#math-and-meta
1 messages · Page 574 of 1
How many trains are doing this route?
Does it need precisely 3, or does it need 3-ish?
idk
it goes to 2 different spots
When he gives me the travelling time, I can tell him if it's too much, enough or too little.
i have 1 for 1 spot at 900/min and 2 to the other spot at 1900/min
i still think traveling time doesnt matter
btw its gonna be a while since i need to wait until the train is full xD
Okay well - again, I'll post the math for you then.
Like what I'm saying is, unless train 3 is docking the moment it fills up to then go, setting it to "wait until full" isn't really helping that much.
no the queue at the stations waiting to roll in
In that case I would definitely turn off waiting.
So they can dock, take what is there, and move. Less waiting and less traffic back up that way.
#old-questions-and-help message
this is the setup
you can see the second train waiting until the first is full
i dont think you can get >780 throughput that way
You can get >780 throughput on a train easily that way.
You just cannot get to 1560.
well atleast not on long tracks with multiple trains is what i mean
the issue would be if 2 trains dock after each other and then theres a long pause
Which you just said they are waiting for each other with your current "wait till full system".
yes you need to wait so they dont dock at the same time
Unless you build them one immediately after the other that will never happen.
btw current throughput is 1100 since im currently inputting 1100 but im plannign to increase it to 1400
Build one, send it. Once it reaches the other station build the other.
That way you've always got one docked at the opposite station.
thats impossible to time
and it would have the same effect right? instead of manually timing it you tiem it with wait until full
(just to make sure it doesnt block until its full its always 30s)
Not if the alternating stations loop would happen when they are like 60% full.
Then you're just wasting time waiting for the other 40%.
You need to take the time from Honk to Honk in minutes. You can round up to .25, so if it's 3 minutes and 28 seconds, make it 3.5.
You can add .5 per stop. Lets use an example of two stations.
We will continue using the example of 4.5 as time.
You take the time, 4.5 and times that the desired throughput times two, in this case 2800x2=5600.
So 4.5x2800=25200
So it means that in the time your train does one entire loop, it needs to be able to carry 25200 items.
You have two carts, one carts is 32 slots, so 64 slots of cargo. Steel Pipes can stack up to 200, so that's 64*200, meaning 12800.
So it is essentially less than half of the carts needed, for a 3 minutes and 28 seconds trip.
The last equation is 25200/(32x200)
That's the real math.
It's also not impossible to time because you can just watch the first train on your map...
well it actually is in my case since they go to 2 different stations
Ok so we're talking about a 3-station loop now?
That's not at all impossible?
You time from the first honk to the third honk then.
And then you add 1.5 to the time
And do the equation.
@thorn bane @ashen girder wiki will be updated once U5 reaches stable, unless you measured it on U4
ok i have an outpost makign steelpipes 2800/min
i have an outpost making automated wiring that takes 900/min
and i have my main base taking 1900/min
i have 1 train going from steel pipe -> AW and 2 trains going from steel pipe -> Main
Good find
measured it in U4 aswell
Alright, will update asap
ty ❤️
still timing chill
Oh.. I have my trains manifolded. 😦 So they just dump all at the first stop until it fills up, then they attempt dump at first and carry all to second. 😬
i feel like that be hard with >780 throughput but idk
and by the way, the number you get after the equation 25200/(32x200) in the example, is the number of carts needed.
To meet that demand.
ok roundtrip time is 8min 30s (roughly since there was a train docking)
Unless you're intentionally not double-belting your platforms I am unsure where this hangup on 780 is coming from?
im currently gettign 2200 throughput using 2 carts
Okay - so then.. let us do this together
8.5+1.5
That's 10, then you wanted 2800 throughput, so 5600.
So 56000
Am I the only one that has variable round trips because of signals and intersections?
You're running two carts, so that's 12800 per train, you have three trains.. you transport 38400 then.
It does have a impact, sure.. but in the grand scheme of things, if you build your intersections well, it should average out and not be that much of a problem. At least imo and in my world.
38400<56000
So no, 3 trains with 2 carts each will not be enough.
Sure, but if you're mathing it and timing it.. how do you know which end of average you're on?
but im currently getting 1100 items per minute
with your math that should be impossible
Okay...
You really think that impact is gonna fix the discrepency between him delivering 38400 right now and wanting 56000? @ashen girder
Nope.
🤷♂️ He needs two more trains.
Don't recall ever implying it did. 😂
no youre using wrong math
with your math 1100 would be impossible
wouldnt that mean i need more trains since all my trains have to go to 2 stations so the roundtrip is longer?
@thorn bane how many cars are on this train?
2
2 cars with the incoming fill rate of 1200 each, right?
currently 1100 i want it to go up to 1400 yes
And you're getting 1100 at the output. Which makes perfect sense.
i mean right now im only providing 1100/min
Yeah.. I don't see how my math is wrong?
You know that items/min thing is about as accurate as the machine efficiency displayed in the UI x:
Yes. And you're getting 1100 out, as you should.
or the drone port port UI.
yes so right now im transport everything im producing
im curious if it would work if i up it to 1400
Okay. So - you said the time from first honk to third was 8.5 minutes, and you have three stations?
And you want to transport 1400 per minute?
Correct?
Gotcha. Gimme a minute. It should work, but I can confirm.
i have 2 freightplatforms
Yes - each train has two carts.
1400 is 700/min.. it should be possible from one platform.. in theory
correct
Correct?
no its 2800 total
Wait. Then no lol.
There's lots of math going on in here. Not sure there's much else though. 😂
#math-and-meta message
#old-questions-and-help message
2 stations 2800 steelpipes/min total
so 1 station is 1400/min
im currently only providing 2200 (1100 each) and i want to know if it would work with 2800
the total from all your train platfoms for train throughput Irrelevant. for math purposes we only need the throughput of one station.
i know its 1100 now and i want to know if 1400 works
steelpipe is a stack of 200 yeah?
yes
train blocks it for 25 seconds
That might be what makes it possible.
30seconds
28
8.5 minutes traveling time
1.5 minutes of locking belts due to docking
desired throughput is 2.800x2 because round trip.
5.600
10x5.600=56.000 items needed to be carried each round trip.
Even if I'm wrong with the belts locking, you'd still need to transport 8.5*5.600=47.600 items per round trip.
Which, you're carrying two carts per train, each cart has 32 slots, so 64 slots, you're sending steel pipes.. which means 200 per stack..
That means one train with two carts can carry 12.800 in total.
But you have three trains doing this route, so that means 12.800x3, which is 38.400
I had a chart for freightplatform throughput..
it was on the wiki but it got removed and replaced with some fancy math..
I literally just did the math but everyone is ignoring it and just keeps talking about how much it could possibly be.
well that doesnt tell me if they actually load fast enough
i know 3 trains is enough if you ignore blocking
Welcome to the Meta part? 😂
you cant just say its 3 trains and multiply throughput by 3
^
Assuming you stagger then, for simplicity, yes I can.
Especially since they'll counter out eachother after a while with blocking.
@thorn bane 8m 30s was including animation times, yes?
blocking input is a thing
Which I accounted for - did you even read it?
nah and it was very rough estimate since it stopped infront of another car
I did. But you can't multiply throughput of one train by 3 to get throughput of 3 trains
I can work with rough estimates.
This particular train has 2 stops or 3?
I think it possible if you stagger trains.
A to B is roughly 830 or A to C?
A to B is 900 A to C is 1900
8m30s sorry.
And when were you gonna tell us this?
I asked for all of the details before..
The one thing that concerns me is you're getting pretty close to 780/min and.. your belt has to be fast enough to move enough items so when the train docks your buffer doesn't empty
?
I would build it, and test it with awesome sinks and see what it do.
The math is this:
((TripTime - (Animation * StationCount)) / TripTime) * 1560 = Max Throughput per Car.
yep thats the issue 🙂
according to my math its just barely enough
So if A to B is 8m 30s then your max is 1394.33/min
That's using 27.08s.
For 1 loop there are 2 animations. Both for loading and unloading.
but i only care about the loading animation since i have trains waiting so it doesnt matter how long they unload
just image its 10 trains instead i think that makes it easier
It matters though. Because you aren't getting throughput during either the loading or unloading.
So both detract from the total possible.
i just care about the time it takes to load the train right? as long as that is lower than my throughput it should be fine
Oh you're saying don't factor the unloading animation time?
Hm.... I guess in a way it doesn't matter.
So then yeah, 8m30s travel time has a max throughput of 1466.17.
ok so a train docks
it now waits 28 seconds
it then loads 6400 steelpipes at 2x780/min so 4min 6 seconds
so in total 4min 34 seconds
so in total i have a train coming every 4min 34 seconds
4min 34 seconds * 6400 items is 1401 items/min
again i dont think the travel time matters since i always have a train waiting
Travel Time usually is just "Time The Loading Station is Filling"
also i just finished the space elevator 🥳
Because that's what you need. % of time the station is actually filling * belt speed.
but since it always waits until 32 stacks that independ of travel time right?
Yes, so for you specifically it would be ((TimeToFill - Animation) / TimeToFill) * 1560 = Max Throughput per Car.
If there is always a train waiting to be filled.
i mean if there isnt ill just add 10 trains
what is TimeToFill is that with 780 or with 700?
Fair, but you can do 1477 throughput per car on 1 train with an 8m30s timer.
So 10 trains seems a bit much.
TimeToFill is how long it takes to fill the car, which will be dependent on stack size.
Le Graph
depending on?
Hour long train still hits only 1548 throughput per car.
i still dont get how an hour long train changes anything
it will still be a train every 4min36s
You don't have an hour long train, you have a 4m36s train.
Graph just 1. is fun and 2. shows 1560 is improssibru.
Asymptotes are stupid.
no i mean if your roundtrip is 1hour you just have 15 trains departing every 4min 36
DumbAs(symptote)
i mean how else are you gonna get that throughput
With 1 hour long train. 😛
(I'm past your particular scenario since we already solved it)
so 20 freight cars or what?
no thank you xD
I mean the formula obviously hard-caps when the station fills, because then you're changing it to this:
((TotalTripTime - (Animation + TimeSpentFull)) / TotalTripTime) * 1560 = Max Throughput per Car.
So you could honestly simplify/complicate it to:
((TimeSpentFillingPlatform - TimeSpentNotFillingPlatform) / TotalRoundTripTime) * (NumberOfBelts * BeltSpeed) = MaxThroughput per Car
If you wanted it purely in variables.
But since "TimeSpentFull" should always be 0...
NumberOfBelts should always be 2, and realistically when going for max you're thinking in belt speeds of 780. Add in the animation time being fixed and the formula simplifies to:
((FillingTime - 27.08) / TotalRoundTripTime) * 1560 = MTpC
Which technically means in shorter distances... Trucks win. 😛
well thats assuming you dont just build multiple trains
Even then. Trucks can actually hit 1560 now.
Since they begin belting the moment the first stack is unloaded.
As long as you aren't fully loading the every single slot in a truck.
Station is also loading behind them while they are loading. So you don't have any throughput loss unless the station at either end of the loop becomes full.
ok next question how the hell do i balance this if i would go for 3 stations
i have 6 lines of 440/min and 1 of 160/min going into 3 stations
You balance it, by stations. So whats input into a station, is a belt on the other side
Platforms or Stations?
platforms sorry
What are you trying to balance?
The math above is per platform since it is per car.
So since none of those platforms are trying to hit 1560, they will all have the throughput exactly where you want them.
nah i just need to get exactly 2800/3 into the platform otherwise the load until full will be screwed since they wont be full at the same time
My solution is just stop doing the load until full 😛
then how would you time the trains so its perfectly 1400/min
longer train? maybe? 3 cars rather than 2 x:
Manifold 🙂
but thats extra effort
building longer platforms is pain
?
bruh... lol
Just overload the shit out of station A until it fills up.
After that, it will stop at A and take everything to B.
compared to clicking "wait until full"???
how would that help me to get 1400 throughput on 8min roundtrip?
considering how long you've spent here and how long you've spent trying to make it work with 2.. it seems like a valid solution
You need 900 at one and you have 2800.
So keep sending 2800 until the 900 cannot accept anymore.
wat?
Sec
Had to find what you wrote earlier.
Send the trains on a loop through all 3 stations.
yes how would that help me?
You need 900 at one and you have 2800.
So keep sending 2800 until the 900 cannot accept anymore.
Just overload the shit out of station A until it fills up.
After that, it will stop at A and take everything to B.
the problem is the 2800 not the 900
im wasnt sure if i can hit 2800
On an 8m30s loop you can do 1477 per car.
that sounds wrong
So if you have 2 cars on 1 train, that can do 2954.
there is no way 1 train does 2954 with 8min roundtrip wat
That's literally what "((TimeSpentFillingPlatform - TimeSpentNotFillingPlatform) / TotalRoundTripTime) * (NumberOfBelts * BeltSpeed) = MaxThroughput per Car" is solving
If Total Round Trip is 8m30s, you have 1477 per car.
So 1 train with 2 cars is double that.
oh right i keep forgetting that its 200 stack size xD
wait what?
if you have 1 train with 2 cars taking 8min 30s you can at most have 6400/(8min 30s) = 750 items/min
i think your formula is wrong
TimeSpentFilling is different than TravelTime so when you're making things wait until full it's a bit different.
welt you said with a round trip of 8min30s you can have 1477 throughput with 1 train/1car
thats impossible
Why?
because at most you can move train size per trip time
Ok.
if you have 1 train the maximum throughput you could ever get is ~750
you need multiple trains to get >780 if you have longer than 8min trip time
This is because of your stack size?
well with 100 stack size its 4min 6s trip time for 780
Yes, so this is where the "TimeSpentNotFilling" comes into play.
Because due to the TotalRoundTripTime you've got space where the platform is backed up if you're doing only 1 train.
Like I said the formula is hard-capped by stack limit.
Let me re-write it because I can see what you're saying so I need to add variables I cancelled out.
752.94ish is what you're getting @thorn bane ?
that was just a rough estimate without docking time
Animation time cancels out if you have 1 loading station.
how does the animation cancel out?
it def. should be in there otherwise youre gettign 1560
Wait... I think I found it.
Oh this is simpler than I thought. 🤦♂️
@thorn bane TimeToFill = TTF, StackSize = SS, StackLimit = SL, RoundTrip = RT, Animation = A
TTF = SS * SL / 1560
If TTF >= RT: MaxThrough = ((RT - A) / RT) * 1560
If TTF < RT: MaxThrough = (TTF / RT) * 1560
does it have enough ingots?
Your stack size is 200.
Limit is 32.
6400/1560 = 4.1 which is less than your travel time of 8.5m.
However, you said the actual travel time is 4-ish mins if you're waiting for the car to be full every time.
So if the 4m6s fill time matches the travel time, then you go back to the first formula. And I'm getting a max through of 1388 ish.
@thorn bane
@wind spade
?
ok i build the extra 600 steel pipes/min
its going up 🙂
It could potentially hit 1400 depending on the actual route time.
But 1380-1400 sounds correct without exact numbers.
Those 2 formulas do account for all scenarios though so I am confident in saying they are the formulas 🙂
U asked if it gets enough ingets
I showed u screenshot
it shows the problem just dont know how to fix
screenshot doesn't tell me anything. How much ingots per minute do you produce
and it doesn't show any problem
The funny part (to me) is that after like 100 trips if you tell me what the throughput is I can tell you exactly how long the trip time is 😂
i still dont think its related to trip time if you do wait until full
If you wait until full it still has to travel from origin to destination.
if you ahve 1 min roundtrip and 1 train it docks every 4min6s
if you have 60 min roundtrip and 20 trains they still dock every 4min6s
What is changing is that instead of doing RoundTripTime you're reducing that simply to PointToPointTime.
Sorry buddy had to get off
What i meant was in the ss u see i got splitter and 1 of those bands u see more ingots then the other 1
because the belt is longer?
4m6s is the "TripTime" there?
Or are you calling that variable something else?
Does that matter?
It doesnt feel as fast tho
time until the car is full so wait time since its set to wait until full
I was making plates and u can only have 3 in the machine maybe
TimeUntilFull + Time it takes to go from A to B though.
but the time from a to b doeesnt matter
the only thing restricting you from 1560 throughput is the dockign animation
and that will ALWAYS happen every 4min6s because thats when you have produced enough items to fill a car
If you have a train leaving every 4m6s that means you have one arriving at the other station every 4m6s, right?
i dont really care about the other station but in a 1 to 1 case yes
if its like my example where i have multiple outputs then no
In your example unless the 2 stations you're sending trains to are exactly the same distance from origin, they will have different throughputs.
yes (also depending on which trains go where)
So, given that, if I may use the 1-1 example:
all i care about is if i can get my production into a train fast enough
because then i know it has to go somewhere
but if my production train stalls im in trouble
If TTF >= RT: MaxThrough = ((RT - A) / RT) * 1560
Your TTF = 4m6s, and the train arrives every 4m6s.
So the total time is 4m6s + Animation.
Which, RT-A gets rid of the animation, and is therefore your FillTime (Because TTF = RT when they are both 4m6s).
Meaning the formula is still working, you're just putting TTF where RT is (which is fine because they are equal).
In your case, writing it ((TTF - A) / TTF) * 1560 is the same thing.
It's when the fill time is longer than RT, which applies when you're not using "wait till full" that writing it my way matters.
And travel time definitely plays a part even when "wait until full" if the TTF < RT.
As shown in the second formula.
Say it take 4m6s to fill that container but 6m to get from A to B.
Second formula then applies, not the first.
Until you add multiple trains, because then it takes it back to RT = TTF given one will always be the exact difference between RT and TTF behind the other.
so it depends on the time to fill not the roundtrip time right?
(4min6s not the 8min30s)
thats what i meant with the roundtrip time doesnt matter (only the time to fill)
With the way you're doing it you are making TTF = RT.
Meaning yes, it can be done entirely in terms of fill time.
So your max is ((TTF - A) / TTF) * 1560
anyway i think im done with satisfactory for a while
i achieved my goal of golden cup and 13 Million awesome points/min (20 ADS 2TPR 1 pasta/min) in a fresh U5 playthrough
but most of those 150 hour was with <20 fps which is just super unfun to play with so until they change that or im upgrading my pc im gonna peace out 🙂
(more pictures here: <#screenshots message>)
GTX 1070
CPU is i7-6700K
Still good
Idk how much FPS im getting and idc how much exactly because it makes me paranoid
Aslong as i dont see it
It runs good for me tho
I probally dont have anything close to your factory
I just got the game
some good old texture down-scaling and u are back with fps xD 80% is good. i playing with 50 fps on old potato that is not even supported 😄
congrats on the cup, We'll see you again soon prehaps
If I'm producing both silica and concrete at the same place, is there a reason not to use Fine Concrete and Cheap Silica?
I'd rather put silica into the sink. What other resources can be addressed at that location?
I'd definitely consider it
tools recommend it if you don't have water or oil
I now hate Cheap Silica as it is one of the only recipes that doesn't respect the rule of 45.
But other than that... no. No reason to not do it.
Oh! Hello! To be brief, not much:
-it's the same as production planner with fewer options/details, but same problems
-Missing arbitrary control over production restrictions, e.g. clockspeed 100% requirement, precise byproduct usage, etc., custom recipes for mods
overall I really like the existing tools, I just wanted to create something I had very fine-level control over without forking a branch and changing the src
whats cheap silicas recipe?
Limestone + Quartz = Silica?
-it's the same as production planner with fewer options/details, but same problems
what prodcution planner do you mean here?
Probably SCIM. 😂
ah. And "fewer options" was that I have fewer or they have fewer? 🤔
I see
Yours definitely has fewer.
SCIM's simple mode is basically the exact same.
SCIM's advanced mode is.... kind of a lot.
(I'm not making any value judgments here. I don't use the advanced stuff.)
It comes out in 26.25's so thats 105 as the whole number. It goes into 60's nicely but blegh if you try to make it 45.
I looked at SCIM's advanced stuff and noped my way out
scim can't do loops e.g.
wait there's an advance mode?
The default mode is advanced.
Sorry, "realistic"
oh cool, yeah that's what I was using, was worried I missed something XD
clockspeed 100% requirement
I've actually tried this and it produces a lot of byproducts so I deemed it not useful.
precise byproduct usage
not sure what do you mean by this?
custom recipes for mods
it's planned for the future, but iirc scim doesn't have it either
I've actually tried this and it produces a lot of byproducts so I deemed it not useful.
The reason your calculator always annoys me. 😂
I want those byproducts. I do it intentionally. But it means I can't actually rely on your calculator at all.
I don't want for this to be "mine is better/worse", but checking SCIM now it isn't that different from what I have. SCIM doesn't do resource limits, also doesn't seem to optimise for raw resources 🤷♂️
Yeah, I wasn't trying to make it that kind of thing.
so add them to your production 🤷♂️
That means I have to calculate them individually. For every step. It's basically as much work to just.. do it by hand anyway.
I know this is numbers so, is this the max the map has for resources?
yes, that should be the map max
wait am I supposed to use all the crude oil on map just to make the item TPR (max a minute)
No, you tell it how much you want to use first.
Do batteries have less power than it is required to make them
I did
#maximize
cause thats what Im goin for
confused.
nvm i got it
yes, that is the maxium resources on the map
xd goodnight. ps: don't try to make 100 thermal rockets a min
I will..
1 or 2 will do x:
hey all, i have a question, I need to do a 40/60 split with splitter and I am really confused on how to do that. basically i am looking to have 240 steel go one way and about 170 go the other.
so the input is 410 total
i think i got it
This is what i got, its not perfect, but I think its close. I got about 136 and 274 in the other.
Was gonna say, that's not a 40/60.
lol
Easy math: split the 410 in half, there's 205. Split again in a 1:5, that's 41 each. Take one of the 41s and split it into 8. That's 5.125 each. Take all but 1 and that's 35ish. 240, to within 1/minute.
Alternatively: overflow and don't bother.
ok, Is that Common Core math or old school math?? 🙂 jk thanks
manifolds get the job done, but sometimes you wanna have a little fun and perfectly split some bizarre ratio. this glass cube in my nuclear plant splits rubber in a 14:15 ratio
yea we are almost done with the last phase so we are cleaning up alot of stuff trying to get the best lines going, btw i am theraymans brother lol
Why not use advantage of the belt speeds? you got the perfect number (240=2xMK2) that you want for it.
If that splitter actually behaved I would be astounded.
why wouldn't it? The belt speed will not take more then 120 so the rest is forced out the other way.
Splitting into different belt speeds doesn't always go as expected due to the splitter's internal storages.
I was about to say that, the first solution proposed was way too complex ahahah
But you need a smart splitter at the first split ^^
Like it could go 170/120/120.
But you also will sometimes get 172/119/119 or other things. It is weird.
hmmm. would the 410 feed in that he has not rectify that in the long run?
I mean that internal storage is nonstop fed by the input faster then the 2 MK2's can pull it out.
The MK3 could still have preference and the mk2 could not be full as Sev pointed out ^^
There is nothing forcing the items to go on the mk2s rather than the MK3
so a bypass (splitter) from the 170 line to the 2 MK2's (merger) would rectify that then.
The only cases where this works reliably is when you're inputting more than the output, so each of the output belt *must be full
I don't know what you mean by "bypass", I'm just saying to extract the 170 as overflow instead as a normal split ^^ (overflow setting with a smart splitters, where the rest of the items are sent towards the mk2s)
Honestly, I've given up on balancing rubber for nuclear 
Tooany weird numbers, I'm overflowing it all (though, I'm also including the rubber production inside the nuclear factory, so I don't have all that much space for balancing anyway)
kinda like this (quick and dirty modification) now the MK3 wil try to fill the MK2 incase of it not been saturated.
Eh, lots of work just to avoid a smart splitter xD
I'm not sure this would work either, but the idea is correct. To make sure it works flawlessly without trying it out, I'd split the "170" line again and merge 2 outputs with the couple empty mergers' inputs making the 120s)
I dont know if the person asking the orignal question has access to them yet. I just found it weird ppl dont use advantge of the belt speed to achieve the final split. But with your explanation of the internal buffer i could see why (if not using smart splitters)
Myself, i'm only been playing for bout 2 weeks so i'm also still learning 😉
It was just the logic in my mind seeing that other solution that i thought, this is to complicated 🤣
Relying on belt speeds doesn't always work
I built ...two complicated splitting systems, I think.
One of them consisting of 30-ish splitters.
Afterwards I simply use rate limiting & manifolds 
it's like building 100500 fuel gens
it might be fun - for the first time
Like i said, i'm also manifolding, but not knowing the splitter problem, that seemed the most logical solution to that question.
well, we could use a better programmable splitter tbh
because currently they're unlocked so late to do so little
I just say: don't expect a splitter to fill up the "slower" belts first when it has a non-full high tier output to use too (unless you can set specific rules for the outputs)
Thus why I say to use "belt throttling" only when the input exceeds the output ^^
tbh, why do the splitters have a internal buffer? just take the incoming item only if you can push it out. no space? entry of the item into the splitter denied 😉
I wouldn't mind if they allowed for a few choices for more complex splitting (eg: send x/10 to the right the rest left), but even as they are, they're the only way to balance-split mixed belts ^^
well thanks guys, learned something to keep in mind when I ever need it in some case scenario.
I don't think that would "fix" anything xD
Splitters and Mergers were given an internal buffer to help fix issues they had when they didn't have one afaik.
I imagine Satisfactory has a lot of issues due to the need to accurately connect factory simulation to unreal engine world
those things are very different
It "solves" a situation where 270 belt splits to 120/270 belts. Before buffer, the 120 belt would have less than 120
It's almost surely gonna have less than 120/min with a buffer too, unless you art split 🤔
||@fierce ruin I was gonna fix this ☝️ with "smart" but thought you might find this the correct version already
😆 ||
iirc now it's like 119/118, before it was like 90-110
Doesn't sound like a proper solution to me 🤷♂️
A machine expecting 120/min would starve with or without buffer
I have 11.5 (ratio not value) input and need to split it to conveyors of 5 and 6.5. Is there an easy way to do this with splitters and mergers?
Not without quite a few split-merges. I'd use an overflow splitter and prefill, if possible
Okay, thanks.
Does this look right for the 1050 uranium waste in?
its suppose to make 30 a minute but it isnt making anywhere near
it says it needs 30 plates per minute
the recipe makes 5/min reinforced plates
owh i dont have 30 plates a minute
I fixed it
tho. i dont have another iron spot anymore
there's tons of iron all over the map
You can overclock resource extractors
Owh how
Get one of the glowing slugs laying all around the map and put them in the MAM
I was able to overclock my CPU to 5.1ghz but no oc something in game
Im dumb
No, just inexperienced
Just remember the belt limits
60 on mk1 120 on mk2
Exactly
But with overclock you can get 2.5 times the normal rate from a resource extractors
No
owh
You don't overclock the belt
it's how much you can output from a miner. You still need good enough belts to support that much
what do i OC
Anything you want... But with normal machines it's cheaper (in power) just to build more machines
Oc extractors to keep them at belt limit is always useful
Whats a Extractor?
I mean what do i build?
Everything you want and need
what do i need
Im making iron plates rn
How do i make Faster
And what is a Space Elevato
Look in your specials tab in the build menu.
Owh yea how am i gonna do this
With assemblers. 😄
Ugh
i would recommend making your smart plating factory a bit bigger than you think you need
or at least easily expandable
I wouldn't recommend making a factory for Project Assembly parts at all, personally.
🤷♂️
That's tiny compared to what you need later 🙂
^
You'll scale up over time. Expect every space elevator phase to be exponentially bigger.
I am currently scaling for 10/m Smart Plating, and it's a tiny tiny part of my factory.
just slap an assembler with reinforced plate and rotor inputs
no need for giant platform, yet, make as you go
Big platform is one option, several smaller factories are another. It's best to find your own style. Don't worry about getting it some kind of perfect first try.
Browsing reddit and screenshot for inspiration is a good idea
is this a good spot tho>
this is a picture of my base from a savefile analyzer, the area outlined in black is the platform i started with, you can see how i've expanded around it and made it longer
yes, you can make good factories on flat land
I just dont understand why my machines are slow
2 reasons: underclock or insufficient resources
a smelter can handle 30 ore to make 30 ingots?
is the machine input full or empty? It may be underfed
and a iron rod machine can handle 15 ingots to 15 plates amirite?
exactly
Yes
so you can feed 2 smelters and 4 constructors with all that iron ore
you're currently using 1 smelter and 1 constructor?
Uh yes
have you unlocked the magic of splitters and mergers?
you need to use conveyor splitters and mergers to feed multiple machines off one conveyor
Yes
Okay hold on
so a splitter to split 60 ore into 2 30 ore belts for smelters, and then split both ingot lines from 2 30 lines to 4 15 lines
seems easy right?
Okay so i place miner down
Then smelter?
And also biomass burner
I also have coal 1 Just dont know how to use it
Coal gets used later for steel production. If you're just starting, I wouldnt worry about it just yet
Okay
Miner makes ore, ore gets put into smelter to make ingots. Buomass burner powers everything. Ingots are used to make parts in constructors or assemblers. The thing is is each machine takes and creates parts at different rates. So you cant just line up a row one smelter to one constructor, etc.
look at the picture i sent: 2, because you need 2 to handle the 60/min ore
also, this
yes, and now hook it up
wtf is this
Space Giraffe-Tick-Penguin-Whale Thing
So if thats the problem to what i got earlier thats the same problem to what i got with my reinforced iron plates
I was making screws and it kept stopping
because it was to much
That's a bean.
i got you 1 minute
And then i got 4 storage things right?
?
Power poles, friend.
why are you making 4 seperate storages? you can use mergers to feed them all into 1 shared storage
Owh
Im dumb
i dont have any idea how tho
Only 3 fit
I think i know what u mean 1 sec
What's a good battery production rate for a drone port network? First time I'd be using drones. First time I'd be using drones, and not sure whether I want to use the default or alt recipe.
Alt has benefit of not requiring weird liquids
That's going to depend on how you plan the drone network, how many do you plan to use? The drone ports are thankfully very info dense and once you them, they tell you how many batteries per minute they use. I use the default recipe and have drones fly in the sulfur for it. They bring in about 204 sulfur /min and use 2.96 batteries per minute per drone ( I use 2 for this purpose)
I removed everything on my deck and im redoing it
I have no idea, might be huge, I'm just wondering what a good starting point or benchmark is.
I haven't even started building it yet and need to build the battery plant first.
So im still using my starter production line of 120 batteries / min and have a network on each base I have so you can start somewhere in that area and be fine for a good while. The battery line wasnt too horrible to set up as long as you have an AU plant
My difficulty was sulfur, which manually drove in until I could set up drones to do it for me
I only have a small basic one for base supplies than a full on real one.
How many AU casings per minute? The default recipe is heavy on those if you're just starting out with AU refinement
@still troutHow do i do the same what i just did but with a assembler
wdym?
use two mergers and merge the output of one merger into the other
explain more
okay i wanna make reinforced iron plates
earlier u helped me fix the problem with this
So how do i do this but with a Assembler?
you need one conveyor with normal iron plates, and one with screws made from rods
I'm using the alclad casing alt, so, looking at the rate you gave, it's 1.067 assemblers. I'm technically making two assemblers of it, but I didn't underclock the other one. I'll go back and check the numbers.
These only do 10
show the screen of an assembler
They take 10/min to make 40/min
I dont understand that lmao
in 10, out 40
Yeah, my set up uses 120 casings / min, so an extra assembler slightly overlocked will fill out that part of making 120 / min.
Uh so i need 2 A smelter or 1 a smelter
One of my to do lists is to actually swap to that alt, because batteries are eating most of my casing production and casings are used for so much in end game
i think you need 1 constructor making rods, then split that into two screw constructors
also 2 iron plate constructors
You best start reading the info inside machines. Go up to a smelter and look what it tells you.
When you selected a recipe
Doesnt tell me much
it tells you everything you need
Wdym, it tells you 30 in, 30 out
But i dont have the brains
play more
Its not about the smelters either its about the Constuctor
If you cant read input and output you might have issues playing
other people won't do the maths for you. There are some online tools that you can use (or just a calculator)
yo
looking forward to making a supercomputer factory
cant pick between OC supercomputer and super-state computer
Okay 1 question how much Constructors do i need?
For what
Reinforced iron plates
5
how many per minute
also, reinforced iron plates are made in assemblers, not constructors
Just start building a random amount of constructors and assemblers. You eventually will produce reinforced plates 
wich ones are for screws and wich for plates?
Lol mcgalleon.
If ya take a look at the machines, you can math out how many for each component
figure it out yourself: the reinforced plate recipe requires 30 plates and 60 screws per minute
open any of the online tools, put in how much you want to produce, check out the numbers, easy.
Online tools? where can i find
If you cant do that type of math yet you better start practicing cause you will need that a lot on this game
i mean, not this early on, you can literally do the math in your head bro
this
I know math i Just dont know the game very well yet
google, pinned messages here, #welcome
And i didnt even know it was a big factor
dude, it's much better if you go in game and figure out how to turn 60 iron ingots to 5 reinforced iron plates
I Just bought the game because it was on sale
go do that rn im serious
Then you should be able to figure out how many machines you need. They all tell you how much they need and how much they produce. Thats all you need
If you need, say, 40 iron plates, how many constructors is that?
2
And how many ingots / min do you need for them?
correct: now for 30 plates?
1 and a half
Or 1 over clocked once
Dont mention overclocking yet thats too advanced

How? like it does 20/min how will i do 30
you need 1.5 constructors for plates for a single reinforced plate asembler, congrats
I did a overclock and the Power shut off
Overclock consumes more power
do 2, the numbers will work themselves out in the end
U are a Fraud u need 3
20 a min
Eh yea true if you want just have one going at 100% and another at 50%
So i need 3
One assembler needs 30 plates
are you serious?
You are the fraud
I am. I just dont understand
check the numbers
It sais on the right 20 a min
Check your smelter
20 x 3 is 60 thats what i needed
It should be what 30 per smelter when it comes to iron?
Why 60
Idk
you need 30
Do you have 2 assemblers or what
that was for iron rods exclusively
Owh
Wait your iron rod build is wrong
Okay so i need 2
if you even have underclocks
but why 30 when the miner does 60
I do
So that one miner can feed multiple lines, if eneded
Because you only need 30 plates for that recipe
plates are made at a 3/2 ratio, so 3 ingots for 2 plates
it isnt always 1:1. Sometimes the production is in your favor, sometimes it isnt
Not 60 or 90 or whatever
uh
you're using 45 iron for plates, and the excess 15 for rods and screws
uhh
You want to feed ONE assemler to make reinforced plates. Thats your goal right now
Dont overcomplicate it
so you got most of the machine down: you need 2 constructors, one underclocked to 50%, making iron plates
now the last 3 constructors
The entire point of this is so you make your reinforced plates. Thats all we are talking about right now
What's the indecision about?
I think those recipes just trade complexity for resource efficiency (mostly a save on aluminum and nitrogen)
iron plates and screws are sub-goals for the goal of reinforced plates
So it comes down to what resources you'd like to save on the most
supoer state is simply overpowered
Okay 1 sec lemme Place down consturctors
dont do OC unless you wanna use TWICE the amount of (weighted) resources
I want to make some extra "byproducts" as well and the build trees are quite different
going with super-state computer for now
don't, before knowing their use
btw super state computers is one of the best recipe for awesome points
BRO WHY IS THERE A STONE IN MY WAY
Because you ignored it?
just build around it
Done
Congrats, what will you use them for?
To make certain things
Yes
which ones
Certainly
what do you need the other 3 machines for
Uh screws
1 for rods, 1.5 for screws
also, you should connect both smelters to a merger and split that into 3 conveyors
screws require rods
so screws does need 60
unless you get cast screws
Bruh how stoned are you
no, 1 rod makes 4 screws so you only need 15 rods for 60 screws
huh
very
Rods make screws, screws and plates make reinforced plates
you have the right amount
Owh
you just need to rewire your conveyors so they work at good efficiency
how
connect smelters to a merger, then that to a splitter
what
Combine the 2 smelter outputs onto one belt. Then split that
dang caterium comps look good but 105 quickwire per manufacturer sounds like conveyor mess
Use a Merger for that. Looks like a splitter, but orange
Can u draw it
Literally just connect the 2 belts to a merger
Wich belts
That's a person.
cute spider thingy 😄
Smelter output
SMELTERS to merger, merger to splitter, splitter to PLATES AND RODS
why merge a splitter
A mess how?
One quickwire belt for up to 7 manifacturers isn't so bad, right? xD
Put Belt from Smelter into Merger.
yeah but you end up with the odd 8th manufacturer with a separate line, just a mild annoyance 😄
then just build more 🙂
Go for 6? ^^
Or 12 xD
the box on the right is supposed to be a merge
you awakening cthulhu or what
na, ill use caterium boards as well and share the quickwire lines
trying to make this guy understand my idea
Belongs in #fan-art 
Like this?
if you dont like quickwire you can always use silicon circuit boards
Connect smelter to merger
they're amazing, but not gonna input quartz in this equation
😦
still planning phase so that might change ¯_(ツ)_/¯
good job
now you need to split it into 3
I still don't get what your priorities and objectives for the plan are 
That isnt connected is it?
- make supercomputers
- have some leftover computers and other things for building
now hook up the 3 to the 2 plate machines and the rod machine
How i only got 1 splitter?
You put one down?
i mentioned 3 machines, for 3 outputs
Hell yea
"Other things" such as ^^
Huh i only need 3?
U said 5 earlier
yes, the screw machines use the fucking rods you're trying to make rn
Rottis stop, this is going nowhere in the next 3 hours
It will trust the process
, so after doing some hardcore math, was able to find a way to get efficient 45 smelted caterium per minute, does this look good to you guys?
Okay so what do i do
(120 belts)
"hardcore"
you have my curiosity
So i only need 3 machines?
i'm not very good at math LOL
Play the game and try things out. You will find a solution eventually
quickwire, rubber, circuit boards, computers - anything really
Are u a developer?
Nah
But thats how i did it
I didnt know the game either
I jist built shit and hope it works
Can u help m,e
Nah i cant i already tried 
we have, for the past 20min
You either have memory issues or are ABSOLUTELY STONED rn
those are rookie numbers
Aight fair
I mean, it's technically been 1.5 hours since we mentioned that factories get bigger than a few constructors and assemblers.
1 more chance?
Rachel gave mike a chance in suits so i deserve 1 too
Only if you start writing shit down on some paper
I got you
draw a plan on some paper
Alright
Start with the assembler that makes reinforced plates
just put the numbers in an online tool lol
Huh
And work BACKWARDS
so you have 60 iron, and it's going into 30 plates and 60 screws for the assembler
send me 1
Thats easier
I have 60 iron yes
no, this is baby math, why use a calc
as I already mentioned, google it, or open pins in this channel or check #welcome
Thanks your not like this douchbag
because they apparently aren't able to do such math
i find it hard to remain calm, i will leave the conversation
I literally said where you can find a list of all the tools...
Don't thank me. Be embarrassed that you still haven;'t got it after 1 and a half hours....
UUUMMM GUYS i did math and, the dessert base that i am planning on fencing off, produce iron nodes without overclocking and basic setup, 2310 iron/m with overclock to mk2 belts that is 3435 iron/m, with only iron, if i add copper or water that is even MORE iron.
i am able to do such things i sufure from memory lose. that means im dissabled so your making fun of a desabled person
I'm not making fun of you, I've linked you to #welcome
Theres like a thousand links
if you can read, you will see them easily
How does this work
to small
Find reinforced plates
yes
And then input "5" on the right
scroll down to see what it shown you
ok am running a balancing coal gen area, 9 gens 3 extractors and it works
🤦
Thats a bad ratio
3 extractors aren't enough to power 9 gens unless you modify clock speeds
Bro what is that. @still trout thing was clearer
I only have the miner with modified clock speed i think lemme check
see? now you respect me?
I do
what's not clear about this?
that it doesnt make clear that u need merger wich rottis said u did
i mean, i'd be surprised if he understoo how to make concrete
I do
you don't need mergers tho
I let a machine do it
Blame @still trout
you can use them if you build it in a certain way, but you can also not use them if you build it some other way
my miner is producing 300ppm which goes to coal gens at 150ppm
you don't have enough water
3 is enough for 8, flat
9 coal gens need 405m3 water, 3 extractors produce 360m3
Do they need to be next to each other or behind?
up to you
all three extractors have two shards each
so no, I think im good
that's kinda wasting power, but sure 🤔 then you have more water than you need
Imma need it quite soon anyway
@lunar pivot where are u from? just curious
and alot more of it too for something late game
The netherlands
still - building more extractors saves you power over OCing them
true, but Im using grasslands puddle which only fits 3 comfortably
that's way too much water, enough for 16 gens, you only need one shard or one more at 50% underclocked
Just place them next to each other. Whats the issue?
Olace what that means?
Sry typo
Place them
How is the rods gonna transfer From one of to the other if they are next
using a belt?
belts
By using mergers and splitters
What is a belt?
Bruh
conveyor belt
......
Owh
-_-
i've lost faith in humanity
Yes i know but how is it gonna acces the back of it when the back is the back
Dude, go to bed, get sober, then try again, okay?
nah bro you got this i believe in you
look this is what i mean imagine 1 is rods and the other is screws
put the one making screws AFTER the one making rods
@wind spade for something late game I will need 34,272.28m3/min
just build that thing on the ocean and don't overclock 🤷♂️
Thats what i said but u said i was able to put them next to each other.... FRAUD
you dont need to put ALL of them next to each other
fraud!
U ARE
north sea has lots of space
south sea? theres void there huh?
@lunar pivot how old are you?
south western @thorn bane
but you cant go as far without taking damage
north you can go really far
15
I only need like 40 extractors I think
sry i got ADHD and forget what we were talking about
I mean, you could connect them next to each other still. Use lifts and attac conveyors that way. Result in a spaghetti mess, but entirely possible.
reality check - all these are "next to each other"
thats alot of water what are you making?
I got 3 on a row
nice. what now?
hard to believe, you act like you're still in preschool
I have plans to make 103.48 TPR/min
ah thatll do it xD
Haven't talked to many 15 year olds, have you? 😛
Danb
Good god that's a lot.
Damn
Now im gonna put it
guess not...
@still trout you can just ask him for his age and then not say yours?
yes, i will do that
Why use 1.5 when i can oc it to 150
technically even if asked neither party should say
or you can build two and oc them to 75
say if u wanna thats the way to go
Nope not effecient
or 3 and oc to 0.5
or 50 in a manifold at 100% and it still works 
owh
power comsumption scales with overclocks
SMART IDEA! very smart!
gys, to make the TPR 104/min I need to use all the nodes on map for crude oil, quartz and nitrogen
ooooor use one at 100% and one at 50%
Is that why my Biomass full was running out that quick?
yep
Does that account for enough power to run itself?
150% uses much power
Damn im stupid
just dont do 104 TPR
if you want points do ADS
if you wanna do TPRs dont go over 50 since you start using bad recipes then
OCing makes too much power
takes a lot
but thats not the most complex item so NO
but you can make 3x as much
eventually probably as much power as ImKibitz has built possibly
also technically i think plutonium rods are more complex? they just give less points
dont think so, half the products for PFR are mid-late game
like the transition phase
and another ingrediant is steel basic
the only ingrediant thats late game is EPC
PFR (PlutFuel Rod), EPC (encased plut cell)
particle accelerator
heat sink and ECR you make mid-late game transition phase
nah fam plut fuel rods complex shit
then look at TPR...
bro i got that automated at 0.5/min alrdy
cause I have and...
raw grey, other outputs that arent reused are green, and orange is reused product/recpies
raw resources
yeah i sent a pic of my spelevator part 4 in #screenshots ages ago
i DID IT
in a fresh U5 playthrough?
ye
nice 🙂
