#help-26

226100 messages · Page 255 of 227

sterile laurel
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My homework Is done

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BTW I REALLY WANTED TO ASK YOU SOMETHING

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do you get paid for this ?

empty sail
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Nope

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This server is all volunteer

sterile laurel
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Why the fuck would you do this 🤣

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If I was you

empty sail
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Because the common factor is everyone here enjoys math

sterile laurel
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I would nope out

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I enjoyed math until 11 pops up

empty sail
empty sail
sterile laurel
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No bro fuck them they can learn by them selfs I can hardly answer my questions

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Bye bro

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Thanks a lot bro❤️ ❤️ ❤️

empty sail
sterile laurel
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👍

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👍

sterile laurel
empty sail
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All of that was just simple Google searches

sterile laurel
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Yup math is not my thing bro

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Anyway byee

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❤️

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. close

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.close

topaz sinewBOT
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subtle temple
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can someone explain plz 👀

topaz sinewBOT
subtle temple
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also am i abusing this server, i feel like im in here 5x a day 😭 i apologize guys i have a test to pass and im stupid

chrome hinge
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How many things do you have in that test

subtle temple
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math portion is 16 questions

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vry short test, but i want to be rly good at that because the other portion is reading, 10 questions, pretty easy, and then theres the physics portion and i havent had a physics class ever in my life lmao

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in short, my prep game plan looks like, try to perfect the math, review some reading practice tests, and then learn the physics portions they're askign

deft mirage
# subtle temple can someone explain plz 👀

Hi again, so what we need to note is that x^4+1 will always be positive, but x^4-1 will be negative for -1<x<1. We are looking for the intervals of x when P(x) is positive in inequality A. Regardless of what these intervals are, they will be the same in inequality B because the denominator does not change the sign of the function at any point. In the case of C, this will definitely reverse the sign of P(x) in the range mentioned as it is negative, so it will certainly add or remove from the solution set, it will not leave it unchanged. So A and B have the same solution sets.

subtle temple
deft mirage
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No it's fine, that's what the server is here for!

subtle temple
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.close

topaz sinewBOT
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kindred inlet
topaz sinewBOT
kindred inlet
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can anyone help?

frosty zephyr
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I’ll read it

kindred inlet
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okok

kindred inlet
topaz sinewBOT
#

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foggy prawn
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You roll a 100 sided die, you get to keep the value of your roll. How much would you pay if you can reroll and infinite number of times and pay one dollar per roll?

foggy prawn
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i got $99 since the face from 2 through 100 gives me profit for each roll

worldly tendon
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no

foggy prawn
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what would it be?

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and can you explain your answer please?

worldly tendon
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if you pay $99 and $1 per roll you literally cannot profit

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you keep only value the end value right

foggy prawn
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?

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i dont undrstand yoiu

worldly tendon
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if you roll a 34 then a 33 you only keep the 33

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right?

foggy prawn
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if i roll 34 i get $34 but to reroll i need to spend $1

worldly tendon
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you don’t get $34 plus the new $33

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otherwise you would literally have infinite money

foggy prawn
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if i roll that than sure

worldly tendon
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your profit is last roll - starting amount - number of rolls

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right?

foggy prawn
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no

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profit is last roll - money spent on reroll

worldly tendon
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dude

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that would mean infinite money

foggy prawn
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oh

worldly tendon
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and that doesn’t even account for starting pay

foggy prawn
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okay

worldly tendon
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profit = last roll - starting amount - number of rolls

foggy prawn
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starting amount is going to be 0

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initially

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right?

worldly tendon
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no

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the amount you pay to play the game at the start

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the initial cost

foggy prawn
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we dont start out with any amount

worldly tendon
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what were solving for

foggy prawn
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before rolling anything

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its $0

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can we agree on that?

worldly tendon
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that is not a cost

foggy prawn
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if we dont roll anything we dont have any value for a die roll

worldly tendon
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it’s not agreeing it’s you understanding
you pay $x to play

foggy prawn
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we start at $0

worldly tendon
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we are finding x

worldly tendon
foggy prawn
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yeah ik

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the cost to play is $1

worldly tendon
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no

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the cost to reroll is $1

foggy prawn
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so what is it than?

worldly tendon
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what we’re solving for bro

foggy prawn
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oh

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we're trying to find the cost to pay for the game

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thats x

worldly tendon
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yes

foggy prawn
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we dont know that

worldly tendon
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that is what we’re solving for

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such that the expected profit is $0

foggy prawn
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yeah

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whats the solution?

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@worldly tendon

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<@&286206848099549185>

topaz sinewBOT
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@foggy prawn Has your question been resolved?

topaz sinewBOT
#

@foggy prawn Has your question been resolved?

topaz sinewBOT
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shy sage
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8 rooks are randomly placed on different squares of a chessboard. A rook is said to attack all of the squares in its row and its column.

Compute the probability that every square is occupied or attacked by at least 1 rook.

shy sage
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here's what i tried:

There are 8^8 ways to put one rook per row and 8^8 ways to put one rook per column. This double counts the ways that have one rook in each row and column, which is the classic definition of covering every square. For that there are 8 ways to choose the column for the first row, 7 ways to choose the column for the second row, and so on making 8! in total. Using inclusion-exclusion the final answer is 2⋅8^8−8!=33514112

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but i'm not sure if i am correct

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Never mind. i got the right answer.

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.close

topaz sinewBOT
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topaz sinewBOT
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graceful sparrow
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Is it possible to calculate the minimum of something given the standard deviation, average and max?

chrome hinge
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I mean if you know the average and maximum I think you can get minimum

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a-(m-a)

graceful sparrow
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oh right-

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im so dumb

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wait no cuz what if theres like 20 different scores

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cuz if it were only 2 scores, then finding min given max and average is easy but with 20, stuff can vary

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thats why standard dev is useful I believe, dont know if its possible to find min tho

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as it can give the range sorta?

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<@&286206848099549185>

odd pagoda
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probably not. but I can't come up with an example

graceful sparrow
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im able to provide some numbers?

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standard dev of 8.11, max of 88.89, average of 75.44

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20 like scores

odd pagoda
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just intuitively there should be a lot more choices for x1,...,x20 than for stdev, min, max, avg. so surely some choices give the same values for stdev, max, avg but not for min

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for example it's not possible to calculate stdev from avg, min, max. see 1 2 4 5 and 1 3 3 5. all min=1, avg=3 and max=5. but stdev of first is 1.58 and second 0.70

graceful sparrow
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I see

odd pagoda
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fixing the stdev is kinda annoying so you can't as easily play around with different values

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but there are probably examples

graceful sparrow
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but as you're given the stdev, would it be possible to substitute it?

odd pagoda
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given any set X, we can modify X so that is has specified mean and stdev by calculating aX+b for some smart values a, b. so there are a lot of datasets which have the same mean and stdev

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sure those might not have the same max but with some extra work you can probably also get the max to be the same

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but the min of them very very likely won't always be the same.

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but finding an explicit example is just annoying

graceful sparrow
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I see, appreciate the help

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.close

topaz sinewBOT
#
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topaz sinewBOT
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timber tartan
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hi guys for part b

topaz sinewBOT
timber tartan
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i dont get why is there a x^2 at the last line of the solution

past kayak
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They multiplied the top and bottom by x

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That way, you don't have to worry about whether or not x is positive or negative

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Well, you do, but it's now built in to the thing

topaz sinewBOT
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topaz sinewBOT
#

@sharp mason Has your question been resolved?

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valid forum
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A quadrilateral with perimeter 52 has an insribed circle with radius 5. What is the area of the quadrilateral?

chrome hinge
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draw

keen venture
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Has a picture of it afaik

topaz sinewBOT
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@valid forum Has your question been resolved?

valid forum
slate raven
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"If the inscribed circle of a polygon with area A and perimeter c exists, then the radius of the incircle has the value 2A/c"

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→A = c*r/2

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= 130

valid forum
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ohhh, so is the area 52x5/2?

slate raven
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yep

valid forum
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and that's the area?

slate raven
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yep

valid forum
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okay, thank you so much

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.close

topaz sinewBOT
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topaz sinewBOT
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loud ingot
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can you do any of the forms?

topaz sinewBOT
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@fast dome Has your question been resolved?

chrome hinge
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kinda skipped parabolas

clear wadi
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um, you can write the factorized form by looking where the graph cuts the x axis, which in this case is at -8 and 12, so the factors will be (x-12) and (x+8) so the factorized form will be (x-12)(x+8)

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and the vertex form is given by (x-h)^2+k just put in the vertex coordinates to get the eq

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foggy prawn
#

You roll a 100 sided die, you get to keep the value of your roll. How much would you pay if you can reroll and infinite number of times and pay one dollar per roll?

foggy prawn
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Wrong

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You pay $1 if you want to reroll?

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You don’t know how to solve this question

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Dude you’re asking stupid questions

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That was in the question

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Lol

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As many as you want

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That’s irrelevant

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We want to know how much we want to play this game

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Okay

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Ty for your efforts

topaz sinewBOT
#

@foggy prawn Has your question been resolved?

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topaz sinewBOT
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broken patio
topaz sinewBOT
broken patio
#

I need help for this proof

topaz sinewBOT
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@broken patio Has your question been resolved?

broken patio
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well after 15 minutes so <@&286206848099549185>

sweet shard
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draw a picture

broken patio
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and like pythagorean theorem

ashen eagle
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Yes, it is the Pythagorean Theorem.

broken patio
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okay, i understand geometrically, but how would the proof look?

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like what to I write

odd pagoda
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calculate the norms explicitly. bit annoying with all the inner products but doable

broken patio
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okay, thank you!

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is it okay that once i'm finished later tonight i can dm?

sweet shard
broken patio
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okay

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.close

topaz sinewBOT
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iron halo
#

I can't figure out how to approach this limit, any ideas?

sturdy oracle
iron halo
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I am not

sturdy oracle
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Aight so you can multiply by the conjugate

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gimmie a sec

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this is gonna be a pain to write in latex lol

iron halo
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my apologies for the trouble, our textbook seems to have left a few things out

sturdy oracle
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lmao np

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i've dealt with worst things to type out

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$$\lim_{t\to 16} \frac{t-16}{\sqrt{t}-4}$$
$$\=\lim_{t\to 16} \left(\frac{t-16}{\sqrt{t}-4}\cdot\frac{\sqrt{t}+4}{\sqrt{t}+4}\right)$$
$$\=\lim_{t\to 16} \frac{\left(t-16\right)\left(\sqrt{t}+4\right)}{t-16}$$
$$\= \lim_{t\to 16} \sqrt{t}+4$$

thorny flameBOT
#

Umbraleviathan

iron halo
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thank you so much, idk how i didn't think of multiplying by the conjugate

sturdy oracle
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try conjuguates if you get any fractional indeterminate forms

iron halo
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I will definitely keep me in the mind in the future, you may have just saved my whole calc career 😂

sturdy oracle
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Lmao np

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You'll eventually learn about L'Hopital's

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Which is a lot easier

iron halo
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our textbook doesn't seem to show anything about it, but its missing a few things that are showing up on our homework anyways

sturdy oracle
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yeah because L'Hopital's utilizes derivatives

iron halo
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ahhh that makes sense. well thank you for all the help!

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grave finch
#

Hi.
I'm trying to help someone with some python code to find how many digits 2 floating points have in common. (so they can discover precision of accuracy in estimating π). Converting them to strings and just comparing them is slow, but accurate. Trying to use logbase10 to count the 0's of their difference is fast, but not entirely accurate. Is their a common math trick for doing this?

cursive abyss
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do you mean first digits or any digits?

grave finch
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for example:
3.141583 is 0.000009653 off from π, log10 of the difference is -5.01 but there are 4 digits after the decimal in common.
3.14159 is 0.000002653 off from π, log10 of the difference is -5.57 and there are 5 digits after the decimal in common.

ashen eagle
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What is usually done is log

grave finch
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looking for something like: accuracy(3.141583, π) is 4 digits the same after the decimal.

grave finch
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I'm supposed to be installing a doorbell, not helping this guy play with numbers. but it feels like there should be an answer here and I'm just missing it. 🙂

cursive abyss
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yeah, log10 doesn't help here
imagine comparing 0.999999 and 1.000001

grave finch
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like I trust log 10 to tell me how many 0's there are in the difference, but i don't trust the difference to be correct when what I really want is just a "per digit comparison."

ashen eagle
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No, that exactitudness not with log

cursive abyss
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how about a loop where you look at the whole part and then multiply each number by 10 mod 10

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i'm not sure about the accuracy though, the digits can change in theory

grave finch
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That's certainly viable, but sadly no faster than just converting to a string and comparing.
I think I'm satisfied that log10 gives me an accurate enough count of the 0s, but it's not going to work for them because the number we're passing to it is not an accurate difference.

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I'm going to write a library that does xor on digits in a floating number. I'm not convinced that will be any faster than the string compare either. Maybe I should install the doorbell.

cursive abyss
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i'm pretty sure you can't do that with loop
it should be cheaper than building a string though

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but I'd probably look into how float-to-string conversion is usually implemented for better precision

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so that we can do it manually without actually using strings

long stirrup
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it's python code, you want to avoid doing stuff

grave finch
long stirrup
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you can't outpace converting to string, because you need to write code for that

cursive abyss
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well, yeah, talking about speed in python doesn't make sense

grave finch
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Anyway, I think I've got the answers I came looking for, so thank you very much for your time and help.

cursive abyss
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of course i wasn't talking about algorithm complexity, it surely matters

grave finch
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And if you ever need any python help come over to the python discord and ask some questions. 🙂

cursive abyss
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i'm actually a c++ TA :)

grave finch
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Ah cool. I did c++ for a couple decades before I learned python. I'm happy with both, but python is actually "fun", similar to how perl is fun, but without the maintenance issues.

cursive abyss
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i'm not happy with either
there're no perfect languages

grave finch
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No. Although rust and nim look interesting.

cursive abyss
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another guy advertising rust :)

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they are everywhere

grave finch
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It's a surprisingly popular language on the python discord. Although I've barely looked at it yet.

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ok thanks!
!close

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.close

topaz sinewBOT
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dense trail
topaz sinewBOT
dense trail
#

Bottom is supposed to be (3x+5)^2

grim jacinth
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You need to carry the limit part down each step 👍

warm finch
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You are doing the formal definition of the derivative

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Which is the lim of that as h goes to 0

dense trail
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Oh shoot

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Completely forgot about that

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Ty guys

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jaunty quiver
#

Well, I can't get this method to tell me both the inequalities

lime zealot
#

when
$$x-1>0, x+1>0$$
you get $x>1$

thorny flameBOT
#

秋水

lime zealot
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when
$$x-1<0, x+1<0$$
you get $x<-1$

thorny flameBOT
#

秋水

lime zealot
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so the result is {x: x<-1 or x>1}

jaunty quiver
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I don't understand the how you get parts

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$x-1 > 0 = x > 1$ but $x+1 >0 \neq x > 1$

thorny flameBOT
#

আত্মদর্শী

jaunty quiver
#

I have a similar problem with the second part

lime zealot
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It's their intersection

jaunty quiver
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What intersection?

jaunty quiver
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(0,1) and (1,0)

lime zealot
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x has to satisfy both x>1 and x>-1, so x>1

jaunty quiver
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Oh okay

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And for the second one it has to satisfy both $x<-1$ and $x <1 $ so it is just $x<-1$

thorny flameBOT
#

আত্মদর্শী

jaunty quiver
#

Okay,I think I got it. Thank you for your help.

#

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torn mica
#

i need dhelp

topaz sinewBOT
torn mica
#

i think its 05

#

-5

past kayak
#

Yep

torn mica
#

lol really?

cursive abyss
#

why not

torn mica
#

i thought it might have been 13

cursive abyss
#

you can't get a negative number when you square something (unless you deal with complex numbers which you are not)

#

so subtracting a non-negative number from 4 you can't get something greater than 4

torn mica
#

righttttt

#

thanks.

#

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torn mica
#

i need help

topaz sinewBOT
torn mica
#

i think its 27

lime zealot
#

$\tan \theta = \frac{120}{235}$

thorny flameBOT
#

秋水

torn mica
#

ok

#

so

lime zealot
#

so you can use calculator to get the angle

#

,w arctan(120/235)/pi*180

topaz sinewBOT
#

@torn mica Has your question been resolved?

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neon iron
#

hello

topaz sinewBOT
neon iron
#

I need some help with tally and frequency tables for math

#

I have to turn this

#

i have to get all these numbers

#

And put them into this

#

Idk where to put any numbers

#

please help

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close

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topaz sinewBOT
steady ocean
#

<@&286206848099549185>

#

just basic z scores

#

somoene help

#

lol

#

i have no idea

#

why i am getting this wrong

wheat grove
#

dont ping helpers before 15 minutes

steady ocean
#

crap

#

yeah

#

soz

topaz sinewBOT
#
Channel closed

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steady ocean
fading glacier
#

use a calculator, you have your standard deviation and mean

#

you also have your lower bound and upper bound

#

should work out

#

otherwise you can use the painful formula by hand

steady ocean
#

its not working out lol

#

i got the probability of 1088 minus probabailty of 1003

fading glacier
#

it says between

#

as ive said

#

your upper bound should be 1088

#

and your lower bound should be 1003

topaz sinewBOT
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subtle timber
#

Define the value of the parameter "a" so that the function will be continuited, "continuity ". True result is 9. I know the way, but somehow i dont understand lim=lim. How to get that lim. For example i have lim (x goes to 0) 2x+a.

subtle timber
#

this is example on how i think it should be done

#

then a = 2

#

got to that point

#

I think i can manipulate it

#

soo i put everthing on one side and it = 0

#

then i remove x and put back to a = 4+5

fading glacier
subtle timber
#

I got it, thanks agaaaain 😁

#

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solemn bolt
#

what does this notation represent?

topaz sinewBOT
long stirrup
#

composition usually uses round brackets, i think this has square just for aesthetics

solemn bolt
#

hmm I see

#

thank you so much for your help

#

appreciate it

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daring geode
#

how would i convert this sequence into a non recursion one or equation?

a₀ = 1;

aₙ = a₍ₙ₋₁₎ + 2* n

long stirrup
#

for this specific one i would write how it starts, it's probably something obvious

#

generally idk

daring geode
#

Thats wat I was thinking it looked obvious

#

this is what it looks like on desmos

#

but i cant seem to pinpoint an equation

#

ive tried quadratic , logarithmic, exponential

#

idk

#

its just a bit off

#

maybe its impossible?

long stirrup
#

it's sqaure +1 minus n

daring geode
#

Thanks sm

#

❤️

#

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foggy prawn
#

Given a six-sided die, what's the expected value of the difference between two die rolls?

foggy prawn
#

wouldnt this be 0, since the ev of 1 die roll would be 3.5

#

which would make the difference be 0 since each die roll has a ev of 3.5

sick hazel
#

no

#

u would need to sum the p(d=0) * 0 + p(d=1) * 1 .... + p(d=5) * 5

#

where d is difference between rolls

snow lake
#

@daring geode

foggy prawn
daring geode
#

l love ui thanks

foggy prawn
#

this channel is occupied

foggy prawn
sick hazel
#

like probability difference is 0 times 0

#

plus probabibility difference is 1 times 1

#

and so on until probability difference is 5

#

times 5

foggy prawn
#

why?

sick hazel
#

by definition of expected value

foggy prawn
#

ic

#

so for this problem since the ev of a fair die is 3.5

#

the prob difference would be 12.25 right?

sick hazel
#

no

#

1

foggy prawn
#

what would it be than?

#

how?

sick hazel
#

the difference is never more than 5

#

for 2 dices

foggy prawn
#

wdym

sick hazel
#

if u roll 2 dice

foggy prawn
#

difference for what?

sick hazel
#

u cant get the differnece of their values to be equal to anything more than 5

#

the max difference is if 1 roll is 1

#

and the other is a 6

foggy prawn
#

difference for what?

sick hazel
#

the values of the rolls

#

6-1 would be the difference for the example above

foggy prawn
#

how do we calculate the values per roll?

sick hazel
#

u dont

#

u just go through the possible difference values( 0-5)

foggy prawn
#

wouldnt that just be ev tho?

sick hazel
#

what ur doing is subtracting 2 expected values

#

which wont give u the expected value of this

foggy prawn
#

yeah

#

since they ask for the difference of that

#

how did you get 1?

sick hazel
#

thats just a possibility of a dice roll

#

i was just using that as an example

foggy prawn
#

what would be the solution?

sick hazel
#

well

#

the solution is

#

to find the probability the difference is 1

#

plus

#

ur refering to the 1 in this right?

foggy prawn
#

continue

#

plus what?

sick hazel
#

probability the difference is 2 times 2

#

plus (probability difference is 3) times 3

#

and so on

#

until

#

(probability difference is 5) times 5

#

so probability difference is 1

#

is 10/36

foggy prawn
#

those numbers basically symbolizes the die rolls right?

sick hazel
#

yeah

#

they

#

symbolize the difference

#

between the values

#

of the rolls

foggy prawn
#

we would only count the situations where we have the same outcomes right?

sick hazel
#

no?

foggy prawn
sick hazel
#

the probabibility of getting a difference of 1

#

cause u can have 1-2, 2-3, 3-4, 4-5, 5-6

#

and reverse

long stirrup
#

you're both sure it's not absolute difference?

#

or you're both sure it is?

#

i can't tell

foggy prawn
#

im not sure

sick hazel
#

it is

#

absolute difference

#

@long stirrup

foggy prawn
long stirrup
#

it would be my first assumption

#

but it makes sense with normal difference too why not

sick hazel
#

u need to calculate probabilities of getting 2,3,4,or 5

sick hazel
#

only the probability of difference of 1 is not what the question was asking

#

cause that's not the only case

foggy prawn
#

what are the other cases?

sick hazel
#

when difference is 2

#

3

#

4

#

or 5

foggy prawn
#

up to 5?

sick hazel
#

yeah

#

cause the first roll can be a 1 and the last roll can be 6

foggy prawn
#

2 - 5 right?

sick hazel
#

yeah

foggy prawn
#

who wouldnt 1 or 6 be a difference?

sick hazel
#

1 is also a difference

foggy prawn
#

for 6 we cant have a difference of 6 between 2 dice

sick hazel
#

yeah

foggy prawn
#

so 10/36 would be wrong than

sick hazel
#

10/36 is just the probability of getting 1 roll

#

so thats just the first case

foggy prawn
#

why cant we have a difference of 0?

sick hazel
#

that wont affect the expected value

foggy prawn
#

ah

sick hazel
#

cause u end up multiplying the probability by 0

foggy prawn
#

so i made the mistake earlier by taking the difference between the ev of both dice

sick hazel
#

yeah

foggy prawn
#

but what i shouldve done is count the number of dice that has differences between 1 to 5 right?

sick hazel
#

yeah

#

use that to calculate probability

foggy prawn
#

and divide it by 36

sick hazel
#

yeah

foggy prawn
#

which

#

is the total outcome

sick hazel
#

yeah

#

and then

#

multiply it by the difference

foggy prawn
#

what if i added a third die into the sequence

#

that wouldnt work right?

sick hazel
#

yeah

#

it wouldnt work

foggy prawn
sick hazel
foggy prawn
#

ok say we have our prob

#

what would be the value than?

sick hazel
#

the difference

foggy prawn
#

of what?

#

oh snap

#

so lets say the differenc eof 1

#

is 10/36

#

it would just be 1 * 10/36 right?

sick hazel
#

yeah

foggy prawn
#

makes sense ty this all makes sense

#

lets say i wanted to make both dice seven instead of six

#

it would be the ev of the dice outcomes of 1 - 6 times the outcome?

sick hazel
#

yeah

#

also remember to sum all the values u get at the end

foggy prawn
#

yeah makes sense

#

ty

topaz sinewBOT
#

@foggy prawn Has your question been resolved?

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neon iron
topaz sinewBOT
neon iron
#

I got this but I have no idea what to do after

topaz sinewBOT
#

@neon iron Has your question been resolved?

neon iron
#

<@&286206848099549185>

carmine stone
#

question seems wrong

#

i graphed all the answers and didn't get a graph that matched the ans

neon iron
#

but doesn't have an explanation

carmine stone
#

these are the two graphs

#

if they were equivalent they should match

#

but they don't which is why i'm not confident that this question is valid

neon iron
#

this question was from an SAT test

#

is it possible for a question to be invalid?

carmine stone
#

idk i think the questions just wrong

neon iron
#

what if its y^1/8^y^9/8

#

instead of multiplying its another exponent?

#

is that possible

carmine stone
#

i don't think that changes anything

neon iron
carmine stone
#

yep

neon iron
#

bruh

#

can I try to ask one more helper

#

to see what their opinion is?

carmine stone
#

yea go for it ig i'm not a helper tho

neon iron
#

oke

empty sail
#

Don't ping specific people

neon iron
#

<@&286206848099549185>

empty sail
#

You stated the answer was a?

#

@neon iron

neon iron
#

yes @empty sail

#

the answer key said that

#

but it doesn't explain

empty sail
#

That font makes it poorly formatted. It's $$y^{\frac{1}{8}} \cdot (y^{\frac{3}{4}} )^{\frac{3}{2}}$$

neon iron
#

hmm

thorny flameBOT
#

dldh06

neon iron
#

ahhhhh ok

#

that makes sense now the font was confusing tho

#

ty

#

.close

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sonic knot
topaz sinewBOT
sonic knot
#

can somebody explain this one

#

the x is positive so it has to be the regular function and the only one i thought it was was b

slow oyster
#

@sonic knot the ans is A

keen venture
#

It can help to try plotting a few points. What's f(0)? f(3)?

slow oyster
#

@sonic knot the value of function goes on decreasing after a certain time

#

You understant what I meant to say ??...

sonic knot
#

okay

#

i am not allowed to use a calculator so this is kinda difficult

slow oyster
#

ok

sonic knot
#

the only point i know is f(0)

slow oyster
#

do f(0) , f(4) , f(10)

keen venture
#

Okay, the only point I was trying to get across is that f(3) is smaller than f(0), so the function is decreasing

#

That happens when the base is less than 1

#

Cannot be B, which is increasing

sonic knot
#

why is it not e, f, or d

keen venture
#

f(0) = 1, so the function is positive somewhere

sonic knot
#

ohhhh ok

#

so it is c

#

thank you

#

.close

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neon iron
#

Can someone help me solve this

topaz sinewBOT
neon iron
#

I kinda get confused when the x's arc gets mixed in one place with the others

lofty salmon
#

Sorry can you rephrase your problem in english?

#

Have you heard of circle theorems?

neon iron
#

yes

#

I think my problem is already in english

lofty salmon
#

look, have you heard of this??

#

Angle Centre Theorem

neon iron
#

yes

#

I applied that

lofty salmon
#

So what did you get?

neon iron
#

96 and 128

#

so

lofty salmon
#

Wdym 96 and 128?

neon iron
#

2x - 224

lofty salmon
#

So using the angle sum property we will get 360 - x + 112 = 360?

neon iron
#

umm

#

are you waiting for me to answer

lofty salmon
#

x is going to be 112

#

@neon iron

neon iron
#

yeah I have the key

#

will it help if I draw what I did

lofty salmon
#

sURE

neon iron
#

one sec

#

is it correct till now

lofty salmon
#

Ye your logic is correct

#

👌

neon iron
#

then I did what is probably wrong

lofty salmon
#

?

#

Your answer seems correct, I am unable to get where you've asssigned values.

neon iron
#

after this

#

what should I do

#

I couldn't decide what I was supposed to equalize 2x - 224 to

lofty salmon
#

0

#

So, the inner angle would be 360 - 2x

#

add with the x and the other two angles and equalize them to 360

neon iron
#

hmm

#

ok I think I got it

#

thanks

#

.close

#

.close

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ripe crane
topaz sinewBOT
ripe crane
#

help please

#

can somebody tell me how i should approach this problem?

topaz sinewBOT
#

@ripe crane Has your question been resolved?

topaz sinewBOT
#

@ripe crane Has your question been resolved?

ripe crane
#

i guess i overestimated the capabilities of the helpers

#

.close

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subtle timber
#

In this case, i dont know, how we got Yo as 9. For Xo and x i know, but for 9 i dont.

sweet shard
#

use that

topaz sinewBOT
#

@subtle timber Has your question been resolved?

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subtle timber
#

.reopen

topaz sinewBOT
#

subtle timber
#

i did

#

insert 3

#

but i guess thats not correct

topaz sinewBOT
#

@subtle timber Has your question been resolved?

topaz sinewBOT
#

@subtle timber Has your question been resolved?

#
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river stag
topaz sinewBOT
river stag
#

can someone pls help me figure out where i am going wrong? im trying to find the area between the curves

#

.close

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#
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proven olive
#

do you recognize this inverted question mark?? I feel like no one knows anything about it , its under conditional statement

empty sail
#

Probably an error with the loading of fonts

proven olive
#

Oh so basically it doesn't mean anything and just the error of the computer?

empty sail
#

Yes

proven olive
#

Okie okie thankyou very much for the help

#

.close

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young vale
topaz sinewBOT
young vale
#

Hey

neon venture
#

hi

young vale
#

Im trying to solve this limit

#

And I've tried multiplying by (sqrt(x+3) +2x)

#

And dividing too, ofc

#

But still getting 0/0

#

What I've done is here

neon venture
#

multiply the denominator and the numerator by sqrtx + 1

young vale
#

Why ?

#

Multiply by that and also by what I've multiplied or just what you have said

neon venture
#

i dont know, try it

young vale
#

Okay

#

Still 0/0

neon venture
#

weird i forgot how to deal with these kind of limit lmao

young vale
#

I was thinking on doing the conjugate too, but no idea why doesn't work

neon venture
#

well can you separate the fraction in two

#

?

young vale
#

Wdym

neon venture
#

like :
$$\frac{\sqrt{x+3}}{\sqrt{x}-1} -\frac{2x}{\sqrt{x}-1}$$

thorny flameBOT
#

Herels

young vale
#

Yes I think I can do that

#

Seems okay

topaz sinewBOT
#

@young vale Has your question been resolved?

young vale
#

.close

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obsidian gale
topaz sinewBOT
obsidian gale
#

how did step 3 become step 4

honest hazel
#

(n-2)^2 +2(n-1)(n-2) = > (n-2)((n-2)+2(n-1))

obsidian gale
#

oh makes sense now 😅

#

thanks

#

.close

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grave lava
#

hi

topaz sinewBOT
grave lava
#

so I'd need some guild for next step

#

,tex

The solid between the sphere $x^2 +y^2 +z^2 = 19$ and the hyperboloid $z^2 -x^2 -y^2 = 1$,
for $z > 0$\\
Converting to spherical coordination:\\
$\begin{cases}
x=\rho\sin(\phi)\cos(\theta)\\
y=\rho\sin(\phi)\sin(\theta)\\
z=\rho\cos(\phi)\\
\end{cases}$\\
$x^2+y^2+z^2=19 \Rightarrow \rho^2=19 \Rightarrow \rho =\sqrt{19}\\
\begin{aligned}
z^2 -x^2 -y^2 &= 1\\
\Rightarrow z^2&=1+(x^2+y^2)\\
\Rightarrow \rho^2\cos^2(\phi)&=1+(\rho^2\sin^2(\phi)\cos^2(\theta)+\rho^2\sin^2(\phi)\sin^2(\theta))\\
\Rightarrow \rho^2\cos^2(\phi)&=1+\rho^2\sin^2(\phi)\\
\Rightarrow \rho^2(\cos^2(\phi)-\sin^2(\phi))&=1\\
\end{aligned}$
thorny flameBOT
#

Darkness

grave lava
#

like how to get the phi

#

if rho isnt cancelled yet

topaz sinewBOT
#

@grave lava Has your question been resolved?

grave lava
#

sad no one is here

#

<@&286206848099549185> may I seek for help

topaz sinewBOT
#

@grave lava Has your question been resolved?

grave lava
#

well then

topaz sinewBOT
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foggy prawn
#

You roll a 100 sided die, you get to keep the value of your roll. How much would you pay if you can reroll and infinite number of times and pay one dollar per roll?

topaz sinewBOT
#

@foggy prawn Has your question been resolved?

knotty ledge
#

uh what, isn't this a bit subjective

#

people will pay however much they feel they want to depending on how much they want to gamble

foggy prawn
#

its asking how much would you pay to play this game

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rugged cradle
#

hello I'm confused on what to do here was hoping to find some help

rugged cradle
#

question c

loud ingot
#

Can you find v at t=5?

rugged cradle
#

how do I go about doing that?

loud ingot
#

Use the equation v=0.4t

#

Can you plug in t=5 to find v?

rugged cradle
#

ahh I see, I could do that but the questions are based on integration and differentiation so I assume the preferred answer would have to involve those methods

#

not to mention the entire questions is worth quite a few marks so yeah :/

loud ingot
#

Aha so do you know that velocity is derivative of distance over time?

rugged cradle
#

yeup

loud ingot
#

So to find distance you would need to integrate v

rugged cradle
#

ahhhh I see I'll try that thank you so much

#

.close

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foggy prawn
#

what calc concept is a derivative before an integral?

foggy prawn
#

is it calc 2 thing?

keen venture
#

You mean the fundamental theorem of calculus? Yeah calc 2

topaz sinewBOT
#

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orchid night
topaz sinewBOT
orchid night
#

how do i differentiate this

drifting swift
#

quotient and product rules

#

hope you aren't being asked to do it from first principles

#

if you are that'll be pain

orchid night
#

yep i know i have to use quotient rule but what do i differentiate that e

#

oh ofc not first principles

drifting swift
#

do you know what the derivative of e^x is?

orchid night
#

nope i dont

drifting swift
#

the derivative of e^x is e^x.

orchid night
#

i tried to differentiate it

drifting swift
#

you made mistakes in several places

orchid night
#

oh

drifting swift
#

also maybe consider listening to things when someone tells you something

#

just as a life pro tip

orchid night
#

ok

#

so how do i differentiate e^x?

#

well instead of already knowing the answer i just wanna know the process

drifting swift
#

you need to know the limit lim[t -> 0] (e^t - 1)/t = 1

orchid night
#

ok

drifting swift
orchid night
#

oh okay

loud ingot
#

which software do you use atomic?

orchid night
#

paint

loud ingot
#

wow! i have it too

#

big brain

orchid night
#

ye its kinda good

#

u can zoom out far

loud ingot
#

how?

orchid night
#

ctrl+scroll

loud ingot
#

how did you black screen?

#

also which brush should i use to make it look like chalk?

orchid night
#

i just fill the background with black

#

brush

loud ingot
#

how do you take screenshot though?

orchid night
#

i use a program called greenshots

tame saddle
#

hey, can i upload pic of problem i need help about?

pine forge
#

go on a new help channel

#

there's three available rn

tame saddle
#

oh ok sorry and ty

pine forge
#

and yes you can upload a pic

pine forge
#

?

#

just do

#

windows key + shift + S

#

there's a built in snipping tool as well in windows

orchid night
#

its stripped from my pc

pine forge
#

what does that mean

orchid night
#

like removed

#

idk how to get it back

pine forge
#

can't you just download it

topaz sinewBOT
#

@orchid night Has your question been resolved?

orchid night
#

thanks

#

.close

topaz sinewBOT
#
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topaz sinewBOT
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celest glade
#

if I apply a function to itself infinity * n times, it's not the same as just applying the function to itself infinity times, right?

odd pagoda
#

well first clearly define what "applying a function to itself infinity times" means

#

then we can talk

celest glade
#

$f(f(f(x)))$ this is applying f to itself 3 times

thorny flameBOT
#

illuminator3

celest glade
#

and applying it to itself infinitely many times would be

#

$\lim_{x \to \infty} a_x, \text{ where } a_k := f(a_{k-1}) \text{ and } a_0 = x$

thorny flameBOT
#

illuminator3

odd pagoda
#

ok and we are assuming that this limit exists

celest glade
#

yes

odd pagoda
#

then probably the limit is a fixed point of f. so applying f one more time just leaves it fixed

celest glade
#

it has a fixed point

#

yea

#

wait

odd pagoda
#

so now what exactly is your question?

celest glade
#

if $a_{\infty \cdot n}$ converges to a fixed point, does $a_{\infty}$ too?

thorny flameBOT
#

illuminator3

odd pagoda
#

what is a_\infty supposed to mean?

#

or a_\infty\cdot n for that matter

celest glade
#

notational shorthand

thorny flameBOT
#

illuminator3

odd pagoda
#

\begin{align*} f(L)&=f\left(\lim_{n\to\infty} f^n(x)\right) = \lim_{n\to\infty} f\left(f^n(x)\right) \&= \lim_{n\to\infty} f^{n+1}(x) = \lim_{n-1 \to \infty} f^{n}(x) \&= \lim_{n\to\infty} f^n(x) = L \end{align*}

thorny flameBOT
#

Denascite

odd pagoda
#

assuming f is cont

celest glade
odd pagoda
celest glade
thorny flameBOT
#

illuminator3

celest glade
#

anyhow

odd pagoda
#

fair enough

celest glade
#

yea thanks

#

forgot that you could do that trick

#

.close

topaz sinewBOT
#
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celest glade
thorny flameBOT
#

illuminator3
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

odd pagoda
#

so, first off, just because $f^n(x)=x$ for some $n$, does not mean $\lim_{n\to\infty} f^n(x)$ converges. do you mean that $f^n(x)=x$ for all $n$?

thorny flameBOT
#

Denascite

celest glade
#

thx

#

.close

topaz sinewBOT
#
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topaz sinewBOT
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gritty compass
#

Help with part (c)

topaz sinewBOT
jade thunder
#

What have you tried

gritty compass
#

I tried changing equating the equation to 0

#

And trying to find two values of t when h=0

jade thunder
#

Which equation

gritty compass
#

This one

#

Which is the same as this essentially

jade thunder
#

What is the left side equal to

#

In general what is it equal to not this specific case you’ve made

gritty compass
#

H=0 ?

#

Because H is vertical height above water

jade thunder
#

No it’s equal to H yeah?

gritty compass
#

Yh yh

#

Same as the one in the question

jade thunder
#

You basically never want to use decimal when dealing with these things in math

gritty compass
#

I put decimals because part (a) asked for decimal to 3.d.p

jade thunder
#

Oh yuck

#

So what happens when you solve for h=0

#

What answer do you get for the given bounds

gritty compass
#

Still doing it

#

Think it might work

jade thunder
#

dont forget the question is asking for an amount of time

gritty compass
#

?

jade thunder
#

that aint the question, the question asks for the time P spent under water

gritty compass
#

So subtract the two values right?

jade thunder
#

are you sure?

gritty compass
#

I think so. The two values of t when h=0. So subtracting them would find the total time under zero?

jade thunder
#

why is it total time under

#

and not total time above

gritty compass
#

Good point

#

Not sure what to do then

#

Do i find the min value for t?

jade thunder
#

ok so instead of finding for h = 0

#

what else can you do

#

h = 0 gives u the points in time at which P is on water level

gritty compass
#

No idea tbh

jade thunder
#

what does it mean if it's under water with h

gritty compass
#

Negative h value

jade thunder
#

so mathematically that means?

gritty compass
#

?

jade thunder
#

h < 0

gritty compass
#

Is that what you meant

jade thunder
#

yes

#

when u state things in english

gritty compass
#

I was so lost lol

jade thunder
#

it gets hard to convert it into something you can do math with

#

so i like to keep the things written in math form

gritty compass
#

Fair enough

jade thunder
#

because with h < 0 you have an inequality

#

and then u also know that h = Rcos(something) + c

#

whatever that equation u had was

#

so you can solve for that < 0

jade thunder
gritty compass
#

But then I would get multiple values/answers

#

Which ones would I use

jade thunder
#

you would get a range

gritty compass
#

Yh

jade thunder
#

ok how about this

#

i meant that if u think about it using h < 0

gritty compass
#

But I need total time not a range