#help-38
1 messages · Page 230 of 1
it doesnt seem like an easy equation to solve 
you sure of the expression ?
@woven sigil its 9x^2 or 2x^2 ?
@woven sigil Has your question been resolved?
|| 5/(3x+2)² + 4/(3x+2)(3x-2) - 1/(3x-2) = 0
5(3x-2) + 4(3x+2) - (3x+2)² = 0
15x - 10 + 12x + 8 - (9x²+12x+4) = 0
27x - 2 - 9x² - 12x - 4 = 0
9x² - 15x + 6 = 0
3x² - 5x + 2 = 0
(3x - 2)(x - 1) = 0
x = ⅔, x = 1 ||
bro i couldnt read what he wrote
wdym
thats how i read it lol
while it was 12x instead of 2x , and 9x^2 instead of 2x^2
your method is good tho
thanks
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Hi, how do I answer this Q? What is easiest way to answer this Q, and Q's similar to this one?
In math discussion, they said I can use fractions I think?
But im not sure how.
So far how many marks would I get for this Q?
/3
Yeah that’d be the easiest way imo
How would you rewrite 1.2 as a fraction?
1.2 / 10?
Ex: if you have 20.22, you just count how many times you “move” the comma and use that as your zeros: 20.22 = 2022/100
yeah
What do I do then?
yup
you tell me, how many times did you move the comma
exactly
you gotta divide them, right?
do you remember how to divide fractions?
remember that it’s 74.88 / 1.2 NOT 1.2 / 74.88
also, are you sure that 7488 * 10 = 74.888 ?
No
Good ?
7488/100 x 10/12
Good ?
Which is
74880
/100
Ooops
Over
1200
you can keep going, notice that 7488 is an even number, and 120 also is
7488/60
7488/10
7488/2
So it is 7488/2
?
Am I right ?
And how do I work that out
7488/2
?
Yes
“Removing” the zeros only works when you’ve got zeros in the denominator and the numerator
but, do you see a zero in 7488?
No
but you know that both of them can be divided by two as they’re both even, right?
in other words
Yes
you haven’t done anything to 7488
find its half
no
when you reached 936/15, you were doing good
but your denominator has to be an integer
(and your numerator too)
I'm saying how do u know mathematics?
I’m a mathematics student at college xd
Do u know calculus?
yeah?
complex numbers?
936/15 = 312/5 as both of them can be divided by 3
5 is a prime number, and 312 cannot be divided by 5. Therefore you can’t keep going. You do 312/5 by hand which is way easier and you get 62.4
That’s your answer
no
you can’t do something on your numerator ignoring your denominator
that’s a mistake
what is algebraic topology
?
No
What is it?
I know topology is summed up by one theorem.
Do u know what theorem that could be?
Do u know what theorem it could be?
For this
It is summed up By this theorem
The theorem is called
Four color theorem
I'm not even gonna elaborate but n o
Its called
four color theorem
yes, and it comes up in graph theory
and you can't exactly sum up topology in a single theorem cause it's an entire field, it's like saying you can sum up number theory in a single theorem
you can't, it's just too vast
me and peano against the world

It is summed up By one theorem.
Topology is anyway
And that theorem is
Four color theorem
This is what im sayint.
Saying
gotcha
Am I right?
No
@blissful prawn Has your question been resolved?
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Okay so y=max{x,1}
So y={(1,1),(2,1),(3,1)} like that ?
Am I right or missing something
R = that
Sorry
i didn't check but prolly right
Yes R is that
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✅
It can also be a number less than 1?
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google says this question doesnt make sense
maybe they mean the normal vector?
that's not unique but at least it has a unique direction
its quite a different thing though
i think its quite safe to just return this question to the teacher or whoever gave you that
because its nonsene
might be a typo, but its a non-obvious one
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I have to find the domain for this equation
This is the solution given in the book:
I have graphed the inequalities, and gotten most of the answer, but I don't understand why there's a -1 + ... in the domain? Should it not just be -{sqrt[1-(x-2)^2]} < y?
it's from here
so we have (y+1)^2>1-(x-2)^2
then it follows y+1 > sqrt(1-(x-2)^2)
and then taking that +1 on the otherside of the inequality results in -1+...
Oh! I was solving the wrong circle, thank you
np
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context: I'm doing proofs over graphs
hey guys, I want to prove that an edge v-w is st-efficient if and only if dist(s, v) + weight(v, w) + dist (w, t) = dist(s, t)
so I'm trying to prove the first part
edge v-w is st-efficient implies dist(s, v) + weight(v, w) + dist (w, t) = dist(s, t)
and I'm having a hard time
on the other hand, is there a channel for graphs?
!occupied
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
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Math with a little motivation(someone give me what to know for the algebra 1 eoc)
@granite pivot Has your question been resolved?
Hop off grow your garden 🥀
no way you are playing that grow a garden 💀
No no I play to make pretty garden 😊
Anyways, you should probably send your syllabus
What’s that
Or curriculum
What’s that
Brother 💀
Ok
Ok!
How you doing on the practice
Could you send an example?
If it is linear, what should you do?
The thing is I don’t know what linear means
Like
Nobody ever told me
It means the graph is a straight line
Oh
Yes
What does y =? M X + b!!
I love ymxtb
I’m so cooked
I’m going to retake this class in 8th grade
So it means that every hour, it changes by the same amount
Yes yes I know that
just find slope to find the rate then use that till the time needed for the problem
0.6 feet an hour
so the answer is 4.5 feet
@granite pivot
who tf wants my help
no one byut i cant havew it
buddy it is 4.5 feet
Y2-y1/x2-x1?
yes kid 0.6 ft per hour
I need to know how to do it
your formula is correct
algerba 1 eoc was so easy
lol
yes but u should be prepared for trianglex/triangley
(Could be 8th)
ban there ass
<@&268886789983436800>
what if he was perrsiomsion
to be on dsicord
like parents
Okay he says he's 13+, so nothing to do here
Let's go back to helping with the question
@granite pivot Has your question been resolved?
No
r we both stressing over algebra eoc
also is ur pfp pure vanilla cookie
thought so
And yes
whens urs
We have science and social studies Wednesday because we have church and they don’t require like
Skills
Just knowledge
if i were u id study mostly graphs/graphing and different methods of solving linear/exponential/quadratics
I know most of that then
can i give u one of the biggest tips i found outmyself
4?
ok
Yes
did she teach you the equation for that
No
But I just plot what looks nice
ok
so basically
when you are given x and y values and you need to find out the equation/function
there is a special tool that hands you the line + equation
its different between linear exponential and quadratic
btw
r u using desmos or like a physical calculator for the test
Physical but desmos is available
Okk
so first, with the x and y values
create a table and plug them in
then from here put in the numbers
im going to use a random thing for mine
1 sec
Ok ok
lets say for this
Ok
so the equaition looks something like this in order to turn the points into a line (linear)
Is this the one where you find where it repetas
to do the 1 under the things, its the top left key
usually the esc key i think
i lied
the
its
just 1
so like
y then press 1
and it makes the under
then for the squiggly
shift + `
A calc
do it on desmos
and after you do that, you get something like this
it tells you the average line for the graph
and for real linear equations (rather than just random dots) it shows the real equation with the y intercept and slope
then here are the equations for exponential and quadratic
quadratic'
exponential
the exponential one isnt always totally correct because it doesnt take into consideration the asymptote
The asymptote I forgot
but they are similar
Know the word forgot the meaning
its the minimum y
see how it stops a little under 4?
then becomes straight
thats where the asymptote is
Ohh ok ok
thats basically all i got rn
Ok ok tyyyy
solving is pretty easy when your given an equation though
just abuse desmos i cant lie
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help
no, because -4 is a vertical translation of 4 down
To get the vertical assymptote, you let whatever is in the logarithm equal to zero
that doesn't affect the vertical asymptote
you would need a horizontal translation/dilation to affect a vertical asymptote, to move it left or right
if you move a vertical line from y = -infinity to y = infinity up or down, nothing changes
ohhh if it was verticle it would be 2ln(x-4)
Yep
okay so then
now the asympote would be x = 4 mhm
how do i draw that graph
ohhhh
okay then
importantly you'd need to solve 2 ln(x) - 4 = 0 for y = 0
the x-intercept
doesn't exist
but
ln 0 is not 0
ln 1 = 0
that'd be the same as saying 0 = e^0 if that helps
1 = e^0
U will get y = 0 at x = e^2
for ln(x), yes
if you have ln(x + k) where k is positive, the vertical asymptote would now be x = -k
so it would have one
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as a rough estimate, how many marks have I probably got with this paper? It's non calculator section A Paper /16 marks
GCSE level paper
@blissful prawn Has your question been resolved?
can you make your writing neater
like, write on spare paper first
especially 4th pic, if i were grading that
i would get a headache
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You are correct on all of them but you reasoning is false for the fourth problem.. aka u got lucky
Okay
What mark do I get out of /16?
@zealous mortar
Idk depends if ur teacher
If I was ur teacher i would have given a 8-10
Which grade
Ye
It is again as I said depends if ur teacher wants to accept ur question able reasoning
Do you know about mathematics? What Mathematics have u done?
Can u tell me
What mathematics did u do
?
Completed 10th grade,
Yep
Just getting introduced to it
How is this coherent to the topic?
it's funny. laugh.
Lol
Hahahaha
😶
Are u learning for jee??
Hey @zealous mortar
Will be soon
Never heard of it
Do u perhaps means equations with two variables?
Yt
@zealous mortar
Do u know all these
Algebra: Linear equations, quadratic equations, polynomials
Geometry: Triangles, circles, coordinate geometry
Mensuration: Surface area and volume
Statistics & Probability: Basic concepts
Trigonometry: Introduction to ratios and identities
Arithmetic: Number systems, ratios, percentages, profit & loss, etc.
Excel at them
You are good at all of them?
Not really
How do I get good at algebra?
Did u scores well in Class 10 Math in India
?
Watch a video ig . Don't let ego get thinking it's easy , it is crucial . It's taught in 7-8grade
91
91%?
I am not a mathematician.
I don't know the formal definition and stuff
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This question is on the introductory unit for integrals. Prove that
[ \int_0^x \left( \int_0^u f(t) dt \right) du = \int_0^x f(u)(x-u) du]
(Hint: Express the integral on the right-hand side as the difference of two integrals. Then show that both sides of the equation have the same derivative with respect to ${x}$.)
k
The pulling out x?
ye
Well you integrate with respect to u so I think it’s fine
so in this case x is a constant mhm
why is that tho
it's part of the notation, otherwise it would say u(x) or have a written comment
so u is an arbritary independent varible?
not sure what "arbitrary" here means.
Not sure it's helpful to think about variables as dependent or indepehr, im thinking about your question
if u is dependent on x, then i dont think we can pull it out, ya?
reason im reluctant is because in calculus we have the implicit function theorem so often
correct
i think its more helpful to think about dependency vs constant, not dependency vs independence
du/dwhat?
any variable?
ye. thats what im about to point out...
true, the difference is whether its a constant AS FAR AS variable x is concerned
not whether it changes in any way
example
let S be the time i spend on cooking on any given day, T be the free time I have that day, Y be the mass of a clump of radioactive material sitting in a lab in France
then dS/dY=0
but dS/dT != 0
actually these are random variables so poor choice of examples
but the point is the quantities are not influencing each other in any way
with respect to that variable yes
ah ic
this is kind of like partial differentiation, except there you temporarily pretend there is no relationship in anything except each variable at a time, even if it's not true
del/del x f(x,y) holds y constant , del/del y f(x,y) holds x constant
so by integrating in the u world
and x is not influenced by u
i can pull it out
of the integral?
yes, but if you have a relationship like x=cos u, you cannot
🎉
so in this question
x is not a function of u
or influenced by u
so it remains fix when i integrate using u
as by moving u around, x doesnt change
because it acts like a number like -4
if you didnt want that implication the writer would write something like x(u) for x, or u(x) for u
i see, isee
or sometimes its clear from context, like
$$
\begin{cases}
\dot{x} = 3x + y \
\dot{y} = 2y + t
\end{cases}
$$
gfauxpas
here the implication is that x is x(t),y is y(t)
because what else are you differentiating x and y wrt?
yes
damn

.close
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I have found a "proof" for the alternating series test but somehow I managed to do so without using two of the main critical conditions. Thing is I cant see where I went wrong so I will write it here for you to judge.
First we choose an epsilon
then consider the following
$|a_m - a_{m-1} + a_{m-2} - a_{m-3} + ... + a_{n+1} - a_{n}|$
CherryMan
remove the space before the $
CherryMan
then we are given that a_n converges to 0
that means that a_n is contractive for some lambda
thus
$\leq |a_{n+1}-a_n|(1+\lambda^1 + \lambda^2 + ... + \lambda^{m-n-1})$
CherryMan
this should be - a_{m-3}
ah
my mistake
if i edit it now tho its gonna be pushed to the bottom
anyways
$\leq |a_{n+1}-a_n|\frac{1}{1-\lambda}$
CherryMan
$\leq\frac{\lambda^n}{1-\lambda}|a_2-a_1|$
CherryMan
now if we take m,n > N
where N is large enough
then this equation can be lesser than the given epsilon
thus
we proved that the alternating series is cauchy
and thus convergent
now wheres my mistake cus i didnt use the fact than a_n converges to 0, nor did i use that it is monotonic
?
thats the givens for the alternating series test
an converges to 0
an is monotonic decreasing
prove the alternating series converges
"cus i didn’t use the fact that a_n converges to 0"
i only used the fact that it converges
what is "contractive"
basically
a contractive sequence is such that
$|a_{n+2}-a_{n+1}|\leq \lambda|a_{n+1} - a{n}|$
oh
CherryMan
but 0 < lambda < 1?
oh ok
ok maybe i got some specifics wrong
but the proof would still hold
like the geometric sequence is prolly
$|1+\lambda^2 + \lambda^4 + ... + \lambda^{2(m-n-1)}|$
CherryMan
how do we know convergence implies contractive?
bruh
theres proofs online
contractive sequences are cauchy and thus convergent but we don’t know that all convergent sequences are contractive
contractive seems to be a "fast" cauchy sequence
ok thanks!
contractive is stronger than cauchy
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Why is there a sqrt
I know that typically the 2 norm means you take the sqrt of the sum of squares
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.close
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hello I unable to request help due to the channel for step 1 is missing even after activating it
heres a photo
this is your help channel
oh crap
by messaging help-38 you created the help channel yea
sorry then
it doesn't have to be help-0, it can be any number
whats ur math question
I'm new to this
ok then
basically this
and also this
I apologize
I personally tell the diffrence between reduce row and row echelon form
these are the answer in the text book for odd number
and my professor said for the linear equation I only need to do
31,35,37
it's not clear what you're asking us
sorry I want to understand row-echelon form and reduce row-echelon form for the first photo which is question 27-30
and I also want to understand Gaussian elimination,
back-substitution and Gauss-Jordan elimination.
so first of all, reduced row echelon form is a type of row echelon form
like how all ducks are a type of bird, or all triangles are polygons
ok then
every matrix of real or complex numbers has a reduced echelon form, which is not unique
involving doing elementary row operations on the matrix, EROs, have you seen that term
there are three ways to change a mtrix using an elementary row operation
interchange two rows
multiply a row by a non-zero scalar
replace a row with that row + a scalar multiple of another row
whats a scalar
a constant real number. or complex number, depending on context
oh ok then
importantly, if a matrix represents a system of equations, an ERO produces a system of equations with the same solutions (or lack of solutions) as the original
so it's beneficial to "simplify" the matrix to see the solutionjs more easily by performing EROs.
if you simplify it partly, you get row echelon form. this is not unique.
if you simplify it even more, you get reduced row echelon form. this is unique.
So these problems needs to be simplify
yes. here are the rules for row echelon and reduced row echelon
echelon is based on a word (Latin? Greek?) for ladder or staircase
ok then
all rows that are all 0s have to be at the bottom
the first non-zero entry of every row (counting left to right) should be below the first non-zero entry of the row above
yeah thats the confusing part I don't get
let me make an example
first check: are all non-zero rows at the bottom? well there aren't any all-zero rows, so that's not a problem
first row: what's the first non-zero entry (pivot) of the first row?
that would be one
position (2,2)
right?
that's to the right of the row above it
third row, what's the position of the pivot? not the number, the position
question: wouldn't it be neither since buttom isn't all zero
doesnt have to be all0, it just has to be: IF there is a row that's all 0, it's last
what position?
it's in column 4
which row which column
privot 7
row 3 column 4
yes
it's to the right now 1
row 2 column 2
and (3,4) is to the right of (2,2) which is to the right of (1,1)
so it's in row echelon formk
yeah thats the confusing part for one of the question
for 29 it seems to meet all the requirement but the text book said it's neither
why the confusion? you just explained to me why it's in row echelon formk, basically
oh, it could be your book is demanding that row-echelon form has positive 1 for the pivot
and not just any non-zero number
that's an ... annoying convention, but some books do that
oh so I doesn't meet it because the number is less than zero
does this mean it depends on my professor
no, because the number is not one
wait didn't the last problem have the number 7
yes, you should ask if row echelon form for your professor's convention has to have a 1 for the pivot or if it can be any non-zero number
yes, I was going by the definition that didn't require 1
there are two definitions and they're not equivalent
between row echelon and reduced row echelon?
between 1 or the more than 1 in the row or colmun
you have to see what the book or professor wants as the definition
I can send to you right now if you want
for reduced row echelon,
the pivots have to be 1,
and all COLUMNS with a pivot has to have 0 everywhere other than the pivot
I tried reading it but the examples are hard to understand
so for this one
if your book wants a leading coefficient of 1 for row echelon
you would need to replace row 1 with -1*row1
gotcha
[
\begin{bmatrix}
1 & -2 & -1 \
0 & 1 & 0 \
0 & 0 & 1 \
\end{bmatrix}
]
gfauxpas
then you get this. is it in reduced row echelon? let's see
the first column has a pivot at entry (1,1), and every other entry in the column is 0, so that's good
for the second column, what are the pivots?
what if pivot (2,2) was -3
does this mean it wouldn't count has a row echelon since it's below 0
if (2,2) was -3 , whether it counts as row-echelon depends on whether your book needs the pivot to be 1, or if it can be any non-zero number
whether it's negative or positive isnt the point
I thought I was starting to understand but now I'm more confuse
gimmie sec let me see what the text book say about it
definition 1: row echelon form can have the pivots be any non-zero number.
definition 2: row echelon form has to have the pivots be 1
the definitions are not interchangeable
here it is
I don't really understand it
I'm guessing the book only excepts
I guess I'll put both for question 29
I believe question 30 is a reduce row echelon
hello is thier anyone
hey bro I'm gonna leave now cause it seems your unavalible at the moment thanks for your help
.close
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hello is anyone avaliable
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Someone help me simplify this using properties
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I've been trying to understand this person's statistical inference. I believe he's using a maximum a posteriori estimation. But I don't exactly follow the estimation. Is the reasoning flawed? Is there a way to formally write this out?
Here's the original context https://knownandstrangethings.video.blog/2019/07/23/a-note-on-the-fine-tuning-argument/
@runic estuary Has your question been resolved?
what text is this from, "probability for poets"?
there's a lot of unclear stuff here, like e.g. in the first paragraph they seem to be suggesting that a uniform distribution on $\mathbb R$ exists
Bungo
@runic estuary Has your question been resolved?
if its unclear, im not sure what other context would be useful, try scrolling thru the bottom section here to get an indepth feel if youre curious
@runic estuary Has your question been resolved?
it has been a long time since i did much statistics at all, so i had to go back and review a bit
as bungo said, there is no canonical uniform distribution on R, so that kind of sounds like nonsense
but sweeping that under the rug, MAP estimation with a uniform prior is just maximum likelihood estimation
anyhow, basically you have a prior distribution $p(\theta)$, and the posterior is given by
$$p(\theta,|,x) = \frac{p(x,|,\theta)p(\theta)}{\int p(x,|,\theta)p(\theta)d\theta}$$
which is just
$$p(x,|,\theta)p(\theta)$$
up to a normalization constant, aka your likelihood function times your prior distribution
suremark ꙮ
in bayesian statistics this is your new distribution for theta, in MAP you just maximize p(x | theta) p(theta) over theta
and if theta is uniformly distributed then p(theta) is a constant and we can drop it when maximizing the RHS
all that said, the article seems like nonsense tbh, one sample does not an estimation make, you would need to sample from many "universes" to have any justification that this approaches the "true" distribution, and moreover things in nature are not normally distributed because of "natural processes", they are normally distributed due to the central limit theorem, which more or less says when you add many independent factors together things tend to a normal distribution
@runic estuary Has your question been resolved?
Okay, great. I understand all your explanation so far. Can you expand on your critique about sample size of 1? Does that mean the maximum MAP is no longer reliable or something?
I'm trying to figure out how the author is applying the MAP stuff to his universe example.
Mistyped there
@runic estuary Has your question been resolved?
@runic estuary Has your question been resolved?
@fervent thorn
.
@runic estuary Has your question been resolved?
donno how accurate, but i think the general idea is just that with very little data:
this is our best estimate
intuitively, say like if you only know that some random marsian is 5 cm tall. We can guess that marsians have an average height of 5cm because everything else would make less sense to guess.
I don't think they're trying to argue that the estimator would be good in any sense, but ig it makes sense to me intiutively idk :3
but idk where the normal distribution popped up from
is the MAP estimator reliable with a sample size of 1?
i believe they're using the central limit theorem to argue for the normal distribution assumption
i mean you're not going to reliably estimate anything with one data point, there's just no getting past that (unless the standard deviation is known to be something like 0). It's just c is just the value that's more likely than any other to be mu given your data.
oh think they were just arguing that "a lot of shit in nature has a normal distribution", And assuming that whatever they're looking at does too.
wait im just looking at the context 🤣
is there a way to estimate the error probability? im thinking with a larger sample size, the error probability when using MAP decreases
yeah i'd guess loads of nature has normal distributions due to the central limit theorem. how would the central limit theorem be applied here to argue for the normal distribution? im trying to think
idk, someone else might be able to answer better :3
but the jump from assuming that any real value has equal chance of being the mean to a normal distribution with low variance based off of one data point is kinda wild.
I feel like the whole back and forth can just be summed up as:
first guy:
- the chance that the universe bears life is so unlikely! This is best explained by god!
second guy:
- well since the only universe that we know of has life in it. That probably means that universes in general tend to have conditions that favours life!
the error would prolly depend on the variance, which they want to assert is small for some reason
yeah that makes sense, what about the assumption of normal distribution & the central limit theorem? i saw they were arguing the assumption of normal distribution was reasonable on the basis of the central limit theorem
i dont think they mentioned CLT at all XD
and i really would not know how you'd figure out if CLT should apply to physical constants "across different universes"
idk, but idk how you'd get a good idea of how the value physical constants get generated.
hmm, lets suppose they did. what are the conditions of the clt to apply? isnt it like independence or something. how could you apply it here
Something like each physical constant (or whatever) we’re interested in is a sum/average of a shit tonne of things that don’t depend on each other.
Can you elaborate? Not sure i follow
@runic estuary Has your question been resolved?
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,tex put $$ 2^x = u $$
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grey
if you know how to solve quadratics , you can solve this
so do you know how would you would solve this ?@fresh igloo
$u^2-5u+4=0$
ppq#7826
$u = a -5 = b + 4=c$
ppq#7826
what are you doing lol
$$ u^2 -4u -u + 4 = u(u-4)-(u-4) = (u-1)(u-4) $$
grey
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$$ 2^x = 1 $$
grey
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u just need to put it in a calc right?
log
log(2)=4
right
$log(2)=4$
Tan
$\log_2 4$
south
no, take log base 2 on both sides
what you wrote isn't correct
oh
but im correct right
no, this is very wrong
u just need to put it in a calculator
ah yes
but you need to put the right thing in
Somebody asked a question yesterday or the day before and it took me quite a while to solve it.
I don't remember which channel or who asked this question
Did you just react to your own message 😭
looks like it 😆
i didn't read entire thing, i just read the pinned msg and in that it was x^(2i) but whatever leave it, he will tell if he still cares.
wym
it's about another help channel, you won't understand without context so leave it, nothing important