help-26

[half edge]

congrats

u played ur self

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[nimble vault]

Can someone help me break down the following

[nimble vault]

like is this saying all the elements in the equivalence class of X maps to some element in y

[scenic flare]

looks more like set exclusion than equivalence classes to me

or is the context equivalence classes?

for the former it just means you can reduce the domain and it's still a function

if f: [0,2] -> C is a function

then f: [0,1] -> C is as well

[nimble vault]

context is equivalence classes, but we use that symbol also for set exclusion

[topaz sinew]

@nimble vault Has your question been resolved?

[topaz sinew]

@nimble vault Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[finite mortar]

For this

[finite mortar]

Would the answer just be c=1 or c=0

Oh wait

Ignore omds

The answer would be c=0, c=4?

[bitter hemlock]

what would be true about the determinant if it isn't invertible?

[finite mortar]

It equals zero?

[bitter hemlock]

yes

so you can write a quadratic equation using that then solve

[finite mortar]

Ooh i can sub it back in to check right

Out of curiosity would i always get two answers for a 2x2

[bitter hemlock]

always for what? situations where you have some random unknown as part of a random amount of entries in the matrix? i don't really know how to answer that question

[finite mortar]

Yea fair enough

[bitter hemlock]

some similarly constructed problems to this where you try the same idea, you might get a quadratic with 1 solution or no solutions

[finite mortar]

The next bit asks to find an expression for the inverse; im assuming u still do gauss Jordan just in terms of c?

Omds wait though u can just use the formula

Lmaooo i need a slap

[bitter hemlock]

https://tenor.com/view/will-smith-chris-rock-jada-pinkett-smith-oscars2022-smack-gif-25234614

[finite mortar]

LOL

Thanks

.close

[topaz sinew]

Channel closed

Closed by @finite mortar

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[knotty briar]

yo any help?

[gusty bane]

what have you tried?

[knotty briar]

well i tried to apply dalemberts formula

f(x)=u(x,0)=0

so i have an integral

[silent garden]

How dose this work

Can I send pictures of the question

[gusty bane]

check out #❓how-to-get-help

read through the instructions

[knotty briar]

is it a good idea to use dalemberts formula?

[gusty bane]

sure yeah

you have the right setup for it

[knotty briar]

so when i use it i stuck at the integral

[gusty bane]

show where you are stuck

[knotty briar]

give me a minute to write it down

so i am there

[topaz sinew]

@knotty briar Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[scenic nacelle]

How do i find the integral of the second part..? I dont know what method to use and if i learned it

[scenic nacelle]

Ive learned using long division, u substitution, basic integration, and inverse trig

[loud oasis]

you need integration by parts i believe

[scenic nacelle]

oh idk how to do that

[loud oasis]

https://www.khanacademy.org/math/ap-calculus-bc/bc-integration-new/bc-6-11/v/deriving-integration-by-parts-formula
https://www.khanacademy.org/math/ap-calculus-bc/bc-integration-new/bc-6-11/v/antiderivative-of-xcosx-using-integration-by-parts
https://tutorial.math.lamar.edu/Classes/CalcII/IntegrationByParts.aspx

[topaz sinew]

@scenic nacelle Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[barren cobalt]

nvm

idk how to do this actually

[topaz sinew]

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[neon iron]

Hi

[neon iron]

Pls help

my grd 3 brothers math

in his test

XD

[wary tulip]

[elfin chasm]

i mean

for all of these we can just start with 999 and work backward 💀

[neon iron]

HELL NO

it would take me 2 days

😭

[elfin chasm]

💀💀💀

[neon iron]

how do u doi t

[elfin chasm]

work backward from 999

[neon iron]

With less work

[magic lake]

work backward

[elfin chasm]

there is literally no work involved

[magic lake]

the answer is pretty close to 999

so it wont take u that long

[neon iron]

ohh okay ty

[elfin chasm]

you only need to check like 3 numbers

[neon iron]

thank youu

.close

[topaz sinew]

Channel closed

Closed by @rare zinc

Use .reopen if this was a mistake.

[grave gale]

@neon iron isn't there a more intelligent way?

[magic lake]

u can just find the greatest 3 number divisible by 2,3,4,5

[elfin chasm]

are these 4 individual questions or is it 1 question that must meet 4 conditions

[magic lake]

its 1 question that has to meet 4 conditions i'm pretty sure

[elfin chasm]

oh, no wonder

[magic lake]

so i mean u could just find lcm

[elfin chasm]

@neon iron nevermind dont work backward from 999

yea, find lcm of 2, 3, 4, and 5 and then subtract 1

[wary tulip]

[elfin chasm]

man i want that emoji

[neon iron]

xD

can anyone help xd

[grave gale]

write the equaations

P, Q, R

Q = 1.2P

R = 0.9P

R = aQ

solve for a

[neon iron]

Uhhhhh

how do i do that

im stupid

[grave gale]

no problem

do you know what Q is 20% more than P mean

[neon iron]

OHHH

Yea

[grave gale]

so based on that statement

[neon iron]

hmm?

[grave gale]

you know that Q is 120% of P

[neon iron]

Yes

[grave gale]

and 120% can be converted to 1.2 (see percent to decimal conversion)

[neon iron]

0.81 for r?

81 right

81%

Wait 19%

right

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[amber star]

Hey all, can someone please help me get a better understanding of the proof here? In my case I need to show that $F[a] = F[a^2]$ which I think is the same?
https://math.stackexchange.com/questions/1393510/prove-that-e-f-alpha2

So I think $a^2\in F[a]$ since F is a field, therefore we have $F[a^2] \subseteq F[a]$\

Now the next part is ok but then $x^2-a^2 \in F[a^2][x]$ because this set contains all the polynomials which $a^2$ is root of? therefore we get that the extension is indeed smaller equal 2 (degree of that polynomial) and thus it must be odd so 1.

is it right? wrong?

[thorny flame]

mtr123

[topaz sinew]

@amber star Has your question been resolved?

[topaz sinew]

@amber star Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cerulean sparrow]

For this question i manage to get the answer but like my answer is negative while the textbook answer is positive. Is it the textbook error? Or is there some mathematical thing going on? Or did I do it wrongly? Pls help and explain. This is qudratic equations btw

[restive inlet]

you did it incorrectly

you messed up the sign here

[cerulean sparrow]

OHH YAAAA

THANKS 🫶🏼🫶🏼

.close

[topaz sinew]

Channel closed

Closed by @cerulean sparrow

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[upper gale]

hello, i have an exam tomorrow and if someone could help me to understand how to read the graph for this question

[upper gale]

I know that i need to look up for the y

but im not sure where to look at

[glossy fable]

What limit do you want to evaluate first?

[upper gale]

x--> 11

can you help me?

<@&286206848099549185>

[hollow marlin]

To evaluate the limit of ( f(x) ) as ( x ) approaches 11, you need to consider the behavior of the function near ( x = 11 ). Based on the graph you've provided, as ( x ) approaches 11, the value of ( y ) (which is ( f(x) )) appears to approach -3. Therefore, the limit of ( f(x) ) as ( x ) approaches 11 is:

$\lim_{{x \to 11}} f(x) = -3$

Is that the answer what you're looking for???

[thorny flame]

ItzJezze

[topaz sinew]

@upper gale Has your question been resolved?

[viral skiff]

??

it doesn't approach -3 though?

like wym

[viral skiff]

there is no limit on x-> 11

as the approach from left side results in positive infinity and the approach from the right side results in negative infinity

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rocky gulch]

how would i solve sin x + cos x = 1

[rocky gulch]

i know one way is to write the coefficient of cos x as tan(pi/4)

[simple orchid]

Why is it equal to 1

[rocky gulch]

that is the equation

[simple orchid]

Is it possible?

[rocky gulch]

…

of course it is possible

for example if sin(x) = 1/2 and cos(x) = 1/2

thats one answer

[simple orchid]

sin(x) and cos(x) can never equal 1/2 at the same time

[rocky gulch]

ok then

sin x = 1/4 cos x = 3/4

[simple orchid]

I would also like to know the solution to this problem

Can you ping me when you find an answer please?

[rocky gulch]

yeah well i know the solution

[simple orchid]

Oh?

[rocky gulch]

i made this channel for a different method

do you want the answer?

[simple orchid]

Yes pls

[rocky gulch]

$\sin(x) + \cos(x) = 1$

[thorny flame]

dqvidutzul

[simple orchid]

?

[rocky gulch]

now you write cos x’s coefficient as tan(pi/4)

tan(pi/4) = 1

[simple orchid]

Why and how?

[rocky gulch]

$\sin(x) + \frac{\sin(\frac{\pi}{4})}{\cos(\frac{\pi}{4})}\cos(x) = 1$

[thorny flame]

dqvidutzul

[rocky gulch]

you write 1 as tan(pi/4)

that simple

now you multiply the whole equation by cos(pi/4)

$\sin(x)\cos(\frac{\pi}{4}) + \sin(\frac{\pi}{4})\cos(x) = \cos(\frac{\pi}{4})$

[simple orchid]

Ohhh I see

[thorny flame]

dqvidutzul

[rocky gulch]

do you notice anything suspicious

sin(x)cos(y) + sin(y)cos(x)

[simple orchid]

I understand now

Tyy

[rocky gulch]

yeah now im waiting for a different approach

sigh

.close

[topaz sinew]

Channel closed

Closed by @rocky gulch

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jade walrus]

how do i proceed with the 8th question?

[jade walrus]

I tried making variables K = (a^2 + 2a); M = (b^2 + 2b) for both the numerator and denominator and then solved the expression but that didn't really take me anywhere

(a and b represent alpha and beta respectively)

[neon iron]

dont think you need that

what is alfa and beta

values

[jade walrus]

since they're the roots of the equation above

which can be written as x^2 - px - (p + c) = 0

alpha + beta = p

alpha * beta = p + c

[neon iron]

ok so viete's

[jade walrus]

huh?

[neon iron]

wait

its wrong actually

your statments

[jade walrus]

oh what

oh shoot that was a typo lmao

oh wait no

hold on

x^2 - px - p - c = 0

x^2 - px - (p+c) = 0

sum of roots = p

product of roots = -p - c

[neon iron]

what did you get on 5

[jade walrus]

1-c

[neon iron]

show me your calculation

[jade walrus]

of this?

[neon iron]

yes

[jade walrus]

wait

i dont have my phone so ill jus type it out

(1 + a)(1 + b)
=> 1 + a + b + ab
=> 1 + (a + b) + (ab)
=> 1 + (p) + (-p - c)
=> 1 - c

[neon iron]

hows ab -p -c

[jade walrus]

product of roots is - p - c

[neon iron]

how

what formula is that

[jade walrus]

uh

Vieta's formulas

[neon iron]

im so tired, but somehow i dont get any of the answer you have

[jade walrus]

oh okay

[neon iron]

can you state me viete's formulas.

[jade walrus]

sum of roots = -b/a

product = c/a

[neon iron]

what is a b and c in your case

[jade walrus]

b = -p
c = - (p + c)

a = 1

[neon iron]

ok yeah

ur calculation is correct

1+p-p-c

so its 1 -c

ok moving to 6

[jade walrus]

alright

[neon iron]

what have you tried

apart from what u tol me

[jade walrus]

uh solving the problem directly but that just gave me a brain aneurysm

[neon iron]

what is the numerator

[jade walrus]

also dunno why i called this the 8th question, i was talking about the 6th question lmao

[neon iron]

what can it also be written as

[jade walrus]

(a^2 + 2a + 1)(b^2 + 2b + 1) + (a^2 + 2a + 1)(b^2 + 2b + 1)

[neon iron]

the numerator of only one fraction

[jade walrus]

oh

a^2 + 2a + 1?

[neon iron]

yes what this can be written as

[jade walrus]

3a^2 - pa(a+1) - 2(p+c) + 1

a = alpha

okay yeah it can also be written as a^2(3-p) - pa - 2(p+c) + 1

[neon iron]

no

its just simply (a+1)²

[jade walrus]

oh shoot yeah

how did i miss that even

wait how do i move forward tho

from that

@neon iron

[neon iron]

im thinking

c != from 1

im thinking of calculating the solutions manually but that will make me go mad

clearly not the way

im thinking to think them through elimination

C) is clearly not the answer

atleast i wouldn't say

[jade walrus]

okay

why's you say it's not (c) though

[topaz sinew]

@jade walrus Has your question been resolved?

[jade walrus]

.close

[topaz sinew]

Channel closed

Closed by @jade walrus

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

[median zenith]

.close

[neon iron]

$m = \frac{y_2 - y_1}{x_2 - x_1}$

[thorny flame]

daniel

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fathom sequoia]

help plsss

[golden blade]

You can differentiate (A) or (B) and see if you get f(x)

[fathom sequoia]

i know this

but they what the anti derivative of f

which confuses me

[fathom sequoia]

a and b are wrong

[fathom sequoia]

thats really confusing lol

ig ll memorize it

[fathom sequoia]

can you explain why tho

cause its confusing

for nvm ig

can you explain this please

how did we know the answer is 3/4pi and 7/4pi

[alpine mist]

it's basically a definition. F is, more or less, defined to be an antiderivative of f(x)

[fathom sequoia]

it makes sense for me to say its the antiderivative of f'(x)

to find f

but nvm

[fathom sequoia]

can u help with this

[alpine mist]

0 = -sin(x) - cos(x) is the same as sin(x) = -cos(x). The only place sin(x) and cos(x) are the same is at the pi/4 values. They have different signs at 3pi/4 and 7pi/4

[topaz sinew]

@fathom sequoia Has your question been resolved?

[fathom sequoia]

how do i know algebrically

can you please assist me in that

[alpine mist]

the only algebra to do there is adding sin(x) to both sides. From there it's knowing your trig values.

you could maybe do other trig substitutions to get it down to just sin or cos, but that's way more work than it's worth.

[fathom sequoia]

.close

[topaz sinew]

Channel closed

Closed by @fathom sequoia

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[brazen saddle]

is number 17 right?

[dapper storm]

no

[brazen saddle]

okay how do you do it?

[dapper storm]

whats the expansion of $(x+y)^2$

[thorny flame]

Infectia

[brazen saddle]

what

[dapper storm]

if you expanded that what would u gete

[brazen saddle]

this is algebra not caculas

[dapper storm]

?

[brazen saddle]

i think ur doing calculus

[dapper storm]

I didnt say anything about calculus

the question is to expand that right?

[brazen saddle]

but that doesn't seem right and no its to find the product

and the chapter were on is talking about polynomials\ and trinomials

[dapper storm]

well $(2x^2-8)^2 \neq (2x^2)^2(-8)^2$

[thorny flame]

Infectia

[brazen saddle]

dude what are u talking about

[dapper storm]

$(x+y)^2 = (x+y)(x+y)$

[thorny flame]

Infectia

[dapper storm]

u r asking about number 17

[brazen saddle]

.close

[topaz sinew]

Channel closed

Closed by @brazen saddle

Use .reopen if this was a mistake.

[rocky gulch]

lmao

[minor zealot]

no way

[dapper storm]

is he good?

[rocky gulch]

reopen it i’ll help you

[brazen saddle]

okay thank you

i didnt know what he was saying cause that was not mentioned at all during our class and notes

[dapper storm]

apologies. expanding just means multiplying everything out

[brazen saddle]

so like what

[dapper storm]

so you need help with number 17 right?

[brazen saddle]

yes

[dapper storm]

.reopen

can u type that

before this closes

[brazen saddle]

.reopen

[topaz sinew]

✅

[dapper storm]

ok so the equation given is: $(2x^2-8)^2$

[thorny flame]

Infectia

[brazen saddle]

yes

[dapper storm]

do you understand when someone writes: $x^2 = x \cdot x$

oops

[thorny flame]

Infectia

[brazen saddle]

yes

[dapper storm]

great so this is basically: $(2x^2-8)(2x^2-8)$

[thorny flame]

Infectia

[brazen saddle]

okay

is that the answer?

[dapper storm]

now you have to multiply it out like you did for the other questions

[brazen saddle]

so like i use the foil method

[dapper storm]

yep

[brazen saddle]

i got u

[dapper storm]

that was the term. i couldnt think of it 😂

ping me when you get an answer

[brazen saddle]

this ?

[dapper storm]

what happened to the $-16x^2-16x^2$ part

[thorny flame]

Infectia

[brazen saddle]

that cancels out because there both - and being added

wait mb

[dapper storm]

so terms only cancel out when its: $-16x^2+16x^2$

[thorny flame]

Infectia

[brazen saddle]

nvm it -32x^2

[dapper storm]

exactly

[brazen saddle]

so the equation is 4x^4-32x^2-64

[dapper storm]

yep!

[brazen saddle]

thank you

[dapper storm]

np

[brazen saddle]

.close

[topaz sinew]

Channel closed

Closed by @brazen saddle

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[misty hedge]

𝑓(𝑥) = 𝑥^2 − 2𝐴𝑥 + 𝐴^2
𝑔(𝑥) = 𝑥^2 − 𝐴^2

Describe the single transformation that would map 𝑔(𝑥) onto 𝑓(𝑥).

I am revising for an exam and completing past papers, however I don't understand this question.

[keen venture]

I agree, this is an awkward question.

I would assume you're supposed to factor both, and recognize a pattern.

[misty hedge]

I have worked out the range for f(x) which is 0 , infinity
i have also worked out the range for g(x) which is -A^2 , infinity

*this may not be correct, i just think it is but i dont know if thats relevant anyway

i see that to make g(x) = f(x) i would need to add 2Ax here 𝑥^2 − (here) + 𝐴^2

but im stuck on that part

[sonic dawn]

hmm i don’t see the single transformation
you can do it in 2 transformations pretty handily, i guess that’s what they want

[misty hedge]

how so? it does state single tranformation

[gusty bane]

could composing them just be the single transformation

[sonic dawn]

convert both to a(x-b)²+c form or whatever you call it

[sonic dawn]

ye i guess

[misty hedge]

so for f then a = 1, b = A, and c = 0 i think

and for g, a = 1, b = 0 and c = -A²

so f is 1(x-A)² + 0
and g is 1(x-0)² + A²

what do i do from here?

[sonic dawn]

now the transformation should be easier to see

[misty hedge]

i don't see it, i have never done anything like this before

[sonic dawn]

ok, then im probably not going to be able to teach you transformations of functions on the fly any better than what’s already online

[misty hedge]

im unable to find any sources that help with this question, could you reccommend any?

dont worry if not

[sonic dawn]

https://www.cuemath.com/calculus/transformation-of-functions/

seems relevant enough

[misty hedge]

i feel that because of this, it would make sense that the change is 2Ax, but I dont understand what that change is

thank you i'll give it a read quickly

[topaz sinew]

@misty hedge Has your question been resolved?

[misty hedge]

when i look at the difference between the graphs when a = 1

i see that to map g(x) onto f(x), the dilation stays the same, and it translates up 1 and across 1

how do i describe this?

the vertex for g(x) is (0,-1) and for f(x) it's (1,0)

<@&286206848099549185> is there anyone that can help with this? i just need help to understand this 1 question then i will be able to do it alone

[misty hedge]

okay i think i've solved it by substituting A

would the answer be to translate/shift g(x) by the vector A,A²

does that make sene? i may have explained it wrong

<@&286206848099549185>

because no matter what the value of A is, the vertex of the parabola always moves by A,A²

.close

[topaz sinew]

Channel closed

Closed by @misty hedge

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[warm knot]

can someone explain why the other answer is 5pi/6

[warm knot]

i thought it was pi/6 and 11pi/6

[cursive patrol]

11pi/6 - pi = 5pi/6

[warm knot]

whyd u do that

im confused

[cursive patrol]

u see the "n * pi"

[warm knot]

yes

[cursive patrol]

the answer says 5pi/6 + n*pi

so it's saying that n can be any integer meaning the number can be 5pi/6 + any multiple of pi

[warm knot]

so is 11pi/6 wrong

or no

because of this

[cursive patrol]

equivalently 11pi/6 + n*pi is also a valid way of expressing the answer

though. normally u want to use the number that is closer to 0

[warm knot]

all of my answers have 2npi

_

_

this is the first one ive done with npi

[cursive patrol]

(secx) has a period of 2pi
(secx)^2 has a period of pi

is why

[warm knot]

how is it pi

like just pi

[topaz sinew]

@warm knot Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[shrewd atlas]

What is a+c+b+d when a,b,c,d are integers and constant but x,y,z are variable while (xᵃyᵇzᶜ)ᵈ = x⁶y⁹z¹⁵ (d>1)

[shrewd atlas]

I tried to submit 31 but it is wrong for unknown reason

[neon iron]

!show

[topaz sinew]

Show your work, and if possible, explain where you are stuck.

[shrewd atlas]

It is a=6 b=9 c=15 d=1 but wrong

[neon iron]

they are requiring that d > 1 tho

so d cant be 1

can you try and find the greatest common divisor between 6,9, and 15?

[shrewd atlas]

3

[neon iron]

yeah

so like

how can you write it now?

[noble laurel]

Nice

[topaz sinew]

@shrewd atlas Has your question been resolved?

[shrewd atlas]

So d=3

[shrewd atlas]

And would the answer be a=2 b=3 c=5 d=3?

.close

[topaz sinew]

Channel closed

Closed by @shrewd atlas

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[slender sonnet]

In ABC triangle AB is 15 and AC is 10 what number can be equal to sinB

[slender sonnet]

3/4. 4/5. 3/5. 5/6

[topaz sinew]

@slender sonnet Has your question been resolved?

[slender sonnet]

<@&286206848099549185>

[slender sonnet]

.close

[topaz sinew]

Channel closed

Closed by @slender sonnet

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mild reef]

Help me please

[analog light]

Have you done part b?

[mild reef]

Um no?

I'm not sure how to

[analog light]

Ok well there are two branches which results in the student taking biology

Either CB or C'B

You want to figure out the probabilities of those two scenarios happening, then add them together

[mild reef]

Are the stuff I've written in the diagram correct?

[analog light]

Yep that looks right

You missed off CB' though

[mild reef]

0.4?

[analog light]

Yep

[mild reef]

I got 0.54 as the answer to b

How do I do C?

Oh wait

I got 0.17 as the answer to c

Is that correct?

Helpppppp

[topaz sinew]

@mild reef Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[shy estuary]

How do you do this?

[shy estuary]

lol I’ve asked same question like 4 times

[pseudo sonnet]

perhaps try the advanced channels then?

I think it’s unlikely you’ll get help here, at least not quickly

is this algebraic topology?

assuming it is, there’s #point-set-topology

[topaz sinew]

@shy estuary Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tranquil badger]

I have had a question on a test today and i need an answer i asked ai but it didnt help

[tranquil badger]

2a-4b+22ab²-11b³ and i need to find all pairs for (a,b)

[keen hinge]

Did you mean "= 0"?

[tranquil badger]

Oh yeah Its = 2024

[keen hinge]

I assume you need integer pairs of solutions?

[tranquil badger]

Yeah

Oh and i can post where i came so far

Oh and my bad another mistake i made

Its 4a-2b

I came this far

[keen hinge]

Consider prime factorization of 2024

[tranquil badger]

This ?

English not my native language so all this frases i wasnt learning them in english 😅

[grim sable]

You can factor the expression

4a - 2b + 22ab^2 - 11b^3 = 2024

[tranquil badger]

Its 4a-2b so you can do 2(2a-b)

I mistyped

[grim sable]

2a(2 + 11b^2) - b(2 + 11b^2) = 2024

(2a - b)(2 + 11b^2) = 2024

So just take cases for b using the table of factors you made

[tranquil badger]

Ill try

It worked for b=2

Then for 11 and 23 i got weird big numbers

Nvm even when i entered b=2 i only got correnct cuz i fucked up calculating

Wrong -

<@&286206848099549185>

[topaz sinew]

@tranquil badger Has your question been resolved?

[topaz sinew]

@tranquil badger Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[viscid yew]

Hi

[viscid yew]

I need some help for this trigonometric equation plz, i need to verify the equation

[half edge]

whatve u tried

also what side u tryna start with

@viscid yew

[topaz sinew]

@viscid yew Has your question been resolved?

[viscid yew]

omgg sry i didn't answer

i started with the right

[topaz sinew]

@viscid yew Has your question been resolved?

[topaz sinew]

@viscid yew Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[strange steeple]

I need help with the first part of this question

I'm not sure how to construct the line integrals for the triangle

[noble laurel]

Have you plotted it?

[strange steeple]

Yeah i've drawn the triangle

[noble laurel]

Have you parametrized the curves?

[bitter hemlock]

you need to find the tangent vector for each individual segment of the triangle

[strange steeple]

I have

I'm trying to take a photo of what ive done but my camera isnt focussing

i'm not sure what to use as the function

[topaz sinew]

@strange steeple Has your question been resolved?

[strange steeple]

.close

[topaz sinew]

Channel closed

Closed by @strange steeple

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[distant lintel]

can someone help me with 5?

[radiant marlin]

by graphical analysis does it mean like the pictures here? https://en.wikipedia.org/wiki/Fixed-point_iteration

[distant lintel]

yes!

but like, how would I even do that using desmos? I've done 1, but 5 is confusing me.

[radiant marlin]

yea it's not super obvious to me

[distant lintel]

we'd also need y = x

wait you have that

yeah im lost on everything else

[radiant marlin]

I just picked a random point in (1/9,2/9) and it spirals out to infinity so I guess that's the idea

I see how to prove it by doing the algebra on the sets and seeing how they expand/contract, but graphically I guess you just draw a line or maybe 2 of a low/high value of the set and just follow it along a few steps until it's going down-right to -infinity

[distant lintel]

so far i have this

I mean, what else?

[radiant marlin]

uh is your tent hidden or something

here's the picture, idk how you get desmos to print it

[distant lintel]

I mean, did you include x being in (1/9,2/9) or x being in (7/9, 8/9)?

[radiant marlin]

this is for 4/36 so just a random point in (1/9,2/9), not sure what a satisfying answer would look like

oh I guess the question wants you to assume 4.'s proof, where if you're in (1/3,2/3) you go to -infinity, and (1/9,2/9)U(7/9,8/9) go there in one step?

idk why you need a graph for this haha

[distant lintel]

No idea..

[topaz sinew]

@distant lintel Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cinder rapids]

im sorry if one of you has only just helped me

[cinder rapids]

but how do you do |x(x-2)| >= 1

[atomic wadi]

Draw graph

[cinder rapids]

,tex $ |x(x-2)| \ge 1

[atomic wadi]

A graph that intersect x=0 and x=2

Den you make watever below x axis to reflect upwards

[thorny flame]

suds
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[cinder rapids]

i wanna do it algebraically because i wont be able to do that in a test

also thats not it

because its inequality not =

[atomic wadi]

Some examples for u to refer

[cinder rapids]

no but thats different because my issue is the x(x-2)

because it makes it x^2 -2x which is a lot harder to equate to x

[atomic wadi]

It's the same concept , juz different function

Lemme type

x²-2x≥1 OR x²-2x≤-1

Becomes
x²-2x-1≥0 OR x²-2x+1≤0

[cinder rapids]

using the quadratic formula? really?

[atomic wadi]

Solve the quadratics

That's why graph would be alot faster and helpful

Algebra in inequality sometimes will be a pain in the ass

[cinder rapids]

i have no idea what you meant with the graph thing btw

[supple hornet]

|x(x-2)| >= 1

you can also try doing this w algebra if you dont want to graph

[cinder rapids]

how

[cinder rapids]

like apreggio did with quadratics?

[supple hornet]

oh nvm i thought they were graphing

in that case yes you have to use quadratics (well this is a quadratic anyway)

you have to do casework and its a bit tedious though

it may be easier to simply solve for the point at which it's 1 and take intervals from there

[cinder rapids]

damn ok

thanks

.close

[topaz sinew]

Channel closed

Closed by @cinder rapids

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dark fog]

Symmeritc relation is A to B and b to a

[tulip monolith]

What do you mean?

Do you mean if aRb then bRa?

[dark fog]

Yes

[tulip monolith]

Well if R and R' are not disjoint

What do you know by the definition of a symmetric relation?

@dark fog

[dark fog]

I didn't understand this part actually

[tulip monolith]

If R is a relation on A then $(a,b) \in \mathbb{R} \implies (b,a) \in \mathbb{R} \forall a,b \in A$

[thorny flame]

ColdTee

[dark fog]

@tulip monolith

[tulip monolith]

,rcw

[dark fog]

I am closing the channel

Am I right? It looks fine

.close

[topaz sinew]

Channel closed

Closed by @dark fog

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[broken holly]

can someone help me with this question?

[broken holly]

so what I tried so far is

use half angle identity for both the cos and the sin

then used the identity for cos3x and sin3x inside the half angle identity

then moved one side over to make the two together = 0

i was doing it on whatever scrap of paper i had left so i had to erase my work to write down new stuff

and therefore dont have any written work to show what ive been thinking of

can someone with a large brain help me out

pretty please

<@&286206848099549185>

please bless me with your benevolence!

[supple hornet]

you might be overthinking this

[broken holly]

O

[supple hornet]

begin with when would sin(u) = cos(u)

and go from there

[broken holly]

uh

er

so

[supple hornet]

draw a unit circle or 2 graphs on a piece of paper if you dont know

[broken holly]

cos (u - 90) = sin (u)

wuagh

what to do after unit circle

uh

i still dont understand what to do-

[supple hornet]

i was thinking more of a number

observe that cos(pi/4) = sin(pi/4) here

[broken holly]

[supple hornet]

what can we do with that? look at the inside of cos(...) and sin(...)

[broken holly]

hmm

[supple hornet]

maybe we can set up an eq with these and use the pi/4

[broken holly]

so then

3/2 x (cos x) = pi/4 somehow

which means

cos x = 2pi/ 12

[supple hornet]

what about 3/2 sin(x)

[broken holly]

it also equals pi/4?

[supple hornet]

we should try to combine them into one eq

[broken holly]

yes sirr

hm

[supple hornet]

simple matter of adding the two

[broken holly]

do we just add the two sides together

and say that it equals pi/2

?

[supple hornet]

you're on the right track

[broken holly]

yippie

[supple hornet]

keep solving that

[broken holly]

yes sir

cosx + sinx = pi/3

1 + sin2x = pi^2/9

[supple hornet]

time to do something which will let us use a property

[broken holly]

O

[supple hornet]

hmm i think that works

you are nearly there

[broken holly]

O

hip hip hoorah

ok ok lets see

2.77 degrees and

87.22 degrees

but

this feels kind of weird

ohhh

wait

(x - 87.22)(x - 2.77)

[supple hornet]

make sure not to mix rad and degrees lol

[broken holly]

dont worry master

as an average degrees enjoyer

using rad scares me

so my calculator is eternally in degrees mode

x^2 - 90x + 238.1106

does this look good

wait a second

the thingy we used earlier

was in radience

🗿

[supple hornet]

lol yes

[broken holly]

wait

im so confused

[broken holly]

this part right

do we have to turn into degrees

since like

lets say im using degree mode

oh

180^2

but like

we are inverse sining this thingy

i dont really understand the logic behind why we have to convert that to degrees as well

since that is supposed to be a ratio not theta

[supple hornet]

i would highly recommend using rad for this kind of thing

i'm not even sure if or how squaring degrees would be defined

[broken holly]

a

so then even that 1 from earlier would be in rad

this is awfully confusing

well ok let me try everything in rad mode

[supple hornet]

i believe desmos uses rad so you can always check your answer there asw

[broken holly]

(x - 0.048)(x - 1.522)

[broken holly]

whot

wait

real

wait

you can check quadratics on desmos?

[supple hornet]

quadratics?

[broken holly]

quack

[supple hornet]

what does this question have to do with quadratics

[broken holly]

sorry

i meant

um

this kind of thingy

[supple hornet]

i mean you can enter your sin(sin ... and cos(cos ... there

[broken holly]

ax bx c thingy

[broken holly]

woah

ill try that in a sec

[supple hornet]

im not sure what abcd are in this question but yes

[broken holly]

like

the constants

i think

[supple hornet]

it can definitely graph a second order equation

[broken holly]

whoa

desmos programmers are so considerate

anyways

gotta

finish

tis thing

x^2 - 1.57x + 0.07366

finally

i finished

time to check on desmos

graph be looking wild

[supple hornet]

what are abcd supposed to be

i dont see any relation to x lol

[broken holly]

like

if i write x = y

you dont write it out

but theres an invisible 1

so im assuming

they just want us to write it in that format

and if there isnt any constant

we just leave it as x

any ways

heres my result

it totally failed

what do i do

[supple hornet]

what were you expecting to see

[broken holly]

2 lines that matches

wot

[supple hornet]

have you tried zooming in

[broken holly]

uh

no

why

[supple hornet]

your radian results should be accurate

[supple hornet]

those are the correct roots

[broken holly]

wuagh

so then desmos is right??

[supple hornet]

you should zoom in

the red lines probably intersect the roots as well

naturally sin/cos are periodic so the lines are repeating

[broken holly]

huh

[supple hornet]

but since your question asked for x in [0, pi/2] just ignore any lines outside of that range

[broken holly]

oh

waaaaaaaaaaait

so

its saying

these two graphs

should have the 2 of the same x and y points from 0 < x < pi/2

wait wait wait

[supple hornet]

i feel like you are confused by multiple points

maybe you can send them and ill address them

[supple hornet]

lack of precision

[supple hornet]

in your quadratic

[broken holly]

so then

if given the precise enough units

they should intersect at y = 0?

[supple hornet]

yes

[broken holly]

ohh

ok its starting to make sense

btw

i forgot

what is this typing of

writing down numbers called again

x^2-1.57x+0.073664591

like

i know what the quadratic is

i know what the slope intercept form is

but i cant remember what that thing is called

[supple hornet]

its just a quadratic equation

?

[broken holly]

huh

i though like

quadratic is this thingy

oh

wait

quadratic formula and quadratic equation are 2 dif thing

man

[supple hornet]

broadly speaking any polynomial with 2 as its highest power is quadratic

the formula refers to the root finding method for quadratics

[broken holly]

right polynomial thats what it is

ah

i see

man

my memory be eroding

i gotta do some review

anyways

[supple hornet]

grind more practice problems

[broken holly]

thanks so much for your help man

[broken holly]

[supple hornet]

np good luck

[broken holly]

one sec tryna find the right emote

there we go

once again thanks so much good night to you my saviour @supple hornet

adios

.close

[topaz sinew]

Channel closed

Closed by @broken holly

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gusty cobalt]

How do I answer this

I’m so confused on it

Is the horizontal speed 40

Or is that the speed it was projected at?

[bitter hemlock]

total speed

[gusty cobalt]

So what am I supposed to do first?

Also why are there 2 lines?

Nvm different angles

So would the initial horizontal speed be 40cos x

And the vertical would be 40 sin x

[topaz sinew]

@gusty cobalt Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pseudo tiger]

the answer for a is 40%

but how?

[cursive mango]

Whey do you expect it to be

[tribal arrow]

If 60% of the students wear neither a ring nor necklace, then whatever remains must wear either a ring or a necklace

So the percent of students who wear one or the other is 100% - 60% = 40%

[pseudo tiger]

hmm ok

what about the second then

is there a formula or a rule about this kin dof exercises

becuase i find it hard to understand the cocnept

i also have this one

[vernal ledge]

for this kind of multiple percentages question, a Venn diagram would be very helpful

hold on let me draw one

[pseudo tiger]

i would appreciate it

[tribal arrow]

A good formula to use is the following:
$|A \cup B| = |A| + |B| - |A \cap B|$

This is using set notation, which you may not be familiar with. Here is how you can read it so it makes mores sense:
The $\cup$ here stands for "or" and the $\cap$ here stands for "and"

So (ring or necklace percent) = (ring percent) + (necklace percent) - (ring and necklace)

You know (ring or necklace percent), (ring percent) and (necklace percent) , so plug in those values and solve

[thorny flame]

curry

[pseudo tiger]

i think i got it

don't worry

[pseudo tiger]

thank you very much

[vernal ledge]

if you have unions and intersections then it's better using that

venn diagrams are not necessary for just two conditions but if like there's a third condition (for example, people who chew tobacco) then venn diagrams are better to visualize

[pseudo tiger]

i get it thank you very much

[topaz sinew]

@pseudo tiger Has your question been resolved?

[pseudo tiger]

.close

[topaz sinew]

Channel closed

Closed by @pseudo tiger

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[earnest arch]

Hi is the answer to this 0.682?

[topaz sinew]

@earnest arch Has your question been resolved?

[earnest arch]

<@&286206848099549185>

.close

[topaz sinew]

Channel closed

Closed by @earnest arch

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vivid mauve]

U said: Yes, that equation represents the tangent line to the function ( f(x) ) at the point ( (x_0, f(x_0)) ). The slope of the tangent line is given by ( f'(x_0) ), and the point ( (x_0, f(x_0)) ) lies on the tangent line.

[thorny flame]

Barda

[vivid mauve]

@storm pendant

can you remember that

what should I put in?

[storm pendant]

To find the equation of the tangent line to a function at a specific point, you need to plug in the following values into the equation:

1. ( f'(x_0) ): The derivative of the function evaluated at ( x = x_0 ), which gives you the slope of the tangent line.
2. ( x_0 ): The x-coordinate of the point where you want to find the tangent line.
3. ( f(x_0) ): The y-coordinate of the point where you want to find the tangent line.

Once you have these values, you can plug them into the equation ( y = f'(x_0)(x-x_0) + f(x_0) ) to get the equation of the tangent line.

[thorny flame]

𝑩𝒍𝒂𝒏𝒄𝒖𝒔

[topaz sinew]

@vivid mauve Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[hushed shoal]

With this vector equation of (x, y) = (-3, 4) - t(-4, -1), what is the dirction vector?

[hushed shoal]

Is it (4, 1) of (-4, -1)

[tribal arrow]

As those two vectors are scalar multiples of each other, both are correct.

[topaz sinew]

@hushed shoal Has your question been resolved?

[hushed shoal]

Oh that helps thank you

[topaz sinew]

Channel closed

Closed by @hushed shoal

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vapid seal]

For question 39. How did we know that the line is x = 0 and not something else?

[vapid seal]

I tried to solve it about the line y = 1, but I got a wrong solution

[cursive mango]

You mean x=1?

[tribal arrow]

The line $\overline{AB}$ is given by the equation $x = 1$

[thorny flame]

curry

[neon fiber]

because the x coordinates of A and B are 1

[vapid seal]

no I tried y = 1

[smoky sinew]

y=1 is a horizontal line

x=1 is a vertical line

[vapid seal]

I'm so dumb.

I thought y = 1 was the vertical

nvm

Another question. Can we use y = 0?

[neon fiber]

me like 30 minutes ago:

[vapid seal]

It happens

[neon fiber]

the question says you need to rotate it about AB so im guessing not

[vapid seal]

Yeah true.

Thank you for the help.

.close

[topaz sinew]

Channel closed

Closed by @vapid seal

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[willow silo]

A triangle ABC is given, for which AB = AC = 18 and BC = 4. A circle of radius 7 is observed that passes through points B and C, while the center, point O,
lies inside the triangle ABC. From point A, tangents to circle are drawn that touch it at
points N and M. Find the area of ​​the quadrilateral OMAN.