#help-26

1 messages · Page 186 of 1

buoyant horizon
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we have dt/dx and dy/dt

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we can multiply these two

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according to your book

frank lodge
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yea

buoyant horizon
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$\frac{\dd{y}}{\dd{x}}=\frac{\dd{t}}{\dd{x}}\times\frac{\dd{y}}{\dd{t}}=\frac{1}{2\sqrt{x}}\times-\sin{\sqrt{x}}$

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ee

thorny flameBOT
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@buoyant horizon

buoyant horizon
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right?

frank lodge
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yess

buoyant horizon
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this gives $\frac{-\sin{\sqrt{x}}}{2\sqrt{x}}$

thorny flameBOT
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@buoyant horizon

buoyant horizon
#

Now in theory, you should've been done

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but the book goes an extra step further

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Do you recall:

$\sin^2\theta+\cos^2\theta=1$

thorny flameBOT
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@buoyant horizon

frank lodge
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sorry

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😭

buoyant horizon
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we got dy/dt as -sin(root x), right?

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we just multiply the two diffs we did

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to get the answer

frank lodge
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ah okay

buoyant horizon
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alright

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now

frank lodge
buoyant horizon
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alright

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now

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can i do this:

$\sin^2\theta=1-\cos^2\theta\implies \sin\theta=\sqrt{1-\cos^2\theta}$

thorny flameBOT
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@buoyant horizon

frank lodge
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ohh okay

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i still have one confusion tho 😭

buoyant horizon
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which?

frank lodge
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i just asked u abt it and checked my book but i really can’t seem to get it

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wait

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here for arccos they took -1/sint but u didn’t 😭 why so (i’m slow as hell)

buoyant horizon
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let's go back to the very first step

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When we did this, did you see that we get a cos on the right, not arccos

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We changed the function we want to diff into cos

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Because well x = (arccos y)² is harder to differentiate when written in that way

buoyant horizon
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We got y = cos(√x)

frank lodge
buoyant horizon
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Y is a function of x with a cos, not an arccos

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dy/dx means "differentiation of y with respect to x"

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after you isolate y

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you need to see what the new function is

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in this case it's cos

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that's why I used d(cos(t))/dt = -sin t

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does this clear it up?

frank lodge
buoyant horizon
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np

buoyant horizon
frank lodge
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yeah

buoyant horizon
thorny flameBOT
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@buoyant horizon

buoyant horizon
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right?

frank lodge
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yeah right

buoyant horizon
frank lodge
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yeah it’s the same expression fishthonk

buoyant horizon
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using the arccos formula in ur book

frank lodge
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would appreciate it 🥲

buoyant horizon
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alright

frank lodge
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im sorry bro i’m actually very slow at understanding

buoyant horizon
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now notice that you havex on the left

frank lodge
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yea

buoyant horizon
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so if you differentiate both sides, you write dx/dy, not dy/dx right?

frank lodge
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yeah right

buoyant horizon
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alright, so

frank lodge
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OHHHHHHH

buoyant horizon
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going by the book method

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Since we have a function squared, we can let t = arccos (y)

frank lodge
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wait…i just realized sometjing

buoyant horizon
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what is it

frank lodge
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or maybe i’m wrong…wait continue maybe you’ll mention it while explaining

buoyant horizon
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lol

frank lodge
buoyant horizon
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so

buoyant horizon
frank lodge
buoyant horizon
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so

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When you had, in the example, arccos(x^2)

frank lodge
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like we let the squared function be t?

buoyant horizon
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You let the "inside" thing as t, right?

frank lodge
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to simplify it

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yes

buoyant horizon
buoyant horizon
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we have arccos y "inside" a square

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so we let t = arccos(y)

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$\frac{\dd{t}}{\dd{y}}=-\frac{1}{\sqrt{1-y^2}}$

thorny flameBOT
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@buoyant horizon

buoyant horizon
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right?

frank lodge
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yea

buoyant horizon
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Now we have dt/dy

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We will need to find dx/dt

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Now, $x=t^2\implies \frac{\dd{x}}{\dd{t}}=2t=2\arccos{y}$

frank lodge
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alr

thorny flameBOT
#

@buoyant horizon

buoyant horizon
#

Now we multiply these two

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$\frac{\dd{x}}{\dd{y}}=\frac{\dd{x}}{\dd{t}}\times\frac{\dd{t}}{\dd{y}}=2\arccos y \cdot \frac{-1}{\sqrt{1-y^2}}$

thorny flameBOT
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@buoyant horizon

buoyant horizon
#

right?

frank lodge
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yes

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why not just 2t tho

buoyant horizon
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Now, we have dx/dy, but we need dy/dx

buoyant horizon
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we gotta get rid of it in the answer

frank lodge
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alr

buoyant horizon
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when you solved the example, you substituted t back to x^2, right?

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thats what i did here

frank lodge
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oh yeah

buoyant horizon
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This gives

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$\frac{\dd{y}}{\dd{x}}=-\frac{\sqrt{1-y^2}}{2\arccos y}$

thorny flameBOT
#

@buoyant horizon

buoyant horizon
#

Right?

frank lodge
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yeah

buoyant horizon
#

Now, we need to get rid of the y's

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since the answer expects us to have everything in terms of x

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to get rid of the $y^2$:

$x=(\arccos y)^2\implies \sqrt{x}=\arccos y\implies y=\cos\sqrt{x}\implies y^2=\cos^2\sqrt{x}$

thorny flameBOT
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@buoyant horizon

buoyant horizon
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right?

frank lodge
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wait let me process this

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okay

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and then

buoyant horizon
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hmm

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we got rid of y^2

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we still have an arccosy on the bottom

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$x=(\arccos y)^2\implies \sqrt{x}=\arccos y$

thorny flameBOT
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@buoyant horizon

buoyant horizon
#

right?

frank lodge
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yess

buoyant horizon
#

so we got rid of y's

buoyant horizon
#

you get the same expression

frank lodge
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ohhhhh

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true

buoyant horizon
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real

frank lodge
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😭😭 neat work

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i wanna save this explanation somewhere so i can comeback to it 😭 i’ll copy the link to one of ur messages and save it 💀

buoyant horizon
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good

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ah wait

frank lodge
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yesss

buoyant horizon
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i think this channel gets dissolved after you mark your question as done

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im not sure

frank lodge
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it gets used by other ppl but the previous msgs will still remain in it

buoyant horizon
#

Ah

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alright

frank lodge
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actially no

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😭

buoyant horizon
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ee

frank lodge
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i’ll just screenrecord

buoyant horizon
#

alr

frank lodge
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okay got it

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tysm bro 😭

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bye ✌️

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.close

topaz sinewBOT
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earnest apex
topaz sinewBOT
earnest apex
#

Is this an LDE?

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okay it is...

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damn

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.close

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earnest apex
#

yo how do I do this now 😭

topaz sinewBOT
acoustic tangle
#

Consider substituting for x+y

glossy nymph
#

Let u = x+y+2

then u' = y'-1 then u' = u^2+1

earnest apex
acoustic tangle
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No

earnest apex
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so do I sub (x+Y) as v

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and continue?

acoustic tangle
#

Right

earnest apex
#

tysm

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.close

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earnest apex
#

.reopen

topaz sinewBOT
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earnest apex
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@acoustic tangle sorry to disturb

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will this be the final answer

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it's given that for x = 0 y = -2

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so const = 0

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,w √3 - pi/3 - 2

neon iron
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oh

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nvm

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its right

earnest apex
acoustic tangle
#

You could check by just plugging your solution into the original equation

earnest apex
#

i think it fits

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thank you all!

#

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white grotto
#

i have a question about the jabcobian and why is it used when we change variables for example from x to u when dealing with a double integral, i really want to know why because the teacher is just spoon feeding us

white grotto
#

<@&286206848099549185>

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please help

topaz sinewBOT
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@white grotto Has your question been resolved?

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eager coral
#

what can cosx-sinx be rewritten as?

topaz sinewBOT
rapid lake
#

proof?

eager coral
#

proof?

rapid lake
#

is it a trig proof

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identity

eager coral
#

yeah

rapid lake
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just rewrite cotg in terms of sin and cos

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unless you have special instructions to work with the left hand side

eager coral
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I guess I could try

rapid lake
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left hand side is doable as well its just cosx-sinx isnt really a known identity

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which side would u prefer to work with

eager coral
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left

rapid lake
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alright

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do you see anything you can do

eager coral
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i was thinking multiply with the denominator but im honestly not entirely sure how to do that or if I can

rapid lake
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we can divide the numerator and denominator by the same thing and the identity stays equal

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lets start with the numerator

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what comes to mind so that it becomes as the right hand side's numerator

eager coral
#

somehow make it cosx/sinx

rapid lake
#

yea

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from the LHS numerator, we have cosx

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what is it missing

eager coral
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/sinx

rapid lake
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yea

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and if we divide the numerator by sinx, we have to do the same for the denominator

eager coral
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so the numerator is fine

denominator is cosx-sinx/sinx

rapid lake
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use brackets

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(cosx-sin)/sinx

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but yeah

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can we separate that fraction as cosx/sinx - sinx/sinx ?

eager coral
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you can do that?

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oh because the denominator is thee same

rapid lake
#

yea

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its the same thing

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can you finish by yourself now

eager coral
#

yeah

#

alr alr thank you

topaz sinewBOT
#

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verbal shadow
#

noice

topaz sinewBOT
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lusty dock
#

I’m afraid of failing math

topaz sinewBOT
lusty dock
#

What?

topaz sinewBOT
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@lusty dock Has your question been resolved?

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red relic
#

could you technically call a cylinder a square just because it could be turned into a square and two circles as 2D shapes? my friend is arguing for this and it doesn't make sense to me.

topaz sinewBOT
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graceful wolf
red relic
#

or that because a square can be folded into a cylinder, a cylinder is a circular square

graceful wolf
#

well then all kinds of other 3-dimensional figures would be squares

red relic
#

she shot it down on that basis

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she used a square piece of paper as an example. if you rolled it up you could make it a cylinder, but by letting it go it would revert to a square

topaz sinewBOT
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@red relic Has your question been resolved?

topaz sinewBOT
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@red relic Has your question been resolved?

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eager compass
#

could you shiw the whole induction? like what you wanna prove?

#

yes

opal vault
#

in P(n) the sum goes to n+1

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so supposing P(k), you know something about the sum that goes from 1 to k+1

opal vault
#

to do that, put the "k+2" term aside

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now you got the sum that goes from 1 to k+1

opal vault
#

we use it

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so now k*2^(k+2) + 2

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  • the "k+2" term we set aside
ocean pier
#

.

#

.

#

.

topaz sinewBOT
#

@ocean pier Has your question been resolved?

sweet gale
#

Can someone please give me tips on how to be better at maths specifically geometry

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dense plover
#

Let $f : X \rightarrow Y$ be a morphism of algebraic curves (one-dimensional integral separated schemes of finite type over a field $k$, not necessarily algebraically closed). How do we construct regular projective curves $X'$ and $Y'$, and a morphism $f' : X' \rightarrow Y'$ such that $f'$ and $f$ are birationally equivalent?

thorny flameBOT
#

DavidL1450

topaz sinewBOT
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wet holly
#

Am I correct with this one?

topaz sinewBOT
wet holly
#

As point a has a sharp turn making it un-differntiable

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but is continous

neon iron
#

yeah I think that would be correct

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(though I am not 100% sure)

wet holly
#

ok thanks

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wet holly
#

Another question

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I went from that to h'(x)=f'(2x+1) (2)

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then I have legit no idea how to get f'(3)

#

<@&286206848099549185>

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wet holly
topaz sinewBOT
wet holly
#

I went from that to h'(x)=f'(2x+1) (2)
then I have legit no idea how to get f'(3)

topaz sinewBOT
#

@wet holly Has your question been resolved?

plucky elbow
#

to find h'(x) we can use chain rule

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let u = g(x) and let y = f(g(x)) = f(u)

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h'(x) = du/dx * dy/du

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= g'(x) * f'(g(x))

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so h'(1) = g'(1)f'(g(1))

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= 2f'(3)

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= and to find f'(3) you need to find the gradient of the line that connects (1,4) and (4,-2)

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neon iron
#

Its visible that 2 components of Fg are Fgx and Fgy (In the book the axis are diffrent from this pic where x is along the ramp) but to find Fgx is tricky how the trig works because its not similar to the normal cirlce trig.

neon iron
#

<@&286206848099549185>

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neon iron
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<@&286206848099549185>

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#

neon iron
#

Its visible that 2 components of Fg are Fgx and Fgy (In the book the axis are diffrent from this pic where x is along the ramp) but to find Fgx is tricky how the trig works because its not similar to the normal cirlce trig.

arctic hawk
#

hmm

arctic hawk
#

it nicely checks out 😄 (mgcos(theta)^2 + mgsin(theta)^2)) =mg

neon iron
#

Yeah but visualy how to understand it?

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Its cos(60grade)

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Why bot sin60 grade?)

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Whos stops me?

velvet hound
#

it's just how the angles add up, we have two related right angle triangles being made from the forces, one of Fg and the other from Fgy

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so when you're calculating Fgy, we need to reverse which trig function we use because now our "y" is adjecent rather than opposite to our theta

topaz sinewBOT
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upbeat minnow
#

What am I doing wrong while integrating this? The cos(4x) doesn't cancel out

agile harness
#

poor choice of u

upbeat minnow
agile harness
#

the sin(4x) should make it obvious outside

upbeat minnow
agile harness
#

no

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notice how the sin(4x) cancels with your original u sub, but it brings along the unwanted cos

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any ideas how to kick cos out like a social reject

upbeat minnow
agile harness
#

brother

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the cos brings along the sin as du

upbeat minnow
#

yes

agile harness
#

so maybe try using cos somewhere in your u sub

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but not the entire 1 + asd;lfjdsal'fgasjdg'lidsuga['sop

upbeat minnow
#

ok i will try that

agile harness
#

good man

upbeat minnow
#

ohhhhh it worked

#

ok thank you 🙏

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signal stirrup
#

what is the answer

topaz sinewBOT
raven sparrow
#

The one you get when you compute the sum

signal stirrup
#

how to do it

agile harness
#

review summation notation

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you add each term with each terms x value increasing by 1 each time

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starting from 1 and ending at 5

signal stirrup
#

.clse

#

.close

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devout fable
#

in the standard form of Ax+By+C=0, is there any convention that A has to be positive?

topaz sinewBOT
#

@devout fable Has your question been resolved?

devout fable
#

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mystic siren
#

how tf do i draw these curves

topaz sinewBOT
mystic siren
#

i cant do it

prime flame
mystic siren
#

i cant draw it on paper

#

it's wrong

prime flame
mystic siren
#

i cant draw the damn curves

#

like how do i even do that

prime flame
#

Just choose some point on the interval and then plug it into the function and then connect the point

mystic siren
#

like i know what to do

#

it dont work

prime flame
# mystic siren it dont work

Why? For these kinds of sketch questions, you only need to maintain the general shape of a function and be careful about endpoints (whether the interval is open or closed)

vernal matrix
#

(I shall also ask what the context behind this question, if any, is? Have you been asked something in particular?)

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#

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slow tusk
#

when you work out the brackets, how does the minus in front of Beta 1 hat, turn into a plus sign

slow tusk
verbal shadow
#

-(-b hat)

slow tusk
verbal shadow
#

i think so

slow tusk
#

Ohhh i get it now

#

Thanks!

#

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near laurel
#

This probably makes me look stupid but I really can’t get my head around this

buoyant horizon
#

for the (i), you have n+1 = 2 or n = 1

#

substitute that in the definition

near laurel
#

So it’s just b-a??

buoyant horizon
#

since u_1=3

near laurel
#

Hang on I’m trying to get my brain around this

near laurel
buoyant horizon
#

yes

near laurel
near laurel
buoyant horizon
#

yep

near laurel
#

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near laurel
#

For this question, I’m not sure what my next step is. I tried getting all into one side and I got a x^4 so unsure of what to do

eager compass
near laurel
#

It’s only 3 marks so there must be something I should do

finite storm
#

i have an idea

#

the function and the inverse function must meet at line y = x

near laurel
#

But I’m not sure how to use that

finite storm
#

2x^2 - 5 = x

#

because y =x

#

then apply quadratic equation

near laurel
#

Ohh

#

And that would get me 1.85 or -1.35

finite storm
#

x >= 0

near laurel
#

Oh yea

#

So do I just ignore the

#

Inverse?

#

As in the equation for it

finite storm
#

oops

near laurel
#

Oh wait

#

Because I worked out the inverse

finite storm
near laurel
#

I can find out the intersection

finite storm
#

u can do it the other way

#

and set the inverse to x

#

same result anyway

near laurel
#

But I had to work out the inverse

#

To know the intersection

near laurel
#

.close

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#
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pliant kelp
topaz sinewBOT
pliant kelp
#
  1. { 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60 }
#

what does #2 mean?

opal vault
#

the exercise is asking you to take one of those subgroups

#

(so one of those divisors)

#

and write the operation table

#

of the generated subgroup

pliant kelp
#

Z_60 = <30>
{ 0, 30 }

smoky sparrow
#

and then write the operation table

#

but yes these are the only two elements in that subgroup

smoky sparrow
#

cool looks good

pliant kelp
#

i think i see

pliant kelp
#

what does 4 mean?

opal vault
#

the multiplicative group of integers mod 60

#

is the subset of Z_60

#

with elements that are invertible (by multiplication)

#

59 is invertible because 59 * 59 = 1

#

20 is not invertible because 20 * x is never 1 in Z_60

pliant kelp
#

59 * 59 = 1?

opal vault
opal vault
#

it's operations in Z_60

pliant kelp
#

and -60

opal vault
pliant kelp
#

until you are in the 0-59 range?

opal vault
#

there are easier ways to see why 59 * 59 in Z_60 but

#

59 is invertible

#

while for example 20 isn't

#

maybe definition 11.4.17 would be worth looking at if the question asks for it

opal vault
pliant kelp
#

no

#

so 60= 2^2 * 3 * 5

#

so i just use numbers divisible by 2,3,5

#

?

opal vault
#

the elements of the multiplicative group are precisely those that share no common factor with 60

#

those that are coprime

pliant kelp
#

ok

#

in 1-59?

#

or in the set from #1

smoky sparrow
#

yeah if you have taken elementary number theory this will be super familiar

that say there is no solution to $10k \equiv 1 \pmod {60}$

cause that implies $10k = 60m + 1$ for $k, m \in \mathbb Z$ and now look at divisibility by $10$ on both sides

thorny flameBOT
#

south's secret twin brother

opal vault
#

in 0 - 59

smoky sparrow
#

that's how you reason that you don't want the divisors of 60

#

and anything else is possible

#

(by the Euclidean algorithm, cause the gcd will be 1)

pliant kelp
#

ok

#

{ 1, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 49, 53, 59 }

#

i gtg to class

opal vault
#

all prime numbers + 1 and 49, nice

topaz sinewBOT
#

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azure dune
#

Hey I'm working through some elementary number theory problems about divisibility and want to prove (or disprove) the following:

$a | (b +c) \implies a | b \lor a | c$

thorny flameBOT
#

texaspb

azure dune
#

i don't see how I can go from b + c = ax for some integer x

long stirrup
#

it's false, you find a counterexample

#

i don't get it i guess

azure dune
#

I mean i tried to find counter examples but idk

#

for ex

#

5 | 15 + 5 => 5 | 15 or 5|5

#

but

#

5 | 13 + 7

#

but 5 does not divide neither 13 or 7

long stirrup
#

yeah or 2 | 7+ 9

azure dune
#

yeah

long stirrup
#

you disproved it

azure dune
#

o

#

oh

#

lol

#

true iguess

#

found a counterexample dur

#

sorry i'm kinda slow today

#

thansk!! ❤️

#

.close

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neon iron
#

prove that if (not iff, i'll do it later) n>9, then 2^n > n^3

silent siren
#

!status

topaz sinewBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
compact zodiac
#

induction?

neon iron
#

yes

compact zodiac
#

so where you stuck at?

limber prairie
neon iron
#

Assume it to be true for n = k
2^k > k^3
2^(k+1) > 2k^3

limber prairie
#

wait

neon iron
#

Bro

#

(k+1)^3

limber prairie
#

mb

#

ye

neon iron
limber prairie
#

lemme think

fresh ridge
#

is using derivatives to prove that allowed for you @neon iron ?

neon iron
#

no

#

lol

limber prairie
#

k>9
1/9 > 1/k
10/9 > (1 + 1/k)
(10/9)^3 > (1+ 1/k)^3

fresh ridge
limber prairie
#

its a roundabout way

neon iron
#

certainly

#

I think we have to prove two inequalities

#

k can't be 9

limber prairie
#

remove equality

#

I'll edit those

limber prairie
fresh ridge
#

hold on, is the original correct

odd forge
#

Assume k >=10

limber prairie
fresh ridge
#

because from what i know 2^x>x^3 till 1.37 (approximately)

#

then x^3 >2^x

limber prairie
fresh ridge
#

nvm

#

right after 9 the statements true

#

mb

neon iron
#

2^k > k^3
2^(k+1) > 2k^3

Now let's compare 2k^3 and (k+1)^3
Find the answer to this ineq, -> 2k^3 > (k+1)^3

odd forge
#

k?9

#

k>9

neon iron
#

wolfram alpha says 2k^3 > (k+1)^3 for k> 3.84 (approx)

#

since this will be true for k>9

odd forge
#

k(k^2)>9k^2

neon iron
#

2^(k+1) > 2k^3 > (k+1)^3

#

I think I am done.

#

I was.

#

Maybe

#

Thanks

#

.close

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#
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neon iron
#

.reopen

topaz sinewBOT
#

neon iron
#

well

#

if 2^k > k^3 for k>9

#

then why is it not valid for 9.01?

odd forge
#

natural numbers?

neon iron
#

There wasn't written natural numbers

#

but that's the most logical assumption

#

ok

fresh ridge
odd forge
#

for natural numbers its good to assume n>=10

#

then solve

fresh ridge
#

2^9.01 would be 515.5... and 9.01^3 would be 731.4....

#

so it is valid

neon iron
#

invalid

#

lol

fresh ridge
#

oh wait nvm

#

im thinking the other way round

#

mb

neon iron
#

happens

topaz sinewBOT
#

@neon iron Has your question been resolved?

prisma coral
#

for you

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prisma coral
# neon iron happens

assume 2^n > n^3 ( base case 9) 2^(n+1) = 2^n *2 > 2 x n^3 , so all you have to do is prove that 2x n^3 > (n+1)^3 => 2> (1+1/n)^3 => (1+1/n)< cuberoot(2) , cube root of (2) ~1.26, ( 1+1/9) = 1.1111 , so for n>= 9 we have (1+1/n) <= (1+1/9) <cube root(3) and u are done

prisma coral
#

try that

neon iron
#

i've done it

prisma coral
#

k

#

.close

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hollow pumice
#

Can I please have some guidance on this

topaz sinewBOT
ionic oar
#

do you know how to invert functions

hollow pumice
#

I dont

ionic oar
#

Alright

#

if you have y = f(x) all you need to do is replace the x and y, so x = f(y), and then solve for y

hollow pumice
#

so the X's turn into Y's?

ionic oar
#

yes and vice versa

hollow pumice
#

so like

#

f(y)=1/2(e^y + e^-y)

night imp
#

Let's take an example

y = x²+2
Now swap x and y
x = y²+2
Find y in terms of x
x-2 = y²
√(x-2) = y
So f`(x) = √(x-2) - this is inverse of f(x)```
#

Yes?

#

y = x²+2
If we swap x and y it will become
x = y²+2

#

I am working as a software engineer, my school days are over

#

Good luck

#

You can proceed with your original question now

#

I hope

#

Nooooo, that was an example I had given

#

😅

night imp
topaz sinewBOT
#

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#
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distant totem
#

I don't really understand the point of limits, as example this one here. I understand that to solve it I would need to refactor it and in that way find out the answer, but what is really the difference between a normal polynomial and one where we have lim before? Is the only difference that when we say P(x) = y that y is the actual answer meanwhile that when x goes towards 2 that the output y goes towards that number?

cedar wagon
#

Do you know what is the definition of derivative ?

distant totem
raven field
cedar wagon
#

Do you know l'hôpital ?

distant totem
# cedar wagon Do you know l'hôpital ?

i just quickly checked it out and i think so, we didn't have that name in the book but it told us that it can decide values for unlimited equations like 0/0 and infinity/infinity

cedar wagon
#

Indeed

#

Here it will result as the same as derivatives definition

distant totem
#

so im really new to limits, but from what i can tell in the example i gave you is that p(2) is a factor in both the denominator and numerator making it 3(x-2)(x+2)/(x-2)

distant totem
#

I did so eventually i came to

3(x+2)

raven field
#

we still got x->2

fallow torrent
#

replace x with 2

raven field
distant totem
#

12 is the correct answer, but my question is really what the big difference is between simplifying this and a normal polynomial? Is the key difference that limits show you an indication of what y could be if x goes towards 2 in this case?

#

so if x -> 2, y goes towards 12, but is not 12

cedar wagon
#

Wdym by normal polynomial ?

distant totem
#

for example P(x) = x^2+4x-4, we put in P(2) and get a value for y

#

Don't know if that is a correct second degree equation, but to get the idea, we put in x, get out y

cedar wagon
#

Yes

distant totem
#

However limits

fallow torrent
distant totem
#

what is the point, what does it tell us/do?

cedar wagon
#

That limits is a trouble iff there is no continuity

raven field
distant totem
#

so as I said in that case, in the example i gave when x -> 2, y -> 12, but is not 12?

raven field
distant totem
#

so in that case, does that mean that the domain is Dv = R \ {2}

raven field
distant totem
#

Alright so, I tried to visualise it, but here comes some confusion with, as I see that when x = 2, y = 12. However when x = 2 that means the fraction would become 0/0

raven field
#

so the function is not defined at x=2

cedar wagon
#

In the original form you can't calculate x = 2 but you can transform it such that x = 2 became something doable

#

Removing discontinuity

distant totem
#

hm alright, so with a 'normal' polynomial we can say that when input is x, y is the output. but with limits we can check the behavior of a function when it gets close to x, but it can't be x thus Dv = R \ {x}

#

did i get that correct?

raven field
distant totem
raven field
distant totem
#

or did i get that wrong

raven field
#

It could be 4 could be 35.72 could be infinity

#

But we can’t determine a specific value for it

distant totem
#

ah, kind of like imaginary numbers?

raven field
#

You check it using another function you could see y approach a completely different value

distant totem
#

i see, that clears a lot up! so to summarize, limits basically help us tell what value y approaches when x goes towards 2 (in my example), but when it becomes 0/0 we know that Dv = R \ {2} since it would become an indeterminate form

raven field
#

?

distant totem
#

yeah if you'd have time for it, i'd appreciate it

raven field
#

lim x^2-9/(x-3)
x->3

distant totem
#

so that would simplify to (x-3)(x+3)/(x-3) = x+3 = 3+3 = 6

raven field
#

Yep but ofc the original function doesn’t have 3 in the domain

#

as you go on it’ll get harder either using other algebraic processes like difference of cubes multiplying by conjugate so on

distant totem
#

I see, so to solve them we would have to find out what value of x makes the function 0/0?

#

Because in class today we also got an example of when the numerator was above 0, and the denominator was 0, that became quite hard

raven field
#

Like 0^0 for example

#

Or sometimes won’t give an indeterminate form like
1/x when x approaches 0

#

But you’ll come to these cases later in limits

distant totem
#

I understand, well thanks for at least making me understand what really the function of limits are ^^

#

.close

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#
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river trail
#

Help! (Calc 3) My professor asked us to use differentials to estimate the maximum error of Kirchhoff’s law.

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#

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mortal bone
#

Hi, i need to find the lowest common divisor between 3(X+1), (X+1) and (X-1)(X+1).
Wolfram alpha isn't really helping with it and i'm unsure about remembering how to do it, i've gotten 3(x+1)(x-1) but i've got the feeling it is wrong, if someone could also help me understand Lowest Common Divisor again it'd be really helpful for future reference

wary tulip
#

that’s not a divisor of X+1?

craggy haven
#

i think you're a bit confused, lowest common divisor isn't a thing

mortal bone
#

oh, is it lowest common denominator maybe? i knew the term in another language and tried looking it up

lean pebble
#

you mean greatest common divisor

mortal bone
#

oh

#

yes yes

lean pebble
#

the lowest would always be a constant

wary tulip
#

are you sure you don’t mean lowest common multiple

mortal bone
#

context should help, let me get the problem i'm solving

#

trying to find a denominator to use for all 3 of these

#

checking my notes rn and it actually is the Greatest Common Divisor, i'm struggling to apply it with this

agile harness
#

common denominator

craggy haven
#

hmm ok well the terminology is a bit confusing but 3(x+1)(x-1) is indeed what you want for a common denominator

mortal bone
#

i see, i know i wasn't very helpful in bringing up my issue, will try to present it better next time and i just wanted to make sure i was on the right track

wary tulip
mortal bone
#

seems to be common denominator

#

instead of common divisor

#

.close

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#
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uneven grotto
#

I am having trouble reading the handwriting. What is the generic name for this Unit in Calculus?

sweet shard
#

multivariable calculus

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surfaces maybe

loud oasis
#

the specific topic covered in the picture seems to be quadric surfaces

topaz sinewBOT
#

@uneven grotto Has your question been resolved?

topaz sinewBOT
#
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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

ornate trellis
#

what is the terminal point of 17 pi

topaz sinewBOT
ocean terrace
#

what in

ornate trellis
#

unit circle

agile harness
#

what in

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what’s the terminal point of pi?

ornate trellis
#

which is what i put

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but google is telling me i’m wrong

ocean terrace
#

what did u google

agile harness
ornate trellis
#

“what is the terminal point of 17pi”

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it told me “0,1”

agile harness
#

was it gemini

ocean terrace
#

google and gemini is a bit different

agile harness
#

don’t trust ai sir

agile harness
ornate trellis
#

like

agile harness
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told ya

ornate trellis
#

at the very top

ocean terrace
agile harness
#

POKE

ornate trellis
#

so it is -1,0?

ocean terrace
ornate trellis
#

lemme seee what the ai is saying again

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maybe i’m dyslexic

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wouldn’t be the first time

ocean terrace
agile harness
agile harness
#

nah i’m talking charmander, squirtle, or bulbasaur

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you seem like the bulbasaur type

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charmander ftw

ocean terrace
#

dissing me

agile harness
#

indeed

ornate trellis
#

oh so uhhh

ocean terrace
ornate trellis
#

it says

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1,0

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i said -1,0

ocean terrace
#

lol

ornate trellis
#

am i wrong

agile harness
#

why do you trust ai

ocean terrace
#

no

ornate trellis
agile harness
#

then why do you question whether you’re wrong

ocean terrace
ornate trellis
#

i just have a lot of self doubt so id prob second guess myself when ai says im wrong

ocean terrace
#

its ok

agile harness
ornate trellis
ocean terrace
#

dont trust @agile harness but trust me. id say you are right

agile harness
ornate trellis
#

"Since a whole number of rotations always end at the starting point (1, 0), the terminal point of 17π is also (1, 0)."

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the correct thing to say would be

agile harness
#

bruh

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gemini thinks 17 is even

ocean terrace
#

lol

ornate trellis
#

"if its odd -1,0 if its even 1,0"

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right>

agile harness
#

yo cj

ornate trellis
#

hm

agile harness
#

what was your starter pokémon

ocean terrace
#

that could work yes

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mew

ornate trellis
agile harness
#

you were too young huh

ornate trellis
#

it always stressed me out because they were all so cute

ornate trellis
#

what game are you talking

ocean terrace
#

pokemon go

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duh

ornate trellis
#

oh

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well

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i was like

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4 when that came out

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anyways

agile harness
#

idk what was it red?

ornate trellis
#

i think i usually picked charmander

agile harness
#

i was like 4-5

ornate trellis
#

or Squirtle

ornate trellis
#

wdym

agile harness
#

pokémon red

ornate trellis
#

idk what that is

agile harness
#

hmm

ornate trellis
#

OH

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is that the one people used to play on twitch?

agile harness
#

don’t know

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i don’t watch twitch

ornate trellis
#

hmm

agile harness
#

never did

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i just played on my ds

ornate trellis
#

well it was some interactive thing where you could type "up" or "down"

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and the whole community eventually beat it

agile harness
#

used to play at daycare back in the early 2010s

ornate trellis
agile harness
#

18

ornate trellis
#

oh

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what math are u in

agile harness
#

many

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i’m taking 4 math classes

ocean terrace
#

this is clearly not math anymore

agile harness
ornate trellis
#

anything fun like real analysis or linear algebra?

agile harness
#

differential equations, intro to higher math which is like a proof writing course, multivariable calc, and a probability course

agile harness
#

i take real analysis in the spring

ornate trellis
#

lucky

agile harness
#

indeed

ornate trellis
#

lucky lucky boi

agile harness
#

how

ornate trellis
#

uhhh

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because if it were up to me

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i would perfer be learning that rn

hallow depot
ornate trellis
agile harness
#

you’re in alegbra 2 or some shit

ornate trellis
#

looks very fun imo

ornate trellis
#

but im bored outta my mind

agile harness
ornate trellis
#

looks like a new language

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anywho

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i dont wanna be in precalc rn

agile harness
#

you can’t skip fundamentals

ornate trellis
#

like half the kids in my class dont know how to factor

ornate trellis
#

In precalc?

agile harness
#

yea the basics

ornate trellis
#

There are like 3 important things in precalc everything else is just review of alg2

agile harness
#

you’ll be lost in further math classes if you haven’t mastered this stuff

agile harness
#

math is cumulative

ornate trellis
#

Was it wrong of me to skip pre algebra because i tested out of it?

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I wouldnt say so

agile harness
#

but you don’t know precalc that well

ornate trellis
agile harness
#

if the higher stuff is appealing to you you should self study

ornate trellis
#

ive been liking essence of calc and pauls online notes

agile harness
ornate trellis
agile harness
#

not exactly

ornate trellis
#

Precalc just seems like a lame excuse to give students a year before calc

agile harness
#

it’s needed

ornate trellis
agile harness
#

you go way more in depth with trig

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you go over limits

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functions

ornate trellis
ornate trellis
agile harness
#

have you ever read a precalc book

ornate trellis
#

dont intend on it either

agile harness
ornate trellis
agile harness
#

you’re calling these things trivial

ornate trellis
#

What does that have to do with AI disagreeing with me and asking for reassurance

ornate trellis
agile harness
#

yet you were confused about the terminal point of 17pi

agile harness
agile harness
#

🤔

ornate trellis
#

I didnt mean to if so

agile harness
#

a concept which is easier

ornate trellis
agile harness
#

the unit circle is taught in early algebra for a reason

ornate trellis
#

probably due to how fucked up the state is but oh well

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W florida am i right

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anyways

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the point is

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i feel like im kinda snoozing

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I wish i could take like half a year where they taught the really important stuff instead of spending weeks on how to factor again

agile harness
#

so self study

ornate trellis
#

BUT

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Unfortuanetly

agile harness
#

you just said you’re not using any books

ornate trellis
#

I cant afford a textbook

agile harness
#

essence of calc isn’t self studying

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that’s just a nice video series

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there’s no theory to it really

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just gives some intuition

ornate trellis
agile harness
#

you learn math by solving problems

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not by reading notes like a novel

ornate trellis
#

Start with a question which begs the iddea of a certain concept

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walk through it

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be able to apply it later

agile harness
#

them providing examples of solving problems isn’t the same

ornate trellis
#

Part of math is patern recognition

agile harness
ornate trellis
#

Watch a couple of problems

agile harness
#

math isn’t a spectator sport

ornate trellis
#

Understand it

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solve some

agile harness
#

you have to solve the problem

ornate trellis
#

I think i might just uhhh

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Ima ask one of my rich friends to buy me the textbook for my b day

ornate trellis
#

I also think you get some benefit in first understanding why something works

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once you understand the WHY then you can learn to apply it

agile harness
#

there’s a reason why textbooks put the exercises at the end of the chapter

ocean terrace
#

dang knief