#help-26

226100 messages · Page 233 of 227

neon iron
#

Hmm

old ether
#

Well, you're looking for a simplified version

#

I just put it in pi notaion

neon iron
#

I thought to apply identity sin(2x) = 2sin(x) cos(x) to simply my product.

old ether
#

makes sense

neon iron
#

Some terms from numerator and denominator will be cancelled out.

#

That's why I tried to find the product upto n, and I'll apply limit of n tends to infinity.

#

But I stuck.

old ether
#

Just looking at an approximation using desmos, it looks close to $\frac{\sin\left(2x\right)}{2x}$, but I have no proof of it other than just how the equation looks.

thorny flameBOT
#

Chixen

neon iron
#

Ohh

old ether
#

If you needed it for some program, sin(2x)/(2x) is a good if not perfect approximation.

neon iron
#

I need to solve mathematical problem (calculator is not allowed).

old ether
#

oh oh ok

#

so you would need a proof of sin(2x)/(2x) as well as how you would come to that conclusion.

#

other than "the equations look the same"

neon iron
#

Hmm

old ether
#

well the product of two cosines is the average of the cosines of the angle's sum and difference.

#

$\cos\left(\alpha\right)\cos\left(\beta\right)=\frac{\cos\left(\alpha+\beta\right)+\cos\left(\alpha-\beta\right)}{2}$

thorny flameBOT
#

Chixen

neon iron
#

Can you check this?

old ether
#

ok

#

having a hard time with your handwriting. Can you type it using latex?

neon iron
old ether
#

it's ok

#

I understand it now

neon iron
# neon iron

That's cos(x) cos(2x) cos(3x) ...
But I need cos(x) cos(x/2) cos(x/4) ...

forest mortar
neon iron
old ether
#

instead of stopping at 2^(n-1), stop at some other variable 2^m.

#

see what happens then

#

then take a limit as m->∞

neon iron
#

I thought to make n terms for easily calculations.

old ether
#

That tends to break whenever limits are involved

neon iron
#

Ohh

#

$$\lim_{m\to \infty} \frac{\sin(2x)}{2^{m+1} \sin(x/2^{m-1})}$$

thorny flameBOT
neon iron
#

the infinite product is sin(2x)/2x

neon iron
#

Thank you!

#

yeah no prob

#

i can send work if you need it

neon iron
#

the product of the first n terms is
$$\lim_{n\to \infty} \frac{\sin(2x)}{2^{n+1} \sin(x/2^{n})}$$

thorny flameBOT
#

dansman1090

neon iron
#

using l'hopitals rule you get the limit of 2^(n+1)*sin(x/2^n) is 2x

neon iron
#

gimmie a min ill send my work

#

Ok

#

@neon iron

neon iron
#

happy to help

#

.close

topaz sinewBOT
#
Channel closed

Closed by @odd fjord

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

polar bough
#

Hi guys, im having trouble with my homework, i need to find the two equation of straights passing through point P which are tangent to the circumference

neon iron
#

Have you tried anything?

polar bough
#

I tried to put the circumference equation and the general straight formule with P in it in a system
y - 1 = m(x -6)
x² + y² + 2x - 4 = 0

north orbit
#

What class is this for. Might help us to know

polar bough
#

im from italy im in 3rd year of high school

solemn wigeon
#

you should 1) complete the square so you can find the center of the circle

#
  1. you should use the fact that the normal slope to a circle would just be (y coordinate - circle y coordinate)/(x coordinate - circle center x coordinate)
polar bough
#

Oh no man i know what u are talking bout

solemn wigeon
#

then 3) you should use the normal slope equation (opposite recripocal) to find the tangent slope

#

and then you are done

polar bough
#

Our teacher wants us to solve in another way

solemn wigeon
#

...

#

and that is?

#

oh wait is this a calc class?

polar bough
#

Wait ill send you a pic

#

Ignore the italian words

solemn wigeon
#

or is it precalc

polar bough
#

The "Primo metodo" paragraph

solemn wigeon
#

sry man i dont know

neon iron
#

It's the same method.

polar bough
#

No, chad was talking bout the second one

neon iron
#

Umm... Can you translate if possible?

polar bough
#

Yea

#

First method

We systematize the equation of the generic line for P (1; 5) with the equation of the given circumference:

numbers

By eliminating y between the two equations we obtain the solving equation of the system, in the unknown x

numbers

we impose the condition of tangency Delta = 0
We will have so

numbers

#

Like i understood the process but i cant get the calc right

topaz sinewBOT
#

@polar bough Has your question been resolved?

topaz sinewBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

rain lotus
#

hI

topaz sinewBOT
rain lotus
#

Hi*

#

Is there anyway I could find this without guessing and checking?

neon iron
#

please tell me how to solve this?

#

<@&286206848099549185>

#

@neon iron start another chanel, this one is occupied

topaz sinewBOT
#

@rain lotus Has your question been resolved?

grand cloud
#

umm what do you mean by guessing and checking

topaz sinewBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wild tapir
#

so i'm trying to solve part b to this question, i got the answer to part a as 5cos2x - 4sin2x + 2

wild tapir
#

for part b i tried to set this equal to 4 and then rearrange for tan but the +2 always got in the way, anyone got any ideas?

wild tapir
#

so for part a of the question

#

i got 5cos2x - 4sin2x + 2, which i checked is correct

#

and then for part b i used this same identity and set it equal to 4

#

so 5cos2x - 4sin2x + 2 = 4

#

and then i had no idea what to do, i tried to rearrange this to get it all under one trig function but i couldn't manage it

#

<@&286206848099549185>

mortal thunder
#

Are you allowed calculator?

#

@wild tapir

#

considering how the question asks for answer upto 2 decimal places

wild tapir
#

yeah

mortal thunder
#

guessed as much

#

okay

#

so do you remember the formula for sin(A + B)?

wild tapir
#

yeah

mortal thunder
#

okay

#

so

wild tapir
#

do i need to use that though? wouldn't that just get me to where i started

mortal thunder
#

nope

#

just listen ...?

wild tapir
#

OHHH i know what to do now

#

you're a genius ty

mortal thunder
#

XD

#

divide the whole equation by sqrt(5^2 + 4^2)

wild tapir
#

.close

topaz sinewBOT
#
Channel closed

Closed by @wild tapir

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

cosmic cedar
topaz sinewBOT
cosmic cedar
#

I did 300 * cos(25) and got 271.892336

#

is it suppose to be in Kilo joules?

#

or jouoles

topaz sinewBOT
#

@cosmic cedar Has your question been resolved?

grand cloud
#

Joules

topaz sinewBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

vague dirge
topaz sinewBOT
vague dirge
#

i cant get the cdf

#

i integrated it but

#

i dont know how to get the result shown

#

nvm got it

#

.close

topaz sinewBOT
#
Channel closed

Closed by @vague dirge

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

tall halo
#

I have a function f. So f: R → (0, ∞), defined by f(x) = e^x. I have to show it's injective or not. And surjective or not. I've showed that this is injective, so now I'm confused about how to show that it's either surjective or not surjective

tall halo
#

What do you mean?

#

That's all I was given

honest hazel
#

do you know how to prove surjectivity in general ?

#

@tall halo

topaz sinewBOT
#

@tall halo Has your question been resolved?

tall halo
#

He didn't go over it much and the textbook is confusing me

vital relic
#

@tall halo You show for any number in (0, infinity), e^x can equal that number for some x.

#

Perhaps you can just use the log function to show this

tall halo
#

So I can choose any number (basically positive) to plug into x?

#

I know that there's, let's say an a and b. f(a) = b. If this is true, then the function is surjective

neon iron
#

Maybe you can just use that exp is continuous and unbounded above

frozen perch
#

so the idea for any b in (0,\infty), you find some a in terms of b such that e^a = b

tall halo
#

Is there a way to show this?

#

Or do I just use examples?

neon iron
#

What will be an acceptable way to show it really depends on what facts about the exponential function you can use

tall halo
#

Like using ln x?

neon iron
#

If you can assume ln as you know it exists, then yea that’s probably the easiest way

#

There is some theory that goes into why ln is a mathematically valid function and this exercise would seem circular to me if you were allowed to use the fact that it exists

#

If you can use the fact that ln exists then f is invertible so it’s injective and surjective

#

Seems too cheaty

#

Idk though, could use some more info on what has been covered in your course

tall halo
#

In my course

#

Hmm

#

Honestly

#

I was just given what a function is when injective, surjective or bijective

#

And then he just gave us pictures of each

neon iron
#

Is this an analysis class or something else?

tall halo
#

Abstract algebra

#

I'm not sure why he teaches the way he does

neon iron
#

Oh ok you can probably use ln then

tall halo
#

Yeah

#

Can I make a = ln(b)?

vital relic
#

Given any y in (0, infinity), ln y is in R.

Therefore the function can take on any value in (0, infinity) so it is surjective.

#

That's it.

tall halo
#

Really?

neon iron
tall halo
#

And when I plug it into the function, I end up with b, which makes the function surjective

vital relic
tall halo
vital relic
#

making a = ln(b)

tall halo
#

Ah

vital relic
#

Given any y in (0, infinity), ln y is in R. Let x = ln y. Then y = e^x.

Therefore the function can take on any value in (0, infinity) so it is surjective.

tall halo
#

Thank you both very much

#

I guess I just needed to see an example from the homework to understand subjectivity better

#

You guys are the best🥺

#

.close

topaz sinewBOT
#
Channel closed

Closed by @tall halo

Use .reopen if this was a mistake.

topaz sinewBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

stable totem
#

I dont know how to solve this task

Draw the parabola p:y=2x+1
a) Draw a line connecting this parabola
intersects at points A(1/3) and B(1.5/7).

topaz sinewBOT
#

@stable totem Has your question been resolved?

topaz sinewBOT
#

@stable totem Has your question been resolved?

neon iron
#

ok

#

i'll help

#

are you still here?

#

@stable totem

topaz sinewBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

topaz sinewBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

normal citrus
topaz sinewBOT
leaden tusk
#

what have you tried

normal citrus
#

I forgot the "definements" but whatever

leaden tusk
#

does $\int{\frac{\sin(x)}{x}}$ look familiar at all?

thorny flameBOT
#

a disappointing son

normal citrus
#

Absolutely not

leaden tusk
#

perhaps just $\frac{\sin(x)}{x}$?

thorny flameBOT
#

a disappointing son

leaden tusk
#

possibly learned something in class about this and its integral?

sweet shard
#

this problem can be hard for first time seeing integrals

vital relic
#

im clueless hmm

normal citrus
#

I'm quite clueless aswell

#

My teacher assigned this as the "harder"part

leaden tusk
#

probably because it doesn't have an elementary answer

normal citrus
#

And why is that

vital relic
#

i thought it was graph sketch smh

leaden tusk
#

none of our normal integration techniques work

sweet shard
leaden tusk
#

honestly lmao

normal citrus
#

Sometimes

leaden tusk
#

what class is this for

sweet shard
#

There's a complicated multivariate way

vital relic
#

wait this thing aint fripping 0 either?

#

?????

sweet shard
#

And a trivial complex analysis way

vital relic
#

wait are u guys saying this aint doable

#

elementary

leaden tusk
#

yes

vital relic
#

...........

normal citrus
#

I'm so confused rn lol

sweet shard
#

But I don't know a single variable calculus way

leaden tusk
#

you can express it as a power series lmao

vital relic
leaden tusk
normal citrus
#

I'm from Sweden

#

This one is called "Math 4"

vital relic
#

you have to do series

#

=.=

leaden tusk
#

what year uni

normal citrus
#

I'm 17

leaden tusk
#

bro what

sweet shard
#

Jesus christ

leaden tusk
#

what kind of teacher

#

???

sweet shard
#

Power series and term-by-term integration works. But is the answer obvious from the series?

vital relic
#

,w integrate (sin x) / x

#

pfff

sweet shard
#

Lol

normal citrus
#

Si?

sweet shard
vital relic
#

Non-elementary function

normal citrus
#

Huh

#

Never heard of it

leaden tusk
#

not surprising lol

vital relic
#

Can you do series expansion?

#

You learnt?

normal citrus
#

Nope

vital relic
#

If yes, at least you can do the question

#

wtf???

leaden tusk
#

what integration techniques do you know

vital relic
#

Your teacher made a mistake then

#

this is bs

leaden tusk
#

not that they help here but i'm curious

normal citrus
leaden tusk
#

damn lmao

vital relic
#

Ok, then here's the answer to your question

#

,w integrate from 0 to pi ((sin x) / x)

leaden tusk
#

yeah your teacher either goofed or is borderline insane

vital relic
#

Just walk to next lesson with this

#

oops

frosty imp
#

lol

vital relic
#

,w integrate from 0 to pi ((sin x) / (2x))

thorny flameBOT
vital relic
#

@normal citrus Here

sweet shard
#

Yea fuck your teacher

#

This reminds me of the time my linear algebra instructor, who was a grad student, told us to disprove Fermat's Last Theorem

normal citrus
#

Well thanks guys

sweet shard
#

Fuck that guy

leaden tusk
#

lmfao

normal citrus
#

.close

topaz sinewBOT
#
Channel closed

Closed by @normal citrus

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

neon iron
#

Is it possible for upper bound of integral to be less than lower bound?

wooden matrix
#

No

neon iron
#

Like I was solving an integral.
$$\int_0^{\frac{\pi}{3}} \sin(x) \ln(\cos(x)) dx$$

thorny flameBOT
wooden matrix
#

oh you mean bounds of integration

#

yes

neon iron
#

Is it possible?

wooden matrix
#

yes

neon iron
#

Umm... But how?

wooden matrix
#

how what?

#

$\int_a^b=-\int_b^a$

thorny flameBOT
neon iron
#

Thanks

wooden matrix
#

Could have googled that btw.

neon iron
#

.close

topaz sinewBOT
#
Channel closed

Closed by @odd fjord

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

topaz sinewBOT
glacial kite
#

I shall just ask this in dynamical systems, gonna delete it.

#

.close

topaz sinewBOT
#
Channel closed

Closed by @glacial kite

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

potent venture
#

Can someone help with this question? Im not sure where to even begin

topaz sinewBOT
#
Channel closed

Closed due to the original message being deleted

potent venture
#

.close

topaz sinewBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

thorny flameBOT
normal citrus
#

I do know how to use partial integration but now it's a function in the exponent and I'm lost

topaz sinewBOT
#
Channel closed

Closed due to the original message being deleted

normal citrus
#

.reopen

#

$\int xe^{2x+3}dx$

thorny flameBOT
normal citrus
#

Here we go again I guess

topaz sinewBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

serene quiver
topaz sinewBOT
serene quiver
#

Im having struggle finding the right u and du

#

I thought it was x^2 for u

#

Then 2x for du, but how would i get to

#

Oh

wooden matrix
#

it is

serene quiver
#

Multiply it by 3/2

#

So 3/2 du

#

Yeah?

#

3/2du = 5x dx?

wooden matrix
#

3?

serene quiver
#

Wait

#

5/2

wooden matrix
#

yes

serene quiver
#

Im so dumb

#

Shit thanks lmao

#

.close

topaz sinewBOT
#
Channel closed

Closed by @serene quiver

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

valid rampart
#

Stuck on how to calculate the partial sum. Calculator is not working.

topaz sinewBOT
#

@valid rampart Has your question been resolved?

#
Channel closed

Closed by @valid rampart

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

small seal
topaz sinewBOT
small seal
#

im doing calc limits

#

it says to take the reciprocal to simplify but I'm not sure how they are getting the answer they get

#

from my understanding reciprocal meant just flipping a fraction around

leaden tusk
#

so do that

#

$\frac{.11}{1}$

#

flip it

thorny flameBOT
#

a disappointing son

small seal
#

how does that become 7.1429 though

#

thats whats throwing me off

leaden tusk
#

uhh

#

it doesn't

small seal
#

tell me im not crazy

#

am i wrong or did they pull that shit out of thin air

#

bro i am so dumbn

#

close

#

idk how to close

#

.close

topaz sinewBOT
#
Channel closed

Closed by @small seal

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

neon iron
topaz sinewBOT
neon iron
#

please explain it to me i will be back in about 5 - 10 minutes

#

<@&268886789983436800> academic dishonesty

vapid lichen
#

@neon iron is this a test?

neon iron
#

im back, and no this is homework

#

i got it just needed a little bit of research thanks guys

#

.close

topaz sinewBOT
#
Channel closed

Closed by @molten lark

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

topaz sinewBOT
#
Channel closed

Closed by @glass plume

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

gray basin
topaz sinewBOT
winged forge
#

Use the cos ratio to find the hypotnuse of the big triangle

hard crown
#

^

gray basin
#

Ok

restive inlet
#

that isn't needed

winged forge
#

then use sin ratio to find the angle

gray basin
#

I’m confused

restive inlet
#

there is much better trig function that can be used

winged forge
#

really?

#

does my way work at least?

gray basin
#

Okay let me try

drifting swift
#

it's a little insidious that the point with the right angle is given no name

gray basin
#

I didn’t get it

sweet shard
drifting swift
gray basin
#

So what do I do

drifting swift
#

look at this diagram

#

do you see this diagram? Y/N

gray basin
#

Y

drifting swift
#

can you name some right triangles in this diagram?

#

there are two of them here.

#

i would like you to name them.

gray basin
#

There’s a scalene and right-angled triangle

drifting swift
#

no, that's not what i'm asking you to do.

#

i'm asking you to name the two right triangles present in this picture,
not just describe them by type

#

if you were asked to name a person you would rather say "Frank" than "a tall man" wouldn't you?

gray basin
#

Yes.

drifting swift
#

so

#

give me the name of one of the right triangles in the picture.

gray basin
#

There is one ‘orthogonal triangle’.

drifting swift
#

give me

#

the

#

NAME

#

do you know how to name a triangle? Y/N

gray basin
#

Y

drifting swift
#

okay, tell me how to name a triangle.

gray basin
#

The right angled triangle is CDB

drifting swift
#

...that is one of the right triangles in the picture, yes.

#

you'vev given a name finally

gray basin
#

And the other is ACB

drifting swift
#

great.

#

er

#

no.

#

ACB is not a right triangle.

gray basin
#

CAB

drifting swift
#

that's the same triangle as ACB...

#

in this context, putting the vertices in a different order makes no difference

gray basin
#

BAC

drifting swift
#

are you being dense on purpose here

gray basin
#

?

drifting swift
#

immediately after i say

in this context, putting the vertices in a different order makes no difference

#

you put the vertices A, B and C in yet another order

#

hoping, apparently, that this time you'll get it right

gray basin
#

Oh right

drifting swift
#

you have named CDB as one of the two right-angled triangles in the picture.

#

what's the other one?

gray basin
#

BDA

drifting swift
#

great.

#

so you have two triangles

#

CDB and BDA

gray basin
#

Okay

drifting swift
#

can you write out what data is known for each triangle?

gray basin
#

They are both right- angled triangles

drifting swift
#

thank you captain obvious

#

if you're going to say something as trivial as that, then at least say which angle in each of them is the right angle.

gray basin
#

Oh yeah triangle BDA has one angle as 39 degrees

drifting swift
#

which angle?

gray basin
#

Angle A

drifting swift
#

okay

#

so we know angle A = 39°

#

is that all we know about triangle ABD?

gray basin
#

No

drifting swift
#

really? so we know nothing else about it?

#

ok, so what else do we know?

gray basin
#

It’s third angle is 51 degrees( angle b)

drifting swift
#

angle B, not b. math is case-sensitive.

gray basin
#

Ok

drifting swift
#

and that's not given, but sure.

#

what else do we know about triangle ABD?

#

again, look at the diagram

#

all i'm asking you to do here is read off what's given.

#

no calculations.

#

just reading.

gray basin
#

The base length is 15.9m

drifting swift
#

what is "the base length"?

#

is this the length of a side? if so, which side?

gray basin
#

Side ad

drifting swift
#

math is case-sensitive

gray basin
#

Side AD

drifting swift
#

please read and understand everything i say.

#

preferably, please do so the first time round.

gray basin
#

Ok

drifting swift
#

okay

#

now

#

what part of triangle ABD are we looking for?

#

i.e. what is asked for in part (a) of the problem?

#

again, no calculations, only reading.

gray basin
#

What is the width w of triangle ADB

drifting swift
#

yes, w is what's asked for.

#

so

#

to bring that all back together

#

we have
a right triangle ADB, with D as the right angle
in which:
the angle A = 39° is known
the side AD = 19.5 is known
the side DB = w is sought

#

can you write down a trigonometric ratio statement relating these three quantities?

gray basin
#

Angle A might be useful here

#

Ok I think I just got the answer

#

I got it thank you

#

For your help

#

I understood how to do it

#

.close

topaz sinewBOT
#
Channel closed

Closed by @gray basin

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

idle spruce
#

hi just a quick question on twiddle in relation statements

idle spruce
#

is twiddle always an equivalence

#

~

#

i guess i should say is twiddle always an equivalence with a condition

topaz sinewBOT
#

@idle spruce Has your question been resolved?

topaz sinewBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

idle spruce
#

.reopen

topaz sinewBOT
#

idle spruce
#

<@&286206848099549185>

viscid thistle
#

question

maiden adder
#

$$\verb|~| A \leftarrow \text{may be negation}$$
$$A \verb|~| B \leftarrow \text{most likely equivalence relation}$$

thorny flameBOT
#

Khazali

topaz sinewBOT
#

@idle spruce Has your question been resolved?

topaz sinewBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

jaunty valley
#

Dose anyone know what is Bases in Japanese? <@&286206848099549185>

topaz sinewBOT
#

@jaunty valley Has your question been resolved?

topaz sinewBOT
#

@jaunty valley Has your question been resolved?

topaz sinewBOT
#
Channel closed

Closed by @jaunty valley

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

livid scarab
#

is there a formula for this summation?

5^0 + 5^1 + 5^2 + 5^3 + 5^4 + 5^(k-1) + 5^k
restive inlet
#

yes

livid scarab
restive inlet
#

you can view this as a geometric series

livid scarab
#

but what is the formula

restive inlet
#

try looking up formula for geometric series

topaz sinewBOT
#

@livid scarab Has your question been resolved?

livid scarab
restive inlet
#

were you able to find a general formula when looking up geometric series

livid scarab
#

ya

restive inlet
#

what did you find

livid scarab
#

this one

restive inlet
#

try and identify the three things listed at the bottom

livid scarab
restive inlet
#

same idea

livid scarab
#

but we would just use the formula twice ?

#

formula * formula

keen venture
#

That's multiplying by 5/7 every time

#

Where the first term is 7^k

livid scarab
#

not sure what common ratio is for r

livid scarab
keen venture
#

Ye

livid scarab
#

$\frac{a_1\left(1-r^n\right)}{1-r}=\frac{5^0\cdot 7^k\left(1-\frac{5}{7}^k\right)}{1-\frac{5}{7}}$

thorny flameBOT
#

The-Elite

livid scarab
#

is this right ? @keen venture @restive inlet

restive inlet
#

not quite

livid scarab
#

n = k right ?

#

a_1 is 5^0 * 7^k

#

r = 5/7

restive inlet
#

note that the exponents go from 0→k (and k→0)
so you actually have k+1 terms

#

and you should also have parentheses when raising your r to a certain power

livid scarab
#

oh

#

$\frac{a_1\left(1-r^n\right)}{1-r}=\frac{5^0\cdot 7^{\left(k+1\right)}\left(1-\frac{5}{7}^{\left(k+1\right)}\right)}{1-\frac{5}{7}}$

thorny flameBOT
#

The-Elite

restive inlet
#

no

livid scarab
#

but i added k+1

restive inlet
#

the first term is still 5^0*7^k, that part was fine

livid scarab
#

oh

restive inlet
#

and parentheses are needed around the (5/7)

#

not the power

livid scarab
#

oh

#

$\frac{a_1\left(1-r^n\right)}{1-r}=\frac{5^0\cdot 7^k\left(1-\left(\frac{5}{7}\right)^{k+1}\right)}{1-\frac{5}{7}}$

thorny flameBOT
#

The-Elite

restive inlet
#

yes

livid scarab
#

thanks

topaz sinewBOT
#

@livid scarab Has your question been resolved?

#
Channel closed

Closed by @livid scarab

Use .reopen if this was a mistake.

topaz sinewBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

livid scarab
topaz sinewBOT
keen venture
topaz sinewBOT
#

@livid scarab Has your question been resolved?

#
Channel closed

Closed by @livid scarab

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

iron mica
topaz sinewBOT
#

@iron mica Has your question been resolved?

iron mica
#

<@&286206848099549185>

iron mica
#

.close

topaz sinewBOT
#
Channel closed

Closed by @iron mica

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

topaz sinewBOT
livid scarab
#

$\frac{\left(\left(7n-5^{\left(k+1\right)}\right)\right)}{2}$

thorny flameBOT
#

The-Elite

topaz sinewBOT
#
Channel closed

Closed due to the original message being deleted

livid scarab
#

I have an assumption that 7^k = n

#

I want to make the base 5 in 5^(k+1) into a base 7

#

but not sure how to

keen venture
#

7^[log7(5)(k+1)]

worthy lake
#

u could use logs

keen venture
#

Where log7(5) is the logarithm, base 7, of 5

livid scarab
#

$\log _7\left(5\right)^{k+1}$

thorny flameBOT
#

The-Elite

livid scarab
#

like that ?

#

$7^{\log :_7\left(5\right)^{k+1}}$

thorny flameBOT
#

The-Elite

livid scarab
#

sorry this

keen venture
#

$7^{\log_7(5)(k+1)}$

thorny flameBOT
#

Kaynex

livid scarab
#

oh

keen venture
#

Note the k+1 can be put as an exponent into the log, then the logs cancel

#

Giving 5^(k+1) back

livid scarab
#

what do you mean

#

I don't understand

#

could you show it using TEX

topaz sinewBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

livid scarab
livid scarab
#

or rule

topaz sinewBOT
#

@livid scarab Has your question been resolved?

gusty pasture
#

hi im new

acoustic tangle
thorny flameBOT
livid scarab
#

thx

livid scarab
livid scarab
#

$\frac{\left(\left(7n-5^k\cdot ::5\right)\right)}{2}$

thorny flameBOT
#

The-Elite

livid scarab
#

anyway to remove the denominator ?

topaz sinewBOT
#

@livid scarab Has your question been resolved?

livid scarab
#

$\frac{\left(\left(7n-5^k\cdot ::5\right)\right)}{2}$

thorny flameBOT
#

The-Elite

livid scarab
#

anyway to remove the denominator ?

lean yacht
#

multiply by 2?

livid scarab
topaz sinewBOT
#

@livid scarab Has your question been resolved?

topaz sinewBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

neon iron
#

anyone see whats wrong here

topaz sinewBOT
neon iron
topaz sinewBOT
#

@neon iron Has your question been resolved?

leaden tusk
neon iron
#

why

leaden tusk
#

wait sorry meant the second one lol

#

essentially no basis i'm just looking at the arrows

neon iron
#

still wrong

topaz sinewBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

jagged glen
#

x^3-2x^2-x+2 / x-1

topaz sinewBOT
empty sail
jagged glen
#

got to x^2 - x then dont know what to do to get -2 at the end

topaz sinewBOT
#

@jagged glen Has your question been resolved?

#
Channel closed

Closed by @jagged glen

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lapis flame
#

trying to find general formula for projectile motion given an initial vector but this looks wrong and I can't figure out the right way to do it

lapis flame
#

a would be x velocity and b would be y velocity

#

seems wrong because 0 should be a zero of the parabola

#

wait I might be dumb zero might be a zero and I might just be wrong gimmie a minute

#

wait wait no it's not

#

okay so I actually do need help, I feel like that b/100 should be squared or something, because otherwise f(0) != 0

#

and if for some reason I change it to b^2 it miraculously works???

#

???????

#

Like, I'm elated that it works but I'm really confused

#

like, this is beautiful to finally see but why is it b^2???

#

OOOOOOHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH
I found it

#

.close

topaz sinewBOT
#
Channel closed

Closed by @lapis flame

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

golden falcon
#

,tex $\int_\frac{-\sqrt{3}}{2}^0 \frac{1}{2}x - x\sqrt{1-x^2}+ \int_0^\frac{\sqrt{3}}{2} x\sqrt{1-x^2} - \frac{1}{2}x$

thorny flameBOT
#

life improver 912839

golden falcon
#

Okay so I know how to find areas from these sorts of equations (I think) but I am stuck trying to simplify $\frac{1}{2}x - x\sqrt{1-x^2}$

thorny flameBOT
#

life improver 912839

golden falcon
#

I found the boundaries of the shaded region from a graph as well as set up the equation, but I am not sure how to simplify from here so that I can find the antiderivative of each side in order to plug in my boundaries and solve

#

Here is the problem as well because it is possible I've already made a miscalculation

sweet shard
#

Why do you need to simplify it

golden falcon
#

I'm unsure how to take the antiderivative of a square root that has an expression or exponent in it

#

Also the fact that the square root is multiplied by x throws me off

wooden matrix
#

the fact it's xsqrt(1-x^2) makes it easier.

golden falcon
#

Well xsqrt(x) is simply x if im not wrong

#

so would xsqrt(x^2) be x^2

#

Oh crap I am wrong

wooden matrix
#

$\int x\sqrt{1-x^2}\dd{x}$

thorny flameBOT
golden falcon
#

With the power rule the antiderivative of $x = \frac{x^2}{2}$

thorny flameBOT
#

life improver 912839

golden falcon
#

And $\sqrt{1-x^2}$ can be rewritten as $(1-x^2)^\frac{1}{2}$

wooden matrix
#

yes.

thorny flameBOT
#

life improver 912839

wooden matrix
#

both of those things are true

#

the prior less helpful.

golden falcon
#

So with the power rule $(1-x^2)^\frac{1}{2}$ the antiderivative is $3\frac{(1-x^2)^\frac{3}{2}}{2}$

thorny flameBOT
#

life improver 912839

sweet shard
#

You need to use substitution first.

golden falcon
#

Ah

sweet shard
#

Try taking the derivative of your expression with chain rule to see why it's wrong. You're close, just fix minor details

golden falcon
#

$u = 1-x^2$, so the antiderivative of $x(1-x^2)^\frac{1}{2}$ is $x\frac{(3u)^\frac{3}{2}}{2} + C$

#

The x has not been antiderived yet

thorny flameBOT
#

life improver 912839

sweet shard
#

I think you need to go back and review your substitution for integrals

golden falcon
#

Okay

sweet shard
topaz sinewBOT
#

@golden falcon Has your question been resolved?

golden falcon
#

This is what I've got now

#

Sorry if it's confusing I have limited space probably should rewrite it on a different page

topaz sinewBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

topaz sinewBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

narrow torrent
#

if you are given two collinear points can the third point be placed anywhere in the plane?

wooden matrix
#

no plane is defined

#

so... sure

narrow torrent
#

wdym

wooden matrix
#

a line doesn't define a plane

narrow torrent
#

yeah ok

vital relic
#

what even is the question

narrow torrent
#

but the line is in a plane lmao

vital relic
#

what?

wooden matrix
#

ok, that's still infinitely many planes

vital relic
#

ask a proper question

narrow torrent
wooden matrix
#

There isnt

narrow torrent
#

the xy plane

vital relic
#

wait im so confused wtf

wooden matrix
#

Ok yeah

vital relic
#

if you are given 2 collinear points

#

?????

#

what????

wooden matrix
#

you have a line in the xy plane

#

@vital relic Can you.. not?

vital relic
#

You guys are making no sense at all

narrow torrent
#

and i give you two points on that line

wooden matrix
#

Yep, with you

narrow torrent
#

now the question is can a third point be placed anywhere not on the line itself

#

to create a triangle

wooden matrix
#

yes

#

it can be placed anywhere not on the line and you'll have a triangle

#

anywhere on the line, it'll be 3 collinear points

narrow torrent
#

what is this called

wooden matrix
#

geometry

narrow torrent
#

but this theorem

wooden matrix
#

No clue

#

Not everything needs a name

#

Nor is everything a theorem

narrow torrent
#

ok so ignoring transformations and rotations let's let the two collinear points be (a,0), (b,0)

#

and then let C = (x,y)

wooden matrix
#

sure

narrow torrent
#

then the sides of the triangle are:
b-a
sqrt((x-a)^2 + y^2)
sqrt((x-b)^2+y^2)

wooden matrix
#

side lengths, but yes

narrow torrent
#

now the task is to prove that this satisfies the inequalities

wooden matrix
#

you mean the triangle inequality?

narrow torrent
#

yeah

wooden matrix
#

have fun

narrow torrent
#

lol ok

#

ok those inequalities should hold if i square the lengths

#

hmm this is tricky

#

(b-a)^2
(x-a)^2 + y^2
(x-b)^2 + y^2

#

<@&286206848099549185>

#

How do I prove this makes a triangle

sweet shard
#

what is this?

#

the bottom two look like circles and the top seems like a point related to the centers of the two circles

narrow torrent
#

Right thats the equilateral case

topaz sinewBOT
#

@narrow torrent Has your question been resolved?

topaz sinewBOT
#

@narrow torrent Has your question been resolved?

limber current
#

Hey

#

I need help

#

Graphing limits

#

<@&286206848099549185>

sweet shard
drifting swift
#

@narrow torrent can you restate your question again

#

and/or whether it's still relevant

narrow torrent
#

sure

#

given two collinear points in the xy plane

#

prove that a triangle can be formed with any other point not on the line

drifting swift
#

that... sounds like theres nothing to prove?

#

also "two collinear points" what?

#

any two points by defn have a line passing through them (and exactly one line in fact)

narrow torrent
#

yeah ik

#

but is there something extremely obvious i'm missing

drifting swift
#

and like, any three points not on the same line make a triangle

#

why wouldnt they

#

who's asking you this question

narrow torrent
#

by defn?

drifting swift
#

???

#

sorry, i don't understand what you're trying to say anymore.

narrow torrent
#

ok i guess it's as simple as saying the lines must have different slopes so they mutually intersect

#

what's unclear?

drifting swift
#

you're refusing to tell me who's asking you this question

narrow torrent
#

relevance?

vital relic
#

From the very start, your question made little sense.

#

Mosh somehow read your mind, but the rest of us can't

narrow torrent
#

i'm not sure i can explain it more clearly

vital relic
#

Can you show us the original question.

narrow torrent
#

just told you lol

#

several times

vital relic
#

That is how it is worded originally?

#

I find that hard to believe.

narrow torrent
#

there's no originally

#

lmao

vital relic
#

???

#

What is the context of this.

narrow torrent
#

none

vital relic
#

A question sheet, you having an idea, or what?

narrow torrent
#

stop asking questions about the question and answer the damn question haha

vital relic
#

I cant answer something that dont make sense

drifting swift
#

there's a big difference between shit wording handed down from above and shit wording that came out of your own mind

narrow torrent
#

I give you two points on a line. Will any point not on that line form a triangle with those other two points?

drifting swift
#

yes

#

of course it will

narrow torrent
#

don't really know how many ways i can rephrase that

#

and now the challenge is to prove it

drifting swift
#

ok sure you have two points A and B and a point C not on AB

#

the lines AC and BC will not coincide with AB

#

AB and AC will intersect at A and AB and BC will intersect at B

#

are you happy now or will you insist something is missing here

narrow torrent
#

ok then that's all

vital relic
#

Any 3 points form a triangle regardless. Any 3rd point not collinear with the first two will form a non-degenerate triangle.

narrow torrent
#

.close

topaz sinewBOT
#
Channel closed

Closed by @narrow torrent

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

limber current
#

Can I ask again now?

topaz sinewBOT
marsh mortar
limber current
#

Do I have to send my math problem again?

#

Before someone was solving another math problem

#

I think I interrupted it sorry

random crescent
#

Idk where your problem is, they do disappear if you don't reply I think

#

I'd just send it again now:)

limber current
#

The graphing image

leaden tusk
limber current
leaden tusk
#

,rotate

thorny flameBOT
leaden tusk
#

what are ya havin trouble on m'friend

limber current
#

Graphing it

#

My prof didn't explain how to do it

leaden tusk
#

gathered that, but what specifically

limber current
#

I'll show you what I got

leaden tusk
#

i see you labeled H.A and V.A, so good start

limber current
leaden tusk
#

oop sorry

#

didn't see this

#

all looks good except for f(0) being 1

#

seems you drew it defined at two points

#

make sure you make a hole in your graph at x=0

limber current
#

Like this right?

#

Thank you!! Appreciate it

leaden tusk
#

looks good 👍

topaz sinewBOT
#

@limber current Has your question been resolved?

#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

void summit
topaz sinewBOT
void summit
#

for the question(first pic)

#

how did the circled equations come in the solution(second pic)

topaz sinewBOT
#

@void summit Has your question been resolved?

topaz sinewBOT
#

@void summit Has your question been resolved?

drifting swift
#

this is a very weird solution

#

but those red circled equations simply state that the normal of your plane is perpendicular to the normals of the two given planes

topaz sinewBOT
#

@void summit Has your question been resolved?

mortal thunder
# void summit

Let $\hat{a}$ be the normal to the plane $2x-2y+z=0$ and $\hat{b}$ be the normal to the plane $x-y+2z=4$, then you can determine that $\hat{a} = \qty(2, -2, 1)$ and similarly the $\hat{b}$ from how the equation of a plane is determined, i.e., $(x-x_1,y-y_1,z-z_1)\cdot \hat{n} = 0$

thorny flameBOT
mortal thunder
#

The red circled equation is tantamount to saying $\hat{a}\cdot \hat{n} = 0$ and $\hat{b} \cdot \hat{n}=0$ as the question clearly says that the plane is perpendicular to these two planes and hence the dot product of their normals must be 0

thorny flameBOT
mortal thunder
#

that's how you got the red circled equation

#

from that, you clearly get a = b, c = 0 and therefore, the equation of your plane

topaz sinewBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

topaz sinewBOT
tribal zephyr
#

or is it just wrong

topaz sinewBOT
#

@tribal zephyr Has your question been resolved?

#
Channel closed

Closed due to the original message being deleted

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

void summit
topaz sinewBOT
#

@void summit Has your question been resolved?

#
Channel closed

Closed by @void summit

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

topaz sinewBOT
#

@copper lotus Has your question been resolved?

untold dirge
#

Basically the question is equivalent to finding the values of k such that the equation has real roots

#

Try to simplify the equation into the form ax^2+bx+c = 0 first

topaz sinewBOT
#

@copper lotus Has your question been resolved?

maiden adder
#

this function should model with some maxima and minima

#

find the derivative's values at x = 0

#

you'll get two points

#

plug in the x values of those points into the original equation

#

you'll likely have minima -> maxima as the range from the y component

topaz sinewBOT
#

@copper lotus Has your question been resolved?

#
Channel closed

Closed by @copper lotus

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

topaz sinewBOT
#
Channel closed

Closed due to the original message being deleted

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

#
Channel closed

Closed by @raw aurora

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

chilly plaza
#

Hi there! needing a bit of confirmation to my solution in regards to the problem on the picture. Is the reason the proof is wrong because M has to be greater or EQUAL to 1? Belle says she doesn't like A because x is lower than 1 but actually its equal to it. Many thanks!

drifting swift
#

no, the proof is wrong for a different reason

#

the proof asserts "M=1 is a non-example of a strict upper bound for [0,1], therefore Belle cannot like it!"

#

conveniently sweeping under the rug that Belle may well like it, but with a different strict upper bound

vital relic
#

Is there missing info for the Q or is that it?

drifting swift
#

Cinderella likes sets with a nonstrict upper bound and Belle likes sets with a strict upper bound

#

to put it briefly

#

@chilly plaza M=1 is not a witness for Belle liking A, but that alone does not mean Belle doesn't like A

topaz sinewBOT
#

@chilly plaza Has your question been resolved?

#
Channel closed

Closed by @chilly plaza

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

neon iron
#

can someone explain what am I supposed to do after factoring?

neon iron
#

OOPS

#

.close

topaz sinewBOT
#
Channel closed

Closed by @tranquil meadow

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

stuck linden
topaz sinewBOT
stuck linden
#

I need help with my math test and multiple questions

#

If you can possibly help that would be much appreciated

empty sail
stuck linden
#

Not yet

#

Can you maybe help me with a few questions?

empty sail
#

You just said you needed help with your math test, is that not a test?

stuck linden
#

Yea the pic I sent is one of the questions on the test

empty sail
#

So that is a test?

unique tundra
#

Can you just help and dont act like a bad person

#

He needs help

stuck linden
#

It’s a performance task before the test to make sure you know the material before the test happens

#

But it has similar questions to the test

empty sail
stuck linden
unique tundra
#

Obviously its not a test he just want to know how to solve this

empty sail
#

It was a reply to that person

stuck linden
empty sail
#

Do you know how to apply SOH CAH TOA?

stuck linden
#

No, this is a culminating activity and we did SOH CAH TOA a while ago so at this point I forget

stuck linden
empty sail
#

Then if you are still stuck, someone can help you through the process

unique tundra
#

If both sides have the same value for example both are 5.7 meters than you have 45 degree angle, but 3.8 meters are way smaller than 5.7 so the degree must be smaller than 45

#

In this case its only 34

empty sail
unique tundra
unique tundra
empty sail
#

He said he knew it but forgot what it was, that video is to refresh he memory

stuck linden
#

Can you tell me which part of the triangle is opp and adj and the hyp??

empty sail
stuck linden
#

Bro but I don’t remember how I used it at the start of the course

unique tundra
#

its multiple choice so efficiency is important

empty sail
stuck linden
#

3.8 m?

empty sail
empty sail
empty sail
#

Now, what side is adj to B?

unique tundra
#

hahahahah

stuck linden
empty sail
stuck linden
unique tundra
#

hahahahha

#

🤣 🤣

empty sail
unique tundra
#

@stuck linden are you allowed to use a calculator on the test?

empty sail
#

What does adjacent mean?

stuck linden
#

I’ll just wing it I have a lot of questions on this to ask so it’ll take too long to slowly go through each one because it’s due by two, which is in an hour

stuck linden
unique tundra
#

you know the formulars for soh cah and toa?

#

in this case the opposite and the adjacent are given, so you can only solve this problem with toa

empty sail
# stuck linden Idk

If you don't want to put the effort in understanding what I'm asking, or using the resource I sent to refresh your memory, then tbh you're out of luck, especially in university level classes. Higher level classes, you're going to need to use resources, outside of the book, to understand material, and you have to understand the concepts and terms used

stuck linden
unique tundra
#

yea i think i can help this guy you can help someone else dldh

unique tundra
#

if you dont have the hypotenuse you cannot use soh or cah

empty sail
unique tundra
stuck linden
unique tundra
#

obv yes

empty sail
empty sail
unique tundra
#

im studying electrical engineering

#

cool right

stuck linden
# empty sail Computer Science

Nice man, I have a computer science course for the first time this semester and I’m doing pretty good in it, I think I got an 80 in it right now

empty sail
unique tundra
#

i will make tons of money with it when i work in daimler or bmw

#

😁