am

[tropic oxide]

did you read this?

[harsh onyx]

i did

[tropic oxide]

and this?

[harsh onyx]

x is width

[tropic oxide]

answer my question

[harsh onyx]

oh I dint see that

[tropic oxide]

BRUH

how can i know what you did and didn't see

[harsh onyx]

wait a minute

wait wait

[tropic oxide]

should i say everything three times to make sure it gets across

[harsh onyx]

oh no what have I done

I used area to find perimeter and perimeter to find area

oh no

5x+x^2= 176

5x+x^2-176= 0

x+x^2-35.2= 0?

this is gonna be wrong

[tropic oxide]

did you try to divide both sides by 5?

[harsh onyx]

u mean 0/5?

[tropic oxide]

i mean exactly what i said

you now started with the correct equation, but then you did some nonsense

and i'm trying to get you to understand why and how what you did is nonsense

[harsh onyx]

x+x^2= 35.2

[tropic oxide]

no

this is incorrect

[tropic oxide]

this one is ok

[tropic oxide]

this one is not

[harsh onyx]

-35.2

[tropic oxide]

will you listen to me or not?

how many times do i have to say things before you react to them???

[harsh onyx]

bro

176/5

[tropic oxide]

don't call me bro.

so you tried to divide both sides by 5, yes?

[harsh onyx]

sorry

[tropic oxide]

so you tried to divide both sides by 5, yes?

[harsh onyx]

both sides

so like 0/5

[tropic oxide]

that's not the issue

0/5 is 0 and you got that right

[harsh onyx]

yes

[tropic oxide]

but for some reason x^2 was completely unaffected

even though it would have become x^2/5

but it didn't and that's your screwup that i've been trying to point out

and all this is even assuming we want to divide both sides by 5 in the first place, which if you ask me is kind of pointless here!

[harsh onyx]

x(x+5)= 176
x^2+5x-176= 0 or 5x+x^2-176= 0

x+x^2/5-32.5= 0

what is x^2/5

[tropic oxide]

/ is the symbol for division...

[wraith dagger]

Ann

[harsh onyx]

yes

[tropic oxide]

i think i'm unable to get anything across to you

[harsh onyx]

this is division yes

so

what is x^2/5

[chrome slate]

we dont know its value, x could be any number

If thats what you meant

[tropic oxide]

spicy, do you want to take over

can you maybe try to teach minus x1 how to solve the equation x^2 + 5x = 176 without taking a detour into pointlessness

[chrome slate]

kinda busy rn, but ill help you later today if you still dont get it

[cedar kiln]

@harsh onyx Has your question been resolved?

[harsh onyx]

but its ok

Im done

i'll do it by my self

[gilded tulip]

help please!!!

[chrome slate]

have you found an expression for dx in terms of u?

[cedar kiln]

@harsh onyx Has your question been resolved?

[harsh onyx]

Hey @tropic oxide I am sorry, I was reading the question the wrong way thats why I dint understand

[harsh onyx]

yup

[cedar kiln]

Channel closed

Closed by @harsh onyx

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[thorn grail]

pls help

[thorn grail]

pls ping me

[zinc mason]

solve f'(x) = 0

[thorn grail]

Idk how. I tried subbing in pi and pi/2 and they don't work

[zinc mason]

you can express $\cos 2t$ as $1-2\sin^2t$

[wraith dagger]

kiid

[thorn grail]

I'm still confused

[zinc mason]

$-2\sin t + 2\cos 2t = -2\sin t + 2(1-2\sin^2 t) = -4\sin^2 t - 2\sin t + 2$

[wraith dagger]

kiid

[zinc mason]

it becomes a quadratic so you can solve for t

[thorn grail]

There

There's no other way to solve it other than trig identities?

I kind of forgot them in calculus

[zinc mason]

you can graph the function other than that i dont think there are other ways

[thorn grail]

What trig identities do I need to know in general for these types of questions?

[zinc mason]

it varies so just know everything i guess

https://studylib.net/doc/25307827/trig-cheat-sheet-reduced

[cedar kiln]

@thorn grail Has your question been resolved?

[thorn grail]

dear lord

thanks for the help

[cedar kiln]

Channel closed

Closed by @thorn grail

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vagrant minnow]

help

[cedar kiln]

@vagrant minnow Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cerulean star]

@kindred crystal do you have a specific questions or are you just plopping your nob on the table and hoping someone will come by and

[cedar kiln]

@kindred crystal Has your question been resolved?

[kindred crystal]

Just the first one?

I might be able to understand it if someone does that

[cerulean star]

ok, what have you tried

the solution doesn't require logarithms

just laws of exponents

[cedar kiln]

@kindred crystal Has your question been resolved?

[kindred crystal]

I will try that thanks a bunch

[cedar kiln]

Channel closed

Closed by @kindred crystal

Use .reopen if this was a mistake.

[cedar kiln]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[teal quail]

Hello

[teal quail]

Can you take 90 degree as theta in a triangle?(basic trigonometry

[graceful karma]

@teal quail Wdym

[teal quail]

I am asking if this question is broken or not basically

Can you take the right angle as theta

[graceful karma]

I mean yeah

It won't give you much useful info for a triangle but sin and cos both can take 90

[crimson sedge]

This question looks kinda sus.

[graceful karma]

Yeah it does

A is the point not the angle

But I can't imagine A is anything else

[teal quail]

Well, a is also like angle a question mark?

[graceful karma]

Maybe

Well cos(90)/sin(90)=0

[crimson sedge]

But cos(90°) = 0.

Yeah.

[graceful karma]

So I guess try that

[crimson sedge]

oH wait, that exists as a choice.

Lol, didn't even see that.

[teal quail]

But if this is true, then what side is adjacent, what is opposite, what is hypotenuse

[graceful karma]

Nada

In traditional triangle trig you can't do anything with the right angle

It just has to be there for it to work

In the background

[teal quail]

Ok

[graceful karma]

Triangle trig still isn't the extent of trig though

So the answer is still 0

Despite it not meaning anything on the triangle

[teal quail]

Thanks a lot

Close

Did I close?

.close

[cedar kiln]

Channel closed

Closed by @teal quail

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[old hearth]

3 + 8 ( 2 - 6 ) = 2 +14

[crimson sedge]

any thoughts on what you think you could start with?

[old hearth]

distrubute?

[crimson sedge]

I would probably simplify the right side as thats just addition and then do the bracket

[old hearth]

what numbers would i simplify tho?

[crimson sedge]

whats 2+14

[old hearth]

16

[crimson sedge]

okay

so u now have 3 + 8 ( 2 - 6 ) = 16

[old hearth]

okay

[crimson sedge]

now do the bracket as that comes first in the order of operations

[old hearth]

its mutlipacation?

i'll brb

[crimson sedge]

well first do the inside of the bracket

and then multiply what’s outside of the bracket (8) with what ur left with inside the bracket

[old hearth]

huh?

im confused

[crimson sedge]

this is the order of operations

so if you had something like (5+2) -8 * 8

u would do the brackets first

so you’d have 7-8*8 now

then you’d do multiplication and you’d have

7-64

and then u simplify that so u have -57

so with your equation :3 + 8 ( 2 - 6 ) = 16

[old hearth]

ohhhhh

okay

[crimson sedge]

do the brackets

[old hearth]

3 + 8 = 4

?

[obsidian coral]

Um, what?

[old hearth]

I did the brackets

[obsidian coral]

But where did 3 + 8 = 4, come from?

[old hearth]

This

[obsidian coral]

No where does it say 3 + 8 = 4

There isn't even a 4

[old hearth]

i subtracted 2 and 6

[obsidian coral]

But where did the equal sign come from?

And 2 - 6 is not 4

[old hearth]

its -4

srry

@crimson sedge

what do i do now?

[crimson sedge]

yep -4

[obsidian coral]

Now explain the equal sign part

[crimson sedge]

so now u have 3 + 8 ( -4) = 16

[old hearth]

o

okay

[obsidian coral]

I'm confused on what the goal of this question is

[old hearth]

its algebra

[obsidian coral]

But what is the goal?

Are you checking to see if the left side equals right side?

[old hearth]

thats what i dont understand

my teach is confusing

[obsidian coral]

Do you have the actual question?

That you can post a picture of

[old hearth]

yes i did

I have it written down but I don’t understand how it was solved

[obsidian coral]

Do you have the actual question?

[old hearth]

that is the queston/

[obsidian coral]

Like if it was typed on paper, can you post a picture of it?

[old hearth]

it wasnt?

[obsidian coral]

Because I don't understand what you wrote

[old hearth]

its 3 + 8 (2 -6) = 2 +14

[obsidian coral]

No it's not, that can't be right

Why is there 14t? Or whatever that symbol next to 14

[old hearth]

its not t its a postive 14

[obsidian coral]

But what's that symbol next to 14? Positive?

[old hearth]

yes

it is

[obsidian coral]

You're missing too much information, like the actual question itself from the teacher

[old hearth]

that is the queston.

its not a worded queston.

[obsidian coral]

So what's the goal?

Because that question doesn't make sense

Like I said not enough details

[old hearth]

how im i ment to know if she doesnt even say what the goal is?!

[obsidian coral]

I'm telling you, that question is missing too much information

[old hearth]

how can i grab informantion if she doesnt even say what it is

[obsidian coral]

Like are you seeing if the left equals right?

[old hearth]

idk probaly

[obsidian coral]

Did you miswrite it? Because you could be missing variables

[old hearth]

i didnt at all thats what it showed

[obsidian coral]

I suggest, talk to your teacher

[old hearth]

mk

.close

[cedar kiln]

Channel closed

Closed by @old hearth

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wheat merlin]

Know that to solve 1 you'll require (-b/2a,f -b/2a ) that only works on quadratics not quartic's, so how do I solve no.2

[loud parcel]

x² * (...)

[wheat merlin]

So
x^2 (-x^2+x+2) ?

But then what

how do i work out the first part

[loud parcel]

the last term ist wrong

[wheat merlin]

*2

[loud parcel]

now it's right

and you can now use the fact that for: x * (...) = 0
x = 0 AND/OR (...) = 0

And because (...) is quadratic... 😉

[wheat merlin]

still get the wrong answer aftere

got 0.5,2.75

hmm

[loud parcel]

How do you solve the quadratic in the brackets?

[wheat merlin]

(-b/2a,f -b/2a )

[loud parcel]

,w -x^4+x^3+2x^2=0

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Moriarty#2262

[loud parcel]

well, looks right

[wheat merlin]

looks like ive misused this?

[loud parcel]

,w extrema -x^4+x^3+2x^2

[wraith dagger]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Moriarty#2262

[cedar kiln]

@wheat merlin Has your question been resolved?

[wheat merlin]

<@&286206848099549185>

[cedar kiln]

@wheat merlin Has your question been resolved?

[cedar kiln]

@wheat merlin Has your question been resolved?

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[wheat merlin]

.reopen

[cedar kiln]

✅

[cedar kiln]

@wheat merlin Has your question been resolved?

[crimson sedge]

i think ur trying to use quadratic formula but u dont need that to factorise the quadratic u had in the bracket

u have x^2 (-x^2+x+2)

so factor the bracket (-x^2 + x + 2)

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sudden hawk]

2(3x+2)(3x-2y) - (3x-y)^2

[sudden hawk]

how do we solve this using special products?

.close

[cedar kiln]

Channel closed

Closed by @sudden hawk

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[woeful spear]

a man has 2x^2 apples and every day he adds the derivative of his amount of apples. How many apples does he have on day 7?

[cedar kiln]

@woeful spear Has your question been resolved?

[abstract gale]

Is that it? The entire question?

[floral thistle]

unique question

[cedar kiln]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed due to the original message being deleted

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson sedge]

i need to understand the idea of what to do

[glad kestrel]

p/q

that ring a bell?

[crimson sedge]

no

[glad kestrel]

quite unfortunate

that's the rational zero theorem

so i'm not quite sure why you're doing questions on it without learning it

[crimson sedge]

my inability to remember what was said in class and also falling asleep contributed to this

[graceful karma]

I didnt learn it as p/q

[glad kestrel]

if i'm not mistaken, that's what it's supposed to be taught as

$\frac{\text{factors of constant}}{\text{factors of leading coefficient}}$

[crimson sedge]

it was, but its hard to learn it when my lazy ass was asleep so thats my problem

[wraith dagger]

a disappointing son

[glad kestrel]

gives you your rational zeroes

then use synthetic division to see if it's actually a zero

[crimson sedge]

this is painful to ask

how do i do synthetic division

[glad kestrel]

https://www.youtube.com/watch?v=FxHWoUOq2iQ

this good man will tell you

[graceful karma]

Long division is easier 😎

[crimson sedge]

thank you

wait

i remember this

just by the thumbnail

too vague have to watc hthe video

[cedar kiln]

@crimson sedge Has your question been resolved?