#help-33

1 messages · Page 58 of 1

young owl
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not even equal right there

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why a +

scarlet hinge
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$\lim_{n \to \infty} U_n = \exp \lim_{n \to \infty} \left( \sin(2\pi \sqrt[2]{1+n^2}) \frac{1}{2} n\frac{1}{n} \sum_{k=0}^n \ln \left( 1 + \frac{k}{n} \right) \right)$\
$ = \exp \left( \left( \lim_{n \to \infty} \sin(2\pi \sqrt[2]{1+n^2}) \frac{1}{2} n \right) \left( \lim_{n \to \infty} \frac{1}{n} \sum_{k=0}^n \ln \left( 1 + \frac{k}{n} \right) \right) \right)$

gray shale
elfin berryBOT
scarlet hinge
#

This is how you should write it.

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You use product of limit

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Limit of product = Product of limit of each factor IF (big IF) both factors exist as limits on their own

gray shale
#

or we can write it with series

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the right part is fine

scarlet hinge
#

due to your riemann argument (only real limits, no "equivalence")

gray shale
#

1/2 -1 = -1/2

scarlet hinge
#

wrong

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wait

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oh yeah I see the mistake

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we integrated ln incorrectly.

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wrong

gray shale
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ok ye

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it's (x+1)ln(1+x) - (1+x)
so 2ln(2) - ln(2) + ln(1)

scarlet hinge
#

so ln(2)

gray shale
#

ye

scarlet hinge
#

Does this make sense?\
$\lim_{n \to \infty} U_n$\
$ = \exp \lim_{n \to \infty} \left( \sin(2\pi \sqrt[2]{1+n^2}) \frac{1}{2} n\frac{1}{n} \sum_{k=0}^n \ln \left( 1 + \frac{k}{n} \right) \right)$
$ = \exp \left( \left( \lim_{n \to \infty} \sin(2\pi \sqrt[2]{1+n^2}) \frac{1}{2} n \right) \left( \lim_{n \to \infty} \frac{1}{n} \sum_{k=0}^n \ln \left( 1 + \frac{k}{n} \right) \right) \right)$\
$ = \exp \left( \left( \lim_{n \to \infty} \sin(2\pi \sqrt[2]{1+n^2}) \frac{1}{2} n \right) \ln(2) \right)$

gray shale
#

ye

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for the sin i have no idea though

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if only i could perform a serie

elfin berryBOT
scarlet hinge
#

This is how you argue watertight.

scarlet hinge
gray shale
#

?

scarlet hinge
#

nevermind, not that easily

young owl
#

Taylor expansion and such works fine after you note that sqrt(1+n²) = nsqrt(1+1/n²)

scarlet hinge
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I think the point is that sqrt(1+n²) is almost n

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but a tiny bit bigger

young owl
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Indeed

gray shale
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the limit is n then

scarlet hinge
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sin(2pi sqrt(1+n²))=sin(2pi n (sqrt(1+1/n²)-1))

gray shale
#

then n(1+n/2 + o(n))

young owl
#

be more careful about the 1/n²

gray shale
#

because of the sign?

young owl
#

no because of your expansion

scarlet hinge
#

L'Hôpital might work

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It probably will work.

gray shale
#

oh ye

scarlet hinge
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just write it as divide by 1/n²

scarlet hinge
gray shale
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n(1+1/2n^2 + o(1/n^2))

scarlet hinge
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you expand

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sin(x)=x - o(x^2)

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you probably do not need higher terms (you also wrote it incorrectly)

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(if you wanted more terms it would be x - 1/6 x^3 + ...)

gray shale
scarlet hinge
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then you need to set x=sqrt(1+n²)-n

gray shale
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$\sin(2\pi \sqrt[2]{1+n^2}) = 2\pi \sqrt[2]{1+n^2} + o(2\pi \sqrt[2]{1+n^2})$

elfin berryBOT
scarlet hinge
#

this will not work

scarlet hinge
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tayler expansion only works if argument converges to 0

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sqrt(1+n²) explodes

gray shale
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ye

scarlet hinge
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so o(...) will explode too

gray shale
scarlet hinge
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subtract n first

gray shale
#

wrong one

scarlet hinge
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you can use

gray shale
scarlet hinge
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sin(2pi sqrt(1+n²)) = sin(2pi (sqrt(1+n²) - n))

scarlet hinge
#

it doesn't look correct.

gray shale
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you put n in factor

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then you have somthing that tend to 0 so you can expand it

scarlet hinge
gray shale
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with x=1/n^2

gray shale
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sqrt(1+n^2) = nsqrt(1 + 1/n^2)

scarlet hinge
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but what will you do with the n in front

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you can't just omit

gray shale
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nothing first

scarlet hinge
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you need to subtract n first and use that sine is periodic.

scarlet hinge
gray shale
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you expand what inside and then you multiply by n

scarlet hinge
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so no taylor

gray shale
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it's not taulor

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it's series

scarlet hinge
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It's taylor series.

gray shale
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,w serie expansion of n*sqrt(1 + 1/n^2)

gray shale
#

,w serie expansion of n*sqrt(1 + 1/n^2) at +infini

scarlet hinge
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oh you are taylor expanding this?

gray shale
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you can say that

scarlet hinge
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Okay I guess that might work.

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Then subtract n.

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I was always thinking only about sin.

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I would have only taylor expanded sin.

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or actually I would have used L'Hôptial instead.

gray shale
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idk what it is

scarlet hinge
#

You have not heard of it?

gray shale
#

nah

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so when n tend +infini sin ten to 0 because 2pi*n

scarlet hinge
#

L'Hôpital's rule (, loh-pee-TAHL), also known as Bernoulli's rule, is a mathematical theorem that allows evaluating limits of indeterminate forms using derivatives. Application (or repeated application) of the rule often converts an indeterminate form to an expression that can be easily evaluated by substitution. The rule is named after the 17t...

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Very very useful, thought okay, let's put it aside for now.

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I didn't know you didn't know. Your limits look advanced, so I assumed you would know this relatively basic rule.

gray shale
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ok i'll check that

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sry i must go somewhere right now
i think i have enough clue to finish, thx a lot for your help

scarlet hinge
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alright

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good luck

gray shale
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thx

#

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still temple
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spare current
marsh citrusBOT
marsh peak
#

!status

marsh citrusBOT
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spare current
#

1

marsh peak
#

Can you evaluate f(6) and g(7)?

spare current
marsh peak
#

Are you sure about $g(7) = 2(7)^2 - 4$ given that $g(x) = 2x - 4$?

elfin berryBOT
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A Lonely Bean

marsh peak
#

Ah okay nvm

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Right so f(6) = 46 and g(7) = 10

spare current
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yea

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its what i do with the ^2

marsh peak
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Why don't you now evaluate 6 * 46 - 10^2 + 8 though

marsh peak
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What do you get?

spare current
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184

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okay i found my error

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Yes 184 is correct

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i basically did 184^2

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thank q tho

#

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still temple
#

If R is equipped with the Discrete metric, the set (0,1) is closed. Yes or no? Justify.

On Google it says

For any subset A of a Discrete metric space, every point x in A has an open ball of radius 1/2(x) centered at x that is entirely contained within A.
This is because the open ball contains only point x and no other points from A.

{{{{{****** is it because we are taking radius of 1/2 only and it is a Discrete metric so next point will be one unit away*******}}}}?
Would appreciate if anyone could confirm this

Since, every point in A has an open ball entirely contained within a, A is open.

And then I understood how A complement would be open using the same logic. Thus, set will be closed.

mint sonnet
#

,close

marsh citrusBOT
#

@still temple Has your question been resolved?

marsh citrusBOT
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marsh citrusBOT
lyric bay
#

Not sure how to start

gentle ledge
#

what is the inverse of the logarithm ?

lyric bay
gentle ledge
#

did you study logarithms in school ?

lyric bay
#

Ohhh

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I forgot

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Sorry, I mean e^y

gentle ledge
#

yep

lyric bay
gentle ledge
#

how can you use e^y in the expression y = ln (bla bla) ?

lyric bay
gentle ledge
main idol
lyric bay
#

x = ln(y^4 - 5)?

main idol
#

that should be your first step

lyric bay
#

I'm really confused

gentle ledge
lyric bay
gentle ledge
#

you plugged in the exponential function in the RHS right ?

lyric bay
#

Yes

gentle ledge
#

and what about the LHS ?

lyric bay
#

e^y = e^(ln(x^4-5))

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Like this you mean?

gentle ledge
lyric bay
gentle ledge
#

screw latex

lyric bay
gentle ledge
lyric bay
#

Ohh thanks

#

I get how to solve it now

#

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gloomy salmon
#

Two events with nonzero probabilities:
a. cannot be both mutually exclusive and independent and are always mutually exclusive
b. cannot both be both mutually exclusive and independent

gloomy salmon
#

ik b is right but idk if a is

static quarry
#

"and are always mutually exclusive"

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that need not be true in general

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in fact if their probabilities add up to more than 1 then they can't be mutually exclusive

marsh citrusBOT
#

@gloomy salmon Has your question been resolved?

gloomy salmon
#

oh yeh

#

ok thx

marsh citrusBOT
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rich mica
#

could anyone help me with solving this integral. im able to get down to the 2nd image i sent but after that im kind of lost

stark trail
#

for the first integrand of your second page integral, I recommend letting u=tan(4x)

rich mica
#

so it would be integral u du?

stark trail
#

for the second integrand of your second page integral, I recommend applying the power reduction formula you used previously again

rich mica
#

ah okay

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i just need to split the second one up again

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perfect thank you

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pseudo ore
#

hey guys

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can somebody help me with a basic algebra issue?

stark trail
marsh citrusBOT
blazing oxide
#

OK

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sure

blazing oxide
blazing oxide
stark trail
#

this channel is going to close

blazing oxide
stark trail
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he can learn to open a new one

blazing oxide
#

when a mod close

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ill stop

pseudo ore
# blazing oxide ill help

so I just started learning systems in school and while solving this system with x, y and z I stumbled upon this system:
x-7z=-3
-3+6z=39
can you help me solve it using elimination?

marsh citrusBOT
pseudo ore
#

should I open another channel?

stark trail
#

yes

pseudo ore
#

alright

blazing oxide
#

no

stark trail
#

an available one

blazing oxide
#

ye do that

gloomy salmon
#

take over dingle's channel

blazing oxide
#

do that

#

its open

gloomy salmon
#

tyranny

marsh citrusBOT
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simple gull
#

how do i start this i have no clue

marsh citrusBOT
main idol
#

try to use trig identities

marsh citrusBOT
#

@simple gull Has your question been resolved?

simple gull
main idol
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slate blaze
#

how would I graph
y = 5x+2
y = 3x + 0

marsh citrusBOT
slate blaze
vale cypress
#

!status

marsh citrusBOT
#
What step are you on?
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6. None of the above
slate blaze
#

1

vale cypress
slate blaze
#

obviously

vale cypress
#

Ok do u know what a standard degree 1 graph looks like?

slate blaze
#

a graph with like one line?

gray shoal
#

so yeah

vale cypress
#

A linear graph

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Wow my messages are laggy

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Is ur question how to graph both of them with 1 equation or two diff equations?

slate blaze
#

2 equations

vale cypress
#

Ok then it’s easy

slate blaze
#

ok what do I do

vale cypress
slate blaze
#

from google?

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or from what I think?

vale cypress
#

U got it?

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Does it look like this?

slate blaze
vale cypress
#

yep

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good

slate blaze
#

but now we need 2 lines

vale cypress
#

now do u know what y = x+2 looks like

vale cypress
#

wait

slate blaze
#

oh sorryy

vale cypress
#

ur good :)

slate blaze
vale cypress
#

just like rough

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just make y axis x axis and the estimate line

slate blaze
vale cypress
#

YEs!

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oh now we know that

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To graph it

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  1. Identify the slope and y-intercept:
  • The coefficient of x, 5, represents the slope of the line.
  • The constant term, 2, represents the y-intercept.
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@slate blaze do u understand what I mean by slope?

slate blaze
#

yes slope = multipler

vale cypress
vale cypress
# slate blaze yes slope = multipler

AI-generated answer
To graph the equation y = 5x + 2, you can follow these steps:

  1. Identify the slope and y-intercept:
  • The coefficient of x, 5, represents the slope of the line.
  • The constant term, 2, represents the y-intercept.
  1. Plot the y-intercept:
  • Start by plotting the point (0, 2) on the graph. This is where the line intersects the y-axis.
#

Now plot the y- intercept

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U know what the y- intercept is right?

slate blaze
#

so for this equation, its 2?

vale cypress
#

so it is 2 over here

vale cypress
slate blaze
#

alr

vale cypress
#

Ok did u plot it?

slate blaze
vale cypress
#

OOps

#

ummm

#

thats wrong :/

slate blaze
#

oh

bright jay
vale cypress
#

I just asked u to plot 0,2

bright jay
slate blaze
#

isn't it y = 5x+2

slate blaze
#

the last ones were only 1 equation

bright jay
#

It's still the same process

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You just have multiple to plot

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There's nothing different

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You just plot more than 1 equation in the same coordinate plane

vale cypress
#

yeah

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Just plot them separately

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1 by 1

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its nothing but a double point = more marks question

#

:p

slate blaze
bright jay
# slate blaze this is different it is 2 equations

A line is in the form of y = mx + b, just different variations, like Ax + By = C is one. But the process in plotting a line is the same, plot the y intercept then use the slope. Or you can create a table of values

slate blaze
#

ok

vale cypress
slate blaze
#

ok

#

ty

#

@bright jay

#

is that correct

bright jay
#

You need to label your x axis too

slate blaze
#

after that

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am I finished

bright jay
#

Yeah but I suggest using a ruler to make the lines neater and straighter

vale cypress
slate blaze
#

that wasn't that hard honestly

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it's same like what we did before

vale cypress
#

yes

slate blaze
#

thank you so much

bright jay
slate blaze
#

btw do I have to make the lines longer

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or is it okay if just connect the dots

bright jay
#

It doesn't matter as long at your teacher understands it

vale cypress
#

make them arrows in the ends

slate blaze
#

ok thank youuu

#

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summer bane
marsh citrusBOT
summer bane
#

This is the math that i did

#

I just don't know how to simplify and get both sides to equal each other

elfin berryBOT
quaint elm
#

use the fact that $n! = n\cdot (n-1)!$

elfin berryBOT
#

hayley!

quaint elm
#

in multiple places :)

summer bane
#

k. Thanks, Ill try it

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jolly sigil
marsh citrusBOT
jolly sigil
#

dang okay this one is a little tricky

#

(I'll post my work bellow )

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so I'm left with the indefinite integral sinh(mt)cosh(mt) dt

#

This identity came to mind but it's not for hyperbolic trig functions!

marsh citrusBOT
#

@jolly sigil Has your question been resolved?

jolly sigil
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sudden hazel
marsh citrusBOT
sudden hazel
#

oh

rancid junco
#

we wrote at the same time, calm down.

hollow sparrow
#

relax it happens lol

hollow sparrow
sudden hazel
#

idk how to find ex

hollow sparrow
#

for the perimeter question?

sudden hazel
#

Yeah

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That’s it and than I’m good

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cause I’m dumb

hollow sparrow
#

so what does the perimeter mean?

sudden hazel
#

Oh wait

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It has a perimeter of 42

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So would it be 42/3?

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idk

hollow sparrow
#

nah

sudden hazel
#

hm

hollow sparrow
#

what is the perimeter?

#

by definition

sudden hazel
#

Its got 4 sides and it’s js adding them up

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Wait

hollow sparrow
#

lol you havne't answered my question

sudden hazel
#

42=4x+3

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Oh

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Hm

#

Idk

hollow sparrow
#

well let's start there. It helps to knowthe defintion

sudden hazel
#

It’s the area around

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The line parts

hollow sparrow
#

not the area around, rather it's the outer limits of an area.

In other words, its the furthest most border of an object

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ok so if we have a rectangle with length l and width w, then the permeter would be l + l + w + w. Make sense so far?

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so a square is a polygon with equal lengths, so it'll be l + l + l + l = 4l.

hollow sparrow
# sudden hazel 42=4x+3

So this is very close, but not quite correct. It'd be x + 3 + x + 3 + x + 3 + x + 3 = 4(x + 3) = 4x + 12. So then it'd be 42 = 4x + 12. now just simply solve for x

sudden hazel
#

oh

#

Ohhh I get it now

#

ty

sudden hazel
#

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halcyon wharf
#

so im lost

marsh citrusBOT
halcyon wharf
#

I used the quotient rule to get the first part

#

and now

#

idk where to go from here

native frigate
#

its asking the tangent line at f(x) where x = 1

native frigate
halcyon wharf
#

yeah

#

1

#

i think

native frigate
#

what

halcyon wharf
#

what

#

well

#

What i did is plug in 1 and i got 4/4

#

or what do i do

native frigate
#

yes

#

thats the right slope

halcyon wharf
#

slope yes

#

can idk where to move from there

native frigate
#

formula for a line is y = mx+b

halcyon wharf
#

yes i am missing a b

#

i dont know how to get it

native frigate
#

well we know the slope is 1, and we know it goes through the point (1, f(1))

#

thats enough to find the y intercept

halcyon wharf
#

oh. so my y is just f(1)

#

say less

#

i plug it in the point slop form and done

#

@native frigate thansk

native frigate
#

no problem

marsh citrusBOT
#

@halcyon wharf Has your question been resolved?

#
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lucid pond
#

Could anyone help me

marsh citrusBOT
#

Please don't occupy multiple help channels.

queen seal
#

Amy

#

Did you even read

lucid pond
#

Hello

queen seal
#

what the guy said

lucid pond
#

What guy

still temple
#

Dont occupy multiple channels @lucid pond

queen seal
lucid pond
#

Ohh soz I forgot to close it

still temple
#

Go to the previously one

lucid pond
#

I closed it!

still temple
tacit fjord
#

.close

marsh citrusBOT
#
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tacit fjord
#

stop thanks.

lucid pond
#

.reopen

marsh citrusBOT
#

lucid pond
#

It was an accident soz I’m new

tacit fjord
#

u have your old channels open what the hell

bright jay
#

.close

marsh citrusBOT
#
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lucid pond
#

I didn’t know bro

bright jay
#

You already posted your question in #help-11, just stay there

lucid pond
#

I pressed off

#

And I didn’t know how to find it

tacit fjord
#

its ok, just stick to one channel, very confusing.

still temple
marsh citrusBOT
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frail raptor
#

simple question, is a function differentiable a point if there is a horizontal tangent?

frail raptor
#

its not differentiable?

#

why not tho

main idol
stoic saddle
#

@main idol you may have misread?

main idol
#

Possibly

stoic saddle
#

"if there is a horizontal tangent at some point, is the function differentiable there?"

stoic saddle
main idol
#

Ann will help since she understands you

frail raptor
#

at that point

#

yes

#

yes

stoic saddle
#

not only is it differentiable you can even tell the value of the derivative

frail raptor
#

one more

#

why cant i send image

#

can I dm you image?

stoic saddle
#

you should be able to send images here

#

what does it say when you try?

frail raptor
#

i got it working

stoic saddle
#

ok and what's your question?

frail raptor
#

is that the right answer

#

when I graph it the first answer makes the most sense

stoic saddle
#

it's the only answer that makes any sense yes

frail raptor
#

.close

marsh citrusBOT
#
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sonic elm
marsh citrusBOT
sonic elm
#

can someone tell me how I can approach and look at this?

young laurel
#

Well this seems to be dealing with the derivative, so finding f'(x) and then testing each option sounds good

sonic elm
young laurel
#

You can solve for f(x) and then use power rule to derive

#

to f'(x)

cunning basin
#

?

#

the line is not f

#

it's the tangent line

young laurel
#

oh shit i can't read

#

my bad

sonic elm
#

no worries :) but in that case, what would I do?

cunning basin
#

you need to find f(0) and f'(0)

#

using properties of tangent line

#

do you know how a tangent line looks like?

sonic elm
#

I do know that a tangent line is a line that barely touches one point on a graph if that makes sense and cannot cross

cunning basin
#

more rigorously, the tangent line of f at x is a line that intersect f at x and its slope equals the slope of f at x

sonic elm
#

and keeping that in mind, how would I find f'(0)? as well as f(0) itself

cunning basin
#

the graph is tangent line at x = 0

#

thus it should intersect f at x = 0 and its slope equals slope of f at 0

#

hmm

#

it's easier with equations

sonic elm
#

i'm just not sure on how to look at this graph and find the values

cunning basin
#

to find f(0) and f'(0), calculate T(0) and T'(0)

young laurel
#

meaning the tangent shares that point with f(x) at x = 0 if that makes sense

#

and then f'(x) is merely just the gradient at any point, and the tangent at that point has the same gradient

marsh citrusBOT
#

@sonic elm Has your question been resolved?

marsh citrusBOT
#
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marsh citrusBOT
#
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next folio
#

need to just evaluate this, but idk the order of stuff im meant to do

stark trail
#

please show the original question

next folio
#

i just need to have the interval and i can do the rest of the question

undone bane
#

test or homework?

next folio
#

hw

stark trail
#

okay so you are given epsilon=1

#

you must now find a range of values centered around c=1

#

such that for all values in this range, the difference in absolute value between their output value and 4 is within 1

next folio
#

i plugged in the known values i just dont know how to proceed

#

do i do the absolute value first, the radical, or what

stark trail
#

you want to find the value of $\delta=...$ such that when $$0<|x-1|<\delta \implies |f(x)-4|<1$$

elfin berryBOT
#

Austin

next folio
#

f(x) being sqrt17-x

#

yes

#

but idk how to evaluate the equation further

#

for example this is another question thats similar just with different values

stark trail
next folio
stark trail
#

$$0<|x-1|<\delta \implies |f(x)-4|<1$$
$$0<|x-1|<\delta \implies |\sqrt{17-x}-4|<1$$
Consider now: for $|\sqrt{17-x}-4|$ to be less than 1, it must be the case that $-1<\sqrt{17-x}-4<1$. Do you understand that?

elfin berryBOT
#

Austin

stark trail
#

@next folio

next folio
#

yes

#

next step?

stark trail
#

well we can take this inequality that we have now

#

$$-1<\sqrt{17-x}-4<1$$

elfin berryBOT
#

Austin

stark trail
#

and add 4 to all sides of it

#

$$3<\sqrt{17-x}<5$$

elfin berryBOT
#

Austin

stark trail
#

now this is something you can solve

#

so you tell me @next folio what is the range of x-values that satisfy this inequality?

next folio
#

(3,5)

stark trail
#

no

next folio
#

😭

stark trail
#

if needed, recall that sqrt(25)=5 and sqrt(9)=3

#

so your upper bound is 17-x=25

#

and your lower bound is 17-x=9

next folio
#

then subtract 17

#

then multiply by -1

#

?

stark trail
#

you don't need my help solving those equations

#

likely you didn't need my help for this entire inequality

#

so let me know once you've decided the range of x-values

#

and then we can continue

next folio
#

-8 < x < 8

stark trail
#

great

#

now

#

recall that we are centering our interval around x=1

#

and as you have just demonstrated

#

our x-values must fall in -8<x<8

#

so what is the largest size interval centered at x=1 that stays within -8<x<8

next folio
#

i got it

#

delta = 7

#

thank you

stark trail
#

yes

next folio
#

i was just confused about the order of operations i was meant to do it ig

#

but yea thank you man

stark trail
#

no problem

#

step by step is key

marsh citrusBOT
#

@next folio Has your question been resolved?

marsh citrusBOT
#
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cyan raft
#

How do I convert Euler angles to Degrees?

marsh citrusBOT
cyan raft
#

So Let's say I have an Euler angle orientation of (60, -180, -180)

#

How do I find the actual rotation in degrees? like (x value) rotated 220°

marsh citrusBOT
#

@cyan raft Has your question been resolved?

marsh citrusBOT
#

@cyan raft Has your question been resolved?

marsh citrusBOT
#

@cyan raft Has your question been resolved?

open relic
marsh citrusBOT
#

@cyan raft Has your question been resolved?

marsh citrusBOT
#
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marsh citrusBOT
#
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tender mantle
marsh citrusBOT
#

@tender mantle Has your question been resolved?

tender mantle
#

How do we find an angle bisector of two vectors?

#

.close

marsh citrusBOT
#
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tender mantle
#

What are they asking?

marsh citrusBOT
stoic saddle
#

let f be a function twice-differentiable on an interval [a,b], and suppose f has 3 roots in (a,b). what's the minimum number of roots that f'' is guaranteed to have?

marsh citrusBOT
#

@tender mantle Has your question been resolved?

marsh citrusBOT
#

@tender mantle Has your question been resolved?

stoic saddle
#

is that so?

#

can you prove that f'' has at least 3 zeros?

tender mantle
#

No idea for f"

#

How to calculate it?

stoic saddle
#

you do not calculate f'' itself

stark trail
#

think about how if f(x) has three zeros this means the graph has to cross the x-axis 3 times

#

it has to go up and then down and then back up ( in some order )

#

in order to do that

tender mantle
#

@stark trail

#

🗡️

stark trail
#

think about what that means for the sign of the derivative

#

🛡️

tender mantle
#

(x-1)(x-2)(x-3)

#

Let me try this one

stark trail
tender mantle
#

1 root only

#

F"

stark trail
#

well start with f'(x) atleast

#

how many roots

tender mantle
#

2

stark trail
#

so then f''(x)

tender mantle
#

It's 1

#

Because linear equations

stark trail
#

not sure what you mean by that

#

but I agree with 1

#

@stoic saddle ?

tender mantle
#

F" is in x terms only

stoic saddle
#

he might mean that in the specific case that f(x) = (x-1)(x-2)(x-3), f'' will be a linear function

#

and those only have one root

tender mantle
tender mantle
stark trail
tender mantle
#

Why did they write in a weird way?

stark trail
#

it would be much quicker to imagine the graph

stark trail
tender mantle
#

Yeah. I hope so

#

Weird opetions

quaint elm
#

it's 2 in english and 2 in hindi

#

(hindi?)

stark trail
#

bruh

stoic saddle
#

they would have written २, ३ and ४ no?

stark trail
#

as the Hindi expert here, no those are incorrect Ann

stoic saddle
#

i copied these off of wikipedia

stark trail
#

I copied my response off of my brain

stark trail
static quarry
#

wha

stark trail
#

Guide us

tender mantle
#

Ann knows hindi

#

@stark trail so f(x) has 2 place where sign vhanges

#

F'x will have 1 place where sign changes

#

F"x no sign changes

#

So roots will be 1 because it will cut only once

static quarry
#

no one said that f'' exists

#

oh wait

#

it's so blurry i miscounted the primes

#

nvm

stark trail
tender mantle
#

So what to do with options?

#

War finished aaustinuu

stark trail
#

we have prevailed

#

but it is yet a battle

static quarry
#

imagine losing the battle after winning the war

stoic saddle
#

anyway

#

you need to use rolle's theorem multiple times here

static quarry
stark trail
stoic saddle
#

yes it is?

#

unless you're shoving that bit in my face again

tender mantle
#

Should I upload my next question?

stoic saddle
#

are you done w/ this one

tender mantle
#

Answer is 1 but options are incorrect right?

stark trail
stoic saddle
#

so they're not automatically incorrect

tender mantle
#

What?

#

So there is answer among a,b,c?

stoic saddle
#

no

#

that's not what i said

stark trail
#

sus

stoic saddle
#

maybe there is a disagreement about what "options are incorrect" means

#

when i see, read or say "options are incorrect", it means that it is impossible to pick one option to answer the question truthfully

#

but that is NOT the case here, since the last option reads "none of the above".

tender mantle
#

I do not consider the 4th option as a answer

#

And no doubt i choose it

#

4

#

So next doubt guys

#

Three vectors are given we need to find for which value of x, volume will be minimum of this rectangle quadrilateral

stoic saddle
#

i'm out

tender mantle
#

x^3-2x

#

I got this

static quarry
#

what rectangle quadrilateral

tender mantle
#

Made by these vectors

#

I tried determinant

tender mantle
#

.close

marsh citrusBOT
#
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#
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drifting trout
#

If I have a sum $$ A = \sum_{i=1}^n \sum_{j=1}^n A_{ij}a_ia_j$$ where $A$ is real and positive, does it follow that $$ A_{ij} = A_{ji}?$$ I can't think of a counterexample, but I also don't know how to prove it.

elfin berryBOT
#

thedude365

drifting trout
#

I know we can rewrite $A$ as $$ A = \sum_{j=1}^n \sum_{i=1}^n A_{ij}a_ja_i$$, and because the indices are arbitrary, we can also write $A$ as $$ A = \sum_{j=1}^n \sum_{i=1}^n A_{ji}a_ja_i$$

elfin berryBOT
#

thedude365

drifting trout
#

but that doesn't seem like enough to show that $A_{ij} = A_{ij}$

elfin berryBOT
#

thedude365

mystic minnow
#

so.... you need to fill in a lot of missing info here.

#

what is A? what is A_ij? what is a_j and a_i?

drifting trout
#

My question is adapted from a physics problem in which A is kinetic energy, A_ij is a generalized mass term, and a_i, a_j are the magnitudes of generalized velocities. The physics lingo only tells me that all terms are real and positive

#

It's completely possible that there is no way to prove this with the available information

marsh citrusBOT
#

@drifting trout Has your question been resolved?

marsh citrusBOT
#

@drifting trout Has your question been resolved?

#
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sleek nimbus
#

Why am I wrong?

marsh citrusBOT
unreal oyster
#

u' = 0

next raft
#

a is not dependent on x, so its a constant and its derivative is 0.

sleek nimbus
#

ohhhhhhh

#

thanks

#

.close

marsh citrusBOT
#
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loud apex
#

π x a ÷ π squared

marsh citrusBOT
desert dirge
#

$\frac{\pi a}{\pi^2}$?

elfin berryBOT
#

AℤØ

loud apex
#

Yes.

A = 68.

desert dirge
#

whats the issue

marsh citrusBOT
#

@loud apex Has your question been resolved?

marsh citrusBOT
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marsh citrusBOT
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solemn rover
#

hello, im new to proofs and there are a few things that i do not understand about this proof:

  1. how does this proof prove the division with remainder theorem?
  2. why is b+ka used instead of aq+r?
  3. why must b+ka≥0?
marsh citrusBOT
#

@solemn rover Has your question been resolved?

marsh citrusBOT
#

@solemn rover Has your question been resolved?

marsh citrusBOT
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rough fulcrum
#

idk where to begin

marsh citrusBOT
silk tangle
rough fulcrum
#

oh ok ty

silk tangle
#

but idk how to solve that

#

ill try gauss XD

rough fulcrum
#

its ok

#

i got the rest

#

i know how to do it

wet holly
#

Gauss is overkill for this bleakkekw

silk tangle
#

whats the answer?

silk tangle
#

XD

#

i think thats wrong

rough fulcrum
#

im working on another one rn but as soon as im done ill do it

silk tangle
rough fulcrum
#

yea

silk tangle
open kayak
silk tangle
#

this is the answer

#

30 cars and 14 vans

open kayak
#

Subtract 5 times the second equation from the first, leaving you with 3y = 42 and so y = 14. Thus, x = 30.

silk tangle
#

making matrix is the only way i remember 😦

rough fulcrum
#

i got 14

#

30 cars and 14 vans

silk tangle
#

yep

rough fulcrum
#

could u help w one more

silk tangle
#

lets see

rough fulcrum
#

could u just write it in the thing u wrote last time

#

u don’t need to solve it

silk tangle
#

z = average speed

#

z=(10/2 + 8/4)/2

rough fulcrum
#

what abt the speed of the current

silk tangle
#

what does that meean

#

im hispanic

#

explain bc i dont understand the traslate

rough fulcrum
#

like the speed of the water

silk tangle
#

water?

#

speed for 1st and 2nd trip?

#

1st = 10/2 and 2nd 8/4

#

km/h

rough fulcrum
#

im confused

silk tangle
rough fulcrum
#

yup ik that triangle

#

but like idk exactly how to use it yk

silk tangle
#

distance = 10
time that it took to complete those 10 km= 2

#

speed = v

#

speed = d/t

#

speed = 10/2 km/h

#

dont forget say km/h

rough fulcrum
#

yupp

#

tysm

#

.close

marsh citrusBOT
#
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manic peak
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.close

marsh citrusBOT
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Please don't occupy multiple help channels.

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subtle swan
#

Given an arithmetic sequence a_n that has 36 elements such that:
a_3 + a_7 + a_18 +a_30 = 248
Calculate the sum first 23 numbers in the series

subtle swan
#

How can I solve this?

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i used a_n=a_1 + (n-1)d and got 2a_1 +27d = 124
how can I move on

marsh citrusBOT
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@subtle swan Has your question been resolved?

marsh citrusBOT
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@subtle swan Has your question been resolved?

marsh citrusBOT
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earnest hound
#

can someone help with this pls?

marsh citrusBOT
earnest hound
#

i rationalized the denominator and got (-129-44√2)/113

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but idk what to do after

whole hazel
#

So what’s A B and C

marsh citrusBOT
bright jay
elfin berryBOT
#

dldh06

earnest hound
bright jay
#

To separate the fraction

marsh citrusBOT
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earnest hound
marsh citrusBOT
bright jay
#

No

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I used a, b, c, in mine as an example

bright jay
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Then simplify if needed

earnest hound
bright jay
#

Yes

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Separate using what I stated

bright jay
earnest hound
bright jay
#

Looks like it

earnest hound
#

thank you

marsh citrusBOT
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brave spire
marsh citrusBOT
brave spire
#

Source: Terence Tao's Solving Mathematical Problems

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The solution provided is good, but I wanna know if what I am doing is possible to continue

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I will type my solution out

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Let $\phi(x)$ be the sum of the digits of x, and $\sigma(x)$ be the number of digits in x \
Now when I rearrange digits, the number of digits (i.e. $\sigma(x)$) and the digits themselves (and thus their sums i.e. $\phi(x)$) will remain same. \
$\Rightarrow$ I need to find two powers of 2 (say $2^n$ and $2^m$) such that $\phi(2^n) = \phi(2^m)$ and $\sigma(2^n) = \sigma(2^m)$ \
Now, we can rewrite $2^n$ as $10^{n \log_{10} 2}$. Since $10^x$ has x+1 digits, therefore $2^n$ has $\lfloor n \log_{10} 2 + 1 \rfloor$ digits. \
$\Rightarrow \sigma(2^n) = \lfloor n \log_{10} 2 + 1 \rfloor$ \
Now when we write the domain and range of $\sigma(2^n)$ as $n$ increases by 1, we notice a pattern. If 10 divides n, then the next three consecutive powers of 2 have the same number of digits. If 10 doesnt divide n, then the next two consecutive powers of 2 have the same number of digits.

stoic saddle
#

thonk hold on what

brave spire
elfin berryBOT
#

ItzKraken

stoic saddle
#

so you're saying that if n = 10k, then 2^n, 2^(n+1), 2^(n+2) and 2^(n+3) always have the same digit count?

stoic saddle
#

er yes sorry

brave spire
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Yes

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I can prove this

stoic saddle
#

had my finger trained on that

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hold on tho.

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im really suspicious of this

brave spire
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lemme write the proof for it

stoic saddle
#

,w number of digits in 2^100

stoic saddle
#

,w number of digits in 2^103

stoic saddle
#

you are just wrong

brave spire
#

Nani!

stoic saddle
#

$\log_{10}(2) \neq 0.3$ !!

elfin berryBOT
brave spire
stoic saddle
#

APPROXIMATELY

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but not exactly!!!

brave spire
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hmm

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so my conjecture is false?

brave spire
#

could I find a version of this conjecture which is true for all n?

crystal sand
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I probably didn't put that well.

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I meant like if you leave 10^(-100) then, that'll also be 1 when multiplied with numbers bigger than 10^100.

brave spire
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I think i got it..What you are trying to say is that there is always a n big enough such that the conjecture will be false

brave spire
brave spire
crystal sand
#

Yes.

brave spire
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i see

crystal sand
#

Somehow, i'm used to saying greatest integer function.

brave spire
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I find that term confusing

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well tysm..Since everything after this is based on my conjecture being true, I suppose its also wrong

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.close

marsh citrusBOT
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marsh citrusBOT
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cold sundial
#

I can't understand how cos(3π/2 + θ) becomes sinθ...

My understanding is at this level.
According to which, I conclude it should be -cosθ.

ancient slate
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Well, do you agree that the cos θ sort of corresponds to the "x-coordinate" in the unit circle?

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Actually, you can even see it in the top left drawing

cold sundial
#

But from that logic, cos(90°+θ) should be -sinθ
Is that correct?

ancient slate
#

That's right

cold sundial
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hmmm

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Somewhat makes sense.

ancient slate
#

I'm guessing you guys haven't talked about sines and cosines of the sum of angles

cold sundial
#

ty for help.
I just miss read the sin 90+θ in google.

cold sundial
#

ty for help.

ancient slate
#

Sure

cold sundial
#

.close

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stark field
marsh citrusBOT
stark field
#

Guys last time on test i had to get lerner indeks (square below) from the thing above

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but i fail

#

anyone understand how?

marsh citrusBOT
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near lava
marsh citrusBOT
near lava
#

the ans to this is -1/2 x^2 right

#

i'll send my working

undone bane
#

there is a x multiplied to f(x)

#

so no, that is not f(x)

marsh citrusBOT
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true iris
#

Hi !

marsh citrusBOT
true iris
#

I have to solve this but i dont know how toi start and where to go

stoic saddle
#

ok just one moment

#

these fucking black bars are each 13.5 times taller than the original image.

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seriously?

vale cypress
#

Fr 😭

true iris
#

Yeah sorry

stoic saddle
#

the problem itself goes:

Solve the inequality $\sqrt{ax+1} \geq x$

elfin berryBOT
true iris
#

Yes

stoic saddle
#

do you have any info about the letter a?

true iris
#

No

stoic saddle
#

i have trouble believing you weren't told anything else.

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but like ok you probably want to at least break into cases based on the sign of a

true iris
#

It's Say based on the values off the parametre a

stoic saddle
#

do you have a pic of the assignment you got this problem in

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or the textbook whatever

true iris
#

Only what i Say to you

#

<@&286206848099549185>

torn quiver
#

?

true iris
#

I don't know how toi solve it

vocal leaf
true iris
#

This

vocal leaf
#

Ok