#help-42 | Mathematics | Page 182

fair cargo May 22, 2026, 4:27 PM

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okay thank you

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finally

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🙏

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.close

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balmy saffron Mar 3, 2022, 2:46 AM

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Screenshot_2022-03-03-10-38-55-294_com.android.chrome.png

calm coralBOT Mar 3, 2022, 2:46 AM

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balmy saffron

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@balmy saffron Has your question been resolved?

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scenic merlin Mar 3, 2022, 3:21 AM

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calm coralBOT Mar 3, 2022, 3:21 AM

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scenic merlin

scenic merlin Mar 3, 2022, 3:22 AM

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Wow a new help room

scenic merlin Mar 3, 2022, 3:22 AM

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scenic merlin

So by definition, the compact subsets are the closed and bounded subsets

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I guess B is unbound in R^3

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Because there is not constrain for the z component

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Oh yay I get it

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But if I have to do a formal proof for “the statement D is not compact”, what can I do?

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Basically I just do this question intuitively

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.close

calm coralBOT Mar 3, 2022, 3:37 AM

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Channel closed

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scenic merlin Mar 3, 2022, 3:37 AM

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.reopen

calm coralBOT Mar 3, 2022, 3:37 AM

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✅

scenic merlin Mar 3, 2022, 3:38 AM

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scenic merlin .reopen

So I tried to consider y=kx

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The answer is not does not exist

scenic merlin Mar 3, 2022, 3:40 AM

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scenic merlin So I tried to consider y=kx

But I stuck

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Due the the square root

dawn steppe Mar 3, 2022, 3:53 AM

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scenic merlin .reopen

May be rationalize can help you to simplify the denominator ,then it will be easy( i think)

scenic merlin Mar 3, 2022, 3:53 AM

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Ok I will try

dawn steppe Mar 3, 2022, 3:54 AM

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Or you can try approching (0,0) form both the axis like put y=0 and the. X=0 then check their limit

scenic merlin Mar 3, 2022, 3:54 AM

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Nice it works

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The (2x^2-5y^2) cancels out each other

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Noice

scenic merlin Mar 3, 2022, 3:55 AM

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dawn steppe Or you can try approching (0,0) form both the axis like put y=0 and the. X=0 the...

Yay I tried this but i guess I still require the rationalisation and doesn’t prove the limit exists

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So the limit is 2

rigid kettle Mar 3, 2022, 3:56 AM

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If you approach on the x-axis and y-axis separately

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I think you will see the answer.

scenic merlin Mar 3, 2022, 3:56 AM

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Yay

scenic merlin Mar 3, 2022, 3:56 AM

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rigid kettle If you approach on the x-axis and y-axis separately

Ya I tried

rigid kettle Mar 3, 2022, 3:57 AM

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nvm bad suggestion

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what is the method then?

scenic merlin Mar 3, 2022, 3:57 AM

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But we will get sqrt(2x^2+1) or sqrt(-5y^2+1)

scenic merlin Mar 3, 2022, 3:57 AM

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rigid kettle what is the method then?

rigid kettle Mar 3, 2022, 3:57 AM

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polar coordinates?

scenic merlin Mar 3, 2022, 3:58 AM

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Nope

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Not so good as cos^2 and sin^2 doesn’t have the same coefficient

scenic merlin Mar 3, 2022, 3:58 AM

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scenic merlin

And this works

rigid kettle Mar 3, 2022, 3:58 AM

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you scale them.

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oh ok that works

scenic merlin Mar 3, 2022, 3:59 AM

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rigid kettle you scale them.

You mean fixing one of x or y?

rigid kettle Mar 3, 2022, 3:59 AM

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?

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you scale so same coeff

scenic merlin Mar 3, 2022, 3:59 AM

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Ok

rigid kettle Mar 3, 2022, 4:00 AM

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idk if it helps ofc

scenic merlin Mar 3, 2022, 4:00 AM

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I think it works too

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Sqrt2-1 as the denominator

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Then we shall simplify the expression by cancelling out each other’s

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Thank you guys!

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pandaHugg

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.close

calm coralBOT Mar 3, 2022, 4:01 AM

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dark knot Mar 3, 2022, 4:50 AM

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so uhh im trying to solve for x but im being left with a remainder

calm coralBOT Mar 3, 2022, 4:50 AM

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dark knot so uhh im trying to solve for x but im being left with a remainder

high igloo Mar 3, 2022, 4:51 AM

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bitmoji teachers catBruh

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@dark knot Please share your work

dark knot Mar 3, 2022, 4:53 AM

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high igloo <@!681757590199599123> Please share your work

alright wait

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high igloo Mar 3, 2022, 4:53 AM

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,rotate

potent lotusBOT Mar 3, 2022, 4:53 AM

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dark knot Mar 3, 2022, 4:53 AM

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i just based it off how my teacher solved it

high igloo Mar 3, 2022, 4:54 AM

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?

dark knot Mar 3, 2022, 4:54 AM

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yes

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did i do smthng wrong

high igloo Mar 3, 2022, 4:54 AM

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this is not how you solve equations

dark knot Mar 3, 2022, 4:54 AM

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i mean

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thats how it was solved

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in the example equation

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ah

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so is it now

high igloo Mar 3, 2022, 4:55 AM

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do you see the difference in the operations now?

dark knot Mar 3, 2022, 4:55 AM

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did i misinterpret it

high igloo Mar 3, 2022, 4:56 AM

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In step 1 x is being added on the right side

dark knot Mar 3, 2022, 4:56 AM

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ohh you mean the sign changed?

high igloo Mar 3, 2022, 4:56 AM

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but to get to step 2 x was subtracted from both sides

dark knot Mar 3, 2022, 4:56 AM

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oh what

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but how did 9 get on the right

high igloo Mar 3, 2022, 4:56 AM

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9 was added to both sides

dark knot Mar 3, 2022, 4:56 AM

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oh

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so thats why theres no 9 on the left since -9 + 9 =0?

high igloo Mar 3, 2022, 4:57 AM

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precisely

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$4x-9=x+6 \ 4x-9-x+9=x+6-x+9 \ 4x-x=6+9$

dark knot Mar 3, 2022, 4:57 AM

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ahhhh I see

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why wasnt it said in the module though

high igloo Mar 3, 2022, 4:58 AM

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I don't know

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You should have your algebra skills down by now if you're doing geomtry

dark knot Mar 3, 2022, 4:58 AM

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high igloo You should have your algebra skills down by now if you're doing geomtry

ahhh I see mb

potent lotusBOT Mar 3, 2022, 4:58 AM

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sills

prisma mango Mar 3, 2022, 4:59 AM

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dark knot why wasnt it said in the module though

It does say combine similar terms, which is saying get everything with x on one side, and then everything else on the other

dark knot Mar 3, 2022, 4:59 AM

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prisma mango It does say combine similar terms, which is saying get everything with x on one ...

ahhh fair enough

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guess I misinterpreted it

high igloo Mar 3, 2022, 5:01 AM

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https://www.youtube.com/watch?v=fDMxOiS5g7k

YouTube

Mike DeVor

Solving Equation with variables on both sides of the equation

Solving basic linear equations with variables on both sides of the equation.

▶ Play video

dark knot Mar 3, 2022, 5:02 AM

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high igloo https://www.youtube.com/watch?v=fDMxOiS5g7k

oooo thanks

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gimme a sec

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omg

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dang thanks

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I got the answer

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is it right

high igloo Mar 3, 2022, 5:08 AM

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2x+14 = x+18

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x = 4

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Nice!

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You learned something

dark knot Mar 3, 2022, 5:09 AM

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thanks man

high igloo Mar 3, 2022, 5:09 AM

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I'm very proud of you

dark knot Mar 3, 2022, 5:09 AM

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also helped me with solving y

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ima close this channel now thanks agai

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.close

calm coralBOT Mar 3, 2022, 5:10 AM

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calm coralBOT May 8, 2022, 4:48 PM

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surreal crypt May 8, 2022, 4:50 PM

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How could I simplify this further? I'm using chain rule to derive here, then substituting t for 5.

calm coralBOT May 8, 2022, 4:50 PM

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surreal crypt How could I simplify this further? I'm using chain rule to derive here, then sub...

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@surreal crypt Has your question been resolved?

surreal crypt May 8, 2022, 5:05 PM

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<@&286206848099549185>

prisma mango May 8, 2022, 5:07 PM

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Can you use a calculator?

surreal crypt May 8, 2022, 5:16 PM

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my main problem is that (-15 625)^(2/3) wont work

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just figured it out thanks

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.close

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bold charm May 8, 2022, 5:39 PM

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calm coralBOT May 8, 2022, 5:39 PM

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bold charm

bold charm May 8, 2022, 5:39 PM

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i got there

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how do i continue?

calm coralBOT May 8, 2022, 5:54 PM

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@bold charm Has your question been resolved?

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brisk cipher May 10, 2022, 5:17 PM

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calm coralBOT May 10, 2022, 5:17 PM

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brisk cipher

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@brisk cipher Has your question been resolved?

calm coralBOT May 10, 2022, 6:02 PM

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@brisk cipher Has your question been resolved?

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remote mural May 10, 2022, 6:39 PM

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.open

fringe leaf May 10, 2022, 6:50 PM

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calm coralBOT May 10, 2022, 6:50 PM

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fringe leaf

fringe leaf May 10, 2022, 6:51 PM

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guys

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i never know whether for the coefficient of restitution

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say a is the speed of A after collision, and b is the speed of B after collision

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is the speed of separation a - b or b - a

calm coralBOT May 10, 2022, 7:06 PM

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@fringe leaf Has your question been resolved?

timid shell May 10, 2022, 7:26 PM

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,tex (\frac{|vb - va|}{|ua - ub|}) = CR?

potent lotusBOT May 10, 2022, 7:27 PM

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heethar

calm coralBOT May 10, 2022, 7:37 PM

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@fringe leaf Has your question been resolved?

fringe leaf May 10, 2022, 7:42 PM

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timid shell ,tex $\frac{|vb - va|}{|ua - ub|}$ = CR?

is this just a fact thats always the case?

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its always b - a ???

timid shell May 10, 2022, 7:45 PM

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It isn't always, seems like there are special cases. But this was provided for the case of a one-dimensional collision involving two objects.

fringe leaf May 10, 2022, 7:45 PM

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what are the special cases?

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i only need 1 dimensional with 2 objects

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are there any special cases 1d with 2 objects?

timid shell May 10, 2022, 7:46 PM

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There's one for an object bouncing off of a stationary object where CR is V/U where V is the speed of the object after impact and U is the speed of the object before impact.

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Object dropped from rest is sqrt(h/H)
h = bounce height
H = drop height
stuff like that

fringe leaf May 10, 2022, 7:48 PM

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ah alright, ok thanks

timid shell May 10, 2022, 7:48 PM

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Was that the one you were looking for?

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I find it very strange that coefficient of restitution is denoted as e

timid shell May 10, 2022, 8:33 PM

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.close

calm coralBOT May 10, 2022, 8:53 PM

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@fringe leaf Has your question been resolved?

fringe leaf May 10, 2022, 8:54 PM

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oh yes, thanks for the help forgot to close it.

calm coralBOT May 10, 2022, 8:55 PM

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• After 15 minutes, feel free to ping <@&286206848099549185>.
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tough granite May 10, 2022, 9:01 PM

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how would you do this

calm coralBOT May 10, 2022, 9:01 PM

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tough granite how would you do this

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@tough granite Has your question been resolved?

leaden thunder May 10, 2022, 9:25 PM

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,rotate

potent lotusBOT May 10, 2022, 9:25 PM

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calm coralBOT May 10, 2022, 9:31 PM

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calm coralBOT Jun 6, 2022, 5:59 PM

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Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

small sierra Jun 6, 2022, 6:21 PM

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calm coralBOT Jun 6, 2022, 6:21 PM

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small sierra

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Please don't occupy multiple help channels.

small sierra Jun 6, 2022, 6:22 PM

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whats the series of transformation for that ?

prisma mango Jun 6, 2022, 6:22 PM

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small sierra

Don't open multiple channels

small sierra Jun 6, 2022, 6:23 PM

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prisma mango Don't open multiple channels

the guy left me

prisma mango Jun 6, 2022, 6:23 PM

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So?

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Just wait patiently

small sierra Jun 6, 2022, 6:24 PM

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do you know

prisma mango Jun 6, 2022, 6:25 PM

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Close one of the channels you have open

small sierra Jun 6, 2022, 6:25 PM

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ok

cursive canopy Jun 6, 2022, 6:26 PM

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Hello

prisma mango Jun 6, 2022, 6:26 PM

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Well, I wasn't good with series, so you should wait patiently for someone to come by

small sierra Jun 6, 2022, 6:26 PM

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oh ok

cursive canopy Jun 6, 2022, 6:26 PM

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Hello

small sierra Jun 6, 2022, 6:27 PM

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cursive canopy Hello

hi

cursive canopy Jun 6, 2022, 6:27 PM

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I NEED HELP

prisma mango Jun 6, 2022, 6:27 PM

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cursive canopy Hello

If you are trying to ask a question, please read #❓how-to-get-help

cursive canopy Jun 6, 2022, 6:28 PM

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I KNOW

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I'VE ALREADY READ IT

prisma mango Jun 6, 2022, 6:28 PM

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Why the caps?

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If you read it, then you should know that you need to open your own channel

calm coralBOT Jun 6, 2022, 6:42 PM

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@small sierra Has your question been resolved?

calm coralBOT Jun 6, 2022, 7:13 PM

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@small sierra Has your question been resolved?

calm coralBOT Jun 6, 2022, 8:13 PM

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@small sierra Has your question been resolved?

delicate nimbus Jun 6, 2022, 9:51 PM

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small sierra

rearrange the first equation so that its only x, and then work from inside out with stretches and translations

calm coralBOT Jun 6, 2022, 10:31 PM

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@small sierra Has your question been resolved?

calm coralBOT Jun 7, 2022, 12:31 AM

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