#help-26

1 messages Β· Page 204 of 1

wispy pier
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Why ?

obsidian sparrow
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well the math is right

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i just messed up with the hypotenuse

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its -1 not 1

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but the math is right hooray

grand trellis
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What 😭

obsidian sparrow
grand trellis
obsidian sparrow
#

quadrant 4 so its negative

obsidian sparrow
wispy pier
#

Let it be so

obsidian sparrow
#

πŸ˜”

grand trellis
wispy pier
#

Also

grand trellis
#

Nevermind that

wispy pier
#

I must mention

obsidian sparrow
wispy pier
#

This side is negative too πŸ™‚

grand trellis
obsidian sparrow
obsidian sparrow
#

so because its sin its negative?

grand trellis
#

First of all

wispy pier
#

Which makes cos(-45°) = (-1/√2)/(-1)

obsidian sparrow
#

since its in quadr 4

grand trellis
#

a is side length 😭

obsidian sparrow
#

yes

grand trellis
#

Wait

obsidian sparrow
grand trellis
#

Is it given to you

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That hypotenuse is 1

obsidian sparrow
#

is what given to me

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its unit circle

obsidian sparrow
#

i assumed it was 1 because its the radius

grand trellis
#

Seems correct

obsidian sparrow
#

but the answer is negative so idk

grand trellis
#

Sin will be 1/√2/1

obsidian sparrow
#

what

grand trellis
#

...

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Like

obsidian sparrow
#

sin-45

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?

grand trellis
#

Opposite side / hypotenuse

obsidian sparrow
#

oh wait i forgot to plug

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lmao

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ahh

wispy pier
obsidian sparrow
#

yea

wispy pier
obsidian sparrow
#

this guy said it cant be negative tho

grand trellis
grand trellis
obsidian sparrow
#

oh

grand trellis
#

Proving it in general is easier for me

obsidian sparrow
#

wait so its (-√1/2)/-1

grand trellis
#

Idk man

obsidian sparrow
#

this

grand trellis
#

Sides of a triangle shouldnt be negative 😭

obsidian sparrow
#

This is a

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which is opp

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and hyp is -1

obsidian sparrow
grand trellis
#

That's like

obsidian sparrow
#

WHAT OD U MEAN NO

grand trellis
#

Imaginary number

obsidian sparrow
#

ahhhh

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dnvbiuvweoiwfefhbovwnm

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okay

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how is the answer negative then

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when does it turn negative

grand trellis
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Idk man 😭

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Lemme tell you how to prove in general

obsidian sparrow
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my work

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okay im pretty sure it can be negative in the unit circle only

grand trellis
#

a^2 + a^2 = x^2
a= 1/√2 x

Sin(-45) = - ( 1/√2)(x) / x
sin (-45) = - 1/√2

obsidian sparrow
#

thats the only way it would make sense

grand trellis
obsidian sparrow
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oh my god bro im gonna kms

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ok whatever next question

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Isnt this just the y value of point A?

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sqrt3/2

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teacher doesnt put the answers on the slides

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kinda dumb

raven field
obsidian sparrow
#

.close

topaz sinewBOT
#
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topaz sinewBOT
#
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digital meteor
topaz sinewBOT
digital meteor
#

How would i know what x is when sin x is 3/5

wispy pier
near bolt
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you need to know inverse trignometry to understand it

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as a = arc sin(3/5)

ivory sorrel
#

Arcsin(3/5) is 37 deg if I remember right

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,calc sin(37deg)

thorny flameBOT
#

Result:

0.60181502315205
ivory sorrel
#

,w sin(37deg)

prisma mesa
hardy crater
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but note that for the question that you showed, getting the exact value of angle a is not necessary to answer the question

topaz sinewBOT
#

@digital meteor Has your question been resolved?

topaz sinewBOT
#
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round pagoda
#

ok so

topaz sinewBOT
round pagoda
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you see the second deravtive graph

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how does that show the maxima and minima

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its just a straight line

near bolt
#

second derivative graph is for concavity

low nymph
#

look at the first derivative graph and see how the roots line up with the original graph's local min/max

topaz sinewBOT
#

@round pagoda Has your question been resolved?

topaz sinewBOT
#
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Remember:
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β€’ Show your work, and if possible, explain where you are stuck.
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rocky crane
#

help me

topaz sinewBOT
rocky crane
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-1/20(x+75)^3/2 = 10

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x = 25 or is it no solution

neon iron
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Eliminate the coefficient first.

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did yo do that?

rocky crane
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i multiplied the recpricol of -1/20

neon iron
#

There is multiple ways of doing it.

rocky crane
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and then once i did that i got (x+75)^3/2 = -200

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and then powered both sides by ^2/3

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so i got x+75 = -200^2/3

neon iron
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after multipluing by reciprocol

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you need to analyze the equation

rocky crane
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i powered the reciprical of 3/2

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so i could remove the power

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$x+75 = -200^(2/3)$

neon iron
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but if you looked closely, the right side is -200

thorny flameBOT
neon iron
#

yeah

rocky crane
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yea -200 to the poewr of 2/3

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which can be written like sqrt(-200^3)

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$sqrt(-200^3)$

neon iron
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there is no solutions from what i got

rocky crane
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ok same

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cuz i got -10 and 10i when i plugged x back into the equation

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so that means no solutions correct?

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cuz for me i got X = -75 ± √40000

neon iron
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because you got (x+75)^3/2 so its not negative but left side is negative

rocky crane
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oh i see

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so no exrtanious solutions aswell corect

neon iron
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yes

rocky crane
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so then for this eqation: sqrt(5x+6) = 1+ sqrt(3x+3 or 2 i forgot)

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i got 2 and -1

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but when i plugged -1 back into the eqatuon i got 2 different decimal ansewrs

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but when i plugged in 2 i got 4 on both sides

neon iron
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is it 3 or 2

rocky crane
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yea wait its 3

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i might have plugged in -1 wrong in the calculator tho cuz i was running out of time

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it might have been -1 aswell

rigid ivy
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It's $\sqrt[3]{(-200)^2}$

rocky crane
#

sqrt

thorny flameBOT
rocky crane
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i maent that my bad

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i said the wrong way

neon iron
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Step 1: Start with the equation

rocky crane
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but it gives cuberoot (40000)

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which gives Β± 43.something

neon iron
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we doing sqrt(5x+6) = 1+ sqrt(3x+3 now?

rocky crane
#

yes

neon iron
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Five x plus six equals one plus the square root of three x plus three.

rocky crane
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i got 2 and -1 but when i plugged in -1 it didnt give me the same answer on both sides

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but i feel like i might have plugged it in wrong on the calculator

neon iron
#

yes

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i got -1

rigid ivy
rigid ivy
rocky crane
#

(-200)^2

rigid ivy
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Oh

neon iron
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400

rigid ivy
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You are right

neon iron
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40000

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whoops

rigid ivy
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I be mixing them up too KEK

rigid ivy
neon iron
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cuberoot 40000

rocky crane
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but its cube root

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negative and postive number works

neon iron
#

34.19 is what i got

rigid ivy
neon iron
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but is it an irrational?

rocky crane
#

wait but in my math test am i suuposed to know if there are parenthesis when it says -200^2

neon iron
#

πŸ’€ πŸ’€ πŸ’€ πŸ’€ πŸ’€ πŸ’€ πŸ’€ πŸ’€ πŸ’€

#

yes

rigid ivy
neon iron
#

πŸ’€ πŸ’€ πŸ’€ πŸ’€ πŸ’€

rocky crane
#

wait im so confused

neon iron
#

πŸ’€

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πŸ’€

rigid ivy
neon iron
rocky crane
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ok but how do i know if there are brackets if i get to -200^2 from evaluating

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is that given or something

neon iron
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with brackets its 40000

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without brackets its -40000

rocky crane
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would either one of them give me 10

neon iron
#

from what

rocky crane
#

cuz it was x -75 Β± cuberoot(40000) or is tehre a different number given if it was cuberoot(-40000_

rigid ivy
# rocky crane wait im so confused

The parentheses must be there. Because at one point, you alegraically got to $(x+75)^{3/2}=-200$. So when you raise both sides to power $2/3$, that exponent is applying to all of $-200$, which you represent through parentheses

thorny flameBOT
rocky crane
#

oh i see

thorny flameBOT
rocky crane
#

so if you subsituted X into the equation with 40000 cuberoot would it equal to 10

rigid ivy
neon iron
#

there is no solutions

rocky crane
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cuz wehn i plugged x in i got -10 and 10i

neon iron
#

misclick?

rocky crane
rigid ivy
neon iron
rigid ivy
rocky crane
#

really?

rigid ivy
#

I forgot the square root nonsense

rocky crane
#

wait the problem is on the test i wrote x = -75 Β± cuberoot(-40000)

neon iron
#

Step 1: Start with the equation
Five x plus six equals one plus the square root of three x plus three.
Step 2: Isolate the square root
Move one to the left side by subtracting it from both sides:
Five x plus six minus one equals the square root of three x plus three.
This simplifies to:
Five x plus five equals the square root of three x plus three.

rocky crane
#

i showed work though

rigid ivy
#

Algebraically, you would arrive at $x=\sqrt[3]{40000}-75$, but this would not work. You would end up with $-10=10$

neon iron
#

Step 3: Square both sides to remove the square root
Square both sides of the equation:
The left side becomes the square of five x plus five.
The right side becomes three x plus three.
Step 4: Expand the square
The square of five x plus five equals twenty-five x squared plus fifty x plus twenty-five.
So the equation becomes:
Twenty-five x squared plus fifty x plus twenty-five equals three x plus three.
Step 5: Move all terms to one side
Subtract three x and three from both sides:
Twenty-five x squared plus fifty x minus three x plus twenty-five minus three equals zero.
This simplifies to:
Twenty-five x squared plus forty-seven x plus twenty-two equals zero.
Step 6: Solve the quadratic equation
Use the quadratic formula to solve for x. The formula is:
x equals negative b plus or minus the square root of b squared minus four a c divided by two a.
Here, a is twenty-five, b is forty-seven, and c is twenty-two.

thorny flameBOT
neon iron
#

oh shit wrong question

rigid ivy
thorny flameBOT
neon iron
#

nah this is on my top 10 dumbest moments

rigid ivy
rocky crane
#

ok what about the second question

rigid ivy
#

Half awake on mobile one eye open. Not at my best

rocky crane
#

i got 2 and -1 but i said -1 was an extranueos solution

rigid ivy
rocky crane
#

ea

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yea

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its also 3 not 2

rigid ivy
#

?

neon iron
#

Start with
negative one over twenty times the quantity x plus seventy five to the power of three over two equals ten.

Step one. Eliminate the fraction.
Multiply both sides by negative twenty to cancel out negative one over twenty.
x plus seventy five to the power of three over two equals ten times negative twenty.

This simplifies to
x plus seventy five to the power of three over two equals negative two hundred.

Step two. Check the left side.
The power three over two means taking the square root first and then cubing the result. The square root of any number is always zero or positive. This means x plus seventy five to the power of three over two cannot equal a negative number.

Final answer. There are no real solutions to this equation.

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this is what i did

rocky crane
#

$\sqrt(5x+6)\ = 1+ \sqrt(3x+3)$

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i cant write with this

neon iron
#

you gotta eliminate the sqrt first

thorny flameBOT
#

.

$\sqrt(5x+6)\ = 1+ \sqrt(3x+3)\$
```Compilation error:```! Missing $ inserted.
<inserted text> 
                $
l.50 \end{document}
                   
I've inserted something that you may have forgotten.
(See the <inserted text> above.)
With luck, this will get me unwedged. But if you
really didn't forget anything, try typing `2' now; then
my insertion and my current dilemma will both disappear.```
rigid ivy
neon iron
#

from ELA

rocky crane
#

the root goes over the 5x+6 and the other root goes over the 3x+3

#

just to clarify

rigid ivy
#

$\sqrt{5x+6}=1+\sqrt{3x+3}$

thorny flameBOT
rocky crane
#

yea

#

jeez this is like bros second language

neon iron
#

i think imma go now

rocky crane
#

alr

rigid ivy
rocky crane
#

cuz when i plugged it in the calc i got on the left side a 3.1irrational and the other side i got a 3.4 irrational

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but i think i may have plugged it in wrong in the calc

rocky crane
#

granted when i was checking the answers the class had ended like 5 seconds ago and i had to give the paper

rigid ivy
rocky crane
#

damn it

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i failed the test

neon iron
#

nooo

rocky crane
#

all these silly mistakes i swear

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only raeson im failing

neon iron
#

what was wrong

rocky crane
#

for the first question i providede i said x = -75 +- cuberoot(-40000)

neon iron
rocky crane
#

when it was no soliution

neon iron
#

bru

rocky crane
#

and the second one i said x = 2 and not x = -1

neon iron
#

bru

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double check

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if it looks wrong in calc, punch num bers in again

rocky crane
#

and then i dont know if i needed to rationalize the denominator for one of them

neon iron
#

but its ok.

rocky crane
#

cuz i had to find the inverse of 3x^8 = y

neon iron
#

there is always another day

rocky crane
#

and i got 8throot(x/3)

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but i didnt rationalize but i had a reason

rocky crane
#

cuz the next question was asking to see if they were inverese and it was f(x) = 2x^5 and g(x) = 5throot(x/2)

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and the fifth root was not rationalized

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and also is the rationalized verison of 8throot(x/3) 8throot(3x)/3

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?

neon iron
#

quick question, whos your fav mathmatician

rocky crane
#

Nobody

neon iron
#

welp

rocky crane
#

Maybe Sal khan

neon iron
#

yeahhhhh

rocky crane
#

lol

rocky crane
#

Ok good

#

What is it

neon iron
#

wait im so confused rn

#

my tiney brain is not braining

rigid ivy
#

$\sqrt[8]{\frac x3}=\frac{\sqrt[8]{3^7x}}3$

thorny flameBOT
rocky crane
#

guys

#

i might have read the question wrong

#

my freinds are sayig it was 60 - (1/20) * (x+75)^3/2 = 10

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and they got 25

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i swear to GOD on my paper there was no 06

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60

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it must have gotten cutten off in the printing no way

rigid ivy
topaz sinewBOT
#

@rocky crane Has your question been resolved?

neon iron
#

NAHHHH

topaz sinewBOT
#
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#
Available help channel!

Send your question here to claim the channel.

Remember:
β€’ Ask your math question in a clear, concise manner.
β€’ Show your work, and if possible, explain where you are stuck.
β€’ After 15 minutes, feel free to ping <@&286206848099549185>.
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β€’ Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

south peak
#

Am I correct in thinking that what the author means by "the same" is really "proportional"?

fallow heart
#

Nope, the same is correct

grim pike
#

By "the same linear combination", I guess the author just means that the coefficients that multiply $\mathbf{x_1}$ and $\mathbf{x_2}$ are the same as the coefficients that multiply $f(\mathbf{x_1})$ and $f(\mathbf{x_2})$, respectively.

thorny flameBOT
neon iron
#

whats the font pls?

south peak
# neon iron omg i love that font

You and me both. I love it, too. I specifially thought... "I love this font, I wonder which one it is". I tried to find the name, but couldn't. However, the font I'm using for my own notes (by coincident) is either very similar or the same.

#

I can get you the name of this font I'm using...

#

Font: Cambria

#

I'm also using "Cambria Math" for the math symbols.

neon iron
#

i remember i have an alt in this server with that latex font, let me check

#

dont ask me why

south peak
#

Not the expression before the function is resolved.

#

Or maybe you mean the multiplication by the constant inside the function?

neon iron
#

i think its eulervm font

south peak
grim pike
# south peak Hmm, you're saying the same `a` and `b` multiply both `x` and `f(x)`, but he's t...

A linear combination of two vectors $\mathbf{x_1}$,$\mathbf{x_2} \in V$ is an expression of the form $a\mathbf{x_1} + b\mathbf{x_2}$, where $a$ and $b$ are elements of the field over which $V$ is defined. So a linear combination can be thought of as an operation uniquely determined by the coefficients $a$ and $b$. If $f$ is a linear transformation, then $f(a\mathbf{x_1} + b\mathbf{x_2}) = af(\mathbf{x_1}) + bf(\mathbf{x_2})$. In this sense, the linear combination determined by $a$ and $b$ remains unchanged under $f$.

thorny flameBOT
south peak
#

Thank you

#

.close

topaz sinewBOT
#
Channel closed

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#
Available help channel!

Send your question here to claim the channel.

Remember:
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β€’ Show your work, and if possible, explain where you are stuck.
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β€’ Type the command .close to free the channel when you're done.
β€’ Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

neon iron
neon iron
#

.close

topaz sinewBOT
#
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Use .reopen if this was a mistake.

topaz sinewBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
β€’ Ask your math question in a clear, concise manner.
β€’ Show your work, and if possible, explain where you are stuck.
β€’ After 15 minutes, feel free to ping <@&286206848099549185>.
β€’ Type the command .close to free the channel when you're done.
β€’ Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

static kettle
#

How do i find the greatest common divisor and least common multiple of (x³-3x²+4x-12) and (x⁴-16)?
I just don't know what to do with x

neon iron
#

it GCD x^+4?

static kettle
neon iron
#

Th x represents the variable and stays within the polynomial during calculations. To find the GCD and LCM, factor both polynomials, identify common factors for the GCD, and combine all unique factors for the LCM.

neon iron
#

are you sure you factored correctly?

static kettle
neon iron
#

Yes!

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then you simplify

static kettle
#

Ohhh okayyy

twin grotto
#

Is there anyone willing to help me on a large amount of geometry πŸ™ i can’t understand it at all and it’s the only class i have left

static kettle
#

From (xΒ²-4)(xΒ²+4) to (x-2)(x+2)(xΒ²+4)?

neon iron
twin grotto
#

How do i do that?

#

Sorry if I interrupted this one i did not know.

static kettle
neon iron
#

help-forum how to get help

twin grotto
#

Ok thank you

neon iron
#

like help-4

static kettle
#

And then is the GCD=(xΒ²+4)?

#

And LCM= (xΒ²+4)(xΒ²+4)(x-2)(x+3)?

#

No

neon iron
#

you can make the first one (x-2)(x-2)

static kettle
#

LCM=(xΒ²+4)(x+2)(x-2)(x-3)?

static kettle
weary sage
neon iron
neon iron
weary sage
#

(x-2) (x-2)

x * x = x^2

-2 * x = -2x

-2 * x = -2x

-2 * -2 = 4

x^2-4x+4

static kettle
#

?

weary sage
#

Yeah I mean can u think of any other way to simplify

static kettle
#

No I can't

#

Thanks for helping me on this one

#

I also don't know what exactly to do for another exercise tho

#

GCD(a,b)=48
a+b=576 is another exercise I don't understand

static kettle
weary sage
neon iron
#

Wait

#

the middle terms cancel out when you expand

weary sage
#

Wait show what u mean

neon iron
#

xx+x2-2x-22=x^2-4

#

wait what

#

i put * not x

heady robin
#

That’s when signs alternate

heady robin
weary sage
#

Yeah lol discord has features like that

#

U gotta add a space

neon iron
#

x * x + x * 2 - 2 * x - 2 * 2

#

there

static kettle
weary sage
#

Is this a linear algebra question ?

static kettle
neon iron
#

be back in 5 min

static kettle
weary sage
#

Oh I was thinking when you originally wrote D (a,b) = 48 that it was the distance between 2 points

static kettle
weary sage
#

So what is GCD mean ?

static kettle
#

I meant to write the greatest common divisor

weary sage
#

Oh ok

#

Ohhhh okk

#

Alr

static kettle
#

Like GCD(6,2)=2 if im not mistaken

weary sage
#

It’s saying a and b are both multiples of 48

#

And you just have to find what two values that are multiples of 48 = 576

#

Wait

#

I got that wrong

#

Or wait it may still apply

static kettle
#

I have the answer if you need it?

#

I just don't know how to get to it

weary sage
#

Yeah show just in case I’m misunderstanding

static kettle
#

a=48 b=528 /
a= 240 b=336

#

Or reversed values for a and b

weary sage
static kettle
#

Umm lemme try

#

a= 48x, b=48y
a+b=576=
=48x+48y=
=48(x+y)

576Γ·48=12
x+y=12

Then i find the values?

#

x could be 1, y could be 11

#

Anddd

#

X could be 5 and y 7 i think

#

So then a=48Γ—1 , b=48Γ—11 or a=48Γ—5, b=48Γ—7

#

I think?

heady robin
#

She got convincing results

heady robin
# neon iron my brain aint braining this

Since both numbers have 48 as GCD, you can just write them as 48x and 48y, and you have the info of a+b=576

Equate, 576=48x+48y
Factor 48 and divide 576 by it

static kettle
#

Sooo it's correct?

#

Or no

heady robin
#

I mean

#

Can’t say it’s wrong

#

But now you have many values for x and y

neon iron
#

aww man i hate algebra 2

heady robin
#

Are you to get specific values for them or not

neon iron
#

oh wait this is algebra 1

static kettle
heady robin
#

Any expression for 12 will be the answer

#

Even negative numbers

#

Smth like -18 for a and 30 for b will fit

static kettle
#

I maybe forgot to say it says that they have to be natural numbers

heady robin
#

My question is, is that ok or do you need specific numbers

heady robin
heady robin
#

Like does a need to be a specific value

static kettle
#

Idk how it correctly translates into English

heady robin
#

Does the question say smth like: find β€œall possible values” of a and b, or find β€œthe values” of a and b

heady robin
static kettle
#

Like 1 and 11

#

And 5 and 7

heady robin
#

Oh

#

Those are prime

static kettle
#

Ohhh

heady robin
#

They only divide by 1 and themselves

#

But

#

1 is not prime

#

1 is just excluded

#

So you only get 5 and 7

static kettle
static kettle
heady robin
#

It just isnt

static kettle
#

Oh okay

#

I'll try to remember this

#

Anyways thankssss

heady robin
#

Anytime

static kettle
#

Y'all helped me

#

Baiii

#

.close

topaz sinewBOT
#
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heady robin
#

Are the prime numbers values of a and b or x and y

static kettle
heady robin
#

Good good

topaz sinewBOT
#
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neon iron
topaz sinewBOT
neon iron
#

I keep getting C but its supposed to be E?

#

I use a u substitution

#

where u is x-3

#

and du is 1

#

so its the integral from -1 to 1 of 1/u^2

#

which i then get as finding from -1 to 1 -1/u

#

which is just -1 - (-1) or 0

young geyser
#

in the interval [2,4] there is a point where the function is not defined

#

x=3

#

Then you must calculate the integral from 2 to 3, and from 3 to 4

neon iron
#

oh so if you take the definite integral of a function which contains an undifiend point, is it always N/A

#

*DNE

silent siren
#

did you change the bounds of integration?

silent siren
neon iron
#

yeah i did

young geyser
#

yeah DNE

neon iron
#

theres an asymptote that goes to infinity

#

thank you!

#

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supple heart
#

how to find the gcd (n, 209)

topaz sinewBOT
supple heart
#

those three informations are given , forget about the french

#

i know that the the $gcd(n,209) \ | \ n$ and $gcd(n,209) \ | \ 209$

thorny flameBOT
#

<rajel />

wraith iron
supple heart
#

yes

wraith iron
#

so final one says n ~ 137 mod 209

#

that means n don't divide 209

#

so we have gcd < 209

merry hill
supple heart
wraith iron
#

n leaves a remainder of 137 when divided by 209

#

that's what it means

supple heart
#

oh make sens

wraith iron
#

209 = 11 x 19 if that helps

supple heart
wraith iron
#

so gcd can only be 1, 11, 19

wraith iron
wraith iron
#

so I think it easily equals 1

supple heart
wraith iron
#

haven't done any number theory though

#

someone needs to verify this

wraith iron
#

so like it must divide both n and 209

#

does a number bigger than 209 divides 209?

supple heart
wraith iron
#

so we can say gcd<209

supple heart
#

given that the gcd can only be {1,19,11} , after verifying it seem to be only 1

#

because none of the other values divides n

#

takin 19 , which have remainder of 4 so it doesnt divide , and takin 11 it has a remainder of 5 non of them have a remainder of 0

wraith iron
#

yep

grand trellis
supple heart
supple heart
#

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topaz sinewBOT
acoustic pecan
#

lmao

#

i dont even know what you get from this

empty spoke
#

do not ping us for help or when there's nothing going on please

bright trail
#

The helpers are volunteers

empty spoke
#

yes, he's not obligated to help you at all this

bright trail
#

They don't have an obligation to help you within some time frame

#

Depends on a lot of things how fast this happens

#

It is just random internet strangers after all

empty spoke
#

unrealistic to expect this given that people here are volunteers, please be empathetic

gleaming phoenix
#

use a calc?

bright trail
#

Why not just check on a calculator?

acoustic pecan
#

you have access to the internet

bright trail
#

You have an internet connection

rigid ivy
#

Nice job, admitting this is a ban-evasion account KEK

torpid sparrow
#

You can use the command ,calc

bright trail
#

Yeah fair lmao

torpid sparrow
#

Anyways, stop trolling please.

bright trail
#

Back to the ban dimension

#

.close

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#
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inner topaz
#

Let $a_n$ be a sequence such that ${a_n : n \in \mathbb{N}} \subseteq [a, b]$. Let $\epsilon > 0$, a sequence $a_n$ is epsilon-dense if for each $x \in [a, b]$ and for each $N \in \mathbb{N}$ there exists an $n \ge N$ such that $|a_n - x| < \epsilon$

thorny flameBOT
#

jason2D

inner topaz
#

so if i understood that correctly, that just means that every number in the interval is a sub limit right?

#

this channel is occupied

empty spoke
#

please post in an available help channel:

inner topaz
empty spoke
#

no

#

someone else will be able to surely

inner topaz
#

but how can every number in an interval be a sublimit?

#

the cardinality of an interval over R is larger than the cardinality of N

empty spoke
inner topaz
#

what does it mean then

empty spoke
#

here's a crude drawing of a (b-a)/4 dense sequence for instance

inner topaz
empty spoke
#

it means that for any point "x" in the interval, you can always find arbitrarily large n such that a_n is at a distance < epsilon from x

empty spoke
inner topaz
#

how so

empty spoke
#

I didn't read that bit lol

#

because then what you can do is build a subsequence $x_{n_k}$ such that $|x-x_{n_k}|<1/k$ for each $k\in \bN$

thorny flameBOT
#

derivada.schwarziana

inner topaz
#

but thats just all of the rationals

empty spoke
#

by picking $\varepsilon=1$ to get $x_{n_1}$, $\varepsilon=1/2$ to get $x_{n_2}$ and so on

thorny flameBOT
#

derivada.schwarziana

empty spoke
thorny flameBOT
#

derivada.schwarziana

empty spoke
#

this is a proper subset of the rationals that is dense on $\bR$

thorny flameBOT
#

derivada.schwarziana

empty spoke
thorny flameBOT
#

derivada.schwarziana

empty spoke
#

so indeed every point of the interval is a limit point of the sequence

inner topaz
#

but i still dont understand

#

how can a sequence have uncountably infinite sublimits

#

when there are only countably infinite subsequences

empty spoke
#

the idea of "sublimits" of a sequence, or limit points of a set, is simply that they can be approximated to an arbitrary degree of error by elements of the sequence or set respectively

#

a priori there's no reason why a countable set cannot approximate an uncountable one

empty spoke
thorny flameBOT
#

derivada.schwarziana

empty spoke
#

one way to do this by rational numbers is by truncating the decimal expansion[x_1=3, \quad x_2=3.1, \quad x_3=3.14,]and so on

thorny flameBOT
#

derivada.schwarziana

empty spoke
#

and it turns out you can do this for all real numbers

inner topaz
#

but isnt this the oppsite?

empty spoke
#

... and that the rational numbers are countable, so we can write $\bQ=(q_n)_{n\geq 1}$ for some sequence $q_n$ (called an \textit{enumeration}). So this is an example of a sequence which has any point of $\bR$ as a sublimit

thorny flameBOT
#

derivada.schwarziana

empty spoke
inner topaz
#

this says that you can map from an uncountably infinite set to a countably infinite one

#

no?

empty spoke
#

not quite, it's saying that any real number is a limit point of the set of rational numbers which is what we want to show

#

it's true that in some sense we're mapping the limit (the real number) to a sequence that approximates it -- we kinda need to show how the sequence can be constructed

inner topaz
#

ohh

#

so

empty spoke
inner topaz
#

what youre saying is, for any real number you can create a sequence that approaches it

empty spoke
#

yes, a sequence of rational numbers

inner topaz
#

right

#

yeah no stil

#

its true that you can create a sequence of rational numbers that approaches any real number

#

but you still have uncountably many sequences like that

empty spoke
#

yes, your original question was how is it possible for one sequence to have uncountably many sublimits

inner topaz
#

yeah i still dont understand that

empty spoke
#

so q_1=1, q_2=2, q_3=1/2 and so on, following the arrows drawn in the diagram

inner topaz
#

yeah we used that to prove that Q is countably infinite a while back

empty spoke
#

it can be shown that this sequence passes through all of the positive rationals

inner topaz
#

right

empty spoke
#

take a positive real number, suppose we know its (possibly infinite) decimal expansion

inner topaz
#

wdym approximation scheme

empty spoke
#

oh just a way to define a sequence of rationals that converges to it

inner topaz
#

oh

#

yeah i understand that part

empty spoke
#

and since this can be done for any positive real number, the sequence q_n has uncountably many sublimits right

#

I haven't been too rigorous explaining this but hopefully that gives an idea of how this kind of thing can happen

inner topaz
#

for the number 0.12345678...

#

our subsequence would be 0.1, 0.02, 0.003, 0.0004...?

empty spoke
#

I'd say 0.1, 0.12, 0.123, 0.1234, etc.

#

since you want the sequence to actually converge to 0.12345678...

inner topaz
#

but what if the number can be truncated to an irrational number?

empty spoke
# empty spoke I'd say 0.1, 0.12, 0.123, 0.1234, etc.

and this can be written as 1/10, 12/100, 123/1000 which respects the order of the sequence q_n but that's not too important -- just shows that it is a valid subsequence since q_n goes first through all fractions of denominator 1, then 2, and so on

empty spoke
inner topaz
#

oh wait if we truncate it then its not irrational

#

ohhh

#

i got it

#

thanks a lot!

empty spoke
inner topaz
#

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#
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#
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vocal dew
#

i know that when g(x) translates 1 unit to the left that it becomes g(x+1) but how would i use that to create an equation of the new curve?

acoustic pecan
#

do exactly what you said

#

replace x with x+1

#

then expand and simplify if you want to do so

vocal dew
#

omds lol i was overthinking it

#

tysm!!

#

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naive carbon
topaz sinewBOT
naive carbon
#

oh correction S1 wont be there

#

for obvious reasons πŸ₯²

#

,tex
$S_k$ is the sum of the infinite G.P. where first term $a_k = k$ and common ratio $r_k = \frac{1}{k}$ $(k\in\mathbb{N})$. Find the value of $S_2^2+S_3^2+...+S_{2n-1}^2$.

thorny flameBOT
#

NightHaunter

naive carbon
#

i tried partial fractions to turn S_k into a telescoping series but didnt work

#

.close

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#
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brazen inlet
#

I’m not sure how to approach this problem

#

Question 41

pseudo horizon
#

you could get two equations and solve for the intersection point

smoky sparrow
thorny flameBOT
smoky sparrow
#

which becomes $r \sin \theta = -\frac{1}{2} r \cos \theta + 2$

thorny flameBOT
brazen inlet
#

How do you know the radii are equal there

#

I did a and b

smoky sparrow
#

solve for r then use (x, y) = (r cos theta, r sin theta)

smoky sparrow
brazen inlet
#

uh

#

haven’t been taught that

smoky sparrow
#

jeez

brazen inlet
#

this is section 1 on polar and parametric

smoky sparrow
#

basically

brazen inlet
#

Yeah I get that

#

That’s trig

smoky sparrow
#

cool

brazen inlet
#

I’m saying how do you know the coefficients are equal

smoky sparrow
#

this applies to any equation when you write it in polar form

brazen inlet
#

How do we know it isn’t an elliptical path?

#

I guess it makes sense

#

I can draw a circle of some radius and some point on that circle to get any point on that line

#

Is that the idea?

smoky sparrow
#

maybe these examples also help

brazen inlet
#

I’ll check that out after this question

smoky sparrow
#

like you can describe any point on the plane with

  1. distance to origin
  2. angle
#

that's the idea

brazen inlet
#

yeah that’s fair

#

Alright back to the question

#

Lemme try and solve what you sent rq

#

I used a on accident and was too lazy to change so a = r

#

Is this the right idea?

#

@smoky sparrow

#

Top equations are seperate

#

Kind of mushed

smoky sparrow
#

right idea

brazen inlet
#

Wrong answer?

smoky sparrow
#

but you can just use (x, y) = (r cos theta, r sin theta) after you have found r

#

anyway I'm sure they're equivalent parametric forms

brazen inlet
#

Hmmmm

#

How did my book get this?

#

Is there an identity here

smoky sparrow
#

take r cos(t) = $\frac{2 \cos t}{\sin t + (1/2) \cos t}$ for example

thorny flameBOT
smoky sparrow
#

if you multiply top and bottom by 2/(cos t)....

brazen inlet
#

Mhmm

#

Alright yeah

#

I see it all thank you for your help, much appreciated

smoky sparrow
#

also you can realise

#

$\frac{y}{x} = \frac{r \sin \theta}{r \cos \theta} = \tan \theta$

thorny flameBOT
smoky sparrow
#

so $x \cdot \tan \theta = y$

thorny flameBOT
smoky sparrow
#

it's no coincidence

brazen inlet
#

Ohh that makes sense

#

thank you!

#

.close

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#
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topaz sinewBOT
#
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errant hamlet
topaz sinewBOT
errant hamlet
#

so

#

PC=PD then triangle PCD isosceles

#

M midpoint DC then PM perpendicular on DC

#

OC=OD then triangle OCD is isosceles

#

M midpoint DC then MO perpendicular on DC

#

so P-M-O are colliniars

#

here i get stuck

#

<@&286206848099549185>

#

<@&268886789983436800>

thorn briar
#

Pls no ping mods for math help

errant hamlet
#

ok

#

sry

pearl fog
errant hamlet
#

yes

pearl fog
#

could you post it here?

errant hamlet
#

yes

#

one moment

topaz sinewBOT
#

@errant hamlet Has your question been resolved?

errant hamlet
#

AB is radial axis for C(O,OC) and C(O', O'O)

#

we can proof

#

so AMOB inscriptible

#

thats what we need to proof

#

<@&286206848099549185>

pearl fog
#

btw D is not always the diameter unless im missing smth

topaz sinewBOT
#

@errant hamlet Has your question been resolved?

topaz sinewBOT
#

@errant hamlet Has your question been resolved?

topaz sinewBOT
#

@errant hamlet Has your question been resolved?

neon iron
#

hi, @pearl fog

#

what's up?

topaz sinewBOT
#
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frosty iron
#

"show an example of at least one set A containing numbers such that
|A| = 4
for any x,y in A ,x^y and y^x are also in A where x !=y"

frosty iron
#

idk if this is valid but Z_5 = {1,2,3,4} works

#

im curious if theres some other solution

long dawn
#

I guess it depends on what x and y are

prisma mesa
#

is the operation ^ supposed to be the one on reals, or can you define them however you want?

long dawn
#

{1,2,3,4} is consistent with the rules given if we have freedom to choose what x and y are

frosty iron
#

oh wait its supposed to be "for any x,y"

pseudo horizon
#

but 2, 3 are in that set, and 2^3 isn't

#

you might need to use negative numbers

frosty iron
long dawn
#

The way it was initially phrased states "if x,y are in A" which doesn't imply that they are in A

pseudo horizon
#

what

#

lol that changes things

frosty iron
pseudo horizon
#

ok

long dawn
#

x,y could have been elements outside of A, but OP has now clarified that they are definitively in A

pseudo horizon
#

uhhhh but the question is talking about exponentiation, it doesn't mention exponentiation modulo 5

frosty iron
#

yeah it doesnt

surreal mural
#

just invent your own number system where you define x^y = 0 always

prisma mesa
#

if this is from some textbook, can you ss the original problem?

frosty iron
#

its in thai hold on

#

its from a competition

#

maybe google translate sucks ill have gpt translate it for me

prisma mesa
#

is it "x^y in A or y^x in A"?

wooden osprey
#

yes this is what i'm suspecting too

frosty iron
#

oh i think so

#

my thai sucks

#

πŸ’”

wooden osprey
#

but i don't think google translate is that dogshit it can't distinguish between "and" and "or"

frosty iron
prisma mesa
#

okay, so firstly, unless the question allows you so, you shouldnt just invent your own number systems to solve the question

frosty iron
#

mb

#

i tried for a while with some numbers and it didnt work

prisma mesa
#

according to chatGPT, it's or btw

#

as well as google translate

frosty iron
#

okay thanks

pseudo horizon
#

seems more possible now

prisma mesa
#

now try experimenting with it a bit

#

its quite easy now

#

keep in mind that you dont need both x^y and y^x be in A, you only need one of them

frosty iron
#

{1,2,4,8}

#

oh wait

prisma mesa
#

neither is in A unfortunately

frosty iron
#

yeah sorry

#

{-1,0,1,2}

prisma mesa
#

yeah, i had this one in mind

wooden osprey
#

that works

prisma mesa
#

i didnt fully verify it but i think it works

#

any pair with 1 obviously works

#

because x^1 = x which must be in that set

frosty iron
#

question was just hard because i translated wrong lmao

frosty iron
prisma mesa
#

and that only leaves (-1, 2)

#

which works since (-1)^2 = 1 is in the set

frosty iron
#

yay!!

#

sorry guys i wasted your time😭

#

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coarse bluff
#

hello

topaz sinewBOT
coarse bluff
#

i just left my discrete math ezam and everyone is asking about this

#

i got 4^2n

#

is it the correct answer?

#

i double checked multiple times

odd pagoda
#

,w \sum_{i=1}^n \binom{n}{i} 3^i 4^n

odd pagoda
#

not quite

#

i=0 term is missing

coarse bluff
#

oh

#

the i=0 term is always 1?

odd pagoda
#

not sure what you mean with "always"

#

but after you move out the 4^n then the i=0 term would be 1, yes

coarse bluff
#

the -1

coarse bluff
#

fair enough

#

thanks for answering

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vivid saffron
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vivid saffron
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neon iron
#

3, 5, 11, 17, ?

what's the next term?

topaz sinewBOT
desert atlas
#

not enough information

#

also polynomial interpolation says it can be anything

ivory sorrel
#

we define a polynomial $a+bx^2+cx^3+dx^4= p(x)$

thorny flameBOT
#

Ζ’( wai ina teacup)= I don't know

ivory sorrel
#

and then it can be anything

#

yeah

neon iron
#

no its not. it has a pattern

desert atlas
#

the increments are +2 +6 +6

#

i dont see any oattern

#

ok chatgpt says its alternate prime sequence

neon iron
#

HAHA GOTCHA

desert atlas
#

k chatgpt is stupid

neon iron
desert atlas
#

did u ask this question to test us

neon iron
#

i made that up.. and its my school project

#

coming up with random four term that has a pattern

desert atlas
#

well its interesting

#

fo sure

neon iron
# desert atlas fo sure

right. ty for the feedback. i really appreciate :)). if u know any interesting patterns, please tell me.

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torpid sparrow
#

What is your question?

obsidian trout
#

i need help with the integral

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obsidian trout
sweet shard
topaz sinewBOT
# obsidian trout

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obsidian trout
naive lion
#

Make a new post in a different available channel

obsidian trout
#

thank you

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zinc star
#

hello can someone please explain the weak and weak * topologies ? i wanna know why and what are they . i already have some backgorund but i cant just wrap my head around them

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rigid ivy
zinc star
#

Thank youu

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glossy wave
#

A frog is travelling from point A(0,0) to point B(4,6) but each step can only be 1 unit up or 1 unit to the right. Additionally, the frog refuses to move three steps in the same direction consecutively.
Compute the number of ways the frog can move from A to B.

glossy wave
#

So I boiled it down to arranging RRRRUUUUUU in a way such that that three Rs and three Us aren’t next to each other

#

No really sure how to proceed

topaz sinewBOT
#

@glossy wave Has your question been resolved?

glossy wave
#

<@&286206848099549185>

wet sun
#

Would it be simpler to calculate the number of ways to arrange it so that there are 3 Rs next to each other, and the number of ways to arrange it so that there are 3 Us next to each other, then subtract them from the total arrangements?

glossy wave
#

Idk

#

Still seems like a lot of combinations to go through

#

I got that the number of ways of having exactly atleast 3 Rs next to each other is 48

#

Not sure how to go about the Us without double counting tbh

topaz sinewBOT
#

@glossy wave Has your question been resolved?

long stirrup
#

you have 5 buckets with U

#

e,g, 1 1 2 1 1 for URURUURURU

#

0 is allowed

#

one 4, one 5, one 6 are disjoint cases

#

4 2 0 0 0: 20 ways
4 1 1 0 0: 30 ways
5 1 0 0 0: 20 ways
6 0 0 0 0: 5 ways

#

ok 3 is also not allowed

#

and 2 0 0 2 2 would have 2 consecutive 0 which is bad for the R

#

but 0 0 2 2 2 is fine because 0s aren't in the middle

#

yeah that's a lot of stuff

#

i get the feeling there's no neat way at all lol

#

so like, 2 2 2 0 0: 5βˆ’2 = 3 ways
2 2 1 1 0: 30 ways
2 1 1 1 1: 5 ways

#

something's missing

#

oh it's 10βˆ’2

#

yeah

pseudo horizon
#

hm

#

i got an answer

long stirrup
#

43 is right

pseudo horizon
#

dang

#

and you can't hace 3 of the same direction in a row, right?

long stirrup
#

yeah

pseudo horizon
#

ok i'll explain my approach, maybe we can figure out where i went wrong

#

U's can be partitioned as 2+2+1 (3c2=3 distinct ways) or 2+1+1+1+1 (5c1=5 distinct ways)
in the former case, two R's must separate the U's, and the other R's have 8 arrangements
in the latter case, all four R's are used to separate the U's
so i got 3*8+5*1

#

oh i messed up the partitions

#

they should be:
2+2+2
2+2+1+1
2+1+1+1+1

#

so you get 1*8+6*5+5*1=43

#

it works

long stirrup
#

that's identical to what i said btw

pseudo horizon
#

oh

#

sorry

long stirrup
#

ah maybe not exactly

#

it's fine

#

the difference is probably just that i included 0s

#

so it was clear that Rs usually get spread out, there's only 2 cases with two consecutive 0 in the middle

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#

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#
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neon iron
#

How to approach this Q? The answer is 661

topaz sinewBOT
pseudo horizon
#

<@&268886789983436800>

topaz sinewBOT
# neon iron How to approach this Q? The answer is 661
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
neon iron
pseudo horizon
#

for three-digit numbers, i think it will be a pyramidal number

#

i mean a tetrahedral number

neon iron
#

I just searched about pyramidal no.s and tetrahedral but i think that's a different concept

#

It's a Q on PnC

pseudo horizon
#

huh?

#

Q? PnC?

neon iron
#

Permutations and combinations, Q-question

pseudo horizon
#

oh