#help-26
1 messages · Page 186 of 1
yea
$\frac{\dd{y}}{\dd{x}}=\frac{\dd{t}}{\dd{x}}\times\frac{\dd{y}}{\dd{t}}=\frac{1}{2\sqrt{x}}\times-\sin{\sqrt{x}}$
ee
@buoyant horizon
right?
yess
this gives $\frac{-\sin{\sqrt{x}}}{2\sqrt{x}}$
@buoyant horizon
Now in theory, you should've been done
but the book goes an extra step further
Do you recall:
$\sin^2\theta+\cos^2\theta=1$
@buoyant horizon
but wait for this why did u not take -1/sinsqrtx
sorry
😭
why reciprocal?
we got dy/dt as -sin(root x), right?
we just multiply the two diffs we did
to get the answer
ah okay
yes
alright
now
can i do this:
$\sin^2\theta=1-\cos^2\theta\implies \sin\theta=\sqrt{1-\cos^2\theta}$
@buoyant horizon
which?
i just asked u abt it and checked my book but i really can’t seem to get it
wait
here for arccos they took -1/sint but u didn’t 😭 why so (i’m slow as hell)
Uh
let's go back to the very first step
When we did this, did you see that we get a cos on the right, not arccos
We changed the function we want to diff into cos
Because well x = (arccos y)² is harder to differentiate when written in that way
yeah
We got y = cos(√x)
yeah i always do this step but still take the reciprocal 😭
Y is a function of x with a cos, not an arccos
dy/dx means "differentiation of y with respect to x"
after you isolate y
you need to see what the new function is
in this case it's cos
that's why I used d(cos(t))/dt = -sin t
does this clear it up?
okay
tysm bro 😭😭😭
np
so, did you understand this?
from here,
$-\sin\sqrt{x}=-\sqrt{1-\cos^2\sqrt{x}}$
@buoyant horizon
right?
yeah right
so put that instead of -sin√x in this and you should get the expression the book's asking
yeah it’s the same expression 
If you are confused about this "isolating y as function of x", we can still try diffing this
using the arccos formula in ur book
would appreciate it 🥲
alright
im sorry bro i’m actually very slow at understanding
now notice that you havex on the left
yea
so if you differentiate both sides, you write dx/dy, not dy/dx right?
yeah right
alright, so
OHHHHHHH
going by the book method
Since we have a function squared, we can let t = arccos (y)
wait…i just realized sometjing
or maybe i’m wrong…wait continue maybe you’ll mention it while explaining
lol

so
this works right?
i don’t understand 😭
okay
so
When you had, in the example, arccos(x^2)
like we let the squared function be t?
You let the "inside" thing as t, right?
you let the thing that's "inside" a bigger thing as t
yes, now
we have arccos y "inside" a square
so we let t = arccos(y)
$\frac{\dd{t}}{\dd{y}}=-\frac{1}{\sqrt{1-y^2}}$
@buoyant horizon
right?
yea
Now we have dt/dy
We will need to find dx/dt
Now, $x=t^2\implies \frac{\dd{x}}{\dd{t}}=2t=2\arccos{y}$
alr
@buoyant horizon
Now we multiply these two
$\frac{\dd{x}}{\dd{y}}=\frac{\dd{x}}{\dd{t}}\times\frac{\dd{t}}{\dd{y}}=2\arccos y \cdot \frac{-1}{\sqrt{1-y^2}}$
@buoyant horizon
right?
Now, we have dx/dy, but we need dy/dx
t is a different variable we took
we gotta get rid of it in the answer
alr
when you solved the example, you substituted t back to x^2, right?
thats what i did here
oh yeah
So, we need to reciprocal this
This gives
$\frac{\dd{y}}{\dd{x}}=-\frac{\sqrt{1-y^2}}{2\arccos y}$
@buoyant horizon
Right?
yeah
Now, we need to get rid of the y's
since the answer expects us to have everything in terms of x
to get rid of the $y^2$:
$x=(\arccos y)^2\implies \sqrt{x}=\arccos y\implies y=\cos\sqrt{x}\implies y^2=\cos^2\sqrt{x}$
@buoyant horizon
right?
hmm
we got rid of y^2
we still have an arccosy on the bottom
$x=(\arccos y)^2\implies \sqrt{x}=\arccos y$
@buoyant horizon
right?
yess
so we got rid of y's
put that back into this fraction
you get the same expression
real
😭😭 neat work
i wanna save this explanation somewhere so i can comeback to it 😭 i’ll copy the link to one of ur messages and save it 💀
yesss
i think this channel gets dissolved after you mark your question as done
im not sure
it gets used by other ppl but the previous msgs will still remain in it
ee
i’ll just screenrecord
alr
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yo how do I do this now 😭
Consider substituting for x+y
Let u = x+y+2
then u' = y'-1 then u' = u^2+1
Was y = Y - 2 the wrong move
No
Right
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✅
@acoustic tangle sorry to disturb
will this be the final answer
it's given that for x = 0 y = -2
so const = 0
,w √3 - pi/3 - 2
constant of integration
oh
nvm
its right
ty
You could check by just plugging your solution into the original equation
oh yes!
i think it fits
thank you all!
.close
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i have a question about the jabcobian and why is it used when we change variables for example from x to u when dealing with a double integral, i really want to know why because the teacher is just spoon feeding us
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what can cosx-sinx be rewritten as?
proof?
proof?
yeah
i'd work with the right hand side
just rewrite cotg in terms of sin and cos
unless you have special instructions to work with the left hand side
I guess I could try
left hand side is doable as well its just cosx-sinx isnt really a known identity
which side would u prefer to work with
left
i was thinking multiply with the denominator but im honestly not entirely sure how to do that or if I can
we can divide the numerator and denominator by the same thing and the identity stays equal
lets start with the numerator
what comes to mind so that it becomes as the right hand side's numerator
somehow make it cosx/sinx
/sinx
yea
and if we divide the numerator by sinx, we have to do the same for the denominator
so the numerator is fine
denominator is cosx-sinx/sinx
use brackets
(cosx-sin)/sinx
but yeah
can we separate that fraction as cosx/sinx - sinx/sinx ?
@eager coral Has your question been resolved?
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noice
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I’m afraid of failing math
What?
@lusty dock Has your question been resolved?
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could you technically call a cylinder a square just because it could be turned into a square and two circles as 2D shapes? my friend is arguing for this and it doesn't make sense to me.
@red relic Has your question been resolved?
cylinder is 3-dimensional
square is 2-dimensional
you can't call a 2-dimensjonal figure a 3-dimensjonal figure
she's saying that because a cylinder (or pipe)'s "original form" is a square, it is technically a circular square.
or that because a square can be folded into a cylinder, a cylinder is a circular square
well then all kinds of other 3-dimensional figures would be squares
I said this, but the examples I gave would be composed of multiple squares, whereas a cylinder only one
she shot it down on that basis
she used a square piece of paper as an example. if you rolled it up you could make it a cylinder, but by letting it go it would revert to a square
@red relic Has your question been resolved?
@red relic Has your question been resolved?
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in P(n) the sum goes to n+1
so supposing P(k), you know something about the sum that goes from 1 to k+1
i know that 1+1=2
yes, so if you're trying to prove P(k+1) using P(k), you want to know something about the sum that goes from 1 to k+2
to do that, put the "k+2" term aside
now you got the sum that goes from 1 to k+1
that's given by P(k)
we use it
so now k*2^(k+2) + 2
- the "k+2" term we set aside
@ocean pier Has your question been resolved?
Can someone please give me tips on how to be better at maths specifically geometry
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Let $f : X \rightarrow Y$ be a morphism of algebraic curves (one-dimensional integral separated schemes of finite type over a field $k$, not necessarily algebraically closed). How do we construct regular projective curves $X'$ and $Y'$, and a morphism $f' : X' \rightarrow Y'$ such that $f'$ and $f$ are birationally equivalent?
DavidL1450
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Am I correct with this one?
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Another question
I went from that to h'(x)=f'(2x+1) (2)
then I have legit no idea how to get f'(3)
<@&286206848099549185>
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I went from that to h'(x)=f'(2x+1) (2)
then I have legit no idea how to get f'(3)
@wet holly Has your question been resolved?
to find h'(x) we can use chain rule
let u = g(x) and let y = f(g(x)) = f(u)
h'(x) = du/dx * dy/du
= g'(x) * f'(g(x))
so h'(1) = g'(1)f'(g(1))
= 2f'(3)
= and to find f'(3) you need to find the gradient of the line that connects (1,4) and (4,-2)
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Its visible that 2 components of Fg are Fgx and Fgy (In the book the axis are diffrent from this pic where x is along the ramp) but to find Fgx is tricky how the trig works because its not similar to the normal cirlce trig.
@neon iron Has your question been resolved?
<@&286206848099549185>
Its visible that 2 components of Fg are Fgx and Fgy (In the book the axis are diffrent from this pic where x is along the ramp) but to find Fgx is tricky how the trig works because its not similar to the normal cirlce trig.
hmm
oh it's mgcos(theta)
it nicely checks out 😄 (mgcos(theta)^2 + mgsin(theta)^2)) =mg
Yeah but visualy how to understand it?
Its cos(60grade)
Why bot sin60 grade?)
Whos stops me?
it's just how the angles add up, we have two related right angle triangles being made from the forces, one of Fg and the other from Fgy
so when you're calculating Fgy, we need to reverse which trig function we use because now our "y" is adjecent rather than opposite to our theta
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What am I doing wrong while integrating this? The cos(4x) doesn't cancel out
poor choice of u
what would have been better for u?
the sin(4x) should make it obvious outside
so u=sin(4x)? im a little confused, what made you think that was the logical pick? I just took the biggest mess and set that as u
no
notice how the sin(4x) cancels with your original u sub, but it brings along the unwanted cos
any ideas how to kick cos out like a social reject
honestly, not really besides setting 2sin(4x) as u, and im not sure if htat would work
yes
so maybe try using cos somewhere in your u sub
but not the entire 1 + asd;lfjdsal'fgasjdg'lidsuga['sop
ok i will try that
good man
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what is the answer
The one you get when you compute the sum
how to do it
review summation notation
you add each term with each terms x value increasing by 1 each time
starting from 1 and ending at 5
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in the standard form of Ax+By+C=0, is there any convention that A has to be positive?
@devout fable Has your question been resolved?
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how tf do i draw these curves
i cant do it
What do you mean by draw? Haven't you already drawn it
thats the prof's
i cant draw it on paper
it's wrong
So you are giving a piece-wise function and have to draw it on paper?
yes
i cant draw the damn curves
like how do i even do that
Just choose some point on the interval and then plug it into the function and then connect the point
it dont work bro 😭
like i know what to do
it dont work
Why? For these kinds of sketch questions, you only need to maintain the general shape of a function and be careful about endpoints (whether the interval is open or closed)
(I shall also ask what the context behind this question, if any, is? Have you been asked something in particular?)
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when you work out the brackets, how does the minus in front of Beta 1 hat, turn into a plus sign
- * - = +
What minus, don’t you just multiply with the epsilon Xi thing
-(-b hat)
Oh you multiply with the minus in front of the brackets?
i think so
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This probably makes me look stupid but I really can’t get my head around this
So it’s just b-a??
Hang on I’m trying to get my brain around this
So for the next one, if n=2 so I’d substitute the last term into the equation? (B-3a)
yes
So like that?
yep
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For this question, I’m not sure what my next step is. I tried getting all into one side and I got a x^4 so unsure of what to do
Can you show what you mean by you got x^4
It’s only 3 marks so there must be something I should do
I was about to say that, it’s in my notes when the question was gone through
But I’m not sure how to use that
x >= 0
oops
I can find out the intersection
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if you take a divisor d, it generates the subgroup {d,2d,3d,...}
the exercise is asking you to take one of those subgroups
(so one of those divisors)
and write the operation table
of the generated subgroup
so just pick a number and add it over and over till you hit the max that is under 60?
Z_60 = <30>
{ 0, 30 }
and then write the operation table
but yes these are the only two elements in that subgroup
https://math.stackexchange.com/questions/2168385/cayley-table-of-mathbbz-5
this is what you need to do
cool looks good
the multiplicative group of integers mod 60
is the subset of Z_60
with elements that are invertible (by multiplication)
59 is invertible because 59 * 59 = 1
20 is not invertible because 20 * x is never 1 in Z_60
59 * 59 = 1?
in Z_60
-some multiple of 60
until you are in the 0-59 range?
yes
there are easier ways to see why 59 * 59 in Z_60 but
59 is invertible
while for example 20 isn't
maybe definition 11.4.17 would be worth looking at if the question asks for it
is there some other part?
no, you have to get rid of those numbers actually
the elements of the multiplicative group are precisely those that share no common factor with 60
those that are coprime
yeah if you have taken elementary number theory this will be super familiar
that say there is no solution to $10k \equiv 1 \pmod {60}$
cause that implies $10k = 60m + 1$ for $k, m \in \mathbb Z$ and now look at divisibility by $10$ on both sides
south's secret twin brother
in 0 - 59
that's how you reason that you don't want the divisors of 60
and anything else is possible
(by the Euclidean algorithm, cause the gcd will be 1)
ok
{ 1, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 49, 53, 59 }
i gtg to class
all prime numbers + 1 and 49, nice
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Hey I'm working through some elementary number theory problems about divisibility and want to prove (or disprove) the following:
$a | (b +c) \implies a | b \lor a | c$
texaspb
i don't see how I can go from b + c = ax for some integer x
I mean i tried to find counter examples but idk
for ex
5 | 15 + 5 => 5 | 15 or 5|5
but
5 | 13 + 7
but 5 does not divide neither 13 or 7
yeah or 2 | 7+ 9
yeah
you disproved it
o
oh
lol
true iguess
found a counterexample dur
sorry i'm kinda slow today
thansk!! ❤️
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prove that if (not iff, i'll do it later) n>9, then 2^n > n^3
!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
induction?
induction?
yes
so where you stuck at?
hlo?
Assume it to be true for n = k
2^k > k^3
2^(k+1) > 2k^3
and 2k^3 > k^3
wait
but... how
lemme think
is using derivatives to prove that allowed for you @neon iron ?
k>9
1/9 > 1/k
10/9 > (1 + 1/k)
(10/9)^3 > (1+ 1/k)^3
oh well, woulda been way easier then
its a roundabout way
But I imagine there to be a more direct way
hold on, is the original correct
Assume k >=10
2> (10/9)^3 > ( (k+1)/k )^3
(10/9)^3 is approx 1.37
2^k > k^3
2^(k+1) > 2k^3
Now let's compare 2k^3 and (k+1)^3
Find the answer to this ineq, -> 2k^3 > (k+1)^3
wolfram alpha says 2k^3 > (k+1)^3 for k> 3.84 (approx)
since this will be true for k>9
k(k^2)>9k^2
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natural numbers?
it is valid
happens
@neon iron Has your question been resolved?
what all is allowed
for you
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assume 2^n > n^3 ( base case 9) 2^(n+1) = 2^n *2 > 2 x n^3 , so all you have to do is prove that 2x n^3 > (n+1)^3 => 2> (1+1/n)^3 => (1+1/n)< cuberoot(2) , cube root of (2) ~1.26, ( 1+1/9) = 1.1111 , so for n>= 9 we have (1+1/n) <= (1+1/9) <cube root(3) and u are done
try that
i've done it
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Can I please have some guidance on this
do you know how to invert functions
I dont
Alright
if you have y = f(x) all you need to do is replace the x and y, so x = f(y), and then solve for y
so the X's turn into Y's?
yes and vice versa
Let's take an example
y = x²+2
Now swap x and y
x = y²+2
Find y in terms of x
x-2 = y²
√(x-2) = y
So f`(x) = √(x-2) - this is inverse of f(x)```

Yes?
y = x²+2
If we swap x and y it will become
x = y²+2
I am working as a software engineer, my school days are over

Good luck
You can proceed with your original question now
I hope
Nooooo, that was an example I had given
😅
To help you understand inverse
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I don't really understand the point of limits, as example this one here. I understand that to solve it I would need to refactor it and in that way find out the answer, but what is really the difference between a normal polynomial and one where we have lim before? Is the only difference that when we say P(x) = y that y is the actual answer meanwhile that when x goes towards 2 that the output y goes towards that number?
Do you know what is the definition of derivative ?
not really, in the book we first get to learn about limits before deriviation
for this one you can’t directly make x=2
Ic
Do you know l'hôpital ?
i just quickly checked it out and i think so, we didn't have that name in the book but it told us that it can decide values for unlimited equations like 0/0 and infinity/infinity
so im really new to limits, but from what i can tell in the example i gave you is that p(2) is a factor in both the denominator and numerator making it 3(x-2)(x+2)/(x-2)
then just simplify
I did so eventually i came to
3(x+2)
we still got x->2
replace x with 2
Not always tho
12 is the correct answer, but my question is really what the big difference is between simplifying this and a normal polynomial? Is the key difference that limits show you an indication of what y could be if x goes towards 2 in this case?
so if x -> 2, y goes towards 12, but is not 12
Wdym by normal polynomial ?
for example P(x) = x^2+4x-4, we put in P(2) and get a value for y
Don't know if that is a correct second degree equation, but to get the idea, we put in x, get out y
Yes
However limits
yes , it depends if it contains an indeterminate form after doing the calculations
what is the point, what does it tell us/do?
That limits is a trouble iff there is no continuity
Limits are used to check the behavior of a function at a certain point
so as I said in that case, in the example i gave when x -> 2, y -> 12, but is not 12?
For the limit definition we check the behavior of the function as it gets closer and closer to 2
but when we write x=2 the function is not defined at x=2
so we use limits to see how a function behaves at some point
so in that case, does that mean that the domain is Dv = R \ {2}
Yep
But using limits we could see how the function will behave at x=2
Alright so, I tried to visualise it, but here comes some confusion with, as I see that when x = 2, y = 12. However when x = 2 that means the fraction would become 0/0
yep but here it says discontinuity
so the function is not defined at x=2
In the original form you can't calculate x = 2 but you can transform it such that x = 2 became something doable
Removing discontinuity
hm alright, so with a 'normal' polynomial we can say that when input is x, y is the output. but with limits we can check the behavior of a function when it gets close to x, but it can't be x thus Dv = R \ {x}
did i get that correct?
yep but another definition for limits check values closer to what value x approaches like
x->1.99
x->1.9999
x->1.999999 so on
Or
x->2.000001
x->2.0001
x->2.01
as checking these values gets closer and closer to 2 and we can understand that the y values are approaching 12
right, so limits are basically used to check the behavior of a function when it closes towards x, so in my example indeed we can understand that when x goes towards 2 that y goes towards 12, but wont ever become 12 as that would become infinity
you can’t say infinity but yea
if we would put in 2 as x in the function i gave as example that would become 0/0, basically infinity right?
or did i get that wrong
not really
0/0 is an indeterminate form meaning the value of it exists it’s just we can’t determine what value is it
It could be 4 could be 35.72 could be infinity
But we can’t determine a specific value for it
ah, kind of like imaginary numbers?
at least imaginary are specified as i but not for 0/0
You check it using another function you could see y approach a completely different value
i see, that clears a lot up! so to summarize, limits basically help us tell what value y approaches when x goes towards 2 (in my example), but when it becomes 0/0 we know that Dv = R \ {2} since it would become an indeterminate form
Yep can I give you another limit with same idea/process
?
yeah if you'd have time for it, i'd appreciate it
lim x^2-9/(x-3)
x->3
so that would simplify to (x-3)(x+3)/(x-3) = x+3 = 3+3 = 6
Yep but ofc the original function doesn’t have 3 in the domain
as you go on it’ll get harder either using other algebraic processes like difference of cubes multiplying by conjugate so on
I see, so to solve them we would have to find out what value of x makes the function 0/0?
Because in class today we also got an example of when the numerator was above 0, and the denominator was 0, that became quite hard
Sometimes some function won’t yield this indeterminate forms
Like 0^0 for example
Or sometimes won’t give an indeterminate form like
1/x when x approaches 0
But you’ll come to these cases later in limits
I understand, well thanks for at least making me understand what really the function of limits are ^^
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Help! (Calc 3) My professor asked us to use differentials to estimate the maximum error of Kirchhoff’s law.
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Hi, i need to find the lowest common divisor between 3(X+1), (X+1) and (X-1)(X+1).
Wolfram alpha isn't really helping with it and i'm unsure about remembering how to do it, i've gotten 3(x+1)(x-1) but i've got the feeling it is wrong, if someone could also help me understand Lowest Common Divisor again it'd be really helpful for future reference
that’s not a divisor of X+1?
i think you're a bit confused, lowest common divisor isn't a thing
oh, is it lowest common denominator maybe? i knew the term in another language and tried looking it up
you mean greatest common divisor
the lowest would always be a constant
are you sure you don’t mean lowest common multiple
context should help, let me get the problem i'm solving
trying to find a denominator to use for all 3 of these
checking my notes rn and it actually is the Greatest Common Divisor, i'm struggling to apply it with this
common denominator
hmm ok well the terminology is a bit confusing but 3(x+1)(x-1) is indeed what you want for a common denominator
i see, i know i wasn't very helpful in bringing up my issue, will try to present it better next time and i just wanted to make sure i was on the right track
i don’t think that’s what you want?
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I am having trouble reading the handwriting. What is the generic name for this Unit in Calculus?
the specific topic covered in the picture seems to be quadric surfaces
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what is the terminal point of 17 pi
what in
unit circle
-1,0
which is what i put
but google is telling me i’m wrong
what did u google
googles stupid
was it gemini
google and gemini is a bit different
don’t trust ai sir
gemini always pops up on my google searches
told ya
at the very top
that occasionally trend on twitter
POKE
so it is -1,0?
don blam me
lemme seee what the ai is saying again
maybe i’m dyslexic
wouldn’t be the first time
dont do ittttttt
yo what starter pokémon did you pick back in the day
mew
nah i’m talking charmander, squirtle, or bulbasaur
you seem like the bulbasaur type
charmander ftw
dissing me
indeed
oh so uhhh
same bro
lol
am i wrong
why do you trust ai
no
i dont TRUST ai
then why do you question whether you’re wrong
why do u trust this guy
i just have a lot of self doubt so id prob second guess myself when ai says im wrong
its ok
cj and i go way back
do we...?
dont trust @agile harness but trust me. id say you are right
yea a whole 8 minutes
"Since a whole number of rotations always end at the starting point (1, 0), the terminal point of 17π is also (1, 0)."
the correct thing to say would be
lol
yo cj
hm
what was your starter pokémon
ughhh
you were too young huh
it always stressed me out because they were all so cute
idk what was it red?
i think i usually picked charmander
i was like 4-5
or Squirtle
pokémon red
idk what that is
hmm
hmm
well it was some interactive thing where you could type "up" or "down"
and the whole community eventually beat it
used to play at daycare back in the early 2010s
how old are you?
18
this is clearly not math anymore
^
which ones?
anything fun like real analysis or linear algebra?
differential equations, intro to higher math which is like a proof writing course, multivariable calc, and a probability course
i already took linear algebra over the summer
i take real analysis in the spring
indeed
lucky lucky boi
how
real analysis fun?
Yes
you’re in alegbra 2 or some shit
looks very fun imo
pre calc
but im bored outta my mind
have you ever seen it
yeah
looks like a new language
anywho
i dont wanna be in precalc rn
you can’t skip fundamentals
like half the kids in my class dont know how to factor
yea the basics
There are like 3 important things in precalc everything else is just review of alg2
you’ll be lost in further math classes if you haven’t mastered this stuff
such as?
Limits?
math is cumulative
to a certain extent
Was it wrong of me to skip pre algebra because i tested out of it?
I wouldnt say so
but you don’t know precalc that well
Well really, what exactly IS precalc?
if the higher stuff is appealing to you you should self study
Im working on it
ive been liking essence of calc and pauls online notes
basically all the algebra you need for calculus
mhm... All algebra which is either trivial and or already taught?
not exactly
Precalc just seems like a lame excuse to give students a year before calc
it’s needed
But you havent really given any specific examples of what is important in pre calc
trivial
already taught
have you ever read a precalc book
you asked what the terminal point of 17 pi was
Limits?
you’re calling these things trivial
What does that have to do with AI disagreeing with me and asking for reassurance
I would argue limits are pretty trivial
yet you were confused about the terminal point of 17pi
i think so, but i’m not sure you can say that atm
why would you need ai if it was trivial
🤔
Did i say the unit circle was trivial?
I didnt mean to if so
a concept which is easier
According to you..?
the unit circle is taught in early algebra for a reason
It isnt where i live
probably due to how fucked up the state is but oh well
W florida am i right
anyways
the point is
i feel like im kinda snoozing
I wish i could take like half a year where they taught the really important stuff instead of spending weeks on how to factor again
so self study
you just said you’re not using any books
I cant afford a textbook
essence of calc isn’t self studying
that’s just a nice video series
there’s no theory to it really
just gives some intuition
Its prob the best im gonna get other then pauls online notes which ive also been reading
Some notes do both
Start with a question which begs the iddea of a certain concept
walk through it
be able to apply it later
them providing examples of solving problems isn’t the same
Why not?
Part of math is patern recognition
^
Watch a couple of problems
math isn’t a spectator sport
you have to solve the problem
I think i might just uhhh
Ima ask one of my rich friends to buy me the textbook for my b day
Also
I also think you get some benefit in first understanding why something works
once you understand the WHY then you can learn to apply it
who said you don’t
there’s a reason why textbooks put the exercises at the end of the chapter
dang knief