help-28

[minor needle]

💀

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torn jolt]

What am I doing wrong?

this is the formula i was going off of

and 85/pi * ((4/5)pi)/2 = 34 so idk what went wrong

[full forum]

@torn jolt Has your question been resolved?

Channel closed

Closed by @atomic zodiac

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[blazing dust]

Here i did this please check

5!/{(3!×3!)×6^6}

Which is option A

[full forum]

@blazing dust Has your question been resolved?

[blazing dust]

<@&286206848099549185>

[blazing dust]

.close

[full forum]

Channel closed

Closed by @blazing dust

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torn jolt]

I get the radius is 24 in, and I think I can use the equation $\omega=\frac{\theta}{t}$ to solve this since t is one hour, but I have no idea what $\theta$ is

[glossy valve]

Matt

[torn jolt]

also I dont get why I need to be converting it to inches when its asking for it in radians

[twilit leaf]

$\theta=\frac dr$

[glossy valve]

Garlik Bred von Friese

[torn jolt]

how does that work? theta can vary depending on the angle

theta can either be 1anything from 0 to 360 degrees wat

how can you get theta from dividing the diameter by radius

[twilit leaf]

distice/radius

Wow spelling

[torn jolt]

oh

i thought you were talkinga bout diameter

[twilit leaf]

how far does the truck go in a certain time frame t

Thats d

[torn jolt]

it goes 50 mph

ok but the question doesnt tell me how far the truck goes

so idk if i can use that yk

@twilit leaf

could i just use $w=\frac{v}{r}$ since it tells me the linear speed which is 50mi/h

[glossy valve]

Matt

[twilit leaf]

Oh yeah

Do that

[torn jolt]

but idk how id turn it into radians

the problem says "hint convert to inches/minutes"

but the final answer asks for radians

[twilit leaf]

Dont worry about rads yet

[torn jolt]

$\omega=\frac{50}{24}$

[glossy valve]

Matt

[torn jolt]

dont know how this answers the questionn tho

[twilit leaf]

Units

[torn jolt]

50 miles on top

and 24 inchs on bottom

$\omega=\frac{3168000}{24}$ ok both are in inches now

[glossy valve]

Matt

[twilit leaf]

$\omega = \frac{50 \frac{miles}{hour}}{24 \frac{inches}{radius}}$

[glossy valve]

Garlik Bred von Friese

[torn jolt]

$\omega = \frac{3168000 \frac{inches}{hour}}{24 \frac{inches}{radius}}$

[glossy valve]

Matt

[torn jolt]

i converted it to inches but idk what else to do

[twilit leaf]

Start cancelling and dividing things

[torn jolt]

$\omega=132000$

[glossy valve]

Matt

[twilit leaf]

UNITS

[torn jolt]

is that better?

[twilit leaf]

$\omega = 132000 \frac{rad}{hour}$

[glossy valve]

Garlik Bred von Friese

[torn jolt]

why the units on the side tho?

[twilit leaf]

do you think you can get it into rad/min?

[twilit leaf]

wdym

[torn jolt]

nvm i get it

[torn jolt]

yes just divide it by 60 but how did you go from inches to radians?

thats what im confused about mostly

like it was inches, then it skipped to radians

[twilit leaf]

How many inches are in a radius

[torn jolt]

for this question its 24

[twilit leaf]

Yeah, so you plug it in

[torn jolt]

ohh since its in inches (and since the radius is 24 inches), the miles were converted to inches and divided by the radius amounnt which turned it into radians

hopefully the way im thinking about it is correct

[twilit leaf]

Yeah

v is (distance unit/time unit) and r is (distance unit/radius) so v/r is (radii/time unit)

[torn jolt]

i see

and then when you divide it by 60, that would be the angular speed in rad/min

right?

[twilit leaf]

You can imagine multiplying by the conversion unit (1hour/60min)

[torn jolt]

ok i see

and to convert this to revolutionns per minute i think id just divide this by 2pi right?

[twilit leaf]

Yes, you can imagine multiplying by the conversion unit (1rev/2pi rad)

[torn jolt]

ok ty for your help

.close

[full forum]

Channel closed

Closed by @atomic zodiac

Use .reopen if this was a mistake.

[twilit leaf]

Youre welcome

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torn jolt]

I have no idea how to solve this or how to get started

I was considering using $v=\frac{s}{t}$ to solve this but im not given an arc length so i have no idea how to find v

[glossy valve]

Matt

[torn jolt]

I'm also confused which radius to take, as theres 2

<@&286206848099549185>

[full forum]

@torn jolt Has your question been resolved?

[robust slate]

I think it refers to the front sprocket

[full forum]

Channel closed

Closed by @atomic zodiac

Use .reopen if this was a mistake.

[torn jolt]

.reopen

[full forum]

✅

[torn jolt]

Knowing that now, how can I solve for the in/min

[robust slate]

tbh just do dimensional analysis

maybe there's a fancy formula but idk it

[sullen parrot]

Calculate the circumfrence of the wheel.

[torn jolt]

the formula for that is $2\pi r$ so $2\cdot\pi\cdot6=37.6991118431$

[glossy valve]

Matt

[torn jolt]

how does that help me tho?

[sullen parrot]

🗿 I said wheel not gear

[torn jolt]

oh

19/2=8

$2\cdot\pi\cdot8=50.2654824574$

[glossy valve]

Matt

[torn jolt]

@sullen parrot is that better?

[sullen parrot]

Find gear ratio

[sullen parrot]

Keep this aside

[torn jolt]

wdym?

6:3

2:1

[sullen parrot]

so its 2

[torn jolt]

2 to 1 yeah

[sullen parrot]

To find Wheel rpm:
Wheel rpm = Pedal rpm * Gear ratio

[sullen parrot]

Plug in the value and keep it aside

[torn jolt]

175 * 2 = 350

[sullen parrot]

Good!

Next, Linear speed in inches per minute:
Linear speed = Circumference * Wheel rpm

[torn jolt]

350 * 50.2654824574 = 17592.9188601

[torn jolt]

what is this formula tho? i thought linear speed = arc length / time

[sullen parrot]

Linear speed = (angular speed) * (radius)

Angular speed = (pedaling speed in rpm) * (2π)

[torn jolt]

and whats the formula for this?

how did you knnow wheel rpm = pedal rpm * gear ratio

so your steps were

1. find the wheel circumference
2. find the gear ratio
3. find wheel rpm by multiplying pedal rpm and gear ratio
4. find linear speed by multiplying wheel rpm and circumference

[sullen parrot]

ngl now I am confused myself

[torn jolt]

lmao

.close

[full forum]

Channel closed

Closed by @atomic zodiac

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tacit rapids]

5. is weird

because i don't see any variable x

hmm

or is it just me?

[torn jolt]

we arent doing calculus and its way above my experise but it kinda looks like the limit definition of a derivative

[tacit rapids]

yeah i know but

i need help finding the function f(x) =

4. was easy

oh wait

i think i can do something with the number 5

oh ok it makes sense now

since h is the change between two points

and the change is going away as h approches 0

so + 205 must be

9(5) - 10(5)^2

but since we're using f(5), we should change it to f(x)

and get 9x - 10x^2

.close

[full forum]

Channel closed

Closed by @tacit rapids

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[blazing dust]

Is this question wrong?

Answer is given 2

[short niche]

there's no B :(

[blazing dust]

Okay edited

[short niche]

i think it should be 1

[cyan wedge]

That's correct

[short niche]

D:

cause if the ratio is 1, then the sum of some positive number by itself infinite times is arbitrarily large

if the ratio is greater than one, the sum is similarly arbitrarily large. thus divergence

[short niche]

why so :(

[cyan wedge]

@blazing dust Shit i can't read, saw convegent and jumped to answer choices. Yeah, it's 1 wtf am i doing

[short niche]

oh. all good then. yay!

[blazing dust]

Huh

I asked is this question wrong?

[cyan wedge]

yeah it's wrong. Anime girl is right

[blazing dust]

May I know the reason?

[cyan wedge]

good reasoning

[short niche]

anime girl haha. well the reason is here

[blazing dust]

In a series convergence and divergence can possible at one time?

You didn't mention convergence

[short niche]

no it's not possible. it's just they are saying given those conditions they will diverge instead. i think the question is worded badly yea

the convergence mentioned earlier is.. irrelevant.

[blazing dust]

They are talking about only one series

Yes irrevalent thing made it difficult

Un+1/un >=1 divergence by ratio test

Un+1/un<1 converge

[short niche]

yea just badly worded

[blazing dust]

Thanks

Anime girl

😆

[short niche]

yea

why can i change my name!!!!

[blazing dust]

Maybe in settings

[short niche]

can't

no the mods set my name i think

[blazing dust]

.close

[full forum]

Channel closed

Closed by @blazing dust

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[junior veldt]

<@&286206848099549185>

[cyan wedge]

Where are you in the process?

[junior veldt]

bro i didnt do nothing

[cyan wedge]

Well, I'm not gonna churn out the answer for you

[junior veldt]

bro really?

im on the first step

hello alpaca

[cyan wedge]

Ok, so tell me the locations of the two points in the form (x,y). Then, can you remind me what step 4 stands for?

[junior veldt]

this is 8th grade btw

wait i gotta go bye baby

[cyan wedge]

ok go to bed

man just left

[full forum]

@junior veldt Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[blazing dust]

Which book covers these topics?

[fathom saddle]

Looks like differential equations

[full forum]

@blazing dust Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[shell dawn]

i dont understand what's happening in the second step

sir said it was via binomial expansion, but i dont get it

[torn jolt]

Context for this question?

[shell dawn]

oh also value of x is very small

[torn jolt]

Yeah

Thats why he brought down the exponent to multiplication

[shell dawn]

i dont understand how that works

[torn jolt]

So here

What we generall mean by x is small is

It is very small as compared to the other term in addition or subtraction

So

Do you agree
(100000)²
(100000 + 0.001)² = (100000.001)²
Do not have much difference in them?

[shell dawn]

yes

[torn jolt]

As the second term is very small

[blazing dust]

Yes but option?

[torn jolt]

?

[shell dawn]

yea i understand how that part works. i didnt understand how the "power is being brought into multiplication"

[torn jolt]

Yeah so refer to the image

You must also know

When a number is less than 1
Its square is less than 1 too and also lesser than the original number

Positive integers im talking about

[blazing dust]

Discord glitch

[torn jolt]

so
(½)² = ¼

[shell dawn]

yea so x^n is even smaller, gotcha

[torn jolt]

Yeah

Now refering to the image

The second and third line is the correct binomial expansion

There

You see for the second and third term we get x² and x³

Now as you know x² is a very small value

The whole term tends to zero

And similarly thereafter

So all that remains (significant portion) is the first term

(1 +nx)

[shell dawn]

ohh okay i get it now

[torn jolt]

So all done?

[shell dawn]

we ignore all the terms with x in them

and only consider first term

[torn jolt]

Not x

x², x³ and so on

[shell dawn]

yea x^n

mhm

[torn jolt]

Yep

Cuz they make the term very very small

Think of x as small

Then x² is doubly small
x³ is too small

They multiply to anything to just give a valuevery near to zero

Thats why we only consider till the x term

[shell dawn]

ohk yes i get it now

thanks

[torn jolt]

You're welcome

.close if youre done

[shell dawn]

.close

[full forum]

Channel closed

Closed by @shell dawn

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torn jolt]

Could you say then when N>2 that the expresion can be represented where (5x5)^n-1 and any odd integer x another odd integer = odd integer and the only odd multiples of 5 are numbers that end with a 5?

[short niche]

um sure

but here it says ends with 25, not 5

also, and the only odd multiples of 5 are numbers that end with a 5?
youve to probably show this as well if you want to use it

[torn jolt]

oh, then could you just indicate the prime factorization of 25?

[torn jolt]

how would you show that other than using an example?

i also thought it said it ended with 5

[short niche]

well lets go back to the question

try showing it with induction

the base case being n=2

[torn jolt]

so 5 ^ 2 = 25

then you do 5^n+1

Im kinda lost

im thinking o expressing 5^n+1 = 0 ( mod 25)

and 5^2 = 0 (mod 25)

which could potentially allow us to sub in 25a somewhere therefore its a divisor??

[acoustic pebble]

OK use induction

Base Case n = 2

Inductive step n=k

Now prove for n=k+1

A big hint is

||5^k = 25 mod 100||

||multiply both side by 5 boom||

[torn jolt]

ahh

[torn jolt]

when yo multiply the right side by 5 what happens

does nothing change?

[acoustic pebble]

125 mod 100 is?

[torn jolt]

ahhh

i see

ok

thank you

.close

[full forum]

Channel closed

Closed by @loud moth

Use .reopen if this was a mistake.

[acoustic pebble]

👍

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pale fog]

Help

[pale fog]

What does Arcsin 7\25 actually mean

[nimble crane]

It’s just another angle, no?

[pale fog]

I know it’s an angle but I just can’t solve this question

[nimble crane]

I believe you use conservation of energy here, alongside work

[pale fog]

yes you do but I can’t get the right answer

to resolve the perpendicular you do 0.5g x cos angle

but in the workings they just do 0.5g x 24/25

Idk why

[nimble crane]

what is the numerical answer provided?

[full forum]

@pale fog Has your question been resolved?

[pale fog]

What is the final answer to the question?

0/5586….

I’m lost here now and I don’t get the boxed bit

.close

[full forum]

Channel closed

Closed by @pale fog

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[deep sinew]

hi can someone help me with question c plz i cannot figure out how to write it in that way

[deep sinew]

pure 3 in 8th of jan
scary shit

[grizzled zodiac]

how did 4root192 become 32 root 3

[deep sinew]

root of 192 is 8 root 3

4 x 8 = 32 therefore 32 root 3

[grizzled zodiac]

RIGHT

[grizzled zodiac]

thanks man appreciate it 😉

[full forum]

@deep sinew Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[limpid monolith]

I'm struggling with finding the upper bound and lower bound for x and y for y^2>2x>0

[limpid monolith]

Do I draw a graph first?

[golden igloo]

anyone please help me with this question-Consider that a, b, c, d are positive real numbers satisfying (a + c)(b + d) = ac + bd.
Find the smallest possible value of S=a/b+b/c+c/d+d/a

[limpid monolith]

@golden igloo the channel is occupied

[last vapor]

Did u legitimately post this in every channel

Dude that's just rude

(and against the rules)

[limpid monolith]

Wow did he?

[last vapor]

yeah lol

[limpid monolith]

😭

[last vapor]

(also, very sorry, I'm not nearly good enough to understand your question, I just happened to be here)

[limpid monolith]

It's okay I just don't know how to draw the inequality y^2>2x>0

I don't know how to find the region

[golden igloo]

so where to ask any question, actually I am new to this server

[limpid monolith]

@golden igloo #help-26

.close

[full forum]

Channel closed

Closed by @limpid monolith

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[next basalt]

Encrypt in Z29 the number 10 with encryption function E (x) = 7x + 18. Then determine the decryption function D(y) and decrypt the number 8.

[next basalt]

I think I already solved decryption but I’d love some advice on how to actually remember

Encrypting 10 with the function gives me d = 7*10+18

So the function becomes
[7*10+18] mod(29) =1

[88] mod(29) =1

[1] mod(29) = 1

Which should be the solution to encryption? But what about decryption?

[devout valley]

Assumedly the decryption function is basically the inverse of E(x) and so you just need to work on "undoing" it, noting you're in Z29?

So any "division" is instead finding the multiplicative inverse mod(29)

[next basalt]

[devout valley]

Why the sad cat thumbs up

[lilac parcel]

sorry hijack but where does it say the D(y) is the inverse of E(x)? i remember that the professor said this but how would you prove it

[devout valley]

[well here I'm assuming that it should be, else otherwise "it wouldn't be encryption" - the idea is that if you encrypt something, then decrypt it, you get the original "message" back]

[As for proving it's the inverse, you'd just want to show that D(E(x)) = x]

[next basalt]

HOW should I know this 😭

[devout valley]

Did they like not explain that before?

[next basalt]

No we have different teachers, my teacher spoke Bulgarian so I don’t understand him.

D(7x+18) = …?

[lilac parcel]

vilken del är det du inte fattar?

[devout valley]

Well, maybe let me "change" the question a tiny bit for a second

Forget modular arithmetic for a moment, and anything in it

Just as a real function, can you find the inverse of the function f(x) = 7x + 18 for me please?

[next basalt]

x= -18/7

[devout valley]

that's a single point, I meant more like

Rearrange y = 7x + 18 to get x by itself?

[next basalt]

Oh I forgot y lol

x = y/7 -18/7

[devout valley]

Yep, that's it

[devout valley]

Now, remember how I said this here

So if instead I asked you to find this inverse mod(29), rather than dividing by 7, you'd need the multiplicative inverse of 7 mod 29

[next basalt]

Ok

Not ok

[d*e] (mod 29) =1

Isn’t that what I have?

[lilac parcel]

is this like

modular inverses

[next basalt]

I’m glad I know what Modular inverses is then

[devout valley]

That's kind of what you want to find, so like in this case you want a solution $d$ to $7d \equiv 1 \mod(29)$

[glossy valve]

@devout valley

[next basalt]

Why 7?

[lilac parcel]

bc E(x) = 7x

[devout valley]

That's pretty much saying you want to solve $7d + 29k = 1$ (but you don't really care about what $k$ is too much)

[glossy valve]

@devout valley

[lilac parcel]

we need to find the coefficient inverse of 7 i guess

[next basalt]

E(x) is 7x + 18

[lilac parcel]

yeah but 18 is not important

the hard part is the coefficient in front of the variable

[devout valley]

Remember it's 7 you want the multiplicative inverse of (luckily here actually solving isn't too hard!)

[next basalt]

Ok..

[devout valley]

I promise it'll make more sense in the end remember that the multiplicative inverse of 7 is basically our "dividing by 7" in mod(29) - land

[lilac parcel]

but our professor was like

since [7*4]mod29 = [1]mod29

we want to find [-1] mod 29

so he just said it has to be [-4]mod29

is this really how one should generally approach these types of questions

[devout valley]

Well I mean trying to solve this one with the Euclidean algorithm basically tells you that: you know that 29 = 7(4) + 1, so 29 + 7(-4) = 1 and then reducing that mod(29) gives you that [7][-4] = [1]

[devout valley]

Assumedly they meant [-1] here? 7 * 4 is 28

[lilac parcel]

yes sorry that's correct

are we lookihgn for [1]mod29 beause 7d = 1 mod 29

[next basalt]

Welp

I have literally zero idea what you guys just said

[lilac parcel]

but I feel like I would've done it like

29 = 4(7) +1 instead of putting the 7 there

it's the same thing i guess, but it's beacuse I don't "know" that I have [-4]mod29 yet if that makes sense?

i know im computing in base29 and i know 7 is my encryption key from the function correct?

[devout valley]

As in you were trying to find [d] as [-4]?

[devout valley]

Yep you do

As long as you can get to finding the inverse, that's like the most important thing (is that alright at least?)

[devout valley]

tl;dr can you e.g. solve that 7d + 29k = 1 from before?

[lilac parcel]

yeah i understand it

[next basalt]

solve for d or k?

i assume d since decrypt?
d = 1/7 - 29k/7

[devout valley]

Well both, using the Euclidean algorithm, remember the stuff you were doing earlier

You want d and k as integers, so like remember how you keep doing the division and then reverse the steps at the end

[next basalt]

dio equations ?

[devout valley]

So like you know how e.g. 29 = 7(4) + 1 of course (and wow life is comfy!)

[next basalt]

Where did you get 29k from?

[lilac parcel]

sorry

d(7) = 1 mod 29

29 = 4(7) + 1 <- thi remaining 1 is equivalent to 1 mod 29 when d=4

but since we are looking for inverse d=-4 instead of 4? so i just make it negative?

[devout valley]

The idea is that you want $7d \equiv 1 \mod (29)$, so like you know, for example, the difference $(7d - 1)$ should be divisible by 29

[glossy valve]

@devout valley

[next basalt]

Honeslty i can't even remember how to do that anymore..

[devout valley]

And you know that 29 is equivalent to 0 mod 29, so you basically get $0 \equiv 4(7) + 1 \mod(29)$, so rearranging that gets you that $-4(7) \equiv 1 \mod(29)$

[glossy valve]

@devout valley

[devout valley]

That's why you choose d = -4

[lilac parcel]

damn how would i have known

but yeah i get it then

so i can 'move things' around as i like?

to see things more clearly if that makess sense

[devout valley]

Yep, you can, rearranging mostly works "the same" as "normal" numbers

[devout valley]

Awww this one is a bit easier at least to deal with

[lilac parcel]

oh yeah i see it now

let's say d = 4

4(7) = 1 mod 29
28 = 1 mod 29 (not valid)
-4(7) = 1 mod 29 (valid)

[next basalt]

I guess i'll try another RSA question

||since i'm mentally braindead clearly||

[devout valley]

[next basalt]

I'm attempting another to see if i can understand it that way

n = 93
E(x) = x^e mod(93)

Determine decryptionkey for d with encryption e = 43

I know that the encryptionfunction e = x^e mod 93

e * d = x^e mod 93?
Where e = 43

idk

i'm fucked

E(x) = x^43 mod 93

would be my only guess..

[devout valley]

This is true, that is the encryption function

[next basalt]

okay hold on

So if i want to decrypt

i'll require the inverse of encryption E(x)

D(x) = 43sqrt(-93) ?

[devout valley]

Well you would be like trying to solve if I recall right e * d = 1 mod(phi(93))

[next basalt]

phi..

like how am i supposed to know that

e*d = 1 mod(93)

where e was 43

43*d mod (93) = 1 mod(93)

[devout valley]

Euler’s function

[next basalt]

Yeah i haven't covered Eulers yet

[devout valley]

wonder how they’re expecting you to cover RSA decryption and finding the decryption key then

From the way I covered it you basically needed it to find the decryption key from the encryption one

[next basalt]

idk

The course book and my teacher went through RSA before eueler

so i'm required to know euler to get rsa ?

[devout valley]

Well at least the way we learned it seemed to heavily imply you do, let me check

Well I mean you don't strictly need it fully, seems like how did they explain it to you?

[lilac parcel]

did u watch the vid i sent you on rsa encryption? they showed you that to get the n you need to use eulers

[next basalt]

My teacher didn't explain anything, we have to learn on our own

From online or coursebook

phi(n) = (p-1)(q-1) is that the part with Euler?

[devout valley]

Yep that is basically as long as you have that

[devout valley]

pretty "wonderful" of them

[bronze forum]

Hi!

[next basalt]

Yeah like 2/3 of my class just stopped going to his lectures because he couldn't speak english and his swedish was awful

So i basically only could rely on online

the last part here

[next basalt]

kollar om den atm

[devout valley]

That's one way to teach independence I guess... not a preferred way imo

[next basalt]

that isn't phi, is it?

[devout valley]

Yea this was what I meant earlier

$\phi$

[glossy valve]

@devout valley

[devout valley]

it isn't but at least the places I've seen it use that one haha

[next basalt]

I'm glad my teacher depict phi as a straight vertical line through an o

[devout valley]

Doesn't matter its name, what it does is more important

[next basalt]

oh it does something in particular?

or just the q-1 * p-1

[devout valley]

It does, all you really need to worry about at least here is that phi(pq) is (p-1) * (q-1) to be fair

(there are some other properties that it has, but meh )

[next basalt]

Okay so if i understand it correctly.
If we have the encryption key, e then we need to do a Extended Euclidean Algorithm?

Based of this

d * e = 1 mod phi(n)

[devout valley]

That's like the idea, you pick the encryption key then use the extended Euclidean algorithm and then that gets you the decryption key

[devout valley]

[This is a similar idea to the last question: d is the multiplicative inverse of e mod(phi(n))]

[next basalt]

I don't get that last part

In my case

n = 93
E(x) = x^e mod 93
e = 43

d * e = 1 mod phi(n)
d * 43 = 1 mod (93)

that should be correct

[devout valley]

Yea, that's what you're solving, you want to find d

Are you happy with them getting to d = -17 = 23 mod40, or was that the bit you don't get?

[next basalt]

I don't get anything

i'm only guessing so far

only intuitive guesses

based of yt videos

like i'm supposed to remember all this as well by heart since nothing we go through right now will be permitted aid on the exam

so i have to remember
p =
q =
n = p * q
F = (p-1)(q-1)
d = decryption key
e = encryption key

d * e = 1 mod(n)

I think that's all?

[devout valley]

Pretty much yep, you pick p and q randomly (and prime), find the rest, and then you pick your encryption key e and use that to find the decryption key d from d * e = 1 mod(phi(n))

[next basalt]

phi(n) = (p-1)(q-1)
n = (p-1)(q-1)

are these equivalent?

[devout valley]

n is pq, but phi(n) = (p-1)(q-1)

[next basalt]

ok!

so when i'm given an encryption function

E(x) = x^e mod 93

uh

let me think

nah nu clue what i'm doing

lol

can't even guess myself to the answer

[devout valley]

it is a bit pain

[next basalt]

runnning out of time aswell

[devout valley]

Oh yea, shit

Hmm, how do you feel about the multiplicative inverses?

[next basalt]

so if n = 93 and i need F, how do i go about doing that?

[next basalt]

Don't even know what they are

[devout valley]

Well, 93 is 3 * 31, so then your F is then (3 - 1) * (31 - 1) = 2 * 30 = 60

[devout valley]

definitely worth going over if you can might make stuff much easier

Tl;dr they're basically the equivalent of "how you divide" as per before

[next basalt]

ed = 1 mod phi(n)
where n = 93
e = 43
E(x) = x^e mod 93

phi(n) = F

right?

F = 60

[devout valley]

Yep to all

[next basalt]

So uh

$ed \equiv 1 mod phi(n) \implies 43*d \equiv 1 mod(60)$

idk how to make the =

with another -

[devout valley]

\equiv

[glossy valve]

Merineth

[next basalt]

i guess something like that

and now i want to solve for d

[devout valley]

Yep, that's the whole "multiplicative inverses" thing

[next basalt]

Wait what is?

When solving for D?

[devout valley]

Solving this

[next basalt]

oh

But that's just

extended euklides ?

[devout valley]

Pretty much, as per before, you're basically solving 43d + 60k = 1

[next basalt]

$60 = 1 * 43 + 17 \
43 = 2 * 17 + 9 \
17 = 1 * 9 + 8\
9 = 1* 8 +1$

[glossy valve]

Merineth

[next basalt]

How do you know this?

[devout valley]

e.g. you want 43d to have remainder 1 when you divide it by 60, so for example you want 43d to be 1 more than some multiple of 60

That's then equivalent to trying to solve the equation 43d + 60k = 1

[next basalt]

how do i decrypt a specific message?

y = 33

[devout valley]

You do y^d to decrypt

Where d is the decryption key you find

[next basalt]

how do you know that

uhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

like it doesn't say that anywhere in the book

fml

[devout valley]

what do they have in your book?

[next basalt]

honestly i woulnd't be able to translate it because i can barely read it in swedish

[devout valley]

pain

[devout valley]

How does the video here explain it then?

[next basalt]

https://www.youtube.com/watch?v=O-4_oS3G7MI&t=253s

as far as i could tell

she didn't cover it

but i prooooobably am worng

[devout valley]

About 7:07 does it

[next basalt]

oh about that

m = c^d mod n

is that an actual formula that i have to remember?

[devout valley]

Well kind of, with "m" for message and "c" for ciphertext, so like c^d is the process of decrypting the ciphertext c under RSA to recover the "original message" m

[next basalt]

c = m^e mod n
m = c^d mod n

ciphertext?

Never heard that before

[devout valley]

ignore me then haha

But basically c is what you have encrypted, m is the original, and encrypting and decrypting are "opposites" of each other!

[next basalt]

do you think if i remember those two formulas

i'll be fine?

to solve other similar quesitons with RSA

or do i have to remember the de = 1 mod phi(n) also?

[devout valley]

You need these here too

[devout valley]

But that alongside this, and...

[devout valley]

...this, that's pretty much all you need!

[next basalt]

p =
q =
n = p * q
F = (p-1)(q-1)
d = decryption key
e = encryption key
d * e = 1 mod(n)
c = m^e mod n
m = c^d mod n

so this total?

[devout valley]

Yep

[next basalt]

it's CRAAAAAAAAAAZY that we aren't provided this info hahah

that we have to remember it by heart

Q.Q

I will try and find another RSA question and attempt it

one momendito

[devout valley]

yeaa that's pretty pain had to memorize that and damn, ouch

[next basalt]

oh i didn't realize we had a Japan kitty

[devout valley]

[next basalt]

I'm gonna do the first one then

Encrypt in Z29 the number 10 with encryption function E(x) = 7x + 18. Then determine the decryption function D(y) and decrypt the number 8.

[devout valley]

Oh yea

You should hopefully be a bit happier with solving something like $7m \equiv 1 \mod(29)$ hopefully!

[glossy valve]

@devout valley

[next basalt]

okay so

c = m^e mod n

isn't that the one which is applicable ?

[devout valley]

Not for this one nope

Remember you're trying to find an m such that you have the above

[next basalt]

29 = 4 * 7 + 1

would be my solemn guess

so

1 = 29 - 4*7

1 = 29 -28

so m is 28?

[next basalt]

how did you come up with this? @devout valley

that is not how i would've guessed

[devout valley]

Take this one here

That then tells you that m = -4

[next basalt]

oooooh

[devout valley]

Because that's what's in front of 7

[next basalt]

E(x) = 7x + 18

based of this?

so m = -4

wb 18?

[devout valley]

Yep, so then, to reverse it, you basically have like

$[y] = [7x + 18]$, so $[y] - [18] = [y] + [11] = [7x]$ (noting that 29 - 18 = 11)

[glossy valve]

@devout valley

[devout valley]

So then because [7x] = [7][x], you "divide by 7" (which is of course multiplying by the inverse of [7], which is [-4])

[next basalt]

I'm not sure i have enough time to process this, learn it before the exam tbh and fully solve an exam question revolving RSA

[devout valley]

That then gets you that $[-4][y + 11] = [-4][7][x] = [-4 * 7][x]$, which is basically telling you that $[x] = [-4][y + 11]$ and all

[glossy valve]

@devout valley

[devout valley]

Awww can be quite a bit to learn, though of course worth noting that the inverses thing is kinda the same thing in RSA anyway

[next basalt]

Encrypt in Z29 the number 10 with encryption function E(x) = 7x + 18. Then determine the decryption function D(y) and decrypt the number 8.

If i were given this

i would probably

p =
q =
n = p * q
F = (p-1)(q-1)
d = decryption key
e = encryption key
d * e = 1 mod(n)
c = m^e mod n
m = c^d mod n

make this ^

and fill in what i know

and guess my way forward

Becuase honestly i have no idea what you are doing

I read it but it's not sticking

[devout valley]

This one is slightly different to RSA

Which is a bit pain of course if it's not too helpful may be worth focusing on the RSA stuff

[next basalt]

Well that is an exam question

so apparantly they are expecting me to understand it

[devout valley]

yeaa, though of course does take some explaining and covering of a bit

[full forum]

@next basalt Has your question been resolved?

Channel closed

Closed by @next basalt

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wraith violet]

hello, does anyone have any idea to prove pt(iv) using the previous parts because i am stuck

[full forum]

@wraith violet Has your question been resolved?

[wraith violet]

/close

.close

[full forum]

Channel closed

Closed by @wraith violet

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torn jolt]

can someone help me integrate this

[buoyant pewter]

use the substitution u = 4 - x

[full forum]

@torn jolt Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[blazing dust]

What is this property?

[full forum]

@blazing dust Has your question been resolved?

Channel closed

Closed by @blazing dust

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torn jolt]

Okay I'm cooked

[torn jolt]

#[derive(Clone, Copy, Debug)]
pub struct Vec2 {
    pub x: i64,
    pub y: i64,
}

impl Vec2 {
    pub fn cross(&self, other: &Self, point: &Self) -> i64 {
        let ab = self - other;
        let pa = point - self;

        ab.x * pa.y - ab.y * pa.x
    }
}

So i have this cross function that is supposed to determine which side of an edge a point resides on.
The edge is from self to other which are points in space.

I would had thought it would be the cross product between the edge from self to other and the edge from the (origin) to the point

other - self and point - self but that does not seem to work at all.

I thought it was other - self because the edges(vectors) have to be (moved) to start at the origin.
But that doesn't seem to be the case

picture

[full forum]

@torn jolt Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torn jolt]

question: find the sum of all possible 4 digit numbers that can be made using the digits 2,3,4 and 5 exactly once. I found a way to approach this problem but i think there's a flaw in it. Break the 4 digit number in the following manner: 10³×a +10²×b +10¹×c +d. 'a' can take any of the four values (2,3,4,5) and that would repeat 3! times. Similarly, for b, c and d. So the answer would be 10³×(3! ×14)+ 10²×(3! ×14)+ 10¹×(3! ×14)+ 10⁰×(3! ×14). But i suppose the cases would be repeated. For example, consider the number 2345. It would appear once when a=2, once when b=3, once when c=4 and once when d=5, which means it has been repeated 4 times.

[full forum]

@torn jolt Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[blazing dust]

How to solve this one?

[minor crater]

there's so many wrong things with this

what's m? is this supposed to be n?

[blazing dust]

I don't know either

[minor crater]

did they mean to take the square root there?

[minor crater]

oof

[blazing dust]

Yes

[minor crater]

huh

i don't see the pattern then

is the last term supposed to be $\sqrt[n]{x_n}$?

[glossy valve]

artemetra

[minor crater]

sorry but i really don't know how to tackle this. hopefully someone else will be able to help you

[blazing dust]

<@&286206848099549185>

[full forum]

@blazing dust Has your question been resolved?

[elfin stream]

its written incorrectly

[elfin stream]

ig yeah

[blazing dust]

Acha

Tq

.close

[full forum]

Channel closed

Closed by @blazing dust

Use .reopen if this was a mistake.

[elfin stream]

.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hybrid nexus]

solve for theta

[hybrid nexus]

can someone help me solve this pls

<@&286206848099549185>

say $$8a\sin\theta-\frac{9b\cos\theta}{2}-\frac{7}{16}\sin2\theta=0$$

[glossy valve]

magnusOP

[torn jolt]

do you know double angle identity for sin

[hybrid nexus]

sin2theta = 2sinthetacostheta?

[torn jolt]

good write that and you can simplify something

[hybrid nexus]

i did

but i wasnt able to

[torn jolt]

show me your work

[hybrid nexus]

i havent been able to simplify it past writing sin2theta as 2sinthetacostheta

[thick hedge]

try subbing x=cos(theta) and then solve it

it will be ugly

but it should work

[hybrid nexus]

but i dont know inverse trignometry

[thick hedge]

oh, so you can't express your answers ans inverese trig functions?

like arcsin(a)?

[hybrid nexus]

this is was actually a part of a bigger question, i had to find maxima of

so i assumed phi to be a constant and differentiated

which led to that eqn

[thick hedge]

hmm, you can find sin(theta)

by solving for x

from that find cos(theta) too

[hybrid nexus]

but how

[thick hedge]

x=sin(theta)

solve for x

you'll get sin(theta) from that

[hybrid nexus]

but we have cos also r8

u want me to write that in terms of sin and then solve?

[thick hedge]

yes

take that to the other side

then square it

[thick hedge]

are you sure phi is a constant here ?

[hybrid nexus]

its not

but i asssumed it to be

[hybrid nexus]

how else wud u find maxima for that eqn

[thick hedge]

Chain rule, maybe. I can't help anymore now, GTG
Sorry

*right now

Sorry again

[hybrid nexus]

oof ok

but there are 2 variables

[full forum]

@hybrid nexus Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lapis ingot]

is there a curvilinear asymptote when the numerator is greater than the denominator by 2 degrees ?

[deep mauve]

is it polynomial function?

[lapis ingot]

yeah

[deep mauve]

something like x³/x

[lapis ingot]

yes

[deep mauve]

the rest is not important so much

[lapis ingot]

but with extra stuff

okay

[deep mauve]

so it is 2. degree

[lapis ingot]

so is that when theres a curvilinear function?

and if higher by 1 degree its a slant or oblique asymptote?

[deep mauve]

Dude I don't know a quadratic asymptote

Maybe there may be point undefined

So it may be undefined at some point, but I don't think it's an asymptote

[lapis ingot]

nvm i got the answer

this is a curvilinear asymptote

thanks i appreciate the effor though

.close

[full forum]

Channel closed

Closed by @lapis ingot

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[full forum]

@tough blaze Has your question been resolved?

[kind lynx]

<@&268886789983436800>

^

[full forum]

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[restive geyser]

If we assume
a equation such as

4√2=4

here let √2=x
so
4x=4
x=4/4
x=1

this is not true why?

[ember shadow]

the original equation is not true

[light nest]

yeah

thats false so

[restive geyser]

can you correct it?

[ember shadow]

no

it is simply not true

unless there is more context, there's nothing else to say about it really

[restive geyser]

so we just cat assume root as variable?

[ember shadow]

it's not a variable, it's a number

[restive geyser]

cant*

[restive geyser]

oh

[nimble crane]

it's like if i said that 10 = 5

so 5(2) = 5

so 2 = 1

[restive geyser]

thank you

[ember shadow]

what is your original question? what is the context?

[restive geyser]

dont worry aboutit

.close

[full forum]

Channel closed

Closed by @restive geyser

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torn jolt]

in the middle of trying to apply feynman

and idk what to plug in for t

to solve for C

this is the original

i could prob do normal trig sub, but i want to do feynman

[full forum]

@torn jolt Has your question been resolved?

[buoyant pewter]

$\text{Note that for }b>0\\\int_{0}^{\infty}\frac{\ln\text{}x\text{ }dx}{x^{2}+b^{2}}\overset{\ast }{=}\\x=\frac{1}{t}\Leftrightarrow dx=-\frac{1}{t^{2}}dt\\\overset{\ast }{=}-\int_{0}^{\infty}\frac{\ln\text{}t\text{ }dt}{1+b^{2}t^{2}}$

[glossy valve]

Joanna Angel

[full forum]

@torn jolt Has your question been resolved?

[full forum]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[torn jolt]

.reopen

[full forum]

✅

[torn jolt]

i still dont see how this helps solve the integral using feynman

[full forum]

@torn jolt Has your question been resolved?

[full forum]

@torn jolt Has your question been resolved?

[gritty rose]

!show

[full forum]

Show your work, and if possible, explain where you are stuck.

[buoyant pewter]

I give you a deeper hint:

$\int_{0}^{\infty}\frac{\ln\text{}x\text{ }dx}{x^{2}+b^{2}}\overset{\ast }{=}\\x=\frac{1}{t}\Leftrightarrow dx=-\frac{1}{t^{2}}dt\\\overset{\ast }{=}-\int_{0}^{\infty}\frac{\ln\text{}t\text{ }dt}{1+b^{2}\cdot\text{}t^{2}}\overset{\ast}{=}\\t=\frac{u}{b}\Leftrightarrow\text{}dt=\frac{du}{b}\\\overset{\ast}{=}-\frac{1}{b}\int_{0}^{\infty}\frac{\ln\text{}u-\ln\text{}b}{1+u^{2}}du$

[glossy valve]

Joanna Angel

[full forum]

@torn jolt Has your question been resolved?

[full forum]

Channel closed

Closed by @raven ferry

Use .reopen if this was a mistake.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[blazing dust]

Hints please

Except riemann sir 🫣

[thick flower]

thats (1^(1/n)+2^(1/n)+...+n^(1/n))/n, yes?

[blazing dust]

Yes

[thick flower]

my hint is, what is the limit of 1/n as n approaches infinity?

[blazing dust]

0

[thick flower]

what is 1^0, 2^0, n^0?

[blazing dust]

1+1+1+1..... =N

So n/n=1

Answer

Yooo bingo

Thanks

[thick flower]

np

[blazing dust]

.clod4

.clod4

.close

[full forum]

Channel closed

Closed by @blazing dust

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

[full forum]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[worldly heron]

ok so for this one just to dobule check all we do is 84,000 * 0.75^3 ?

or do we subract that answer from the original 84,000

[worldly heron]

is the square around the brackets or the x is included?

[spare comet]

$x \cdot (x-1)^2$

[glossy valve]

A Spoon

[spare comet]

@worldly heron

[worldly heron]

so

i see

it would then final anseer wouild be

X^3 -2x +1

@spare comet

[full forum]

@worldly heron Has your question been resolved?

[elfin stream]

,rccw

[elfin stream]

Oof

[worldly heron]

what

.close

[full forum]

Channel closed

Closed by @worldly heron

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[muted kite]

Can someone help me about the graph polynomial function? , I actually have an incomplete notes in my nb and it says :

**Degree of polynomial function :

1. if the degree of the polynomial function is even, then the left........**

does someone know what's next? please elaborate thanks so much !

[rough tundra]

are you familiar with end behavior?

[torn jolt]

what is the context?

left something can be anything no?

[rough tundra]

I think it's end behavior

[muted kite]

noo, I was in another activity while my class having math T^T

[torn jolt]

yeah so rn we have no clue what this is about

so we cant say anything

[muted kite]

its abt

graph of polynomial function

about the degree

[torn jolt]

okay but i hope you recognise the amount of variation "left something" can be describing

[muted kite]

left, as in lefr

left

[torn jolt]

was this given to you in english?

[muted kite]

opposite of right

[muted kite]

yea

[muted kite]

i think so too

[torn jolt]

you just said you werent familiar with end behaviour so how can you say that? But anyways, i wont play detective. If you want to go with the end behaviour we can go with the end behaviour

are you familiar with the graphs of functions like x^2, x^4, ...?

[muted kite]

I did a search

[muted kite]

not yet, i think we haven't discussed that

[torn jolt]

so you dont know what $\m fx = x^2$ is?

[torn jolt]

for example

[muted kite]

OHH THAT

ik that

[torn jolt]

ok so do u know how it looks like in a graph?

[muted kite]

nope

[torn jolt]

what grade is this for btw? Its suspicious you would be considering end behaviour without knowing the graph of the function even

[muted kite]

10TH

[muted kite]

graphing of polynomial functions just got introduced to us

[torn jolt]

,w plot x^2 from -20 to 20

[glossy valve]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by qylooo

[muted kite]

so like my teacher isnt really teaching us how to really graph

[torn jolt]

this is what f(x) = x^2 looks like

[limpid moat]

"looks like"?

[torn jolt]

it looks a parabola or a U

[muted kite]

ohh so that's a quadratic function?

[torn jolt]

yeah it is

[limpid moat]

in which way?

[torn jolt]

? what are you talking about

[muted kite]

will they look the same when graphing? T^T

[torn jolt]

this is graphing

[muted kite]

I MEAN

[limpid moat]

maybe she doesn't even know what is a function's graph

[muted kite]

does it apply to other quadratic functions??

[torn jolt]

?? she is studying end-behaviour. She needs to know what the graph is like

[muted kite]

im so sorry im so dumb rn

[limpid moat]

you have to say to her that it is the set of point such that (x,f(x))

[torn jolt]

No. Not all of them

[muted kite]

but its quadratic tho why?

[torn jolt]

wdym?

[muted kite]

khsajdfhsfjsah

hold on

i cant explain

[torn jolt]

can you send me an image of your question without you typing it? Preferbly like the full paper if this is a homework

i really need to gauge what this is about

[muted kite]

the questions imasking is on my mind........i really dont have like a literal paper to problem to solve

i just wnna understand

so like for example

f(x) = 3x^2 , it is quadratic right? so if you're gonna graph it will it look like the graph of f(x)=x^2 ?

[torn jolt]

yeah

what the 3 is doing is vertically stretching it

[muted kite]

how?

[torn jolt]

those are called function transformations

[torn jolt]

take a few points for example

[muted kite]

oh so the graph will loook the same but abit larger?

[torn jolt]

for f(x) = x^2, you have f(0) = 0, f(1) = 1, f(2) = 4

but for f(x) = 3x^2 you have f(0) = 0, f(1) = 3, f(2) = 12

do you see how the second one is "getting there" faster than the first?

[torn jolt]

no the opposite

it will look thinner

[muted kite]

whyy??

isnt 3x^2 bigger than x^2

[torn jolt]

this is a desmos illustration

[torn jolt]

well again think of what the other person said earlier

a graph is just a collection of points (x, f(x)) right?

do u agree with that

[muted kite]

oh so the bigger thing the thinner in the graph??

[torn jolt]

yes

[muted kite]

OHHHH

I SEE