oh check whether or not
#help-36
polar obsidian
so as we intuitvely understand we just prove that its not neccesarily transitive?
novel kettle
yes
polar obsidian
cool
glad plume
Can someone help me with this? My best friend randomly sent me this through messenger and i'm not much of an ai guy to ask it to AI.
9.246 ** 1.5 * sqrt(9.246) - 2(9.246) + 0,003484
final saddleBOT
Can someone help me with this? My best friend randomly sent me this through mess...
sly forum
the ** means power
sly forum
alr
final saddleBOT
If you are done with this channel, please mark your problem as solved by typing .close
final saddleBOT
final saddleBOT
Available help channel!
covert breach
Hii I'm just wondering if there's is anyway I could have done this easier
covert breach
My teacher told me to use
a^c = b^c
(a/b)^c = 1
But I didnt know to
orchid coral
My teacher told me to use
a^c = b^c
(a/b)^c = 1
But I didnt know to
Did you not know that that identity existed (except some values), or did you not know that that identity is to be used?
covert breach
Did you not know that that identity existed (except some values), or did you not...
I didnt know
I didnt know it existed and can be used
orchid coral
a^c = b^c is converted into (a/b)^c = 1 using basic rules of exponents.
a^c = b^c
=> a^c/b^c = 1
=> (a/b)^c = 1 (because m^x / n^x = (m/n)^x)
honest carbon
As long as b ≠ 0, b^c always has an inverse reciprocal
covert breach
a^c = b^c is converted into (a/b)^c = 1 using basic rules of exponents.
a^c = b^...
Yes
covert breach
As long as b ≠ 0, b^c always has an ~~inverse~~ reciprocal
Pls dont talk abt functions
I hate it
covert breach
Huh
orchid coral
As long as b ≠ 0, b^c always has an ~~inverse~~ reciprocal
As long as b ≠ 0, b^c always has an inverse a reciprocal.
covert breach
Idk
manic herald
Hii I'm just wondering if there's is anyway I could have done this easier
you can take the log of both sides as step 1
covert breach
Thank you
manic herald
,tex .log rules
soft zealotBOT
Tushar
covert breach
Yeah
meager flax
2+3(4-5)
covert breach
.close
final saddleBOT
honest carbon
Wow tex also has factoids too.
honest carbon
What are the list of tex's factoids?
manic herald
it doesn't have any
factoids are user-defined
I'm using this one by @vital crag https://github.com/riemann-discord/math-discord
final saddleBOT
Available help channel!
radiant igloo
?????
radiant igloo
!status
final saddleBOT
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
2
ionic venture
Is this a pattern problem?
azure shard
Is this a pattern problem?
prob smth abt sequences
ionic venture
Yeah
radiant igloo
logical reasoning problem!
timber leaf
I would first convert alphabetical letter into numbers respectively.
ionic venture
logical reasoning problem!
What have you tried doing with the letters?
A | 1
B | 2
C | 3
D | 4
E | 5
F | 6
G | 7
H | 8
I | 9
J | 10
K | 11
L | 12
M | 13
N | 14
O | 15
P | 16
Q | 17
R | 18
S | 19
T | 20
U | 21
V | 22
W | 23
X | 24
Y | 25
Z | 26
Try using this
timber leaf
Wall
radiant igloo
What have you tried doing with the letters?
already done all that stuff
already tried arithmetic plus small exponential patterns as well
azure shard
already tried arithmetic plus small exponential patterns as well
idk why the problem doesnt say if its a geometric or arithmetic sequence tbh
kinda frustrating
radiant igloo
C=3 k=11 11+3=14/2=7+2=9
whatttt
radiant igloo
idk why the problem doesnt say if its a geometric or arithmetic sequence tbh
"logical reasoning problem!"
omg
timber leaf
Try add 2 letters together Itsuki
azure shard
"logical reasoning problem!"
ig 💔
final saddleBOT
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
azure shard
bro
timber leaf
Delete the comment.
timber leaf
Delete all the working
timber leaf
You are doing Itsuki's working process
fiery comet
Ok?
radiant igloo
You are doing Itsuki's working process
in these types of questions there is no exam based logic so it was a valid idea
fiery comet
I kept 1 only
timber leaf
in these types of questions there is no exam based logic so it was a valid idea
The problem is he is solving everything for you
radiant igloo
The problem is he is solving everything for you
ig
final saddleBOT
fiery comet
The problem is he is solving everything for you
I have helped like 15-20 people only I am new helper
So i didn't knew
(well I knew but I didn't realise that I was doing whole(
final saddleBOT
Available help channel!
silent ruin
Whats 1+1 how to solvr
final saddleBOT
Whats 1+1 how to solvr
polar spruce
yea buddy just use a calc
silent ruin
I cant figure it out
polar spruce
,w 1+1
soft zealotBOT
silent ruin
Alr ty
polar spruce
do .close to close it
silent ruin
.close
final saddleBOT
tropic crest
Whats 1+1 how to solvr
<@&268886789983436800> troll
marble cedar
silent ruin
silent ruin
<@&268886789983436800> troll
Son
marble cedar
https://tenor.com/view/this-is-a-snitch-free-zone-jidon-adams-jidion-no-snitchin...
U arent banned yet
silent ruin
Yk what
tropic crest
U arent banned yet
which is a suprise
marble cedar
shadow hornet
Average pre-uni.
marble cedar
which is a suprise
Where mod
orchid coral
Average pre-uni.
Not really
silent ruin
<:banhammer:502230984771764244>
Chill
marble cedar
azure shard
Average pre-uni.
radiant igloo
uhhh
shadow hornet
Yeah that behaviour, lowkey banned.
silent ruin
Yeah that behaviour, lowkey banned.
What if i leave and then rejoin 24 hours later
marble cedar
shadow hornet
What if i leave and then rejoin 24 hours later
Do it then?
marble cedar
What if i leave and then rejoin 24 hours later
Mods are too pussy anyways to ban for more than a day
silent ruin
Mods are too pussy anyways to ban for more than a day
<@&268886789983436800>
shadow hornet
Beautiful language.
orchid coral
Whats 1+1 how to solvr
1 + 1 = 2 by definition
silent ruin
Uno reverse
shadow hornet
Swearing by the way.
marble cedar
<@&268886789983436800>
<@&268886789983436800>
radiant igloo
omg
orchid coral
lmao
quasi rapids
ok lads can we fucking chill
polar spruce
@silent ruin you had like 3 shots to divert the conversation and get the mods to ignore you
how the FUCK did you miss all of them
marble cedar
1 + 1 = 2 by definition
By definition?
silent ruin
<@1486061600111591644> you had like 3 shots to divert the conversation and get t...
My finger slipped
polar spruce
yea bro
shadow hornet
Dude.
orchid coral
By definition?
yes
polar spruce
@quasi rapids fulfill your mute quota ig
quasi rapids
<@&268886789983436800>
and what was this ping all about then
orchid coral
it's not something to prove
marble cedar
and what was this ping all about then
He is trolling
marble cedar
it's not something to prove
Average Pre-Uni
polar spruce
what a fucking dipshit am i rite
quasi rapids
you know what ill do this a different way
orchid coral
Average Pre-Uni
huh
quasi rapids
if anyone sends a message after mine im muting you
final saddleBOT
Available help channel!
thick echo
what are the "0x"s for, what do they mean and why are they there
final saddleBOT
what are the "0x"s for, what do they mean and why are they there
severe canyon
Well, what is the the coefficient of x³ in your given polynomial?
And the coefficient of x?
thick echo
0??
tawdry pike
what are the "0x"s for, what do they mean and why are they there
you wont be needing x^3 but for structural purpose and clarity, because you will be getting the same result after first subtraction
do you know how to perform long division for polynomials?
thick echo
yes but this was never explained before
adding random monomials into the dividend i mean
tawdry pike
yes but this was never explained before
adding random monomials into the dividen...
just for clarity, nonetheless you will be getting the same result when you continue subtraction
coral prawn
You're practicing an algorithm that gives you a polynomial Q such that Q(x)(x-3) = 6x^4 - 9x^2 + 18
Now it's true that 6x^4 - 9x^2 + 18 has no third degree term and that can be omitted, however Q(x) actually does have a third degree term because Q(x) needs to utilize its third degree term to produce 6x^4. So therefore you need to write 0x^3 because the result Q needs a third degree term even though your input polynomial doesn't have one
tawdry pike
so you know how to perform long division?
tawdry pike
You're practicing an algorithm that gives you a polynomial Q such that Q(x)(x-3)...
yeh this
thick echo
so you know how to perform long division?
yes obviously
tawdry pike
yes obviously
you can continue with or without the x^3
thick echo
ty for the answers btw
final saddleBOT
final saddleBOT
Available help channel!
left trail
For 14 to 17 is f(a)^k=x and y=b
final saddleBOT
For 14 to 17 is f(a)^k=x and y=b
tardy quartz
For 14 to 17 is f(a)^k=x and y=b
use the Bernoulli substitution $(v = y^{1-n})$.
soft zealotBOT
4ever
final saddleBOT
@left trail Has your question been resolved?
left trail
use the Bernoulli substitution $(v = y^{1-n})$.
Yes I know about that but what about the starting values they give
Say for 14 we have x =0 implies y=2. So does this mean f(0)^1/2=2
Or is it f(0)=2 and then based off that f(0)^1/2 = sqrt2
<@&286206848099549185>
tardy quartz
Or is it f(0)=2 and then based off that f(0)^1/2 = sqrt2
The second one is right. y = 2 when x = 0 just means $f(0) = 2$. Then based on that, $f(0)^{1/2} = \sqrt{2}$.
soft zealotBOT
4ever
white venture
If x=0 gives y=2 then f(0)=2
tardy quartz
Aight sleep timee
left trail
Ok thanks guys
white venture
!done
final saddleBOT
If you are done with this channel, please mark your problem as solved by typing .close
left trail
.solved
final saddleBOT
hazy bay
For 14 to 17 is f(a)^k=x and y=b
good question the 13
final saddleBOT
Available help channel!
left trail
I only have theorem 8.3 for dealing with linear first order equations. For 16 we end up having v'+(1/x)v =2x^3. But 1/x is not continuous on (-infinity,+infinity)
final saddleBOT
I only have theorem 8.3 for dealing with linear first order equations. For 16 we...
left trail
And based on theorem 8.3 I can't continue
final saddleBOT
@left trail Has your question been resolved?
left trail
<@&286206848099549185>
floral nova
You are solving an IVP on R and your theorem gives you a unique solution for every open subset of R away from 0. At the minimum you will need to use that Theorem anyway for most of the interval and you should hope that either that solution works at 0 too or looking at why that solution fails would give you some insight into what is going on at 0 to deal with it as a special case.
left trail
You are solving an IVP on R and your theorem gives you a unique solution for eve...
Well it's clear why it doesn't work 1/x is not continuous at 0
left trail
By away from 0 mean not at 0?
floral nova
Over an open interval not containing 0
floral nova
Well, the first step is to look at the solution everywhere else and hope it just works at 0
floral nova
When you have a solution that works everywhere except at finitely many points, usually one would hope that you can just plug in the hole
left trail
Ok I'm going to solve over those intervals and see what that leads
floral nova
You should pick up an intuition from Real Analysis that when you have a solution that works everywhere except a single point, that tells you a lot about the behavior. A little minuscule dot is not the problem after you have the unique solution everywhere else.
final saddleBOT
@left trail Has your question been resolved?
left trail
When you have a solution that works everywhere except at finitely many points, u...
@floral nova so I solved on (-infinity,0) and (0,infinity) and I obtained 2x^4/5-2/5x. But it isn't a hole
floral nova
I don't want to solve the problem myself, but that doesn't quite look right at a glance and it doesn't solve the differential equation when I just plug it into wolfram alpha.
left trail
Ok then I will resolve it.
final saddleBOT
@left trail Has your question been resolved?
fair gulch
final saddleBOT
fair gulch
Which are the first and second logs I need to check for y in my solution to make sure the solution works?
glossy zephyr
Assuming you mean these
fair gulch
Isn't that only one log equation?
glossy zephyr
Importantly, thats the original equation
fair gulch
?
final saddleBOT
final saddleBOT
Available help channel!
still eagle
Hi
severe canyon
You can't bring the x out! It's a HUGE and SERIOUS mistake
Because x is not a constant
still eagle
You can't bring the x out! It's a HUGE and SERIOUS mistake
So what do i do with the x ? i cant just ignore it
woven solstice
u get rid of the x by doing a u-sub
still eagle
its x times e
woven solstice
what function, when differentiated gives kx? for any constant k?
still eagle
im not sure
woven solstice
try substituting u = x^2
still eagle
Ok wait
loud sundial
still eagle
@woven solstice sorry i still cant
severe canyon
try substituting u = x^2
Do this
severe canyon
No
woven solstice
only take the x^2 part
severe canyon
u = x²
still eagle
i dont really ,now how to use U because i just follow integration formula rules
severe canyon
i dont really ,now how to use U because i just follow integration formula rules
Which rules? Do you have a list?
still eagle
yes
severe canyon
Which one?
still eagle
5th one
severe canyon
There's only one!
severe canyon
Do you know what an exponential function is? 🙈 😭
severe canyon
Mmhh
woven solstice
the exponential function has an f(x) value, and the other one is f'(x)
still eagle
2x
woven solstice
so, you have to make an 2x from that x you got
still eagle
no, you only take in consideration the x^2
but that is also part of the exponeital
woven solstice
the formula states that f(x) is the exponent of 'e', you just have to identify f(x), not the whole function
Why don't you try learning u-substitution? it's easier to understand, and can help you solve more exercices of this type
earnest tusk
can any one do this plss.
severe canyon
can any one do this plss.
!occupied
final saddleBOT
can any one do this plss.
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
still eagle
Why don't you try learning u-substitution? it's easier to understand, and can he...
i cant understand it
im notsure where this came from
honest carbon
huh? It's literally explained in the line right before it
still eagle
if u is x^2 shouldnt the equation be xe^u
still eagle
its x^2
severe canyon
Now replace xdx with what "you" found
candid pulsar
you didn't write a dx in the original image either
still eagle
???
severe canyon
They mean there's no dx here. Which, again, is a serious and huge mistake
candid pulsar
$\int x e^{x^2} dx$
soft zealotBOT
candid pulsar
this is your question
honest carbon
I didn't see the original question.
severe canyon
thats my question
Do you now see that it's different from yours, because of the dx missing?
still eagle
i guess
severe canyon
Wdym guess?
still eagle
Im not sure what dx means
severe canyon
I hope you're able to see whether something is absent or not
still eagle
i just need to ibntegrate xe^x^2
honest carbon
It's variable of integration
If there is no variable of integration, you simply can't integrate
still eagle
okay
candid pulsar
$\int f'(x) e^{f(x)} dx$
soft zealotBOT
candid pulsar
what would f(x) be assuming question is in this form
compare the part above the e^
vital jackal
topaz kite
How do you do geometry and drawing the shapes 😭
!occupied, sorry. please ask your question in an available channel like #help-39.
final saddleBOT
How do you do geometry and drawing the shapes 😭
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
bitter badger
!occupied, sorry. please ask your question in an available channel like <#908078...
Ok sorry
final saddleBOT
@still eagle Has your question been resolved?
timber plume
final saddleBOT
timber plume
how do we do this
tiny gorge
yea so in order to find x = cosh^-1(y), you must have y = cosh(x), right? So what possible values does the cosh function take on? (i.e. what values can y possibly be)
weak silo
what's the domain of cosh^-1 (t)?
weak silo
mmm not quite
do you wanna graph cosh^-1 (x) and see the domain
what's the domain here?
timber plume
1 to infinty
weak silo
1 to infinty
so the domain of cosh^-1 (x) is [1, infinity)
so what would ln(f(x)) need to be in cosh^-1 (ln(f(x)))
?
timber plume
im not that sure with ln functions
weak silo
okay think about this
in cosh^-1 (x), we need x to be [1, infinity)
so in cosh^-1 (ln(f(x))), what would we need ln(f(x)) to be?
in $$\cosh^{-1} (x)$$ we know that $x \in [1, \infty)$
so in $$\cosh^{-1} (\ln f(x))$$ what does $\ln f(x)$ need to be?
soft zealotBOT
Moonful
timber plume
ln(f(x)) = 1 to inf?
weak silo
yess
weak silo
ln(f(x)) = 1 to inf?
well you would say $\ln f(x) \geq 1$ or $\ln f(x) \in [1, \infty)$
soft zealotBOT
Moonful
weak silo
ln(f(x)) = 1 to inf?
but yes thats correct
weak silo
does that help you answer the first q?
weak silo
yep?
soft zealotBOT
Moonful
weak silo
what can you say about f(x) from this?
weak silo
yes this question
timber plume
**Moonful**
yep
weak silo
what can you say about f(x) from this?
timber plume
f(x) >=0 since log funcctions accept 0
timber plume
oh ok so its f(x)>=1
final saddleBOT
@timber plume Has your question been resolved?
vestal kestrel
You mind if I help you on this one?
timber plume
sure
vestal kestrel
Ok, so what is b?
vestal kestrel
f(x) has a range to it
The restriction is that ln(f(x))≥1
Since ln is a strictly increasing function, f(x)≥e
Makes sense?
vestal kestrel
ln(f(x)) is an increasing function as f(x) increases
So the minimum value of ln(f(x)) will be based on the minimum value of f(x)
vestal kestrel
Ask away
vestal kestrel
What are the options?
topaz kite
timber plume
vestal kestrel
So you know that a unit circle is the result of e^ix, right?
timber plume
e^ix graphs it on the unit circle, yes
this i got right
the complex roots are plotted inside the unit circle right? why is it wrong
vestal kestrel
No, its along the circumference of the circle
weak silo
<@547342841781944331>
Sorry I had to drive at the time. I have to go now, but I'm sure tzkken's got you!
vestal kestrel
For example, e^ix has a modulus of 1, so for a unit circle, its on the circumference
And the points traces the outline of the circle
timber plume
timber plume
Sorry I had to drive at the time. I have to go now, but I'm sure tzkken's got yo...
Thank you Moon, have a good one!
timber plume
i dont get these last 3 options
vestal kestrel
For circles we dont really talk about side lengths
vestal kestrel
And the radius would be?
vestal kestrel
Ok
timber plume
how do we know if one of the point lies on the positive real axis
i mean we can find it out if we plotted it but is there a shortcut
vestal kestrel
Or we can sub k=0
vestal kestrel
What are z1 and z5?
timber plume
they are in factorised form
vestal kestrel
As in, do you know their values?
vestal kestrel
Yup
vestal kestrel
How about z5?
timber plume
4e^[i(5pi/3)]
vestal kestrel
So what is the nature of these 2 roots?
vestal kestrel
Exactly
timber plume
but what does this tell about the coefficies of p(z)?
vestal kestrel
Well, do you know how quadratic coefficients are linked to its roots?
timber plume
hm I think I forgot
vestal kestrel
Let's say Ive got 2 roots a and b, for a quadratic x²+cx+d,
c=-(a+b) and d=ab
timber plume
yep I agree
vestal kestrel
So based on those roots, can you find the coefficients?
timber plume
hm one way I could go about that is expand p(z)
vestal kestrel
And by expanding, you're using those 2 formulae
timber plume
$p(z)=z^2-z(z_5)-z_1(z)+z_1(z_5)$
$p(4e^i(\frac{5pi}/{3}) )= (4e^i(\frac{5pi}/{3})^2-z(z_5)-4e^i(\frac{5pi}/{3}) (z)+4e^i(\frac{5pi}/{3}) (z_5)$
vestal kestrel
Yes
timber plume
so plug in z1 and z5?
vestal kestrel
Yes
soft zealotBOT
ø
vestal kestrel
You know de Moivre theorem?
timber plume
yes
vestal kestrel
Use that and simplify each coefficient
Focus on the formulae
The expansion may be a bit too much for you to tackle
timber plume
shadow hornet
That's the right one
timber plume
The expansion may be a bit too much for you to tackle
so instead of expanding p(z) we just use de moiveres formula
vestal kestrel
Yeah, along with the sum and product of roots
timber plume
and theres two statements, which one do we use
vestal kestrel
The polar form one may be easier for you
You do know how to convert between polar and exponential forms, right?
timber plume
theres two polar forms
timber plume
^
timber plume
You know de Moivre theorem?
ik what it is but how do we use it with our question?
vestal kestrel
ik what it is but how do we use it with our question?
The sum of roots, we are going to use the conversion from exponential to polar
final saddleBOT
@timber plume Has your question been resolved?
vestal kestrel
The sum of roots, we are going to use the conversion from exponential to polar
Do you get it?
vestal kestrel
Yeah
vestal kestrel
Yes
vestal kestrel
I meant the exponential to polar form conversion
timber plume
ohh
how does the trig polar form tell us about the nature of the coefficients?
or if we simplify it, it will give us a real number or a purely imaginary number?
vestal kestrel
For the sum, you add, then you can tell if its real or imaginary
For product, leave it as expo, its simpler
main mirage
or if we simplify it, it will give us a real number or a purely imaginary number...
Yes
Well
main mirage
how does the trig polar form tell us about the nature of the coefficients?
So you need to use De Moivre's Theorem to simplify the coefficients of the polynomial
Well not even De Moivres, you really just need to use the trig form of a complex number, as mentioned.
main mirage
**ø**
To help you out a bit, you might want to rewrite this as:
||p(z) = z^2 - (z5 + z1)z + (z1)(z5)||
timber plume
vestal kestrel
The 8 is supposed to be an e?
timber plume
Is this how u convert from exponential to trig form
main mirage
No - you need an e somewhere
timber plume
vestal kestrel
Remove the e from the polar form
main mirage
You don't need the e anymore
vestal kestrel
Then put z5 in polar
main mirage
Exponential to trig form is all about converting e^(it) into cos(t) + isin(t); so the e itself gets removed.
timber plume
In polar?
pseudo estuary
A bag contains 6 blue sweets and (n) red sweets. There are more than 10 sweets in total. Fred eats two sweets at random. If the probability of eating one blue and one red is 1/2, how many red sweets (n) were in the bag?
vestal kestrel
You know what z5 is in expo form?
crimson zenith
A bag contains 6 blue sweets and (n) red sweets. There are more than 10 sweets i...
<@&268886789983436800> could you ask him to delete this? its really spammy
crimson zenith
Don’t I need to simplify
what's the problem?
timber plume
^
timber plume
^
crimson zenith
idk sorry
timber plume
main mirage
main mirage
Good! So, what's the polynomial then?
main mirage
why did we add z1 and z5 together?
Remember, your main goal is to find what p(z) is
And this is what you got for p(z)
final saddleBOT
final saddleBOT
Available help channel!
nocturne peak
I have a linear algebra question:
leaden moon
I have a linear algebra question:
don't delete the original message
nocturne peak
in my course they discussed this
leaden moon
don't delete the original message
@nocturne peak
nocturne peak
don't delete the original message
it was the wrong exercise
nocturne peak
what is going on
tropic crest
!msgdel
final saddleBOT
The original post of this help channel has been deleted, and it will abruptly close and possibly lock. (This is irreversible.) Please claim a new channel, and don't delete the first message of any future channel you claim.
leaden moon
in my course they discussed this
secondly you should send your question as your first message when you send in a new channel
leaden moon
can I ask now?
try sending your question as your 1st message in #help-6 for example
nocturne peak
honestly
I feel like this doesnt have to be this complicated
I mean the help channel is open and I posted my question
but now it is lost in this convo
royal gust
No the help channel is closed
nocturne peak
bleak granite
it's not closed yet, but it will
you're right, this doesn't have to be complicated
nocturne peak
but ok then it makes sense
leaden moon
it's not closed yet, but it will
it's already closed
bleak granite
move to help-29 or smthn and post ur question again
royal gust
I agree with you that it shouldn't be like this, but yeah it's what's programmed
leaden moon
.
leaden moon
I agree with you that it shouldn't be like this, but yeah it's what's programmed
idk why they programmed like this
timber leaf
Why Kaynex pfp looks like my friend's dog avatar
chilly granite
idk why they programmed like this
it is done so so users dont just open a help channel and then delete thier msg.
timber leaf
Hmm 
leaden moon
it is done so so users dont just open a help channel and then delete thier msg.
secondly i actually requested to remove the name when it is closed, but it's denied
i think you didn't join the server when i requested that
chilly granite
secondly i actually requested to remove the name when it is closed, but it's den...
its so ppl cant /reopen if need be i assume.
leaden moon
its so ppl cant /reopen if need be i assume.
but like it should signify that the channel is closed or smth
yk what i mean?
tropic crest
but like it should signify that the channel is closed or smth
#help-36 message this did specify that its closed
leaden moon
https://discord.com/channels/268882317391429632/908076393198419988/1508465767035...
ik
tropic crest
unless your saying that the name should be help-xx (closed) | <name>
in that case you could suggest it in #『bot-and-website』
final saddleBOT
Available help channel!
real patio
Pls help
fiery comet
I think you should go to physics discord
heady portal
Looks like a physics ques 
heady portal
Out of my league i guess
final saddleBOT
Pls help
Please don't repeatedly close and claim a new channel with the exact same question. This erases all previous progress made towards your problem and is confusing for helpers, making it more difficult to help you. Please be patient, even if your channel has not received much attention.
real patio
.close
final saddleBOT
real patio
.close
tropic crest
also i said to move to discord.gg/physics people might not be able to help here
tropic crest
They said it is a math question
wait, who are "they"
real patio
The whole freaking server
heady portal
Isn't this ques from quantum mechanics
tropic crest
So where can I get help
ideally the physics server
fiery comet
The whole freaking server
But 66k people are offline
tropic crest
The whole freaking server
... which server? here?
real patio
.CLOSE
heady portal
Chill it's closed now
real patio
.close
real patio
Oke
final saddleBOT
Available help channel!
honest widget
final saddleBOT
honest widget
.rotate
soft zealotBOT
final saddleBOT
@honest widget Has your question been resolved?
stoic temple
final saddleBOT
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
If you are done with this channel, please mark your problem as solved by typing .close
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hidden apex
i need to prove the limit using epsilon delta formal definition
final saddleBOT
i need to prove the limit using epsilon delta formal definition
hidden apex
and im not sure if when doing the formal definition, | ( sin(x) x^2 +6 )/3| < epsilon and |x-0| < delta
or can i break down , sinx , x^2 +6, and the 3, and then do -1 <=|sin(x) <= 1
icy glacier
Wdym break it down? But yes using -1<=sin(x)<=1 is a good idea
hidden apex
Wdym break it down? But yes using -1<=sin(x)<=1 is a good idea
well doing 3 limits, lim x->0 3, lim x-> x^2 +6, and lim x->0 sin(x)
and just solve 3 and x^2+6,
3, and 6
and then finally apply theorem on sin(x)
icy glacier
No not what you are asked to do
You need to find the value of delta such that the definition is fullfilled
icy glacier
Sure?
hidden apex
ill try to do it like that
final saddleBOT
@hidden apex Has your question been resolved?
hidden apex
Sure?
if you are still there, got a question , while solving this
|sin(x)| < 3e/( x^2+6) , and im not sure what do about the sin x
icy glacier
-1<=sin(x)<=1
hidden apex
wb epsilon ?
icy glacier
? You should pick your delta as a function of epsilon (might be easier picking it as minimum of a constant and as a function of epsilon though)
hidden apex
you mean that epsilon is determined and i should just proceed to this -1<=sin(x)<=1?
icy glacier
No?
Check your definition
You have to prove for all epsilon>0 that there exists a delta>0 such that…
hidden apex
im confused but ill recheck stuff
hidden apex
.close
tranquil pine
final saddleBOT
tranquil pine
my answer is x = 0, x = -195
but i can't get a negative answer
or zero
so is this problem incorrect?
or am i doing it wrong
uneven ruin
my answer is x = 0, x = -195
this is wrong
youre probably doing it wrong
use pythagoras and remember distance cant be negative
merry temple
is this channel free?
uneven ruin
no
merry temple
ok thanks
final saddleBOT
@tranquil pine Has your question been resolved?
midnight coyote
I can't seem to be able to solve this, what would be your approach?
final saddleBOT
I can't seem to be able to solve this, what would be your approach?
fallow zinc
find the distance equations and solve probably
midnight coyote
what are the distance equations? I dont do physics so I'm unsure
fallow zinc
x=vt+x_0 for displacement x, speed v, and time t.
midnight coyote
I am not going lie, I'm slightly clueless here. Could you put that into context of one of the people?
fallow zinc
Laura travels at speed v and starts at x=s
midnight coyote
what do you mean by x_0?
fallow zinc
initial displacement.
midnight coyote
thanks
final saddleBOT
final saddleBOT
@tranquil pine Has your question been resolved?
final saddleBOT
final saddleBOT
Available help channel!
analog fiber
I know I am not supposed to ask physics
final saddleBOT
I know I am not supposed to ask physics
analog fiber
This is what I got so far
Not sure if I am heading right direction,
I already find normal force
For system 1
I am here to make sure that I am heading to right direction so I don't have to redo everything
final saddleBOT
@analog fiber Has your question been resolved?
analog fiber
<@&286206848099549185>
final saddleBOT
@analog fiber Has your question been resolved?
final saddleBOT
@analog fiber Has your question been resolved?
burnt topaz
This should go to the physics server in #old-network
analog fiber
Ahh I did
analog fiber
This should go to the physics server in <#406129911992942593>
But no one is alive
final saddleBOT
@analog fiber Has your question been resolved?
final saddleBOT
final saddleBOT
Available help channel!
tranquil pine
who knows how much pecent is 25min from and hour
final saddleBOT
who knows how much pecent is 25min from and hour
sharp apex
.close
final saddleBOT
final saddleBOT
Available help channel!
tranquil pine
do number after the decimal count as digits
final saddleBOT
do number after the decimal count as digits
@tranquil pine Has your question been resolved?
Available help channel!
digital elk
$1. 3ax^{2} +9x - \frac {5x^{2}}{4} - 7x =\
2. \left(3a- \frac {5} {4}\right)x^{2} + \left(9-7\right)x =\
3. \left(3a- \frac {5}{4}\right)x^{2} + 2x \implies \
4. 3a - \frac {5}{4} = 0 =\
5. 3a = \frac {5}{4} =\
\frac {3a}{3} = \frac {\frac {5}{4}}{3} \implies \
\text {fin. }a = \frac {5}{12}$
final saddleBOT
$1. 3ax^{2} +9x - \frac {5x^{2}}{4} - 7x =\\
2. \left(3a- \frac {5} {4}\right)x^...
digital elk
Confused with step 4
soft zealotBOT
Ploombie
lavish fossil
There might be some other statement like coefficient of x² is 0 or something like that
digital elk
There might be some other statement like coefficient of x² is 0 or something lik...
Yes that!
It says that
Why??
Why do they do that?
lavish fossil
Why do they do that?
Because it might be umm... included in the question...
digital elk
Wait but i see people putting 0 as an answer to a question all the time!
And then finding the variables using that 0
Is it not the same case here?
lavish fossil
What was the actual problem given?
digital elk
It said that find a such that the simplified version of this algebraic expression will be only 1 term
lavish fossil
Yeah. So best we can do is remove the x² term
digital elk
And we can use that all the time?
lavish fossil
(3a-5/4)x²+2x will have only one term left that is 2x when we take 3a-5/4=0
granite yoke
I realize that you need to use the fundamental theorem of calculus to solve this, but i do not understand how the transition i marked is possible. Why is t only evaluated as 2x and not 4?
final saddleBOT
I realize that you need to use the fundamental theorem of calculus to solve this...
steady grotto
t was evaluated as 4 too but this will result in a constant, so when you differentiate it becomes 0, that's why only the 2x bit appears in the end
granite yoke
so what happend to the evaluation of 4?
as i see it d/dx and int are inverse, so they get rid of eachother which means the integrand is left to be evaluated at the two boundaries, correct?
steady grotto
yes
granite yoke
so you end up with sqrt(ln(1+e*t)) | (4 and 2x)
steady grotto
you can see what happened in the second-to-last line, substitute 2x by 4. you see that (4)' gives 0, that's why it's gone
granite yoke
ahh ok i understand that part
next question, where is the chain rule coming from here? why is there (2x)'?
cause didnt the d/dx inverse the int, which means both those operators are gone, so why is there yet another derivative in the equation?
dawn steppe
next question, where is the chain rule coming from here? why is there (2x)'?
,tex $\frac{d}{dx}\int^{g(x)}_a f'(x)dx=\frac{d}{dx}(f(g(x))+C)$
soft zealotBOT
Brun。
dawn steppe
you are correct in saying that d/dx gets rid of the integral, but it still has to evaluate the primitive, since that's a function in its own right in this case (2x), the chain rule pops up
final saddleBOT
final saddleBOT
Available help channel!
stiff bolt
final saddleBOT
stiff bolt
How in the first step following the substitution is (-t) replaced by (-x) when it was stated -t=x?
final saddleBOT
@stiff bolt Has your question been resolved?
main nymph
why is the half circle used in this lab?
final saddleBOT
why is the half circle used in this lab?
@main nymph Has your question been resolved?
cobalt dew
hi how can i solve this?
final saddleBOT
hi how can i solve this?
cobalt dew
is 1 equal to the money that omar has?
astral ice
1 is 100%
cobalt dew
oh ok i see. do i apply 1 when i dont know the exact value?
cobalt dew
hi how can i solve this type of question?
final saddleBOT
hi how can i solve this type of question?
jade fable
Yeee
jade fable
Yes sth went wrong in my calculation
How I calculate it? How should I approach to it?
dense minnow
You added up the denominator incorrectly
jade fable
You added up the denominator incorrectly
I have noticed it
dense minnow
Wait, maybe I did 💀
jade fable
Wait, maybe I did 💀
I don’t know but I know there’s definitely sth wrong in the calculation
dense minnow
No, that's fine
jade fable
Okay
dense minnow
The last part
To turn 0.01089 into 1089, you have to multiply by 10^5
So you must multiply the numerator by 10^5 too
Which gives 90 not 0.09
jade fable
To turn 0.01089 into 1089, you have to multiply by 10^5
i thought i could just cancel out those 0s
let me give you an example
also if there's sth wrong in grammar, please correct it
dense minnow
wrong with my grammar*
jade fable
thank you
here's the example
example of what i have done in the calculation
the bottom is correct, those two sides are equivalent
let me check the top
dense minnow
There's no such thing as cancelling
jade fable
really
dense minnow
There is multiplying the numerator and the denominator by the same thing
In the bottom one, you multiplied the numerator and the denominator by 10
jade fable
In the bottom one, you multiplied the numerator and the denominator by 10
yes in other words i have "cancel out those 0s on the numerator and denominator"
dense minnow
In the top one you multiplied the numerator by 10^2, but the denominator by 10^5, so they are not the same.
dense minnow
If you really want to think of it in terms of cancelling zeroes, which I strongly advise you not to do, then in the top one, you are cancelling out the zeroes, but NOT the decimal point, so you should have ended up with 1.089 in the denominator
jade fable
If you really want to think of it in terms of cancelling zeroes, which I strongl...
got you, its such a bad habit that i've adapted from my science teacher
i will never use the trick again
i think i will just recalculate it and practice makes perfect
its solved, thank you so much Lunasong the Supergay
dense minnow
One thing you can use is that moving the decimal point to the right by n position means multiply by 10^n
dense minnow
So in the bottom one, you moved it up by 1 positiom to get 09/00.2 which is 9/0.2
And in the top one, you can move it up by 2 positions, so you end up with 000.09/001.089 which is 0.09/1.089
But you always need to keep it mind that what you are actually doing is multiplying the numerator and denominator by the same power of 10
jade fable
got you
jade fable
So in the bottom one, you moved it up by 1 positiom to get 09/00.2 which is 9/0....
it works so well, i should take this to my note
thank you so much
dense minnow
👍
jade fable
.close
bitter root
How do I show that the equation 3e^x+x^2y+y^3=4 crosses the line y=x?
drowsy widget
Is there an e in 3e^x?
bitter root
yeah
the method of taking 3e^x+x^2y+y^3-4=x creates a too difficult equation to solve
I know that the point (0,1) in the equation has a tangent with the equation y=1-x and therefore negative slope
dense minnow
Do you know intermediate value theorem?
bitter root
yeah
bitter root
do you mean 3e^x+x^2y+y^3-4=x?
dense minnow
No
All points on the line y = x are of the form (x,x), now this will also be a point on the curve 3e^x + x^2y + y^3 = 4 if 3e^x + x^2 x + x^3 = 4
It has to satisfy the equation when you replace y with x
bitter root
okay
dense minnow
Are you happy w that? I don't want to move on unless you are
bitter root
yeah I understand that
dense minnow
Okay, now 3e^x + x^3 + x^3 = 4 can be rewritten as 3e^x + 2x^3 - 4 = 0
So, we want to show that f(x) = 3e^x + 2x^3 - 4 has a root
And you can do that using the intermediate value theorem
You don't actually need to find the root
Just show it exists
bitter root
Then I need to find a point such that y has negative value in (x,y)?
dense minnow
I don't understand what you mean
You need to find a point where f(x) is negative and a point where f(x) is positive, then apply IVT on that interval
bitter root
so that the curve goes from positive to negative
dense minnow
Yeah, of from negative to positive
bitter root
the hard part is to algebraically find such a point where f(x) is negative
bitter root
it will only be approximately, and I dont know if thats good enough
dense minnow
What do you mean?
bitter root
to find a value where f(x) is negative, I could just argue that it must be negative
dense minnow
You can choose an x value and work out what f(x) is
And see that it's negative
Idk what the issue is
bitter root
yeah, its just I cant just calculate f(x) from it directly
it contains both y and x in the equation 3e^x+x^2y+y^3-4
dense minnow
No
dense minnow
So, we want to show that f(x) = 3e^x + 2x^3 - 4 has a root
f(x) is this
bitter root
idk how you got that
dense minnow
Read the whole conversation again
Because it came from the equation you agreed is what we have to solve
tranquil pine
How do I even determine x and y
final saddleBOT
How do I even determine x and y
final tangle
apply sec-sec theorem
apply intersection chords theorem
(or more generally power of a point)
solve the system of equations
tranquil pine
well I tried x(5.2+x) = 1(y+1) and 3.6x = 1y but that doesnt work
final tangle
those are the two equations you're starting with
solve the system of equations
using something like substitution to rid yourself of one of the variables
since you have y = 3.6x
for your second equation
it would be quite convenient to sub that into the first
rain compass
there's a lot of solutions to this
final saddleBOT
Available help channel!
jade fable
i have a question
final saddleBOT
i have a question
jade fable
if event A and event B are not related
jade fable
if event A and event B are not related
emmm sth wrong in my grammar, can someone fix it first
astral ice
your grammar is fine
rain compass
smth wrong with my grammar
jade fable
alright
if event A and event B are not related, P(A)=1/2, P(AUB)=2/3 then P(B|A)=?
okay so what is P(AUB)?
that mean event A and event B both happens?
rain compass
the probability of A or B happening
rain compass
where or is either A, B, or both
jade fable
well, ive made a equation to find the P(B) which led me to a wrong answer
let me show you and i wanna know where's wrong in my equation
sorry for my handwriting
its wrong right
rain compass
have you heard of bayes' theorem?
jade fable
im quite familiar with it
can i use the adverb quite in here?
rain compass
yes you can
jade fable
thank you
rain compass
and you can also use bayes' to solve this problem i believe
jade fable
okay, let me redo it then
thank you
in this case P(B) will be equals to P(B|A), right?
rain compass
your firs equation is correct
if these events are mutually exclusive
do they say anything about that?
cedar ivy
emmm sth wrong in my grammar, can someone fix it first
Role-playing hard on the name
jade fable
if these events are mutually exclusive
"mutually exclusive" means those two events has no intersection right?
they are independence