#help-38

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dapper swift
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you're now doing the numerator right, so you need to write down the combinations where the 2 numbers add up to 3

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(you can't have 3, 0 cause if you roll 3 first, the game ends)

vestal plaza
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yes

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I didn't say three first

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so its
2 1
1 2
0 3

dapper swift
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yep!

vestal plaza
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1/61/6 + 1/61/6 + 1/6*1/2= 5/36

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Ya so got it

dapper swift
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cool

vestal plaza
# dapper swift cool

Ty so much got it and Ty so much for replying really fast and explaining so well

dapper swift
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no worries mate!

vestal plaza
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wise whale
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can anybody verify something for me

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wise whale
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i have this question here, i believe i got it right but for some reason, theyre saying im wrong

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can anybody explain why im wrong

zinc ginkgo
wise whale
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alright give me a sec

wise whale
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i just combined the intervals after

zinc ginkgo
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$\cup$

solid kilnBOT
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riemann

wise whale
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so what i did was correct right

zinc ginkgo
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,w plot sin^2(x) < 3/4 for -pi < x < pi

wise whale
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ahh i see where i fucked up thank you

zinc ginkgo
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,w solve sin^2(x) = 3/4 for -pi<x<pi

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rough goblet
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*sighs*

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yk the drill

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new channel

rough goblet
zinc ginkgo
rough goblet
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well there they go

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heavy dawn
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hello everyone

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heavy dawn
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umm

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i wanted to ask, what is the difference between horizontal stretches and vertical stretches in a formula? i find it challenging to find the difference

dapper swift
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but for most functions this is not the case

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there's a clear difference when you stretch the function in the top-down direction

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versus the left-right direction

heavy dawn
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well for examples

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example*

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lets say i have 1/2y = sqrt x

dapper swift
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ok

heavy dawn
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1/2 can be a vertical compression or horizontal stretch

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how do i know which one

dapper swift
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you mean $\frac{1}{2} y = \sqrt{x}$ right?

heavy dawn
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? how so?

solid kilnBOT
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higher's secret twin brother

heavy dawn
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yeah

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that one

dapper swift
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yeah cause $y = 2 \sqrt{x}$

solid kilnBOT
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higher's secret twin brother

dapper swift
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as opposed to $y = \sqrt{x}$ for example

solid kilnBOT
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higher's secret twin brother

heavy dawn
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are you a laptop lol

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hmm

dapper swift
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yeah I'm on laptop

heavy dawn
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hmm

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why couldnt $y = 2 \sqrt{x}$ be a horizontal stretch? wouldnt a horizontal stretch be 1/2 since 1 > b > 0 ?

solid kilnBOT
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ゼロноль9: The Slothful 天仙

dapper swift
heavy dawn
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so

dapper swift
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so $y = \sqrt{2x}$ would be a compression by factor 2

solid kilnBOT
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higher's secret twin brother

heavy dawn
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i give x a value?

dapper swift
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or $y = \sqrt{\frac{x}{100}}$ is also horizontal

heavy dawn
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oh

solid kilnBOT
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higher's secret twin brother

heavy dawn
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so

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if x is multiplied by a no., it would be a horizontal , but if it were not directly like sqrt x, it would be a vertical?

heavy dawn
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oooh

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thank you

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soo much

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ive been struggling in this part for a while

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found it to be the hardest part of transformation

dapper swift
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yeah it's basically f(ax) versus a * f(x)

(5x)^2 versus 5 * x^2
sin(5x) versus 5 * sin(x)

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no worries

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first one is horizontal and second is vertical

heavy dawn
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ooh

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i understand now

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thank you

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have a good day

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or evening

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or night

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i dunn

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thank you though

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cinder lark
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I need someone to help me solve this.

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cinder lark
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I know the formula is P = Ae^-rt

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So I do A = 100,000, r = 0.8 , and then t=15 for formula

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when i do the present value im doing 100,000 x e^-0.08x15

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and im rounding to the nearest cent

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i get 30,211.49 but my platform is telling me this is wrong?

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covert swift
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hey! how would you find the limit for a question like this ?

ionic pendant
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take the integral with the upper bound being a variable, then take the limit as the upper bound goes to infinity

covert swift
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i had that idea, im just confused on how to integrate the equation

ionic pendant
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u-subtitution

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tepid isle
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need help

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Please don't occupy multiple help channels.

tepid isle
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\Need help with c for inverse of D + R and how to find that

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thats it

zinc ginkgo
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zinc ginkgo
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Close one of your channels

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tepid isle
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how to close the other one

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@zinc ginkgo apologies didnt get the ping

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rough iron
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in this q i got y1 and y2 as opposite and my determinant is 1

rough iron
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why is this wrong?

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serene parcel
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Hello, I’m needing some help with finding this limit! Currently in calculus 1 and I can’t use L’Hopital. Any help would be great thanks!

serene parcel
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After writing things in terms of sin and cos I could only get this far but this is the part I’m confused on

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serene parcel
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<@&286206848099549185>

serene parcel
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empty wyvern
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To solve this I changed 1 to 4/4, then added 4/4 with the left most fraction, and then cross multiplied with the left side and I got x = 31/21, why is this wrong?

shell quest
empty wyvern
shell quest
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Yeah your approach seems fine

empty wyvern
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I think what I got wrong was I ended up doing 5(-2-7x+4), where I should have added the 4 with da -2 before I cross multiplied

stray drum
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Yes order of operations

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Do whats in the parentheses first

empty wyvern
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Word

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Ty

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.solved

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echo jasper
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echo jasper
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why is the answer not 201 grams

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201145 g rojunded 3 sf is 201 i thought

ionic pendant
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you have to replace the rounded out digits with 0's...

echo jasper
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got it

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.close thnxs

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sly basalt
#

is this correct?
won't answer be 60 and not 120

lusty delta
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is 120

sly basalt
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cosπ will be -1 and 180 will divide by 3

lusty delta
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cos(0) is 1

sly basalt
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yes then 60 × 1

lusty delta
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no

sly basalt
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180/3=60

lusty delta
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cos(pi) - cos(0) = -2

sly basalt
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oh

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I ignored lower limit

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thank you

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late laurel
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Cos(180-x)

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late laurel
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I can write this as

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Cos(-(x-180))

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But since cos is an even function

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Cos(180-x) = cos(x-180)

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Is this correct?

vapid lynx
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,w cos(pi-x) = cos(x-pi)

vapid lynx
late laurel
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thank you

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true flare
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this is a perfect sphere so they should all be 4 but they weren't and idk what I should do from here

mellow tendon
true flare
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wait

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it;s 8?

mellow tendon
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You will see that the most right side is from 4 to -4 only
While the others are from 6 to -6

true flare
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HUH

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I SEE THE 6

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WHAT THE HECK

mellow tendon
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Did you see it

true flare
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so both x and y are 6

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for a and b

true flare
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they have to be 6

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if not then 💀

mellow tendon
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Yeah I think

true flare
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this is why I'm actually fearful of even touching my homework

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and why I can't do calc 3

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and am so afraid of it

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do you think there's any way you could help me through my homework?

mellow tendon
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Lol it was 5

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I mean it was kinda look like 5 catgiggle

summer musk
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to be fair, that picture and the labeling on the axes was plain shit imo

true flare
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agreed

summer musk
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I guess the "lesson" to be learned is some psycho may be scaling their axes so always check the numbers lol

true flare
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still I can't even imagine doing something like this on my own
tbh I used chatgtp cause I didn't even understand the video

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(doing it on my own I somehow got every single one of them wrong, that's like a 1/16 chance)

true flare
summer musk
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at the very least you can type them into desmos 3d to help graph them, but you really should learn to graph them by hand

true flare
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I guess you just...add them together and square root them

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and set them equal to 0?

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idk how to even think about these

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v and u

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I learned going from rectangular to polar

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but not this

ancient escarp
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haha Lol you're here no way

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Hello orion

true flare
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yo

true flare
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that's definitely a screw

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(I also have no clue how to use desmos for 3d calc where I can't just re-write everything as x and y)

summer musk
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it uses u and v just like your problem does

true flare
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(it should just be x^2,y,x?)

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sorry if I'm being dumb rn

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I genuinely have no clue how to do this stuff

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so does it recognize u and v

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but not anything else?

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or do you need to make it recognize it

summer musk
true flare
summer musk
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yeah like try making the 3rd one and see what you get

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the second one is showing, I made the first one too but turned it off

true flare
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its literally so small

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just like a puzzle piece I guess

summer musk
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yeah, they do something kind of annoying and make u and v only take values in [0,1]

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on mine I increased it to be from -10 to +10 so I could see more of the shape

true flare
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that's better

summer musk
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yup

true flare
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just a cylinder

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0_0

summer musk
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there's multiple ways to think about graphing these on paper or mentally

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like personally I see cos(u) and sin(u) and think "oh that's a circle in the xz plane

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cause it's in the x and z coordinate

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then the v coordinate is just kind of "extruding it outwards along the y-axis making the cylinder

true flare
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I see it

summer musk
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kind of complicated until you get used to it, if you really want to do it the hard way you can always just plug in specific values

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like u=0 and v=0, where will this point be in 3D space?

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at the end of the day a surface is infinitely many points so if you get one down, only... infinitely many more to go... lol

true flare
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1,0,0

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or i

summer musk
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yeah perfect

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so like I was saying, ok that's on a circle in the xz plane, and it is "extruding" along the y axis

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so what hapens if you keep u=0 and make v=1

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does that point kind of move along to where I said it would?

true flare
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1,1,0

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and v doesn't depend on u

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so we can keep the "x" and "z" coordinates the same

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and it moves along "y"

summer musk
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yeah exactly

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like definitely clear to see (1,v,0) is just a line really

true flare
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bro I have a big smile on my face and idk why

summer musk
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😛

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yeah cool right?

true flare
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YEAH

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bro

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I wanna be just like you when I grow up

summer musk
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xD

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same...

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😮

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ok open this one up you can see like instead of picking u=0 I made u this constant

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so you can see that line, but then make the cylinder by rotating that line around it instead

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cause u was basically an angle

true flare
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goofy line go brr

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circular moiton

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that's crazy

summer musk
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I gotta go to sleep it's nearly 4AM here but try to see if you can play around with them a bit

true flare
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u is an angle

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I just realized it

summer musk
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like try to see if you can fix one parameter or fix both parameters

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fixing both will get you specific points on the surface which might help get a feel for what you're looking at

true flare
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calc 2 and differential equations has scarred me with using x instead of theta

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XD

summer musk
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but if you can fix one and then you have a curve, so you can kind of reason what happens as the curve "moves" by changing the other

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sorta complicated, this isn't something I was born with but I did a lot of multivariable calculus in my life haha

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so don't get too frustrated if it doesn't come too easy but remember you can always build the little pieces like tiny points or maybe make a handful of lines/curves by picking the numbers

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and you can always check yourself with desmos 3D to see if that makes sense or not

summer musk
true flare
#

ur awesome bro

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sleep good

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PEACE

true flare
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I'm legit suing the company

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in no world is that 3

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literally touching the edges of the container

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(just had to vent a little)

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what do I do lord

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it says 3

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there's no one in the world who would agree

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absolutely no one

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am I upset for no reason rn?

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(if you were wondering, the answer to b is 3)

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winged flare
#

How do I do part a

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winged flare
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Is it a stretch parallel to the x axis scale factor 3

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Follow by a translation by the vector

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(3 sin theta
0)

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icy salmon
#

how to prove?

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trail ingot
#

one direction should be pretty easy

icy salmon
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Assume a divides 1, implies there exist integer c such that 1=ac. it is either 1=(1)(1) or 1=(-1)(-1) so a=1 or a=-1

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but idk how to prove the other direction

trail ingot
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that's just proving 1 divides 1 and -1 divides 1

icy salmon
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Assume a=+-1, so a=1 or a=-1. idk whats next

trail ingot
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1 divides 1 means there exists an integer n such that 1n = 1

icy salmon
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If a=1, implies a(1)=1, then 1 divides 1, or a divides 1
If a=-1, implies a(1)=-1, then -1 divides 1, or a divides 1

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is my proof correct?

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earnest nymph
#

this q doesnt make sense to me

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earnest nymph
#

this is my diagram

rough goblet
#

yes, your diagram is incorrect

earnest nymph
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is smth wrong? cause the ans says x=5, A=62.5

rough goblet
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it's CDQP

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so B isn't there

earnest nymph
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oh

rough goblet
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so you need to subtract 0.5(10 - x)(10) as well

earnest nymph
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LMAO WHOOPS

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THANKS

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fresh pendant
#

how can I draw sequence in desmos? like a_n=n+1, Is it possible?

fresh pendant
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Wonderful

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#
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empty wyvern
#

Is there an easy/faster way of soloving the division of polynomials by binomials other than long division?

charred trail
#

well you can factor x^2+7x+12 in this case quite easily

#

in general you can also compare coefficients

meager bloom
somber ginkgo
#

if you do a lot of problems, you'll eventually spot i.e. x^2 + 7x + 12 = (x+3)(x+4) + 0 quickly

empty wyvern
#

Ty

#

.solved

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urban copper
#

For each natural number $n$, $\a_n$ is defined as $a_n = \int_{0}^{\frac{\pi}{2}} x \sin(nx) , dx$.
$\$ Calculate $a_n$.

solid kilnBOT
#

ඞඞඞ

urban copper
#

what should I Calculate, the definite integral?

#

isnt it like a sequence

trim joltBOT
#

@urban copper Has your question been resolved?

urban copper
#

<@&286206848099549185>

small root
urban copper
#

how do I do that

small root
#

And by parts

urban copper
#

since n is inside sine

#

and is saying for all natural numbers

small root
#

So FOR the INTEGRAL it's treated as a 'constant'

urban copper
#

but depending on n changes the value of the integral

small root
urban copper
#

limits?

small root
#

And that's why value of n changes the value of a_n

small root
urban copper
#

ahh

#

how to integrate this

small root
#

By parts

urban copper
#

,, \int v du = vu - \int udv

solid kilnBOT
#

ඞඞඞ

small root
#

Yea

#

Try that while treating n as 'constant'

mild oxide
#

Fr

small root
#

Want an integral?

urban copper
small root
urban copper
#

x = v
sin(nx) = du

small root
#

You mean x = v and sin(nx) dx = du?

urban copper
#

yes

small root
#

Ok

#

That's correct

urban copper
#

i am not sure

small root
#

About wht

urban copper
#

du = sin(nx)

#

why isnt correct

small root
urban copper
#

,, \int v du = vu - \int udv

solid kilnBOT
#

ඞඞඞ

small root
#

Yea?

urban copper
#

,, \int_{0}^{\frac{\pi}{2}} x \sin(nx) , dx

solid kilnBOT
#

ඞඞඞ

urban copper
#

ah right

#

sin(nx)dx=du

small root
#

Ye

#

Solve for u

#

And dv also

small root
urban copper
#

x = v
sin(nx) dx = du

urban copper
#

v'=1

small root
urban copper
#

,, u = \int \sin(nx)dx

solid kilnBOT
#

ඞඞඞ

urban copper
#

this is the hard part

small root
#

Let's suppose that n is 2

#

What'd you do then

urban copper
#

u sub

small root
#

Yeah

urban copper
#

u = nx

small root
#

So do that here as well

small root
urban copper
#

du = nx dx

small root
#

I think you made a typo

urban copper
#

no

#

or a moment

#

u = nx

#

we differentiate both sides

small root
#

Yea

urban copper
#

du = n dx

small root
#

Yea

urban copper
#

du/n=dx

#

,, \int_{0}^{\frac{\pi}{2}} x \sin(nx) , dx

solid kilnBOT
#

ඞඞඞ

urban copper
#

do the bounds of the integral change?

small root
#

But instead of that

#

Convert back to

#

X

small root
#

They wouldn't

small root
urban copper
#

oh right

#

we were in the middle of ibp

small root
urban copper
#

,, u = \int \sin(nx)dx \ v = x \ dv = 1 \ du = \sin(nx) dx

solid kilnBOT
#

ඞඞඞ

urban copper
#

,, \int v du = vu - \int udv

solid kilnBOT
#

ඞඞඞ

small root
#

Ig you are already doing tht

urban copper
#

what is the u integral

#

,, \int \frac{\sin(t)}{n} dt , t = nx \implies \frac{1}{n} \int \sin(t)dt

solid kilnBOT
#

ඞඞඞ

urban copper
#

-cos(t)/n

#

-cos(nx)/n

#

let me grab paper

small root
urban copper
small root
urban copper
#

,, u = \frac{-\cos(nx)}{n} \ v = x \ dv = 1 dx\ du = \sin(nx) dx \ \int v du = vu - \int udv \ \int_{0}^{\frac{\pi}{2}} x \sin(nx) dx = \left[\frac{-x \cos(nx)}{n}\right]{0}^{\frac{\pi}{2}} + \int{0}^{\frac{\pi}{2}} \frac{\cos(nx)}{n}dx

small root
#

dv = dx

#

v' = 1

#

Yea

#

Ye

#

Yea

#

Remember to Put the bounds tho

urban copper
#

sorry

#

0 to pi/2

small root
small root
#

If you put the bounds

#

One of the terms goes to 0

#

Yea

solid kilnBOT
#

ඞඞඞ

urban copper
#

which one

small root
#

Since you'd first need to solve the integral to start plugging the bounds

urban copper
#

let me grab paper

#

or we will be here ages

small root
small root
urban copper
#

ok let me go to the toilet then

#

I ll ping you in 3 min

small root
#

Okk

#

I'll be back in like 5 min

#

I'm back

urban copper
#

same

urban copper
#

,w cos(pi/2)

solid kilnBOT
urban copper
#

,w cos(pi)

solid kilnBOT
urban copper
#

what

#

,rotate

solid kilnBOT
urban copper
#

I dont think its zero

small root
#

There's a u there

#

Mb

urban copper
#

i did a bunch of progress

small root
#

Looks right

#

Then using the limits

urban copper
#

bounds

small root
#

Yea

#

Same thing

urban copper
#

,rotate

solid kilnBOT
small root
#

Ye

urban copper
#

,rotate

solid kilnBOT
small root
#

How'd you get u in the numerator

urban copper
#

is n

small root
#

With cos()

urban copper
#

is not u

#

sorry for the bad handwriting

small root
#

Yea but it should be in denominator

urban copper
#

this step

#

,rotate

small root
solid kilnBOT
urban copper
small root
#

Hlo?

urban copper
#

are u sure or no

#

like

small root
#

It's (Pi/2)/(u)

#

$$( pi/2)/u = pi/(2u) $$

urban copper
#

bro

solid kilnBOT
#

Rishabh Nirwan

small root
urban copper
#

also the cosine

#

is divided by the u

#

or no

#

wtf

small root
urban copper
#

nah I think you are right

small root
#

I think you're a good example of what doing Linear Algebra does to a man

#

Like Prof Gilbert Strang

urban copper
#

wdym

small root
#

I mean basic algebra becomes hard after tht, Prof also struggles

urban copper
#

xdd

#

,rotate

solid kilnBOT
urban copper
#

ye now is corrected

small root
#

Ye

urban copper
small root
#

Yeah

#

And you can confirm by plugging some values

urban copper
#

,rotate

solid kilnBOT
small root
#

Ye

#

You can check for 1 and 0

#

But for 0 you'll have to take a limit

urban copper
#

how do I calcukate for each n

#

wtf?

small root
#

For a_n

urban copper
#

ye I think thats enough

small root
#

Yea

urban copper
#

I dont know any harmonic analysis nor number theory

small root
#

Idek what's harmonic analysis

urban copper
#

which grade u in

small root
urban copper
#

I think this was full of calculation but wasnt particularly difficult

#

the real exercise was I guess to analyze the behavior of the sine and cosine

#

for the multiples of 90 deg

small root
#

Yeah

urban copper
#

but that is not coming in exam I think so I guess its fine

#

I am not very invested into math

small root
small root
urban copper
#

not really, like this is foundation year I have to take so I enter university

small root
#

Isn't tht in college?

urban copper
#

oh, you saw that?

#

is algebra course I have to pass in foundation year program

urban copper
small root
small root
urban copper
#

is nothing too advanced, but very specific

#

you can grasp it on your own

small root
#

I'm in 12

urban copper
#

tru

small root
#

Yeah

urban copper
#

its fine, u will grasp it in uni

small root
#

Well

#

I'mma head to bed now

#

It's 11 pm

urban copper
#

have a good night sir

small root
#

GN bro

small root
#

Noice

urban copper
#

I dont know the difference of ages

small root
urban copper
#

I was told to talk respectfully to older ppl than me

small root
#

I'm older..?

#

Noice ig

urban copper
#

anyways, ty for the integral help

#

I will go for a walk, have a nice one

small root
small root
#

Remember to close this

#

Bye

urban copper
#

.close

trim joltBOT
#
Channel closed

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trim joltBOT
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vague walrus
#

S= 1+(2+3)+(4+5+6)+…

S=?

trim joltBOT
vague walrus
#

i tried forming the nth term but not succesful

wind cloak
#

isn't that just sum of natural numbers?

vague walrus
#

no

main sigil
#

it almost is I think

dapper swift
#

how is it different?

vague walrus
#

the ans is n(n+1)(n^2+n+2)/8

main sigil
dapper swift
#

oh okay that's different

#

ahhhhh

main sigil
#

the terms are 1, (2+3), (4 + 5 + 6) etc

vague walrus
#

yea

main sigil
#

I'd just find how many naturals are you summing

#

e.g. for n = 1, you are summing 1 natural

#

for n = 2, you are summing 3 naturals

#

for n = 3, you are summing 6 naturals

#

and then once you find out the formula for how many of them you're summing, you can just plug that in the formula for sum of first n naturals

vague citrus
#

would that work

main sigil
vague citrus
#

we don't know a definite value for n

main sigil
#

and then plug that in the formula for sum of first n naturals

dapper swift
#

,w (sqrt(8n+1)-1)/2 * ((sqrt(8n+1)-1)/2 + 1) * ((sqrt(8n+1)-1) + 1)/6 simplify

main sigil
#

i can dm you a huge spoiler

main sigil
#

let's compute the value for n = 5

vague walrus
#

i dont think its forming a simple series

main sigil
#

firstly, how will that sum look like? What will be the last term?

vague walrus
#

i saw the soln

#

but didnt understand it

main sigil
#

yeah, it can be hard to grasp

dapper swift
#

okay you can explain to them now

main sigil
#

but if you do 1 or 2 examples, it wont be that bad

vague walrus
main sigil
#

I see, my approach is same

main sigil
#

what will the sum look like?

#

if you remove the parens

#

what will be the last term if you remove parens (for n = 5)

vague walrus
#

12+13+14+15+16+17

main sigil
vague walrus
#

manually wrote it down

main sigil
#

I see

dapper swift
#

yeah, the partial sums (up to 1 term, up to 2 terms, ... up to n terms) are

1, 6, 21, .....
= 1 * 2 / 2, 3 * 4 / 2, 6 * 7/2

but then the 1, 3, 6 follow a pattern, the triangular numbers

#

hopefully that helps you see how

vague walrus
#

dont wanna use triangular numbers

dapper swift
#

what are you going to use then

vague walrus
#

nvm

minor charm
#

hi

vague walrus
#

ill figureit out ig

#

.close

main sigil
#

The key realization is that
S(1) = 1 --> (1 term)
S(2) = 1 + (2 + 3) -->(1 + 2 = 3 terms)
S(3) = 1 + 2 + 3 + 4 + 5 + 6 --> (1 + 2 + 3 = 6 terms)
S(4) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 --> (1 + 2 + 3 + 4 = 10 terms)

trim joltBOT
#
Channel closed

Closed by @vague walrus

Use .reopen if this was a mistake.

main sigil
minor charm
#

hello

dapper swift
#

!help

trim joltBOT
#

To ask for mathematics help on this server, please open your own help channel or help thread. See #❓how-to-get-help for instructions.

dapper swift
#

you can get your own help channel here

main sigil
#

S(n) = 1 + 2 + 3 + ... + n(n+1)/2

minor charm
main sigil
#

which can be computed again using the formula for sum of first n naturals

minor charm
#

wait

main sigil
minor charm
#

what level math is this

#

i think wrong server

main sigil
#

but you can get help at pretty much any level here

minor charm
#

alr...........

#

like i just turned

dapper swift
#

I mean this is the biggest maths server

main sigil
dapper swift
#

if you ask on Maths Stack I guarantee you that you'll get closed for 'not providing context' with probability 0.99

somber ginkgo
solid kilnBOT
#

LY
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

somber ginkgo
#

damn it didn't work

vague walrus
#

this isnt even lowkey true and i dont even know much math

somber ginkgo
dapper swift
main sigil
trim joltBOT
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Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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crisp sinew
#

hi i need help

trim joltBOT
crisp sinew
#

its high school level

vapid lynx
#

post the question

crisp sinew
#

two sec:,)

#

i tried translating with google translatw

#

does it make sense in english

vapid lynx
#

, rotate

solid kilnBOT
vapid lynx
crisp sinew
#

sure

#

its in danish tho

vapid lynx
#

specifically "regularization" and "zero point" aren't standard

crisp sinew
#

i think they mean the like: ax+b

#

type of thing

#

i dont know what zero point is

vapid lynx
#

oh like the equation sure

#

zero point is either the x or y intercept

crisp sinew
#

ohhh

vapid lynx
crisp sinew
#

a litte, ive had some time off from school, i think b is 2 on the y thing

vapid lynx
vapid lynx
#

so we have y=ax+2

#

thoughts on how we would get the a?

crisp sinew
#

a is the one that doesnt need b right?

#

or is it the othr way around

vapid lynx
#

a is the slope

#

rise over run

crisp sinew
#

the line going up?

#

english isnt my first language:,)

vapid lynx
#

it's how fast it goes up

#

for example if it goes up 1 every 1 change in x, the slope is 1/1 = 1

#

your function goes up 1 every 3 change in x (between 0 and 3)

crisp sinew
#

ohh yeah i see

#

do you devide then?

#

or what do you do with that info

vapid lynx
#

rise over run

#

up / distance to go up

crisp sinew
#

run is the x line

#

yeah okey

#

1:3?

vapid lynx
#

yes 1/3

#

so what is the whole equation now?

crisp sinew
#

i dont want to sound stupid

#

isnt that like 0,33

#

oh nvm

#

sorry

#

1/3x+2??

vapid lynx
#

it's 0.33... but just leave it as 1/3

vapid lynx
#

do you understand how we got this?

crisp sinew
#

yeah it made sense thank you:)

vapid lynx
#

now we need to do part b

crisp sinew
#

yeah

vapid lynx
#

we want to find where the line hits the x axis

crisp sinew
#

yes

vapid lynx
#

or in other words, we want to find when y = 0 (the height is 0)

#

so if we have y=1/3x+2 and we want to make y=0, can you find the x?

crisp sinew
#

im not sure i understand sorry

#

the height is 0 i get

#

but how do i find x

#

: (

#

what do i do

vapid lynx
#

we want to make y=0 in our equation y=1/3x+2

#

if y = 0, then 0=1/3x+2 right?

crisp sinew
#

oh are you putting 0 in y's place?

#

wait

#

oooof

vapid lynx
#

well since y=0 they are the same, so I'm allowed to switch between them

crisp sinew
#

okay

vapid lynx
#

do you know how to find x in 0=1/3x+2?

crisp sinew
#

without drawing it out no..

#

is there a trick or way

#

wait hold on

#

on the graph or solving it like an equation?

vapid lynx
#

equation

crisp sinew
#

oh

#

no, division in equations are confusing

vapid lynx
#

okay, well let's go through it. we want x to be by itself right?

crisp sinew
#

yes

vapid lynx
#

so let's get rid of the +2 on its side, how do we do that?

crisp sinew
#

minus?

vapid lynx
#

minus what

crisp sinew
#

-2 on both sides?

vapid lynx
#

perfect

#

-2 = 1/3 x

#

do you know how to get rid of the division?

crisp sinew
#

wait where are the two sides seperated

#

multiplikation?

vapid lynx
#

what do you mean?

crisp sinew
#

like usually theres a "="

vapid lynx
#

there is one in our equation

crisp sinew
#

oh

#

the 0=***?

#

ohh

#

sorry

#

yeah

#

i see

vapid lynx
#

yes, one side is 0 and the other side is the other stuff

crisp sinew
#

and remove divide by multiplying?

vapid lynx
#

yes

#

multiply what

crisp sinew
#

the 1?

#

no

#

i dont know

vapid lynx
#

well we want the x by itself, and right now we have it multiplied by 1/3

#

but we want it multiplied by 1

#

so we have to do 1/3 times something = 1

#

do you know what that number is?

crisp sinew
#

no

#

3?

vapid lynx
#

yes

crisp sinew
#

oops

#

sorry im slow

vapid lynx
#

so what do we do with this 3 to get the x by itself?

crisp sinew
#

minus it?

#

but i have a question

#

can we only multiply on a single side?

#

oh nvm

#

omfg

vapid lynx
vapid lynx
crisp sinew
#

but isnt the division gone?

#

doesnt the equation look like 0=3x+2 now?

#

oh

#

no 2

vapid lynx
#

no

#

first we subtract 2 from each side to get -2= 1/3 x right?

#

then what happens if we multiply both sides by 3?

crisp sinew
#

-6 on one of the sides?

#

on nothing on the 1/3?

vapid lynx
#

-6= 3*1/3*x

#

what is 3*1/3?

crisp sinew
#

3/3?

#

0

#

or 1?

#

grahhh

vapid lynx
#

yes 1

#

so -6 = 1*x

#

so -6 =x

#

x= -6

#

your line will pass through the x axis at x =-6

crisp sinew
#

yess

vapid lynx
#

which is the nullpunkt or however you spell it

crisp sinew
#

okey, thank you for patience:,)

#

do you have more time?

#

or do i need to ask for help again

trim joltBOT
#

@crisp sinew Has your question been resolved?

trim joltBOT
#
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#
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teal dome
trim joltBOT
teal dome
#

What next?

#

the answer is 2p2q1/3

#

bold is power

true kestrel
#

,rotate

solid kilnBOT
teal dome
#

what next?

true kestrel
#

use the exponential properties

teal dome
#

wdym?

true kestrel
#

quotient rule

teal dome
true kestrel
#

p^(6/3)
and we know (6/3) = 2,
so it's written as p^2

teal dome
#

ok

true kestrel
#

& check q from denomintor

true kestrel
teal dome
#

.close

trim joltBOT
#
Channel closed

Closed by @teal dome

Use .reopen if this was a mistake.

teal dome
crisp sinew
#

i need help with this

#

im not sure what to do or where to begin

#

btw its google translated

trim joltBOT
#
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Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

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sleek canopy
#

remember always that you are not dumb 😭

#

idk

limpid dawn
#

overcooked

#

could it be that d(t) is a distance time function

#

so that d''(t) = 0

#

which would be acceleration

trim joltBOT
#

@karmic spade Has your question been resolved?

trim joltBOT
#
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echo dove
#

Did I solve the problem correctly?

trim joltBOT
wind cloak
echo dove
#

Where did I go wrong?

wind cloak
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you entered the range of -8x

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instead of just x

echo dove
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Oh okay wait I thought I was supposed to account for the variable in the middle?

wind cloak
echo dove
#

wait then what did I do because I thought that that is what I did?

wind cloak
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-5 =< -8x < 9

lunar galleon
#

so you divide both sides by -8 and flip the inequality signs

echo dove
#

Oh okay one moment please

#

as in flip their directions or flip weather they are open/closed?

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-5/8less than or equal to x<9/8 ?

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<@&286206848099549185>

tight rose
#

what

wind cloak
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you divided by 8

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now you deal with the negative as usual

echo dove
#

and it needs to be -?

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8/5=<x<-9/8 ?

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wait I got it right yey!

wind cloak
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nice

echo dove
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thanks for the help!

wind cloak
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but a slight mistake

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or something

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it is 5/8

wind cloak
echo dove
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oh

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so I just undo the negative?

wind cloak
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and also the inequality signs are to be flipped

wind cloak
wind cloak
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the inequality signs will flip

echo dove
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okay

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got it

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so if it has an or equal to sign then it will always be flipped or what are the conditions for flliping the inequality?

trim joltBOT
#

@echo dove Has your question been resolved?

trim joltBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

river willow
trim joltBOT
river willow
#

i want to find all homomorphisms from Z6 to Z15. i came across this but i don't uh understand how they got f(1+6Z)=a+15Z

wooden plover
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it's an hypothesis

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let's suppose that 1 is sent to whatever a

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let's see what a can be

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that's what they're doing

river willow
#

ohh thanks

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.close

trim joltBOT
#
Channel closed

Closed by @river willow

Use .reopen if this was a mistake.

trim joltBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

autumn trout
trim joltBOT
autumn trout
#

F(inf) = 0 right?

#

chat gpt says 1

vagrant marsh
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i say 1

autumn trout
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why

vagrant marsh
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how did you get 0?

autumn trout
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inf isnt in the range 0<=t<inf therefor 0 elsewhere applies

vagrant marsh
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f(inf) doesnt really exist

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they mean the limit of x -> inf

autumn trout
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they didnt say that

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they said F(inf)

vagrant marsh
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its implied

autumn trout
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how is it implied