#help-38

1 messages · Page 19 of 1

quaint gazelle
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its because cos is smaller than 1

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so 1-cos is bigger than 0

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by definition of cos

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yeah

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you could

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since for positive numbers

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x=|x|

fathom ivy
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because sin can be negative

but it has to be positive

so you take the abs value to force it to be

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yes

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the full working out should involve putting abs value on both and then you remove the abs of 1-cos because it's completely unnecessary

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good habit

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dense zealot
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quaint gazelle
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yeah

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usually

trail ingot
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it could just be part of the name of the variable

wraith hinge
trail ingot
#

never seen that before then 🤷‍♀️

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wide gyro
#

can someone help me out, I need to completely factor each polynomial over real numbers and find its roots and simplify my answer: f(x) = 2x^4+x^3-35x^2-113x+65

inland orbit
#

Do you know the rational root theorem?

wide gyro
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I tried using a graphing calculator to find the zeros but I think I'm doing it incorrectly because I can't seem to find them

inland orbit
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You couldn't find any?

wide gyro
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I'm not sure, but yeah I fail to find any

inland orbit
wide gyro
inland orbit
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Both, probably

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Your polynomial is degree 4, if you divide by both linear factors, you'll get a quadratic

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It appears the other two roots are non-real, so you won't be able to factor the quadratic in the reals

wide gyro
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yeah you kind of lost me there, but I'm gonna try to use 0.5 to divide thank you

inland orbit
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Use 0.5 how?

wide gyro
inland orbit
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Sure, to divide by (x-0.5), right?

wide gyro
inland orbit
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I just meant, after that, you'll probably want to also divide the result by (x-5)

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That's what I meant by use both

wide gyro
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I couldn't understand what you said before, it didn't feel like it was in english

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my bad

inland orbit
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Lol sorry

wide gyro
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nah i'm just dumb

inland orbit
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Every time you divide by something like (x-k), the degree goes down by 1. You're starting with something of degree 4 (since it's x^4), so you'll need to divide by both to get it down to degree 2

wide gyro
inland orbit
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Which is what you want, degree 2 is something you can deal with with the quadratic formula or whatever

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No problem 👍

wide gyro
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rugged latch
#

not sure how to do this, or where to start

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@rugged latch Has your question been resolved?

rugged latch
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<@&286206848099549185>

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pls tag if u can help

zinc ginkgo
rugged latch
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Yes I found them to be -1 and 7

zinc ginkgo
#

eigenvectors?

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Working towards putting all the stuff together for spectral theorem

rugged latch
# zinc ginkgo eigenvectors?

So I found the reduced matrices, but I’m not sure how to get the eigenvectors from them. Here’s a picture. It feels so simple but I’m having a brain freeze.

rugged latch
rugged latch
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i think my understanding is very lacking on this subject

zinc ginkgo
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use the definition of eigenvector

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Find a v such that

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$(A - \lambda I) v = 0$

solid kilnBOT
#

riemann

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loud plover
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loud plover
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I know messed up somewhere just don't know where

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loud plover
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.close

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grand lark
#

Hi, I'm having trouble understanding the part how 2det(A) = 0. Can someone explain that to me?

zinc ginkgo
grand lark
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All

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?

zinc ginkgo
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,calc 3

solid kilnBOT
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Result:

3
zinc ginkgo
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,calc -3

solid kilnBOT
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Result:

-3
zinc ginkgo
grand lark
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AHAHAHAH ok I see

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x = -x
2x = 0

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Man I hate it when these abstract things block my mind from simple algebra

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Tytytyt

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remote beacon
#

Confused on how - 3²⁸ / 3³⁰ equals - 1/3²

remote beacon
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(whole fraction is negative)

random citrus
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30-28 = 2

stoic saddle
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n^a / n^b = n^(a-b)

remote beacon
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But 28 - 30 is -2

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Can i just switch numerator and denominator?

stoic saddle
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1/n^b = n^(-b)

remote beacon
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Oh

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Ok thx

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wraith hinge
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wraith hinge
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Is there a way to write this as a decimal?

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Itried to simplify so far

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<@&286206848099549185>

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The x and y confuses me do i need to do sonmethibg to get rid of them

zinc ginkgo
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x and y are unknown variables and you have to leave them as variables

wraith hinge
zinc ginkgo
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only if you're given them

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and explicitly told to plug them in

wraith hinge
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#

Please don't occupy multiple help channels.

zinc ginkgo
#

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stoic iron
#

Look harder

silent canyon
#

Don't be a noob

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languid pier
#

it says its right?

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stoic saddle
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you found the x values

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pain

languid pier
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oh just use the other ones?

stoic saddle
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im presuming so

languid pier
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mk

stoic saddle
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values of f to me says f(x_min) f(x_max)

languid pier
#

worked ty

stoic saddle
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no worries

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be careful to read the q next time

languid pier
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im so tired

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stoic saddle
#

understandable

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clever slate
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did I do this wrong or something

zinc ginkgo
#

holy

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can you just use the geometric series

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$\frac{1}{1-(-x)} = \sum_{k=0}^\infty (-x)^k$

solid kilnBOT
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riemann

clever slate
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no

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i have to use this

zinc ginkgo
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oh your derivatives are wrong

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calculate f''' and f''''

clever slate
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oh

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its n!

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right

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ok got it

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thanks

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delicate lance
#

How do I prove this ?

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lament jewel
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hi

delicate lance
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hi

lament jewel
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well

lethal anvil
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hi

delicate lance
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hi

lament jewel
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use sin^2+cos^2=1

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on the left

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also notice that tan = sin/cos

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for the right

delicate lance
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okay

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Oh wait this is easy sry nvm

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full dock
#

Can someone check this if it’s wrong or correct?

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@full dock Has your question been resolved?

steady moth
#

its wrong

#

@full dock

full dock
steady moth
#

you forgot to divide x by /2

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full dock
#

Ohh

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.reopen

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full dock
#

@steady moth

kindred pier
#

What does If cos(x/2) apply mean?

rugged latch
#

Maybe it’s: if f(x) = cos (x/2)

kindred pier
#

oh

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then yes

wraith hinge
#

Ur my only hope

rugged latch
trim lichen
#

open your own channel.

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it takes one click.

wraith hinge
kindred pier
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What makes you so special to take someone else's channel?

wraith hinge
#

Idk

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Nothink

steady moth
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full dock
#

Tysm for the help

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stiff crescent
#

hello, i was wondering if i could get some help in proving a function f is surjective?

stiff crescent
#

is it as simple as supposing some b in the codomain of f such that f(a) = b, then working backwards to show that a is, indeed, in the domain of f?

stoic iron
#

you need to pick an arbitrary b in the codomain, and show b = f(a) for some a in the domain

stiff crescent
#

in practice, do i basically solve for a in terms of b, then show that that solved term is indeed in the domain?

marble wharf
#

yes

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well depends on the function of course, but that is definitely a viable strategy in a lot of cases

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stiff locust
#

So in a linear relationship

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stiff locust
#

a value is increasing by a constant amount

#

What about in a power series?

left oriole
#

depends on the power series, because power series can represent a wide range of possible functions

#

could be a constant function, linear, any polynomial, an exponential, a cosine or sine, etc

stiff locust
#

here is the one am doing

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How would I describe it?

left oriole
#

could be a quadratic (parabola)

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depends on the exact values of the points

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5 points uniquely determine a 4th order polynomial, so that would certainly work

stiff locust
#

So for linear I wrote
The mathematical relationship is linear where acceleration is increasing by a constant amount

left oriole
#

if it were linear, the graph would look like a line

stiff locust
#

What about this?
The mathematical relationship is a power series where acceleration..

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no its for different one

left oriole
#

yea like that one

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wraith hinge
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modest rampart
#

what u want help with as in where are u stuck

wraith hinge
modest rampart
#

for this type of question i will tell u step to go thru it easily
first open the brackets (like multipying 1/6 and 2/3 with their respectives
then transfer variables to one side and constant to other
solve it

wraith hinge
#

Ok thank you

zinc ginkgo
#

,rotate

solid kilnBOT
wraith hinge
#

I have one more equation can u explain

left oriole
#

,rotate

solid kilnBOT
left oriole
# wraith hinge

a reasonable first step would be to clear the denominator (multiply both sides by x-5)

wraith hinge
#

I can't really understand can u show in a paper please

left oriole
#

multiply both sides by x-5, you don't understand that?

wraith hinge
#

Ok can u say next step

left oriole
#

simplify both sides and rearrange into the form ax^2 + bx + c = 0

wraith hinge
#

Btw it's linear equations

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.reopen

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.close

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dense agate
#

Hi!

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dense agate
#

i need help

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please!

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it’s for my math homework tmr

mellow hull
#

Ask

dense agate
#

and sorry it’s just a test

mellow hull
#

Yea just ask

dense agate
#

so we are doing equivalent fractions lemme screen shot it rq

mellow hull
#

Okay

dense agate
#

I wanna know what is that equal to.

mellow hull
#

That's equal to a lot of things

#

Need more context

hazy light
#

If you want the decimal equivalent, it's 0.75

mellow hull
#

Thatss equal to 3k/4k

dense agate
#

so like lemme show you

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it’s comes with this

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so it’s not just any equal number .

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1/8?

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maybe?

mellow hull
shell radish
#

you got 8 pieces on the other thing so to equal it you'd multiply your first fraaction by 2

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leaving you with 6/8

hazy light
#

Multiply and divide 3/4 by 2

mellow hull
dense agate
#

yeah so wouldn’t it be 1/8?

mellow hull
# dense agate

"A single part of the first diagram is equivalent to two parts in the second diagram"

dense agate
#

is it 1/8?

mellow hull
dense agate
#

that’s how fraction works.

night zodiac
dense agate
#

I shaded the left one

mellow hull
night zodiac
night zodiac
mellow hull
dense agate
#

6

4

#

wait no

shell radish
#

everyone calm down and help with my question 💀 . naw im playing but the first "pie" is cut into 4 equal pieces and the second is cut into 8 equal pieces. if both pies are the same size then that means one piece of the first pie is equal to two pieces of the second pie

#

and since you have a total of 3 pieces out of 4

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that means in the second pie, youd have 6 pieces out of 8

night zodiac
#

First, you have $\frac{3}{4}$ on the left pie, on the right pie, it's out of 8. The out of part, is the number in the denominator, aka the total amount of pieces you have. What do you need to multiply by, to make that 4 into 8?

solid kilnBOT
#

dldh06

night zodiac
shell radish
#

sorry dad

dense agate
#

<@&286206848099549185>

#

If 6(x+4)=36, what is the value of x+4?

night zodiac
#

Set it equal to x + 4

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toxic sigil
#

Anything wrong in that?

#

Logarithmic differentiation

rugged latch
#

looks right to me

toxic sigil
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harsh flower
#

How would I solve this

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harsh flower
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<@&286206848099549185>

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harsh flower
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<@&286206848099549185>

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verbal fable
#

how do i simplify [xe^(10lnx)]

trim joltBOT
verbal fable
#

?

#

it would be x^11 but how?

cerulean ember
#

a*ln(x)=ln(x^a)

solid kilnBOT
delicate bobcat
#

these two

#

and you're done

verbal fable
#

i dont get then

#

them

cerulean ember
#

What's confusing you?

verbal fable
#

idk how to apply those rules

#

the question was to differentiate it

#

he solved it like this

#

question 26

verbal fable
#

nvm nvm

#

i got it

#

e cancels ln

#

and 10lnx = x^10

#

so its x * x ^ 10

#

= x ^ 11

#

Thank you @cerulean ember @delicate bobcat

cerulean ember
verbal fable
#

.close

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lament ermine
trim joltBOT
lament ermine
#

What should I do next after this?

#

<@&286206848099549185>

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trim joltBOT
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austere cove
#

Does image of linearly transformation is also called as projection?

zinc ginkgo
austere cove
#

No

austere cove
zinc ginkgo
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@austere cove Has your question been resolved?

austere cove
zinc ginkgo
#

In mathematics, the kernel of a linear map, also known as the null space or nullspace, is the linear subspace of the domain of the map which is mapped to the zero vector. That is, given a linear map L : V → W between two vector spaces V and W, the kernel of L is the vector space of all elements v of V such that L(v) = 0, where 0 denotes the zero...

austere cove
zinc ginkgo
#

wiki is pretty simple?

#

i don't know what you're asking for

austere cove
#

Why kernel and where it is used , need an example relates to real life scenario say like in data science we split data or obtain insights in it like that

zinc ginkgo
#

Just google examples?

austere cove
#

Anything just wanna understand the concept

zinc ginkgo
#

or maybe you're better off asking in a data science server

austere cove
#

I can't message there

zinc ginkgo
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surreal harness
#

would I use permutation or combinations here?

rare nexus
#

Combinations

surreal harness
#

i used brute force to get 4 ways, but what is a step I can take to get started

trim joltBOT
#

@surreal harness Has your question been resolved?

surreal harness
#

no I still need help <@&286206848099549185>

trim joltBOT
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@surreal harness Has your question been resolved?

surreal harness
#

no

#

i need help still

#

<@&286206848099549185>

surreal harness
#

hello

#

anyone

#

.close

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wraith hinge
#

"It is given that m% of the students wait between r minutes to s minutes to get on the bus. State the value of m."

wraith hinge
#

Why is the answer 50? Since it is between r and s minutes, it can be 50 or 75 right?

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wraith hinge
#

What am I doing wrong?

trim joltBOT
fathom ivy
#

what’s larger, (n-6)! or (n-5)!

wraith hinge
#

Yeah it just clicked

#

N-5

fathom ivy
#

rest looks good

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#

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warm sierra
trim joltBOT
warm sierra
#

Eigen value checking if Mine is correct? As online calculator has different value

#

Can someone please help out

slender shard
#

You forgot to subtract -12 in the second column from the 2nd row to the 3rd row.

#

And in the first column, third row; -(-5) = 5.

warm sierra
slender shard
#

Yes, it should be positive.

warm sierra
#

Nd abt the 12 was there an error there?

slender shard
#

Hmm, something else doesn't seem right.

#

You made M_21 = -1 when it should be +1.

warm sierra
#

Found it

#

I wrote the 1 with the wrong sign there

slender shard
#

The -12 should also be +12.

warm sierra
#

Yuppppp

#

Thank youuuu so muchhh ur acc a lifesaver Ty appreciate a lot

warm sierra
slender shard
#

Yeah.

warm sierra
slender shard
#

yw

warm sierra
#

🙏

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#

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dense zealot
trim joltBOT
dense zealot
#

hi can any explain maybe how to get from the clue part to why it's 1* k* 1

#

.close

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warm sierra
trim joltBOT
warm sierra
#

Is my rref correct?

wraith hinge
#

Seems... Fine

warm sierra
#

Fr? Because I had it wrong bfr and I did this again

wraith hinge
#

,w RREF {{-4, 12}, {-1, 3}}

solid kilnBOT
warm sierra
#

Yoooooo

warm sierra
wraith hinge
#

Ofc

warm sierra
#

But also then here the eigen vector is 3,1 which wld be correct in the previous rref and not this

#

Must be doing something wrong

#

I think this is error ?

#

,w RREF {{-3, 12}, {-1, 4}}

warm sierra
trim joltBOT
#

@warm sierra Has your question been resolved?

scarlet escarp
#

the equation would be v_1 - 3v_2 = 0

warm sierra
#

If I had +3 wld the equation still be -3v_2 or then it wld be +3v_2

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#
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warm sierra
#

.reopen

trim joltBOT
#

scarlet escarp
#

so your matrix equation states

#

v1 - 3v2 = 0

#

so v1 = 3v2

#

this your vector should be [3 1] as the one from wolfram alpha

warm sierra
#

Correct yes

#

I just had the question regarding the formula

warm sierra
scarlet escarp
#

which formula

warm sierra
scarlet escarp
#

do you know how matrix multiplication works? in particular matrix-vector multiplication

#

this is no different

warm sierra
#

Ik this sounds stupid but

scarlet escarp
#

think of it as always adding, but we can change the sign of the coefficient

#

so if it was -3

#

it would be v1 + (-3v2)

#

which as you know

#

is just v1 - 3v2

warm sierra
#

Yes

scarlet escarp
#

if you prefer to think of pluses in front of the constants i’m sure that’s fine

warm sierra
#

If the coefficient is a positive number then it would just be addition sign there

#

Since + + = +

scarlet escarp
#

err not exactly, but it works

#

it’s really just a 3, and matrix multiplication calls for addition

#

but again if it works for you run with it

warm sierra
#

Thank you

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#

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true oar
trim joltBOT
true oar
#

i cannot solved this pls help me :((

#

we have to find simply equation of y

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#

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rapid kiln
trim joltBOT
rapid kiln
#

for this question i made 3x - 4y = 35 and x - 2y = 15

#

which i ended up getting y = -5 and x = 5

#

so is that a and b cause in that case the answer is 0

past widget
#

which part about After 15 mins, ping helpers do you not understand?

rapid kiln
#

my bad

past widget
#

Anyways, yeah your answer is right

rapid kiln
#

ok thank you

past widget
#

v = (5, -5) and a + b = 0

rapid kiln
#

.close

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#
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strong horizon
#

Could any1 help me with this problem? I was having difficulties with it yesterday

strong horizon
#

Just to clarify, we’d get this, right?

stark bison
#

First find y'(4)

strong horizon
stark bison
#

Eh, did you get y' = 4^(x^2 - 5x + 5) * (2x - 5) * ln4 ?

stark bison
#

Then it's correct

#

And now plug in x = 4 to get m

strong horizon
stark bison
#

Derivative of 4^x is 4^x * ln4

strong horizon
stark bison
#

Yeah you just find m and then find the free constant so that the tangent actually crosses the graph

strong horizon
stark bison
#

y = mx + b, b here is the free constant

strong horizon
stark bison
#

Yeah

#

What did you get for y'(4)?

strong horizon
strong horizon
stark bison
#

We did* that, now just plug x = 4 into y'(x) = 4^(x^2 - 5x + 5) * (2x - 5) * ln4

strong horizon
stark bison
#

You should have gotten 12ln4 though

stark bison
strong horizon
stark bison
#

$4^{4^2 - 5\cdot{4} + 5}\cdot{(2\cdot{4}-5)}\cdot{\ln{4}} = 4^1 \cdot{3}\cdot{\ln{4}} = 12\ln{4}$

solid kilnBOT
#

A Lonely Bean

stark bison
#

Yes

#

So y = 12ln4 * x + c for some number c

#

We gotta solve for c now

#

We need 12ln4 * x + c to have the same value as y when x = 4

#

So 12ln4 * 4 + c = y(4)

#

48ln4 + c = 4

#

c = 4 - 48ln4

#

So the tangent line is y = 12ln4 * x + 4 - 48ln4

#

Which can be nicely written as y = 12ln4 (x - 4) + 4 actually

strong horizon
stark bison
#

y = 12ln4 * x + c needs to cross the point (4, y(4))

strong horizon
#

Why do we multiply 4 by 12ln(4)?

stark bison
#

Meaning that if we plug in x = 4 and y = y(4) then the equation will still be true

stark bison
stark bison
#

Ight gtg now

strong horizon
#

Last question

#

<@&286206848099549185>

#

<@&286206848099549185>

whole coral
trim joltBOT
#

@strong horizon Has your question been resolved?

strong horizon
#

We substitute 4 into the equation?

whole coral
solid kilnBOT
#

chartbit

whole coral
#

y(4) is y when x=4

strong horizon
#

What does this mean?

whole coral
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#
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whole coral
#

In any case, you want to find out what y = ... is equal to when x=4

trim joltBOT
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eternal gull
#

Is this the right answer, 49?

trim joltBOT
long basin
#

No

#

How did you get 49

fresh pecan
#

its almost right

#

you just forgot the last step

old pebble
#

Quite the username...

eternal gull
eternal gull
fresh pecan
#

write the algebra

#

5x * x = 245

eternal gull
fresh pecan
#

no

eternal gull
old pebble
#

What are your steps?

eternal gull
fresh pecan
#

245 is not 5x

old pebble
#

5x is a line here

eternal gull
#

what do i do

old pebble
old pebble
eternal gull
#

I thought yall could help me step by step but it doesnt seem like im getting any help i have to study for this test and Idont even know all the steps its not like i can just pull them out of my bum like magic, guess Ill seek help elsewhere

eternal gull
#

what has this generation come to

#

degeneracy

old pebble
#

🤣

fresh pecan
old pebble
#

Dude you're the one who's getting mad

fresh pecan
#

i remember being an edgy teen lol

#

i was never this cringe though

eternal gull
#

yall are soft as flies

#

little gay femboys

fresh pecan
#

enters chat

#

assumes beliefs of other peeople

#

gets angry

old pebble
#

You are the one afraid of being gay lol

old pebble
#

That sounds pretty beta male to me

fresh pecan
#

whats your bench

#

bet its lower than mine

eternal gull
old pebble
#

MAN LIFT ROCK, STRONG MAN IN VILLAGE

eternal gull
old pebble
#

he does it all

fresh pecan
#

bro you weigh 135 lbs time to shut up

old pebble
#

He's ready to throw down in case anyone tells him he might like men

eternal gull
mystic forge
#

wtf has this become

eternal gull
#

comparing me to the goat

old pebble
#

We are truly being epicly owned

eternal gull
mystic forge
unborn cipher
#

I like you @eternal gull , in a very very straight way

unborn cipher
#

idk. I just wanted to be a part of this chat

#

I’m bored

old pebble
#

Super heterosexual really likes Andrew Tate

#

But not In a weird way

unborn cipher
#

lol. Ok good

old pebble
#

He will stare at the man for hours but it's normal behavior

unborn cipher
#

doesn’t sound like straight behavior

eternal gull
#

this doesnt sound like straight behavior

mystic forge
eternal gull
old pebble
#

It gets worse

#

I'm a woman.... With a girlfriend!!!!

eternal gull
#

I mean, i dont think any non soft straight man or woman would setup a pronouns page just for satire

old pebble
#

Burn me at the stake

unborn cipher
#

clogger
lol

mystic forge
eternal gull
old pebble
#

If he looks at it too long he might contract being gay from me......

old pebble
#

Really into the muscular men huh

unborn cipher
#

ok this Andrew Tate obsession is getting out of hand

old pebble
#

It's amazing kids actually think he's what they should aspire towards

mystic forge
#

the only good thing that came out of tate's existence is that I discovered Indila because of him lol

unborn cipher
#

India? wdym

mystic forge
#

well tate has a "theme song" associated with him
that songs singer is Indila, who is amazing

unborn cipher
#

O

#

@eternal gull to close the chat write
.close

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#

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tidal crane
trim joltBOT
tidal crane
#

This is what i worked out, but in the solution of the problem they let

#

delta = min {1, 3/2 epsilon}

#

I don’t really understand why it has to be the minimum of the those two and not just 3/2 epsilon?

whole coral
solid kilnBOT
#

chartbit

whole coral
#

Setting $\delta$ to be the minimum of both means that $|x|$ will be less that both of those values (1 and $\frac{3\epsilon}{2}$)

solid kilnBOT
#

chartbit

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coral viper
#

What number gives a result of −3 when 8 is subtracted from the quotient of the number and 5?

Im not really good with these kinds of word problems if someone could help me that would be great!

coral viper
#

As far as I know it has to start with -3=

#

And I think quotient is divide but idk how to apply that

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stable comet
#

What are the points for 3x^2-5x+1

trim joltBOT
stable comet
#

On a graph

#

Ik the vertex is 5/6,-13/12

#

This is the equation in vertex: 3(x-5/6)^2 -13/12

#

<@&286206848099549185>

tepid junco
#

set = 0

#

solve for x

stable comet
#

Hey

#

The vertex is correct right

#

I just need to find the other points on the graph all i have is the vertex

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#

@stable comet Has your question been resolved?

trim joltBOT
#

@stable comet Has your question been resolved?

stable comet
#

<@&286206848099549185>

cyan zinc
#

Electrify

stable comet
#

Yea

trim joltBOT
#

@stable comet Has your question been resolved?

#
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queen yarrow
#

Yo

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queen yarrow
#

Anyone knows how to prove this

#

Knowing

#

This is S

stoic iron
#

do the computation

queen yarrow
#

Like put my own values and try it?

#

Ok

stoic iron
#

well no for general values

#

put variables in w1 and w2

solid kilnBOT
queen yarrow
#

Lowkey my teacher probably over did it here

stoic iron
#

or if you know anything about how tranpose interacts with dot product then use that

queen yarrow
#

Is this even linear algebra

stoic iron
#

yes this is definitely linear algebra

queen yarrow
#

Lol

#

O I see

#

Is it this or am I dumb

#

I put w1 is 1 and w2 is 2

#

It gives same thing at the end so the equality is true I guess

#

Feels this is too simple and wrong

amber python
#

w1 and w2 are vectors

boreal dome
queen yarrow
#

But

#

I don’t know

#

The components

boreal dome
#

w1 et w2 sont des vecteurs

amber python
#

you should prove it in general

queen yarrow
#

So how do I put do I just put x and y and z

#

And then do it

amber python
#

just write w1 and w2 as two general vectors

boreal dome
#

$\begin{pmatrix} x \ y \end{pmatrix}$

solid kilnBOT
#

Herels

boreal dome
#

for example

amber python
#

say w1 = (x, y), w2 = (z, w)

queen yarrow
#

Oh also

#

Ok

#

I’ll do that

#

Brb

#

Is it this

#

Well whatever last question

#

Surely this is just bullshit?

#

Bro said derivative w and w is some orthogonal?

#

O I see

#

So w is = (cos Teta, sin teta)

#

We gotta show w times it’s derivative = 0

#

Can anyone confirm that’s it’s this

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#

@queen yarrow Has your question been resolved?

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wraith hinge
#

Linear equations grade 8

trim joltBOT
wraith hinge
#

,rotate

solid kilnBOT
wraith hinge
#

<@&286206848099549185>

#

<@&286206848099549185>

#

.close

trim joltBOT
#
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#
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random river
#

how do you work out if congruences are fulfilled?

random river
#

for example 13 = 124 (mod 37)

upbeat lynx
#

124 / 37 = 3 + 13 / 37 so it's 13 mod 37

stoic saddle
#

can you also do (13-124 )/ 37, which is -3 and show that since there is no remainder ?

upbeat lynx
#

not really good at this tbh but I believe a = b (mod k) is the same as a - b = 0 (mod k) so showing a - b has no remainder when divided by k should work

#

a = b (mod k) <=> a = mk + l and b = nk + l <=> a - b = (m - n)k + 0 <=> a - b = 0 (mod k)

I hope this reasoning is right

trim joltBOT
#

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vast goblet
#

hi

trim joltBOT
vast goblet
#

what is √ of 72164823845

split chasm
#

,calc sqrt(72164823845)

solid kilnBOT
#

Result:

2.6863511282965e+5
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#

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glacial kelp
#

help

trim joltBOT
glacial kelp
#

can someone quickly check my work on this?

convert the decimal number 257 to 8-bit unsigned binary

since 257 is larger than 8 bit
do i just chop off the MSB and make it 00000001? so 1 basically?

visual dome
#

well codeblocks says that this is the case

glacial kelp
#

ok, I tested with an online calculator and it did that, so just making sure because the calculator website looked older than my blood line, thanks

#

!solved

#

!close

#

idk how to close lol

#

.close

trim joltBOT
#
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wraith hinge
#

If 1/y-x;1/2y and 1/y-z are three consecutive terms of an arithmetic sequence prove that x, y and z are three consecutive terms of a geometric sequence

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#

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twin swan
#

if they are an arith seq then $\f{1}{y-x} + d = \f{1}{2y} \ \f{1}{2y} + d = \f{1}{y-z}$

#

rip

wraith hinge
#

no

#

wait

#

@twin swan

twin swan
#

reopen lool

#

yes

#

.reopen

wraith hinge
#

.reopen

trim joltBOT
#

twin swan
#

$hi$

#

ok texit is down whatever

#

i'll explain using words

wraith hinge
#

Okey

twin swan
#

basically you know 1/(2y) - 1/(y-x) = 1/(y-z) - 1/(2y)

wraith hinge
#

yes

twin swan
#

it comes from the fact that the differences in AP are constant

wraith hinge
#

$1$

twin swan
#

okay, so doing common denominator stuff

#

you can massage it into a form thats much nicer

wraith hinge
twin swan
#

arithmetic progression

#

aka arithmetic sequence

#

anyway this is what it boils down to

#

once you do all the simplifying

wraith hinge
#

yeah its like b²=a*c

twin swan
#

now i'll show they are a geometric sequence

#

let y = x*r, z = x*r^2

#

then the left side turns into x^2 r^2 and RHS turns into (x*r)^2

#

which is also x^2 r^2

#

that means it is a geometric sequence

twin swan
wraith hinge
#

i have a question

twin swan
#

ask

wraith hinge
#

where is the square from the y ?

twin swan
#

what do you mean

#

where does it come from?

wraith hinge
twin swan
#

that happens when simplifying

wraith hinge
#

Ok

twin swan
wraith hinge
twin swan
#

yes, r is the common ratio

#

that just proves x,y,z are in geometric progression

wraith hinge
#

ok isee

#

but u replace the z with r ?

twin swan
#

z is x*r^2

#

also known as y*r

wraith hinge
#

wait

#

y is x*r

#

and z is x*r²

#

?

twin swan
#

yes

#

thats the definition of a geometric sequence

wraith hinge
#

oh

#

then i need to replace the other unknown by the same unknown

#

?

twin swan
#

yeah

#

and just show it is all equal

wraith hinge
#

but its only for x y z or for the all fraction like 1/y-x;1/2y and 1/y-z

twin swan
#

you showed that the fraction being in AP implies xz = y^2

#

so now you show x,y,z is geometric

twin swan
wraith hinge
#

but wait

#

1/y-x is a1 for AP and y x and z is for GP ?

#

y-x is the a1 for GP ?

#

@twin swanhey

twin swan
#

yes 1/(y-x) was for AP

#

we showed that since it was AP, using the AP equations we got xz = y^2 and that only concerns x,y,z

#

and thats a geometric sequence

wraith hinge
#

but i need to find x y z or no ?

wraith hinge
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#

@wraith hinge Has your question been resolved?

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frail current
#
Friday, with each dinner being at one of his ten favorite restaurants.
(a) How many possibilities are there for Fred’s schedule of dinners for that Monday ```
frail current
#

can anyone explain this question for me?

restive drift
#

Is that the entire question? Only Monday?

#

for part a

#

cuz he only has 10 choices is it’s just Monday

frail current
#

theres a part b

#

but i wanna understand this part

#

@restive drift

restive drift
#

Am I seeing it correctly?

frail current
#

yes

restive drift
#

This would just be 10 if it’s only on Monday

frail current
#

what is the question asking though

#

oh snap

#

wtf

#

if he has 10 total favorite restaurants

#

to choose from for the first day

#

the number of possibilities for that day is 10

restive drift
#

Yes

frail current
#

why was this hard for me to comprehend the first time

#
through Friday, if Fred is willing to eat at the same restaurant more than once, but is
not willing to eat at the same place twice in a row (or more)?```
restive drift
#

It happens

#

What have you tried for this one?

frail current
#

since he cant eat back to back restuarants the following day will always be 9

#

10-9-10-9-10

restive drift
#

Yes but how did you get 10 for wed and fri

frail current
#

because after tuesday i can choose the same restuarant i chose on monday, same applied with the latter

restive drift
#

Yes but you can’t choose the restaurant you chose on Tuesday

frail current
#

yes

restive drift
#

You can go to Monday’s restaurant on Wednesday

#

But not the one you chose on Tuesday

frail current
#

oh snap so itll be 9 for both wed and friday then

restive drift
#

Yes

frail current
#

since i cant choose back to back days

restive drift
#

Yep

#

So what would the answer be

frail current
#

yeah i missed that case

restive drift
#

Just make sure to fully understand the problem before jumping in and you’ll be good

frail current
#

ty

#

@restive drift sorry i messed up for the first part

#

i didnt paste full question

restive drift
#

yw

frail current
#
through Friday, if Fred is not willing to eat at the same restaurant more than once?```
restive drift
#

No worries

frail current
#

this is the full question

restive drift
#

How would you do this one?

frail current
#

10-9-8-7-6

restive drift
#

Yep that’s correct

frail current
#

we just multiply those to get our solution

restive drift
#

Yep since we start off with 10 choices for day 1 and lose a choice a day

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#

@frail current Has your question been resolved?

#
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jovial sluice
#

Someone can help ?

trim joltBOT
jovial sluice
#

Here

#

This 17 and 20

#

Help

#

<@&286206848099549185>

#

.close

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jovial sluice
#

,reopen

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