#help-36

1 messages · Page 108 of 1

tired knot
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tyty

granite tapir
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.close

final saddleBOT
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final saddleBOT
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heavy grove
#

37, how are these equal?

final saddleBOT
warm ether
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isnt that what it asks you

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youre the one showing how theyre equal

heavy grove
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But I can’t

heavy grove
warm ether
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what do your derivatives give

heavy grove
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I get 1/(x+1)^2 and 1/x+1

solemn igloo
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try chain and exponent rules

heavy grove
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💀

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I made a mistake

rocky tusk
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indeed

heavy grove
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We all good

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Thanks

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Wait in the second part how does it not contradict if

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If they are equal the only variation in the functions can be a constant C

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And I don’t see how a constant is the different between them

pliant shore
soft zealotBOT
pliant shore
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Just add 1

heavy grove
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But is that a constant

pliant shore
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Yes, (x + 1)/(x + 1) = 1

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1 is a constant cause it's just a number

heavy grove
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Just seems iffy

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Yeah

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Yeah alr

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Thanks

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pliant shore
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No worries

final saddleBOT
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tranquil pine
final saddleBOT
tranquil pine
#

I want to know how i could solve this

rocky tusk
inland kettle
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"while escaping superman" opencry

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whoever made this has a great sense of humor

tranquil pine
rocky tusk
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well do you know the kinematic equations

tranquil pine
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ofc basic

tranquil pine
rocky tusk
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so what would the equation for the position of the money bag be

tranquil pine
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uh idk i can't make out the values of acceleration and stuff if you know what i mean

rocky tusk
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well it’s a projectile

unreal topaz
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Use position vector with range

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Yes projectile motion

rocky tusk
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so it will have no horizontal acceleration but the vertical acceleration will be gravity

unreal topaz
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It is physics not maths

rocky tusk
tranquil pine
unreal topaz
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Yup it is 11th projectile

rocky tusk
unreal topaz
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If you are from India

tranquil pine
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can you solve it pls

rocky tusk
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!noans

final saddleBOT
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The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

unreal topaz
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No but we can help u

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!noans

final saddleBOT
#

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

tranquil pine
rocky tusk
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are you

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then you should know

tranquil pine
tranquil pine
rocky tusk
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💀

unreal topaz
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Use range formula

tranquil pine
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so what is the first step

rocky tusk
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i asked you a question

unreal topaz
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Look it up in ur book

tranquil pine
rocky tusk
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what’s the position function

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of the money bag

unreal topaz
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And then use

rocky tusk
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you didn’t answer

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you decided to ask for the answer

unreal topaz
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Then divide displacement by vel to get time

tranquil pine
rocky tusk
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x=xo+vot+1/2at^2

tranquil pine
rocky tusk
tranquil pine
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i told you

rocky tusk
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this is what you have to use

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x is final position

tranquil pine
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i dont have time and acceleration

rocky tusk
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you have acceleration

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it’s a projectile

tranquil pine
rocky tusk
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gravity🤝🏻

tranquil pine
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oh you mean gravity?

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kk

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whats o?

tranquil pine
rocky tusk
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it’s supposed to be a subscript

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for initial

tranquil pine
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..

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kk

rocky tusk
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naught

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you don’t need xo

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in this problem

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you could just do deltax

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which is the same as x-xo

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either will be zero

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depending on how you define your coordinate system

tranquil pine
rocky tusk
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bruh

tranquil pine
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its totally out of my league

rocky tusk
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💀

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no it’s not

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i promise

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i mean

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is down positive or negative

tranquil pine
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I need some sleep man

rocky tusk
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where is position=0

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🤷🏼‍♂️

tranquil pine
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can you give me a step by step procedure how i can do this

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i will learn the concept and solve it

rocky tusk
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you’re not even following what i’m telling you to do

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so

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you need to find the vertical position function

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of the money bag

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voy=vosintheta

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a=-g

tranquil pine
tranquil pine
rocky tusk
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we’re defining down to be negative but

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if you want

rocky tusk
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you could define down to be positive

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and make a=g

tranquil pine
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you mean vy = sinx?

rocky tusk
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this would just change the sign for

rocky tusk
tranquil pine
rocky tusk
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the initial velocity in the vertical direction is the initial velocity times the sine of theta

rocky tusk
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👍🏻

tranquil pine
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and then we find the time and give the answer right?

rocky tusk
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well you need to know if superman gets there first

tranquil pine
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i think tht is easy

rocky tusk
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yea so how would you do it

tranquil pine
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bye

rocky tusk
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💀

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bro

tranquil pine
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.close

final saddleBOT
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clever hamlet
rocky tusk
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for the position function of the money bag?

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it’s y=voyt+1/2 gt^2

clever hamlet
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Yes we’ll you typed initial velocity twice

rocky tusk
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yes

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because

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we’re taking the vertical position function

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so we need the vertical component

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of initial velocity

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it has components in both the x and y direction

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the x component is irrelevant to the vertical position

clever hamlet
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Yes I understand that

rocky tusk
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ok so what’s the problem

clever hamlet
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In your explanation

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You say initial velocity = initial velocity times the sien of theta

rocky tusk
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no

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i said initial velocity in the vertical direction

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read

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aka

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vertical component

clever hamlet
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Oh I see

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Yeah ur right I completely misinterpreted what your wrote

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Ty

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I understand at and it now

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.close

rocky tusk
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the channel wasn’t open

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.close

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see

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already closed

clever hamlet
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Oh ok well then bye

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drifting cosmos
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tranquil pine
#

For the Wronskian $Wy_1,,y_2$ how exactly does $\ds W'y_1,, y_2 = \mat[v]{ y_1 & y_2 \ y_1'' &y_2''}$ hold

soft zealotBOT
tranquil pine
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i might be conceptualising this wrongly

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because like

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what i would expect instead is

soft zealotBOT
worldly vale
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Differentiate y1y2' - y1'y2?

tranquil pine
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right, so you get [\8{y_1'y_2' + y_1y_2''} - \8{y_1'' y_2 + y_1' y_2'} = y_1y_2'' - y_1'' y_2] right lmao. i didn't actually expect you'd need to actually differentiate the thing to retreieve the above. I thought it was like some weird substitution idk

soft zealotBOT
tranquil pine
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anyways thanks

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worldly vale
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Yeah well like not rly any other way around it lol

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blazing breach
#

is it possible to tile a square with noncongruent right isosceles triangles?

blazing breach
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how so?

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well i guess you can use an infinite number of them

vital surge
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oh i meant a finite construction is also possible*

vital surge
blazing breach
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ahh thats cool

vital surge
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is very interesting indeed 🤔

vital surge
blazing breach
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yea

vital surge
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oh that's fun

final saddleBOT
#

@blazing breach Has your question been resolved?

neon slate
# blazing breach yea

https://youtu.be/4HHUGnHcDQw?si=D_wStOJ78xOVJEg0&t=382
if you're curious about tiling stuff, i highly recommend to check out this story (starting at 6:20 in this video) about some fun and interesting tiling discoveries from last year : )

Quanta Magazine’s mathematics coverage in 2023 included landmark results in Ramsey theory and a remarkably simple aperiodic tile capped a year of mathematical delight and discovery.

Read about more math breakthroughs from this year at Quanta Magazine: https://www.quantamagazine.org/the-biggest-discoveries-in-math-in-2023-20231222/

00:05 Ramse...

▶ Play video
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heavy laurel
#

Can someone help me with these problems?

final saddleBOT
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@heavy laurel Has your question been resolved?

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velvet saffron
#

in this this system of equations:

final saddleBOT
velvet saffron
#

$$ \left{\begin{matrix}
I. 2x+3y = a\
II. \ bx+12y = 100
\end{matrix}\right.$$

soft zealotBOT
#

eitiel

velvet saffron
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find a and b given this set of equations have an infinite solutions

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how do I start? infinite soulutions means I and II are equal to each other right? cause they are the same equation

wet warren
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Yeah
You might think of it as the second equation is a multiple of the first equation

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Like here you can divide 12/3 to find the factor of multiplication between the two equations

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Which is 4

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Then by that you would be able to get a & b

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@velvet saffron understandable?

velvet saffron
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im trying hold on

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ok a is easy 100/4 = 25

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what about b tho?

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@wet warren

final saddleBOT
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@velvet saffron Has your question been resolved?

velvet saffron
#

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tranquil pine
#

Just started learning about limits and continuity, found this to be slightly confusing:

tranquil pine
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for lim f(x) as x -> 3...

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in the video it's said that the function is continuous.

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but the function itself is not continuous correct?

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only the part for where x approaches 3 the function is continuous.

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please correct me where I'm wrong.

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Because I did a quick search to understand what a continuous function is and what I got was a function that doesn't show breaks or disconnects/leaps.

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which to me clearly isn't that.

static plinth
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if we look at the function near x=3, is there any holes or discontinuities?

tranquil pine
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Nope.

static plinth
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that would imply that at x=3 the function is continuous

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but that doesn’t necessarily mean that it is continuous for all other numbers

tranquil pine
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Perfect that's what I thought as I said but had to confirm, sorry to waste your time. Thank you so much 🙏

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You've helped me before as well, really appreciate your patience btw lol.

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tranquil pine
#

im just a bit confused regarding the definition of homogeneity for ODEs. As far as I know there are three "definitions" (ill consider first order here)

1- if for y' + p(t)y = g(t), we have g(t) = 0

2- if for y' = f(t,y) we can have f(t,y) = f(y/t) = f(u)

3- if for y' = f(t,y) we have f(kt, ky) = k^n f(t,y)

tranquil pine
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i am curious if those all are equivalent?

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or are describing different things

final saddleBOT
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@tranquil pine Has your question been resolved?

cyan kayak
#

If 1 and 2 are precisely the same then f(t, y) = f(y/t) implies that p(t)y - g(t) = f(y/t) which would demand that p(t) = 1/t and g(t) = 0. But clearly we have more complicated homogeneous ODEs than just this one. So 1 and 2 are incompatible in general except in the one specific case.

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Similarly 3 and 2 are incompatible.

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I would imagine that these are describing 3 different senses of homogeneous, rather than 3 facets of one larger sense.

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However, I couldn't swear to it. I do know that this was never brought up in my particular ODE class.

tranquil pine
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with the different ways of mentioning it like here

cyan kayak
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Obviously they mentioned homogeneous itself many times, but I took the different usages to be just the homogeneous case of whatever particular solution case we were working on

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It is interesting to think that they might be deeply related concepts, but I do not think they are

tranquil pine
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alright so i guess the question becomes what exactly do you consider the "homogenous case" of some solution

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i mean surely there is some sort of relevance to the word "homogenous" maybe

cyan kayak
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Unfortunately, that's not something I'm equipped to answer, I took the engineering ODE class. 😦

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I just learned homogeneous as the "nice and easy to solve" case lol

tranquil pine
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hmmm

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seems like the term itself is totally arbitrary in that case then. Well, I will let this stay open for further input from others I suppose

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#

@tranquil pine Has your question been resolved?

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dim brook
#

I do not know after I take three derivatives of YP, and the outcome is not same as the equation in red circle.

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shell panther
#

How do u solve q1 and 2

final saddleBOT
silver roost
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Do you know the period of sinx

shell panther
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Yea

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Is it 2pi/1/2

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@silver roost

steep tendon
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yea 2pi/(1/2)

shell panther
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So it’s D

steep tendon
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yes

shell panther
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I don’t rly understand q2

steep tendon
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do u know which ones are definitly correct/definitly incorrect?

shell panther
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Well I think A and B are def incorrect

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And I Think E is correct

steep tendon
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so CDE only has 1 correct or none, AB is the same

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now A and B you can determine with the amplitude

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and CDE u can determine by finding when sin(2pit/12-pi/2) is largest

shell panther
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Or does phase shift only change the graph function

steep tendon
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yea u need the phase shift because the time

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it will move the graph pi/2 to the right

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wait not pi/2

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it will move it x amount right where 2pit/12 = pi/2

shell panther
#

Alright

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So is it A and C

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@steep tendon

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alpine wind
#

am I the only one whose brain can't seem to comprehend this problem?

alpine wind
#

"is it likely that the guaranteed condition is verified", I mean I'm fucking looking at test data that doesn't meet the condition

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what am I supposed to do here even?

static plinth
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have you done hypothesis testing or is this just supposed to be a 95 percent confidence interval

alpine wind
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this is part of the confidence interval section so I assume we use confidence interval

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I already know how to conduct a hypothesis test and build a confidence interval

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but what am I supposed to be testing against here anyway

static plinth
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i see

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well it is asking for us to test whether or not the “guaranteed condition” is verified

alpine wind
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it's not we can see it

static plinth
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or rather the alternative hypothesis would be that mu is less than 5

alpine wind
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how does mu being less than 5 prove anything

static plinth
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it does look like it doesn’t

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but we can’t know for sure

alpine wind
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if the "average" is less than 5, that doesn't gaurantee that some values are not higher than 5

static plinth
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it doesn’t

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but it is good enough evidence

alpine wind
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hence the test will be usless

static plinth
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to show that most of them is less than 5

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since we are doing it with 95 percent confidence

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it will be even more accurate

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where 95 percent of the samples would fall under the condition

alpine wind
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but for the sake of what the question is already asking "is it likely that the guaranteed condition is verified?" isn't hte question already answered

static plinth
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supposing that the hypothesis test proves our alternative hypothesis

alpine wind
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we can see some values of which it is higher than 5

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so the answer would just be no

static plinth
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well that is more intuition

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for stats we usually need statistical evidence to back it up

alpine wind
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it's not intuition it's what we observe

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the verified is an existence proof

static plinth
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we can’t really just say, oh one value is greater so it must not

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a sample can have its outliers

alpine wind
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if there exists one value which does not meet the condition, then the condition is not verified

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if there exists outliers then by definition the condition is not met

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the condition is "it is gauranteed to be less than 5"

static plinth
#

well the thing is, we are doing this with 95 percent confidence

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not 100 percent

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so there will be some samples that might not do something like that

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but ig the question is a little extreme by saying that it is guaranteed

alpine wind
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I don't think we're on the same page here

static plinth
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regardless, we have to do hypothesis testing or a confidence interval whether you like it or not

alpine wind
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the very context of the problem doesn't need a hypothesis test

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you don't disprove mathematical theorems with hypothesis testing

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for "for all ...." theorems, you can disprove them with a single counter example

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same with here

static plinth
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note how the question also asks if it is likely that the condition is verified, and not if the condition is verified

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so just because there is one outlier that doesn’t satisfy the condition

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doesn’t mean that it is unlikely that is satisfied

static plinth
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they will most likely have a better way to counteract that than i do

lucid tiger
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whats up

alpine wind
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sorry but I'm still not convinced

static plinth
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what you said up there is true that, yes the condition is not verified because there is one counterexample

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but it isn’t asking if it is, rather if it is likely that it is true

alpine wind
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when we look at a sample we assume all values are sampled from the population

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non of them are "false"

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whether they represent the bigger population is what we're testing

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but in an existence proof, just one single value from a sample is enough

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as in this case

static plinth
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again, that is verifying whether or not the condition IS true, not whether or not it is LIKELY to be true

alpine wind
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I might be stupid but I don't see how there is a distinction between the two in this context

static plinth
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let’s say this, from the sample that we got there, there is one number above 5 which disproves the condition about the entire population

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but this is just one sample out of the many samples we could’ve taken

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and maybe a majority of these samples don’t have a number above 5

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then that shows that we got a sample that has a low probability of occurring that disproves this condition

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meaning that it is more likely that the condition is true than it isn’t

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based on the sample we’ve taken

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like if we took multiple samples, there might be a higher chance that i get a sample that doesn’t have a number above 5

#

which shows how it is more likely to prove the condition than it isn’t

#

doing it this way proves whether or not the condition is likely to be true

#

but doesn’t necessarily mean that the condition is true

final saddleBOT
#

@alpine wind Has your question been resolved?

final saddleBOT
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#
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tranquil pine
final saddleBOT
tranquil pine
#

i am lost

#

the divisors is the prime factorization of n^2

#

$n = p_1^{k_1}p_2^{k_2}p_3^{k_3}....p_n^{k_n}$

soft zealotBOT
#

Derivative

tranquil pine
#

thats the prime factorization

#

but the rest i am lost

final saddleBOT
#

@tranquil pine Has your question been resolved?

tranquil pine
#

<@&286206848099549185>

#

nvm i found it

#

.close

final saddleBOT
#
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#
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tranquil pine
final saddleBOT
tranquil pine
#

how do i use telescoping series for this

#

this is what i got, tell me if i got it good

#

$\lim_{n\to\infty} 1 + \dfrac{1}{2} - \dfrac{1}{nn!} - \dfrac{1}{n!(n+1)} = \dfrac{3}{2}$

soft zealotBOT
#

Derivative

tranquil pine
#

<@&286206848099549185>

#

urgent need to give back assigment

#

homework assigment

#

ah i used helpers tag for previous question i asked but then i asked another question and used again

#

i found the answer to my first question but to that question i did but wanted to make sure it is right

#

ye i know but scroll up i asked another question

#

ok so i broke the rules my bad

#

yes thanks for the explanation i wont do it again

final saddleBOT
#

@tranquil pine Has your question been resolved?

final saddleBOT
#
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gentle swan
#

From personal experience is linear algebra or topology more fun(and or useful)? I don’t know which I want to take next year, I’m finishing up multi rn

zenith pollen
#

linear algebra is like 50 times more useful and topology may/may not be more fun depending on how analysis heavy it is

royal gust
#

Linear algebra is very useful

#

I'm wondering how you're getting to decide between Lin Alg and Topology though

final saddleBOT
#

@gentle swan Has your question been resolved?

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#
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meager sky
#

Suppose we roll 4 6 sided die. What is the expected largest integer to appear on any of the four die?

meager sky
#

I can imagine enumerating and finding an answer, but that’s too tedious obviously. I wanted to used linearity of expectation, but I’m not sure how to apply it

#

It may be neither approach

#

I can’t think of any other way so maybe I am just supposed to count?

#

So to find E(2) we might say

WLOG let one die roll 2. then the other 3 have 2 options. We then need to multiple it by 4 for each one we fix, Which I feel like tells us

E(2) = 24/1296

#

wait that overcounts

subtle juniper
#

Tbh I can’t think of any other way (there might be one) so I might just count all possibilities

#

We can count the probability of 1 with (1/6)^4

#

And the probability of 2 with (2/6)^4-(1/6)^4

pine crescent
#

hi. I'm new here. Why are there so many different help channels?

meager sky
meager sky
pine crescent
#

oooh...I see. In [Math Help Available]

#

thanks

meager sky
#

np

subtle juniper
#

Which is (2/6)^4

#

But this over counts the possibility we got all 1s or less

#

So we subtract (1/6)^4

meager sky
#

Also am I just supposed to put the one with the highest expectation? Seems obvious but I just want to make sure

subtle juniper
meager sky
#

the problem asks what is the expected largest integer that appears on any of the four dice

subtle juniper
#

So you would have 1*(1/6)^4+2*((2/6)^4-(1/6)^4)

#

And so on

meager sky
#

Can I be certain that evaluates to an integer?

subtle juniper
#

No

#

But expected value doesn’t have to be an integer

#

If you wanted the integer that would be most likely to occur

#

It would be 6

meager sky
#

My main worry is I’m not sure if my problem is a normal EV problem. It might be but it’s wording says “compute the expected value of the largest integer that appears on any of the four dice”

subtle juniper
#

Expected value is just an average so it should just be normal

#

The expected value of a dice roll is 3.5 and that’s not an integer

#

So it shouldn’t be a problem

meager sky
#

alright thank you I just wanted to make sure

#

.close

final saddleBOT
#
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#
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livid schooner
final saddleBOT
livid schooner
#

question D

#

someone help pls

final saddleBOT
#

@livid schooner Has your question been resolved?

pliant shore
#

$|R_n (x)| < \frac{M}{(n + 1)!} |x - x_0|^{n + 1}$

soft zealotBOT
pliant shore
#

So here M = 128/3

livid schooner
#

wait how did you get M

pliant shore
#

Now, if we want to find the error of the second degree term, what must n be?

pliant shore
#

|f''(x)| < 128

livid schooner
#

ok

#

ty

livid schooner
pliant shore
#

Second degree = x^2

livid schooner
pliant shore
livid schooner
#

?

#

why

pliant shore
#

Remember -1/4 < x < 1/4 cause that's your radius of convergence

livid schooner
#

ok

#

so what will x1-x0 be?

#

cuz n=2 since it is f prime prime but Idk what x1-x0 be

pliant shore
pliant shore
livid schooner
pliant shore
#

Yes

livid schooner
#

yes

#

then what is x1 then?

pliant shore
#

Right, so what's the maximum value that |x - x0| can be

pliant shore
livid schooner
#

I mean x

#

cuz x-x0

#

the x

pliant shore
livid schooner
#

oh ok I get it

pliant shore
#

Yep and if you can figure that one out, you just need to figure out what n is, given you have the Taylor series to x^2

#

I'm not sure if you've learned this, but the maximum error of any Taylor series is just the next... (fill in the blank)

livid schooner
#

like u expand the entire thing out

#

and the next one is error

pliant shore
#

So you know n then

livid schooner
#

yes

pliant shore
#

So it's accurate to x^n

#

And so the next precision it may not be accurate to is x^(n + 1)

livid schooner
pliant shore
#

Sometimes the max error may never be that big at all

pliant shore
#

That's the reasoning

livid schooner
#

and cos is all even numbers

pliant shore
#

Even and odd powers of the Taylor series

livid schooner
pliant shore
#

Yeah it is haha

livid schooner
#

.close

final saddleBOT
#
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final saddleBOT
#
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final saddleBOT
lyric quiver
#

The factorial is throwing me off

steep tendon
#

see if every next number in the sequence gets smaller by a percent? idk

final saddleBOT
#

@lyric quiver Has your question been resolved?

silver maple
#

What techniques have you tried

lyric quiver
#

I tried graphing / looking at the plots. Table graph, it looks like it goes to infinity, not to a specific number

#

I thought it diverges, but the answer key is almost stating that it converges? Not sure if I am reading that wrong or not though

#

Usually a factorial is more powerful than an exponent too

#

So to me, it's almost as if it's saying infinity / bigger infinity = goes to 0 ?

silver maple
#

I asked for the definition

#

You might be able to get the answer through inspection, however I would use the ratio test

lyric quiver
#

Ah, we have not learned about the ratio test yet

#

But this looks like... I could use the telescoping sum?

silver maple
#

I am afraid I can't help you

lyric quiver
#

That's ok, thank you for trying @silver maple

solemn igloo
#

seems like a pretty perfect fit for ratio test

#

weird problem to assign without that

#

oh im stupid

#

nth term

lyric quiver
#

Ah ok hmmm.. I'm trying to plug in the answers and see if I get any hits that way 💀

solemn igloo
#

just consider the limit of the individual terms as n->\infty

lyric quiver
#

oh right

#

hmmm

final saddleBOT
#

@lyric quiver Has your question been resolved?

lyric quiver
#

.close

final saddleBOT
#
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final saddleBOT
#
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Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

viscid frigate
#

can someone tell me how to solve fractions equations

viscid frigate
#

<@&286206848099549185>

flat hearth
#

For addition

viscid frigate
flat hearth
#

You can use cross-multiplication on proportions.

viscid frigate
#

so what dod i do

#

here

flat hearth
#

Let's take an example

#

This might be far-fetched btw

viscid frigate
#

oh ok

flat hearth
#

5/7 = x/35

viscid frigate
#

what is this /

sand hare
#

It means fraction

flat hearth
#

It can represent a fraction bar

viscid frigate
#

oh ok

flat hearth
#

Then we can cancel out the 7 in the left side of the equation

#

by dividing

#

So it becomes 7x/7 = 175/7

#

x = 175/7

#

Therefore x = 25

sand hare
#

BUT

#

You can get more complicated ones

viscid frigate
#

can make in a pic so i can understand more

flat hearth
#

Wait for a bit

viscid frigate
#

ok

flat hearth
sand hare
#

As you can see here I’ve gotten rid of the fraction by multiplying evry term. Then just simply expand an solve, no fraction. (This is obviously more complicated because you can’t cross multiply)

#

So I always just get rid of the fractions then I solve

viscid frigate
flat hearth
sand hare
#

Sorry if I got it more complicated 😂

flat hearth
viscid frigate
sand hare
#

If your not gonna come across the ones I did don’t worry bout it

viscid frigate
#

so i'm going to solve a fraction and you tell me if i'm correct

#

the fraction is x/5 = 4/7

#

5x4=20

#

and then i divide 20 with 7

#

am i correct ?

#

or did i miss some steps ?

sand hare
#

Yup ur correct

viscid frigate
#

so what is the answer ?

sand hare
#

20/7

#

X=20/7

viscid frigate
#

oh

#

I saw the teacher looking for the lcm with fractions do i do the same thing to those type of fractions ?

#

and something about terms not sure

sand hare
#

Ok

#

So teach was talking about adding and subtracting fractions which is far different

#

For that you need a common denominator

#

I’ll show you

viscid frigate
#

ok

sand hare
#

Sorry did you want that with variables or without

viscid frigate
#

oh idk

#

i think she was mostly solving the ones with x

sand hare
#

For multiplying and dividing fractions simply make multiply the numerators and multiply the denominators.

#

Sorry for division you do literally the same thing as multiplication but first you flip over one of the fractions then multiply them

viscid frigate
#

wait

#

im not talking about those fractions

sand hare
sand hare
sand hare
#

Yes but your teach was talking about lcm

#

So most likely an expression like

viscid frigate
#

this

sand hare
#

Oh

#

Your teacher just multiples everything by 15 because you can’t get rid of all the fraction in one go that’s all

#

If you need more help just ask I can’t help with much but I can help with this

viscid frigate
#

idk how to solve those type of fractions

viscid frigate
random elm
#

Uhm

random elm
viscid frigate
#

could u help with how to solve those type of fractions

random elm
#

So it's easy

viscid frigate
#

steps ?

random elm
#

Because my English is poor and cost to explain

viscid frigate
#

ok

random elm
#

One moment please

viscid frigate
#

take your time

brittle mesa
#

Just multiply 6/7 by x and 4/x by 7 which is = 6x-28/7x=0

random elm
brittle mesa
#

bring 4/x to the other side first

random elm
#

Goodbye

viscid frigate
viscid frigate
brittle mesa
#

Step 1: bring 4/x to the LHS which is: 6/7 - 4/x=0

Step 2: u wanna combine them so u multiply 4/x by 7 and 6/7 by x which is: 6x-28/7x=0

#

Then u gotta get rid of the 7x

#

U multiply 7x on both sides

#

And since the RHS is 0, then 7x*0 =0

#

So 6x-28 = 0

#

Then bring 28 to the RHS and divide it by 6

viscid frigate
#

what's the answer?

brittle mesa
#

x = 14/3

viscid frigate
brittle mesa
#

Huh

viscid frigate
brittle mesa
#

Cuz I’m pretty sure it’s 14/3

viscid frigate
brittle mesa
viscid frigate
viscid frigate
brittle mesa
#

For 6/7 = 4/x

#

I was talking bout this one

viscid frigate
#

bro i'm failing my test 💀

brittle mesa
#

💀💀💀

viscid frigate
#

i'm cooked

brittle mesa
brittle mesa
#

When’s ur test?

viscid frigate
viscid frigate
brittle mesa
#

u can do it another way

#

I find it easier

viscid frigate
brittle mesa
brittle mesa
#

okay okay

#

So like what u can do

#

I’ll draw

viscid frigate
#

my test is on fraction and equations , 1 step equation 2 step equation .linear equations

#

bro..

brittle mesa
#

HAHAHAHAHA

#

In how long is ur test?

viscid frigate
#

6-7 hours ?

#

and i have school today

#

so i should be going soon

brittle mesa
#

Damnn

viscid frigate
#

ya'll what do i doo

brittle mesa
#

U can study during ur other classs

viscid frigate
brittle mesa
#

That’s why u study it so u can do it😍👍

#

I’m almost done

viscid frigate
#

@brittle mesa what grade ur in

brittle mesa
#

Wait a sec

viscid frigate
#

ok

#

?

brittle mesa
#

Huh

viscid frigate
#

what's igcse

#

oh

#

i'm grade 9

#

lol

brittle mesa
#

Hahaha

#

I can’t make it clearer💀

#

Every single step there

viscid frigate
#

hmm let me see

#

bro im stupid didn't understand a single thing

brittle mesa
#

It’s ok hahaha😭

#

Read it and try to process it

#

Takes time

viscid frigate
#

my i......1.1.1.1.1.1.1.q is prob 5

brittle mesa
#

Chillout💀

viscid frigate
#

from

brittle mesa
#

You’ll eventually get it

#

There’s no 3k/2?

#

I don’t see any

viscid frigate
#

no the 3/k

#

bro the k/3

brittle mesa
#

It’s in the question

viscid frigate
#

oh ur answering this question

brittle mesa
#

3k/5 - 6 = k/3

brittle mesa
viscid frigate
#

I told you im stupid

brittle mesa
#

Nah ur not

#

It’s not about being stupid

#

But do u get it now?

viscid frigate
#

no

brittle mesa
#

HAHAHAHAHA

#

U gotta trust urself

viscid frigate
#

hahaha

brittle mesa
#

Fr tho

#

Guaranteed

viscid frigate
#

hmm i'l try my best pls wish me gud luck on the test

brittle mesa
#

Wishing u good luck🙏

#

What do u not get tho?

viscid frigate
#

@brittle mesa have you failed any courses ?

brittle mesa
#

Nope

viscid frigate
#

brooo ur smart

brittle mesa
#

💀💀💀

viscid frigate
#

so luck i'm pretty i could understand if u follow my words

#

so what is the first step like the first step to solve those kind of fraction

brittle mesa
#

Ok so the first thing I did

viscid frigate
#

broo u aren't a helper sorry i took so much of ur time

brittle mesa
#

It’s ok lmfaooo

viscid frigate
#

u don't have school ?

brittle mesa
#

Holidays

viscid frigate
#

ur in the us ?

brittle mesa
#

And it’s 8pm

#

Nope

viscid frigate
#

damm

#

ur asian ?

brittle mesa
#

I’m French

viscid frigate
#

oh bonjour

brittle mesa
#

viscid frigate
#

lmao

viscid frigate
brittle mesa
#

Bring all the fractions together

#

So to do that

#

U need to put 3k/5 and k/3 to the same side

#

Which is what I did in the 2 first steps

viscid frigate
#

use the bot pls

brittle mesa
#

Hence why I +6 and -k/3

#

Idk how to use it

#

is it this

viscid frigate
#

oh ok

brittle mesa
#

Which one is it?

viscid frigate
#

idk

brittle mesa
#

k/3

#

I cant use it💀

#

Prob cuz I ain’t a helper

viscid frigate
#

ok

#

augh

#

i hate math

brittle mesa
#

Idk what else to do

#

Call a helper or sum💀

#

Way more qualified

#

My teaching skills mid

viscid frigate
#

bro it's not u

#

i just lose braincells from learning math

#

@brittle mesa thank you

brittle mesa
#

Hahahaha

#

It’s better if u ask ur teacher to explain in detail what u didn’t get

#

Face to face is more practical

viscid frigate
#

too late

brittle mesa
#

B4 the tests starts ofc

#

Ur friends then idk💀

viscid frigate
#

my friends are stupid

#

you know what idc what i get on the test but i rlly need to improve

#

cause my average is 33.38 %

#

alr later

brittle mesa
#

See you

#

Don’t forget to close🤓

viscid frigate
#

🤓 ok

#

.close

final saddleBOT
#
Channel closed

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final saddleBOT
#
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heavy grove
#

If a company makes x hundred A tires and y hundred B tires.

0=<x=<4

y = 40-10x / 5-x

The profit on grade A tires is twice that of the profit of B tires Find the number of each tires to be made to maximize profit

final saddleBOT
#

@heavy grove Has your question been resolved?

final saddleBOT
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After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

molten raptor
#

Hello!

final saddleBOT
molten raptor
#

If I have the following

#

I'm well aware that I can do

#
ln( (1-x) / (x+3) ) = ln 1
e^ln(1-x/x+3) = e^ln(1)
(1-x) / (x+3) = 1
1-x = x+3
2x = -2
x = -1
#

however, say I didn't want to do the step where I put the ln terms together

#

what would that look like

#

would it be e^ln(1-x) - e^ln(x+3) = e^ln(1)

#

or would it be

#

e^ln(1-x) - ln(x+3) = e^ln(1)

lucid marsh
#

e^(entire rhs) = 1

molten raptor
#

lhs i guess you mean

lucid marsh
molten raptor
#

but alright then i get the idea

#

cheers

#

.close

final saddleBOT
#
Channel closed

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final saddleBOT
#
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tranquil pine
#

Can anyone once again explain where and how multisets are used?

upbeat zephyr
#

can you help me with question 4?

tranquil pine
upbeat zephyr
tranquil pine
tranquil pine
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You can ping helpers after 10 min ig

tranquil pine
upbeat zephyr
#

can someone help me?

tranquil pine
#

You should ask this in another channel

upbeat zephyr
#

which channel?

tranquil pine
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Any free one

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Where is written "available"

tranquil pine
#

For example

tranquil pine
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@tranquil pine , sorry, but I don't know so much about multisets

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Good luck!

tranquil pine
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Even I don't 🫂

final saddleBOT
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@tranquil pine Has your question been resolved?

tranquil pine
final saddleBOT
#

@tranquil pine Has your question been resolved?

final saddleBOT
#

@tranquil pine Has your question been resolved?

#
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#
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bleak fractal
#

yo

final saddleBOT
bleak fractal
#

.close

final saddleBOT
#
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Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

mint orbit
final saddleBOT
mint orbit
#

So I'm working on part 2, I understand it's supposed to be trivial, but I don't really understand.

soft zealotBOT
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jan Niku

mint orbit
#

I'm not understanding the next steps from here though, in the proofs that I'm reading

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We do want to introduce a pointwise limit, right?

final saddleBOT
#

@mint orbit Has your question been resolved?

final saddleBOT
#

@mint orbit Has your question been resolved?

mint orbit
#

please help bearlain

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I have a solution

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it doesnt make any sense

rain stirrup
#

Anyone?

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I don't know which one to pick

neon slate
final saddleBOT
rain stirrup
#

i dont know how to work this discord server

void fjord
#

!occupied

final saddleBOT
#

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

void fjord
#

Go to the channel and read.

mint orbit
#

while youre here please help @neon slate happy

neon slate
#

i dont know anything about analysis

final saddleBOT
#

@mint orbit Has your question been resolved?

final saddleBOT
#

@mint orbit Has your question been resolved?

versed crater
mint orbit
versed crater
#

Oh it’s just some other function in the sequence

#

I’m not sure what $|f_k-f_m|\leq ||f_k-f_m||_\infty$ means

soft zealotBOT
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Frosst

versed crater
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It’s a function on the left and a real number on the right

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How can I have inequalities between those 2 things

mint orbit
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like if you have $||f|| = a$

soft zealotBOT
#

jan Niku

mint orbit
#

then almost everywhere, $a\geq f$

soft zealotBOT
#

jan Niku

mint orbit
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or, $a$ is a supremum of $f$ except on some set of measure 0

versed crater
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Oh as a constant

soft zealotBOT
#

jan Niku

mint orbit
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sure

versed crater
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Ok

versed crater
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@mint orbit what are you struggling to get in this question

mint orbit
versed crater
#

I think you’re just supposed to stack the Cauchy on the uniform convergence

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Cauchy tells you you can squeeze that norm as tight as you wish

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Then that tight bound is the same as picking any epsilon to show uniform convergence

mint orbit
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i do not understand the one that i linked at all i just thought it might help bait someone to help me to be honest

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i know the definition of cauchy

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i just dont follow the rest of this proof

mint orbit
mint orbit
#

can u delete this and move to an open channel?

glad dragon
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ok

hearty scroll
#

Heyyy

chilly cloud
mint orbit
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I get the framework is like

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#1 you need to find some candidate function that this cauchy sequence converges to

chilly cloud
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you'r following this?

mint orbit
#

#2 you need to show it does converge to that

mint orbit
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like "look the problem is easy"

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i dont understand that proof at all

chilly cloud
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Convergence in sup norm is uniform convergence iirc

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sorry its been a while since i took this

mint orbit
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I was working with another person in my dept

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he suggested that i like

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so take cauchy to mean that we can find some k such that $||f_k - f_j|| < \epsilon$ given $k < j$

soft zealotBOT
#

jan Niku

mint orbit
#

and fix k

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then a candidate with this k fixed is $\limsup _j f_j$

soft zealotBOT
#

jan Niku

mint orbit
chilly cloud
#

Which jump specifically?

mint orbit
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the proof just ends

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it seems like it barely starts

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I guess I need more details than this

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like

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i dont understand whats going on with the union

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and then he just asserts that it converges uniformly but doesnt show it?

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and then the proof just stops

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the rest of this document is about p < infty

mint orbit
chilly cloud
#

Ok lemme write out the details (or attept to rn)

mint orbit
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but idk if this is even going the right direction

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at least this is step #1

chilly cloud
mint orbit
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does that step make sense

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The limsup has to move closer to the fixed f_k

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so you can use it as a candidate since its at least less than epsilon

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but I'm not sure how to resolve this outside of some fixed k

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Like the dream is that you just say

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okay take $N_j$ to be the set where $|f_k - f_j| \geq \epsilon$ for some fixed $k,j$

soft zealotBOT
#

jan Niku

mint orbit
#

then call $N = \bigcup _J N_j$ has $|N|=0$ and on $N^c$ you have that $|f_k - f_j| < \epsilon$

soft zealotBOT
#

jan Niku

mint orbit
#

now it makes sense to propose the candidate $|f_k - \limsup _j f_j| < \epsilon$ because $\limsup _j f_j \leq f_j$ i think

soft zealotBOT
#

jan Niku

mint orbit
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and well the limsup will be within the epsilon ball

mint orbit
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once we want to involve other k, presumably, to get convergence

chilly cloud
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iirc it depended on completedness of reals

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but im just doublechcking if im a crank now LOL

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yea my prof literally said

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'key ingredient is completedness of R' ill send pic

mint orbit
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limsup isnt guaranteed to converge to f_k

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it will only converge along j,k

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the limsup might actually eternally be some non-negative distance away from f_k, we can't actually bound it without un-fixing k

chilly cloud
mint orbit
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since atm epsilon is actually fixed

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unless im mistaken

chilly cloud
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you want to pass to the reals at the end of the proof

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All this Z_n,k nonsense is doing is carving out the bad set wher bad things happn

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So you have: