help-26

[eternal spoke]

so 3x=2x+3

cuz you know the lenght is 2x+3

and the lenght is also 3x

so you set them to be equal

ok?

do you get it?

[coral sapphire]

Ok

Yes

[eternal spoke]

so x is 3

[coral sapphire]

Ok

[eternal spoke]

so whats the side of the graden?

2x+3

and x is 3

[coral sapphire]

Yes

[eternal spoke]

ok so how long is the side of the graden

?

[coral sapphire]

The entire thing or the one in the middle

[eternal spoke]

the side of the garden

the graden is the green thing

you know its side is 2x+3

and x is 3

so how long will the side be>

[coral sapphire]

Am I supposed to plug it in?

[eternal spoke]

yes

[coral sapphire]

9

[eternal spoke]

yes

good

now the area

if the side is 9

whats the area?

[coral sapphire]

81

[eternal spoke]

yeah

good job

now b)

the area of the walkway

it is made out of how many squares?

[coral sapphire]

16

[eternal spoke]

yes

an whats the area of a single tile?

[coral sapphire]

X^2

[eternal spoke]

yeah

good

and x is 3

so...

[coral sapphire]

Wait but I’m supposed to get an answer with X in it like 4x^2+12x+9 and stuff I’m not supposed to make it only numbers

[eternal spoke]

you found x

x is 3

[coral sapphire]

Yeah but I’m not supposed to plug anything in for x

[eternal spoke]

i dont get what you mean

everywhere where you see "x", replace it with 3

it should make it easier

[coral sapphire]

But I’m not supoosed to do that

[eternal spoke]

why not

[coral sapphire]

I’m supposed to be combining them and stuff like that not solving for x

[eternal spoke]

nope

[coral sapphire]

BUT THATS WHAT THE TEACHER WANTS US TO DO

[eternal spoke]

bro

you can find x

im 100% sure your teacher doesnt want you to do that

if you can find x

why not do it

i dont understand

😐

[coral sapphire]

Alright so we got 2 papers. One with the problems and one with the answers where you have to color it and stuff. On the answer paper it says the answers for this question are 4x^2+12x+9 and 21x^2-12x-9. But I need to show how to get them

[eternal spoke]

ok

but just so you know

its not wrong what i told oyu

[coral sapphire]

Ok

[eternal spoke]

that picture is specifically made to find x

that what the question should have been

anyway

so

the garden lenght is 2x+3

so whats $(2x+3)^2$

[thorny flame]

Master Oogway

[eternal spoke]

?

[coral sapphire]

4x^2+12x+9

[eternal spoke]

yes

nice

[coral sapphire]

But the other one

[eternal spoke]

what

[coral sapphire]

Is impossible to get

The other answer

[eternal spoke]

🤣

lets see

so

whats the area of a single tile?

[coral sapphire]

X^2

[eternal spoke]

good

how many do we have?

[coral sapphire]

16

[eternal spoke]

good

what do we do now?

[coral sapphire]

I don’t know

[eternal spoke]

)

its like saying

x^2 plus x^2 plus x^2 plus x^2..........

16 times

right?

[coral sapphire]

Yeah

[eternal spoke]

ok]

so...

[coral sapphire]

16x^2

[eternal spoke]

nicee

yeah

thats it

well done

[coral sapphire]

NO IT ISNT

[eternal spoke]

it is

[coral sapphire]

or maybe the teacher got it wrong

[eternal spoke]

yes he did]

do you see any mistake in what we did?

i dont

[coral sapphire]

I don’t know I’ll just leave it like this

It’s the only problem I got wrong

[eternal spoke]

nope

its the only problem HE got wrong

😇

[coral sapphire]

So how do I write it

As an equation

[eternal spoke]

at b. ?

[coral sapphire]

Yes

[eternal spoke]

area of the walkway=$16\cdot x^2$

[thorny flame]

Master Oogway

[eternal spoke]

so $16x^2$

[thorny flame]

Master Oogway

[coral sapphire]

Ok

Thanks

[eternal spoke]

np

wait

ask your teacher

if it is wrong to find "x"

cuz i dont think it is

ok?

[coral sapphire]

I already passed that class

It was last period

[eternal spoke]

ok

bye

.close

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[neon iron]

How do I do 10

[topaz sinew]

@neon iron Has your question been resolved?

[past kayak]

What have you tried?

[neon iron]

What I showed in my work

3x2x4x3x2

But I get 144

[neon iron]

So how do do it

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[neon iron]

.reppen

.reopen

[topaz sinew]

✅

[past kayak]

Well, how many ways are there to select 2 vowels and 3 consonants, if order didn't matter?

Order does matter, of course, but let's just consider this question first

[neon iron]

There’s 3 ways to chose vowels and 4 ways to choose constonants

[past kayak]

I mean, how many ways are there to pick the vowels and consonants together?

[neon iron]

144

Right?

[past kayak]

But I want to know if order didn't matter at all

[neon iron]

Oh then uh

7

?

[past kayak]

Not quite

[neon iron]

Ohhhh

Wait

Nvm I got nothing

[neon iron]

Sorry idk how to do that

[past kayak]

You know there's 144 ways to pick 2 vowels and then 3 consonants

How many ways are there to order those 2 vowels?

[neon iron]

10

?

[past kayak]

10 ways to order 2 vowels?

[neon iron]

Don’t u do 5 choose 2?

[past kayak]

Just look at the vowels

You're staring at only two letters

How many ways to order them?

[neon iron]

2 ways?

[past kayak]

Yes

[neon iron]

So then…

[past kayak]

So we can decrease the possibilities from 144 to 144/2 = 72

Because now we've eliminated orderings that had the same vowels but in a different order

[neon iron]

Oh kk

[past kayak]

Let's do the same for the consonants

How many ways are there to order 3 consonants?

[neon iron]

3

So then 72/3

[past kayak]

You sure it's 3?

[neon iron]

Oh wait

6

[past kayak]

Yep

[neon iron]

So then 72/6

[past kayak]

Which is?

[neon iron]

?

12

But I don’t get why u divide

[past kayak]

Well, let's say I had 3 letters: A, A, and B

[neon iron]

Ya

[past kayak]

These 3 letters can be ordered in 3! = 6 ways

However, this assumes that AAB and AAB are different orderings. Swapping the As counts as a different ordering, but it shouldn't

[neon iron]

Oh I see

[past kayak]

There are 2 ways to arrange the As, so for every unique combo, there's another combo that's the same with the As swapped

[neon iron]

But the word picture doesn’t have red eating letters

[past kayak]

So we divide by 2 to eliminate them

[neon iron]

Repaying

Repeating

[past kayak]

We're trying to ignore the ordering, so we're basically saying that the vowels are identical and the consonants are identical

But now we're gonna factor in the fact that order matters

There are 12 ways to grab a pile of 2 vowels and 3 consonants

[neon iron]

Acc I think I get it tysm

[past kayak]

To be sure, what do you think is the answer?

[neon iron]

12

Right?

[past kayak]

That's not the final answer, no

We need to account for the fact that order matters

[neon iron]

Ohhhh

So then..?

[past kayak]

We have a pile of 5 letters, right?

How many ways can we order them?

[neon iron]

10

[past kayak]

10 ways to order 5 letters?

[neon iron]

120?

[past kayak]

Yes

So there's 12 piles of 5 letters, and each of those piles can be ordered in 120 ways, what's the total number of orders?

[neon iron]

1440

Kk I think I understand now ty

U were so much help

Ty

[past kayak]

Np

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[empty sail]

This is more Chem related so you should go to a Chem server. I think there is on in #old-network

[dusty ember]

no it's a math quesiton

on my assignment

[empty sail]

Then plug in 9.4 and find $H^+$

[thorny flame]

dldh06

[empty sail]

It gives you the pH

[cold night]

In place of pH keep 9.4 and solve for $H^+$

[thorny flame]

Lelouch

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[lyric thistle]

This Is my solution but I think that this is wrong because it is a R3 to R2 transformation while this represents R3 to R3 I think

Idk what I did wrong.

[ashen eagle]

You did all well

If you put a (x1, x2, x3) you get (y1, y2)

congrats

[lyric thistle]

So this matrix is correct?

Cuz isn’t that R3 not R2

Ohh wait I’m trying to find the standard matrix

.close

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[fluid phoenix]

Blinding lights

that's really hard to see

[eternal spoke]

u mean this

https://open.spotify.com/track/0VjIjW4GlUZAMYd2vXMi3b?si=2a1f2981e6a447de

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@teal sentinel Has your question been resolved?

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@teal sentinel Has your question been resolved?

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@teal sentinel Has your question been resolved?

[covert slate]

At any point in time, the horizontal velocity vx=dx/dt and the vertical velocity vy=dy/dt. Then the speed is the magnitude of velocity, sqrt(vx²+vy²). This will ultimately just be a function of t that you can find maxima/minima of

[topaz sinew]

@teal sentinel Has your question been resolved?

[covert slate]

What is the answer you expect to get?

How do you know its wrong if you haven't compared it to a known correct answer

Don't be so pessimistic, my friend

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[mellow sequoia]

Im not sure how to calculate these areas

like

for the bottom triangle portion

is it just ∫x√3-0.5?

from x=0.28 to x=0.5?

[velvet whale]

yeah

[mellow sequoia]

I'm just confused bc I was previously asked to convert these equations to polar coordinates

so like

[velvet whale]

wait not 0.5

just the intgral of x sqrt{3}

[mellow sequoia]

oh because y=0.5 is considered the baseline

like the height is just the value of x√3

this is such a weird question though bc I'm in calc2 and this is def a calc1 question

is it possible to calculate these areas using the polar versions of these equations?

[velvet whale]

They may want you to integrate in polar coordinates instead of cartesian

yeah it is, this example doesn't seems super nice tho

[mellow sequoia]

but x√3 in polar coordinates is just ∂=π/3

thats meant to be theta^

[velvet whale]

yeah exactly

[mellow sequoia]

but ∫π/3 is just π/3*∂

[velvet whale]

you just need to express the circle as a polar function and find the other line

no no no, you need to integrate a function r(theta) from your first line to your second line

find the circle as a function r(theta)

[mellow sequoia]

I got r=2sin∂

wait

wait yes

[velvet whale]

it should be something like that lol, now find the angle made by the second line then integrate

[mellow sequoia]

isn't that just 0.5csc∂?

[velvet whale]

the integral?

[mellow sequoia]

the polar of the circle

wait no

the horizontal line

is y=0.5

so the polar of that is r=1/2sin∂

so 1/2*csc∂

[velvet whale]

Okay, so the line is y = x, right?

What angle does that line make with the x-axis?

[mellow sequoia]

45 degrees

so π/4 rad

[velvet whale]

okay, good. We have $$\displaystyle A = \int_{\theta_{1}}^{\theta_{2}} r(\theta) d \theta$$ where $\theta_{1} < \theta_{2}$. Now just fill in everything you know.

[thorny flame]

Billy Clintorus

[mellow sequoia]

oh okay yeah that makes sense thanks

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[velvet whale]

.reopen

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[velvet whale]

@mellow sequoia you do still need to be a bit careful, remember to subtract off the area of the triangle below the line y = 0.5

[velvet whale]

.close

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[floral sage]

“What is the height of a pyramid whose base side length is 140 cubits and seked 5 palms and 1 finger?”

[floral sage]

Someone gave me this problem and I know it’s Egyptian math but I don’t know how to do it

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@floral sage Has your question been resolved?

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@floral sage Has your question been resolved?

[floral sage]

Sure

.close

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[sturdy vigil]

Hi

[sturdy vigil]

,rotate

[sturdy vigil]

What rule is applied here?

Because 4^2 + 4^(1/3) should be 2/1+(1/3)?

[past kayak]

$a^{\frac{b}{c}} = \sqrt[c]{a^b}$

[thorny flame]

Gamer Dio

[sturdy vigil]

Thank you!

[past kayak]

How'd you get this?

[sturdy vigil]

well fractional rules right?

[past kayak]

2/3 ≠ 2 + 1/3

Moreover, a^(b + c) ≠ a^b + a^c

[sturdy vigil]

I seee

Thank you, I got it

.close

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[viscid storm]

Idk how solve that

I know how to do it for F2 but then i get lost

[loud ingot]

What is the question?

[empty sail]

If it's finding the resultant, sum of forces in x and y direction

[viscid storm]

Yes

Sow the questions says wait let me translete it sec

[patent forge]

you have to break F2 into its vertical and horizontal component using sin/cos

[viscid storm]

Mark the individual components of the forces on the coordinate system in the figures calculate the size of the force components given in the figure below and determine the size of the resultant

[viscid storm]

Yes but idk how to breka f3 and f1

Cuz they are weird position

[patent forge]

you dont need to break them

[viscid storm]

?

[patent forge]

they have only vertical and horizontal component to themselves

[empty sail]

F3 is already in the vertical direction only

[viscid storm]

Sow i need to add hypot.

[loud ingot]

F3 is in directly x direction and F1 directly y

[empty sail]

That's backwards, F3 is along y only

[patent forge]

you need to break f2 and add horizontal component to f3 and vertical to f1

[loud ingot]

Ah my bad

[viscid storm]

Can you pls send a pic idk what you mean

Please

[empty sail]

Use trig, find x and y components of F2

Add up all the x components, and add up all the y components

[viscid storm]

Is hard cuz language

You use rly difrent words in math stuff

How do i position it

[viscid storm]

Yes i know for that part but wht about f3 and f1

[empty sail]

You don't need to do anything to them

[patent forge]

they are in the x and y direction already

you dont need to break them

[viscid storm]

Sow i just add them after i am getti g frx and fry

[patent forge]

add f2sin40- F3 to get sum of forces in y direction and then add f1-f2cos40 to get sum of forces in x direction

[viscid storm]

?

[patent forge]

if you need resultant you can get it from that 2 vectors

[patent forge]

?

whats not clear in that :d

[viscid storm]

Can you simplify explanation

Why - and stuff

[patent forge]

💀

[solemn palm]

So we have a spinner with 6 divisions(1,2,3,4,5,6) each with probability 1/6.

What is the probability of getting (1 and 2 and 3) is after spinning the spinner in 10 times?

Find the probability of getting on (1 or 2 or 3) is after spinning the spinner in 25 times?

Find the probability of getting on 1 is after spinning the spinner in 5 times

[empty sail]

90% sure you swapped the sin and cos. If that is where the angle is, that the horizontal component is applying sin

[empty sail]

#❓how-to-get-help

[empty sail]

You add numbers in x direction together

Add numbers in y direction together

[viscid storm]

Sow the x is in -

And y is +

X is negative and
Y is positive

[empty sail]

For what?

[viscid storm]

Cuz f3 goes down

F1 is normal

[patent forge]

it can be it just points to the direction of your vector

[empty sail]

There is no reference to this

Are you referring to F1?

F2?

F3?

[viscid storm]

F3 is negative

Nad f1 is postive

Correct?

[empty sail]

Negative what?

[viscid storm]

-f3

[empty sail]

Negative z direction?

Negative y?

[viscid storm]

?

[empty sail]

What direction?

[viscid storm]

WdM

Wdym

[empty sail]

Negative just means negative

[viscid storm]

Yes minus

[empty sail]

What do you mean F3 is negative?

[viscid storm]

Sow if x goes under

Is negative

My bad

[patent forge]

yup yup mb

[viscid storm]

My bad

[empty sail]

What do you mean "x goes under"?

[viscid storm]

I switched them

Mbmb

Sow they both positive

?

[empty sail]

Whatever you are saying makes no sense

[viscid storm]

Can you solve it with robot

[empty sail]

No

You can solve it yourself

[viscid storm]

Idk how

That why i am here

🥲

[empty sail]

Add up the x components

[viscid storm]

Howww

[empty sail]

Add up the y components

You add

The ones in the x direction

[viscid storm]

Is easy to say

Idk what are they

[patent forge]

JUST SUM IT

[empty sail]

Do you know which axis is the x?

[viscid storm]

What is axis

We probly say difrent

[patent forge]

x and y

[empty sail]

The horizontal line that you drew

[viscid storm]

Ye

Wht with thhem

[patent forge]

sum up the forces along the x axis

[empty sail]

Those are called axes( axis is singular)

[viscid storm]

Sow f3 and f1

[empty sail]

Add up the forces in the x direction

[viscid storm]

Are axus

[empty sail]

No

They are forces on that axis

[viscid storm]

Yeye

How can i add up forces if idk the value

[empty sail]

You wrote them on the side of your paper

The F1 =
F2 =
F3 =

You have the values

[viscid storm]

That? But i need to break them

I need to break f2

F2 and f3 idk wht to do with

[empty sail]

The break up F2

You don't need to do anything you F1 and F3, because they are already in the axes

They are already along the axis

[viscid storm]

You mean the are alrdy on x an y

[empty sail]

That's what I said

They're along the axes already

[viscid storm]

No you make things more complicated

But i get it now

[empty sail]

No, it's simple terms, that you need to look into

[viscid storm]

I know them but idk how you say it in american

Sow it was confusing we just say x and y

[empty sail]

x axis and y axis are the same thing

[patent forge]

just cause somebody knows english doesnt make them american 😄

[empty sail]

There is such thing as a z axis

[viscid storm]

Let me first get f2x and f2y and the you help me fxr and fxy

Oke that okey?

[viscid storm]

Mb

[empty sail]

Find F2x and F2y, then add up the forces along the x and along the y

Simple as that

[viscid storm]

Yes the add up thing you show me in a min

Wait

Pls dont give up on me

[patent forge]

do you know how to break it yourself?

[viscid storm]

Ye i do this

[patent forge]

type it

or send pic

[viscid storm]

This

[patent forge]

,rotate

,rotate

,rotate

[viscid storm]

Good?

[patent forge]

bruh

wait

,rotate

[viscid storm]

Nk mean oposite

And pk meand close one

[patent forge]

is that a - or*

[viscid storm]

Hip is hypoti sum

[viscid storm]

?

[patent forge]

F2x -h.k?

or what is that

[viscid storm]

N.k

Opisite

[patent forge]

is it a -

[viscid storm]

In my language

[patent forge]

in between

or *

multiply

or minus

[viscid storm]

All is positve

Now is use sin

And cos

[patent forge]

should ve already used it

but yes

[viscid storm]

Give me a sec

Oke

Sow o got

F2x is 160.7 N

F2y is 191.5 N

@patent forge

[patent forge]

which is sin and which is cos

[viscid storm]

Sin is fx2

Nas cos is fy2

[patent forge]

yeah that should be good

[viscid storm]

And now how do i add them

[patent forge]

you add the forces that are along the X

[patent forge]

so which ones

[viscid storm]

I do

F2x + f1x = frx

And for y

F2y + f3y = fry

[patent forge]

no, becasue F2x is facing opposite direction

[patent forge]

same with F3

[viscid storm]

Ohh yes

F3

But f2x no

X need to go under

[patent forge]

no it doesnt

[viscid storm]

You sure

Can you explain me how you know is + or -

I always get stuck on this

[patent forge]

this is how you broke the vector to its x and y component

red is F2x and blue is F2y

see why its negative now?

[viscid storm]

But

I know is going left but if its x then in needs to go under but if its y it need to go left

[patent forge]

you look at the direction force is facing

if it goes in the direction of x its +

if it goes in other direction its -

same with y

[viscid storm]

Are you 100000% sure

Sow i dont do that on test and them

😵

[patent forge]

brother in christ this is how you break vectors

and yes i am sure

[empty sail]

If they weren't sure, they wouldn't be showing you how to do it

[viscid storm]

Sow if it goes left or down is - for x and y

And if it goes right or up is + for x and y

[patent forge]

well this is when you break the force into its components

[viscid storm]

Did i understand

[patent forge]

but kinda i guess

you have to be careful which way the vector is going when you break it into components

https://www.youtube.com/watch?v=9QwivZK_Vfs

suggest you watch this

[viscid storm]

I will

[empty sail]

That is if you draw it specifically like that

[viscid storm]

?

I am confused

[empty sail]

If you draw it like this, then yes, left and down is negative

Right and up is positive

[viscid storm]

How else could you draw it

[patent forge]

i mean doubt at his level he will need to draw it differently 😄

[viscid storm]

How can you draw them

Differently

[viscid storm]

O nah wht is this

Why you rotate whole rhing

[empty sail]

Just the axis at different angles

[empty sail]

Because I can

[viscid storm]

Damn you smart

[viscid storm]

Sow do i need this

[patent forge]

[viscid storm]

?

[patent forge]

no you dont in general, because usually you can pick how you want to put the coordination system

whats not clear 😄

[viscid storm]

Idk how to get fry and frx on my problem

[empty sail]

If you had a force, like this, the red arrow, then what you can do is rotate the axis

So it be like this

[empty sail]

Just add

[viscid storm]

Is not that simpleee

[patent forge]

what is Fry and Frx

force in y direction and force in x direction?

[empty sail]

Resultant force in x

And Resultant force in y

[viscid storm]

Sow fry is lime you put all fys together

Yes

[empty sail]

Yes it is

Just add up the forces in the x

And the forces in the y

[patent forge]

yeah and how you do it?

we went over + and - and components x y

[viscid storm]

Sow

I think i need to

[patent forge]

type for Frx first

[viscid storm]

Oke

Frx = f1x-f2x

[patent forge]

yes, and the result is?

[viscid storm]

Sec

19.3n

I think we 🦧 somewhere

[patent forge]

why?

[viscid storm]

I think is to small

[patent forge]

xD

its not, why would it be

type for Fry

[viscid storm]

Oke

Sow

F2y-f3y

[patent forge]

yes

[viscid storm]

Oh and to be honest i still dont knoe why f2x is negative

I just not logic

[patent forge]

well the vector is going in the opposite direction of x axis

thats why

[viscid storm]

O

Why didnt you say that in first place

I get it just oppisite directions of x and y

[patent forge]

well its opposite direction of x and same direction of y

[viscid storm]

?

[patent forge]

???????

[viscid storm]

Wdmy y is going left x right

[empty sail]

You should review that material in your own language

You are getting too confused

[viscid storm]

Probly

[patent forge]

thats not what i said

i said y go up and x go left!

[viscid storm]

How is that the samee

[patent forge]

@empty sail idk how is that the same?

[viscid storm]

You said it

[empty sail]

I'm being serious, look at that material in your own language

[viscid storm]

.

[patent forge]

its the same lmao

do you have any other questions or?

[viscid storm]

No txn btw should i watch the vid

U send or

[patent forge]

yes watch it

and rewise materials on your language

[viscid storm]

Oke ty for all sry for waisting your time byeeee

.close

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[noble owl]

Need help with matrix bisection

[noble owl]

or anyone who knows how to program in octave

[topaz sinew]

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[noble owl]

Need help with matrix bisection or anyone who knows how to program in octave

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[topaz sinew]

Please don't occupy multiple help channels.

[loud ingot]

.close

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[neon iron]

i need halpp !!!
again

[restive inlet]

what's your issue here?

[neon iron]

idk how im supposed to find b & c

[restive inlet]

consider angle sum on a line

[neon iron]

huh

a+b = 180

?

whenever you have a straight line, its angle is 180 degrees

if you have another line going through that line, that creates 2 angles, but their sum is still 180 degrees

.close

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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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[blazing oyster]

117.5 = ((2x)^2)/((.187-x)(.187-x))

[winged roost]

$117.5 = \frac{(2x)^2}{(.187-x)(187-x)}$

[thorny flame]

IntelligentCake

[winged roost]

this?

[blazing oyster]

Yes

117.5 = ((2x)^2)/x^2 -.374x+.0349

[winged roost]

ok so multiply across

[blazing oyster]

117.5(x^2-.374x+.0349)=(2x)^2

[winged roost]

now put everything on one side and solve the quadratic

[blazing oyster]

117.5x^2-43.945x+4.10075=(2x)^2

115.5x^2-43.945x+4.10075=0

Im subpose to get x = .158

[winged roost]

you havent done the multiplication of brackets on the denominator properly

[blazing oyster]

So i didnt mess up algebraically

[winged roost]

check again

[blazing oyster]

Oh

[winged roost]

.187 * 181 != 0.0349

[blazing oyster]

Wait i mean .187*.187

I meant

[winged roost]

ok hang on

is it 2x all squared

or just the x squared

yeah I get x = 0.158

so it is 2x all squared

you did 2x^2

[topaz sinew]

@blazing oyster Has your question been resolved?

[topaz sinew]

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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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[grand ermine]

help

[grand ermine]

<@&286206848099549185>

@winged roost

[winged roost]

No

[grand ermine]

?

[topaz sinew]

@grand ermine Has your question been resolved?

[grand ermine]

<@&286206848099549185>

help

[keen vessel]

is it 27

[grand ermine]

how u get it

[keen vessel]

i made an assumption that im not sure is correct

ill draw it out

[grand ermine]

?

bro

U SMORT

*SMART

[keen vessel]

is it correct?

[grand ermine]

YEA

how u did it

[keen vessel]

ok im drawing it on my ipad

[grand ermine]

ok

[keen vessel]

man this is going to be really complicated proof lol

[grand ermine]

lol

[grand ermine]

ohh\

[keen vessel]

i made the assumption efd is similar to che. im still unsure how to 100% prove that

[grand ermine]

oh ok

i ned to take note

[keen vessel]

EBC is an isoceles triangle with EB and EC having same length

[grand ermine]

uh huh

[grand ermine]

yea

[keen vessel]

is this a multiple choice question?

[grand ermine]

u have to list which is correct

like for example

1,4,3

[keen vessel]

i havent went through it but if condition 1 is correct then its a right triangle

[grand ermine]

or smth

[keen vessel]

oh

i dont have time for it lol i spent so much time on your other one

[grand ermine]

wuts this

[keen vessel]

z

[grand ermine]

oh ok

czn u do the other one

[keen vessel]

just to simplify things

[grand ermine]

like the 1,2,3 one

[keen vessel]

ill try but i wont spend too much time

[grand ermine]

okok

[keen vessel]

1 is true

2 isnt

[grand ermine]

ok

@keen vessel u there?

[keen vessel]

3 is true i think

ADC and ABC should be similar

[grand ermine]

ok

so just 1 and 3?

[keen vessel]

still working on it

[grand ermine]

oh ok

[keen vessel]

i have no idea what 4 and 5 suggests

i think 6 is true

similar thought process to 3

SAS but different scale so they should be similar

[grand ermine]

so 1,3,6 are def true

alr thanks man

or

women

[keen vessel]

man

[grand ermine]

ok

[keen vessel]

no problem

[grand ermine]

dont wana assume gender

tysm

[keen vessel]

was fun doing these questions too

[grand ermine]

can u help with 1 more or u gtg

[keen vessel]

sure

ill see. if it takes too much brain power then i wont

[grand ermine]

lol ok

[keen vessel]

im just going to guess 36/7

made another assumption that i cant prove

or wait

yeah 36/7 is my best guess

i assumed abd is similar to adc because im lazy

nvm its wrong

they are not similar

[grand ermine]

noo

yea its not 36/7

[keen vessel]

btw what is this for

why are these questions so difficult

do the answers have explanations for them

[grand ermine]

its my hw

IM IN 8TH GRD and my mom makes me do these

[keen vessel]

for mathcounts?

[grand ermine]

no

just hw

[keen vessel]

do the solutions have explanations

[grand ermine]

no

[keen vessel]

im wondering because of the first question

oh that sucks

@grand ermine 9?

[grand ermine]

ok thanks

YES

HOW U GET IT

[keen vessel]

ill draw it out again

[grand ermine]

k

[keen vessel]

@grand ermine

[grand ermine]

thx

[keen vessel]

np

btw what was the correct answer for this question @grand ermine

[grand ermine]

i ddint get it right

:((

[keen vessel]

oof. let me know when you get it

[grand ermine]

ok

thanks

@keen vessel

i gtg

and TYSM for hte answers and explanitions

wanna be friends?

[keen vessel]

ok let me know if you ever figure it out because i want to know the answer

[grand ermine]

ok

[keen vessel]

sure but i probably wont have much time to help in other times

[grand ermine]

oh ok

i will dm u the question and u can dm me back with the answer and explantion

.close

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[topaz sinew]

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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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[neon iron]

What's the logic behind canceling e, when e is raised to a natural log $e^{ln7} \rightarrow 7}$ ?

[thorny flame]

kav
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[sweet shard]

exponential and natural logarithm are inverses of each other

do you know what inverse functions are?

[neon iron]

Sort of, my basics are bad. I'm aware that logs are inverse of exponential.

I just don't know how the math simplifies to cancel the e @sweet shard like what's the process behind it

[sweet shard]

https://www.cuemath.com/algebra/inverse-functions/

[neon iron]

I mean I do know function compositions

[sweet shard]

Then just apply that to $f(x) = e^x$ and $f^{-1}(x) = \ln(x)$

[thorny flame]

riemann

[neon iron]

Right right right, but the e^ln cancels... wiat.

e raised to power of it's opposite.

[sweet shard]

i suggest you read this page

[neon iron]

I'm trying to think of it like $e^{{e^-}}

[neon iron]

Alright.

Thank you

.close

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Closed by @proven breach

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[trail trench]

I’m doing Multiplying and Dividing Rational Expressions

I don’t understand how I’m supposed to get x/3

I simplified the other numbers, but I don’t know what to do after

Right now I have (x-2)^2/3x(x-2) * x^2/x-2

[chrome hinge]

You can simplify (x-2) I think

you can yes

[trail trench]

What do I simply it to?

[chrome hinge]

think

[trail trench]

Uh

1?

[chrome hinge]

yh

[trail trench]

What does that mean

[chrome hinge]

yeah

[trail trench]

Oh

Ok so

(X-2)^2/3x(1) * x^2/x-2 = (X-2)^2/3x

[chrome hinge]

no

[trail trench]

Let me think for a moment

[chrome hinge]

$\frac{\left(x-2\right)\left(x-2\right)}{3x\left(x-2\right)}$

[thorny flame]

.,..

[chrome hinge]

whats that equal to

[trail trench]

It’s equal to (x-2)^2/3x(x-2)

[chrome hinge]

no its not

[trail trench]

It isn’t?

How?

[chrome hinge]

well that too

you had multiplication

[trail trench]

I meant to put ^

[chrome hinge]

but what can you simplify

[trail trench]

I cancel out the x-2s?

[chrome hinge]

yes

[trail trench]

Ok so now I understand why I have the x in x/3

But where does the X in the numerator come from?

[chrome hinge]

wdym

[trail trench]

Hm

So I canceled out the x-2s

Now I have 3x

[chrome hinge]

no you dont

[trail trench]

How

I thought by canceling out the x-2s I get rid of them, leaving only the 3x and then I multiply the 3x by the x^2/x-2

[chrome hinge]

show me what you mean

[trail trench]

Ok hold on

Forgot the other )

Just pretend it’s there

Ok so now I have 3x

And the other fraction

[chrome hinge]

whats $\frac{b}{b}$

[thorny flame]

.,..

[chrome hinge]

always equal to

[trail trench]

I don’t know.

[chrome hinge]

substitute any number other than 0 and tell me what you get

[trail trench]

What do you mean by that?

Sorry if I’m really slow here

[chrome hinge]

where are you from

[trail trench]

United States

[chrome hinge]

oh

so you just say that b=4 for example

[trail trench]

Ok

Uh

Then what

[chrome hinge]

what did you get

[trail trench]

I don’t know what you mean by b/b

Oh wait

[chrome hinge]

b is just a variable

[trail trench]

Is the answer 1

[chrome hinge]

yes

[trail trench]

Yeah sorry massive brain fart

4/4 would be = 1

Any fraction like that is always 1

[chrome hinge]

so lets consider the case $\frac{a^2}{ab}$

[thorny flame]

.,..

[chrome hinge]

whats an another way to write that fraction

[trail trench]

(a)(a)/a*b

?

[chrome hinge]

well () were unnecessary its just a*a but anyways

$\frac{a\cdot a}{a\cdot b}$

[thorny flame]

.,..

[chrome hinge]

now what would that be equal to

[trail trench]

a^2/ab

[chrome hinge]

simplify it

lol

[trail trench]

x/-1

[chrome hinge]

what

[trail trench]

I cancel out the a?

So it would just be b

[chrome hinge]

$\frac{a\cdot a}{a\cdot b}$ can also be written as $\frac{a}{a}\cdot\frac{a}{b}$

[thorny flame]

.,..

[trail trench]

Oh

[chrome hinge]

so what do we get

simplify

[trail trench]

We cancel out the a

So we only have the b

[chrome hinge]

so whats our final answer

[trail trench]

B

[chrome hinge]

nope

we know that this is 1 when $x\neq 0$ $\frac{a}{a}$

[thorny flame]

.,..

[chrome hinge]

so

$1\cdot\frac{a}{b}=\frac{a}{b}$

[thorny flame]

.,..

[trail trench]

Where are these other a and b’s coming from?

[chrome hinge]

wdym

[trail trench]

Ok so above it seemed like I canceled out all the a’s

Now there’s a 1 and new fractions

[chrome hinge]

so you see how $\frac{a^2}{ab}$ and $\frac{(x-2)^2}{3x(x-2)}$ are similar

[thorny flame]

.,..

[chrome hinge]

there we go smh

[trail trench]

Yes

[chrome hinge]

and what do we know about a/a