geometry-and-trigonometry

[upper karma]

thats why i was confused

[copper marten]

-4 = -3x+2
subtract 2 from both sides
-6 = -3x
divide by -3 on both sides
2 = x

[upper karma]

iuh

oh

[copper marten]

did that make sense

[upper karma]

oops

yea kinds

[copper marten]

ur trying to find x so u want x to be by itself in the equation

[upper karma]

still processing but I'll fully get it soon

[copper marten]

ok

[upper karma]

Given h(x)=−2x+4 solve for x when h(x)=−8

so are we finding what goes into -8?

so is it -12? because -12+4 = -8 @copper marten

Bro pls help

<@&286206848099549185>

[vague orbit]

imagine being sorry about other people's "problems"

[humble pulsar]

Ok guess you didnt want help after all

[vague orbit]

NO, I DIDN'T

It was a test

a failed one

[humble pulsar]

Oh so you wanted to cheat on a test?

[vague orbit]

LOL ur absent minded

[humble pulsar]

That explains the lack of patience

[vague orbit]

U literally didnt even interpret what I said correctly

no wonder

"it was a test"

I'm the one testing

[humble pulsar]

No shit sherlock

read the rules next time

[vague orbit]

Yeah, "Cheated on a test" my ass

Lol "READ" next time

[humble pulsar]

If you want to be pathetic and breach academic integerity, try another server

[vague orbit]

Dude ur IQ

it's sad

u literally are 100% wrong in this situation

I just explained that I wasn't cheating

I'm not going to explain

to the ppl here who (jeez) understand will see you the way u are

[olive cove]

@vague orbit Don't just come here and insult people. That's extremely rude.

If you don't agree with someone be polite.

[vague orbit]

sorry, emotion influences my execution

[copper marten]

-8 = -2x + 4
subtract 4 on both sides
-12 = -2x
divide by negative 2 on both sides
6 = x

@upper karma sorry i was in my class

[upper karma]

its alr I get it

[copper marten]

okok

[upper karma]

can u show me first step to this? Given h(x)=-x+2, find h(4)

[copper marten]

ok so ur given h(4)
and in the parentheses of h(x) it is x so 4=x
plug in 4 as x in the given function

so h(4)=-4+2
and then simplify the right side of the equation

[upper karma]

so -2?

[copper marten]

yup

h(4)=-2

[upper karma]

divide 4 both side?

i mean 2

[copper marten]

no

[upper karma]

oh

[copper marten]

h(4) isn’t a number exactly

it’s just like a variable

[upper karma]

oh

[copper marten]

no need to divide

it’s just saying when x is 4, it equals -2

[upper karma]

oh

so the answer -2?

[copper marten]

yeah

[upper karma]

alright thanks!

[copper marten]

no prob

[upper karma]

are we supposed to multiply for this one? Given g(x)=−3x−5, find g(-4)

[copper marten]

g(-4) = -3(-4) - 5

just plug in -4 where there is x

yeah ur supposed to multiply ^

[upper karma]

12-5=7?

[copper marten]

yes

g(-4)=7 is the final answer

[upper karma]

oh

thanks

[copper marten]

mhm

[upper karma]

I get how to find g and all of that but the other way is harder to process

[copper marten]

which process?

or which way is hard?

[upper karma]

the solve for x

im going see if i can do this one

Given f(x)=3x−1, solve for x when f(x)=-7

oops

[copper marten]

finding x explanation:
make ur equation look like this:
x = __

[upper karma]

are we subtractig?

misspelled the word

[copper marten]

for the equation u just sent?

[upper karma]

I mean add

yeah

[copper marten]

no ur subtracting and multiplying

f(x)=-7 means x=-7

[upper karma]

o

[copper marten]

so plug in -7 as x and solve

ur only working on the right side of the equation

[weary drift]

that's not quite what it means

[copper marten]

i meant it this equation ^

[upper karma]

but there's an -1

[copper marten]

yeah so -3(-7) - 1

[upper karma]

oh

so 20

[copper marten]

yeah

[upper karma]

20 divide by 3?

[copper marten]

no

[weary drift]

we're finding values of x so that f(x)=-7, not finding f(-7)

[copper marten]

ohhh

[weary drift]

we start with f(x)=-7. we're told f(x)=3x-1, so we can replace f(x) with that to get 3x-1=-7. we then solve for x

[upper karma]

oh yeah

[upper karma]

so 4x3-1=7?

[upper karma]

does that look right?

i mean 4x2-1=7

hold up confusion

im trying see what number can go into 3 times

[weary drift]

we're using x as a name for an unknown quantity, not as a symbol for multiplication

[upper karma]

oh

[upper karma]

can u go through this wit me?

sorry to waste ur time

[paper valley]

anybody know how to do this

[trim breach]

Have you learned to solve triangles using trigonometric ratios?

Since you are given the angles, you have to determine which ratio you need to use to get leg GH.

[weary drift]

@upper karma i'm not available to sit down and help but i'll recommend you go through any notes you have on solving algebraic equations

[upper karma]

i've got it done already

[strange wigeon]

how are these proven to be isoceles triangles?

*i drew the blue marks

[trim breach]

Were you given any information in the problem?

Like, it is not immediately evident to me, if there is even a way do conclude that, anything is isosceles until it is known that the outside shape is a rectangle.

Or at least some other piece of information is given.

[strange wigeon]

Well I came to the conclusion of, since parallelograms have parallel sides, thats how they are isoceles

[torpid hearth]

In a rectangle, parallel sides are equal in length

[strange wigeon]

Always right

[torpid hearth]

if you draw one bisector, you can form a right triangle

[strange wigeon]

Which theres 2, so 4 right triangles

[torpid hearth]

If we give names to each side of the rectangle we can calculate the length of the (green) bisecting diagonal

drawing a second bisecting line we find that the two lines are equal

This is the new diagram that we have:

[strange wigeon]

would a+b=180 inside here?

[torpid hearth]

yes, the angle of a line is 180

so a = x and b= 180 - x

okay final part of the proof

[strange wigeon]

Hmm cause i was trying to do this earlier

Someone told me to divide the rectangle in half to get that x = 60

[torpid hearth]

what's the 120 pointing to?

[strange wigeon]

The angle

[torpid hearth]

oh yeah

[strange wigeon]

Cause 180-60=120

And i tried to do 120/2 which is 60 for both sides but that doesnt add to 180

[torpid hearth]

okay

[strange wigeon]

I thought thats what you do with iscoceles triangles

[torpid hearth]

there are 3 angles in a triangle

one of the angles is 120

and the sum of the angles equal 180

finally, since the triangle is iscosocles the two base angles are equal

[torpid hearth]

can you find an equation for x?

[strange wigeon]

Apparenty i had to do this to get x

[torpid hearth]

???

what's that

[strange wigeon]

#help-1 message

read from here

[torpid hearth]

huh

do you want me to tell you how i would've approached it?

[strange wigeon]

yeh

[torpid hearth]

how many angles does a triangle have?

[strange wigeon]

3

[torpid hearth]

so would you agree with this?

sum of angles = angle 1 + angle 2 + angle 3

[strange wigeon]

yes

[torpid hearth]

and what's the sum of angles in a triangle?

[strange wigeon]

180

[torpid hearth]

180 = angle 1 + angle 2 + angle 3

we are given that 180 is the angle of a line, and 60 is one part of that angle

[strange wigeon]

yea

[torpid hearth]

you solved for the other part:
180 = 60+unkown
180 - 60 = unknown
120 = unknown

[strange wigeon]

yes

[torpid hearth]

okay so that's one angle

go back to the equation that i put up earlier

180 = angle 1 + angle 2 + angle 3

we can subsitute one angle with 120

180 = 120 + angle 2 + angle 3

subtracting 120 from both sides gives

180 - 120 = angle 2 + angle 3
60 = angle 2 + angle 3

@strange wigeon do you agree with this?

[strange wigeon]

So 30 for each

[torpid hearth]

how do you know to divide by 2?

not that you're wrong tho

[strange wigeon]

Explain that part tho

divide by 2 cause 2 unknown angles i suppose

like 2a=60

[torpid hearth]

well

[strange wigeon]

a=30

[torpid hearth]

those angles could be different

we need to prove that bisecting a rectangle produces an iscoceles triangle

#geometry-and-trigonometry message

[strange wigeon]

Could they tho? we're talking about a rectangle

[torpid hearth]

yea

ik

[strange wigeon]

Which it always does right?

[torpid hearth]

yep, it's a theorum

I was just making sure you knew

[strange wigeon]

Alright that makes sense now

[torpid hearth]

yep

angle 2 = angle 3

[strange wigeon]

Splitting in half is odd

[torpid hearth]

60 = 2(angle)

[torpid hearth]

wdym?

[strange wigeon]

Kinda odd but just extra

but it makes sense

[torpid hearth]

kk

[strange wigeon]

cause of 306090

suppose to be 30's and 60's but

drawing with finger

[torpid hearth]

LMAO

[strange wigeon]

lol

[torpid hearth]

OH

i see what you were doing now

[strange wigeon]

yeh

thats what the other guy was saying

I was clueless

[torpid hearth]

xD

he basically used the proof for 30 60 90 triangles to solve a problem

it works, but is really hard to understand

[strange wigeon]

Yeah i get it though,45,45,90 aswell

they both make sense

[torpid hearth]

yee

aight imma head out

https://tenor.com/view/glhf-scout-team-fortress2-team-fortress-video-game-gif-5378995

[strange wigeon]

alright

https://tenor.com/view/ight-imma-head-out-spongebob-imma-head-out-ima-head-out-gif-14902967

[inland mountain]

Anyone good at explaining trig?

[upper karma]

https://cdn.discordapp.com/attachments/486841106298961930/822509265083302009/unknown.png

[trim breach]

What type of lines are GA and GB?

[upper karma]

someone already helped me with this

if you can help me with this it would be nice

[trim breach]

Ah.

[silent plank]

distance formula for the radius

and you should know what the standard form for eqn of a circle is

[inland mountain]

So had would I get x for this I've been very confused

[humble pulsar]

what trig ratio relates the 50 and x side with the 22 deg angle?

[copper marten]

reference angle is 22 degrees, use SohCahToa to find which ratio u should use

[hidden crescent]

when are the diagonals of a parallogram perpendicular to each other\

[west basin]

if all side lengths are equal

they are perpendicular

[hidden crescent]

is cos-1(-5/2) possible

inverse cos

[trim breach]

If you think about the domain of arccos, (-5/2) is not in it.

[hidden crescent]

ok

[shadow hedge]

I need help figuring out, what is 6 times 6

[karmic kraken]

I think it’s like 23 or something

[inland mountain]

Trig ratio?

[dark sparrow]

@shadow hedge http://lmgtfy.com/?q=what+is+6+times+6

[night vigil]

Help, Im trying to find the answer to this problem:

so basically

A circle has chord length 18

40cm from center

what is radius

[dark sparrow]

make a diagram

[night vigil]

Well, the question didnt come with a diagram

[dark sparrow]

so what

[night vigil]

ok ok

[dark sparrow]

it's not like your hands will wither away

crude and wildly not to scale

[night vigil]

oh

ok

well

Oh now its so obvious just pythagorean

Thank you!!

[dark sparrow]

yw

this is why 90% of the time the solution to a geometry problem is to draw the diagram ftr

[night vigil]

Ok

Hmmm, There are only two angles

[mint dune]

~Opposite angles of a cyclic quadrilateral are supplementary~

are you allowed to use that statement

[night vigil]

I dk this is a pre test

but probably

[mint dune]

you can probably use that lol

idk tho dont sue me

[night vigil]

so 85 degrees?

[mint dune]

yeah

[night vigil]

lol

ok

[mint dune]

the answer is definitely 85, but im just saying that idk if youre expected to know that theorem

[night vigil]

well

I think well learn it

so

maybe

Also are there any tangent theorems

tangent triangles

with vertex at center of circle?

[mint dune]

huh

[night vigil]

like an iscoceles?

hmm

lemme show you

[mint dune]

tangent triangles?

yes pls

[night vigil]

this

height is 6?

[mint dune]

well, theres no relation in general but there sure is in this case

[night vigil]

so pythagorean?

4?

oh

[mint dune]

yes height will be 6

[night vigil]

X = 4 then?

[mint dune]

and it will be aright triangle since the 8 8 thing is a tangent

sooo uh

wait

yeah 4

[night vigil]

mk

[vague orbit]

<@&286206848099549185>

What is the diameter

[pure cape]

What have you tried

And ping after only a min of 15min of unactivity

[vague orbit]

umm

I got 34

wait no

36

[pure cape]

Can you show your work?

[atomic delta]

Does this equation hold for conic sections other than ellipses?

[dark sparrow]

seems to give you a hyperbola for e > 1

[atomic delta]

wait so it does work?

[dark sparrow]

at first glance yes

but this won't give you parabolas

[atomic delta]

i see, thanks

[woven haven]

360/12= 30
30 x 15= 450

[upper karma]

how do i solve this

<

[trim breach]

Late reply…this question is basically testing how much you know about a rhombus. All sides are of equal length in a rhombus, and the diagonals are perpendicular. Try to see what you can figure out with this information.

[trim atlas]

hi, does anyone know a material that explains basic theorems, axioms, definition, etc.. that are used to write proofs?

[wise pulsar]

Bruh trig kinda hard ngl

[upper karma]

how do i find a "clean" expression for alpha in terms of theta

like i can get a very ugly looking expression using some sines and cosines law but it just ends up being an absolute mess

[livid moss]

Show what you got and how

It's possible it can't be cleaner

[upper karma]

mhm one sec

like it's not really a school problem that i can submit and say "yes this is α in terms of θ"

im kinda trying to use it in a physics problem and using that would (probably) be hell

ignore L_B

[livid moss]

I can't read any of that

[upper karma]

okok hm

[upper karma]

oh the result was wrong lol

but the right result isnt any cleaner

[livid moss]

This doesn't look like it has a clean result

[upper karma]

idk if you can read it now but i tried my best lol

[upper karma]

awe

[livid moss]

That looks clean enough lol

[upper karma]

ok but i need sin(α)

and ill have to deal with bunch if square roots

ugh

ty !

[livid moss]

Instead of using sin rule on 90° + α, use cos rule

Unless you need cos(α) too anyway

[upper karma]

oh

that works

one sec

better than what i expected

ty <3

[livid moss]

Np

[vale urchin]

what is this ive been thinking for like 5 mins

"iscocoles right triangle with legs 20 cm in length find the hypotenuse

[sacred elbow]

I need some help with this

[vale urchin]

hell

[sacred elbow]

Do u know how to do it ?

[lethal sigil]

Minecraft

[willow crypt]

roblo

roblox

[river hazel]

yo i need help badly

[hot meteor]

I've been working on this question for the past forty minutes and I can't work it out. Does anybody know if this is possible and not a trick question? The mark scheme says that x=7.5 (2sf)

oh my god

[versed narwhal]

:/

[hot meteor]

well folks, be sure to check if your rendition of the question is the correct one

[versed narwhal]

w8

[hot meteor]

as your software may mess up the question B)

[versed narwhal]

which one should i try

[hot meteor]

the first one is impossible to solve i'm pretty sure

but i just found the second one (the correct interpretation)

[versed narwhal]

oh

[hot meteor]

i'll be okay now. thank you for the offer though ^_^

[versed narwhal]

k

[tired pine]

compare the radii of the circles

[versed narwhal]

help for number 16

[main lintel]

What have you tried?

[versed narwhal]

i got it

[main lintel]

@versed narwhal How you solved it. It is pretty interesting problem. I got this:

The last equation on the right gives sinA=sin(2E)/2

[versed narwhal]

some1 else got 4

x = 4

bc i haven't learned sin stuff yet

so we prob aren't tested on it

[main lintel]

Did you got the angles as I did?

Wait BED is right triangle

[crude patio]

hey

i have a problem that i'm stuck on i just honestly dont know how to solve it in general

[mint dune]

pythagoras theorem

[surreal ingot]

What is different between evaluate and evaluate the integral?

Is there a different?

[mighty shell]

Integral means whole number, evaluate the integral means find the whole number. If your answer is not a whole number you done something wrong. @surreal ingot

[tribal galleon]

8^(2)+y^(2)=12^(2)

[regal whale]

can someone help me with this?

I know that a regular polygon is equlangular and equlateral

and convex

and a polygon would be equal to 180?

[mint dune]

connect all the vertices of the polygon to the center. that'll help you find the sum of an interior angle

[silent plank]

sum of exterior angles is 360°

[river python]

hi

i have no idea

how to do this

or this

idk how to get perimeter and area

[silent plank]

applying stuff like trig formula for area
and cosine rule

[river python]

oh

i have no idea how to do that

[silent plank]

those terms are alien to you?
you're being given these questions without being taught the methods required to solve them?

[wintry tundra]

area = 1/2 ab sin C

of any triangle

[river python]

yea

our teacher is

crazy

[wintry tundra]

i somehow doubt that u didnt get any of this info

[river python]

we know sin

[wintry tundra]

but anyways just use the area formula

[river python]

and cosine

and tan

[silent plank]

if you know about sine, it isn't a huge leap to derive the trig area formula yourself

[river python]

wait so is it

area = 1/2 14x19 sin C?

[silent plank]

you are given C

[river python]

c is 60?

[silent plank]

capital C

[river python]

ok so is it

area = 1/2 14x19 sin 60?

[silent plank]

yes

[river python]

ok thanks

weait wat

i got -40

@silent plank

[silent plank]

check whether your calculator is in degrees

[river python]

sorry fr the ping btw

oh i was in rad

@silent plank what abt the perimiter one

[silent plank]

cosine rule/law to get the 3rd side

then add your sides up

[river python]

whats the law

like is it

[river python]

SAS right?

but idk the law

[silent plank]

google cosine rule/law

[river python]

yea i got it

tysm

[upper karma]

So, I was wondering what the formula for this type of angle was, I couldn't find an example of this online

[upper karma]

anyone?

[lunar hull]

am looking at it

[upper karma]

alrighty

[lunar hull]

do you have an option for 110?

[upper karma]

It isn't a multiple choice question, but I was just wondering what formula is used to solve it

How'd you get to 110?

[lunar hull]

yeah I'm venturing a guess here but I think it's just 180 - 70

I'll draw a pic if you want

[upper karma]

wait, really?

A picture might be helpful yeah

[upper karma]

Ohh, I see how you did it now, thank you so much

[terse dove]

sad times

let sin = Math.sin(angle);
let cos = Math.cos(angle);
line.x2 -= line.x1;
line.y2 -= line.y1;
line.x2 = line.x2 * cos - line.y2 * sin;
line.y2 = line.y2 * cos + line.x2 * sin;
line.x2 += line.x1;
line.y2 += line.y1;
line.angle += angle;

can someone please tell me why this makes the line shrink when you rotate it?

lmao

[tiny snow]

Cumulative error?

[terse dove]

big oof

im guessing math.sin and math.cos are a bit inaccurate

[tiny snow]

@terse dove You have an error in the following statement:

line.y2 = line.y2 * cos + line.x2 * sin;

line.x2 has already been modified in the previous line.

This will work as intended:

  let sin = Math.sin(angle);
  let cos = Math.cos(angle);

  let x2 = line.x2 - line.x1;
  let y2 = line.y2 - line.y1;

  line.x2 -= line.x1;
  line.y2 -= line.y1;
  line.x2 = x2 * cos - y2 * sin;
  line.y2 = y2 * cos + x2 * sin;
  line.x2 += line.x1;
  line.y2 += line.y1;
  line.angle += angle;

Fiddle: https://jsfiddle.net/u9x8h3yn

[terse dove]

HOLY

TYSM MAN

I SHALL BE SURE TO CREDIT U

literally almost gave up

l e g e n d

[waxen glen]

im trying to understand trigonometry, tan is 1 here, what do 1 mean? area of green shape?

or length of this side

[humble pulsar]

From what Ive seen tan is usually defined as the distance from A to the x axis via the tangent

[waxen glen]

@humble pulsar

you mean this?

[humble pulsar]

read what I wrote

I meant what I said

[stiff tulip]

Hiiii so my geometry teacher has been out of service for the past 2 weeks and she hasn’t taught us anything about this?

Am I suppose to subtract two from the Y values when I reflect the points across the Y-axis?

[mighty shell]

just assume the y=-2 there is a horizontal line and reflect the shape over it

[stiff tulip]

Oh

So like I have reflect over (0,-2)

[mighty shell]

yea

pretty much

[stiff tulip]

Wait wat

[mighty shell]

wait nvm i am not too sure

wait for smeone else sorry

[stiff tulip]

No it’s ok

I’m just confused on how to plot this then lol

Nvm someone just told me

Yeah you were right

I was confused about it going over the pre-image but yeah he just told me it will overlap lol

[mighty shell]

oh alright nw

[upper karma]

tan is the slope, I don’t think it represents anything from the image.
If you like a visualization of tan then I suggest going to https://www.mathsisfun.com/sine-cosine-tangent.html and scroll down

you should be able to play around

[waxen glen]

oh

i understand now

thanks

[upper karma]

np

[limber ice]

Hi

How do I solve cos(2x) = 2/pi

I'm completely stuck and this is for a section of my calc homework...

[silent plank]

the values in that question seem a bit questionable

can you double check whether you copied it correctly

[waxen glen]

i think answer is (rounded to tenth) 0.5

cos goes to right which is 2x = arccos 2/pi

and x is equal to = (arccos 2/pi)/2

@limber ice

[serene obsidian]

hey

what is the perimeter of a triangle if two sides are 27 and 37 inches and the included angle is 82 degrees. perimeter needs to be rounded to nearest tenth too

[silent plank]

what have you tried?

[serene obsidian]

i know i need to apply a trig formula

im not sure which one

cos?

[silent plank]

yes. cosine rule/law

[serene obsidian]

kk

[silent plank]

will get you the 3rd side

[quick junco]

How do I solve a problem like this?

[vast python]

A. our teachers wants us to make a table of coordinates

[waxen glen]

https://www.desmos.com/calculator it will help

@vast python

[tiny snow]

@quick junco All three triangles are similar, so you can set up ratios between the sides.

[quick junco]

Thank you !!

[waxen glen]

there is formula for that, 60= root of 36x

3600=36x

x is 100

ignore writings

@quick junco

[quick junco]

Thank you!!

[mighty shell]

i do not have calucaltor on me but all you have to do is use the cos rule since u got included and angle and two sides

then added the answer with 27 and 37

the final answer should have 1 d.p

[agile venture]

What have you tried?

[brisk sierra]

im confused for 8-10

[upper karma]

HI i’m learning the same thing do you know how to solve them i need help too

[urban barn]

pls help

[urban barn]

nvm

[upper karma]

use soh cah toa to find that lenght, in this case tan = opposite/adjacent

then use pythagoream theorem to find yz

[tiny snow]

@urban barn You can use similar triangles and set up ratios for the corresponding sides.

[gusty terrace]

so whats is the answer?

nvm

[urban barn]

Tks

[meager karma]

can some1 help

[wanton phoenix]

Would law of Cos work?

[meager karma]

ya but can u elaborate

my brain = small i tried doing it but it’s wrong apparently

like just explain the steps and i can do it

[wanton phoenix]

Like do bsq= asq+csq -2acCosB

Just plug in the numbers basically and it should work

Also make sure ur calc is in the correct mode for trig

And then find the square root of ur result

[meager karma]

tyyyy

[wanton phoenix]

Np

[rough stone]

anyone here to help answer my question for trig?

[rough stone]

16sin^2theta-4=0

I was able to break it all the way down to sin 1/2

but I get confused on the intervals

0</=theta</equal2pi

I believe it is in quadrant four but I'm not sure which radian to use

[storm portal]

$\sin(\theta) = \frac{1}{2}$ then $\theta = \frac{\pi}{6}, \frac{5\pi}{6}$

[somber coyote]

Shen

[storm portal]

@rough stone

[upper karma]

is this in the right category

😭

[trim breach]

Givens always go first.

And your statement about the congruency should, logically, go last.

[trim breach]

Angle-side-angle means you have two congruent angles with a congruent side in between.

So which option shows the side between the angles are congruent?

[upper karma]

b?

@trim breach

[trim breach]

Yep!

[upper karma]

ty ❤️

oh shoot i thought i was on last question i have 1 more can u help w/ this 1 too

cuz this asa and aas thing i dont rly understand

i understood all the other theorms its just this

[trim breach]

So, these theorems for proofs basically explain themselves. ASA is angle-side-angle, which means that there is a congruent angle, then a congruent side, and then another congruent angle.

They have to be in that order though.

[upper karma]

so b and d?

[trim breach]

Yes!

[upper karma]

ur a genius

ilysm

[trim breach]

❤️

A and C are both AAS, by the way.

[upper karma]

yeah cuz there is no side in between correct?

[trim breach]

Yep.

[vivid tangle]

can anyone help in thiss thank uu....we r basically learning abt proportions, angles, ratios in case that helps sooo we need to make proportions and solve for x

[trim breach]

So because there are parallel lines, there are similar triangles. For example, triangle MPQ is similar to triangle MSR.

Using this, you can set up a proportion to solve for an unknown side.

If the length of line PQ is x, then:
(x/5) = (5/8)

Which is:
(PQ/SR) = (MQ/MR)

You can use this to solve around the diagram until you have enough information to solve for MT.

[vivid tangle]

ahhhh alrightt how did u get 5 for SR?

[spring swan]

Can sum 1 help w this plz

The words are under the picture btw

[waxen glen]

i think you need to use tan here, so tan(28)= 66/x (x is the lenth of first triangle's base) tan(72) = 66/z (z is the length of the second triangle's base) and you find x and z here

x-z is the answer

[spring swan]

Ok thanks

[dense storm]

Yep, you need to use tangent for this

[trim breach]

My bad — that was an error in my reading the diagram. Ignore the proportion where I set up x; the “second”, conceptual one is right, but you don’t necessarily have the right information to solve it right away.

[north sandal]

Anyone know how to do part d?

I tried to prove the scalar resolute of BO is half of the magnitude of BC but the numbers I got don't satisfy that

[obtuse tapir]

A triangle ABC is drawn to circumscribe a circle of radius 4cm such that the segments BD and DC into which BC is divided by the point of contact D are of length 8cm and 6 cm respectively. find the sides AB and AC

[tiny snow]

@obtuse tapir The solution is not that hard if you draw a sketch and know some properties of inscribed circles.

(although the resulting lengths are not neat numbers)

[lavish torrent]

no format given?

[silent plank]

do you know your right triangle trig?

[boreal badge]

well id assume the hypotenuse is 3, as it's the radius the corner would be sin() = o / 3

And the tangent would be the negative reciprocal of the hyp but idk how to calculate the coordinates from there

@silent plank

[silent plank]

use something like t to represent theta

similar to a point on the unit circle, the coordinates of P would be (r*cos(t), r*sin(t))

[boreal badge]

is that a formula i should know?

(rcos(t), rsin(t))

[silent plank]

somewhat yes.

[boreal badge]

okay ty

[silent plank]

you should be familiar with the coordinates of a point on the unit circle in terms of theta

[late swan]

could someone help

my brain is gonna explode trying to answer this

[neon hamlet]

Is it possible to find FP? I got 6.36 but im not sure if this is right.

https://gyazo.com/2f095dcce66452a6e44463f9163526b2

[waxen glen]

yes

[trim breach]

I haven’t worked it out, but it should be possible.

[waxen glen]

so there are 6 triangles

APF and FPB are congruient , APD and PEB are congruient, DPC and CPE are congruent

[neon hamlet]

I did the pythargoem theorem with triangle CDP

and then got CP

which is 2/3 of FP

but all the options are in whole numbers

[waxen glen]

wait a min

[neon hamlet]

all the options

[waxen glen]

as i know if bisector is heigh too, it is median too

and it equal triangle

let me check it

so

you can find

[kindred rover]

How would you find |FH| with only the angle and length of the hypotenuse?

[neon hamlet]

right

[waxen glen]

@neon hamlet i think i share you false picture but you can find it

just search properties of perpendicular bisectors

you will understand what i mean

[neon hamlet]

so its possible?

[waxen glen]

i think so

[neon hamlet]

alright thanks

[waxen glen]

you need to use trigonometry things

you need opposite side

and you have hypothonuseblabla

from sin,cos,tan, which one of them has opposite side and hypo?

@kindred rover

[kindred rover]

Cos?

Sorry my bad, sin

[waxen glen]

just remember SoH Cah ToA

it is easier

yes it is sin

so sin (36)= FH/43

can u solve it?

or do you need help

[kindred rover]

Yeah all good, thanks man appreciate it 👍

[waxen glen]

[obtuse tapir]

they are

I know the solution

its just that im looking for new methods

the most popular method is doing it through area

which i find lame

i tried trig

but

tan(x)=6/4 is a hard thing to solve

[tiny snow]

Yes, I had to resort to trig, but that gives you an ugly arctan in the end. Note that the triangle is not drawn to scale.

,w 4/(arctan(pi/2 - tan(4/6) - tan(4/8))

[somber coyote]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Roenbaeck#4166

[obtuse tapir]

law of sines maybe

[tiny snow]

That'd be x in my sketch... so, what's the exact expression with that ugly decimal approximation?

[obtuse tapir]

i don't know

the answer is 15, 13

the conventional method is to

express the triangle's area with heron's formula

then equate it with

the usual base*height

[tiny snow]

Really? Then I must have drawn the sketch wrong given the info?

[obtuse tapir]

maybe

should look something like this

[tiny snow]

I swapped the lengths of BD and CD, but that shouldn't matter.

Hmm.. <ACB = 2tan(4/6) and <ABC = 2tan(4/8), so <CAB = Pi - 2tan(4/6) - 2tan(4/8), right?

Also, <CAB = 2tan(4/x)

[obtuse tapir]

shouldnt it be noted as tan(ocd)=4/6

[tiny snow]

You're right, I'm mad 🙂

,w 4/(tan(pi/2 - arctan(4/6) - arctan(4/8))

[somber coyote]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Roenbaeck#4166

[tiny snow]

Corrected

Can't believe I just mixed up tan and arctan...

[warm sphinx]

Can someone teach me Trig Identities?

[storm portal]

@warm sphinx googling them will help a lot

https://tutorial.math.lamar.edu/pdf/Trig_Cheat_Sheet.pdf

https://trigidentities.net/

[obtuse tapir]

my guy

can you tell me this without the notation

[upper karma]

can someone help pls

<@&286206848099549185>

[steel raft]

someone tell me if negative angle makes sense here been a while since i did geometry

[silent plank]

no. negative angles don't make sense here

[steel raft]

do i have to approach the problem as if its not a kite?

trying to help a friend out but its been a whiel since i did geometry stuff

[silent plank]

does the page explicitly say what shape it is?

[steel raft]

there is no right triangle symbols or congruent symbols so its confusing no it donesnt

[silent plank]

in the context of the problem, i.e for it to be doable, it would be safe to assume that it is a kite

[steel raft]

if i aussed its a kite then when i solve the sytem i get negative angle and if its isnt a kite apperantly the problem doesnt say anythign else

[silent plank]

what values are you getting

(for x and y)

[steel raft]

9x+8y=11; 5x-27=6y i get 3 and -2

[silent plank]

yeh ok. there's an issue with the problem

[steel raft]

yeah thats what i thought

ty

[teal mica]

can anyone explain how they came up with the domain of [0,180] please?

[trim breach]

In terms of degrees, [0, 180] should be range, right?

I think that is just wrong, unless I am missing something.

[warm sphinx]

Ty @storm portal

[storm portal]

🙂

[upper karma]

anyone tryna help me

[ashen phoenix]

i wrote cpctc and diagonals bisect each other which creates 2 congruent triangles for no.3

[upper karma]

Asking for x

[waxen glen]

@ashen phoenix 3. is rigt, 4. answer is 52 bcs diagonals are perpendicular

so they made 4 90 degree angles

[tepid musk]

So I was doing some origami and stumbled on this. If you fold a diagonal and then fold triangles, the point were the lines intersect, it will give you the point to fold the paper in n pieces.

I graphed it and created formulas, the dotted lines are where you fold to get, say a square paper folded in three parts

Could someone maybe enlight me on why this is so? What's even more fascinating is that these points have both x and y coordinates of 1/3, 1/4 etc

[ashen phoenix]

thanks a lot @waxen glen !

[upper karma]

Yes,it is

thanks

[upper karma]

Wait I guess I solved it

we can't solve it without using sin30

[misty ermine]

$sin^2(\frac{\theta}{2})* cos^2(\frac{\theta}{2}) = \frac{1}{4} sin^2(\theta)$

[somber coyote]

moar55

[misty ermine]

i found this in the solutions of some exercise

how is this possible?

[silent plank]

poor place to write those exponents,
but double angle identity

[misty ermine]

cool thx

[tepid musk]

Uh, a cannot be both the circle's radius and half of the square's side length. Am I wrong?

Since the square's side length is a chord rather than the diameter of the circle

[humble pulsar]

yes in that diagram they're different

[tepid musk]

oh wait, someone already said that, never mind

[upper karma]

2a is equal to one side of the square and the radius of the quarter circle

[tepid musk]

Ah, but why is there an a between O and the smaller ciricle's circumference?

[upper karma]

because we need to use sin30

I hope I explained it well

If you have anything on your mind, you can ask

[tepid musk]

👍

[late swan]

prove: sin(θ) * cos(θ) * tan(θ) = 1 - cos ^ 2(θ)

guys please help

[pure cape]

what is tan(theta)?

in terms of sine and cosine

[late swan]

yes

i need to prove the left and right side

[pure cape]

yes, but that didnt answer my question

[late swan]

i know its true i just dont know how to explain it

wdym then

[pure cape]

there is another way you can express tan(theta)

in terms of sine and cosine

are you familiar with tan(theta) = sin(theta)/cos(theta)?

[late swan]

not really

this is all its asking

[pure cape]

yes

i know

again, thats not what im saying

[late swan]

oh

[pure cape]

what im saying is that you need to rewrite tan(theta) as sin(theta)/cos(theta)

[late swan]

ohhhhh

that makes sense

[warm coyote]

is anyone avaliable to call

cause

i need help badly

[late swan]

can I write sin^2 (theta)??

[pure cape]

wdym?

[waxen glen]

bro what is sin
what is cos

[warm coyote]

https://i.gyazo.com/6ac6b2151d3245e64c30b7b284f68a09.png

[waxen glen]

oh

[waxen glen]

do you know properties of parallelogram

[warm coyote]

no

[waxen glen]

[warm coyote]

i guessed'

[waxen glen]

it would be better to learn properties first

[warm coyote]

see my teacher isnt a good teacher

he makes shit complicated

[waxen glen]

you can learn from youtube/websites

[warm coyote]

i literally came here

[waxen glen]

khan academy or the organic chemistry tutor are must populars

[warm coyote]

for help

and ur telling me

to go online

to get help

[waxen glen]

well, isnt this channel for help for problem solving

[warm coyote]

then

[waxen glen]

how can i help you if you dont know properties

[warm coyote]

what

the

fuck

is

the

point

of

this

channel

[waxen glen]

[sharp plume]

[late swan]

this isn't a discord to cheat fam

its to learn

and become better

[warm coyote]

omg

thats why i came here

wtf

nvm

[waxen glen]

lmao

[warm coyote]

yall arent helping at all

[sharp plume]

Just tell him the properties

So he stops crying

[late swan]

lol

[humble pulsar]

Have you tried looking up the properties yourself or do you expect everything to be hand delivered?

[warm coyote]

shut the fuck up cunt

[sharp plume]

Lol

[humble pulsar]

Ok and now no more help for them

[warm coyote]

i have mosh

[waxen glen]

lmao

[warm coyote]

i wasnt talking to u mosh

i did check

and the shit

is still complicated

[late swan]

im experiencing second hand embarrassment

lol

[waxen glen]

You are like "PleASe HelP me TO soLVe THis AMth BuT i DOnt KNw hOW to WrITe"

[warm coyote]

can u shut the hell up

mg

[humble pulsar]

So if you checked and saw the properties you needed to learn, why are you bitching in this channel?

[warm coyote]

did u not understand what the words are coming out of my mouth

well

through this text

"the"

[waxen glen]

you are cringier than tiktok lmao

[warm coyote]

"shit"

"is"

"complicated"

[sharp plume]

[late swan]

its like coming to a discord server asking how to drive a car

[warm coyote]

its like sucking someones dick and riding it

[vocal lodge]

how do you do this one do you use arc?

[waxen glen]

maybe it is complicated because YOU DONT KNOW PROPERTIES

huh

[warm coyote]

bro

[late swan]

?

[warm coyote]

did

i

just

say

i checked

and that

my teacher

[waxen glen]

which trigonometric thing is for the adj and hypothesis

[warm coyote]

is so bad

[humble pulsar]

you shouldn't need inverse trig to find the lengths

[warm coyote]

at fucking teaching

?

[vocal lodge]

then how do you find the lengths

[sharp plume]

Can someone

Make him go

[vocal lodge]

tan35=y/x?

[humble pulsar]

that;s one equation you need

[waxen glen]

oh

[humble pulsar]

make one using tan(18) and then you have 2 equations 2 unknowns

[vocal lodge]

tan 18=y/x+12

[humble pulsar]

but yes

[vocal lodge]

so how do i solve that

[humble pulsar]

have you solved systems of equations before?

[vocal lodge]

system of equations>

ohhh

i see

how to do in fraction form

[humble pulsar]

2 equations 2 unknowns, the co-efficients are just trig values

[vocal lodge]

wait what

you can do tan35-tan18=tan17???

[humble pulsar]

no

tan isnt a linear function

$\tan(18)=\frac{y}{x+12}\to \tan(18)(x+12)=y=x\tan(35) \ \tan(18)x+12\tan(18)=\tan(35)x$

[limber crest]

$\tan(18)=\frac{y}{x+12}\to \tan(18)(x+12)=y=x\tan(35)$

[somber coyote]

Sedaps

[limber crest]

,help

[somber coyote]

moshill1

A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!

[humble pulsar]

#bots

[limber crest]

ok

[humble pulsar]

They left the server

I mean that hasnt stopped you from "helping" in other channels

[trim breach]

I don’t really think they were looking for help anyway…they were probably expecting answers and got impatient when they had to do some work themselves.

[humble pulsar]

Oh yeah definitely

[waxen glen]

oh just discord karens lol

[humble pulsar]

well then you haven't faced advanced stuff

[waxen glen]

questions are hard if there are a circle and a triangle inside it, change my mind

[waxen glen]

wait, test?

[late swan]

I need to prove that sin^2(theta) = 1 - cos^2(theta)

[humble pulsar]

Unit circle and its equation prove it quickly

[humble pulsar]

I mean, you've already said test then "let's just say it's homework"

so it's definitely a test

yeah no

[weary drift]

why'd you call it a test in the first place?

[humble pulsar]

So why did you say this?

[weary drift]

i'm asking why you initially referred to it as a test

you referred to it as a test too when asking for help in #help-0

[humble pulsar]

Your first ever message was asking for help on a test, and the screenshot's youve posted look like a test

[near imp]

so i understand we can’t ask for help on test does the same goes for quizzes (i’m new here i just don’t wanna break any rules in the chat)

[stuck dragon]

well yeah ofc

[weary drift]

yes asking for help on such timed assessments is academic dishonesty and a bannable offense

[near imp]

ok just making sure i didn’t know thank you for answering :))

[tiny snow]

I am looking for an alternative proof that α = 2β. So, given that we do not know that, do you see some simple way to show that <FBE = w?

Oh, I think the triangles FBE and DBC are similar.

[upper karma]

Can anyone help me with this I don’t want to fail this class 😂

[round prism]

Did I do this wrong? My teacher says I shouldn’t be getting decimals in my answer when I divide 4500 by 27

[wintry tundra]

Hmm

So it has to be an integer?

[round prism]

The answer has to be a whole number

[humble pulsar]

sum of the measures, not the individual angles of a regular n-gon

[round prism]

Sooo what am I doing wrong

[wintry tundra]

Ur only getting measure for a single angle I think

[humble pulsar]

you've assumed it's a regular 27-gon and found the value of 1 of the angles

the question is asking for the sum of the angles of a 27-gon

[round prism]

Yes soo hkw would I find the sum?

[wintry tundra]

Well

[humble pulsar]

you did...

[wintry tundra]

What's the angle sum formula

[round prism]

S=(n-2)180

[wintry tundra]

Ok so

If u know it then use it

[round prism]

Soo wouldn’t the sun just be 4500

Sum

[wintry tundra]

Yes

[round prism]

Oh I must of read the question wrong.. the questions before made us divide after

[wintry tundra]

Eh happens all the time

[round prism]

Well thanks !

[wintry tundra]

No problem

[round prism]

Ok soo just to be clear since this ones asking for the measure of “each” interior angle I would do this? Question 3 btw

I think I did 1 wrong than

It would just be 540 right

[humble pulsar]

yes

[devout cove]

How do you do this pls help

[dark sparrow]

no multiposting.

[devout cove]

Sorry

[lethal sigil]

find area of the circle, subtract that from the area of the rectangle

(b x h) -pi (r^2)

10=b 6=h r=1

pretty sure im right

normally you would account for it being only 1/4 of a circle, but since there are four quarters, it makes a whole