help-41

[mint nacelle]

you can ignore the (-1)^(n + 1) for now

or you can try differentiating sin x if you observe it directly

[elder harbor]

It’s sinx tho

After shifting

[mint nacelle]

yeah that's right, so you'd have an x^(2n), a (2n + 1), and a (2n + 1)!

which matches with x^(2n - 1), (2n), and (2n - 1)!

ah right so yeah you must know how to finish it off

[elder harbor]

Holy shit

U’re a genius

[mint nacelle]

nah I mean

I'm still processing this

[elder harbor]

Differentiating sinx pulls 2n + 1 down to be come 2n and its x^(2n)

[mint nacelle]

I don't think it works the way I thought, cause it doesn't match

[elder harbor]

Now we have another 😭

Wait let me get out of bed rq

[mint nacelle]

can you close this and open a new help channel?

[elder harbor]

It’s not my question

[amber wasp]

@nocturne swan Has your question been resolved?

[nocturne swan]

so how do i do it?

.close

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[real helm]

.

[real helm]

Linear algebra

How do i approach this problem

And also is is in z/7z

[indigo cloud]

how would you do it if it was in R

[real helm]

I would trurn it into a matrix

And then fing ref

Or rref

@indigo cloud

[indigo cloud]

yes

do that

[real helm]

Already don that

[indigo cloud]

just with mod 7 operations instead of R

[real helm]

What happens if i add 3_ and 2

Do i take the mod then?

And also does the _ sign stay on the same place or does it move based on the operations i use

??

@indigo cloud

[indigo cloud]

do you mean the bar?

[real helm]

Yes

[indigo cloud]

that just means you are doing mod 7 stuff

[real helm]

Can i move the bar or does it stay on the same place

Lets say i do R1=R1+R2

How will it look like

[indigo cloud]

the bar is something you put on top of the numbers to signal that you are doing mod 7

[real helm]

But only some numbers have the bar

[indigo cloud]

all of them do

[real helm]

Some don't

Lol

[indigo cloud]

all of the numbers appearing have it

the ones would also have it

[real helm]

Ohh i understand now

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[split sail]

need help with 1 st question

im keep messing up

.close

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[tardy gyro]

How do I go about solving this one?

[tardy gyro]

I know I can't sum them separately because they'd both give infinite, and inf-inf won't work.

what other rules/ways are there then that I could/should use?

[patent raptor]

Write down the first few terms, what do you notice?

[tardy gyro]

1/sqrt(2) - 1

• 1/sqrt(3) - 1/sqrt(2)
• 1/sqrt(4) - 1/sqrt(3)

Oh god I noticed lmao

[patent raptor]

So it looks like what

[tardy gyro]

the terms with the roots eliminate each other, leaving -1

[patent raptor]

not quiet

it seems that there will be always the n+1th term left too

[tardy gyro]

there's 1/sqrt(inf+1) left at the end, but that one goes to 0

[patent raptor]

yes

[tardy gyro]

Okay I'll remember it.

How did you know? Did you just know that specific series or was there some kind of pattern you saw?

[patent raptor]

look up "telescoping sum"

that's very important

[tardy gyro]

well mh, yes the pattern, I see it as well technically, but it would've taken me a bit to notice

[patent raptor]

and that sum you posted is a telescoping sum

meaning i can tell by the form that terms will cancel

[tardy gyro]

Alright I'll def look it up, thank you for your help!

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[mint patio]

how to integrate $\int(x^{3} + x^{2/5} + 5(x^{-1}) + 8)dx$

[inland pulsar]

! original

[amber wasp]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[mint patio]

you wait

[inland pulsar]

Btw shouldnt it be Luna Lovegood?

[mint patio]

no im not from HP

[inland pulsar]

Lol

[grizzled pagoda]

LunaLoves❤

[thorny terrace]

what have you tried @mint patio

[mint patio]

the ones im having trouble with are the 2 and 3rd terms

the others are x^4 / 4 and 8x

[inland pulsar]

Good

Do you know the power rule for integration?

[mint patio]

yes

so x^7/5 / (7/5)

[inland pulsar]

Yes correct

And for 1/x can you use the power rule?

[mint patio]

wait

i think my teacher wants it in a easier to understand form

[inland pulsar]

Hmm

[mint patio]

so is it $\frac {5x^{7/5}} {7}$

[grizzled pagoda]

LunaLoves❤

[tardy gyro]

that looks good, for the second term

[mint patio]

what about the third

[tardy gyro]

as for 5x^-1

do you know the integral for x^-1? it's a 'special' one

[mint patio]

no

[tardy gyro]

okay so it's ln(|x|), for the sake of simplicity people oftentimes say ln(x)

[mint patio]

so is it 5ln(x)

[tardy gyro]

plus a constant theoretically, but we'll keep that in mind for the end. Meaning we'll add the constant only in the end

[tardy gyro]

yeah

[mint patio]

ok thanks

do you want to help again

[tardy gyro]

and 8 becomes 8x. then add the constant and you're finished.

[tardy gyro]

I don't think I can sorry, I was already leaving but then I saw your question and thought it's gonna be quick.
You best open a new help channel, so you're at the top again

[mint patio]

i'll just leave

but thanks for helping!

i'll be back

.close

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[night sundial]

d?

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@night sundial Has your question been resolved?

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@night sundial Has your question been resolved?

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[golden hamlet]

is this sufficient to say that cbrt(x) is not differentiable at 0

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[long peak]

not really sure what im doing wrong

but the answer is supposed to be x = 6.02

[sterile nymph]

@long peak dumb question, is your calculator in radians?

,w 15 * sin(23 deg)/sin(53 deg)

[grizzled pagoda]

Results provided by WolframAlpha

Click here to refine your query online
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Requested by omnipotententity

[sterile nymph]

Nope, you got what you should have from that expression

Let's see if you have the right expression now

[meager gale]

they swapped the sins

nvm

they didnt

what was the actual question?

[sterile nymph]

I don't see an error

! original

[amber wasp]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[long peak]

im super confused

it happened to me again

[meager gale]

there might be an error in your diagram, can you send the actual q?

[sterile nymph]

Yup, angle error

[long peak]

the textbook

oh

so where was my mistake here

[sterile nymph]

77 is not 53

[long peak]

omh

LMFAO

MY EYES R SO BAD

ok but wait there was an error similar to this but

[meager gale]

you found a

not x

[long peak]

ok thank u i made stupid mistakes

[meager gale]

allg

[long peak]

.close

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[verbal lark]

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[verbal lark]

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[quick ridge]

$(fg)’ = fg’ + gf’$

[verbal lark]

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[grizzled pagoda]

knief

[verbal lark]

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[worthy ridge]

Remember that the derivative of a constant is 0

[verbal lark]

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[quick ridge]

bro what problem is this

[verbal lark]

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[worthy ridge]

So if you do the expansion you have (c * f(x))’=c * f’(x)+c’ * f(x)

[verbal lark]

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[quick ridge]

write f’ though

not f(x)’

[verbal lark]

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[quick ridge]

$\frac{d}{dx}(cf(x)) = c \frac{d}{dx} f(x) + f(x) \frac{d}{dx} c$

[grizzled pagoda]

knief

[quick ridge]

derivative of f(x) is f’

derivative of c is zero

[verbal lark]

One message removed from a suspended account.

[quick ridge]

thus the right term is zero

[quick ridge]

cf’

[worthy ridge]

Right term is zero so you are left with the left term

Which is c * f’(x)

[verbal lark]

One message removed from a suspended account.

[quick ridge]

yo you still desperately need sleep?

it’s been months bro

[worthy ridge]

Yessir

[quick ridge]

rest up boss

[worthy ridge]

Thx gng

[verbal lark]

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[quick ridge]

indeed

[verbal lark]

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[quick ridge]

that’s how it is for most people

[verbal lark]

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[quick ridge]

it can

[verbal lark]

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[amber wasp]

Channel closed

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[verbal lark]

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[amber wasp]

✅

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[quick ridge]

kenzo

[verbal lark]

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[quick ridge]

what did you try

[verbal lark]

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[quick ridge]

oh no

[verbal lark]

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[quick ridge]

quotient rule brother

[verbal lark]

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[quick ridge]

the answer should be pretty clear

you could also use long division first

then differentiate

[verbal lark]

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[quick ridge]

the answer is immediate

[worthy ridge]

Its the quotient rule, not long division

[quick ridge]

brother

i was offering a method to avoid quotient rule

[verbal lark]

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[worthy ridge]

Oh shi mb

[verbal lark]

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[quick ridge]

$\frac{x+1}{x-1} = 1 + \frac{2}{x-1}$

[grizzled pagoda]

knief

[quick ridge]

then differentiate

you get -2/(x-1)^2

😤😤

[quick ridge]

it’s alright you probably desperately need sleep

[verbal lark]

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[quick ridge]

hell

did you find that paper in the trash?

[verbal lark]

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[quick ridge]

or maybe you just write so damn hard

[verbal lark]

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[quick ridge]

yes it’s right

but just simplify

my methods better

😤😤😤

[verbal lark]

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[quick ridge]

simplify further

[verbal lark]

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[quick ridge]

it does

as i said

[quick ridge]

^

[verbal lark]

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[quick ridge]

you did

big ups kenzo

[verbal lark]

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[quick ridge]

poor pencil

[quick ridge]

on the finger?

[verbal lark]

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[quick ridge]

sure

i haven’t had one in a minute tbh

[verbal lark]

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[quick ridge]

i type now

[verbal lark]

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[minor night]

how would i do this?

[minor night]

calculator assumed

I did a simultaneous equation of the integral and x^3 -ax = ax but it didnt work

nevermind i got it

.close

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[tribal plank]

Hello, did i answer both of these questions correctly? For number 1 i think i did it wrongly 😭😭

[inland pulsar]

I mean that is until the body is static

Once it starts moving

It will be mew k

It talks about 5cm/s

[tribal plank]

Sorry i dont understand 😭, can u tell me what i should fix?

Like this?

[inland pulsar]

I think this is correct

But I don't know how the block will descend with 5cm/s

Maybe it is to confuse you

[tribal plank]

This is my new answer

But its from chat gpt so idk if its credible 😭😭

[inland pulsar]

9.8 is good

I'm still kinda confused about static or kinetic

[tribal plank]

So i should go with the first option?

Or the chatgpt one?

Can you check this as well? For number 4 is the final answer 2 then? Cuz 2r =2

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[scenic aurora]

hi

[scenic aurora]

i just need help understanding what’s the difference between a word problem for arithmetic and a word problem for geometric..

[celest cove]

alright

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[grave sage]

Dude, I've got no idea how to answer this question

[tulip tapir]

what field of math is this?

i'm assuming it's graph theory

[grave sage]

I don't know it's a past HSC question

[tulip tapir]

wtf

[grave sage]

and I'm gonna be honest I didn't study for it and it's kinda kicking me in the ass rn 😭😭

let me try and look it up and find it on the syllabus

the category is under is called "Critical Path Analysis"

[tulip tapir]

okay imma b honest no clue what that even is

what is HSC

[grave sage]

oh it's the exam you do once you finish school in Australia for each of your subjects

[tulip tapir]

jesus chr7st

[grave sage]

and bassicly the higher your mark is the more options you have for uni and tafe and other careers]

[tulip tapir]

now i understand why terence tao is so smart 😭

[fast badger]

Did this in my third year Algorithmic Graph Theory module…

[grave sage]

Ok I don't know if this is it but I've got this from the textbook and it shows that you've got to add it up??

[grave sage]

PLEEASE Help

[fast badger]

I’m gonna need to refresh my mind

[grave sage]

ok

[sharp moon]

The only thing i could remember from HSC is finding the shortest path between A en B but i'm not sure if that's what you have to do here

[grave sage]

if it's the shortest path between A and B then do you go straight, left, right since the end path is 15 compared to the other once which is 20?

and since the question doesn't say that the diagram isn't to scale then can you measure the difference between the two paths with a ruler and then use that to find the distance of everything else and then get the answer?

[fast badger]

No, this seems like more of an ‘understanding terminology’ type question

[grave sage]

oh

[fast badger]

Pretty sure it’s a.

Since the capacity of a cut is the upper bound for the flow from source to sink

Man I can barely remember to be honest

This was probably the most boring module I tookp

[grave sage]

dang

[grave sage]

bruhhh the answers say C

I'm gonna be completely honest, when I saw that questions I had no idea what to do

like if you give me a trapezoidal question or an algebraic question I'd do okay for it but not for that

[fast badger]

I guess that makes sense since you have no information on the left side, so one of the paths may have a capacity lower than 30

The basis of this question was ‘do you know what the capacity of a cut means’

[grave sage]

dang

well I guess if I got that for a short answer question then I'd still get some marks for it ig

well thank you for your help anyways @fast badger I really appreciate it bro

[fast badger]

Just curious, what is the toughest question you have come across on the HSC?

[grave sage]

probably a bio question

it was about something about an experiment comparing DNA and RNA

or maybe a geo skills question

[fast badger]

What about maths q

[grave sage]

maths maan idk

well I do standard, so most of the questions are pretty straight forward, there was one question I came across that was like a page of writing and it asked me to compare the amount of crickets in a field or something or other, the answer turned out to be pretty simple but it was just an extremely wordy question

but usually because math standard is a pretty simple course, most of the questions are relatively easy to figure out

[fast badger]

Are they all multiple choice?

[tulip tapir]

frankly i think this question might just be word vomit

[grave sage]

you have 20 multiple choice questions and about 15-20 short answer questions

this is the paper that im working on atm

[fast badger]

Ahh rest of it seems fine, i’m just surprised you have some graph theory qs in there. In year 12/13 I only saw basic network qs in comp sci

[grave sage]

daamn well I guess thats good then

alr well thanks very much for ur help

.close

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[candid elbow]

Hello!
I need help with geogebra, I am trying to make something similar to this:

https://www.youtube.com/watch?v=fHw1kFgJDtw&ab_channel=RemiFabre

How can I go about making this, so I can indirectly control the angle at a joint using a slider for the linear actuator between the two sides?

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@candid elbow Has your question been resolved?

[candid elbow]

<@&286206848099549185>

[cobalt roost]

!occupied

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Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[amber wasp]

@candid elbow Has your question been resolved?

[amber wasp]

@candid elbow Has your question been resolved?

[candid elbow]

Whatever

[amber wasp]

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[deft vine]

Can someone help me with this? It's a derivative of trigonometric.

[deft vine]

I forgot to study, and I need to pass it tomorrow. 🥹🙏🏼

[patent raptor]

You will🥹🙏🏼

cot(x) = cos(x)/sin(x) or you can memorize that cot(x)' = -csc(x)²

[deft vine]

oh

what will happen to (2x)?

[gilded socket]

this is calc 2 right

[patent raptor]

chain rule

[deft vine]

Calculus 1

[patent raptor]

cot²(2x) is basically 2 function compositions:

f(x) = x²
g(x) = cot(x)
h(x) = 2x
then f(g(h(x))) = cot²(2x)

[gilded socket]

a

[grizzled pagoda]

bacc the sigma😔🤞

[deft vine]

where did you get the x^2?

[patent raptor]

²

[grizzled pagoda]

bacc the sigma😔🤞

[patent raptor]

do you see it now

[deft vine]

I still don't get it, I'm so sorryyyyy.

[amber wasp]

@deft vine Has your question been resolved?

[deft vine]

I'll just have my answer checked later.

I can go back here, right? 🥹🙏🏼

[green sparrow]

Are you aware of the power rule in differentiation?

[deft vine]

yes

[green sparrow]

So the 2 comes from the square on the cot function

Oh wait

[deft vine]

Ohhhh

[green sparrow]

I'm dumb

[deft vine]

what 🥹

[green sparrow]

The f(x) = x^2 is just to do the composition

Since cot ^2 x can be written as (cot x)^2

[green sparrow]

^

[deft vine]

Oh, I get it now. So what will happen to the denominator?

[green sparrow]

What denominator

[deft vine]

oh sorry wait

this is the problem

[green sparrow]

Ok

So use the quotient rule

[amber wasp]

Channel closed

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[deft vine]

Like f'.g + f.g'/g^2?

.reopen

[amber wasp]

✅

[green sparrow]

No

It's g.f' - f.g' / g^2

[deft vine]

so g = 1+x^2?

[green sparrow]

Yes

[deft vine]

like this?

or is it wrong? 🥹

[patent raptor]

,rccw

[green sparrow]

No

[deft vine]

so wrong

[patent raptor]

quotient rule is wrong

[green sparrow]

The quotient rule is this ^

[deft vine]

Oh

[patent raptor]

that too no

[deft vine]

mb

[grizzled pagoda]

bacc the sigma😔🤞

[green sparrow]

That is the same thing

[patent raptor]

you didn't use brackets

anyway

[green sparrow]

Also you haven't differentiated the 1+x^2 term

[green sparrow]

Oh true mb

[patent raptor]

try to figure out f' first, it's a bit difficult because you have basically 2 function compositions

[grizzled pagoda]

bacc the sigma😔🤞

[patent raptor]

First thing you notice is that the outer function is (...)²

So for that you would use the power rule

[grizzled pagoda]

bacc the sigma😔🤞

[patent raptor]

Now we figure cot(2x) derivative

the outer function is cot(...)

Previously I gave a hint that the derivative of cot(x) is -csc²(x)

[grizzled pagoda]

bacc the sigma😔🤞

[patent raptor]

The derivative of 2x is simply 2

[grizzled pagoda]

bacc the sigma😔🤞

[patent raptor]

Now we can simplify the terms

[grizzled pagoda]

bacc the sigma😔🤞

[patent raptor]

That is your f'

Now figure out g'

[deft vine]

4x?

[patent raptor]

ye

also!

[patent raptor]

I notice, you don't use brackets

(1+x²) not 1+x²

you multiply the whole g with f'

[green sparrow]

It should be 2x not 4x

[patent raptor]

oh right

[deft vine]

Why?

[patent raptor]

You bring down 2, not 4

x² -> 2x^(2-1) = 2x

[deft vine]

but it's squared? 🥹

[patent raptor]

You have g

not g²

you wann find g' not (g²)'

[deft vine]

Oh sorry

[patent raptor]

forgive and forget

[deft vine]

So I'm going to substitute this into the formula? 🥹

[patent raptor]

Ya

[deft vine]

okkk

[grizzled pagoda]

bacc the sigma😔🤞

[deft vine]

so um...what do I do next?✋🏻

[patent raptor]

you... you would simplify the expression as much as possible✋🏻

[deft vine]

Okkk

-4cos(2x)/1 is not the same to 1-cosx/x, right?

yeah right

[amber wasp]

@deft vine Has your question been resolved?

[deft vine]

Waiiittt

🙏🏼👴🏼

what am I even doing?

Help ✋🏻🥹

[amber wasp]

Channel closed

Closed due to timeout

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[deft vine]

.reopen

[amber wasp]

✅

[deft vine]

🙋🏻‍♀️

help me math wizards 🤸🏻‍♀️🤸🏻‍♀️🤸🏻‍♀️

so the answer is zero?

🥹✋🏻

[amber wasp]

@deft vine Has your question been resolved?

[patent raptor]

ping wizard

[patent raptor]

how did you get 0 🥹

[deft vine]

✋🏻🥹

-2xcos^2(2x)

🙏🏼👴🏼

and the wizard vanished...😔

[patent raptor]

hm

,w simplify ((-4cot(2x)csc^2(2x)) * (1+x^2)-cot^2(2x)*2x)/(1+x^2)^2

[grizzled pagoda]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by adoniszgks

[patent raptor]

yea idt you can do much

[deft vine]

Oh wow, thank you so muchhhhhh. 🥹🙏🏼 🫶🏻

[amber wasp]

@deft vine Has your question been resolved?

[amber wasp]

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[amber wasp]

Please don't occupy multiple help channels.

[split sail]

<@&286206848099549185>

[pallid canopy]

!15m

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Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[pallid canopy]

!1c

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Please stick to your channel.

[vagrant scroll]

!status

[amber wasp]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[pallid canopy]

take it to their other channel

#help-23

[split sail]

I got an answer but I was that it was wrong.

[vagrant scroll]

oh right

[vagrant scroll]

close this channel sis

[split sail]

.close

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[clear meteor]

Is this a valid way to show that the limit DNE?

[storm moth]

yea

[clear meteor]

Thank you

Just wouldn’t be valid for getting a value, correct?

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@clear meteor Has your question been resolved?

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[amber wasp]

Channel closed

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[split sail]

Say x>0, do I assume x is a real number

[limpid sun]

depends

in general yes

[split sail]

To be specific, it does not include imaginary

[astral olive]

What's the original question

Because that on its own doesn't really mean anything

[split sail]

Just a random thoughtbut here it is

What do you think

[floral terrace]

i did not get complex sols but i was just wonderig

[split sail]

. close

.close

[amber wasp]

Channel closed

Closed by @hearty hornet

Use .reopen if this was a mistake.

[solar musk]

.open

anyone here

i need

jelp

PLS

<@&286206848099549185>

Help

<@&286206848099549185>

<@&286206848099549185>

<@&286206848099549185>

<@&286206848099549185>

<@&286206848099549185>

<@&286206848099549185>

<@&286206848099549185>

<@&286206848099549185>

<@&286206848099549185>

<@&286206848099549185>

<@&286206848099549185>

<@&286206848099549185>

<@&286206848099549185>

<@&286206848099549185> <@&286206848099549185> <@&286206848099549185>

[torn lotus]

/What

[solar musk]

i need help

[torn lotus]

well go on now

[solar musk]

how do find the

domain and range

[indigo pilot]

Broo

[solar musk]

of a function

[whole lion]

Gurl stop

[solar musk]

from agraph

[torn lotus]

do you have a table or graph to work from?

oh ok

[pastel silo]

dawg

[solar musk]

ye

[visual sigil]

Bro stop
I got 15 pings

[torn lotus]

you find the x and y coordinates for each spot

[solar musk]

see

[indigo pilot]

Bro that to mutch mentions

[torn lotus]

so (1,1) would be a point

[solar musk]

how

[torn lotus]

because (x,y) denotes where one would find it on the graph

[solar musk]

ye

[amber wasp]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

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[solar musk]

whats the domain

[solar musk]

how do i find it

[torn lotus]

ah sorry

[solar musk]

wdym

[torn lotus]

Domain is X, Range is Y

[solar musk]

ye

ik

how do i find

the

domain and range

in this graph

[torn lotus]

Did it not work what I told you the first time??

[solar musk]

no like show mea

how u got 1,1

[torn lotus]

ok

[solar musk]

where ru bro

????

ANYONE

<@&286206848099549185>

[visual sigil]

This is annoying

[solar musk]

help me

pls

[solar musk]

wha

i didnt do that

[visual sigil]

.

[solar musk]

and instead of helping ur a moron

[rotund oak]

You look at what x values the graph takes and what y values the graph takes

For domain and range respectively

[solar musk]

okh

[pallid canopy]

<@&268886789983436800>

[thorny terrace]

its over for you bud

[solar musk]

bru

that idiot didnt even help

and started

insulting me

[winged mantle]

stop being rude

[solar musk]

Fine

[hollow wolf]

don't insult other people here, no one in this channel has insulted you that I know of

[solar musk]

😦

[hollow wolf]

spamming the Helpers ping isn't fine either

[solar musk]

idk

bro

no ones helpin gme

😭

i tried

solving it

[hollow wolf]

well everyone here is volunteering their own time, whether you get timely help or not depends on how busy the server is atm, how clear your question is etc

[solar musk]

okh

[outer hull]

do you know what domain and range are?

[solar musk]

YES

IK

i know how to solve

it

but

idk how to show

it

like

in parethesis

whatever u call tha

[rotund oak]

In set notation?

[solar musk]

ye

exactly

i got a mark off

bcuz

[ebon whale]

alright dude. the domain is basically all the possible x values that could be on this graph. the range is all the possible y values that could be on this graph.

[solar musk]

of that

[ebon whale]

so basically its square brackets if its included

[solar musk]

can u show me

that

[ebon whale]

parentheses if not

[solar musk]

the symbol

and when to use it

[ebon whale]

this is square brackets []

this is parentheses ()

[solar musk]

whats the difference

[ebon whale]

so on this graph, you would only be using the square brackets, because the y values go up to and INCLUDE 4

[solar musk]

ok

[ebon whale]

lets say for example if there were two open dots instead of closed dots, you would be using parentheses

[solar musk]

ohhhh

i heard

[ebon whale]

because that means the function goes up to 4 but does NOT include 4

[solar musk]

my teachers= saying that

[rotund oak]

Square brackets include the endpoints of the interval

[ebon whale]

this is a better way to put it i just lack the english

[solar musk]

so if it is

open dot

i use parenthsis

[ebon whale]

yes, but only on the side of it where there is open dot

[solar musk]

okh

[ebon whale]

for this example all the possible y values fit within [0, 4]

[solar musk]

ye

[ebon whale]

try to figure out the x

[solar musk]

wait

look at this graph

bro

lemme send

ss

so to graph it

do i put

(0,3)

wait

[ebon whale]

close

[solar musk]

(0,3]

[ebon whale]

yup you got it

[solar musk]

Les gooooo

[ebon whale]

because it approaches and never touches 0 but it includes 3

good stuff

[solar musk]

wdym

it touches zero

[ebon whale]

so the x values would keep going like until 0.000000000000000000000000000000000000000000001

but would never touch 0

its just signifying that all the values up until 0

[solar musk]

so the domain

would never

be 0

[ebon whale]

yeah

but it would approach

0

[solar musk]

ye

it would approach

but wont

be

the domain

[ebon whale]

yes exactly

[solar musk]

okh

whats this

i dont

[ebon whale]

so this is just the same thing a different way

[solar musk]

get what i need to solve

do i graph

it

[ebon whale]

the bar under the < means that its a square bracket

[ebon whale]

idk dude what does the question say

[solar musk]

i did the first two

by myself

idk this

[ebon whale]

is this matching?

dude im stupid

why are there 3 answers

[solar musk]

no

itz not matchin

[ebon whale]

is it 3 answer choices for 7?

[solar musk]

wai

a sec

it might be matchin

[ebon whale]

figure out that first jit

[solar musk]

ye i think it is matching

[ebon whale]

well then ur done

you did 7 and 8

found the domain and range

ur good

[solar musk]

ye

i just find

the

matching

stuff

@ebon whale

whats this

like does s match with

7

idk

[ebon whale]

you said the answers urself

scroll up

[solar musk]

no for domain

it says

at s

see

i dont see 0

at 7

k i got it

[amber wasp]

@solar musk Has your question been resolved?

[solar musk]

@minor trellis

<@&286206848099549185>

anyone

<@&286206848099549185>

<@&286206848099549185>

pls

<@&286206848099549185>

<@&286206848099549185>

<@&286206848099549185>

<@&286206848099549185>

<@&286206848099549185>

<@&286206848099549185>

i waited

for a 13 min

alr

[junior mantle]

You can ping once

[solar musk]

can u help me

pls

[junior mantle]

Resend the question

[solar musk]

find the domain

and range

[junior mantle]

What are you supposed to awnser

[solar musk]

represented by graph

[junior mantle]

okay

look at what x ineravals have a actual output

like if x = 2 y = undefined

becuase ther is o point over there

but 1<=x<2 has a output

so tell me all the intrevals

[solar musk]

wdym

[junior mantle]

tell me ll the inravls that ahve a output

likke 1<=x<2

[solar musk]

2 to 4

[junior mantle]

wait, x=4 does not have an output

so what is teh corect inequality

write in inequality form

[solar musk]

i dont know what your talking about 😭

[junior mantle]

instead of righting things liek 2 to 3 write 2<x<3

[solar musk]

i qui

bruh

fr

i dont what ur trying to say

[junior mantle]

wait,... it does not acept grapfs

[solar musk]

i quit

bro i gtg

itz 2 am

[junior mantle]

where are you

[cobalt roost]

Ughhhh

[cobalt roost]

Remember that the black points mean closed interval

[amber wasp]

@solar musk Has your question been resolved?

[amber wasp]

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• Be polite and have a nice day!

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[supple galleon]

Could someone help me with limits and asymtopes

[supple galleon]

<@&286206848099549185>

[shy hazel]

Howd u get 8 for the first one

[amber wasp]

@supple galleon Has your question been resolved?

[supple galleon]

8 was wrong but at that point I tried anything

And it said that it wouldn’t have a decimal

[shy hazel]

Alright, do you have an answer your most confident in or nah

And yeah none of these should require decimals

[amber wasp]

@supple galleon Has your question been resolved?

[amber wasp]

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[mystic rock]

Onsnsnsnsns

[mortal dust]

snsnsnsnsnO

[amber wasp]

@mystic rock Has your question been resolved?

[split kraken]

if there is no question here, I will close this

.close

[amber wasp]

Channel closed

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[amber wasp]

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[molten shale]

not sure what to do with the numerator

[amber wasp]

@molten shale Has your question been resolved?

[reef kraken]

What's the last term?

@molten shale

[molten shale]

i think u can rewrite it like this

$\frac{1 - \cos^{\frac{1}{n}}(nx)}{x^2}$

[reef kraken]

N! ?

[grizzled pagoda]

pppoopoo

[reef kraken]

Is the first cos x a typo or is the first term different?

[molten shale]

first term

[molten shale]

this big blob of cos = 1

so i get 0/0 from the substitution

what do i do after this

[amber wasp]

@molten shale Has your question been resolved?

[amber wasp]

@molten shale Has your question been resolved?

[amber wasp]

@molten shale Has your question been resolved?

[amber wasp]

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[sand fractal]

can someone explain to me how I can find the angles and according to what rules.

[tulip tapir]

co-interior angles

[covert onyx]

angle 1, due to it is allied with angle 3.angle 5, due to it form a straight line with angle 3. angle 7 due to it is allied with angle 5. angle 6, due to angle 5,7,8,6 form a quadrilateral

[amber wasp]

@sand fractal Has your question been resolved?

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[rocky tendon]

they ask to respresent D (interval of integration )

[rocky tendon]

and that's what i did

please tell me if i'm right

2-

3-

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[fiery star]

33rd question pls

[fiery star]

<@&286206848099549185>

Pls help

[gentle dome]

It looks like the quadrilateral has to be a square for this to be true right?

[fiery star]

But that ain’t given

[gentle dome]

maybe it's something you have to prove

[fiery star]

Yeeeee

[gentle dome]

just suggesting something you can try

i don't have paper atm so i can't do it myself

but thats what i would do first

[fiery star]

Using angle bisector theorem and similarity ryt

[gentle dome]

thats a good start i think

[fiery star]

I tried it bruh

I am getting stuck somewhere

[gentle dome]

can i see the working?

[fiery star]

Could u pls send the soln

[fiery star]

It’s too clumsy

[gentle dome]

send it anyways?

[fiery star]

R u there????

<@&286206848099549185>

[fiery star]

<@&286206848099549185> pls help

<@&286206848099549185>

.close

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[agile cloak]

Guys, Im trying to create a bot that gets goal information (cumulative goals + timestamp) for a given handball game.

My goal is to predict the number of goals that the end of the match.

I guess the prediction will be dynamic, since maybe in a given period of X minutes we have lots of goals (so the prediction might rise), and maybe in other moments we have less goals.

So having said this, I was thinking about using poisson to predict the number of goals at the end of the match, but I might want to use other types of "predictors" also.

I wanna chart the goals, and the different predictions. We will have a line/curve describing the goals, another one describing the poisson prediction, etc etc.

So, first of, what do you think?

Like, is it possible to come up with something that around minutes 35-55 (a handball match lasts 60mins) gives somewhat accurate predictions?

What math models should I try to use apart from Poisson?

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[jovial oar]

Given are the graph of the function f with f(x) = x² and a point P(P1, P₂) with p2> p1^2

a) Describe the position of the point P in comparison to the graph of f.

b) Show that there is no tangent from the outside to the graph, through the point P.

c) Explain that for every point Q(q1/q₂) with q2 < q1^2 there are two tangents from the outside to the graph, through Q.

[jovial oar]

for a)

i said that

p1^2 isnt p2

so P is not on the graph of x^2

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@noble coral Has your question been resolved?

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<@&286206848099549185>

[pallid canopy]

are you not given the concentration?

[noble coral]

No, we will use constants in the final answer.

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[void steeple]

given an input x(t) and the unit step function u(t), is their convolution
$$y(t) = x(t) * u(t) = \int^t_{-\infty} x(\tau) d\tau$$ ?

[grizzled pagoda]

jack

[void steeple]

might be going insane but i recall somewhere saying that its actually $\int^t_{0} x(\tau) d\tau$ but that makes no sense to me

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jack