#help-23

1 messages · Page 420 of 1

warm warren
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if $\sin \theta = 0$ then $\cos \theta \neq 0$

flat frigateBOT
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Annie Maqionde

warm warren
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it is implied

graceful lichen
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and cancelling cos(a) while multiplication

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oh okay

warm warren
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well you assuem so

graceful lichen
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Herr in this step

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While cancelling cos(a) we should say cos(a) =/ 0

warm warren
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you may cancel it out; if you want to be absolutely rigorous, you may write a small note on why $cos(xy) \neq 0$(then tan is undefined, right, but tan is an integer here)

flat frigateBOT
#

Annie Maqionde

warm warren
graceful lichen
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To define both equations

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Right?

warm warren
graceful lichen
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yes

warm warren
flat frigateBOT
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Annie Maqionde

graceful lichen
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so it is not necessary to say cos(a) is not zero if equations are defined on integers

graceful lichen
#

what it is

warm warren
graceful lichen
warm warren
#

$\cos(xy) \neq 0$ since if $\cos(xy) = 0$ then $\tan(xy)$ will be undefined. But as stated in question, $\tan(xy)$ is an integer. Therefore $\cos(xy)$ is not zero

flat frigateBOT
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Annie Maqionde

warm warren
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something along the lines of this

graceful lichen
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I want to clear one thing only

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from the step where we did xy=0

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After sin(xy)=xy

graceful lichen
warm warren
#

please reread our entire conversation again

safe radishBOT
#

@graceful lichen Has your question been resolved?

safe radishBOT
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stuck tusk
#

The question is confusing when there comes 2^x and x too

desert pasture
flat frigateBOT
lone ocean
#

Sketch approximate graphs

stuck tusk
#

because of power property in log of quantity

stuck tusk
lone ocean
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Usually it’s too much to handle both exponentials and x in the same expression

stuck tusk
#

I see

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considering 2^x = t becomes difficult too

lone ocean
#

Is this a Jee question

stuck tusk
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Jee Main level question

lone ocean
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Yeah then graph

stuck tusk
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can't we use hit & trial method?

lone ocean
#

Here you can

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But how will you confirm that those are the only solutions

brisk apex
stuck tusk
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And there's a condition of log too

lone ocean
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Doing those is equivalent to solving it graphically right

stuck tusk
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Well

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How to do that😭

lone ocean
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You know graphical transformations?

honest perch
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graph log_2(x+5)

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and 6-x

stuck tusk
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initially

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i am 11th moving student

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And our teachers haven't taught us graph

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but yeah they showed exponential graph

honest perch
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do you know the log graph

stuck tusk
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Yeah

upbeat hatch
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Do u know the fact that log function takes only positive values ?

stuck tusk
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Yep

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quantity and base should be positive

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not the answer of logs but

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and base shouldn't be 1

honest perch
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you should know graph transformations probably

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graph log_2(x) then shift it 5 units left

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to get log_2(x+5)

stuck tusk
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is there any animation graph website

honest perch
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desmos

stuck tusk
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like this?

honest perch
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yup

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now 6-x

stuck tusk
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Parallel to y axis

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I think this is the answer

fair hound
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yeah x = 3 gives log2(8) = 3 which is true

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that's why your first screenshot gives the line x = 3

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on your second screenshot you see the intersection at x = 3, where it's equal

stuck tusk
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ohh yes

fair hound
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from log_2(x+5) = 6-x
you could also have written x+5 = 2^(6-x) by log properties
so 2^x (x+5) = 64, and since 2^x (x+5) is strictly increasing as the product of 2 strictly increasing functions, it will go through 64 only once

stuck tusk
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intersect at x = 3

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is it possible to solve without graphically?

stuck tusk
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ohhh

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Like multiplication

fair hound
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your equation is log_2(x+5) = 6-x, so x+5 = 2^(6-x)
multiply by 2^x on both sides, you get 2^x (x+5) = 2^6 = 64

stuck tusk
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@tawny seal

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@flat frigate

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,help

flat frigateBOT
#

A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!

stuck tusk
#

Wait for 1 min

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,tex 2^x(x+5) = 64

flat frigateBOT
#

- H I D D E N 8 7
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

stuck tusk
#

@fair hound

fair hound
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yes

stuck tusk
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Now what to do?

fair hound
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2^x (x+5) is strictly increasing as the product of 2 strictly increasing functions, it will go through 64 only once

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hence the answer is 1

stuck tusk
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Yes

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Thanks

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Can I ask another doubt too?

fair hound
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yes

stuck tusk
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JEE Advanced level question

thorn dragon
fair hound
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I would first simplify A

thorn dragon
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is the qn saying 5 power raised to the power of 1/2 10 times?

fair hound
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10 times

thorn dragon
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yeah so 5 power 1/1024

fair hound
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yes, you simplify A, you get 1/512, and then it asks for log_sqrt(3) (2+1)

fair hound
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which is 2

stuck tusk
#

,tex 1/2^10

flat frigateBOT
#

- H I D D E N 8 7
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

stuck tusk
#

,tex 1/2^(10)

thorn dragon
flat frigateBOT
#

- H I D D E N 8 7
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

thorn dragon
#

this qn isnt that hard eh

upbeat hatch
stuck tusk
#

i guess this question comes in the category of atleast mains or conceptual level

upbeat hatch
#

So it could be for conceptual clarity

stuck tusk
#

alright thanks for the doubt have a good day

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,close

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.close

safe radishBOT
#
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golden nebula
#

<@&268886789983436800>

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vague phoenix
#

Fact?

azure harbor
vague phoenix
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fiery remnant
#

<@&268886789983436800>

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karmic sleet
#

tryna understand remainder theorem

where is f(a) plugged? and why is x now -1

i can see how we get 16 if u yk..add to the other side to cancel out n stuff

manic patrol
#

here's an excerpt of my own writeup of the polynomial remainder theorem (technically it's part of my proof of the polynomial factor theorem, but this part is enough for the remainder theorem).

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perhaps this will help you understand a little more about the polynomial remainder theorem.

safe radishBOT
#

@karmic sleet Has your question been resolved?

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karmic sleet
#

.reopen

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karmic sleet
crystal wigeon
#

if we put x value in function(x), we need to find value of x first, so we find it by putting 0 in rhs, so x + 1 = 0

karmic sleet
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yeah cause...if the r is 7 that means a is 7 which means x-a should be x-7? no?

rugged cave
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r = 7 means f(a) = 7, not a itself.

karmic sleet
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noted

crystal wigeon
rugged cave
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specifically, this part right here.

karmic sleet
#

i did but it was still pretty confusing for me :')

rugged cave
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should have said so

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which part confuses you?

karmic sleet
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ig just...the principle of it? like

when f(x) is divided by (x-a) the remainder is f(a)
so f(a)=7

f(a) = (a-a)q(a)+7
and a-a=0 so
f(a) = 0q(a)+7...which is =7....

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am i on the right track

rugged cave
#

please don't gif spam in help channels

karmic sleet
#

sorry

rugged cave
#

takes up half the screen, esp. when one of your helpers has a vision-related request

karmic sleet
#

ah gotcha, noted

rugged cave
#

in fact you've kinda stumbled upon the idea of the proof of the remainder theorem

karmic sleet
rugged cave
#

I haven't actually looked at your original question, a moment

manic patrol
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there seems to be insufficient information to solve the original question. you have one constraint to find two unknowns with, and there are no cheap tricks you can do with q - 2p that makes it possible to ignore the two-unknown problem.

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oh wait never mind.

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I misread the sign of q, sorry.

manic patrol
manic patrol
karmic sleet
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-1?

manic patrol
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yes!

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and by the remainder theorem, p(a) = r -> p(-1) = 7.

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so evaluate your original polynomial at x = -1.

karmic sleet
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wait why r we replacing x with -1 again?

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and whats p(a)

manic patrol
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p(x) is the polynomial in question.

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p(a) is the polynomial evaluated at x = a.

manic patrol
karmic sleet
manic patrol
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well yes. I just use p(x) because p for polynomial.

karmic sleet
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ahh i see

manic patrol
#

but you can use f(x).

karmic sleet
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so p(x) or f(x) = 7 and because the remainder theorem says that when f(x) is divided by x-a the remainder is f(a)...f(a)=7 which is...the same as f(x)=7 except that x...or well..now a will always be -1 because the general term x-a in which in this case is x+1 (x-(-1))...

so f(-1)=7 and i just plug neg 1 from there and work it out?

manic patrol
#

do not interchange x with a freely.
p(x) has no definite value because it is still in terms of x. p(a) is when you actually substitute the value of a for x. so saying that p(x) or f(x) = 7 is incorrect.

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because the remainder theorem says that when f(x) is divided by x-a the remainder is f(a)...f(a)=7
this...
a will always be -1 because the general term x-a in which in this case is x+1 (x-(-1))...
...and this... (note the correction)
so f(-1)=7 and i just plug neg 1 from there and work it out?
...and this are correct.

karmic sleet
#

ahh oki doki

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the top part lost me

karmic sleet
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idk how they lost the first -1

manic patrol
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so if my eyes are not failing me, that's 2p(-1) - 4 + (-5) + q in the second line.

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where's the entire 2p term to begin with after that?

manic patrol
manic patrol
#

but moving from line 2 to line 3, the 2p term just vanished.

karmic sleet
manic patrol
#

2p(-1) is a single term. you should multiply those two.

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remember, multiplication before addition.

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also, don't forget that this entire expression is equal to 7.

karmic sleet
#

-2p?

manic patrol
#

correct.

karmic sleet
manic patrol
#

and so your final answer is?

karmic sleet
#

16? but how is that matched up back to q-2p

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if u flip em around?

manic patrol
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is -2p + q not the same as (+)q - 2p?

karmic sleet
#

how? i thought u couldnt flip subtraction problems

manic patrol
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but you are bringing the signs with the terms.

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you cannot flip q - 2p to become 2p - q, sure.

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but you can reorder terms as long as you bring their sign with them.

karmic sleet
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ohhhh

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ohh

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i can visualize it better if i use 0

manic patrol
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if that doesn't stick in your mind, -2p + q = q + (-2p) = q - 2p.

karmic sleet
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0-2p+q = 0+q-2p

manic patrol
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if that works for you, then sure. it's not wrong, it's just a little awkward personally.

#

so I presume you're done with the question?

karmic sleet
#

yeah yeah for sure i get it now

manic patrol
#

well done!

karmic sleet
#

🤗 tysmmm for ur help

manic patrol
#

unfortunately my eyes are really starting to fail me now, so I will have to take my leave. I'm sorry if you have any further questions.

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all the best!

karmic sleet
#

i understand waayy better now

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.close

safe radishBOT
#
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brisk turret
#

Help needed in number theory and combinatorics:

I want to prove that a sequence characterized by floor(1.26*m^{\frac{3}{2}}) follows this identity. I know empirically that the sequence does follow this identity :

r(d)<=d-1

Where r(d) counts how many times a distance d shows up as a positive difference between any 2 elements. So like a golomb ruler, but instead of every difference d limited to appear once, they can appear atmost d-1 times

An optimal set that follows the above identity would be for example:

[0,2,5,8,12,16]

Any suggestions on how I can prove it? Even a probabilsitic proof approach would be fine

safe radishBOT
#

@brisk turret Has your question been resolved?

brisk turret
#

<@&286206848099549185>

safe radishBOT
#

@brisk turret Has your question been resolved?

devout scroll
#

Use the fact that 1) after a certain point, consecutive difference are strictly increasing, and 2) that if the difference of two numbers are d, and you look at the consecutive differences between those two numbers, their sum is d

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safe radishBOT
#

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shrewd herald
#

Hello. My current understanding of fraction multiplication is the following:
When multiplying a fraction by a whole number, it'd be like increasing the magnitude of the fraction by the amount the whole number indicates. In multiplying a fraction by another fraction, it's as if the product's magnitude of growth were fractional, so it wouldn't really increase in numerical value, but even regress.

Is my understanding appropiate? Anything I missed?

drowsy moss
#

basically, yes.
the magnitute changes by the size of the number multiplied (fraction or not)

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If you multiply by 2/3 the magnitude shrinks, if you multiply by 3/2 the magnitude grows.

shrewd herald
drowsy moss
#

yes, but it's reversed.

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division is like multiplying by the reciprocal. i.e. Dividing by 2 is the same as multiplying by 1/2 and dividing by 2/3 is the same as multiplyin by 3/2

shrewd herald
#

Is that why the algorithm for division between fractions is crossed multiplication?

drowsy moss
#

one of the reasons, yea

shrewd herald
#

Are there other relevant reasons?

drowsy moss
#

With what you're doing now, that's enough of an understanding.

shrewd herald
#

Alright, thank you! Before you go, I'd like to get your feedback on my reasoning behind division by fractions.

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If fractional multiplication is fractional magnitude growth or change, then fractional division is multiplication by the reciprocal, which essentially means magnitude growth by more than one fraction (at least for proper fraction division).

outer pollen
#

fractional division is multiplication by the reciprocal
I agree with this part, not sure about the part that comes after it. (sorry for jumping in.)

drowsy moss
#

Not sure what you mean by the last part of that, the first part is fine

shrewd herald
#

Thank you!

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I'll refine it further later. If you don't mind, I'll close the chat

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.close

safe radishBOT
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frigid sedge
#

hi guys, can someone help me with this?

safe radishBOT
opaque fern
nimble wyvern
#

-# context that they asked for what functions are in discussion

frigid sedge
#

i know the basics, but when graphs are given i tend to get confused

wintry bronze
#

first change the origin transformation..
then apply scale transformation @frigid sedge

opaque fern
#

so let's start with the simplest

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how do you 'move down' a graph?

frigid sedge
opaque fern
#

yeah

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you see that peak in both graphs, right?

frigid sedge
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yes

opaque fern
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what is the value of the peak for both

frigid sedge
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for f(x) its (0,6) and for g(x) (0,-2)

frigid sedge
opaque fern
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now

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there is the 'flat corner' to the right of both peaks, can you tell me the coordinates of that as well, for both graphs

frigid sedge
#

the rightmost point?

opaque fern
frigid sedge
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ooh okay

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3,3 and 3,8

opaque fern
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ok so

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for f(x), the peak is at (0, 6) and the corner point is at (3,3)
for g(x), the peak is at (0,-2) and the corner point is at (3,-8)

frigid sedge
#

yes

opaque fern
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for both functions, how much is the vertical drop between the peak and the corner point?

frigid sedge
#

wait i dont get what ur asking

opaque fern
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how much is the difference between the second number in the parantheses between the peak and corner point

frigid sedge
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3 and 6?

opaque fern
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yeah

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so the vertical distance has doubled

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review your function transformations

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what type of transformation is this

frigid sedge
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oh stretch factor 2 vertically

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so in y direction

opaque fern
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its a vertical stretch by 2

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so now

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we need to figure out the vertical translation

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to do that

opaque fern
frigid sedge
#

(0,12) and (3,6)

opaque fern
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yeah

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so now

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could you please calculate the vertical difference between the peak of f and g

frigid sedge
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8?

opaque fern
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nope!

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remember, it become (0,12) now

frigid sedge
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ooh so without multiplying the g's peak with 2?

opaque fern
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nope!

frigid sedge
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😔

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so the peak of f is now (0,12) right

opaque fern
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yeah

frigid sedge
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does the peak of g remain as (0,-2) or is it now (0,-4)?

nimble wyvern
#

remain (0,-2)

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because we only changed f(x)

frigid sedge
#

okay so the veritcal distance becomes 10 then?

nimble wyvern
#

no

frigid sedge
#

14?

opaque fern
#

yeah

nimble wyvern
#

yes

opaque fern
#

you are basıcally done now

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you have to formulate your equatıon

frigid sedge
#

wait i have a few questions,

  1. why 14
  2. why didnt we mutiply g(x) with 2?
nimble wyvern
#

because the distance between 12 and -2 is 14
because we are changing f(x) to g(x)

frigid sedge
#

right 😭

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thankyou so much guys

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!!!!

nimble wyvern
#

!done

safe radishBOT
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If you are done with this channel, please mark your problem as solved by typing .close

frigid sedge
#

.close

safe radishBOT
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pulsar pine
#

I am trying to find the shortest distance between two points if there is a triangle in the way, like this desmos geometry example: (the black line is the shortest path in the current setup, but it wont necessarily be if you move the triangle or the points around)

link

i dont even know where to start here aside from just checking every combination of vectors that make the path (start point)->(1-2 points on the triangle)->(end point)

manic bane
#

By shortest distance do you mean along the lines?

manic bane
# manic bane By shortest distance do you mean along the lines?

If I understand you right you might be interested in shortest path algorithms, e.g https://en.wikipedia.org/wiki/Dijkstra's_algorithm

Dijkstra's algorithm (, DYKE-strəz) is an algorithm for finding the shortest paths between nodes in a weighted graph, which may represent, for example, a road network. It was conceived by computer scientist Edsger W. Dijkstra in 1956 and published three years later.
Dijkstra's algorithm finds the shortest path from a given source node to every ...

smoky nacelle
#

idk how to implement algorithms in desmos lol

#

but if you just present the desmos as an example for a graph

#

then yes

#

dijkstra's

#

a*

#

etc

safe radishBOT
#

@pulsar pine Has your question been resolved?

pulsar pine
#

no

#

<@&286206848099549185>

outer pollen
#

remember to react to the bot!

safe radishBOT
#
Channel closed

Closed due to timeout

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#
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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

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ionic blaze
#

quick question is there a number theory theory on this

ionic blaze
#

(number theory) theory on this or postulate or whatever those fancy things are

cursive remnant
#

id suggest just doing casework, honestly

#

if n is divisible by 3, then the expression is 3 times some cube, so it's not prime for any n divisible by 3, n>3

ionic blaze
cursive remnant
#

similarly, if n^3 is 1 mod 9, then the expression becomes n^3-1/9

#

which you can show quite easily isn't prime for all but easily computable list of n

#

i'm sure there's some other tricks you can think of to make it less lengthy

brave wolf
#

its not really lengthy, you only have to consdier mod 3, not mod 9

#

3k, 3k+1, 3k+2

ionic blaze
#

🥀

#

wait

#

not mod

cursive remnant
#

myb

#

yeah then its pretty trivial

ionic blaze
brave wolf
ionic blaze
#

yeah for k=

#

wait

#

what was 0 1 2 3 4

#

counting numbers

brave wolf
#

N? naturals?

ionic blaze
#

ain't naturals not including 0

brave wolf
#

depends on context (or rather convention)

#

if you wanna be clear, you can just write N_0

ionic blaze
#

we should end separating numbers

ionic blaze
#

after cubing I don't like looking at the quotient

#

oh wait

#

oh thanks

#

nvm I'm stupid

brave wolf
#

,w expand (3k+1)^3/9

flat frigateBOT
brave wolf
#

should simplify nicely

ionic blaze
# flat frigate

yeah so we only have to consider k(3k^2+3k+1) or when it's 2 like k(3k^2+6k+4)

#

wo there'sreally only two choices

#

man the things people have to do in timed stuff 🥀

#

truly a 30s question of all time

#

.close

safe radishBOT
#
Channel closed

Closed by @ionic blaze

Use .reopen if this was a mistake.

brave wolf
ionic blaze
brave wolf
#

i didnt do the algebra lol, thats the hardest part (in sense of time)

ionic blaze
#

.if I was quite frank I'm not sure if it was 15s or 30s

#

they say "easy round" but it kinda changes from 15s to 30 a lot

ionic blaze
safe radishBOT
#
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hoary seal
#

I need help

safe radishBOT
hoary seal
#

last one too

opaque fern
hoary seal
#

which matrix?

opaque fern
#

I said A

hoary seal
#

ah

#

so it shoud been no solution for A

hoary seal
outer pollen
#

why did you put -3/2?

hoary seal
#

ill send u my wokrng out

opaque fern
#

you used the 4 frmo row 1

#

instaed of the 1 from row 2

#

remember its important to make a pivot

#

and stick with it

#

you effectively undid your previous work

outer pollen
#

wait. you seem to have identified the right pivot but somehow you're taking 3 and 2 from... where?

opaque fern
#

yeah uh

#

you are just plugging the wrong numbers idk

outer pollen
#

if that 3 and 2 is from the i and j, take note that i and j are the row numbers.

opaque fern
#

i think you plugged in the indices instead of the values lol

hoary seal
opaque fern
#

ignore that comment

#

i was just guessing

hoary seal
opaque fern
#

can you tell us what that is

hoary seal
#

6

opaque fern
#

what is the number you are using to turn the 6 into a 0

hoary seal
#

u mean the pivot?

#

thats 1

opaque fern
#

ok

#

so whats ur equation

hoary seal
#

0=6+alpha*1

#

alpha should be negative 6?

#

ah

opaque fern
#

ye

safe radishBOT
#

@hoary seal Has your question been resolved?

hoary seal
# opaque fern ye

also do u know how to find the critical pont but the non differentiable parts

#

the spike

opaque fern
#

yea

#

just check where f' is undefined

#

ofc f has to be defined there as well

hoary seal
#

i have this function rn

#

is it when x=-4?

opaque fern
#

can u just open a new help channel btw

#

less clutter

#

as this one was pertaining to your old question

hoary seal
#

yeah after this because I already typed the stuff

opaque fern
#

x = -4 is one of em

hoary seal
#

and 2?

#

nvm I already included 2

astral glacier
opaque fern
#

it is -2, 2 and 4

hoary seal
#

nvm i see

#

ty

#

.close

safe radishBOT
#
Channel closed

Closed by @hoary seal

Use .reopen if this was a mistake.

safe radishBOT
#
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glass edge
#

State the coordinates of D and E

safe radishBOT
upbeat swan
#

!original

safe radishBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

glass edge
#

this is the original problem

upbeat swan
#

did the problem have any text

glass edge
#

yeah

upbeat swan
#

...

glass edge
#

but its too blurry to read

#

"Consider the triangular-based prism alongside."

upbeat swan
#

ok im assuming D is directly above C?

glass edge
#

yes

upbeat swan
#

and AD is parallel to the plane of the floor?

#

the gorund

#

ground

glass edge
#

what

#

im pretty sure

upbeat swan
#

the line AD

#

is it like

upbeat swan
glass edge
upbeat swan
#

ok then D will have the same z coordinate as A

#

correct?

glass edge
#

no

upbeat swan
#

interesting

glass edge
#

from the diagram, you can see that D is clearly above A

upbeat swan
#

its called perspectivew

glass edge
#

that was my thinking

upbeat swan
#

3D

#

also if you dont give me the text i dont know for certain

glass edge
#

okay

#

let me give u the whole thing

upbeat swan
#

👍

glass edge
upbeat swan
#

there we go

glass edge
#

how did that help tho now

upbeat swan
#

ok so im assuming that there is a prism which lies flat on the ground

#

would you agree

glass edge
#

yeah

upbeat swan
#

so A and D are on the same line

#

and that line is parallel to the ground

#

correct

glass edge
#

yea

upbeat swan
#

so A and D have the same height

#

correct

glass edge
#

no

upbeat swan
#

see that's what people call a contradiction

glass edge
#

D has a height of 5

upbeat swan
#

well thats what you need to figure out

#

or?

glass edge
#

i need to state the coordinates

#

of D & E

upbeat swan
#

yeah and where did you get the 5

glass edge
#

re

#

here

#

wait its 6

#

mb

upbeat swan
#

bro

#

thats not how 3D works

glass edge
#

what

upbeat swan
#

is this your first 3D problem you're doing?

glass edge
#

kinda

upbeat swan
#

ok makes sense

glass edge
#

so ur telling me that unlike a xy plane

#

we can't measure the x,y, or z value of a point

upbeat swan
#

ok imagine watching the prism from the right side

glass edge
#

using the x,y,and z axis

upbeat swan
#

you are on the ground

#

ok?

glass edge
#

ok

upbeat swan
#

lets say you re at the point -3, 6 , 0

#

wait

glass edge
#

okay

upbeat swan
#

and you're looking at the pyramid

#

you see the line

#

BE

#

which lies flat on the ground

glass edge
#

uh huh

upbeat swan
#

and you look up

#

to the top of the prysm

#

and see the line at the top where the prism ends

#

AD

glass edge
#

oh, i get they have the same height

upbeat swan
#

yes

#

just imagine that ABED

#

is a rectangle

glass edge
#

yea

upbeat swan
#

good

#

so what are the coordinates of D

glass edge
#

(-7,0,3)

#

?

upbeat swan
#

yes

#

exactly as C

#

but 3 units up

glass edge
#

thats hard to visualize, damn

upbeat swan
#

it becomes ver yver yeasy with time

#

you just need to practice

#

and imagine yourself

#

in the plane

glass edge
#

so E would be (something, 4, 0)

upbeat swan
#

looking at stuff

glass edge
#

oh

upbeat swan
#

so tell me for E

glass edge
#

(-7,4,0)

upbeat swan
#

yes

#

easy

#

right

glass edge
#

confusing

upbeat swan
#

haha

glass edge
#

sometimes i can envision it

#

then i lose it

upbeat swan
#

one more question

#

what shape is OBEC

#

o being the origin

glass edge
#

rectangle

upbeat swan
#

yes

glass edge
#

rhombus

upbeat swan
#

good

glass edge
#

nvm

#

all sides are not equal

upbeat swan
#

nevermind the sides

#

what angle do the axis form with eachother

#

the x and y axes

glass edge
#

45

#

?

upbeat swan
#

angle COB

#

at the intersection of x and y axes

glass edge
#

45 right

upbeat swan
#

really

#

45

#

imagine you're in 2D

#

what angle do the axes make

glass edge
#

Z and Y make 90 degrees obv cuz theyre perpendicular

upbeat swan
#

well then why did yo usay 45

#

its the same

glass edge
#

X and Y are also 90 edgrees?

upbeat swan
#

its still the exam same axes

#

x and y

glass edge
#

ohh

#

i can see it now

upbeat swan
#

the only difference is that you added a third axis

#

that is perpendicalar to both x and y

glass edge
#

first, i visualized it like the X axis is a line going through the 2d Z and Y axes

upbeat swan
#

and goes up

glass edge
#

it exactly splits it in half

#

and thats why it was 45 degrees

#

im still thinking about it in a 2d way ;/

upbeat swan
#

the ground plane can be visualized exactly like a regular 2D plane

glass edge
#

yeah

upbeat swan
#

good

#

so what shape is OBEC

glass edge
#

okay

#

didnt we do this

#

rectangle

upbeat swan
#

yes we did

#

we are reiterating

#

whats the mneasure of angle OCE

glass edge
#

90

upbeat swan
#

OBE

glass edge
#

90

#

still

upbeat swan
#

AOC

glass edge
#

cuz BE is parallel to x axis

#

90

#

still

#

YES

upbeat swan
#

DCB

glass edge
#

now i can visualize it

#

?

#

DCB?

upbeat swan
#

DCB

glass edge
#

90

upbeat swan
#

correct

#

yes you are starting to get it

glass edge
#

can we do b

upbeat swan
#

ok

glass edge
#

my teacher told me not to use formulas for calculating surface areas and stuff

upbeat swan
#

then what should you use

glass edge
#

idk

#

i think for the volume its fine, because we did a problem including cylinders and he used 4/3 pir^2

#

^3

upbeat swan
#

ok

#

whats the forumla for prism volume

glass edge
#

i have no idea

upbeat swan
#

its A_triangle * height

glass edge
#

we know height is 3

#

and base is 4

#

so 4x3x3?

upbeat swan
#

well we are taking the base to be AOB

glass edge
#

oh

#

i thought it was OB

upbeat swan
#

i said

#

A_triangle

#

times height

glass edge
#

A_triangle means area of triangle right

upbeat swan
#

yes

glass edge
#

i think im not visualizing it in a 3d way

#

i see the height of triangle and prism as 3

#

the base of triangle as 4

#

but i know its not going to be that easy

upbeat swan
#

just imagine

#

we take the prism

#

and put it on its triangle base

#

so that it stays upright

#

so it will stay on its base

#

<@&268886789983436800>

upbeat swan
glass edge
upbeat swan
#

no

#

imagine a giant

#

that sits at 5,3,0

#

ok?

whole hill
upbeat swan
glass edge
#

giant what

upbeat swan
#

giant

#

ogre

#

shrek

#

something

glass edge
#

ok

upbeat swan
#

done?

glass edge
#

yes

upbeat swan
#

and now the giant sits up, puts his hands on the DE line

glass edge
#

its sitting outside the prism

upbeat swan
#

and pulls it towards him

upbeat swan
#

5,3,0

upbeat swan
#

what happenes with the prism

glass edge
#

oh i get it

#

the triangle base is on the ground

upbeat swan
#

yes

#

now you can find the volume

#

A_base * height

#

what will be the base

glass edge
#

so by the height they mean the distance AD

upbeat swan
#

well yes

glass edge
#

wait

#

is

#

AB the hypotenuse

#

yeah it is

#

okay

upbeat swan
#

no

#

ah yes

#

sorry

glass edge
#

then A_triangle is 6

#

3*4/2

#

12/2

#

6

upbeat swan
#

yes

#

and the height

glass edge
#

multiplied by the height

#

sqrt(49+9)

#

oh no

#

no

#

nvm

#

sqrt[(-7-0)^2+(0)^2+(0-3)^2]

#

sqrt(49+9)

#

wait what

#

i was right??

upbeat swan
#

what shape is AOCD

glass edge
#

rectangle

upbeat swan
#

whats the length of AD

#

in that rectangle

glass edge
#

sqrt58

#

i calculated that using distance formula

upbeat swan
#

ok lets try something diffrenect

#

whats the length of OC

glass edge
#

-7

upbeat swan
#

length cant be negative

glass edge
#

|-7|=7

upbeat swan
#

yes

#

if OC=7

#

and AOCD is a rectangle

#

whats the length of AD

glass edge
#

AD must be 7

upbeat swan
#

yes

glass edge
#

but then why when i calculate

#

my estimate is far off

upbeat swan
#

sqrt[(-7-0)^2+(0)^2+(0-3)^2]

turbid ore
#

triangular based*

upbeat swan
#

,w sqrt((-7-0)^2 + (3-0)^2)

flat frigateBOT
glass edge
#

yeah see its 7.6

#

not even 7.5

#

so theres no way they messed up and rounded 7.6 to 7

#

i think our D coordinates are wrong

upbeat swan
#

no

#

A (0,0,3)

#

D (-7,0,3)

#

so sqrt ( (-7-0)^2 + (3-3)^2 )

glass edge
#

oh..

upbeat swan
#

,w sqrt ( (-7-0)^2 + (3-3)^2 )

flat frigateBOT
glass edge
#

i get it

#

so now the volume is unironically 6x7

turbid ore
upbeat swan
glass edge
#

why

upbeat swan
#

wdym why😭

glass edge
#

why did it have to be 7

upbeat swan
glass edge
#

:/

upbeat swan
#

they predicted the 67 joke

glass edge
#

okay c is pretty easy tho

#

just use pythagorean theorem correct

upbeat swan
#

yeah

glass edge
#

done

#

okay

#

now surface area next

upbeat swan
#

so what the asnwer

glass edge
#

what the ai

glass edge
upbeat swan
#

good

turbid ore
#

i havent learned the 3d geometry yet

glass edge
#

surface area ;-;

turbid ore
#

can ask anyhting bout 2d

upbeat swan
upbeat swan
glass edge
#

wait no

turbid ore
upbeat swan
glass edge
#

find the area of the triangle which we know

#

and multiply it by 2

upbeat swan
glass edge
#

since there are 2 similar triangles

turbid ore
upbeat swan
#

ok

upbeat swan
turbid ore
glass edge
#

then use the coordinates to find the heights and lengths of the rectangles, find the area and sum it all up

upbeat swan
#

yes

glass edge
glass edge
#

how do we write it

#

cuz my teachers not gonna accept some

#

working

turbid ore
#

ohhhh

glass edge
#

*calculation

turbid ore
#

now i can see this a total dif way

upbeat swan
#

just find all the areas of the rectangles

glass edge
upbeat swan
#

and add them with 2*area rectangle

turbid ore
#

this question is soo easy

glass edge
glass edge
upbeat swan
#

well

#

what shape is OBEC

glass edge
#

rectangle

upbeat swan
turbid ore
upbeat swan
#

and whats the length of oc

glass edge
#

nvm its 7

#

BE is 7

upbeat swan
#

yes

glass edge
upbeat swan
safe radishBOT
# turbid ore surface area is 96

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

upbeat swan
#

please

turbid ore
#

um

glass edge
#

this isnt who's going to be a millionaire where you just say the answer, and get it correct. you have to show working.

glass edge
# turbid ore hmm

plus i cant trust u u just used ai to solve this didnt you? chat is really unreliable

turbid ore
glass edge
turbid ore
#

wait a min

glass edge
#

ABED = 5*7

#

=35

upbeat swan
#

yes

glass edge
#

AOCD = 21

upbeat swan
#

yes

glass edge
#

OBEC = 28

upbeat swan
#

yes

glass edge
#

total surface area is 96

upbeat swan
#

yes

glass edge
#

units^3

upbeat swan
#

no

glass edge
#

no

#

^2

upbeat swan
#

thats for volume

upbeat swan
glass edge
#

okay i get it

#

tysm

#

do u have any tips

#

on how to visualize

upbeat swan
#

um

glass edge
#

as you can see, im pretty egregious

upbeat swan
#

just imagine yourself being in the plane

glass edge
#

;-;

upbeat swan
#

watching from the bottom

#

or from the top

#

it depends

glass edge
#

so like standing at the y axis

upbeat swan
#

from behind, from the left etc

glass edge
#

looking at the object

#

?

upbeat swan
#

whatever helps you picture the shape

turbid ore
upbeat swan
#

just imagine

#

being on a field

#

with a giant prism in front of you

#

and how it would look like

#

walking around

glass edge
#

hmm

#

tysm

upbeat swan
#

you're welcome

glass edge
#

.close

safe radishBOT
#
Channel closed

Closed by @glass edge

Use .reopen if this was a mistake.

#
Available help channel!

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Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
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• Be polite and have a nice day!

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heavy vector
#

help

safe radishBOT
heavy vector
#

please someone tell me at the last step how -x^2 became +x^2

exotic anvil
#

add x^2 to both sides and subtract 40 x from both sides

outer pollen
#

alternatively, subtract 400 from both sides, then multiply the equation by -1.

heavy vector
#

what the hell why to do that

#

why was -x^2 not eligible

exotic anvil
#

because usually with polynomials one likes the term of highest degree to have a positive coefficient

#

its neater

#

-x^2+40x-400=0 would give you the same answer if you solved it for x

exotic anvil
heavy vector
#

oh

#

thanks for the help

#

.close

safe radishBOT
#
Channel closed

Closed by @heavy vector

Use .reopen if this was a mistake.

azure harbor
#

vro mustve had a life changing experience

safe radishBOT
#
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

pearl silo
#

someone help me for this integral question?

safe radishBOT
wild copper
#

The base of this exponential part looks annoying. I wonder if there is a way to simplify it into one single variable:
$(x^4+1)^5$

flat frigateBOT
safe radishBOT
#

@pearl silo Has your question been resolved?

#
Channel closed

Closed by @pearl silo

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Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

summer lark
#

How do I graph this

safe radishBOT
summer lark
#

Find the volume of the solid generated by revolving about the line x = 2 the region bounded by y = x ^ 2, x = 2 and y = 0

viral wren
#

Where do you want to graph it?

brave wolf
#

are you trying to graph the solid or just the region?

#

For finding the volume, it suffices to graph the region

summer lark
#

Both

#

Do I use the disk or the washer?

brave wolf
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you will find out after you sketch the region

summer lark
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Is this correct?

brave wolf
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not quite

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you're correct that the region looks like this

summer lark
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Whre will it rotate?

brave wolf
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itll rotate around x = 2

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but the disks will be like this

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sorry for the terrible drawing lol

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but the discs will basically lay flat (parallel with x-axis)

summer lark
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Ohh okeyy okeyy

brave wolf
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so your integral isnt set up correctly

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you need to work with the horizontal discs

summer lark
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Integral of √y

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Is this correct?

brave wolf
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you're forgetting the square

summer lark
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Ohh yeahh

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Soo I guess it will just cancel out

brave wolf
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yeah, it will be essentially just integral of y

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but i think you might be forgetting some constants

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and you havent stated the bounds yet

summer lark
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The bounds is 4 and 0 right

brave wolf
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yep

summer lark
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The final answer will be 8piu³

brave wolf
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wdym u?

summer lark
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Sq unit

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Since we are talking about volume

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brave wolf
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oh

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yeah, sounds about right

summer lark
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I just check it online, why the answer in the internet 8/3 pi

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This is their graph

brave wolf
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what the hell did they do

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this doesnt look correct at all

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oh wait

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yeah mb, integrating (sqrt(y))^2 is wrong

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but their pic is also wrong it seems

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sqrt(y) is this distnace

summer lark
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It should be (2-√y)² right?

brave wolf
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yeah

summer lark
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Okeyy okeyy

brave wolf
summer lark
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But can I use the vertical

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Or not?

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To avoid square root

brave wolf