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what is the conjugate of 1-z?
u need a imaginary number to take conjugate
yeah let z be an imaginary number
complex or imaginary
complex mb
then its 1+z , no?
aight so if z = 2(cis theta) ur saying that the conjugate of 1-z is 1+2(cis theta)??
yeah i get the conjugate of z flips the imaginary part, but what about the conjugate of 1-z i dont get this
so the conjugate of 1-z is 1-z̅
then what was i supposed to do?
you were supposed to find two points such that the value of f at one of them is positive and on the other is negative and then apply ivt to the interval between those points
i look online and no one is showing how to find those two points
can you tell how i do it.
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$\frac{1-2cosθ}{5-4cosθ}$
Galaxy
Galaxy
let z = 2(cisθ)
i have to express the imaginary part of 1/(1-z) in terms of θ
im not too sure if this is the correct expansion
and im not sure if im overcomplicating this but is the answer just
$-\frac{sinθ}{5-4cosθ}$
Galaxy
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yo
u guys seem smart right
help me w my shit
or do it for me
i aint doin alla that
@ionic viper Has your question been resolved?
no
the shit closed anyway
wait thats a bot💀
@ionic viper Has your question been resolved?
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I would like to know how do you know if a line is parallel
Like
I’m learning coordinate geometry
and this line is parallel to another
how similar are the equations of them?
do you have an example question
if the slope is the same then they are parallel
Oh ok
thank you very much
I have another question though
how do you show that a point lies on the same line?
as another point
converting to y=mx+b form makes everything easy
yes I’m doing that
if you sub in (x,y) into that equation and it holds, then it lies on the line
if the equation doesn't hold then it's not on the line
no problem
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@thorn verge Has your question been resolved?
How does $a_n>\delta_1$ mean that $f(\varepsilon) < \varepsilon_2$?
Edward II
and also what is $N_1$?
Edward II
@thorn verge
@thorn verge Has your question been resolved?
because for all $x > \delta_1 $, $f(x)<\epsilon$ and im just choosing $N_1$ such that it satisfy the condition
cheesycrunchwrap
is it not allowed
oh I missed another error
double check the definition of a limit, because you do should not get $x>\delta_1$ means $|f(x)|<\varepsilon_1$.
Edward II
e.g. you're claiming that in the case where f(x)=x, all x greater something are also close to 0...
so for the limit definition as x approach 0+ i get for $x-0 > \delta_1$ then $|f(x)-0|<\epsilon$
cheesycrunchwrap
x-0 < delta
oh yah sorry
so that's where my proof is problematic
partly
. is this allowed thou
there's also the fact that the value of an has nothing to do with the value of f(epsilon)
so what im understanding from this question is that limit right hand side of f(x) =0 and if $n > N$ then $a_n -L < f(x)$ which give me nothing about how n would behave as n get bigger
(you need $s, latex uses > for upside down question mark outside of math mode)
cheesycrunchwrap
now you know you can pick some specific x such that f(x) < epsilon
by using this (correcting to x<delta)
thanks
so im picking x s.t $f(x)<\epsilon_1$ then it follows $|a_n-L|<f(x)<\epsilon_1$ and i don't have to restrict n because as n gets bigger the $|a_n-L|$ condition will be satisfied am i getting this correct now?
cheesycrunchwrap
yes
ok thank you so much
you don't even need the subscript 1s btw
for epsilon?
mhm, because you're not using any others
bc i wanted to distinct between the interval and the dummy variable
in the question it mention $f(\epsilon)$
it's notation anyway
cheesycrunchwrap
ok thanks just want to be sure bc im horrible with proof
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cba someone just double check pls
uh whats the y intercept for 2x-4y+8=0
what does the y intercept mean
yh its 2
point where x=0
and whats the y intercept for your equation
which one are u talking abt
oh it’s suppose to be +2?
yh
okay next one, the slope is correct here but the y intercept isnt
whats the y intercept for y=-x/2 - 3 and x+2y-5=0
uhh
Y= -x/2-5/2
hmm? how do you find the y intercept in the first place
cuz it’s 2y
and I only want y
so I divide by 2
you find the y-intercept by letting x=0
the x-intercept by letting y=0
oh
so what is the answer for those eq
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I have the problem of using the Gaussian method for the first task because I can't find a solution.
For the second task I don't know how to come up with the solution, so I don't have an approach.
@sleek thorn Has your question been resolved?
@sleek thorn Has your question been resolved?
Fürs erste würde ich alles in die erste einsetzen und dann die 8 möglichen Gleichungen ohne Betragsstriche durchgehen die das gleiche Ergebnis haben könnten
Keine Ahnung wohin man damit kommt, aber es wäre mein Lösungansatz
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determine the equation parallel to the bisector of the second and fourth quadrants which cuts off a chord of measurement 2squareroot(6) on the parabola of equation y = x^2 -x +3
Please don't occupy multiple help channels.
no one???
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There’s three vectors from the question, do I just assign one of them as (0,0,0)
the generalization
what is this "generalization" of which the problem speaks?
If there exist 3 scalars , (a x scalar ) + (b x scalar) + (c x scalar) = 0, then it asks for the generalisation for k vectors in R^ n
!original
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
this wording is D tier
Scalars being alpha, beta, gamma, and a, b and c being vectors
Then ending with vector k I guess
sorry, it's very hard to understand you when you try to type it out like that
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how do i continue / am i on the right path?
Please don't occupy multiple help channels.
Please stick to your channel.
.close
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and i cant use l'hopital
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Don't use chatgpt for math
!nogpt
Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).
I usually just use it to make sure I’m not missing anything because it is right sometimes
That's bad
Write it out and show it here
@leaden thunder is this correct
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Let ABC be a right triangle in B with AB=5 and BC=4. Hb is the intersection of AC with the height originating from B. AE is the symmedian originating from A. AE and BHb intersect at P. Find the area of triangle APB.
I tried to add new perpendicular lines coming from P on AB and BC and think about the problem in terms of the pedal triangle HaHbHc but that didn’t really help
@zinc pelican Has your question been resolved?
<@&286206848099549185>
@zinc pelican start by finding information you already know how to find
like angle C
and angle A
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Breh
Why didn’t u just combine the terms
5^x * (e^6.5)^x
Becomes
(5e^6.5)^x
No need for product rule
@glossy crown
U found f’ to be 5 which is wrong
f’ = 5^x * ln5
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so just checking
we are going to need 3 terms
our phi values are going to be interscetions
our rho values are obv going to differ from 0 to something each time
and theta will always be 0 to 2pi?
right?
this is a past quiz i found but no answers are linked lol
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2-x-x^2
How do i factorise this?
My guess would be to use this ?
no
to factorize a polynomial, find a root
and that means?
for factoring a quadratic of the form $\m fx = ax^2 + bx +c$, try to find two integers $u,v$ that satisfy the equations [
u\cdot v =a\cdot c \
u + v = b
]
a root is a value x such that P(x) = 0
and then you can substitute [
\m fx = ax^2 + vx + ux + c
]
and factor normally
So when y = 0 ?
whats y?
do you know how to solve a quadratic?
yeah
but no need to talk about y
I can do that but
how does that help me knowing that
Or rather, what is the next step after figuring that out
if you know the roots of a polynomial
then you know the polynomial can be written as a factor of a(x-r1)(x-r2).....(x-rn)
oh ok
thats a theorem on polynomials
So how would i go about finding the roots out?
solve the quadratic
like thats what solving a quadratic means
its litteraly the same as finding the two roots
its the definition of solving it even
I'm not sure how to solve it
because i've done it using pq formula
but i'm not allowed to use a calculator
so i can't utilize it
i assume i have to use square completion ?
I have no idea what to do
@austere moth Has your question been resolved?
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nadav
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uhh
how do you even solve these without calculator
rough tl : Every year in a city, there's a 2% increasement of the citizen amount.
in 2010 they had 900k citizen, how much citizien in 2020
well
the population increases by 2%
this is the same as being multiplied by 1.02
do you see why
yes
so uhh theres a formula right
yeah im just saying theres a formula for it
you know that from year to year the population multiplies by 1.02
how many years passed from 2010 to 2020
i can instantly count the next year will be 918000
no need
10
right
so 1.02^9?
how do i count them then
do you have a calculator?
so yeah we need a calculator in the end
uhh yeah i got one
its midnight here
i think this is jsut a bad question
wanna leave it at that or you can count it
why is it a bad question?
just put this into your calculator.
you are expected to do that, no doubt.
cuz its gonna take a long time without calculator?
okay then
here?
i mean you could do the long and painful calculation of 1.02^10
there are some tricks you can use to make your life easier
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im trying to figure out the question, what it wants from me?
It shows a system of 2 linear equations written in augmented matrix, and it wants you to solve it
i still dont get it, its probably because i dont know what to do(?)
like , x-3z=5 ?
yeah
note that this system doesnt have a unique solution
in fact, it has infinitely many solutions
The best thing you can do, is given an arbitary choice of x, find the form of y and z such that they give a solution to the system
so i can choose any value for z and then use the equations to find x and y?
hmm you will miss infinitely many solutions by doing so
Instead try working with x, and expressing the values of y and z using x
You could probably do it with z as well for simplicity, but the convention is to use x I guess
so i need to give any value to x?
This might be what he meant?
You already have z in both equations so...
Nope, you dont give it any value. You just let it as a letter x
So in the first equation you have x - 3z = 5
Try solving for z
yeah
now the second equation is y + 2z = 4
can you express y using x?
note that you might need the solution of first equation to do this
y = -2/3 x + 10/3 i think
You forgot the 4
4+10/3 = 22/3 but yeah
You sure?
oh alr
Ic what you did
Yeah so y = -2x/3 + 22/3
Though like I said, z is already in both, so I would've done it like
x = 3z+5
y = -2z+4
z is whatever
I would think so
this is a general form of solution
there are infinitely many solutions, so giving just 1 or 2 would be absurd
This tells you that given arbitary x, the solution is of this form
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Hi, can someone recommend a detailed, slow paced resource resource for stats. From which I can learn measures of central tendency and dispersions
Please ping me if someone replies
@remote mural Has your question been resolved?
Well I’m in highschool, maybe a little deeper than that. I just want a really good understanding
The basics
idk too much then but for hs math try basic resources
Can you then recommend me some resources to that would help me understand the concepts better?
Because teachers lectures and the reference books I’m given are really basic, they don’t make any attempts at improving understanding, just formula bashing
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how should I approach finding a solution for the second linear equation since i cant factorize 3m^2 - 6m + 6?
should I treat it as non-homegenous put -1 on the other side?
quadratic formula
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How would you go about solving for the area that encapsulates both 8sinϴ and 8cosϴ?
i cant wrap my head around the explanation my friend is providing so id like someone more adept to explain it please :)
if sorry if im not understanding the question but do you want the area of this?
because you could just integrate 8sin(x) from 0 to pi/4 and multiply by 2 to get that
oops i meant r=8cosϴ and r=8sinϴ
im sorry!!
polar is beyond me
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if the sum of the roots = 0, how do you know that the sum of the real part of the roots also equal to 0
does the imaginary parts of the roots cancel out?
because thats the only way for it to zero
the real part and imaginary part cant interfere
oh
so they need to zero independently
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just comparing both sides
what is next to sin(x) on the left side should be also on the right side next to sin(x)
on the left we have 3sin(x) ---> so "3" is next to the sin(x)
on the right we have Rsin(x)cos(a) ---> so "Rcos(a)" is next to the sin(x)
it implies 3 = Rcos(a)
R * cos(a) is a number, constant
if R * cos(a) = 3 then you have:
3sin(x) + 4cos(x) = 3sin(x) + Rcos(x)sin(a)
in other words equation holds when both sides are exactly same
nothing, it stays
thing is we only look at the coeffcients
ugh, yea it may be said this way
okay, but lemme show you a simpler example
when 5x = a * x
what is a in this scenario
and if 5x^2 + x = a * x^2 + b * x?
a = 5 and b = 1, right
thing is you just compare what stands next to x^2 and x
you don't care about x^2 and x
how? it's not
it's a conclusion
in the equation you'll still have sin(x)
like 5x = a * x and we say a = 5
in a = 5 there is no x anymore, but in the equation it is
5x = 5x
that's it
thing is here that "a" is made of two factors
R and cos(a)
but logic is same
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does anyone know if this a^k , so the k in the exponent is a common notation ? I have never seen that , therefore I dont know what it is supposed to mean and it isnt defined anywhere.
lol I see, but its very confusing that it wasnt set in the first occurrence of aij
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wait just to be sure
sorry
because you said A^k , you meant A in {0,1}^k by that right ?
.close
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How do i determine if a function is odd or even, i forgot how to do this
Definition of odd is f(x)=-f(-x). This means you want to show x^2=-(-x)^2.
Also the first one is even not odd
so is the 2nd one lol
mb
For first one, use (-1)^2=1
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0.000000000000011409999999999998458
diagonal method to solve?
lmao, my calculator would explode
You can transform the matrix and get some easy zeroes in there
Adding a row to another row does not change the determinant
so I should probably work my way from bottom to top
R4 - R3 -> R3
or would you recommend top to bottom
Doesn't matter
R1 - R2 -> R2
I will be stuck with a shitty large number tho, for R1 if I keep subtracting from R1
its zero
what is 0?
No?
Try it
determinant
Actually it's even easier with columns if you want to do it that way
how do you recommend tackling it?
I was thinking diagonal would be fastest for 4x4
but not this guy
You want the solution?
OK
Column 2 is all 1000 so you can subtract any value from all elements of any column
are we sure that no precision issues are at hand her
So subtract 1202 from the first column and 49 from the 4th
yeah you want to do this with columns not rows
if you insist on rows only it will be difficult and hard and a AEM
Then subtract the 4th from the 1st
You can still get a row of zeroes pretty easily
oh this answer is for different question but same idea
Exactly the same process
Subtract 1303 from the 1st column, and 39 from the 4th
C2 = 1/100 C2
i didn't know you could do column operations too
I thought it was only row operations
multiplying row by scalar
multiplying column by scalar
both of these are allowed when finding RREF?
It's similar to Gaussian elimination
Not identical because swapping rows or columns can change the sign and stuff
you are finding a determinant.
not RCEF
it'd be RCEF
right
reduced column echeelon form
also this is not necessarily a goal
we do not achieve it here
so if I wanna avoid RCEF here, what's the option?
i don't necessarily like or follow the way this has been solved, is there another way to do it?
column 0 makes sense, it means if you multiply the diagonal you will always get 0, so the determinant = 0
why does the 1/100 C2 now become a scalar of 100 to the entire matrix?
that doesn't make sense to me
the det of the new matrix = 1/100 the det of the first matrix (cause we divided a row by 100)
If you want a row of zeroes you can do R1 - R2 - R3 + R4
so det of first matrix = 100 det of new matrix
that's the most favorable interpretation I can see
@noble cedar
@noble cedar Has your question been resolved?
If you multiply a matrix A by a diagonal matrix D where d11 = 1, d22 = 100, d33 = 1, d44 = 1, then the result B has all the same columns as A except the 2nd column got multiplied by 100.
The determinant of AD is equal to the determinant of A multiplied by the determinant of D.
In your example the matrix on the left is B, the matrix on the right is A, and so the determinant of B is 100 times the determinant of A.
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so this is my problem and i know the head director is male because it is myself in this case
this is my work i have but dont know if im doing it correctly
<@&286206848099549185>
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Is a correct?
,w differentiate x^0.25 (x^(4/7) + x^(1/3))
Not the one u chose
Just do it like that:
f(x)=x^(1/4+4/7)+x^(1/4+1/3)=x^(7/28+16/28)+x^(7/12)=x^(23/28)+x^(7/12)
Now use that (x^n)'=n*x^(n-1) --> f'(x)=23/28*x^(23/28-1)+7/12*x^(7/12-1)
I leave the rest to you
I still think its c
this is what I got
23/28x^-5/28 + 7/12x^-5/12
correct
so c?
yeah
ok can you help me with another
If its a lot harder, sure. But if its almost the same, im sure youll get it by yourself 😄
yeah it is
Sure. Just calc it. You can easily calc the derivative of all 4 functions at 1 and eliminate 2 of them with just the slope. Then you need to calc f(1) and use the definition of the slope to see which of those possible two tangents contains (0,11)
@cyan fox Has your question been resolved?
<@&286206848099549185>
hi
Sorry, was afk. No, its not c. If you check f(1) of c, youll get -3+2+12=11. But your linear equation should contain (0,11). If its slope is -4 and it contains (1,11) (cause it hits the c) there), it cant contain (0,11).
s does that mean its a
because it has -4 slope and its f(1) is not 11
yeah
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@heavy snow Has your question been resolved?
that's fine yes
@heavy snow
p_0 sends everything to 0
yup
sure
it's completely fine
not everything has to be hard yk
I mean that's what you do for subspace proofs
they're not sophisticated at all
if you have a polynomial P with P(8) = P(-5)
then lP satisfies (lP)(8) = (lP)(-5)
it is yup eat cake
(at least for freebie subspaces like this)
intro linalg is more getting used to a new language than interesting proofs most of the time
nice profile dude
I mean it's nice if they feel like common sense to you, you'll crush that exam
try and find another subject to read about if you're really bored
oh thats my college entrance exam date
yea
#calculus is the gen chat
idk I mostly just lurk there
depends how serious the thing you're talking about is
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im so bad at proofs
yall have no idea
if yall can help with this and help me understand it so i can do the rest on the assignment that would be great
...
It’s my brothers h.w but I’m a little confused
just name 3 things that take a minute or just a few minutes
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I think it can be rays of light, blinking
what no
!occupied
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I’m saying for 1
@coarse bolt please go to a different channel. This channel is already occupied.
yeah
im gonna be a hardass about this but one person per channel
yeah i know i was confused 💀
she just asked in my channel
its a really simple question though so its fine i guess
Oh I’m new so I am a little confused
yeah its okay just type in one of the available help channels
#❓how-to-get-help for instructions
anytways can someone help me with this
im really bad at these
i just need help understanding how and stuff
so i can do the rest
Srry don’t know
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How would I set up the equations for this
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<@&286206848099549185>
3x+2+(x^2)+(2y^2)-x = 180
2x+2+(x^2)+(2y^2) = 180
2x+x^2+2y^2 = 178
Good luck soldier
Thanks
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How would I find BC
<@&286206848099549185>
<@&286206848099549185>
<@&286206848099549185>
Idk how to do sin yet our teacher didn't teach us that
@solid skiff
<@&286206848099549185>
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ohkk
pins your first message which is supposed to be your question
i needed help btw
past tense?
need*
ask away
i cant help, but what class is that for? just curious
precal
ohok
if i remember my statistics right this is an underestimate. y-y^. positive residual is the prediction (y^) was too low. negative means the prediction was too high.
oh so its an underestimate?
residual = observed value - predicted value
what is the observed value in this case?
23.4?
right
whats the predicted value?
not given
we don't, this is testing your interpretation of a plot of residuals
huh
in the context of the problem, its asking what does the point (175, 23.4) mean
i mean how do we find out if its an underestimate or overestimate
by knowing the definition of a residual.... observed value - predicted value
ohkk
but like
how wud we know if its an overestimate or underestimate
bonglord
dont give up on me pls
if we predict a value of 10, and the observed value is 15, then the residual is 15-10 = 5. which means the prediction was too low
when a residual is positive it must mean the same, that the prediction was an underestimate.
there is some estimate for a height of 175cm where the observed value was 23.4.
$$r_i=y_i-\hat{y}_i$$
$$23.4=y_i-\hat{y}_i$$
$$\Rightarrow y_i \geq \hat{y}_i$$
b0ngl0rd
$y_i$ being the observed value and $\hat{y}_i$ the predicted value.
b0ngl0rd
idk how much clearer i can make it
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i cant figure this otu
.close
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b prime cant be found with the given information
the trick is to substitute b for h
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how does this make sense
Does the denominator effect whether or not the left hand side would be 0?
you can also think of it as multiplying both sides by the denominator
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They didn't explain the reasoning behind setting the interval p >= -1/2.
I understand that this says as long as p is either -1/2 or any number that's larger than -1/2, the lim as n approch infin will not be 0.
But did they get that from just thinking about the function given? Calculator?
@sudden nebula Has your question been resolved?
You just multiply (n^2)^p with n
What's the exponent after multiplying?
huh? My question is about the choice of -1/2. I'm not sure I follow your response.
after multiplying where?
Multiplying this
For large n, what's 1+n^2 approximately equal to?
okay one sec
for any large n? hmmm. Some large number haha..
No
So this section is on series. I'm not sure if you question involves me looking for a pattern or.
I'm not sure then.
1 + n^2 is approximately n^2
oh sure
Hence why you can drop the 1
yes the 1 would make a very small diff. I would agree with that.
Hence why you do this calculation
can I do this -> n^(2 * n)
n^1 * n^(2*p) = n^(1 +(2 times p)) ?
I double checked on symbolab.
It's goochi
If you say so
Yes. Why is there a 2n in the exponent
Nobody is playing games
You just said you've convinced yourself that you're right
n^1 * n^2*n = n^( 1 + (2 times n) )
because:
Exponent Properties: a^n * a^m = a^ (n+m)
the 2 comes from:
(n^2)^p = n^2p
because,
Exponent Prop: (a^n)^m = a^nm
No idea where you're getting n^(1+2n) from
Multiplication is *
Exponentiation is ^
@sudden nebula Has your question been resolved?
I showed each step.
I'm trying to get help rn 😦
You can open a channel still bud
Do you see the math help (available) section
Well you ignored this first question
I gave my explanation for why I had the 2n in the exponent though.
You explained why 2p should be in the exponent
p and n are different variables
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yo

@smoky crypt Has your question been resolved?
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so Im having issues with this problem here
what do we have to find?
I keep trying it, and get the same answer of y=5, but the book has the answers in the back, and says its 1 but i cant seem to get that
the x, y, and z
solving for x,y,z?
oof i am stil at 2 variable idk 3 variable
right
alr
you can find x from 3rd eqation i think
wait its ezy
u find x
then put value of x in 1 and 2
then apply elimination or substituion method to find value of y and z
wait i wil be back
ah shit i think i know the issue. thats a 6z not 62
i didnt make the zs stand out from 2s
here
so like, the back of the book says x is 2, y is 1, and z is -2, but when I try to show my work (required) I keep getting y=5 every time
srry i cant i am stil at 2 variable
lemme see if i can kinda learn it from google
alr its fine
Decide which variable you will eliminate.
Work with a pair of equations to eliminate the chosen variable.
Multiply one or both equations so that the coefficients of that variable are opposites.
Add the equations resulting from Step 2 to eliminate one variable.
google * - *
lol
lol
i am kinda understand
im just stumped since I watched 2 tutorials, looked at my teachers slides, and did it multiple ways, yet I still get 5 and not 1 for Y
is the book right :>
can i see your work
hold on
wait I had to do it again and with the correct way of doing stuff I get 3.5=y (the numbers in top left are book's numbers)
why r u getting y=3.5 here
idk man
lel
did u got it?
I GOT 5 AGAIN
omg what r u doing wrong
which one?