#help-33
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$\lim_{n \to \infty} U_n = \exp \lim_{n \to \infty} \left( \sin(2\pi \sqrt[2]{1+n^2}) \frac{1}{2} n\frac{1}{n} \sum_{k=0}^n \ln \left( 1 + \frac{k}{n} \right) \right)$\
$ = \exp \left( \left( \lim_{n \to \infty} \sin(2\pi \sqrt[2]{1+n^2}) \frac{1}{2} n \right) \left( \lim_{n \to \infty} \frac{1}{n} \sum_{k=0}^n \ln \left( 1 + \frac{k}{n} \right) \right) \right)$
ye minus
M8732
This is how you should write it.
You use product of limit
Limit of product = Product of limit of each factor IF (big IF) both factors exist as limits on their own
^ here the second limit in the last line is something
due to your riemann argument (only real limits, no "equivalence")
1/2 -1 = -1/2
ye
Does this make sense?\
$\lim_{n \to \infty} U_n$\
$ = \exp \lim_{n \to \infty} \left( \sin(2\pi \sqrt[2]{1+n^2}) \frac{1}{2} n\frac{1}{n} \sum_{k=0}^n \ln \left( 1 + \frac{k}{n} \right) \right)$
$ = \exp \left( \left( \lim_{n \to \infty} \sin(2\pi \sqrt[2]{1+n^2}) \frac{1}{2} n \right) \left( \lim_{n \to \infty} \frac{1}{n} \sum_{k=0}^n \ln \left( 1 + \frac{k}{n} \right) \right) \right)$\
$ = \exp \left( \left( \lim_{n \to \infty} \sin(2\pi \sqrt[2]{1+n^2}) \frac{1}{2} n \right) \ln(2) \right)$
M8732
This is how you argue watertight.
L'Hôpital?
?
nevermind, not that easily
Taylor expansion and such works fine after you note that sqrt(1+n²) = nsqrt(1+1/n²)
Indeed
the limit is n then
good idea
sin(2pi sqrt(1+n²))=sin(2pi n (sqrt(1+1/n²)-1))
then n(1+n/2 + o(n))
be more careful about the 1/n²
because of the sign?
no because of your expansion
oh ye
just write it as divide by 1/n²
^ and this
n(1+1/2n^2 + o(1/n^2))
no
you expand
sin(x)=x - o(x^2)
you probably do not need higher terms (you also wrote it incorrectly)
(if you wanted more terms it would be x - 1/6 x^3 + ...)
then x have to be expand it
then you need to set x=sqrt(1+n²)-n
$\sin(2\pi \sqrt[2]{1+n^2}) = 2\pi \sqrt[2]{1+n^2} + o(2\pi \sqrt[2]{1+n^2})$
this will not work
^ you need to do this as I said.
tayler expansion only works if argument converges to 0
sqrt(1+n²) explodes
ye
so o(...) will explode too
then we have to do that first
subtract n first
wrong one
you can use
^
sin(2pi sqrt(1+n²)) = sin(2pi (sqrt(1+n²) - n))
idk how you got that, it is probably wrong though.
it doesn't look correct.
put where
with x=1/n^2
sqrt(1+n^2) = nsqrt(1 + 1/n^2)
correct
but what will you do with the n in front
you can't just omit
nothing first
you need to subtract n first and use that sine is periodic.
^ otherwise you will fail.
you expand what inside and then you multiply by n
it is true but still the entire argument (which includes n factor) goes to infinity
so no taylor
It's taylor series.
,w serie expansion of n*sqrt(1 + 1/n^2)
,w serie expansion of n*sqrt(1 + 1/n^2) at +infini
oh you are taylor expanding this?
you can say that
Okay I guess that might work.
Then subtract n.
I was always thinking only about sin.
I would have only taylor expanded sin.
or actually I would have used L'Hôptial instead.
idk what it is
You have not heard of it?
L'Hôpital's rule (, loh-pee-TAHL), also known as Bernoulli's rule, is a mathematical theorem that allows evaluating limits of indeterminate forms using derivatives. Application (or repeated application) of the rule often converts an indeterminate form to an expression that can be easily evaluated by substitution. The rule is named after the 17t...
Very very useful, thought okay, let's put it aside for now.
I didn't know you didn't know. Your limits look advanced, so I assumed you would know this relatively basic rule.
ok i'll check that
sry i must go somewhere right now
i think i have enough clue to finish, thx a lot for your help
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!status
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1
Can you evaluate f(6) and g(7)?
Are you sure about $g(7) = 2(7)^2 - 4$ given that $g(x) = 2x - 4$?
A Lonely Bean
Why don't you now evaluate 6 * 46 - 10^2 + 8 though
184
okay i found my error
Yes 184 is correct
i basically did 184^2
thank q tho
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If R is equipped with the Discrete metric, the set (0,1) is closed. Yes or no? Justify.
On Google it says
For any subset A of a Discrete metric space, every point x in A has an open ball of radius 1/2(x) centered at x that is entirely contained within A.
This is because the open ball contains only point x and no other points from A.
{{{{{****** is it because we are taking radius of 1/2 only and it is a Discrete metric so next point will be one unit away*******}}}}?
Would appreciate if anyone could confirm this
Since, every point in A has an open ball entirely contained within a, A is open.
And then I understood how A complement would be open using the same logic. Thus, set will be closed.
,close
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Not sure how to start
what is the inverse of the logarithm ?
I dunno
did you study logarithms in school ?
yep
What next?
how can you use e^y in the expression y = ln (bla bla) ?
e^(y^4-5) = x?
nope
don't skip steps
write this down
that should be your first step
so y = ln(x^4-5) but also y = e^(ln(x^4-5)) ????
Can you give me a more straightforward hint?
you plugged in the exponential function in the RHS right ?
Yes
and what about the LHS ?
yes
What do I do next?
x
correct. use this fact here
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Two events with nonzero probabilities:
a. cannot be both mutually exclusive and independent and are always mutually exclusive
b. cannot both be both mutually exclusive and independent
ik b is right but idk if a is
"and are always mutually exclusive"
that need not be true in general
in fact if their probabilities add up to more than 1 then they can't be mutually exclusive
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could anyone help me with solving this integral. im able to get down to the 2nd image i sent but after that im kind of lost
for the first integrand of your second page integral, I recommend letting u=tan(4x)
so it would be integral u du?
for the second integrand of your second page integral, I recommend applying the power reduction formula you used previously again
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!help
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ill help
its quick, he is fine, hes new
this channel is going to close
one or two
he can learn to open a new one
so I just started learning systems in school and while solving this system with x, y and z I stumbled upon this system:
x-7z=-3
-3+6z=39
can you help me solve it using elimination?
sure
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should I open another channel?
yes
alright
no
an available one
take over dingle's channel
tyranny
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how do i start this i have no clue
try to use trig identities
@simple gull Has your question been resolved?
which ones
the simplest ones with csc
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how would I graph
y = 5x+2
y = 3x + 0
or like any example works, but how would I graph it
What step are you on?
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1
Aight do u know what a graph is
obviously
Ok do u know what a standard degree 1 graph looks like?
a graph with like one line?
A linear graph
Wow my messages are laggy
Is ur question how to graph both of them with 1 equation or two diff equations?
2 equations
Ok then it’s easy
ok what do I do
Can u show me what a linear graph looks like
What u think!!!
U got it?
Does it look like this?
now do u know what y = x+2 looks like
oh sorryy
In a graph?
yep
just like rough
just make y axis x axis and the estimate line
YEs!
oh now we know that
To graph it
- Identify the slope and y-intercept:
- The coefficient of x, 5, represents the slope of the line.
- The constant term, 2, represents the y-intercept.
@slate blaze do u understand what I mean by slope?
yes slope = multipler
yep
AI-generated answer
To graph the equation y = 5x + 2, you can follow these steps:
- Identify the slope and y-intercept:
- The coefficient of x, 5, represents the slope of the line.
- The constant term, 2, represents the y-intercept.
- Plot the y-intercept:
- Start by plotting the point (0, 2) on the graph. This is where the line intersects the y-axis.
Now plot the y- intercept
U know what the y- intercept is right?
it's the number in the end I believe
so for this equation, its 2?
its the point at where the line crosses the y axis
so it is 2 over here
just like u showed here
alr
Ok did u plot it?
oh
I'm not sure where you are getting confused on, you've been explained this concept multiple times. It's not any different from the other problems you've been doing, all that's different is you have a different slope and y intercept
#help-0 message
I just asked u to plot 0,2
If it's a whole number, like 4, that's just 4/1
this is different it is 2 equations
the last ones were only 1 equation
It's still the same process
You just have multiple to plot
There's nothing different
You just plot more than 1 equation in the same coordinate plane
yeah
Just plot them separately
1 by 1
its nothing but a double point = more marks question
:p
would the run be 1
A line is in the form of y = mx + b, just different variations, like Ax + By = C is one. But the process in plotting a line is the same, plot the y intercept then use the slope. Or you can create a table of values
ok
can u do this ive got a chem question of my own tysm #help-37 imma go try to do that tysm again
You need to label your x axis too
Yeah but I suggest using a ruler to make the lines neater and straighter
hey sorry but can u help me in #bots
so that's what a 2 equation graph is?
that wasn't that hard honestly
it's same like what we did before
yes
thank you so much
That's what I've been telling you
sorry mb
btw do I have to make the lines longer
or is it okay if just connect the dots
It doesn't matter as long at your teacher understands it
make them arrows in the ends
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This is the math that i did
I just don't know how to simplify and get both sides to equal each other
use the fact that $n! = n\cdot (n-1)!$
hayley!
in multiple places :)
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dang okay this one is a little tricky
(I'll post my work bellow )
so I'm left with the indefinite integral sinh(mt)cosh(mt) dt
This identity came to mind but it's not for hyperbolic trig functions!
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oh
we wrote at the same time, calm down.
relax it happens lol
what problem are you having issues with?
idk how to find ex
for the perimeter question?
not dumb just learning 🙂
so what does the perimeter mean?
nah
hm
lol you havne't answered my question
well let's start there. It helps to knowthe defintion
not the area around, rather it's the outer limits of an area.
In other words, its the furthest most border of an object
ok so if we have a rectangle with length l and width w, then the permeter would be l + l + w + w. Make sense so far?
so a square is a polygon with equal lengths, so it'll be l + l + l + l = 4l.
So this is very close, but not quite correct. It'd be x + 3 + x + 3 + x + 3 + x + 3 = 4(x + 3) = 4x + 12. So then it'd be 42 = 4x + 12. now just simply solve for x
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so im lost
I used the quotient rule to get the first part
and now
idk where to go from here
its asking the tangent line at f(x) where x = 1
do you know what a tangent line is?
what
formula for a line is y = mx+b
well we know the slope is 1, and we know it goes through the point (1, f(1))
thats enough to find the y intercept
oh. so my y is just f(1)
say less
i plug it in the point slop form and done
@native frigate thansk
no problem
@halcyon wharf Has your question been resolved?
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Could anyone help me
Hello
what the guy said
What guy
Dont occupy multiple channels @lucid pond
Ohh soz I forgot to close it
Go to the previously one
I closed it!
There one more 11
.close
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stop thanks.
.reopen
✅
It was an accident soz I’m new
u have your old channels open what the hell
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You already posted your question in #help-11, just stay there
its ok, just stick to one channel, very confusing.
#help-11 << click on blue
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simple question, is a function differentiable a point if there is a horizontal tangent?
No
That's not what you said
@main idol you may have misread?
Possibly
"if there is a horizontal tangent at some point, is the function differentiable there?"
@frail raptor is this what you were asking?
Ann will help since she understands you
not only is it differentiable you can even tell the value of the derivative
ok thanks
one more
why cant i send image
can I dm you image?
i got it working
ok and what's your question?
it's the only answer that makes any sense yes
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can someone tell me how I can approach and look at this?
Well this seems to be dealing with the derivative, so finding f'(x) and then testing each option sounds good
may I ask how I would find f'(x)?
no worries :) but in that case, what would I do?
you need to find f(0) and f'(0)
using properties of tangent line
do you know how a tangent line looks like?
I do know that a tangent line is a line that barely touches one point on a graph if that makes sense and cannot cross
more rigorously, the tangent line of f at x is a line that intersect f at x and its slope equals the slope of f at x
and keeping that in mind, how would I find f'(0)? as well as f(0) itself
the graph is tangent line at x = 0
thus it should intersect f at x = 0 and its slope equals slope of f at 0
hmm
it's easier with equations
i'm just not sure on how to look at this graph and find the values
it means if T(x) is the tangent line of f(x) at point a, then f(a) = T(a) and f'(a) = T'(a)
to find f(0) and f'(0), calculate T(0) and T'(0)
The tangent touches f(X) at any particular point, in this case it tells you, at x = 0
meaning the tangent shares that point with f(x) at x = 0 if that makes sense
and then f'(x) is merely just the gradient at any point, and the tangent at that point has the same gradient
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need to just evaluate this, but idk the order of stuff im meant to do
please show the original question
test or homework?
hw
okay so you are given epsilon=1
you must now find a range of values centered around c=1
such that for all values in this range, the difference in absolute value between their output value and 4 is within 1
i plugged in the known values i just dont know how to proceed
do i do the absolute value first, the radical, or what
you want to find the value of $\delta=...$ such that when $$0<|x-1|<\delta \implies |f(x)-4|<1$$
Austin
f(x) being sqrt17-x
yes
but idk how to evaluate the equation further
for example this is another question thats similar just with different values
so this you understand right @next folio ?
$$0<|x-1|<\delta \implies |f(x)-4|<1$$
$$0<|x-1|<\delta \implies |\sqrt{17-x}-4|<1$$
Consider now: for $|\sqrt{17-x}-4|$ to be less than 1, it must be the case that $-1<\sqrt{17-x}-4<1$. Do you understand that?
Austin
@next folio
Austin
Austin
now this is something you can solve
so you tell me @next folio what is the range of x-values that satisfy this inequality?
(3,5)
no
😭
if needed, recall that sqrt(25)=5 and sqrt(9)=3
so your upper bound is 17-x=25
and your lower bound is 17-x=9
you don't need my help solving those equations
likely you didn't need my help for this entire inequality
so let me know once you've decided the range of x-values
and then we can continue
-8 < x < 8
great
now
recall that we are centering our interval around x=1
and as you have just demonstrated
our x-values must fall in -8<x<8
so what is the largest size interval centered at x=1 that stays within -8<x<8
yes
i was just confused about the order of operations i was meant to do it ig
but yea thank you man
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How do I convert Euler angles to Degrees?
So Let's say I have an Euler angle orientation of (60, -180, -180)
How do I find the actual rotation in degrees? like (x value) rotated 220°
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@cyan raft Has your question been resolved?
Hello. What kind of Euler angles are these? ZYZ?
Also, do you want the rotations with respect to the original axes?
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let f be a function twice-differentiable on an interval [a,b], and suppose f has 3 roots in (a,b). what's the minimum number of roots that f'' is guaranteed to have?
@tender mantle Has your question been resolved?
@tender mantle Has your question been resolved?
3?
you do not calculate f'' itself
think about how if f(x) has three zeros this means the graph has to cross the x-axis 3 times
it has to go up and then down and then back up ( in some order )
in order to do that
2
so then f''(x)
F" is in x terms only
he might mean that in the specific case that f(x) = (x-1)(x-2)(x-3), f'' will be a linear function
and those only have one root
Option C?
no need for computation here though arjunn
Why did they write in a weird way?
it would be much quicker to imagine the graph
idk what 2/2, 3/3, and 4/4 mean. like aren't they all just 1?
bruh
they would have written २, ३ and ४ no?
as the Hindi expert here, no those are incorrect Ann
I copied my response off of my brain
Let us ask our supreme leader @static quarry
wha
Guide us
Ann knows hindi
@stark trail so f(x) has 2 place where sign vhanges
F'x will have 1 place where sign changes
F"x no sign changes
So roots will be 1 because it will cut only once
no one said that f'' exists
oh wait
it's so blurry i miscounted the primes
nvm
the dark side has clouded your vision
imagine losing the battle after winning the war
f'' DOES exist
anyway
you need to use rolle's theorem multiple times here
this is not rolles theorem
Should I upload my next question?
are you done w/ this one
Answer is 1 but options are incorrect right?
the options include a "none of these"
so they're not automatically incorrect
sus
maybe there is a disagreement about what "options are incorrect" means
when i see, read or say "options are incorrect", it means that it is impossible to pick one option to answer the question truthfully
but that is NOT the case here, since the last option reads "none of the above".

I do not consider the 4th option as a answer
And no doubt i choose it
4
So next doubt guys
Three vectors are given we need to find for which value of x, volume will be minimum of this rectangle quadrilateral
i'm out
what rectangle quadrilateral
.close
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If I have a sum $$ A = \sum_{i=1}^n \sum_{j=1}^n A_{ij}a_ia_j$$ where $A$ is real and positive, does it follow that $$ A_{ij} = A_{ji}?$$ I can't think of a counterexample, but I also don't know how to prove it.
thedude365
I know we can rewrite $A$ as $$ A = \sum_{j=1}^n \sum_{i=1}^n A_{ij}a_ja_i$$, and because the indices are arbitrary, we can also write $A$ as $$ A = \sum_{j=1}^n \sum_{i=1}^n A_{ji}a_ja_i$$
thedude365
but that doesn't seem like enough to show that $A_{ij} = A_{ij}$
thedude365
so.... you need to fill in a lot of missing info here.
what is A? what is A_ij? what is a_j and a_i?
My question is adapted from a physics problem in which A is kinetic energy, A_ij is a generalized mass term, and a_i, a_j are the magnitudes of generalized velocities. The physics lingo only tells me that all terms are real and positive
It's completely possible that there is no way to prove this with the available information
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Why am I wrong?
u' = 0
a is not dependent on x, so its a constant and its derivative is 0.
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π x a ÷ π squared
$\frac{\pi a}{\pi^2}$?
AℤØ
Yes.
A = 68.
whats the issue
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hello, im new to proofs and there are a few things that i do not understand about this proof:
- how does this proof prove the division with remainder theorem?
- why is b+ka used instead of aq+r?
- why must b+ka≥0?
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idk where to begin
i think is something like this
oh ok ty
Gauss is overkill for this 
XD
i think thats wrong
oh i didnt do it yet
im working on another one rn but as soon as im done ill do it
ok do it patiently
yea
i know whats wrong
Absolutely, lol
Subtract 5 times the second equation from the first, leaving you with 3y = 42 and so y = 14. Thus, x = 30.
making matrix is the only way i remember 😦
yep
could u help w one more
lets see
what abt the speed of the current
like the speed of the water
im confused
distance = 10
time that it took to complete those 10 km= 2
speed = v
speed = d/t
speed = 10/2 km/h
dont forget say km/h
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Please don't occupy multiple help channels.
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Given an arithmetic sequence a_n that has 36 elements such that:
a_3 + a_7 + a_18 +a_30 = 248
Calculate the sum first 23 numbers in the series
How can I solve this?
i used a_n=a_1 + (n-1)d and got 2a_1 +27d = 124
how can I move on
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can someone help with this pls?
So what’s A B and C
Show your work, and if possible, explain where you are stuck.
$\frac{a + b}{c} = \frac{a}{c} + \frac{b}{c}$
dldh06
A = -129
B = -44√2
C = 113
im not sure..
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so is it
A = -129/113
B = -44/113
C = √2
You need to separate the fraction like I showed
Then simplify if needed
so i need to seperate this into fractions?
.
A = -129/113
B = 44/113
C = 2
Looks like it
thank you
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Source: Terence Tao's Solving Mathematical Problems
The solution provided is good, but I wanna know if what I am doing is possible to continue
I will type my solution out
Let $\phi(x)$ be the sum of the digits of x, and $\sigma(x)$ be the number of digits in x \
Now when I rearrange digits, the number of digits (i.e. $\sigma(x)$) and the digits themselves (and thus their sums i.e. $\phi(x)$) will remain same. \
$\Rightarrow$ I need to find two powers of 2 (say $2^n$ and $2^m$) such that $\phi(2^n) = \phi(2^m)$ and $\sigma(2^n) = \sigma(2^m)$ \
Now, we can rewrite $2^n$ as $10^{n \log_{10} 2}$. Since $10^x$ has x+1 digits, therefore $2^n$ has $\lfloor n \log_{10} 2 + 1 \rfloor$ digits. \
$\Rightarrow \sigma(2^n) = \lfloor n \log_{10} 2 + 1 \rfloor$ \
Now when we write the domain and range of $\sigma(2^n)$ as $n$ increases by 1, we notice a pattern. If 10 divides n, then the next three consecutive powers of 2 have the same number of digits. If 10 doesnt divide n, then the next two consecutive powers of 2 have the same number of digits.
hold on what
?
ItzKraken
so you're saying that if n = 10k, then 2^n, 2^(n+1), 2^(n+2) and 2^(n+3) always have the same digit count?
no, if n=10k
er yes sorry
lemme write the proof for it
,w number of digits in 2^100
,w number of digits in 2^103
you are just wrong
Nani!
Ann
its approximately no?
if I were to take a finer approximation
could I find a version of this conjecture which is true for all n?
No. No matter what small part you leave out of consideration, that multiplied with a big enough n will contribute to greatest integer function.
I probably didn't put that well.
I meant like if you leave 10^(-100) then, that'll also be 1 when multiplied with numbers bigger than 10^100.
I think i got it..What you are trying to say is that there is always a n big enough such that the conjecture will be false
yes thats exactly what I was thinking
floor is known greatest integer function?
Yes.
i see
Somehow, i'm used to saying greatest integer function.
I find that term confusing
well tysm..Since everything after this is based on my conjecture being true, I suppose its also wrong
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I can't understand how cos(3π/2 + θ) becomes sinθ...
My understanding is at this level.
According to which, I conclude it should be -cosθ.
Well, do you agree that the cos θ sort of corresponds to the "x-coordinate" in the unit circle?
Actually, you can even see it in the top left drawing
But from that logic, cos(90°+θ) should be -sinθ
Is that correct?
That's right
I'm guessing you guys haven't talked about sines and cosines of the sum of angles
ty for help.
I just miss read the sin 90+θ in google.
Yah. Sir just assumed we know.
ty for help.
Sure
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Guys last time on test i had to get lerner indeks (square below) from the thing above
but i fail
anyone understand how?
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Hi !
ok just one moment
these fucking black bars are each 13.5 times taller than the original image.
seriously?
Fr 😭
Yeah sorry
the problem itself goes:
Solve the inequality $\sqrt{ax+1} \geq x$
Ann
Yes
do you have any info about the letter a?
No
i have trouble believing you weren't told anything else.
but like ok you probably want to at least break into cases based on the sign of a
It's Say based on the values off the parametre a
do you have a pic of the assignment you got this problem in
or the textbook whatever
?
I don't know how toi solve it
What
Ok
