math-help

[green root]

no problemm glad it helped

[left knoll]

does anyone know what i did wrong

[azure carbon]

I'm not entirely sure how many places you went wrong but one mistake I found was in the second step when differentiating -xy^3 you did't consider the negative sign from the second term of the differentiation property.

[azure carbon]

This is the solution I got. Try to complete the problem using this and you might get it. 🙂 (correct me if I'm wrong)

[left knoll]

thank youu!!

[azure carbon]

no problem : )

[glossy latch]

hi can anyone help me pls, i don’t know i how to do it and im not allow to use l’hopital rule as well. is there any other way to solve?

[obsidian sage]

you can try subbing x = 1/e^t

[azure carbon]

the trick is, when using L'Hopitals rule, we need to make sure we have 0/0 form or infinity/infinity form when the limit is applied. Then we can differentiate the numerator and denominator separately till we have the desirable result.

sorry for my ugly handwriting XD

[solid anvil]

c no is the line brought from pyramid to base always perpendicular ?

[left knoll]

bro

[solid anvil]

yes

[left knoll]

area of 4 triangles

[solid anvil]

i get confused

and a base

thats pyramid

[left knoll]

Tsa or csa is asked?

[solid anvil]

tsa

[left knoll]

Yes

then base too

so whats the issue?

[solid anvil]

:/

slant height

i cant find not given perpendicular

[left knoll]

oho

wait

let me think

pls help

[left knoll]

hey

listen

[solid anvil]

yes

[solid anvil]

tell me

[left knoll]

so

SLANT

LENgth

[solid anvil]

yes how do i find ?

[left knoll]

will

be?

10?

[solid anvil]

how ?

[left knoll]

consider a triangle which is actually slant

and the tip

touching the base of the ground

[solid anvil]

ok

[left knoll]

so the height is 6

base

[solid anvil]

do i construct a line making it perpendicular ?

[left knoll]

is

8

[left knoll]

.

[solid anvil]

base given 6

[left knoll]

base of the triangle we considered

is

[solid anvil]

and its adjacent sides equal :/

[left knoll]

Yea?

whats the ans

lets verify first

[solid anvil]

96

[left knoll]

how can ans we 96?

Area of

sqaure

is

itself 256

[solid anvil]

😭

[left knoll]

Bro

dm

@solid anvil

[solid anvil]

ok

more clear version

[willow basin]

My question is gonna look long, but I just put gaps for clarity. I hope it's not marked as spam or something...

Hi! I had a maths question.

If you want to work out what (3/4)^-1 is, you can do:

(3/4)^-1 = 1/3/4 = 1 divided by 3/4, using the general formula x^-a = 1/x^a.

Then KCF (keep, change, flip)

1x (4/3) = 4/3.

However…

for working out (1/3)^-4, if you try to do the same method you get:

(1/3)^-4 = 4/1/3 = 4 divided by 1/3.

Then KCF:

4 x (3/1) = 12.

But this is not correct, because you’re supposed to:

Flip the fraction inside the brackets so that the denominator becomes the numerator and vice versa, and change the negative indices to a positive one.

(1/3)^-4 = (3/1)^4 = 3^4 = 81.

My question is: why doesn’t the method used to solve the first question apply to the second question? I wouldn’t like a “just because” answer. If anyone has a somewhat detailed explanation to offer, then I would be very appreciative of that.

[ember kernel]

Did you really learn to multiply the flipped fraction by the exponent itself ? That makes absolutely no sense to me

Sorry for the harsh answer, but the KFC method is just about flipping fractions used as divider in larger fractions/divisions
From the little research I've made, there was no mention of using any exponent whatsoever, beside the classic "-1"

KFC method is just about :

[ember kernel]

Conclusion : I think the mistake just comes from your understanding of what the KFC method is

[lofty oasis]

Hello, anyone know how to isolate for 'y' when ln(y) = 2x / 7x - 4 ?

[lofty arch]

e(ln(y)) = y = e(2x / 7x - 4)

[lofty oasis]

ahh right thank you

[boreal meadow]

Hey guys

Can someone help me help my friend with a physics question

[small remnant]

post it here

[olive trail]

Hey could anyone please explain the steps to solving this please?

[mystic dune]

Can someone help me, like, right now?

This is the last question, my brain is mush, and it's due in less than 20 mins. Question 92

[mental dragon]

Boxplots just describe the distribution of the data. So you could say that Princeton on average has higher values and a wider distribution/range (meaning more rainfall, and bigger difference in rainfall from month to month). Tuscon is the opposite; lower values and tighter distribution/range. The single dot denotes an outlier, which is a single month that had an abnormally large amount of rainfall.

[wispy tiger]

thanks @mental dragon

[mystic dune]

I love you. TYSM. Let me know if there is anything i can do for you

[mental dragon]

np. good luck.

[azure carbon]

it looks like there isn't enough information to solve this problem as there is only one equation given. Is there any additional description or information that's given for the problem?

[glossy latch]

thank u so much!! < 3 one question, is there any other way i can solve beside using l’hopital rules?? and also, your handwriting isn’t bad !! ^_^

[azure carbon]

I tried a few other methods like changing the given function into different forms but i'm always ending up with an indeterminable form [i.e, 0/0 or infinity/infinity form]. As far as I know, I don't think it is possible to solve it using another method. [or maybe there is but I don't know it]

[slate dune]

Im having brain lag right now. I think this is right?

[steel berry]

p sure u got all of em correct

[slate dune]

nice

[steel berry]

wait

sqrt x^2 = x is correct

it is mathematically correct but

it just misses a case

but it is correct

shouldnt be false

[glossy latch]

okay thanks once again!!

[azure carbon]

but they didn't specify the sign of x. if x is positive then that case would be true.

[steel berry]

oh wait i think im thinking of smth else

ya true

[olive trail]

Hey guys I have a really important exam tomorrow and am struggling with problems 7, 19, 25, and 27. Ik that is a lot but it would mean the world to me if someone could help me out! 🙂

[gleaming spear]

does anyone know how to solve this specific type of rational inequality? equating the denominator to zero gives me an x of -4/5, and i dont know where to go from there. most practice problems doesnt have an x that is greater than 1 (denominator-wise)

[steel berry]

x cant be -4/5

denominator cant be 0

its = 0 when numerator = 0 when x = -12

[gleaming spear]

ohhh ok, thank you!

[left knoll]

can you pls send a clearer picture, I might be able to help!

[stuck pewter]

Help pls

[olive trail]

@left knoll oh sure thing! It looks fine on my end I’m gonna try to zoom in. Tysm!

@left knoll Is this better?

[left knoll]

its still not readable 😅
if it is in a pdf, can you perhaps copy the text and send it here?

[olive trail]

Ya sure!

The first question is “If you roll a red doe and a green die what is the probability that the sum is a prime number”

The next one is based on this chart of a bag of candy with these proportions in each bag. The questions asks “what is the probability of taking one candy each from two newly opened bags and both being brown?”

Actually sorry that’s the wrong problem. Its based on the same chart but asks what is the prob of getting one green and one red if you draw one from each new bag.

The last question is based on a pack of 24 cards containing “Jack, King, Queen, Ace, 10, and 9” of all 4 suits which are “spades, hearts, diamonds, and clubs” so there are 4 types of each card, and each hand/set of cards drawn will have six total cards. The first question is what is the probability that a hand/set is all spades. The second is what is the probability that a hand/set contains all four of the “aces”

@left knoll Thank you in advance! Ur a life saver!

[left knoll]

2/5

[left knoll]

this one i think i wont be able to solve, its above my level...

[left knoll]

they are standard die with 6no.s right?

[shrewd wave]

anyone who knows anything about data collection or data classification hmu

[willow basin]

...No. The exponent was negative before flipping the fraction, and after flipping the fraction it became negative.

[willow basin]

... If you plug some values into this formula, e.g - a = 6, b = 3, c = 2. 6x(1/3)^2 = 2/3. And...6x3^2 = 54. So they are not equivalent.

[willow basin]

It's fine, thanks for offering to help.

[mystic dune]

@mental dragon you available to help again? I need help on 128

Or anyone

I just need help

It's the last question and my brain is mush again

@ember kernel you know Statistics?

@left knoll you know Statistics?

Anybody?

[ember kernel]

No sorry

[left knoll]

I'm taking stats rn so i can give it a shot. so the male and female samples combined adds up to a 91.8% feedback rate which is a good statistic for the targeted population. from the graph you can tell that females more frequently seek feedback and revise their papers to improve their writting than the males do

this doesnt mean that the females are smarter than the males, it just means that they are more likely to succeed because they more actively seek feedback to improve themselves than the males do

hope that helps!

[eager summit]

sin(x)-tan(x/2)=y

[cyan night]

sin cos sincos sec c

[ember kernel]

?

[lunar forge]

hi! would anyone be able to help me with some water rocket physics questions?

G. Take a reading on the pressure gauge on the pump to estimate the launch pressure
H. Measure the nozzle diameter, and calculate the nozzle area of the water rocket
I. Calculate the theoretical propulsion force at the moment of launch

I´ve been trying to get this by myself but I am just getting more confused overtime

[lunar forge]

Or what I need to be able to answer

[mystic dune]

Awesome tysm

[left knoll]

In one company, men make up 25% of the total number of employees. There are 445 more women than men. How many employees work in this company?

[azure carbon]

Total employees are 890.

consider total employees as T. Number of men working are T/4 (as the question says 25%) and number of women is 3T/4.
now 445 + T/4 = 3T/4.
solving the above equation we get the value of T

[left knoll]

ty

[left knoll]

Pls help

@ember kernel

[ember kernel]

QRP and R.S are similar, which means the ratio of their lengths are the same constant.

Therefore, the ratios |QP|/|.S| and |PR|/|R.| are the same

Using actual values, that gives :

y/10.2 = 3.6/9.4

Isolate y by multiplying both sides by 10.2 and there you go :)

[left knoll]

Howd you know QRP and RS are similar?

[left knoll]

So is it 3.90?

@ember kernel

[left knoll]

find derivative of

using 1st principle method

@ember kernel

[glacial vine]

Pls help,Is this 2 or 3

[left knoll]

3

[glacial vine]

Tysm😊

[small remnant]

inverse matrix of 1x3 order doesnt exist right?

.3x1

[vapid osprey]

find the relative position between the r line of the equation (x, y) = (t + 2, 4t-16) and the s line of the equation (x, y) = (2t + 2, 8t-4).
HELP

[nimble gust]

does anyone know how to do this

[hollow escarp]

uhh, maybe

[nimble gust]

or this :(

[left knoll]

multiply the are of the flat part by the length

@nimble gust

[nimble gust]

so just 880 x 1800

[hollow escarp]

i'll send part d now. one moment

[nimble gust]

thank you so much

i think i got d but i’m not sure i ended up getting 4.5

do you know how to solve this problem?

[hollow escarp]

This is how I solved

I'm not very sure though

90 metres seems like a lot tbh

[left knoll]

should we ping @ peeps ???

[nimble gust]

that’s okay!! thankyou so muchhh

[boreal meadow]

Hey guys

Can anyone help me with math questions

[digital crypt]

can someone help me with this? why in the second state when he reads a 0 the arrow doesn't come back to second state again?

[hollow escarp]

Post it here. You’ll get help

[frozen meadow]

The value of sin 45 and cos 45 will always be same right. No matter what it is

[ember kernel]

Right. Only a square matrix can be inversed

[small remnant]

well your question isnt clear. you have put a definite value and yes for this their values are same for both sine and cosine operator

[small remnant]

you have to specify what kind of other scenarios you are talking about

[frozen meadow]

Is sin 45 just a ratio or is something more. It confuses me sometines

[ember kernel]

Short answer : sin(x) not equal to cos(x)
But sin(45°) = cos(45°) no matter what

[small remnant]

yes it is a ratio

[frozen meadow]

Oh alright.

[frozen meadow]

So that mean sin and cos a has a periodic value right?

[ember kernel]

sin(x) and cos(x) yeah

sin(45°) and cos(45°) nope

[frozen meadow]

Ok

Whats its periodic value

[ember kernel]

360°

[small remnant]

if you take a right angled triangle with an angle x then the ratio of the length of perpendicular and hypotenuse is the sinx

[frozen meadow]

I mean how do i find its periodic value by myself. Can i find it by using ratio values??

[small remnant]

its 2 times pie

[frozen meadow]

Yea i know. Thats easy. The same i did with circle to find 180 degreaand above

[frozen meadow]

Alright thanks

[small remnant]

no each function has a specific periodic value which can only be found by graphing

[frozen meadow]

Oooh

[ember kernel]

Well you could also find the periodic value using the content of the trigonometric function

With sin(ax) or sin(ax + b)
The periodic value is 360°/a

(And that's the exact same thing for cosine and tangent)

[ember kernel]

@cyan night Looks like someone took you phone to send an unnecessary troll message

[cyan night]

no

it was someone who posted the nitro

scam link

i said they were nerd

[ember kernel]

Oh ok

Thought you were targetting pm

[cyan night]

no..

[junior sorrel]

what does AxB mean

nvm im dumb i figured it out

[vapid osprey]

find the relative position between the r line of the equation (x, y) = (t + 2, 4t-16) and the s line of the equation (x, y) = (2t + 2, 8t-4).
HELP

[cloud ocean]

HOLAAA

ayuda

Can somebody help me

[small remnant]

english plz

[cloud ocean]

okok

[small remnant]

np i got the question

its 10m

@cloud ocean

[prime hound]

Hi guys, I would appreciate if someone can help me with a question about trigonometric functions in lR. Is the relationship between the graph of the functions and the trigonometric ratios only the sides that relate? For example, both relate for sin (Θ) the opposite side of Θ with its hypotenuse.

[odd night]

help?

[rose bridge]

how would i solve this

[wide heron]

im not sure since the provided interval is an open one, but i think you can use (2,6) where a=2 and b=6, just to show that there is at least one solution to the problem.

[left knoll]

3[5 -6]- [6 y] =3[3 -2] then y=.........

pls help

[lofty oasis]

anyone know how to do this question: The acceleration of a particular car during braking has magnitude bt, where t is the time in seconds from the instant the car begins braking, and b = 2.5 m/s3. If the initial speed is 45m/s, how far does the car travel before stopping?

dont we have to integrate -2.5t

and do that until we get the distance function with respect to time

[slim hazel]

anyone know this?

[frozen meadow]

dy/dx=(4xy-x^2)/x

rearrange it like this. and solve the equation. using the formulas u studied

[slate dune]

I'm a bit stuck on this question

[azure carbon]

is there any other information given to the question? Because it looks like you need to do partial differentiation but you will get the answer in terms of f'(x+h) which isn't right.

[slate dune]

Its fine I managed to rack my head out and find the answer

[azure carbon]

could you please explain it because i didn't understand it XD

[slate dune]

Okay, so for this question it provides you with f(x+h) - f(x) and since we know that derivative can be found using this equation below

all we do is substitue the top half for the given and then factorize to cancel out the h on the denom (since you cannot divide by 0)

and then you make h = to 0 and then it will give you the answer after simplifying

[azure carbon]

Got it. That's a pretty unique way to use the differentiability equation : )

[slate dune]

👍

[opal rock]

So like how do you find the two answers

[left knoll]

there will be 1

[past finch]

it will leave you to a bhaskara equation

[opal rock]

Nah theres 2 cause of the 0 at the end

[past finch]

yeye

[left knoll]

c = root6 @opal rock

[opal rock]

Cause like the answer is c=0 and c=6 but like what about the 4c at the start

[left knoll]

solve the bracket first'

[opal rock]

But what about the 4

Do you just exclude it?

[left knoll]

wait

Won't it be c= 6 ?

[opal rock]

Thank you for spending your time to my problem @left knoll I appreciate it

[left knoll]

yes sorry my bad, its 6
@opal rock

[left knoll]

np

[opal rock]

yes

and c is 0

[left knoll]

Yes

[opal rock]

I'm just gonna copy down your math working out

[past finch]

4c.(c-6)=0
if: 4c=0 -> c=0
if: c-6=0 -> c=6

ig thats how your teacher wants you to answer

[opal rock]

HAHAHAHA Yeah thats true

[hollow escarp]

allow me to confuse you even more

[opal rock]

Thank you guys for the time and effect to work out my math problems much ❤️ As always

[opal rock]

Nah I'm not confused at all, It makes sense

[ember kernel]

It doesn't matter. Divide both sides by 4 ; 0/4 is still 0 and the 4 in the left side disappears. Voilà :)

[opal rock]

Are you a bot?

[ember kernel]

beep boop

[opal rock]

Cause you have [math,phys,FR help] in your name How interesting

[ember kernel]

Well, that's just to indicate that I'm able to help in these subjects

[opal rock]

Wait Quentin Bot can you help me out with sketching these equations on a parabola?

[ember kernel]

beep boop of course

[opal rock]

So like how do I sketch this on a parabola?

[ember kernel]

For beginners, the best way to sketch a parabola is by mapping a set of points that belong to the parabola, then linking all of them with a curve

Like :
Replace x by 0, you get y = 3 * 0² = 0. Add the point (0,0) onto your graph
Replace x by 1, you get y = 3 * 1² = 3. Add the point (1,3) onto your graph
Replace x by -1, you get y = 3 * (-1)² = 3. Add the point (1,3) onto your graph
Replace x by 2, ....

[opal rock]

ok I get the sequence

[ember kernel]

If you want, you can also do that with x = 0.5, x = 1.5, ...

That increases the precision

Once you're satisfied with the quantity of points you have, just link them with a hand-drawn curve :)

[opal rock]

Thank you Quentin Bot for the parabola advice to structure it

[ember kernel]

beep boop np

[dim tinsel]

hi, does anyone know how to compute for the rate?

In a certain account providing an interest rate of r compounded quarterly, $2,500 is deposited every end of the quarter. What value of r will make the future value of the account $5,200 in six months?

[opal rock]

I will just watch some more Kahn Academy vids if I'm still in trouble

[ember kernel]

Ok, so when you invest an initial capital 'c', you receive C = c + c*r = c(1+r) at the end of the period (= a quarter = 3 months)

With the info in the question, that, after a period, we have :

[ember kernel]

Now, for the first period, you reinvest that money C1 AND a bonus of $2,500 (since you add it at the end of every quarter)

Re-use the equation C = c(1+r) but with an updated value for c, and you get :

[ember kernel]

You want $5,200 after 6 months (= 2 periods), which means you want C2 = 5,200

That gives the equation :

[ember kernel]

Use the quadratic formula and you get r = 0.0264337522474

(there's a second solution, but it is negative so it's of no interest to us)

Voilà :)

[ember kernel]

Did it help ?

[gleaming spear]

stuck by a whole lot on this problem, appreciate the help xo

[vapid osprey]

find the relative position between the r line of the equation (x, y) = (t + 2, 4t-16) and the s line of the equation (x, y) = (2t + 2, 8t-4).
HELP

[dim tinsel]

thank youuu both of you! @ember kernel and @hollow escarp <3

[cobalt mural]

hello!!! for #41 and #43 i don’t know how to do it

do i need z score or is it like,, completely something else?

[ember kernel]

Divide both sides by 9.37*10⁶ then take the cubic root of both sides

You'll end up with l = (w/(9.37*10⁶))⅓

That's you function l(w). For the second question, just replace w by 0.679

[frozen meadow]

someone know the answer??

the value of sin12 sin48 sin 54 is equal to

2/3 1/2 1/8 1/3 3

(the numbers 12 48 54 are degree)

high school level question. came in an entrance

[ember kernel]

Simpson's formulas

[frozen meadow]

soo i was that equation. f

i thought it wouldnt work. im such an idiot

[ember kernel]

Answer : ||1/8||

[frozen meadow]

yea ur right. i have answer but no steps

thanx man @ember kernel

lemme try it

[ember kernel]

Yup ! ^^

[left knoll]

do u know the identity

(a+b)^2

[opal rock]

Yeah why?

[left knoll]

so use it

[opal rock]

What? I don't think thats how you do it

[left knoll]

im quite sure

[opal rock]

But are you suppose to square root it?

[left knoll]

mm exactly

[opal rock]

Cause I'm stuck with square rooting 50

[left knoll]

youll find it

but in decimals

not efficient

[opal rock]

Wait how did you get 5 square root 2

[left knoll]

prime factorisation

even that will give 1 value, but shouldnt it become a quadratic nskdj

oh wait

you gotta mod it

mbmbmb

[opal rock]

Use math bot?

[left knoll]

for what

do u know quadratic equations

[opal rock]

to find 5 root 2 of 50

not really

[left knoll]

we just said it is not efficient

[opal rock]

The quadratic formula is not efficient

[left knoll]

ok u have 2 methods:

[opal rock]

I'm just gonna guess and check

[left knoll]

1. find the square root of 50, hence rooting both sides, remember to put + - in front of it and then bring 6 to the other side

[opal rock]

Yeah guess and check

[left knoll]

2. open up the left hand side using the identity, bring 50 to the left side, use quadratic formula

your choice, you should get 2 answers in any case

[opal rock]

Oh ok Thanks for the two methods @left knoll and @left knoll

[left knoll]

is the answer given

in your book

[opal rock]

So this is my working out

x+6=+-5squared 2

[left knoll]

ye

[left knoll]

yeye

you would get this using quad formula too

this is ok

[frozen meadow]

this is faster than quad i think

[opal rock]

Wait @left knoll Do I need to use quadratic formula for...

[left knoll]

yeye it was, oiwajdszx we usually get them already expanded so it completely slipped

[frozen meadow]

yep u have to

[left knoll]

ye i dont think u can middle term split this

[cyan night]

a+6 = +- sqrt 50

[frozen meadow]

if u know any tricks use it too

[cyan night]

i know a trick for it

[opal rock]

What is it then?

[opal rock]

OKAY 👍

[cyan night]

= x^2 + 2x + 1/4 - 29/4

= (x+1/2)^2 - 29/4

[frozen meadow]

when u practise these problems u start making ur own tricks and ideas. so practisse alot

[cyan night]

=> (x+1/2)^2 = 29/4

[left knoll]

@frozen meadow ye we usually get ques like this and when i get that i think 1. middle term split or 2. quad formula so the way pooh did it i didnt think of it

[cyan night]

=> x+1/2 = +- square root 29/2

x = +- square root 29 -1/2

pls listen to me guys

using this way u can solve any quadratic

[frozen meadow]

i used to think like that. but then i started practicing and found that for some questions. it takes only 5 sec.

[cyan night]

guys

please

[frozen meadow]

lol sorry

[frozen meadow]

send a written pic one buddy

[cyan night]

this way you can do it without middle term split

or quad formmula

[left knoll]

mhm

[opal rock]

I'm just going to use quadratic formula but thanks for the method you showed us

[cyan night]

bruh

quadratic formula sucks

[left knoll]

I second that

[cyan night]

my way real creative

[frozen meadow]

bro, u should audition for nasa ur too talented for middle school

[cyan night]

bruh

guys

[left knoll]

BRUH

[cyan night]

use my way

sigma male way

[frozen meadow]

cringe

[cyan night]

no

it is one of the best ways

also works for finding min max problems

[frozen meadow]

lets stop it type in gen. mods will kill us

[opal rock]

I'm sorry but like this way is more easier, conventional and the way I have to use

[left knoll]

.....bruh

[cyan night]

...

[left knoll]

😂

[cyan night]

right, applying quadratic formula

its my last resort

real not creative and beta male

[opal rock]

Wait @cyan night Are you in the last year of middle school?

[cyan night]

yes

8th

i want to popularizr the sigma male way to solve quadratics

x^2+2x + 7
= x^2 + 2x + 1/4 - 29/4
= (x+1/2)^2 - 29/4

[opal rock]

Cause I got confused with our country's schooling system despite our last year in primary/elementary/middle school is year 6

[cyan night]

ok

[cyan night]

DO IT THIS WAY

[opal rock]

n

o

[cyan night]

why

its very creative and easy

[left knoll]

What was this method called?

[cyan night]

im not sure

[left knoll]

This

[cyan night]

but you make it factorizable under (a+b)^2 or (a-b)^2 + something

[opal rock]

But like quadratic formula is more easier and efficient

[cyan night]

then take the square root +- both sides

[left knoll]

Isn't it the splitting the middle term method?

[cyan night]

1 its not easier 2 this is more efficient can do without calculator 3 this is creative

[opal rock]

I'm just not bothered to use your method dear sir

[cyan night]

i didnt split the middle term

[frozen meadow]

if u write it like this he wont understand. write in a paper clearly and send him

[opal rock]

I get what you mean

[opal rock]

Y-E-S

[cyan night]

... its really easy to understand

[left knoll]

For you

[cyan night]

i am younger than the guy

he should have no difficulties understanding

[frozen meadow]

stop flexing ur intelligence. shut up and send him

[cyan night]

?

[frozen meadow]

joking bruh

[cyan night]

how is it hard to understand

[left knoll]

It's completing square method

[cyan night]

yes that

[frozen meadow]

he hasnt learned it yet. so just send him in a paper.

[cyan night]

Ok ill do it after school

[opal rock]

You don't need to send the method paper, is not like its an emergency

[cyan night]

ill just write it on word

[opal rock]

...

[cyan night]

what

[opal rock]

nothing

[cyan night]

wait

does that equation have a solution

oh i thought it was +7 the whole time

@opal rock

[opal rock]

It has two solutions

[cyan night]

yeah there

get it?

[opal rock]

Its pretty confusing because you type it up but it doesn't matter cause I got the answer and the working out

[cyan night]

...

[opal rock]

BRO My Math Tutor gives out so much homework I'm being literally doing the work for the whole afternoon

[cyan night]

its all easy work so doesnt really matter

[opal rock]

Only for you but I just learn't it nerd

[cyan night]

what

learnt

[left knoll]

I never got homework in middle school, lucky me

[opal rock]

Quadratic Equations like I'm still doing it

[cyan night]

it's learnt not learn't

[opal rock]

Whatever

[cyan night]

yes big word user

[opal rock]

What a bully

[cyan night]

you called me nerd

and undermined my methods 😠

[opal rock]

I don't really care about your method right now

[cyan night]

quadratic method is not a good method

[opal rock]

Your perspective

[cyan night]

why do you think it is good

[opal rock]

Cause its easy to follow

[cyan night]

its just applying the formula so uninteresting

[opal rock]

Thats the majority for every math formula

[cyan night]

the way i just presented you did not directly apply any formula

no

consider many methods and math is more interesting

[opal rock]

ok

[left knoll]

Pooh gave up

[opal rock]

Pretty much Yes

[cyan night]

gave up on what

[ember kernel]

Hey. Helping involves no judgement.

1. Everyone has different learning curves
2. Everyone doesn't learn from the same source. He has no influence on what his school decides to teach at what grade
3. His age doesn't change the fact he's new to the subject. Skill and understanding have nothing to do with age. A 40-year-old human could also have problems with quadratic functions when learning about them for the first time.

[ember kernel]

Also, this is wrong.
(x+1/2)² = x² + x + 1/4, and not ...+ 2x + ...

(On an unrelated note, I'd recommend you start using the quadratic formula. Your ""sigma male"" way of finding solutions might work for now, but it'll turn useless or hard to use when you want to use parameters or factorise a quadratic function without finding its solutions)

[cyan night]

yes i knew it was wrong i redemption on the screenshot i sent him

[ripe knoll]

Anyone good with sets?

[cyan night]

yesterday i barely slept so i am pretty short tempered today sorry

[ember kernel]

Depends on the difficulty of the question

[ripe knoll]

Do you know that Cartesian product thing

I'll send you a question i have a doubt in

[ember kernel]

Like A x B ?

[ripe knoll]

Yeah

But what will A x A be

Its a dumb doubt

[ember kernel]

That's a subset of R², which means it's under the format (a,b) where a and b both belong to A (but they don't have to be equal)

Imagine A = (1,2)

[ripe knoll]

Is this correct

[ember kernel]

It is :)

[ripe knoll]

Oh ok

Cool

Thxx

[ember kernel]

No problem !

[ripe knoll]

So 1,1 doesnt count?

A and b are equal right

[ember kernel]

Yeah yeah (1,1) does count

I said a and b "don't have to be equal", but they could :)

[ember kernel]

So what you wrote here is correct

[ripe knoll]

Yeah gotchu

Thanks a lot

[ember kernel]

Np ^^

[ember kernel]

I hope you get better. However, there was no need to take it out on an innocent guy that just seeked help. Self-control man

[cyan night]

yeah i agree

wait can you give an example of like working with quadratic parameters as you just mentioned

also which channel should i watch math lectures on

i want to watch logarithm lecture

[ember kernel]

The green A, B, C and Y are just there to make the steps clearer and shorter

[cyan night]

sorry i cant quite look at the picture

[covert anchor]

Hi

i cant understand how to draw a sine graph

[ember kernel]

Like, what it looks like or how to reproduce it ?

[covert anchor]

how to produce !

🙂

im confused

mostly cuz of amplitude

For example ii

[ember kernel]

Take some values for x between 0 and pi

[cyan night]

wait u actually wrote sigma male method

[ember kernel]

Like, x = 0, x = pi/4, x = pi/2, x = 3pi/4, x = pi
Then, for each value of x compute the equivalent y using the formula, and sketch that (x,y) pair on your graph

[cyan night]

so like i recommended @opal rock sigma male method because its really helpful when finding minimum/maximum value of a quadratic

[ember kernel]

The more points you add on the graph, the higher the precision is. Finally, just link all those points with a smooth hand-drawn curve :)

[covert anchor]

can someone draw it out im very lost

[cyan night]

oh i wasnt talking to u btw

[covert anchor]

noted

[ember kernel]

It might, but for now he is just getting started with quadratic functions. Introducing him to min/max is kinda early. Especially since you advised him to use an advanced method instead of a straight-forward-very-easy-to-use-almosy-brainless formula that's very popular and works all time

[opal rock]

@cyan night

[cyan night]

well i was taught this thing before quadratic formula so my bad

[opal rock]

... Proceed

[opal rock]

Well yeah thats the situation I'm in right now

[cyan night]

Ok do you need help

[opal rock]

Nah I finished my math already

[cyan night]

do you know how to complete the square

[covert anchor]

for me i am not sure how many set of curves to draw

isit 2 sets for this qs ?

[covert anchor]

ok thanks

I have one more qs

Given that Sin35=k
Express cos35 in terms of K

[cyan night]

is that 1-k^2

[ember kernel]

(I deleted my answer 'cause I had misread the question)

[covert anchor]

how did u derive ?

[cyan night]

wait no

shouldnt it be square root of 1-k^2

sin^2 (35) + cos^2 (35) = 1

cos^2 (35) = 1 - k^2

so cos (35) = square root of 1 - k^2

[ember kernel]

Forgot to answer, but yeah. I did both so you could see how slow the sigma method was. That method was the way mathematicians discovered the quadratic formula.

So yeah, using the sigma method instead of the quadratic formula is like making a new bike every time you need to go out instead of using the one that's been pre-build for you

[dim leaf]

Hello

Could someone help me with limits ?

[cyan night]

probably

i can help with simple

[dim leaf]

So, for the first one, I found : +oo

The second : 2

[cyan night]

2nd one is 2?

ye

[dim leaf]

And the last I found 49

Because 7*7 = 49 but I didn’t write that because we can’t write it

I wrote lim when n->+oo of 7-1/n) = 7 because 1/n is 0

Same for 7+2/n

[cyan night]

ok dont ask me i havent learn this yet

[dim leaf]

And after that I directly wrote Wn = 49 without writing the calculating

Okay x)

That’s what I’m learning, we have the same age

Thank you so much tho ‘

!

Going to school, see you brother ;)

[cyan night]

byebye bro

[cyan night]

you are also middle school?

[lost wadi]

A

[small remnant]

i think its b

the dashed curve has 4 extreme points and the smooth one has 3 which means 1 degree less which indicates the first derivative

[small remnant]

could you please say the reasoning behind your answer

[lost wadi]

Trace the tangent of the bold function

you will get the dashed one

[small remnant]

on the right side the tangent can be traced but certainly not on the left side

[left knoll]

I'm so lost 💀

[lost wadi]

We can. The bold function got the value reduced, stopped at local minima and then started to increase

Same is shown in the dashed version

[lost wadi]

Answer is A

[left knoll]

My classmates are saying it

Neither graph could be the derivative of the other

@lost wadi

[lost wadi]

I put the logic here

Don't think that they are right

[ember kernel]

Sorry to break down your logic but that's wrong

Not A : because near x = 0 (positive side) the solid line has a local max but the dashed line is actually non-zero, so it couldn't be f'(x)

[left knoll]

Is it B then?

[small remnant]

i think thats correct

[ember kernel]

B

[small remnant]

on the left side the dashed curve isnt tangential to the solid one

i think its D

what say?

[ember kernel]

Double-checked. May the mods ban me from this server if it's not B

[ember kernel]

The graph of a derivative has nothing to see with the graph of the original function

Also, at no point in the graph are the solid and dashed lines tangent to each other

[small remnant]

so we just analyse the degree of function and then its B?

[ember kernel]

What do you mean by "degree" ?

[cyan night]

deg

[ember kernel]

Doesn't help

[cyan night]

Ok sorry

[ember kernel]

A polynomial can have a degree, but as we don't have the expression of plotted function it won't really help

[cyan night]

Oh

[small remnant]

the polynomial whose curve is plotted

the curve definitely doesnt look exponential loagrithmic trigonometric or even inverse trigonometric

[ember kernel]

I do agree with you, but why did you mention it ?

[small remnant]

you can say the degree of a function by counting the number of extreme points it has

the degree is generally one more than the number of extreme points

[ember kernel]

to some extents* it doesn't work all the time

[small remnant]

say for a quadratic deg=2 points=1

[cyan night]

that thing has deg 3 then?

f(x)

[ember kernel]

Ok, but how is it related to the question about f(x) and f'(x) ?

[small remnant]

well for how much we can see fx has 4 and f'x has 3

so i deduced that the dashed one is the first derivative of the solid one

[ember kernel]

Your point is valid, but I'd say it's rather weak

At least, it isn't sufficient to establish an actual, precise answer

Look at this, here
g(x) has 2 limit points
f(x) has 1 limit points

However, g(x) is not equal to f'(x)

Your method is good at double-checking the answer, but not finding it

It's kinda tricky to explain this to you, but you'll have to trust me on that

[small remnant]

ok so whats your logic behind option B?

[small remnant]

well the question provided was more of a deduction type rather than finding a value or something

but would like to know your method

[ember kernel]

When dashed is at a limit point, solid = 0 (slope = 0)
When dashed goes up, solid is positive, and when dashed goes down, solid is negative

Finally, while solid is negative, dashed decreases the fastest when solid is at its local lowest

When we assume that dashed = derivative of solid, it all makes sense

[cyan night]

very interesting

[ember kernel]

What do you think of it ?

[small remnant]

man thats a very good observation

you good

[ember kernel]

Thank you !

[cyan night]

yes he is very good

[small remnant]

he certainly is

[cyan night]

he is like professor

[small remnant]

whats your credentials?

[ember kernel]

I'm a civil engineer student

[small remnant]

thats great

[cyan night]

can you make a time machine

[ember kernel]

Nah

I'm kinda bad at engineering so all I can do is teleport people

[cyan night]

😳

[dim leaf]

I'm in high school, last year

[cobalt mural]

answer is 1/4 but idk why rip

[ember kernel]

Replacing t by 3 in the expression leads to an undetermined case 0/0
Therefore, use L'Hospistal's rule ; differentiate the numerator and denominator separatedly, and replace t by 3 once again

[cobalt mural]

OH RIGHT LHOSPITAL FFFFF

tysm man ive been stuck on it lmao

[ember kernel]

Np !

[obsidian skiff]

Hey can someone please help me with this hypothesis testing question
I got the answer for this correct but idk why you take P(X > 15)

[slate dune]

Can someone help me with question b?

[wide heron]

N_net is situated in the y-axis, therefore has no x-component. This means that the vector component for N_net is just its y-component. Similarly, T_net is oriented towards the x-axis, therefore has no y-component. As for the W_net, it has both x and y-components so it has extra steps: 1. find the x and y-components and use arrowheads to indicate their direction (these are vectors so direction is important); 2. solve for their length in terms of the given values (in this case, W_net and the angle (beta)). 3. note that W_net is equal to the sum of its x and y-components, so just add what you got from step number 2, paying close attention to their signs (which you can determine based on the direction of each component).

sending you this as an extra clue. remember your SOH CAH TOAs!

[meager sleet]

can someone help me i have been asked " Can you see how you could have mathematically made your calculations? How? Does this connect to the rule you found? "

the rule is up top

[left knoll]

Hey guys I need help with some questions , I've got a test tomorrow and I'm just not getting them, I'd appreciate it if someone could explain it to me :)

[cyan night]

Ok

zay didnt we already do 11

[left knoll]

Oh :3

[left knoll]

Noh , well kinda but not really

I need visual explaining as well

[cyan night]

https://www.youtube.com/watch?v=wr3EvQZzoRI

maybe watch this

[random flame]

Hi can someone help me with Q2? Ping if you do and thanks in advance!! Any help is appreciated :)

[wind dagger]

https://cdn.discordapp.com/attachments/714790573214793749/888489118877761596/video0-484.mp4

guys help,can anyone of you tell me how long is this video will finish?. My friend dared me to calculate the specific time to finish it in years,month,days and hours to complete it.

[small remnant]

input (10,1) and (0,-4) in the given equation and you will get 2 linear equation of h and k. Solve it by your favourable substition or cross multiplication method. Then in put (r,-2) in your new equation(putting h and k in the given one) and u will get r as well.

hope it helped

[weary arrow]

Using the time given in the video? Or calculating how long each cheese takes

Each cheese takes 3 seconds, so you multiply 3 seconds with 29 * 10^18, then divide by 60, 60, 24, 365 and you will get years

[random flame]

Ah alright thank you!! I think I complicated the question myself 😂

[left knoll]

Thank u

[gusty bluff]

can someone help

i can't seem to get the cross section area right

nvm got it

[dreamy depot]

can someone help me with this:( i spend so much time on this although it's 2:42am here

[ember kernel]

Are we supposed to express the last logarithm in terms of a, b and c ?

[pallid mason]

Can someone explain how I find the restriction of a radical equation for example (x=3) = Square root(2x^2 - 7)?

[rough plume]

can someone help🙇🏻‍♀️

[cyan night]

what have you figured out yet

so 70% are green => 30% are red

which means 200*0.3 = 60 are red

so if you want to remove green jelly beans such that 60% of the remaining jelly beans are green

you might want to try make it that 40% of the remaining jelly beans are red

which means 60 = 40% of something

you have to think outside box a bit

[dreamy depot]

yessss

[fervent sapphire]

is 860,187,752.5 in 3 significant figures 86.0 x 10^7 ?

[dreamy depot]

nvm i got it 🥰

[primal pagoda]

can someone help me with this? Implicit Differentiation

[maiden fog]

Can anyone help me with this please

[ember kernel]

Chain rule : dy/dx = dy/du * du/dx

[ember kernel]

Take the cubic root of both sides. You'll get y = (...)^(1/3)

From there you can differentiate the usual way

[woven peak]

mmmm calculus

[primal pagoda]

Thanks a lot! I appreciate it

[rich sky]

heyy anyone here knows anything about data analytics? i have this assignment about it and our lecturer is being unclear about how to do it despite the number of times we asked

[worn lava]

Hey can some one help w working this q out, cuz I keep getting 1082870 as my answer

[ember kernel]

Hey, sorry for the late reply. When using scientific notation, we often want only one digit before the decimal point. Therefore, I think 8.60*10⁸ would be more appropriate

[fervent sapphire]

alr, thanks!

[ivory pumice]

Position vector of any point = Xi +Yj +Zk

[woven maple]

A car was travelling at a constant speed for 30minutes. just then it met with an accident and is sped became three-fourth its original because of the decrease speed the journey after the accident took 60 more minutes than it would have taken if there was no accident. Find the total time take by the car in this journey

[ember kernel]

I tried it and got 541 435 mm³, with a height of roughly 37,81

[woven maple]

can anyone help me with this?

[worn lava]

Yeah when I used the calculators the max/min points were at 37.81 or 138.86. When I used 138.8 I got a negative number so that wouldnt be it the answer and I got 1082870 when I used 37.81 but I dont get what im doing wrong

[woven maple]

can anyone help me with this:
Shubham lends a sum of rs.5500 to snajay. This has to repaid within a year. Find by what amount shubham will get benefited if the lends the sum on a 20% annual rate of interest coumpounded half-yearly instead of a 20% rate of interest compounded yearly.

[ashen jay]

do u still need help for this one?

[woven maple]

yeah

[ashen jay]

ok

v= x/t

where v is the speed

x the distance

but with or without accident

x is the same

so v1t1 = v2t2

with accident

(30)*v1+(3/4)v1(a+60)

without

(30)v2+v2*(a)

where a is the time it should take without accident

and u know in the question v1 = v2

u have 1 equation with a

u can find a easily

did u understand?

[woven maple]

yeah thanks alot for helping me out!!!

[ashen jay]

i could make a mistake, but i don't think so

if the sum is s

after 1 year (if the interest is yearly), they will get s*(1.2)

after 1 year (if the interest is half-yearly), they will get s*(1.2) for the first half-year, and then (s*(1.2))*1.2 for the second one

so u can easily calculate the benefit between the 2 methods

[woven maple]

yeah thanks for saying the steps!!

if 150 men working 8hrs a day takes 36 days to harvest to harvest 30fields of 12 acres each. How many men will be needed to harvest 24feilds of 15acers in 30 days working 12hrs a day.

over here i am getting problem because of acres, can you pls help with this one too?

[ashen jay]

if u double the acres

u double the men needed

same for number of fields

and for the days and hrs working

it's not the case

if each man works the double

u don't need the double of men

u need the half

[woven maple]

can you pls say the final ans for this one

[ashen jay]

start with 150

8hrs to 12hrs

means

12/8 = 3/2

so

150*(2/3)

now for the fields

30 to 24

24/30=4/5

so 150*(2/3)*(4/5)

i'll let u find the final answer by yourself

don't forget

for the days, use the same method than for hrs

and for acres, same than fields

(and i hope u understand why it works like that)

[woven maple]

yeahh i understood it, alright i will do
Thanks alot for helping me!!!

[ashen jay]

np

[ember kernel]

@ashen jay what a lad 😎

[slate dune]

So Wx = tan(beta)*W_net
Wy = (W_net)/cos(beta)?

[slate dune]

both will be negative cuz its going down and left?

[slate dune]

-W_net * sec(b)-W_net * tan(b)

[teal karma]

Help

[pearl crown]

This is mostly about intuition

As x approaches 2, the top approaches 4

however, the bottom approaches to some really small number

so small that it makes the entire thing a big number

so the result is infinity

[wide heron]

you cannot use tangent because tangent does not pertain to the hypotenuse in this problem (which is W_net). instead, use sine for W_x and cosine for W_y; therefore, the answers are: W_net = -(W)(sin(beta)) - (W)(cos(beta)), or simplified: -W(sin(beta) + cos(beta))

[slate dune]

Oh

I see thanks

[wide heron]

this works, especially since both terms are squared which prevents the graph from having negative y values. just a reminder to always check how the equation moves as it approaches from the left of x (not just from the right of x), otherwise you have a sound understanding of limits.

[pearl crown]

wrong person

haha

[minor rapids]

can i get help with math

[peak orchid]

Does this have a sequential formula?
What is the formula if it does?
{3, 5, 9, 17, 33,...}

[peak orchid]

I tried a(n)=2^(n) + 1
Does it even make sense regarding what was given?

[ember kernel]

Looks like 2^n + 1

[peak orchid]

Thanks!

[random flame]

Hi can someone teach me how to sketch this graph? Any help is appreciated and thanks in advance!!

Ignore the line btw, this is the axes I have to work with

[lofty arch]

How much calculus do you know?

If you're expected to use calculus, you're going to want to find the y-intercept, the zeros of the function, and the stationary point

For zeros, we need to solve x(2x+3) = 0, giving us intercepts at 0 and -3/2

The stationary point is when y' = 0, so when 4x+3 = 0, giving us a stationary point at -3/4

you should be able to go from there!

[eager oyster]

I attempted to do this, dont know where to get started (High School Math with knowledge of functions and sequences is needed for this)

[last echo]

The zeroes of the polynomial x^2-3x-m(m+3) are
how do i solve this?

i need a step by step explanation

i didnt understand a thing from google

[ashen jay]

if u have the polynomial a(x^2)+bx+c

the zeroes are

where delta (the triangle) is equal to (b^2)-4ac

so in ur exercise

a=1

b=-3

and c=-m(m+3)

!! if they want 2 zeroes: delta>0

if delta=0, there is only 1 zero

and if delta<0, there is no zero

[verbal robin]

does simplifying this give me

log_10(x^1/3(x+3)^3

or a whole different equation

[ember kernel]

Yup

[verbal robin]

i looked further into it, does this work out as well?

[left knoll]

hi need help with arithemtic progression

[ember kernel]

No, it's a different expression. You made a mistake somewhere

[ember kernel]

Ask your question, somebody will answer ^^

[verbal robin]

pardon my janky paint job, but does this not work?

[ember kernel]

Ok

(x+3)³ is NOT equal to x³ + 3³

(and 3³ = 27, not 9, because 3³ = 3.3.3)

Remember : (x+3)³ = x³ + 9x² + 27x + 27

[verbal robin]

ohhhhhhhhh

thank you so very much i feel dumbfounded rn lmao

[ember kernel]

If you feel trouble understanding what (a+b)³ is, you can always compute it by hand

(That's Newton's Binomial Theorem)

[verbal robin]

log_10(x^1/3(x+3)^3) is simplifying it right? then (x+3)³ = x³ + 9x² + 27x + 27 would be part of solving it, is that the difference?

[ember kernel]

is simplifying "what" precisely ?

[ember kernel]

Yes it does

[verbal robin]

thank you so much again

[ember kernel]

No worries ^^

[verbal robin]

seems like i made it harder than it actually is lmao

[ember kernel]

Yup :D

[strong glacier]

Hi you guys , anyone here learn discrete math (boolean algebra), i need help to simplify this

[left knoll]

Hiiiii
Can someone help me with this?

I know
f'(x) =15x^2+2e^x+3

[regal oxide]

anyone here?

Find the least non negative remainder when 2^99 is divided by 5.

[slate dune]

Can someone explain why lim x->4 = -1 instead of -1/2 or -3/2?

[cyan night]

i can help

do you know modular arithmetic?

it's much easier to explain using modular arithmetic

considering the last digit also works

it's p much the same direction

[ember kernel]

Just try to find the solutions to 15x² + 2exp(x) + 3 = 2, you won't find any

[ember kernel]

2¹ = 2 (ends with 2)
2² = 4 (ends with 4)
2³ = 8 (ends with 8)
2⁴ = 16 (ends with 6)

2⁵ = 32 (ends with 2)
2⁶ = 64 (ends with 4)
2⁷ = 128 (ends with 8)
2⁸ = 256 (ends with 6)

2⁹ = 512 (ends with 2)
...

Starting to see a pattern there ?
Once you get the last digit of 2⁹⁹, get the remainder of its division by 5 and there you have your solution :)

That's because every digit that's not the last is at least divisible by 10, which is also divisible by 5. Therefore, only the last digit might produce a remainder
Eg. 234/5 = 230/5 + 4/5 = 165 + 4/5
===> Remainder = 4

⚠️ Here's the answer. ONLY press this message once you've done the exercise yourself, to verify your answer
||Remainder I found = 3||

[ember kernel]

Have a closer look at the scale of the vertical axis

[slate dune]

Ohhhh

[cyan night]

2^4 congruent 1 mod 5 applying fermat's little theorem => 2^(424) * 2^3 congruent 1 mod 5 => 2^96 * 2^3 congruent 1 mod 5 => 2^99 congruent 12^3 = 8 mod 5 and 8 congruent 3 mod 5 => 2^99 congruent 3 mod 5 or the remainder is 3

[toxic wagon]

Anyone? can help me

[slate dune]

@toxic wagon Basically what the question is asking you to do is for example (g*k)(3) in words mean using the equation of g(a) as the template, insert the function of k(3) into the x variable

so it would be you take the equation x^2 - 9, then substitute the equation of k(a) for x, and then make the x=3

[toxic wagon]

here are some example but i don't get it because i'm excuse that day my prof teach this

[cyan night]

why did it say find (f-g)(2) and then express (f*g)(2)

[toxic wagon]

that's why i asking for lmao

im so confused

[cyan night]

is there any other example

[cyan night]

oh there

its just distribution

[cyan night]

then it's just g(3)*k(3), substitute 3 in functions g(a) and k(a), and calculate

similar to the other ones

[vital skiff]

hi guys, could someone who knows linear algebra recommend some good material?

[left knoll]

Rs aggarwal/rd sharma
grade 9 and 10 maths
hopefully you'll get their pdfs online
both have good variety
go for rd sharma if you want to practice a good lvl

[ember kernel]

G. STRANG, "Introduction to linear algebra, 5th edition"

That's what we used in my uni, and I can't stress enough how well this book is written. If you read the book and have trouble with understanding some concepts it covers, you can additionally watch YouTube videos of the MIT Algebra course, lectured by Strang himself.

Again, I highly recommend you read that book

[vital skiff]

Ok, thanks for the help 😁

[hoary umbra]

Can someone help me with this 😅

[scenic wolf]

someone B.Tech student here?

[azure lion]

dy/dx = 2x+5 point (2,24) what is equation line

[ember kernel]

Let me be the slope of a curve at a certain point.

The slope of a second curve, normal to the first one, is -1/m

That's a start

[teal karma]

Help

[agile trench]

1/292200000?

[frail nova]

Pls help

[ember kernel]

#welcome-verification rule 5 my dude
Also, the answer was 5,8

[pearl vapor]

anyone know what this bar notation is called? I know what it is and how to use it, just curious for the name since I want to look more into it, and I can't seem to find it online

its used like when you're evaluating something at a certain number, like y=x^2, so ```y|=3^2
x=3

would also be nice if anyone knows how to do it in latex

[weary arrow]

No clue of the name but isn't it possible to just use the | key on the keyboard for latex?

[pearl vapor]

did some messing around. it works with just the | key on the keyboard, but it looks pretty strange. Using \biggr fixes it though

thanks!

[echo temple]

can anyone help me with this question? i don't know how to solve it and what method to use

define r

[marble basin]

You have to integrate

For the first just replace sec^4t with (1 + tan^2t)^2 and do the basic integration

For the second use the relation

Sin3t = 3sint -4sin^3t

Sin^3t = 3sint -sin3t/4

For the third term
Substitute t^2 as Sinθ

[ancient prawn]

anyone know basic calc when it comes to limits

im trying to understand what it means when a function converges and diverges

so I know if it has a limit

does anyone have a clear explanation for it?

[left knoll]

wrong chat but can someone help me with this?

[carmine willow]

https://www.chegg.com/homework-help/introduction-to-mathematical-statistics-8th-edition-chapter-2.1-problem-4e-solution-9780134686998

I need answer to this question

[carmine willow]

Can someone help me with this question

[hardy hare]

hey can someone lend a hand lol

[ember kernel]

This function has several expressions for different values of x.
eg. If x>=8, |x-8| = (x-8)
Byt if x<8, |x-8| = -(x-8) = (8-x)
(That's the definition of absolute value)

Do that for the second abs. val. as well, and determine what expression is used for what values of x

That's a solid start

[carmine willow]

what about mine

This

[carmine willow]

.

[left knoll]

ooohhh i see i see thank you [other account]

[kind grove]

Any1 can help me with this question on joint distribution?

[ember kernel]

I'm in a lecture rn, you'll have to be patient sorry (I haven't thought about it too much but it seems your question needs more time to answer)

[carmine willow]

ok

nvm

I got the answer

[echo temple]

yeah i got it not long after, thanks!

[ember kernel]

The first thing you can observe is, no matrix among those who have at least one odd dimension will ever count

Why so ?
Imagine you have a 3x2 matrix that's only filled with +1 or -1 values. How could the sum of the 3 items in each column ever sum to 0 ? (Impossible)

So all the matrices you must take into account are m×n ones, such that m and n are either 2 or 4

From there, either you find another trick to get to the answer, or you can draw every of the few matrices you're left with, and count how many satisfy the requirements

[hardy falcon]

The answer is A but idk why can somebody please help out?

Math is hard, but I’ll get there one day!

[left knoll]

not sure how to explain it in english but ill try my best hold on!

since -1 has a zero value that'll be the function x that you have to focus on. the general formula for this kinda exercise is x- a, so if you replace a with -1 it becomes: x-(-1) which can be written as x + 1

[frail nova]

How did you solve it

[steel plover]

can someone tell me how to solve b and c?

[ember kernel]

Replace n by the values 3 and 4 one at a time

[ember kernel]

For b you can see that the first term inside the squared parenthesis is equal to 3

The second term being b, you can find it knowing that the x-term on the left = 2 * 3 * b = -12

[steel plover]

can you explain how you got that? thanks for answering btw

[cyan night]

you identify the "a" and "b" in (a-b)^2 = a^2-2ab+b^2. in this case you observe 9x^2 = (3x)^2 => the "a" is 3x. Now the problem gave you "-12x" as the "2ab" in the general formula, whereas you have a = 3x => 2*3x * b = -12x and then you find "b" = -2. Since the last term of (a-b)^2 is b^2, not b, you have to square -2, which is (-2)^2 = 4.

= (3x-2)^2

[harsh patio]

Need help with a question:

Jessie makes a base monthly salary of $3900 selling art for an established multimedia artist. As part of their contract, Jessie must sell a minimum of $11000 worth of art per month to work with this artist. On top of their monthly salary they make a 6% commission rate on all art sales beyond the monthly quota. There is also an additional 3% bonus on top of the normal commission rate for any sales beyond $17000.
If Jessie made $5500, what was the total value of art they sold to the nearest dollar that month?

It's a simple question but I think I might have made a mistake

[steel plover]

ohh I got it! thank you that cleared it up

[cyan night]

Ok no problem

[brave ledge]

$\frac{a^{2}+14b^{2}}{a+b}$

we dont have latex bot?

[ember kernel]

Start with =tex and follow it up with the equation (no $$ tag needed here)

[left knoll]

=tex\frac{a^{2}+14b^{2}}{a+b}

[cyan night]

is there any way to do this without using sigma?

3 + 8 + 15 + 24 + 35 + ... + 2303 + 2400

evaluate

[hollow escarp]

Hope it's clear