#help-26

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noble laurel
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Okay

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It says that this is obvious because e^1 is 2.71… so if |x|<1 e^x-1 will be at most 1.71.. and related by what |x| actually is, of course as x-> it’d approach 0 which is exactly what’ you hope for here

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We prove that f(x)=e^x, the natural exponential function, is continuous on its entire domain - the real numbers. We complete this proof using the epsilon delta definition of continuity of a function at a point. To do this, we simply take an epsilon greater than 0 and an arbitrary point c from our domain, then go through the motions of finding a ...

β–Ά Play video
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I’d like to explain but I have to go and this is probably better anyways

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Skip to about 5 minutes if you wish

hasty bane
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hoary wraith
#

Good Evening!
Can someone explain to me why we dont need to divide the 2 by k aswell?

pastel salmon
pastel salmon
hoary wraith
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And in the denumerator we also divide all products?

pastel salmon
hoary wraith
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But I think I see it

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Was just wondering

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because you can also multiply by 2 first

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and receive 2k + 2 and then divide that by k

pastel salmon
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2 is safe alone

hoary wraith
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Bit late here, thanks!

pastel salmon
#

yw)

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placid temple
#

hello

topaz sinewBOT
placid temple
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Hello in statistics, I do not understand the difference between discrete random variable and absolutely continuous random variable.

Is it in the 1st case something that can be counted and in the 2nd case something that cannot be counted?

pastel salmon
placid temple
pastel salmon
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like

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0, 1, 2, 3, 4, 100000000

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etc

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countable set is the set you can assign to natural numbers

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and

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the exampoel fo continuous is:

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Let's assume that you are interested in the height of students in your country, but there are too many universities to measure them all, then you set the distribution based on an n-element random sample, and the index can take any value from the range, e.g. [140, 210] - their height

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certaibly the precision of tools also is imporant but we extrapolte our measure into ideal world continous one

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these above are the typical ones

placid temple
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Ok so in the case of discrete it is something that we know precisely and in the case of continuous it is something that we estimate but do not know precisely ?

pastel salmon
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ok ?

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0, 1, 2, 3, - dioscrete

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and if numbers you get, with any precision from interval

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  • continuous
placid temple
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Ok I see

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thank you very much

pastel salmon
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yw

topaz sinewBOT
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sick oasis
topaz sinewBOT
sick oasis
#

what does z bar mean in this context? (linear algebra problem)

acoustic pecan
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it would mean complex conjugate here

sick oasis
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so like z = a + bi so zbar = a - bi?

acoustic pecan
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exactly so

sick oasis
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oh okie, perfect

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thank you!!

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late quiver
topaz sinewBOT
late quiver
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help me king

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im doing exponetial functions

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πŸ›‘ help needed please πŸ›‘

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placid temple
#

Statistic

topaz sinewBOT
placid temple
#

Convergence in law

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The sequence (Xn) converges to continue bounded we have :

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Example 1 : . Let X_n ∼ B(p+ (1βˆ’p)/n) with p ∈ (0, 1), then (X_n) converges to a random variable

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Example 2 : Let X_n ∼ E(λ_n) and λ_n -> +∞ when n -> + ∞ then we can see that (X_n) converges in law towards the null variable

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I don't understand the example 2

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twin heath
#

why are you allowed to substitute (A-B/2) and (A+B)/2) into part of the product to sum rule to get the sum to product rule? every video I've seen just takes it as granted that you plug those in as a and b, but I don't see why I couldn't just plug anything in at that point

twin heath
#

I don't really get how the sum to product rule is derived

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balmy bolt
topaz sinewBOT
balmy bolt
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what is an

noble laurel
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the sequence that you are summing

topaz sinewBOT
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@balmy bolt Has your question been resolved?

balmy bolt
#

is that not right

rigid ivy
balmy bolt
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can u tell me and explain it to me LOL

rigid ivy
#

You neglected the sign

balmy bolt
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i dont get it

#

which sign

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clear knot
#

COVID-19 is present in 10% of the population. There's also a test that correctly tests positive with 95% accuracy, and incorrectly tests positive with 10% chance.

clear knot
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If a random person tests positive for COVID, what's the chance they actually have COVID?

sweet shard
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Use bayes theorem

clear knot
sweet shard
clear knot
clear knot
sweet shard
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Oh I approve

clear knot
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0.185 is P(testpositive for covid) btw

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i think is 0.185 cuz 0.10*0.95+0.9*0.10

topaz sinewBOT
#

@clear knot Has your question been resolved?

clear knot
# sweet shard Oh I approve

A random person is given 2 covid tests, both come back positive. These tests are independent what's the chance the person actually has covid?

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steel lodge
#

Hello I am trying to solve this question, it is a grade 10 highscool trignometry question, i am not sure how to solve a) and b) please help

steel lodge
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@knotty finch could someone help?

gray ridge
steel lodge
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oh okay

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so what i dont get is if its labelled point a -b is 15cm wouldbt b - a be the same?

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but when i checked the answers its showing 14.77

gray ridge
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to tackle this question, let's name something first

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for (a) it says to find "how far east"

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that is actually to find AX

steel lodge
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ohh okay so it would we use sin 0?

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like using 0 as theta

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theta is 10 so

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sin(10) x/15 ?

gray ridge
gray ridge
steel lodge
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so cosine

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yeah

gray ridge
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so cos(10deg) = AX/15

gray ridge
steel lodge
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Yes thanks you

gray ridge
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good

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i bet you know how to do b now

steel lodge
#

yeah thanks a lot

gray ridge
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but just be careful it's in millimetre

steel lodge
#

πŸ‘

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sharp dew
#

how do I distinguish between a rational number and a irrational?

sharp dew
#

let's discuss

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1.every number (except perfect square) inside a square root results in a irrational number.

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2.A lots of well-known yet frequently used constant like pi, euler, light speed, etc. are also irrational too.

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does anyone want to add something in the discussion.

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this is a discussion for irrational number identification.

abstract wadi
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  1. Irrational has nothing to do with non perfect squares and famous constants.
sharp dew
abstract wadi
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I do not.

sharp dew
#

a counter example, please?

abstract wadi
#

Check my pfp.

sharp dew
#

ohhh

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damn

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damn

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imaginary number

abstract wadi
#

You said "every number"

odd pagoda
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the most famous constants like 0,1,2 etc are all rational

sharp dew
#

okay, alright. I will fix the statement

sharp dew
odd pagoda
#

no

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sqrt(9/4)

sharp dew
odd pagoda
#

that wouldnt usually be called a perfect square

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perfect square usually also means integer

sharp dew
hardy prism
sharp dew
#

i'm perplexed

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there's a lot of flaws on my statement

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i will take a 5 mins break, then we will continue the discussion.

hardy prism
#

Ok

sharp dew
#

The discussion is being canceled by Mickey Mouse.

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sharp dew
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sharp dew
topaz sinewBOT
#

Please don't occupy multiple help channels.

sharp dew
#

considered triangle ABC, sinA:sinB:sinC=2:3:4, then cosA / cosB = ?

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above is the question after being translated into English.

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I had stuck on this one

topaz sinewBOT
#

@sharp dew Has your question been resolved?

topaz sinewBOT
#

@sharp dew Has your question been resolved?

pulsar sun
#

direct applications

sharp dew
pulsar sun
#

ratio means $\sin A = 2x, \sin B = 3x, \sin C = 4x$

thorny flameBOT
#

γ‚«γƒŠγƒ΄

pulsar sun
#

by sine law

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By sine law, \
$\frac{\sin A}{a} = \frac{\sin B}{b} = \frac{\sin C}{c}$\
$\Rightarrow \frac{2x}{a} = \frac{3x}{b} = \frac{4x}{c}$\ \
Let the above equation be eqn. 1
By cosine law, \
$\cos A = \frac{a^2 + b^2 - c^2}{2ab}$\
$\cos B = \frac{b^2 + c^2 - a^2}{2bc}$

thorny flameBOT
#

γ‚«γƒŠγƒ΄

pulsar sun
#

Then from equation 1 we can isolate a and b in terms of c

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substitute in cos A and cos B formulae and then find the ratio

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@sharp dew do u now understand

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robust jasper
topaz sinewBOT
robust jasper
#

u3= ln16

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u7=ln256

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I’m a bit stuck

pulsar sun
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what do u need to find

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a and b?

robust jasper
#

Arthumetric sequences

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Yes

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a is the first n=1 term

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b is the (common difference)

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n is just yk n=1 n = 2 n = 3, the terms

pulsar sun
#

not really an AP with the ln

robust jasper
#

AP?

pulsar sun
#

well u messed up in ur working

pulsar sun
robust jasper
pulsar sun
#

$\ln 16 = \ln a + 2\ln b$ \ \
$\Rightarrow e^{\ln 16} = e^{\ln a + 2\ln b}$ \ \
$\Rightarrow 16 = e^{\ln a} \cdot e^{2\ln b}$ \ \

thorny flameBOT
#

γ‚«γƒŠγƒ΄

pulsar sun
#

meaning 2ab is 16

pulsar sun
robust jasper
#

oh

pulsar sun
#

also theres a better solution

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treat it as a system of equations

robust jasper
pulsar sun
#

that allows u to get $\ln 16 = 4\ln b$

thorny flameBOT
#

γ‚«γƒŠγƒ΄

pulsar sun
robust jasper
#

Oh nvm i get it

pulsar sun
#

kk

robust jasper
robust jasper
pulsar sun
thorny flameBOT
#

γ‚«γƒŠγƒ΄

pulsar sun
#

i is imaginary unit btw

robust jasper
#

wait how did we get ln 16 =4lnb

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Im a bit confused

lofty salmon
#

thats how logarithmic form works

robust jasper
#

I would understand if we got

16 = 4-1(2lnb)
6 ln b

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Ok ill have to check out logs a bit more

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tbh

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I never understoof that stuff

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thank you

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Ill have a check after this chapter again

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: 3

pulsar sun
#

np

robust jasper
#

lol

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:>

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robust jasper
#

.reopen

topaz sinewBOT
#

βœ…

robust jasper
#

Nvm

pulsar sun
#

?

robust jasper
#

But that wouldnt give me the answer

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of a and b

pulsar sun
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hmm

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eh just treat as a system of eqn

robust jasper
#

ok?

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not sure what that is lol

pulsar sun
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bruh

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do this

robust jasper
#

yessir

pulsar sun
#

subtract $\ln 16 = \ln a + 2\ln b$ from $\ln 256 = \ln a + 6\ln b$

thorny flameBOT
#

γ‚«γƒŠγƒ΄

robust jasper
#

ok

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but isnt that what I did

lofty salmon
#

do you know why

robust jasper
#

I just canceled out the ln

lofty salmon
#

good

robust jasper
#

Ig its bc i canceled out the ln

pulsar sun
robust jasper
#

no?

pulsar sun
#

hmm i must've misinterpreted then

robust jasper
#

markscheme just says find d value

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and go from there

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un = ln a + (n βˆ’ 1)ln b

u3 = ln 16 and u7 = ln 256

So uh

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ln b = d

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un = a + (n βˆ’ 1) d

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is the usual formula

.

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How do I find what d is

#

my brain

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@pulsar sun girlbleak

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Can u explain me how they got d

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tehe

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or anyone

pulsar sun
#

they did what i did 😐

robust jasper
#

blobsweat I dont know what you did

pulsar sun
#

okay see

#

we have two equations

robust jasper
#

yes

pulsar sun
#

$u_3 = \ln 16 = \ln a + 2\ln b$

thorny flameBOT
#

γ‚«γƒŠγƒ΄

pulsar sun
#

and $u_7 = \ln 256 = \ln a + 6\ln b$

thorny flameBOT
#

γ‚«γƒŠγƒ΄

pulsar sun
#

is that correct?

robust jasper
#

yes

pulsar sun
#

nice

#

now

#

if u subtract u_3 from u_7

#

u will get

#

$\ln 256 - \ln 16 = 6\ln b - 2\ln b$

thorny flameBOT
#

γ‚«γƒŠγƒ΄

pulsar sun
#

correct?

robust jasper
#

yes

pulsar sun
#

now we use log rules

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log a - log b = log(a/b)

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and also taking \ln b common

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giving us

#

$\ln \frac{256}{16} = (6-2)\ln b$

thorny flameBOT
#

γ‚«γƒŠγƒ΄

pulsar sun
#

which gives $\ln 16 = 4 \ln b$

thorny flameBOT
#

γ‚«γƒŠγƒ΄

pulsar sun
#

then we use a log b = log b^a

#

giving us $\ln 16 = \ln b^4$

thorny flameBOT
#

γ‚«γƒŠγƒ΄

pulsar sun
#

then we exponentiate both sides

#

giving us

#

$b^4 = 16$

thorny flameBOT
#

γ‚«γƒŠγƒ΄

pulsar sun
#

giving us b=2

robust jasper
pulsar sun
#

(as b is real)

robust jasper
#

I should look at log again

#

slightlyembarrassed sorrie for the waste of time lol

pulsar sun
#

which is ln b in our case

pulsar sun
#

I orignially thought a and b were functions of n πŸ˜… + ln threw me off

robust jasper
#

good for both of us I guess lol tehe

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Thank you though a lot

pulsar sun
#

np

robust jasper
#

Im going to reread the log

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rules

#

and ln

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and e^

#

xD

#

ty ty

#

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fallen plume
topaz sinewBOT
fallen plume
#

where the domain is 0 < x <=360

topaz sinewBOT
#

@fallen plume Has your question been resolved?

pulsar hedge
fallen plume
#

@pulsar hedge yes, one o the answers is 16.86 so ur correct

#

but there are two answers for the range

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neon iron
#

Is there something wrong in what i did

topaz sinewBOT
neon iron
#

The question is integral 1/(sin^2xcos^2x)

#

i divided the sin^2x in the denominator with cos^2x/cos^2x

ivory sorrel
#

,rotate

thorny flameBOT
neon iron
#

oh wait

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wtf

#

1/tan^2x = sec^2x

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i must be tripping

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ok ty 😭

#

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whole geode
neon iron
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quaint tulip
#

help

topaz sinewBOT
quaint tulip
#

oh

#

mb

#

.close

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#
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fair dagger
#

How to prove that AEC and ABC are similar triagnles? Except for that 80 angle I have no idea what to do

fair dagger
#

yes

cursive patrol
#

is one way you can do this without much strain

fair dagger
#

I swear I have never seen this theorem in my life

#

Useful to remember

#

Just need to find if I can use it in the exam without proof

cursive patrol
#

it’s usually considered a staple theorem in geometry but fair

fair dagger
#

Wait but how does it help me

#

If I don't know the lengths of the arcs

cursive patrol
#

you use central angle - inscribed angle relationship

cursive patrol
cursive patrol
# cursive patrol

as extra note.
this theorem also works with two secants… or two tangents… doesn’t have to be a secant and a tangent

fair dagger
#

Wait I need to try it I can't do it in my head

#

So In my case it will be like that

fair dagger
cursive patrol
#

yes

fair dagger
#

Good to know

cursive patrol
#

and, if the β€œline” is not a line but a line segment that is contained completely within the circle, then it is called a chord

fair dagger
cursive patrol
cursive patrol
fair dagger
#

Oh wait maybe I do

fair dagger
#

Wait just a sec

#

I mean I know how to get the number 40 but the steps feel weird

#

Because I am supposed to substitute arc lengths not the angles

fair dagger
fair dagger
topaz sinewBOT
#

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fair dagger
#

.close

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shrewd horizon
#

well the obvious idea would be to try induction

#

7 * 4^0 - 2^0 is 6, so it works for n = 0

#

so then if you take 4 * (7 * 4^(n-1) - 2^(n-1)) + 2^n

#

you get 7 * 4^n - 2^(n+1) + 2^n = 7 * 4^n - 2^n

#

...ok so yeah it's just induction

#

@lucid tiger

lucid tiger
shrewd horizon
#

well f(n) = 4*f(n-1) + 2^n

#

and the inductive hypothesis is that f(n-1) is 7*4^(n-1) - 2^(n-1), just putting n-1 into the expression 7*4^n-2^n

#

since the idea is that we're proving "f(n) = 7*4^n - 2^n" by induction

lucid tiger
#

this one is d) how?

#

@shrewd horizon ?

lucid tiger
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#

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unkempt nova
#

I think I need to calculate the partial derivative of x and y
but
given the two points
I don't know if it's possible

unkempt nova
#

<@&286206848099549185>

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calm pollen
#

Hey I don't think this is an actual math question but I was curious if anyone knew programs for the ti84 that graphs vector fields given in the form F(x,y) = something i + something j ?

calm pollen
#

i know it's possible for the cas but it's banned unfortunatley /

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#

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burnt pumice
topaz sinewBOT
burnt pumice
#

Hi, I am trying to find arc length and I’m getting stuck at integrating.. am I making the correct choice by splitting the square roots then trying to integrate them?

pastel salmon
glacial adder
# burnt pumice

$\sqrt{1+\frac{9x}{4}}$ does not equal $\sqrt{1} + \sqrt{\frac{9x}{4}}$

thorny flameBOT
burnt pumice
#

Okay I figured something was wrong.. so I am leaving it at sqrt 1+9x/4 and integrating that as a whole?

glacial adder
#

yep

burnt pumice
#

Thank you!

#

.close

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#
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neon iron
#

hi

#

hi lex

#

do u know what lim is

#

in calculus

#

how did u open help

#

i want to get help and i dont see help channel

restive inlet
#

supposedly this is about geometric sequences
if so this is just the property of the common ratio

#

do you know properties of geometric sequences?

#

yeh

#

so if you divide a term by the term before it, you'll get r

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#
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fathom crypt
topaz sinewBOT
fathom crypt
#

not particularly sure where to even start

topaz sinewBOT
#

@fathom crypt Has your question been resolved?

fathom crypt
#

<@&286206848099549185>

woven quartz
#

By Wilson's Theorem, we know that $(p-1)! \equiv -1 \pmod{p}$.
So, $x = \frac{p-1}{2}! = \frac{(p-1)!}{(p-1)/2} \equiv \frac{-1}{(p-1)/2} \pmod{p}$.

thorny flameBOT
#

Flamey

woven quartz
#

@fathom crypt

fathom crypt
#

ok so what from there?

#

@woven quartz

woven quartz
#

Since $p \equiv 3 \pmod{4}$, we have $(p-1)/2$ is an integer and $(p-1)/2$ is not divisible by $p$.
Therefore, we can cancel out $(p-1)/2$ from the numerator and denominator, and we get $x \equiv -2 \pmod{p}$.

thorny flameBOT
#

Flamey

woven quartz
#

Now, we want to find $x^2 \pmod{p}$. We have $x^2 \equiv (-2)^2 \equiv 4 \equiv 4 \pmod{p}$.
So, the value of $x^2 \pmod{p}$ is 4

thorny flameBOT
#

Flamey

woven quartz
#

@fathom crypt

fathom crypt
#

oh right ok

#

something else i found had the answer as x^2 = 1 mod p so im confused

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#

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neat wing
#

im confused what this question wants me to answer

neat wing
#

it wants me to find a solution

barren oak
#

zero

#

intersecting x axis

#

so like what point intersects it

neat wing
#

just the answer as 0?

barren oak
#

x value

neat wing
#

when i enter it

#

it says its incorrect

barren oak
#

4?

neat wing
#

yes!!!

#

thank you

#

could u help me with this last one?

#

its similar

barren oak
#

alr

neat wing
#

The set of the other solutions is

#

i guess it needs the other 2?

#

nvm got it!

#

this is similar i guess

barren oak
#

just need where y = 0

#

cuz that solution

neat wing
#

so 2?

#

am i doing that right

barren oak
#

yeah

neat wing
#

thanks so much i was so confused lol

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#

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peak yarrow
#

Hello!

topaz sinewBOT
peak yarrow
#

I was wondering how I could solve these problems

#

the first two in this are from the same problems and the bottom two are not.

urban bone
#

The domain is how far the line goes across the x-axis. The range is the same but with the y-axis.
If the highest point was at 3 and the lowest was -5 on the y axis, it would be written as -5<y<3 (assuming that the points are not filled in)
If it keeps going infinitely, it would be all real numbers

The intervals that are positive are the parts of the line that are above the x-axis line, while the negative intervals are below it

Where the graph is increasing on the intervals is where the line goes up, whilest where it is decreasing is where the line goes down.

I’m sorry for the poor explanation, but I could try to explain it better if needed ^^ (im not great with the actual terminology, just explaining)

peak yarrow
#

So you would just write the increasing on the intervals for the line that goes diagnol?

urban bone
#

Depending on whether it is positive or negative, yes.

If the diagonals slope is positive, its increasing

If it’s negative, it’s decreasing

peak yarrow
#

Alright thank u so much <33

urban bone
#

Mhm!

peak yarrow
#

Imma finish my work rq then ill close the channel cuz wow I was struggling

#

😭

urban bone
#

Alright lol

peak yarrow
#

My professor didn't post a Lecture for Lesson 7 so i was just.. struggling half the time

urban bone
#

Oof

peak yarrow
#

wait hold on-

#

which one would u do for the decreasing

#

the one on the left or the right

#

or both

urban bone
#

Both, there can be more than one spot where a graph is increasing or decreasing

peak yarrow
#

bless

#

wait wha

#

oh wait

#

.close

topaz sinewBOT
#
Channel closed

Closed by @peak yarrow

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peak yarrow
#

.reopen

topaz sinewBOT
#

βœ…

peak yarrow
#

thanks

latent veldt
#

hello help

#

Help me

peak yarrow
#

how is it -4,0? and not -1,infinity

peak yarrow
urban bone
#

Oh wait

peak yarrow
#

and i tried the previous question before this (it was diff points) and it was wrong as well

north panther
# peak yarrow

decreasing means when the derivative or the slope is negative

peak yarrow
north panther
#

are you sure bc on -1 to infinity the slope is not negative

peak yarrow
#

like i know the rules and stuff it just doesnt click to me what numbers i am meant to write

north panther
#

so interval notation basically works like [x, x]

#

and thats inclusive of the beginning x and ending x

#

(x, x) is not inclusive

#

so what x to what x does that graph have a negative slope?

peak yarrow
#

OHHHHH

#

-4,0 now i get it okay okay i thought it was the whole thing

#

😭

north panther
#

ur good

peak yarrow
#

i was losing it for a hot second

north panther
#

happens

peak yarrow
#

thank u <333

#

@north panther

#

tried

north panther
#

uhh

peak yarrow
#

oh the infinity thing is ) mb

#

and the -2 is a ]

north panther
#

well i don't think that's the whole problem with the answer

#

I think the increasing interval would be (-infinity, -2.5) U (1, infinity)

#

and the decreasing would be

#

(-2.5, 1)

#

you understand why?

peak yarrow
#

yes i do

#

wait

#

so it increases from x=1 to infinity

#

thats why its

#

(1, infinity)

#

?

north panther
#

yes

#

i'm pretty sure its wrong because of [] vs ()

#

but I don't really remember the rules for what's what

#

i would try to make them all ()

#

OHH

#

wait

#

i read the graph wrong πŸ’€

#

its not -2.5

#

its -1.5

#

i forgot how graphs work mbb

peak yarrow
#

😭

#

its okay

#

we both learnt somethings today

north panther
#

lol yh

#

change all the brackets to parenthesis and the -2.5s to -1.5s

urban bone
#

You guys answer these problems so differently from how my school does it aha (maybe its the grade difference too πŸ™)

north panther
#

wdym

peak yarrow
#

this is college algebra 😭

#

im doing dual credit

#

idk why

#

but im doin it

urban bone
#

Thats probs why lol, the way we’d input it for decreasing is -1.5<x<1

peak yarrow
#

see i wish i still did that

#

but noooo

#

interval notation 05amad

#

AYYYY

north panther
#

light work

peak yarrow
#

not light work

#

sometimes these graphs be making me wanna scream

north panther
#

it only gets worse

peak yarrow
#

yeah..

#

ik

#

😭

#

but its okay we got this

topaz sinewBOT
#

@peak yarrow Has your question been resolved?

#
Channel closed

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#
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Remember:
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β€’ Show your work, and if possible, explain where you are stuck.
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keen lance
#

Hi would anyone be willing to check over 4 calc questions?

topaz sinewBOT
#

Please don't occupy multiple help channels.

keen lance
#

Oh sorry I didn't realize I had more than one opened. I didn't see my other one in the side bar. Thought it had closed. I still don't seem to see it

neon iron
#

No problem! Just run a .close

keen lance
neon iron
#

you can't see 908078029778083872?

verbal crater
neon iron
#

yeah there you go

keen lance
#

okay thank you!

neon iron
#

but close this one, as the other has content

keen lance
#

will close this one then thanks!

#

.close

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#
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#
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digital raft
#

If f(x) = 2x+6 and g(x) = 3x

What is the simplified expression for f^(-1)(g^(-1)(x))

gray trail
#

do you know how to find the inverse of a function?

digital raft
#

Yeah, we'll get:
f(x) = x-6/2
g(x) = x/3

gray trail
#

okay so what is g^(-1)(x) using what you just said

digital raft
#

x/3

#

I am confused what you are asking for

gray trail
#

so lets break it down

#

f^(-1)(g^(-1)(x))

#

the thing in bold is what we just found

#

that is equal to x/3

#

so now all we have left to find is f^(-1)(x/3)

#

does that make sense?

digital raft
#

yes

#

So it would become:
(x/3)-6/2

gray trail
#

yes

#

you mean ((x/3)-6)/2 right?

digital raft
#

Yes, my bad

gray trail
#

okay but i think you get it so that is the answer

#

just simplify it

digital raft
#

Yeah but that is what I am confused about

gray trail
#

oh

#

ok lets ignore the denominator of that thing so we are left with (x/3)-6

#

how do we get that into one fraction

digital raft
#

(x/3)-(18/3)

gray trail
#

yes or in other words (x-18)/3

digital raft
#

yeah

gray trail
#

so we have that divided by 2

#

dividing by 2 is the same as multiplying by 1/2 right?

digital raft
#

yep

gray trail
#

so we can write it as (x-18)/3 * 1/2?

digital raft
#

Oh wait! It makes so much sense

#

thanks

gray trail
#

yes no problem!

#

happy to help

digital raft
#

.close

topaz sinewBOT
#
Channel closed

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clear vessel
#

How do I start answering this? 0.7854d^(2)=pi r^(2)

neon iron
#

Do you know d or r?

clear vessel
#

I need to find r. Idk about d

neon iron
#

!xy

topaz sinewBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

clear vessel
clear vessel
#

oh

#

how do I start solving this step by step?

neon iron
#

Do you have the whole problem? I don't believe it possible if you don't know d or r

#

You need to provide the context to this. Your question is weirdly engimatic and incomplete.

clear vessel
neon iron
#

No, is there anything else you can show?

clear vessel
#

here

neon iron
#

alright amazing

clear vessel
#

sorry for not submitting that sooner.

neon iron
#

alright great, so do you know the radius or diameter of the problem you are looking to solve?

clear vessel
#

yes

#

I am looking for r

neon iron
#

,, r = \4d2

thorny flameBOT
neon iron
#

you could use that

#

That still isn't solvable! do you have the diameter?

neon iron
#

yeah i'm dead wrong right there whoops

clear vessel
#

the answer is (1/2)d but I want to know the step by step to it if any of you know.

#

r=(1/2)d

neon iron
#

the radius is one half that of the diameter

neon iron
#

the diameter is two times that of the radius

clear vessel
#

ok, but when I set it up, I got the picture below.

neon iron
#

replace r on the right with d/2

#

yeah thata correct

#

but yes replace the r with d/2

#

and now you have the one unit you need to work with to get the answer

neon iron
#

thanks

clear vessel
#

ok so it be 0.7854d^(2)=pi (d/2)^(2)

neon iron
#

yeah

clear vessel
#

?

#

ok

neon iron
#

distribute in the exponent in $\ds\p{\4d2}^2$

thorny flameBOT
clear vessel
neon iron
#

,,\p{\4ab}^n=\4{a^n}{b^n}

thorny flameBOT
clear vessel
#

ah~

neon iron
#

so what do you get doing that

clear vessel
#

I got d^2/4. is that right?

neon iron
#

yeah!

#

Perfect!

#

so what is your full equation now

clear vessel
#

0.7854d^(2)=pi (d^2/4)

#

now what?

neon iron
#

d^2 on the right

#

remember d^2

#

Does this evaluate to d^2=d^2?

clear vessel
#

yes

neon iron
#

Right, 2 definitions for Area

clear vessel
#

ok

neon iron
#

whoops lol, gave you that one

clear vessel
#

huh?

neon iron
#

d = 0 is the only solution so something is pretty weird with this question

#

Thats what I have been thinking

#

Is this an actual problem?

#

Or just a textbook definition

clear vessel
#

the answer is r=(1/2)d btw

neon iron
#

well yes that is just true

#

Ngl I'm kinda lost

clear vessel
#

how does one get there is my problem.

neon iron
#

because radius is halfway through a circle

#

diamater is all the way across, so 2r = d

#

therefore r = 1/2d

#

this is so dumb why did they approximate [
\4\pi4 \approx 0.7854
]

thorny flameBOT
neon iron
#

idk

#

ok that was the issue

#

why do physics majors say gravity is 10m/s/s

clear vessel
#

my mind hurts~

neon iron
#

Do you understand how r = 1/2d?

clear vessel
neon iron
thorny flameBOT
clear vessel
neon iron
#

yeah

#

try 2r = d

#

although thats probably not it

neon iron
clear vessel
#

what does it mean by "the answer must match a sepecified pattern"?

clear vessel
neon iron
#

I would just take the "Note:" into account

#

Your teacher will manually grade that, and what you have is correct

clear vessel
neon iron
#

Haha, do you still need clarification on it though?

clear vessel
#

I hate math!!!! And math hates me!!!!!!!!

clear vessel
#

bye bye

neon iron
#

I'd say that program hates you, we got you all confused for a weird problem

#

Of course, ask away, remember .close

clear vessel
#

.close

topaz sinewBOT
#
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topaz sinewBOT
#
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cosmic widget
#

i am attempting to study for my GED and i simply cannot comprehend how to go about solving this problem, can someone please walk me through this

neon iron
#

the height is 45 inches

#

what is the diameter in year 13?

cosmic widget
#

i have the diameter which is 22.2 and the height 45 inches

neon iron
#

right

#

and what are you trying to find

cosmic widget
#

the square footage?

#

im not sure what i would do to go about finding that out

neon iron
#

you are trying to find the lateral surface area of thr cylinder

#

,, LSA = d\pi h

thorny flameBOT
neon iron
#

so plug it in in the above

cosmic widget
#

im very confused here as this is something ive never seen before

neon iron
#

you never studied the lateral surface area of a cylinder?

cosmic widget
#

the question i had sent was an image of the GED practice test, or high school equivalent test, so no

neon iron
#

ok so what's the circumference of a circle

cosmic widget
#

Can you detail it out for me specifically?

cosmic widget
#

i’m sorry, i watched a youtube video showing me how to find the lateral surface area and my answer was 445.8, i’m not sure if that’s right or wrong

smoky sparrow
#

22.2 Γ— 45 Γ— pi is not that

#

The circumference is pi Γ— diameter

#

That's the width of your rectangle

#

And the height is just 22.2

#

Imagine cutting the curved surface area and unrolling it

topaz sinewBOT
#

@cosmic widget Has your question been resolved?

smoky sparrow
#

I'm gonna go on a bit of a rant here

#

Imagine someone like Elon Musk comes up to you and says: "Hey, why are you reading books like To Kill A Mockingbird or Moby Dick when you could just read a 100 word summary of the book?"

#

You'd feel very weird right

#

Cause the point of reading isn't just to absorb factual information, but to enjoy what happens and what it makes you feel, the characters, the events, the highs and lows

#

Maths is just the same

#

The purpose of maths is not to get the answer: we have calculators for that

#

It's about training your thinking skills and creativity so that you can apply your knowledge to questions you might never have seen before

#

Cause there's value in thinking creatively, but also systematically and communicating that thinking clearly

#

It's a shame that maths in a lot of grade school has been reduced to memorising formulas, memorising things without really understanding why

#

It's super sad cause a lot of geometry and trig, heck even calculus can be discovered with visual intuition

#

So the next time you're thinking about maths

#

Don't just ask if your answer is right or wrong

#

If you don't understand why somrthing is true, just ask why!

#

You'll hopefully start to realise there's value in being educated and thinking for yourself rather than memorising without knowing why

topaz sinewBOT
#
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#
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β€’ Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

sour egret
#

Hello,
We did this one chapter ago and I forgot.. can someone help me with the steps towards dividing this?

sour egret
#

I looked at my old notes and I see that I have to start at the second term so everything is lined up and then I have to see what I can add to the x to make it 6x^2?

#

Not sure if that’s right

rustic finch
#

”add to the x” sounds weird

sour egret
#

Multiply ?

rustic finch
#

multiply with x+1 sure

sour egret
#

Idk what to do

rustic finch
#

maybe watch a video, polynomial division is just a procedure to follow

#

you want to multiply x+1 by something and have a 6x^2 show up

#

6x should sound good

topaz sinewBOT
#

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β€’ Type the command .close to free the channel when you're done.
β€’ Be polite and have a nice day!

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indigo estuary
topaz sinewBOT
indigo estuary
#

how do i do i)

topaz sinewBOT
indigo estuary
#

.close

topaz sinewBOT
#
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topaz sinewBOT
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Remember:
β€’ Ask your math question in a clear, concise manner.
β€’ Show your work, and if possible, explain where you are stuck.
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tough beacon
#

could someone please explain how to do this? ive been stuck on it for like 15 minutes 😭

restive inlet
#

show what you've been doing in that 15 minutes

serene wyvern
tough beacon
#

i tried making the top one into slope-interept form cause idk what else to do, and when i tried to do it normally it js looked wrong

boreal mulch
#

substitute that into (1)

tranquil grail
#

Fr

#

Do it by substituting

tough beacon
#

mk thx

topaz sinewBOT
#

@tough beacon Has your question been resolved?

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#
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β€’ Show your work, and if possible, explain where you are stuck.
β€’ After 15 minutes, feel free to ping <@&286206848099549185>.
β€’ Type the command .close to free the channel when you're done.
β€’ Be polite and have a nice day!

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jaunty phoenix
topaz sinewBOT
jaunty phoenix
#

hello can i get some hints on how to answer this question pls

#

i converted them into logs but not sure where to go from there

ivory sorrel
#

let $5^x =y$

thorny flameBOT
#

Why am. I here

outer carbon
#

YEA

#

u dont need logs

jaunty phoenix
#

Ah ok

#

It’s just it’s from a logs worksheet

#

So I assumed I needed to use logs

#

Hidden quadratic I see ty

topaz sinewBOT
#

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#
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β€’ Show your work, and if possible, explain where you are stuck.
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β€’ Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

vapid hemlock
topaz sinewBOT
vapid hemlock
#

I just need to know how to do these

#

My teacher just didn’t explain it right

#

Can somebody please give me a simple step by step on how

restive inlet
#

look up point slope formula

#

apply that then rearrange to slope-intercept form

vapid hemlock
#

Got it

restive inlet
#

or alternatively
start with slope intercept form with the given slope,
then sub in the point to determine the y-intecept / (unkown constant)

vapid hemlock
#

So -5=-4(-1)+b

restive inlet
#

are you doing Q14?

vapid hemlock
#

Yeah sorry

#

Should have said that my bad

#

But say it was number 11, do I write -2=4(0)+b

topaz sinewBOT
#

@vapid hemlock Has your question been resolved?

#
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vapid hemlock
#

Nope(;

topaz sinewBOT
#
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ivory island
#

does this mean that something here emplies g'(r) cannot equal 0 or are they just hoping it aint

ivory island
#

oh wait nvm its in cauchys mean value theorem

#

.close

topaz sinewBOT
#
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β€’ Type the command .close to free the channel when you're done.
β€’ Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

vivid ravine
#

The solution paper always skips past every step what happened between these two??

vivid ravine
#

so the one theta turned into a 1 but what about that theta in the bottom part of the fraction?

toxic grove
#

are they trying to find maxima/minima of l(theta) ?

vivid ravine
#

Its maximum likelihood so we wanna optimize Theta yea

#

basically setting it to 0

cursive thorn
#

$a - b = 0 \iff a = b$, right?

thorny flameBOT
cursive thorn
#

or am I missing something

vivid ravine
#

oh ok wait yeah i see that part now

#

and that last part? how is n/(\theta-1) extracted to only be theta

cursive thorn
#

They multiplied both sides by $\theta - 1$ and then divided both sides by the sum again

thorny flameBOT
cursive thorn
#

after that it's rearranging again

vivid ravine
#

oh god ok let me try tyty

#

maximum likelihood is gonna be the end of me

#

.close

topaz sinewBOT
#
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cursive thorn
#

You should probably learn to ignore the giant symbols and sums, and look at it like they are high-school algebra questions

topaz sinewBOT
#
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modern drift
topaz sinewBOT
modern drift
#

we dont get the elapsed time at least i dont see it so Idk how I would answer this

#

I think the way you get the displacement is 50*25 and divide that by 2

half edge
#

elapsed time is what you're trying to calcualte

#

"how long" will it take for the puck to reach a distance 50 cm away from where to was released

modern drift
half edge
#

u can rearrange the terms of the equation lol

#

you have velocity and displacement, just rearrange for time

modern drift
#

how would I

half edge
#

v = d/t

#

solve for t

modern drift
#

I get told to rearrange equations but i never understand how to, to get what I want

half edge
#

hmm

#

if a + b = c

#

how would you get a

#

solve for a

modern drift
#

c-b

half edge
#

right

#

how about x = z * r * c

#

solve for r

modern drift
#

no clue lmao

half edge
#

ok thats a serious issue, lemme see if i can find a vid for u

#

havent watched the whole thing but maybe this will help

#

algebra is very important, even in physics

#

make sure you know concepts like these before attempting problems that require these types of concepts

modern drift
#

I need the answer or at least how to solve that equation rn

#

I have a mountain of assignments and thats the last question to the lab

half edge
#

alr, well figure out how to solve for t in v = d/t

#

we can go from there

modern drift
#

t=d/v?

topaz sinewBOT
#

@modern drift Has your question been resolved?

topaz sinewBOT
#

@modern drift Has your question been resolved?

modern drift
#

.close

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#
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gleaming cape
#

Idk how to do 6B

topaz sinewBOT
gleaming cape
#

I cant even use -b/2a

crystal goblet
#

And c is the product of the x intercepts

gleaming cape
#

No

#

No i wasnt aware of that

#

but how do i do that here

#

like

#

so c = 3

#

wait c is the product

#

but, with this explanation, b = -3 and c = -4

#

which is wrong according to textbook