#help-23
1 messages · Page 420 of 1
Annie Maqionde
it is implied
you may cancel it out; if you want to be absolutely rigorous, you may write a small note on why $cos(xy) \neq 0$(then tan is undefined, right, but tan is an integer here)
Annie Maqionde
yes it is good practise, but not necessary, to do so
So for integers we can ignore it
To define both equations
Right?
well because if cos is zero, tan is undefined
yes
correct. so that $\tan(xy)$ is an integer
Annie Maqionde
so it is not necessary to say cos(a) is not zero if equations are defined on integers
you may add a small point
what it is
this one
cos(xy)=/ 0 because it is equal to some integer already
no
$\cos(xy) \neq 0$ since if $\cos(xy) = 0$ then $\tan(xy)$ will be undefined. But as stated in question, $\tan(xy)$ is an integer. Therefore $\cos(xy)$ is not zero
Annie Maqionde
something along the lines of this
I want to clear one thing only
from the step where we did xy=0
After sin(xy)=xy
here because tanx= sinx/cosx and sinx= 0 means tan 0 but here tan can't be zero it is fixed integer then this implies cos is 0 right?
since when is cos zero?
please reread our entire conversation again
@graceful lichen Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
The question is confusing when there comes 2^x and x too
What is $\log_{2}(2^x)$
Wai
This is a graph question
Sketch approximate graphs
I think x?
because of power property in log of quantity
can't we do without graphically?
Usually it’s too much to handle both exponentials and x in the same expression
Is this a Jee question
Jee Main level question
Yeah then graph
can't we use hit & trial method?
I think given that rhs is 6- x
And there's a condition of log too
Doing those is equivalent to solving it graphically right
You know graphical transformations?
initially
i am 11th moving student
And our teachers haven't taught us graph
but yeah they showed exponential graph
do you know the log graph
Yeah
Do u know the fact that log function takes only positive values ?
Yep
quantity and base should be positive
not the answer of logs but
and base shouldn't be 1
you should know graph transformations probably
graph log_2(x) then shift it 5 units left
to get log_2(x+5)
is there any animation graph website
desmos
like this?
yeah x = 3 gives log2(8) = 3 which is true
that's why your first screenshot gives the line x = 3
on your second screenshot you see the intersection at x = 3, where it's equal
ohh yes
from log_2(x+5) = 6-x
you could also have written x+5 = 2^(6-x) by log properties
so 2^x (x+5) = 64, and since 2^x (x+5) is strictly increasing as the product of 2 strictly increasing functions, it will go through 64 only once
I did here
2^x (x + 5) = 64?
ohhh
Like multiplication
your equation is log_2(x+5) = 6-x, so x+5 = 2^(6-x)
multiply by 2^x on both sides, you get 2^x (x+5) = 2^6 = 64
A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!
- H I D D E N 8 7
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
@fair hound
yes
Now what to do?
2^x (x+5) is strictly increasing as the product of 2 strictly increasing functions, it will go through 64 only once
hence the answer is 1
yes
JEE Advanced level question
hmm
I would first simplify A
is the qn saying 5 power raised to the power of 1/2 10 times?
10 times
yeah so 5 power 1/1024
yes, you simplify A, you get 1/512, and then it asks for log_sqrt(3) (2+1)
which is 2
,tex 1/2^10
- H I D D E N 8 7
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
,tex 1/2^(10)
yep
- H I D D E N 8 7
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
this qn isnt that hard eh
Lol this can't be jee adv level
I can but the section where this question belongs to is JEE advanced level (it is shown like that)
i guess this question comes in the category of atleast mains or conceptual level
Logarithm usually won't have standalone qs without other concepts in jee mains or adv
So it could be for conceptual clarity
I see that the some questions of logarithm which looks advanced but ain't is asked in jee advanced
alright thanks for the doubt have a good day
,close
.close
Closed by @stuck tusk
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
<@&268886789983436800>
Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.
Fact?
blud got hacked
Ah
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
<@&268886789983436800>
Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
tryna understand remainder theorem
where is f(a) plugged? and why is x now -1
i can see how we get 16 if u yk..add to the other side to cancel out n stuff
here's an excerpt of my own writeup of the polynomial remainder theorem (technically it's part of my proof of the polynomial factor theorem, but this part is enough for the remainder theorem).
perhaps this will help you understand a little more about the polynomial remainder theorem.
if f(x)
x + 1 =0
x = -1 /
@karmic sleet Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
.reopen
✅ Original question: #help-23 message
i dont get it
you asked why is x = -1
if we put x value in function(x), we need to find value of x first, so we find it by putting 0 in rhs, so x + 1 = 0
yeah cause...if the r is 7 that means a is 7 which means x-a should be x-7? no?
r = 7 means f(a) = 7, not a itself.
take a look here
when you put x value in polynomial f(x), then the value of polynomial will be equal to r.
again OP, may I know if you've read this?
specifically, this part right here.
i did but it was still pretty confusing for me :')
ig just...the principle of it? like
when f(x) is divided by (x-a) the remainder is f(a)
so f(a)=7
f(a) = (a-a)q(a)+7
and a-a=0 so
f(a) = 0q(a)+7...which is =7....
am i on the right track
please don't gif spam in help channels
sorry
takes up half the screen, esp. when one of your helpers has a vision-related request
yeah that looks good
ah gotcha, noted
in fact you've kinda stumbled upon the idea of the proof of the remainder theorem
not sure where to go from there..im trying to keep f(a)=7 right? how do i find out what q is? and a?
I haven't actually looked at your original question, a moment
there seems to be insufficient information to solve the original question. you have one constraint to find two unknowns with, and there are no cheap tricks you can do with q - 2p that makes it possible to ignore the two-unknown problem.
oh wait never mind.
I misread the sign of q, sorry.
hint: don't find p and q separately.
instead, note that you are dividing by x + 1.
now, compare the expression you're dividing by here (x + 1) to the general term in the polynomial remainder theorem (x - a).
what is a?
-1?
yes!
and by the remainder theorem, p(a) = r -> p(-1) = 7.
so evaluate your original polynomial at x = -1.
and because the remainder theorem tells us that evaluating the polynomial at x = a gives us the remainder on division by (x - a).
so p is f?
well yes. I just use p(x) because p for polynomial.
ahh i see
but you can use f(x).
so p(x) or f(x) = 7 and because the remainder theorem says that when f(x) is divided by x-a the remainder is f(a)...f(a)=7 which is...the same as f(x)=7 except that x...or well..now a will always be -1 because the general term x-a in which in this case is x+1 (x-(-1))...
so f(-1)=7 and i just plug neg 1 from there and work it out?
do not interchange x with a freely.
p(x) has no definite value because it is still in terms of x. p(a) is when you actually substitute the value of a for x. so saying that p(x) or f(x) = 7 is incorrect.
because the remainder theorem says that when f(x) is divided by x-a the remainder is f(a)...f(a)=7
this...
a willalwaysbe -1 because the general term x-a in which in this case is x+1 (x-(-1))...
...and this... (note the correction)
so f(-1)=7 and i just plug neg 1 from there and work it out?
...and this are correct.
just cause claude said -4
idk how they lost the first -1
so if my eyes are not failing me, that's 2p(-1) - 4 + (-5) + q in the second line.
where's the entire 2p term to begin with after that?
also, please refrain from using AI if you are not already familiar with the topic.
by the way, up to this point, you are correct.
but moving from line 2 to line 3, the 2p term just vanished.
i didnt add it yet, wasnt sure if i was to subtract the 4 from the -1 or if it was supposed to stay with the 2p
2p(-1) is a single term. you should multiply those two.
remember, multiplication before addition.
also, don't forget that this entire expression is equal to 7.
-2p?
correct.
and so your final answer is?
is -2p + q not the same as (+)q - 2p?
how? i thought u couldnt flip subtraction problems
but you are bringing the signs with the terms.
you cannot flip q - 2p to become 2p - q, sure.
but you can reorder terms as long as you bring their sign with them.
if that doesn't stick in your mind, -2p + q = q + (-2p) = q - 2p.
0-2p+q = 0+q-2p
if that works for you, then sure. it's not wrong, it's just a little awkward personally.
so I presume you're done with the question?
WOAHHH OK
yeah yeah for sure i get it now
well done!
🤗 tysmmm for ur help
unfortunately my eyes are really starting to fail me now, so I will have to take my leave. I'm sorry if you have any further questions.
all the best!
Closed by @karmic sleet
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Help needed in number theory and combinatorics:
I want to prove that a sequence characterized by floor(1.26*m^{\frac{3}{2}}) follows this identity. I know empirically that the sequence does follow this identity :
r(d)<=d-1
Where r(d) counts how many times a distance d shows up as a positive difference between any 2 elements. So like a golomb ruler, but instead of every difference d limited to appear once, they can appear atmost d-1 times
An optimal set that follows the above identity would be for example:
[0,2,5,8,12,16]
Any suggestions on how I can prove it? Even a probabilsitic proof approach would be fine
@brisk turret Has your question been resolved?
<@&286206848099549185>
@brisk turret Has your question been resolved?
Use the fact that 1) after a certain point, consecutive difference are strictly increasing, and 2) that if the difference of two numbers are d, and you look at the consecutive differences between those two numbers, their sum is d
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Please don't occupy multiple help channels.
Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Hello. My current understanding of fraction multiplication is the following:
When multiplying a fraction by a whole number, it'd be like increasing the magnitude of the fraction by the amount the whole number indicates. In multiplying a fraction by another fraction, it's as if the product's magnitude of growth were fractional, so it wouldn't really increase in numerical value, but even regress.
Is my understanding appropiate? Anything I missed?
basically, yes.
the magnitute changes by the size of the number multiplied (fraction or not)
If you multiply by 2/3 the magnitude shrinks, if you multiply by 3/2 the magnitude grows.
Thank you. On a similar topic, does something similar happen with division by fractions?
yes, but it's reversed.
division is like multiplying by the reciprocal. i.e. Dividing by 2 is the same as multiplying by 1/2 and dividing by 2/3 is the same as multiplyin by 3/2
Is that why the algorithm for division between fractions is crossed multiplication?
one of the reasons, yea
Are there other relevant reasons?
With what you're doing now, that's enough of an understanding.
Alright, thank you! Before you go, I'd like to get your feedback on my reasoning behind division by fractions.
If fractional multiplication is fractional magnitude growth or change, then fractional division is multiplication by the reciprocal, which essentially means magnitude growth by more than one fraction (at least for proper fraction division).
fractional division is multiplication by the reciprocal
I agree with this part, not sure about the part that comes after it. (sorry for jumping in.)
Not sure what you mean by the last part of that, the first part is fine
Thank you!
I'll refine it further later. If you don't mind, I'll close the chat
.close
Closed by @shrewd herald
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
hi guys, can someone help me with this?
what function transformations do you know
-# context that they asked for what functions are in discussion
i know the basics, but when graphs are given i tend to get confused
first change the origin transformation..
then apply scale transformation @frigid sedge
f(x)-b
yes
what is the value of the peak for both
for f(x) its (0,6) and for g(x) (0,-2)
no haha, i know what functions are obviously. its just that sometimes domain and range questions get a bit tricky for me although theyre the basics
ok lets keep that in mind
now
there is the 'flat corner' to the right of both peaks, can you tell me the coordinates of that as well, for both graphs
the rightmost point?
this
ok so
for f(x), the peak is at (0, 6) and the corner point is at (3,3)
for g(x), the peak is at (0,-2) and the corner point is at (3,-8)
yes
for both functions, how much is the vertical drop between the peak and the corner point?
wait i dont get what ur asking
how much is the difference between the second number in the parantheses between the peak and corner point
3 and 6?
yeah
so the vertical distance has doubled
review your function transformations
what type of transformation is this
yep!
its a vertical stretch by 2
so now
we need to figure out the vertical translation
to do that
try to multiply the second value in parantheses by 2 for f(x)'s corner and peak
(0,12) and (3,6)
yeah
so now
could you please calculate the vertical difference between the peak of f and g
8?
ooh so without multiplying the g's peak with 2?
nope!
yeah
does the peak of g remain as (0,-2) or is it now (0,-4)?
okay so the veritcal distance becomes 10 then?
no
14?
yeah
yes
wait i have a few questions,
- why 14
- why didnt we mutiply g(x) with 2?
because the distance between 12 and -2 is 14
because we are changing f(x) to g(x)
!done
If you are done with this channel, please mark your problem as solved by typing .close
.close
Closed by @frigid sedge
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
I am trying to find the shortest distance between two points if there is a triangle in the way, like this desmos geometry example: (the black line is the shortest path in the current setup, but it wont necessarily be if you move the triangle or the points around)
i dont even know where to start here aside from just checking every combination of vectors that make the path (start point)->(1-2 points on the triangle)->(end point)
By shortest distance do you mean along the lines?
If I understand you right you might be interested in shortest path algorithms, e.g https://en.wikipedia.org/wiki/Dijkstra's_algorithm
Dijkstra's algorithm (, DYKE-strəz) is an algorithm for finding the shortest paths between nodes in a weighted graph, which may represent, for example, a road network. It was conceived by computer scientist Edsger W. Dijkstra in 1956 and published three years later.
Dijkstra's algorithm finds the shortest path from a given source node to every ...
idk how to implement algorithms in desmos lol
but if you just present the desmos as an example for a graph
then yes
dijkstra's
a*
etc
@pulsar pine Has your question been resolved?
remember to react to the bot!
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
quick question is there a number theory theory on this
(number theory) theory on this or postulate or whatever those fancy things are
id suggest just doing casework, honestly
if n is divisible by 3, then the expression is 3 times some cube, so it's not prime for any n divisible by 3, n>3
😔
similarly, if n^3 is 1 mod 9, then the expression becomes n^3-1/9
which you can show quite easily isn't prime for all but easily computable list of n
i'm sure there's some other tricks you can think of to make it less lengthy
(k+3)^3=k^3+9k^2+27k+27 => 3k^2+9k+9+k^woops nvm
oh yeah nvm that's actually really easy to do wow
🥀
wait
not mod
oh yeah that's way better
myb
yeah then its pretty trivial
I'm being stupid rn can u expound
well, n has to be either 3k, 3k+1 or 3k+2
N? naturals?
ain't naturals not including 0
depends on context (or rather convention)
if you wanna be clear, you can just write N_0
we should end separating numbers
then wut
after cubing I don't like looking at the quotient
oh wait
oh thanks
nvm I'm stupid
,w expand (3k+1)^3/9
should simplify nicely
yeah so we only have to consider k(3k^2+3k+1) or when it's 2 like k(3k^2+6k+4)
wo there'sreally only two choices
man the things people have to do in timed stuff 🥀
truly a 30s question of all time
.close
Closed by @ionic blaze
Use .reopen if this was a mistake.
30s? Damn this has to take at least 2 mins
u figured it out in 30s 😭
i didnt do the algebra lol, thats the hardest part (in sense of time)
.if I was quite frank I'm not sure if it was 15s or 30s
they say "easy round" but it kinda changes from 15s to 30 a lot
.people can be imaginative I guess 😭
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
I need help
the third to last row in A is saying 0 = 2
which matrix?
I said A
what about this ?
why did you put -3/2?
you used the 4 frmo row 1
instaed of the 1 from row 2
remember its important to make a pivot
and stick with it
you effectively undid your previous work
wait. you seem to have identified the right pivot but somehow you're taking 3 and 2 from... where?
if that 3 and 2 is from the i and j, take note that i and j are the row numbers.
i think you plugged in the indices instead of the values lol
yeah this lol
how?
i got the values but i mis subbed it?
what is the number you want to turn to 0
can you tell us what that is
6
what is the number you are using to turn the 6 into a 0
ye
@hoary seal Has your question been resolved?
also do u know how to find the critical pont but the non differentiable parts
the spike
can u just open a new help channel btw
less clutter
as this one was pertaining to your old question
yeah after this because I already typed the stuff
Closed by @hoary seal
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
State the coordinates of D and E
!original
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
this is the original problem
did the problem have any text
yeah
...
ok im assuming D is directly above C?
yes
so its parallel to the ground
i dont know their slopes so i cant tell for sure, but i would assume so
no
interesting
from the diagram, you can see that D is clearly above A
its called perspectivew
that was my thinking
👍
there we go
how did that help tho now
ok so im assuming that there is a prism which lies flat on the ground
would you agree
yeah
yea
no
see that's what people call a contradiction
D has a height of 5
yeah and where did you get the 5
what
is this your first 3D problem you're doing?
kinda
ok makes sense
so ur telling me that unlike a xy plane
we can't measure the x,y, or z value of a point
ok imagine watching the prism from the right side
using the x,y,and z axis
ok
okay
and you're looking at the pyramid
you see the line
BE
which lies flat on the ground
uh huh
and you look up
to the top of the prysm
and see the line at the top where the prism ends
AD
oh, i get they have the same height
yea
thats hard to visualize, damn
it becomes ver yver yeasy with time
you just need to practice
and imagine yourself
in the plane
so E would be (something, 4, 0)
looking at stuff
oh
(-7,4,0)
confusing
haha
rectangle
yes
rhombus
good
45 right
Z and Y make 90 degrees obv cuz theyre perpendicular
X and Y are also 90 edgrees?
the only difference is that you added a third axis
that is perpendicalar to both x and y
first, i visualized it like the X axis is a line going through the 2d Z and Y axes
and goes up
it exactly splits it in half
and thats why it was 45 degrees
im still thinking about it in a 2d way ;/
the ground plane can be visualized exactly like a regular 2D plane
yeah
90
OBE
AOC
DCB
DCB
90
can we do b
my teacher told me not to use formulas for calculating surface areas and stuff
then what should you use
idk
i think for the volume its fine, because we did a problem including cylinders and he used 4/3 pir^2
^3
i have no idea
its A_triangle * height
well we are taking the base to be AOB
A_triangle means area of triangle right
yes
i think im not visualizing it in a 3d way
i see the height of triangle and prism as 3
the base of triangle as 4
but i know its not going to be that easy
just imagine
we take the prism
and put it on its triangle base
so that it stays upright
so it will stay on its base
<@&268886789983436800>
like imagine
this?
FEE-FI-FO-FUM???
wdym
ok
done?
yes
and now the giant sits up, puts his hands on the DE line
its sitting outside the prism
and pulls it towards him
so by the height they mean the distance AD
well yes
multiplied by the height
sqrt(49+9)
oh no
no
nvm
sqrt[(-7-0)^2+(0)^2+(0-3)^2]
sqrt(49+9)
wait what
i was right??
rectangle
-7
length cant be negative
|-7|=7
AD must be 7
yes
sqrt[(-7-0)^2+(0)^2+(0-3)^2]
triangular based*
,w sqrt((-7-0)^2 + (3-0)^2)
yeah see its 7.6
not even 7.5
so theres no way they messed up and rounded 7.6 to 7
i think our D coordinates are wrong
oh..
,w sqrt ( (-7-0)^2 + (3-3)^2 )
umm
yeah
why
wdym why😭
why did it have to be 7
lol
idk
:/
they predicted the 67 joke
so what the asnwer
what the ai
5
good
surface area ;-;
can ask anyhting bout 2d
what do you think we shoulld do
like when the question is only is asked in x axis and y axis
yeah what about it
ok
since there are 2 similar triangles
i only learnd that
ok
if you have a specific question you go refer to #❓how-to-get-help
where's O
then use the coordinates to find the heights and lengths of the rectangles, find the area and sum it all up
yes
in the intersection of the X,Y, and Z axes
the thing is tho
how do we write it
cuz my teachers not gonna accept some
working
ohhhh
*calculation
now i can see this a total dif way
just find all the areas of the rectangles
its called origin in 2d
and add them with 2*area rectangle
BE would be 4 right
yeah, srry im not as smart as you
rectangle
surface area is 96
and whats the length of oc
yes
it is
bro
!nosols
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
please
um
this isnt who's going to be a millionaire where you just say the answer, and get it correct. you have to show working.
hmm
plus i cant trust u u just used ai to solve this didnt you? chat is really unreliable
just focus on the question
i will send a pic of solution
okay
wait a min
AOCD = 21
yes
OBEC = 28
yes
total surface area is 96
yes
units^3
no
thats for volume
yes
um
as you can see, im pretty egregious
just imagine yourself being in the plane
;-;
so like standing at the y axis
from behind, from the left etc
whatever helps you picture the shape
just imagine
being on a field
with a giant prism in front of you
and how it would look like
walking around
you're welcome
.close
Closed by @glass edge
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
help
please someone tell me at the last step how -x^2 became +x^2
add x^2 to both sides and subtract 40 x from both sides
alternatively, subtract 400 from both sides, then multiply the equation by -1.
because usually with polynomials one likes the term of highest degree to have a positive coefficient
its neater
-x^2+40x-400=0 would give you the same answer if you solved it for x
Also a lot of factorisation methods are cleaner if your polynomial has a leading coefficient of 1
Closed by @heavy vector
Use .reopen if this was a mistake.
lance lance helper arc?
vro mustve had a life changing experience
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
someone help me for this integral question?
The base of this exponential part looks annoying. I wonder if there is a way to simplify it into one single variable:
$(x^4+1)^5$
Xwtek
@pearl silo Has your question been resolved?
Closed by @pearl silo
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
How do I graph this
Find the volume of the solid generated by revolving about the line x = 2 the region bounded by y = x ^ 2, x = 2 and y = 0
Where do you want to graph it?
are you trying to graph the solid or just the region?
For finding the volume, it suffices to graph the region
you will find out after you sketch the region
Whre will it rotate?
itll rotate around x = 2
but the disks will be like this
sorry for the terrible drawing lol
but the discs will basically lay flat (parallel with x-axis)
Ohh okeyy okeyy
you're forgetting the square
What?
Ohh yeahh
Soo I guess it will just cancel out
yeah, it will be essentially just integral of y
but i think you might be forgetting some constants
and you havent stated the bounds yet
The bounds is 4 and 0 right
yep
The final answer will be 8piu³
wdym u?
what the hell did they do
this doesnt look correct at all
oh wait
yeah mb, integrating (sqrt(y))^2 is wrong
but their pic is also wrong it seems
sqrt(y) is this distnace
It should be (2-√y)² right?
yeah
Okeyy okeyy
youd have to use shells
