help-36

[past mesa]

💛

[void crest]

i think

its

time

to use my final form

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[ancient kestrel]

What do I do after this? I need to find ZY

[loud sundial]

use this in triangle WZY

[ancient kestrel]

Would this be right?

[loud sundial]

assuming you can use a calculator and intermediate rounding is acceptable, yes.

[ancient kestrel]

Thanks

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[compact bolt]

Hi,

I'm starting to learn index laws and I'm struggling with the question below. How would I start off? I've only learnt the basic laws like x^a * x^b = x^(a+b). The division sign/symbol on the x^5 is confusing me.

[compact bolt]

i need to simplify the expression

[grim badger]

That's a square root sign

[compact bolt]

what does that do

[grim badger]

Not division sign

Have you ever seen $\sqrt{4}$ before?

[soft zealot]

dldh06

[compact bolt]

i think so

[strange rune]

if that can help we are doing roughly the same kind of thing here #help-4 message

[compact bolt]

but i thought that meant like what numbers divide 4

[grim badger]

No

Square root

[compact bolt]

how does that work

what does the square root symbol do

is it like a function

cuase i haven't learnt functions yet

[grim badger]

https://www.youtube.com/watch?v=yICR9PiW340&ab_channel=MathwithMr.J

[compact bolt]

oh, so sqrt 36 is 6 because 6 times 6 equals 36

so does that mean $\sqrt{x}$ is equal to the number that when multiplied by itself gives {x}?

[soft zealot]

MePushp

[compact bolt]

<@&286206848099549185>

[flint marsh]

$\sqrt{x} = a \iff a^{2} = x$

[soft zealot]

texaspb

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[sweet cipher]

one sec

[sweet cipher]

this is a stats question

so Idk if I did question 1 correctly

like idk when someone would prefer single blinding

also when it comes to double blinding, is there someone who wouldn't be blinded or are the instructions a little confusing bc I thought double blinding means everyone is blinded

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[next dove]

im stuck here since i realised that i'll be going towards an indeterminate value

but i'm not sure how else i can approach this

[inland bison]

you can cancel out the m if you want
now note that the denominator is going to approach 0, but we can at the same time we can rationalise it by multiplying by the conjugate

so here, we can get rid of that 0 in the denominator hopefully by rationalising the denominator

or, multiply the top and bottom by the conjugate of the denominator

[next dove]

ah

i didn't see it that way

let me give it a try

did i do this correctly

i still get a 0 in the denominator

[inland bison]

yes looks good

now do common denominator for the expression in the denominator

[next dove]

sorry i'm not quite sure what you mean by this

[inland bison]

can you simplify $\frac{1}{1-\frac{v^2}{c^2}}-1$ into one fraction?

[soft zealot]

waler

[next dove]

ah ok

you mean like this?

[inland bison]

yes

you dont have to distribute the 1/2 inside tho

now can you simplify it dfurther?

[next dove]

oh yea

i can cancel out the (v/c)^2

[inland bison]

yes, i suppose you can finish with the problem now?

[next dove]

yup

thanks alot!

just to help me in the future but like

how do you manage to deduce that

[inland bison]

thats just usually how it's done

[next dove]

do i just need to do more limit problems

[inland bison]

well yeah, practice help

but what helps is to notice the pattern

the goal is to clear out the 0 in the denominator

in this case that is

and so we did that

in other times, your goal may be getting the expression to a familiar limit that you can evaluate

[next dove]

great, thanks once again, i'll remember the multiplying of conjugates in the future

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[icy torrent]

Hello, everyone. I am asked to solve for the area bounded by the function. Can you check my work? Im not sure wether it’s positive or negative tho

[void crest]

woww

thats some beautiful handwriting

,w antiderivative of xsqrt(4-x)

[soft zealot]

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[void crest]

oh

i think

u used substituition

uve to change bounds of int

nvm i think u did

o well sry im bad at int

[icy torrent]

I tried to use an online calculator to check my work but the definitie integral is positive for that

But mine is negative hahaha

[void crest]

yeye

same

i

[icy torrent]

Idk where i got wrong hahahaha

Waitt should i change the bounds from 4 to 0 after substituting “u” to the equation?

[void crest]

um

well

actually

u should

but

it makes no diff

cuz then itll be from

4 lower and 0 upper

which is the same as using a negative

n u del an neg

so i assumed u kinda did a double neg

ok but

this is

[icy torrent]

But then my answer would be positive because the bounds are flipped

[void crest]

exactly the same

D:

2/5(1-4^2.5) - 8/3(1-4^1.5)

idk why im gettin

6.266..

o well

:c

[icy torrent]

I forgot to substitute 4-x back to the “ u” since i did not change the bounds.

That’s why it’s negative

I got positive now. Thank you!

[void crest]

w8

iss the ans right

if u just changed to +ve

how wld u change bounds anw

im

bad

hahaha

but gd u got it

OMG

i was wrong

if u changed bounds

u would get

0 above

and

-4 below

so it would make a diff

D:

then yes u shld also add a neg

cuz thats from change of basis

from

dx=-du

@icy torrent

why did i take so long

but i finally got it

i just read

https://en.wikipedia.org/wiki/Integration_by_substitution

under definite integrals

n thought a bit more

well

it was fun

hahhaa

[icy torrent]

Yesss thank youu if you did not mention the changing of bounds then i wouldnt notice where i got wrong hahaha

Thanksss!,

[void crest]

ayyy

❤️

[icy torrent]

Thank you @void crest

[void crest]

npppp

i learnt with u

n got stuck with

u

HAHAHA

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[inner wind]

whats wrong with my answers?

[vital crag]

is the graph f or inverse of f

[inner wind]

im not sure

my answers were 0% correct

so i guess inverse?

[wraith crater]

Yes inverse

f^-1

[inner wind]

how would i calculate the inverse points?

[wraith crater]

f^-1(-4) is asking what value of input x gives -4 as the output

So you’d go the the point where y=-4 and read off the value of x

[inner wind]

so for that itd be 4?

[wraith crater]

5?

[inner wind]

oh i see what you mean

i think for this one it be approx 5.5

nvm its 5

ty

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[inner wind]

.reopen

[final saddle]

✅

[inner wind]

but what about f^-1(0)?

[wraith crater]

When y=0 what’s x?

[inner wind]

3

but i keep getting it wrong

[wraith crater]

-3 is not 5:5

[inner wind]

why not?

[wraith crater]

It’s 4.5

[inner wind]

oh

tyy

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[wraith crater]

Np

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[fierce ridge]

i feel like this is really stupid but imma ask it anyway...

[fierce ridge]

is this the same as

$\int _0^1\frac{1}{x^2+1}dx$

[soft zealot]

imagine

[worldly vale]

Yes it is

[fierce ridge]

alright cool

tysm

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[vital crag]

so helpful

unironically

[worldly vale]

Green for go baby

[dawn elk]

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[icy torrent]

.Hello, everyone I just wanted to ask if i answered it right? I used the washer method, and im still lacking the other method,.

Based on the problem the axis of revolution is about the y-axis, so i transformed the equation of the function as a function of y, since it is given as a function of x in the problem.

[grim nebula]

bot?

[grim nebula]

wait what

@icy torrent this appears to have bugged

try posting in another channel

.close

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[dawn elk]

.Hello

[grim nebula]

shadow banned?

[dawn elk]

um?

[grim nebula]

#help-18

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[abstract snow]

How do we solve this, All real numbers except 0 was incorrect

[chrome cove]

Try substituting x with 0, and see why 0 is actually good in this case

[abstract snow]

Therefore, is the answer all real numbers?

[chrome cove]

As a rule of thumb, if you have any "rational" functions check if something in the denominator cancels out

[abstract snow]

F(x)= x+3 is the simplest form? So domains of the function would be all real numbers since it is a polynomial equation?

[chrome cove]

Yup exactly!

[abstract snow]

Thank you so much!

[chrome cove]

This gets quite tricky later on, be sure to always factorise the numerator and the denominator

[worldly vale]

I think this is a poor question. Technically speaking something like f(x) = x/x is a different function than f(x)=1 exactly because one of them is not defined at x=0

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[cunning finch]

What do u call the red region within a symmetric matrix?

[cunning finch]

id like to refer to all the upper off-diagonal elements at once

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[cunning finch]

(found my answer from other sources)

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[tranquil pine]

hi i need help :(((( pls y=-x^2 + 5 what is the condomain and "vertex coordinates" :_:

[frigid sierra]

hihii

what is condomain?

for vertex u can use -b/2a or complete the square

[tranquil pine]

codomain :-:

[dawn elk]

The codomain is the set of all possible values which can come out as a result of f(x)

[tranquil pine]

how i solve this ;_; idk

[inner spoke]

Isnt that the range?

[dawn elk]

well if you think about it, what can co-domain be

[dawn elk]

range is what values f(x) actually has

range is a subset of codomain

[inner spoke]

But here you say all possible values that come out result of f(x), if f:R-->R, f(x)=sinx, theres a lot of values in the codomain which i defined as R that cant come out as the result of f(x)

[dawn elk]

range also known as image

[dawn elk]

who says f has be every element of codomain

[worldly vale]

Deep was a bit loose with the language, they meant like possible values f(x) COULD take, but not necessarily all the ones it does take

[dawn elk]

that’s what range is

so like for example “I live in india” here india is codomain that doesn’t mean i live in every part of india

uhh do you get it?

[tranquil pine]

or vertex u can use -b/2a or complete the square. can i do it?

y=-x^2 + 5

[dawn elk]

hm?

[tranquil pine]

wait a minute

here

Coordenadas do vértice= vertex coordinates

Codomain

only the first one is enough

[dawn elk]

have you learnt how to find vertices yet?

[tranquil pine]

I forgot everything, I've been studying languages and humanities for two years.

[dawn elk]

https://youtu.be/IbI-l7mbKO4

[tranquil pine]

but how do I do this in an equations of the first degree? :_:

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@tranquil pine Has your question been resolved?

[dawn elk]

there is no vertex in an equation of first degree

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[dry light]

Just a curious question, because I can't find it on Google, what would $\sqrt[4]{x}$ look like on the complex plane? (Or somehow both Cartesian and complex simultaneously if that's possible)

[soft zealot]

Umbraleviathan

[dry light]

Because I know that when x = -1 there are 4 outputs so

[dawn elk]

1,i,-1,-i?

is that what you mean?

[final saddle]

@dry light Has your question been resolved?

[dry light]

Well no, like if I do $\sqrt[4]{-1}$ I get 4 results. Wondering how that would look like on the complex graph plane thing

[soft zealot]

Umbraleviathan

[dry light]

Because if it's like -2 instead of -1, the radius changes

So is it a disc or a cross?

[dawn elk]

okay i get it, idk but iirc there are some python libraries that let you plot functions in complex planes

[dry light]

I don't know code uhhh

[dawn elk]

hmm it’s really not that hard, lemme see if i find something

[dry light]

I'm assuming it'll be a cross though

Just because if it's like -2 or -3 or -0.6 it'll just change the radius

I'm only concerned with x being negative real numbers

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[light wren]

Would these be the correct answers for this limit question?

[hollow iron]

Yes

[light wren]

nice

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[neat mauve]

anyone who can help me with maple

[neat mauve]

how do i plot this

in maple

or something else

in a complex graf

graph

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@neat mauve Has your question been resolved?

[solemn sage]

Both simultaneously or separately?

You could try the complexplot function, but you'd need to know the parameter (t) range

Or, if you prefer Mathematica, you could use ParametricPlot

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[ionic moon]

I'm completely lost as to where to start

[void crest]

hii

so first

we can start by letting the length of a side be x

then we can use the formula for a triangle

this thing

[ionic moon]

Can I choose any side, but the square right?

[void crest]

to find the area in terms of x

then we can solve the x

[void crest]

um actually

the sides of the triangle n squ r the same

so doesnt rly matter

[ionic moon]

Ohhh okayyy

So I would first find a side by using area of triangle

[void crest]

um

yes

[ionic moon]

I'm so sorry I'm acc so bad at maths

[void crest]

nono

is allg

we here to learn n stuff

[ionic moon]

So would it be 60 = 0.5absinC ?

[void crest]

yess

[ionic moon]

Ahh then do I have to find the values of a, b and c?

[void crest]

ok o

so

[void crest]

we can do this

let one side b length x

and also

equi triangle

[ionic moon]

Okay

[void crest]

we k each angle is

60 degrees

so we can use that

[ionic moon]

Ohh my dayz I didn't even see that TT

[void crest]

hahaa

[ionic moon]

Wowww I'm acc so blind lol

[void crest]

happens

[ionic moon]

Hahaha thxxx

[ionic moon]

We have to unknowns, how exactly do I continue?

[void crest]

o so

um

all side of the triangle hv the same len

cuz its an equ tri

so its

x and x

[ionic moon]

All x

Ahhh

[void crest]

yessss

all x

[ionic moon]

Thank youuuuu

[void crest]

❤️

[ionic moon]

That's the answer I got, it's in the form it wants but is that all or do I do something different for the square

[void crest]

,w solve 60=1/2(x^2sin(pi/3))

[soft zealot]

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Requested by Circle#0025

[void crest]

hm did i do smt wrong

[ionic moon]

Wait it could be me TT

[void crest]

,w sin(pi/3)

[soft zealot]

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[void crest]

ah ye

this is

x^2

on the right

[ionic moon]

Ohh okay let me try again thanks

[void crest]

ayy

❤️

[ionic moon]

It's not giving it to me in the exact form TT

I'm so sorry for making u do more work

[void crest]

ok so

[void crest]

u can try using this

sin 60 is

sqrt(3)/2

$\frac{\sqrt{3}}{2}$

[ionic moon]

Okay so I am using my calculator in degrees and its giving me a completely different answer and still not in surds form

[void crest]

eh

:c

i think calc doesnt rly give exact

[ionic moon]

Should I try in radians?

[void crest]

nono

idt it makes a diff

its just how the calcs normally work

just try

working it out in ur head or smt

hahaha

wait actually

u dont really hv to

so like

uk how the length of 1 side is

x

and they asked u for area of a square

so the area of the squ is

x^2

[void crest]

so u can use the

x^2 here

u dont hv to sqrt it

oops

hahaa

mb earlier

[ionic moon]

Ohhh

Nooo it's okay dw

But it made sense to sqrt it tho

[void crest]

well

not when u need the square

hahahaa

[ionic moon]

Ah so for the formula u treat a and b the same as its equil right ?

[void crest]

yess

so u get

x^2

then u just need to use the

x^2

cuz thats the area of a squ formula

[ionic moon]

Ohhh yehhh I've lost u now TT

I'm so sorry I'm acc so sorry

[void crest]

let

the formula is

area = absinC

right

and the area =60

a = length = x

b = length = x

C = angle = 60 (all angles on equ tri is 60)

so we get

60 = x^2sin(60)

yay?

[ionic moon]

Yes but 0.5 right ?

[void crest]

wait

ooops

yeshhh

hahhaha

that

just

add that inside

hahaha

[ionic moon]

Yes that's right haha

[void crest]

60 = x^2sin(60)/2

ok so

also we know

x^2 is the area of the sq

and they want the area of a sq

right

cuz the

[void crest]

sides of the tri is all equ

n sides of squ r all equ as well

yay?

[ionic moon]

Yes yes

[void crest]

ye so from here

just try to write

x^2 = something

[ionic moon]

I got 15root3 as x^2

[void crest]

,w solve 60=1/2(xsin(pi/3))

[soft zealot]

Results provided by WolframAlpha

Click here to refine your query online
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Requested by Circle#0025

[void crest]

um

hahaa

i

[ionic moon]

Nvmmm

I got 80root3

[void crest]

how did u

[ionic moon]

Dw

[void crest]

yayyy

[ionic moon]

Typo in cal

[void crest]

[ionic moon]

Yahhhhh

Thank you so much for the help

[void crest]

nppp

❤️

[ionic moon]

I rrly appreciate it xxxx

[void crest]

ayyy

nppp

[ionic moon]

Okay so we close now ?

[void crest]

yuppp

[ionic moon]

❤️

[void crest]

❤️

[ionic moon]

.close

[final saddle]

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[bleak mesa]

Is what I did in blue legal

[void valley]

what does x-1 mean

[tranquil pine]

not illegal

[bleak mesa]

multiply by negative 1

[wraith crater]

Yes that’s the way to do it

But change it back at the end

[bleak mesa]

like plug u back in

?

[wraith crater]

so u = cos theta

Yeah

[bleak mesa]

ty

[wraith crater]

np

[final saddle]

@bleak mesa Has your question been resolved?

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[dull dirge]

So if the first person chosen is a boy, that makes there 12 boys left out of 27 students. That's the fraction for question a

[eager galleon]

hmm ok

[dull dirge]

For question b, you'll have to multiply 2 fractions together

[eager galleon]

so I multiply 15/28 by 15/28?

[dull dirge]

Almost

The probability of a girl being chosen is 15/28

But for the second selection, one girl is already chosen. So you can't choose one again

[eager galleon]

so it will be 14

[dull dirge]

That makes the second chance 14/27

[eager galleon]

thank you!

[dull dirge]

Np

[final saddle]

@eager galleon Has your question been resolved?

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[abstract mica]

can someone help me solve this without telling me the answer

[chrome cove]

what have you tried? What are your thoughts about the exercise?

[abstract mica]

im honestly confused

i know for a i should find the discontinuity but im having a hard time finding it

[chrome cove]

Usually, how do you do it?

[abstract mica]

id find the discontinuity

but for a its seems that it dosent have one

[chrome cove]

So usually, how do you find a discontinuity

[abstract mica]

for example

we try to find what =0

1/3-3

that would be the discontinuity here

[void crest]

idk whats gg on

[chrome cove]

what

[void crest]

but do u mean with brackets

[abstract mica]

.close

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[chrome cove]

there is a series of things to check when you look for the domain, for example taking roots of negative numbers, using logs with negative bases, and so on, all things that "break" math
Are you sure none of that business is going on here, and nothing bad will ever happen for any value of x?

[final saddle]

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[rugged pendant]

Help

With no 9

&10

[void crest]

hii

so

when u see than x

they mean

x is like

100%

,rccw

[soft zealot]

Couldn't find an attached image in the last 10 messages.

Sep 25, 2022, 9:28 PM

[void crest]

,rccw

[void crest]

so in this case, the first statement, its saying u can take rao is 100%

n pand will b 20pc less

[rugged pendant]

Ok

[void crest]

the 2nd is saying

if pand is 100pc

whats rao

[rugged pendant]

Umm

Idk how to find

[void crest]

ok so

if rao is 100pc

how many pc is pand

[rugged pendant]

80

[void crest]

yes

so

pand/rao = 4/5 right

like

80/100=4/5

[rugged pendant]

Yes

[void crest]

so now u wanna make

w8 i typoed earlier

anw

now

pand/rao = 4/5 right

u wanna make pand 100pc

so what pc would rao be

[rugged pendant]

100‰

Umm

5/4of100

[void crest]

yes and

what would that be

[rugged pendant]

125

[void crest]

yehhh

so

[rugged pendant]

Now no 10

[void crest]

how many pc more does pand hv

[rugged pendant]

125%

[void crest]

ahh i mean rao

oops

nono

[rugged pendant]

25% more then rao

[void crest]

125 is the

yeshhhh

so

thats it 25pc

um this is quite similar

Q10

try repeating what was done earlier

[rugged pendant]

Ok

[void crest]

noting the person mentioned after the than is 100pc

[rugged pendant]

Kumaris income 100%

[void crest]

yuppp

[rugged pendant]

Puri 120%?

[void crest]

yesss

so then if we simplify it what do we get

[rugged pendant]

5/6

[void crest]

yep so

[rugged pendant]

6/5*100

[void crest]

km/pu = 5/6

nono

the 2nd one wants us to use

pu as 100 pc

[rugged pendant]

Oh yes

We have to find less then

5/6*100

[void crest]

yesss

and what number is that?

[rugged pendant]

250/3

83?

[void crest]

yepp

nicee

so

[rugged pendant]

83 1/3

[void crest]

how many percent less

[rugged pendant]

17 2/3%

[void crest]

nice u got a

exact val

[void crest]

um

i think its

16

16 2/3

[rugged pendant]

16 2/3

Yes

[void crest]

but idk it looks a bit weird when u write it that way for pc

maybe use

16.67

anyway

yayy

finish!!

[rugged pendant]

Thank you so much

[void crest]

npp

❤️

[rugged pendant]

.close

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[tranquil pine]

How do I represent this in set builder notation if I is the index set of all sets Ai

[tranquil pine]

same as before but replace the for each quantifier with a there exists quantifier

oh shit

that didnt even occur to me

thanks again

.close

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[rugged pendant]

https://media.discordapp.net/attachments/908076393198419988/1023710435482017833/unknown.png

Well how to put it in sentences

[sweet summit]

well a percent is a ratio right. Suppose that Mr. Kumar's income is $100 and Mr. Puri makes $200 (since Mr. Kumar's income is less than Mr. Puri's). So Mr. Kumar makes 100/200 = 1/2 = 0.5 or 50% less than Mr. Puri

[rugged pendant]

,rccw

[rugged pendant]

No 10

[final saddle]

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[rugged pendant]

Sorry look at the full question

[rugged pendant]

Help

[sweet summit]

Ah okay yeah that context makes more sense lol

so let x be Mr. Kumar's income, right?

[rugged pendant]

Yes

No wait

[sweet summit]

Then we know that Mr. Puri's income is 20% more

[rugged pendant]

Without linear equation

[sweet summit]

I'm not doing a linear equation

I'm just setting up some stuff to help express the idea

[rugged pendant]

Ok

[sweet summit]

so with that, Mr. Puri makes 20% more

so he can be represented as 1.2x

do you see why?

[rugged pendant]

Yes

[sweet summit]

So what is the difference of their income?

given what we have written down?

[rugged pendant]

0.2
20%

Increase

[sweet summit]

0.2x 😛

so then we find the ratio of how much more by taking Kumar's income over Puri's income and multiplying by 100

in other words

0.2x /1.2x

then multiply that by 100

[rugged pendant]

1000/6

[sweet summit]

whoah no lol

[rugged pendant]

100/6

[sweet summit]

bingo

and what is that in decimal form? 🙂

[sweet summit]

bingo

so Mr. Kumar's income is 16.67% less than Mr. Puri's income

basically we're finding the ratio between them

something like:

$\frac{\text{Puri's Income - Pumar's Income}}{\text{Pumar's Income}$

[soft zealot]

MellowDramaLlama
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[sweet summit]

ugh

okay

let P be Puri's income. Let K be Kumar's income

$\frac{P -K}{P} \times 100$

[soft zealot]

MellowDramaLlama

[rugged pendant]

-k=100

[sweet summit]

huh?

[rugged pendant]

Ok
Finally can do in pen and paer

Now this sum

Help

With this sum

Hello?

.close

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[late knot]

Why do people normally say 3 as the answer to the sqrt of 9?

[late knot]

Why don’t they say -3?

I think too many people would say 3

say if they did like a math speedrun, nobody would say -3

Which is an absolute valid answer

We should promote -3 as the answer more often so it comes natural to our mind

Ykwis?

[grim badger]

Because the domain of sqrt is x >= 0

[late knot]

How so?

[grim badger]

Can you take the sqrt of a negative number?

[late knot]

Aren’t we talking about the range?

[grim badger]

No

[late knot]

Assuming the domain is the sqrt of 9

The range should be both

-3 and 3

Right?

[grim badger]

Are you referring to $\sqrt{x}$ where x = 9?

[soft zealot]

dldh06

[late knot]

Yeah

[grim badger]

If so, the domain of sqrt function is x >= 0

[late knot]

Yeh i do know that

Lets not relate to range nor domain right now

Lets just find out what the answer to sqrt 9 is

[late knot]

It’s both -3 and 3

[fair ginkgo]

no

[grim badger]

Now if you are referring to $x^2 = 9$ that's when x can be -3 or 3 because domain is all real numbers

[soft zealot]

dldh06

[fair ginkgo]

the solutions to 9=x^2 are two but sqrt9=x has only one solution

[grim badger]

Because of the domain

[late knot]

The answer squared should be the number inside the sqrt

So like

Lets say the number inside the sqrt is 9

Then if we say the answer is -3

If we sq that

-3 * -3

We get 9

Huh?

[grim badger]

That's the case if the function was x^2

Because the domain is all real numbers

[late knot]

Oh

[grim badger]

As stated, if the function was $\sqrt{x}$ , the domain is x >= 0

[soft zealot]

dldh06

[fair ginkgo]

the square root is not the inverse of squaring a number

[grim badger]

It is based on the function you are using because of the acceptable domain

[fair ginkgo]

because of domain, as dldh06 said

[late knot]

Yeah i learned that domain can not be negative if it’s inside the sqrt

But its still

…

Not intuitive to me

[grim badger]

$x^2$ and $\sqrt{x}$ have two different domains

[soft zealot]

dldh06

[fair ginkgo]

if you were right then (-3)^2 = (3)^2 => -3=3

which is ofc false

[grim badger]

Oh if you took the sqrt of both sides

[fair ginkgo]

yeah exactly

[late knot]

Oh actually

That just

Straightened up everything

Yeah now it makes sense

Yeah taking the sqrt of both

Make them different

It’s more intuitive to understand that way

Thank you

Proving is the most beautiful part of math

And its pretty hard

.close

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[late knot]

I feel like it’s pretty controversial

[late knot]

I did additional research

And i think the answer is it depends

It can be -3 in some cases

And can’t be in some cases

In real life you definitely can’t

[dry light]

NOOO

YOURE FONNA START A WAR

[late knot]

@fair ginkgo

No we already talked about it above

[dry light]

I told you $\sqrt{x^2} := |x|$

[soft zealot]

Umbraleviathan

[dry light]

Oh it's a hell hole

Oh hell naw

Ndueoskdkdiuguunynyny

[dry light]

@fair ginkgo @late knot fart

Easy

That's how it's defined

[late knot]

Yes by that you mean both + and -?

So you’re on the yes -3 side?

[dry light]

I'm on neither

[late knot]

Well by that equation

You are

[dry light]

Im on "it's situational, but also this is how it's defined"

[late knot]

Oh

[late knot]

Ok

Well said

So neutral

[grim badger]

I'm on this side $x^2$ and $\sqrt{x}$ have two different domains

[soft zealot]

dldh06

[dry light]

But this should indicate that it's always gonna be a positive result

[late knot]

Oh hold on

I got confused with +- on that

Lmao

Lmao i confused absolute value with +-

Which are two diff things

Oh sorry so you’re possibly on the no -3 side and neutral?

[late knot]

What is := btw

Oh i see

Right is defined by the left

[dry light]

:= is kinda like "defined as"

[late knot]

Ok i correct myself once again

So you could be on the yes -3 side or neutral by that equation

Because if you put -3 in that equation it is correct

Or might not be?

[late knot]

If you put -3 in there is it correct?

Cuz if you skip the -3*-3=9 part and just cancel out the sqrt and sq, it’s just -3

Cuz sqrt cancels out the sq

Im so throughly confused by this sqrt concept rn

Never had problem with sq on school math tests

But just deep thinking about this makes me crazy

😢

:Yelp:

Isn’t pure math always about deep thinking about the concept of math

Id kms if i take pure math

.close

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[hardy linden]

can someone please help

[hardy linden]

consider the function f(x) = x to the power of three + 4x^2 + kx - 4. The remainder from f(x) divided by (x+2) is twice the remainder from f(x) divided by (x-2). Determine the value of K.

[strange rune]

do you know how to do divisions for polynomials?

[hardy linden]

yes

[strange rune]

so did you try doing the two division involved and if so what did you find?

[hardy linden]

i tried

and i got x^2 +6x -12

[strange rune]

for which division?

[hardy linden]

i didn't know what to do when it came to dividing the k

thats the part that im stuck on

x-2

[strange rune]

ok

so you'll get something that depends on k

the first terms of what you get seem right for the quotient

[hardy linden]

ok

[strange rune]

can you show me your process so i can see where its hard for you?

like a picture of your division

[hardy linden]

i dont think were supposed to do long divison

I think were supposed to sub in -2 for x and solve

[strange rune]

i found a remainder

[hardy linden]

how

[final saddle]

@hardy linden Has your question been resolved?

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[tranquil pine]

I’m trying to learn infinite limits

Im struggling to answer questions like this

[void crest]

infinite?!

[tranquil pine]

Yea

What?

[void crest]

ye um

[tranquil pine]

Something’s missing?

[void crest]

no im just confused by the Q so i left lol

[tranquil pine]

Ah

[grim nebula]

LOL

[void crest]

it looks

weird ok

[grim nebula]

this question

was asked here

[tranquil pine]

Lemme rewrite it

[grim nebula]

a couple days ago

possibly by you

[tranquil pine]

Its from my recitation class

[tranquil pine]

No

[grim nebula]

hm

so i guess you have a fren

[tranquil pine]

Maybe this is better?

[tranquil pine]

Can u ping it?

[void crest]

LOL

yes snow

[grim nebula]

ping it?

[void crest]

go ping em

[grim nebula]

what is the it you're referring to lol

[tranquil pine]

The question that was asked two days ago

[tranquil pine]

.

[grim nebula]

two

i didn't say two

[tranquil pine]

Couple means two

[void crest]

...

[tranquil pine]

Whats the difference

[void crest]

LOL

[grim nebula]

that

is not how couple is used

couple means

[tranquil pine]

Couple of days

[grim nebula]

2 or more

[void crest]

look at that couple over there

[tranquil pine]

Bro im trying to study math not English

[void crest]

refers to 2 ppl

[grim nebula]

lol

[void crest]

[grim nebula]

well

i'll see if i can find it

[void crest]

HAHAHA

[tranquil pine]

<@&286206848099549185>

[grim nebula]

#help-21｜아리스킨충1 message

do you know what it means

[tranquil pine]

OMg

Lmaoo

[grim nebula]

to have an odd/even asymptote

[tranquil pine]

He is my friend

[grim nebula]

LOL

[tranquil pine]

From the same math section as mine

Same instructor too

[grim nebula]

successfully stalked 😎

[void crest]

wowz

[grim nebula]

look at this couple over here

[void crest]

[grim nebula]

still, do you know what it means