peak viper
Ty
#help-33
rugged moat
How do I go about solving this and finding the domain
marsh citrusBOT
How do I go about solving this and finding the domain
rugged moat
I would assume just plugging in the x and adding but how would the y^2 come into place
marsh citrusBOT
@rugged moat Has your question been resolved?
rugged moat
<@&286206848099549185>
rugged moat
Is this where the graph would be curved and infinite
Or am I thinking of a different one
main idol
you only need to plot a few points to show that it's not a function
next ravine
When we say $x \in \mathbb{R}$, does it only mean $x$ is a real number (i.e. that statement only tells us what type of number we're dealing with)?
marsh citrusBOT
When we say $x \in \mathbb{R}$, does it only mean $x$ is a real number (i.e. tha...
elfin berryBOT
Shen
main idol
yup
gritty vortex
Hello, im wondering how to find angles A, B, C and D. Heres a screenshot
gritty vortex
wraith moat
Thatβs an inscribed quadrilateral
So the opposite angles are supplementary (180)
@gritty vortex
For angle c, you would do 180-91
For angle d do 180-105
Now for angle a
You would have to do
Since angle c is 89 the arc it opens up to is 178 because you have to multiply by 2 because itβs inscribed, same with angle d, angle d is 75 so the arc it opens up to 150
To find angle a you would need to add 150 and 95
gritty vortex
got it tysm
marsh citrusBOT
@gritty vortex Has your question been resolved?
slim cloud
Hi
bright jay
<@&286206848099549185> s
You have to wait at least 15 minutes before pinging helpers
slim cloud
@bright jay bro i did
bright jay
No you didn't
bright jay
So? Doesn't matter, you opened a new channel, you still wait
You're trying to get your question attention
bright jay
Nah, don't feel like it
split drum
give me a sec @slim cloud ill try it out
slim cloud
@split drum appreciate it
split drum
can you resend the problem
split drum
ok are you confused about all parts or just part e
split drum
good job!
slim cloud
mhm
split drum
and the ferris wheel needs to rotate pi/3 radians to reach the bottom right?
slim cloud
yea
For a, you want to see how much time it takes to reach the bottom of the wheel if itβs rotating clockwise or moving to the left. In this case, we know that a full circle is 2pi and takes 6 mins to cover. The distance it covers is pi/3 of that 2pi. We can use that proportion to see how much of 6 minutes would be covered equivalently. Does that make sense?
split drum
yep, so a full circle is 2pi
you only need to go pi/3
if the full circle takes 6 minutes
how many minutes does pi/3 radians take?
split drum
yeah!
slim cloud
okay
what about b)
For b) we can actually split up the circle into two triangles and trigonometric ratios, then consider the height of the ground.
slim cloud
ye
split drum
you want to find the length from B to the ground
slim cloud
this what my teacher wrote
split drum
uh lets do part B first
slim cloud
wouldnt it be 10m
split drum
not quite, but we can get there
you are looking to find the distnace from D to the ground
so since D and B are the same distance from the ground
we can find B to the ground
split drum
yep! so its 8
slim cloud
okay
split drum
now we need to subtract AB
slim cloud
how do I find AB
split drum
guiding
no problem
after this though i recommend looking up khan academy trig videos
basically
we have the angle BAD = pi/3 = 60 degrees
slim cloud
yea
split drum
so we can now use the cosine function
slim cloud
o
split drum
we have cos(60) = AB/AD = AB/8
slim cloud
i did
split drum
hmm hold on
split drum
yes!
slim cloud
so 8-4 = 4
slim cloud
add the 2
split drum
yes!!!
split drum
no homo if your a guy
haha π
split drum
so answer is 6 for b
yep!
for part e now
imagine you are on this ferris wheel
where would be the first 2 points you are 12 meters above the ground?
split drum
yep!
slim cloud
I can show you what my teacher hinted π
e) you want to use two cast triangles and solve for the principle angles. you can set your pi/3(t-1) equal to x and then find the respective angles. sub it back into what you set equal to x.
slim cloud
ye
split drum
we aren't gonna get that for part e
slim cloud
ye
slim cloud
e. What are the first two times to the nearest second, when the passenger is 12 metres.
split drum
ok cool so we also know the length from the center to the circle is 8 right
then we can use trig to find the angle in the middle
the "wedge"
split drum
sorry i haven't heard of that
split drum
to be honest you dont need that
let me show you
the wedge between the 8 and the 2 is angle A
the wedge between the 8 and the parallel plane is angle B
by trig
slim cloud
yeah
split drum
we know angle A is arccos(2/8)
thus, angle B is pi/2-A = pi/2-arccos(2/8)
can you see this?
split drum
ok great!
so let's call the time you get to that first angle time 1
you would need to travel pi/3 + pi/2 + angle B to get there right?
slim cloud
yep
split drum
ok so we can use distance (angle in this case) = rate * time
the distance is pi/3 + pi/2 + pi/2 - arccos(2/8)
and the rate is 6pi/min
slim cloud
yeah
split drum
so whats the answer?
slim cloud
so pi/3 + pi/2 + pi/2 - 6pi 2/8
split drum
wait where is that coming from
split drum
we have pi/3 + pi/2 + pi/2 - arccos(2/8) = 6pi * time
split drum
does this make sense?
slim cloud
what is arccos?
split drum
i sincerely suggest you take a look at the khan academy videos
split drum
how about I do it?
slim cloud
ok
split drum
oops
i read something wrong!
sorry the rate isnt 6pi
it travels 2pi in 6 minutes
so the rate is pi/3 per minute
do you understand?
im so sorry
split drum
yep!
so the answer is 2.7413 minutes
(pi/3 + pi/2 + pi/2 - arccos(2/8)) = x*pi/3
if you solve this
split drum
try to understand that
slim cloud
e. What are the first two times to the nearest second, when the passenger is 12 ...
but it says first TWO times?
wouldn't there be 2 values
slim cloud
ok
split drum
alright
the next time this ferris wheel hits 12m above the ground
is at the right side of the image
you would have traveled pi/3 + pi + angle A to get there right
slim cloud
yeah
split drum
so can you try to find this?
slim cloud
sure
split drum
cool!
split drum
it would be + arccos(2/8)
slim cloud
o
slim cloud
ah ok
you might need to add the distance from the ground for it! think about why you might need to do that, read the question!!
Yo for b) she said add 2
marsh citrusBOT
@slim cloud Has your question been resolved?
still temple
marsh citrusBOT
marsh citrusBOT
@still temple Has your question been resolved?
still temple
.close
still temple
how do we assume a | the right hand side? i.e acu + bcv
marsh citrusBOT
how do we assume a | the right hand side? i.e acu + bcv
still temple
<@&286206848099549185>
marsh citrusBOT
@still temple Has your question been resolved?
still temple
<@&286206848099549185> π
shell current
how do we assume a | the right hand side? i.e acu + bcv
where is the acu + bcv part?
Wait sorry I saw it now
shell current
how do we assume a | the right hand side? i.e acu + bcv
I'm a bit confused, please give me time too
since d is the GCD of a and b, d | a
not a | d
still temple
I'm a bit confused, please give me time too
alright np lmk if ur looking for more context
still temple
I'm a bit confused, please give me time too
actually im on part 2
shell current
actually im on part 2
Yeah I know
wait
I think I get their meaning now
See, the proof says assume gcd(a,b) = 1. Then, gcd(a,b) = au + bv.
1 = au + bv
Therefore, c = acu + bcv
Their conclusion is incorrect, I think. How did they conclude a divides the right hand side, if a and b are coprime, and you know nothing about v and c?
π€
still temple
thats waht im thinking π
shell current
If a | acu + bcv, a | bcv, since a | acu. But b is coprime to a, so it can't contribute any factors of a. c and v is something we know nothing about
still temple
ill just skip that problem ig. thanks for clarification
shell current
Their conclusion makes no sense without them telling why their statement is true
shell current
ill just skip that problem ig. thanks for clarification
No problem
still temple
.close
fair pagoda
can someone help explain how to integrate 10/5x^2
marsh citrusBOT
can someone help explain how to integrate 10/5x^2
main idol
Do you know power rule
still temple
$\int_{}^{} \frac{10}{5x^2} dx$
elfin berryBOT
Pi Creature
fair pagoda
i tried just simplifying it then deriving it so i got something like 2/x^2
still temple
$\int_{}^{} \frac{2}{x^2} dx$
now bring the constants outside the integral
And use power rule
$\int_{}^{} x^a dx = \frac{x^{a+1}}{a+1}$
elfin berryBOT
Pi Creature
still temple
Where $a \neq -1$ and a is a real number
elfin berryBOT
Pi Creature
still temple
@fair pagoda does that make sense?
elfin berryBOT
Pi Creature
fair pagoda
kinda so i got 2x^2 once i used the power rule right?
still temple
I missed the dx last time while writing
still temple
kinda so i got 2x^2 once i used the power rule right?
$2 \int_{}^{} \frac{1}{x^2} dx$
elfin berryBOT
Pi Creature
still temple
U got till here?
fair pagoda
yeah around that
still temple
Now convert $\frac{1}{x^2}$ to $x^{-2}$ and try to use power rule
elfin berryBOT
Pi Creature
fair pagoda
x^-1/-1?
elfin berryBOT
Pi Creature
fair pagoda
-2/x?
still temple
Yes
fair pagoda
thank you if you dont mind this could you check this for me cause this was just part of a whole answer
for this it would it be? x^6-10x-2/x+C
still temple
Lemme solve it
still temple
for this it would it be? x^6-10x-2/x+C
U messed up one sign
fair pagoda
which one?
still temple
The -2/x
u are substracting -2/x
Which is same as adding 2/x
So it should be addition
Not substraction
lime gate
marsh citrusBOT
lime gate
how do I find the value of k in question 5(b)
mystic minnow
use standard normal z-score in reverse
mystic minnow
?
lime gate
does the value 0.2236 is in standard normal distribution table?
like
P(z < something) = 0.2236
mystic minnow
yes
lime gate
O
mystic minnow
you need more than that
there are a lot of values for -0.7 row
-0.71? -0.72?....... or something else?
lime gate
@mystic minnow may I ask if the P(-0.93 < Z < 1003) = 0.7235
what column should I looking for
mystic minnow
<@334482942506041345> may I ask if the P(-0.93 < Z < 1003) = 0.7235
that's not true
lime gate
wait
@mystic minnow P(-0.93 < Z < 0.1003) = 0.7235
this one
sorry another mistake ;-;
my understanding for the column still weak
mystic minnow
<@334482942506041345> P(-0.93 < Z < 0.1003) = 0.7235
also not true
lime gate
ohh
lime gate
because the question should be P(-0.93 < Z < K) = 0.7235
but I look for my friend answer says that the value of K is 0.1003
mystic minnow
nope, not true.
lime gate
rip ;- ;
mystic minnow
my guess is your friend is confusing probability and z-score
lime gate
I have the same fate with my friend T-T
mystic minnow
what question are you trying to answer?
this is different than the one you posted.
lime gate
I think I want to find the new answer of this P(-0.93 < Z < K) = 0.7235
after finding the K
I want to know which column is it to get the 0.7235
mystic minnow
you know P(-0.93 < Z < K) = P(Z<K) - P(Z<-0.93)
You can find P(Z<-0.93) on the table I posted above.
mystic minnow
yep
mystic minnow
So, P(Z<K) - 0.1762 = 0.7235
lime gate
So, P(Z<K) - 0.1762 = 0.7235
so to find K I need to subtract 0.7235 with 0.1762?
mystic minnow
how would you solve x - 0.1762 = 0.7235
mystic minnow
,w 0.7235+0.1762
elfin berryBOT
lime gate
wait I mean 0.8997
mystic minnow
and yes, you find that on the z-table
lime gate
my brain is f__ with me rn
mystic minnow
π€· it happens. Yesterday I was certain 1 - .8 was negative.
mystic minnow
that's the k-value yes. (also called a z-score)
lime gate
ah I see
mystic minnow
but just to be clear. If we were working on your original question P(X<k) then there'd be an extra step
we'd have to convert the z-score back to the x-values
since z is a 'standard normal variable' and x is just a 'normal variable'
lime gate
ah yes
I did that on 5(a)
anyways thank you @mystic minnow for helping me ^^
.close
dawn rune
How do I find g
marsh citrusBOT
How do I find g
dawn rune
indigo night
the radius always make 90 degrees wiith a tangent
dawn rune
So I do 90 - 57 to find the angle of the triangle next to 57?
faint pewter
lime gate
last question about probability standard normal distribution ;-;
marsh citrusBOT
last question about probability standard normal distribution ;-;
lime gate
how can I interpret age of 18 and 24 is randomly selected
p(18*24 > 120)
is it like that?
or
something else
stoic saddle
no, the numbers 18 and 24 actually have nothing to do with the calculations in this problem.
stoic saddle
yes
fair pagoda
marsh citrusBOT
fair pagoda
im confused abou this problem so far i think i understand that i have to do something along the lines of xy then plug the equation of y into the area idk if im headed into the correct direction or not.
marsh citrusBOT
@fair pagoda Has your question been resolved?
fair pagoda
.close
final arch
I'm quite stuck on this so can anyone help?
marsh citrusBOT
I'm quite stuck on this so can anyone help?
zealous copper
I'm quite stuck on this so can anyone help?
Think about if the pencil can fit diagonally
craggy maple
no it cannot
marsh citrusBOT
@final arch Has your question been resolved?
marsh citrusBOT
craggy maple
$\frac{dy}{dx}=\frac{dy/dt}{dx/dt}$
elfin berryBOT
Trystnest
marsh citrusBOT
@pale thunder Has your question been resolved?
marsh citrusBOT
marsh citrusBOT
Available help channel!
slim pine
The Volume of a sphere is 60ft^3
Find the surface area
marsh citrusBOT
The **Volume** of a sphere is 60ft^3
**Find the surface area**
slim pine
My answer always comes out to 159, it should be 74.12 not sure what I am doing wrong
60Ο = 4/3Οr^3
V
45=r^3
V
3.56
V
4Ο 3.56^2
V
distant night
slim pine
but volume is cubed already right?
nova totem
Well you can either solve for r
Or
You can solve for a formula of surface area in relation to volume
nova totem
I would just solve for the surface area with respect to volume and then just plug in volume
slim pine
I am undoing the Volume equation to get "r" so I can put it into SF right?
slim pine
π
nova totem
Let $V$ be volume and $S$ be surface area. We know that:
$$V = \frac{4Ο}{3}r^3$$
$$S = 4Οr^2$$
I am going to rearrange the volume formula:
$$r = \sqrt[3]{\frac{3V}{4Ο}}$$
And then I am going to replace that in the surface area formula:
$$S = 4Ο\left(\sqrt[3]{\frac{3V}{4Ο}}\right)^2$$
Bruh
elfin berryBOT
Umbraleviathan
slim pine
oh wow
nova totem
Saves a lotta space
slim pine
no for this I just need the answer....
This equation is pretty complex for me π I am not sure what order I need to do things in.... Like how do I get the cubed root of a fraction?
Thank you for the help though @nova totem I appreciate it
marsh citrusBOT
@slim pine Has your question been resolved?
marsh citrusBOT
@slim pine Has your question been resolved?
raven wasp
conditional probability that East has 3 spades given that
North and South have a combined total of 8 spades.```what do they mean by hand of bridge?
devout mauve
well no. again, I have no clue how bridge works
marsh citrusBOT
Available help channel!
fleet wedge
is anyone able to offer some guidance for this question? I am really not that confident in this level of maths and am getting really confused
marsh citrusBOT
is anyone able to offer some guidance for this question? I am really not that co...
@fleet wedge Has your question been resolved?
tiny pollen
$$a^y+^z+a^x+^z+a^x+^y$$
marsh citrusBOT
$$a^y+^z+a^x+^z+a^x+^y$$
elfin berryBOT
Nayan RBLX
marsh citrusBOT
Available help channel!
wicked matrix
can someone help with part c
marsh citrusBOT
can someone help with part c
@wicked matrix Has your question been resolved?
Available help channel!
winged idol
can i rearrange so it works when a = 1?
marsh citrusBOT
can i rearrange so it works when a = 1?
lean flame
How can you rearrange brother?
winged idol
what do you mean?
marsh citrusBOT
@winged idol Has your question been resolved?
marsh citrusBOT
@winged idol Has your question been resolved?
still temple
not in a continuous way
oh but wait, it's a function depending on 'a' or 'x'?
or both?
marsh citrusBOT
@winged idol Has your question been resolved?
main idol
can i rearrange so it works when a = 1?
Your question is too vague. Do you have the original problem
manic crescent
question is 4cm the height?
marsh citrusBOT
question is 4cm the height?
leaden monolith
question is 4cm the height?
No
leaden monolith
Start with area = 1/2 bc sinA
manic crescent
Start with area = 1/2 bc sinA
wait wot
leaden monolith
Thatβs a formula
bright jay
FYI, easily searchable if you didn't know that existed
manic crescent
Thatβs a formula
area = 1/2b(c)(sin(a))?
isnt c the opposite length
idk if this dumb quesiton
leaden monolith
Man donβt add random brackets
The angle A is opposite the line a
The lines b and c are the 2 around angle A
manic crescent
The angle A is opposite the line a
im sorry which line is a π
nova totem
question is 4cm the height?
Use your trigonometric area of a triangle
manic crescent
The lines b and c are the 2 around angle A
,w 6.75/12
elfin berryBOT
bright jay
Google is an actual calculator, you don't have to use the bot
elfin berryBOT
manic crescent
Google is an actual calculator, you don't have to use the bot
ye im just showing work
to se if im on track
bright jay
ye im just showing work
Then write it out and post it
leaden monolith
,w solve for x, 6.75 = 0.546*sin(x)
elfin berryBOT
leaden monolith
,w solve for x, 6.75 = 0.546*sin(x), 0< x < pi
elfin berryBOT
bright jay
The bot defaults to radians making it harder so using an actual calculator is much easier
bright jay
But you do you, I guess. I gave you the necessary information to solve it
manic crescent
But you do you, I guess. I gave you the necessary information to solve it
uh
is it 34.2289 degrees
@bright jay
bright jay
π
dense verge
marsh citrusBOT
dense verge
where is my math off?
leaden monolith
What even am I looking at
dense verge
sorry that was the trailor
here we go
anyway
I did a 6 player match version of this question
the probablities of a hacker being in a node under the conditions I listed are...
<@&286206848099549185>
Hereβs my recent rework can you check it?
marsh citrusBOT
@dense verge Has your question been resolved?
main idol
Hereβs my recent rework can you check it?
This is impossible to follow. Where's your premise and question for what you're trying to calculate
dense verge
This is impossible to follow. Where's your premise and question for what you're ...
The primise is in the image
actually
But here i'll tell you
In this video game mindnight
I'm calulating the odds that in a 6players game with a outsider looking in who knows nothing about anyone's roles
and people who are voting randomly what are the odds of a hacker being chosen
using a probablity tree
proper zodiac
What do you mean precisely by "a hacker being chosen"?
1 person picking the hacker? A majority? Etc
dense verge
dense verge
1 person picking the hacker? A majority? Etc
if the propotion by a player is accepted what are the odds that prop
will contain a hacker
no hackers 2 hackers
proper zodiac
Sorry my guy but no one is going to watch a video to understand your maths problem
dense verge
does that make sense?
proper zodiac
I think @main idol should take this one, said he was interested
marsh citrusBOT
dense verge
.reopen
marsh citrusBOT
β
marsh citrusBOT
@dense verge Has your question been resolved?
marsh citrusBOT
@dense verge Has your question been resolved?
whole sleet
Well I watched it, lol. Seems fun, I'll check it out
Basically, let's say there's 6 cards, h of them are red, the rest are black. We draw n cards. What's the probability that any of them are red?
Does that sound about right? @dense verge
Instead, we find the probability that there's no reds in the draw. That is, (6-h)/6 Γ (5-h)/5 Γ ... for n products
Then take 1 - that
main idol
I think <@261933205387477002> should take this one, said he was interested
Fake news
dense verge
Basically, let's say there's 6 cards, h of them are red, the rest are black. We ...
sure
dense verge
Basically, let's say there's 6 cards, h of them are red, the rest are black. We ...
yea
dense verge
Instead, we find the probability that there's no reds in the draw. That is, (6-h...
really where is that taught statictics?
or is it....fundamental conuting principal
as i've never seen that before
whole sleet
Common trick for "at least one" problems
dense verge
weird my
whole sleet
Find the probability of none, and realize you've found the complement
dense verge
Find the probability of none, and realize you've found the complement
that's what the finds?
whole sleet
Hmm?
dense verge
likw that formula finds the complement of a probablity?
whole sleet
Let's say there's 6 players, 2 hackers. You want to pick 3 players to form a group.
The probability of getting no hackers in the group is (probability of first draw being good) Γ (probability of second draw being good) Γ (probability of third draw being good)
That is 4/6 Γ 3/5 Γ 2/4
,calc (4/6)( 3/5)(2/4)
dense verge
Let's say there's 6 players, 2 hackers. You want to pick 3 players to form a gro...
oh
elfin berryBOT
Result:
0.2
yep i got 20 percent as well
whole sleet
So an 80% chance a hacker is included
whole sleet
Others?
dense verge
like i am to do every other...
player set
as the limit to players in mindnight is 8
so I gonna do all the combintions for each type of node
on each of the things in mindnight
then post it on the discord
for people to see
and also be goo dpractice for statictics
whole sleet
Well, there is a "common form" for the above formula. See the hypergeometric distribution. We're calculating that, but for 0 hackers
dense verge
hypergeometric distrubution?
whole sleet
So we can make a common formula. Let's say there's N players and n being chosen for a group. There's h hackers and we want the probability of choosing none
dense verge
where is this taught?
whole sleet
Probability/statistics
dense verge
I found it in my textbook but they don't seen to give a formula
whole sleet
We can compress our formula into:
1 - ((N-h)Ch / NCn)
dense verge
oh they do give it
whole sleet
Which is easier to do on calculator
dense verge
but they didn't explain it in the part of the book
they gave the formula in a appendix
OKay that's bad on their part
relally bad
my textbook is open stax statictics
so that's what I'm using
it's online for free
i'm looking at the formula now
oh they just said use a calulator
or computer
but then said ti-83+ adn ti-84 doesn't havea hypergeometric probablity functions
and gave the formula somewhere else
what si this
I forgot my statictics class
what is a distrbution again?
marsh citrusBOT
@dense verge Has your question been resolved?
marsh citrusBOT
@dense verge Has your question been resolved?
mental hare
yes or no
wooden oriole
yes, (-2)^2-4*3*1<0
atomic nest
is this a trick question or is it just 3/4
marsh citrusBOT
is this a trick question or is it just 3/4
limber gull
is this a trick question or is it just 3/4
how did you get that
atomic nest
erm
timber widget
it'll be 3/4, when I was in grade 11, it was taught to us like to remember example, I guess this is taught in ratio and proportions
limber gull
it'll be 3/4, when I was in grade 11, it was taught to us like to remember examp...
uh what
oh
bruh
yeah
atomic nest
haha
limber gull
i misread the question
atomic nest
ok i was really worried that id embarassed myself for a sec
atomic nest
it'll be 3/4, when I was in grade 11, it was taught to us like to remember examp...
tyy
limber gull
dwdw i embarassed myself
timber widget
Time to revise those stuff , if a question comes in the test which uses that property I will be dead π
timber widget
yes you can close I guess, or wait to reverify because I don't remember it very well π
timber widget
welp i put 3/4 as the answer on my exam today so
then you can wait for results π€£
hidden anvil
ive completed the first part, unsure of the second
marsh citrusBOT
ive completed the first part, unsure of the second
hidden anvil
i equated the equation in question to the integral of tan^2 theta as shown in the top right but usually how ive done these is once ive integrated, i sub x = sectheta back into the question
so for this question
tan^2theta = sec^2theta - 1
then do i let sec^2theta = x^2? or do i integrate first
[ tan (theta) - theta ] limits pi/3 and 0
but its the first time im seeing 'theta' by its self after having integrated, the tan (theta) i understand, but is it valid for me to integrate -1 .dtheta to - theta?
... should this be in pre calculus channel? im in y13 (uk) revising for alvls rn not uni stuff so im unsure
back to the question, the part that I'm unsure of is whether i can integrate sec^2theta - 1 .dtheta
to tan(theta) - theta... because then there is no sec(theta) available for me to sub x back into... or do i not need to do that subbing in part at all?
i found that the exact value is sqrt(3) - pi/3
and that matches with when i input the original integral with limits 2 and 1 in calculator
<@&286206848099549185>
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frigid frost
how do i go about solving this
marsh citrusBOT
how do i go about solving this
frigid frost
like what function is it
marsh citrusBOT
@frigid frost Has your question been resolved?
terse thicket
@sour relic
elfin berryBOT
Hunterr
marsh citrusBOT
frigid frost
.reopen
marsh citrusBOT
β
marsh citrusBOT
@frigid frost Has your question been resolved?
marsh citrusBOT
frigid frost
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marsh citrusBOT
Available help channel!
tranquil needle
Pls help with this question
marsh citrusBOT
Pls help with this question
marsh citrusBOT
@tranquil needle Has your question been resolved?
still temple
@tranquil needle are you here
tranquil needle
Yes
still temple
so had you solved a bit..or don't know how to start??
tranquil needle
Nvm I got it thanks anyways
still temple
π okey...
tranquil needle
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hollow saddle
marsh citrusBOT
hollow saddle
Can someone tell me where i went wrong ?
proud pawn
Last step
I mean
$\lim_{x\rightarrow -\infty}\frac{-7x-16}{\sqrt{x^2+x}-x-4}=\lim_{x\rightarrow \infty}\frac{7x-16}{\sqrt{x^2-x}+x-4}=\lim_{x\rightarrow \infty}\frac{7x}{\sqrt{x^2}+x}=\lim_{x\rightarrow \infty}\frac{7x}{2x}=\frac{7}{2}$
Because it is β/β
Same degree
elfin berryBOT
jnkena
marsh citrusBOT
@hollow saddle Has your question been resolved?
marsh citrusBOT
hollow saddle
.reopen
marsh citrusBOT
β
hollow saddle
Is it legal to change -inf to inf :/
glacial hedge
he just made the substitution u = -x but renamed u to x, making it harder to notice
marsh citrusBOT
β
hollow saddle
he just made the substitution u = -x but renamed u to x, making it harder to not...
Wait why is it necessary to do a sub here?
glacial hedge
it isn't, it's just the method they chose to use
hollow saddle
Why canβt i just bring out the x^2 from the square root from the beginning and x-x ?
:/
glacial hedge
because the x in the square root matters. It's specifically this x that makes the result 7/2 instead of 4
hollow saddle
Could you elaborate further?
glacial hedge
if there was no x, then you would have sqrt(xΒ²), which is just |x|, and so the original expression directly simplifies to 4 (for x <= 0). But there's this x in sqrt(xΒ²+x), and so if you try to take the x out of the square root, you would have a small leftover from that x, and it's that leftover that makes the result 7/2 instead of 4
specifically, sqrt(xΒ²+x) + x goes to -0.5 as x goes to -inf, hence the result is 4 + (-0.5) = 7/2
hollow saddle
I thought u can just do sqrt(x^2(1+1/x)) and the root cancels :/
glacial hedge
then you have |x|(sqrt(1+1/x) - 1). Do you think you can show that this goes to -0.5 ?
hollow saddle
Noβ¦..
glacial hedge
so this method, while valid, is not so simple to do properly
hollow saddle
Ah so i gotta remember if thereβs multiple xβs in a square root itβs not possible to just factor the highest power out
glacial hedge
hence using the conjugate to get rid of the square root on the numerator is a good idea because it gets rid of the complicated stuff
you can, but the rest stays in the sqrt
like sqrt(x^4 + x^3 + xΒ²) = |x| sqrt(xΒ²+x+1)
hollow saddle
Ahhh doesnβt really click rn i guess i gotta do more problems
glacial hedge
that's just square root: sqrt(ab) = sqrt(a) sqrt(b)
upper anchor
help
whole linden
you can use similarity but not sure if there are easier ways
upper anchor
can u tell me how to solve it with similarity
@whole linden ?
<@&286206848099549185>
@still temple help
yea
it should be a ratio
no
idk how to get it
marsh citrusBOT
@upper anchor Has your question been resolved?
upper anchor
<@&286206848099549185>
digital spindle
Yeah wait
upper anchor
okok
upper anchor
not giv eup
digital spindle
DAC is similar to dcb
digital spindle
Yeah and that too
upper anchor
uh huh so DAC similar to DCB
upper anchor
huh?
digital spindle
Pause
digital spindle
Acb is not a right angle
digital spindle
Wait it is
upper anchor
it says ABC is right triangle
upper anchor
mhm
digital spindle
And you know ac over bc
upper anchor
yea 1/3
digital spindle
With this 2 information you should be able to do this
upper anchor
idk tho
digital spindle
What is the thing about similar triangles?
upper anchor
they are similar?
elfin berryBOT
Lelouch
digital spindle
Sorry i cant type today
digital spindle
**Lelouch**
And that is cuz dac is similar to DCB
upper anchor
uh huh
digital spindle
In similar triangles the respective sides have the same ratio
And $\frac{AD}{DC}=\frac{CD}{DB}$
elfin berryBOT
Lelouch
digital spindle
You have to find $\frac{AD}{DB}$
elfin berryBOT
Lelouch
digital spindle
Use all the equations above
upper anchor
idk how tho
upper anchor
uh huh im listen
upper anchor
uh huh
digital spindle
Either i tell you how to do it and u basically do nothing and gain no experiance from it
Or maybe u brainstorm a bit more and maybe u solve it
And that will increase ur skill in math
upper anchor
i choose
the 2nd option
but im stuck on how can i find the sides if it dosnt give me any
digital spindle
U don't need any
upper anchor
it gives me a ratio and i dont know what to do with it
digital spindle
I will have you know u have enough resources to solve this question and enough knowledge
Do you have enough skill?
In a Gandalf voice ofc
upper anchor
idk
digital spindle
If you have time , scroll up use the 2 equations i gave you , and think for good 5 to 10 minutes
digital spindle
I'm gonna solve other people's doubts in here meanwhile
Will be back when u ping me , won't be back before 7 minutes
Starts now
upper anchor
ok