#help-39
1 messages · Page 167 of 1
Sorry, which information are we missing?
I just mean it’s not a real value but I guess it’s just to illustrate the point
What is not a real value?
Just because they're unknown variables, doesn't mean they're not real values.
Think of it as of a parameter, idk
As if someone can come and suddenly write 42 instead of x0
Or 7 or any other number
just to show the form of the equation gotcha
but some of these questions are asking me to sketch it based on just looking at the graph with no value
so i guess in an equation it makes sense
i'm not sure how to incorporate this with graphing tho
or at the very least i'm not sure i understand what they're asking
I assume they're asking you to draw a bunch of tangent lines on some given graph
This is the way it’s pictured in the book
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Whats ⁸√w⁴ transformed into Algebraic expression with rational exponents
$\sqrt[a]{x}^b = x^{\frac{b}{a}}$
Herels
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Let p be prime, show that 7^p + 4p^2 is never a perfect square
all i can think of is 7^p = 1 (mod 4) but i dont think that helps
7 ≡ -1 (mod4)
7^p ≡ (-1)^p (mod4)
since p is odd, (-1)^p = -1?
ye
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this came from 7^p + 4p^2 = k^2 (mod 4) btw
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can anybody help me with this?
do you have to use all 4 of the numbers?
Yeah
ah try 8 * 9/6 - 5
I can only use what’s in the number base
I know
Oh mb
basically you just have to keep trying
different combinations
make sure you don't end up with a fraction
yeah Ive been stuck for abt an hour
brother there’s no / or *
3.0 5 ! 6 / 8 - 9 -
4 5 !! 6 + 8 - 9 -
5.0 5 6 8 9 * ! / +
7.0 5 !! 6 8 * + 9 /
8.0 5 6 !! 8 / - 9 +
close but didint work
,calc 8 * 9/6 - 5
Result:
7
keep trying lmao
apparently my script gives up? hold on
I've played these games before and all should be possible
Yeh they are
broken calculator game lmao
8,5,4,3
oh I see how to make 3 also but when you're ready
ready
yeah?
from 5, 6, 8, 9 but we added 6 + 9
5,8 we can use
yeah we have 5, 8, 15
yeah
can you try dividing two of the numbers
which two?
if you use 5 and 15
how can you divide them to get a whole number?
do you know your 5 times tables
or really times tables at all
no but ik my 5
okay what are the first three numbers in the 5 times table
5,10,15
ok i fixed my script jeez that was really bad
nice
great so that means 5 * 3 = 15
so divide both sides by 5
$\frac{\cancel{5} \cdot 3}{\cancel{5}} = \frac{15}{5}$
south's secret twin brother
$3 = 15 \div 5$
south's secret twin brother
huhhhh
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In this MightyOwl video we will explore the relationship between #division and #multiplication. We will see how multiplication and division are so closely related.
Aligned with Common Core State Standard—Math...
if you want to get better at maths, first step is to understand numbers
understanding the relationships between numbers and operations
addition and subtraction undo each other
multiplication and division also undo each other
Bro I don’t care about math I want to just finish this all ten so tommorow at school I can say I instantly finished it
say if 5 + 2 = 7, then 7 - 2 = 5
you have to be honest with yourself, that you're missing something huge
yes I am
that if you don't understand this maths will keep getting harder and harder
like please just spend a bit of time on this
or in school in general
finding all 10 numbers is hard yeah, it's supposed to be hard
hm
but it's so much harder if you don't have the right foundations to start with
yeah ur right
thank you
I mean I honestly didn’t understand half of the things u said so I had to search them up but still yeah
cause at this level of maths you're going to struggle to manage your own money
Really
struggle with knowing if 3 bottles of soda for 5 bucks is a better deal than 10 bottles of soda at 30 bucks
poor numeracy, that's the word for number skills
a lot of maths is harder than numbers and yeah you probably aren't interested in those parts
Ur actually right cuz im having a hard time knowing which ones better rn
really holds people back in life, keeps them in poverty and shit
I’m a lazy guy that’s not interested in school hoping to just make a living off games
there's a trick we can use
3 bottles of soda = 5 bucks
multiply everything by 6
18 bottles of soda = 30 bucks
so wow, we can get 18 bottles of soda for the same 30 bucks
Probably would of never thought of that tbh
oh yeah then you definitely need some level of maths to code, to build your own games and animations
u help me more than my teacher does bro ima be serious
stuff like trigonometry for instance, maths to do with triangles
No I ment like Fortnite
like functions also help, algebra 1 and 2 basically
ah shit
I thought you meant a real programming language like JS
Im actually really good ngl
I’m too lazy for that
no wonder you don't need maths to work as a game dev on Roblox
I wanna be a content creator too. But again too lazy
Are you going to be a teacher?
nah I'm going to be a researcher in the social sciences
Wow bro
I've done 1 1/2 years of maths at undergraduate level though
Wow
but right now I've switched to sociology, the study of society basically
I have no idea what that is but nice job
why is our society built the way it is
and I'm aiming to finish my undergrad so that I can get a step closer
Damn
you have many more options after you graduate HS for example
Im not tryna joke rn but sometimes if ppl explain stuff to me in Fortnite terms i understand better
but if you want to do something academic or a good white-collar job you need your undergraduate, I don't mind studying tbh
if you want to do a trade then forget uni haha
it's good money but I'm not good with my hands
can u be my teacher for a while
stuff like HVAC, aircon renovations, landscaping, welding etc
nah I don't deserve it
there are other people who will be just as patient with you also
I'm not the only one like this
but yeah people like me aren't super common I agree
also lucky to be living somewhere where an undergraduate degree is 3 years instead of 4
1 less year spent mucking around I bet
the way education works is that unfortunately you have to climb a ladder to the top
could u still help me with the all ten
you have to graduate HS before you start uni most of the time, unless you have dual enrollment courses where you can go to college and HS at the same time
okay
Nice bro I don’t think I’ll be doing that
Thanks
$5 = 8 - (9 + 6) \div 5$
south's secret twin brother
$3 = 6 - 9 \div (8 - 5)$
south's secret twin brother
It’s crazy how I’ve tried all ai bots to try solve all ten and they all failed
interesting let me try GPT
I tried gpt the most
I'm missing the solution for 4 but I swear I had it at one point
Always fails
7
||```
0 = ((8 - 9) - 5) + 6
1 = ((8 - 9) * 5) + 6
2 = ((8 + 9) - 5) / 6
3 = (8 * 6) - (9 * 5)
4 = (8 / (5 - 9)) + 6
5 = 8 - ((9 + 6) / 5)
6 = ((8 + 9) - 5) - 6
7 = ((8 * 9) / 6) - 5
8 = (8 / (9 - 5)) + 6
9 = (8 - 5) * (9 - 6)
10 = ((8 - 9) + 5) + 6
solutions
It’s blank
click on it, it's a spoiler tag
O
oh wait $4 = 6 - 8 \div (9 - 5)$
south's secret twin brother
your a legend omg
yeah Hayley knows how to code
How did u do this bro howww
Ur a legendddd
python
I could probably do it but I'm rusty
I'd need at least 30 minutes, no, scrap that, 1 hour
cause implementing parentheses is hard
I have to go now but thank you both, is it fine if I add you guys?
the trick is to do the parentheses last
import operator
import math
import itertools
import time
import sys
import argparse
from collections import defaultdict
OPERS = {
'+': operator.add,
'-': operator.sub,
'*': operator.mul,
'/': lambda a,b: a/b,
#'^': lambda a,b: a**b if 0 < b < 100 and 0 <= a else 0/0,
}
NUMBERS = set([5, 6, 8, 9])
def tryit(stack=(), nums=None, journal=''):
if nums is None: nums = set(NUMBERS)
#print(f'{journal=!r}, {stack=!r}')
if len(stack) == 1 and not nums:
yield stack[0], journal
return
if len(stack) >= 2:
for oper in OPERS:
try:
op = OPERS[oper]
res = op(*stack[-2:])
if abs(res) > 10**1000:
continue
yield from tryit(
stack=stack[:-2] + (res,),
nums=nums,
journal=journal + ' ' + oper
)
except OverflowError:
pass
except ZeroDivisionError:
pass
for num in nums:
yield from tryit(
stack=stack + (num,),
nums=(nums - set([num])),
journal = journal + ' ' + str(num)
)
def post2in(s: str) -> str:
symStack = []
for tok in s.split():
if not tok: continue
if tok in OPERS:
symStack[-2:] = [f'({symStack[-2]} {tok} {symStack[-1]})']
else:
symStack.append(tok)
out = symStack[0]
if out.startswith('('):
out = out[1:-1]
return out
def main(args):
found = defaultdict(list)
for dest, path in tryit(nums=set(args.seeds) or None):
found[dest].append(path)
seen = set()
for dest in sorted(found):
if abs(dest) > 10**100:
continue
destI = round(dest, 2)
if destI % 1 == 0:
seen.add(int(destI))
postfix = found[dest][0]
if args.postfix:
expr = postfix
else:
expr = post2in(found[dest][0])
print(f'{int(destI):-3d} = {expr}')
for num in range(1, 300):
if num not in seen:
print(f'did not see {num}')
if __name__ == '__main__':
parser = argparse.ArgumentParser()
parser.add_argument('seeds', nargs='*', type=int)
parser.add_argument('--postfix', action='store_true')
args = parser.parse_args()
main(args)
also the last 10% takes the same time as the first 90%, common inside joke in programming
i generate it as postfix first
yeah I can't code that in 30 minutes for sure
probably would take me hours
neither can i, this was code that i had written but had to adapt
it's super challenging the more I think of it
because the original problem was 4 numbers that you had to use in order
fuck yeah it's a good coding challenge
Is there a way I could get a hold of this and change the numbers every time I need to use it?
yeah that's why i posted it lol
I was thinking you create like 4 arrays
1 array has all 4 of the the original numbers
the second array has only 3, since you combine 2 numbers to make another one
when you run it it will dump out all the solutions
hayls@yavin ~/projects/12345 $ python 12345.py
-427 = 5 - ((8 * 9) * 6)
-402 = (5 - (8 * 9)) * 6
-392 = 8 * (5 - (9 * 6))
-387 = 9 * (5 - (8 * 6))
-354 = 6 - ((8 * 9) * 5)
-330 = 5 * (6 - (8 * 9))
-312 = 8 * (6 - (9 * 5))
-306 = 9 * (6 - (8 * 5))
-262 = 8 - ((9 * 5) * 6)
-231 = 9 - ((8 * 5) * 6)
-230 = (8 - (9 * 6)) * 5
you can pass seeds on the command line
hayls@yavin ~/projects/12345 $ python 12345.py 3 4 7
-25 = 3 - (4 * 7)
-17 = 4 - (3 * 7)
-16 = (3 - 7) * 4
-9 = 3 * (4 - 7)
-8 = (3 - 4) - 7
-7 = (3 - 4) * 7
-6 = (4 - 3) - 7
-5 = 7 - (3 * 4)
-1 = 3 / (4 - 7)
0 = (3 + 4) - 7
1 = (3 + 4) / 7
5 = (3 * 4) - 7
the third array has only 2
the fourth array is the answer
put all the arrays in a loop
then iterate over like all possible combinations
so that you don't have to think about implementing brackets
Loaded maybe I'll send you the code if I even manage to do it
wait then there will be like (4 * 3 * 4) * (3 * 2 * 4) * (2 * 4) possible answers
,w (4 * 3 * 4) * (3 * 2 * 4) * (2 * 4)
a computer can do it though
I’m back sorry I had to go for a sec
for a computer it can spit out numbers from 1 to 10,000 in under 1 sec
jeez yeah this is actually fairly challenging to code
I'd be quicker with my brain
So do I just run the command in a channel or sum?
there would be a million loops
Is python what I need to run it on
yes
yeah search up python online
I went on the website and it won’t really let me do anything
Ok I found the right website
This is what it said
you've included the discord comment as code. only use what's in the code block
could u paste that for me
on desktop for me you can click the top right of the text block to copy to clipboard
it's too long for me too paste lol
Bruh
Alg
just don't include the part of the message
the trick is to do the parentheses last
that's not python code
I just won’t use it bruh
i ran it successfully here https://www.online-python.com/g14HJtCAN0
ah thanks
all you hehe
I appreciate you so much, you’re one of the best people I have ever met. Thank you
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Which integration is the diagram of in the top right?
those should be equivalent
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Can someone explain what the first 2 points are trying to say
since i got no clue
what does i and j mean?
The i'th row of the vector/matrix (and j'th column for a matrix)
e.g. if you take $n = 3$ and $\mathbf{a} = \pmqty{4 \ 20 \ 69}$ then $a_1 = 4, a_2 = 20, a_3 = 69$
@merry carbon
if you also took $\mathbf{b} = \pmqty{4 \ 5 \ 9}$ then the dot product $\mathbf{a} \cdot \mathbf{b} = 4(4) + 20(5) + 69(9)$, but then $\mathbf{a}\mathbf{b}^T = \pmqty{4(4) & 4(5) & 4(9) \ 20(4) & 20(5) & 20(9) \ 69(4) & 69(5) & 69(9)}$
@merry carbon
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can someone help with this, i dont even know where to start
its suppost tpo be an exercise of finite projective planes
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I just assumed because the question says to use bracket notation. i could see the answer being a scalar or a vector depending on how you solve it. i tried solving it by plugging (3,1,2) into F and G and adding them and then multiplying by f(3,1,2) which gives a vector but i could also see it as plugging the x y and z values of F + G into f and then plugging in 3,1,2 which would give a scalar
@plush bramble heres what i get when doing it the vector way
i don't know how you're getting any of that. repost the question here
i still have no idea where you're getting this from
should show your entire steps so people can follow your work
sorry ill rewrite that. i tried to make this scalar method more clear
vector method
@robust cedar Has your question been resolved?
@robust cedar Has your question been resolved?
this is not what the question is asking for
$f(F+G) \neq f \cdot (F+G)$
riemann
This is function composition
this is multiplication
so is the top way correct
yea
alright that makes sense to me the question just made me think it was supposed to be a vector 😭
thanks
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Im not sure if im doing this correctly
a) 3x = 9 mod 10
=> x = 3 mod 10
and the solution is [3]?
b) 5x + 2 = 27 mod 15
=> 5x = 25 mod 15
=> x = 5 mod 3
[5] = {...., -4, -1, 2, 5, 8, 11, 14....}
But we need it in terms of mod 15 idk what to do...
c) -11x - 3 = 30 mod 7
=> -11x = 33 mod 7
=> -x = 3 mod 7
and the solution is [3]?
for (b) you'll have multiple solutions, just list all of them that are between 0 and 14
so x = z mod 15 where z \in {2, 5, 8, 11, 14}?
your answer for (c) is wrong, you didn't deal with the - sign
mod 15 but yea
how would I deal with that. I havent really done anything like this in class before
and why do we ignore the negatives? (-4, -1 etc)
add 7 to that and you get x=4
they're also valid, but for example -1 = 14 (mod 15)
yw, cheers
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I have question about proofs. If we have "If p and r and s then q, and I want to use contraposition. Would it be fine to do if (not q) and r and s, then not p?
yo can any1 help me review for amc 10b
I'm using this channel already lol
It's definitely on the right track, your statement if not q, and r and s, then not p (Meaning -q, r, and s are all true and thus p is not) is true but not quite the contrapositive
Right
but I was wondering because
um
So if I only assume not q, then I would have to show
3 different cases, which at least one of them fails
but then if I have some way to assume r and s or something
then I would have more tools followed from proposition, theorem, etc
maybe contradiction is the best way
Yeah if not q is true, then at least one of p, s, and r must be false
I think the full contraposition would be if not q, then not (p and r and s)
Which can be expanded to if not q, then not p or not r or not s
yea that's what I was saying
because
if p and s and r, then q
I am not sure if we can reformulate
s and r holds first, and if p then q
for example,
for all x > 0, x^2 > 0
contraposition of this is if x^2 <=0, then x <= 0
however notice that we already have that x is real number
so if I think differently, then
if x^2 <=0, then x <= 0 or x is not a real number
If x^2 <= 0 then the only real x can be is 0 if I'm not mistaken
right
For any x^2<0, x is complex
right
but if you see the original statement
"if x^2 <=0, then x <= 0"
This was sufficient
or something like this
I am not communicating this well i guess
I'm not either lol I dipped my toes into a subject I'm not good at lol
lmao
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I think this notation is right too?
Your reimann sum is 124/3 and the integral is equal to 21 so something's off
It shouldn't ., should it
so we move the origin one unit to the right, and then sum between 1 and 3n, because we're now effectuvely finding teh area between 1 and 3
*0 and 3
why 3n
Where did the six come from in the first place?
Also I never shifted the limits in my class so I'm not sure if it's a method I'm unaware of but I imagine the nature of functions like this suggest that the integral from 0 to 3 will be a different area as that from 1 to 4
huh
For this particular integral, evaluated from 1 to 4 is equal to 21, but from 0 to 3 is 3, so I don't see why the Riemann sum would follow a different pattern
I'm trying to figure out why the -5 remains -5
In what way?
nvm, makes sense
Riemann sum includes f(stuff) so naturally it would be there
I was overthinking it
oops
This is a digression, but where can I find problems on upper and lower sums
stewart doesn't seem to have any
I do have spivak, but not\ sure if that's the right choice 3 weeks before my exam
I always used Wolfram's problem generator but I don't think they have series
yeah, doesn't seem to have any
I think my library does have lang
I think that has upper and lower sum problems
thanks!
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I’m on a and the answer is B
Are you referring to the < and > signs?
That's inequality symbols
yeah but my teacher says it tells which way they are shading but I forgot
Like he doesn’t have notes
Solid line means less/greater than or equal to, dotted line means exclusively less/greater than. That’s why the answer is b over a- which is what you circled (?)
oh so when it’s solid it’s >
Other way around
Yup
okay valid but how do you tell which way it’s shading using the symbol
You can plug in a value from the shaded region to check
Like take a point from where they overlap?
Yes
okay so if I wanted to test 1,4 I would plug 1 for x and 4 for y?
and then if it symbol is correct then it’s right?
Yes
We plug it in for both right
Linear and parabola?
okay bet I just got understand jy
Yes, if you've given the graph and want to find out what choice it is, you can plug in a value from the overlap region to check
Imma try these next problems
But if you know a way I can tell which equation goes to the graph without having to plug from the overlap please lemme know
With process of elimination and knowing that solid line is great/less than or equal to and dotted is less/greater than, then you can eliminate to 2 choices then just plug in a value for just those two rather than 4 choices
thanks bro imma try that I did process of elimination for the next problem and it rlly helped
Do you want to help me with number 5 if you have time @feral leaf
I don't see a 5?
oh sorry imma send it it’s a different problem
Wait hold on
don’t we just draw lines through where the equal sign is
Not sure what you mean by draw a line where the equal sign is
Like for example the first one equal 12
so wouldn’t we draw a line thru 12 on the graph like
That
Or am I wrong cause ngl I forgot 😂
That's right
I’m on fire
Then you just find the x values that intersect it
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i need help with 3b, struggling to get started, would appreciate anything
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The way it reduced 21 and 35 modulo 19 and then subbed in 2 and 16 for 21 and 35 ... is something like this legal? The reason im asking this is because I havent really seen anything like this in class before
oooh tysm
It is legal whenever the mod is prime, you can just do algebra
You need to be careful with multiplication when the mod is composite though.
Im kinda confused by this
can you show me a case pls
Sure, take mod 12 as an example.
4 * 3 = 0 mod 12
Which means 3 and 4 are divisors of 0 in mod 12.
This winds up breaking stuff a little bit
3x + 4 = 4 mod 12 gives x = 0 mod 12. But you are missing cases, because x could be 4 and 8 as well
sorry but how did u get x = 0 mod 12 here
3x = 0 mod 12
whats the next step
oh wait
im slow
divide by 3
Yes exactly.
I thought u divide mod 12 by gcd(3, 12)
Yes.
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given a function, i can find the inflection points like this:, right?
set f''(x)=0, plug the found x value(s) into f(x),
(x,(fx)) is an inflectionpoint
am i correct
sign needs to change
well it isn’t enough for f’’ to be zero
we need to ensure f’’ changes sign
f’’ = 0 is a necessary but not sufficient condition
well
i guess f’’ could also technically not exist
so technically not necessary
wait youre right
think of points of inflection as the relative extrema of f’
i missed the part where inflection=change in concavity
yep
so was my initial method of findingt POI correct or no
i assumed f''=0 meant sign change
yes that’s one condition
key word is can
the other condition is that f’’ must change sign
example: f''=o at x=1 and x=2
from this i have 3 intervals: (-inf,1)(1,2)(2,inf)
then
i choose numbers from each interval, plug into f'', and see if the output changes sign on each interval?
like uhhhhhh if f''(0) and f"(1.5) are both positive, there would be NO POI on any of the first 2 intervals?
i hope that was clear sorry
well you’re checking to see if the sign changes from before those critical points to after
yea
well POI at the point x = 1
no POI there you mean
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im getting a diff answer from the solution is there a mistake??
i havent read the thing yet but your most critical mistake is not having a differential
i did differentiate it
this is what an integral look like
you are missing the dx, called the differential
oho
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Hi I'm an architecture student. I want to make a wall system consisting of movable panels, I designed the columns so the panels could rotate around them. Column should look like the image below ( L shaped part is piece of + shaped column). In order for the panel to rotate smoothly while moving on the blue rail line; What should be the minimum rail-column distance (x), the length of the rail (y), the length of the column part (z)?
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I have a question.
you don't say?
hello
Suppose I have rope. It's length is L.
Suppose it hangs from the edge of a table. The rope is by mass uniformly distributed over the length.
The gravitational acceleration is g.
What is the G.P.E of the whole rope?
gravitational potential energy
Or, in other words, what will be the work done to pull it wholly to the table.
Yes.
Of course not
complete derivation and answer
Hi Yoobie, are you doing this problem now?
yes
I know that GPE of a point of mass m at a height h is mgh.
actually we are from the same country
But the height of different point varies.
that is a common problem from JEE i have already given that exam before
and solved the problem too
Alright Yoobie, let me get out of your way then
i dont mean to intrude either.. sorry if i dusturbed you
Of course you do
go ahead though
hey anjali how much part of rope is hanging from the edge of the table
The GPE of a small part of the rope ∝ the height of that part from the lower end of the rope.
L
I mean
so the entire rope is
Is friction there?
No
Use CM
Disconsider every other factor
Center of mass
i mean she should ideally use centre of mass.. if she has learnt that chapter
if not then she has to integrate it completely and solve
I don't think she knows integration
a basic level of integration for physics is taught in class 11
for solving these types of problems
Center of mass also in 11th
that is the standard solution in every textbook
This integration is linear
That GPE ∝ height
So there must be a simple way to do it
that chapter is after Work Power Energy, if she wants to solve the question using solely work power energy concepts she will have to use integration
yess that is the case here
you should actually learn it step by step
because learning this integration will be very helpful for further physics in JEE
you dont learn this type of integration in maths in class 12
so L part of the rope is hanging down from the edge right?
yes
Yeah but the WPE in this is class 9 and she has done it
in class 9 the level is very low compared to JEE level
its just basic
Yup
ok
you can try going x distance down from the edge
and select a small portion of rope dx
can you write dU? (gravitational potential for the small portion of rope)
I don't think she does
lets see if she can
if not i should try to teach that
this is a very common type of problem for JEE
uhm, what is dx
Lol
Sort of
Hmm
I just know the def
oh
listen so
dx is the small lenght of rope you selected after going x distance down
Center of mass is basically a point where we can concentrate all the mass of a body for the purposes of NLM, GPE only
oh
You will learn why in chapter centre of mass and rotational dynamics
can't we use graphs
I don't think so
well if you want to there is a short trick
Graph of what?
yes
since the integration is linear
it will be a triangle
you can just take the mean
mhm
so in this case MgL/2
gpe = mgh
but like its not the ideal,, its fast but you should know the fundamentals
that is what i was talking about..
!nosols
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
oops
oops
my bad
I hope to do so too
dont worry its for the better just try your best thats all that matters
yes
yes
So m mass will be at a depth of l/2
Ohh thanksss
what about the average power on a block if the acceleration of the block is constant in a horizontal plane
what is the question?
A force 'F' accelerates a block of mass 'm' along a straight line to velocity 'v' from rest adn displace it through a distance of 's'. What is the average power developed?
What's the formula for avg power?
I think I get it
we would again take the mean of the initla power and the final power
Ok thanks
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✅
Because a is constant the answer would be correct
But the correct method would be
Average power = total work done / total time
yup
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Did I setup the integral correctly?
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!show
Show your work, and if possible, explain where you are stuck.
Question iii
did you see this message #help-39 message
This statistics video tutorial explains how to calculate the variance of a sample.
Statistics - Free Formula Sheet: https://bit.ly/47zjTVT
Introduction to Statistics:
https://www.youtube.com/watch?v=XZo4xyJXCak
Arithmetic, Geometric, & Harmonic Mean:
https://www.youtu...
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SHRIMPLE QUESTION
sorry for caps
is this just
0 and 1 integral + | 1 and 2 integral|
1/2?
or is it
0 untill 2 inegral
regular integral is signed area
so it would cancel out
so yes you'd want to break it up and abs value the integrand from P to Q
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Anyone know what I do to get an answer for this? V and p are throwing me of a bit
,rotate
You should get a value for p and a value for k
Use the fact that if a+bi=c+di then a=c and b=d
@chilly imp Has your question been resolved?
Oh so
Its
Yeah but where does a=c and b=d come from?
Oh wait
I understand now so its a+bi but instead you have c+di as well?
The only issue is how do you remove the ki and pi? I dont see a way to do it through addition or subbing since they cant get rid of each other w different symbols
I got
-7-3pi=+1-6ki
If anyones interested 😭
You can factor out the i
Also wait how did you get that
You should combine all the real terms and all the imaginary terms
@chilly imp Has your question been resolved?
Yeah that's what I tried but I got stuck again on with ki and pi
I wasnt sure how to get rid of them to combine the real and imaginary numbers
Oh is that cause i=1? So it just goes away?
,, 2-3pi - 9 -ki = 4k+1-i
Bair
,, -7+(-3p-k)i = (4k+1)-i
Bair
,,-7 = 4k+1, (-3p-k)=-1
Bair
Ah ok I get you now
@ocean hornet thanks a million
I got exams for maths in 2 days, that helped a lot
Now I wont be cooked completely..
Np, type .close
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what does a "unique solution" mean in matrices?
"There are no others, and if you find another solution, it's actually the same" 
could u give an example of what u mean?
If $A$ is an invertible square matrix then the \emph{only} solution to $A\mathbf{x} = \mathbf{b}$ is $\mathbf{x} = A^{-1}\mathbf{b}$, in which case that's a unique solution as there are no others
@merry carbon
Whereas e.g. if I take the matrix $A = \pmqty{1 & 0 \ 0 & 0}$ then both $\mathbf{x} = \pmqty{0 \ 1}$ and $\mathbf{x} = \pmqty{0 \ 69420}$ are solutions to $A\mathbf{x} = \pmqty{0 \ 0}$, so there is not a unique solution in that case
@merry carbon
third time lucky 
ohhh btw the x values can be found by inversing A or?
if A is invertible, you can, but if it isn't, no 
if A isnt invertible then how are the x values found?
e.g. Gaussian elimination
hmm i dont think ive learnt how to do that but ill keep it in mind, tysmm tho!
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I’m trying to answer part b however I’m getting a wrong answer. I don’t know where im making the mistake
hi
so u completed the square alr
As to where I’m making the mistake
hmm
Yeah I completed the square to find the equation of the circle in order to substitute the equation of l inside of it and find point p and w
Q
And to find the tangents of point p and q I just done the normal formula but I’m getting the wrong answer according to my text book I tried this multiple times but I don’t know what I’m doing wrong
idk what formula is
i just do math without memorising too much frfr
aiyo
Ohh okay bro it’s y2-y1 divided by x2-x1 to find the gradient
i know
Yeahh
fr just sub it in
then 2 sols
one negative one pos
we have the grid axis as the reference
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who here has chegg premium
what
yo
tf chegg premium
i dont got that bro
💀
chegg premium got the answer
you pay for homework answers
ah
i can but i dont want to buy it
since theres this server here
i am asking for someone cuz this server isnt helping out
you could just send the question
it’s all good man everyone’s in different positions
ppl would answer if you did first time
i bought too many coc passes
other than 'chegg premium'
i cant afford chegg
gold pass fire though
ahh damn don’t tell me you bought the hammer jam packs
i’m th16 bruh
you would not
very related to math
bro you edrag spam
once m yqueen gets upgraded though
nah i am like albert estien on that
fr though how u do this
i been procastrinating my chem exam studying with this
for last 3 hours
W choices
your so ded
you’re in calc yea?
i dont even really need this either but icant
yea
i dont wanna skip it without knowing how to do it
chatgpt but i can give u the formulas
ik how to do it but the problem is one isnt bigger than the other
and one of them is negative
and i havent seen any of these kinds of problems before
what we doing @versed mica whats the game plan
is this what your teacher gave you?
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I’m trying to prove (3)
No matter what I do they all equal to 0, but I can’t prove the limit does exist either
I only learned to prove it dne
😭
I’m looking at 3 by the way
question 3
how did you get that for the limit with x = 0?
wait nvm i was looking at q4
have you tried any other paths than x = 0, y = 0?
Ya I tried other paths. But sin(whatever) always equal to 0
Because both x and y is 0
i would recommend trying some path that would allow you to simplify the denominator
Even if I simplify detonator if sin keeps going to 0 the final limit still results in 0
Please expand on that 😭
you can pick any path going through (0,0)
for example x = f(y) or y = g(x) for any function f, g which pass through the origin
Yes I tried many😭
such as?
remember that 0/0 is an indeterminate form
so you can get a limit in the form 0/0 which is not 0
try this one
well 0/0 is indeterminate meaning we haven't solved it yet, not that we can't solve it
if we can show this path limit exists and is not 0, then that would show the overall 2D limit DNE
Yes
That’s what I’m trying to do, but can’t
Please, no more puzzles, what can I plug in so it’s not 0?😭😭😭
so we are considering [ \lim_{x \to 0} \frac{x^2\sin^2(x)}{2x^4}]
cloud
Ya
this is a one variable limit so you can use all of the techniques you have used for one variable limits before
Even if I cancel it out, sin(0) is still 0
I would still get 0
Which doesn’t prove it dne since other substitutions also gets me 0
ok so what simplification can we perform?
does the limit [ \lim_{x \to 0}\frac{\sin^2 x}{2x^2} ] remind you of any famous limits?
cloud
Not in my knowledge 🥸
what if we rewrote it as [ \frac 12 \lim_{x \to 0}\ab(\frac{\sin x}x)^2 ]
cloud