help-26

[keen raptor]

everything else represents what's consumed in the process of producing

[finite mortar]

Ohhhhhhhhh

[keen raptor]

so like net gain of good j = Production - Expense

[finite mortar]

Oh okay that makes sense

Thanks

.close

[topaz sinew]

Channel closed

Closed by @finite mortar

Use .reopen if this was a mistake.

[keen raptor]

np

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[queen rock]

having trouble solving this limit

[chilly walrus]

looks like 0 to me but let me check

[queen rock]

tried using L' Hospital but I end up with inf*0

[radiant sparrow]

use log rules

you can write x as lne^x

[queen rock]

yeah I should have thought of that

[chilly walrus]

you can use that. just write the part that is the 0 as 1/that part

you'll be able to transform it into inf/inf

[queen rock]

I think it is easily solvable if you write x as lne^x

[chilly walrus]

i agree

[queen rock]

checking real quick

yeah it's easy

thanks, I just needed to approach from a different angle

[radiant sparrow]

[queen rock]

.close

[topaz sinew]

Channel closed

Closed by @queen rock

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fierce zealot]

Is it true that a function is bijective if there is one and only one left inverse?

[fierce zealot]

I think it should be false?

[fierce zealot]

I don’t understand the wording

.close

[topaz sinew]

Channel closed

Closed by @fierce zealot

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[keen sorrel]

If anyone could explain about #10 how it went from 2xy(x^2-2x-8) to 2xy(x+2)(x-4) it would mean a lot but no rush for this one

[topaz sinew]

Please don't occupy multiple help channels.

[gusty bane]

#help-4

[keen sorrel]

I was gonna say that one disappeared like it wouldn’t let me enter

.close

[topaz sinew]

Channel closed

Closed by @keen sorrel

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fallow harness]

how did she get -sin^-1(x/3) as the back substitution for -theta in the bottom right

[sweet shard]

show the original question

[fallow harness]

original question is top left

$\int_{}^{}\frac{\sqrt{9-x^2}}{x^2}dx$

[thorny flame]

Jai

[sweet shard]

solve for theta in terms of x

[fallow harness]

what do you mean?

[sweet shard]

did you see this

[fallow harness]

Oh right x/3

What I'm confused about is why an inverse sin is used when back substituting instead of a regular sin

[sweet shard]

did you see the double red underline

[fallow harness]

yeah

but I don't understand why that becomes sin^-1(x/3)

[sweet shard]

did you do this yet

[sweet shard]

from this eqn

[fallow harness]

so if x = sin(theta) then theta = sin^-1(x)

oh that does make sense

sweet thanks

.close

[topaz sinew]

Channel closed

Closed by @fallow harness

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[severe lichen]

ik how they got the first two solutions but how did they get 7pi/3 and 8pi/3

like how do you figure out the distance between 2pi/3 and pi/3 going counter clockwise

if that makes sense

[sleek gate]

do you know what a general solution is for this equation?

in interval (-inf,inf)

[severe lichen]

like how do you calculate this distance

[severe lichen]

it doesnt matter

[sleek gate]

it definitely does

do you know or not?

[severe lichen]

a general solution is just pi/3 + 2pn and 2pi/3 + 2pin

[sleek gate]

yeah

so when n is one

you get 7/3pi and 8/3pi

[severe lichen]

oh okay i thought i had to do some weird math to get it

just a little bit of mental gymnastics is what i mean

[sleek gate]

just it

[severe lichen]

okay that makes a lot more sense then

[sleek gate]

since 7/3pi and 8/3pi are in (0,4pi) interval they are valid solutions

[severe lichen]

but cant i keep going

[sleek gate]

try

[severe lichen]

oh nvm i cant

[sleek gate]

you cant

cuase they would be outside of an interval

[severe lichen]

13/3 and 14/3 are too big

okay thanks

[sleek gate]

you're welcome

[severe lichen]

.close

[topaz sinew]

Channel closed

Closed by @severe lichen

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[topaz sinew]

Please don't occupy multiple help channels.

[proud ridge]

yep, i was gonna move

[wary tulip]

austin just really wanted to post that

[noble laurel]

Stick to one channel #help-20

.close

[topaz sinew]

Channel closed

Closed by @noble laurel

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vivid meteor]

how does my prof go from the first to second line

[wooden osprey]

prod to sum formula

$\sin\alpha\sin\beta = \frac12[\cos(\alpha-\beta)-\cos(\alpha+\beta)]$

[thorny flame]

FungusDesu MSC2020 34A05

[vernal leaf]

What about the Partial Integration

$\int [u * dv] = u*v - \int [v * du]$

I hope that works

Cool

I think that is the partial integration

[thorny flame]

Player

[vernal leaf]

So take the derivative of sin(2x)

So use u substitution for that I think

So d/dx sin(2x) would be d/dx sin(u) • d/dx u

So that is cos(u) since derivative of sin is cos, and then put the 2x that we replaced with u back into the expression

So it's cos(2x) • d/dx 2x, that's just 2 • cos(2x)

So derivative of sin(2x) is 2cos(2x)

Now you say that "u" is sin(10x), "v" is sin(2x), "dv" which is derivative of v, is 2cos(2x), and now all you need is "du" which is derivative of u

Which is 10cos(10x)

So just plug those in to the partial integration until it cancels out one of them

So you don't need to repeat the process

Then simplify by adding them all up

And that's the answer

The previous version is probably easier though

This takes long

[topaz sinew]

@vivid meteor Has your question been resolved?

Channel closed

Closed by @vivid meteor

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid bear]

ok so i am confused on finding the primitive roots, I know for the primitive roots of cube they are 2pi/3, 4pi/3, and for fourth pi/2 and 3pi/2

[timid bear]

i just don't understand how to find the sixth

[worthy storm]

can you name some sixth roots of unity? then reason about which ones are primitive

[timid bear]

yes, 0, pi/3, 2pi/3, pi, 4pi/3, 5pi/3

i think pi, pi/3, 2pi/3, 4pi/3, 5pi/3 are primitive

@worthy storm

<@&286206848099549185>

[topaz sinew]

@timid bear Has your question been resolved?

[topaz sinew]

@timid bear Has your question been resolved?

[topaz sinew]

@timid bear Has your question been resolved?

Channel closed

Closed by @timid bear

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[errant sun]

I have a linear algebra question. How does the E3 go away? I marked it in green

[worthy storm]

looks like they multiplied the last two matrices together

[errant sun]

right. E1 and E2 was multiplied to = the -2,3,1,0 matrix

but im not sure what happened to the third matrix

[worthy storm]

they computed (E2^-1)(E3^-1)
when you do that, you get one less matrix, right?

[errant sun]

i dont see any computations with E3

[worthy storm]

are you talking about the two red lines near the end

[errant sun]

yes

[worthy storm]

from left to right, those are
(E1^-1)(E2^-1)(E3^-1)
then, on the next line:
(E1^-1)(X)
where X is the result of multiplying (E2^-1)(E3^-1)

[errant sun]

oh I see

the middle matrix looked so similar that i thought E1 and E2 wass jusut brought down

and E3 disappeared

.close

[topaz sinew]

Channel closed

Closed by @errant sun

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lunar merlin]

hey im up to A. atm and expanded it but im confused with collecting the like terms

[lunar merlin]

Ive gotten so far x^3 + bx^2 + cx + x^2 +bx + c

im just confused if I can add bx^2 + x^2

[sweet shard]

yes you can

[lunar merlin]

how would it work?

[sweet shard]

those are "like terms" because they share x^2 in common

[lunar merlin]

2bx^2

?

[sweet shard]

nah

[lunar merlin]

im not sure

[sweet shard]

use r * s + r * t = r * (s + t)

x^2 = 1 * x^2

bx^2 = b * x^2

where * is multiplication

[lunar merlin]

ah

so

ok wait im still confused

would it be

x^2(b + 1)

[sweet shard]

,w simplify bx^2 + x^2

[thorny flame]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by rie.mann

[lunar merlin]

woohoo

alright ill close this if i get stuck on anythhing else ill be back

.close

[topaz sinew]

Channel closed

Closed by @lunar merlin

Use .reopen if this was a mistake.

[lunar merlin]

.reopen

[topaz sinew]

✅

[lunar merlin]

im back

[lunar merlin]

im confused what its asking me to do in part B

[lunar merlin]

math magician

[sweet shard]

equate coefficients is like setting the thing multiplying the powers of x equal

[lunar merlin]

setting the thing?

[sweet shard]

a + bx + cx^2 = d + ex +fx^2 implies
a = d
b = e
c = f

[lunar merlin]

ah

[sweet shard]

the correct word is coefficients. it was escaping me

[lunar merlin]

but we only have one equation right now?

[fair thorn]

not necessarily, but i'll go along with it

[sweet shard]

yea, your equation is pretty close to the first equation here. the process is the same when there are x^3 terms on both sides

[lunar merlin]

hm

im confused what we equate it to?

[lunar merlin]

x^3 + ax^3 + bx + c ?

[sweet shard]

Write down your entire equation expanded

[lunar merlin]

so without the (b +1)x^2

[sweet shard]

It is known...

[lunar merlin]

huh wha

AHAHAHA

oh my gosh

i need to read questions

alright ill continue lol thanks

.close

[topaz sinew]

Channel closed

Closed by @lunar merlin

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[manic turret]

How do you get the length at d? I don’t get.

[wooden osprey]

not enough information

[manic turret]

Not drawn to scale, but this is all I have.

[wooden osprey]

wait i might be wrong

[manic turret]

?

[frosty prairie]

Can you give any more information so that we can consider it as a figure drawn to scale?

[manic turret]

I really can’t.

If it can’t be solved, I’ll just skip it.

One of my friends said this was the equation to solve it, but I don’t understand how they got this.

[topaz sinew]

@manic turret Has your question been resolved?

[manic turret]

Welp

[manic turret]

F

[topaz sinew]

@manic turret Has your question been resolved?

[topaz sinew]

@manic turret Has your question been resolved?

[manic turret]

I just don’t get it…

[topaz sinew]

@manic turret Has your question been resolved?

[manic turret]

Guess it’s a lost cause.

.close

[topaz sinew]

Channel closed

Closed by @manic turret

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[robust jasper]

No hables

So basically no matter what angle at 0 cannot exist

as its undefined

So i never write zeroes as a solution?

Bc i dont understand the explination one bit

Like 0

I do everything a different way

:3

[rose thorn]

vewwy confus

Is the question to find theta that solves cos \theta + 2 sin \theta = 1?

'cus then, yeah, theta = 0 is a solution, right?

@robust jasper

cot and cosec never even show up in the screenshot so I feel like we're missing something

[topaz sinew]

@robust jasper Has your question been resolved?

[robust jasper]

Here ill show you sry

[robust jasper]

Oh ok good to know, no yeah that makese sense what you said there

[rose thorn]

Ah oki. Yeah then theta is not a legit solution of course; do you have any question beyond that?

[robust jasper]

I dont understand why

xD

So any 1/sin 1/cos 1/tan

If its = 0

its wrong

dont include it

[rose thorn]

cotangens = cos/sin, and sin(0) = 0, so if you insert theta = 0 here then you divide by zero

So that's illegal

And idk the definition of cosec by heart but I'm guessing you also divide by sin there

[robust jasper]

1/sin

Ok

[rose thorn]

ye! 1/cos would be fine at theta = 0, because cos(0) = 1

[robust jasper]

so if you are able to

1/sin ^-1 or 1/ cos^-1 or 1/ tan ^-1 a 0

no that doesnt make sense

oof

yeah

ok

I think i got it

tyyyyyyyyyyyy

!!

apprecaite it

.close

[topaz sinew]

Channel closed

Closed by @robust jasper

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[neon iron]

when i "flip" the equation, why are the fraction brackets being flipped upside down?

[past knoll]

what is the problem here

[neon iron]

i dont understand why the 4pi^2L is being flipped to the top when the flip the equation around

[past knoll]

oh

try power (-1) for the first equation

[neon iron]

no like

its right, but i dont get it lol

im just practicing transposing

[past knoll]

u want easy way

[neon iron]

yes

WAIT

I AM SO STUPID

SORRY

I GET IT NOW

[past knoll]

just multiple few time

[neon iron]

yeah xdd

i misread something and assumed two flips were happening xD

whoops

ty anyways tho

.close

[topaz sinew]

Channel closed

Closed by @charred robin

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[woven otter]

Can someone tell me if this is correct

[left root]

are you simplifying the equation?

[woven otter]

Factorising

[lofty salmon]

yes

all good

[woven otter]

But how

My question is the position of the brackets

[lofty salmon]

huh

[woven otter]

Uhm how do i explain it .wait

For 01st one

5x(a-2b)_3(a-2b)

We take the one in the first bracket (a-2b )and then multiplying it by the number that isnt outside (5x-3)

But in the second question

a(2x+3)+b(2x+3)

We put the numbers thats were outside first (a+b) then multiplying my the brackets one (2x+3)

Making it (a+b)(2x+3)

Is there a specific order on how i should put the two brackets

[sleek gate]

no

[woven otter]

Because if i shift the two brackets wont it be wrong

[toxic grove]

multiplication (of real numbers*) is commutative

[woven otter]

Like if i turn (a-2b)(5x-3)
Into (5x-3)(a-2b ) it will be wronh

[toxic grove]

both are correct

[tulip monolith]

$xa - ya$ how do you factor out a?

[toxic grove]

think about it, 7 x 9 is same as 9 x 7

[thorny flame]

ColdTee

[tulip monolith]

$a(x - y)$ is not the same as $a(y -x)$

[thorny flame]

ColdTee

[woven otter]

But like if we expand the bracket .it wont give the same number

[woven otter]

These two

[tulip monolith]

you are just factoring out (a - 2b) and (2x + 3) in this case

[tulip monolith]

it wont

matter

since multiplication is commutative

$a \times b = b \times a$

[thorny flame]

ColdTee

[woven otter]

So it doesnt matter in which way the brackets go?

[tulip monolith]

what do you mean

exactly

[sleek gate]

it gives you the same

try to do it

[woven otter]

Ohhh ok i understand

[tulip monolith]

if you do something like (3 - 5x)(a - 2b) that will be wrong

[sleek gate]

they are exactly the same

see?

[woven otter]

Ohh

Oki thx

Hv a nice day

.close

[topaz sinew]

Channel closed

Closed by @woven otter

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[river jetty]

so 57 and 70 and |H and K| must divide |G| (by Lagrange's theorem), then what?

[keen venture]

(H and K) is a subgroup of H, and is a subgroup of K.

[lofty salmon]

normal subgroup*

[topaz sinew]

@river jetty Has your question been resolved?

[river jetty]

ohhh

thanks for pointing that out

makes sense now

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fierce zealot]

If $n$ is a pseudo prime to $2 \in Z_{n}$, then $N = 2^n - 1$ is a pseudo prime to $2 \in Z_{N}$

[thorny flame]

WhoTao

[fierce zealot]

So by def, n being a pseudoprime to 2 in Zn means $2^{n-1} - 1 = nk$ for some integer k.

[thorny flame]

WhoTao

[fierce zealot]

Then Im not sure what to do

[topaz sinew]

@fierce zealot Has your question been resolved?

[topaz sinew]

@fierce zealot Has your question been resolved?

[topaz sinew]

@fierce zealot Has your question been resolved?

Channel closed

Closed by @fierce zealot

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[neon iron]

how'd they go from line 2 to 3

[sweet shard]

that handwriting makes it impossible to tell

[neon iron]

ikr

first line is

semi-readable

@sweet shard how about this

[sweet shard]

what about this

[neon iron]

how do they go from 1 to 2

[sweet shard]

,tex .exp rules

[thorny flame]

riemann

[neon iron]

$\frac{\sqrt[3]{(-4)^2}}{3} \cdot \frac{-5\pi}{16\pi ^2}$

[thorny flame]

wyldinwilliam

[neon iron]

$\frac{-5\pi \sqrt[3]{(-4)^2}}{48\pi^2}$

[thorny flame]

wyldinwilliam

[neon iron]

$\frac{-5\pi \sqrt[3]{(16)}}{48\pi^2}$

[thorny flame]

wyldinwilliam

[neon iron]

$\frac{-5\ \sqrt[3]{(16)}}{48\pi}$

[thorny flame]

wyldinwilliam

[neon iron]

$-\frac{5\ \sqrt[3]{(16)}}{48\pi}$

[thorny flame]

wyldinwilliam

[neon iron]

@sweet shard closest I could get to the answer

[sweet shard]

16 = 2^4

and 4 = 3 + 1

[neon iron]

$-\frac{5\ \sqrt[3]{(2)^4}}{48\pi}$

[thorny flame]

wyldinwilliam

[neon iron]

$-\frac{5\ \sqrt[3]{(2)^{3+1}}}{48\pi}$

[thorny flame]

wyldinwilliam

[neon iron]

are you suggesting we cancel the cube root?

[sweet shard]

try it

[neon iron]

try what exactly

$-\frac{5 (2)^{1}}{48\pi}$

[thorny flame]

wyldinwilliam

[neon iron]

$-\frac{5}{24\pi}$

[thorny flame]

wyldinwilliam

[neon iron]

going to be honest here, don't think those two expressions are equal

[sweet shard]

no

$\sqrt[3]{2^{3+1}} = (2^{3+1})^{1/3}$

[thorny flame]

riemann

[sweet shard]

use this to simplify the exponent

[neon iron]

I figured it out but without all the headache of adding exponents lol

basically just 2^4

is 16

so cuberoot 16

= 8^1/3 *2 ^1/3

8^ 1/3 = 2

2 simplifies with denom

therefore giving use 24pi

$\sqrt[3]{16}$

[thorny flame]

wyldinwilliam

[neon iron]

$\sqrt[3]{8\cdot2}$

[thorny flame]

wyldinwilliam

[neon iron]

$8^{\frac{1}{3}}\cdot2^{\frac{1}{3}}$

[thorny flame]

wyldinwilliam

[neon iron]

$2\cdot2^{\frac{1}{3}}$

[thorny flame]

wyldinwilliam

[neon iron]

but idk if this is the easier way

[topaz sinew]

@neon iron Has your question been resolved?

Channel closed

Closed by @barren orbit

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[elfin cliff]

.reopen

what is 40 as expanded form

[topaz sinew]

Please don't occupy multiple help channels.

[elfin cliff]

ok

[acoustic pecan]

2(20)(lne)(lim{x to 0} sin(x) /x )

.close

[topaz sinew]

Channel closed

Closed by @acoustic pecan

Use .reopen if this was a mistake.

[elfin cliff]

.reopen

[topaz sinew]

✅

[elfin cliff]

What is .20 x 360

[acoustic pecan]

use a calculator

.close

[topaz sinew]

Channel closed

Closed by @acoustic pecan

Use .reopen if this was a mistake.

[elfin cliff]

.reopen

[topaz sinew]

✅

[elfin cliff]

I dont hav one

[acoustic pecan]

you have the internet

[elfin cliff]

yea, ur right

.close

[topaz sinew]

Channel closed

Closed by @elfin cliff

Use .reopen if this was a mistake.

[elfin cliff]

.reopen

[topaz sinew]

✅

[elfin cliff]

Give me a grade 7 term 2 question

.close

[topaz sinew]

Channel closed

Closed by @elfin cliff

Use .reopen if this was a mistake.

[scenic flare]

How many times does SmellyLemon need to reopen and close a channel until something unnice happens? would be my grade 7 term 2 question.

[elfin cliff]

ok, ill leave the server

[acoustic pecan]

bon voyage

[elfin cliff]

.close

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tight kiln]

need help

[acoustic pecan]

what have you tried

[tight kiln]

i literally dont know this

one

need a formula or smth to help

[acoustic pecan]

soh cah toa

[tight kiln]

hmm

i know this

so do i use soh for this?

[ivory wave]

yep

[tight kiln]

x/4.1

then what

[ivory wave]

what do you think you could do after

butterfly method basically

[ivory wave]

but you have forgotten something

before x/4.1

something = x/4.1

can you tell me what is something will be?

[tight kiln]

sin

[ivory wave]

sin what

make sure you add the angle

[tight kiln]

sin 40\

[ivory wave]

good

now you have sin 40=x/4.1

[tight kiln]

so sin 40 =x/4.1

[ivory wave]

exactly

solve for x now

[tight kiln]

lemme figure what sin 40 is first

[ivory wave]

use a calculator

[tight kiln]

ye ima do it

it says 0.745

[ivory wave]

yea and what about the final answer you got it?

[tight kiln]

some where else it says sin 40 is o.642

0.642

[ivory wave]

,calc sin(40)

[thorny flame]

Result:

0.74511316047935

[tight kiln]

hmm

[ivory wave]

it should be this

[tight kiln]

so how do i get x

i gotta fill in the blank

[ivory wave]

you have to do the butterfly method

[tight kiln]

its like around 3 ish right

[tight kiln]

whats that

[ivory wave]

its like multiplication

[tight kiln]

its in between 3 and 3.1

[ivory wave]

no not like that

[tight kiln]

its 3.055 basically

[thorny flame]

Result:

0.18170731707317

[ivory wave]

hmm

[thorny flame]

Result:

5.503355704698

[ivory wave]

how did you get this?

[tight kiln]

kept pluggin in

[ivory wave]

its not like that

[tight kiln]

so whats the answer

[ivory wave]

when you have this expression $\frac{\sin(40)}{1}=\frac{x}{4.1}$ you do the butterfly method

[thorny flame]

MSC2020 11N36 (Akira)

[ivory wave]

after that

you'll get your answer

[tight kiln]

its 3.055 though

[ivory wave]

,calc 4.1 * 0.745

[thorny flame]

Result:

3.0545

[tight kiln]

ah

[ivory wave]

you got it

[tight kiln]

545

hmm

aight is that the answer?

[ivory wave]

yes

[tight kiln]

alr bet

[topaz sinew]

If you are done with this channel, please mark your problem as solved by typing .close

[tight kiln]

,calc sin 37

[thorny flame]

The following error occured while calculating:
Error: Unexpected type of argument in function multiplyScalar (expected: number or Complex or BigNumber or Fraction or Unit or string or boolean, actual: function, index: 0)

[topaz sinew]

@tight kiln Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[slender sonnet]

Wich equation is correct for the diagram?

[hollow drum]

Use the intercepts

What are the coordinates of the x intercept?

[neon iron]

(5,0)

[sweet shard]

no one's asking you

[slender sonnet]

5,0

[hollow drum]

Wasn't asking you

[neon iron]

so rude for no reason

[slender sonnet]

And y is 0,3

Its ok guys

That was not a hard question

[hollow drum]

So you know that that if you plug in the x value then you result in the y value

You know the x is 5, then you should result in 0

[slender sonnet]

So i plug in x?

As 5?

[hollow drum]

Same process for the y intercept

[hollow drum]

Yes

[slender sonnet]

And plug y as 3?

[hollow drum]

Yes

[slender sonnet]

And i need to get what?

Zero?

[hollow drum]

For 0, 3 you plug in 0 for x and should result in 0 as y

[slender sonnet]

So i don’t get it do i plug in 5 as x in every equation?

[neon iron]

find the slope first, then plug in either of the coordinates to find b

[neon iron]

5,0 or 0,3

[hollow drum]

You can do that but if given the equations, you can plug in the points

[neon iron]

oh yeah i didnt see that pic

[hollow drum]

So the x intercept is (5, 0), then plug in 5 as x into all the equations see which results in 0

[slender sonnet]

Ok when i plug it in what should i get

So i should get answer 0?

[hollow drum]

Then using the y intercept, (0, 3) if you plug in 0 for x, you should result in 3

[hollow drum]

Yes

Because the equations are y = mx + b

[slender sonnet]

And the equation thag satisfis both is the correct one?

[hollow drum]

Take the first choice, y = 5x + 3, if you plug in the x value from the x intercept, (5, 0), which is 5. Plug in 5 into that equation for x, what do you result in?

[slender sonnet]

25+3

[hollow drum]

Equals what?

[slender sonnet]

3?

Or y

[neon iron]

the y coordinate is 0

so that equation doesnt work

[slender sonnet]

Ohh so 0

28 equals 0

So thats wrong

[hollow drum]

y = 5x + 3, you plugged in 5 for x, so y = 5 * 5 + 3, you get y = 28

But the coordinate was (5, 0) the y value is 0

[slender sonnet]

Second one is right

I think

[hollow drum]

28 does not equal 0

[slender sonnet]

I get y 0

[hollow drum]

Check with the other intercept

(0, 3)

Plug in 0 for x, what do you get?

[slender sonnet]

That would give me zero

So no

[hollow drum]

Are you sure?

Did you plug 0 for x?

The equation is y = -(3/5)x + 3

[slender sonnet]

So that would give 3

So it is the correct one

[hollow drum]

Yes

[slender sonnet]

But do i not need to plug 3 into y?

[hollow drum]

Why?

You can plug in 0 for x

And find out what value you get

[slender sonnet]

Like here

[hollow drum]

You are given a set of coordinates, you can just plug in the value for x and see what y value you result in

Given (0, 3), you can just plug in 0 for x and see if you get 3 for y

[slender sonnet]

Oh ok i got it thanks

[neon iron]

if you plugged in the 3 in the y coordinate the equation would become 3=3

which works

[topaz sinew]

@slender sonnet Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lilac nymph]

A plane parallel to the axis of the roll divides the arc of the roll base in a ratio of 2:1. The length of the height of the roll is 16, and the length of the radius of the base is 5. Calculate the cross-sectional area.

[lilac nymph]

i do believe it looks something like this

[topaz sinew]

@lilac nymph Has your question been resolved?

[topaz sinew]

@lilac nymph Has your question been resolved?

[topaz sinew]

@lilac nymph Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[half oracle]

Hi, could I get help with this?

[gray ridge]

do what know what is square root property?

[half oracle]

sorry i just realized you texted. not really tbh

[gray ridge]

oh ok

[gray ridge]

https://study.com/learn/lesson/square-root-property.html

you can read this first

[half oracle]

okay i'll let u know when i'm done reading it

it wouldnt letme read or watch the video fully because i'm not a member on the website

[gray ridge]

it's alright

you can just read the first few paragraphs

[half oracle]

okay

[gray ridge]

the main point is if $x^2=a$, then $x=\pm\sqrt{a}$

[thorny flame]

Biscuity

[half oracle]

hmm okay

[gray ridge]

we have + version and - version

[gray ridge]

now we work on this

firstly we have
3x²=39
agreed?

[half oracle]

ohh we take away the 0?

[gray ridge]

nah, we didn't take away the 0

3x²-39+39=0+39
do you recall this method?

[half oracle]

no

[gray ridge]

oh...

[half oracle]

are we not just moving the 39 to the other side of the equals sign

[gray ridge]

we can't just move things around the equal sign

for example
x+1=3, we can't just move x=3+1 or else it will be wrong❌

[half oracle]

right but we also changed the sign of the 39

[gray ridge]

we need to do the reverse of the operation,
e.g. if we have +, we do -
if we have -, we do +
if we have ×, we do ÷
if we have ÷, we do ×

[gray ridge]

that's correct

[half oracle]

so is that how you removed the zero

[gray ridge]

well, 0+39 is 39

if that's what you mean😁

[half oracle]

i think we're on the same page lol

[gray ridge]

anyways whats the next step after
3x²=39

(your turn)

[half oracle]

we divide 39 by 3?

[gray ridge]

both sides by 3, yes

[half oracle]

okay so it'd be x^2=13?

[gray ridge]

Correct

next we will have x=±√??

[half oracle]

wdym?

[gray ridge]

next we take square root on both sides

so for x² side, we have x

and for
13 side, we have ±squareroot(13)

[gray ridge]

recall:

[half oracle]

so... x=±square root of 13

?

[gray ridge]

side note: ±something means
"positive something or negative something"

[half oracle]

so since 13 doesnt have a perfect square root, would the answer be √-13, V13?

√13 i mean

[gray ridge]

that is eg
$$x=\pm\sqrt{13}$$
$$x=\sqrt{13}\text{ or }-\sqrt{13}$$

[thorny flame]

Biscuity

[gray ridge]

careful

the negative is outside the squareroot

[half oracle]

ahh okay thanks for pointing that out

and i think that makes sense now! than you for your help biscuit

[gray ridge]

Cheers!

[half oracle]

.close

[topaz sinew]

Channel closed

Closed by @half oracle

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[neon dune]

i need help

[neon dune]

i dont know how to enter this as a matrix

<@&286206848099549185>

[neon iron]

<@&286206848099549185> what does recursive formula means and what do we mean also by closed formula please

[sweet shard]

!occupied

[topaz sinew]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[neon dune]

<@&286206848099549185> can someone help me here please

.close

[topaz sinew]

Channel closed

Closed by @neon dune

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crimson glacier]

oh wboops

sorry

[lilac lily]

no its alright

[crystal goblet]

!status

[topaz sinew]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[crimson glacier]

uh so

i tried to substitute

2 into the eq

but i got a=2

but answers say a = 1

wait

nvm

[crystal goblet]

You have made a mistake in calculating

[crimson glacier]

ok! i got it

yep

lol i did ax^3 instead of x^4

[topaz sinew]

@crimson glacier Has your question been resolved?

Channel closed

Closed by @crimson glacier

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[trim trench]

is there a step-by-step method i can follow to find out if this is/isn't a vector space and what properties it might violate?

[worthy storm]

is the addition commutative?

for a step by step method, you could just walk through the vector space axioms one by one and see if any are violated

[trim trench]

ah x + x' should = x' + x but it doesn't

okay

if it fails that property does it also mean it isn't closed under vector addition?

or are those two separate

[worthy storm]

well it's closed under vector addition by definition, since (x', y+y', z') is in V

but it's not a well-behaved addition since commutativity is violated

[trim trench]

okay thank you!

.close

[topaz sinew]

Channel closed

Closed by @trim trench

Use .reopen if this was a mistake.

[trim trench]

.reopen

[topaz sinew]

✅

[trim trench]

hold the phone.

is this an example of it not being closed under vector addition? that being (a,b) aren't in R

or are those just variables

[worthy storm]

a and b are in R

so are c and d

therefore so are ac and bd

so it's closed under addition

[trim trench]

when is it not closed under an operation?

[worthy storm]

if you restricted your definition of V

for example:

V = {(x,y) : x and y are in R and x < 1 and y < 1}

that won't be closed under addition

(the usual addition)

but since you're starting with V = all of R^2, you'd have to define an addition that either delivers a 2-d vector of things that aren't real numbers, or something that isn't a 2-d vector at all

for example:
(a,b) + (c,d) = i(a+b, c+d)
where i = sqrt(-1)

or

(a,b) + (c,d) = (a+b, c+d, a-b)

[trim trench]

i'm trying to picture it in my head

would this be an example of something not being closed under vector add.

V = {(x,y) : x and y are in the set of counting numbers and x < 0 and y < 0}

[topaz sinew]

@trim trench Has your question been resolved?

[worthy storm]

that's still closed, because negative + negative = negative

oh wait, set of counting number and x < 0 and y < 0

aren't counting numbers positive (i.e. the naturals)

[trim trench]

yea they are

ran a few more exercises, do these look right?

i feel like i've got it down

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jade scarab]

it says "Determine all the eigenvalues ​​and associated eigenvectors of the matrix" could someone help me solve this?

[outer ledge]

You know what eigenvalues are, right ?

[jade scarab]

yes i have written up the |A-lambda*I| matrix but i have the most trouble solving the matrix

I think it’s like this?

[outer ledge]

Yeah great now solve for $\lambda$

[thorny flame]

Solomaniac

[jade scarab]

well that is what i have truouble with

like i dont know what to eliminate

[tulip monolith]

what do you mean?

[jade scarab]

nevermind but i got lambda1 = 5

[tulip monolith]

did you find the determinant?

[jade scarab]

and lambda 2 = 7

[tulip monolith]

lamda3?

[jade scarab]

i only got two

[tulip monolith]

that's weird

[jade scarab]

i eliminated the first line from the second and then lamba dissepear from the second line

[tulip monolith]

can you show

your work

It's difficult to understand what you mean exactly

[jade scarab]

how do i rotate

[tulip monolith]

i dont know for anti

[tulip monolith]

,rcw

[tulip monolith]

this seems more difficult

[jade scarab]

well how should it do it?

[tulip monolith]

I meant rotating

[jade scarab]

oh

[outer ledge]

Try subtracting the rows and columns from each other.

[tulip monolith]

But your lamda values seem wrong

[jade scarab]

okay

[tulip monolith]

Let me check

,w x^3 - 2x^2 - 35x - 637 = 0

that's

absurd

[jade scarab]

haha

[tulip monolith]

wait a min

[tulip monolith]

,w x^3 - 2x^2 - 35x = 0

[thorny flame]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by coldtee

[tulip monolith]

Im so dumb

anyways

lamda 1,2,3 = -5,0,7

[jade scarab]

yes okay!

and now we put it in to the matrix?

[tulip monolith]

yes

[jade scarab]

and we get 0 for the first -7 for the second and -3 for the last?

no sorry

i did it in the wrong order

we get 12 at the top -7 in the middle and -5 at the bottom

[tulip monolith]

can you show

it

[tulip monolith]

you put in -5?

[jade scarab]

Yes 2-7 is -5

And 7–5 is 12

[tulip monolith]

you put lamda = 7

[jade scarab]

Lambda 1 = -5 lambda 2 = 0 and lambda 3 = 7

[tulip monolith]

you have to solve them seperately

[jade scarab]

Ohh I forgot

[tulip monolith]

if you are taking a value for lamda that goes for the whole matrix right

[jade scarab]

okay i solved the matrix for -5 and got 1 and 0

and for 0 i got 0 and -1

and for 7 i got -1 and -1

[tulip monolith]

can you show the calculations

[jade scarab]

i can show you the matrixes but i did not write down when i did gauss elimination

[tulip monolith]

sure

[jade scarab]

Sorry for my handwriting

[tulip monolith]

seems correct

[jade scarab]

Or am I supposed to get three answers?

[tulip monolith]

yes since you have three values

you have to find eigenvector

for each

,w x - y + z = 0, 7x - 2y + 7z = 0

[thorny flame]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by coldtee

[tulip monolith]

that's for the first one

[jade scarab]

Okay but why does it only have two answers

[tulip monolith]

which one

[jade scarab]

I mean wolf it got 0 and -1

[tulip monolith]

it got three?

which one are you talking about

[jade scarab]

This one what is the third 0?

[tulip monolith]

y = 0, z = 1 , x = -1

(-1,0,1)

[jade scarab]

Ohh sorry I see now

Okay I will calculate again and see if I get the third one but thank you for the help!

[tulip monolith]

Alright

np

Is that a random cat

[jade scarab]

Yes haha

[tulip monolith]

looks like jiji but small

[jade scarab]

Haha I just found it online so I’m not sure

[tulip monolith]

Looks cute

[jade scarab]

Yes it does!

.close

[topaz sinew]

Channel closed

Closed by @jade scarab

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dusk sluice]

Hello
Write two expressions that:
a) Their product equals to a-2/a+7
b) Their sum equals to a-2/a+7

thanks for ur help

[ionic oar]

I think we're missing something here

Can you provide the original question

[dusk sluice]

that the original question

it said write 2 numbers that:
xy=a-2/a+7
x+y=a-2/a+7

like that

[ionic oar]

ah okay

are you sure you're not

!xy

[topaz sinew]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[ionic oar]

because this feels like a Vieta's thing

[reef fjord]

hmm..i think it just wants them to rewrite

[dusk sluice]

its not

[reef fjord]

rewrite (a-2)/(a+7) as a product and rewrite (a-2)/(a+7) as a sum?

[dusk sluice]

yes

[ionic oar]

I mean

You can assume it to be something simple like c for now

$xy = c$ and $x + y = c \implies x + \frac{c}{x} = c$

[thorny flame]

NEON

[ionic oar]

you can solve that equation

and then also find y

and then put back c in terms of a

[dusk sluice]

can you explain it more
or for example find x

[ionic oar]

Multiply the whole equation with x

Have you solved a quadratic before?

[dusk sluice]

no

ax^2+bx+c=0?

[ionic oar]

hmm

yes

[dusk sluice]

i didnt

im in 9th grade

idk anything about that formul

a

[ionic oar]

Isn't this stuff taught in 8th grade

Anyways uh

[dusk sluice]

no

[ionic oar]

Its out of scope then

[dusk sluice]

and...
how can i solve it

[ionic oar]

You can't :/

Skip it for now and ask your teacher about it

[dusk sluice]

u to?

[ionic oar]

I can but

That won't be of any use to you

[dusk sluice]

the formula that you do to answer that its not importent i only want the answer untill i meet my teacher again

[ionic oar]

I can give you the quadratic formula alright if that's what you're asking

[thorny flame]

NEON

[dusk sluice]

how can i use quadratic formula in that question

[ionic oar]

identify what a, b, c are

in your case

and plug them in

[dusk sluice]

how can i identify them?

[ionic oar]

a is the coefficient of x^2, b is the coefficient of x and c is the constant term

[dusk sluice]

i prefer to ask my teacher

[topaz sinew]

@dusk sluice Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[carmine pelican]

[outer ledge]

Do you know the angular coordinate system ?

[carmine pelican]

3d?

[outer ledge]

No no

[carmine pelican]

o

[sonic hemlock]

Let u = r(cos 60 i + sing 60 j)
Now proceed and find r

[carmine pelican]

Ohhh

[outer ledge]

Rectangular coordinate system is one with the axes at 90°. This system has axes at 60°, I believe.

[carmine pelican]

so it was sin 60

I was takin cos 60 in j too

[outer ledge]

Ohhh no no no.

[carmine pelican]

Iccic

[outer ledge]

I complicated the question too much.

[carmine pelican]

o

[sonic hemlock]

Ah i see

well it's because i'm assuming it's a planar system

so the angle wrt y axis is 90 - 60

so sin 60

[carmine pelican]

yea that makes sense why they say rectangular

[carmine pelican]

90-60 so sin 30 no?

[sonic hemlock]

no u need to the cosine of that

cuz it's sloping 60 degrees wrt to the x axis

[carmine pelican]

oh yea im tripin

[sonic hemlock]

again i'm assuming it's all on a single plane and not 3d

[carmine pelican]

okok imma try ty

[sonic hemlock]

my pleasure :D

[carmine pelican]

@sonic hemlock you jee 2024 too

damn

so many jee aspi here

[sonic hemlock]

xD

u too?

[carmine pelican]

yee

[sonic hemlock]

oh nice lol

[carmine pelican]

howd ur jan went

[sonic hemlock]

not that great
uk 27th jan shift 1

[carmine pelican]

ah fucj

Dw 27s1 was fucjed up

[sonic hemlock]

i scored 210 :(
and still got a 97.5 sadge

how bout u?

[carmine pelican]

Damn

Youll do great in adv

Dwdw

[sonic hemlock]

hope so lesse xD

u too o7

[carmine pelican]

I had 31s1

got a bit lucky

[sonic hemlock]

oh dem xD
how'd it go

[carmine pelican]

99.66

i feel a bit

[sonic hemlock]

wow nice o77

[carmine pelican]

dunno i was just lucky

mains is fucked up now

[sonic hemlock]

nah man it's more than luck

[carmine pelican]

[topaz sinew]

@carmine pelican Has your question been resolved?

[carmine pelican]

im gettin

r = -1

somehow