#help-33

1 messages · Page 37 of 1

thin frost
marsh citrusBOT
thin frost
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some help with this question please, i can see OABC is a rhombus but im not sure where to go from there

marsh citrusBOT
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@thin frost Has your question been resolved?

marsh citrusBOT
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@thin frost Has your question been resolved?

marsh citrusBOT
#

@thin frost Has your question been resolved?

keen plover
#

OABC is a rhombus therefore all its sides are equal

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draw a line OC

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what can you say about the two triangles OBC and OAC

marsh citrusBOT
#
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still temple
#

I'm getting undefined for the tangent

marsh citrusBOT
still temple
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I differentiated and got $\frac{8x-3y}{3x+2y}$

elfin berryBOT
still temple
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$3(2)+2(-3)=0$

elfin berryBOT
stoic saddle
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,w implicit derivative 4x^2 - 3xy - y^2 = 25

stoic saddle
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checks out

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and you got that y' is undefined at this point?

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you can either go through the same song and dance but to find dx/dy instead of dy/dx,

or you could acknowledge that you just have a vertical tangent at this point.

brave spire
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Yeah..0 is in the denominator

brave spire
stoic saddle
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who's he

still temple
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?

still temple
brave spire
stoic saddle
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_____ does not have a pronoun role, so i would refrain from assuming he/him pronouns for them

still temple
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i dont care about pronouns for myself

stoic saddle
stoic saddle
still temple
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oh ok

still temple
stoic saddle
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no, overthinking it

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your line is a vertical line that passes through (2, -3)

still temple
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oh....

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it's just x=2

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can u explain what this means though?

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this is what the answer key says

brave spire
still temple
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Because it’s tangent is vertical

brave spire
stoic saddle
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okay, hold on.

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something's not adding up

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let me desmos this

still temple
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Ok

brave spire
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Desmos go brrrrr

stoic saddle
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red = the curve
green = your tangent line (correct)
blue = answer key (wrong)

still temple
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Ok thanks

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I hate it when the answer key is wrong

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Thanks guys

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.close

marsh citrusBOT
#
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polar fable
marsh citrusBOT
polar fable
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these are my 3 doubts

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help any one

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pleaseee

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.close will come later gtg

marsh citrusBOT
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sinful barn
#

Sup

marsh citrusBOT
sinful barn
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How can i approach this question?

lofty gyro
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is it given that x,y are integers or what condition?

sinful barn
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Yup

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I need to find all values of x and y

lofty gyro
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integers, right?

sinful barn
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Yes

lofty gyro
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hint1

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add those two equations up

sinful barn
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Done

lofty gyro
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hint2
consider xy+x+y+1

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you can factorize that into something nice

sinful barn
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Yea

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(X+1)(Y+1)=5

lofty gyro
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yea, i guess that's what you're looking for

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remember to check the negatives

sinful barn
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Now i can subsitute it in any of those 2 eq right?

lofty gyro
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you can just check the integer values that
(x+1)(y+1)=5 is valid

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all those 4 pairs of (x,y)

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and plug them back to the original equation to see if they are valid

marsh citrusBOT
#

@sinful barn Has your question been resolved?

marsh citrusBOT
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olive gate
marsh citrusBOT
olive gate
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Isn't this slide incorrect?

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It should be "strongly connected"

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Here is the accompanying graph:

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the above graph is strongly connected, not weakly connected

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Or am I misunderstanding something here?

glass silo
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Complete wild guess (and I almost certainly won’t remember any more to help extra), but does strongly connected imply weakly connected?

olive gate
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they are two different states, I believe

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weakly connected would be where some vertices only have an in-degree or out-degree, but not both

stoic saddle
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an euler circuit is a circuit that visits each edge exactly once, yes?

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given that a circuit comes back where it starts, the existence of one does imply strong connectedness and not weak...

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so it looks like the slide is in error

olive gate
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ok, I will email my professor then

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ty

olive gate
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The same error seems to be repeated here as well.

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How can there be so many typos that seem to be significant

stoic saddle
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ah, no, for an euler path you don't need strong connectedness

olive gate
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let me show the accompanying example

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this graph is strongly connected, not weakly

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this is why I feel this is another typo

stoic saddle
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do you mean to claim "this graph is strongly connected and fails to be weakly connected"?

olive gate
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or it seems to be based on the example given

olive gate
stoic saddle
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do you have a definition of weak connectedness on hand? we could check your graph against it.

olive gate
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or as far as i have been taught so far

stoic saddle
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i think either you misheard your teacher or they chose to misinform you.

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as far as i know, strong connectedness implies weak connectedness.

olive gate
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But this is a reason why I feel a graph can't be both.

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Here is one of the self test questions are teacher gave us during lecture:

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as you can see, the options are strongly OR weakly connected

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not both

glass silo
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Not the way I read the wording “…and if not, whether…”

stoic saddle
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^

olive gate
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which is "not connected at all"

stoic saddle
olive gate
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and here's an example of that:

stoic saddle
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any strongly connected graph is also weakly connected.

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so really, it's "Strongly connected", "Not strongly connected, but weakly connected", and "Not connected"

olive gate
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so, if this is true, what does this mean for my original question?

stoic saddle
olive gate
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I'm not sure I understand how this negates the potential typo

olive gate
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that one, too, I think

stoic saddle
# olive gate

this screenshot has a typo. "weakly" should be "strongly" here.

olive gate
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because even if we accept your interpretation, then why would the slide read "weakly" instead of "strongly"?

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one is listed instead of the other because there is a difference intended to be shown

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so, this slide would also have a typo:

stoic saddle
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no, i cannot say whether that screenshot has a typo. i know for a fact that there exists a graph that is weakly and only weakly connected, and which has an euler path. therefore the "weakly" there should not be changed to "strongly".

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i do not know how else to communicate my point to you...

olive gate
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the example here is clearly incorrect, but maybe the definition isn't

stoic saddle
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a -> b -> c -> d

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this graph is just a path

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its sole euler path is itself

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it is weakly connected but not strongly connected

olive gate
stoic saddle
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in what way?

olive gate
stoic saddle
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do you think there are not two vertices with unequal in- and out-degrees?

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or that there are exactly two of them, but the differences between their in- and out-degrees are not what they should be?

olive gate
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a doesn't have an in-degree

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everyone else does

stoic saddle
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you mean a doesn't have any incoming edges!

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that's different from it not having an indegree at all!

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the number zero exists!

olive gate
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ok, that's true

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a: in: 0 out: 1
b: in: 1 out: 1
c: in: 1 out: 1
d: in: 1 out: 0

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ok, you're right

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it does match

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then, maybe the example is just incorrect

stoic saddle
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in what way?

olive gate
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the graph is strongly connected

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I know you feel this implies weakly connected

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but the slides says "weakly"

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specifically

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not implied

stoic saddle
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i do not "feel" that way

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it is an easy theorem that any strongly connected graph is also weakly connected

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being strongly connected does not mean you fail to be weakly connected too

olive gate
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for instance, I'm sure I will get a 0 for a problem that requires an answer of "strongly", but I write "weakly"

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this logic will not hold, I don't think

stoic saddle
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do you mean problems of the kind you showed?

olive gate
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yes

stoic saddle
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i.e. "determine if this graph is strongly connected; if it fails to be strongly connected, determine whether it is weakly connected"?

olive gate
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this isn't the wording of the problems above

stoic saddle
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then indeed, writing "weakly connected" would mean that you determined the graph to be weakly and not strongly connected, and that is what would contradict said graph being strongly connected.

olive gate
stoic saddle
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"Determine whether this graph is strongly connected, and if not, whether it is weakly connected."

olive gate
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yes, this

stoic saddle
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are you or are you not now going to argue that, because my wording isn't the same-to-the-letter as that, i have committed misinterpretation thereof?

olive gate
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no, you are likely very correct here

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but the issue is answering to my professor's standards

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if strongly implies weakly, then, an answer of 'weakly' should be correct

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but i will get that marked wrong every time, I assume

stoic saddle
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yes, because analyzing a strongly connected graph and following the instructions provided cannot result in an answer of "weak"

olive gate
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yes, so the slide's example is incorrect

stoic saddle
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no

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not everything revolves around that one damn assignment

olive gate
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not the description, but the example

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I'm trying to keep repeating that to be clear here

stoic saddle
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def answer_assignment(G):
  if is_strongly_connected(G):
    print "Strong"
  else:
    if is_weakly_connected(G):
      print "Weak"
    else:
        print "Not connected"
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FOR THE ASSIGNMENT you are supposed to follow this pseudocode i just wrote here

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do you agree or disagree with this

olive gate
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i agree

stoic saddle
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okay

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in that case

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let me attempt for the third time to clear up the apparent confusion

olive gate
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wait

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before you do that

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let's use this algorithm

stoic saddle
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on what

olive gate
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we input this graph into that function

stoic saddle
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that will print "Strong"

olive gate
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what is printed is:

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Strong

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exactly!

stoic saddle
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yes, but you didn't let me finish.

olive gate
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so, the slide is incorrect

stoic saddle
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you chose not to let me finish my point.

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can i finish my point now?

olive gate
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not to cut you, but why would there be any follow up if we follow the algorithm?

stoic saddle
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"answer_assignment(G) prints Weak" is NOT equivalent to "G is weakly-connected".

olive gate
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that's all I wanted to inquire

stoic saddle
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that's the follow-up.

stoic saddle
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our algorithm prints Weak for graphs that are WEAKLY CONNECTED WHILE FAILING TO BE STRONGLY CONNECTED, and no others.

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but the definition does NOT call for a graph specifically like that.

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it calls for a weakly connected graph, which ALSO INCLUDES STRONGLY CONNECTED GRAPHS.

olive gate
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this is confusing to me so let me follow up with this question

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why is "weakly" specifically used here instead of "strongly"?

stoic saddle
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here as in where? the euler path slide?

olive gate
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this slide:

stoic saddle
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so the euler path slide, yes.

olive gate
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if what you are saying is indeed the case, then there must be a reason why the professor chose one term over the other

stoic saddle
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yeah, of course there's a reason.

olive gate
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every google search i read states "strongly" not "weakly"

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so, there's that also

stoic saddle
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requiring that the graph be STRONGLY connected will exclude graphs that aren't strongly connected yet have an euler path.

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the slide says "a graph has an euler path if and only if such-and-such conditions."

olive gate
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but "strongly" implies "weakly", not vice versa

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which is why I don't understand this statement:

stoic saddle
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all strongly-connected graphs are weakly-connected, therefore "weakly-connected graphs" includes strongly-connected ones.

olive gate
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maybe you can share a weakly connected graph that is also strongly connected?

stoic saddle
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okay, sure...

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i can't depict it in plain text easily, but take 4 vertices a, b, c, d with edges ab, bc, cd and da

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this graph is both weakly connected and strongly connected

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does this or does this not satisfy you

olive gate
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how is this strongly connected

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both vertices do not have an in-degree and out-degree greater than 0

stoic saddle
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what "both" vertices? there aren't two of them, there are four.

olive gate
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or I mean none of them

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so, c and d specifically

stoic saddle
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this is my graph

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i do not know what you imagined or drew

olive gate
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oh, ok

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then, that isn't weakly connected

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maybe, we have different ideas of what 'weakly' means

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do you agree that this is weakly?

stoic saddle
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yeah and you have the wrong one

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you think that we are only allowed to call a graph weakly connected if it isnt also strongly connected

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and that isnt the case

olive gate
stoic saddle
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as i tried

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to say

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5

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whole

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fucking

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times

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to NO AVAIL WHATSOEVER

olive gate
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is this "weakly" to you?

stoic saddle
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AND YOU STILL REFUSE TO BUDGE

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YES THIS GRAPH IS WEAKLY CONNECTED I NEVER ARGUED AGAINST THAT

olive gate
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why must you get so infuriated when someone doesn't understand your position?

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it's not that serious

stoic saddle
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i've made my position as clear as i possibly could've, several times in a row.

olive gate
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and if it is then, perhaps return to this later when you've had a break?

tacit fjord
#

Are these the defns you are using:

  • 2 vertices are (weakly) connected if there exists a path between them
  • 2 vertices are strongly connected if there exists a path in both directions between them
tacit fjord
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ok.

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whats the issue

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All strongly connected graphs are also weakly connected. Yes?

olive gate
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OR

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the accompanying example is incorrect:

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or both, i guess

tacit fjord
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Without delving into the graph theory

tacit fjord
olive gate
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i think so

tacit fjord
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(I just thought this was the source of much confusion)

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and wanted to clarify

olive gate
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ok

tacit fjord
tacit fjord
#

Purely from the defns you linked

tacit fjord
# olive gate

Prove all strongly connected graphs are also weakly connected

olive gate
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ahh!

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I totally see your point now

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by "weakly", my professor is just saying that there needs to be a path between the vertices

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not necessarily in both directions, just that there is a path

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then, my professor was never incorrect in any of the slides

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even in my initial query, the slide is correct

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"weakly" connected does mean ONLY weakly connected

tacit fjord
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will look later if someone else didnt

olive gate
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it just means the minimum requirement

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great to have this cleared up

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now, i don't need to email them

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ty

marsh citrusBOT
#

@olive gate Has your question been resolved?

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sick mesa
#

Hi, why is it true please ?

marsh citrusBOT
sick mesa
dire bobcat
#

If you think about integral as the area under a graph, it might help you out.

marsh peak
#

Note that for every t in the interval 1/(k + 1) <= 1/t <= 1/k

marsh citrusBOT
#

@sick mesa Has your question been resolved?

sick mesa
sick mesa
marsh peak
dire bobcat
marsh citrusBOT
#

@sick mesa Has your question been resolved?

marsh citrusBOT
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calm anvil
#

If X is uncountable, equipped with the cocountable topology, how do I show that

calm anvil
#

I've shown that:

proper zodiac
calm anvil
#

ok ty

#

.clos

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.close

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wind cloud
marsh citrusBOT
wind cloud
#

I know this is super simple

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But can the base number be the LCM?

frosty linden
#

Yes

glacial hedge
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if a divides b, then lcm(a, b) = b

wind cloud
#

Okay awesome, thank you

#

Good to know

#

-close

#

.close

marsh citrusBOT
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still temple
#

can we discuss induction

marsh citrusBOT
still temple
#

its like recursion right

marsh citrusBOT
#

@still temple Has your question been resolved?

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lethal bridge
#

Hi, when completing the square and getting to the square root process. I know that you just remove the ^2 but what happens to the 4?

bleak reef
#

4 is also a square number

lethal bridge
#

Does it just become 2

bleak reef
#

yes

lethal bridge
#

Alright thanks

bleak reef
#

np

lethal bridge
#

Here’s the full thing, do you checking if I’ve done anything wrong?

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Oh wait

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There should be a +- sign

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but I need to get the x by itself right

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I can’t leave it as just 2x

bleak reef
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you multiplied the whole thing by 4 but you only have 4x^2

lethal bridge
#

Oh I thought I take the leading coefficient or something during cts

bleak reef
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yes but that affects what's inside

lethal bridge
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Oh so I should be distributing it inside the square root first, and then removing the square?

bleak reef
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I don't know what you mean

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try and copmlete the square ont his again

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actually it might help to just start from 4x^2 + 7x - 1

lethal bridge
bleak reef
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no that's not the problem

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the problem is that you completed the square wrong

lethal bridge
#

Oh

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I see

marsh citrusBOT
#

@lethal bridge Has your question been resolved?

marsh citrusBOT
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still temple
#

Where should I go from here?

marsh citrusBOT
still temple
lofty gyro
#

did you try and draw the line y=mx out and see how it cuts the shape?

still temple
#

Well how should I draw it if I don’t know the slope

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O wait

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It’s gonna be

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Like this

lofty gyro
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yea, something similar, you dont really have to be exact, just to get the picture it's okay

still temple
#

Ok and now I just do the integral

lofty gyro
#

now that it is divided into 2 parts

still temple
#

Thanks

lofty gyro
#

yea

still temple
#

Well about

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.close

marsh citrusBOT
#
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still temple
#

So here you'll see the question is already solved, but can someone walk me through how to solve it?

marsh citrusBOT
#

@still temple Has your question been resolved?

past maple
#

Do you know what eigenvalues and eigenvectors are?

still temple
#

No. We've never discussed it in class or studied it

past maple
#

So you have x^n = x^(n-1) + 6 x^(n-2), right?

still temple
#

not ^ but _.

But yeah

past maple
#

But

past maple
past maple
still temple
#

I don't know

past maple
still temple
#

How do you get those as solutions?

past maple
still temple
#

Where does x = 0 and x ≠ 0 come from?

past maple
still temple
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So if x ≠ 0 then why do we divide the equation by x^(n-2)?

past maple
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Which we can solve

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We had a polynomial equation of degree n. To simplify it, we can divide by x^(n-2) to obtain an equation of degree 2, but if we divide by x then x should not equal 0

past maple
still temple
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okay give me a minute

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let me try to write it down

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wait I messed up

still temple
past maple
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Yes

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But the fractions can be simplified

still temple
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Let me see if I can fix it

past maple
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No

#

(a^b)/(a^c) equals a^(b-c), right?

still temple
past maple
#

That is still wrong

past maple
still temple
#

x is a, n is b, n-2 is c

#

right?

past maple
#

Yes

#

So then, what would be b-c?

still temple
#

2?

past maple
#

Yes

past maple
still temple
#

x^2 = x^1 + 6?

past maple
#

Exactly

still temple
#

that was embarassing

past maple
#

It is not an embarrassing thing, it is indeed very common

still temple
past maple
#

That is a quadratic equation

#

What are its solutions?

still temple
#

Ah I see

past maple
#

How did you reach that solution?

still temple
#

oh

#

I see

past maple
still temple
#

I know it's not correct. I'm redoing it

past maple
#

Ok

still temple
#

This will take a minute

#

-1^2 = 1 right?

past maple
#

(-1)^2 = 1, yes

#

But -(1^2) = -1

#

And -1^2 actually denotes -(1^2)

still temple
#

so this right?

past maple
#

No
I think you wrote twice something inside the square root

#

There are two 4, but there sould only be one

still temple
#

oh I see it

#

So this is as far as I could simplify it

past maple
#

Be careful with the - signs

still temple
#

This isn't correct?

past maple
#

No

#

Take a look at the expression that you obtain with the quadratic formula

past maple
still temple
#

Oh I know what I did wrong

#

So x=3 and x=-2

past maple
#

Yes

#

So what does that mean?

still temple
#

So that answers that

past maple
#

Yes

#

But what was x? What were we doing at the beginning?

still temple
past maple
#

Correct

#

But before that

still temple
#

This will take me a minute to write down

#

So this

past maple
still temple
#

fixed

past maple
#

So we obtained two sequences
a_n = 3^n and b_n = (-2)^n

#

What do we know about these sequences?

still temple
#

Do we need b_n?

past maple
#

I wrote b_n to use a different letter

still temple
#

Ah

#

So we could choose either?

past maple
#

We are not going to choose any of them yet

still temple
#

Oh

past maple
#

They are sequences we obtained after solving a different problem from what we originally wanted

#

We wanted that a_n = a_(n-1) + 6 a_(n-2), that a_0 = 3, and that a_1 = 6

#

But a_n and b_n satisfy the first one, right?

past maple
still temple
still temple
#

So all of this was step 1?

past maple
#

Yes

still temple
#

Ah

past maple
#

But step 2 is shorter

still temple
#

I see

past maple
#

Now we have a_n and b_n

#

And a_n = a_(n-1) + 6 a_(n-2)

#

And b_n = b_(n-1) + 6 b_(n-2)

#

Do you understand why?

#

Remember that a_n = 3^n and b_n = (-2)^n

still temple
#

Sorry, give me a minute to write this down

#

So now I have this?

past maple
#

Yes

#

But why?

still temple
#

So we found sequences in the form of aₙ = xⁿ?

past maple
#

Yes

#

And since -2 and 3 are solutions to the equation x^n = x^(n-1) + 6 x^(n-2)

#

We can substitute x^n with a_n, x^(n-1) with a_(n-1) et cetera

past maple
#

Do you understand the logic?

still temple
#

So what about 6a_n-2?

past maple
#

You can also substitute x^(n-2) with a_(n-2)

still temple
#

I will write your message down

#

converting a_n to x^n

past maple
#

I will write it in a more clear way
You know that -2 and 3 hold the equation
x^n = x^(n-1) + 6 x^(n-2)
Therefore, the following identities are true:
3^n = 3^(n-1) + 6*3^(n-2)
(-2)^n = (-2)^(n-1) + 6*(-2)^(n-2)
Furthermore, we defined a_n = 3^n and b_n = (-2)^n. Because of that, the previous lines can be rewritten as
a_n = a_(n-1) + 6*a_(n-2)
b_n = b_(n-1) + 6*b_(n-2)

past maple
still temple
#

Still writing things down, sorry

#

So now I have this

past maple
#

Yes

still temple
#

So what is step 2?

past maple
#

But do you understand why what we have done so far makes sense and works?

#

Or are you just writing down all what I'm saying, even though you don't understand it?

still temple
#

I'm confused

past maple
#

Why are you confused?

still temple
#

So my professor's solution to the question was a_n = (3/5)((-2)^n) + (12/5)((3)^n)

past maple
#

Yes, and that is the only correct solution to the problem

#

So you are confused because we obtained something different

still temple
#

Yeah

past maple
#

Well

#

As I said before, what we have made so far is to solve an auxiliary problem, a more simple one. It is actually a different problem, so of course the solution is different

#

But we need it to obtain the solution of the original problem

past maple
still temple
#

I don't.

past maple
#

Ok

#

Let's review it

still temple
#

I'm so sorry if I'm wasting your time

past maple
#

First, what does a_n = a_(n-1) + 6 a_(n-2) mean?

#

What is a_n?

still temple
#

3^n

past maple
#

That is true

#

But do you understand what a sequence is?

still temple
#

Yeah, but how does that relate to my initial question?

past maple
#

Because it is important to understand what you are doing

#

You should not just memorize how to solve every kind of problem every time you see it for the first time

#

Because that is just too difficult

#

Instead, understand math in general is easier in the long term, because you have to memorize less things

past maple
still temple
#

Alright. Sorry but give me a moment

still temple
past maple
#

Ok

still temple
#

Thanks for your time

marsh citrusBOT
#

@still temple Has your question been resolved?

marsh citrusBOT
#
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brave pilot
#

Just started a discrete math course, I have a question that I can’t get my head off of.

brave pilot
#

From this post, how does ExE!y differ from E!xEy?

#

Any help would be greatly appreciated.

still temple
#

there exists an x and there exists only one y

#

vs

#

there exists one x and there exists a y

brave pilot
#

Yes

#

Would the latter still mean there exists exactly two?

still temple
#

yeah

brave pilot
#

How about E!xE!y?

still temple
#

yeah thats one the solutions if you scroll down

brave pilot
#

This?

still temple
#

yea

brave pilot
#

Got it, thanks!

#

.close

marsh citrusBOT
#
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marsh citrusBOT
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upbeat needle
#

Radioactive radium has a half-life of approximately 1599 years. What percent of a given amount remains after 100 years?

upbeat needle
#

Idk how to start this problem

#

Ik equation is y=Ce^(kt)

#

<@&286206848099549185>

late pasture
#

Let the output of this function be in percentage

#

Then C would be 100

#

As at t=0, it would be at 100% and then will decay afterwards

#

So the function becomes 100e^(kt)

upbeat needle
#

Why is C 100?

late pasture
#

Do you know the correct answer?

upbeat needle
#

Yeah it’s 95.76%

late pasture
#

Yes so, its given that half life is 1599 yrs, so it decays to 50% in 1599 years. So, at t=1599, its output must be 50. Substituting the values we get...

#

100e^(1599k) = 50

#

=>e^(1599k)=0.5
=>k=-ln(2)/1599 = 0.000433

#

Are you getting it till this?

upbeat needle
#

Yes

#

Wait

#

Isn’t it -0.000433

late pasture
#

Ya sorry k=-0.000433

upbeat needle
#

All good

late pasture
#

So, now putting k back in equation, we get
100e^(-0.000433t)
Now we need to find the decay percent at t=100 years, so substituting t=100 in it, and you'll get the answer 95.76%

#

Got it?

upbeat needle
#

Ohhhhh yeah I get it

#

So the C value is the percent at t=0?

late pasture
#

Yes

#

According to this question

upbeat needle
#

And the y value is the half life percentage at t= amount of years

#

And I’m assuming half life is always 50%?

upbeat needle
#

Tysm

#

What does the value k represent tho?

marsh citrusBOT
#

@upbeat needle Has your question been resolved?

#
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lavish owl
#

can anyone help me with this?

marsh citrusBOT
lavish owl
#

its urgent

vale panther
#

But the best (for me) is using the equation

#

Thank you

stoic saddle
vale panther
#

Bruh

stoic saddle
#

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

elfin berryBOT
weak tulip
#

Backward slash

stoic saddle
#

if you meant this

#

i dont think its worthwhile here

vale panther
stoic saddle
#

given that this is a mulitple choice question

vale panther
#

I mean in general

stoic saddle
#

it might be less headache to simply expand all the answer options and see which matches

lavish owl
vale panther
#

When it comes to solving complex polynomials this is literally the only way but in this case there are faster ways

wheat sedge
#

you could look at the coefficient and constant

scarlet blaze
#

and factor

wheat sedge
#

yea and that will make +7.x and -4.x which is d

#

you could check this by looking at the constants, 7*-4 is -28 so it checks out

vale panther
#

Or you could do trial and error on each of the answers (try multiplying the numbers together to see if it matches the c coefficient and summing up together to see if they match the b coefficient

wheat sedge
scarlet blaze
#

x^2 + 7x - 4x - 28 = x(x + 7) - 4(x + 7) = (x + 7)(x - 4)

vale panther
#

You can even draw squares to find it

#

Like thats how the ancient people do it

wheat sedge
vale panther
#

Lol

lavish owl
vale panther
#

He re-writes 3x as 7x-4x

wheat sedge
#

did it

lavish owl
#

but its positive in the equation

wheat sedge
scarlet blaze
wheat sedge
#

yea just try the factors of -28 constant and sum them

lavish owl
#

4*-7

#

(x+4)(x-7)

wheat sedge
#

because of the 3 coeficcient in 3x, 4,-7 does not work because 4+(-7) would make -3

lavish owl
#

thats what i get

wheat sedge
#

so it would be -3x instead of +3x

wheat sedge
#

yep

lavish owl
#

so -4*7?

wheat sedge
#

yes

#

so we just find the matching one

lavish owl
#

(x-4)(x+7)

#

however

#

wait

#

-4x+7x is

#

3x

#

x^2+3x-28

#

i got it

lavish owl
#

because 7 is higher than 4

#

@wheat sedge

wheat sedge
#

yea

lavish owl
#

okay'

#

thanks for the help

#

.close

marsh citrusBOT
#
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marsh citrusBOT
placid oak
#

How do I start?

marsh citrusBOT
#

@placid oak Has your question been resolved?

marsh citrusBOT
#

@placid oak Has your question been resolved?

marsh citrusBOT
#

@placid oak Has your question been resolved?

sage pollen
#

How about you try subtracting eq 2 from eq 1 🙂

#

I think it'll be quite enlightening

elfin berryBOT
placid oak
#

@sage pollen

#

What next?

sage pollen
elfin berryBOT
placid oak
#

.close

marsh citrusBOT
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lethal zinc
#

differentiate w.r.t x

marsh citrusBOT
lethal zinc
serene parcel
#

use quotient rule

lethal zinc
#

i'm just learning derivatives and i'm not sure about if i'm supposed to leave the answer without simplifying it or simplify it cause the question just asks to differentiate w.r.t. x

serene parcel
#

normally its just simplifying the top bit

#

leave the bottom as something^2

lethal zinc
#

oh. thanks

#

.close

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still temple
#

Is there a function where the derivative is undefined everywhere, by any chance?

still temple
#

and by "everywhere" i mean for all points of the function's domain

outer arrow
#

perhaps a fractal

#

google it, I think it's quite an asked question

sage heath
#

hmmCat how about dirichlet's function

nova totem
#

The among us function

sage heath
outer arrow
#

yeah but u have more than 1 value at every x

hollow quest
#

continuous doesnt mean differentiable

sage heath
#

ya

#

fractals are just not diffable hmmCat

sage heath
#

because some fractals can be conti iirc

marsh citrusBOT
#

@still temple Has your question been resolved?

outer arrow
marsh citrusBOT
#
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vale marten
#

@marsh citrus

marsh citrusBOT
#
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placid oak
#

Let W={(x,y,z)∣x=2y+z} be a subspace of R³. Let β={(2,1,0),(1,0,1)} be a basis of W.

Let T : W→R be a linear transformation such that T(2,1,0)=(1,0) and T(1,0,1)=(0,1).

placid oak
#

How do I prove that T is an Isomorphism?

obsidian shard
#

It maps basis to basis so it must be an isomorphism

placid oak
#

T(x,y,z)=(y,z) or T(x,y,z)=(x-y-z,x-2y)

obsidian shard
#

If you want to show a bit in detail, you would wanna prove 1-1 and onto

#

But notice the dimensions are same so proving either 1-1 OR onto is enough

placid oak
#

How do I know which transformation is T?

obsidian shard
#

That would be a bit hard to find, a better option is to consider inverse transformation T' : R2 -> W

#

then the transformation is easy to find

placid oak
obsidian shard
#

well, there's a theorem which says that T is 1-1 if and only if T maps linearly independent subsets to linearly independent subsets

#

but anyway, since you're given the explicit transformation that should be used

placid oak
#

.close

marsh citrusBOT
#
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ionic owl
#

[\frac{d}{dx}\frac{x^2 + x}{x^2 -x}]
[(x^2 - x)(2x+1)-((2x-1)(x^2+x))]
[\frac{-4x^2 + 2x^2}{(x^2 -x)^2}]
[\frac{-2x^2}{(x^2 -x)^2}]

ionic owl
#

,w derivative (x^2 +x)(x^2 - x)^-1

#

Where is my mistake?

elfin berryBOT
#

dopediscorduser

obsidian shard
placid oak
#

Why?

#

Why not the second one?

obsidian shard
#

They might be equivalent but as per my calculations I got the 1st one

placid oak
#

If T is the first one, then T(1,0,0)=(0,0) and T(0,0,0)=(0,0). So they are not one-one?

obsidian shard
#

nah cause (1,0,0) doesn't lie in W

#

anyway get a different channel, I didn't notice you closed the channel

obsidian shard
#

It's just that wolfram simplified it by cancelling x

#

,w diff (x+1)/(x-1)

obsidian shard
#

basically same as you got above

#

you might as well cancel x in the first place cause x won't be 0

#

@ionic owl

marsh citrusBOT
#

@ionic owl Has your question been resolved?

marsh citrusBOT
#
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twin ether
marsh citrusBOT
twin ether
#

the one on the right is the answer

#

is it correct?

#

bc im not quite sure

obsidian shard
#

what's the question?

twin ether
obsidian shard
#

I think you should be able to cancel some stuff before performing the fraction substraction

twin ether
#

yeah I did

#

but I want to make sure

#

if it's correct

obsidian shard
#

how did you get a 2x^3 in the numerator?

#

nvm, got it

twin ether
#

yep

obsidian shard
#

Hmm, looks correct to me

twin ether
#

nice and the restrictions are x != 0, -1, 1, -2?

#

lol sry for asking a lot

obsidian shard
#

as in the domain restrictions?

twin ether
#

yesss

obsidian shard
#

yep

twin ether
obsidian shard
#

sure

twin ether
#

the one at the right is my answer, is it correct as well?

obsidian shard
twin ether
#

1/x^2-4x - 12 + 1/4x+8

#

like that

obsidian shard
#

weird question but I think it does mean that only

twin ether
obsidian shard
#

yep, got the same

twin ether
#

ty a lot for helping :)

#

.close

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gritty wren
#

Hi there can someone tell me how to deal with sine double angle identity

gritty wren
#

Like how is 2sin(x/2)cos(x/2)=sin(x)

late geode
#

x/2 is half of x

#

$\sin(\text{this}) = 2\sin(\frac{\text{this}}{2})\cos(\frac{\text{this}}{2})$

elfin berryBOT
#

ℝamonov

gritty wren
#

Ohhhhh i see, thank you so much!!!

marsh citrusBOT
#

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uneven musk
#

how much do you need to get 9664 to 10058 help pls im stupid

cobalt sentinel
#

So u want to do 10058 - 9664?

knotty trellis
#

10058-9664

uneven musk
#

OHHH

#

right

cobalt sentinel
#

What’s troubling you with that

uneven musk
#

i forgot i could minus it

#

:l

#

well

#

.close

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shell hill
#

Btw

marsh citrusBOT
shell hill
#

@quaint hill there's an easier

#

Solution for the problem I had

#

U remember it right?

#

$\lim_{x\to\infty}x^0 = 1$

elfin berryBOT
#

RulzerFly.

shell hill
#

.close

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frosty linden
#

if $p$ is prime and $p²+8$ is prime, Prove that $p^{3} + 8p + 2$ is prime too. Can someone gives me a hint?

elfin berryBOT
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phoestaclies

devout mauve
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consider mod 3

frosty linden
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I think I don't get the idea ?

devout mauve
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when in doubt, try examples

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go through the first few primes p, check if p^2+8 is prime and if yes check if p^3+8p+2 is prime

frosty linden
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yes I did that with 3 and 7

marsh peak
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p^2 + 8 is not prime when p is 7

devout mauve
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if 2 examples is not enough then maybe do 4 or 5

frosty linden
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euh yes sorry mb

devout mauve
marsh peak
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To whom?

frosty linden
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ok I will try to test other, and see what I get ty 🙂

marsh peak
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Btw I noticed that p^2 + 8 is most of the times divisible by 3

frosty linden
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.close

marsh citrusBOT
#
Channel closed

Closed by @frosty linden

Use .reopen if this was a mistake.

devout mauve
marsh peak
#

What/Who is grothendieck?

devout mauve
marsh peak
#

Oh

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Lol

marsh citrusBOT
#
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marsh peak
#

Actually I once picked 57 as prime for some reason as well thonk

marsh citrusBOT
#
Channel closed

Closed due to the original message being deleted

devout mauve
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it does look quite primelike

frosty linden
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yes I didn't calculate just see for me 57 is prime

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so like grothendieck

devout mauve
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as general advice btw, if any claim says "this formula will always be prime", then either the claim is false or the hypothesis only hold for finitely many cases

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in 99% of cases anyway

frosty linden
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ok thanks

glacial hedge
# devout mauve as general advice btw, if any claim says "this formula will always be prime", th...

Formulas for the nth prime number actually exist! One was cleverly engineered in 1964 by C. P. Willans. But is it useful?


References:

Herbert Wilf, What is an answer?, The American Mathematical Monthly 89 (1982) 289–292.
https://doi.org/10.1080/00029890.1982.11995435

C. P. Willans, On formulae for the nth prime number, The M...

▶ Play video
marsh peak
#

That is what is meant in the remaining 1%

frosty linden
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yes i saw that

main idol
devout mauve
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abusing wilsons theorem to give integers or not I guess with the cosine there

marsh peak
frosty linden
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.close

knotty trellis
frosty linden
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ah

main idol
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bot's just slow

knotty trellis
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Stupid bot

main idol
devout mauve
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10 minute timelimit before bot can move channel again

frosty linden
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I wasn't thinking about the consequences of my question

devout mauve
#

how dare you

marsh citrusBOT
#
Available help channel!

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Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

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narrow kite
#

does anyone know how'd you maximize a function of this type?

narrow kite
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with respect to N

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i cant find anything on it

sand vigil
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what are d and g

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?

narrow kite
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where d>g

night mica
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try to use the formula for geometric series ..then you get a simpler function on N

narrow kite
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if so, good point. Thanks for help

night mica
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yes but i think you have to add a -1 because the series doesn t strat from 0

narrow kite
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alr how do I close this?

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.close

marsh citrusBOT
#
Channel closed

Closed by @narrow kite

Use .reopen if this was a mistake.

night mica
#

np

marsh citrusBOT
#
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kindred spear
#

could someone give me pointers for this

marsh citrusBOT
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Please don't occupy multiple help channels.

marsh citrusBOT
#

@kindred spear Has your question been resolved?

kindred spear
#

<@&286206848099549185>

kindred spear
#

higher probability and stochastic processes

marsh citrusBOT
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@kindred spear Has your question been resolved?

kindred spear
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can u tell more

marsh citrusBOT
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@kindred spear Has your question been resolved?

flat raft
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what's a geometric series

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I think here you just need to show that Q(A) satisfies all of the axioms of a probability measure

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which honestly I constantly forget, but it should be something like Q(emptyset) = 0, Q(the whole space) = 1, countable additivity, and nonnegativity

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countable additivity is where you might need to use monotone convergence

tacit fjord
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<@&268886789983436800> could you check this person's msg history along with their deleted msgs
Seems to just be trolling

kindred spear
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I'll try it out

kindred spear
flat raft
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no

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read the definition of Q

kindred spear
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right

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im guessing for a set A in the collection of events H, the measure Q outputs a number [0,1]

kindred spear
flat raft
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you need to prove that it is a measure

kindred spear
flat raft
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why didn't you just look it up

kindred spear
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i was trying to but i couldnt find smth explaining it

flat raft
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how do you expect to do a problem if you don't even know what it's saying

kindred spear
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found stuff taht used it

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like some proofs

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but didnt explain it

flat raft
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it's never defined in your textbook?

kindred spear
flat raft
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it's called an indicator function

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so what have you been wasting your time on

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if you don't even know what the problem is saying

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no it is not

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do you know what a sample space is

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let's say A is an event

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do you know what an event is

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do you know the definition of event

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bruh

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go review

kindred spear
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sure

flat raft
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an event is a measurable subset of Omega

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it is a set of outcomes

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"measurable" means it belongs to H

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no it is not

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you need to review the definitions of sample space, probability measure, random variable

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H is the set of all measurable sets

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do you know how expectation is defined

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do you know what a Lebesgue integral is

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do you know what a random variable is

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you kinda need to know the definitions

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to do something that depends on them

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after you review everything, to check your understanding, come back with an explanation of why E[1_A] = P(A)

marsh citrusBOT
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@kindred spear Has your question been resolved?

flat raft
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you need to show it for general random variables

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using the definition of expectation given by the Lebesgue integral

flat raft
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it's basically the same thing, because 1_A is a discrete random variable

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but you need to understand what the Lebesgue integral is and where the formula for discrete RVs come from

flat raft
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no you don't have to

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you should just know the definitions

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you don't

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just evaluate Q(omega)

flat raft
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it definitely isn't

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do you know what the definition of a random variable is

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im surprised that there would be any work for it