#help-38
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yep!
cool
Ty so much got it and Ty so much for replying really fast and explaining so well
no worries mate!
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can anybody verify something for me
i have this question here, i believe i got it right but for some reason, theyre saying im wrong
can anybody explain why im wrong
Show your work
alright give me a sec
riemann
so what i did was correct right
,w plot sin^2(x) < 3/4 for -pi < x < pi
ahh i see where i fucked up thank you
,w solve sin^2(x) = 3/4 for -pi<x<pi
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well there they go
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hello everyone
umm
i wanted to ask, what is the difference between horizontal stretches and vertical stretches in a formula? i find it challenging to find the difference
the trouble is for some functions, like kx^2 or kx^3 and so on, a horizontal stretch can also give the same result as a vertical stretch
but for most functions this is not the case
there's a clear difference when you stretch the function in the top-down direction
versus the left-right direction
ok
it's a vertical stretch
you mean $\frac{1}{2} y = \sqrt{x}$ right?
? how so?
higher's secret twin brother
yeah cause $y = 2 \sqrt{x}$
higher's secret twin brother
as opposed to $y = \sqrt{x}$ for example
higher's secret twin brother
yeah I'm on laptop
hmm
why couldnt $y = 2 \sqrt{x}$ be a horizontal stretch? wouldnt a horizontal stretch be 1/2 since 1 > b > 0 ?
ゼロноль9: The Slothful 天仙
for a horizontal stretch or compression, you are changing x
so
so $y = \sqrt{2x}$ would be a compression by factor 2
higher's secret twin brother
i give x a value?
or $y = \sqrt{\frac{x}{100}}$ is also horizontal
oh
higher's secret twin brother
so
if x is multiplied by a no., it would be a horizontal , but if it were not directly like sqrt x, it would be a vertical?
yep!
oooh
thank you
soo much
ive been struggling in this part for a while
found it to be the hardest part of transformation
yeah it's basically f(ax) versus a * f(x)
(5x)^2 versus 5 * x^2
sin(5x) versus 5 * sin(x)
no worries
first one is horizontal and second is vertical
ooh
i understand now
thank you
have a good day
or evening
or night
i dunn
thank you though
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I know the formula is P = Ae^-rt
So I do A = 100,000, r = 0.8 , and then t=15 for formula
when i do the present value im doing 100,000 x e^-0.08x15
and im rounding to the nearest cent
i get 30,211.49 but my platform is telling me this is wrong?
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hey! how would you find the limit for a question like this ?
take the integral with the upper bound being a variable, then take the limit as the upper bound goes to infinity
i had that idea, im just confused on how to integrate the equation
u-subtitution
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need help
Close one of your channels
@tepid isle Has your question been resolved?
hey
how to close the other one
@zinc ginkgo apologies didnt get the ping
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in this q i got y1 and y2 as opposite and my determinant is 1
why is this wrong?
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Hello, I’m needing some help with finding this limit! Currently in calculus 1 and I can’t use L’Hopital. Any help would be great thanks!
After writing things in terms of sin and cos I could only get this far but this is the part I’m confused on
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To solve this I changed 1 to 4/4, then added 4/4 with the left most fraction, and then cross multiplied with the left side and I got x = 31/21, why is this wrong?
I got 6/31 you prob just made a calculation mistake somewhere
Oh okay, that's good, so my approach was valid yeah? Would you have done LCM, or done what I did?
Yeah your approach seems fine
I think what I got wrong was I ended up doing 5(-2-7x+4), where I should have added the 4 with da -2 before I cross multiplied
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you have to replace the rounded out digits with 0's...
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is this correct?
won't answer be 60 and not 120
is 120
cosπ will be -1 and 180 will divide by 3
cos(0) is 1
yes then 60 × 1
no
180/3=60
cos(pi) - cos(0) = -2
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Cos(180-x)
I can write this as
Cos(-(x-180))
But since cos is an even function
Cos(180-x) = cos(x-180)
Is this correct?
,w cos(pi-x) = cos(x-pi)
sure is
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this is a perfect sphere so they should all be 4 but they weren't and idk what I should do from here
If you looked carefully at the co-ordinates
You will see that the most right side is from 4 to -4 only
While the others are from 6 to -6
Did you see it
Yeah I think
this is why I'm actually fearful of even touching my homework
and why I can't do calc 3
and am so afraid of it

do you think there's any way you could help me through my homework?
to be fair, that picture and the labeling on the axes was plain shit imo
agreed
I guess the "lesson" to be learned is some psycho may be scaling their axes so always check the numbers lol
still I can't even imagine doing something like this on my own
tbh I used chatgtp cause I didn't even understand the video
(doing it on my own I somehow got every single one of them wrong, that's like a 1/16 chance)
can you graph these by hand?
coordinates? no....
at the very least you can type them into desmos 3d to help graph them, but you really should learn to graph them by hand
I guess you just...add them together and square root them
and set them equal to 0?
idk how to even think about these
v and u
I learned going from rectangular to polar
but not this
yo
I graphed a few in desmos3d to help you get started https://www.desmos.com/3d/acvo7rfo62?beta3d
that's definitely a screw
(I also have no clue how to use desmos for 3d calc where I can't just re-write everything as x and y)
it uses u and v just like your problem does
(it should just be x^2,y,x?)
sorry if I'm being dumb rn
I genuinely have no clue how to do this stuff
so does it recognize u and v
but not anything else?
or do you need to make it recognize it
did you click this link you can play around there
ye, I kinda wanted to also know how to set it up on my own too, but its all good
yeah like try making the 3rd one and see what you get
the second one is showing, I made the first one too but turned it off
yeah, they do something kind of annoying and make u and v only take values in [0,1]
on mine I increased it to be from -10 to +10 so I could see more of the shape
yup
there's multiple ways to think about graphing these on paper or mentally
like personally I see cos(u) and sin(u) and think "oh that's a circle in the xz plane
cause it's in the x and z coordinate
then the v coordinate is just kind of "extruding it outwards along the y-axis making the cylinder
kind of complicated until you get used to it, if you really want to do it the hard way you can always just plug in specific values
like u=0 and v=0, where will this point be in 3D space?
at the end of the day a surface is infinitely many points so if you get one down, only... infinitely many more to go... lol
yeah perfect
so like I was saying, ok that's on a circle in the xz plane, and it is "extruding" along the y axis
so what hapens if you keep u=0 and make v=1
does that point kind of move along to where I said it would?
1,1,0
and v doesn't depend on u
so we can keep the "x" and "z" coordinates the same
and it moves along "y"
bro I have a big smile on my face and idk why
xD
same...
😮
ok open this one up you can see like instead of picking u=0 I made u this constant
so you can see that line, but then make the cylinder by rotating that line around it instead
cause u was basically an angle
I gotta go to sleep it's nearly 4AM here but try to see if you can play around with them a bit
like try to see if you can fix one parameter or fix both parameters
fixing both will get you specific points on the surface which might help get a feel for what you're looking at
but if you can fix one and then you have a curve, so you can kind of reason what happens as the curve "moves" by changing the other
sorta complicated, this isn't something I was born with but I did a lot of multivariable calculus in my life haha
so don't get too frustrated if it doesn't come too easy but remember you can always build the little pieces like tiny points or maybe make a handful of lines/curves by picking the numbers
and you can always check yourself with desmos 3D to see if that makes sense or not
ok I'm heading out now, just wanted to give some tips before I run. Feel free to ping me if you need help on this sort of stuff in the future even if I'm not awake I can respond in the morning or whatever
bro you weren't joking
I'm legit suing the company
in no world is that 3
literally touching the edges of the container
(just had to vent a little)
what do I do lord
it says 3
there's no one in the world who would agree
absolutely no one
am I upset for no reason rn?
(if you were wondering, the answer to b is 3)
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How do I do part a
Is it a stretch parallel to the x axis scale factor 3
Follow by a translation by the vector
(3 sin theta
0)
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how to prove?
one direction should be pretty easy
Assume a divides 1, implies there exist integer c such that 1=ac. it is either 1=(1)(1) or 1=(-1)(-1) so a=1 or a=-1
but idk how to prove the other direction
that's just proving 1 divides 1 and -1 divides 1
Assume a=+-1, so a=1 or a=-1. idk whats next
1 divides 1 means there exists an integer n such that 1n = 1
If a=1, implies a(1)=1, then 1 divides 1, or a divides 1
If a=-1, implies a(1)=-1, then -1 divides 1, or a divides 1
is my proof correct?
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this q doesnt make sense to me
this is my diagram
yes, your diagram is incorrect
is smth wrong? cause the ans says x=5, A=62.5
oh
so you need to subtract 0.5(10 - x)(10) as well
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how can I draw sequence in desmos? like a_n=n+1, Is it possible?
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Is there an easy/faster way of soloving the division of polynomials by binomials other than long division?
well you can factor x^2+7x+12 in this case quite easily
in general you can also compare coefficients
inspection
I don't think so, there is a synthetic division but that is also similar to long division
if you do a lot of problems, you'll eventually spot i.e. x^2 + 7x + 12 = (x+3)(x+4) + 0 quickly
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For each natural number $n$, $\a_n$ is defined as $a_n = \int_{0}^{\frac{\pi}{2}} x \sin(nx) , dx$.
$\$ Calculate $a_n$.
ඞඞඞ
@urban copper Has your question been resolved?
<@&286206848099549185>
Pretty sure you Calculate the integral
how do I do that
And by parts
n is independent of x
So FOR the INTEGRAL it's treated as a 'constant'
but depending on n changes the value of the integral
No, after integration and putting limits you get a expression for a_n in n
limits?
And that's why value of n changes the value of a_n
I meant the bounds of the integral
By parts
,, \int v du = vu - \int udv
ඞඞඞ
Fr
i am trying
Ok
x = v
sin(nx) = du
You mean x = v and sin(nx) dx = du?
yes
i am not sure
About wht
A differential cannot equal a function..?
,, \int v du = vu - \int udv
ඞඞඞ
Yea?
,, \int_{0}^{\frac{\pi}{2}} x \sin(nx) , dx
ඞඞඞ
Then use this
x = v
sin(nx) dx = du
Yea
,, u = \int \sin(nx)dx
ඞඞඞ
this is the hard part
u sub
Yeah
u = nx
So do that here as well
Yeah
du = nx dx
Yea
du = n dx
Yea
ඞඞඞ
do the bounds of the integral change?
They would
But instead of that
Convert back to
X
Since you substitute this
Ye
,, u = \int \sin(nx)dx \ v = x \ dv = 1 \ du = \sin(nx) dx
ඞඞඞ
,, \int v du = vu - \int udv
ඞඞඞ
what is the u integral
,, \int \frac{\sin(t)}{n} dt , t = nx \implies \frac{1}{n} \int \sin(t)dt
ඞඞඞ
u = integral sin(nx)
yes
Yeah that's right
,, u = \frac{-\cos(nx)}{n} \ v = x \ dv = 1 dx\ du = \sin(nx) dx \ \int v du = vu - \int udv \ \int_{0}^{\frac{\pi}{2}} x \sin(nx) dx = \left[\frac{-x \cos(nx)}{n}\right]{0}^{\frac{\pi}{2}} + \int{0}^{\frac{\pi}{2}} \frac{\cos(nx)}{n}dx
No need for tht bro
ඞඞඞ
which one
You can only plug the bounds for the non integral term
Since you'd first need to solve the integral to start plugging the bounds
I don't have a problem
Kk
same
,w cos(pi/2)
,w cos(pi)
I dont think its zero
bounds
Ye
is n
With cos()
Yea but it should be in denominator
No it's good
bro
Rishabh Nirwan
Ye?
Yeah but it's in multiplication with these
nah I think you are right
I think you're a good example of what doing Linear Algebra does to a man
Like Prof Gilbert Strang
wdym
I mean basic algebra becomes hard after tht, Prof also struggles
ye now is corrected
Ye
ye I think thats enough
Yea
I dont know any harmonic analysis nor number theory
I only know basic number theory, like the basic of the basic
Idek what's harmonic analysis
same
12
I think this was full of calculation but wasnt particularly difficult
the real exercise was I guess to analyze the behavior of the sine and cosine
for the multiples of 90 deg
Yeah
but that is not coming in exam I think so I guess its fine
I am not very invested into math
You in college?

not really, like this is foundation year I have to take so I enter university
But I see you doing vector space and all tht??
Isn't tht in college?
depends on your uni I pressume
Yea multiple times, I wasn't able to help cause I only know basics
I see
For me it's advanced for now
I'm in 12
tru
Yeah
its fine, u will grasp it in uni
Nah I'll probably start that before
Well
I'mma head to bed now
It's 11 pm
have a good night sir
GN bro
I dont know the difference of ages
I wasn't offended or anything
I was told to talk respectfully to older ppl than me
Np
You too
Remember to close this
Bye
.close
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S= 1+(2+3)+(4+5+6)+…
S=?
i tried forming the nth term but not succesful
isn't that just sum of natural numbers?
no
it almost is I think
how is it different?
the ans is n(n+1)(n^2+n+2)/8
I believe that they want a formula in terms of n, where n is the number of terms
the terms are 1, (2+3), (4 + 5 + 6) etc
yea
I'd just find how many naturals are you summing
e.g. for n = 1, you are summing 1 natural
for n = 2, you are summing 3 naturals
for n = 3, you are summing 6 naturals
and then once you find out the formula for how many of them you're summing, you can just plug that in the formula for sum of first n naturals
would that work
Why not?
we don't know a definite value for n
we can find out how many naturals we are summing in terms of n
and then plug that in the formula for sum of first n naturals
,w (sqrt(8n+1)-1)/2 * ((sqrt(8n+1)-1)/2 + 1) * ((sqrt(8n+1)-1) + 1)/6 simplify
i can dm you a huge spoiler
i dont think its forming a simple series
firstly, how will that sum look like? What will be the last term?
yeah, it can be hard to grasp
okay you can explain to them now
but if you do 1 or 2 examples, it wont be that bad
https://math.stackexchange.com/questions/2270348/how-to-find-the-sum-of-the-series-1-2-3-4-5-6-cdots-to-n-t actually theres even a stackexchange thread
I see, my approach is same
Anyway, let's try computing n = 5 now
what will the sum look like?
if you remove the parens
what will be the last term if you remove parens (for n = 5)
12+13+14+15+16+17
hmm, hwo did you get that?
manually wrote it down
I see
yeah, the partial sums (up to 1 term, up to 2 terms, ... up to n terms) are
1, 6, 21, .....
= 1 * 2 / 2, 3 * 4 / 2, 6 * 7/2
but then the 1, 3, 6 follow a pattern, the triangular numbers
hopefully that helps you see how
dont wanna use triangular numbers
what are you going to use then
nvm
hi
The key realization is that
S(1) = 1 --> (1 term)
S(2) = 1 + (2 + 3) -->(1 + 2 = 3 terms)
S(3) = 1 + 2 + 3 + 4 + 5 + 6 --> (1 + 2 + 3 = 6 terms)
S(4) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 --> (1 + 2 + 3 + 4 = 10 terms)
Closed by @vague walrus
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oh, thats pretty bad
hello
To ask for mathematics help on this server, please open your own help channel or help thread. See #❓how-to-get-help for instructions.
you can get your own help channel here
in general, for S(n) there would be n(n+1)/2 terms
S(n) = 1 + 2 + 3 + ... + n(n+1)/2

which can be computed again using the formula for sum of first n naturals
wait
any of these channels is free
HS level with olympiad-ish taste
but you can get help at pretty much any level here
I mean this is the biggest maths server
If you need help, go to e.g. #help-43
if you ask on Maths Stack I guarantee you that you'll get closed for 'not providing context' with probability 0.99
\sout{$-\frac{1}{12}$}
LY
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
damn it didn't work
this isnt even lowkey true and i dont even know much math
(just imagine that's strikethrough like this)
their mission is to build a library of quality maths knowledge so they're not really incentivised to cater to the millions of people who have maths questions
that -1/12 is a joke, because through (incorrect) algebraic manipulations, one may derive that 1 + 2 + 3 + 4 + .... (up to infinity) = -1/12
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hi i need help
its high school level
post the question
two sec:,)
i tried translating with google translatw
does it make sense in english
, rotate
it's not clear, can you post the original?
specifically "regularization" and "zero point" aren't standard
ohhh
are you familiar with the ax+b form? how do you think you would start this?
a litte, ive had some time off from school, i think b is 2 on the y thing
it's f(x) = 0
yes!
so we have y=ax+2
thoughts on how we would get the a?
it's how fast it goes up
for example if it goes up 1 every 1 change in x, the slope is 1/1 = 1
your function goes up 1 every 3 change in x (between 0 and 3)
it's 0.33... but just leave it as 1/3
yeah it made sense thank you:)
now we need to do part b
yeah
we want to find where the line hits the x axis
yes
or in other words, we want to find when y = 0 (the height is 0)
so if we have y=1/3x+2 and we want to make y=0, can you find the x?
im not sure i understand sorry
the height is 0 i get
but how do i find x
: (
what do i do
well since y=0 they are the same, so I'm allowed to switch between them
okay
do you know how to find x in 0=1/3x+2?
without drawing it out no..
is there a trick or way
wait hold on
on the graph or solving it like an equation?
equation
okay, well let's go through it. we want x to be by itself right?
yes
so let's get rid of the +2 on its side, how do we do that?
minus?
minus what
-2 on both sides?
what do you mean?
like usually theres a "="
there is one in our equation
yes, one side is 0 and the other side is the other stuff
and remove divide by multiplying?
well we want the x by itself, and right now we have it multiplied by 1/3
but we want it multiplied by 1
so we have to do 1/3 times something = 1
do you know what that number is?
yes
so what do we do with this 3 to get the x by itself?
minus it?
but i have a question
can we only multiply on a single side?
oh nvm
omfg
no, you had it right before... "remove dividing by multiplying"
you always have to do the same thing to both sides
no
first we subtract 2 from each side to get -2= 1/3 x right?
then what happens if we multiply both sides by 3?
yes 1
so -6 = 1*x
so -6 =x
x= -6
your line will pass through the x axis at x =-6
yess
which is the nullpunkt or however you spell it
okey, thank you for patience:,)
do you have more time?
or do i need to ask for help again
@crisp sinew Has your question been resolved?
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,rotate
what next?
use the exponential properties
wdym?
how do i get to this
p^(6/3)
and we know (6/3) = 2,
so it's written as p^2
ok
& check q from denomintor
and apply this^
.close
Closed by @teal dome
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ty
i need help with this
im not sure what to do or where to begin
btw its google translated
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overcooked
could it be that d(t) is a distance time function
so that d''(t) = 0
which would be acceleration
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Did I solve the problem correctly?
no
Where did I go wrong?
Oh okay wait I thought I was supposed to account for the variable in the middle?
of course that's what you have to do
wait then what did I do because I thought that that is what I did?
so you divide both sides by -8 and flip the inequality signs
Oh okay one moment please
as in flip their directions or flip weather they are open/closed?
-5/8less than or equal to x<9/8 ?
<@&286206848099549185>
what
-5/8 =< -x < 9/8
you divided by 8
now you deal with the negative as usual
nice
thanks for the help!
not 8/5
and also the inequality signs are to be flipped
eh no
after this just dividng both sides by -1
you'll get 5/8 >= x > -9/8
the inequality signs will flip
okay
got it
so if it has an or equal to sign then it will always be flipped or what are the conditions for flliping the inequality?
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i want to find all homomorphisms from Z6 to Z15. i came across this but i don't uh understand how they got f(1+6Z)=a+15Z
it's an hypothesis
let's suppose that 1 is sent to whatever a
let's see what a can be
that's what they're doing
Closed by @river willow
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i say 1
why
how did you get 0?
inf isnt in the range 0<=t<inf therefor 0 elsewhere applies
its implied
how is it implied


